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Research article

Composition operators on Hardy-Sobolev spaces with bounded reproducing kernels

  • Received: 17 July 2022 Revised: 19 September 2022 Accepted: 10 October 2022 Published: 09 November 2022
  • MSC : 47B33, 47A53

  • For any real β let H2β be the Hardy-Sobolev space on the unit disc D. H2β is a reproducing kernel Hilbert space and its reproducing kernel is bounded when β>1/2. In this paper, we prove that Cφ has dense range in H2β if and only if the polynomials are dense in a certain Dirichlet space of the domain φ(D) for 1/2<β<1. It follows that if the range of Cφ is dense in H2β, then φ is a weak-star generator of H, although the conclusion is false for the classical Dirichlet space D. Moreover, we study the relation between the density of the range of Cφ and the cyclic vector of the multiplier Mβφ.

    Citation: Li He. Composition operators on Hardy-Sobolev spaces with bounded reproducing kernels[J]. AIMS Mathematics, 2023, 8(2): 2708-2719. doi: 10.3934/math.2023142

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  • For any real β let H2β be the Hardy-Sobolev space on the unit disc D. H2β is a reproducing kernel Hilbert space and its reproducing kernel is bounded when β>1/2. In this paper, we prove that Cφ has dense range in H2β if and only if the polynomials are dense in a certain Dirichlet space of the domain φ(D) for 1/2<β<1. It follows that if the range of Cφ is dense in H2β, then φ is a weak-star generator of H, although the conclusion is false for the classical Dirichlet space D. Moreover, we study the relation between the density of the range of Cφ and the cyclic vector of the multiplier Mβφ.



    Let D be the unit disc in the complex plane C and H(D) be the space of all analytic functions on D. For fH(D) we use

    Rf(z)=zfz(z)

    to denote the radial derivative of f at z. If f(z)=k=0akzk is the Taylor expansion of f, it is easy to see that

    Rf(z)=k=1kakzk.

    More generally, for any real number β and any fH(D) with the Taylor expansion above, we define

    Rβf(z)=k=1kβakzk

    and call it the radial derivative of f of order β.

    It is clear that these fractional radial differential operators satisfy RαRβ=Rα+β. When β<0, the effect of Rβ on f is actually "integration" instead of "differentiation". For example, radial differentiation of order 3 is actually radial integration of order 3.

    For βR, the Hardy-Sobolev space H2β consists of all analytic functions f on D such that Rβf belongs to the classical Hardy space H2. It is clear that H2β is a Hilbert space with the inner product

    f,gβ=f(0)¯g(0)+Rβf,RβgH2.

    The induced norm in H2β is then given by

    f2β=|f(0)|2+Rβf2H2.

    Recall that H2 is the space of analytic functions f on D such that

    f2H2=sup0<r<1T|f(rζ)|2dσ(ζ)<,

    where dσ is the normalized Lebesgue measure on the unit circle T=D. It is well known that every function fH2 has radial limits

    f(ζ)=limr1f(rζ)

    for almost all ζT. Moreover, the radial limit function f(ζ) above belongs to L2(T,dσ). The inner product in H2 can then be written as

    f,g0=f,gH2=Tf(ζ)¯g(ζ)dσ(ζ),

    and its induced norm on H2 is given by

    f20=f2H2=T|f(ζ)|2dσ(ζ).

    It is well known that a function fH(D) belongs to H2 if and only if

    D|Rf(z)|2(1|z|2)dA(z)<,

    where dA is the normalized area measure on D. See [22,26,27]. More generally, for any t>1, we consider the weighted area measure

    dAt(z)=(t+1)(1|z|2)tdA(z),

    which is a probability measure on D. The spaces

    A2t=L2(D,dAt)H(D)

    are called weighted Bergman spaces (with standard weights). When t=0, we simply write A2 for the ordinary Bergman spaces. The following result establishes a natural connection between Hardy-Sobolev spaces and weighted Bergman spaces via fractional derivatives.

    Proposition 1. [6] Suppose βR and fH(D). Then the following conditions are equivalent.

    (a) fH2β.

    (b) Rβ+1fA21.

