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An introduction to the theory of OBCI-algebras

  • The purpose of this paper was to introduce the concept of "OBCI-algebras" as a partially ordered generalization of BCI-algebras. The notion of OBCI-algebras was introduced, and related properties were investigated. The notions of OBCI-subalgebras and (closed) OBCI-filters of OBCI-algebras were defined and the relationship between the OBCI-subalgebras and OBCI-filters was discussed. In addition, the direct product OBCI-algebra was discussed, and the OBCI-filter related to it was also addressed.

    Citation: Eunsuk Yang, Eun Hwan Roh, Young Bae Jun. An introduction to the theory of OBCI-algebras[J]. AIMS Mathematics, 2024, 9(12): 36336-36350. doi: 10.3934/math.20241723

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  • The purpose of this paper was to introduce the concept of "OBCI-algebras" as a partially ordered generalization of BCI-algebras. The notion of OBCI-algebras was introduced, and related properties were investigated. The notions of OBCI-subalgebras and (closed) OBCI-filters of OBCI-algebras were defined and the relationship between the OBCI-subalgebras and OBCI-filters was discussed. In addition, the direct product OBCI-algebra was discussed, and the OBCI-filter related to it was also addressed.



    The renowned integral Steffensen's inequality [1] is written as: Let f and g be integrable functions on [a,b] such that f is nonincreasing and 0g(J)1 on [a,b]. Then

    bbλf(J)dJbaf(J)g(J)dJa+λaf(J)dJ, (1.1)

    where λ=bag(J)dJ.

    It is simple to notice that inequalities (1.1) are reversed if f is nondecreasing.

    The discrete version of the Steffensen inequality [2] states:

    Theorem A. Assume that {f(k)}nk=1 is a nonincreasing nonnegative real sequence and {g(k)}nk=1 is a real sequence such that 0g(k)1 for every k. Furthermore, let that λ1, λ2{1,,n} be such that λ2nk=1g(k)λ1. Then

    nk=nλ2+1f(k)nk=1f(k)g(k)λ1k=1f(k). (1.2)

    Jakšetić et al. [3] established the following interesting results among many other similar results for a positive finite measure μ. States:

    Theorem B. Let ˆμ be a positive finite measure on B([a,b]), and let f, g:[a,bR be measurable functions on [a,b] such that f is nonincreasing and 0g(J)1 for all t[a,b]. Further, let ˆμ([c,d])=[a,b]g(J)dˆμ(J), where [c,d][a,b]. Then

    [a,b]f(J)g(J)dˆμ(J)[c,d]f(J)g(J)dˆμ(J)+[a,c](f(J)f(d))g(J)dˆμ(J).

    Also, the authors proved that:

    Theorem C. Let f, g:[a,b]R be measurable functions on [a,b] such that f is nonincreasing and 0g(J)1 for all t[a,b]. Further, let ˆμ([c,d])=[a,b]g(J)dˆμ(J), where [c,d][a,b]. If ˆμ is a positive finite measure on B([a,b]), then

    [c,d]f(J)dˆμ(J)[d,b](f(c)f(J))g(J)dˆμ(J)[a,b]f(J)g(J)dˆμ(J).

    In 1982, Pečarić [4] gave speculation of the Steffensen inequality as the following two hypotheses.

    Theorem 1.1. Let ˆf, ˆg, ˆh:[a,b]R be integrable functions on [a,b] such that ˆf/ˆh is nonincreasing and ˆh is nonnegative. Further, let 0ˆg(J)1 J[a,b]. Then

    baˆf(J)ˆg(J)dJa+ˆaˆfdJ, (1.3)

    where ˆ is the solution of the equation

    a+ˆaˆh(J)dJ=baˆh(J)ˆg(J)dJ.

    We get the reverse of (1.3), if ^f(J)/^h(J) is nondecreasing.

    Theorem 1.2. Let ˆf, ˆg, ˆh:[a,b]R be integrable functions on [a,b] such that ˆf/ˆh is nonincreasing and ˆh is nonnegative. Further, let 0ˆg(J)1 J[a,b]. Then

    bbˆˆf(J)dJbaˆf(J)ˆg(J)dJ, (1.4)

    where ˆ gives us the solution of

    bbˆˆh(J)dJ=baˆh(J)ˆg(J)dJ. (1.5)

    We get the reverse of (1.4), if ^f(J)/^h(J) is nondecreasing.

