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Finite groups all of whose proper subgroups have few character values

  • Received: 30 December 2022 Revised: 11 January 2023 Accepted: 29 January 2023 Published: 13 February 2023
  • MSC : 20C15, 20C33

  • In this paper, the structures of non-solvable groups whose all proper subgroups have at most seven character values are identified.

    Citation: Shitian Liu, Runshi Zhang. Finite groups all of whose proper subgroups have few character values[J]. AIMS Mathematics, 2023, 8(4): 9074-9081. doi: 10.3934/math.2023454

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  • In this paper, the structures of non-solvable groups whose all proper subgroups have at most seven character values are identified.



    We always think that groups under consideration are all finite. Let G be a group and Irr(G) be the set of all complex irreducible characters of a group G. Let g be an element of a group G. Then denote by cv(G)={χ(g):χIrr(G),gG}, the set of character values of G, so cd(G)cv(G) where cd(G)={χ(1):χIrr(G)} is the set of character degrees of a group G. We will use these symbols in this paper:

    Epn: the elementary abelian p-group of order pn;

    Cn: the cyclic group of order n;

    Q8: the quaternion group of order 8;

    D2n: the dihedral group of order 2n.

    Character values of finite groups have large influence on their structures; see [1,2,23,26]. Recently, Madanha [17] and Sakural [24] studied the influence of character values in a character table on the structure of a group respectively. In particular, Madanha in [17] showed that if a non-solvable group G with |cv(G)|=8, then GPSL2(5) or PGL2(5).

    Some scholars are of interest in the set cd(G). For example, the structure of finite groups are determined if the degrees of finite groups are either prime powers [13,19,20] or divisible by two prime divisors [21] or the direct product of at most two primes [9,16] or square-free [12] or p-numbers [6] or are consecutive [8,14,15,22].

    In this paper, we go on the subgroup's character values and group structure, namely, we replace the condition "the number of character values of a group is small" with the condition "the number of character values of each proper subgroup of a group is small". For convenient arguments, we introduce the following definition.

    Definition 1.1. Let G be the set of the proper subgroups of a group G, and n a positive integer. A group is called a pcvn-group if for each HG, |cv(H)|n.

    We mainly show the following.

    Theorem 1.2. If G is a pcvn-group with n5, then G is solvable.

    Theorem 1.2 is corresponding to [10,Theorem 12.15] or [17,Theorem 1.1] which says that a finite group with |cv(G)|7 or |cd(G)|3 is solvable. Here we use the structure of a minimal simple group to prove Theorem 1.2.

    We also obtain the following result which is corresponding to [17,Theorem 1.2] or [18,Theorem 2.2].

    Theorem 1.3. Let G be a non-solvable pcvn-group.

    (1) If n=6, then G is isomorphic to A5.

    (2) If n=7, then G is isomorphic to PSL2(q) with q{5,7}.

    The structure of this short paper is as follows. In Section 2, some basic results are given, and in Section 3, the structures of non-solvable pcv6- and pcv7-groups are identified respectively. For the other notions and symbols are standard, please see [5,10].

    In this section, we assemble some results needed. First result is due to Madanha.

    Lemma 2.1. [17,Theorem 1.1] If |cv(G)|7, then G is solvable.

    A minimal simple group is a simple group of composite order all of whose proper subgroups are solvable.

    Lemma 2.2. [25,Corollary 1] Every minimal simple group is isomorphic to one of the following minimal simple groups:

    (1) PSL2(2p) for p a prime;

    (2) PSL2(3p) for p an odd prime;

    (3) PSL2(p), for p any prime exceeding 3 such that p2+10(mod5);

    (4) Sz(2p) for p an odd prime;

    (5) PSL3(3).

    Let A be a group, and let expA be a number which is minimal such that the order of all elements from A divides expA. The following two lemmas are given because the subgroups of a group can control the structure of a group.

    Lemma 2.3. Let G be a dihedral group D2n of order 2n. Then |cv(G)|n+1.

    Proof. Obviously expAn with equality when A is cyclic and so by [17,Lemma 2.2], |cv(A)|n, and so |cv(G)|n+1.

    Remark 2.4. In Lemma 2.3 we cannot replace with =. For instance, Let n=16, then by [4], cv(D32)={1,2,1,2,0,A,A,B,B,C,C}. Now |cv(D32)|=11<16.

    Remark 2.5. The result of Lemma 2.3 is mostly possible. For example, let n=5. Then by [4], cv(D10)={1,0,1,2,A,A}. Now |cv(D10)|=6=5+1.

    Lemma 2.6. Let G be a Frobenius group with the form Epn:Cpn1 where n1 is a positive integer. Then |cv(G)|=p+1. In particular, if Epn:Ck is a Frobenius subgroup of Epn:Cpn1, then |cv(Epn:Ck)|p+1.

