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Research article Special Issues

New classes of unified fractional integral inequalities

  • Many researchers in recent years have studied fractional integrals and derivatives. Some authors recently introduced generalized fractional integrals, the so-called unified fractional integrals. In this article, we establish certain new integral inequalities by employing the unified fractional integral operators. In fact, for a class of n (nN), positive continuous and decreasing functions on [v1,v2], certain new classes of integral inequalities are discussed. The inequalities established in this manuscript are more general forms of the classical inequalities given in the literature. The existing classical inequalities can be rectified by imposing the conditions stated in remarks. By imposing certain conditions on and Λ available in the literature, many new forms of fractional integral inequalities can be produced.

    Citation: Gauhar Rahman, Muhammad Samraiz, Saima Naheed, Artion Kashuri, Kamsing Nonlaopon. New classes of unified fractional integral inequalities[J]. AIMS Mathematics, 2022, 7(8): 15563-15583. doi: 10.3934/math.2022853

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  • Many researchers in recent years have studied fractional integrals and derivatives. Some authors recently introduced generalized fractional integrals, the so-called unified fractional integrals. In this article, we establish certain new integral inequalities by employing the unified fractional integral operators. In fact, for a class of n (nN), positive continuous and decreasing functions on [v1,v2], certain new classes of integral inequalities are discussed. The inequalities established in this manuscript are more general forms of the classical inequalities given in the literature. The existing classical inequalities can be rectified by imposing the conditions stated in remarks. By imposing certain conditions on and Λ available in the literature, many new forms of fractional integral inequalities can be produced.



    Fractional calculus is presently primarily concerned with studying fractional-order integral and derivative functions over real and complex domains and their applications. Using arithmetic from classical analysis in the fractional analysis is critical in many cases for producing more realistic findings. Fractional order differential equations can handle a wide variety of mathematical models. Fractional mathematical models provide more comprehensive and accurate results than classical mathematical models because they are particular cases of fractional-order mathematical models. In classical analysis, integer orders are not a good model for nature. On the other hand, fractional computing allows us to look at any number of orders and come up with significantly more concrete objectives.

    In [1,2,3,4,5], some researchers defined new fractional derivative operators by using exponential and Mittag-Leffler functions in the kernels. Such developments encourage further study into new concepts for combining fractional derivative and integral operators and obtaining fractional integral inequalities using these modified fractional derivatives and integral operators. In the theory of differential equations and applied mathematics, integral inequalities and their applications are crucial. Using the classical fractional integral, fractional derivative operators and their extensions, many different forms of classical integral inequalities and their modifications have been created [6,7,8,9,10,11,12,13].

    Sarikaya and Budak investigated the (k,s)-Riemann-Liouville fractional integral and its applications in [14]. In [15], enlarged Hermite-Hadamard type inequalities are discovered using fractional integral operators. Agarwal et al. [16] used the k-fractional integrals operators to introduce Hermite-Hadamard type inequalities.

    Using a family of n positive functions, Dahmani, in [17], presented certain classes of fractional integral inequalities. Using the (k,s)-fractional integral operators, the authors of [18] constructed fractional integral inequalities for a class of n (nN), positive continuous and decreasing functions on [a,b].

    Using fractional conformable integrals, the authors [19,20,21,22] recently developed numerous forms of inequalities. In [29], Akin studied the boundedness and compactness of integral operators on time scales. Akin [30] established fractional maximal integrals to establish integral inequalities on time scales. New principles of non-linear integral inequalities are presented in time scales via diamond-α dynamic integrals and the nabla integral in [31]. Younus et al. [32] gave some new variants of Gronwall type inequalities on time scales. An interesting application of fractional integrals and differentials can be found in the works [33,34,35].

    Definition 1.1. [23] Let Λ:[0,)[0,) be the function satisfying the hypothesis given below:

    10Λ(υ)υdυ<, (1.1)
    1KΛ(1)Λ(2)K,12122, (1.2)
    Λ(2)22LΛ(1)21,12, (1.3)
    |Λ(2)22Λ(1)21|M|21|Λ(2)22,12122, (1.4)

    where K,L,M>0 and are independent of 1,2>0. If Λ(2)σ2 is increasing for some σ>0, and Λ(2)μ2 is decreasing for some μ>0, then Λ satisfies (1.1)–(1.4).

    Definition 1.2. [25] Let the function be differentiable and strictly increasing on [v1,v2] and let the weighted function ω(θ)0 be defined on [v1,v2]. Let Xpω(v1,v2), 1p, be the space of all Lebesgue measurable functions defined on [v1,v2] for which Xpω< is

    Xpω=(v2v1(ω(θ)(θ))p(θ)dθ)1p,1p<,

    and

     |Xω=esssupv1θv2ω(θ)(θ)∣<.

    Note that Xpω(v1,v2)ω(θ)(θ)((θ))1pLP(v1,v2) for 1p<, and Xω(v1,v2)ω(θ)(θ)L(v1,v2).

    Definition 1.3. [24] The unified weighted left and right sided integral operators are respectively given below:

    (ωIΛv1+)(λ)=ω1(λ)λv1Λ((λ)(υ))(λ)(υ)ω(υ)(υ)(υ)dυ,v1<λ, (1.5)

    and

    (ωIΛv2)(λ)=ω1(λ)v2λΛ((υ)(λ))(υ)(λ)ω(υ)(υ)(υ)dυ,v2>λ. (1.6)

    Remark 1.1. Here, we discuss the following special cases of (1.5) and (1.6) by applying some specific conditions on and Λ.

    (i) If we take Λ((λ))=(λ), then unified weighted integrals (1.5) and (1.6) will become

    (ωIv1+)(λ)=ω1(λ)λv1ω(υ)(υ)(υ)dυ,v1<λ,

    and

    (ωIv2)(λ)=ω1(λ)v2λω(υ)(υ)(υ)dυ,v2>λ,

    respectively.