    If N is a nonnegative integer with N>β, then the conditions above are also equivalent to

    (c) RNfA22(Nβ)1.

    Hardy-Sobolev spaces contain many classical analytic function spaces as special cases. For example, H21/2 is the Bergman space A2, H20 is the Hardy space H2, and H21/2 is the Dirichlet space D consisting of analytic functions f on D such that

    f2=|f(0)|2+D|f(z)|2dA(z)<.

    More generally, for any domain GC and any positive measure dω on G, we will use A2(G,dω) to denote the weighted Bergman space of analytic functions f on G such that

    G|f(z)|2dω(z)<.

    Similarly, we use D(G,dω) for the weighted Dirichlet space of analytic functions f on G with

    G|f(z)|2dω(z)<.

    When dω is ordinary area measure, we will simply write A2(G) and D(G).

    Let φ:DD be an analytic self-map D. For any Hilbert space H of analytic functions on D we consider the composition operator Cφ:HH defined by Cφf=fφ. For β<1/2, every composition operator is bounded on H2β. However, this is not so for β1/2. For example, not every composition operator is bounded on the Dirichlet space. There are conditions (in terms of Carleson type measures, for example) that tell us exactly when Cφ is bounded on D. See [11,20,29] for example.

    The density of the range of a composition operator is an interesting problem. Bourdon and Roan studied the problem for the Hardy space (see [3,21]) and Cima raised the problem for the Dirichlet space in [9]. In [7], we settled Cima's problem completely:

    Theorem 2. Suppose φ:DD is analytic, non-constant, and G=φ(D). Then the following two conditions are equivalent.

    (i) Cφ:DD is bounded and has dense range.

    (ii) φ is univalent and the polynomials are dense in A2(G).

    In [3], Bourdon proved the following result.

    Theorem 3. If G=φ(D), where φ is a weak-star generator of H, then the polynomials are dense in A2(G).

    It is thus natural for us to consider the following problem.

    Question 4. Does the density of polynomials in A2(G) imply that φ is a weak-star generator of H?

    In general, the answer is no. In fact, Sarason gave a condition in [23] for φ to be a weak-star generator of H, which combined with the Corollary 2 in that paper yields a bounded simply connected domain G such that the polynomials are dense in A2(G) but any Riemann map φ:DG is not a weak-star generator of H; see [3,17].

    In Section 2, we will give a necessary and sufficient condition for composition operators to have dense range on Hardy-Sobolev spaces. Our result shows that if φ is a univalent self-map of D, then the density of polynomials in the weighted Dirichlet spaces

    D(φ(D),(1|φ1|2)12βdA),12<β<1,

    implies that φ is a weak-star generator of H.

    The density of the range of the composition operator Cφ is relative to the cyclic vectors of the multiplier Mβφ with symbol φ defined as Mβφf=φf for any fH2β. In the last part of this paper, we discuss the relations between the density of Cφ on H2β and the cyclic vectors of Mβφ for 1/2<β<1. Thank you for your cooperation.

    In [17], S. N. Mergeljan and A. P. Talmadjan showed that if sufficiently many slits are put in the unit disc then we can obtain a domain G such that the polynomials are dense in A2(G). By the Riemann mapping theorem, there is an analytic homeomorphism φ:DG, so Cφ has dense range in D by Theorem 2 but φ is not a weak-star generator of H by Corollary 2 of [23]. However, the boundary of the above domain is not a Jordan curve, the Riemann map may not be continuous up to the boundary, and φ does not belong to the disc algebra A(D). Furthermore, φD12β for 1/2<β<1, where

    D12β={fH(D)|fA212β}

    is the weighted Dirichlet space with the norm

    fD12β=[|f(0)|2+D|f(z)|2(1|z|2)12βdA]12.

    Thus, for β<1, Proposition 1 shows that fH2β if and only if RfA212β and hence H2β=D12β, see [6] for more details.

    The following result is due to P. Bourdon.

    Proposition 5. (Corollary 3.7 in [3]) Let φ map D univalently onto GD. If the polynomials are dense in A2(G,(1|φ1|2)dA), then Cφ:H2H2 has dense range.

