Research article

Global solutions to the Cauchy problem of BNSP equations in some classes of large data

  • Received: 25 June 2024 Revised: 05 September 2024 Accepted: 12 September 2024 Published: 26 September 2024
  • In this paper, we obtained the global existence and large time behavior of the solution for bipolar Navier-Stokes-Poisson equations under the partially smallness assumption of the initial data. Due to the complexity of bipolar Navier-Stokes-Poisson equations, we chose Green's function method instead of the classical energy method and thus discussed the regularity criterion under decaying structures in time instead of only integrability of time variable. It made the whole proof more simple and clear, meanwhile, resulted in the large time decaying estimates of the solution. It also showed the advantage of Green's function method in the study of global existence in the large perturbation framework.

    Citation: Jie Qi, Weike Wang. Global solutions to the Cauchy problem of BNSP equations in some classes of large data[J]. Electronic Research Archive, 2024, 32(9): 5496-5541. doi: 10.3934/era.2024255

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  • In this paper, we obtained the global existence and large time behavior of the solution for bipolar Navier-Stokes-Poisson equations under the partially smallness assumption of the initial data. Due to the complexity of bipolar Navier-Stokes-Poisson equations, we chose Green's function method instead of the classical energy method and thus discussed the regularity criterion under decaying structures in time instead of only integrability of time variable. It made the whole proof more simple and clear, meanwhile, resulted in the large time decaying estimates of the solution. It also showed the advantage of Green's function method in the study of global existence in the large perturbation framework.



    The bipolar Navier-Stokes-Poisson system has been used to simulate the transport of charged particles under the influence of electrostatic force governed by the self-consistent Poisson. In this paper, we are concerned with the Cauchy problem of the bipolar Navier-Stokes-Poisson system in 3 dimensions:

    {tρ1+div(ρ1u1)=0,tu1+div(ρ1u1u1)+P1(ρ1)=μ1Δu1+μ2divu1+ρ1Φ,tρ2+div(ρ2u2)=0,tu2+div(ρ2u2u2)+P2(ρ2)=μ1Δu2+μ2divu2ρ2Φ,ΔΦ=ρ1ρ2,lim|x|Φ(x,t)=0, (1.1)

    with initial data

    (ρ1,u1,ρ2,u2,Φ)(x,0)=(ρ1,0,u1,0,ρ2,0,u2,0,Φ0)(x),xR3. (1.2)

    Here ρi(x,t),ui(x,t),Φ(x,t), and Pi(ρ)((x,t) represent the fluid density, velocity, self-consistent electric potential and pressure. The viscosity coefficients satisfy the usual physical conditions μ1>0, 3μ1+2μ2>0. We assume that Pi(ρ) satisfies Pi(ρ)>0 for all ρ>0 and Pi(ˉρ)=1, where ¯ρ>0 denotes the prescribed density of positive charged background ions, and in this paper is taken as a positive constant. Without loss of generality, we take ¯ρ to be 1. For the initial data (ρ1,0,u1,0,ρ2,0,u2,0), we consider small perturbations of (¯ρ,0,¯ρ,0), in which ¯ρ is defined as before and taken to be 1, and we assume that ρ1,0,ρ2,0 has positive lower bound and upper bound.

    Now, we review some previous works on the Cauchy problem for some related models. There has been a lot of studies for the compressible Navier-Stokes system (CNS) for either isentropic or non-isentropic cases on the existence, stability, and Lp-decay rates with p2. For the results of small solutions, see [1,2] and [3,4,5,6,7], where the authors use the (weighted) energy method together with spectrum analysis, and for the results of partial small solutions (under the setting that the initial data is of small energy but possibly large oscillations), see [8,9] and the references therein. On the other hand, many scholars also use the method of Green's function to analyze the asymptotic behavior of a specific system, for example, by using the method of Green's function, Liu and Zeng [10] first studied the point-wise estimates of solutions to the general hyperbolic-parabolic equations in one dimension. Later, Liu and Wang [11] give the point-wise estimates of diffusion wave for the Navier-Stokes systems in odd multi-dimension and explain the generalized Huygens' principle for the Navier-Stokes systems.

    For the unipolar Navier-Stokes-Poisson system (NSP), there is also a mass of results for the Cauchy problem when the initial data (ρ0,u0) is a small perturbation around the constant state (ˉρ,0). For instance, the global existence of weak solutions was obtained by [12,13]; the framework of Matsumura and Nishda [14,15] shows the global existence of small strong solutions in HN Sobolev spaces. In [16,17], the authors obtain the global existence of small solutions in some Besov spaces. For the solutions which are of small energy but possibly large oscillations, see [18,19] and the references therein. In fact, the NSP system is a hyperbolic-parabolic system with a nonlocal term arising from the electric field Φ. From the analysis of Green's function, the symbol of this nonlocal term is singular in the long wave of the Green's function and it destroys the time-decay rate for the velocity. As we know, for the CNS system, when the initial perturbation ρ01,u0LpHN, with p near 1, and N3 is a large enough integer for the nonlinear system, then the solutions have L2 optimal decay rate

    (ρ1,u)(t)L2C(1+t)32(1p12).

    In [15,20,21], the authors survey the decay rate of solutions for the NSP system and they observed that the electric field destroys the decay rate of the solutions, i.e., when the initial perturbation ρ01,u0LpHN, with p[1,2], then the solutions have L2 optimal decay rate

    (ρ1)(t)L2C(1+t)32(1p12),  u(t)L2C(1+t)32(1p12)+12.

    In [22], the author gives another comprehension toward the effect of the electric field on the decay rate of the solutions for the NSP system. The author believes that it is natural to assume that Φ0L2, and with this condition in hand, we can obtain the L2 optimal decay rate for the linear NSP system as follows:

    (ρ1)(t)L2C(1+t)32(1p12)12,  u(t)L2C(1+t)32(1p12).

    In this sense, we see that the electric force enhances the decay rate of the density with the factor 12 compared with the CNS system.

    For the bipolar Navier-Stokes-Poisson system (BNSP), Wang and Xu [23] obtain the global existence of small solutions and the decay rate of the solutions. [24,25,26] observed the large time behavior of the BNSP system. The global existence of the solutions for the BNSP system under the partial smallness of the initial value is still an open problem, and the aim of this paper is to obtain the global existence of the solution to the system (1.1) and (1.2) provided that the initial data is partially small, which means that we require the initial value itself to be small and its derivative only to be bounded. In other words, its initial value is large in some classes, that is, its derivative can be large except for the initial value itself. In this paper, we first establish a regularity criterion to obtain the uniform boundedness of the solutions, and then combine abstract bootstrap argument to extend the local solutions. In order to prove the global existence of solution under the condition of initial data is partially small, the general regularity hypothesis requires that the solution is bounded with respect to time in the sense of some Sobolev norm, and another important condition is that the solution is integrable with respect to the time variable, which is necessary to obtain a consistent estimate of the solution through Gronwall's inequality.

    However, in this paper, it is difficult to obtain the regularity condition of integrability due to the more complex nonlinear structure in BNSP equations. The classical regularity criterion is established based on the energy method and the decay property in time variable is usually captured by integrability. It is always difficult and not applicable for the bootstrap argument. In fact, in [27] for the global existence of solutions for shallow water equations with partially large initial data, we applied Green's function method and replaced the integrability condition by detailed decaying structure in time variable, which makes the bootstrap argument more clear and concise.

    The linear and nonlinear structures of BNSP equations discussed in this paper are far more complicated, and we can imagine that it could be quite difficult and complex for the energy method. Even in the construction of Green's function, compared with the previous case for shallow water equations, BNSP equations are hyperbolic-parabolic-elliptic coupled ones and the structure is very complicated. The elliptic structure provides a nonlocal operator and also causes the lack of symmetry. These are all troubles we need to overcome in this paper.

    Before we list the main result, we introduce some notations. Throughout this paper, t stands for the derivative with respect to time variable and ft=tf. The symbol if(i=1,2,3) means partial derivative with respect to xi,

    if=fxi.

    We use the notation kf to mean the partial derivative of order k. That is, if k is a nonnegative integer, then

    kf:={αf|α=(α1,α2,α3),|α|=k}

    is a set of all partial derivatives of order k, endowed with the norm

    kf2L2=|α|=kαf2L2,

    where

    αf:=α1x1α2x2α3x3f,  αi0.

