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The properties of generalized John domains in metric spaces

  • In this paper, we studied the properties of generalized John domains in metric space. We prove that a domain D is a φ-John domain if, and only if, DP is a φ-John domain, where P is a subset of D containing finitely many points of D. Meanwhile, we also showed that the union of φ-John domains is a φ-John domain in metric space.

    Citation: Hongjun Liu, Fang Yan, Ling Xia. The properties of generalized John domains in metric spaces[J]. AIMS Mathematics, 2024, 9(6): 15875-15890. doi: 10.3934/math.2024767

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  • In this paper, we studied the properties of generalized John domains in metric space. We prove that a domain D is a φ-John domain if, and only if, DP is a φ-John domain, where P is a subset of D containing finitely many points of D. Meanwhile, we also showed that the union of φ-John domains is a φ-John domain in metric space.



    John [17] and Martio and Sarvas [24] were the first who introduced and studied John domains and uniform domains, respectively. Now, there are plenty of alternative characterizations for uniform and John domains; see [5,6,20,23,28,29,30,31,32]. Additionally, its importance along with some special domains throughout the function theory is well documented; see [5,7,13,15,20,25,26,35,36,37]. Moreover, John domains and uniform domains in Rn enjoy with numerous geometric and function theoretic features in many areas of modern mathematical analysis, see [1,2,3,6,18,19,21,22,31,34]. As in [10], Guo and Koskela have introduced the class of φ-John domains, which form a natural generalization of John domains. The motivation for this paper stems from the discussions in [16,33], where the effect of the removal of a finite set of points and union of generalized John domain was examined. The main result of this paper shows that D is a φ-John domain if, and only if, DP is a φ-John domain, where P is a subset of D containing finitely many points of D, φ and φ depend on each other, and, finally, we prove that the union of φ-John domains is φ-John domain.

    Throughout the paper, unless otherwise stated, we always assume that D is a proper subdomain of the metric space X and B(x,r)={yX:|xy|<r} denotes the metric ball at x of radius r. For a set D in X, we use ¯D to denote the metric completion of D, and we let D=¯DD be its metric boundary. We write

    A(x;r,R)={y:r|xy|R}

    for the closed annular ring center at x with inner and outer radii r and R, respectively.

    From now on, for notational convenience, we use notation |xy| to indicate the distance between x and y in any metric space X.

    Definition 1.1. A domain (open and connected) D in X is said to be a C-uniform domain if there exists a constant C1 with the property that each pair of points z1,z2 in D can be joined by a rectifiable arc γ in D satisfying

    (1) (Double cone condition) min{l(γ[z1,z]),l(γ[z2,z])}CδD(z) for all zγ, and

    (2) (Quasiconvex condition) l(γ)C|z1z2|,

    where l(γ) denotes the arc-length of γ, γ[zi,z] is the subcurve of γ between zi and z, and δD(z) denotes the distance dist(z,D). At this time, γ is said to be a double C-uniform curve.

    If the condition (1) is satisfied, not necessarily (2), then D is said to be a C-John domain and the arc γ is called a C-John curve.

    The classes of John domains and of uniform domains in Euclidean space enjoy an important role in many areas of modern mathematical analysis; see [14,24,27]. Inspired by the study on generalized quasidisks [12], Guo and Koskela [11] generalized the definition of John domain as follows.

    Definition 1.2. Let DX be a bounded domain, let φ:[0,)[0,) be a continuous, increasing function with φ(0)=0 and φ(t)t for all t>0, and let C1 be a constant, z0D. We say that D is φ-John domain, if for any zD, there exists a rectifiable curve γ:zz0, such that

    l(γ[z,u])φ(CδD(u)),

    for all uγ. The concept of φ-dist and φ-diam John domains are defined analogously. A corresponding curve is called a φ- length(dist, diam) John curve.

    The notion of φ-John domains allows us to formulate a second definition of φ-John domains, and the next definition and Definition 1.2 are equivalent; please see [8].

