In this paper, we study a boundary value problem for the hybrid fractional integro-differential system involving the conformable fractional derivative. We first discuss the existence of solutions using the Krasnoselskii fixed point theorem. The second result will be the existence and uniqueness of solution and we obtain it using the Banach fixed point theorem. Finally, we end our work with an example to illustrate our results.
Citation: Ala Eddine Taier, Ranchao Wu, Naveed Iqbal. Boundary value problems of hybrid fractional integro-differential systems involving the conformable fractional derivative[J]. AIMS Mathematics, 2023, 8(11): 26260-26274. doi: 10.3934/math.20231339
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In this paper, we study a boundary value problem for the hybrid fractional integro-differential system involving the conformable fractional derivative. We first discuss the existence of solutions using the Krasnoselskii fixed point theorem. The second result will be the existence and uniqueness of solution and we obtain it using the Banach fixed point theorem. Finally, we end our work with an example to illustrate our results.
In recent years, fractional calculus has attracted a large number of mathematicians and modelers. In view of the growing interests in the subject, several definitions of fractional order differential and integral operators have been proposed according to the physical aspects of the problem under investigation. Some fractional order initial value problems and boundary value problems, involving Riemann-Liouville, Liouville, Caputo and Hadamard type fractional differential equations, has attracted the attention of many researchers, for instance, see [1,2,3,4,5,6,7,8,9].
In 2014, Abdeljawad [10] and Khalil [11] introduced and elaborated the concept of conformable fractional differential and integral operators, which were used in many interesting problems related to the solvability of nonlinear equations and systems. This is the field where advances are continuously taking place.
In order to present our problem, in this paper, we need first to mention some important research results published in the field of fractional differential systems. In [12], Tahereh Bashiri et al. considered a non cooperative system with the fractional order p∈(0,1) and investigated the existence of solutions. In [13], Varsha Daftardar-Gejji proposed a fractional differential system and analyzed the existence of positive solutions of the system in detail. In [14], Liu considered a cooperative system with the fractional order α,β∈(0,1). In [15], Ahmed et al. obtained the existence and uniqueness results for a nonlinear coupled system involving Caputo fractional derivatives with a new kind of coupled boundary condition.
In [16], Ahmed et al. introduced and analyzed an impulsive hybrid system of conformable fractional differential equations with boundary conditions, described by
Ttkαx(t)=f(t,x(t)),Δx(tk)=Sk(x(tk)),Δx′(tk)=S∗k(x(tk)),x(0)=0,x(T)=0, |
where Tα denotes the conformable fractional derivative of order α∈(1,2].
In [12], the fractional order of the two equations is the same and the perturbation term is also the same. In [14], the perturbation is a simple type. In [16], the authors studied discrete problems. Compared with the study in this article, we will consider a continuous problem with an integro-differential hybrid perturbation and the different order of fractional derivatives.
Due to the importance and academic value of the topic of fractional differential equations and systems, the importance of this subject in the modeling of so many phenomena, and the studies published in this field, we choose to study such models. As we know, there are few studies on the subject of conformable fractional systems. Motivated by the studies cited above, we will study a new type of fractional differential system, called the conformable fractional differential system, and a new type of hybrid perturbation (integro-differential term).
In this paper, motivated by all the aforementioned work on fractional differential equations and conformable fractional differential systems, we introduce and analyze a hybrid system of conformable fractional integro-differential system with boundary conditions, which is given by
Tα(u(t)−m∑i=1Ipifi(t,u(t),v(t)))=h(t,u(t),v(t)),Tβ(v(t)−m∑i=1Iqigi(t,u(t),v(t)))=k(t,u(t),v(t)),u(0)=u(T)=0,v(0)=v(T)=0. | (1.1) |
Here, Tα denotes the conformable fractional derivative of order α∈(1,2], Tβ is the conformable fractional derivative of order β∈(1,2], Ipi is the conformable fractional integral of order pi, Iqi is the conformable fractional integral of order qi, and h,k∈C([0,T]×R×R,R) and fi,gi∈C([0,T]×R,R).