    Wu and Srivastava in [5] acquired the accompanying result.

    Theorem 1.3. Let ˆf, ˆg, ˆh:[a,b]R be integrable functions on [a,b] such that ˆf is nonincreasing. Further, let 0ˆg(J)ˆh(J) J[a,b]. Then the following integral inequalities hold true:

    bbˆˆf(J)ˆh(J)dJbbˆ(ˆf(J)ˆh(J)[ˆf(J)ˆf(bˆ)][ˆh(J)ˆg(J)])dJbaˆf(J)ˆg(J)dJa+ˆa(ˆf(J)ˆh(J)[ˆf(J)ˆf(a+ˆ)][ˆh(J)ˆg(J)])dJa+ˆaˆf(J)ˆh(J)dJ,

    where ˆ gives us the solution of

    a+ˆaˆh(J)dJ=baˆg(J)dJ=bbˆˆh(J)dJ.

    The following interesting findings were published in [6].

    Theorem 1.4. Suppose the integrability of ˆg, ˆh, ˆf, ψ:[a,b]R such that ˆf is nonincreasing. Also suppose 0ˆψ(J)ˆg(J)ˆh(J)ˆψ(J) for all J[a,b]. Then

    baˆf(J)ˆg(J)dJa+ˆaˆf(J)ˆh(J)dJba|(ˆf(J)ˆf(a+ˆ))ψ(J)|dJ,

    where ˆ is given by

    a+ˆaˆh(J)dJ=baˆg(J)dJ.

    Theorem 1.5. Under the hypotheses of Theorem 1.4. Then

    bbˆˆf(J)ˆh(J)dJ+ba|(ˆf(J)ˆf(bˆ))ˆψ(J)|dJbaˆf(J)ˆg(J)dJ,

    where ˆ is given by

    bbˆˆh(J)dJ=baˆg(J)dJ.

    The calculus of time scales with the intention to unify discrete and continuous analysis (see [7]) was proposed by Hilger [8]. For more details on the time scales calculus we refer to the book by Bohner and Peterson [9].

    Lately, several dynamic inequalities on time scales has been investigated by using exclusive authors who have been inspired with the aid of a few applications (see[10,11,12,13,14,15,16,17,18]). Some authors created different results regarding fractional calculus on time scales to provide associated dynamic inequalities (see [19,20,21,22,23,24,25,26,27]).

    In this article, we explore new generalizations of the integral Steffensen inequality given in [4,5,6] via general time scale measure space with a positive σ-finite measure. We also retrieve some of the integral inequalities known in the literature as special cases of our tests.

    In what follows B([a,b]T) is Borel σ-algebra [a,b]. Next, we enroll the accompanying suppositions for the verifications of our primary outcomes:

    (S1) ([a,b]T,B([a,b]T),ˆμ) is time scale measure space with a positive σ-finite measure on B([a,b]T).

    (S2) η, Υ, Ξ:[a,b]TR are Δˆμ-integrable functions on [a,b]T.

    (S3) η/Ξ is nonincreasing and Ξ is nonnegative.

    (S4) 0Υ(J)1 for all J[a,b]T.

    (S5) ˆ[0,).

    (S6) η is nonincreasing.

    (S7) 1Υ(J)Ξ(J) for all J[a,b]T.

    (S8) 0ψ(J)Υ(J)Ξ(J)ψ(J) for all J[a,b]T.

    (S9) 0MΥ(J)1M for all J[a,b]T.

    (S10) 0ψ(J)Υ(J)1ψ(J) for all J[a,b]T.

    ˆ is the solution of the equations listed below:

    (S11) [a,a+ˆ]TΞ(J)Δˆμ=[a,b]TΞ(J)Υ(J)Δˆμ.

    (S12) [bˆ,b]TΞ(J)Δˆμ=[a,b]TΞ(J)Υ(J)Δˆμ.

    (S13) [a,a+ˆ]TΞ(J)Δˆμ=[a,b]TΥ(J)Δˆμ=[bˆ,b]TΞ(J)Δˆμ.

    (S14) [a,a+ˆ]TΞ(J)Δˆμ=[a,b]TΥ(J)Δˆμ.

    (S15) [bˆ,b]TΞ(J)Δˆμ=[a,b]TΥ(J)Δˆμ.

