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Boundedness of a predator-prey model with density-dependent motilities and stage structure for the predator

  • In this paper, we consider a predator-prey model with density-dependent prey-taxis and stage structure for the predator. We establish the existence of classical solutions with uniform-in-time bound in a one-dimensional case. In addition, we prove that the solution stabilizes to the prey-only steady state under some conditions.

    Citation: Ailing Xiang, Liangchen Wang. Boundedness of a predator-prey model with density-dependent motilities and stage structure for the predator[J]. Electronic Research Archive, 2022, 30(5): 1954-1972. doi: 10.3934/era.2022099

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  • In this paper, we consider a predator-prey model with density-dependent prey-taxis and stage structure for the predator. We establish the existence of classical solutions with uniform-in-time bound in a one-dimensional case. In addition, we prove that the solution stabilizes to the prey-only steady state under some conditions.



    This paper deals with the predator-prey model with density-dependent motilities and stage structure for the predator

    {ut=(d1(w)u)xx+bvcu,xΩ,t>0,vt=(d2(u)v)xx+kuwv,xΩ,t>0,wt=d3wxx+aww2uwrvw,xΩ,t>0,uν=vν=wν=0,xΩ,t>0,u(x,0)=u0(x),v(x,0)=v0(x),w(x,0)=w0(x),xΩ, (1.1)

    under homogeneous Neumann boundary conditions in a smooth bounded domain ΩR and /ν represents the outer unit normal vector of Ω, where u=u(x,t),v=v(x,t) and w=w(x,t) are the densities of the mature predator, immature predator and prey at position x and time t, respectively. d3,a,b,c,k,r are positive constants and more details of the parameters can be found in [1,2]. The terms (d1(w)u)xx and (d2(u)v)xx state that the motility functions d1(w) and d2(u) have some influence on the diffusion of mature predator and immature predator.

    Biological predator-prey model plays a critical role in survival and reproduction of organisms, especially the predator-prey system with stage structure of predator describes the biological predator-prey phenomenon and its irregular movement more vividly(see [3,4,5,6,7] and reference therein). Recently, the following stage structure of predator with taxis mechanisms model has been studied by Wang and Wang [2]:

    {ut=d1Δuχ(uw)+bvcu,xΩ,t>0,vt=d2Δvρ(vu)+kuwv,xΩ,t>0,wt=d3Δw+aww2uwrvw,xΩ,t>0,uν=vν=wν=0,xΩ,t>0,u(x,0)=u0(x),v(x,0)=v0(x),w(x,0)=w0(x),xΩ. (1.2)

    In the case n=1 with ρ>0 and n=2 with ρ=0, the authors [2] first established that the solutions of problem (1.2) are global existence and boundedness. Secondly, the linearized stability of normal steady state and predator-free steady state are obtained by using local bifurcation and Hopf bifurcation theory. Moreover, they proved the global stability of predator-free steady state. On the other hand, many scholars have also studied the stage state for prey [8,9] and the different state of the predator[10].

    In order to describe the movement of species more meaningfully, we illustrate a chemotaxis system with density-dependent motility to describe the motility law of predators. At present, this kind of model is mostly used in the field of chemical signal substances. The classic model is proposed in [11]

    {ut=Δ(γ(v)u)+μu(1u),xΩ,t>0,vt=Δvv+u,xΩ,t>0, (1.3)

    where u(x,t) is the densities of bacteria and v(x,t) is the concentration of AHL at position x and time t. This system describes bacteria with logistic sources whose diffusion rate depends on the motion function γ(v), which considers the repressive effect of AHL concentration on bacteria motility by supposing γ(v)<0. This diffusion mechanism is called "density suppression motility" in [12,13]. Therefore, it is a very interesting phenomenon and has been widely studied. If μ>0, Jin et.al [14] proved that the problem in two dimensions possesses a global classical solution and coexistence steady state is globally asymptotically stable. Yoon and Kim [15] obtained a global classical solution with μ=0 and a particular form of γ(v)=c0vk,c0>0,k>0 in any dimensions provided c0 is small. Moreover, Tao and Winkler [16] proved that some weak solutions exist globally under high dimensional conditions and in a specific three-dimensional case, this solution is bounded and classical with μ=0. We refer the readers to [17,18,19,20,21,22,23,24] for other interesting results on density-suppressed model.