The organization of this work is as follows. Section 2 contains some preliminary facts. In Section 3, we present the solution for the boundary value problem of hybrid fractional integro-differential system (1.1) involving the conformable fractional derivative, and then prove our main existence results. In Section 4, we prove the existence and uniqueness of solutions to the system. Finally, we illustrate the obtained results by an example.
Now, we give some basic concepts of conformable fractional calculus (see [10] and [11]).
Definition 2.1. [10,11] For α∈(0,1]. The conformable fractional derivative of a function f:[a,∞)→R of order α is defined by
Tαaf(t)=limϵ→0f(t+ϵ(t+a)1−α)−f(t)ϵ, | (2.1) |
for all t>a. If Tαaf(t) exists on (a,b), then Tαaf(a)=limt→aTαaf(t).
Definition 2.2. [10,11] Let α∈(n,n+1]. The conformable fractional derivative of a function f:[a,∞)→R of order α, where f(n)(t) exists, is defined by
Tαaf(t)=Tα−naf(n)(t). | (2.2) |
Definition 2.3. [10,11] Let α∈(n,n+1]. The conformable fractional integral of a function f:[a,∞)→R of order α is defined by
Iαaf(t)=1n!∫ta(t−s)n(s−a)α−n−1f(s)ds. | (2.3) |
Lemma 2.1. [10,11] Let α∈(n,n+1]. If f(t) is a continuous function on [a,∞), then TαaIαaf(t)=f(t) for all t>a.
Lemma 2.2. [10] Let α∈(n,n+1]. Then Tαa(t−a)k=0 for all t∈[a,b] and k=1,2,...,n.
Lemma 2.3. [10] Let α∈(n,n+1]. If Tαaf(t) is a continuous function on [a,∞), then
IαaTαaf(t)=f(t)−n∑k=0f(k)(a)(t−a)kk!, | (2.4) |
for all t>a.
Lemma 2.4 (Krasnoselskii fixed point theorem).[17] Let E be a non-empty, bounded, closed and convex subset of a Banach space X, and A,B:E↦E satisfy the following assumptions:
(1) Ax+By∈E, for every x,y∈X,
(2) A is a contraction,
(3) B is compact and continuous.
Then, there exists z∈X such that Az+Bz=z.
Lemma 2.5. (Banach fixed point theorem).[18] Let X be a non-empty complete metric space, and T:X↦X be a contraction mapping. Then, there exists a unique point x∈X such that Tx=x.
Now we define a solution to the system (1.1).
Definition 2.4. The pair of functions u,v∈C(J,R) with their conformable fractional derivatives of order α and β existing on J is a solution of (1.1) if it satisfies (1.1).
In this section, we study the existence of solutions to the system (1.1). By Lemma 3.1, we transform the system (1.1) into a fixed point problem.
Lemma 3.1. Let φ,ϕ∈C(0,T) and u,v∈C(J,R) be continuous real valued functions. Then the solution of the system
Tα(u(t)−m∑i=1Ipifi(t,u(t),v(t)))=φ(t),Tβ(v(t)−m∑i=1Iqigi(t,u(t),v(t)))=ϕ(t),u(0)=u(T)=0,v(0)=v(T)=0, | (3.1) |
is given by
u(t)=∫t0(t−s)sα−2φ(s)ds+m∑i=1∫t0(t−s)spi−2fi(s,u(s),v(s))ds−1T[∫T0(T−s)sα−2φ(s)ds+m∑i=1∫T0(T−s)spi−2fi(s,u(s),v(s))ds]t, | (3.2) |
v(t)=∫t0(t−s)sβ−2ϕ(s)ds+m∑i=1∫t0(t−s)sqi−2gi(s,u(s),v(s))ds−1T[∫T0(T−s)sβ−2ϕ(s)ds+m∑i=1∫T0(T−s)sqi−2gi(s,u(s),v(s))ds]t. | (3.3) |
Proof. Applying the conformable fractional integrals Iα and Iβ on the both sides of equations of system (3.1) respectively and using Lemma 2.3, we get that the general solution of the system (3.1) for t∈J is
u(t)=Iαφ(t)+C1+C2t+m∑i=1Ipifi(t,u(t),v(t)), | (3.4) |
v(t)=Iβϕ(t)+C3+C4t+m∑i=1Iqigi(t,u(t),v(t)). | (3.5) |
where C1,C2,C3 and C4 are unknown constants. Using the conditions u(0)=0 and v(0)=0 gives C1=0 and C3=0.