    Let Λ be a quasi-differential operator defined as follows:

    Λα=(Δ)α2.

    The main result of this paper is the following:

    Theorem 1.1. Let (ρ1,01,u1,0,ρ2,01,u2,0,Φ0)Hs+1(s4), and

    (ρ1,01,u1,0,ρ2,01,u2,0,Φ0)L2(R3)L1(R3)E0,

    where E0 is sufficiently small, then the Cauchy problem (1.1) and (1.2) has a global solution in time that satisfies

    (ρ11,u1,ρ21,u2)L([0,);Hs+1),  (u1,u2)L2([0,);Hs+1),

    For 2p+ and α=(α1,α2,α3), |α|s1, it holds

    Dα(ρ11,u1,ρ21,u2)(,t)LpC(1+t)32(11p)|α|2.

    Remark 1.1. In Theorem 1.1, we only assume the norm of the initial datum ρ1,0,ρ2,0,u1,0,u2,0 and Φ0 are small enough, but for the derivatives of ρ1,0,ρ2,0,u1,0,u2,0, and Φ0, we assume that they are bounded.

    The rest of this paper is organized as follows. In Section 2, we establish the uniform time estimate of solutions. In Section 3, we analyze the Green's function of the linear BNSP system, and the different properties of the Green function at high and low frequencies are obtained. In Section 4, we complete the partial proof of Theorem 1.1, i.e., we mainly obtain the existence of the solutions. In this paper, we also obtain the decay rate of the solutions, and the reader can see Sections 4 and 5 for details.

    Throughout this paper, we denote by C a positive constant that varies from line to line.

    We reformulate the Cauchy problem (1.1) and (1.2) about constant state (1,0,1,0) as follows:

    {tρ1+divu1=div(ρ1u1),tu1μ1Δu1μ2divu1+ρ1Φ=u1u1(P1(1+ρ1)1+ρ11)ρ1ρ11+ρ1(μ1Δu1+μ2divu1),tρ2+divu2=div(ρ2u2),tu2μ1Δu2μ2divu2+ρ2+Φ=u2u2(P2(1+ρ2)1+ρ21)ρ2ρ21+ρ2(μ1Δu2+μ2divu2),ΔΦ=ρ1ρ2,lim|x|Φ(x,t)=0, (2.1)

    where we also note (ρ11,u1,ρ21,u2) as (ρ1,u1,ρ2,u2) without causing confusion. In this section, we will get the estimates of the solutions for the system (2.1) under the assumption that for any fixed 0<T<+, t[0,T],

    (ρ1(t)L(R3),u1(t)L(R3),ρ2(t)L(R3),u2(t)L(R3))C(1+t)2, (2.2)

    and

    (ρ1,0,ρ2,0,u1,0,u2,0,Φ0)L2L1E0, (2.3)

    where E0 is a positive constant which is sufficiently small. Similar to reference [28,29], we call Eq (2.2) the regularity criterion. In this section, based on this regularity criterion, we get a consistent estimate of the solutions of the equations and its derivatives.

    We first define

    F1(ρ)=P1(1+ρ)1+ρ1,   F2(ρ)=P2(1+ρ)1+ρ1,   H(ρ)=ρ1+ρ.

    To do this end, from (2.2), (2.3), and Gagliardo-Nirenberg's inequality, we know that there exists a sufficiently small ε1>0 that satisfies

    ρ1L(R3)ε1 and  ρ2L(R3)ε1. (2.4)

    First of all, from (2.4), we obtain

    231+ρ143,   231+ρ243.

    Hence, by the definition of F1(ρ),F2(ρ), and H(ρ), we immediately have

    |F1(ρ1)|,|H(ρ1)|C|ρ1|,  |F2(ρ2)|,|H(ρ2)|C|ρ2|,|F(k)1(ρ1)|,|F(k)2(ρ2)|,|H(k)(ρ1)|,|H(k)(ρ2)|C  for any k1. (2.5)

    Let us start with a lemma that will be frequently used later.

    Lemma 2.1. [22] Assume that ρL(R3)1, and f(ρ) is a smooth function of ρ with bounded derivatives of any order, then for any integer k1, we have

    k(f(ρ))L(R3)CkρL(R3).

    We obtain the estimates of the low order derivatives of the system (2.1) first.

    Lemma 2. Under the assumption (2.2) and (2.4), we have

    (ρ1,u1,ρ2,u2,Φ)L(0,T;L2(R3)),(u1,u2)L2(0,T;L2(R3))C,

    where C is a constant depending on (ρ1,0,ρ2,0,u1,0,u2,0,Φ0)L2.

    Proof. Multiplying the Eqs (2.1)1, (2.1)2, (2.1)3, and (2.1)4 by ρ1,u1,ρ2,u2, respectively, and integrating the equations over R3, we obtain

       12tR3(ρ21+|u1|2+ρ22+|u2|2)dx+μ1R3(|u1|2+|u2|2)dx+μ2R3(|divu1|2+|divu2|2)dx=R3Φ(u2u1)dxR3div(ρ1u1)ρ1dxR3div(ρ2u2)ρ2dxR3u1u1u1dxR3u2u2u2dxR3F1(ρ1)u1ρ1dxR3F2(ρ2)u2ρ2dxR3H(ρ1)(μ1Δu1+μ2divu1)u1dxR3H(ρ2)(μ1Δu2+μ2divu2)u2dx=:9i=1Ai. (2.6)

    Now we estimate Ai one by one. Because the self-consistent potential Φ(x,t) is coupled with the density through the Poisson equation, using Hölder's inequality and Cauchy's inequality, for A1, it holds

    A1=R3Φ(u2u1)dx=R3Φdiv(u1u2)dx=R3Φ(tρ1div(ρ1u1)+tρ2+div(ρ2u2))dx=R3Φt(ρ1ρ2)dx+R3Φ(div(ρ1u1)div(ρ2u2))dx=R3ΦtΔΦdx+R3Φ(div(ρ1u1)div(ρ2u2))dx=12tR3|Φ|2dxR3Φ(ρ1u1ρ2u2))dx12tR3|Φ|2dx+(Φ2L2+u12L2+u22L2)(ρ1L+ρ2L). (2.7)

    For A4 and A5, by Hölder's inequality, we easily check that

    |A4|+|A5|u1Lu12L2+u2Lu22L2. (2.8)

    Integrating by parts, and using Hölder's inequality and Cauchy's inequality, it holds

    |A2|+|A3|ρ1L(u12L2+ρ12L2)+ρ2L(u22L2+ρ22L2). (2.9)

    By the definition of F1(ρ) and F2(ρ), using Hölder's inequality and Cauchy's inequality, and from (2.5), we have

    |A6|+|A7|ρ1L(u12L2+ρ12L2)+ρ2L(u22L2+ρ22L2). (2.10)

    Also integrating by parts, using Hölder's inequality and Cauchy's inequality, and by (2.5) and Lemma (2.1), we have

    |A8|+|A9|=|R3H(ρ1)(μ1u1+μ2divu1)u1dxR3H(ρ1)(μ1u1+μ2divu1)u1dx|+|R3H(ρ2)(μ1u2+μ2divu2)u2dxR3H(ρ2)(μ1u2+μ2divu2)u2dx|ρ12Lu12L2+ϵu12L2+ρ22Lu22L2+ϵu22L2, (2.11)

    where we take ϵ small enough such that ϵ1. Plugging the estimates for A1A9, i.e., (2.7)(2.11) into (2.6), we get

       12tR3(ρ21+|u1|2+ρ22+|u2|2+|Φ|2)dx+μ1R3(|u1|2+|u2|2)dx+μ2R3(|divu1|2+|divu2|2)dx(ρ1L+ρ2L)(Φ2L2+u12L2+u22L2)+(ρ1L+ρ12L+u1L)(u12L2+ρ12L2)+(ρ2L+ρ22L+u2L)(u22L2+ρ22L2). (2.12)

    Using Gronwall's inequality, we complete the proof of the lemma.

    In the following, we would like to give the high regularity estimates of the solutions.

    Lemma 2.3. Under the assumption (2.2) and (2.4), we have

    (ρ1,u1,ρ2,u2,2Φ)L(0,T;L2(R3)),(2u1,2u2)L2(0,T;L2(R3))C,

    where C is a constant depending on (ρ1,0,ρ2,0,u1,0,u2,0,2Φ0)L2.

