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Some integral inequalities for harmonical cr-h-Godunova-Levin stochastic processes

  • Received: 19 October 2022 Revised: 24 December 2022 Accepted: 29 December 2022 Published: 06 April 2023
  • MSC : 39B62, 52B55, 94B75

  • An important part of optimization is the consideration of convex and non-convex functions. Furthermore, there is no denying the connection between the ideas of convexity and stochastic processes. Stochastic processes, often known as random processes, are groups of variables created at random and supported by mathematical indicators. Our study introduces a novel stochastic process for center-radius (cr) order based on harmonic h-Godunova-Levin (GL) in the setting of interval-valued functions (IVFS). With some interesting examples, we establish some variants of Hermite-Hadamard (H.H) types inequalities for generalized interval-valued harmonic cr-h-Godunova-Levin stochastic processes.

    Citation: Waqar Afzal, Sayed M. Eldin, Waqas Nazeer, Ahmed M. Galal. Some integral inequalities for harmonical cr-h-Godunova-Levin stochastic processes[J]. AIMS Mathematics, 2023, 8(6): 13473-13491. doi: 10.3934/math.2023683

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  • An important part of optimization is the consideration of convex and non-convex functions. Furthermore, there is no denying the connection between the ideas of convexity and stochastic processes. Stochastic processes, often known as random processes, are groups of variables created at random and supported by mathematical indicators. Our study introduces a novel stochastic process for center-radius (cr) order based on harmonic h-Godunova-Levin (GL) in the setting of interval-valued functions (IVFS). With some interesting examples, we establish some variants of Hermite-Hadamard (H.H) types inequalities for generalized interval-valued harmonic cr-h-Godunova-Levin stochastic processes.



    Fractional calculus has shown great effectiveness in describing and modeling many phenomena in many fields such as physics, chemistry, biology, electricity, economics, etc [1,2,3,4]. Recently, many researchers focus to introduce and develop fractional operators such as Caputo-Fabrizio, Atangana-Baleanu and conformable derivatives [5,6,7,8,9,10,11].

    A new extended fractional operator was proposed in [12] as a combination between conformable and Caputo derivatives. The novel fractional derivative has attracted attention in limited papers, see [13,14,15,16]. For the first time authors in [13] investigated the existence, uniqueness and Ulam-Hyers stability of solutions for conformable derivatives in Caputo setting with four-point integral conditions by applying suitable fixed point theorems. Baleanu et al. [14] discussed Caputo fractional conformable differential inclusion subject to four-point conditions using some analytical techniques on the α-ψ contractive mappings. In [17] authors applied this fractional derivative to describe the behavior of an electrical circuit model.

    Delay differential equations and integro-differential equations in classical and fractional order have been used in modeling many situations from science and engineering. For this reason they have attracted great attention in the last two decades and have been investigated theoretically in many papers [18,19,20,21,22,23,24,25,26,27,31,32,33,34,35]. In a previous study [36], Kavitha et al. established the existence results of Hilfer fractional neutral evolution equation with infinite delay by utilizing the semigroup theory, fractional calculus and Mönch fixed point theorem. In [20] authors studied the existence of mild solutions for a class of non local fractional integro-differential equation in neutral type with infinite delay, using the theory of resolvent operators. Valliammal et al. in [31] established some sufficient conditions for the existence of solutions for neutral delay fractional integro-differential systems, where the authors in [37] studied controllability of nonlocal neutral impulsive differential equations with measure of noncompactness.

    Inspired by the above research, we consider the following nonlocal fractional integro-differential evolution equation with finite delay:

    {Dα,ϱ0+u(t)=Au(t)+f(t,ut,t0h(t,s,us)ds),t[0,b],u(t)+(gu)(t)=φ(t),t[δ,0], (1.1)

    where Dα,ϱ0+ is the Caputo conformable fractional derivative of order 0<α<1 and type 0<ϱ1, and A is infinitesimal generator of a fractional C0-ϱ-semigroup {Tϱ(t)}t0 of bounded operators on a Banach space X with the norm .. The functions φC([δ,0],X), f:[0,b)×C([δ,0],X)×XX, h:[0,b)×[0,+)×C([δ,0],X)X and g:C([δ,b],X)C([δ,0],X) are given abstract functions and ut:[δ,0]X is defined by ut(θ)=u(t+θ).

    In this paper, we try to refine the conditions imposed in some previous works[20,31,36,38,39] and prove the existence of a mild solution under weaker and more general conditions than those mentioned in the previous works. For example, when we chose ϱ=1,δ=0 and h0, problem (1.1) improves the results of existence of a mild solution for the nonlocal Caputo fractional evolution equation discussed in [39]:

    {CDα0+u(t)=Au(t)+f(t,u(t)),t(0,b]u(0)=g(u).

    We study problem (1.1) by converting it to an equivalent integral equation using a suitable fractional Laplace transform, then we define the mild solution of (1.1) in terms of two new families of operators. Each family of operators is associated with the wright function and a suitable fractional semigroup. In the second part of this paper, we apply the Mönch fixed point theorem to establish our main results on the existence of mild solutions with the help of the general version of Gronwall's inequality under weaker conditions in the sense of Kuratowski measure of non-compactness.

    We organize the contents of our paper as follows: In Section 2, we state some basic definitions, concepts and preliminary results which are used throughout this paper. The representation of mild solution of (1.1) using fractional Laplace transform is given in Section 3. In Section 4, under some sufficient conditions, we prove the existence theorem of a mild solution of (1.1), based on Mönch fixed point theorem. An application of our abstract results is given in the last section.

