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Research article

Existence of radial solutions for k-Hessian system

  • Received: 25 June 2023 Revised: 04 September 2023 Accepted: 06 September 2023 Published: 15 September 2023
  • MSC : 35A01, 35A09, 35A24, 35A35

  • In this paper, we consider the existence of radial solutions to a k-Hessian system in a general form. The existence of radial solutions is obtained under the assumptions that the nonlinearities in the given system satisfy k-superlinear, k-sublinear or k-asymptotically linear at the origin and infinity, respectively. The results presented in this paper generalize some known results. Examples are given for the illustration of the main results.

    Citation: Hongliang Gao, Liyuan Wang, Jiemei Li. Existence of radial solutions for k-Hessian system[J]. AIMS Mathematics, 2023, 8(11): 26498-26514. doi: 10.3934/math.20231353

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  • In this paper, we consider the existence of radial solutions to a k-Hessian system in a general form. The existence of radial solutions is obtained under the assumptions that the nonlinearities in the given system satisfy k-superlinear, k-sublinear or k-asymptotically linear at the origin and infinity, respectively. The results presented in this paper generalize some known results. Examples are given for the illustration of the main results.



    In this paper, we consider the existence of radial solutions for the following k-Hessian system

    {Sk(σ(D2z1))=λf(|x|,z1,z2), in Ω,Sk(σ(D2z2))=μg(|x|,z1,z2), in Ω,z1=z2=0, on Ω, (1.1)

    where λ,μ are positive parameters, Ω={xRN:|x|<1}, kN<2k, the nonlinear terms f and g are nonnegative continuous functions, Sk(σ(D2z)) is the k-Hessian operator of z, k=1,2,,N. From a discrete perspective, the k-Hessian operator has the form

    Sk(σ(D2z))=1kNi,j=1(Sijkzi)j,

    where Sijk=Sk(σ(D2z))zij, see details in [1,2].

    In general, the k-Hessian operator is defined as

    Sk(σ(D2z))=Pk(Λ)=1j1<<jkNλj1λj2λjk,    k=1,2,,N,

    where Λ=(λ1,λ2,,λN) are the eigenvalues of Hessian matrix D2z. In particular, when k=1, k-Hessian operator reduces to Laplace operator S1(σ(D2z))=Ni=1λi=z; when k=N, k-Hessian operator is Monge-Ampère operator SN(σ(D2z))=Ni=1λi=det(D2z). About Laplace problem and Monge-Ampère problem, there are a lot of brilliant papers, see [3,4,5,6,7].

    k-Hessian equations for k1 are fully nonlinear partial differential equations [8,9], which have important applications in fluid mechanics, geometric analysis and other disciplines [10,11,12]. For single k-Hessian equation, in recent years, many interesting results have been obtained by different methods, such as the monotone iterative method[13,14,15], upper and lower solution method[16,17] and different kinds of fixed point theorems[18,19,20]. However, there are few studies about k-Hessian system. In 2015, Zhang and Zhou [13] investigated the k-Hessian system

    {Sk(σ(D2z1))=p(|x|)f(z2), in Ω,Sk(σ(D2z2))=q(|x|)g(z1), in Ω,

    where p,q:[0,)(0,) are continuous, f,g:[0,)[0,) are continuous and increasing. The existence of entire positive radial solutions was obtained by using monotone iterative method. Recently, Yang and Bai[21] considered a class of more general k-Hessian system with parameters

    {Sk(σ(D2z1))=λp(|x|)f(z1,z2),  in Ω,Sk(σ(D2z2))=μq(|x|)g(z1,z2),  in Ω,z1=z2=0, on Ω.

    They were interested in the existence of at least one or two k-convex radial solutions by analysing the growth of f and g at the origin and infinity.

    Some researchers focused on the blow-up radial solution of the k-Hessian equations, such as, Covei [14] established the necessary and sufficient conditions for the coupled k-Hessian system

    {S1kk(σ(D2z1))=p(|x|)f(z1,z2), in Ω,S1kk(σ(D2z2))=q(|x|)g(z1,z2), in Ω.

    For more results about blow-up solutions, we refer the reader to [22,23,24,25].

    Based on the above discussions, in this paper, we consider the existence of the radial solutions of the k-Hessian system (1.1). Three cases are considered for the growth of the nonlinear terms f and g, that is, k-superlinear, k-sublinear and k-asymptotically linear at the origin and infinity, respectively.

