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Existence of multiple solutions for a singular p()-biharmonic problem with variable exponents

  • In this work, we study a multiplicity result related to a p(τ)-Biharmonic equation involving singular and Hardy nonlinearities. More precisely, we use the variational method to develop the analysis of the fibering map in the Nehari manifold sets to prove the existence of two nontrivial solutions for such a problem.

    Citation: Ramzi Alsaedi. Existence of multiple solutions for a singular p()-biharmonic problem with variable exponents[J]. AIMS Mathematics, 2025, 10(2): 3779-3796. doi: 10.3934/math.2025175

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  • In this work, we study a multiplicity result related to a p(τ)-Biharmonic equation involving singular and Hardy nonlinearities. More precisely, we use the variational method to develop the analysis of the fibering map in the Nehari manifold sets to prove the existence of two nontrivial solutions for such a problem.



    The biharmonic problem with variable exponents usually arises in the context of partial differential equations where the biharmonic operator is applied to a function, but the coefficients or exponents of the problem are not constant. This type of problem has important applications in several fields, such as mathematical physics, engineering, and differential geometry, especially in modeling phenomena in which the underlying material or medium has non-uniform properties. In particular, the biharmonic equation describes the deflection of thin plates subjected to forces [1]. Su et al. [2] established the solution of the thin film epitaxy equation, and the biharmonic equation can include variable exponents to account for this heterogeneity. This is particularly useful for modeling composite materials where the material properties change gradually with position. For example, a composite plate may have different stiffnesses in different regions, and the biharmonic problem with variable exponents can model the deformation of the plate under external loads. Also, the biharmonic equation appears in the study of flow around objects [3,4,5]. When the viscosity of the fluid varies in space, the biharmonic operator with variable exponents can be used to model the diffusion of momentum in such media. This would allow a more realistic description of flow around objects with variable surface characteristics. The biharmonic equation was used for smoothing, denoising, and segmentation tasks [1]. When applied to images with nonuniform texture or intensity, a biharmonic operator with variable exponents can better model local image properties. For example, areas of an image with low contrast may have different smoothing behavior than areas with high contrast, leading to a variable exponent formulation in partial differential equations. A biharmonic operator with variable exponents can also be applied in the analysis of electromagnetic wave propagation in media with varying permeability, which is particularly useful in the design of optical and microwave devices with spatially graded materials.

    In this paper, we fix a bounded domain ΩRN with N3 and consider the following system

    Pλ,μ{Δ2p(τ)φ=λ|φ|p(τ)2φδ(τ)2p(τ)+b(τ)|φ|r(τ)2φ+μa(τ)φθ(τ)in Ω,φ=0,on Ω,

    where δ(τ) is the distance between τ and the boundary of Ω. The operator Δ2p(.) is defined by:

    Δ2p(τ)φ=Δ(|Δφ|p(τ)2Δφ).

    The functions a, b, and θ are non-negative and satisfy suitable hypotheses that are fixed later, and the functions p and r are continuous on ¯Ω, such that for any τ¯Ω, we have

    1<p(τ)<r(τ)<p(τ).

    For a given function Z, and for any τ in Ω, we denote

    Z=infx¯ΩZ(x),Z+=supx¯ΩZ(x),andZ(τ)={NZ(τ)N2Z(τ),ifz(τ)<N,,ifZ(τ)N. (1.1)

    Hereafter, we assume that

    1<pp+<N2, (1.2)

    and

    0<λ<CH:=min(pp+γp,pp+γp++),

    where

    γ±=N(p±1)(N2p±)(p±)2.

    We recall that for each φW2,p(τ)0(Ω), we have

    Ω|Δφ(τ)|p(τ)p(τ)dτCHΩ|φ(τ)|p(τ)p(τ)δ(τ)2p(τ)dτ. (1.3)

    The last inequality was introduced in the reference [6] for the case N=1, and in the reference [7] for the case N2.

    Recently, problems related to biharmonic operators have been extensively studied by several authors, and by using several methods, we cite for instance the papers of Su and Chen [8], who used a combination of the bipolar Rellich inequality with Gigliardo-Nirenberg inequality and Ekeland variational principle; Su and Shi [9], who used a combination of the non-vanishing and the structure of a Palais-Smale sequence to prove ground state solutions to prove the existence of nontrivial solutions; Su and Feng [10], who used the generalized versions of Lions-type theorem to prove ground state solutions; Alsedi [11], who used a fountain theorem to prove the existence of infinitely many solutions; Dhifli and Alsedi [12], who used the Nehari manifold to prove a multiplicity result; Ji and Wang [13], who used the Nehari manifold to prove the existence of two nontrivial solutions.