    In this section, we introduce fractional integral, fractional derivative, fractional semigroup and then give the definition of the fractional Laplace transform. Finally, we will give some definitions and lemmas which are used throughout this paper.

    Let X be a Banach space with the norm .. Let δ,bR+. Denote By C=C([δ,0],X) and C([δ,b],X) the spaces of continuous X-valued functions on [δ,0] and [δ,b] with the norms

    uC=supt[δ,0]u(t)

    and

    u=supt[δ,b]u(t)

    respectively, and B(X) be the space of all bounded linear operators from X into X with the norm TB(X)=supxX,X1Tx. Define Lϱp([0,b],X) to be the space of X-valued Bochner functions on [0,b] with the norm uϱp=(b0u(s)pdss1ϱ)1p, 1p<.

    Definition 2.1. [5,10] The left conformable derivative with lower point a of the function f:[a,+)R of order 0<ϱ1 is defined by

    Dϱaf(t)=limϵ0f(t+ϵ(ta)1ϱ)f(t)ϵ.

    If Dϱaf(t) exists on (a,b), then Dϱaf(a)=limta+Dϱaf(t). If f is differentiable, then

    Dϱaf(t)=(ta)1ϱf(t).

    Definition 2.2. [12] Let α,ϱ>0. The left-sided Riemann-Liouville conformablde fractional integral operator of order α and type ϱ with lower limit a for a function f:[a,+)R is defined by

    Iα,ϱau(t)=1Γ(α)ta((ta)ϱ(sa)ϱϱ)α1u(s)ds(sa)1ϱ.

    Definition 2.3. [12] Let α>0, 0<ϱ1 and n=[α]+1. The left Caputo conformable fractional derivative with lower limit a of order α and type ϱ of a function fCnϱ,a([a,b],X) is defined by

    Dα,ϱaf(t)=Inα,ϱa(nDϱaf)(t) (2.1)
    =1nαta((ta)ϱ(sa)ϱϱ)nα1Dϱaf(s)(sa)1ϱds, (2.2)

    where nDϱa=DϱaDϱa...Dϱantimes, and Dϱa is the left conformable derivative given in Definition 2.1.

    Lemma 2.1. [12]Let α,β,γ>0. Then

    Iα,ϱa(Iβ,ϱaf)(t)=Iα+β,ϱaf(t),

    and

    (Iα,ϱa(sa)α(γ1))(t)=1αϱΓ(γ)Γ(ϱ+γ)(ta)α(ϱ+γ1).

    Theorem 2.2. [12]Let α>0, 0<ϱ1 and n=[α]+1. Then

    (1) If αN and fC([a,b],X), then

    Dα,ϱa(Iα,ϱaf)(t)=f(t).

    (2) If αN and fC([a,b],X), then

    Dα,ϱa(Iα,ϱaf)(t)=f(t)Iαn+1,ϱaf(a)ϱnαΓ(nα)(ta)ϱ(nα).

    (3) If fCnϱ,a([a,b],X), then

    Iα,ϱa(Dα,ϱaf)(t)=f(t)n1k=0kDϱaf(a)(ta)ϱkϱkk!.

    Definition 2.4. ([5]) Let aR, 0<ϱ1 and f:[a,)X be an X-valued Bochner function. The fractional Laplace transform of order ϱ started from a is given by

    Lϱaf(s)=+aes(ta)ϱϱf(t)dt(ta)1ϱ. (2.3)

    Definition 2.5. Let 0<ϱ1, and u,v be two X-valued Bochner functions. We define the fractional convolution of u and v of order ϱ by

    (uϱv)(t)=t0u((tϱτϱ)1ϱ)v(τ)dττ1ϱ. (2.4)

    Proposition 2.1. Let 0<ϱ1 and u,v be two X-valued functions which are piecewise continuous at each interval [a,b]and of ϱ-exponential order (u(t)Mectϱ). Then

    (1) For any c1,c2R, Lϱa{c1u+c2v}(s)=c1Lϱa{u}(s)+c2Lϱa{v}(s).

    (2) Lϱa{((ta)ϱϱ)α}(s)=Γ(α+1)sα+1.

    (3) Lϱ0(uϱv)(s)=Lϱ0{u}(s)Lϱ0{v}(s).

    (4) For α>0, Lϱ0{Iα,ϱau}(s)=Lϱ0u(s)sα.

    Proof. The proof follows from the argument of [40] by letting ψ(t)=tϱϱ.

    Lemma 2.3. [41]Let α0, 0<ϱ1 Assume that u,v are two nonnegative locally integrable real valued functions on[0,b] and h is a nonnegative and nondecreasing real valued function on [0,b].If

    u(t)v(t)+h(t)t0(tϱsϱϱ)α1u(s)dss1ϱ,

    then

    u(t)v(t)+t0k=1(h(t)Γ(α))kΓ(kα)(tϱsϱϱ)kα1v(s)dss1ϱ.

    Now, we define and give some results about the so called fractional ϱ-semigroup of bounded linear operators, these results can be found in [5,42,43,44]

    Definition 2.6. [5] Let 0<ϱ1. A family {Tϱ(t)}t0B(X) is called a fractional ϱ-semigroup of bounded linear operators on Banach space X if

    (i) Tϱ(0)=I,

    (ii) Tϱ(t+s)1ϱ=Tϱ(t1ϱ)Tϱ(s1ϱ) for all t,s[0,).

    An ϱsemigroup Tϱ(t) is called a C0-ϱ-semigroup, if for each xX, Tϱ(t)xx as t0+.

    A linear operator A defined by

    D(A)={xX|limt0+Dϱ0+(Tϱ)(t)xexists},

    and

    Ax=limt0+Dϱ0+(Tϱ)(t)x

    is called the ϱinfinitesimal generator of the fractional ϱsemigroup Tϱ(t).

