Research article

Existence and multiplicity of solutions for Schrödinger equations with sublinear nonlinearities

  • Received: 13 January 2021 Accepted: 09 March 2021 Published: 17 March 2021
  • MSC : 35A15, 35J60, 58E05

  • In the paper, we investigate a class of Schrödinger equations with sign-changing potentials V(x) and sublinear nonlinearities. We remove the coercive condition on V(x) usually required in the existing literature and also weaken the conditions on nonlinearities. By proving a Hardy-type inequality, extending the results in [1], and using it together with variational methods, we get at least one or infinitely many small energy solutions for the problem.

    Citation: Ye Xue, Zhiqing Han. Existence and multiplicity of solutions for Schrödinger equations with sublinear nonlinearities[J]. AIMS Mathematics, 2021, 6(6): 5479-5492. doi: 10.3934/math.2021324

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  • In the paper, we investigate a class of Schrödinger equations with sign-changing potentials V(x) and sublinear nonlinearities. We remove the coercive condition on V(x) usually required in the existing literature and also weaken the conditions on nonlinearities. By proving a Hardy-type inequality, extending the results in [1], and using it together with variational methods, we get at least one or infinitely many small energy solutions for the problem.



    In this paper, we are devoted to studying the existence and multiplicity of solutions for the following Schrödinger equation with a sublinear nonlinearity,

    Δu+V(x)u=K(x)f(u), xRN, (1.1)

    where N3, V is sign-changing, K is positive and fC(R). We remove the coercive condition usually imposed on V(x) and obtain the existence of at least one or infinitely many small energy solutions to (1.1) for sublinear nonlinearities K(x)f(u).

    As mentioned in [1,10,12], this type of equations is essentially related to seeking for the standing waves ψ(t,x)=eiωtu(x) for the time-dependent Schrödinger equation,

    itΨ=ΔΨ+U(x)Ψg(x,Ψ), xRN, tR, (1.2)

    where the potential V is given by V(x)=U(x)ω. Hence V may be indefinite in sign for large ω(see [1,23]).

    Much attention has been paid on the following equation,

    Δu+V(x)u=f(x,u), xRN, N3, (1.3)

    involving a continuous term V(x). We refer, for instance, to [2,3,4,5,6,7,8,11,14,15,17,18,19,20,22,23] and the references therein. It is known to all that the main difficulty in dealing with problem (1.3) arises from the lack of the compactness of Sobolev embeddings, which prevents from checking directly that the energy functional associated with (1.3) satisfies the PS-condition.

    To obtain the compactness in RN, some feasible methods are provided in the existing papers. For example, Bartsch, Pankov and Wang [6] have studied a class of Schrödinger equations, where V(x) is continuous function verifying the following conditions,

    (v1) essinfV(x)>0;

    (v2) for any M>0, there exists x0 such that lim|y|meas({xRN:|xy|x0, V(x)M})=0,

    where meas devotes the Lebesgue measure on RN. Under conditions (v1) and (v2), the compactness of Sobolev embedding can be recovered. With the assumptions (v1) and (v2), equation (1.3) has been investigated by the variational methods by [6] and some other authors.

    In [22], the authors studied a class of sublinear Schrödinger equations, where f(x,u)=ξ(x)|u|μ2u with 1<μ<2 and ξ(x):RNR being a positive continuous function. Under conditions (v1) and (v2), they established a theorem on the existence of infinitely many small energy solutions.

    The results of [22] were improved in the recent paper [7], where they improved the results of [22] by removing assumption (v2) and relaxing the assumptions on f(x,t). By using the genus properties in critical point theory, they established some existence criteria to guarantee that the problem has at least one or infinitely many nontrivial solutions.

    In [8], for problem (1.3), Cheng and Wu studied a sublinear problem and used conditions on V(x) below:

    (V1) VC(RN) is bounded below; 

    (V2) for every M>0, meas {x:V(x)M}<.

    Under some additional conditions of f, two theorems are obtained in [8]. One theorem states that equation (1.3) possesses at least one nontrivial solution. By using a variant fountain theorem, they obtained the existence of infinitely many small energy solutions in another theorem.

