Research article

Characterization of ternary derivation of strongly double triangle subspace lattice algebras

  • Received: 04 August 2023 Revised: 20 October 2023 Accepted: 23 October 2023 Published: 30 October 2023
  • MSC : 47B49, 47L35

  • Let D be a strongly double triangle subspace lattice on a nonzero complex reflexive Banach space. In this paper, we characterize the linear maps δ,τ: AlgDAlgD satisfying δ(A)B+Aτ(B)=0 for any A,BAlgD with AB=0. This result can be used to characterize linear maps derivable (centralized) at zero point and local centralizers on AlgD, respectively.

    Citation: Zijie Qin, Lin Chen. Characterization of ternary derivation of strongly double triangle subspace lattice algebras[J]. AIMS Mathematics, 2023, 8(12): 29368-29381. doi: 10.3934/math.20231503

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  • Let D be a strongly double triangle subspace lattice on a nonzero complex reflexive Banach space. In this paper, we characterize the linear maps δ,τ: AlgDAlgD satisfying δ(A)B+Aτ(B)=0 for any A,BAlgD with AB=0. This result can be used to characterize linear maps derivable (centralized) at zero point and local centralizers on AlgD, respectively.



    Let A be an algebra and (γ,δ,τ) be a triple of linear maps of A. Recall that (γ,δ,τ) is a ternary derivation of A if

    γ(ab)=δ(a)b+aτ(b)

    for all a,bA. Clearly, if γ=δ=τ, then γ is a derivation of A; if γ=δ and τ is a derivation of A, then γ is a generalized derivation of A; if γ=δ and τ=0, then γ is a left centralizer of A. In 2003, Jiménez-Gestal and Pérez-Izquierdo [9] introduced the terminology of ternary derivation and described ternary derivations of the generalized Cayley-Dickson algebras over a field of characteristic not 2 and 3. In [18,19], Shestakov studied ternary derivations of separable associative and Jordan algebras and Jordan superalgebras, respectively. Recently, ternary derivations of triangular algebras have been precisely described in [2]. We refer the reader to [10,17] for background information about the definition of ternary derivations.

    Let (γ,δ,τ) be a ternary derivation of A. It is easy to verify that δ and τ satisfy

    ab=0δ(a)b+aτ(b)=0 (1.1)

    for all a,bA. However, the converse of this observation is not necessarily true (see [5, Example 1.1]). It is natural to ask how to characterize linear maps δ and τ satisfying (1.1). Benkovič and Grašič [3] considered linear maps δ and τ satisfying (1.1) on algebras generated by idempotents. In [1], the authors showed that if A is a unital standard operator algebra on a Banach space X, and δ,τ: AB(X) are linear maps satisfying (1.1), then there exist R,S,TB(X) such that

    δ(A)=ASRAandτ(A)=ATSA

    for all AA, where B(X) denotes the algebra of all bounded linear operators on X. Recently, Fošner and Ghahramani [5] proved that if linear maps δ,τ: AlgNAlgN satisfy (1.1), then exists a unique linear map γ: AlgNAlgN defined by

    γ(A)=RA+AT

    for some R,TAlgN such that (γ,δ,τ) is a ternary derivation of AlgN, where AlgN is a nest algebra on a real or complex Banach space with NN complemented whenever N=N.

    In this paper, we will consider linear maps δ and τ satisfying (1.1) on another important kind of reflexive algebra, that is, strongly double triangle subspace lattice algebra. Note that both standard operator algebras on Banach spaces and nest algebras are rich in rank-one operators. This makes it possible to identify certain behavior of the linear maps on some special set of rank-one operators. Actually, the proofs in [1,5] depend heavily on the existence of rank-one operators. However, strongly double triangle subspace lattice algebras contain no rank-one operators [13]. So, the problem is more complicated than the previous one, and we will study this problem by means of operators of even rank.

    This paper is organized as follows. In Section 2, all the results of the paper are presented. Section 3 is devoted to the proof of our central result (see Theorem 2.1).