    Presently, we are prepared to state and explain the principle results that make bigger numerous effects inside the literature.

    Theorem 2.1. Let S1, S2, S3, S4, S5 and S11 be satisfied. Then

    [a,b]Tη(J)Υ(J)Δˆμ[a,a+ˆ]Tη(J)Δˆμ. (2.1)

    We get the reverse of (2.1), if η/Ξ is nondecreasing.

    Proof. From our hypotheses, we observe that,

    [a,a+ˆ]Tη(J)Δˆμ[a,b]Tη(J)Υ(J)Δˆμ=[a,a+ˆ]TΞ(J)[1Υ(J)]η(J)Ξ(J)Δˆμ[a+ˆ,b]Tη(J)Υ(J)Δˆμη(a+ˆ)Ξ(a+ˆ)[a,a+ˆ]TΞ(J)[1Υ(J)]Δˆμ[a+ˆ,b]Tη(J)Υ(J)Δˆμ=η(a+ˆ)Ξ(a+ˆ)[[a,a+ˆ]TΞ(J)Δˆμ[a,a+ˆ]TΞ(J)Υ(J)Δˆμ][a+ˆ,b]Tη(J)Υ(J)Δˆμ=η(a+ˆ)Ξ(a+ˆ)[[a,b]TΞ(J)Υ(J)Δˆμ[a,a+ˆ]TΞ(J)Υ(J)Δˆμ][a+ˆ,b]Tη(J)Υ(J)Δˆμ=η(a+ˆ)Ξ(a+ˆ)[a+ˆ,b]TΞ(J)Υ(J)Δˆμ[a+ˆ,b]Tη(J)Υ(J)Δˆμ=[a+ˆ,b]TΞ(J)Υ(J)(η(a+ˆ)Ξ(a+ˆ)η(J)Ξ(J))Δˆμ0.

    The proof is complete.

    Remark 2.1. In case of T=R and related to Lebesgue measure in Theorem 2.1, we recollect [4,Theorem 1].

    Theorem 2.2. Assumptions S1, S2, S3, S4, S5 and S12 imply

    [bˆ,b]Tη(J)Δˆμ[a,b]Tη(J)Υ(J)Δˆμ. (2.2)

    We get the reverse of (2.2), if η/Ξ is nondecreasing.

    Proof. From our hypotheses, we observe that,

    [bˆ,b]Tη(J)Δˆμ[a,b]Tη(J)Υ(J)Δˆμ=[bˆ,b]TΞ(J)[1Υ(J)]η(J)Ξ(J)Δˆμ[a,bˆ]Tη(J)Υ(J)Δˆμη(bˆ)Ξ(bˆ)[bˆ,b]TΞ(J)[1Υ(J)]Δˆμ[a,bˆ]Tη(J)Υ(J)Δˆμ=η(bˆ)Ξ(bˆ)[[bˆ,b]TΞ(J)Δˆμ[bˆ,b]TΞ(J)Υ(J)Δˆμ][a,bˆ]Tη(J)Υ(J)Δˆμ=η(bˆ)Ξ(bˆ)[[a,b]TΞ(J)Υ(J)Δˆμ[bˆ,b]TΞ(J)Υ(J)Δˆμ][a,bˆ]Tη(J)Υ(J)Δˆμ=η(bˆ)Ξ(bˆ)[a,bˆ]TΞ(J)Υ(J)Δˆμ[a,bˆ]Tη(J)Υ(J)Δˆμ=[a,bˆ]TΞ(J)Υ(J)(η(bˆ)Ξ(bˆ)η(J)Ξ(J))Δˆμ0.

    Remark 2.2. By observing Lebesgue measure in Theorem 2.2, and T=R, we recapture [4,Theorem 2].

    We will need the following lemma to prove the subsequent results.

    Lemma 2.1. Let S1, S2, S5 hold, such that

    [a,a+ˆ]TΞ(J)Δˆμ=[a,b]TΥ(J)Δˆμ=[bˆ,b]TΞ(J)Δˆμ.