    The results obtained in this paper generalize and develop some known results from two aspects. The one is that the nonlinearities f and g have such more general form as f(|x|,z1,z2) and g(|x|,z1,z2) than the nonlinearity in [21], in which the nonlinear term is separable with the form H(|x|)f(z1,z2). The other one is, to the best of our knowledge, there are few results about the existence of the entire radial solutions for k-Hessian equations, especially for k-Hessian system. In [26], the authors only discussed the existence of solutions for the single k-Hessian equation. From this perspective, parts of our main results generalize the results in [26].

    The rest of the paper is organized as follows. In Section 2, we provide some preliminary results, which are useful in the following proof. In Section 3, under the conditions of k-superlinear or k-sublinear for nonlinear terms, the existence of solutions of (1.1) is obtained for any positive parameters λ and μ. For the case of k-asymptotically linear growth, the range of parameters is determined to ensure the existence of radial solutions of system (1.1). Four examples are given to verify some of our results in Section 4.

    In this section we will provide basic lemmas which are necessary for the understanding of subsequent results.

    Lemma 2.1. [27] Assume y(r)C2[0,1), with y(0)=0. Then for z(|x|)=y(r), r=|x|<1, we have that z(|x|)C2(Ω), and

    σ(D2z)={(y(r),y(r)r,,y(r)r), r(0,1),(y(0),y(0),,y(0)), r=0,

    and then

    Sk(σ(D2z))={Ck1N1y(r)(y(r)r)k1+CkN1(y(r)r)k, r(0,1),CkN(y(0))k, r=0,

    where Ω={xRN:|x|<1} and  CkN=N!k!(Nk)!.

    Set space X=C[0,1]×C[0,1] with the norm (y1,y2)=y1+y2, where denotes the max norm in C[0,1]. It is well known that the space (X,) is a Banach space. For any θ(0,12), the cone K is defined by

    K={(y1,y2)X y1,y20, minr[θ,1θ](y1(r)+y2(r))θ(y1+y2)}.

    Throughout the paper, we assume that

    (H) f,g:[0,1]×[0,)×[0,)[0,) are continuous.

    Define the operator T:XX as follows

    T(y1,y2)(r)=(T1(y1(r),y2(r)),T2(y1(r),y2(r))),

    for any (y1,y2)X, and Ti:XC[0,1], (i=1,2) be the operators

    T1(y1(r),y2(r))=1r(ktNkt0sN1Ck1N1λf(s,y1(s),y2(s))ds)1kdt,T2(y1(r),y2(r))=1r(ktNkt0sN1Ck1N1μg(s,y1(s),y2(s))ds)1kdt.

    Now we can claim that the radial solutions of system (1.1) is equivalent to the fixed point of the operator T in Banach space X. In fact, set (z1(|x|),z2(|x|))=(y1(r),y2(r)) with y1(0)=y2(0)=0. According to Lemma 2.1, system (1.1) can be transformed into the ordinary differential boundary value problems

    {Ck1N1y1(r)(y1(r)r)k1+CkN1(y1(r)r)k=λf(r,y1(r),y2(r)), 0<r<1,Ck1N1y2(r)(y2(r)r)k1+CkN1(y2(r)r)k=μg(r,y1(r),y2(r)), 0<r<1,y1(0)=0, y2(0)=0, y1(1)=0, y2(1)=0. (2.1)

    Noticed that CkN1=NkkCk1N1, the left side of the first equation of (2.1) can be reduced to

    Ck1N1y1(r)(y1(r)r)k1+CkN1(y1(r)r)k=Ck1N1rN1{rNkk(y1(r))k},

    then the first equation of (2.1) can be rewritten as

    {rNkk(y1(r))k}=rN1Ck1N1λf(r,y1(r),y2(r)).

    Furthermore, integrating the above equation twice, we have

    y1(r)=1r(ktNkt0sN1Ck1N1λf(s,y1(s),y2(s))ds)1kdt,   0<r<1. (2.2)

    Similarly, from the second equation of (2.1) and boundary value conditions, we can get

    y2(r)=1r(ktNkt0sN1Ck1N1μg(s,y1(s),y2(s))ds)1kdt,   0<r<1. (2.3)

    Combining (2.2), (2.3) and the definition of operators T1, T2 and T, we can conclude that the radial solutions of system (1.1) is equivalent to the fixed point of the operator T in Banach space X. In addition, standard arguments show that the operator T:KK is completely continuous.