    Very recently, singular biharmonic equations have attracted the attention of several authors, we cite for example the works of Ghanmi and Sahbani [14], who used the mountain pass and the symmetric mountain pass theorems to prove their results; Alsaedi et al. [15], who used the Nehari manifold to prove some multiplicity results; Drissi et al.[16], who used the Nehari manifold to study biharmonic problems with Hardy nonlinearities, and Rǎdulescu and Repovš [17], who used variational and topological arguments to study singular biharmonic problem including the capillarity equation and the mean curvature problem. In particular, Ghanmi and Sahbani [14] considered the following singular problem:

    {Δ2p(τ)φ=λ|φ|p(τ)2φδ(τ)2p(τ)+b(τ)|φ|r(τ)2φ+a(τ)φθ(τ)in Ω,φ=0,on Ω, (1.4)

    where a, b, and θ are three non-negative functions, θ(0,1). Using the condition 1<r(τ)<p(τ), for all τ¯Ω, the authors proved that the functional associated with the problem (1.2), is coercive and bounded below in its domain, and based on the min-max theorem, they proved that, for all λ(0,CH), the problem (1.2) admits a nontrivial weak solution. For interested readers, we cite [18,19,20] for other interesting related works.

    Motivated by the above-mentioned results, our aim in this paper is to investigate a more general problem. More precisely, problem Pλ,μ contains two types of singularities (i.e., a power singularity and a singularity of Hardy type), and this makes our study more difficult. Moreover, the associated functional energy is not of class C1, so the direct variational method cannot be applied. In particular, the energy functional does not satisfy the mountain pass geometry, which implies also that the Ekland's variational principle cannot be applied. On the other hand, the exponent r is assumed to satisfy r>p, and this implies that the functional energy is not coercive in its domain. To guarantee the coercivity of the associated functional energy, we will work in some subsets called Nehari manifold sets. By these sets, we prove the multiplicity of solutions in the space X=W2,p(τ)0(Ω). For this aim, we assume the following hypotheses:

    (H1) a:ΩR, is such that

    aLt(τ)t(τ)+θ(τ)1(Ω),

    with

    1<t(τ)<p(τ)<r(τ)<p(τ),τ¯Ω.

    There exist b1, b2>0, such that

    0<b1b(τ)b2,τ¯Ω.

    (H2)

    (1θp)r+(1θr+)p<p+(1θ+)r(1θ+).

    Remark 1.1. If a is a continuous function on ¯Ω, then, the function a satisfies the hypothesis (H1) for any

    t(τ)=p(τ)a1,p(τ)=p(τ)a2,r(τ)=p(τ)a3,

    with a1>a2>a3>1. On the other hand, there are several functions satisfying hypothesis (H2). So, we can construct a class of functions satisfying hypotheses (H1) and (H2).

    Definition 1.1. A function  φ in the space X is a weak solution of the problem (Pλ,μ) if, for each function v in X, we have

    Ω|Δφ|p(τ)2ΔφΔvdτλΩ|φ(τ)|p(τ)2δ(τ)2p(τ)φ(τ)v(τ)dτμΩa(τ)|φ|θ(τ)v(τ)dτΩb(τ)|φ(τ)|r(τ)2φ(τ)v(τ)dτ=0.

    Our main result of this paper is the following.

    Theorem 1.1. Assume assumptions (H1) and (H2). Then, for each λ(0,CH), the problem (Pλ,μ) admits two non-trivial solutions, provided that μ(0,μ) for some positive constant μ.

    In Section 2 we introduce some results on functional spaces. In Section 3, we present and prove the main result of this work.

    In this section, we recall some preliminaries on the Lebesgue and Sobolev spaces. For interested readers, we refer to the works [21,22,23].

    The sets C+(Ω) will denote the set of all functions μ that are continuous on Ω, and satisfy

    μ(τ)>1,τΩ.

    For each μC+(Ω), we define the space Lμ(τ)(Ω) by:

    Lμ(τ)(Ω)={φ:ΩR,measurable,Ω|φ(τ)|μ(τ)dτ<}.

