In this paper, we consider the existence and multiplicity of nontrivial solutions to second order partial difference equation with Dirichlet boundary conditions by Morse theory. Given suitable conditions, we establish multiple results that the problem admits at least two nontrivial solutions. Moreover, we provide five examples to illustrate applications of our theorems.
Citation: Huan Zhang, Yin Zhou, Yuhua Long. Results on multiple nontrivial solutions to partial difference equations[J]. AIMS Mathematics, 2023, 8(3): 5413-5431. doi: 10.3934/math.2023272
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In this paper, we consider the existence and multiplicity of nontrivial solutions to second order partial difference equation with Dirichlet boundary conditions by Morse theory. Given suitable conditions, we establish multiple results that the problem admits at least two nontrivial solutions. Moreover, we provide five examples to illustrate applications of our theorems.
Let N and Z be natural number set and integer set, respectively. For integers a, b, define the discrete interval Z(a,b):={a,a+1,⋯,b} for a≤b. Write Ω:=Z(1,T1)×Z(1,T2), where T1, T2≥2 are given integers. We consider the existence and multiplicity of nontrivial solutions to the following nonlinear second order partial difference equation
Δ21u(i−1,j)+Δ22u(i,j−1)=−f((i,j),u(i,j)),(i,j)∈Ω, | (1.1) |
with Dirichlet boundary conditions
u(i,0)=u(i,T2+1)=0i∈Z(1,T1),u(0,j)=u(T1+1,j)=0j∈Z(1,T2), | (1.2) |
where Δ1, Δ2 are the forward difference operators defined by Δ1u(i,j)=u(i+1,j)−u(i,j) and Δ2u(i,j)=u(i,j+1)−u(i,j). Δ2u(i,j)=Δ(Δu(i,j)). Here f((i,j),⋅)∈C1(Ω×R,R) satisfies f((i,j),0)=0, which means that (1.1) and (1.2) possesses a trivial solution u=0. Meanwhile, We are interested in nontrivial solutions and intend to seek nontrivial solutions to (1.1) and (1.2).
Due to wide applications in many fields such as computer science, economics and mechanical engineering, the theory of nonlinear discrete problems has been widely studied and many results are obtained [1,2,3,4,5,6]. With the rapid development of modern computer technology, more and more mathematical models involve functions with two or more variables. Partial difference equations, involving two or more discrete variables, are regarded as discrete analogs of partial differential equations. Therefore, the study of difference equations has gradually shifted to the study of partial difference equations and attracted much attentions, for example, [7,8,9,10,11,12,13,14].
As known to all, with the rapid development of critical point theory, the Morse theory becomes a more and more powerful tool to study the multiplicity and existence of nontrivial solutions to both differential equations and difference equations having variational structure [15,16,17,18]. Very recently, [19,20,21] studied partial difference equations via the Morse theory and obtained rich results on the existence and multiplicity of nontrivial solutions. Thus those reasons are encouraging us to consider the existence and multiplicity of nontrivial solutions to (1.1) and (1.2) by the Morse theory.
We organize this paper as follows. In Section 2, the variational structure and the corresponding functional are established. Moreover, we also recall some related definitions and propositions, which are necessary to our main results. Section 3 states our main results and their detailed proofs. Finally, five examples and numerical simulations are provided to demonstrate applications of our main results in Section 4.
Let E be a T1T2-dimensional Euclidean space equipped with the usual inner product (⋅,⋅) and norm |⋅|. Let
S={u:Z(0,T1+1)×Z(0,T2+1)→Rsuch thatu(i,0)=u(i,T2+1)=0,i∈Z(0,T1+1)andu(0,j)=u(T1+1,j)=0,j∈Z(0,T2+1)}. |
Define the inner product ⟨⋅,⋅⟩ on S as
⟨u,v⟩=T1+1∑i=1T2∑j=1Δ1u(i−1,j)Δ1v(i−1,j)+T1∑i=1T2+1∑j=1Δ2u(i,j−1)Δ2v(i,j−1),∀u,v∈S. |
Then the induced norm is
‖u‖=√⟨u,u⟩=(T1+1∑i=1T2∑j=1|Δ1u(i−1,j)|2+T1∑i=1T2+1∑j=1|Δ2u(i,j−1)|2)12,∀u∈S. |
Thus S is a Hilbert space and isomorphic to E. Here and hereafter, we take u∈S an extension of u∈E if necessary.