    Theorem 2.4. [42,43]Let A be the ϱ-infinitesimal generator of a fractionalC0-ϱ-semigroup {Tϱ(t)}t0 where 0<ϱ1.Then

    (1) There exist M1 and ω0, such that Tϱ(t)Meωtϱ, t0.

    (2) A is closed densely defined.

    (3) The resolvent set ρ(A) of A contains the interval (ω,+) and for any λ>ω, we have R(λ,A)B(X)Mλω, where the resolvent operator R(λ,A) is defined by

    R(λ,A)x=(λIA)1x=+0eλτϱϱTϱ(τ)dττ1ϱ,xX.

    Throughout this paper, assume that A is the infinitesimal generator of a uniformly bounded C0-ϱ-semigroup {Tϱ(t)}t0 on X. i.e, there exists M1 such that M=supt[0,+)Tϱ(t).

    Next, we define the Kurtawoski measure of noncompact μ(.) on each bounded subset Λ of Banach space X by

    μ(Λ)=inf{ε0:Λmi=1Bi,wherediam(Bi)ε},

    where diam(B) is the diameter of B. The Kurtawoski measure of noncompact (KMN) μ satisfies the following basic properties (see [45,46]):

    (1) μ(Λ1)μ(Λ2), for any bounded subsets Λ1,Λ2X such that Λ1Λ2.

    (2) μ(Λ)=0 if and only if Λ is relatively compact in X.

    (3) μ({x}Λ)=μ(Λ) for all xX and ΛX.

    (4) μ(Λ1Λ2)max{μ(Λ1),μ(Λ2)}.

    (5) μ(Λ1+Λ2)μ(Λ1)+μ(Λ2).

    (6) μ(ηΛ)|η|μ(Λ) for ηR.

    (7) If Θ:ΩXX is a Lipschitz map with constant K, then μ(Θ(Λ))Kμ(Λ) for any bounded subset ΛΩ.

    Lemma 2.5. [47]If ΛC([0,b],X) is bounded, then μ(Λ(t))μ(Λ) forevery t[0,b], where Λ(t)={u(t),uΛ}. Moreover if Λ is equicontinuouson [0,b], then tμ(Λ(t)) is continuous real valued function on [0,b], μ(Λ)=sup{μ(Λ(t)),t[0,b]}. Furthermoreμ(t0Λ(s)ds)t0μ(Λ(s))ds.

    Lemma 2.6. [48]If {un}n=1 is a sequence of Bochner integrable X-valued functions on[0,b] satisfies un(t)ϕ(t) for almost all t[0,b] and every n1, whereϕL1([0,b],R), then the functionψ(t)=μ({un(t):n1})L1([0,b]) and satisfiesμ({t0un(t)ds:n1})2t0ψ(s)ds.

    Lemma 2.7. Let Ω be a closed convex subset of a Banach space X, and G:ΩΩ be continuous satisfying Mönch's condition, i.e.,

    ΛΩiscountable,¯Λ¯conv(0G(Λ))Λiscompact,

    where conv(Λ) denotes the convex hall of Λ. Then G has a fixed point.

    According to Theorem 2.2, we can rewrite the nonlocal problem (1.1) in the following equivalent integral equation:

    {u(t)=φ(0)(gu)(0)+1Γ(α)t0(tϱsϱϱ)α1[Au(s)+f(s,us,Bu(s))]dss1ϱ,t[0,b]u(t)+(gu)(t)=φ(t),t[δ,0] (3.1)

    where Bu(t)=t0h(t,s,us)ds, provided that the integral in (3.1) exists.

    To introduce the mild solution of (1.1) we need to define the two families of operators {Sα,ϱ(t)}t0 and {Pα,ϱ(t)}t0 by

    {Sα,ϱ(t)x=ϱ0θϱ1ψα(θ)Tϱ(ϱ1αϱtϱθ)xdθ,xX,Pα,ϱ(t)=αϱ0θ2ϱ1ψα(θ)Tϱ(ϱ1ϱtαϱθ)xdθ,xX (3.2)

    where 0α,ϱ1 and for θ0

    ψα(θ)=k=0(θ)kk!Γ(α(k+1)+1)=k=0(θ)kΓ(α(k+1))k!sin(π(k+1)α)

    is the wright type function defined on (0,) which is positive and satisfies

    0ψα(θ)dθ=1, (3.3)
    0θγψα(θ)dθ=Γ(1+γ)Γ(1+αγ), (3.4)
    0eλθϕα(θ)dθ=eλα, (3.5)

    where ϕα(θ)=αt1αψα(tα).

    Lemma 3.1. If (3.1) holds, then we have

    {u(t)=Sα,ϱ(t)[φ(0)(gu)(0)]+t0(tϱsϱϱ)α1Pα,ϱ(tϱsϱϱ)f(s,us,Bu(s))dss1ϱ,t[0,b],u(t)+(gu)(t)=φ(t),t[δ,0] (3.6)

    where the operators Sα,ϱ(t) and Pα,ϱ(t)are defined in (3.2).

    Proof. Let λ>0. By applying the fractional Laplace transform of order 0<ϱ1 to (3.1) for t0, we get:

    U(λ)=1λ[φ(0)(gu)(0)]+Lϱ0{Iα,ϱ0(Au(t)+f(t,ut,Bu(t)))}(λ)=1λ[φ(0)(gu)(0)]+1λα[AU(λ)+F(λ)]U(λ)=λα1(λαA)1[φ(0)(gu)(0)]+(λαA)1F(λ)=J1+J2

    where U(λ)=Lϱ0(u)(λ) and F(λ)=Lϱ0(f(t,ut,Bu(t)))(λ).

