max(PSL2(q)) | Condition | |
C1 | Eq:C(q−1)/k | k=gcd(q−1,2) |
C2 | D2(q−1)/k | q∉{5,7,9,11} |
C3 | D2(q+1)/k | q∉{7,9} |
C5 | PSL2(q0).(k,b) | q=qb0, b a prime, q0≠2 |
C6 | S4 | q=p≡±1(mod8) |
A4 | q=p≡3,5,13,27,37(mod40) | |
S | A5 | q≡±1(mod10),Fq=Fp[√5] |
In this paper, the structures of non-solvable groups whose all proper subgroups have at most seven character values are identified.
Citation: Shitian Liu, Runshi Zhang. Finite groups all of whose proper subgroups have few character values[J]. AIMS Mathematics, 2023, 8(4): 9074-9081. doi: 10.3934/math.2023454
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In this paper, the structures of non-solvable groups whose all proper subgroups have at most seven character values are identified.
We always think that groups under consideration are all finite. Let G be a group and Irr(G) be the set of all complex irreducible characters of a group G. Let g be an element of a group G. Then denote by cv(G)={χ(g):χ∈Irr(G),g∈G}, the set of character values of G, so cd(G)⊆cv(G) where cd(G)={χ(1):χ∈Irr(G)} is the set of character degrees of a group G. We will use these symbols in this paper:
Epn: the elementary abelian p-group of order pn;
Cn: the cyclic group of order n;
Q8: the quaternion group of order 8;
D2n: the dihedral group of order 2n.
Character values of finite groups have large influence on their structures; see [1,2,23,26]. Recently, Madanha [17] and Sakural [24] studied the influence of character values in a character table on the structure of a group respectively. In particular, Madanha in [17] showed that if a non-solvable group G with |cv(G)|=8, then G≅PSL2(5) or PGL2(5).
Some scholars are of interest in the set cd(G). For example, the structure of finite groups are determined if the degrees of finite groups are either prime powers [13,19,20] or divisible by two prime divisors [21] or the direct product of at most two primes [9,16] or square-free [12] or p′-numbers [6] or are consecutive [8,14,15,22].
In this paper, we go on the subgroup's character values and group structure, namely, we replace the condition "the number of character values of a group is small" with the condition "the number of character values of each proper subgroup of a group is small". For convenient arguments, we introduce the following definition.
Definition 1.1. Let ∑G be the set of the proper subgroups of a group G, and n a positive integer. A group is called a pcvn-group if for each H∈∑G, |cv(H)|≤n.
We mainly show the following.
Theorem 1.2. If G is a pcvn-group with n≤5, then G is solvable.
Theorem 1.2 is corresponding to [10,Theorem 12.15] or [17,Theorem 1.1] which says that a finite group with |cv(G)|≤7 or |cd(G)|≤3 is solvable. Here we use the structure of a minimal simple group to prove Theorem 1.2.
We also obtain the following result which is corresponding to [17,Theorem 1.2] or [18,Theorem 2.2].
Theorem 1.3. Let G be a non-solvable pcvn-group.
(1) If n=6, then G is isomorphic to A5.
(2) If n=7, then G is isomorphic to PSL2(q) with q∈{5,7}.
The structure of this short paper is as follows. In Section 2, some basic results are given, and in Section 3, the structures of non-solvable pcv6- and pcv7-groups are identified respectively. For the other notions and symbols are standard, please see [5,10].
In this section, we assemble some results needed. First result is due to Madanha.
Lemma 2.1. [17,Theorem 1.1] If |cv(G)|≤7, then G is solvable.
A minimal simple group is a simple group of composite order all of whose proper subgroups are solvable.
Lemma 2.2. [25,Corollary 1] Every minimal simple group is isomorphic to one of the following minimal simple groups:
(1) PSL2(2p) for p a prime;
(2) PSL2(3p) for p an odd prime;
(3) PSL2(p), for p any prime exceeding 3 such that p2+1≡0(mod5);
(4) Sz(2p) for p an odd prime;
(5) PSL3(3).
Let A be a group, and let expA be a number which is minimal such that the order of all elements from A divides expA. The following two lemmas are given because the subgroups of a group can control the structure of a group.
Lemma 2.3. Let G be a dihedral group D2n of order 2n. Then |cv(G)|≤n+1.
Proof. Obviously expA≤n with equality when A is cyclic and so by [17,Lemma 2.2], |cv(A)|≤n, and so |cv(G)|≤n+1.