    Bao and Han [4] also considered a nonlinear sublinear Schrödinger equation,

    Δu+V(x)u=a(x)|u|μ2u, xRN, (1.4)

    where V(x)L(RN) is sign-changing and a(x)L(RN) with a(x)>0 a.e. in RN. Under some conditions on V(x) and by using bounded domain approximation technique, infinitely many small energy solutions are obtained.

    In those above papers, (v2), (V2) or the coercive condition on V plays an important role in obtaining the compact embedding. In this paper, we remove the coercive condition of V(x) and also weaken the conditions on f.

    We remark that there have been many interesting results for the similar sublinear problems (1.1) but on bounded domains ΩRN. We refer to [13] for some results for pLaplacian equation problems and the references therein.

    Before stating our main results, we make some assumptions, where V+(x)=max{V(x),0}, V(x)=max{V(x),0}.

    (K1) K(x)>0, xRN and K(x)L(RN).

    (V1) V=V+V, where V+L1(RN,R), VLN2(RN,R).

    Ω={xRN| V(x)<0},

    measΩ>0 and there exists a large constant R0 such that V(x)>0  for a.e. |x|R0.

    (V2) There exists a constant η0>1 such that

    η1:=infuH1(RN){0}RN|u|2dx+RNV+u2dxRNVu2dxη0.

    (KV) K|V|L(RN).

    (f1) fC(R) and there exist constants τ1,τ2(1,2) with τ1<τ2 such that

    0f(u)u|u|τ1+|u|τ2  for all uR.

    (f2) F(u)C|u|τ1, uR, where C is some positive constant, F(u)=u0f(τ)dτ.

    Remark 1.1. Conditions similar to (V2) can be found in [9] and [16]. By condition (V1) and the Hölder and Sobolev inequalities,

    RN|u|2+V+(x)|u|2dxRNV(x)|u|2dxRN|u|2dx|V|N2|u|22RN|u|2dxS1|V|N2RN|u|2dx=S|V|N2, (1.5)

    where S is the best constant for the Sobolev embedding of D1,2(RN)L2(RN) and 2=2NN2. It implies that if |V|N2<S, then μ1S|V|N2>1. Hence, (V2) is satisfied for V(x) with sufficiently small |V|N2.

    By (V2) and a simple calculation,

    RN|u|2+V+|u|2dxRN|u|2+V|u|2dxη01η0(RN|u|2+V+|u|2dx). (1.6)

    More details on condition (V2) can be found in [9].

    Theorem 1.2. Assume that conditions (K1), (V1), (V2), (KV), (f1) and (f2) hold. Then Eq (1.1) possesses at least one nontrivial solution.

    Theorem 1.3. Assume that conditions (K1), (V1), (V2), (KV), (f1) and (f2) hold. Moreover, f(u)=f(u), uR. Then equation (1.1) possesses infinitely many small energy solutions.

    We emphasize that the conditions on V(x) in this paper are essentially different from those in [8] and [22]. In fact, we are dealing with the vanishing potentials V(x). As far as we know, for problem (1.1) with sublinearity, few works in this case seem to have appeared in the literature. Since V(x) is sign-changing and vanishing, it seems not to be obvious from the literature to obtain the compactness suitable to deal with the problem. By proving a Hardy-type inequality, which extends the results in [1], we can obtain the needed compactness. Our theorems also extend the results in [8,22] and our hypotheses on nonlinearities are more general.

    The paper is organized as follows. In Section 2, we introduce the variational setting and state some preliminary results which will be needed later. In Section 3, the proofs of our main results are given.

    In this paper, we define

    E={uD1,2(RN):RNV+(x)|u|2dx<}.

    We know E is a separable Hilbert space with the inner product

    u,v=RN(uv+V+(x)u(x)v(x))dx

    and the norm u=u,u12. Let LqK(RN) be the weighted space of measurable functions u:RNR satisfying

    |u|K,q=[RNK(x)|u|qdx]1q<+.

    Denote Lq(RN) with

    |u|q=[RN|u|qdx]1q<+,

    where 1q<+. And set

    u=ess supxRN|u(x)|,  uL(RN).

    It is well known that the embedding ELs(RN)(2s2) is continuous.

    Now we give a Hardy-type inequality which extends the one in [1] and is suitable for dealing with our sublinear problems. Before stating the result, we recall condition (A),

    (A) if {An}RN is a sequence of Borel sets such that |An|R for some R>0 and all n, then

    limrAnBcr(0)K(x)dx=0, uniformly in nN. (2.1)

    As stated in [1], if KL1(RNBρ(0)) for some ρ>0, we know that K satisfies condition (A).