    Now, differentiating (3.5) with respect to λ, we obtain

    0θϕα(θ)eλθdθ=αλα1eλα. (3.7)

    Using (3.7) and from Theorem 2.4, we get

    J1=λα1(λαA)1[φ(0)(gu)(0)]=λα1+0eλαsϱϱTϱ(s)[φ(0)(gu)(0)]dss1ϱ=+0(sϱϱ)1α1(λ(sϱϱ)1α)α1e(λ(sϱϱ)1α)αTϱ(s)[φ(0)(gu)(0)]dss1ϱ=+0+0eλ(sϱϱ)1αθϕα(θ)Tϱ(s)[φ(0)(gu)(0)]1α(sϱϱ)1α1θdθdss1ϱ. (3.8)

    By using the substitution τϱϱ=(sϱϱ)1αθ and ϑ=θαϱ in the last equation, we obtain

    J1=+0eλτϱϱ+0ϕα(θ)Tϱ(ϱ1αϱτα1θαϱ)[φ(0)(gu)(0)]dθdττ1ϱ=+0eλτϱϱ[+0ϱϑϱ1ψα(ϑϱ)Tϱ(ϱ1αϱταϑ)[φ(0)(gu)(0)]dϑ]dττ1ϱ. (3.9)

    Similarly, from (3.5) and by using the substitution τϱϱ=(sϱϱ)1αθ, we get

    J2=(λαA)1F(λ)=+0eλsϱϱTϱ(s)F(λ)dss1ϱ=+0+0ϕα(θ)eλ(sϱϱ)1αθTϱ(s)F(λ)d(θ)dss1ϱ=+0eλτϱϱ+0(τϱϱ)α1αθαϕα(θ)Tϱ(ϱ1αϱτα1θαϱ)F(λ)d(θ)dττ1ϱ=+0eλτϱϱ+0αϱθ2ϱ1ψα(θϱ)(τϱϱ)α1Tϱ(ϱ1αϱταθ)F(λ)d(θ)dττ1ϱ. (3.10)

    Applying the property 3 of Proposition 2.1 yields

    J2=+0eλτϱϱ+0αϱθ2ϱ1ψα(θϱ)(τϱϱ)α1Tϱ(ϱ1αϱταθ)F(λ)d(θ)dττ1ϱ=+0+0eλ(τϱϱ+sϱϱ)+0αϱθ2ϱ1ψα(θϱ)(τϱϱ)α1×Tϱ(ϱ1αϱταθ)f(s,us,Bu(s))d(θ)dττ1ϱdss1ϱ=+0eλtϱϱ[αt0+0ϱθ2ϱ1ψα(θϱ)(tϱsϱϱ)α1×Tϱ(ϱ1αϱ(ταsϱ)αϱθ)f(s,us,Bu(s))d(θ)dss1ϱ]dtt1ϱ. (3.11)

    According to (3.9) and (3.11), we have

    U(λ)=+0eλtϱϱ(+0ϱθϱ1ψα(θϱ)Tϱ(ϱ1αϱtαθ)[φ(0)(gu)(0)]dθ)dtt1ϱ++0eλtϱϱ(αt0+0ϱθ2ϱ1ψα(θϱ)(tϱsϱϱ)α1×Tϱ(ϱ1αϱ(ταsϱ)αϱθ)f(s,us,Bu(s))d(θ)dss1ϱ)dtt1ϱ (3.12)

    Now, by inverting the inverse fractional Laplace transform, we obtain

    u(t)=+0ϱθϱ1ψα(θϱ)Tϱ(ϱ1αϱtαθ)[φ(0)(gu)(0)]dθ+αt0+0ϱθ2ϱ1ψα(θϱ)(tϱsϱϱ)α1Tϱ(ϱ1αϱ(ταsϱ)αϱθ)f(s,us,Bu(s))d(θ)dss1ϱ=Sα,ϱ(t)[φ(0)(gu)(0)]+t0(tϱsϱϱ)α1Pα,ϱ(tϱsϱϱ)f(s,us,Bu(s))dss1ϱ

    Definition 3.1. An X-valued function uC([δ,b],X) is called a mild solution of the nonlocal Cauchy problem (1.1), if it satisfies:

    {u(t)=Sα,ϱ(t)[φ(0)(gu)(0)]+t0(tϱsϱϱ)α1Pα,ϱ(tϱsϱϱ)f(s,us,Bu(s))dss1ϱ,t[0,b],u(t)+(gu)(t)=φ(t),t[δ,0]. (3.13)

    Lemma 3.2. The family of operators{Sα,ϱ(t)}t0 and{Pα,ϱ(t)}t0 satisfy:

    (i) For any fixed t0, Sα,ϱ(t) and Pα,ϱ(t) are linear and bounded.

    (ii) For any xX, the X-valued functions tSα,ϱ(t)x and tPα,ϱ(t)x are continuous on [0,+).

    Proof. The linearity is obvious. Since Tϱ(t)M for any t0 and from (3.3), we get

    Sα,ϱ(t)xϱ+0ψα(θϱ)Tϱ(ϱ1αϱtαθ)xdθθ1ϱMx+0ψα(θϱ)d(θϱ)Mx+0ψα(θ)dθ=Mx.

    Similarly:

    Pα,ϱ(t)xMxαϱ+0θ2ϱ1ψα(θϱ)dθαMx+0θψα(θ)dθ=αMΓ(1+α)x=MΓ(α)x.