    Proof. We operate each equation of (2.1) with operator to derive

    {tρ1+divu1=div(ρ1u1),tu1μ1Δu1μ2divu1+ρ1Φ=(u1u1)((P1(1+ρ1)1+ρ11)ρ1)(ρ11+ρ1(μ1Δu1+μ2divu1)),tρ2+divu2=div(ρ2u2),tu2μ1Δu2μ2divu2+ρ2+Φ=(u2u2)((P2(1+ρ2)1+ρ21)ρ2)(ρ21+ρ2(μ1Δu2+μ2divu2)), (2.13)

    and multiplying the above equations by ρ1,u1,ρ2,andu2, respectively, and integrating over R3 yields

       12tR3(|ρ1|2+|u1|2+|ρ2|2+|u2|2)dx+μ1R3(|2u1|2+|2u2|2)dx+μ2R3(|divu1|2+|divu2|2)dx+R32Φ(u2u1)dx=R3div(ρ1u1)ρ1dxR3div(ρ2u2)ρ2dxR3(u1u1)u1dxR3(u2u2)u2dxR3(F1(ρ1)ρ1)u1dxR3(F2(ρ2)ρ2)u2dxR3(H(ρ1)(μ1Δu1+μ2divu1))u1dxR3(H(ρ2)(μ1Δu2+μ2divu2))u2dx=:8i=1Bi. (2.14)

    For the last term on the left-hand side of (2.14), since Φ(x,t) satisfies the Poisson equation, we have

       R32Φ(u2u1)dx=R3Φdiv(u1u2)dx=R32Φ(t(ρ1ρ2)+div(ρ2u2ρ1u1)dx=12tR3|2Φ|2dx+R32Φdiv(ρ1u1ρ2u2)dx. (2.15)

    For the term R32Φdiv(ρ1u1ρ2u2)dx, using Hölder's inequality and Young's inequality, we have

       |R32Φdiv(ρ1u1ρ2u2)dx|ρ1L(u12L2+2Φ2L2)+u1L(ρ12L2+2Φ2L2)+ρ2L(u22L2+2Φ2L2)+u2L(ρ22L2+2Φ2L2). (2.16)

    Now, we estimate each term on the righthand side of (2.14). Hölder's inequality and Young's inequality gives

    |B1|R3|ρ1||2u1||ρ1|dx+R3|u1||ρ1|2dxC(ϵ)ρ12Lρ12L2+ϵ2u12L2+u1Lρ12L2, (2.17)

    where ϵ is a positive number that is small enough to be determined, as ϵ appears in the following inequalities. Similar to the estimate of B1, we obtain

    |B2|R3|ρ2||2u2||ρ2|dx+R3|u2||ρ2|2dxC(ϵ)ρ22Lρ22L2+ϵ2u22L2+u2Lρ22L2. (2.18)

    Simple computation gives

    |B3|+|B4|u1Lu12L2+u2Lu22L2.

    By the definition of F1 and F2, integrating by parts, and using Hölder's inequality and Young's inequality, from (2.5) we have

    |B5|+|B6|=|R3f1(ρ1)ρ1divu1dx|+|R3f2(ρ2)ρ2divu2dx|C(ϵ)ρ12Lρ12L2+ϵ2u12L2+C(ϵ)ρ22Lρ22L2+ϵ2u22L2. (2.19)

    Integrating by parts, by (2.5) and Lemma 2.1, we obtain

       |B7|+|B8|=|μ1R3H(ρ1)(|2u1|2+2u1divu1)dx|+|μ2R3H(ρ2)(|2u2|2+2u2divu2)dx|ϵ(2u12L2+divu22L2). (2.20)

    Consequently, by (2.14)(2.20) and taking ϵ1, we deduce

       12tR3(|ρ1|2+|u1|2+|ρ2|2+|u2|2+|2Φ|2)dx+μ1R3(|2u1|2+|2u2|2)dx+μ2R3(|divu1|2+|divu2|2)dx(ρ12L+u1L+u1L+u2L)ρ12L2+(ρ22L+u2L+u1L+u2L)ρ22L2+(u1L+ρ1L+ρ2L)u12L2+(u2L+ρ1L+ρ2L)u22L2+(ρ1L+ρ2L+u1L+u2L)2Φ2L2. (2.21)

    With the help of Gronwall's inequality, we complete the proof of the lemma.

    Lemma 2.4. Under the assumption (2.2) and (2.4), we have

    (2ρ1,2u1,2ρ2,2u2,3Φ)L(0,T;L2(R3)),(3u1,3u2)L2(0,T;L2(R3))C,

    where C is a constant depending on (2ρ1,0,2ρ2,0,2u1,0,2u2,0,3Φ0)L2.

    Proof. Operating 2 on each equation of (2.1) gives

    {t2ρ1+2divu1=2div(ρ1u1),t2u1μ12Δu1μ22divu1+2ρ12Φ=2(u1u1)2((P1(1+ρ1)1+ρ11)ρ1)2(ρ11+ρ1(μ1Δu1+μ2divu1)),t2ρ2+2divu2=2div(ρ2u2),t2u2μ12Δu2μ22divu2+2ρ2+2Φ=2(u2u2)2((P2(1+ρ2)1+ρ21)ρ2)2(ρ21+ρ2(μ1Δu2+μ2divu2)), (2.22)

    and multiplying the above equations by 2ρ1,2u1,2ρ2,and 2u2, respectively, and integrating over R3 gives

       12tR3(|2ρ1|2+|2u1|2+|2ρ2|2+|2u2|2)dx+μ1R3(|3u1|2+|3u2|2)dx+μ2R3(|2divu1|2+|2divu2|2)dx+R32Φ2(u2u1)dx=R32div(ρ1u1)2ρ1dxR32div(ρ2u2)2ρ2dxR32(u1u1)2u1dxR32(u2u2)2u2dxR32(F1(ρ1)ρ1)2u1dxR32(F2(ρ2)ρ2)2u2dxR32(H(ρ1)(μ1Δu1+μ2divu1))2u1dxR32(H(ρ2)(μ1Δu2+μ2divu2))2u2dx=:8i=1Ci. (2.23)

    Similar to the proof of Lemma 2.3, for the last term on the left-hand side of (2.23), we get

       R32Φ2(u2u1)dx=R32Φ2div(u1u2)dx=R32Φ2(t(ρ1ρ2)+div(ρ2u2ρ1u1)dx=R32Φ2t2Φdx+R33Φ2(ρ1u1ρ2u2)dx=12tR3|3Φ|2dx+R33Φ2(ρ1u1ρ2u2)dx. (2.24)

    For the term R33Φ2(ρ1u1ρ2u2)dx, we can easily check that

       R33Φ2(ρ1u1ρ2u2)dx(ρ1L+u1L)(3Φ2L2+2ρ12L2+2u12L2)+ρ1L(3Φ2L2+u12L2)+(ρ2L+u2L)(3Φ2L2+2ρ22L2+2u22L2)+ρ2L(3Φ2L2+u22L2). (2.25)

    Now we estimate Ci. We hereby declare that ϵ occurring in the following inequalities is a sufficiently small positive number to be determined. To begin, it is easy to check that

    |C3|+|C4|=|R3(u1u1)3u1dx|+|R3(u2u2)3u2dx|ϵ3u12L2+C(ϵ)u12Lu12L2+u1L2u12L2+ϵ3u22L2+C(ϵ)u22Lu22L2+u2L2u22L2. (2.26)

    Using Hölder's inequality and Young's inequality, we have

    |C1|=|R32(ρ1divu1+u1ρ1)2ρ1dx|R3|2ρ1||u1||2ρ1|dx+R3ρ1|3u1||2ρ1|dx+R3|ρ1||2u1||2ρ1|dxu1L2ρ12L2+ϵ3u12L2+C(ϵ)ρ12L2ρ12L2+ρ1L(2ρ12L2+2u12L2). (2.27)

    Similarly, we also have

    |C2|u2L2ρ22L2+ϵ3u22L2+C(ϵ)ρ22L2ρ22L2+ρ2L(2ρ22L2+2u22L2). (2.28)