    Definition 1.3. Let DX be a bounded domain. We say that D is φ-John domain if there exist constant C1 and function φ with the property that each pair of points z1,z2 in D can be joined by a rectifiable arc γ in D satisfying

    min{l(γ[z1,u]),(γ[u,z2])}φ(CδD(u)),

    for all uγ. Here, φ is a continuous, increasing function with φ(0)=0 and φ(t)t for all t>0.

    We remark that, in general, the generalized John domain means the φ-John domain. Obviously, the φ-John domain is a generalization of the C-John domain since the C-John domain coincides with the φ-John domain with φ(Ct)=Ct. In this paper, we always simplify C-John domain by John domain and φ-John domain by generalized John domain.

    In [16], Huang et. al. showed that a domain D in Rn is a John domain if, and only if, DP is a John domain, where P is a subset of D containing finitely many points of D.

    Theorem 1.4. (See [16], Theorem 1.4) A domain DRn (n2) is a John domain if, and only if, G=DP is also a John domain, where P={p1,p2,,pm} and piD (i=1,2,,m).

    To state our results, we introduce the following definition.

    Definition 1.5. Let c1. Let X be a rectifiable connected and locally compact metric space, and DX. Then, D is called

    (1) c-quasiconvex, if for any x,yD there is a curve γ joining x and y in D satisfying l(γ)c|xy|. We also call this γ a c-quasiconvex curve;

    (2) c-annular quasiconvex, if for every xD and for all r>0, each pair of points y,zA(x;r,2r)D can be joined with a curve γ in A(x;r/c,2cr)D such that l(γ)c|yz|.

    Remark 1.6. It was proved by Buckley et al. in [4] that if X is connected and c-annular quasiconvex at some point ωX, then X is 9c-quasiconvex. Therefore, the annular quasiconvexity implies quasiconvexity.

    Our first purpose is to show that a domain D in metric space X is a φ-John domain if and only if DP is a φ-John domain, where P is a subset of D containing finitely many points of D. Our proof is based on a refinement of the method of Huang et. al. [16]. We obtain a general result as follows.

    Theorem 1.7. Suppose that X is a rectifiably connected and locally compact metric space, and that domain DX is a c-annular quasiconvex. Then, the following are quantitatively equivalent:

    (1) D is a φ-John domain;

    (2) G=DP is a φ-John domain, where P={p1,p2,,pm} and piD (i=1,2,,m).

    Here, φ and φ depend on each other and c.

    In [33], Väisälä studied the union of John domains in Euclidean spaces, and showed that the union of John domains also is a John domain. In [8], Guan proved that the union of John domains also is a John domain in Banach spaces. Under affable geometric conditions, we obtain a general result as follows.

    Theorem 1.8. Let X be a metric space, and let D1,D2X be two c-quasiconvex domains, where c1. Suppose that D1 and D2 are two φ-John domains in X, and that z0D1D2 and r>0 with

    B(z0,r)D1D2andmin{diam(D1),diam(D2)}c0r,

    where c01 and diam(Di) is the diameter of Di, i=1,2. Then, D1D2 is a φ-John domain with φ depending only on c, c0 and φ. Note that the function φ is a continuous, increasing function with φ(0)=0 and φ(t)t for all t>0.

    The rest of this paper is organized as follows. In Section 2, we show that D is a generalized John domain if, and only if, DP is a generalized John domain, where P is a subset of D containing finitely many points of D. The goal of Section 3 is to show that the union of generalized John domains is a generalized John domain.

    In this section, we always assume that X is a rectifiably connected and locally compact metric space, and that domain DX is a c-annular quasiconvex. Furthermore, we suppose that P={p1,p2,,pm} and piD (i=1,2,,m).

    In what follows, we continue to investigate the decomposition properties of generalized John domain in metric space. The following results play a key role in the proof of Theorem 1.7. Based on [10] and [16], we will prove the following results.

    Lemma 2.1. Under the assumptions of Theorem 1.7. If D is a φ-John domain, then G=DP is also a φ1-John domain with φ1 depending only on φ.

    Proof. By assumption, we show that G=DP is also a φ1-John domain with φ1 depending only on φ. Without loss of generality, in order to prove Lemma 2.1, we need only to consider the case P={p1}. For convenience, we let

    r=12δD(p1)andBr=B(p1,r).