    Recently, this kind of model is also studied in the predator-prey mode [25,26]. In [26], the following density-dependent model with homogeneous Neumann boundary conditions is proposed

    {ut=Δ(d1(w)u)+u(a1wb1uc1v),xΩ,t>0,vt=Δ(d2(w)v)+v(a2wb2uc2v),xΩ,t>0,wt=Δww(u+v)+μw(m(x)w),xΩ,t>0, (1.4)

    when b1=c2,c1=c,b2=b and m(x)=1, the model (1.4) exists the global bounded classical solution, and asymptotic behavior is derived in different parameter regimes. di(w)(i=1,2) indicates the resource dependent diffusion rate of species with monotonic properties: di(w)<0(i=1,2), which is consistent with the fact that predators reduce their random diffusion when encountering the prey observed by kareiva and odell [27]. The major difference between (1.1) and (1.4) is that the motility of immature predators are influenced by mature predators rather than prey and mature predators grow from immature predators. Hence, due to its biological significance, the density-dependent model has attracted the interest of many scholars.

    The goal of this paper is to establish global existence and large time behavior of classical solutions to the model (1.1). We shall suppose that there exist η2>η1>0 such that d1(w) and d2(u) satisfy

    (H1)d1(w)C3([0,)),d1(w)>0 and d1(w)0 for all w0,

    (H2)d2(u)C3([0,)),η1d2(u)η2 for all u0.

    In this paper, the main results are stated as below. Our first result derives global boundedness of classical solution to (1.1).

    Theorem 1.1. Let ΩR be a bounded domain with smooth boundary and the assumptions (H1)(H2) hold. Suppose that the parameters a,b,c,k,r>0 and (u0,v0,w0)[W1,(Ω)]3 with u0,v0,w00. Then the model (1.1) has a unique nonnegative classical solution (u,v,w) satisfying

    u(,t)L(Ω)+v(,t)L(Ω)+w(,t)W1,(Ω)Cfor allt>0, (1.5)

    where C>0 is a constant. Particularly, we have 0wM, where

    M:=max{a,w0L}.

    The second result is that we consider the global stability of the classical solution obtained in Theorem 1.1.

    Theorem 1.2. Let (u0,v0,w0)[W1,(Ω)]3 with u0,v00(0) and w0>0 in ˉΩ. The solution (u,v,w) of (1.1) obtained in Theorem 1.1 has the following properties: If the positive parameters a,b,c,k and r satisfy cabkkcar>1, then

    u(,t)L(Ω)+v(,t)L(Ω)+w(,t)aL(Ω)0ast. (1.6)

    In the paper, for simplicity, we abbreviate t0Ωf(,s)dxds, Ωf(,s)ds, Lp(Ω) and W1,p(Ω) as t0Ωf, Ωf, p and 1,p, respectively. Moreover, C stands for a generic positive constant which may alter from line to line and is independent of time.

    The organizational structure of this paper is as below. In Section 2, we show the local existence of a solution to (1.1) and some preliminary results are given. In Section 3, we establish global existence and boundedness for the model (1.1) and proof of Theorem 1.1. Section 4, we obtain the prey-only global stability to achieve Theorem 1.2.

    We first give the existence of local solutions of (1.1) by using Amann's theorem [28,29](cf. also[30,Lemma 1.1] or [31,Lemma 2.6]).

    Lemma 2.1. (Local existence).Let ΩR be a bounded domain with smooth boundary. Suppose that the parameters a,b,c,k,r>0 and the assumptions (H1)(H2) hold. Assume that (u0,v0,w0)[W1,(Ω)]3 with u0,v0,w00. Then there exists a constant Tmax(0,] such that the problem (1.1) has a unique nonnegative classical solution (u,v,w) and satisfies

    (u,v,w)[C0(¯Ω×[0,Tmax))C2,1(¯Ω×(0,Tmax)Lloc([0,Tmax);W1,(Ω))]3,

    and which is such that if Tmax<,

    u(,t)L(Ω)+v(,t)L(Ω)+w(,t)W1,(Ω)astTmax.

    Moreover, if the initial data (u0,v0,w0)[W1,(Ω)]3 with u0,v00(0) and w0>0 in ˉΩ, then the solution of (1.1) satisfies u,v,w>0 in ¯Ω×(0,Tmax).