    For the part (ii), let t1,t20. Then

    Sα,ϱ(t1)xSα,ϱ(t2)xϱ+0ψα(θϱ)Tϱ(ϱ1αϱtα1θ)xTϱ(ϱ1αϱtα2θ)xdθθ1ϱ.

    From the strong continuity of Tϱ(t) and by using Lesbegue dominated convergence we obtain limt2t1Sα,ϱ(t1)xSα,ϱ(t2)x=0, which implies that {Sα,ϱ(t)}t0 is strongly continuous. A similar argument enables us to prove the strong continuity of {Pα,ϱ(t)}t0.

    In this section we will establish the existence results by using the Hausdorff measure of noncompactness. To state and prove our main results for the existence of mild solutions of problem (1.1), we need the following hypotheses:

    (H1) The uniformly bounded C0-ϱ-semigroup {Tϱ(t)}t0 generated by A is continuous in the uniform operator topology for t>0.

    (H2) The function f:[0,b]×C×XX satisfies the following

    (i) For each (v,x)C×X, f(.,v,x) is strongly measurable, f(t,.,.) is continuous a.e. for t[0,b].

    (ii) There exists mL1([0,b],R+) such that Iα,ϱ0mC((0,b],R+) and limt0+Iα,ϱ0m(t)=0, satisfying: f(t,x,v)m(t) for all (x,v)X×C and almost all t[0,b].

    (iii) There exists a constant L0 such that for any bounded sets Λ1C, Λ2X

    μ(f(t,Λ1,Λ2))L(supθ[δ,0]μ(Λ1(t))+μ(Λ2)),a.e.t[0,b].

    ((H3)) The function h:[0,b]×[0,b]×CX satisfies the following

    (i) For each vC, h(.,.,v) is strongly measurable, h(t,s,.) is continuous a.e. for (t,s)[0,b]×[0,b].

    (ii) There exists a function m1:[0,b]×[0,b]R+, such that supt[0,b]t0m1(t,s)ds=m1< and h(t,s,v)m1(t,s)vC, for all t,s[0,b] and vC.

    (iii) There exists a function γ:[0,b]×[0,b]R+, such that supt[0,b]t0γ(t,s)ds=γ< and

    μ(h(t,s,Λ))γ(t,s)supθ[δ,0]μ(Λ(t))

    for each bounded subset ΛC and almost all t,s[0,b].

    H4)) The operator g:C([δ,b],X)C satisfies

    (i) For each t[δ,0], the operator Υt:C([δ,b],X)X defined by Υt(u)=(gu)(t) is continuous. There exists a constant L3(0,1M) such that g(u)CL3u for all uC([δ,b],X), and the subset g(Λ)C is equicontinuous for each bounded set ΛC([δ,b],X)

    (ii) There exists a constant L4[0,1) such that μ(Υt(Λ))L4μ(Λ(t)) for each bounded set ΛC([δ,b],X) and all t[δ,0].

    Lemma 4.1. If (H1) holds, then the family of operators {Sα,ϱ(t)}t0 and{Pα,ϱ(t)}t0 are continuous in the uniform operator topology for t>0.

    Proof. Let t1,t20. For ε>0 we have

    Sα,ϱ(t1)xSα,ϱ(t2)xϱ+εψα(θϱ)Tϱ(ϱ1αϱtα1θ)xTϱ(ϱ1αϱtα2θ)xdθθ1ϱ+ϱMε0ψα(θϱ)dθθ1ϱϱ+εψα(θϱ)Tϱ(ϱ1αϱtα1θ)Tϱ(ϱ1αϱtα2θ)xdθθ1ϱ+ϱMεϱ0ψα(θ)dθ. (4.1)

    Applying the Lebesgue dominated convergence by using the continuity of Tϱ in the uniform operator topology and the Eq (3.3), we obtain

    ϱ+εψα(θϱ)Tϱ(ϱ1αϱtα1θ)Tϱ(ϱ1αϱtα2θ)xdθθ1ϱ0ast2t1.

    Then for any xX, x1

    limt2t1Sα,ϱ(t1)xSα,ϱ(t2)xϱMεϱ0ψα(θ)dθ.

    From (3.3), and since ε is arbitrary, then

    εϱ0ψα(θ)dθ0asε0,

    and therefore

    limt2t1Sα,ϱ(t1)xSα,ϱ(t2)x=0

    which implies that the continuity in the uniform operator topology of Sα,ϱ(t) for t>0.

    Using the similar argument we can prove that Pα,ϱ(t) is continuous in the uniform operator topology for t>0.

    Let Br={uC([δ,b],X),ur}, where r0. Then Br is clearly a bounded closed and convex subset in C([δ,b],X). We define the operator Φ by

    (Φ1u)(t)={Sα,ϱ(t)[φ(0)(gu)(0)]+t0(tϱsϱϱ)α1Pα,ϱ(tϱsϱϱ)f(s,us,Bu(s))dss1ϱ,t[0,b],φ(t)(gu)(t),t[δ,0]. (4.2)

    Obviously, uBr is a mild solution of (1.1) if and only if the operator Φ has a fixed point on Br, i.e., there exists uBr satisfies u=Φu.

    Lemma 4.2. If (H1)(H4) hold, then {Φu,uBr} is equicontinuous.

    Proof. Let uBr. For δt1t20, we have

    Φu(t2)Φu(t1)φ(t2)φ(t1)+gu(t2)gu(t1).

    Since φC and from (H4)(i), we obtain

    Φu(t2)Φu(t1)0independentlyforuBrast2t1.

