We investigate the existence of nodal solutions for the nonlinear Lidstone boundary value problem
{(−1)m(u(2m)(t)+cu(2m−2)(t))=λa(t)f(u), t∈(0,r),u(2i)(0)=u(2i)(r)=0, i=0,1,⋯,m−1, (P)
where λ>0 is a parameter, c is a constant, m≥1 is an integer, a:[0,r]→[0,∞) is continuous with a≢0 on the subinterval within [0,r], and f:R→R is a continuous function. We analyze the spectrum structure of the corresponding linear eigenvalue problem via the disconjugacy theory and Elias's spectrum theory. As applications of our spectrum results, we show that problem (P) has nodal solutions under some suitable conditions. The bifurcation technique is used to obtain the main results of this paper.
Citation: Meng Yan, Tingting Zhang. Existence of nodal solutions of nonlinear Lidstone boundary value problems[J]. Electronic Research Archive, 2024, 32(9): 5542-5556. doi: 10.3934/era.2024256
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We investigate the existence of nodal solutions for the nonlinear Lidstone boundary value problem
{(−1)m(u(2m)(t)+cu(2m−2)(t))=λa(t)f(u), t∈(0,r),u(2i)(0)=u(2i)(r)=0, i=0,1,⋯,m−1, (P)
where λ>0 is a parameter, c is a constant, m≥1 is an integer, a:[0,r]→[0,∞) is continuous with a≢0 on the subinterval within [0,r], and f:R→R is a continuous function. We analyze the spectrum structure of the corresponding linear eigenvalue problem via the disconjugacy theory and Elias's spectrum theory. As applications of our spectrum results, we show that problem (P) has nodal solutions under some suitable conditions. The bifurcation technique is used to obtain the main results of this paper.
We investigate the existence of nodal solutions for nonlinear Lidstone boundary value problem
{(−1)m(u(2m)(t)+cu(2m−2)(t))=λa(t)f(u), t∈(0,r),u(2i)(0)=u(2i)(r)=0, i=0,1,⋯,m−1, | (1.1) |
where λ>0 is a parameter, c is a constant, m≥1 is an integer, a:[0,r]→[0,∞) is continuous with a≢0 on the subinterval within [0,r], and f:R→R is a continuous function.
Problem (1.1) is called a Lidstone boundary value problem. Lidstone boundary value problems arise in a lot of various fields of applied mathematics and physics. If m=1, problem (1.1) are Newton's equations of motion under Dirichlet boundary conditions. If m=2, problem (1.1) is the elastic beam equation with simple support at both ends. If m=3, problem (1.1) can be used to describe the speed of a flagellate protozoan [1]. From this point of view, it is not only of great theoretical significance to discuss such problems, but also of practical application value.
Lidstone boundary value problems in a comparable form to (1.1) have been taken into account in many papers, particularly in second and fourth-order cases, see for example [2,3,4,5,6] and [7,8,9,10] and references therein. Specifically, Lazer and McKenna [10] considered the existence for nodal solutions of (1.1) with m=2, a(t)≡1, and a "jumping" nonlinearity, i.e.,
{u⁗(t)+cu″=λ[(u+1)+−1], t∈(0,r),u(0)=u(r)=u″(0)=u″(r)=0. | (1.2) |
The eigenvalues of the linear eigenvalue problem corresponding to (1.2) can be obtained directly by ordinary differential equation calculation, but for the linear eigenvalue problem with weighted function a(t), the eigenvalues cannot be calculated. In addition, it is worth noting that a complicated method was used in [10] (see Lemma 2.2) to certify that all zeros of the solutions are simple, moreover, this method does not seem to apply in the case of m>2.