    Lemma 2.2. [28] Let X be a Banach space and KX be a cone in X. Assume Ω1,Ω2 are open subsets of X with 0Ω1, ¯Ω1Ω2 and

    T:K(¯Ω2Ω1)K

    is a completely continuous operator such that either

    (1) Tyy, yKΩ1 and Tyy, yKΩ2

    or

    (2) Tyy, yKΩ1 and Tyy, yKΩ2.

    Then T has a fixed point in K(¯Ω2Ω1).

    For the convenience, we firstly introduce some notation

    f0=lim infy1+y20minr[θ,1θ]f(r,y1,y2)(y1+y2)k, f=lim infy1+y2minr[θ,1θ]f(r,y1,y2)(y1+y2)k,g0=lim infy1+y20minr[θ,1θ]g(r,y1,y2)(y1+y2)k, g=lim infy1+y2minr[θ,1θ]g(r,y1,y2)(y1+y2)k,f0=lim supy1+y20maxr[0,1]f(r,y1,y2)(y1+y2)k, f=lim supy1+y2maxr[0,1]f(r,y1,y2)(y1+y2)k,g0=lim supy1+y20maxr[0,1]g(r,y1,y2)(y1+y2)k, g=lim supy1+y2maxr[0,1]g(r,y1,y2)(y1+y2)k.

    Here we are in the position of our main results.

    Theorem 3.1. Assume (H) holds, f0=g0=0, f= or g=. Then, for all λ,μ(0,), the k-Hessian system (1.1) has at least one radial solution.

    Proof. Let L1=k2kN(NCkN)1k. Since f0=g0=0, we can choose J1>0 such that

    f(r,y1,y2)ε(y1+y2)k,   g(r,y1,y2)ε(y1+y2)k,

    for r[0,1], 0<y1+y2J1, where ε>0 satisfies

    L1(λεN)1k12,    L1(μεN)1k12.

    Set

    Ω1={(y1,y2)X |(y1,y2)<J1}.

    Then, for any (y1,y2)KΩ1, we have

    T1(y1,y2)(r)=1r(ktNkt0sN1Ck1N1λf(s,y1(s),y2(s))ds)1kdt10(ktNk10sN1Ck1N1λf(s,y1(s),y2(s))ds)1kdt=k2kN(NCkN)1k(10sN1λf(s,y1(s),y2(s))ds)1kL1(λε10sN1ds)1k(y1+y2)(y1,y2)2, r[0,1].

    Therefore, we have

    T1(y1,y2)(y1,y2)2. (3.1)

    Similarly, we can get

    T2(y1,y2)(y1,y2)2. (3.2)

    Combining inequalities (3.1) and (3.2), for (y1,y2)KΩ1, we have

    T(y1,y2)=T1(y1,y2)+T2(y1,y2)(y1,y2).

    For any θ(0,12), denote

    L2=k2kN(NCkN)1k(1(1θ)2kNk).

    Next, considering f=, an analogous estimate holds if g=. There is ˆJ>0 such that

    f(r,y1,y2)δ(y1+y2)k, (3.3)

    for any r[θ,1θ], y1+y2ˆJ, where δ>0 satisfies

    θL2(λδ1θθsN1ds)1k>1.

    Let J2=max{2J1,1θˆJ} and

    Ω2={(y1,y2)X|(y1,y2)<J2}.

    If (y1,y2)KΩ2, then

    minr[θ,1θ](y1(r)+y2(r))θ(y1+y2).

    Furthermore, from the above inequality and (3.3), we have

    T1(y1,y2)(1θ)=11θ(ktNkt0sN1Ck1N1λf(s,y1(s),y2(s))ds)1kdt11θ(ktNk1θθsN1Ck1N1λf(s,y1(s),y2(s))ds)1kdt=k2kN(NCkN)1k(1(1θ)2kNk)(1θθsN1λf(s,y1(s),y2(s))ds)1kθL2(λδ1θθsN1ds)1k(y1+y2)(y1,y2).

    Therefore, if (y1,y2)KΩ2, then

    T(y1,y2)=T1(y1,y2)+T2(y1,y2)(y1,y2).