    Let us introduce some notations used in this paper. Throughout, X will be a nonzero reflexive complex Banach space with topological dual X. For AB(X), by ker(A), ran(A) and rank(A), we denote the kernel, the range and the rank of A, respectively. For nonzero vectors eX and fX, we define the rank-one operator ef by xe(x)f for xX. For any nonempty subset LX, by L we denote the annihilator of L, that is,

    L={fX:f(x)=0 for all xL}.

    Dually, for any nonempty subset MX, M denotes its pre-annihilator, that is,

    M={xX:f(x)=0 for all fM}.

    A family L of closed subspaces of X is called a subspace lattice on X if it contains (0) and X, and is closed under the operations closed linear span and intersection in the sense that γΓLγL and γΓLγL for every family {Lγ: γΓ} of elements in L. Given a subspace lattice L on X, the associated subspace lattice algebra AlgL is the set of operators on X leaving every subspace in L invariant, that is,

    AlgL={AB(X):AxL for every xL and for every LL}.

    A double triangle subspace lattice on X is a set

    D={(0),K,L,M,X}

    of subspaces of X satisfying

    KL=LM=MK=(0)

    and

    KL=LM=MK=X.

    We say that D is a strongly double triangle subspace lattice if one of the three sums K+L, L+M and M+K is closed. Observe that

    D={(0),K,L,M,X}

    is a double triangle subspace lattice on the reflexive Banach space X. Put

    K0=K(L+M), L0=L(M+K), M0=M(K+L)

    and

    Kp=K(L+M), Lp=L(M+K), Mp=M(K+L).

    It follows from [11, Lemma 2.2] that

    dimK0=dimL0=dimM0

    and

    dimKp=dimLp=dimMp.

    We close this section by summarizing some lemmas on strongly double triangle subspace lattice algebras, which will be used to prove our main results.

    Lemma 1.1. ([11]) Let

    D={(0),K,L,M,X}

    be a double triangle subspace lattice on a nonzero complex reflexive Banach space X. Then the following statements hold.

    (1) K0KKp, L0LLp and M0MMp.

    (2) K0L0=L0M0=M0K0=(0).

    (3) KpLp=LpMp=MpKp=(0).

    (4) K0+L0=L0+M0=M0+K0=K0+L0+M0.

    (5) Kp+Lp=Lp+Mp=Mp+Kp=Kp+Lp+Mp.

    Lemma 1.2. ([11]) Let

    D={(0),K,L,M,X}

    be a double triangle subspace lattice on a nonzero complex reflexive Banach space X. Then the following statements hold.

    (1) Every finite-rank operator of AlgD has even rank (possibly zero).

    (2) If e,fX and e,fX are nonzero vectors satisfying eK0, fL0, e+fM0 and eKp, fLp, e+fMp, then R=effe is a rank-two operator in AlgD. Moreover, every rank-two operator in AlgD has this form for such vectors e,fX and e,fX.

    (3) AlgD contains a nonzero finite-rank operator if and only if dimK00 and dimKp0.

    Lemma 1.3. ([11]) Let

    D={(0),K,L,M,X}

    be a strongly double triangle subspace lattice on a nonzero complex reflexive Banach space X. If K+L is closed, then the following statements hold.

    (1) K0 is dense in K, L0 is dense in L.

    (2) K0+L0+M0 is dense in X.

    (3) Kp+Lp+Mp is dense in X.

    Lemma 1.4. ([11]) Let

    D={(0),K,L,M,X}

    be a strongly double triangle subspace lattice on a complex reflexive Banach space X. If AlgD contains a rank-two operator, then the following statements hold.

    (1) span{ran(R):RAlgD,rank(R)=2}=K0+L0+M0.

    (2) {ker(R):RAlgD,rank(R)=2}=(Kp+Lp+Mp).

    The above two lemmas show that strongly double triangle subspace lattice algebras are rich in rank-two operators. We refer readers [11,13,15] to more properties of strongly double triangle subspace lattice algebras.

    In this section, we present the results of this paper. The central result is as follows.