    Lemma 2.2. ([32,Lemma 2.2]) Let the assumptions in Lemma 2.1 hold. Then the solution (u,v,w) of system (1.1) fulfills that

    0w(x,t)Mfor allxΩ,t>0, (2.1)

    where M:=max{a,w0L}, and it also founds that

    lim suptw(x,t)afor allxˉΩ. (2.2)

    In order to prove our results, we will quote the following lemma.

    Lemma 2.3. ([33,Lemma 2.3]) Let T>0 and τ(0,T), assume that a,b>0, and y:[0,T)[0,) is absolutely continuous and satisfies

    y(t)+ay(t)b(t)

    with some nonnegative function b(t)L1loc([0,T)) fulfilling

    t+τtb(s)dsbfor allt[0,Tτ).

    Then

    y(t)max{y(0)+b,baτ+2b}for allt(0,T).

    Lemma 2.4. ([34,Lemma 2.4]) Let T>0 and τ(0,T), assume that α,β>0, and y:[0,T)[0,) is absolutely continuous and satisfies

    y(t)+a(t)y(t)b(t)y(t)+c(t)

    with the nonnegative functions a(t),b(t),c(t)L1loc([0,T)) fulfilling

    sup0tTt+τtb(s)dsαfor allt[0,Tτ)

    and

    sup0tTt+τtc(s)dsβfor allt[0,Tτ).

    Moreover, there also exists a positive constant ρ satisfies

    t+τta(s)dst+τtb(s)ds>ρfor allt[0,Tτ).

    Then

    y(t)eα(y(0)+βeα1eρ+β)for allt(0,T).

    Lemma 5. Under the assumptions in Theorem 1.1, the solution (u,v,w) of (1.1) fulfills

    ΩuCandΩvCfor allt(0,Tmax), (2.3)

    where C>0 is a constant.

    Proof. The first equation of (1.1) adds the second equation of (1.1) multiplied by b+1 and adds the third equation of (1.1) multiplied by k(b+1), then integrating we have

    ddtΩ(u+(b+1)v+k(b+1)w)+Ω(cu+v+w)=(ka(b+1)+1)Ωwk(b+1)Ωw2k(b+1)Ωrvw(ka(b+1)+1)M|Ω|. (2.4)

    Using Gronwall's inequality to (2.4), we obtain (2.3) immediately.

    Next, we shall obtain W1,p bound for the prey w(,t).

    Lemma 2.6. Under the assumptions in Theorem 1.1 and (u,v,w) is a solution of (1.1), for any p>1, there exists a constant C>0 such that

    wx(,t)pCfor allt(0,Tmax). (2.5)

    Proof. By the variation-of-constants method, w can be written as

    w(,t)=ed3tΔw0+t0ed3(ts)Δ(aww2uwrvw),

    using (2.1) and (2.3), then there exists a constant c1>0 satisfies

    aww2uwrvw1aw1+w21+uw1+rvw1c1. (2.6)

    According to standard LpLq estimates in [35,Lemma 1.3], there exist λ>0 and some constants ci>0(i=2,3) such that

    wx(,t)pc2w01,+c2t0eλ(ts)(1+(ts)1+12p)aww2uwrvw1c2w01,+c1c2t0eλ(ts)(1+(ts)1+12p)c3

    for all t(0,Tmax). Hence, the proof of (2.5) is completed.

    Next, we apply the method of [25,Lemma 2.3] to obtain the following estimates.

    Lemma 2.7. Under the conditions in Theorem 1.1 and (u,v,w) is a solution of (1.1). Then there exists a constant C>0 such that

    t+τtΩu2Candt+τtΩv2Cfor allt(0,Tmaxτ), (2.7)

    where τ=min{1,Tmax2}.

    Proof. Let A represents the self-adjoint realization of Δ+δ ([36,Lemma 3.1]) under homogeneous Neumann boundary conditions in L2(Ω) and

    0<δ<min{cd1(0),1(b+1)η2}, (2.8)

    where η2>0 is from (H2) and

    d1(0)=max0wMd1(w)

    due to (H1) and Lemma 2.2. Since δ>0, A has an order-preserving bounded inverse A1 on L2(Ω), then there exists a constant c1>0 such that

    A1ψ2c1ψ2for all ψL2(Ω) (2.9)

    and

    A12ψ22=ΩψA1ψc1ψ22for all ψL2(Ω). (2.10)