Now the Eqs (3.4) and (3.5) have the form
u(t)=Iαφ(t)+C2t+m∑i=1Ipifi(t,u(t),v(t)),v(t)=Iβϕ(t)+C4t+m∑i=1Iqigi(t,u(t),v(t)). |
Using the conditions u(T)=0 and v(T)=0 we obtain
C2=−1T(∫T0(T−s)sα−2φ(s)ds+m∑i=1∫T0(T−s)spi−2gi(s,u(s),v(s))ds),C4=−1T(∫T0(T−s)sβ−2ϕ(s)ds+m∑i=1∫T0(T−s)sqi−2gi(s,u(s),v(s))ds). |
Using the values of C1,C2,C3 and C4 in (3.4) and (3.5), we get the solution. The converse follows from direct computation. This completes the proof.
Our first result concerns the study of existence of solution for problem (1.1) using the Krasnoselskii fixed-point theorem. For this, we will need some assumptions about the functions fi, gi, h and k.
Denote by X=(C([0,T]×R)×C([0,T]×R),R), the Banach space endowed with the norm
‖(u,v)‖=‖u‖+‖v‖=supt∈[0,T]|u(t)|+supt∈[0,T]|v(t)|, |
for (u,v)∈X.
(H1) The functions fi,gi:J×R×R⟶R and h,k:J×R×R⟶R are continuous and there exist nonnegative functions ηi,σi, i=1,..,m,μ, and λ such that
|fi(t,u(t),v(t))|≤ηi(t),|gi(t,u(t),v(t))|≤σi(t),|h(t,u(t),v(t))|≤μ(t),|k(t,u(t),v(t))|≤λ(t). |
(H2) There exist positive constants Ck, k=1,..,4, Lij, j=1,2, Mi,Ni, i=1,2,..,m such that
|h(t,u1,v1)−h(t,u2,v2)|⩽C1‖u1−u2‖+C2‖v1−v2‖, |
|k(t,u1,v1)−k(t,u2,v2)|⩽C3‖u1−u2‖+C4‖v1−v2‖, |
|fi(t,u1,v1)−fi(t,u2,v2)|⩽Li1‖u1−u2‖+Li2‖v1−v2‖, |
|gi(t,u1,v1)−gi(t,u2,v2)|⩽Ni‖u1−u2‖+Mi‖v1−v2‖. |
Theorem 3.1. Assume that the assumptions (H1) and (H2) hold. If
(TαCα(α−1)+m∑i=1TpiLipi(pi−1))<1 |
and
(TβNβ(β−1)+m∑i=1TqiMiqi(qi−1))<1, |
then the fractional integro-differential system (1.1) has at least one solution in X on J.