    We equip the space Lμ(τ)(Ω) with the following norm,

    |φ|μ(τ)=inf{μ>0:Ω|φ(τ)μ|μ(τ)dτ1}.

    Equipped with the last norm, the space Lμ(τ)(Ω) becomes a Banach space. Moreover, it is separable and reflexive if and only if μ satisfies

    1<μμ+<.

    Proposition 2.1. [24,25] For any φLμ(τ)(Ω) and vLμ(τ)(Ω), where 1μ(τ)+1μ(τ)=1, we have,

    |Ωφvdτ|(1μ+1(p))|φ|μ(τ)|v|μ(τ).

    Let

    ρμ(τ):Lμ(τ)(Ω)R,
    φΩ|φ(τ)|μ(τ)dτ,

    the modular on the space Lμ(τ)(Ω).

    Proposition 2.2. [22,24] For all φLμ(τ)(Ω), we have,

    (1) |φ|μ(τ)<1(resp=1,>1)ρμ(τ)(φ)<1(resp=1,>1);

    (2) |φ|μ(τ)>1|φ|μμ(τ)ρμ(τ)(φ),|φ|μ+μ(τ);

    (3) |φ|μ(τ)<1|φ|μ+μ(τ)ρμ(τ)(φ)|φ|μμ(τ).

    Also, we get the following proposition.

    Proposition 2.3. [22] Let μ and q be measurable functions such that qL(Ω) and 1μ(τ).q(τ) for all τΩ.

    Let φLμ(τ)(Ω),φ0. Then,

    (1) |φ|μ(τ)q(τ)1|φ|μ+μ(τ)q(τ)||φ|μ(τ)|q(τ)|φ|μμ(τ)q(τ),

    (2)|φ|μ(τ)q(τ)1|φ|μμ(τ)q(τ)||φ|μ(τ)|q(τ)|φ|μ+μ(τ)q(τ).

    Let us define the space

    W2,μ(τ)(Ω)={φLμ(τ)(Ω):|φ|Lμ(τ)(Ω),|Δφ|Lμ(τ)(Ω)},

    equipped with the norm

    ||φ||=inf{μ>0:Ω(|Δφ(τ)μ|μ(τ)+a(τ)|φ(τ)μ|μ(τ))dτ1}.

    W2,μ(τ)(Ω) is a separable and reflexive Banach space (see [21,23]).

    Let W2,μ(τ)0(Ω) be the closure of C0(Ω) in W2,μ(τ)(Ω). Then, W2,μ(τ)0(Ω) is a Banach and reflexive space with the norm

    ||φ||=|Δφ|μ(τ).

    Theorem 2.1. [26] If qC+(¯Ω) with q(τ)<μ(τ), for any τ¯Ω, then the embedding from W2,μ(τ)(Ω) into Lq(τ)(Ω) is compact and continuous.

    Let

    Θ(φ)=Ω|Δφ|μ(τ)dτ.

    Then, we have the following result.

    Proposition 2.4. [21,23]

    (1) If Θ(φ)1, then ||φ||μΘ(φ)||φ||μ+,

    (2) If Θ(φ)1, then ||φ||μ+Θ(φ)||φ||μ,

    (3) Θ(φ)1(=1,1)||φ||1(=1,1).

    In this section, we prove the main result of this paper. We begin by defining the functional Φλ,μ:XR, associated with the problem (Pλ,μ), as follows:

    Φλ,μ(φ)=Ω|Δφ(τ)|p(τ)p(τ)dτλΩ|φ(τ)|p(τ)p(τ)δ(τ)2p(τ)dτμΩa(τ)1θ(τ)|φ|1θ(τ)dτΩb(τ)|φ(τ)|r(τ)r(τ)dτ.

    We note that, due to the singular term, the functional  Φλ,μ is not of class C1. Moreover, from the fact that 0<1θ(τ)<p(τ)<r(τ), we see that  Φλ,μ is not bounded below in X. So, we cannot use the direct variational method to prove the existence of solutions. Throughout this paper, we consider for φX, the function Jφ:[0,[R, defined by

    Jφ(t)=Φλ,μ(tz).

    We note that, by the fact that 0<1θ(τ)<p(τ)<r(τ), the functional  Φλ,μ is not bounded below in X, so we will prove that Φλ,μ is bounded on the Nehari manifold which is defined as:

    ={φX{0}:Jφ(1)=0}.