    From (1.1), we have

    (u+(b+1)v+k(b+1)w)t=Δ(d1(w)u+(b+1)d2(u)v+k(b+1)d3w)cuv+k(b+1)(aww2rvw),

    which can be rewritten as

    (u+(b+1)v+k(b+1)w)t+A(d1(w)u+(b+1)d2(u)v+k(b+1)d3w)=δ(d1(w)u+(b+1)d2(u)v+k(b+1)d3w)cuv+k(b+1)(aww2rvw)=(δd1(w)c)u+(δ(b+1)d2(u)1)v+k(b+1)(δd3w+aww2rvw). (2.11)

    Noting the facts (2.1), (2.8) and (H1)(H2), one can find c2:=kM(b+1)(δd3+a)>0 such that

    (δd1(w)c)u+(δ(b+1)d2(u)1)v+k(b+1)(δd3w+aww2rvw)(δd1(0)c)u+(δ(b+1)η21)v+c2c2. (2.12)

    Substituting (2.12) into (2.11), one has

    (u+(b+1)v+k(b+1)w)t+A(d1(w)u+(b+1)d2(u)v+k(b+1)d3w)c2,

    hence, multiplying the above inequality by A1(u+(b+1)v+k(b+1)w)0, we have

    12ddtΩ|A12(u+(b+1)v+k(b+1)w)|2+Ω(u+(b+1)v+k(b+1)w)(d1(w)u+(b+1)d2(u)v+k(b+1)d3w)c2ΩA1(u+(b+1)v+k(b+1)w),

    which together with the fact (H1)(H2), we can find d1(M)=min0wMd1(w) and c3:=min{d1(M),η1,d3} such that

    12ddtΩ|A12(u+(b+1)v+k(b+1)w)|2+c3Ω(u+(b+1)v+k(b+1)w)2c2ΩA1(u+(b+1)v+k(b+1)w). (2.13)

    By (2.9) and (2.10), we can obtain that

    c34c1Ω|A12(u+(b+1)v+k(b+1)w)|2+c2ΩA1(u+(b+1)v+k(b+1)w)c34Ω(u+(b+1)v+k(b+1)w)2+c1c2|Ω|12u+(b+1)v+k(b+1)w2c32Ω(u+(b+1)v+k(b+1)w)2+c21c22|Ω|c3.

    Therefore, combining with (2.13), and denoting y1(t):=Ω|A12(u+(b+1)v+k(b+1)w)|2, one has

    y1(t)+c32c1y1(t)+c3Ω(u+(b+1)v+k(b+1)w)22c21c22|Ω|c3.

    Then using Gronwall's inequality implies y1(t)c4 with some constant c4>0, thus

    t+τtΩu2t+τtΩ(u+(b+1)v+k(b+1)w)2y1(t)c3+2c21c22|Ω|τc23c4c3+2c21c22|Ω|c23for all t(0,Tmaxτ),

    because τ1. Similarly, we have

    t+τtΩv2c4c3+2c21c22|Ω|c23for all t(0,Tmaxτ).

    Hence, we can obtain (2.7).

    In addition, as the result of Lemma 2.7, we can deduce the following results.

    Lemma 2.8. Under the conditions in Theorem 1.1 and (u,v,w) is a solution of (1.1). Then there exists a constant C>0 such that

    t+τtΩw2xxCfor allt(0,Tmaxτ), (2.14)

    where τ=min{1,Tmax2}.

    Proof. Testing the third equation of (1.1) by wxx, using Young's inequality and (2.1), we have

    12ddtΩw2x=d3Ωw2xxaΩwwxx+Ωw2wxx+Ωuwwxx+rΩvwwxxd3Ωw2xx+d32Ωw2xx+2a2d3Ωw2+2d3Ωw4+2d3Ωu2w2+2r2d3Ωv2w2d32Ωw2xx+2M2d3Ωu2+2r2M2d3Ωv2+c1,

    where c1:=2M2|Ω|(a2+M2)d3, which yields

    ddtΩw2x+d3Ωw2xx4M2d3Ωu2+4r2M2d3Ωv2+2c1. (2.15)

    By the Gagliardo-Nirenberg inequality and the fact w2M|Ω|12, there exist some constants c2,c3>0 such that

    Ωw2x=wx22c2(wxx2w2+w22)d32wxx22+c3. (2.16)