Remark 2.4. In Lemma 2.3 we cannot replace ≤ with =. For instance, Let n=16, then by [4], cv(D32)={1,2,−1,−2,0,A,−A,B,−B,C,−C}. Now |cv(D32)|=11<16.
Remark 2.5. The result of Lemma 2.3 is mostly possible. For example, let n=5. Then by [4], cv(D10)={1,0,−1,2,A,A∗}. Now |cv(D10)|=6=5+1.
Lemma 2.6. Let G be a Frobenius group with the form Epn:Cpn−1 where n≥1 is a positive integer. Then |cv(G)|=p+1. In particular, if Epn:Ck is a Frobenius subgroup of Epn:Cpn−1, then |cv(Epn:Ck)|≤p+1.
Proof. We see expEpn=p, so Lemma 2.2 of [17] forces cv(Epn)=p. We know that Cpn−1, acts fixed-point-freely on Epn so by Theorem 18.7 of [8], |cv(G)|=p+1.
Lemma 2.7. (1) G is a pcvn-group G if and only if for H∈∑G, |cv(H)|≤n.
(2) Let N be a normal subgroup of a pcvn-group G, then, both N and G/N are pcvn-groups.
Proof. We conclude the two results from the definition of a pcvn-group.
In this section we will first determine the structure of simple pcvn-groups for n=6,7 by using Lemma 2.2 and then show the solvability of pcvn-groups when n≤5. For easy reading, we rewrite Theorem 1.3 here.
Theorem 3.1. Let G be a non-abelian simple pcvn-group with n≤7. Then
(1) if n=6, G is isomorphic to A5;
(2) if n=7, G is isomorphic to A5 or PSL2(7).
Proof. We know that for each H∈∑G, |cv(H)|≤7, H is solvable by Lemma 2.1. It follows that G is a group whose proper subgroups are all solvable, so we can assume that G is a minimal simple group. Thus G is isomorphic to PSL2(2p) for p a prime; PSL2(3p) for p an odd prime; PSL2(p), for p any prime exceeding 3 such that p2+1≡0(mod5); Sz(2p) for p an odd prime; PSL3(3); see Lemma 2.2. So in what follows, these cases are considered.
Case 1: PSL2(q) for certain q.
By Table 1, D2(q+1)/k∈maxPSL2(q) and so by Lemma 2.3, q+12≤7 when q is odd or q+1≤7 when q is even. It follows that q is equal to 4, 5, 7, 9, 11 or 13. Note that PSL2(4)≅PSL2(5)≅A5, so two subcases are dealt with.
max(PSL2(q)) | Condition | |
C1 | Eq:C(q−1)/k | k=gcd(q−1,2) |
C2 | D2(q−1)/k | q∉{5,7,9,11} |
C3 | D2(q+1)/k | q∉{7,9} |
C5 | PSL2(q0).(k,b) | q=qb0, b a prime, q0≠2 |
C6 | S4 | q=p≡±1(mod8) |
A4 | q=p≡3,5,13,27,37(mod40) | |
S | A5 | q≡±1(mod10),Fq=Fp[√5] |
Subcase 1: q∈{5,7}.
Let q=5. Then by [5,p. 2], maxA5={A4,D10,S3} and by [4], cv(A4)={−1,0,1,A,A∗}, cv(D10)={−1,0,1,2,A,A∗} and cv(S3)={−1,0,1,2}. It follows that for each H∈maxA5, |cv(H)|≤6, so G is isomorphic to A5.
If q=7, then maxPSL2(7)={S4,7:3} and by [4], cv(7:3)={1,3,A,A∗,B,B∗,0}, cv(S4)={1,2,3,−1,0}, so |cv(7:3)|=7 and |cv(S4)|=5. Assumption shows that G is isomorphic to PSL2(7) as desired.
Subcase 2: q∈{9,11,13}.
By Table 1, A5∈maxPSL2(q) when q=9 or 11 and |cv(A5)|=8 by [17,Theorem 1.2] or [5,p. 2].
If q=13, then 13:6∈maxPSL2(13) and cv(13:6)={1, 6, A, A∗, B, −B, B∗, −B∗, -1, 0} by [4], so |cv(13:6)|=10, a contradiction.
It follows that PSL2(q) for q∈{9,11,13} is not a pcvn-group with n≤7.
Case 2: Sz(2p) for p an odd prime.