    Theorem 2.1. Let

    D={(0),K,L,M,X}

    be a strongly double triangle subspace lattice on a nonzero complex reflexive Banach space X. Suppose δ,τ: AlgDAlgD are linear maps satisfying the relation (1.1). Then exists a linear map γ: AlgDAlgD such that (γ,δ,τ) is a ternary derivation. Moreover, there exist densely defined, closed linear operators R,T,S: MX such that

    τ(A)x=(TA+AS)x,
    δ(A)x=(RAAT)x

    and

    γ(A)x=(RA+AS)x,

    for all AAlgD and all xM. Here M is invariant under every element of AlgD.

    The proof of Theorem 2.1 will be given in Section 3. We now give some applications. In the following corollaries, D will always denote a strongly double triangle subspace lattice on a nonzero complex reflexive Banach space.

    First of all, as an immediate consequence, we get the following corollary.

    Corollary 2.2. Let (γ,δ,τ) be a ternary derivation of AlgD. Then (γ,δ,τ) is of the form in Theorem 2.1.

    Recall that a linear map δ: AlgDAlgD is derivable at zero point if

    δ(A)B+Aδ(B)=0

    for any A,BAlgD with AB=0. In [7,8,15,21], the authors studied the linear maps derivable at zero point for some algebras. Recently, Fallahi and Ghahramani [4] considered another type of derivable maps at zero point, and they showed that if A is a standard operator algebra on a Banach space X, and δ is a linear map from A into itself, then δ satisfies

    bδ(a)+δ(b)a=0

    for any a,bA with ab=0 if and only if δ=0. Here, applying Theorem 2.1, we can get the main result in [15].

    Corollary 2.3. ([15, Theorem 2.3]) Suppose δ: AlgDAlgD is a linear map derivable at zero point. Then there exist a complex scalar λ and a derivation d such that

    δ(A)=d(A)+λA

    for all AAlgD.

    Proof. By Theorem 2.1, there exists a linear map γ: AlgDAlgD such that (γ,δ,δ) is a ternary derivation. That is,

    γ(AB)=δ(A)B+Aδ(B)

    for every A,BAlgD. Let P be any idempotent in AlgD. Then,

    P(IP)=(IP)P=0.

    Since δ is derivable at zero point, we can get

    0=δ(P)(IP)+Pδ(IP)=δ(IP)P+(IP)δ(P),

    which further implies that δ(I)P=Pδ(I) for every idempotent PAlgD. Then by the proof of [15, Theorem 2.3], there exists a constant λ such that δ(I)=λI. Define a linear map d: AlgDAlgD by

    d(A)=γ(A)2λA

    for every AAlgD. By the definition of γ, we have

    γ(A)2λA=δ(A)λA.

    Then

    d(AB)=γ(AB)2λAB=δ(A)B+Aδ(B)2λAB=(δ(A)λA)B+A(δ(B)λB)=(γ(A)2λA)B+A(γ(B)2λB)=d(A)B+Ad(B).

    The proof is complete.

    Recall that a linear map ϕ: AlgDAlgD is a left (right) centralizer if

    ϕ(AB)=ϕ(A)B(ϕ(AB)=Aϕ(B))

    for all A,BAlgD and ϕ is a centralizer if it is both left and right centralizer. There have been a number of papers on the study of conditions under which centralizers on algebras can be determined by the action on some sets of operators (see [6,12,16] and the references therein). Among others, in [6], the authors studied the structure of linear maps ϕ on certain operator algebras A satisfying

    ϕ(abba)=ϕ(a)bbϕ(a)

    or

    ϕ(abba)=aϕ(b)ϕ(b)a

    for any a,bA with ab=0. A linear map ϕ: AlgDAlgD is said to be left (right) centralized at zero point if

    ϕ(A)B=0(Aϕ(B)=0)

    for any A,BAlgD with AB=0 and ϕ is said to be centralized at zero point if it is both left centralized and right centralized at zero point. The following corollary characterizes linear maps on AlgD which are centralized at zero point.

    Corollary 2.4. Suppose δ,τ,ϕ: AlgDAlgD are linear maps. The following statements hold.

    (1) If δ is left centralized at zero point, then there exists TAlgD such that δ(A)=TA for all AAlgD.