    For δt10<t2b, then from (H2)(ii) and Lemma 3.2, we get

    Φ2u(t2)Φ2u(t1)=φ(t1)gu(t1)Sα,ϱ(t2)[φ(0)(gu)(0)]t20(tϱ2sϱϱ)α1Pα,ϱ(tϱ2sϱϱ)f(s,us,Bu(s))dss1ϱφ(t1)φ(0)+Sα,ϱ(t2)φ(0)φ(0)+gu(t2)gu(0)+Sα,ϱ(t2)gu(0)gu(0)+MΓ(α)t20(tϱ2sϱϱ)α1m(s)dss1ϱI1+I2+I3+I4+I5.

    Since φC and from (H2)(ii), (H4)(i) and Lemma 4.1, we find I1,...,I50 as t1,t20 and hence

    Φu(t2)Φu(t1)0independentlyforuBrast2t1.

    For 0<t1t2b, we have

    Φ2u(t2)Φ2u(t1)(Sα,ϱ(t2)Sα,ϱ(t2))(φ(0)gu(0))+t2t1(tϱ2sϱϱ)α1Pα,ϱ(tϱ2sϱϱ)f(s,us,Bu(s))dss1ϱ+t10(tϱ2sϱϱ)α1Pα,ϱ(tϱ2sϱϱ)f(s,us,Bu(s))dss1ϱt10(tϱ1sϱϱ)α1Pα,ϱ(tϱ2sϱϱ)f(s,us,Bu(s))dss1ϱ+t10(tϱ1sϱϱ)α1Pα,ϱ(tϱ2sϱϱ)f(s,us,Bu(s))dss1ϱt10(tϱ1sϱϱ)α1Pα,ϱ(tϱ1sϱϱ)f(s,us,Bu(s))dss1ϱ (4.3)
    Sα,ϱ(t2)Sα,ϱ(t1)B(X)φ(0)gu(0)+MΓ(α)t2t1(tϱ2sϱϱ)α1m(s)dss1ϱ+MΓ(α)t10[(tϱ1sϱϱ)α1(tϱ2sϱϱ)α1]m(s)dss1ϱ+t10(tϱ1sϱϱ)α1Pα,ϱ(tϱ2sϱϱ)f(s,us,Bu(s))Pα,ϱ(tϱ1sϱϱ)f(s,us,Bu(s))dss1ϱ (4.4)
    Sα,ϱ(t2)Sα,ϱ(t2)B(X)φ(0)gu(0)+MΓ(α)|t20(tϱ2sϱϱ)α1m(s)dss1ϱt10(tϱ1sϱϱ)α1m(s)dss1ϱ|+2MΓ(α)t10[(tϱ1sϱϱ)α1(tϱ2sϱϱ)α1]m(s)dss1ϱ+t10(tϱ1sϱϱ)α1Pα,ϱ(tϱ2sϱϱ)Pα,ϱ(tϱ1sϱϱ)B(X)m(s)dss1ϱ (4.5)
    J1+J2+J3+J4. (4.6)

    Applying Lemma 4.1, we get J10 as t2t1. According to (H2)(ii), we find J20 as t2t1. For t1<t2 and since

    J32MΓ(α)t10(tϱ1sϱϱ)α1m(s)dss1ϱ,

    then from Lebesgue dominated convergence, we get J30 as t2t1. For ε>0 small enough, we have

    J4t1ε0(tϱ1sϱϱ)α1Pα,ϱ(tϱ2sϱϱ)Pα,ϱ(tϱ1sϱϱ)B(X)m(s)dss1ϱ+t1t1ε(tϱ1sϱϱ)α1Pα,ϱ(tϱ2sϱϱ)Pα,ϱ(tϱ1sϱϱ)B(X)m(s)dss1ϱt1ε0(tϱ1sϱϱ)α1Pα,ϱ(tϱ2sϱϱ)Pα,ϱ(tϱ1sϱϱ)B(X)m(s)dss1ϱ+2MΓ(α)|t10(tϱ1sϱϱ)α1m(s)dss1ϱt1ε0((t1ε)ϱsϱϱ)α1m(s)dss1ϱ|+2MΓ(α)t1ε0[((t1ε)ϱsϱϱ)α1(tϱ1sϱϱ)α1]m(s)dss1ϱJ41+J42+J43.

    Since

    J412MΓ(α)t1ε0(tϱ1sϱϱ)α1m(s)dss1ϱ

    and from Lemma 4.1, Pα,ϱ(t) is continuous in the uniform operator topology, then by using Lebesgue dominated convergence we find J410 as t2t1. Using the same manner in J2 and J3 we get J42,J430 as ε0, and consequently J4 converges to zero independently for uBr as t2t1. Therefore

    Φ2u(t2)Φ2u(t1)independentlyforuBrast2t1,

    which means that {Φu,uBr} is equicontinuous.

    Lemma 4.3. If (H1)(H4) hold, then Φ is continuous in Br and maps Br into Br for any r0 satisfies

    M1L3M(φC+supt[0,b]{1Γ(α)t0(tϱsϱϱ)α1m(s)dss1ϱ})r. (4.7)

    Proof. Claim: Φ maps Br into Br.

    Obviously, from Lemma 4.2, ΦuC([δ,b],X). For t[0,b] and for any uBr, by using (H1), (H2)(ii) and (H4)(i), we get

    Φu(t)Sα,ϱ(t)[φ(0)(gu)(0)]+t0(tϱsϱϱ)α1Pα,ϱ(tϱsϱϱ)f(s,us,Bu(s))dss1ϱM(φ(0)+L3u)+MΓ(α)t0(tϱsϱϱ)α1f(s,us,Bu(s))dss1ϱM(φC+L3r+supt[0,b]{1Γ(α)t0(tϱsϱϱ)α1m(s)dss1ϱ})r.