Proof. We define an operator Π:X⟼X associated with the system (1.1) by
Π(u,v)(t)=(Π1(u,v)(t),Π2(u,v)(t)), |
where
Π1(u,v)(t)=∫t0(t−s)sα−2h(s,u(s),v(s))ds+m∑i=1∫t0(t−s)spi−2fi(s,u(s),v(s))ds−tT[∫T0(T−s)sα−2h(s,u(s),v(s))ds+m∑i=1∫T0(T−s)spi−2fi(s,u(s),v(s))ds],Π2(u,v)(t)=∫t0(t−s)sβ−2k(s,u(s),v(s))ds+m∑i=1∫t0(t−s)sqi−2gi(s,u(s),v(s))ds,−tT[∫T0(T−s)sβ−2k(s,u(s),v(s))ds+m∑i=1∫T0(T−s)sqi−2gi(s,u(s),v(s))ds]. |
First, we will transform problem (1.1) into a fixed point problem Πx=x, where Π is the operator defined above. So, before starting the proof, we decompose Πi into a sum of two operators Ai and Bi, i=1,2 where
A1(u,v)(t)=∫t0(t−s)sα−2h(s,u(s),v(s))ds+m∑i=1∫t0(t−s)spi−2fi(s,u(s),v(s))ds,A2(u,v)(t)=−tT[∫T0(T−s)sα−2h(s,u(s),v(s)ds+m∑i=1∫T0(T−s)spi−2fi(s,u(s),v(s))ds], |
and
B1(u,v)(t)=∫t0(t−s)sβ−2k(s,u(s),v(s))ds+m∑i=1∫t0(t−s)sqi−2gi(s,u(s),v(s))ds,B2(u,v)(t)=−tT[∫T0(T−s)sβ−2k(s,u(s),v(s))ds+m∑i=1∫T0(T−s)sqi−2gi(s,u(s),v(s))ds]. |
Observe that
Π1(u,v)=A1(u,v)+A2(u,v),Π2(u,v)=B1(u,v)+B2(u,v). |
Now, we show that the operators A1,A2,B1 and B2 satisfy all conditions of Lemma 2.4 in a series of steps.
Step 1. We define the set Ω={(u,v)∈X:‖(u,v)‖X≤r}, where r is a positive real constant satisfying the condition
r⩾max{2‖μ‖Tαα(α−1)+m∑i=12‖ηi‖Tpipi(pi−1);2‖λ‖Tββ(β−1)+m∑i=12‖σi‖Tqiqi(qi−1)}. | (3.6) |
First, we show that A1(u,v)+A2(u,v)∈Ω and B1(u,v)+B2(u,v)∈Ω. So for (u,v)∈Ω and t∈J, we have
|A1(u,v)(t)+A2(u,v)(t)|≤∫t0(t−s)sα−2|h(s,u(s),v(s))|ds+m∑i=1∫t0(t−s)spi−2|fi(s,u(s),v(s))|ds+tT[∫T0(T−s)sα−2|h(s,u(s),v(s))|ds+m∑i=1∫T0(T−s)spi−2|fi(s,u(s),v(s))|ds]≤∫t0(t−s)sα−2μ(s)ds+m∑i=1∫t0(t−s)spi−2ηi(s)ds+tT[∫T0(T−s)sα−2μ(s)ds+m∑i=1∫T0(T−s)spi−2ηi(s)ds]≤‖μ‖(∫t0(t−s)sα−2ds+tT∫T0(T−s)sα−2ds)+‖ηi‖(m∑i=1∫t0(t−s)spi−2ds+tTm∑i=1∫T0(T−s)spi−2)≤‖μ‖(tαα(α−1)+tTαTα(α−1))+m∑i=1‖ηi‖(tpipi(pi−1)+tTpiTpi(pi−1))≤‖μ‖2Tαα(α−1)+m∑i=1‖ηi‖2Tpipi(pi−1)≤r. |
That implies that ‖A1(u,v)(t)+A2(u,v)(t)‖X≤r, which means that A1(u,v)(t)+A2(u,v)∈Ω. Analogously, we obtain
|B1(u,v)(t)+B2(u,v)(t)|≤‖λ‖2Tββ(β−1)+m∑i=1‖σi‖2Tqiqi(qi−1)≤r. |
That means that B1(u,v)(t)+B2(u,v)∈Ω.