Consider the functional J:S→R as
J(u)=12T1+1∑i=1T2∑j=1|Δ1u(i−1,j)|2+12T1∑i=1T2+1∑j=1|Δ2u(i,j−1)|2−T1∑i=1T2∑j=1F((i,j),u(i,j))=12‖u‖2−T1∑i=1T2∑j=1F((i,j),u(i,j)),∀u∈S, | (2.1) |
where F((i,j),u)=∫u0f((i,j),τ)dτ for each (i,j)∈Ω. Notice that f((i,j),u) is continuously differentiable with respect to u. Therefore, the expression of J means that J∈C2(S,R) and solutions of the problems (1.1) and (1.2) are precisely critical points of J(u). Moreover, for any u, v∈S, applying Dirichlet boundary conditions, direct computations gives that the Fréchet derivative of J(u) is
⟨J′(u),v⟩=T1+1∑i=1T2∑j=1Δ1u(i−1,j)Δ1v(i−1,j)+T1∑i=1T2+1∑j=1Δ2u(i,j−1)Δ2v(i,j−1)−T1∑i=1T2∑j=1f((i,j),u(i,j))v(i,j)=−T1∑i=1T2∑j=1[Δ21u(i−1,j)+Δ22u(i,j−1)+f((i,j),u(i,j))]v(i,j). | (2.2) |
Let Ξ be the discrete Laplacian, which is defined by Ξu(i,j)=Δ21u(i−1,j)+Δ22u(i,j−1). Owe to [11], −Ξ is invertible and the distinct eigenvalues of −Ξ with zero Dirichlet boundary conditions on Ω can be denoted by 0<λ1<λ2≤⋯≤λT1T2. Let ϕk=(ϕk(1),ϕk(2),⋯,ϕk(T1T2))tr, k∈[1,T1T2] be an eigenvector corresponding to the eigenvalue λk. Write
W−=span{ϕ1,⋯,ϕk−1},W0=span{ϕk},W+=(W−⊕W0)⊥. |
Then S can be expressed in the form as
S=W−⊕W0⊕W+. |
For later use, define another norm as
‖u‖2=(T1∑i=1T2∑j=1|u(i,j)|2)12,u∈S. |
Then for any u∈S, we have
λ1‖u‖22≤‖u‖2≤λT1T2‖u‖22. | (2.3) |
In particular, we have
λk+1‖u‖22≤‖u‖2≤λT1T2‖u‖22,u∈W+,λ1‖u‖22≤‖u‖2≤λk−1‖u‖22,u∈W−. | (2.4) |
Now we recall some basic results on the Morse theory.
We say that the functional J satisfies the Palais-Smale condition ((PS) in short) if any sequence {un}⊆S, there is a constant M>0 such that |J(un)|≤M, J′(un)→0 as n→∞, has a convergent subsequence. From [22,23], if (PS) is satisfied, then both the weaker Cerami condition ((C) for short) and the deformation condition ((D) in short) are also fulfilled.
Definition 2.1. [16,24] Let u0 be an isolated critical group of J with J(u0)=c∈R, and U be a neighborhood of u0, the group
Cq(J,u0):=Hq(Jc∩U,Jc∩U∖u0),q∈Z, |
is called the q-th critical group of J at u0. Let κ={u∈S|J′(u)=0}. For all a∈R each critical point of J is greater than a and J∈C2(S,R) satisfies (D), the group
Cq(J,∞):=Hq(S,Ja),q∈Z, |
is called the q-th critical group of J at infinity.
To compute critical groups of J at both an isolated critical point and infinity, the following auxiliary propositions are needed.
Proposition 2.1. [16,24] Suppose that u0 is an isolated critical point of J with finite Morse index μ(u0) and zero nullity ν(u0). Then
(Q1) Cq(J,u0)≅0 for q∉[μ(u0),μ(u0)+ν(u0)];
(Q2) Cq(J,u0)≅δq,u0Z, q∈Z, if u0 is nondegenerate;
(Q3) Cq(J,u0)≅δq,kZ for k=μ(u0) or k=μ(u0)+ν(u0), if Ck(J,u0)≆0.