In this case, by Table 2, D2(q−1)∈maxSz(q), so by Lemma 2.3, q−1≤7, so q=8. Now 23+3:7∈maxSz(8) and by [4], cv(23+3:7)={1, 7, 14, −2, −1, A, −A, B, B∗, C, C∗, D, D∗, 0}. Thus |cv(23+3:7)|=14, a contradiction.
max(2B2(q)) | Condition |
E1+1q:Cq−1 | |
D2(q−1) | |
Cq+√2q+1.C4 | |
Cq−√2q+1.C4 | |
2B2(q0) | q=qa0, a prime, q0≥8 |
Case 3: PSL3(3).
By [5,pp. 13], 13:3∈PSL3(3) and so by [4], cv(13:3)={0,1,3,A,A∗,B,B∗,C,C∗}. Now |cv(13:3)|=9≰7, a contradiction.
Now we can prove Theorem 1.2. For reader's convenience, we rewrite it here.
Theorem 3.2. If G is a pcvn-group with n≤5, then G is solvable.
Proof. By hypothesis, we know that every proper subgroup of G is solvable. If G is non-solvable, then we can assume that G is simple. Now as the proof of Theorem 3.1 we obtain a contradiction. Thus G is solvable.
In this section, we first show the structure of non-solvable pcv6-groups and then the structures of non-solvable pcv7-groups are determined. For convenient reading, we rewrite Theorem 1.3 here.
Theorem 4.1. Let G be a non-solvable pcvn-group.
(1) If n=6, then G is isomorphic to A5
(2) If n=7, then G is isomorphic to PSL2(q) with q∈{5,7}.
Proof. The non-solvability of G shows that G has a normal sequel 1≤H≤K≤G such that K/H is isomorphic to a direct product of isomorphic simple groups and that |G/K| divides |Out(K/H)|, where Out(A) denotes the outer-automorphism group of a group A; see [27].
Now we have that
K/H is isomorphic to S×S×⋯×S⏟m times |
where S≅A5 when n=6 and S≅A5 or PSL2(7) when n=7; see Theorem 3.1. By Lemma 2.7, K/H is a pcvn-group, so let H∈maxS, now
H×S×⋯×S⏟m−1 times is a maximal subgroup of S×S×⋯×S⏟m times. |
If m≥2, then |cv(A5)|=8 and |cv(PSL2(7))|=10 as cv(A5)={1,3,4,5,−1,0,A,A∗} and cv(PSL2(7))={1,3,6,7,8,−1,2,0,A,A∗} by [5,p. 2-3], so |cv(H×S×⋯×S)|≥8, a contradiction. Thus m=1 and for any S<H≤Aut(S), |cv(S)|≥8 shows that H is not a pcvn-group with n=6,7; see [17,Theorem 1.2]. Now G/H≅A5 or PSL2(7) and G is not an almost simple group. It follows that
G′/H≅PSL2(q) or SL2(q) with q∈{5,7}; |
see [7,Chap 2,Theorem 6.10].
So in the following two cases are done with.
Where N1 maximal under <δ> with |δ|=(q−1,2); N2 maximal under subgroups not contained in <φ> with |φ|=e, q=pe, p a prime.
Case 1: G′/H≅A5 or SL2(5).
By Table 3, 2.A4∈maxSL2(5) and by [4], cv(2.A4)={1,3,2,−2,0,A,A∗,−A∗,−A}. It follows that |cv(2.A4)|=9>7, so SL2(5) is not a pcvn-group with n=6,7. Thus G′/H≅SL2(5) is impossible. Now G′/H≅A5 and G′∩H=1, so [G′,H]≤G′∩H=1. Thus,
G′≅G′G′∩H≅G′H≅A5. |
maxSL2(q) | Condition |
Eq:Cq−1 | |
Q2(q−1) | q≠5,7,9,11; q odd |
N1 if q=7,11; N2 if q=9 | |
D2(q−1) | q even |
Q2(q+1) | q≠7,9; q odd |
N1 if q=7; N2 if q=9 | |
D2(q+1) | q even |
SL2(q0).2 | q=q20, q odd |
SL2(q0) | q=qr0, q odd, r odd prime |
PSL2(q0) | q=qr0, q even, q0≠2, r prime |
2.S4 | q=p≡±1(mod8) |
2.A4 | q=p≡±3,5,±13(mod40) |
N1 if q=p≡±11,±19(mod40) | |
2.A5 | q=p≡±1(mod10) |
q=p2, p≡±3(mod10) |
It follows that G≅H×A5. If H≠1, then A5∈∑G. Observe that |cv(A5)|=8, so in this case G is a non-pcvn-group with n=6,7. Therefore G is isomorphic to A5, the desired result.