    For any points z1,z2G=D{p1}. Now, we divide the discussions into three cases:

    Case 1. z1,z2DBr.

    Since D is a φ-John domain, then there exist constant C1 and function φ with the property that each pair of points z1,z2 in D can be joined by a rectifiable arc γ in D satisfying

    min{l(γ[z1,z]),(γ[z,z2])}φ(CδD(z)) (2.1)

    for all zγ.

    We now consider two subcases:

    Subcase 1.1. γDBr.

    If γDBr, then we take β=γ, and it is clear that βG.

    To prove this subcase, we have the following claim.

    Claim 1. Let z be any point in βDBr, and we have

    δD(z)3δG(z).

    Since β=γ and βDBrG, for any zβ, we get

    |zp1|>r.

    If δD(z)|zp1|, by using the definitions of δD(z) and δG(z), we have

    δD(z)=δG(z). (2.2)

    If δD(z)>|zp1|, it follows that

    δD(z)>δG(z)=|zp1|.

    According to the triangle inequality and |zp1|>r, we deduce that

    δD(z)|zp1|+δD(p1)=δG(z)+2r3δG(z). (2.3)

    So, from (2.2) and (2.3), Claim 1 is obtained.

    Since D is a φ-John domain, and β=γDBrG, for any zβ, from the conclusion of Claim 1 and (2.1), it follows that

    min{l(β[z1,z]),l(β[z2,z])}φ(3CδG(z)).

    Subcase 1.2. γBr.

    We let z1 be the first intersection point of γ from z1 to z2, with Br and z2 as the last intersection point of γ from z1 to z2 with Br. Let Ur be the disk determined by z1, z2 and p1 in ¯Br with center p1 and radius r. Then, z1, z2 divide Ur into subarcs, and we denote the subarc with shorter arclength by α (if they have the same arclength, then we choose one of them to be α), that is,

    l(α)πr. (2.4)

    Set

    β=γ[z1,z1]αγ[z2,z2].

    Claim 2. l(α)π2|z1z2|.

    In disk Ur, according to the chord arc formula and the properties of trigonometric function, it follows that

    π22rsinθ2θrand2rsinθ2=|z1z2|. (2.5)

    where θ[0,π] is the center angle of two points z1 and z2. According to (2.5) and l(α)=θr, we get that

    π2|z1z2|l(α). (2.6)

    Therefore, the proof of the Claim 2 is now complete.

    By the definition of z1, z2 and disk Ur, we have

    l(γ[z1,z2])|z1z2|. (2.7)

    Together with (2.6) and (2.7), it follows that

    l(α)π2l(γ[z1,z2]).

    If zγ[z1,z1] or zγ[z2,z2], by symmetry, we only prove zγ[z1,z1]; the proof of zγ[z2,z2] uses the same argument for zγ[z1,z1].

    For any zγ[z1,z1]DBr. It follows immediately from Claim 1 that δD(z)3δG(z).

    Hence, together with Claim 2 and δD(z)3δG(z), it follows that

    min{l(β[z1,z]),l(β[z2,z])}π2min{l(γ[z1,z]),l(γ[z2,z])}π2φ(CδD(z))π2φ(3CδG(z)).

    If zαUr, then we have

    δG(z)=randδG(z2)δD(p1)+r=3r. (2.8)

    According to the inequality (2.4) and (2.8), it follows immediately from the definition of the φ-John domain that

    min{l(β[z1,z]),l(β[z2,z])}l(α)+min{l(γ[z1,z1]),l(γ[z2,z2])}πr+min{l(γ[z1,z2]),l(γ[z2,z2])}πr+φ(CδD(z2))πδG(z)+φ(3CδG(z))φ(πδG(z))+φ(3CδG(z))2φ(4CδG(z)),

    where C1 is a constant.

    Case 2. z1,z2¯Br{p1}.