Proposition 2.2. [17] Let J∈C2(S,R) satisfy (D). We have
(Q4) if Cq(J,∞)≆0 holds for some q, then J possesses a critical point u such that Cq(J,u)≆0;
(Q5) if 0 is the isolated critical point of J and Cq(J,∞)≆Cq(J,0) holds for some q, then J has a non-zero critical point.
Proposition 2.3. [25] Suppose that S is a Hilbert space. For all t∈[0,1], Jt∈C2(S,R) is a functional satisfying J′t and ∂tJt are locally continuous. If J0 and J1 satisfy (C), and there exist a∈R and δ>0 such that
Jt(u)≤a⇒(1+‖u‖)‖Jt(u)‖≥δ,t∈[0,1], |
then
Cq(J0,∞)=Cq(J1,∞),q∈Z. | (2.5) |
In particular, if there is R>0 such that
inft∈[0,1],‖u‖>R(1+‖u‖)‖J′t(u)‖>0, | (2.6) |
and
inft∈[0,1],‖u‖≤R(1+‖u‖)‖J′t(u)‖>−∞, | (2.7) |
then (2.5) is satisfied.
Proposition 2.4. [16] Let S be a real Hilbert space. J∈C1(S,R) satisfies
J(u)=12⟨Tu,u⟩+Q(u), | (2.8) |
where T:S→S is a self-adjoint linear operator, and 0 is the isolated spectral point of T. Suppose Q∈C1(S,R) satisfies
lim‖u‖→∞‖Q′(u)‖‖u‖=0. | (2.9) |
Let W+(W−) be an invariant subspace corresponding to the positive (negative) of spectrum of T, which has a bounded inverse. Assume that k=dimW− is finite, then J satisfies (PS) and
Cq(J,∞)≅δq,kZ,q∈Z. |
For the purpose to obtain the critical group at origin, the following proposition about local linking is important.
Proposition 2.5. [26] Let 0 be an isolated critical point of J with Morse index μ0 and nullity ν0. Assume that J has a local linking at 0 subject to S=S−⊕S+, m=dimS−<∞, namely, there exists ρ>0 such that
J(u)≤0,u∈S−,‖u‖≤ρ,J(u)≥0,u∈S+,‖u‖≤ρ. |
Then if m=μ0 or m=μ0+ν0, we get
Cq(J,0)≅δq,mZ,q∈Z. |
In this section, we state our main results and provide detailed proofs. For convenience, we give some notations subject to our main results.
α∞:=f′((i,j),∞)=lim|u|→∞f((i,j),u)u∈R,(i,j)∈Ω, | (3.1) |
and
α0:=f′((i,j),0)=lim|u|→0f((i,j),u)u∈R,(i,j)∈Ω. | (3.2) |
Moreover, for all (i,j)∈Ω, we make the following assumptions:
(I1) α0<λ1;
(I2) α∞>λT1T2;
(I3) λp<α0<λp+1, p∈Z(1,T1T2−1);
(I4) α0>λT1T2;
(I5) α∞<λ1;
(I6) λp<α∞<λp+1, p∈Z(1,T1T2−1);
(F±∞) For ∀(i,j)∈Ω, there exists k∈Z(2,T1T2−1) such that
limu→+∞(f((i,j),u)−λku)=±∞,limu→−∞(f((i,j),u)−λku)=∓∞. |
We are now in a position to state our main results as the following:
Theorem 3.1. If one of the following conditions is satisfied:
(˙1) (I1), (I2) or (I6) (˙1˙1) (I3), (I2) or (I5) (˙1˙1˙1) (I4), (I5) or (I6),
then (1.1) and (1.2) possesses at least two nontrivial solutions.
Theorem 3.2. Suppose that α∞=λk. If T1T2 is odd, then (1.1) and (1.2) has at least two nontrivial solutions provided one of the following conditions is fulfilled:
(˙1) (I1) (˙1˙1) (I4) (˙1˙1˙1) (I3) with p≠T1T22.
Theorem 3.3. Let (F+∞)[(F−∞)] hold and α∞=λk. Then (1.1) and (1.2) admits at least two nontrivial solutions provided one of the following conditions is met:
(˙1) (I1) (˙1˙1) (I4) (˙1˙1˙1) (I3) with p≠k[p≠k−1].