Case 2: G′/H≅PSL2(7) or SL2(7).
In this case n=7. Table 3 gives that E7:C6∈maxSL2(7) and by [4], cv(E7:C6)={1,6,−1,0,A,−A,A∗,−A∗}. It follows that |cv(E7:C6)|=8 (this result can be gotten from Lemma 2.6), so SL2(7) is not a pcv7-group. Thus G′/H≅SL2(7) is not possible. Now consider when G′/H≅PSL2(7). Then G′∩H=1, [G′,H]=1 and G≅H×PSL2(7) too. If H≠1, then PSL2(7) is not a pcv7-group, so H=1 and G is isomorphic to PSL2(7), the wanted result.
Proposition 4.2. Let G be a pcvn-group with n≤7. Assume that G has no section isomorphic to PSL2(q) for q∈{5,7}, then G is solvable.
Proof. By Theorems 1.2 and 1.3, we can get the desired result.
The authors were supported by NSF of China(Grant No: 11871360) and also the first author was supported by the Opening Project of Sichuan Province University Key Laborstory of Bridge Non-destruction Detecting and Engineering Computing (Grant Nos: 2022QYJ04), and by the the Project of High-Level Talent of Sichuan Institute of Arts and Science (Grant No: 2021RC001Z).
The authors declare that they have no conflicts of interest.
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max(PSL2(q)) | Condition | |
C1 | Eq:C(q−1)/k | k=gcd(q−1,2) |
C2 | D2(q−1)/k | q∉{5,7,9,11} |
C3 | D2(q+1)/k | q∉{7,9} |
C5 | PSL2(q0).(k,b) | q=qb0, b a prime, q0≠2 |
C6 | S4 | q=p≡±1(mod8) |
A4 | q=p≡3,5,13,27,37(mod40) | |
S | A5 | q≡±1(mod10),Fq=Fp[√5] |
max(2B2(q)) | Condition |
E1+1q:Cq−1 | |
D2(q−1) | |
Cq+√2q+1.C4 | |
Cq−√2q+1.C4 | |
2B2(q0) | q=qa0, a prime, q0≥8 |
maxSL2(q) | Condition |
Eq:Cq−1 | |
Q2(q−1) | q≠5,7,9,11; q odd |
N1 if q=7,11; N2 if q=9 | |
D2(q−1) | q even |
Q2(q+1) | q≠7,9; q odd |
N1 if q=7; N2 if q=9 | |
D2(q+1) | q even |
SL2(q0).2 | q=q20, q odd |
SL2(q0) | q=qr0, q odd, r odd prime |
PSL2(q0) | q=qr0, q even, q0≠2, r prime |
2.S4 | q=p≡±1(mod8) |
2.A4 | q=p≡±3,5,±13(mod40) |
N1 if q=p≡±11,±19(mod40) | |
2.A5 | q=p≡±1(mod10) |
q=p2, p≡±3(mod10) |
max(PSL2(q)) | Condition | |
C1 | Eq:C(q−1)/k | k=gcd(q−1,2) |
C2 | D2(q−1)/k | q∉{5,7,9,11} |
C3 | D2(q+1)/k | q∉{7,9} |
C5 | PSL2(q0).(k,b) | q=qb0, b a prime, q0≠2 |
C6 | S4 | q=p≡±1(mod8) |
A4 | q=p≡3,5,13,27,37(mod40) | |
S | A5 | q≡±1(mod10),Fq=Fp[√5] |
max(2B2(q)) | Condition |
E1+1q:Cq−1 | |
D2(q−1) | |
Cq+√2q+1.C4 | |
Cq−√2q+1.C4 | |
2B2(q0) | q=qa0, a prime, q0≥8 |
maxSL2(q) | Condition |
Eq:Cq−1 | |
Q2(q−1) | q≠5,7,9,11; q odd |
N1 if q=7,11; N2 if q=9 | |
D2(q−1) | q even |
Q2(q+1) | q≠7,9; q odd |
N1 if q=7; N2 if q=9 | |
D2(q+1) | q even |
SL2(q0).2 | q=q20, q odd |
SL2(q0) | q=qr0, q odd, r odd prime |
PSL2(q0) | q=qr0, q even, q0≠2, r prime |
2.S4 | q=p≡±1(mod8) |
2.A4 | q=p≡±3,5,±13(mod40) |
N1 if q=p≡±11,±19(mod40) | |
2.A5 | q=p≡±1(mod10) |
q=p2, p≡±3(mod10) |