    (2) If τ is right centralized at zero point, then there exists TAlgD such that τ(A)=AT for all AAlgD.

    (3) Suppose ϕ is centralized at zero point, then there exists λC such that ϕ(A)=λA for all AAlgD.

    Proof. (1) By Theorem 2.1, there exists a linear map γ: AlgDAlgD such that

    γ(AB)=δ(A)B

    for every A,BAlgD. By the definition of γ, we have γ(A)=δ(A) for every AAlgD. So, δ(BA)=δ(B)A for all A,BAlgD. Taking B=I in the above equation, we arrive at δ(A)=TA for all AAlgD, where T=δ(I).

    (2) The proof is similar to the proof of (1).

    (3) By (1) and (2), there exists TAlgD such that

    δ(A)=TA=AT

    for all AAlgD. By the proof of Corollary 2.3, there exists λC such that δ(A)=λA for all AAlgD.

    The other direction of the study of centralizers by the local actions is the well-known local maps problem. See, for example [12,20]. Recently, in [14], Molnár introduced a new type of local maps, and calculated the operational reflexive closures of some important classes of transformations. We say that a linear map ϕ: AlgDAlgD is a local left (right) centralizer of AlgD, if for every AAlgD, there exists a left (right) centralizer ϕA, depending on A, such that ϕ(A)=ϕA(A). Similarly, we can define a local centralizer. Now, we study the local centralizers on strongly double triangle subspace lattice algebras.

    Corollary 2.5. The following statements hold.

    (1) Every local left centralizer on AlgD is a left centralizer.

    (2) Every local right centralizer on AlgD is a right centralizer.

    (3) Every local centralizer on AlgD is a centralizer.

    Proof. We only show (1). By a similar argument, we can get (2) and (3). Take A,BAlgD such that AB=0. Now we show that ϕ(A)B=0. For AAlgD, there exists a left centralizer ϕA, depending on A, such that ϕ(A)=ϕA(A). From this, we get

    ϕ(A)B=ϕA(A)B=ϕA(I)AB=0.

    Applying Corollary 2.4, we see that ϕ is a left centralizer.

    Let

    D={(0),K,L,M,X}

    be a strongly double triangle subspace lattice on a nonzero complex reflexive Banach space X. Note that

    dimK0=dimL0=dimM0

    and

    dimKp=dimLp=dimMp.

    It is easy to prove that dimK00 and dimKp0. It follows from Lemma 1.2 (3) that AlgD contains nonzero finite-rank operators. In this section, we will complete the proof of Theorem 2.1.

    First, we need the following lemma, which comes from [1].

    Lemma 3.1. Let A be an algebra with unit I and AA. Suppose δ,τ: AA are linear maps satisfying the relation (1.1). Then the following statements hold.

    (1) δ(AP)+APτ(I)=δ(A)P+Aτ(P) for every idempotent PA.

    (2) δ(P)A+Pτ(A)=δ(I)PA+τ(PA) for every idempotent PA.

    Now we are at a position to give the proof of our main result.

    Proof of Theorem 2.1. Without loss of generality, we may assume that K+L is closed. We will prove the theorem by checking several claims.

    Claim 3.2. Let AAlgD. Then the following statements hold.

    (1) δ(AR)+ARτ(I)=δ(A)R+Aτ(R) for every rank-two operator RAlgD.

    (2) δ(R)A+Rτ(A)=δ(I)RA+τ(RA) for every rank-two operator RAlgD.

    We only show (1). With the same argument, one can get (2). By Lemma 1.2, we can write

    R=effe

    for some nonzero vectors eL0, fM0, e+fK0 and eLp, fMp, e+fKp. Now we consider two cases:

    Case 1. e(f)0. Since L0Lp, M0Mp, K0Kp by Lemma 1.1, we have

    e(e)=f(f)=0

    and

    e(f)+f(e)=(e+f)(e+f)=0.

    It follows that

    R2=e(f)ef+f(e)fe=e(f)R.

    So,

    (1e(f)R)2=1e(f)R.