    By part (1) of Lemma 2.2, system (1.1) has at least one radial solution.

    Theorem 3.2. Assume (H) holds, f=g=0, f0= or g0=. Then, for all λ,μ(0,), the k-Hessian system (1.1) has at least one radial solution.

    Proof. Considering f0=, an analogous estimate holds if g0=. We can choose J3>0 such that

    f(r,y1,y2)η(y1+y2)k,   r[θ,1θ], 0<y1+y2J3, (3.4)

    where η>0 satisfies

    θL2(λη1θθsN1ds)1k>1,

    here the positive constant L2 is defined the same as in proof of Theorem 3.1.

    Set

    Ω3={(y1,y2)X|(y1,y2)<J3}.

    For any (y1,y2)KΩ3, according to (3.4), we can get

    T1(y1,y2)(1θ)=11θ(ktNkt0sN1Ck1N1λf(s,y1(s),y2(s))ds)1kdt11θ(ktNk1θθsN1Ck1N1λf(s,y1(s),y2(s))ds)1kdt=k2kN(NCkN)1k(1(1θ)2kNk)(1θθsN1λf(s,y1(s),y2(s))ds)1kθL2(λη1θθsN1ds)1k(y1+y2)(y1,y2),

    furtheremore, we have

    T(y1,y2)=T1(y1,y2)+T2(y1,y2)(y1,y2).

    In order to construct Ω4, we define two new functions

    F(r,t)=max0y1+y2tf(r,y1,y2),  G(r,t)=max0y1+y2tg(r,y1,y2),

    it is easy to see F(r,t) and G(r,t) are nondecreasing about variable t. From the definitions of f and g and the expressions of F and G, it can be seen that the following two limits are valid according to f=g=0,

    limtmaxr[0,1]F(r,t)tk=0,  limtmaxr[0,1]G(r,t)tk=0,

    therefore, there is a constant J4>2J3, such that

    F(r,t)ρtk,   G(r,t)ρtk,  tJ4,  0r1,

    for ρ>0 satisfying

    L1(λρN)1k12,   L1(μρN)1k12,

    here positive constant L1 is defined the same as in proof of Theorem 3.1.

    Set

    Ω4={(y1,y2)X|(y1,y2)<J4}.

    For any (y1,y2)KΩ4, we have

    T1(y1,y2)(r)=1r(ktNkt0sN1Ck1N1λf(s,y1(s),y2(s))ds)1kdt10(ktNk10sN1Ck1N1λf(s,y1(s),y2(s))ds)1kdt10(ktNk10sN1Ck1N1λF(s,J4)ds)1kdt=k2kN(NCkN)1k(10sN1λF(s,J4)ds)1kL1J4(λρ10sN1ds)1k(y1,y2)2,  r[0,1].

    Therefore, we have

    T1(y1,y2)(y1,y2)2. (3.5)

    Similarly, we can get

    T2(y1,y2)(y1,y2)2. (3.6)

    Combining inequalities (3.5) and (3.6), for (y1,y2)KΩ4, one has

    T(y1,y2)=T1(y1,y2)+T2(y1,y2)(y1,y2).

    By part (2) of Lemma 2.2, system (1.1) has at least one radial solution.

    Let

    L3=k2kN(1CkN)1k,   L4=k2kN(1θθsN1ds)1k(NCkN)1k(1(1θ)2kNk).

    Theorem 3.3. Assume (H) holds, f0, g0, f, g(0,), f>f0 and g>g0. Then, for each λ(1Lk4fθk,1Lk3f02k) and μ(1Lk4gθk,1Lk3g02k), the k-Hessian system (1.1) has at least one radial solution.

    Proof. Let λ and μ be given in (3.7). Now, let ε>0 be chosen, such that

    1Lk4(fε)θkλ1Lk3(f0+ε)2k (3.7)

    and

    1Lk4(gε)θkμ1Lk3(g0+ε)2k. (3.8)

    Since f0, g0(0,), for ε>0, there exists J5>0, such that

    f(r,y1,y2)(f0+ε)(y1+y2)k,   g(r,y1,y2)(g0+ε)(y1+y2)k, (3.9)

    for r[0,1], 0<y1+y2J5. Therefore, choosing (y1,y2)K with (y1,y2)=J5, one gets

    T1(y1,y2)(r)=1r(ktNkt0sN1Ck1N1λf(s,y1(s),y2(s))ds)1kdt10(ktNk10sN1Ck1N1λf(s,y1(s),y2(s))ds)1kdtk2kN(NCkN)1k(10sN1λ(f0+ε)(y1(s)+y2(s))kds)1kλ1kk2kN(NCkN)1k(10sN1ds)1k(f0+ε)1k(y1,y2)=λ1kk2kN(1CkN)1k(f0+ε)1k(y1,y2)=λ1kL3(f0+ε)1k(y1,y2)(y1,y2)2, r[0,1].