    Now, we split into the following parts:

    +={φN:Jφ(1)>0}.
    ={φN:Jφ(1)<0}.
    0={φN:Jφ(1)=0}.

    It is clear that:

    Jφ(1)=Ω(|Δφ(τ)|p(τ)|φ(τ)|p(τ)δ(τ)2p(τ))dτμΩa(τ)φ1θ(τ)dτΩb(τ)|φ(τ)|r(τ)dτ,

    and

    Jφ(1)=Ωp(τ)(|Δφ(τ)|p(τ)|φ(τ)|p(τ)δ(τ)2p(τ))dτμΩa(τ)(1θ(τ))φ1θ(τ)dτΩb(τ)r(τ)|φ(τ)|r(τ)dτ,

    Moreover, we have

    φA(φ)B(φ)C(φ)=0, (3.1)

    where

    A(φ)=Ω(|Δφ(τ)|p(τ)λ|φ(τ)|p(τ)δ(τ)2p(τ))dτ,
    B(φ)=μΩa(τ)|φ|1θ(τ)dτ,

    and

    C(φ)=Ωb(τ)|φ(τ)|r(τ)dτ.

    Next, we will prove the following lemma.

    Lemma 3.1. Assume assumption (H1) holds. Let φX, for λ(0,CH). Then, we have the following:

    (1) There exists a constant CH=pp+(1λCH)>0 such that,

    CH||φ||pA(φ)||φ||p+if||φ||1.
    CH||φ||p+A(φ)||φ||pif||φ||1.

    (2) There exists a constant C1>0 such that,

    B(φ)C1μmax(||φ||1θ+,||φ||1θ).

    (3) There exists a constant C2>(CH)2 such that,

    C(φ)C2max(||φ||r+,||φ||r).

    Proof. (1) Let φX and 0<λ<CH. By (1.3), we have

    λCHΩ|Δφ(τ)|p(τ)p(τ)dτλΩ|φ(τ)|p(τ)p(τ)δ(τ)2p(τ)dτ.

    This implies that

    Ω|Δφ(τ)|p(τ)p(τ)dτλΩ|φ(τ)|p(τ)p(τ)δ(τ)2p(τ)dτ(1λCH)Ω|Δφ(τ)|p(τ)p(τ)dτ. (3.2)

    Moreover, we have

    p(Ω|Δφ(τ)|p(τ)p(τ)dτλΩ|φ(τ)|p(τ)p(τ)δ(τ)2p(τ)dτ)A(φ)Θ(φ). (3.3)

    From (3.2) and (3.3), we get

    p(1λCH)Ω|Δφ(τ)|p(τ)p(τ)dτA(φ)Θ(φ).

    So,

    pp+(1λCH)Θ(φ)A(φ)Θ(φ).

    Then, by Proposition 2.4, we deduce the assertion (1).

    (2) By (H1) and Proposition 2.1, we get

    Ωa(τ)φ1θ(τ)dτ|a|t(τ)t(τ)+θ(τ)1||φ|1θ(τ)|t(τ)1θ(τ).

    Using, 1<t(τ)<p(τ), Proposition 2.2, and Theorem 2.1, we have

    B(φ)μ|a|t(τ)t(τ)+θ(τ)1max(|φ|1θ+t(τ),|φ|1θt(τ))μ|a|t(τ)t(τ)+θ(τ)1max(||φ||1θ+,||φ||1θ).

    (3) By (H1), Proposition 2.2, and Theorem 2.1, we get

    C(φ)=Ωb(τ)|φ(τ)|r(τ)τb2|φ|r+r(τ)+b2|φ|rr(τ)C[||φ||r++||φ||r]C2max(||φ||r+,||φ||r),

    where, C2=2C+(CH)2.

    Lemma 3.2. Assume that assumption (H1) holds. For λ(0,CH), Φλ,μ is coercive and bounded below on .

    Proof. Let φN, for ||φ||>1, from (3.1) and Lemma 3.1, we have

    Φλ,μ(φ)1p+A(φ)11θ+B(φ)1rC(φ)1p+A(φ)11θ+B(φ)1r[A(φ)B(φ)](1p+1r)A(φ)(11θ+1r)B(φ)(1p+1r)CH||φ||pμC1(11θ+1r)||φ||1θ.

    Since 0<1θ+<1θ<p<p+<r<r+, we get,

    Φλ,μ(φ)+,as||φ||+.