    Combining (2.15) and (2.16), let c4:=2c1+c3, then we have

    ddtΩw2x+Ωw2x+d32Ωw2xx4M2d3Ωu2+4r2M2d3Ωv2+c4. (2.17)

    Let y(t):=Ωw2x and b(t):=4M2d3Ωu2+4r2M2d3Ωv2+c4. From (2.17) we have

    y(t)+y(t)+d32Ωw2xxb(t)for all t(0,Tmax), (2.18)

    by Lemma 2.7 implies there exists a constant c5>0 such that t+τtΩ(u2+v2)c5, therefore, we have

    t+τtb(s)c6:=4M2c5max{1,r2}d3+c4for all t(0,Tmaxτ),

    because τ1. Using (2.18) and Lemma 2.3 to ensure that

    y(t)c7:=max{Ω(w0)2x+c6,c6τ+2c6}for all t(0,Tmax).

    Therefore, an integration of (2.18) over (t,t+τ) yields

    y(t+τ)+t+τty(s)+d32t+τtΩw2xxy(t)+t+τtb(s)c7+c6

    for all t(0,Tmaxτ), which in view of the nonnegativity of y implies (2.14).

    In the first, we will obtain a priori L2estimate of the predator u.

    Lemma 3.1. Let the assumptions in Theorem 1.1 hold, then there exists a constant C>0 such that

    u(,t)2Cfor allt(0,Tmax). (3.1)

    Proof. Testing the first equation of (1.1) by u, integrating the result by part and using Young's inequality, we obtain

    12ddtΩu2+cΩu2+Ωd1(w)u2x=Ωd1(w)uuxwx+bΩuv12Ωd1(w)u2x+12Ω(d1(w))2d1(w)u2w2x+b22cΩv2+c2Ωu2,

    which yields

    ddtΩu2+cΩu2+Ωd1(w)u2xΩ(d1(w))2d1(w)u2w2x+b2cΩv2, (3.2)

    by Lemma 2.6 implies wx2c1 with some c1>0, thus using (H1) and (2.1), we have from (3.2) that

    ddtΩu2+cΩu2+d1(M)Ωu2xK21u2Ωw2x+b2cΩv2K21c21u2+b2cΩv2, (3.3)

    where K1:=max0wM|d1(w)|d1(M). By the Gagliardo-Nirenberg inequality, Young's inequality and (2.3), there exist constants ci>0(i=2,3) satisfy

    K21c21u2c2(ux432u231+u21)d1(M)2ux22+c3.

    This together with (3.3), one has

    ddtΩu2+cΩu2+d1(M)2Ωu2xb2cΩv2+c3. (3.4)

    Using (2.7) and Lemma 2.3, we derive (3.1).

    We are now in the position to derive some estimates for u.

    Lemma 3.2. Let the assumptions in Theorem 1.1 hold and (u,v,w) be a solution of (1.1). Then there exists a constant C>0 such that

    Ωu2x(,t)Cfor allt(0,Tmax), (3.5)
    t+τtΩu2xx(,t)Cfor allt(0,Tmaxτ) (3.6)

    and

    u(,t)Cfor allt(0,Tmax), (3.7)

    where τ=min{1,Tmax2}.

    Proof. Testing the first equation of (1.1) by uxx and using Young's inequality, we have

    12ddtΩu2x=Ωuxx(d1(w)uxx+d1(w)uwxx+2d1(w)uxwx+d1(w)uw2x+bvcu)Ωd1(w)u2xx+58Ωd1(w)u2xx+2Ω(d1(w))2d1(w)u2w2xx+2Ωc2d1(w)u2+8Ω(d1(w))2d1(w)u2xw2x+2Ω(d1(w))2d1(w)u2w4x+2Ωb2d1(w)v238Ωd1(w)u2xx+2u2Ω(d1(w))2d1(w)w2xx+2Ωc2d1(w)u2+8ux2Ω(d1(w))2d1(w)w2x+2u2Ω(d1(w))2d1(w)w4x+2Ωb2d1(w)v2.