    Therefore, we have

    T1(y1,y2)(y1,y2)2. (3.10)

    Similarly, we can get

    T2(y1,y2)(y1,y2)2. (3.11)

    Combining (3.11) and (3.12), we can get

    T(y1,y2)=T1(y1,y2)+T2(y1,y2)(y1,y2).

    Therefore, if we set

    Ω5={(y1,y2)X|(y1,y2)<J5},

    then, for (y1,y2)KΩ5,

    T(y1,y2)(y1,y2).

    In view of f(0,), for ε>0, there is ˉJ>0, such that

    f(r,y1,y2)(fε)(y1+y2)k,  r[θ,1θ], y1+y2ˉJ.

    Let J6=max{2J5,1θˉJ} and set

    Ω6={(y1,y2)X|(y1,y2)<J6}.

    If (y1,y2)K with (y1,y2)=J6, then

    minr[θ,1θ](y1(r)+y2(r))θ(y1+y2)ˉJ.

    From the above inequality and (3.10), we have

    T1(y1,y2)(1θ)=11θ(ktNkt0sN1Ck1N1λf(s,y1(s),y2(s))ds)1kdt11θ(ktNk1θθsN1Ck1N1λf(s,y1(s),y2(s))ds)1kdtk2kN(NCkN)1k(1(1θ)2kNk)(1θθsN1λ(fε)(y1(s)+y2(s))kds)1kλ1kk2kN(NCkN)1k(1(1θ)2kNk)(1θθsN1ds)1k(fε)1kθ(y1,y2)=λ1kL4(fε)1kθ(y1,y2)(y1,y2).

    Furthermore, T(y1,y2)=T1(y1,y2)+T2(y1,y2)(y1,y2). System (1.1) has at least one radial solution for the given λ and μ due to Lemma 2.2.

    Similarly, we can also prove T(y1,y2)(y1,y2) if g(0,). This completes the proof.

    Theorem 3.4. Assume (H) holds, f0,g0,f,g(0,), f0>f and g0>g. Then, for each λ(1Lk4f0θk,1Lk3f2k) and μ(1Lk4g0θk,1Lk3g2k), the k-Hessian system (1.1) has at least one radial solution.

    Proof. Let λ and μ be given in (3.13). Now, let ε>0 be chosen, such that

    1Lk4(f0ε)θkλ1Lk3(f+ε)2k (3.12)

    and

    1Lk4(g0ε)θkμ1Lk3(g+ε)2k. (3.13)

    For f0(0,), an analogous estimate holds for g0(0,), there exists positive constant J7, for r[θ,1θ],0<y1+y2J7, such that

    f(r,y1,y2)(f0ε)(y1+y2)k.

    Therefore, choosing (y1,y2)K with (y1,y2)=J7, one gets from (3.14)

    T1(y1,y2)(1θ)=11θ(ktNkt0sN1Ck1N1λf(s,y1(s),y2(s))ds)1kdtk2kN(NCkN)1k(1θθsN1λ(f0ε)(y1(s)+y2(s))kds)1kθλ1kk2kN(NCkN)1k(1(1θ)2kNk)(1θθsN1ds)1k(f0ε)1k(y1,y2)=θL4λ1k(f0ε)1k(y1,y2)(y1,y2).

    Thus, if we set

    Ω7={(y1,y2)X|(y1,y2)<J7},

    then, for (y1,y2)KΩ7, we have

    T(y1,y2)=T1(y1,y2)+T2(y1,y2)(y1,y2).

    In order to construct Ω8, for t0, we define two new functions

    F(r,t)=max0y1+y2tf(r,y1,y2),    G(r,t)=max0y1+y2tg(r,y1,y2).