Existence and multiplicity of positive solutions for 2mth-order Lidstone boundary value problems have been extensively studied by several authors, see [11,12,13,14,15,16,17]. For example, Yuan et al. [17] considered the existence of a positive solution for the 2mth-order Lidstone boundary value problem
{(−1)mu(2m)(t)=λf(t,u(t)), t∈(0,1),u(2i)(0)=u(2i)(1)=0, i=0,1,⋯,m−1 | (1.3) |
by the fixed point theorem of mixed monotone operators. However, relatively little is known about the existence of nodal solutions for 2mth-order Lidstone boundary value problems, see [18,19]. In [19], Xu and Han dealt with the existence of nodal solutions of Lidstone boundary value problems with the assumption that the nonlinearity f is asymptotically linear
{(−1)mu(2m)(t)=μa(t)f(u), t∈(0,1),u(2i)(0)=u(2i)(1)=0, i=0,1,⋯,m−1 | (1.4) |
under these suppositions:
(A1) a∈C([0,1],[0,∞)), a≢0 on subinterval within [0,1];
(A2) f∈C(R,R), f(s)s>0 for s≠0;
(A3) there exist f0,f∞∈(0,∞) such that
lim|s|→0f(s)s=f0, lim|s|→∞f(s)s=f∞. |
Let μk be the kth eigenvalue of the linear eigenvalue problem associated with (1.4). By using bifurcation techniques, they obtained
Theorem A. [19,Theorem 1.1.] Let (A1)–(A3) hold. Assume that for some k∈N, either
μkf∞<μ<μkf0, |
or
μkf0<μ<μkf∞. |
Then, (1.4) possesses two solutions, namely u+k and u−k. The solution u+k has precisely k−1 simple zeros within the interval (0,1) and is positive in the vicinity of 0. Similarly, u−k also has exactly k−1 simple zeros in (0,1) and is negative near 0.
However, the more general operator (−1)m(u(2m)(t)+cu(2m−2)(t)) and "jumping" nonlinearity are not considered in [19].
Inspired by [10] and [19], the main purpose of this paper is to analyze the existence of nodal solutions for problem (1.1). One of the contributions of this paper is to employ the disconjugacy theory to examine a sufficient condition that guarantees the disconjugacy of (−1)m(u(2m)(t)+cu(2m−2)(t))=0 on the interval [0,r]. In addition, it is probably the first time that we utilize Elias's spectrum theory to explore the spectrum structure of the linear operator (−1)m(u(2m)(t)+cu(2m−2)(t))=λa(t)u, t∈(0,r) coupled with the boundary conditions u(2i)(0)=u(2i)(r)=0, i=0,1,⋯,m−1. Moreover, we use a bifurcation technique to obtain the existence of nodal solutions for problem (1.1). It is worth noting that a novel method is employed to prove that all zeros of the solution of problem (1.1) are simple, which is based on the well-known Uri Elias formula, see [20,21].
The assumptions of this paper are as follows:
(H1) c is a constant with c<π2r2;
(H2) a∈C([0,r],[0,∞)) and a≢0 on subinterval within [0,r];
(H3) f∈C(R,R), f(s)s>0 for s≠0,
lims→−∞f(s)s=0, lims→+∞f(s)s=f+∞, lims→0f(s)s=f0 |
for some f+∞,f0∈(0,∞). Using the disconjugacy theory and Elias's spectrum theory, we first consider the spectrum structure of the linear eigenvalue problem
{(−1)m(u(2m)(t)+cu(2m−2)(t))=λa(t)u, t∈(0,r),u(2i)(0)=u(2i)(r)=0, i=0,1,⋯,m−1. | (1.5) |
Theorem 1.1. Assume that (H1) is satisfied, and a satisfies (H2). Then,
(i) There is an infinite series of positive eigenvalues for problem (1.5)
λ1[c]<⋯<λk[c]<⋯. |
(ii) λk[c]→∞ as k→∞.
(iii) For each eigenvalue λk[c], there is an essentially unique eigenfunction φk. This eigenfunction φk has exactly k−1 simple zeros within the interval (0,r) and is positive in the vicinity of 0.
(iv) For an arbitrary subinterval within [0,r], an eigenfunction corresponding to a sufficiently large eigenvalue will undergo a sign change in that subinterval.
(v) For every k∈N, the algebraic multiplicity for λk[c] is 1.
According to Theorem 1.1, we employ bifurcation theory to acquire our main results.