    From Lemma 2.6, we choose p=2,4, then there exist c1,c2>0 such that wx2c1,wx4c2, we obtain

    ddtΩu2x+3d1(M)4Ωu2xx4K21u2Ωw2xx+16K21c21ux2+4K22c42u2+4b2d1(M)Ωv2+4c2d1(M)Ωu2. (3.8)

    where K2:=max0wM|d1(w)|d1(M). Using the Gagliardo-Nirenberg inequality and Lemma 3.1, for each ε>0 one can find some cε>0 and ci>0(i=3,4,5) such that

    u2c3(ux432u231+u21)εux22+cε (3.9)

    and

    16K21c21ux2c4(uxx322u122+u22)d1(M)4uxx22+c5. (3.10)

    Using Lemma 3.1 again, for some c6>0, we have u(,t)2c6. Substituting (3.9)-(3.10) into (3.8), we obtain

    ddtΩu2x+d1(M)2Ωu2xx4K21εux22wxx22+4K21cεwxx22+4K22c42εux22+4b2d1(M)Ωv2+c7, (3.11)

    where c7:=c5+4K22c42cε+4c2c26d1(M). Using (3.1), for some c8,c9>0, we obtain

    (4K22c42ε+1)ux22c8(uxx2u2+u22)d1(M)4uxx22+c9.

    Combining it with (3.11), there exists c10>0 satisfying

    ddtΩu2x+Ωu2x+d1(M)4Ωu2xx4K21εux22wxx22+4K21cεwxx22+4b2d1(M)Ωv2+c10. (3.12)

    From Lemma 2.8, one has t+τtΩw2xxc11 with some c11>0. Let a(t):=1,b(t):=4K21εwxx22 and c(t):=4K21cεwxx22+4b2d1(M)Ωv2+c9, choosing ε=τ8K21c11>0 such that t+τta(s)dst+τtb(s)ds=τ2>0. Hence, using Lemma 2.4, we can derive the boundedness of Ωu2x(,t) for all t(0,Tmax). Furthermore, (3.6) can be obtained upon an integration in time for (3.12). Finally, using the boundedness of Ωu2x(,t) and (3.9), which implies (3.7).

    Now we establish some estimates of v.

    Lemma 3.3. Let the assumptions in Theorem 1.1 hold, then there exists a constant C>0 such that

    Ωv2(,t)Cfor allt(0,Tmax) (3.13)

    and

    t+τtΩv2x(,t)Cfor allt(0,Tmaxτ), (3.14)

    where τ=min{1,Tmax2}.

    Proof. Testing the second equation of (1.1) by v, integrating and using Young's inequality, we have

    12ddtΩv2=Ωvx(d2(u)vx+d2(u)vux)+kΩuvwΩv2Ωd2(u)v2x+14Ωd2(u)v2x+Ω(d2(u))2d2(u)v2u2x+k2M22Ωu2+12Ωv2Ωv234Ωd2(u)v2x+Ω(d2(u))2d2(u)v2u2x+k2M22Ωu212Ωv2.

    From (3.7), we can find a constant u>0 such that 0u ess supΩu=uu. Using (H2), which yields

    ddtΩv2+Ωv2+3η12Ωv2x2K23v24ux24+k2M2Ωu2, (3.15)

    where K3:=max0uu|d2(u)|η1. Using the Gagliardo-Nirenberg inequality, there exist some constants ci>0(i=1,2,3) such that

    v24c1(vx2v1+v21)c2(vx2+1) (3.16)

    and

    ux24c3(uxx2ux1+ux21)c3(12uxx2ux22+|Ω|2uxx2+|Ω|ux22), (3.17)

    where we use Young's inequality and the Cauchy-Schwarz inequality. Using (3.5), there exists a constant c4>0 such that

    ux24c4(uxx2+1). (3.18)

    By Lemma 3.1, there exists c5>0 such that u(,t)2c5. Substituting (3.16) and (3.18) into (3.15) and using Young's inequality, we have

    ddtΩv2+Ωv2+3η12Ωv2x2K23c2c4(vx2+1)(uxx2+1)+k2M2Ωu2η12Ωv2x+4K43c22c24+η1η1Ωu2xx+c6, (3.19)

    where c6:=k2M2c25+2K23c2c4η1+4K43c22c24+K43c22c24η1η1, which yields

    ddtΩv2+Ωv2+η1Ωv2x4K43c22c24+η1η1Ωu2xx+c6.

    Using (3.6) and Lemma 2.3, we derive (3.13) and (3.14).

    Finally, we shall establish the estimate of v(,t).