Given the following sign conditions:
(F+0) there exist m∈Z(1,T1T2−1) and δ>0 such that
2F((i,j),u)−λmu2>0,|u(i,j)|≤δ,(i,j)∈Ω, |
(F−0) there exist m∈Z(2,T1T2) and δ>0 such that
2F((i,j),u)−λmu2<0,|u(i,j)|≤δ,(i,j)∈Ω. |
Then we have
Theorem 3.4. Assume that (F+0)[(F−0)] holds and α0=λm. Then (1.1) and (1.2) possesses at least two nontrivial solutions if one of the following conditions is fulfilled:
(˙1) (I5) (˙1˙1) (I2) (˙1˙1˙1) (I6) with p≠m[p≠m−1].
Theorem 3.5. Let α∞=λk and α0=λm. If either
(˙1) (F−0), (F+∞) and m+1≠k, or
(˙1˙1) (F+0), (F−∞) and k+1≠m,
then (1.1) and (1.2) admits at least two nontrivial solutions.
To calculate the critical group at infinity under conditions of Theorems 3.1 and 3.4, we have the following lemma.
Lemma 3.1. If (I5) or (I2) or (I6) is satisfied, then Cq(J,∞)≅δq,kZ, q∈Z.
Proof. Let αs be a constant for s∈Z(1,T1T2) and denote
lim|u|→∞f((i,j),u)u=αs,(i,j)∈Ω. | (3.3) |
Set
J(u)=12‖u‖2−T1∑i=1T2∑j=1F((i,j),u(i,j))=12⟨Tu,u⟩+Q(u), |
where Q(u)=12⟨Λu,u⟩−T1∑i=1T2∑j=1F((i,j),u(i,j)). Then Q′(u) is compact and T:S→S is a self-adjoint bounded linear operator such that 0 is not in the spectrum of T. Thus T±=T|W± has bounded inverse on W±. Moreover, k=dimW−=0 if (I5) is satisfied, k=T1T2 if (I2) is satisfied and k=p if (I6) is satisfied. Together with (3.3), it yields that (2.9) is fulfilled. As a matter of fact, using (3.3), we obtain
lim|u|→∞f((i,j),u)−αsuu:=lim|u|→∞˜f((i,j),u)u=0,∀(i,j)∈Ω. |
Thus for any ε>0, there exists R>0 such that
|˜f((i,j),u)|<√λ1ε√2|u(i,j)|,(i,j)∈Ω,|u(i,j)|>R. | (3.4) |
Thanks to the continuity of ˜f((i,j),u), there exists some Mε>0 such that
|˜f((i,j),u)|≤Mε:=max(i,j)∈Ω,|u(i,j)|≤R{|˜f((i,j),u)|}. | (3.5) |
If ‖u‖>max{√T1T2λT1T2R,√2T1T2Mεε}, (2.3) implies that |u(i,j)|>R for any (i,j)∈Ω. Consequently,
T1∑i=1T2∑j=1˜f2((i,j),u(i,j))=∑|u(i,j)|≤R˜f2((i,j),u(i,j))+∑|u(i,j)|>R˜f2((i,j),u(i,j))<T1T2M2ε+ε2λ12‖u‖22≤T1T2M2ε+ε22‖u‖2≤ε2‖u‖2, |
which ensures that (2.9) is valid. By Proposition 2.4, we conclude that Cq(J,∞)≅δq,kZ, q∈Z.
In the following Lemmas 3.2 and 3.3, we calculate critical groups at both infinity and origin to make preparations for the proof of Theorem 3.3.
Lemma 3.2. Assume α∞=λk. Then
(1) Cq(J,∞)≅δq,k−1Z, q∈Z if (F−∞) holds;
(2) Cq(−J,∞)≅δq,T1T2−kZ, q∈Z if (F+∞) is valid.
Proof. We prove the case (1) at length. The proof of (2) is similar and is omitted for brevity.