Theorem 1.2. Let (H1), (H2), (A2), and (A3) hold. Suppose that for k∈N, either
λk[c]f∞<λ<λk[c]f0, |
or
λk[c]f0<λ<λk[c]f∞. |
Then, (1.1) possesses two solutions, namely u+k and u−k. The solution u+k has precisely k−1 simple zeros within the interval (0,r) and is positive in the vicinity of 0. Similarly, u−k also has exactly k−1 simple zeros in (0,r) and is negative near 0.
Remark 1.1. If c=0 and r=1, then Theorem 1.2 is transformed into Theorem 1.1 in [19].
Furthermore, we consider the case of the "jumping" nonlinearity.
Theorem 1.3. Assume (H1)–(H3) hold. When λ>λk[c]f0, there exist at least 2k−1 non-trivial solutions of the boundary value problem (1.1). Indeed, there are solutions w−1,⋯,w−k, such that, for each 1≤j≤k, w−j has exactly j−1 simple zeros on the open interval (0,r) and is negative close to 0. Also, there are solutions z+2,⋯,z+k such that for each 2≤j≤k, z+j has precisely j−1 simple zeros on the open interval (0,r) and is positive close to 0.
Remark 1.2. If m=2, a(t)≡1, f(u)=(u+1)+−1, then Theorem 1.3 is transformed into Theorem 1 in [10].
Example 1.1. Let a(t)=sinπrt and c<π2r2. We consider the existence of nodal solutions for sixth order boundary value problem
{−u′′′′′′(t)−cu⁗(t)=λsinπrtf(u), t∈(0,r),u(0)=u(r)=u″(0)=u″(r)=u⁗(0)=u⁗(r)=0, | (1.6) |
where
f(u)={−4, u<−2,2u, −2≤u≤2,6u−8, u>2. |
It is easy to verify that
limu→−∞f(u)u=0, limu→+∞f(u)u=6, limu→0f(u)u=2. |
Then, the conditions of Theorem 1.3 are fulfilled. Therefore, when λ>λk[c]f0, there exist at least 2k−1 non-trivial solutions of the boundary value problem (1.6). Indeed, there are solutions w−1,⋯,w−k, such that, for each 1≤j≤k, w−j has exactly j−1 simple zeros on the open interval (0,r) and is negative close to 0. Also, there are solutions z+2,⋯,z+k such that for each 2≤j≤k, z+j has precisely j−1 simple zeros on the open interval (0,r) and is positive close to 0.
The remainder of this paper is structured as follows. Section 2 is dedicated to demonstrating the spectrum results of the linear eigenvalue problem (1.5). In Section 3, we study the existence of nodal solutions for the nonlinear problem (1.1) under some suitable conditions via bifurcation theory.
Definition 2.1. [22] Let pk∈C[a,b] for k=1,...,n. A linear differential equation of order n
Ly≡y(n)+p1(t)y(n−1)+⋯+pn(t)y=0 | (2.1) |
is regarded as disconjugate on an interval [a,b] if every non-trivial solution possesses less than n zeros on [a,b], where multiple zeros are accounted for in accordance with their multiplicity.
Definition 2.2. [22] The functions y1,⋯,yn∈Cn[a,b] are claimed to form a Markov system when the n Wronskians
Wk:=W[y1,⋯,yk]=|y1⋯yk⋯⋯⋯y(k−1)1⋯y(k−1)k|, (k=1,⋯,n) |
are positive on [a,b].
Lemma 2.1. [22] Equation (2.1) possesses a Markov fundamental system of solutions on [a,b] when and only when it is disconjugate on [a,b].
Lemma 2.2. [22] Equation (2.1) possesses a Markov fundamental system of solutions when and only when L has a representation
Ly≡v1v2⋯vnD1vnD⋯D1v2D1v1y, |
where D=d/dt, and
1=W0, v1=W1, vk=WkWk−2/W2k−1, (k=2,⋯,n). |
Example 2.1. For every M∈(−m40,m41), the equation u⁗(t)+Mu(t)=0 is disconjugate on the interval [0,1], where m0,m1 are the first positive solution of the equations
cos(m)cosh(m)=1, tanhm√2=tanm√2 |
respectively. See [23] for details.
Example 2.2. For every M∈(−∞,2π), u‴+Mu′=0 is disconjugate on [0,1]. See [24] for details.