    Lemma 3.4. Let the assumptions in Theorem 1.1 hold, then there exists a constant C>0 such that

    v(,t)Cfor allt(0,Tmax). (3.20)

    Proof. Testing the second equation of (1.1) by vxx and using Young's inequality yields

    12ddtΩv2x=Ωvxx(d2(u)vxx+d2(u)vuxx+2d2(u)uxvx+d2(u)vu2x+kuwv)Ωd2(u)v2xx+48Ωd2(u)v2xx+2Ω(d2(u))2d2(u)v2u2xx+8Ω(d2(u))2d2(u)u2xv2x+2Ω(d2(u))2d2(u)v2u4x+2Ωk2M2d2(u)u2Ωv2x12Ωd2(u)v2xx+2v2Ω(d2(u))2d2(u)u2xx+8vx2Ω(d2(u))2d2(u)u2x+2ux4Ω(d2(u))2d2(u)v2+2Ωk2M2d2(u)u2Ωv2x.

    From Lemmata 2.5, 3.2 and 3.3, there exists ci>0(i=1,2,3) satisfies v(,t)1c1, ux(,t)22c2, v(,t)22c3. Using the Gagliardo-Nirenberg inequality, for each ε>0 one can find some cε>0 and ci>0(i=4,5,6,7,8) such that

    v2c4(vx432v231+v21)εvx22+cε

    and

    vx2c5(vxx322v122+v22)η116K23c2vxx22+c6

    as well as

    ux4c7(uxx22ux22+ux42)c8(uxx22+1).

    From Lemma 3.1, for some c9>0, one has u(,t)2c9. Combining with the above inequalities and using (H2), we conclude

    ddtΩv2x+2Ωv2x4K23εvx22uxx22+(4K23cε+4K24c3c8)uxx22+c10.

    where K4:=max0uu|d2(u)|η1 and c10:=16K23c2c6+4K24c3c8+4k2M2c29η1. From (3.6), one has t+τtΩu2xxc11 with some c11>0. Using Lemma 2.4, denoting a(t):=2, b(t):=4K23εuxx22 and c(t):=(4K23cε+4K24c3c8)uxx22+c10, choosing ε=τ4K23c11 such that t+τta(s)dst+τtb(s)ds=τ>0, therefore, we derive the boundedness of Ωv2x(,t). Finally, using the boundedness of Ωv2x(,t) and the Gagliardo-Nirenberg inequality, we obtain (3.20).

    We can now easily prove Theorem 1.1.

    Proof of Theorem 1.1. From Lemmata 3.1 and 3.3, there exists a constant C>0 satisfies u(,t)2+v(,t)2C for all t(0,Tmax), then we have w(,t)1,C ([32,Lemma 3.1]), combining Lemmata 3.2, 3.4 and 2.1, we can obtain Theorem 1.1 immediately.

    In this section, we shall construct appropriate Lyapunov functional to derive the global stability in Theorem 1.2.

    Lemma 4.1. ([26,Lemma 3.6]) Let the assumptions in Theorem 1.2 hold, then there exist θ(0,1) and C>0 such that

    uCθ,θ2(ˉΩ×[t,t+1])+vCθ,θ2(ˉΩ×[t,t+1])+wC2+θ,1+θ2(ˉΩ×[t,t+1])Cfor allt1. (4.1)

    Lemma 4.2. Let a,b,c,k>0. Then

    ddtΩu=bΩvcΩu, (4.2)
    ddtΩv=kΩuwΩv (4.3)

    and

    ddtΩw+Ωuw+rΩvw+Ω(wa)2=aΩ(wa) (4.4)

    for all t>0.

    Proof. Integrating the three equations of (1.1), respectively, we obtain (4.2)-(4.4).

    Lemma 4.3. Let a,r,d30. Then

    ddtΩlnw+d3Ωw2xw2=Ωu+rΩv+Ω(wa) (4.5)

    for all t>0.

    Proof. By the third equation in (1.1), we make use of the positivity of w in ˉΩ×(0,) to see that

    ddtΩlnw=Ωd3wxxw2uwrvw+aww=d3Ωw2xw2+Ωu+rΩv+Ω(wa) (4.6)

    for all t>0.

    Combining Lemmata 4.2 and 4.3, when cabkkcar>1, we have the following lemma.

    Lemma 4.4. Under the assumptions in Theorem 1.2, there exists C>0 such that

    0ΩuC (4.7)

    and

    0ΩvC (4.8)

    as well as

    0Ωw2xC,0Ω(wa)2C (4.9)

    for all t>0.