    Hence, the lemma is proved.

    Lemma 3.3. Under assumption (H1), there exists μ0>0, given by

    μ0=1C1(rp+r(1θ+))([p(1θ)](CH)2[r+(1θ)]C2)p+(1θ+)rp+,

    such that for any λ(0,CH), and μ(0,μ0), we have 0=. The positive constants CH,C1,C2, and CH are given in (1.3) and in Lemma 3.1.

    Proof. We suppose that there exists 0<μ<μ0 such that 0. Then, there exists φ0. So, if ||φ||<1, then by (3.1), we have

    0=Jφ(1)p+A(φ)(1θ+)B(φ)rC(φ)p+A(φ)(1θ+)B(φ)r(A(φ)B(φ))(p+r)A(φ)+C1[r(1θ+)]B(φ).

    Then

    (rp+)A(φ)C1[r(1θ+)]B(φ).

    By Lemma 3.1, we have

    (rp+)CH||φ||p+μC1[r(1θ+)]||φ||1θ+.

    Then,

    (rp+)CHC1[r(1θ+)]||φ||p+(1θ+)μ. (3.4)

    Again from (3.1), we have

    0=Jφ(1)pA(φ)(1θ)B(φ)r+C(φ)pA(φ)(1θ)(A(φ)C(φ))r+C(φ)[p(1θ)]A(φ)[r+(1θ)]C(φ).

    Then, using Lemma 3.1, we obtain

    C2||φ||r[r+(1θ)][p(1θ)]CH||φ||p+.

    Then,

    ||φ||([p(1θ)]CHC2[r+(1θ)])1rp+. (3.5)

    Combining (3.4) and (3.5), we get

    μ1C1(rp+r(1θ+))([p(1θ)](CH)2[r+(1θ)]C2)p+(1θ+)rp+. (3.6)

    Now, if ||φ||1, we have

    ||φ||([p(1θ)]CHC2[r+(1θ)])1r+p, (3.7)

    and

    μ1C1(rp+r(1θ+))([p(1θ)](CH)2[r+(1θ)]C2)p(1θ)r+p. (3.8)

    Using C2>(CH)2 and 0<1θ+<1θ<1<q<q+<p<p+<r<r+, we have,

    0<[p(1θ)](CH)2[r+(1θ)]C2<1, (3.9)
    q(1θ)r+p<p+(1θ+)rp+. (3.10)

    Combining, (3.6), (3.8), (3.9), and (3.10), we get

    μ1C1(rp+r(1θ+))([p(1θ)](CH)2[r+(1θ)]C2)p+(1θ+)rp+,

    which is a contradiction.

    Remark 3.1. For any 0<λ<CH, 0<μ<μ0 and from Lemmas 3.2 and 3.3, we obtain that

    (1) N=+.

    (2) Φλ,μ is coercive and bounded below on + and .

    Then, we note,

    m=infφ(Φλ,μ(φ));m+=infφ+(Φλ,μ(φ));m=infφ(Φλ,μ(φ)).

    Lemma 3.4. If (H1) and (H2) hold, then for any 0<λ<CH and 0<μ<μ0, we have

    mm+<0.

    Proof. If φ+, from (3.1) we have,

    0<Jφ(1)p+A(φ)(1θ+)B(φ)rC(φ)p+A(φ)(1θ+)(A(φ)C(φ))rC(φ)[p+(1θ+)]A(φ)[r(1θ+)]C(φ).

    Then,

    C(φ)<(p+(1θ+))r(1θ+)A(φ). (3.11)

    On the other hand, we also have from (3.1) that:

    Φλ,μ(φ)1pA(φ)11θB(φ)1r+C(φ)1pA(φ)11θ[A(φ)C(φ)]1r+C(φ)(1p11θ)A(φ)+(11θ1r+)C(φ).

    By to (3.11), we get,

    Φλ,μ(φ)<(1p11θ)A(φ)+(11θ1r+)p+(1θ+)r(1θ+)A(φ).

    Then,

    Φλ,μ(φ)(1θp)r+p(1θr+)p+(1θ+)r(1θ+)pr+(1θ)A(φ).

    From (H2), we have,

    (1θp)r+p(1θr+)p+(1θ+)r(1θ+)pr+(1θ)<0.

    So, Φλ,μ(φ)<0, φ+. Thus mm+<0.