    Proposition 5 extends a result of Roan [21] and supplies additional examples of composition operators with dense range. As a special case of our next result, we see that the density of polynomials in A2(G,(1|φ1|2)dA) is also a necessary condition for the density of the range of Cφ in H2β, that is, the converse of Bourdon's result above is also true.

    We will use the notion R(Cφ) to denote the range of a composition operator. The space on which Cφ acts is usually obvious from the context, or it will be specified whenever there is a possibility for confusion.

    Theorem 6. Suppose β<1 and φ is a non-constant analytic self-map of D. Then Cφ has dense range in H2β=D12β if and only if φ is univalent and the polynomials are dense in D(G,(1|φ1|2)12βdA), where G=φ(D).

    Proof. First assume that Cφ has dense range in D12β. It is easy to see that φ must be univalent. In fact, if there are z1,z2D, z1z2, such that φ(z1)=φ(z2), then for any fD12β we have Cφf(z1)=Cφf(z2), which clearly contradicts the assumption that the range of Cφ is dense in D12β. To prove that the polynomials are dense in D(G,(1|φ1(z)|2)12βdA), fix any g0D(G,(1|φ1(z)|2)12βdA). Since Cφg0D12β and Cφ has dense range in D12β, we can find a sequence {pk} of polynomials such that CφpkCφg0D12β0 in D12β. This, by a change of variables, is equivalent to pkg00 in D(G,(1|φ1|2)12βdA).

    Conversely, assume that φ is univalent and the polynomials are dense in the space D(G,(1|φ1|2)12β)2dA). It is clear that Cφ is an invertible operator from D(G,(1|φ1|2)12βdA) onto D12β, with the inverse being Cφ1. Thus, for any gD12β there is an fD(G,(1|φ1|2)12βdA) such that Cφf=g. Let {pk} be a sequence of polynomials such that pkf in D(G,(1|φ1|2)12βdA). Then, by a change of variables again,

    CφpkgD12β=∥CφpkCφfD12β0

    in D12β. This shows that the range of Cφ is dense in D12β.

    However, if the image φ(D) has infinite area, even if φA2(D), then the polynomials may not be dense in A2(φ(D)). Here is an example.

    Let f(z)=1/3z be the principal branch of 1/3z on C[0,+). Then the function

    φ(z)=f(1+z)=131+z

    is analytic function on D. It is obvious that φ belongs to A2 and is univalent in the open unit disc, but φA2, that is, the region φ(D) has infinite area. This implies that the polynomials are not dense in A2(φ(D)). In fact, if

    g(w)=φ1(w)=1w31,

    then gA2(φ(D)), but gA2(φ(D)). However, g cannot be approximated by polynomials in A2(φ(D)).

    This example also implies that the Dirichlet space is not necessarily contained in the Bergman space on a general domain in the complex plane. See [7] and additional references there.

    Proposition 7. Suppose β<1 and φD12β is univalent. Then Cφ is an invertible operator from D(φ(D),(1|φ1|2)12βdA) onto D12β with the inverse being Cφ1. Moreover, Cφ preserves the Dirichlet semi-norms.

    Proof. This follows from an easy change of variables. We leave the routine details to the interested reader.

    To further characterize the dense range of Cφ on D12β and its relation to weak-star generator of H, we still need the following lemmas.

    Lemma 8. [23] A sequence {ψn}1 in H converges weak-star to the function ψ if and only if it is uniformly bounded and converges piontwise to ψ on D.

    Lemma 9. Mergelyan's Theorem [24] If K is a compact subset of the plane whose complement is connected, then every complex function that is continuous on K and analytic on its (topological) interior can be uniformly approximated on K by polynomials.

    It follows from Proposition 7 that if 1/2<β<1 and φD12β is univalent, then

    φ1D(φ(D),(1|φ1(z)|2)12βdA).