    Hence, by the linearity of δ and Lemma 3.1, we obtain (1).

    Case 2. e(f)=0. Note that K+L=X. Then,

    M0=M(K+L)=M.

    Take f1M0 such that e(f1)0. Actually, if e(f1)=0 for all f1M0, we have

    eM0=M.

    Applying the fact that

    eLp=L(M+K),

    since

    LM=(0),

    it follows that

    eLM=(0),

    a contradiction. By Lemma 1.1, there exist unique elements e1L0 and g1K0 such that e1+f1=g1. Denote

    R1=ef1fe1

    and

    R2=e(f1+f)f(e1+e).

    Then R1,R2AlgD are of rank two by Lemma 1.2. Since

    e(f+f1)=e(f1)0,

    it follows from Case 1 that

    δ(AR)+ARτ(I)=δ(A(R2R1))+A(R2R1)τ(I)=δ(AR2)+AR2τ(I)δ(AR1)AR1τ(I)=δ(A)R2+Aτ(R2)δ(A)R1Aτ(R1)=δ(A)R+Aτ(R).

    Claim 3.3. Let A,BAlgD. Then,

    δ(AB)=Aδ(B)+δ(A)BAδ(I)B.

    Let RAlgD be any rank-two operator. By Lemma 1.2, we can write

    R=effe

    for some nonzero vectors eL0, fM0, e+fK0 and eLp, fMp, e+fKp. Since AeL0, AfM0 and

    Ae+Af=A(e+f)K0,

    we have

    AR=eAffAeAlgD

    by Lemma 1.2. Take A=I in Claim 3.2 (1), then,

    δ(R)+Rτ(I)=δ(I)R+τ(R) (3.1)

    for every rank-two operator RAlgD. Since ARAlgD has rank at most two, and AlgD contains no rank-one operators, we have either AR=0 or rank(AR)=2. By Eq (3.1), we can obtain that

    δ(AR)+ARτ(I)=δ(I)AR+τ(AR).

    This together with Claim 3.2 (1) leads to

    δ(I)AR+τ(AR)=δ(A)R+Aτ(R) (3.2)

    for all AAlgD. Replace A by AB in Eq (3.2), we have

    δ(I)ABR+τ(ABR)=δ(AB)R+ABτ(R) (3.3)

    for all A,BAlgD. On the other hand, it follows from Eq (3.2) that

    δ(I)ABR+τ(ABR)=δ(A)BR+Aτ(BR)=δ(A)BR+A(δ(B)R+Bτ(R)δ(I)BR)=δ(A)BR+Aδ(B)R+ABτ(R)Aδ(I)BR

    for all A,BAlgD. This together with Eq (3.3) implies that

    δ(AB)R=Aδ(B)R+δ(A)BRAδ(I)BR

    for all A,BAlgD and all rank-two operators RAlgD. By Lemma 1.4 (1),

    δ(AB)x=Aδ(B)x+δ(A)BxAδ(I)Bx

    for all A,BAlgD and all xK0+L0+M0. Since K0+L0+M0 is dense in X by Lemma 1.3 (2), we have

    δ(AB)=Aδ(B)+δ(A)BAδ(I)B

    for all A,BAlgD.

    Claim 3.4. Let A,BAlgD. Then,

    τ(AB)=Aτ(B)+τ(A)BAτ(I)B.

    With the similar argument as in the proof of Claim 3.3, one can get that

    Rτ(AB)=RAτ(B)+Rτ(A)BRAτ(I)B

    for all A,BAlgD and all rank-two operators RAlgD. It follows that

    (τ(AB)Aτ(B)τ(A)B+Aτ(I)B)xker(R)

    for all xX. Note that

    {ker(R):RAlgD,rank(R)=2}=(Kp+Lp+Mp)

    by Lemma 1.4. Since R is arbitrary, by Lemma 1.3, we have

    (τ(AB)Aτ(B)τ(A)B+Aτ(I)B)xX=(0)

    for all xX. This implies that

    τ(AB)=Aτ(B)+τ(A)BAτ(I)B

    for all A,BAlgD.