    Lemma 2.1. Suppose that (K1), (V1) and (KV) hold. Then E is compactly embedded in LrK(RN) for r(1,2].

    Proof. By (V1) and noticing that V+L1, for any ε>0, we can choose Rε>R0 such that

    RNBRεV(x)dx=RNBRεV+(x)dx<ε2. (2.2)

    Fixed 1<r2. For given ε, there are 0<T0ε<Tε and Cε>0 such that, for a.e. |x|Rε,

    K(x)|s|rCε(V(x)|s|+|s|2)+CεK(x)χ(T0ε,Tε)|s|2, sRN. (2.3)

    Hence,

    BcRε(0)K(x)|u|rdxCε(BcRε(0)V(x)|u|dx+BcRε(0)|u|2dx)+CεT2εABcRε(0)K(x)dx, uE, (2.4)

    where

    A={xRN:T0ε|u(x)|Tε}.

    If {vn} is a sequence such that vnv in E, then there is M>0 such that

    RN(|vn|2+V+(x)|vn|2)dxM2  (2.5)

    and

    RN|vn|2dxM2, nN. (2.6)

    It follows that

    BcRε|vn|2dx<M2 (2.7)

    and

    BcRε(0)V+(x)|vn|dx[RNV+(x)|vn|2dx]12[BcRε(0)V+(x)]12Mε. (2.8)

    Thus, by (V1), (2.7) and (2.8), we obtain that

    BcRε(0)V(x)|vn|dx+BcRε(0)|vn|2dx=BcRε(0)V+(x)|vn|dx+BcRε(0)|vn|2dxMε+M2. (2.9)

    By (2.2) and (KV), we have

    RNBRεK(x)dx=RNBRεK(x)V(x)V(x)dxCRNBRεV(x)dx<Cε. (2.10)

    Furthermore, set

    An={xRN:T0ε|vn(x)|Tε}. (2.11)

    By (2.6),

    (T0ε)2|An|An|vn|2dxM2, nN, (2.12)

    that is,

    supnN|An|<+. (2.13)

    Therefore, by (2.1), (2.10) and (2.13), there is a constant ˉRε>0 such that

    AnBcˉRε(0)K(x)dx<εCεT2ε,  for all nN. (2.14)

    Hence, for ˆRε=max{ˉRε,Rε}, (2.4), (2.9) and (2.14) lead to

    BcˆRε(0)K(x)|vn|rdxCε(BcˆRε(0)V(x)|vn|dx+BcˆRε(0)|vn|2)+CεT2εAnBcˆRε(0)K(x)dxCε(BcRε(0)V(x)|vn|dx+BcRε(0)|vn|2)+CεT2εAnBcˉRε(0)K(x)dxCε(Mε+M2)+εˆCε, nN. (2.15)

    Furthermore, for that ε>0 and large n, it is easy to obtain that

    BˆRε(0)K(x)(|vn|r|v|r)dx<ε. (2.16)

    Therefore, from (2.15) and (2.16), we obtain that

    |RNK(x)(|vn|r|v|r)dx|=|BˆRε(0)K(x)(|vn|r|v|r)dx|+|BcˆRε(0)K(x)(|vn|r|v|r)dx|BˆRε(0)K(x)||vn|r|v|r|dx+BcˆRε(0)K(x)|vn|rdxˉCε, (2.17)

    which completes the proof.

    Lemma 2.2. (Lemma 2.13 [21]) Let V(x)LN2(Ω) and suppose that unuinE. Then

    ΩV(x)|un|2dxΩV(x)|u|2dx. (2.18)

    Lemma 2.3. Suppose that (K1), (V1) and (KV) hold. Then the functional J:ER defined by

    J(u)=12u212RNV(x)|u|2dxRNK(x)F(u)dx (2.19)

    is well defined and belongs to C1(E,R). Moreover,

    J(u),v=u,vRNV(x)uvdxRNK(x)f(u)vdx. (2.20)

    Proof. By (V1) and Lemma 2.13 in [21], we know RNV(x)|u|2dx is well defined for uE. By virtue of (f1),

    |F(u)|C|u|τ1+C|u|τ2. (2.21)

    Hence, by Lemma 2.1, we get

    RNK(x)|F(u)|dxCRN(K(x)|u|τ1+K(x)|u|τ2)dxCuτ1+Cuτ2, (2.22)

    which means that J is well defined for uE.