    Lemma 3.5. If (H1) and (H2) hold, then for 0<λ<CH, 0<μ<1θ+p+μ0, there exists k0>0, such that

    mk0>0.

    Proof. Let φ. Then we know that φφ(1)<0. Moreover, we have two cases:

    Case 1. ||φ||<1. From Lemma 3.2 and (3.5), we have

    Φλ,μ(φ)(1p+1r)CH||φ||p+μC1(11θ+1r)||φ||1θ+||φ||1θ+[(1p+1r)CH||φ||p+(1θ+)μC1(11θ+1r)](p(1θ)C2[r+(1θ)])1θ+rp+[(1p+1r)([p(1θ)](CH)2C2[r+(1θ)])p+(1θ+)rp+μC1(11θ+1r)]=d1.

    So, if

    μ<(1p+1r)([p(1θ)](CH)2C2[r+(1θ)])p+(1θ+)rp+1C1(11θ+1r)=1θ+p+μ0,

    we conclude that Φλ,μ(φ)d1>0.

    Case 2. ||φ||>1. From Lemma 3.2 and (3.7), we have

    Φλ,μ(φ)(1p+1r)CH||φ||pμC1(11θ+1r)||φ||1θ||φ||1θ[(1p+1r)CH||φ||p(1θ)μC1(11θ+1r)](p(1θ)C2[r+(1θ)])1θr+p[(1p+1r)([p(1θ)](CH)2C2[r+(1θ)])p(1θ)r+pμC1(11θ+1r)]=d2.

    So, if we have

    μ<(1p+1r)(p(1θ)C2[r+(1θ)])p(1θ)r+p1C1(11θ+1r),

    then we obtain J(φ)d2>0.

    Now, a simple calculation shows that

    1θ+p+μ0<(1p+1r)(p(1θ)C2[r+(1θ)])p(1θ)r+p1C1(11θ+1r).

    Hence, if we put k0=min(d1,d2), then from the above study, we obtain Φλ,μ(φ)k0>0, which implies that

    m=infφN(Φλ,μ(φ))k0.

    Lemma 3.6. If (H1) and (H2) hold, then for φX{0}, there exists μ>0, such that, for 0<μ<μ and 0<λ<CH, there exists t>0 and t+<t such that, tφ,t+φ+,

    Φλ,μ(t+φ)=inf0ttΦλ,μ(tz)andΦλ,μ(tφ)=supt0Φλ,μ(tz).

    Proof. Let φX{0}. For all t>1, we have

    A(φ)tp1B(φ)tθ+C(φ)tr+1Jφ(t)A(φ)tp+1B(φ)tθC(φ)tr1,

    and for all 0<t1, we get

    A(φ)tp+1B(φ)tθC(φ)tr1Jφ(t)A(φ)tp1B(φ)tθ+C(φ)tr+1.

    Now, we introduce the following function

    h(t)=A(φ)tαB(φ)tθC(φ)tβ,t>0,

    where, β>α>θ>0,A(φ),B(φ),C(φ)0, we have

    h(t)=0tθh(t)=0A(φ)tα+θC(φ)tβ+θ=B(φ).

    Define τ(t)=A(φ)tα+θC(φ)tβ+θ. So, τ possesses a unique maximum point at

    tmax=(A(φ)(α+θ)C(φ)(β+θ))1(βα).

    B(φ)=μΩa(τ)|φ|1θ(τ)τ>0 and if μ>0, is small enough such that B(φ)<τ(tmax), then there exist 0<t1<tmax<t2< such that τ(t+)=τ(t)=B(φ),τ(t+)>0, and τ(t)<0, that is, t+ and t are two solutions of the equation h(t)=0, for all t>0.

    The graph Jφ(t) is between two graphs

    Uφ(t)=A(φ)tp1B(φ)tθ+C(φ)tr+1,

    and

    Vφ(t)=A(φ)tp+1B(φ)tθC(φ)tr1.

    Now, using the discussion as τ, there exists μ>0 and 0<t+<t< such that Jφ(t)=Jφ(t+)=0, and t+φ+tφ λ for all μ(0,μ).

    Nextly, we pose μ=min{μ,1θ+p+μ0}, where μ and μ0, are given in Lemmas 3.6 and 3.3, respectively.

    Proposition 3.1. If (H1) and (H2) hold, then for λ(0,CH) and μ(0,μ) the functional Φλ,μ has a minimizer φ1+, such that,

    Φλ,μ(φ1)=m+<0.