    A standard argument shows that the operators from Proposition 7 satisfy

    Cφ1˜Kw=Kφ1(w),CφKz=˜Kφ(z),

    where ˜Kw(u)=˜K(u,w) and Kz(v)=K(v,z) are the reproducing kernels of D(φ(D),(1|φ1|2)12βdA) at wφ(D) and of D12β at zD, respectively. Since K(w,z) is continuous on ¯DׯD, we know that ˜K(u,v) is also continuous on ¯φ(D)ׯφ(D). Hence each function f in D(φ(D),(1|φ1|2)12βdA) is continuous on ¯φ(D) by properties of the reproducing kernel. In particular, φ1 is continuous on ¯φ(D). Furthermore, by Lemma 9, φ1 can be uniformly approximated on φ(D) by polynomials.

    Proposition 10. Suppose 1/2<β<1 and φ is a univalent analytic self-map of D with φD12β. Then Lat(Mβφ)=Lat(Mβz), where Mβφ and Mβz are multiplication operators on the weighted Bergman space A212β, and Lat(Mβφ) and Lat(Mβz) are their invariant subspace lattices.

    Proof. Since φD12β, it is clear that Mβφ is bounded on A212β. Lemma 9 implies that there is a sequence {pk} of polynomials such that pk(z)φ1(z) uniformly on D, and this implies that pk(φ(z))z uniformly on D. Thus

    D|(pk(φ)(z)z)g(z)|2(1|z|2)12βdA(z)0,gA212β.

    This shows that Mβpk(φ) converges to Mβz in the weak operator topology. Hence, Lat(Mβφ)Lat(Mβz). The reversed inclusion is obvious, so we have Lat(Mβφ)=Lat(Mβz).

    Corollary 11. Suppose 1/2<β<1 and φ is a univalent analytic self-map of D with φD12β. Then Cφ has dense range in D12β if and only if H(φ(D)) is dense in A2(φ(D),(1|φ1|2)12βdA).

    Proof. This is a direct consequence of Theorem 6, because every bounded analytic function can be approximated by polynomials in the norm topology of A2(φ(D),(1|φ1|2)12βdA).

    Theorem 12. Suppose 1/2<β<1 and φ is an analytic self-map of D such that Cφ is bounded on D12β. If R(Cφ) is dense in D12β, then φ is a weak-star generator of H.

    Proof. For any fD12β there is a sequence {pk} of polynomials such that

    CφpkfD12β0.

    Note that

    |pk(φ)(z)f(z)|=|pk(φ)f,Kz|pk(φ)fD12βKzD12β,

    where Kz is the reproducing kernel of D12β at z. Since 1/2<β<1, the function zKzD12β=K(z,z) is bounded on D. Thus, pk(φ)(z) converges uniformly to f(z). Furthermore, pk(φ)f0 as k.

    If fH, then for any 0<r<1, fr(z)=f(rz)D12β. Choose rn(0,1) such that rn1 as n, then frnwf in H by the dominated convergence theorem. For any n, there is a sequence of polynomials {p(n)k} such that p(n)k(φ)frn0 as k. Hence, we may find subsequence {kn} such that p(n)kn(φ)wf in H. It follows that

    {Cφpk:pkis a polynomial}={pk(φ):pkis a polynomial}

    is weak-star dense in H.

    It is clear that if Cφ maps H2β to itself and 1/2<β<1, then φH2βA(D). If β1, then zD12β, so the polynomials cannot be dense in D12β. In this case, we need to consider higher order derivatives.

    From the discussion above, we see that the density of polynomials in D(φ(D),(1|φ1|2)12βdA) for 1/2<β<1 implies that φ is a weak-star generator of H. On the other hand, φ being a weak-star generator of H implies that the polynomials are dense in the Dirichlet spaces D and D(φ(D),(1|φ1|2)12βdA) for all β1/2.

    It is intriguing for us to find some relationship between the density of R(Cφ) on two different spaces D12β1 and D12β2 for 1/2<β1,β2<1. We already know that if Cφ has dense range in D12β for some 1/2<β<1, then φ must be a weak-star generator of H, which implies that φ is univalent on the closed unit disc ¯D. However, this does not imply that the polynomials are dense in D(φ(D),(1|φ1|2)12βdA) for all 1/2<β<1. In fact, for any given 1/2<β1<β2<1 we can find an analytic self-map of D such that φD12β1D12β2. Then the polynomials are not dense in D(φ(D),(1|φ1|2)12β2dA) but they are dense in D(φ(D),(1|φ1|2)12β1dA). Hence, there exists an analytic self-map φ of D such that Cφ has dense range in D12β1 but does not have dense range in D12β2. This also shows that φ being a weak-star generator of H does not imply that polynomials are dense in D(φ(D),(1|φ1|2)12βdA) for all 1/2<β<1.