    Let z1 be the intersection point of the ray starting from p1 and passing through z1 with Br, and let z2 be the intersection point of the ray starting from p1 and passing through z2 with Br, then we have

    |z1z1|rand|z2z2|r. (2.9)

    We use Ur to denote the disk determined by z1, z2 and p1 in ¯Br with center p1 and radius r. Then, z1 and z2 divide Ur into two subarcs. Let α denote the subarc with the shorter arclength (if they have the same arclength, then we choose one of them to be α). We set

    β=[z1,z1]α[z2,z2],

    where [zi,zi] denotes the line segments in metric space of zi and zi, i=1,2.

    If zαUr, it is clear that

    δG(z)=|zp1|=r. (2.10)

    Together with (2.9) and (2.10), it follows that

    min{l(β[z1,z]),l(β[z2,z])}l(α)+min{|z1z1|,|z2z2|}πr+r=(π+1)δG(z)φ((π+1)δG(z)). (2.11)

    If z[z1,z1] or z[z2,z2], by symmetry, it is sufficient to show that z[z1,z1]. For any z[z1,z1], we have the desired estimate

    min{l(β[z1,z]),l(β[z2,z])}|z1z|δG(z)φ(δG(z)). (2.12)

    Hence, by combing (2.11) with (2.12), for any zβ, we deduce that

    min{l(β[z1,z]),l(β[z2,z])}φ((π+1)δG(z)).

    Case 3. z1D¯Brandz2Br{p1}.

    Since D is a φ-John domain, there must exist a curve γ joining z1 and z2 such that

    min{l(γ[z1,z]),l(γ[z2,z])}φ(CδD(z))

    for all zγ.

    Let z1 to be the first intersection point of γ from z1 to z2 with Br, and let z2 be the intersection point of the ray starting from p1 and passing through z2 with Br. We use Ur to denote the disk determined by z1, z2 and p1 in ¯Br with center p1 and radius r. Then, z1 and z2 divide Ur into two subarcs. Let α denote the subarc with the shorter arclength (if they have the same arclength, then we choose one of them to be α). Then, according to the description above, we have

    l(α)πrand|z2z2|r. (2.13)

    Set

    β=γ[z1,z1]α[z2,z2],

    where [z2,z2] represents a straight line segment joining z2 to z2.

    We now consider three subcases:

    Subcase 3.1. zαUr.

    Using a similar argument as in Case 2, we have δG(z)=r. According to (2.13), from the definition of φ-John domain, we get that

    min{l(β[z1,z]),l(β[z2,z])}l(α)+min{l(γ[z1,z1]),|z2z2|}πr+|z2z2|πr+r=(π+1)δG(z)φ((π+1)δG(z)).

    Subcase 3.2. z[z2,z2].

    From the definition of z2, it follows from z[z2,z2] that

    min{l(β[z1,z]),l(β[z2,z])}|z2z|δG(z)φ(δG(z)).

    Subcase 3.3. zγ[z1,z1].

    If l(γ[z1,z])l(γ[z2,z]). Since D is a φ-John domain, by using the conclusion of Claim 1, it follows that

    min{l(β[z1,z]),l(β[z2,z])}l(γ[z1,z])φ(CδD(z))φ(3CδG(z)).

    If l(γ[z1,z])>l(γ[z2,z]), by the conclusion of Subcase 3.1, we deduce that

    l(β[z2,z1])=l(α)+|z2z2|(π+1)r. (2.14)

    Now, for any zγ[z1,z1] with l(γ[z1,z])<r/2, then we have

    δG(z)δD(z1)|z1z|δD(z1)l(γ[z1,z])rr2=r2. (2.15)

    Together with (2.14) and (2.15), it follows that

    min{l(β[z1,z]),l(β[z2,z])}=l(β[z2,z1])+l(γ[z1,z])(π+32)r(2π+3)δG(z)φ((2π+3)δG(z)).

    If l(γ[z1,z])r/2, for any zγ[z1,z1]D¯Br, by Claim 1, we know that δD(z)3δG(z). According to inequality (2.14) and the definition of the φ-John domain, we get

    min{l(β[z1,z]),l(β[z2,z])}=l(β[z2,z1])+l(γ[z1,z])(π+1)r+l(γ[z1,z])(2π+3)l(γ[z1,z])(2π+3)φ(3CδG(z)).