    It is easy to see F(r,t) and G(r,t) are nondecreasing about variable t. From the definitions of f and g and the expressions of F and G, it can be seen that the following two limits are valid according to f(0,) and g(0,),

    limtmaxr[0,1]F(r,t)tk=f,    limtmaxr[0,1]G(r,t)tk=g.

    Therefore, there is a constant J8>2J7, such that

    F(r,t)(f+ε)tk,  G(r,t)(g+ε)tk,  tJ8,  0r1,

    where ε>0 satisfying

    L3λ1k(f+ε)1k12,  L4μ1k(g+ε)1k12.

    Set

    Ω8={(y1,y2)X|(y1,y2)<J8},

    for any (y1,y2)KΩ8, we have

    T1(y1,y2)(r)=1r(ktNkt0sN1Ck1N1λf(s,y1(s),y2(s))ds)1kdt10(ktNk10sN1Ck1N1λf(s,y1(s),y2(s))ds)1kdt10(ktNk10sN1Ck1N1λF(s,J8)ds)1kdt=k2kN(NCkN)1k(10sN1λF(s,J8)ds)1kJ8L3λ1k(f+ε)1k(y1,y2)2, r[0,1].

    Therefore, we have

    T1(y1,y2)(y1,y2)2. (3.14)

    Similarly, we can get

    T2(y1,y2)(y1,y2)2. (3.15)

    Combining (3.16) and (3.17), for (y1,y2)KΩ8, we can get

    T(y1,y2)=T1(y1,y2)+T2(y1,y2)(y1,y2).

    System (1.1) has at least one radial solution for the given λ and μ due to Lemma 2.2.

    Example 4.1. Consider the following 3-Hessian system

    {S3(σ(D2z1))=λ(|x|z1)(z1z2)5, in Ω,S3(σ(D2z2))=μ(|x|z1)sin4(z1z2), in Ω,z1=z2=0,  on Ω, (4.1)

    where Ω={xR4:|x|<1}. Similar to the transformation method in Section 2, the corresponding nonlinear terms in (4.1) have the following form

    f(r,y1,y2)=(r+y1)(y1+y2)5,  g(r,y1,y2)=(r+y1)sin4(y1+y2).

    Therefore, the nonlinear terms f and g are continuous functions. It is not difficult to check that f0=g0=0 and f=. Then, all the conditions of Theorem 3.1 are fulfilled, the conclusion follows, that is, for any positive parameters λ and μ, (4.1) has at least one radial solution.

    Example 4.2. Consider the following 4-Hessian system

    {S4(σ(D2z1))=λ(|x|z1z2), in Ω,S4(σ(D2z2))=μsin6(|x|z1z2), in Ω,z1=z2=0,  on Ω, (4.2)

    where Ω={xR5:|x|<1}. Similar to the transformation method in Section 2, the corresponding nonlinear terms of (4.2) have the following form

    f(r,y1,y2)=r+y1+y2,  g(r,y1,y2)=sin6(r+y1+y2).

    So, the nonlinear terms f and g are continuous functions. It is not difficult to check that f0= and f=g=0. Therefore, all the conditions of Theorem 3.2 are satisfied, the conclusion follows, that is, for any positive parameters λ and μ, (4.2) has at least one radial solution.

    Example 4.3. Consider the following 3-Hessian system

    {S3(σ(D2z1))=λf(|x|,z1,z2), in Ω,S3(σ(D2z2))=μg(|x|,z1,z2), in Ω,z1=z2=0, on Ω, (4.3)

    where Ω={xR4:|x|<1}, the nonlinearities f and g are given by

    f(|x|,z1,z2)={(z1z2)3arctan(|x|z1z2),   0z1z2<90,903arctan(|x|z1z2)[(913×41)(z1z290)+1],   90z1z2<91,9034(z1z2)3arctan(|x|z1z2),   z1z291,

    and

    g(|x|,z1,z2)={(z1z2)3sin2(|x|z1z2),     0z1z2<30,303sin2(|x|z1z2)+623×106(z1z230)arctan(|x|z1z2),   30z1z2<31,303sin2(|x|z1z2)+8×106arctan(|x|z1z2)(z1z2)3,    z1z231,

    respectively.