    Proof. The functional Φλ,μ is bounded below in +. So, there exists {vn}, such that, Φλ,μ(vn)m+. By Lemma 3.2, we conclude that {vn} is bounded on reflexive space X, so, up to a sub-sequence, there exist {vn} and φ1 in X such that

    {vnφ1,weakly in X,vnφ1, strongly in Lβ(τ)(Ω),1β(τ)<p(τ),vnφ1, a.e in Ω.

    Next, by Proposition 2.3, we get

    limnB(vn)=B(φ1),limnC(vn)=C(φ1). (3.12)
    limnΩ|vn(τ)|p(τ)p(τ)δ2p(τ)dτ=Ω|φ1(τ)|p(τ)p(τ)δ2p(τ)dτ. (3.13)

    We prove that φ10 and B(φ1)>0. If B(φ1)=0, since (vn)+ and by (3.1) and (3.12), we get

    Φλ,μ(vn)(1p+1r)A(vn)(11θ+1r)B(vn).

    Then,

    limnΦλ,μ(vn)(1p+1r)limnA(vn)0.

    From, Lemma 3.4, limnΦλ,μ(vn)=m+<0. This is a contradiction. Then, B(φ1)>0 and φ1X{0}.

    Now, we will be showing that vnφ1 strongly in X.

    Supposing the contrary, then vnφ1 strongly in X. By the Brezis-Lieb Lemma (see [27]), we get

    Ω|Δ(φ1)|p(τ)p(τ)dτ<lim infnΩ|Δ(vn)|p(τ)p(τ)dτ. (3.14)

    Using (3.12)–(3.14), we get

    Φλ,μ(φ1)<limnΦλ,μ(vn). (3.15)

    From Lemma 3.6, for φ1X{0}, there exists t+>0, such that t+φ1+. Since, vnφ1 in X, we concluded that,

    A(t+φ1)<lim infnA(t+vn). (3.16)

    Then, by Proposition 2.3, we get

    B(t+φ1)=limnB(t+vn),C(t+φ1)=limnC(t+vn). (3.17)

    By (3.16) and (3.17), we obtain

    0=Jφ1(t+)<limnJvn(t+).

    Then for n large enough, we obtain

    Jvn(t+)>0. (3.18)

    Now, since vn+ for all nN, we have, Jvn(1)=0. Thus t+1. Clearly, t+ is a minimizer of g(t)=Φλ,μ(tz1), for t>0. Then, by (3.15), we get

    Φλ,μ(t+φ1)Φλ,μ(φ1)<limnΦλ,μ(vn)=infφ+Φλ,μ(φ).

    This is a contracted t+φ1+. So, vnφ1 strongly in + as n+, and by Lemma 3.2, 0=. Then, φ1+, and by Lemma 3.4,

    Φλ,μ(φ1)=limnΦλ,μ(vn)=m+<0.

    Proposition 3.2. If (H1) and (H2) hold, then for λ(0,CH) and μ(0,μ) the functional Φλ,μ has a minimizer φ2, such that

    Φλ,μ(φ2)=m>0.

    Proof. Let {vn} in , such that, Φλ,μ(vn)m. Lemma 3.2 implies that {vn} is bounded in reflexive space X. So, up to a sub-sequence, there exist {vn} and φ2 in X such that,

    {vnφ2,weakly in X,vnφ2, strongly in Lβ(τ)(Ω),1β(τ)<p(τ),vnφ2, a.e in Ω,

    and

    limnC(vn)=C(φ2). (3.19)

    Next, we have φ20. Indeed, if φ2=0, from (3.19), we obtain,

    C(vn)0,asn. (3.20)

    Using the fact that {vn}, Eq (3.1), and Lemma 3.5, we have

    0<k0<Φλ,μ(vn)(1p11θ)A(vn)+(11θ1r+)C(vn).

    Then, by (3.20) and the fact that 1θ<p, we obtain

    0<k0limnΦλ,μ(vn)0,

    which is a contradiction. So, φ2X{0}. On the other hand, by Lemma 3.6 there exists a positive real t such that tφ2.