    Therefore, as discussed above, it follows that G=DP is a φ1-John domain. Here,

    φ1(C1t)=max{2φ(4Ct),φ((2π+3)t),(2π+3)φ(3Ct)}.

    Hence, this completes the proof of Lemma 2.1.

    Lemma 2.2. Under the assumptions of Theorem 1.7. If G=DP is a φ-John domain, then D is also a φ2-John domain, where φ2 depends only on φ and c.

    Proof. We always assume that DX is a c-annular quasiconvex, and that G=DP is a domain, where

    P={p1,p2,,pm}andpiD(i=1,2,,m).

    Let φ be a continuous, increasing function with φ(0)=0 and φ(t)t for all t>0. For any pair of points z1,z2D, we divide the discussions into three cases:

    Case 1. z1,z2G.

    According to the assumptions of Theorem 1.7, we know that G=DP is a φ-John domain, that is, there is a rectifiable curve γG connecting z1 and z2 such that

    min{l(γ[z1,z]),l(γ[z2,z])}φ(CδG(z))

    for all zγ, where C1 is a constant. Since G=DPD, we have

    δG(z)δD(z).

    According to φ being a continuous, increasing function, it follows that

    min{l(γ[z1,z]),l(γ[z2,z])}φ(CδD(z)) (2.16)

    for all zγ.

    Case 2. z1,z2DG.

    Let z1,z2P=DG, and P={p1,p2,,pm}, piD (i=1,2,,m). Set

    min{δD(z1),δD(z2)}=12crands=min{|pipj|:ij}.

    We choose

    z1B(z1,τ)Gandz2B(z2,τ)G,

    where

    τ=min{r,s12c}.

    According to the definition of the φ-John domain, there must exist a curve γG joining z1 with z2 such that

    min{l(γ[z1,z]),l(γ[z2,z])}φ(CδG(z)).

    for all zγ.

    Since DX is a c-annular quasiconvex, by Remark 1, we have the D is 9c-quasiconvex, that is, there exists a rectifiable curve γ1 in D joining z1 to z1 with l(γ1)9c|z1z1|, and there exists a rectifiable curve γ2 in D joining z2 to z2 with l(γ2)9c|z2z2|, where c1. Hence, we have

    max{l(γ1),l(γ2)}9cτ9cr.

    Let

    β=γ1γγ2.

    For any zβ, if zγ1 or zγ2, by symmetry, we assume that zγ1. From the definition of quasiconvexity, it follows that

    min{l(β[z1,z]),l(β[z2,z])}l(β[z1,z])=l(γ1[z1,z])9c|z1z|9c12c1δD(z)φ(9c12c1δD(z))<φ(δD(z)). (2.17)

    If zγ and min{l(γ[z1,z]),l(γ[z2,z])}cr, we deduce that

    δD(z)min{δD(z1),δD(z2)}min{l(β[z1,z]),l(β[z2,z])}=12crmin{l(β[z1,z]),l(β[z2,z])}=12cr(min{l(γ1)+l(γ[z1,z]),l(γ2)+l(γ[z2,z])})12cr(9cr+min{l(γ[z1,z]),l(γ[z2,z])})2cr. (2.18)

    Hence, by inequality (2.18) and the definition of function φ, it is clear that

    min{l(β[z1,z]),l(β[z2,z])}=min{l(γ1)+l(γ[z1,z]),l(γ2)+l(γ[z2,z])}9cr+min{l(γ[z1,z]),l(γ[z2,z])}10cr5δD(z)φ(5δD(z)). (2.19)

    If zγ and min{l(γ[z1,z]),l(γ[z2,z])}>cr, it follows from the definition of the φ-John domain that

    min{l(β[z1,z]),l(β[z2,z])}=min{l(γ1)+l(γ[z1,z]),l(γ2)+l(γ[z2,z])}9cr+min{l(γ[z1,z]),l(γ[z2,z])}10min{l(γ[z1,z]),l(γ[z2,z])}10φ(CδD(z)). (2.20)

    Together with (2.17), (2.19) and (2.20), which shows that in this subcase, the lemma holds with

    φ2(C2t)=max{φ(5t),10φ(Ct)}. (2.21)

    Case 3. z1G and z2DG.