Step 2. We want to show that A2 and B2 are contractions on Ω, for (u1,v1),(u2,v2)∈Ω and t∈J. Using the assumption (H1), we have
|A2(u1,v1)(t)−A2(u2,v2)(t)|=|−tT[∫T0(T−s)sα−2h(s,u1(s),v1(s))ds+m∑i=1∫T0(T−s)spi−2fi(s,u1(s),v1(s))ds]+tT[∫T0(T−s)sα−2h(s,u2(s),v2(s))ds+m∑i=1∫T0(T−s)spi−2fi(s,u2(s),v2(s))ds]|≤tT∫T0(T−s)sα−2|h(s,u1(s),v1(s))−h(s,u2(s),v2(s))|ds+tTm∑i=1∫T0(T−s)spi−2|fi(s,u1(s),v1(s))−fi(s,u2(s),v2(s))|ds≤tT[∫T0(T−s)sα−2[C1(u1(s)−u2(s))+C2(v1(s)−v2(s))]ds+m∑i=1∫T0(T−s)spi−2[L1i(u1(s)−u2(s))+L2i(v1(s)−v2(s))]ds]≤tT[(Tα(C1‖u1−u2‖+C2‖v1−v2‖)α(α−1))+m∑i=1Tpi(L1i‖u1−u2‖+L2i‖v1−v2‖pi(pi−1)]≤TαCα(α−1)‖u1−u2,v1−v2‖+m∑i=1TpiLipi(pi−1)‖u1−u2,v1−v2‖≤(TαCα(α−1)+m∑i=1TpiLipi(pi−1))‖u1−u2,v1−v2‖. |
Analogously, we obtain
|B2(u1,v1)(t)−B2(u2,v2)(t)|≤(TβNβ(β−1)+m∑i=1TqiMiqi(qi−1))‖u1−u2,v1−v2‖. |
Hence, the operators A2 and B2 are contractions on Ω.
Step 3. Now, we prove that A1 and B1 are completely continuous on Ω. We need to show that the sets (A1Ω) and (B1Ω) are uniformly bounded, the sets ¯(A1Ω) and ¯(B1Ω) are equicontinuous, and the operators A1:Ω⟼Ω and B1:Ω⟼Ω are continuous.
For (u,v)∈Ω and t∈J, we have
|A1(u,v)(t)|=|∫t0(t−s)sα−2h(s,u(s),v(s))ds+m∑i=1∫t0(t−s)spi−2fi(s,u(s),v(s))ds|≤∫t0(t−s)sα−2|h(s,u(s),v(s))|ds+m∑i=1∫t0(t−s)spi−2|fi(s,u(s),v(s))|ds≤∫t0(t−s)sα−2μ(s)ds+m∑i=1∫t0(t−s)spi−2ηi(s)ds≤‖μ‖tαα(α−1)+m∑i=1‖ηi‖tpipi(pi−1)≤‖μ‖Tαα(α−1)+m∑i=1‖ηi‖Tpipi(pi−1). |
Then the set (A1Ω) is uniformly bounded. Analogously, we obtain
|B1(u,v)(t)|≤‖λ‖Tββ(β−1)+m∑i=1‖σi‖Tqiqi(qi−1), |
so the set (B1Ω) is uniformly bounded.
Now, we show that ¯(A1Ω) and ¯(B1Ω) are equicontinuous. Let t1,t2∈J with t1<t2, we have for any (u,v)∈Ω,
|A1(u,v)(t2)−A1(u,v)(t1)|=|∫t20(t2−s)sα−2h(s,u(s),v(s))ds+m∑i=1∫t20(t2−s)spi−2fi(s,u(s),v(s))ds−∫t10(t1−s)sα−2h(s,u(s),v(s))ds−m∑i=1∫t10(t1−s)spi−2fi(s,u(s),v(s))ds|≤∫t10(t2−s)sα−2|h(s,u(s),v(s))|ds+∫t2t1(t2−s)sα−2|h(s,u(s),v(s))|ds−∫t10(t1−s)sα−2|h(s,u(s),v(s))|ds+m∑i=1∫t10(t2−s)spi−2|fi(s,u(s),v(s))|ds+m∑i=1∫t2t1(t2−s)spi−2|fi(s,u(s),v(s))|ds−m∑i=1∫t10(t1−s)spi−2|fi(s,u(s),v(s))|ds≤∫t2t1(t2−s)sα−2|h(s,u(s),v(s))|ds+m∑i=1∫t2t1(t2−s)spi−2|fi(s,u(s),v(s))|ds≤∫t2t1(t2−s)sα−2μ(s)ds+m∑i=1∫t2t1(t2−s)spi−2ηi(s)ds≤‖μ‖(tα2−tα1α(α−1))+m∑i=1‖ηi‖(tpi2−tpi1pi(pi−1)). |
Analogously,
|B1(u,v)(t2)−B1(u,v)(t1)|≤‖λ‖(tβ2−tβ1β(β−1))+m∑i=1‖σi‖(tqi2−tqi1qi(qi−1)). |
As t1⟼t2, the right hand side of the above inequalities tend to zero. Therefore, it follows that ¯(A1Ω) and ¯(B1Ω) are equicontinuous.