Elias [21] developed a theory on the eigenvalue problem
{Ly+λh(x)y=0,x∈[a,b],(Liy)(a)=0,i∈{i1,⋯,ik},(Ljy)(b)=0,i∈{j1,⋯,jn−k} | (2.2) |
where
L0y=ρ0yLiy=ρi(Li−1y)′,i=1,⋯,nLy=Lny |
and ρi∈Cn−i[a,b] with ρi>0 on [a,b]. L0y,⋯,Ln−1y are called the quasi-derivatives of y(x). To apply Elias's spectrum theory, we have to prove that problem (1.1) can be rewritten in the form of (2.2), i.e., the linear operator
L[u]:=u(2m)(t)+cu(2m−2)(t) |
has a factorization of the form
L[u]=v1v2v3⋯v2m(1v2m⋯(1v3(1v2(1v1u)′)′)′⋯)′ |
on [0,r], where vi∈C2m−i[0,r] with vi>0 on [0,r], and
u(2i)(0)=u(2i)(r)=0, i=0,1,⋯,m−1 |
if and only if
Liu(0)=Liu(r)=0, i=0,1,⋯,m−1. |
This can be achieved under (H1) by using the disconjugacy theory in [22].
Define a linear differential equation of order 2m
L[u]:=u(2m)(t)+cu(2m−2)(t)=0, t∈(0,r). |
Theorem 2.1. Let (H1) hold. Then, L[u] has a factorization
L[u]=v1v2v3⋯v2m(1v2m⋯(1v3(1v2(1v1u)′)′)′⋯)′, | (2.3) |
where vk∈C2m−k+1[0,r] with vk>0 \ (k=1,2,3,⋯,2m).
Proof. Take ϕ(t) as the unique solution of the initial value problem
ϕ″+cϕ=0,ϕ(0)=0, ϕ′(0)=1. |
Subsequently, (H1) along with the Sturm Comparison Theorem leads to the conclusion that
ϕ(t)>0,t∈(0,r], |
and therefore
ϕ(t+σ)>0,t∈[0,r], |
if σ>0 is small enough. Take
v1=1,v2=1,v3=1,v4=1,⋯ ⋯v2m−3=1,v2m−2=1,v2m−1=ϕ(t+σ),v2m=1ϕ2(t+σ). |
One can easily verify that (2.3) holds true.
At present, we are able to compute
L0u=1v1u=u |
L1u=1v2(L0u)′=u′ |
L2u=1v3(L1u)′=u″ |
⋯ |
L2m−3u=1v2m−2(L2m−4u)′=u(2m−3) |
L2m−2u=1v2m−1(L2m−3u)′=1ϕ(t+σ)u(2m−2) |
L2m−1u=1v2m(L2m−2u)′=u(2m−1)ϕ(t+σ)−u(2m−2)ϕ′(t+σ) |
L2mu=v1v2v3⋯v2m(L2m−1u)′=u(2m)(t)+cu(2m−2) |
Therefore, it is easy for us to reach the following conclusion.
Theorem 2.2. Let (H1) hold. Then,
u(2i)(0)=u(2i)(r)=0, i=0,1,⋯,m−1 |
is equivalent to
Liu(0)=Liu(r)=0, i=0,1,⋯,m−1. |
Remark 2.1. In [20], Rynne considered the boundary value problem
Lu(x)=p(x)u(x)+g(x)u(x), t∈(0,π). |
He assumes that L is a 2mth-order, disconjugate, ordinary differential operator on (0,π), together with separated boundary conditions at 0 and π. However, we give a constructive proof (Theorem 2.1.) to obtain that u(2m)(t)+cu(2m−2)(t)=0 is disconjugate on the interval [0,r] if and only if c<π2r2 in Theorem 2.1.
Currently, we are capable of applying Elias's spectrum theory to investigate the eigenvalue problem.