    Also, integrating by parts, using Hölder's inequality and Cauchy's inequality, and by (2.5) and Lemma 2.1, we have

    |C5|=|R3(F1(ρ1)ρ1)3u1dx|=|R3F1ρ13u1dx+R3F12ρ13u1dx|ϵ3u12L2+C(ϵ)ρ12Lρ12L2+C(ϵ)ρ12L2ρ12L2. (2.29)

    Similarly to the estimate of C5, we obtain that

    |C6|ϵ3u22L2+C(ϵ)ρ22Lρ22L2+C(ϵ)ρ22L2ρ22L2. (2.30)

    For the rest estimates of Ci, it is easy to check that

    |C7|=|R3(H(ρ1)(μ1Δu1+μ2divu1))3u1dx|=|R3H(ρ1)(μ1Δu1+μ2divu1)3u1dx+R3H(ρ1)(μ1Δu1+μ2divu1)3u1dx|ϵ3u12L2+C(ϵ)ρ12L2u12L2, (2.31)

    and

    |C8|ϵ3u22L2+C(ϵ)ρ22L2u22L2. (2.32)

    Combining (2.23)–(2.32), we have

       12tR3(|2ρ1|2+|2u1|2+|2ρ2|2+|2u2|2+|3Φ|2)dx+μ1R3(|3u1|2+|3u2|2)dx+μ2R3(|2divu1|2+|2divu2|2)dxC(ρ1L+u1L+ρ2L+u2L+ρ1L+ρ2L)3Φ2L2+C(ρ1L+u1L+ρ12L+ρ1L+u1L)2ρ12L2+C(ρ1L+u1L+ρ1L+u1L+ρ12L)2u12L2+C(ρ2L+u2L+ρ22L+ρ2L+u2L)2ρ22L2+C(ρ2L+u2L+ρ2L+u2L+ρ22L)2u22L2+C(ρ12Lρ12L2+ρ22Lρ22L2)+C(ρ1L+u12L)u12L2+C(ρ2L+u22L)u22L2. (2.33)

    By Gronwall's inequality, we complete the proof of the lemma.

    Lemma 2.5. Under the assumption (2.2) and (2.4), for 3ls+1, we have

    (lρ1,lu1,lρ2,lu2,l+1Φ)L(0,T;L2(R3)),(l+1u1,l+1u2)L2(0,T;L2(R3))C,

    where C is a constant that depends only on (lρ1,0,lρ2,0,lu1,0,lu2,0,l+1Φ0)L2.

    Proof. Similar to the proof of Lemma 2.4, we can obtain the conclusion of the lemma. So we omit it.

    In order to see the Green's function of the linear part of the system better, we reformulate the system (2.1) slightly. Let

    n=ρ1+ρ2,m=ρ2ρ1,v=u1+u2,w=u2u1, (3.1)

    which equivalently gives

    ρ1=nm2,ρ2=n+m2,u1=vw2,u2=v+w2. (3.2)

    Then, the Cauchy problem (2.1) can be reformulated into the following form:

    {tn+divv=Q1(n,v,m,w),tvμ1Δvμ2divv+n=Q2(n,v,m,w),tm+divw=Q3(n,v,m,w),twμ1Δwμ2divw+m+2Φ=Q4(n,v,m,w),ΔΦ=m,(n,v,m,w,Φ)(x,0)=(n0,v0,m0,w0,Φ0)(x), (3.3)

    where (n0,v0,m0,w0,Φ0)(x)=(ρ1,0+ρ2,0,u1,0+u2,0,ρ2,0ρ1,0,u2,0u1,0,Φ0)(x) and

    Q1(n,v,m,w)=div(nm2vw2)div(n+m2v+w2) (3.4)
    Q2=vw2(vw2)v+w2(v+w2)(P1(1+nm2)1+nm21)(nm2)(P2(1+n+m2)1+n+m21)(n+m2)nm21+nm2(μ1Δ(vw2)+μ2div(vw2))n+m21+n+m2(μ1Δ(v+w2)+μ2div(v+w2)), (3.5)
    Q3(n,v,m,w)=div(nm2vw2)div(n+m2v+w2) (3.6)
    Q4=vw2(vw2)v+w2(v+w2)+(P1(1+nm2)1+nm21)(nm2)(P2(1+n+m2)1+n+m21)(n+m2)+nm21+nm2(μ1Δ(vw2)+μ2div(vw2))n+m21+n+m2(μ1Δ(v+w2)+μ2div(v+w2)). (3.7)

    The linearized system of (3.3) is

    {tn+divv=0,tvμ1Δvμ2divv+n=0,tm+divw=0,twμ1Δwμ2divw+m+2Φ=0,ΔΦ=m. (3.8)

    We can also rewrite (3.8) as

    (t+A(D))V=0, (3.9)

    where

    A(D)=(0div00μ1Δμ2div00000div00+2(Δ)1μ1Δμ2div), V=(nvmw). (3.10)

    Consider the Green's function G of (3.9), i.e., the solution to the following Cauchy problem

    {(t+A(D))G(x,t)=0,G(x,0)=δ(x)I8×8, (3.11)

    where δ(x) denotes the Dirac function and I8×8 denotes the unit matrix. By direct calculation, we obtain the Fourier transform of the Green's function G as

    ˆG=(ˆG100ˆG2), (3.12)

    where

    ˆG1(ξ,t)=(λ+eλtλeλ+tλ+λ1eλteλ+tλ+λξT1eλteλ+tλ+λξeμ1|ξ|2tI+(λ+eλ+tλeλtλ+λ+eμ1|ξ|2t)ξξT|ξ|2),
    ˆG2(ξ,t)=(˜λ+e˜λt˜λe˜λ+t˜λ+˜λ1e˜λte˜λ+t˜λ+˜λξT1(1+|ξ|2)e˜λte˜λ+t˜λ+˜λξeμ1|ξ|2tI+(˜λ+e˜λ+t˜λe˜λt˜λ+˜λ+eμ1|ξ|2t)ξξT|ξ|2),

    and

    λ±=μ|ξ|2±μ2|ξ|44|ξ|22,
    ˜λ±=μ|ξ|2±μ2|ξ|44(|ξ|2+2)2,  μ=μ1+μ2.

    For the convenience of writing, we also give the following definition,

    ˆG=(ˆG100ˆG1), (3.13)

    where ˆG is the Fourier transform of the Green's function G. In this paper, we divide Green's function into a high frequency part and a low frequency part since Green's function has different properties in high and low frequency. Let χ(ξ) be a smooth cutoff function

    χ(ξ)={1,|ξ|12,0,|ξ|>1. (3.14)

    We denote G=GL+GRH+S, where GL stands for the lower frequency part, GRH stands for the regular part of the high frequency, and the S stands for the sigular part. GL,GRH, and S have the following forms:

    GL=χ(D)G,    GRH=(1χ(D))GS,S=e1μtδ(x)(1χ(D)000000000000000000000000000000000001χ(D)000000000000000000000000000), (3.15)

    Here, μ=μ1+μ2. For the convenience of the description in the fifth part of this paper, we redefine smooth cutoff functions χ1(ξ) and χ2(ξ)

    χ1(ξ)={1,|ξ|1,0,|ξ|>76.χ2(ξ)={1,|ξ|13,0,|ξ|>12. (3.16)

    Let us redefine the low frequency of G and the high frequency of G,

    G˜L=χ1(D)G,  G˜H=(1χ2(D))G=:G~RH+G˜S,

    where

    G˜S=e1μtδ(x)(1χ2(D)000000000000000000000000000000000001χ2(D)000000000000000000000000000). (3.17)

    Here, μ=μ1+μ2. From the definition of χ(ξ), χ1(ξ), and χ2(ξ) in (3.14) and (3.16), we can obtain

    χ(D)G˜L=χ(D)G,  (1χ(D))G˜H=(1χ(D))G.

    In this paper, we use Gi,j to represent the element in row i and column j of G.

    Below, we list some properties of Green's function, and the readers can refer to [11,21,30,31] for details.

    Lemma 3.1. If ϵ1>0 is small enough, then for |ξ|<ϵ1, we have

    λ±=μ2|ξ|2±1|ξ|(1+j=1dj|ξ|2j),

    and

    ˜λ±=μ2|ξ|2+j=2aj|ξ|2j±1(2+j=1bj|ξ|2j).

    Proof. The readers can refer to [11,21,30,31] for details, so we omit the proof.