For t∈[0,1], consider
ˆJ(u)=‖u+‖2+‖u0‖2−‖u−‖2,u+∈W+,u−∈W−,u0∈W0. |
Define Jt:S→R as
Jt(u)=(1−t)J(u)+tˆJ(u),u∈S. | (3.6) |
In order to apply Proposition 2.3, we need to prove that there exist a∈R and δ>0 such that
Jt(u)≤a⇒‖J′t(u)‖≥δ,t∈[0,1]. | (3.7) |
Otherwise, there exist {un}⊆S, tn∈[0,1] such that
Jtn(un)≤−n,‖J′tn(un)‖<1n, |
that is,
−Jtn(un)→+∞,J′tn(un)→0. | (3.8) |
Note
|−Jtn(un)|=|(tn−1)J(un)−tnˆJ(un)|≤|(tn−1)J(un)|+|tnˆJ(un)|≤|tnJ(un)|+|J(un)|+|tnˆJ(un)|≤2|J(un)|+|ˆJ(un)|≤2|J(un)|+‖un‖2. |
If {un} is bounded, for J is continuous, then there exists M>0 such that ‖J(un)‖≤M‖un‖, which leads to
‖−Jtn(un)‖≤(2M+1)‖un‖. | (3.9) |
Obviously, (3.9) is inconsistent with (3.8). Thus, ‖un‖→∞.
Define a bilinear function
σ(u,v)=λkT1∑i=1T2∑j=1(u(i,j),v(i,j)),u,v∈S. |
Since |σ(u,v)|≤λkλ1‖u‖‖v‖, there exists an unique continuous linear operator K:S→S such that
⟨Ku,v⟩=λkT1∑i=1T2∑j=1(u(i,j),v(i,j)). |
Let g((i,j),u)=f((i,j),u)−λku, where G((i,j),u)=∫u0g((i,j),τ)dτ=F((i,j),u)−12λku2. Then for any u, v in S,
⟨J′(u),v⟩=⟨u,v⟩−λk⟨u,v⟩−T1∑i=1T2∑j=1g((i,j),u(i,j))v(i,j)=⟨(I−K)u,v⟩−T1∑i=1T2∑j=1g((i,j),u(i,j))v(i,j), | (3.10) |
and ∂tJt=−J(u)+ˆJ(u) is locally continuous. Denoted by ˆu=u++u0−u−, then (3.10) can be rewritten as
⟨J′(u),ˆu⟩=⟨(I−K)u,ˆu⟩−T1∑i=1T2∑j=1g((i,j),u(i,j))ˆu(i,j). | (3.11) |
By the definition of ˆu, we have
⟨(I−K)u,ˆu⟩=⟨(I−K)u++u0+u−,u++u0−u−⟩=‖u+‖2−λk‖u+‖22+‖u0‖2−λk‖u0‖22−‖u−‖2+λk‖u−‖22≥(1−λkλk+1)‖u+‖2+(λkλk−1−1)‖u−‖2. |
In view of α∞=λk and (F−∞), there exist 0<ε<λkλk−1−1, R1>0 such that
−λ1⋅ε<g((i,j),u)u≤0,|u(i,j)|>R1,(i,j)∈Ω. |
Moreover,
g((i,j),u)ˆu=g((i,j),u)uuˆu=g((i,j),u)u[(u++u0)2−(u−)2]<λ1ε(u−)2. |
Consequently,
T1∑i=1T2∑j=1g((i,j),u(i,j)ˆu(i,j)=∑|u(i,j)|>R1g((i,j),u(i,j)ˆu(i,j)+∑|u(i,j)|≤R1g((i,j),u(i,j)ˆu(i,j)<λ1ε∑|u(i,j)|>R1(u−(i,j))2+C1∑|u(i,j)|≤R1|ˆu(i,j)|≤λ1εT1∑i=1T2∑j=1(u−(i,j))2+C1T1∑i=1T2∑j=1|ˆu(i,j)|≤λ1ε‖u−‖22+C1‖ˆu‖2=λ1ε‖u−‖22+C1‖u‖2≤ε‖u−‖2+C1√λ1‖u‖, |
where C1:=max(i,j)∈Ω,|u(i,j)|≤R1{|g((i,j),u(i,j))|}. Denoted by C2:=C1√λ1 and C3:=min{1−λkλk+1,λkλk−1−1−ε}, from (3.11), we obtain
⟨J′(u),ˆu⟩≥(1−λkλk+1)‖u+‖2+(λkλk−1−1−ε)‖u−‖2−C2‖u‖≥C3(‖u+‖2+‖u−‖2)−C2‖u‖. |
Define P−:S→W− as P−u=u−. Then
ˆJ(u)=⟨u,u⟩−2⟨P−u,u⟩=⟨(I−2P−)u,u⟩,ˆJ′(u)=2(I−2P−)u,ˆJ″(u)=2(I−2P−). |
In the following, our aim is to show tn→0 as n→∞. Or else, there exists t0>0 such that tn≥t0 and −C2(1−tn)≥−C2(1−t0). Define C4:=C2(1−t0), since J′tn(un)→0 as ‖un‖→∞, there exists some R2>0 such that