    Using a similar argument as in Case 2, we can show that there is a rectifiable curve γD connecting z1 and z2 such that for any zγ,

    min{l(γ[z1,z]),l(γ[z2,z])}φ2(C2δD(z)). (2.22)

    By combining (2.16), (2.21) and (2.22), we get that D is a φ2-John domain, that is

    min{l(β[z1,z]),l(β[z2,z])}φ2(C2δD(z)).

    where C21 is a constant, and

    φ2(C2t)=max{φ(5t),10φ(Ct)}.

    Hence, Lemma 2.2 is proved.

    The proof of Theorem 1.7. Under the assumptions of Theorem 1.7, Theorem 1.7 follows from Lemmas 2.1 and 2.2.

    The proof of Theorem 1.8. The assumption implies that D1,D2X are two c-quasiconvex and φ-John domains. Furthermore, we suppose that z0D1D2 and r>0 with

    B(z0,r)D1D2andmin{diam(D1),diam(D2)}c0r.

    Let D=D1D2. Under these assumptions, in order to prove Theorem 1.8, we need only to show that there exist constant C1 and function φ with the property that each pair of points a,b in D can be joined by a rectifiable arc γ in D satisfying

    min{l(γ[a,z]),l(γ[z,b])}φ(CδD(z))

    for all zγ. Here, φ is a continuous, increasing function with φ(0)=0 and φ(t)t for all t>0.

    Without loss of generality, we assume that diam(D1)diam(D2). Let aD1 and bD2, and we can choose φ-John curves α:az0 and β:bz0 in D1 and D2, respectively. The continuum αβ contains a curve γ:ab. It suffices to show that γ is a φ-John curve in D=D1D2.

    We choose two points a1α and b1β dividing α and β to subarcs of equal length, respectively. Let

    a2=sup{uα:α[u,z0]¯B(z0,r2)},

    and

    b2=sup{vβ:β[v,z0]¯B(z0,r2)}.

    In what follows, we will divide the proof into two steps.

    Step 1. For all xα, we prove that

    min{l(α[a,x]),l(α[x,z0]β)}φ3(C3δD(x)) (3.1)

    with constant C31.

    Since D1 is φ-John domain and α:az0 is φ-John curve in D1, thus, we have

    min{l(α[a,x]),l(α[x,z0])}φ(CδD1(x)). (3.2)

    Let xα. Now, to prove inequality (3.1), we divide the discussions into three cases:

    Case 1. xα[a,a1].

    Since D=D1D2, it is clear that

    δD1(x)δD(x).

    From the definitions of a1 and the φ-John domain, for any xα[a,a1], by (3.2), it follows that

    min{l(α[a,x]),l(α[x,z0]β)}min{l(α[a,x]),l(α[x,z0])}φ(CδD1(x))φ(CδD(x)).

    Case 2. xα[a2,z0].

    Now that diam(D1)c0r, according to the definition of a2, it is clear that

    δD(x)r2diam(D1)2c0. (3.3)

    Since D1 is a c-quasiconvex domain, we have

    l(α)c|az0|cdiam(D1), (3.4)

    where c1 is a constant. Therefore, according to (3.3), (3.4) and the definition of function φ, it follows that

    min{l(α[a,x]),l(α[x,z0]β)}l(α)cdiam(D1)2cc0δD(x)2cc0φ(δD(x)).

    Case 3. xα[a1,a2] and a2α[a1,z0].

    This case may be empty. From the construction of a2, it is obvious that

    min{l(α[a,x]),l(α[x,z0])}r2. (3.5)

    From the definition of c-quasiconvex domain and inequality diam(D1)c0r, we obtain that

    l(α)c|az0|cdiam(D1)cc0r. (3.6)

    Hence, Combing (3.2), (3.5) and (3.6), it follows that

    min{l(α[a,x]),l(α[x,z0]β)}l(α[a,x])l(α)cc0r2cc0min{l(α[a,x]),l(α[x,z0])}2cc0φ(CδD1(x))2cc0φ(CδD(x)).