    Then

    [a,b]Tη(J)Υ(J)Δˆμ=[a,a+ˆ]T(η(J)Ξ(J)[η(J)η(a+ˆ)][Ξ(J)Υ(J)])Δˆμ+[a+ˆ,b]T[η(J)η(a+ˆ)]Υ(J)Δˆμ, (2.3)

    and

    [a,b]Tη(J)Υ(J)Δˆμ=[a,bˆ]T[η(J)η(bˆ)]Υ(J)Δˆμ+[bˆ,b]T(η(J)Ξ(J)[η(J)η(bˆ)][Ξ(J)Υ(J)])Δˆμ. (2.4)

    Proof. The suppositions of the Lemma imply that

    aa+ˆbandabˆb.

    Firstly, we prove the validity of the integral identity (2.3). Indeed, by direct computation, and from our hypotheses, we find that

    [a,a+ˆ]T(η(J)Ξ(J)[η(J)η(a+ˆ)][Ξ(J)Υ(J)])Δˆμ[a,b]Tη(J)Υ(J)Δˆμ=[a,a+ˆ]T(η(J)Ξ(J)η(J)Υ(J)[η(J)η(a+ˆ)][Ξ(J)Υ(J)])Δˆμ+[a,a+ˆ]Tη(J)Υ(J)Δˆμ[a,b]Tη(J)Υ(J)Δˆμ=[a,a+ˆ]Tη(a+ˆ)[Ξ(J)Υ(J)]Δˆμ[a+ˆ,b]Tη(J)Υ(J)Δˆμ=η(a+ˆ)([a,a+ˆ]TΞ(J)Δˆμ[a,a+ˆ]TΥ(J)Δˆμ)[a+ˆ,b]Tη(J)Υ(J)Δˆμ. (2.5)

    Since

    [a,a+ˆ]TΞ(J)Δˆμ=[a,b]TΥ(J)Δˆμ,

    we have

    η(a+ˆ)([a,a+ˆ]TΞ(J)Δˆμ[a,a+ˆ]TΥ(J)Δˆμ)[a+ˆ,b]Tη(J)Υ(J)Δˆμ=η(a+ˆ)([a,b]TΥ(J)Δˆμ[a,a+ˆ]TΥ(J)Δˆμ)[a+ˆ,b]Tη(J)Υ(J)Δˆμ=η(a+ˆ)[a+ˆ,b]TΥ(J)Δˆμ[a+ˆ,b]Tη(J)Υ(J)Δˆμ)=[a+ˆ,b]T[η(a+ˆ)η(J)]Υ(J)Δˆμ. (2.6)

    Combination of (2.5) and (2.6) led to the required integral identity (2.3) asserted by the Lemma. The integral identity (2.4) can be proved similarly. The proof is done.

    Theorem 2.3. Suppose S1, S2, S5, S6, S7 and S13 give

    [bˆ,b]Tη(J)Ξ(J)Δˆμ[bˆ,b]T(η(J)Ξ(J)[η(J)η(bˆ)][Ξ(J)Υ(J)])Δˆμ[a,b]Tη(J)Υ(J)Δˆμ[a,a+ˆ]T(η(J)Ξ(J)[η(J)η(a+ˆ)][Ξ(J)Υ(J)])Δˆμ[a,a+ˆ]Tη(J)Ξ(J)Δˆμ.

    Proof. From our hypotheses. In perspective of the considerations that the function η is nonincreasing on [a,b] and 0Υ(J)Ξ(J) for all J[a,b], we infer that

    [a,bˆ]T[η(J)η(bˆ)]Υ(J)Δˆμ0, (2.7)

    and

    [bˆ,b]T[η(bˆ)η(J)][Ξ(J)Υ(J)]Δˆμ0. (2.8)

    Using (2.3), (2.7) and (2.8), we find that

    [bˆ,b]Tη(J)Ξ(J)Δˆμ[bˆ,b]T(η(J)Ξ(J)[η(J)η(bˆ)][Ξ(J)Υ(J)])Δˆμ[a,b]Tη(J)Υ(J)Δˆμ. (2.9)

    In the same way as above, we can prove that

    [a,b]Tη(J)Υ(J)Δˆμ[a,a+ˆ]T(η(J)Ξ(J)[η(J)η(a+ˆ)][Ξ(J)Υ(J)])Δˆμ[a,a+ˆ]Tη(J)Ξ(J)Δˆμ, (2.10)

    The confirmation is finished by joining the integral inequalities (2.9) and (2.10).

    Remark 2.3. We can reclaim [5,Theorem 1] with the use of Lebesgue measure in Theorem 2.3, and T=R.