‖un‖≥⟨J′tn(un),ˆun⟩=(1−tn)⟨J′(un),ˆun⟩+2tn‖un‖2≥(1−tn)C3(‖u+‖2+‖u−‖2)−C4‖un‖+2tn‖un‖2as|u(i,j)|>R2, |
which implies
(1+C4)‖un‖≥(1−tn)C3(‖u+‖2+‖u−‖2)+2tn‖un‖2≥2tn‖un‖2. |
Making use of (3.11), we obtain tn→0 and
(1+C4)‖un‖≥C3(‖u+n‖2+‖u−n‖2). |
Therefore,
‖u+n‖2‖un‖+‖u−n‖2‖un‖≤1+C4C3, |
which means both {‖u+n‖2‖un‖} and {‖u−n‖2‖un‖} are bounded, and
‖u+n‖2‖un‖2+‖u−n‖2‖un‖2≤1+C4C31‖un‖. | (3.12) |
Recall ‖un‖→∞, (3.12) implies that
‖u+n‖‖un‖→0and‖u−n‖‖un‖→0. |
Joint with ‖un‖2=‖u+n‖2+‖u0n‖2+‖u−n‖2, we obtain ‖u0n‖‖un‖→1. Therefore, ‖u+n‖2+‖u0n‖2−‖u−n‖2>0, namely, ˆJ(un)>0.
Since
J(un)=12‖un‖2−T1∑i=1T2∑j=1F((i,j),u(i,j))=12⟨(I−K)un,un⟩−T1∑i=1T2∑j=1G((i,j),u(i,j))≥12[(1−λkλk+1)‖u+n‖2+(λkλk−1−1)‖u−n‖2]−T1∑i=1T2∑j=1G((i,j),u(i,j))≥12(λkλk−1−1)‖u−n‖2−T1∑i=1T2∑j=1G((i,j),u(i,j)), |
then
1‖un‖J(un)≥12(λkλk−1−1)‖u−n‖2‖un‖−T1∑i=1T2∑j=11‖un‖G((i,j),u(i,j))≥−C5−T1∑i=1T2∑j=11‖un‖G((i,j),u(i,j)), | (3.13) |
where C5:=12(λkλk−1−1)1+C4C3. Denote vn=un‖un‖, then ‖vn‖=1. Hence up to a convergent subsequence, without loss of generality, we set the subsequence to be the subsequence, which means that there exists some v∈S satisfying ‖v‖=1 such that vn→v as n→∞.
Setting
Θ:={(i,j)|(i,j)∈Ω,v(i,j)≠0}, |
then Θ≠∅. If (i,j)∈Θ, then un(i,j)=vn(i,j)⋅‖un‖→∞ and lim|u|→∞−G((i,j),u)|u(i,j)|=+∞. Therefore, for any M1>0, there exists N2>0 such that −G((i,j),u)|u(i,j)|>M1 as n>N2. If (i,j)∉Θ, then vn(i,j)→0. Since ‖un‖→∞, there exist C6, N3>0 such that −G((i,j),u)‖un‖≥−C6. Consequently,
limn→∞T1∑i=1T2∑j=1−G((i,j),un(i,j))‖un‖=+∞. |
Combining with (3.13), we can deduce that 1‖un‖J(un)→+∞. Further,
Jtn(un)=(1−tn)J(un)+tnˆJ(un)≥(1−tn)J(un)≥‖un‖2(1‖un‖J(un))→+∞, |
which is a contradiction. Thus {Jt:t∈[0,1]} satisfies (PS), that is, J=J0 and J1 satisfy (PS). By Proposition 2.3, we have
Cq(J,∞)≅Cq(J0,∞)≅Cq(J1,∞). | (3.14) |
If ˆJ′(u)=J′1(u)=0, then u++u0=u−, namely u=2u−. Therefore, u=0 is the only critical point of J1 such that
Cq(J1,∞)=Cq(J1,0). | (3.15) |
Let J″1(0)u=0, it is easy to compute that u=0, which means that u=0 is a nondegenerate critical point of J1 and its corresponding Morse index μ0=dimW−=k−1. Finally, combining (3.14) with (3.15), we achieve Cq(J,∞)≅δq,k−1Z, q∈Z. And this completes the proof of Lemma 3.2.