{(−1)m(u(2m)(t)+cu(2m−2)(t))=λa(t)u, t∈(0,r),u(2i)(0)=u(2i)(r)=0, i=0,1,⋯,m−1. | (2.4) |
The Proofs of Theorem 1.1. Items (i) to (iv) are direct consequences of Elias (as mentioned in Theorems 1–5 in reference [21]) as well as Theorems 2.1 and 2.2. We shall only provide a proof for (v). Let Y=C[0,r] be the Banach space which is equipped with the norm
||u||∞=maxt∈[0,r]|u(t)|. |
Define ˉL:D(ˉL)→Y by setting
ˉLu:=(−1)m(u(2m)(t)+cu(2m−2)(t)),u∈D(ˉL), | (2.5) |
where
D(ˉL)={u∈C2m[0,r]: u(2i)(0)=u(2i)(r)=0, i=0,1,⋯,m−1}. |
For simplicity, we define λk:=λk[c]. For demonstrating (v), it suffices to prove
ker(ˉL−λk)2=ker(ˉL−λk). |
Clearly,
ker(ˉL−λk)2⊇ker(ˉL−λk). |
Assume by contradiction that the algebraic multiplicity of λk is greater than 1. In that case, there exists a vector u that belongs to ker(ˉL−λk)2 but not to ker(ˉL−λk). Subsequently,
ˉLu−λku=γφk |
for some γ≠0. After multiplying both sides of the aforementioned equation by φk and integrating from 0 to r, we can infer that
0=γ∫r0[φk(t)]2dt, |
which is a contradiction.
Remark 2.2. Let a(t)=1. We consider the eigenvalue problem
{(−1)m(u(2m)(t)+cu(2m−2)(t))=λu(t), t∈(0,r),u(2i)(0)=u(2i)(r)=0, i=0,1,⋯,m−1, | (2.6) |
we see that the eigenvalues are λk=ηk⋯ηk⏟m−1(ηk−c) for k=1,2,⋯ with corresponding eigenfunctions φk(t)=sinkt, k=1,2,⋯ for c<π2r2, where {ηk}∞1 are the eigenvalues of the problem
{−y"=ηy, t∈(0,r),y(0)=y(r)=0. |
It is worth noting that the first eigenvalue η1=π2r2. Therefore, the eigenvalues of problem (2.6) are simple, the eigenfunctions have only simple zeros on (0,r), and the kth eigenfunction possesses exactly k−1 simple zeros on the open interval (0,r). If m=2, then problem (2.6) reduces to the situation in [10].
Theorem 2.3. Suppose that condition (H1) is satisfied. Take e∈C[0,r], e≥0 in [0,r] with e≢0 in [0,r]. If u∈C2m[0,r] satisfies
{(−1)m(u(2m)(t)+cu(2m−2)(t))=e(t), t∈(0,r),u(2i)(0)=u(2i)(r)=0, i=0,1,⋯,m−1, | (2.7) |
then u(t)>0 in (0,r).
Proof. Let Du=−u″. Then,
(−1)m(u(2m)(t)+cu(2m−2)(t))=D⋯D⏟m−1(D−cI)u. |
Let z1:=D⋯D⏟m−2(D−cI)u=(−1)m−1(u(2m−2)(t)+cu(2m−4)(t)). From (2.7), then we have that
−z1"=e, z1(0)=z1(r)=0, |
which implies
z1(t)>0, t∈(0,r). |
Repeating this procedure m−1 times, we obtain
−zm−1"=zm−2, zm−1(0)=zm−1(r)=0, |
which implies
zm−1(t)>0, t∈(0,r), |
where zm−1=(D−cI)u.
According to c<π2r2, we get
−u″−cu=zm−1, u(0)=u(r)=0. |
This together with zm−1(t)>0 implies that u(t)>0 for t∈(0,r).
Let E={u∈C2m−2[0,r]: u(2i)(0)=u(2i)(r)=0, i=0,1,⋯,m−1} be the Banach space which is equipped with the norm
||u||E=maxt∈[0,r]{||u(2i)||∞}, i=0,1,⋯,m−1. |
Then, ˉL−1:Y→E is completely continuous. Here, ˉL is presented as in (2.5).