    In fact, similar to the transformation method in Section 2, the corresponding nonlinear terms in (4.3) have the following form

    f(r,y1,y2)={(y1+y2)3arctan(r+y1+y2),   0y1+y2<90,903arctan(r+y1+y2)[(913×41)(y1+y290)+1],   90y1+y2<91,9034(y1+y2)3arctan(r+y1+y2),   y1+y291,

    and

    g(r,y1,y2)={(y1+y2)3sin2(r+y1+y2),   0y1+y2<30,303sin2(r+y1+y2)+623×106(y1+y230)arctan(r+y1+y2),30y1+y2<31,303sin2(r+y1+y2)+8×106arctan(r+y1+y2)(y1+y2)3,   y1+y231.

    From the expressions of f and g, we can calculate

    f0=arctan1,  f=2903π,  g0=sin21,  g=4106π,

    so, f>f0 and g>g0. Then all the conditions of Theorem 3.3 hold.

    Furthermore, for fixed θ=14,

    L3=32(14)13,     L4=32(5128)13(1(34)23).

    Therefore, it follows from Theorem 3.3 that (4.3) has at least one radial solution for any λ(150, 37200) and μ(3400,10).

    Example 4.4. Consider the following 3-Hessian system

    {S3(σ(D2z1))=λf(|x|,z1,z2), in Ω,S3(σ(D2z2))=μg(|x|,z1,z2), in Ω,z1=z2=0, on Ω, (4.4)

    where Ω={xR4:|x|<1}, the nonlinearities f and g are given by

    f(|x|,z1,z2)={(z1z2)3(cos(|x|z1z2)+200),   0z1z2<30,303(cos(|x|z1z2)+200)+(z1z230)arctan(|x|z1z2),   30z1z2<31,303(cos(|x|z1z2)+200)+arctan(|x|z1z2)(z1z2)3,   z1z231,

    and

    g(|x|,z1,z2)={(z1z2)3(sin(|x|z1z2)+200),   0z1z2<30,303(sin(|x|z1z2)+200)+(z1z230)arctan(|x|z1z2),   30z1z2<31,303(sin(|x|z1z2)+200)+arctan(|x|z1z2)(z1z2)3,   z1z231,

    respectively.

    As a matter of fact, similar to the transformation method in Section 2, the corresponding nonlinear terms in (4.4) have the following form

    f(r,y1,y2)={(y1+y2)3(cos(r+y1+y2)+200),   0y1+y2<30,303(cos(r+y1+y2)+200)+31(y1+y230)arctan(r+y1+y2),   30y1+y2<31,303(cos(r+y1+y2)+200)+arctan(r+y1+y2)(y1+y2)3,   y1+y231,

    and

    g(r,y1,y2)={(y1+y2)3(sin(r+y1+y2)+200),   0y1+y2<30,303(sin(r+y1+y2)+200)+31(y1+y230)arctan(r+y1+y2),   30y1+y2<31,303(sin(r+y1+y2)+200)+arctan(r+y1+y2)(y1+y2)3,   y1+y231.

    From the expressions of f and g, we can calculate

    f0=g0=200,  f=g=π2,

    so, f0>f and g0>g. Then all the conditions of Theorem 3.4 are fulfilled.

    Furthermore, for fixed θ=14,

    L3=32(14)13,     L4=32(5128)13(1(34)23).

    Therefore, it follows from Theorem 3.4 that (4.4) has at least one radial solution for any λ(1100, 21250) and μ(1100, 21250).

    In this paper, a class of k-Hessian system with parameter is concerned. we are interested in the range of parameters λ and μ on which there exists at least one radial solution. By using the Guo-Krasnosel'skii fixed point theorem, we find that there is a close relation between the range of parameters and the growth of nonlinearities f and g at the origin and infinity. The results obtained in this paper generalize and develop some of the known results, such as, parts of the results in [21,26] from two sides. The one is that the more general form of nonlinearities f and g is investigated here. The other is that there are no existence results for k-Hessian system under the conditions that nonlinearities f and g satisfy k-superlinear, k-sublinear and k-asymptotically linear conditions at the origin and infinity. Finally, we also illustrate the obtained results with four examples.

    The authors declare they have not used Artificial Intelligence (AI) tools in the creation of this article.

    This work is supported by the NSFC (No. 11801243) and the Innovation Ability Improvement Project of Universities of Gansu (No. 2019B-054), China.

    The authors declare no conflict of interest.



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