Lemma 3.3. Assume α∞=λk and (F−∞) holds. Then
(1) Cq(J,0)≅δq,0 if (I1) is satisfied;
(2) Cq(J,0)≅δq,T1T2 if (I4) is satisfied;
(3) Cq(J,0)≅δq,p if (I3) is satisfied, where p≠k−1.
Proof. In case (1), u=0 is a local minimizer of J and Cq(J,0)≅δq,0Z. In case (2), combing u=0 is a local maximum of J with the Morse index on u=0 is μ0=T1T2, it follows that Cq(J,0)≅δq,T1T2Z. In case (3), μ0=p≠k−1, which means that Cq(J,0)≅δq,pZ.
To prove Theorem 3.4, the following lemma on local linking is needed.
Lemma 3.4. Let α0=λm and (F+0) (or (F−0)) hold. Then J has a local linking at 0 with respect to
S=S−⊕S+, |
where S−=span{ϕ1,⋯,ϕm} (or S−=span{ϕ1,⋯,ϕm−1}).
Proof. In view of (F+0), there exists ˉδ>0 such that
F((i,j),u)≥12λmu2,|u(i,j)|≤ˉδ,(i,j)∈Ω. |
For u∈S− with |u(i,j)|≤ˉδ, there has
J(u)=12‖u‖2−T1∑i=1T2∑j=1F((i,j),u(i,j))≤12‖u‖2−12λm‖u‖22=0. | (3.16) |
Since α0=λm, we have
limu→02F((i,j),u)u2=limu→0f((i,j),u)u=λm. |
Then for any ε>0, there exists ˜δ>0 such that |2F((i,j),u)u2−λm|<ε as 0<|u(i,j)|<˜δ, that is, λm−ε<2F((i,j),u)u2<λm+ε. Thus,
12(λm−ε)u2<F((i,j),u)<12(λm+ε)u2,0<|u(i,j)|<˜δ,(i,j)∈Ω. |
For u∈S− with 0<|u(i,j)|<˜δ, we have
J(u)≥12‖u‖2−12(λm+ε)‖u‖22≥12(1−λm+ελm+1)‖u‖2. | (3.17) |
Choose δ=min{ˉδ,˜δ} and 0<ε<λm+1−λm. Denote ρ=δ√T1T2λT1T2. Then (3.16) and (3.17) indicate that
J(u)≤0,u∈S−,‖u‖≤ρ,J(u)≥0,u∈S+,‖u‖≤ρ. |
Moreover, J(0)=0 is obvious. Consequently, J has a local linking at 0. And the proof is achieved.
As for Theorem 3.5, we consider the critical groups at infinity with respect to −J. In the same manner as Lemma 3.3, we have
Lemma 3.5. Let (F+∞) hold and α∞=λk. Then
(1) Cq(−J,0)≅δq,T1T2, if (I1) is satisfied;
(2) Cq(−J,0)≅δq,0, if (I4) is satisfied;
(3) Cq(−J,0)≅δq,T1T2−p, if (I3) is satisfied and p≠k.
With above preparations, it is time for us to provide detailed proofs of Theorems 3.1–3.5.
Proof of Theorem 3.1 Since all three cases of Theorem 3.1 can be proved similarly, here we only prove the case (i) at length for brevity.