Finally, we show that the operators A1 and B1 are continuous in X. Let (un,vn) be a sequence in Ω converging to a point (u,v)∈Ω. Then, by Lebesgue dominated convergence theorem, for all t∈J, we have
limn⟼∞A1(un,vn)(t)=limn⟼∞(∫t0(t−s)sα−2h(s,un(s),vn(s))ds+m∑i=1∫t0(t−s)spi−2fi(s,un(s),vn(s))ds)=∫t0(t−s)sα−2limn⟼∞h(s,un(s),vn(s))ds+m∑i=1∫t0(t−s)spi−2limn⟼∞fi(s,un(s),vn(s))ds=∫t0(t−s)sα−2h(s,u(s),v(s))ds+m∑i=1∫t0(t−s)spi−2fi(s,u(s),v(s))ds=A1(u,v)(t). |
A similar proof works for the operator B1.
Consequently, A1 and B1 are continuous. Therefore, A1 and B1 are also relatively compact on Ω. Using the Arzilà-Ascoli theorem, we conclude that A1 and B1 are compact on Ω. Now, all conditions of the Krasnoselskiiś fixed point theorem are satisfied, so the operator Π has a fixed point in Ω. Finally, we deduce that the system (1.1) has at least one solution in X on J.
In this section, we study the existence and uniqueness of solution of the system (1.1). Our result is based on the Banach fixed point theorem.
Theorem 4.1. Assume that the hypothesis (H1) and (H2) are true. If
2[CTαα(α−1)+m∑i=1LTpipi(pi−1)]<1 |
and
2[CTββ(β−1)+m∑i=1MTqiqi(qi−1)]<1, |
then, the fractional integro-differential system (1.1) has a unique solution in X on J.
Proof. We define an operator Π:X⟼X associated with the system (1.1) by
Π(u,v)(t)=(Π1(u,v)(t),Π2(u,v)(t)), |
given in the proof of Theorem 3.1.
Now, we show that the operator Π has a fixed point in Bρ, which represents a unique solution of system (1.1). So, the proof is given in two steps.