    Next, we will prove that vn converges strongly to φ2 in X. Assume that this is not true. Then, by the Brezis-Lieb Lemma (see [27]), we have

    Ω|Δ(tφ2)|p(τ)p(τ)dτ<lim infnΩ|Δ(tvn)|p(τ)p(τ)dτ. (3.21)

    On the other hand, from Eq (3.21) and Proposition 2.3, we obtain

    Φλ,μ(tφ2)<limnΦλ,μ(tvn). (3.22)
    0=Jφ2(t)<limnJvn(t).

    Thus for n large enough, we conclude that

    Jvn(t)>0. (3.23)

    Since vn, then we have Jvn(1)=0 and using (3.23), we get t1. Observe that the function G(t)=Φλ,μ(tvn), for t>0, attains its maximum at t=1 and using (3.22), we get

    Φλ,μ(tφ2)<limnΦλ,μ(tvn)limnΦλ,μ(vn)=infφΦλ,μ(φ).

    This contradicts the fact that tφ2. Then, vnφ2 strongly in X as n+, and thus φ2. By Lemma 3.2 we have, 0= and by Lemma 3.4, we get,

    Φλ,μ(φ2)=limnΦλ,μ(vn)=m>0.

    So, we conclude that φ2.

    Lemma 3.7. If (H1) and (H2) hold and φ±, there exist ϵ>0, and a continuous function α:Bϵ(0)(0,+), such that

    α(0)=1,α(v)(φ+v)N+,vBϵ(0),

    where

    Bϵ(0)={vX:||v||<ϵ}.

    Proof. Let φ+ and let the function f:X×RR defined by:

    f(v,t)=Jφ+v(t)=Ωtp(τ)1|Δ(v+φ)(τ)|p(τ)dτΩtp(τ)1|(v+φ)(τ)|p(τ)δ(τ)2p(τ)dτμΩtθ(τ)a(τ)(v+φ)1θ(τ)dτΩb(τ)tr(τ)1|(v+φ)(τ)|r(τ)dτ,vX.

    Since φ+, ve have f(0,1)=Jφ(1)=0 and f(0,1)=Jφ(1)>0.

    Then, from the implicit function theorem, there exist ϵ>0 and a continuous function α:Bϵ(0)(0,+), such that

    f(v,α(v))=0,α(0)=1. (3.24)

    Using (3.24), we get

    α(v)(φ+v),vBϵ(0).

    Taking ϵ>0 even smaller if necessary, we can also have

    α(v)(φ+v)+,vBϵ(0).

    The proof for the case φ is very similar, so we omit it.

    Proof of Theorem 1.1. By Lemma 3.7, we can find ϑ(t)>0,t[0,t0] such that,

    ϑ(t)(φ1+th)+,ϑ(t)1ast0+.

    Then, by Proposition 3.1, we have, t[0,t0],

    m+=Φλ,μ(φ1)Φλ,μ(ϑ(t)(φ1+th)).

    So, t[0,t1] with 0<t1t0, we get

    m+Φλ,μ(φ1)Φλ,μ(φ1+th).

    Then,

    0Φλ,μ(φ1+th)Φλ,μ(φ1).

    So, for t>0, we get

    0limt0Φλ,μ(φ1+th)Φλ,μ(φ1)t,

    which yields to

    Ω|Δφ1|p(τ)2Δφ1ΔhdτλΩ|φ1(τ)|p(τ)2δ(τ)2p(τ)φ1(τ)h(τ)dτμΩa(τ)|φ1|θ(τ)h(τ)dτΩb(τ)|φ1(τ)|r(τ)2φ1(τ)h(τ)dτ0.

    Since the function h is arbitrary, then we can change h by h in the last inequality, and we conclude that φ1+ is a nontrivial weak solution to the problem (Pλ,μ).

    Now, by Lemma 3.7 and Proposition 3.2, the proof is the same for φ2. By this stage, the proof of Theorem 1.2 is now completed.

    In this paper, we studied a p(x)-biharmonic problem involving two types of nonlinearities: Singular and Hardy type. More precisely, we combine a variational method with the Nehari manifold method to prove that such a problem admits two nontrivial solutions. We will generalize this study to problems involving the p(,)-Laplace operator, and we will extend this study to double-phase and multi-phase problems.

    The author declares he has not used Artificial Intelligence (AI) tools in the creation of this article.

    This project was funded by the Deanship of Scientific Research (DSR) at King Abdulaziz University, Jeddah, under grant no. (GPIP: 1898-130-2024). The authors, therefore, acknowledge with thanks DSR for technical and financial support.

    The author declares that there is no conflict of interest.



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