    Lemma 3.2. If 1p+ and α=(α1,α2,α3), αi0, xR3, we have

    DαGL(,t)LpC(1+t)32(11p)|α|2.

    Proof. By the representation of G and Lemma 3.1, we can obtain the proof of the lemma, so we omit it.

    Lemma 3.3. If K>0 is large enough, then for |ξ|>K, we have

    λ+=1μ+μ2j=1ej|ξ|2j,  λ=μ|ξ|2+1μj=1ej|ξ|2j,
    ˜λ+=1μ+j=1lj|ξ|2j,  ˜λ=μ|ξ|2+1μj=1lj|ξ|2j.

    Here, μ=μ1+μ2, and all ej,lj are real constants.

    Proof. See [11,21,30,31] for details, and we omit the proof.

    Remark: This lemma states that in G, only the terms related to

    λ(ξ)λ+(ξ)λ(ξ)eλ+(ξ)t  or  ˜λ(ξ)˜λ+(ξ)˜λ(ξ)e˜λ+(ξ)t

    will occur in a singular part, and the other terms will bear at least a first derivative.

    Lemma 3.4. If 1p+ and α=(α1,α2,α3), αi0, |α|1, we have

    DαGRH(,t)LpCeC0t,
    DαG~RH(,t)LpCeC0t,
    S(,t)V(,t)LpCeC0tV(,t)Lp,
    G˜S(,t)V(,t)LpCeC0tV(,t)Lp,

    where C0>0 is the fixed normal number associated with μ.

    Proof. The readers can refer to [11,21,30,31] for details, so we omit the proof.

    Below we derive an estimation method that combines the advantages of the Green's function and energy estimate. We consider the system:

    {(t+B(D))U(x,t)=R(U(x,t)),U(x,0)=U0(x), (3.18)

    where B(D) is an operator and R(U) is nonlinear terms. The Green's function G(x,t) corresponding to the system (3.18) is the fundamental solution of the Cauchy problem of the linear equations of its corresponding system, i.e., G(x,t) is the solution of the following Cauchy problem:

    {(t+B(D))G(x,t)=0,G(x,0)=δ(x)In×n. (3.19)

    where δ(x) denotes the Dirac function and In×n denotes the unit matrix.

    The solution of (3.18) is usually discussed in terms of energy estimate or the Green's function. The following lemma combines the advantages of Green's function and energy estimate, which we may call the G-E estimate. The advantage of this estimate is that on the one hand, the fine decaying estimate of the solution can be obtained with the Green's function; on the other hand, the derivative in the singular part of the high frequency can be shared through integration by parts similar to the energy estimate.

    Lemma 3.5. [27] If B(ξ) is a complex normal matrix (i.e., BB=BB, B=¯BT), then it holds

    U(,t)2L2=Rn(GT(,t)U0)TG(,t)U0dx+2t0Rn(GT(x,tτ)U(,τ))TG(x,tτ)R(U(,τ))dxdτ, (3.20)

    where G is Green's function about (3.19).

    Remark 3.1. If GT=G, then we have

    U(,t)2L2=G(,t)U02L2+2t0RnG(x,tτ)U(,τ)G(x,tτ)R(U(,τ))dxdτ. (3.21)

    The Eq (3.20) is in the form of row vector times column vector, while the Eq (3.21) is in the form of the inner product of vectors.

    Remark 3.2. As can be seen from (3.10), G, which we defined in (3.13), satisfies GT=G.

    In this section, we first give the local existence theory.

    According to (2.1), we construct the approximate solution sequence {˜Vn(t)} by the following linearized iteration scheme:

    {tρn+11+divun+11+div(ρn+11un1)=0,tun+11μ1Δun+11μ2divun+11+ρn+11Φn+1=un1un1(P1(1+ρn1)1+ρn11)ρn1ρn11+ρn1(μ1Δun1+μ2divun1),tρn+12+divun+12+div(ρn+12un2)=0,tun+12μ1Δun+12μ2divun+12+ρn+12+Φn+1=un2un2(P2(1+ρn2)1+ρn21)ρn2ρn21+ρn2(μ1Δun2+μ2divun2),ΔΦn+1=ρn+11ρn+12,lim|x|Φn+1(x,t)=0, (4.1)

    where {˜Vn(t)} is defined as ˜Vn(t)=(ρn1(t),un1(t),ρn2(t),un2(t),Φn(t)),n0, and ˜V0(t)=(0,0,0,0,0). For any given integer s[32]+3, we define

    XsT,E={˜V(t)|˜VXs<E}

    as the suitable space for the solutions, where

    ˜VXs=sup0tT˜V(t)Hs.

    It is easy to show that XsT,E, equipped with the norm Xs, is a nonempty Banach space. To obtain the local soluiton, we need the following two lemmas. To do this end, we first give a prior assumption. For sufficiently small ε1>0, we have

    ρ1L(R3)ε1 and  ρ2L(R3)ε1. (4.2)

    Lemma 4.1. Under the assumption (4.2), when T is small enough, there exists a constant E>0 such that {˜Vn(x,t)}Xs+1T,E.

    Proof. We imply the inductive method to accomplish the proof. To start, when n=0, we have

    {tρ11+divu11=0,tu11μ1Δu11μ2divu11+ρ11Φ1=0,tρ12+divu12=0,tu12μ1Δu12μ2divu12+ρ12+Φ1=0,ΔΦ1=ρ11ρ12,lim|x|Φ1(x,t)=0, (4.3)

    By the energy estimate, we have

    12t(ρ112Hs+u112Hs+ρ122Hs+u122Hs+Φ12Hs0.

    We take E=2(ρ1(x,0),u1(x,0),ρ2(x,0),u2(x,0))Hs, then we get ˜V1(x,t)XsT,E. Now, assuming that {˜Vj(x,t)}XsT,E for all jn, we need to prove it holds for j=n+1.

    Applying the energy method to (4.1), we have

       12tR3(|ρn+11|2+|un+11|2+|ρn+12|2+|un+12|2)dx+μ1R3(|un+11|2+|un+12|2)dx+μ2R3(|divun+11|2+|divun+12|2)dx=R3Φn+1(un+12un+11)dxR3div(ρn+11un1)ρn+11dxR3div(ρn+12un2)ρn+12dxR3un1un1un+11dxR3un2un2un+12dxR3F1(ρn1)un+11ρn1dxR3F2(ρn2)un+12ρn2dxR3H(ρn1)(μ1Δun1+μ2divun1)un+11dxR3H(ρn2)(μ1Δun2+μ2divun2)un+12dx=:9i=1Gi. (4.4)

    Similar to the proof of Lemma 2.2, we have the following estimates for each Gi,  1i9.

    |G1|12tR3|Φ|2dx+CΦn+12L2(un12L+un22L)+Cρn+112L2+ρn+112L2,
    |G2+G3|Cdivun1Lρn+112L2+Cdivun2Lρn+122L2,
    |G4+G5|Cun12Lun12L2+Cun22Lun22L2+Cun+112L2+Cun+122L2,
    |G6+G7|Cρn12Lρn12L2+Cun+112L2+Cρn22Lρn22L2+Cun+122L2,
    |G8+G9|Cρn12Lun+112L2+C(1+ρn12L)un12L2+ϵun+112L2+Cρn22Lun+122L2+C(1+ρn22L)un22L2+ϵun+122L2.

    where we take ϵ small enough such that ϵ1. Plugging the estimates for G1G9 into (4.4), and integrating with respect to t, we obtain

       sup0tT(ρn+11(t)2L2+un+11(t)2L2+ρn+12(t)2L2+un+12(t)2L2+Φn+1(t)2L2)+μ1t0R3(|un+11|2+|un+12|2)dx+μ2t0R3(|divun+11|2+|divun+12|2)dx(12E)2+CTE2sup0tTΦn+12L2+CT(1+E)sup0tTρn+112L2+CT(1+E)sup0tTρn+122L2+CT(1+E2)sup0tTun+112L2+CT(1+E2)sup0tTun+122L2+CTE2(1+E2). (4.5)

    Taking T small enough, we can get the following estimate from (4.5),

    sup0tT˜Vn+1(t)L2E. (4.6)

    To derive higher-order estimates, similar to the proof of Lemmas 2.3–2.5, we can obtain

    sup0tTDα˜Vn+1(t)L2E,  1αs+1. (4.7)

    Combining (4.6) and (4.7) yields

    sup0tT˜Vn+1(t)Hs+1E,

    which means ˜Vn+1(x,t)Xs+1T,E. We complete the proof of the lemma.