Take ζ, ξ∈C(R,R) such that
f(u)=f0u+ζ(u),f(u)=f+∞u++ξ(u), |
where u+=max{u,0}. Clearly,
lim|u|→0ζ(u)u=0,lim|u|→∞ξ(u)u=0. | (3.1) |
Let
˜ξ(u)=max0≤|s|≤u |ξ(s)|. |
Then, ˜ξ is nondecreasing and
limu→∞˜ξ(u)u=0. | (3.2) |
Let us consider
ˉLu−λa(t)f0u=λa(t)ζ(u) | (3.3) |
as a bifurcation problem originating from the trivial solution u≡0.
Equation (3.3) can be equivalently transformed into
u(x)=λˉL−1[a(⋅)f0u(⋅)](t)+λˉL−1[a(⋅)ζ(u(⋅))](t). | (3.4) |
Obviously, the compactness of ˉL−1 combined with (3.1) indicates that
||ˉL−1[a(⋅)ζ(u(⋅))]||=o(||u||E)as ||u||E→0. |
In the following content, we adopt the terminology of Rabinowitz [25].
Let S+k represent the set of functions in E that possess exactly k−1 interior nodal (i.e., nondegenerate) zeros within the interval (0,r) and are positive in the vicinity of t=0. Set S−k=−S+k, and Sk=S+k∪S−k. These sets are disjoint and open in E. Let Σ denote the closure of the set consisting of nontrivial solutions of (3.4) in R×E.
Lemma 3.1. Suppose that (H1)–(H3) (or (A2) and (A3)) are satisfied. If u∈D(ˉL) is a nontrivial solution of
{(−1)m(u(2m)(t)+cu(2m−2)(t))=λa(t)f(u), t∈(0,r),u(2i)(0)=u(2i)(r)=0, i=0,1,⋯,m−1, | (3.5) |
then u has only simple zeros in (0,r). Thus, by definition, u∈Sk.
Proof. In fact, (3.5) can be rewritten as
ˉLu=λˆa(t)u |
where
ˆa(t)={a(t)f(u(t))u(t),as u(t)≠0,a(t)f0,as u(t)=0. |
Obviously, ˆa(t) meets (H2). Therefore, Lemma 2.2 of [20] implies that all zeros of u on the interval (0,r) are simple.
Remark 3.1. We say that u is a nodalsolution if all of zeros of the solution are simple. It is a challenging problem to prove that all zeros of the solution are simple, see [10,Lemma 2.2]. In this paper, a novel method is employed to prove that all zeros of the solution of problem (1.1) are simple, which is based on the well-known Uri Elias formula [20,21], see Lemma 3.1.
By the Rabinowitz global bifurcation theorem [25], there is a continuum Ck⊂Σ of solutions for (3.4) bifurcating from (λkf0,0) which is either unbounded or contains a pair (λjf0,0) for j≠k. By Lemma 1.24 of [25], it implies that if (λ,u)∈Ck and is near (λkf0,0), u=αφk+ω with ω=o(|α|). Since S±k is open and φk∈Sk, then
(Ck ∖ {(λkf0,0)}∩Bε(λkf0,0))⊂R×Sk, |
for all positive ε small enough, where
Bε(λkf0,0)={(λ,u)∈R×E:‖u‖+|λ−λkf0|<ε}. |
Define ^Ck=Ck−Bε(λkf0,0). Then, Lemma 3.1 implies that
^Ck⊂R×Sk. |
Otherwise, there exists (ˉλ,ˉu)∈ˆCk such that ˉλ>0 and ˉu is in the boundary of Sk. If ˉu=0, then ˉλ=λj for some j≠k, and so all points in ˆC+k near (λj,0) are in Sj, a contradiction. Hence, ˉu≠0. Since all the sets Sj,j=1,2,⋯, are open, it follows that there is t0∈[0,r] such that ˉu(t0)=ˉu′(t0)=0. But, this contradicts Lemma 3.1. Consequently, one has that
Ck⊂(R×Sk∪{(λkf0,0)}). |
It follows that Ck returning to the set of trivial solution axis is impossible. So, Ck is unbounded.