    Claim 3.5. Let AAlgD. Then,

    δ(A)δ(I)A=τ(A)Aτ(I).

    By Eq (3.1) and Claim 3.4, we have

    δ(AR)=δ(I)AR+τ(AR)ARτ(I)=δ(I)AR+Aτ(R)+τ(A)RAτ(I)RARτ(I)=δ(I)AR+A(τ(R)Rτ(I))+τ(A)RAτ(I)R=δ(I)AR+A(δ(R)δ(I)R)+τ(A)RAτ(I)R=δ(I)AR+Aδ(R)Aδ(I)R+τ(A)RAτ(I)R.

    This together with Claim 3.3 gives us

    (δ(A)δ(I)A)R=(τ(A)Aτ(I))R

    for all rank-two operators RAlgD. By a similar argument as in Claim 3.3, we get

    δ(A)δ(I)A=τ(A)Aτ(I).

    Claim 3.6. There exists a linear map γ on AlgD such that (γ,δ,τ) is a ternary derivation.

    Define a map γ: AlgDAlgD by

    γ(A)=δ(A)+Aτ(I)=τ(A)+δ(I)A

    for every AAlgD. Clearly, γ is linear. Let A,BAlgD. It follows from Claims 3.4 and 3.5 that

    γ(AB)=τ(AB)+δ(I)AB=Aτ(B)+τ(A)BAτ(I)B+δ(I)AB=Aτ(B)+(τ(A)Aτ(I))B+δ(I)AB=Aτ(B)+(δ(A)δ(I)A)B+δ(I)AB=δ(A)B+Aτ(B).

    Claim 3.7. There exist densely defined, closed linear operators R,T,S: MX such that

    τ(A)x=(TA+AS)x,
    δ(A)x=(RAAT)x

    and

    γ(A)x=(RA+AS)x

    for all AAlgD and all xM. Here M is invariant under every element of AlgD.

    Define Δ: AlgDAlgD by

    Δ(A)=τ(A)Aτ(I)

    for every AAlgD. Obviously, Δ is a linear map. Let A,BAlgD. Then by Claim 3.4, we have

    Δ(AB)=τ(AB)ABτ(I)=Aτ(B)+τ(A)BAτ(I)BABτ(I)=A(τ(B)Bτ(I))+(τ(A)Aτ(I))B=AΔ(B)+Δ(A)B.

    So, Δ is a derivation. By [15, Theorem 2.1], we know that every derivation of AlgD is quasi-spatial, that is, there exists a densely defined, closed linear operator T: MXX with M invariant under every element of AlgD such that

    Δ(A)x=(TAAT)x (3.4)

    for all AAlgD and all xM. Set

    R=T+δ(I)|M

    and

    S=τ(I)|MT.

    It follows from Eq (3.4) that

    τ(A)x=(Δ(A)+Aτ(I))x=(TAAT+Aτ(I))x=(TA+A(τ(I)T))x=(TA+AS)x

    for all AAlgD and all xM. Similarly, by Claim 3.5 and Eq (3.4), we can obtain that

    δ(A)x=(RAAT)x

    for all AAlgD and all xM. Hence, by the definition of γ, we can get

    γ(A)x=(τ(A)+δ(I)A)x=(TA+AS+δ(I)A)x=((T+δ(I))A+AS)x=(RA+AS)x

    for all AAlgD and all xM.

    In this paper, we described the structure of linear maps δ and τ satisfying (1.1) on strongly double triangle subspace lattice algebras AlgD. We proved that if linear maps δ,τ: AlgDAlgD satisfy (1.1), then exists a linear map γ: AlgDAlgD such that (γ,δ,τ) is a ternary derivation of AlgD. Using the result obtained, we characterized linear maps on AlgD derivable (centralized) at zero point. Moreover, we showed that every local centralizer of AlgD is a centralizer.

    The authors declare they have not used Artificial Intelligence (AI) tools in the creation of this article.

    This work is supported by the National Natural Science Foundation of China (No. 12061018). The authors would like to thank the referee for a very thorough reading of the paper and many helpful comments that improved the paper.

    The authors declare no conflicts of interest.



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