    Lemma 4.2. Under the assumption (4.2), when T is small enough, {˜Vn(x,t)} is a Cauchy sequence in XsT,E.

    Proof. We set

    fn+11=ρn+11ρn1, fn+12=ρn+12ρn2, gn+11=un+11un1,
    gn+12=un+12un2, Ψn+1=Φn+1Φn,

    and define

    Yn+1=(fn+11,fn+12,gn+11,gn+12,Ψn+1),

    then we only need to verify that

    Yn+1HsκYnHs,

    where 0<κ<1. From (4.1), we get Yn+1 satisfies

    {tfn+11+divgn+11+div(ρn+11un1ρn1un11)=0,tgn+11μ1Δgn+11μ2divgn+11+fn+11Ψn+1=(un1un1un11un11)((P1(1+ρn1)1+ρn11)ρn1(P1(1+ρn11)1+ρn111)ρn11)(ρn11+ρn1(μ1Δun1+μ2divun1)ρn111+ρn11(μ1Δun11+μ2divun11)),tfn+12+divgn+12+div(ρn+12un2ρn2un12)=0,tgn+12μ1Δgn+12μ2divgn+12+fn+12+Ψn+1=(un2un2un12un12)((P2(1+ρn2)1+ρn21)ρn2(P2(1+ρn12)1+ρn121)ρn12)(ρn21+ρn2(μ1Δun2+μ2divun2)ρn121+ρn12(μ1Δun12+μ2divun12)),ΔΨn+1=fn+11fn+12,lim|x|Ψn+1(x,t)=0. (4.8)

    Applying the energy method to (4.8), we have

       12tR3(|fn+11|2+|gn+11|2+|fn+12|2+|gn+12|2)dx+μ1R3(|gn+11|2+|gn+12|2)dx+μ2R3(|divgn+11|2+|divgn+12|2)dx=R3Ψn+1(gn+12gn+11)dxR3div(ρn+11un1ρn1un11)fn+11dxR3div(ρn+12un2ρn2un12)fn+12dxR3(un1un1un11un11)gn+11dxR3(un2un2un12un12)gn+12dxR3(F1(ρn1)ρn1F1(ρn11)ρn11)gn+11dxR3(H(ρn1)(μ1Δun1+μ2divun1)H(ρn11)(μ1Δun11+μ2divun11))gn+11dxR3(H(ρn2)(μ1Δun2+μ2divun2)H(ρn12)(μ1Δun12+μ2divun12))gn+12dxR3(F2(ρn2)ρn2F2(ρn12)ρn12)gn+12dx=:9i=1Ji. (4.9)

    Similar to the proof of Lemma 2.2, we have the following estimates for each Ji,  1i9.

    For J1, we have

    J1=12tΨn+12L2+R3Ψn+1(fn+12un2+ρn2gn2fn+11un1ρn1gn1)dx12tΨn+12L2+4Ψn+12L2+un22Lfn+122L2+un12Lfn+112L2+ρn22Lgn22L2+ρn12Lgn+112L2.

    For J2, we have

    J2=R3div(fn+11un1+ρn1gn1)fn+11dxun1Lfn+112L2+ρn1Lfn+112L2+gn12L2+gn12L2+ρn1Lfn+112L2.

    Similar to the proof of J2, for J3, we can obtain

    J3=R3div(fn+12un2+ρn2gn2)fn+12dxun2Lfn+122L2+ρn2Lfn+122L2+gn22L2+gn22L2+ρn2Lfn+122L2.

    For J4, we have

    J4=R3(gn1un1+un11gn1)gn+11dxgn12L2+(un12L+un112L)gn+112L2+ϵgn+112L2+Cgn12L2un112L.

    Similar to the estimate of J4, for J5, we can obtain

    J5=R3(gn2un2+un12gn2)gn+12dxgn22L2+(un22L+un122L)gn+122L2+ϵgn+122L2+Cgn22L2un122L.

    For J6, we have

    J6=R3((F1(ρn1)F1(ρn11)ρn1+F1(ρn11)fn1)gn+11dxρn12Lgn+112L2+2ρn12L2+2ρn112L2+fn12L2+ρn112Lgn+112L2+ϵgn+112L2+Cρn112Lfn12L2.

    Similar to the estimate of J6, for J9, we can obtain

    J9=R3((F2(ρn2)F2(ρn12)ρn2+F2(ρn12)fn2)gn+12dxρn22Lgn+122L2+2ρn22L2+2ρn122L2+fn22L2+ρn122Lgn+122L2+ϵgn+122L2+Cρn122Lfn22L2.

    For J7, we have

    J7=R3((H(ρn1)H(ρn11))(μ1Δun1+μ2divun1)+H(ρn11)(μ1Δgn1+μ2divgn1))gn+11dxC(ρn12L+ρn112L)gn+112L2+Cun12L2+ϵgn+112L2+C(ρn12L+ρn112L)un12L2+Cgn12L2+Cρn112Lgn+112L2.

    Similar to the estimate of J7, for J8, we have

    J8=R3((H(ρn2)H(ρn12))(μ1Δun2+μ2divun2)+H(ρn12)(μ1Δgn2+μ2divgn2))gn+12dxC(ρn22L+ρn122L)gn+122L2+Cun22L2+ϵgn+122L2+C(ρn22L+ρn122L)un22L2+Cgn22L2+Cρn122Lgn+122L2.

    Plugging the estimates for J1J9 into (4.9), and integrating with respect to t over [0, T], we obtain

    sup0tTYn+1(t)2L212sup0tTYn(t)2L2, (4.10)

    where T is small enough. To derive higher-order estimates, similar to the proof of Lemma (2.3)–(2.5), we can obtain

    sup0tTDαYn+1(t)L212sup0tTDαYn(t)2L2,  1αs. (4.11)

    Combining (4.10) and (4.11) yields

    sup0tTYn+1(t)Hs12sup0tTYn(t)Hs,

    so we complete the proof of the lemma.

    So far, we complete the proof of local existence.

    Lemma 4.3. Let (ρ1,01,u1,0,ρ2,01,u2,0,Φ0)Hs+1(s4), and

    (ρ1,01,u1,0,ρ2,01,u2,0,Φ0)L2(R3)L1(R3)E0,

    where E0 is sufficiently small, then there exists a time T>0, such that the Cauchy problem (1.1) and (1.2) admits a unique classical solution in [0, T) that satisfies

    (ρ11,u1,ρ21,u2)L([0,T);Hs+1),  (u1,u2)L2([0,T);Hs+1).

    In this subsection, we will establish the global solution to the systems (1.1) and (1.2) by using the bootstrap argument if the initial data satisfies

    (ρ1,0,ρ2,0,u1,0,u2,0,Φ0)L2L1E0, (4.12)

    where E0 is sufficiently small. However, for the derivatives of ρ1,0,ρ2,0,u1,0,u2,0, and Φ0, we only assume that they are bounded. Now, we first give the following abstract bootstrap argument.

    Lemma 4.4. [32] Let T>0. Assume that two statements C(t) and H(t) with t[0,T] satisfy the following conditions:

    1) If H(t) holds for some t[0,T], then C(t) holds for the same t;

    2) If C(t) holds for some t0[0,T], then H(t) holds for t in a neighborhood of t0;

    3) If C(t) holds for tm[0,T] and tmt, then C(t) holds;

    4) C(t) holds for at least one t1[0,T].

    Then, C(t) holds on [0,T].