    Proof. We see expEpn=p, so Lemma 2.2 of [17] forces cv(Epn)=p. We know that Cpn1, acts fixed-point-freely on Epn so by Theorem 18.7 of [8], |cv(G)|=p+1.

    Lemma 2.7. (1) G is a pcvn-group G if and only if for HG, |cv(H)|n.

    (2) Let N be a normal subgroup of a pcvn-group G, then, both N and G/N are pcvn-groups.

    Proof. We conclude the two results from the definition of a pcvn-group.

    In this section we will first determine the structure of simple pcvn-groups for n=6,7 by using Lemma 2.2 and then show the solvability of pcvn-groups when n5. For easy reading, we rewrite Theorem 1.3 here.

    Theorem 3.1. Let G be a non-abelian simple pcvn-group with n7. Then

    (1) if n=6, G is isomorphic to A5;

    (2) if n=7, G is isomorphic to A5 or PSL2(7).

    Proof. We know that for each HG, |cv(H)|7, H is solvable by Lemma 2.1. It follows that G is a group whose proper subgroups are all solvable, so we can assume that G is a minimal simple group. Thus G is isomorphic to PSL2(2p) for p a prime; PSL2(3p) for p an odd prime; PSL2(p), for p any prime exceeding 3 such that p2+10(mod5); Sz(2p) for p an odd prime; PSL3(3); see Lemma 2.2. So in what follows, these cases are considered.

    Case 1: PSL2(q) for certain q.

    By Table 1, D2(q+1)/kmaxPSL2(q) and so by Lemma 2.3, q+127 when q is odd or q+17 when q is even. It follows that q is equal to 4, 5, 7, 9, 11 or 13. Note that PSL2(4)PSL2(5)A5, so two subcases are dealt with.

    Table 1.  PSL2(q), q5 [11,p. 191].
    max(PSL2(q)) Condition
    C1 Eq:C(q1)/k k=gcd(q1,2)
    C2 D2(q1)/k q{5,7,9,11}
    C3 D2(q+1)/k q{7,9}
    C5 PSL2(q0).(k,b) q=qb0, b a prime, q02
    C6 S4 q=p±1(mod8)
    A4 q=p3,5,13,27,37(mod40)
    S A5 q±1(mod10),Fq=Fp[5]

     | Show Table
    DownLoad: CSV

    Subcase 1: q{5,7}.

    Let q=5. Then by [5,p. 2], maxA5={A4,D10,S3} and by [4], cv(A4)={1,0,1,A,A}, cv(D10)={1,0,1,2,A,A} and cv(S3)={1,0,1,2}. It follows that for each HmaxA5, |cv(H)|6, so G is isomorphic to A5.

    If q=7, then maxPSL2(7)={S4,7:3} and by [4], cv(7:3)={1,3,A,A,B,B,0}, cv(S4)={1,2,3,1,0}, so |cv(7:3)|=7 and |cv(S4)|=5. Assumption shows that G is isomorphic to PSL2(7) as desired.

    Subcase 2: q{9,11,13}.

    By Table 1, A5maxPSL2(q) when q=9 or 11 and |cv(A5)|=8 by [17,Theorem 1.2] or [5,p. 2].

    If q=13, then 13:6maxPSL2(13) and cv(13:6)={1, 6, A, A, B, B, B, B, -1, 0} by [4], so |cv(13:6)|=10, a contradiction.

    It follows that PSL2(q) for q{9,11,13} is not a pcvn-group with n7.

    Case 2: Sz(2p) for p an odd prime.

    In this case, by Table 2, D2(q1)maxSz(q), so by Lemma 2.3, q17, so q=8. Now 23+3:7maxSz(8) and by [4], cv(23+3:7)={1, 7, 14, 2, 1, A, A, B, B, C, C, D, D, 0}. Thus |cv(23+3:7)|=14, a contradiction.

    Table 2.  Sz(q), q=22m+18 [3,p. 385].
    max(2B2(q)) Condition
    E1+1q:Cq1
    D2(q1)
    Cq+2q+1.C4
    Cq2q+1.C4
    2B2(q0) q=qa0, a prime, q08

     | Show Table
    DownLoad: CSV

    Case 3: PSL3(3).

    By [5,pp. 13], 13:3PSL3(3) and so by [4], cv(13:3)={0,1,3,A,A,B,B,C,C}. Now |cv(13:3)|=97, a contradiction.

    Now we can prove Theorem 1.2. For reader's convenience, we rewrite it here.

    Theorem 3.2. If G is a pcvn-group with n5, then G is solvable.