Step 1. First, we define the set Bρ by
Bρ={(u,v)∈X;‖(u,v)‖X≤ρ}, |
where the positive real constant ρ is chosen so that
ρ>2(‖μ‖Tαα(α−1)+‖λ‖Tββ(β−1))+2m∑i=1(‖ηi‖Tpipi(pi−1)+‖σi‖Tqiqi(qi−1)). |
We will show that ΠiBρ⊂Bρ, i=1,2. For each t∈J and (u,v)∈Bρ,
|Π1(u,v)(t)|≤∫t0(t−s)sα−2|h(s,u(s),v(s))|ds+m∑i=1∫t0(t−s)spi−2|fi(s,u(s),v(s))|ds+tT[∫T0(T−s)sα−2|h(s,u(s),v(s))|ds+m∑i=1∫T0(T−s)spi−2|fi(s,u(s),v(s))|ds]≤∫t0(t−s)sα−2μ(s)ds+m∑i=1∫t0(t−s)spi−2ηi(s)ds+tT[∫T0(T−s)sα−2μ(s)ds+m∑i=1∫T0(T−s)spi−2ηi(s)ds]≤‖μ‖∫t0(t−s)sα−2ds+m∑i=1‖ηi‖∫t0(t−s)spi−2ds+tT[‖μ‖∫T0(T−s)sα−2ds+m∑i=1‖ηi‖∫T0(T−s)spi−2ds]≤‖μ‖tα+Tαα(α−1)+m∑i=1‖ηi‖tpi+Tpipi(pi−1)≤‖μ‖2Tαα(α−1)+m∑i=1‖ηi‖2Tpipi(pi−1). |
This implies
‖Π1(u,v)(t)‖≤‖μ‖2Tαα(α−1)+m∑i=1‖ηi‖2Tpipi(pi−1)≤ρ. |
Therefore, Π1Bρ⊂Bρ. Analogously, we obtain
‖Π2(u,v)(t)‖≤‖λ‖2Tββ(β−1)+m∑i=1‖σi‖2Tqiqi(qi−1)≤ρ, |
so Π2Bρ⊂Bρ. For any (u,v)∈Bρ, we have
‖Π(u,v)(t)‖=‖Π1(u,v)(t)‖+‖Π2(u,v)(t)‖≤‖μ‖2Tαα(α−1)+m∑i=1‖ηi‖2Tpipi(pi−1)+‖λ‖2Tββ(β−1)+m∑i=1‖σi‖2Tqiqi(qi−1)≤2(‖μ‖Tαα(α−1)+‖λ‖Tββ(β−1))+2m∑i=1(‖ηi‖Tpipi(pi−1)+‖σi‖Tqiqi(qi−1))≤ρ, |
which shows that Π maps Bρ into itself.
Step 2. We will show that the operator Π:Bρ↦Bρ is a contraction. Let (u1,v1), (u2,v2)∈X and t∈J. By assumption (H2), we obtain
‖Π1(u1,v2)(t)−Π1(u2,v2)(t)‖=|∫t0(t−s)sα−2h(s,u1(s),v1(s))ds+m∑i=1∫t0(t−s)spi−2fi(s,u1(s),v1(s))ds−tT[∫T0(T−s)sα−2h(s,u1(s),v1(s))ds+m∑i=1∫T0(T−s)spi−2fi(s,u1(s),v1(s))ds]−∫t0(t−s)sα−2h(s,u2(s),v2(s))ds+m∑i=1∫t0(t−s)spi−2fi(s,u2(s),v2(s))ds+tT[∫T0(T−s)sα−2h(s,u2(s),v2(s))ds+m∑i=1∫T0(T−s)spi−2fi(s,u2(s),v2(s))ds]|≤∫t0(t−s)sα−2|h(s,u1(s),v1(s))−h(s,u2(s),v2(s))|ds+m∑i=1∫t0(t−s)spi−2|fi(s,u1(s),v1(s))−fi(s,u2(s),v2(s))|ds+tT[∫T0(T−s)sα−2|h(s,u1(s),v1(s))−h(s,u2(s),v2(s))|ds+m∑i=1∫T0(T−s)spi−2|fi(s,u1(s),v1(s))−fi(s,u2(s),v2(s))|ds]≤∫t0(t−s)sα−2[C1(u1(s)−u2(s))+C2(v1(s)−v2(s))]ds+m∑i=1∫t0(t−s)spi−2[L1i(u1(s)−u2(s))+L2i(v1(s)−v2(s))]ds+tT[∫T0(T−s)sα−2[C1(u1(s)−u2(s))+C2(v1(s)−v2(s))]ds+m∑i=1∫T0(T−s)spi−2[L1i(u1(s)−u2(s))+L2i(v1(s)−v2(s))]ds]≤C1‖u1−u2‖+C2‖v1−v2‖α(α−1)tα+m∑i=1L1i‖u1−u2‖+L2i‖v1−v2‖pi(pi−1)tpi+C1‖u1−u2‖+C2‖v1−v2‖α(α−1)Tα+m∑i=1L1i‖u1−u2‖+L2i‖v1−v2‖pi(pi−1)Tpi≤2CTαα(α−1)(‖u1−u2‖+‖v1−v2‖)+2m∑i=1LTpipi(pi−1)(‖u1−u2‖+‖v1−v2‖)≤2[CTαα(α−1)+m∑i=1LTpipi(pi−1)]‖(u1−u2,v1−v2)‖. |
This implies that Π1 is a contraction.