    For any fixed 0<T<, t[0,T], through the regularity criterion in the Section 2, we know that if (ρ1,ρ2,u1,u2,Φ)(x,t) satisfies

    (ρ1(t)L(R3),u1(t)L(R3),ρ2(t)L(R3),u2(t)L(R3))C(1+t)2,

    and

    ρ1(t)L(R3)ε1 and  ρ2(t)L(R3)ε1,

    where ε1>0 is small enough, then

    (ρ1,u1,ρ2,u2,Φ)L([0,T];Hs+1)+(u1,u2)L2([0,T];Hs+1)C,

    where s4. From (3.1) and (3.2), we get

    (ρ1,0,u1,0,ρ2,0,u2,0,Φ0)L2L1E0,

    is equal to

    (n0,v0,m0,w0,Φ0)L2L1E0, (4.13)

    and

    (ρ1(t)L(R3),u1(t)L(R3),ρ2(t)L(R3),u2(t)L(R3))C(1+t)2,

    is equal to

    (n(t)L(R3),v(t)L(R3),m(t)L(R3),w(t)L(R3))C(1+t)2, (4.14)

    as well as

    ρ1L(R3)ε1 and  ρ2L(R3)ε1,

    is equal to

    nL(R3)ε1 and  mL(R3)ε1,

    For convenience, in this subsection, we use the condition (4.13) and the assumption (4.14). Let δ be a fixed positive number, say,

    2V0L1L2+2V0Lδ2,

    where V0 is defined as V0=(n0,v0,m0,w0,Φ0)T. For any fixed 0<T<,t[0,T], let us denote

    C(T):(n(t)L(R3),v(t)L(R3),m(t)L(R3),w(t)L(R3))δ2(1+t)2

    and

    H(T):(n(t)L(R3),v(t)L(R3),m(t)L(R3),w(t)L(R3))δ(1+t)2, (4.15)

    Based on the local existence of solutions, we only need to verify the condition 1 in Lemma (4.4) under the condition (4.12), i.e., given H(T) as the condition, to derive C(T) is valid. Before we check the condition 1, we need some lemmas.

    Lemma 4.5. Under the assumption (4.15) and the condition (4.13), the following estimate holds:

    (n,v,m,w,Φ)L(0,T;L2(R3))CE0,   T(0,+). (4.16)

    Proof. By (4.15) and Lemma 2.2, we complete the proof of the lemma.

    Lemma 4.6. Under the assumption (4.15) and the condition (4.13), we have

    ((n,v,m,w)(t)L(R3)CE250(1+t)65,
    (n,v,m,w)(t)L2(R3)CE17280(1+t)34,
    (v,m)(t)L4(R3)C(1+t)118,   t[0,T].

    Proof. By the Gagliardo-Nirenberg inequality, we know

      (n,v,m,w)(t)L(R3)C(n,v,m,w)(t)25L2(n,v,m,w)(t)35L(R3)CE250(1+t)65,v(t)L2CΛ1+ϵv(t)θLv(t)1θL2, (4.17)

    and

    Λ1+ϵv(t)LCv(t)|1βLΛ1+kϵv(t)βL, (4.18)

    where θ=22ϵ+5,β=1k. Then, from (4.17) and (4.18), we have

    v(t)L2Cv(t)122ϵ+5L2v(t)(11k)22ϵ+5LCE122ϵ+50(1+t)(11k)42ϵ+5.

    Taking k=1ϵ, ϵ=122 in the above inequality, we obtain

    v(t)L2(R2)CE17280(1+t)34.

    The same computation also gives

    (n,m,w)(t)L2(R2)CE17280(1+t)34.

    By the interpolation inequality, it holds

    (v,w)(t)L4C(v,w)12L2(v,w)12L.C(1+t)(1234+122)=C(1+t)118.

    Thus we complete the proof of the lemma.

    Lemma 4.7. Under the condition (4.13), we have

    (n(t),m(t))L1(R3)CE0.

    Proof. By (3.3)1 and (3.3)3, and using the condition (4.13), we can obtain the result.

    Now let us use Green's function to prove some lemmas. To begin, by Duhamel's principle, we know

    V(t)=G(t)V0+t0G(ts)N(V)(s)ds, (4.19)

    where

    V=(nvmw), V0=(n0v0m0w0)=:(V10V20V30V40), N(V)=:(Q1Q2Q3Q4). (4.20)

    where the Qi(i=1,2,3,4) are defined by (3.4)(3.7). From (4.19), for the component v and w of V, we have

    v=(4k=1G2,k(t))Vk0+t04k=1G2,k(ts)Qk(s))ds4k=1G3,k(t))Vk0+t04k=1G3,k(ts)Qk(s))ds4k=1G4,k(t))Vk0+t04k=1G3,k(ts)Qk(s))ds)=:(M1M2M3), (4.21)
    w=(8k=5G6,k(t))Vk0+t08k=5G6,k(ts)Qk(s))ds8k=5G7,k(t))Vk0+t08k=5G7,k(ts)Qk(s))ds8k=5G8,k(t))Vk0+t08k=5G8,k(ts)Qk(s))ds)=:(N1N2N3), (4.22)

    where G(t)V0, G(ts)N(V)(s) obey matrix multiplication.

    Lemma 4.8. Under the assumption (4.15) and the condition (4.13), it holds that

    (v(t),w(t))L1(R3)CE250,  t[0,T].

    Proof. Because we can't directly get the estimate of (v(t),w(t))L1, we first obtain the boundedness of (v(t),w(t))Lr for some r(1,2). In the following, we take r=43.

    We first consider (v,w)(t)Lr. By (4.21) and the representation (3.15) of S, we have

       M1Lr4k=1G2,k(t))Vk0Lr+t04k=1G2,k(ts)Qk(s))Lrds4k=1G2,kL(t))Vk0Lr+4k=1G2,kRH(t))Vk0Lr+t04k=1G2,kL(ts)Qk(s))Lrds+t04k=1G2,kRH(ts)Qk(s))Lrds=:4i=1Pi. (4.23)

    For the estimate of the linear part, it is easy to check that

    P1CV0L1CE0,  P2CeC0tV0L1CE0. (4.24)

    For the estimate of the nonlinear part, utilizing the definitions (3.4)–(3.7) of Qi, we have

    P3t04k=1G2,kL(ts)Qk(s))L1rdst0(1+ts)32(11r)12(n(s)L1+m(s)L1)(v(s)L+w(s)L)ds+t0(1+ts)32(11r)(v(s)L2+w(s)L2)(v(s)L2+w(s)L2)ds+t0(1+ts)32(11r)(n(s)L2+m(s)L2)(n(s)L2+m(s)L2)ds+t0(1+ts)32(11r)(2v(s)L2+2w(s)L2)(n(s)L+m(s)L)dsCE0t0(1+ts)78(1+s)65ds+CE0t0(1+ts)38(1+s)34ds+CE250t0(1+ts)38(1+s)65dsCE250, (4.25)

    and

    P4t04k=1G2,kRH(ts)Qk(s))L1rdsCt0eC0(ts)(n(s)L1+m(s)L1)(v(s)L+w(s)L)ds+Ct0eC0(ts)(v(s)L2+w(s)L2)(v(s)L2+w(s)L2)ds+Ct0eC0(ts)(n(s)L2+m(s)L2)(n(s)L2+m(s)L2)ds+Ct0eC0(ts)(2v(s)L2+2w(s)L2)(n(s)L2+m(s)L2)dsCE750t0eC0(ts)(1+s)65ds+CE0t0eC0(ts)(1+s)34ds+CE0t0eC0(ts)dsCE250. (4.26)

    Combining (4.24)–(4.26), we obtain

    M1L43CE250.

    The same procedure gives

    3i=1(MiL43+NiL43)CE250.

    So far, we can obtain

    (v(t),w(t))L43CE250.

    Now, we can obtain the estimate of (v,w)L1 by using (v,w)L43. For M1,

    M1L14k=1G2,kL(t))Vk0L1+4k=1G2,kRH(t))Vk0L1+t04k=1G2,kL(ts)Nk(s))L1ds+t04k=1G2,kRH(ts)Nk(s))L1ds=:4i=1Fi.

    A simple check gives us that

    F1CV0L1CE0,
    F2CeC0tV0L1CE0.

    Then, by using Lemma 4.6 and Young's inequality for convolution, we have

    F3t04k=1G2,kL(ts)Qk(s))L1dst0(1+ts)32(11)12(n(s)L1+m(s)L1)(v(s)L+w(s)L)ds+t0(1+ts)32(11)(v(s)L43+w(s)L43)(v(s)L4+w(s)L4)ds+t0(1+ts)32(11)(n(s)L1+m(s)L1)(n(s)L+m(s)L)ds+t0(1+ts)32(11)(2v(s)L2+2w(s)L2)(n(s)L+m(s)L)dsCE0t0(1+ts)12(1+s)65ds+CE250t0(1+s)118ds+CE0t0(1+s)2ds+CE250t0(1+s)65dsCE250, (4.27)

    and

    F4t04k=1G2,kRH(ts)Qk(s))L1dsCt0eC0(ts)(n(s)L1+m(s)L1)(v(s)L+w(s)L)ds+Ct0eC0(ts)(v(s)L2+w(s)L2)(v(s)L2+w(s)L2)ds+Ct0eC0(ts)(n(s)L2+m(s)L2)(n(s)L2+m(s)L2)ds+Ct0eC0(ts)(2v(s)L2+2w(s)L2)(n(s)L2+m(s)L2)dsCE750t0eC0(ts)(1+s)65ds+CE0t0eC0(ts)(1+s)34ds+CE0t0eC0(ts)dsCE250. (4.28)

    Combining the estimate of each Fi, we obtain

    M1L1CE250.