    (ii) If we take (λ)=λ, then the unified integrals (1.5) and (1.6) will become

    (ωIv1+)(λ)=ω1(λ)λv1Λ(λυ)λυω(υ)(υ)dυ,v1<λ, (1.7)

    and

    (ωIv2)(λ)=ω1(λ)v2λΛ(υλ)υλω(υ)(υ)dυ,v2>λ, (1.8)

    respectively.

    (iii) If we take Λ((λ))=(λ)ζΓ(ζ), then (1.5) and (1.6) will lead to the following generalized Riemann-Liouville fractional integrals, respectively, as defined by[25].

    (ωIζv1)(λ)=ω1(λ)Γ(ζ)λv1((λ)(υ))ζ1ω(υ)(υ)(υ)dυ,v1<λ, (1.9)

    and

    (ωIζv2)(λ)=ω1(λ)Γ(ζ)v2λ((υ)(λ))ζ1ω(υ)(υ)(υ)dυ,v2>λ, (1.10)

    where ζ,C with (ζ)>0.

    (iv) If we take (λ)=λ and Λ((λ))=λζΓ(ζ), then (1.5) and (1.6) reduce to the given weighted Riemann-Liouville fractional integrals, respectively:

    (ωIζv1+)(λ)=ω1(λ)Γ(ζ)λv1(λυ)ζ1ω(υ)(υ)dυ,v1<λ, (1.11)

    and

    (ωIζv2)(λ)=ω1(λ)Γ(ζ)v2λ(υλ)ζ1ω(υ)(υ)dυ,v2>λ. (1.12)

    (v) If we take (λ)=lnλ and Λ((λ))=(lnλ)ζΓ(ζ), then (1.5) and (1.6) will lead to the weighted Hadamard integrals given below:

    (ωIζv1+)(λ)=ω1(λ)Γ(ζ)λv1(lnλlnυ)ζ1ω(υ)(υ)dυυ,v1<λ, (1.13)

    and

    (ωIζv2)(λ)=ω1(λ)Γ(ζ)v2λ(lnυlnλ)ζ1ω(υ)(υ)dυυ,v2>λ. (1.14)

    (vi) If we take (λ)=λη and Λ((λ))=ληη, η>0, then (1.5) and (1.6) will become weighted Katugampola fractional integrals as follows:

    (ωIζv1)(λ)=ω1(λ)Γ(ζ)λv1(ληυηη)ζ1ω(υ)(υ)dυυ1η,v1<λ, (1.15)

    and

    (ωIζv2)(λ)=ω1(λ)Γ(ζ)v2λ(υηληη)ζ1ω(υ)(υ)dυυ1η,v2>λ. (1.16)

    (vii) If we take (λ)=λ and Λ((λ))=ληexp(1ηηλ), η(0,1), then (1.5) and (1.6) will reduce to the weighted fractional integrals given by

    (ωIηv1+)(λ)=ω1(λ)ηλv1exp(1ηη(λυ))ω(υ)(υ),v1<λ, (1.17)

    and

    (ωIηv2)(λ)=ω1(λ)ηv2λexp(1ηη(υλ))ω(υ)(υ)dυ,v2>λ. (1.18)

    Remark 1.2. (i) If we take ω(λ)=1 and Λ((λ))=(λ), then (1.5) and (1.6) will become

    (Iv1+)(λ)=λv1(υ)(υ)dυ,v1<λ,

    and

    (Iv2)(λ)=v2λ(υ)(υ)dυ,v2>λ,

    respectively.

    (ii) If we take ω(λ)=1, then (1.5) and (1.6) will lead to the unified integrals defined by [26] as follows:

    (IΛv1+)(λ)=λv1Λ((λ)(υ))(λ)(υ)(υ)(υ)dυ,v1<λ, (1.19)

    and

    (IΛv2)(λ)=v2λΛ((υ)(λ))(υ)(λ)(υ)(υ)dυ,v2>λ. (1.20)

    (iii) If we take ω(λ)=1 and (λ)=λ, then (1.5) and (1.6) will reduce to the fractional integrals defined by [27] as follows:

    (IΛv1+)(λ)=λv1Λ(λυ)λυ(υ)dυ,v1<λ, (1.21)

    and

    (IΛv2)(λ)=v2λΛ(υλ)υλ(υ)dυ,v2>λ. (1.22)

    (iv) [28,36] If we put ω(λ)=1 and Λ((λ))=(λ)ζΓ(ζ), then (1.5) and (1.6) will become generalized Riemann-Liouville fractional integrals as follows:

    (Iζv1)(λ)=1Γ(ζ)λv1((λ)(υ))ζ1(υ)(υ)dυ,v1<λ, (1.23)

    and

    (Iζv2)(λ)=1Γ(ζ)v2λ((υ)(λ))ζ1(υ)(υ)dυ,v2>λ, (1.24)

    where ζ,C with (ζ)>0.

    (v) If we take ω(λ)=1, (λ)=λ and Λ((λ))=λζΓ(ζ), then (1.5) and (1.6) will reduce to the following Riemann-Liouville fractional integrals

    (Iζv1+)(λ)=1Γ(ζ)λv1(λυ)ζ1(υ)dυ,v1<λ, (1.25)

    and

    (Iζv2)(λ)=1Γ(ζ)v2λ(υλ)ζ1(υ)dυ,v2>λ, (1.26)

    respectively (see, [28,36]).

    (vi) If we take ω(λ)=1, (λ)=lnλ and Λ((λ))=(lnλ)ζΓ(ζ), then (1.5) and (1.6) will respectively become the following Hadamard integrals [28,36].