Analogously, we can prove that Π2 is a contraction. Then, by the Banach fixed point theorem, there exists a unique point (u,v)∈X, such that Π(u,v)=(u,v). It is the unique solution of our system (1.1), and then the proof of the theorem is completed.
Consider the following Hybrid fractional integro-differential system involving conformable fractional derivative operators
T32(u(t)−2∑i=1Ipifi(t,u(t),v(t)))=1+t2+sin(u(t))+cos(v(t))8(1+t),T53(v(t)−2∑i=1Iqigi(t,u(t),v(t)))=t3+t+cos(u(t))+sin(v(t))(t+1)(t2+1),u(0)=u(T)=0,v(0)=v(T)=0. | (5.1) |
The problem (5.1) is a particular case of (1.1) with α=32, β=53, and
fi(t,u(t),v(t))=t(|u(t)|+|u(t)|)8i,gi(t,u(t),v(t))=it(cos(u(t))+|v(t)|)50. |
Clearly, fi,gi, i=1,2,..,m,h, and k are continuous functions and satisfy condition (H1) with ηi(t)=t4i, σi(t)=it25, μ(t)=1+t28(1+t) and λ(t)=t3+t(1+t)(1+t2).
Also
|fi(t,u1,v1)−fi(t,u2,v2)|≤t8i|u1−u2+v1−v2|≤T8i‖u1−u2,v1−v2‖, |
|gi(t,u1,v1)−gi(t,u2,v2)|≤it50|cos(u1)−cos(u2)+sin(v1)−sin(v2)|≤iT50‖u1−u2,v1−v2‖, |
and
|k(t,u1,v1)−k(t,u2,v2)|≤1(t+1)(t2+1)‖u1−u2,v1−v2‖. |
Taking the value of T=1 we get
(TαCα(α−1)+m∑i=1TpiLipi(pi−1))=0.37500000<1,(TβNβ(β−1)+m∑i=1TqiMiqi(qi−1))=0.42161904<1, |
where C=18, L1=14,L2=18, N=12 and M1=125,M2=225 and the values of pi and qi are chosen as pi=3i. This gives p1=3, p2=32, and qi=2i+32i we get q1=52, q2=74.
Since the assumptions (H1) and (H2) hold, according to Theorem 3.1 the problem (5.1) has at least one solution. To see if the solution is unique, note that assumptions (H1) and (H2) hold, from the first part of the existence result. Also, the conditions of Theorem 3.2
2(TαCα(α−1)+m∑i=1TpiLipi(pi−1))=0.75000000<1,2(TβNβ(β−1)+m∑i=1TqiMiqi(qi−1))=0.84323808<1, |
are satisfied. Therefore, from Theorem 3.2, the problem (5.1) has a unique solution.
In this work, we consider the existence and uniqueness of solutions for the boundary value problem of hybrid fractional integro-differential systems involving the conformable fractional derivative. By transforming the problem into a Volttera integral equation and using the Krasnoselskii fixed point theorem, we get the results about the existence of solutions for the boundary value problem (1.1) under some conditions. Then, using the Banach fixed point theorem, we get the existence and uniqueness of the solution for the boundary value problem, after transforming the problem into a fixed point problem.
The authors declare that they have not used Artificial Intelligence (AI) tools in the creation of this article.
This work was supported by the National Natural Science Foundation of China (Nos. 11971032, 62073114).
The authors declare that there are no competing interests.
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