    By a direct computation, it is not difficult to prove that (2.20) holds. Furthermore, by a standard argument, we obtain that the critical points of J in E are solutions of problem (1.1).

    Finally, we will show that J(u) is weakly continuous, that is, if unu in E, then

    J(un)J(u),v0, vE. (2.23)

    Arguing directly, by unu in E, choose a subsequence {unk} of {un} such that unk(x)u(x) a.e. in RN and Q1(x)L2K(RN), where

    Q1(x)=(Σk=1|unk(x)u(x)|2)12.

    It is clear that

    K(x)|f(unk)f(u)|22K(x)(|f(unk)|2+|f(u)|2)42i=1(K(x)|unk|2(τi1)+K(x)|u|2(τi1))=42i=1(K(x)|unku+u|2(τi1)+K(x)|u|2(τi1))2i=1C(τi)(K(x)|unku|2(τi1)+K(x)|u|2(τi1))2i=1C(τi)[K(x)Q2(τi1)1(x)+K(x)|u|2(τi1)]. (2.24)

    Write Q2(x)=2i=1C(τi)[K(x)Q2(τi1)1(x)+K(x)|u|2(τi1)]. By (V1) and (KV), we obtain that KL1(RN). By 1τi1>1 and 12τi>1, one has

    RNQ2(x)dx=2i=1C(τi)RN[K(x)Q2(τi1)1(x)+K(x)|u|2(τi1)]dx=2i=1C(τi)RNK(τi1)+(2τi)(x)Q2(τi1)1dx+2i=1C(τi)RNK(τi1)+(2τi)(x)|u|2(τi1)dx2i=1C(τi)(RNK(x)Q21dx)τi1(RNK(x)dx)2τi+2i=1C(τi)(RNK(x)u2dx)τi1(RNK(x)dx)2τi2i=1C(τi)[|Q1|2(τi1)K,2(RNK(x)dx)2τi+|u|2(τi1)K,2(RNK(x)dx)2τi]<. (2.25)

    This together with Lebesgue's Dominated Convergence Theorem implies that

    limnRNK(x)|f(un)f(u)|2dx=0. (2.26)

    Therefore, for any vE,

    J(un)J(u),v=|unu,vRNV(x)(unu)vdxRNK(x)|f(unk)f(u)|vdx||unu,v|+RNV(x)|(unu)v|dx+C(RNK(x)|f(unk)f(u)|2dx)12v0, as n.

    Hence, J(u) is weakly continuous in E. The proof is complete.

    Definition 2.4. (PS condition) Let E be a Banach space, cR and JC1(E,R). The function J is said to satisfy the (PS)c-condition on E if any (PS)c-sequence {un} such that

    J(un)c and J(un)0,as n

    has a strongly convergent subsequence in E.

    Let {ej} be an orthonormal basis of the Hilbert space E and define Xj=Rej, Yk=kj=1Xj, Zk=¯j=kXj. For the statement of Dual Fountain Theorem, we need the following condition. More details can be found in [21].

    (A1) A compact group G acts isometrically on the Hilbert space E=¯jNXj, the spaces Xj are invariant and there exists a finite dimensional space V such that, for every jN,XjV and the action of G on V is admissible.

    Lemma 2.5. (Theorem 3.18 in [21] Dual Fountain Theorem, Bartsch-Willem, 1995) Assume that condition (A1) holds and let JC1(E,R) be an invariant functional. If, there exist two sequences 0<rk<ρk0 as k and the following conditions (D1)(D4) hold, then J has a sequence of negative critical values converging to 0, where

    (D1) ak:=infuZk,u=ρkJ(u)0;

    (D2) bk:=maxuYk,u=rkJ(u)<0;

    (D3) dk:=infuZk,uρkJ(u)0 as k;

    (D4) for every c[dk,0), J satisfies the (PS)c condition, that is, every sequence unjE satisfying

    unjYnj,J(unj)c, J|Ynj(unj)0,nj

    contains a subsequence converging to a critical point of J.