    (Iζv1+)(λ)=1Γ(ζ)λv1(lnλlnυ)ζ1(υ)dυυ,v1<λ,

    and

    (Iζv2)(λ)=1Γ(ζ)v2λ(lnυlnλ)ζ1(υ)dυυ,v2>λ.

    (vii) If we take ω(λ)=1, (λ)=λη and Λ((λ))=ληη, η>0, then (1.5) and (1.6) will become Katugampola [37] integrals as follows:

    (Iζv1)(λ)=1Γ(ζ)λv1(ληυηη)ζ1(υ)dυυ1η,v1<λ,

    and

    (Iζv2)(λ)=1Γ(ζ)v2λ(υηληη)ζ1(υ)dυυ1η,v2>λ.

    (viii) If we take ω(λ)=1, (λ)=λ and Λ((λ))=ληexp(1ηηλ), η(0,1), then (1.5) and (1.6) reduce to the integrals given below:

    (Iηv1+)(λ)=1ηλv1exp(1ηη(λυ))(υ),v1<λ,

    and

    (Iηv2)(λ)=1ηv2λexp(1ηη(υλ))(υ)dυ,v2>λ,

    respectively. Similarly, (1.5) and (1.6) will reduce to the integrals introduced by [22,38,39,40].

    The main motivation of this paper is to establish certain new integral inequalities by employing the unified fractional integral operators. In fact, for a class of n (nN) positive, continuous and decreasing functions on [v1,v2], certain new classes of integral inequalities will be discussed. The inequalities obtained in this manuscript are more general forms of the classical inequalities given in the literature. The existing classical inequalities can be rectified by imposing the conditions stated in remarks. By imposing certain conditions on and Λ available in the literature, many new forms of fractional integral inequalities can be produced. It is expected that the ideas and techniques of the paper will inspire interested readers.

    In this section, we utilize the weighted integral (1.5) to obtain the refinement of some classical inequalities. Throughout the paper, we let the function be an increasing and positive function on [v1,v2] with a continuous derivative on (v1,v2). To do this, first we prove that the operators defined by (1.5) and (1.6) are bounded.

    Theorem 2.1. Let the functions Λ,:[v1,v2]R, 0<v1<v2, be positive and integrable functions. Let :[v1,v2]R be a positive, increasing function having a continuous derivative on (v1,v2). If Λλ is increasing on [v1,v2], then for λ[v1,v2], we have

    ω1(λ)λv1Λ((λ)(υ))(λ)(υ)ω(υ)(υ)(υ)dυ∣≤ω1(λ)Λ((v2)(v1))||||Xpω

    and

    ω1(λ)v2λΛ((υ)(λ))(υ)(λ)ω(υ)(υ)(υ)dυ∣≤ω1(λ)Λ((v2)(v1))||||Xpω.

    Furthermore, one can get

    ω1(λ)λv1Λ((λ)(υ))(λ)(υ)ω(υ)(υ)(υ)dυ+ω1(λ)v2λΛ((υ)(λ))(υ)(λ)ω(υ)(υ)(υ)dυ2ω1(λ)Λ((v2)(v1))||||Xpω.

    Proof. By the given hypothesis, is increasing, and therefore for υ[v1,λ), λ[v1,v2], (λ)(υ)(λ)(v1). Also, since the function Λλ is increasing, we have

    Λ((λ)(υ))(λ)(υ)Λ((λ)(v1))(λ)(v1). (2.1)

    By the given hypothesis, and ω are positive functions, and is increasing and differentiable. Therefore, from (2.1), it follows that

    Λ((λ)(υ))(λ)(υ)ω(υ)(υ)(υ)Λ((λ)(v1))(λ)(v1)ω(υ)(υ)(υ). (2.2)

    From this, the following inequality can be easily obtained

    ω1(λ)λv1Λ((λ)(υ))(λ)(υ)ω(υ)(υ)(υ)dυ∣≤ω1(λ)Λ((λ)(v1))∣∣Xpω. (2.3)

    Similarly, one can get

    ω1(λ)v2λΛ((υ)(λ))(υ)(λ)ω(υ)(υ)(υ)dυ∣≤ω1(λ)Λ((v2)(v1))∣∣Xpω. (2.4)

    Finally, by adding (2.3) and (2.4), we get the last inequality.

    Theorem 2.2. Suppose that the function is a positive, continuous and decreasing function on [v1,v2]. Let v1<λv2,ϑ1>0, and σγ>0. Then, for generalized integral operator (1.5), we have

    ωIΛv1+[σ(λ)]ωIΛv1+[γ(λ)]ωIΛv1+[(λv1)ϑ1σ(λ)]ωIΛv1+[(λv1)ϑ1γ(λ)]. (2.5)

    Proof. Since is a positive, continuous and decreasing functions on the interval [v1,v2], we have

    ((ρv1)ϑ1(υv1)ϑ1)(σγ(υ)σγ(ρ))0, (2.6)

    where v1<λv2, ϑ1>0, σγ>0, and υ,ρ[v1,λ].