    Proof. Using Lemmata 4.2 and 4.3, we have

    ddtΩ{au+ckv+cwcalnw}+rcΩvw+cΩ(wa)2+cad3Ωw2xw2=(ckracab)Ωv (4.10)

    for all t>0. Since cabkkcar>1, integrating (4.10) on [0,t) to obtain

    aΩu+ckΩv+cΩw+rct0Ωvw+ct0Ω(wa)2+cad3t0Ωw2xw2+(ckracab)t0ΩvaΩu0+ckΩv0+cΩw0acΩlnw0+acΩlnw (4.11)

    for all t>0. Due to lnww for all w>0, one has

    aΩu+ckΩv+cΩw+rct0Ωvw+ct0Ω(wa)2+cad3t0Ωw2xw2+(ckracab)t0ΩvaΩu0+ckΩv0+cΩw0acΩlnw0+acΩwaΩu0+ckΩv0+cΩw0acΩlnw0+acM|Ω| (4.12)

    for all t>0, which implies (4.8) and (4.9) hold. Integrating (4.2) on [0,t) to obtain

    Ωu+ct0Ωu=bt0Ωv+Ωu0.

    Using (4.8), we can obtain (4.7). The proof is completed.

    Lemma 4.5. Under the assumptions in Theorem 1.2, there exists C>0 satisfies

    0Ωu2xC,0Ωu2C (4.13)

    and

    0Ωv2C (4.14)

    for all t>0.

    Proof. By (3.7) and (3.20), for some c1,c2>0, we have u(,t)c1,v(,t)c2. Testing the first and second equations in (1.1) by u and v, respectively, using Young's inequality and integrating to see that

    12ddtΩu2+cΩu2+Ωd1(w)u2x=Ωd1(w)uuxwx+bΩuv12Ωd1(w)u2x+c212Ω(d1(w))2d1(w)w2x+bΩuv12Ωd1(w)u2x+c212Ω(d1(w))2d1(w)w2x+bvΩu

    and

    12ddtΩv2+Ωv2+Ωd2(u)v2x=Ωd2(u)vvxux+kΩuvw12Ωd2(u)v2x+c222Ω(d2(u))2d2(u)u2x+kΩuvw12Ωd2(u)v2x+c222Ω(d2(u))2d2(u)u2x+kMvΩu.

    Since (H1)(H2), (2.1) and (3.7), which yields

    ddtΩu2+2cΩu2+d1(M)Ωu2xc21K21Ωw2x+2bc2Ωu, (4.15)
    ddtΩv2+2Ωv2+η1Ωv2xc22K23Ωu2x+2kMc2Ωu. (4.16)

    Then using (4.7) and (4.9) imply (4.13) and (4.14).

    Lemma 4.6. Let the assumptions in Theorem 1.2 hold, the solution of (1.1) satisfies

    u(,t)0ast, (4.17)
    v(,t)0ast (4.18)

    and

    w(,t)a0ast. (4.19)

    Proof. Suppose that (4.17) is false, for some c1>0, there exist (xi)iNΩ and (ti)iN(1,) satisfying ti as i such that

    |u(xi,ti)|c1for alliN.

    From Lemma 4.1, we know that u is uniformly continuous in Ω×(1,), therefore, for any iN, we can find some r1>0 and τ1>0 such that

    |u(x,t)|c12for allxLr1(xi)Ωandt(ti,ti+τ1),

    where Lr1(xi) denotes a line segment with xi as the center, r1 as the radius and 2r1 in total length and hence

    ti+τ1tiΩ|u(x,t)|2c21c2τ14for alliN, (4.20)

    where c2:=infiN|Lr1(xi)Ω| is positive due to smoothness of Ω. By Lemma 4.5, we have

    ti+τ1tiΩ|u(x,t)|20for alli.

    Together with (4.20), this leads to a contradiction, thus (4.17) is established. Similarly, we can obtain (4.18) and (4.19) immediately.

    Proof of Theorem 1.2. Lemma 4.6 derives the conclusions of Theorem 1.2.

    The authors are very grateful to the anonymous reviewers for their carefully reading and valuable suggestions which greatly improved this work. L. Wang is supported by Natural Science Foundation of Chongqing (No. cstc2021jcyj-msxmX0412) and China Scholarship Council (202108500085).

    The authors declare there is no conflicts of interest.



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