    It is well-known that if φ is a weak-star generator of H, then the polynomials are dense in the Bergman space A2(φ(D)), but the converse is not true in general. The following theorem gives a condition for the converse to hold for certain analytic self-maps of D.

    Theorem 13. Suppose 1/2<β<1 and φD12β is an analytic map-self of D such that the polynomials are dense in A2(φ(D)). Then the following statements are equivalent to each other:

    (i) {Cφp:pis a polynomial} is dense in A212β.

    (ii) φ is a weak-star generator of H.

    (iii) φ is univalent on the open unit disc.

    Proof. If {Cφp:p is a polynomial} is dense in A212β, then φ is clearly univalent on D by the beginning of the proof of Theorem 6. This shows that (i) implies (iii).

    To prove that (iii) implies (ii), assume that φD12β is univalent on the open unit disc. Then φ is also univalent on the closed unit disc by Corollary 3.5 in [3] and the continuity of φ on ¯D. Thus, φ1 is continuous on ¯φ(D). By Lemma 9, there is a sequence {pk} of polynomials such that pk converges uniformly to φ1. Then pkφ converges uniformly to f(z)=z. This implies that φ is a weak-star generator of H since z is the weak-star generator of H.

    Finally, let us assume that (ii) holds. Then for any fH there exists a sequence {pk} of polynomials such that pk(φ(z))φ(z)f(z) pointwise on D and {pk} is bounded. By the dominated convergence theorem, we have CφpkfA212β0 as k. This shows that (ii) implies (i) and completes the proof of the theorem.

    Choosing β=0 and β=±1/2 in Theorem 6, we see that, for univalent functions φ:DD, R(Cφ) is dense in A2(D) if and only if the polynomials are dense in A2(φ(D),(1|φ1|2)2dA), R(Cφ) is dense in H2(D) if and only if the polynomials are dense in A2(φ(D),(1|φ1|2)dA) (see [3]), and R(Cφ) is dense in D if and only if the polynomials are dense in A2(φ(D)) (see [7]).

    Closely related to these discussions, we mention the following result of Hedberg from [25].

    Theorem 14. If f is in the Bergman space A2 and if f is the derivative of a univalent function, then f is a cyclic vector for A2. Equivalently, if φD is univalent, then H(φ(D)) is dense in A2(φ(D)).

    The proof of Theorem 14 in [25] is quite technical. If φ is univalent and (φ1) can be approximated by polynomials on φ(D), we will give a simpler proof for the density of H(φ(D)) in A2(φ(D)). The above condition about (φ1) seems natural because, as the (normalized) area of D=φ1(φ(D)), we have

    φ(D)|(φ1)|2dA=1.

    Thus, (φ1)A2(φ(D)).

    Proposition 15. Suppose φ is an analytic self-map of D and φD. Then the function z belongs to ¯R(Cφ) in D if and only if φ is univalent and (φ1) can be approximated by polynomials in A2(φ(D)).

    Proof. If φ is univalent and there is a sequence {pk} of polynomials such that

    φ(D)|(pk(φ1))(w)|2dA(w)0,

    then

    φ(D)|(pk(φ1))(w)|2dA(w)=D|pk(φ(z))(φ1)(φ(z))|2|φ(z)|2dA(z)=D|pk(φ(z))φ(z)(φ1)(φ(z))φ(z)|2dA(z)=D|pk(φ(z))φ(z)1|2dA(z)0

    as k. Write

    qk(z)=z0pk(u)du,k1.

    Then qk is also a polynomial for each k and

    (Cφqk)(z)=(φ(z)0pk(u)du)=pk(φ(z))φ(z).

    Thus

    D|(Cφqk)1|2dA(z)0,k,

    so the function z belongs to ¯R(Cφ) in D.