    By (2.6), we have

    (ρv1)ϑ1σγ(υ)+(υv1)ϑ1σγ(ρ)(ρv1)ϑ1σγ(ρ)(υv1)ϑ1σγ(υ)0. (2.7)

    Define a function

    G(λ,υ):=Λ((λ)(υ))(λ)(υ)ω(υ)(υ). (2.8)

    We observe that the function G(λ,υ) remains positive for all υ(v1,λ) and v1<υ<λv2, as each term of the above function is positive in view of the conditions stated in Theorem 2.2. Therefore, multiplying (2.7) by

    G(λ,υ)γ(υ)=Λ((λ)(υ))(λ)(υ)ω(υ)(υ)γ(υ),

    for υ(v1,λ) and v1<λv2, we have

    G(λ,υ)[(ρv1)ϑ1σγ(υ)+(υv1)ϑ1σγ(ρ)(ρv1)ϑ1σγ(ρ)(υv1)ϑ1σγ(υ)]γ(υ)=(ρv1)ϑ1Λ((λ)(υ))(λ)(υ)ω(υ)(υ)γ(υ)σγ(υ)+(υv1)ϑ1Λ((λ)(υ))(λ)(υ)ω(υ)(υ)γ(t)σγ(ρ)(ρv1)ϑ1Λ((λ)(υ))(λ)(υ)ω(υ)(υ)γ(υ)σγ(ρ)(υv1)ϑ1Λ((λ)(υ))(λ)(υ)ω(υ)(υ)γ(υ)σγ(υ)0. (2.9)

    Integrating (2.9) with respect to υ over (v1,λ), we have

    (ρv1)ϑ1λv1Λ((λ)(υ))(λ)(υ)ω(υ)(υ)σ(υ)dυ+σγ(ρ)λv1Λ((λ)(υ))(λ)(υ)ω(υ)(υ)(υv1)ϑ1γ(υ)dυ(ρv1)ϑ1σγ(ρ)λv1Λ((λ)(υ))(λ)(υ)ω(υ)(υ)γ(υ)dυλv1Λ((λ)(υ))(λ)(υ)ω(υ)(υ)(υv1)ϑ1σ(υ)dυ0. (2.10)

    Multiplying (2.10) by 1ω(λ), we get

    (ρv1)ϑ1ωIΛv1+[σ(λ)]+σγ(ρ)ωIΛv1+[(λv1)ϑ1γ(θ)](ρv1)ϑ1σγ(ρ)ωIΛv1+[γ(λ)]ωIΛv1+[(λv1)ϑ1σ(λ)]. (2.11)

    Multiplying (2.11) by

    G(λ,ρ)γ(ρ)=Λ((λ)(ρ))(λ)(ρ)ω(ρ)(ρ)γ(ρ)

    for ρ(v1,λ) and v1<λv2, and integrating the resultant identity with respect to ρ over (v1,λ), we get

    ωIΛv1+[σ(λ)]ωIΛv1+[(λv1)ϑ1γ(λ)]ωIΛv1+[(λv1)ϑ1σ(λ)]ωIΛv1+[γ(λ)]0.

    It follows that

    ωIΛv1+[σ(λ)]ωIΛv1+[(λv1)ϑ1γ(λ)]ωIΛv1+[(λv1)ϑ1σ(λ)]ωIΛv1+[γ(λ)].

    Dividing the above equation by ωIΛv1+[(λv1)ϑ1γ(λ)]ωIΛv1+[γ(λ)], we get the desired inequality (2.5).

    Remark 2.1. If is increasing on [v1,v2], then the inequality in Theorem 2.2 will reverse.

    Remark 2.2. If we take ω(λ)=1, (λ)=λ and Λ((λ))=λζΓ(ζ), then Theorem 2.2 will reduce to Riemann-Liouville fractional integrals.

    Remark 2.3. If we take ω(λ)=1, (λ)=λ, λ=v2 and Λ((λ))=λ, then Theorem 2.2 will reduce to Theorem 3, proved earlier by Liu et al. [8].

    Example 2.1. The special case of Theorem 2.2 is by taking ω(λ)=1, (λ)=λ, Λ((λ))=λ, σ=2, γ=ϑ=1 and (υ)=2υ, which is positive, continuous and decreasing on [0,1], and then we have

    102(υ)dυ10(υ)dυ10υ2(υ)dυ10υ(υ)dυi.e., 4.666>1.375.

    Theorem 2.3. Suppose that the function is a positive, continuous and decreasing function on [v1,v2]. Let v1<λv2,ϑ1>0, and σγ>0. Then, for generalized fractional integral (1.5), we have

    ωIΛv1+[σ(λ)]ωIΦv1+[(λv1)ϑ1γ(λ)]+ωIΦv1+[σ(λ)]ωIΛv1+[(λv1)ϑ1γ(λ)]ωIΛv1+[(λv1)ϑ1σ(λ)]ωIΦv1+[γ(λ)]+ωIΦv1+[(λv1)ϑ1σ(λ)]ωIΛv1+[γ(λ)]1. (2.12)

    Proof. By multiplying both sides of (2.11) by

    G(λ,ρ)γ(ρ)=Φ((λ)(ρ))(λ)(ρ)ω(ρ)(ρ)γ(ρ)

    for ρ(v1,λ) and v1<λv2, and integrating the resultant identity with respect to ρ over (v1,λ), we get

    ωIΛv1+[σ(x)]ωIΦv1+[(λv1)ϑ1γ(λ)]+ωIΦv1+[σ(λ)]ωIΛv1+[(λv1)ϑ1γ(λ)]ωIΛv1+[(λv1)ϑ1σ(λ)]ωIΦv1+[γ(λ)]ωIΦv1+[(λv1)ϑ1σ(λ)]ωIΛv1+[γ(λ)]0.

    It follows that

    ωIΛv1+[σ(x)]ωIΦv1+[(λv1)ϑ1γ(λ)]+ωIΦv1+[σ(λ)]ωIΛv1+[(λv1)ϑ1γ(λ)]ωIΛv1+[(λv1)ϑ1σ(λ)]ωIΦv1+[γ(λ)]+ωIΦv1+[(λv1)ϑ1σ(λ)]ωIΛv1+[γ(λ)]. (2.13)

    Hence, dividing (2.13) by

    ωIΛv1+[(λv1)ϑ1σ(λ)]ωIΦv1+[γ(λ)]+ωIΦv1+[(λv1)ϑ1σ(λ)]ωIΛv1+[γ(λ)]

    completes the proof.

    Remark 2.4. Applying Theorem 2.3 for Λ=Φ, we get Theorem 2.2.