    The same procedure gives

    3i=1(MiL1+NiL1)CE250.

    So far, we can obtain

    (v(t),w(t))L1CE250,

    and we complete the proof of the lemma.

    Lemma 4.9. Under the assumption (4.15) and the condition (4.13), we have

    2V(t)L(R3)CE180(1+t)65,  t[0,T]. (4.29)

    Proof. Applying Duhamel's principle, we have

    D2V(t)=D2(G(t)V0)+t0D2(G(ts)N(V)(s))ds.

    Then,

    D2V(t)L(R3)D2(G(t)V0)L(R3)+t0D2(G(ts)N(V)(s))L(R3)ds.

    Now we estimate the righthand side of the inequality. Simple computation yields

       D2(G(t)V0)L(R3)D2(GL(t)V0)L(R3)+D2(GRH(t)V0)L(R3)+D2(S(t)V0)L(R3)CV0L1(R3)(1+t)52+CDGRHL2(R3)DV0L2(R3)+CD2V0L(R3)eC0tCV0L1(R3)(1+t)52+CV012L2(R3)D2V012L2(R3)eC0t+CV018L2(R3)D4V078L2(R3)eC0tC(V0L1(R3)+V018L2(R3))(1+t)65CE180(1+t)65, (4.30)

    and

       t0D2(G(ts)N(V)(s))L(R3)dst0D2(GL(ts)N(V)(s))L(R3)ds+t0D2(GRH(ts)N(V)(s))L(R3)ds+t0D2(S(ts)N(V)(s))L(R3)ds=:3i=1Oi.

    Now we turn to estimate each Oi. By the definition (4.20) of N(V), we easily check that

    O1t0D2GL(ts)L2(n(s)L2+m(s)L2+v(s)L2+w(s)L2)(v(s)L+w(s)L+n(s)L+m(s)L)ds+t0D2GL(ts)L2(v(s)L2+w(s)L2)(v(s)L+w(s)L)ds+t0D2GL(ts)L2(n(s)L2+m(s)L2)n(s)L+m(s)L)ds+t0D2GL(ts)L2(2v(s)L2+2w(s)L2)(n(s)L+m(s)L)ds. (4.31)

    Using Sobolev's inequality, we obtain

    then for , we have

    (4.32)

    For , we can get

    (4.33)

    Also by Sobolev's inequality, it holds

    then we have

    (4.34)

    For , we have

    (4.35)

    Sobolev's inequality gives

    (4.36)

    then we have

    (4.37)

    Combining (4.32), (4.34), and (4.37), we obtain

    (4.38)

    Using (4.30) and (4.38), we complete the proof of the lemma.

    With the above lemmas at hand, we now check the condition 1 of Lemma 4.4, that is, the following lemma.

    Lemma 4.10. Under the assumption (4.15) and the condition (4.13), we have

    Proof. Duhamel's principle gives rise to

    Then

    Similar to the proof of Lemma 4.9, it holds for the first term on the righthand side of the inequality that

    (4.39)

    For for the second term on the right side of the inequality, it is easy to get that

    For the nonlinear part of lower frequency, Lemma 4.5 gives

    (4.40)

    For the terms of Lemma 4.5 gives

    By Lemmas 3.2 and 4.5–4.9, we have

    (4.41)

    The same procedure gives

    (4.42)

    and

    (4.43)

    Combining (4.40), (4.41), (4.42), and (4.43), we have

    (4.44)

    For the nonlinear part of high frequency, Lemma 4.5 gives

    (4.45)

    and

    (4.46)

    (4.45) and (4.46) gives

    (4.47)

    For the nonlinear part estimate for the singular part, by Lemmas 4.6 and 4.9, we have

    (4.48)

    Combining (4.43), (4.47), and (4.48), we obtain

    (4.49)

    By (4.39) and (4.49), we complete the proof of the lemma.

    Under the condition (4.13), the bootstrap argument and the local existence of the solutions for the syestem (1.1) and (1.2) gives the following result.

    Proposition 4.1. Let and

    where is sufficiently small, then the Cauchy problem (1.1) and (1.2) has a global solution in time that satisfies

    and

    (4.50)

    In this section, we would like to get the decay rate of solutions. The main result is stated as follows.

    Proposition 5.1. Let and

    where is sufficiently small, is the solutions for the Cauchy problem (1.1) and (1.2), then when and it holds

    Proof. From (3.1) and (3.2), the decay rate of is equivalent to the decay rate of . Therefore, we only need to consider the attenuation estimate of . Note that if the decay rate of the higher-order spatial derivatives of the solution are obtained, then the general decay rate of the solution follows by the Sobolev interpolation. For instance, using the Sobolev embedding theorem, we have

    where V(t) is defined as (3.10). So we only consider the decay of Below we will prove the following assertion by induction,

    (5.1)

    When we have

    For the terms and , we have

    Then, from Proposition (4.1), using Sobolev's inequality, we obtain

    and

    For the term , from Proposition (4.1), we have

    We assume that (5.1) holds when and later we shall prove that (5.1) holds when To get the estimate of we perform high and low frequency decomposition of the solution itself. The low frequency part of the solution V is

    and the high frequency part of the solution V is

    where is a pseudo-differential operator with symbol we can see (3.14) for the definition of Then, we can decompose as follows:

    (5.2)
    (5.3)

    where , , and are defined in (3.12), (3.13), and (4.20), respectively. We define as follows:

    (5.4)

    Here, and , and are defined in (3.4)–(3.7). For , we have

    Then, (5.2) and (5.3) are equal to

    (5.5)
    (5.6)

    Now let us estimate (5.5) and (5.6) separately. For the low frequency part, we have

    For we have

    For we first estimate

    Then, for we have

    For we have

    where we use the Gagliardo-Nirenberg inequality to obtain the estimate for and . Combining the estimate of , , and , we obtain the low frequency part estimate of

    For the high frequency part of , by Lemma 3.5, we have

    (5.7)

    By the definition of in (3.16), we know (5.7) is equal to

    (5.8)

    Now we turn to estimate each To start, for

    (5.9)

    From the definition of and in (4.20), (5.4), we have

    (5.10)

    For the nonlinear item, we can check without difficulty that

    (5.11)

    From the conclusion of Proposition (4.1), we know (4.14) holds, i.e.,

    (5.12)

    and by the Sobolev embedding theorem, we have

    (5.13)

    Now for we can obtain

    For , we have

    With the help of (5.11)–(5.13), we can get the estimates of as follows. By using Lemma 3.4, we can get the estimate for ,

    where we used the (5.1) when in the last inequality of the above. The estimate of is parallel to i.e.,

    By integrating by parts, the estimate of is similar to then we have

    As for by the defination of , and using (5.12) and (5.13), we have

    By the Gagliardo-Nirenberg inequality, we have

    Then, for it holds

    By the same analysis as it holds

    By the definition of in (3.17) and in (5.10), we have

    Combining the estimate for each , and from (5.7), it holds,

    (5.14)

    To close the estimate, we take our attention to the estimate of From we know

    For the linear partition, we have

    For the nonlinear partition, we still adopt the method of high and low frequency decomposition of the solution. Here we omit the details of the calculation since the analysis is parallel to the estimate of

    For we have

    (5.15)

    The same way also gives

    (5.16)

    Combing (5.14)–(5.16), since the is small enough, we have

    Now we proved (5.1) when The proposition is proved.

    The authors declare they have not used Artificial Intelligence (AI) tools in the creation of this article.

    This work was partially supported by the National Natural Science Foundation of China (Nos.12271357, 12161141004) and Shanghai Science and Technology Innovation Action Plan (No.21JC1403600).

    The authors declare there is no conflicts of interest.



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