    Therefore, for all xα, we have

    min{l(α[a,x]),l(α[x,z0]β)}φ3(C3δD(x)),

    where

    φ3(C3t)=max{2cc0φ(t),2cc0φ(Ct)}=2cc0φ(Ct),

    and C31 is a constant.

    Step 2. For all yβ, we prove that

    min{l(αβ[z0,y]),l(β[y,b])}φ4(C4δD(y)) (3.7)

    with constant C41.

    Let yβ. To prove inequality (3.7), our proof consists of three parts. For the first part, if yβ[b,b1], Since D2 is φ-John domain and β:bz0 is a φ-John curve in D2, thus, we get that

    min{l(β[z0,y]),l(β[y,b])}φ(CδD2(y)). (3.8)

    By the inequality (3.8), we deduce that

    min{l(αβ[z0,y]),l(β[y,b])}min{l(β[z0,y]),l(β[y,b])}φ(CδD2(y))φ(CδD(y)).

    For the second part, if yβ[b2,z0], according to the definition of b2, we obtain that

    δD(y)r2diam(D1)2c0. (3.9)

    Since D2 is a c-quasiconvex domain, and β is a φ-John curve, from the definitions of a2 and b2, it is clear that

    l(β[z0,y])c|yz0|c|a2z0|cdiam(D1). (3.10)

    Combing (3.4), (3.9) and (3.10), it follows that

    min{l(αβ[z0,y]),l(β[y,b])}l(αβ[z0,y])=l(α)+l(β[z0,y])2cdiam(D1)4cc0δD(y)4cc0φ(δD(y)).

    For the final part, if b2β[b1,z0] and yβ[b1,b2], this case may again be empty. Since D1 is a c-quasiconvex domain, and diam(D1)c0r, we get that

    l(α)c|az0|cdiam(D1)cc0r, (3.11)

    and since D2D is a φ-John domain, we have

    min{l(β[z0,y]),l(β(y,b))}φ(CδD2(y))φ(CδD(y)). (3.12)

    In addition, from the definition of b2, we deduce that

    min{l(β[z0,y]),l(β(y,b))}r2. (3.13)

    According to (3.11)–(3.13), we get

    l(α)cc0r2cc0min{l(β[z0,y]),l(β(y,b))}2cc0φ(CδD(y)). (3.14)

    Now, it follows immediately from the inequality (3.14) that

    min{l(αβ[z0,y]),l(β[y,b])}l(α)+min{l(β[z0,y]),l(β[y,b])}2cc0φ(CδD(y))+φ(CδD(y))4cc0φ(CδD(y)).

    Therefore, for all yβ, we have

    min{l(αβ[z0,y]),l(β[y,b])}φ4(C4δD(y))

    where

    φ4(C4t)=max{4cc0φ(t),4cc0φ(Ct)}=4cc0φ(Ct),

    and C41 is a constant.

    Hence, we verified all the cases and our conclusion holds, that is, D1D2 is a φ-John domain with

    φ(Ct)=max{φ3(C3t),φ4(C4t)}=φ4(C4t)=4cc0φ(Ct),

    where C1 is a constant.

    In summary, we investigated the removability and union of generalized John domain, that is, the main result of this paper showed that D is a φ-John domain if, and only if, DP is a φ-John domain, where P is a subset of D containing finitely many points of D, φ and φ depend on each other, and finally we prove the union of φ-John domains is φ-John domain.

    Given the Theorem 1.7 of the paper, it is natural to ask the following question:

    Question 4.1. Let X be a rectifiably connected, locally compact and c-annular quasiconvex metric space, and let P be a countable subset of X. Is X φ-John metric space if and only if XP φ-John metric space?

    The authors thank the referee for their careful reading and valuable comments that led to the improvement of the paper.

    This research work is supported by the National Natural Science Foundation of China (Grant No. 11671057), and the Guizhou Province Science and Technology Foundation (Grant No. QianKeHeJiChu[2020]1Y003, QianKeHeJiChu-ZK[2021] general 001).

    The authors declare they have not used Artificial Intelligence (AI) tools in the creation of this article.

    All authors declare no conflicts of interest in this paper.



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