    Theorem 2.4. Suppose that the functions and h1 are positive and continuous on [v1,v2] such that h1 is increasing and is decreasing on the interval [v1,v2]. Let v1<λv2,ϑ1>0, and σγ>0. Then, for generalized fractional integral (1.5), we have

    ωIΛv1+[σ(λ)]ωIΛv1+[hϑ1(λ)γ(λ)]ωIΛv1+[hϑ1(λ)σ(λ)]ωIΛv1+[γ(λ)]1. (2.14)

    Proof. By the hypothesis given in Theorem 2.4, we can write

    (hϑ1(ρ)hϑ1(υ))(σγ(υ)σγ(ρ))0, (2.15)

    where v1<λv2,ϑ1>0,σγ>0, and υ,ρ[v1,λ].

    From (2.15), we have

    hϑ1(ρ)σγ(υ)+hϑ1(υ)σγ(ρ)hϑ1(ρ)σγ(ρ)hϑ1(υ)σγ(υ)0. (2.16)

    Multiplying both sides of (2.16) by

    G(λ,υ)γ(υ)=Λ((λ)(υ))(λ)(υ)ω(υ)(υ)γ(υ)

    for υ(v1,λ) and v1<λv2, we have

    G(λ,υ)γ(υ)[hϑ1(ρ)σγ(υ)+hϑ1(υ)σγ(ρ)hϑ1(ρ)σγ(ρ)hϑ1(υ)σγ(υ)]=hϑ1(ρ)Λ((λ)(υ))(λ)(υ)ω(υ)(υ)σ(υ)+hϑ1(υ)Λ((λ)(υ))(λ)(υ)ω(υ)(υ)σγ(ρ)σ(υ)hϑ1(ρ)Λ((λ)(υ))(λ)(υ)ω(υ)(υ)σγ(ρ)σ(υ)hϑ1(υ)ϑ1Λ((λ)(υ))(λ)(υ)ω(υ)(υ)σ(υ)0. (2.17)

    Integrating (2.17) with respect to υ over (v1,λ), we have

    hϑ1(ρ)xaΛ((λ)(υ))(λ)(υ)ω(υ)(υ)σ(υ)dυ+σγqq(ρ)λv1Λ((λ)(υ))(λ)(υ)ω(υ)(υ)hϑ1(υ)γ(υ)dυhϑ1(ρ)σγ(ρ)λv1Λ((λ)(υ))(λ)(υ)ω(υ)(υ)γ(υ)dυλv1Λ((λ)(υ))(λ)(υ)ω(υ)(υ)hϑ1(υ)σ(υ)dυ0. (2.18)

    Multiplying (2.18) by 1ω(λ) and in view of (1.5), we can write

    hϑ1(ρ)ωIΛv1+[σ(λ)]+σγ(ρ)ωIΛv1+[hϑ1(λ)γ(λ)]hϑ1(ρ)σγ(ρ)ωIΛv1+[γ(λ)]ωIΛv1+[hϑ1(λ)γ(λ)]0. (2.19)

    Again, multiplying (2.19) by

    G(λ,ρ)γ(ρ)=Λ((λ)(ρ))(λ)(ρ)ω(ρ)(ρ)γ(ρ)

    for ρ(v1,λ) and v1<λv2, and integrating the resultant identity with respect to ρ over (v1,λ), we get

    ωIΛv1+[σ(λ)]ωIΛv1+[hϑ1(λ)γ(λ)]ωIΛv1+[hϑ1(λ)σ(λ)]ωIΛv1+[γ(λ)]0.

    This can be written as

    ωIΛv1+[σ(λ)]ωIΛv1+[hϑ1(λ)γ(λ)]geqωIΛv1+[hϑ1(λ)σ(λ)]ωIΛv1+[γ(λ)],

    which completes the desired inequality (2.14) of Theorem 2.4.

    Theorem 2.5. Suppose that the functions and h1 are positive and continuous on [v1,v2] such that h1 is increasing and is decreasing on the interval [v1,v2]. Let v1<xv2,ϑ1>0, and σγ>0. Then, for generalized integral (1.5), we have

    ωIΛv1+[σ(λ)]ωIΦv1+[hϑ1(λ)γ(λ)]+ωIΦv1+[σ(λ)]ωIΛv1+[hϑ1(λ)γ(λ)]ωIΛv1+[hϑ1(λ)σ(λ)]ωIΦv1+[γ(λ)]+ωIΦv1+[hϑ1(λ)σ(λ)]ωIΛv1+[γλ)]1. (2.20)

    Proof. Multiplying (2.19) by

    G(λ,ρ)γ(ρ)=Φ((λ)(ρ))(λ)(ρ)ω(ρ)(ρ)γ(ρ)

    for ρ(v1,λ) and v1<λv2, and integrating the resultant identity with respect to ρ over (v1,λ), we get

    ωIΛv1+[σ(λ)]ωIΦv1+[hϑ1(λ)γ(λ)]+ωIΦv1+[σ(λ)]ωIΛv1+[hϑ1(λ)γ(λ)]ωIΛv1+[hϑ1(λ)σ(λ)]ωIΦv1+[γ(λ)]ωIΦv1+[hϑ1(λ)σ(λ)]ωIΛv1+[γ(λ)]0.

    It follows that

    ωIΛv1+[σ(λ)]ωIΦv1+[hϑ1(λ)γ(λ)]+ωIΦv1+[σ(λ)]ωIΛv1+[hϑ1(λ)γ(λ)]ωIΛv1+[hϑ1(λ)σ(λ)]ωIΦv1+[γ(λ)]+ωIΦv1+[hϑ1(λ)σ(λ)]ωIΛv1+[γ(λ)].