    For t[δ,0], we get

    Φu(t)φ(t)+L3uφC+L3rM(φC+L3r)r.

    Hence, Φur for all uBr.

    Claim: Φ is continuous in Br.

    Let {un}n=0Br such that limnunu=0.

    For t[0,b], we have

    Φun(t)Φu(t)Sα,ϱ(t)[(gun)(0)(gu)(0)]+t0(tϱsϱϱ)α1Pα,ϱ(tϱsϱϱ)(f(s,(un)s,Bun(s))f(s,us,Bu(s)))dss1ϱM(gun)(0)(gu)(0)+MΓ(α)t0(tϱsϱϱ)α1f(s,(un)s,Bun(s))f(s,us,Bu(s))dss1ϱ

    From conditions (H2)(i), (ii) and (H3)(i), (ii) we get

    limnf(s,(un)s,Bun(s))=f(s,us,Bu(s))

    and

    1s1ϱ(tϱsϱϱ)α1f(s,(un)s,Bun(s))f(s,us,Bu(s))2s1ϱ(tϱsϱϱ)α1m(s).

    Then by using Lesbegue dominated convergence, we obtain

    t0(tϱsϱϱ)α1f(s,(un)s,Bun(s))f(s,us,Bu(s))dss1ϱ0asn.

    From (H4)(i), we obtain

    (gun)(0)(gu)(0)0asn.

    Hence

    Φun(t)Φu(t)asn. (4.8)

    From (H4)(i), we find ΦunΦu pointwise on [δ,0] and consequently ΦunΦu pointwise on [δ,b], so the sequence {Φun}n=0 is pointwise relatively compact on [δ,b]. From Lemma 4.2, {Φun}n=0 is equicontinuous, then by Ascoli-Arzela theorem, {Φun}n=0 is relatively compact, i.e., there exists subsequence of {Φun}n=0 converge uniformly, clearly, to Φu as n, and since C([δ,b]) is compete, ΦunΦu uniformly on [δ,b], as n, and so Φ is continuous.

    Theorem 4.4. Assume that (H1)(H4) are hold. Then the nonlocal Cauchy problem (1.1) has at least a mild solution on Br, where r satisfies (4.7).

    Proof. We know that Br is closed and convex. From Lemmas 4.2 and 4.3, we know that Φ is a continuous map from Br into Br and the set {Φu,uBr} is equicontinuous. We shall prove that Φ satisfies the Mönch condition Br. Let Λ={un}n=0 be a countable subset of Br such that Λconv(0Φ(Λ)). Then Λ is bounded and equicontinuous and therefore the function tϖ(t)=μ(Λ(t)) is continuous on [δ,b]. From (H4)(ii), we have, for any t[δ,0],

    ϖ(t)μ(conv(0Φ(Λ(t))))=μ(0Φ(Λ(t)))μ(Φ(Λ(t)))μ({gun(t)}n=1)L4μ({un(t)}n=1)=L4ϖ(t).

    Since L4<1, then ϖ(t)=0 for all t[δ,0]. For t[0,b], then from (H2)(iii), (H3)(iii), (H4)(ii) and by using Lemma 2.6 and properties of the measure μ, we obtain

    ϖ(t)μ(conv(0Φ(Λ(t))))μ(Φ(Λ(t)))μ({gun(t)}n=1)+μ(t0(tϱsϱϱ)α1Pα,ϱ(tϱsϱϱ)f(s,{(un)s}n=1,{Bun(s)}n=1)dss1ϱ)L4μ({un(0)}n=1)+2MΓ(α)t0(tϱsϱϱ)α1μ(f(s,{(un)s}n=1,{Bun(s)}n=1)))dss1ϱL4sup0θtμ({un(θ)}n=1)+2MLΓ(α)t0(tϱsϱϱ)α1[supδθ0μ({un(s+θ)}n=1)+μ({Bun(s)}n=1)]dss1ϱL4sup0θtμ({un(θ)}n=1)+2ML(1+2γ)Γ(α)t0(tϱsϱϱ)α1supδθ0μ({un(s+θ)}n=1)dss1ϱL4sup0θtμ({un(θ)}n=1)+2ML(1+2γ)Γ(α)t0(tϱsϱϱ)α1sup0θsμ({un(θ)}n=1)dss1ϱ.

    From the last equation and by using the properties of supremum, we get

    sup0θtϖ(θ)2ML(1+2γ)(1L4)Γ(α)t0(tϱsϱϱ)α1sup0θsϖ(θ)dss1ϱ.

    Then from Lemma 2.3, we obtain sup0θtϖ(θ)=0 for all t[0,b]. Hence ϖ0 on [γ,b]. This implies that Λ(t) is relatively compact for each t[γ,b]. From Ascoli-Arzela theorem, Λ is relatively compact on Br. Hence from Lemma 2.7, Φ has a fixed point in Br, i.e., the nonlocal Cauchy problem (1.1) has at least mild solution on Br.

    Consider the following nonlocal integro-differential equation:

    {14,ϱtv(t,x)=2xv(t,x)+etarctan(0δsin(|vt(θ,x)|)dθ)+π0(1+|t0(tϱsϱϱ)450δζ(θ)(1exp((sϱϱ)15)s1ϱ|vt(θ,x)|1+|vt(θ,x)|)dθds|)1dx,t[0,b],x[0,π],v(t,0)=v(t,π)=0,t[0,b],v(t,x)+b0ζ1(θ)cos(π2+|vt(θ,x)|)dθ=ψ(t,x),t[δ,0],t[0,π], (5.1)

    where 0<ϱ1, δ>0, and vt(θ,x)=v(t+θ,x). The following conditions hold:

    (1) The function ζ:[δ,0]R is integrable, i.e., 0δ|ζ(θ)|dθ<.