    Proof. By hypothesis, we know that every proper subgroup of G is solvable. If G is non-solvable, then we can assume that G is simple. Now as the proof of Theorem 3.1 we obtain a contradiction. Thus G is solvable.

    In this section, we first show the structure of non-solvable pcv6-groups and then the structures of non-solvable pcv7-groups are determined. For convenient reading, we rewrite Theorem 1.3 here.

    Theorem 4.1. Let G be a non-solvable pcvn-group.

    (1) If n=6, then G is isomorphic to A5

    (2) If n=7, then G is isomorphic to PSL2(q) with q{5,7}.

    Proof. The non-solvability of G shows that G has a normal sequel 1HKG such that K/H is isomorphic to a direct product of isomorphic simple groups and that |G/K| divides |Out(K/H)|, where Out(A) denotes the outer-automorphism group of a group A; see [27].

    Now we have that

    K/H is isomorphic to S×S××Sm times

    where SA5 when n=6 and SA5 or PSL2(7) when n=7; see Theorem 3.1. By Lemma 2.7, K/H is a pcvn-group, so let HmaxS, now

    H×S××Sm1 times is a maximal subgroup of S×S××Sm times.

    If m2, then |cv(A5)|=8 and |cv(PSL2(7))|=10 as cv(A5)={1,3,4,5,1,0,A,A} and cv(PSL2(7))={1,3,6,7,8,1,2,0,A,A} by [5,p. 2-3], so |cv(H×S××S)|8, a contradiction. Thus m=1 and for any S<HAut(S), |cv(S)|8 shows that H is not a pcvn-group with n=6,7; see [17,Theorem 1.2]. Now G/HA5 or PSL2(7) and G is not an almost simple group. It follows that

    G/HPSL2(q) or SL2(q) with q{5,7};

    see [7,Chap 2,Theorem 6.10].

    So in the following two cases are done with.

    Where N1 maximal under <δ> with |δ|=(q1,2); N2 maximal under subgroups not contained in <φ> with |φ|=e, q=pe, p a prime.

    Case 1: G/HA5 or SL2(5).

    By Table 3, 2.A4maxSL2(5) and by [4], cv(2.A4)={1,3,2,2,0,A,A,A,A}. It follows that |cv(2.A4)|=9>7, so SL2(5) is not a pcvn-group with n=6,7. Thus G/HSL2(5) is impossible. Now G/HA5 and GH=1, so [G,H]GH=1. Thus,

    GGGHGHA5.
    Table 3.  SL2(q), q4([3,p. 377]).
    maxSL2(q) Condition
    Eq:Cq1
    Q2(q1) q5,7,9,11; q odd
    N1 if q=7,11; N2 if q=9
    D2(q1) q even
    Q2(q+1) q7,9; q odd
    N1 if q=7; N2 if q=9
    D2(q+1) q even
    SL2(q0).2 q=q20, q odd
    SL2(q0) q=qr0, q odd, r odd prime
    PSL2(q0) q=qr0, q even, q02, r prime
    2.S4 q=p±1(mod8)
    2.A4 q=p±3,5,±13(mod40)
    N1 if q=p±11,±19(mod40)
    2.A5 q=p±1(mod10)
    q=p2, p±3(mod10)

     | Show Table
    DownLoad: CSV

    It follows that GH×A5. If H1, then A5G. Observe that |cv(A5)|=8, so in this case G is a non-pcvn-group with n=6,7. Therefore G is isomorphic to A5, the desired result.

    Case 2: G/HPSL2(7) or SL2(7).

    In this case n=7. Table 3 gives that E7:C6maxSL2(7) and by [4], cv(E7:C6)={1,6,1,0,A,A,A,A}. It follows that |cv(E7:C6)|=8 (this result can be gotten from Lemma 2.6), so SL2(7) is not a pcv7-group. Thus G/HSL2(7) is not possible. Now consider when G/HPSL2(7). Then GH=1, [G,H]=1 and GH×PSL2(7) too. If H1, then PSL2(7) is not a pcv7-group, so H=1 and G is isomorphic to PSL2(7), the wanted result.

    Proposition 4.2. Let G be a pcvn-group with n7. Assume that G has no section isomorphic to PSL2(q) for q{5,7}, then G is solvable.

    Proof. By Theorems 1.2 and 1.3, we can get the desired result.

    The authors were supported by NSF of China(Grant No: 11871360) and also the first author was supported by the Opening Project of Sichuan Province University Key Laborstory of Bridge Non-destruction Detecting and Engineering Computing (Grant Nos: 2022QYJ04), and by the the Project of High-Level Talent of Sichuan Institute of Arts and Science (Grant No: 2021RC001Z).

    The authors declare that they have no conflicts of interest.



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