    Dividing both sides by

    ωIΛv1+[hϑ1(λ)σ(λ)]ωIΦv1+[γ(λ)]+ωIΦv1+[hϑ1(λ)σ(λ)]ωIΛv1+[γ(λ)]

    gives the desired inequality (2.20).

    Remark 2.5. Taking Λ=Φ in Theorem 2.5, we get Theorem 2.4.

    In this section, we utilize the left unified integral operator (1.5) to establish some inequalities for a class of decreasing positive functions.

    Theorem 3.1. Suppose that the functions (l)l=1,2,3,,n be n positive, continuous and decreasing functions on [v1,v2]. Let v1<λv2,ϑ1>0, and σγq>0 for any fixed q{1,2,3,,n}. Then, for generalized fractional integral operator (1.5), we have

    ωIΛv1+[nlqγllσq(λ)]ωIΛv1+[nl=1γll(λ)]ωIΛv1+[(λv1)ϑ1nlqγllσq(λ)]ωIΛv1+[(λv1)ϑ1nl=1γll(λ)]. (3.1)

    Proof. Since (l)l=1,2,3,,n are n positive, continuous and decreasing functions on the interval [v1,v2], we have

    ((ρv1)ϑ1(υv1)ϑ1)(σγqq(υ)σγqq(ρ))0 (3.2)

    for any fixed q{1,2,3,,n},v1<λv2,ϑ1>0,σγq>0 and υ,ρ[v1,λ]. By (3.2), we have

    (ρv1)ϑ1σγqq(υ)+(υv1)ϑ1σγqq(ρ)(ρv1)ϑ1σγqq(ρ)+(υv1)ϑ1σγqq(υ). (3.3)

    Multiplying both sides of (3.3) by

    G(λ,υ)nl=1γll(υ)=Λ((λ)(υ))(λ)(υ)ω(υ)(υ)nl=1γll(t)

    for ρ(v1,λ) and v1<λv2, we have

    G(λ,υ)[(ρv1)ϑ1σγ(υ)+(υa)ϑ1σγ(ρ)(ρv1)ϑ1σγ(ρ)(υv1)ϑ1σγ(υ)]nl=1γll(υ)=(ρv1)ϑ1Λ((λ)(υ))(λ)(υ)ω(υ)(υ)nl=1γll(t)σγqq(υ)+(υv1)ϑ1Λ((λ)(υ))(λ)(υ)ω(υ)(υ)nl=1γll(υ)σγqq(ρ)(ρv1)ϑ1Λ((λ)(υ))(λ)(υ)ω(υ)(υ)nl=1γll(υ)σγqq(ρ)+(υv1)ϑ1Λ((λ)(υ))(λ)(υ)ω(υ)(υ)nl=1γll(υ)σγqq(υ). (3.4)

    Integrating (3.4) with respect to υ over (v1,λ), we have

    (ρv1)ϑ1λv1Λ((λ)(υ))(λ)(υ)ω(υ)(υ)nl=1γll(t)σγqq(υ)dυ+σγqq(ρ)λv1Λ((λ)(υ))(λ)(υ)ω(υ)(υ)nl=1γll(υ)dυ(ρv1)ϑ1σγqq(ρ)λv1Λ((λ)(υ))(λ)(υ)ω(υ)(υ)nl=1γll(υ)dυ+λv1Λ((λ)(υ))(λ)(υ)ω(υ)(υ)(υv1)ϑ1nl=1γll(υ)σγqq(υ)dυ.

    In view of (1.5), it follows that

    (ρv1)ϑ1ωIΛv1+[nlqγllσq(λ)]+σγqq(ρ)ωIΛv1+[(λv1)ϑ1nl=1γll(λ)](ρv1)ϑ1σγqq(ρ)ωIΛv1+[nl=1γll(λ)]ωIΛv1+[(λv1)ϑ1nlqγllσq(λ)]. (3.5)

    Again, multiplying both sides of (3.5) by

    G(λ,ρ)nl=1γll(ρ)=Λ((λ)(ρ))(λ)(ρ)ω(ρ)(ρ)nl=1γll(ρ)

    for ρ(v1,λ) and v1<λv2, and integrating the resultant identity with respect to ρ over (v1,λ), we get

    ωIΛv1+[nlqγllσq(λ)]ωIΛv1+[(λv1)ϑ1nl=1γll(λ)]ωIΛv1+[(λv1)ϑ1nlqγllσq(λ)]ωIΛv1+[nl=1γll(λ)],

    which gives the required inequality (3.1).

    Remark 3.1. If we consider that (l)l=1,2,3,,n are increasing functions on [v1,v2], then the inequality in Theorem 3.1 will reverse.

    Remark 3.2. If we take ω(λ)=1, (λ)=λ and Λ((λ))=λζΓ(ζ), then Theorem 3.1 will reduce to the result proved by Dahmani [17].

    Remark 3.3. If we take ω(λ)=1, (λ)=λ, λ=v2, n=1 and Λ((λ))=λ, then Theorem 3.1 will reduce to Theorem 3, proved earlier by Liu et al. [8].