    (2) The function ζ1:[0,b]R is integrable, and b0|ζ2(θ)|dθ<1.

    (3) The function ψ:[δ,0]×[0,π]R is measurable and saisfies

    limt2t1π0|ψ(t2,x)ψ(t2,x)|2dx=0,

    for all t1,t2[δ,0].

    Let X=L2([0,π]). Consider the operator A=2x2 in X with domain

    D(A)=H2([0,π])H10([0,π])

    where H2([0,π]) and H10([0,π]) are the classical Sobolev spaces. Eigenvalues and the corresponding normalized eigenfunctions of A are given by n2, υn=2πsinnx, nN. The family of eigenfunctions {υn}n=0 forms an orthonormal basis in X with inner product (ω,ν)=10ω(x)¯ν(x)dx.

    Define the family of linear operators {Tϱ(t)}t0 by

    Tϱ(t)ω=Σn=1en2tϱϱ(ω,υn)υn,

    for ωX given by ω=Σn=1(ω,υn)υn. This family satisfies the following

    (1) Tϱ(t) is a bounded linear operator, with Tϱ(t)1 for t0.

    (2) For s,t0 and ωX we get the semigroup property Tϱ(t1ϱ)Tϱ(s1ϱ)ω=Tϱ(tϱ+sϱ)1ϱω.

    (3) For s,t0, Tϱ(s)Tϱ(t)0 when st.

    (4) For ωD(A), Dϱ0+Tϱ(t)ω=ATϱ(t)ω. In particular limt0+Dϱ0+Tϱ(t)ω=Aω.

    Clearly, {Tϱ(t)}t0 is a uniformly bounded C0-ϱ-semigroup which is continuous in the uniform operator topology for t0, and A its generator. For x[0,π] and ϕC([δ,0],X), we set

    u(t)(x)=v(t,x)φ(t)(x)=ψ(t,x)f(t,ϕ,ω)(x)=etarctan(0δsin(|ϕ(θ)(x)|)dθ)+π0(1+|ω(x)|)1dx.h(t,s,ϕ)(x)=(tϱsϱϱ)450δζ(θ)(1exp((sϱϱ)15)s1ϱ|ϕ(θ)(x)|1+|ϕ(θ)(x)|)dθg(u)(t)(x)=b0ζ1(θ)cos(π2+|ϕt(θ)(x)|)dθ.

    Then Eq (5.1) can be transformed to the abstract form (1.1).

    For t[0,b], we can obtain

    f(t,ϕ,ω)π32(et2+1)=m(t)

    where Iα,ϱ0mC((0,b],R+) and limt0+Iα,ϱ0m(t)=0.

    For any ϕ,˜ϕC and ω,˜ωX, by straightforward calculations we get

    f(t,ϕ,ω)f(t,˜ϕ,˜ω)δetϕ˜ϕC+πω˜ω.

    Then for any bounded sets Λ1C, ΛX

    μ(f(t,Λ1,Λ2))L(supθ[δ,0]μ(Λ1(t))+μ(Λ2)),

    where L=δ+π and t[0,b].

    For each t,s[0,b], ϕC, we obtain

    h(t,s,ϕ)(tϱsϱϱ)450δζ(θ)1exp((sϱϱ)15s1ϱ|ϕ(θ)(x)|1+|ϕ(θ)(x)|)dθ(tϱsϱϱ)45(sϱϱ)15s1ϱ0δ|ζ(θ)|dθϕCm1(t,s)ϕC,

    where m1(t,s)=(tϱsϱϱ)45(sϱϱ)15s1ϱ0δ|ζ(θ)|dθ satisfies

    m1=supt[0,b]t0m1(t,s)ds=0δ|ζ(θ)|dθsupt[0,b]t0(tϱsϱϱ)45(sϱϱ)15dssϱ1=0δ|ζ(θ)|dθt0t45(1t)15dt=β(15,45)0δ|ζ(θ)|dθ.

    For any t,s[0,b], ϕ,˜ϕC([δ,0],X)

    h(t,s,ϕ)h(t,s,˜ϕ)(tϱsϱϱ)45(sϱϱ)15s1ϱ0δ|ζ(θ)|dθϕ˜ϕC.

    Hence, for any bounded set ΛC,

    μ(h(t,s,Λ))γ(s,t)supθ[δ,0]μ(Λ1(t))

    where γ(s,t)=2(tϱsϱϱ)45(sϱϱ)15s1ϱ0δ|ζ(θ)|dθ, and γ=2β(15,45)0δ|ζ(θ)|dθ.

    For all t[δ,0], ϕ,˜ϕC([δ,b],X), we have

    gϕCL3ϕ,

    and

    gϕ(t)g˜ϕ(t)ϕ˜ϕL4

    where L3=L4=b0|ζ2(θ)|dθ. Then g(.)(t):C([δ,b],X)X is continuous for any t[δ,0], and therefore

    μ(g(Λ)(t))L4μ(Λ(t)).

    Since all conditions of Theorem 4.4 are satisfied, problem (5.1) has at least a mild solution.

    In this manuscript, the existence results of mild solutions for non local fractional evolution equations with finite delay in the sense of Caputo conformable fractional derivative have been successfully investigated under some sufficient conditions on Kuratowski measure of non compactness. To the best of our knowledge, this type of problems supplemented with newly defined Caputo conformable fractional operator has not been investigated in any literature. All the obtained results are supported by an application showing the applicability of the presented theory.

    The authors declare no conflict of interest



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