    Conversely, if the function z is in the closure of R(Cφ) in D, then φ is obviously univalent (see the beginning of the proof of Theorem 6), and reversing the calculations above implies that there is a sequence {pk} of polynomials such that

    φ(D)|(pk(φ1))(w)|2dA(w)0

    as k. This ends the proof.

    The following result gives a simpler proof for Hedberg's theorem (i.e., Theorem 14) under an additional assumption.

    Proposition 16. Suppose φ is an analytic self-map of D and φD. If the function z belongs to ¯R(Cφ) in D, then H(φ(D)) is dense in A2(φ(D)).

    Proof. Assume ˜fA2(φ(D)). Once again, z¯R(Cφ) implies that φ is univalent. Thus, there is an fA2(D) such that

    ˜f(w)=f(φ1(w))(φ1)(w).

    Let pk be the k-th partial sum of the Taylor series of f. Then

    pkfA20,k.

    By the formula of changing variables,

    (pkφ1)(φ1)˜fA2(φ(D))0,k.

    Since z¯R(Cφ), it follows from Proposition 15 that there is a sequence {qn} of polynomials such that qn converges to (φ1) in A2(φ(D)). For any ϵ>0 choose K0 such that

    (pkφ1)(φ1)˜fA2(φ(D))<ϵ2forkK0.

    Choose a positive integer N such that

    (pK0φ1)(qn(φ1))A2(φ(D))<ϵ2fornN.

    Then for nN we have

    (pK0φ1)qn˜fA2(φ(D))(pK0φ1)qnpK0φ1(φ1)A2(φ(D))+pK0φ1(φ1)˜fA2(φ(D))<ϵ.

    This shows that H(φ(D)) is dense in A2(φ(D)).

    Theorem 17. Suppose 1/2<β<1 and φ is a univalent analytic self-map of D with φD12β. If Cφ has dense range in D12β, then φ is a cyclic vector for both Mβz and Mβφ on D12β.

    Proof. Define

    Eφ:A2(φ(D),(1|φ1|2)12βdA)A212β

    by

    Eφ(f)(z)=(fφ)(z)φ(z).

    Similarly, define

    Eφ1:A212βA2(φ(D),(1|φ1|2)12βdA)

    by

    Eφ1(f)(w)=(fφ1)(w)(φ1)(w).

    Direct calculation shows that both Eφ and Eφ1 are isometric operators and

    EφEφ1=IA212β,Eφ1Eφ=IA2(φ(D),(1|φ1|2)12βdA),

    are identity operators. Thus, for any function fA212β there is a function ˜fA2(φ(D),(1|φ1|2)12βdA) such that f(z)=˜f(φ(z))φ(z).

    Assume {pk} is a sequence of polynomials such that

    φ(D)|pk(w)˜f(w)|2(1|φ1|2)12βdA(w)0,k.

    Then

    D|pk(φ)(z)φ(z)f(z)|2(1|z|2)12βdA(z)=D|pk(φ)(z)φ(z)˜f(φ(z))φ(z)|2(1|z|2)12βdA(z)=D|pk(φ(z))˜f(φ(z))|2|φ(z)|2(1|z|2)12βdA(z)=φ(D)|pk(w)˜f(w)|2(1|φ1|2)12βdA(w)0

    as k. Note pk(φ)(z)φ(z)=pk(Mφ)(φ)(z), this shows that φ is a cyclic vector of Mφ on D12β. By Proposition 10, φ is also a cyclic vector of Mz on D12β.

    In this paper, we show that Cφ has dense range in H2β if and only if the polynomials are dense in a certain Dirichlet space D(G,(1|φ1|2)12βdA) for 1/2<β<1(see Theorem 6). It follows that if the range of Cφ is dense in H2β, then φ is a weak-star generator of H(see Theorems 12 and 13). Moreover, the relation between the density of the range of Cφ and the cyclic vector of the multiplier Mβφ is studied(see Theorem 17).

    The author would like to thank the referees for their helpful comments and suggestions. This work was supported by National Natural Science Foundation of China (Grant No. 11871170).

    The author declares no conflicts of interest in this paper.



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