    Theorem 3.2. Suppose that the functions (l)l=1,2,3,,n are n positive, continuous and decreasing functions on [v1,v2]. Let v1<λv2,ϑ1>0, and σγq>0 for any fixed q{1,2,3,,n}. Then, for generalized fractional integral (1.5), we have

    ωIΛv1+[nlqγllσq(λ)]ωIΦv1+[(λv1)ϑ1nl=1γll(λ)]+ωIΦv1+[nlqγllσq(λ)]ωIΛv1+[(λv1)ϑ1nl=1γll(λ)]ωIΛv1+[(λv1)ϑ1nlqγllσq(λ)]ωIΦv1+[nl=1γll(λ)]+ωIΦv1+[(λv1)ϑ1nlqγllσq(λ)]ωIΛv1+[nl=1γll(λ)]1. (3.6)

    Proof. Multiplying both sides of (3.5) by

    G(λ,ρ)nl=1γll(ρ)=Φ((λ)(ρ))(λ)(ρ)ω(ρ)(ρ)nl=1γll(ρ)

    for ρ(v1,λ) and v1<λv2, and integrating the resultant identity with respect to ρ over (v1,λ), we get

    ωIΛv1+[nlqγllσq(λ)]ωIΦv1+[(λv1)ϑ1nl=1γll(λ)]+ωIΦv1+[nlqγllσq(λ)]ωIΛv1+[(λv1)ϑ1nl=1γll(λ)]ωIΛv1+[(λv1)ϑ1nlqγllσq(λ)]ωIΦv1+[nl=1γll(λ)]+ωIΦv1+[(λv1)ϑ1nlqγllσq(λ)]ωIΛv1+[nl=1γll(λ)]. (3.7)

    It follows that

    ωIΛv1+[nlqγllσq(λ)]ωIΦv1+[(λv1)ϑ1nl=1γll(λ)]+ωIΦv1+[nlqγllσq(λ)]ωIΛv1+[(λv1)ϑ1nl=1γll(λ)]ωIΛv1+[(λv1)ϑ1nlqγllσq(λ)]ωIΦv1+[nl=1γll(λ)]+ωIΦv1+[(λv1)ϑ1nlqγllσq(λ)]ωIΛv1+[nl=1γll(λ)]. (3.8)

    Hence, dividing (3.8) by

    ωIΛv1+[(λv1)ϑ1nlqγllσq(λ)]ωIΦv1+[nl=1γll(λ)]+ωIΦv1+[(λv1)ϑ1nlqγllσq(λ)]ωIΛv1+[nl=1γll(λ)]

    completes the proof.

    Remark 3.4. Applying Theorem 3.2 for Λ=Φ, we get Theorem 3.1.

    Theorem 3.3. Suppose that the functions (l)l=1,2,3,,n and h1 are positive and continuous on [v1,v2] such that h1 is increasing and (l)l=1,2,3,,n are decreasing on [v1,v2]. Let v1<λv2,ϑ1>0, and σγq>0 for any fixed q{1,2,3,,n}. Then, for generalized fractional integral (1.5), we have

    ωIΛv1+[nlqγllσq(λ)]ωIΛv1+[hϑ1(λ)nl=1γll(λ)]ωIΛv1+[hϑ1(λ)nlqγllσq(λ)]ωIΛv1+[nl=1γll(λ)]1. (3.9)

    Proof. Under the hypothesis given in Theorem 3.3, we can write

    (hϑ1(ρ)hϑ1(υ))(σγqq(υ)σγqq(ρ))0 (3.10)

    for any fixed q{1,2,3,,n},v1<λv2,ϑ1>0,σγq>0 and υ,ρ[v1,λ].

    From (3.10), we can write

    hϑ1(ρ)σγqq(υ)+hϑ1(υ)σγqq(ρ)hϑ1(ρ)σγqq(ρ)hϑ1(υ)σγqq(υ)0. (3.11)

    Multiplying (3.11) by

    G(λ,υ)nl=1γll(υ)=Λ((λ)(υ))(λ)(υ)ω(υ)(υ)nl=1γll(υ)

    for υ(v1,λ) and v1<λv2, we have

    hϑ1(ρ)Λ((λ)(υ))(λ)(υ)ω(υ)(υ)nl=1γll(υ)σγqq(υ)+hϑ1(υ)Λ((λ)(υ))(λ)(υ)ω(υ)(υ)nl=1γll(υ)σγqq(ρ)hϑ1(ρ)Λ((λ)(υ))(λ)(υ)ω(υ)(υ)nl=1γll(υ)σγqq(ρ)hϑ1(υ)ϑ1Λ((λ)(υ))(λ)(υ)ω(υ)(υ)nl=1γll(υ)σγqq(υ)0. (3.12)

    Integrating (3.12) with respect to υ over (v1,λ), we have

    hϑ1(ρ)λv1Λ((λ)(υ))(λ)(υ)ω(υ)(υ)nl=1γll(υ)σγqq(υ)dυ+σγqq(ρ)λv1Λ((λ)(υ))(λ)(υ)ω(υ)(υ)hϑ1(υ)ϑ1nl=1γll(υ)dυhϑ1(ρ)σγqq(ρ)λv1Λ((λ)(υ))(λ)(υ)ω(υ)(υ)nl=1γll(υ)dυλv1hϑ1(υ)nl=1γll(υ)σγqq(υ)dυ0. (3.13)

    In view of (1.5), we can write from (3.13)

    hϑ1(ρ)ωIΛv1+[nlqγllσq(λ)]+σγqq(ρ)ωIΛv1+[hϑ1(λ)nl=1γll(λ)]hϑ1(ρ)σγqq(ρ)ωIΛv1+[nl=1γll(λ)]ωIΛv1+[hϑ1(λ)nlqγllσq(λ)]0. (3.14)

    Again, multiplying (3.14) by

    G(λ,ρ)nl=1γll(ρ)=Λ((λ)(υ))(λ)(υ)ω(υ)(υ)nl=1γll(ρ)

    for ρ(v1,λ) and v1<λv2, and integrating the resultant identity with respect to ρ over (a,x), we get

    ωIΛv1+[nlqγllσq(λ)]ωIΛv1+[hϑ1(λ)nl=1γll(λ)]ωIΛv1+[hϑ1(λ)nlqγllσq(λ)]ωIΛv1+[nl=1γll(λ)]0,

    which gives the required inequality (3.9).