    Theorem 2.4. Assume S1, S2, S5, S6, S8 and S13 be fulfilled. Then

    [bˆ,b]Tη(J)Ξ(J)Δˆμ+[a,b]T|[η(J)η(bˆ)]ψ(J)|Δˆμ[a,b]Tη(J)Υ(J)Δˆμ[a,a+ˆ]Tη(J)Ξ(J)Δˆμ[a,b]T|[η(J)η(a+ˆ)]ψ(J)|Δˆμ. (2.11)

    Proof. From our hypotheses. Clearly function η is nonincreasing on [a,b] and 0ψ(J)Υ(J)Ξ(J)ψ(J) for all J[a,b], we obtain

    [a,a+ˆ]T[η(J)η(a+ˆ)][Ξ(J)Υ(J)]Δˆμ+[a+ˆ,b]T[η(a+ˆ)η(J)]Υ(J)Δˆμ=[a,a+ˆ]T|η(J)η(a+ˆ)|[Ξ(J)Υ(J)]Δˆμ+[a+ˆ,b]T|η(a+ˆ)η(J)|Υ(J)Δˆμ[a,a+ˆ]T|η(J)η(a+ˆ)|ψ(J)Δˆμ+[a+ˆ,b]T|η(a+ˆ)η(J)|ψ(J)Δˆμ[a,b]T|[η(J)η(a+ˆ)]ψ(J)|Δˆμ.

    Also

    [a,a+ˆ]T[η(J)η(a+ˆ)][Ξ(J)Υ(J)]Δˆμ+[a+ˆ,b]T[η(a+ˆ)η(J)]Υ(J)Δˆμ[a,b]T|[η(J)η(a+ˆ)]ψ(J)|Δˆμ. (2.12)

    Similarly, we find that

    [a,bˆ]T[η(J)η(bˆ)]Υ(J)Δˆμ+[bˆ,b]T[η(bˆ)η(J)][Ξ(J)Υ(J)]Δˆμ[a,b]T|[η(J)η(bˆ)]ψ(J)|Δˆμ. (2.13)

    By combining (2.3), (2.4), (2.12) and (2.13), we arrive at the inequality (2.11) asserted by Theorem 2.

    Remark 2.4. If we take T=R, and consider the Lebesgue measure in Theorem 2.4, we recapture [5,Theorem 2].

    In the following theorem, we use the additional parameters ˆ1, ˆ2[0,).

    Theorem 2.5. Let S1, S2, S5, S6, S9 be satisfied, and

    0ˆ1[a,b]TΥ(J)Δˆμˆ2ba.

    Then

    [bˆ1,b]Tη(J)Δˆμ+η(b)([a,b]TΥ(J)Δˆμˆ1)+M[a,b]T|η(J)f(b[a,b]TΥ(J)Δˆμ)|Δˆμ[a,b]Tη(J)Υ(J)Δˆμ[a,a+ˆ2]Tη(J)Δˆμη(b)(ˆ2[a,b]TΥ(J)Δˆμ)M[a,b]T|η(J)f(a+[a,b]TΥ(J)Δˆμ)|Δˆμ. (2.14)

    Proof. By using straightforward calculations, we have

    [a,b]Tη(J)Υ(J)Δˆμ[a,a+ˆ2]Tη(J)Δˆμ+η(b)(ˆ2[a,b]TΥ(J)Δˆμ)=[a,b]Tη(J)Υ(J)Δˆμ[a,a+ˆ2]Tη(J)Δˆμ+[a,a+ˆ2]Tη(b)Δˆμ[a,b]Tη(b)Υ(J)Δˆμ=[a,b]T[η(J)η(b)]Υ(J)Δˆμ[a,a+ˆ2]T[η(J)η(b)]Δˆμ[a,b]T[η(J)η(b)]Υ(J)Δˆμ[a,a+[a,b]TΥ(J)Δˆμ][η(J)η(b)]Δˆμ, (2.15)

    where we used the theorem's hypotheses

    aa+ˆ1a+[a,b]TΥ(J)Δˆμa+ˆ2b,

    and

    η(J)η(b)0for allJ[a,b].