Furthermore, by Theorem 2 of [26], there exist two continua C+k and C−k composed of the bifurcation branch Ck which satisfy that either C+k and C−k are both unbounded or C+k∩C−k≠ {(λkf0,0)}. We know that u=αφk+ω for (λ,u)∈Ck ∖ {(λkf0,0)} near (λkf0,0). Since αφk∈S±k if 0≠α∈R± or R∓, we have that
(C±k ∖ {(λ1f0,0)}∩Bε(λ1f0,0))⊂R×S±k |
for all positive ε small enough. Similar to the above argument, we are able to demonstrate that C±k ∖ {(λkf0,0)} cannot depart from R×S±k outside a neighborhood of (λkf0,0). Therefore, we have that C±k⊂(R×S±k∪{(λkf0,0)}). It follows that both C+k and C−k are unbounded. Otherwise, at the expense of generality, we suppose that C−k is bounded. Then, there is (λ∗,u∗)∈C+k∩C−k such that (λ∗,u∗)≠(λkf0,0) and u∗∈S+k∩S−k. This contradicts the definitions of S+k and S−k.
The Proofs of Theorem 1.2. By applying a similar method as used to prove [19,Theorem 1.1], with appropriate and obvious modifications, we can obtain the desired result.
The Proofs of Theorem 1.3. We only need to show that
C−j∩({λ}×E)≠∅, j=1,2,⋯,k, |
and
C+j∩({λ}×E)≠∅, j=2,⋯,k. |
Suppose on the contrary that
Cνj∩({λ}×E)=∅ for some (j,ν)∈Γ, |
where
Γ:={(j,ν) | j∈{2,⋯,k} as ν=+, and j∈{1,2,⋯,k} as ν=− }. |
As Cνj joins (λkf0,0) to infinity in Σ, and since (λ,u)=(0,0) is the sole solution of (3.3) in E, there exists a sequence {(μm,um)}⊂Cνj such that μm∈(0,λ) and ‖um‖E→∞ as m→∞. We may assume that μm→ˉμ∈[0,λ] as m→∞. Let vm=um‖um‖E,m≥1. From the fact
ˉLum=μma(t)f+∞(um)++μma(t)ξ(um), |
we have that
vm=μmˉL−1(a(t)f+∞(vm)+)+μmˉL−1(a(t)ξ(um)‖um‖E). |
Therefore, since ˉL−1:E→E is completely continuous, it can be assumed that there is v∈E together with ‖v‖E=1 such that ‖vm→v‖E→0 as m→∞. According to
|ξ(um)|‖um‖E≤˜ξ(‖um‖∞)‖um‖E≤˜ξ(‖um‖E)‖um‖E, |
and (3.2), we have that
v=ˉμˉL−1(a(t)f+∞v+). | (3.6) |
i.e.,
{(−1)m(v(2m)(t)+cv(2m−2)(t))=ˉμa(t)f+∞v+, t∈(0,r),v(2i)(0)=v(2i)(r)=0, i=0,1,⋯,m−1. |
By (H1), (H2), (3.6), and the fact that ‖v‖E=1, we conclude that ˉμa(t)f+∞v+≢0, and consequently
ˉμ>0, v+≢0. |
According to Theorem 2.3, it is known that v(t)>0, t∈(0,r).
By Theorem 2.3, we know that v(t)>0 in (0,r). This implies that ˉμf+∞ is the first eigenvalue of ˉLu=λa(t)u and v is the corresponding eigenfunction of λ1. Hence, v∈S+1, and therefore, since S+1 is open and ‖v−vm‖E→0 as m→∞, we have that vm∈S+1 for m large. But, this contradicts the assumption that (λm,vm)∈Cνj and (j,ν)∈Γ. This proves Theorem 1.3.
Remark 3.2. In this paper, we consider the "jumping" nonlinearity, i.e.,
lims→−∞f(s)s=0, lims→+∞f(s)s=f+∞, lims→0f(s)s=f0 |
for some f+∞,f0∈(0,∞), which complements the main result in [19].
Remark 3.3. For the existence result of solutions for (1.1) with m=2, n≥1 (PDE case), see [27,28,29,30]. For other results on the Lidstone BVPs, see [31,32,33].
The authors declare they have not used Artificial Intelligence (AI) tools in the creation of this article.
This paper was supported by National Natural Science Foundation of China (No.12061064 and No.12361040). The authors would like to thank the editor and the anonymous reviewers for their helpful suggestions.
The authors declare there is no conflicts of interest.
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