    Theorem 3.4. Suppose that the functions (l)l=1,2,3,,n and h1 are positive and continuous on [v1,v2] such that h1 is increasing and (l)l=1,2,3,,n are decreasing on the interval [v1,v2]. Let v1<λv2,ϑ1>0, and σγq>0 for any fixed q{1,2,3,,n}. Then, for generalized fractional integral (1.5), we have

    ωIΛv1+[nlqγllσq(λ)]ωIΦv1+[hϑ1(λ)nl=1γll(λ)]+ωIΦv1+[nlqγllσq(λ)]ωIΛv1+[hϑ1(λ)nl=1γll(λ)]ωIΛv1+[hϑ1(λ)nlqγllσq(λ)]ωIΦv1+[nl=1γll(λ)]+ωIΦv1+[hϑ1(λ)nlqγllσq(λ)]ωIΛv1+[nl=1γll(λ)]1. (3.15)

    Proof. Multiplying (3.14) by

    G(λ,ρ)nl=1γll(ρ)=Φ((λ)(ρ))(λ)(ρ)ω(ρ)(ρ)nl=1γll(ρ)

    for ρ(v1,λ) and v1<λv2, and integrating the resultant identity with respect to ρ over (v1,λ), we get

    ωIΛv1+[nlqγllσq(λ)]ωIΦv1+[hϑ1(λ)nl=1γll(λ)]+ωIΦv1+[nlqγllσq(λ)]ωIΛv1+[hϑ1(λ)nl=1γll(λ)]ωIΛv1+[hϑ1(λ)nlqγllσq(λ)]ωIΦv1+[nl=1γll(λ)]ωIΦv1+[hϑ1(λ)nlqγllσq(λ)]ωIΛv1+[nl=1γll(λ)]0.

    This can be written as

    ωIΛv1+[nlqγllσq(λ)]ωIΦv1+[hϑ1(λ)nl=1γll(λ)]+ωIΦv1+[nlqγllσq(λ)]ωIΛv1+[hϑ1(λ)nl=1γll(λ)]ωIΛv1+[hϑ1(λ)nlqγllσq(λ)]ωIΦv1+[nl=1γll(λ)]+ωIΦv1+[hϑ1(λ)nlqγllσq(λ)]ωIΛv1+[nl=1γll(λ)].

    Dividing both sides by

    ωIΛv1+[hϑ1(λ)nlqγllσq(λ)]ωIΦv1+[nl=1γll(λ)]+ωIΦv1+[hϑ1(λ)nlqγllσq(λ)]ωIΛv1+[nl=1γll(λ)]

    gives the desired inequality (3.15).

    Remark 3.5. Applying Theorem 3.4 for Λ=Φ, we get Theorem 3.3. Similarly, we can establish the inequalities for the right generalized proportional fractional integral defined by (1.6).

    By using our main results, we get the following certain new and well-known inequalities in terms of well-known fractional integral operators:

    Corollary 4.1. Suppose that the function is a positive, continuous and decreasing function on [v1,v2]. Let v1<λv2,ϑ1>0, and σγ>0. Then, for generalized integral operator (1.7) (see, for example, [27]), we have

    IΛv1+[σ(λ)]IΛv1+[γ(λ)]IΛv1+[(λv1)ϑ1σ(λ)]IΛv1+[(λv1)ϑ1γ(λ)].

    Proof. Taking ω=1, (λ)=λ and Λ((λ))=λ in Theorem 2.2, we get the desired result.

    Corollary 4.2. Suppose that the functions (l)l=1,2,3,,n are n positive, continuous and decreasing on [v1,v2]. Let v1<λv2,ϑ1>0, and σγq>0 for any fixed q{1,2,3,,n}. Then, for generalized fractional integral operator (1.7), we have

    IΛv1+[nlqγllσq(λ)]IΛv1+[nl=1γll(λ)]IΛv1+[(λv1)ϑ1nlqγllσq(λ)]IΛv1+[(λv1)ϑ1nl=1γll(λ)].

    Proof. Taking ω=1, (λ)=λ and Λ((λ))=λ in Theorem 3.1, one can get the desired result.

    Similarly, by taking ω=1 in Theorems 2.2 and 3.1, one can get results for the fractional integral defined by Farid [26] as follows:

    Corollary 4.3. Suppose that the function is a positive, continuous and decreasing function on [v1,v2]. Let v1<λv2,ϑ1>0, and σγ>0. Then, for generalized integral operator (1.19), we have

    IΛv1+[σ(λ)]IΛv1+[γ(λ)]IΛv1+[(λv1)ϑ1σ(λ)]IΛv1+[(λv1)ϑ1γ(λ)].

    Corollary 4.4. Suppose that the functions (l)l=1,2,3,,n are n positive, continuous and decreasing on [v1,v2]. Let v1<λv2,ϑ1>0, and σγq>0 for any fixed q{1,2,3,,n}. Then, for generalized fractional integral operator (1.19), we have

    IΛv1+[nlqγllσq(λ)]IΛv1+[nl=1γll(λ)]IΛv1+[(λv1)ϑ1nlqγllσq(λ)]IΛv1+[(λv1)ϑ1nl=1γll(λ)],

    where is a differentiable, increasing and continuous function on [v1,v2].

    In this present investigation, we generalized many classical inequalities discussed in the literature via unified fractional integrals and proved that the operators defined in (1.5) and (1.6) are bounded. We developed certain new classes of unified fractional integral inequalities for a class of n (nN) positive, continuous and decreasing functions on [v1,v2]. Certain special cases of the main result are discussed in Section 4. By applying specific conditions on and Λ as given in the literature, we can produce certain new classes of inequalities as discussed in Remark 1.1. We hope that our ideas and techniques of this paper will inspire interested readers working in this field.

    This research has received funding support from the National Science, Research and Innovation Fund (NSRF), Thailand.

    The authors declare no conflict of interest.



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