    Lemma 3.1. Assume that conditions (K1), (V1), (V2), (KV) and (f1) hold. Then the functional J is coercive and bounded below on E.

    Proof. It is obvious to obtain that

    J(u)=12u212RNV(x)|u|2dxRNK(x)F(u)dxη012η0u2cuτ1cuτ2. (3.1)

    Since τ1,τ2(1,2), the above inequality implies that J is coercive and bounded below on E.

    By Lemma 3.1 and Ekeland's variational method, there exists a minimizing sequence {un} such that

    J(un)infEJ  and J(un)0, as n.

    By Lemma 3.1, it is clear that the minimizing sequence {un} is bounded in E.

    Lemma 3.2. Assume that conditions (K1), (V1), (V2), (KV) and (f1) hold. Then there exists a strong convergent subsequence of the minimizing sequence {un}.

    Proof. By Lemma 3.1, the minimizing sequence {un} is bounded. Passing to a subsequence, one has

    {unu in E,unuin L2K(RN),un(x)u(x) a.e. in RN. (3.2)

    By a direct computation, we derive that

    unu2=J(un)J(u),unu+RNV(x)|unu|2dx+RNK(x)(f(un)f(u))(unu)dx. (3.3)

    By Lemma 2.2, RNV(x)|unu|2dx0. It is obvious that J(un)J(u),unu0. Thus, it is enough to show

    RNK(x)(f(un)f(u))(unu)dx0, as n.

    We can see that

    |RNK(x)(f(un)f(u))(unu)dx||RNK(x)f(un)(unu)+K(x)f(u)(unu)dx|RN(K(x)|f(un)(unu)|+K(x)|f(u)(unu)|)dx. (3.4)

    Since 2τi2+12+τi12=1, i=1,2, we have

    RNK(x)|f(un)(unu)|dx=RNK(x)|(|un|τ11+|un|τ21)(unu)|dx2i=1(RNK(x)dx)2τi2|un|τi1K,2|unu|K,2. (3.5)

    This together with (3.2), for large n, we obtain that RNK(x)|f(un)(unu)|<Cε. Similarly, for that ε and large n, RNK(x)|f(u)(unu)|dxε. The proof is complete.

    Proof of Theorem 1.2. Assume that conditions (K1), (V1), (V2), (KV), (f1) and (f2) hold. Then the limit u0 of the minimizing sequence {un} is nontrivial.

    Proof. We will argue directly. First, we take a subspace ˆE of E with dimˆE<. By Lemma 2.1 and a similar discussion to the proof of Lemma 2.4 in Zhang and Wang [22](see (5) of Lemma 3.1 in [20]), there exists a constant κ>0 such that

    meas{x:K(x)|u(x)|τ1κuτ1,  uˆE}κ. (3.6)

    We consider the sets Λ={x:K(x)F(u)κuτ1, uˆE} and Ω={x:K(x)|u(x)|τ1κuτ1, uˆE}. By (f2), we obtain that ΩΛ. Hence, meas(Λ)meas(Ω)κ. Then for any fixed uˆE{0} and s>0, it follows from (f2) that

    J(su)12su2RNK(x)F(su)dx12su2Λκsuτ1dx12su2κsuτ1meas(Λ)12s2u2κ2sτ1uτ1. (3.7)

    Since 1<τ1<2, J(su)<0 for s sufficient small and uE{0}. Since J is coercive and by Lemma 3.2, we obtain that

    J(u0)=infEJ(u)<0,

    which implies that u00.

    Now, we show that the energy functional J has the geometric properties in Lemma 2.5 under the conditions of Theorem 1.3.

    Lemma 3.3. Assume that conditions (K1), (V1), (V2), (KV), (f1) and (f2) hold. Moreover, f(u)=f(u),uR. Then there exists a sequence 0<ρk (ρk0 ask) such that

    ak:=infuZk,u=ρkJ(u)0.

    Proof. By (V2) and (f1), we obtain that

    J(u)=12u212RNV(x)|u|2dxRNK(x)F(u)dxη012η0u2c|u|τ1K,τ1c|u|τ2K,τ2. (3.8)

    Let

    βk,τi:=supuZk,u=1|u|K,τi, i=1,2, kN.