    The function η(J)η(b) is nonincreasing and integrable on [a,b] and by applying Theorem 2 with Ξ(J)=1, ψ(J)=M and η(J) replaced by η(J)η(b), hence

    [a,b]T[η(J)η(b)]Υ(J)Δˆμ[a,a+[a,b]TΥ(J)Δˆμ][η(J)η(b)]ΔˆμM[a,b]T|η(J)f(a+[a,b]TΥ(J)Δˆμ)|Δˆμ. (2.16)

    From (2.15) and (2.16) we obtain

    [a,b]Tη(J)Υ(J)Δˆμ[a,a+ˆ2]Tη(J)Δˆμ+η(b)(ˆ2[a,b]TΥ(J)Δˆμ)M[a,b]T|η(J)f(a+[a,b]TΥ(J)Δˆμ)|Δˆμ, (2.17)

    which is the right-hand side inequality in (2.14).

    Similarly, one can show that

    [a,b]Tη(J)Υ(J)Δˆμ[bˆ1,b]Tη(J)Δˆμ+η(b)([a,b]TΥ(J)Δˆμˆ2)[a,b]T[η(J)η(b)]Υ(J)Δˆμ+[b[a,b]TΥ(J)Δˆμ,b][η(b)η(J)]ΔˆμM[a,b]T|η(J)f(b[a,b]TΥ(J)Δˆμ)|Δˆμ, (2.18)

    which is the left-hand side inequality in (2.14).

    Remark 2.5. [5,Theorem 3] can be obtained if T=R and Lebesgue measure in Theorem 2.5.

    Theorem 2.6. If S1, S2, S5, S6, S7 and S14 hold. Then

    [a,b]Tη(J)Υ(J)Δˆμ[a,a+ˆ]Tη(J)Ξ(J)Δˆμ[a,b]T|(η(J)η(a+ˆ))ψ(J)|Δˆμ. (2.19)

    Proof. Follows similar to the proof of the right-hand side inequality in Theorem 2.

    Remark 2.6. If we take T=R, and consider the Lebesgue measure in Theorem 2.6, we recapture [6,Theorem 2.12].

    Corollary 2.1. Hypotheses S1, S2, S3, S10 and S11 yield

    [a,b]Tη(J)Υ(J)Δˆμ[a,a+ˆ]Tη(J)Δˆμ[a,b]T|(η(J)Ξ(J)η(a+ˆ)Ξ(a+ˆ))Ξ(J)ψ(J)|Δˆμ. (2.20)

    Proof. Insert Υ(J)Ξ(J)Υ(J), η(J)η(J)/Ξ(J) and ψ(J)Ξ(J)ψ(J) in Theorem 2.

    Remark 2.7. [6,Corollary 2.3] can be recovered with the help of T=R, and Lebesgue measure in Corollary 2.1.

    Theorem 2.7. If S1, S2, S5, S6, S7 and S15 hold. Then

    [bˆ,b]Tη(J)Ξ(J)Δˆμ+[a,b]T|(η(J)η(bˆ))ψ(J)|Δˆμ[a,b]Tη(J)Υ(J)Δˆμ. (2.21)

    Proof. Carry out the same proof of the left-hand side inequality in Theorem 2.

    Remark 2.8. If we take T=R, and consider the Lebesgue measure in Theorem 2.7, we recapture [6,Theorem 2.13].

    Corollary 2.2. Let S1, S2, S3, S9 and S12, be fulfilled. Then

    [bˆ,b]Tη(J)Δˆμ+[a,b]T|(η(J)Ξ(J)η(bˆ)Ξ(bˆ))Ξ(J)ψ(J)|Δˆμ[a,b]Tη(J)Υ(J)Δˆμ. (2.22)

    Proof. Proof can be completed by taking Υ(J)Ξ(J)Υ(J), η(J)η(J)/Ξ(J) and ψ(J)Ξ(J)ψ(J) in Theorem 2.

    Remark 2.9. By letting T=R, and consider the Lebesgue measure in Corollary 2.2, we recapture [6,Corollary 2.4].

    In this article, we explore new generalizations of the integral Steffensen inequality given in [4,5,6] via general time scale measure space with a positive σ-finite measure, we generalize a number of those inequalities to a general time scale measure space. Besides that, in order to obtain some new inequalities as special cases, we also extend our inequalities to discrete and constant calculus.

    This work was supported by Inho Hwang Incheon National University Research Grant 2021–2022.

    The authors declare that there is no competing interest.



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