    Based on Lemma 3.8 in [21] and Lemmas 2.1, βk,τi0,i=1,2, as k. We have that

    J(u)η012η0u2cβτ1k,τ1uτ1cβτ2k,τ2uτ2=u2(η012η0cβτ1k,τ1uτ12cβτ2k,τ2uτ22). (3.9)

    Choose u=ρk:=(η0η01)12τ1[8cβτ1k,τ1+(η0η01)2τ12τ21(8cβτ2k,τ2)2τ12τ2]12τ1. By the definition of ρk, a direct computation implies

    cβτ1k,τ1ρτ12k=cβτ1k,τ1η0η01[8cβτ1k,τ1+(η0η01)2τ12τ21(8cβτ2k,τ2)2τ12τ2]η018η0 (3.10)

    and

    cβτ2k,τ2ρτ22k=cβτ2k,τ2(η0η01)2τ22τ1[8cβτ1k,τ1+(η0η01)2τ12τ21(8cβτ2k,τ2)2τ12τ2]2τ22τ1η018η0. (3.11)

    Then, we get

    J(u)ρ2k(η012η0cβτ1k,τ1ρτ12kcβτ2k,τ2ρτ22k)ρ2kη01η0(1214)=η014η0ρ2k>0. (3.12)

    Thus, for every k, uZk and u=ρk, we have ak0. Since βk,τ1,βk,τ20 as k, it follows that ρk0 as k.

    Lemma 3.4. Assume that conditions (K1), (V1), (V2), (KV), (f1) and (f2) hold. Moreover, f(u)=f(u),uR. Then there exists a sequence rk0<rk<ρk, rk0 ask such that

    bk:=maxuYk,u=rkJ(u)<0.

    Proof. Noticing that Yk is of finite dimension for each kN. By a similar discussion to the proof of Theorem 1.2, it follows from (f1) and (f2) that

    J(u)12u2RNK(x)F(u)dx12u2Λκuτ1dx12u2κ2uτ1=uτ1(12u2τ1κ2). (3.13)

    Choosing u:=rk=min{(κ2)12τ1,12ρk}, we obtain 0<rk<ρk and 12u2τ1κ2=12κ2<0 for un=rk. Hence, for each k, we have bk<0. This completes the proof.

    Lemma 3.5. Assume that conditions (K1), (V1), (V2), (KV), (f1) and (f2) hold. Moreover, f(u)=f(u),uR. Then it holds that

    dk:=infuZk,uρkJ(u)0ask.

    Proof. For uZk, uρk, we derive that

    J(u)12u2RNK(x)F(u)dx12u212ρ2k. (3.14)

    On the other hand, by (3.9), we obtain that

    J(u)=12u212RNVu2dxRNK(x)F(u)dxη012η0u2cβτ1k,τ1uτ1cβτ2k,τ2uτ2cβτ1k,τ1ρτ1kcβτ2k,τ2ρτ2k. (3.15)

    Since βk,τ10, βk,τ20 and ρk0 as k, it follows from (3.14) and (3.15) that

    dk:=infuZk,uρkJ(u)0 as k.

    This proof is complete.

    Proof of Theorem 1.3. We just need to prove the (PS)c condition. Consider a sequence {unj} such that

    nj, unjYnj,
    J(unj)c, J|Ynj(unj)0.

    For the proof of boundedness of {unj}, arguing indirectly, unj+, as nj+. It follows that J|Ynj(unj)0, that is,

    η01η0unj2RN|unj|2+V(x)|unj|2dx=RNK(x)f(unj)unjdx (3.16)

    and for 1<τ1<τ2<2, we derive that

    η01η0RNK(x)f(unj)unjdxunj2|unj|τ1K,τ1+|unj|τ2K,τ2unj2Cuτ1+Cuτ2unj2=Cunj2τ1+Cunj2τ20, (3.17)

    as j, which is contradiction. Therefore, we derive that {unj} is bounded in E.

    Since {unj} is bounded in E, by Lemma 2.1, we get that the sequence {unj} has strong convergent subsequence in E. Passing to a sequence, we suppose that unjuk in E. Thus, by Lemma 2.5, for each k, {uk} is a critical point of J and J(uk)0, as k. Hence, (1.1) possesses infinitely many small energy solutions. The proof of Theorem 1.3 is complete.

    The authors declare no conflict of interest.



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