On account of (I1), u=0 is a local minimizer of J and its Morse index μ0=0 and zero nullity ν0=0 and
Cq(J,0)≅δq,0Z,q∈Z. |
By Lemma 3.1, we get
Cq(J,∞)≅δq,kZ,q∈Z. |
Moreover, the process of proof of Lemma 3.1 indicates that J satisfies (PS). By Proposition 2.2, there exists u1∈κ such that u1≠0 and Ck(J,u1)≆0. Then u1 is a non-zero critical point of J and
J″(u1)=I−diag{f′((1,1),u1(1,1)),⋯,f′((T1,T2),u1(T1,T2))}. |
Note that the rank of J″(u1) is greater than T1T2−1, which implies ν(u1)=dimker(J″(u1))≤1 and Cq(J,u1)≅δq,kZ, q∈Z. Assume that κ={0,u1}, then the Morse equality is
(−1)0+(−1)k=(−1)k, |
which is impossible. Hence, J has at least another nontrivial critical point, namely, (1.1) and (1.2) possesses at least two nontrivial solutions. And the proof of Theorem 3.1 is completed.
Proof of Theorem 3.2 Recall G((i,j),u)=F((i,j),u)−12λku2, there has
J(u)=12⟨(I−K)u,u⟩−G(u):=12⟨Bu,u⟩−G(u). |
Then B:S→S is a self-adjoint bounded linear operator such that 0 is not in the spectrum of B and B′(u) is compact. Write B±=B|W±, then B± has a bounded inverse on W±. Let k=dimW−=T1T22, then α∞=λk guarantees that (2.9) is valid. By Proposition 2.4, we obtain
Cq(J,∞)≅δq,T1T22Z,q∈Z, |
and J satisfies (PS). Use (I1) once more, we have u=0 is a local minimizer of J and
Cq(J,0)≅δq,0Z,q∈Z. |
According to Proposition 2.2 and ν(u2)≤1, we draw a conclusion that there exists u2∈κ with u2≠0 such that
CT1T22(J,u2)≆0. |
Assume κ={0,u2}, then the Morse equality expresses as
(−1)0+(−1)T1T22=(−1)T1T22, |
which is a contradiction. Therefore, J has at least another nontrivial critical point, (1.1) and (1.2) possesses at least two nontrivial solutions. And this completes the proof of Theorem 3.2.
Proof of Theorem 3.3 By Lemma 3.2, Cq(J,∞)=δq,k−1Z, q∈Z and J satisfies (PS). Then Proposition 2.2 indicates there exists u3∈κ such that Ck−1(J,u3)≆0, which means that u3 is a non-zero critical point of J. Since
J″(u3)=I−diag{f′((1,1),u3(1,1)),⋯,f′((T1,T2),u3(T1,T2))}, |
and the rank of J″(u3) is greater than T1T2−1. Then ν(u3)=dimker(J″(u3))≤1. If q∉[μ(u3),μ(u3)+ν(u3)] and Cq(J,u3)=0, then either k−1=μ(u3)+ν(u3) or k−1=μ(u3). Thus, Cq(J,u3)≅δq,k−1Z. If κ={0,u3}, by the Morse equality, we have
(−1)∗+(−1)k−1=(−1)k−1, | (3.18) |
where ∗=0, T1T2 or p corresponds to (I1), (I4) or (I3), respectively. Meanwhile, it is impossible for (3.18) to be true. Therefore, J at least has another non-zero critical point, and (1.1)–(1.2) possesses at least two nontrivial solutions and the proof is achieved.
Proof of Theorem 3.4 Lemma 3.1 yields Cq(J,∞)≅δq,kZ, q∈Z, which means that there exists u4∈κ such that Ck(J,∞)≆0. Since
J″(u4)=I−diag{f′((1,1),u4(1,1)),⋯,f′((T1,T2),u4(T1,T2))}, |
and the rank of J″(u4) is greater than T1T2−1, then ν(u4)=dimker(J″(u4))≤1. If q∉[μ(u4),μ(u4)+ν(u4)] and Cq(J,u4)=0, then either k=μ(u4) or k=μ(u4)+ν(u4), which implies that Cq(J,u4)≅δq,kZ. Note that Lemma 3.4 shows that J has a local linking at 0 and dimS−=m. Further, 0 is the isolated critical point of J and J″(0) is a Fredholm operator and Cm(J,0)≆0, then Cq(J,0)≅δq,mZ. If κ={0,u4}, the Morse equality is in the form as
(−1)m+(−1)k=(−1)k. | (3.19) |
However, (3.19) is impossible. Consequently, J at least has another non-zero critical point, (1.1) and (1.2) possesses at least two nontrivial solutions. The proof of Theorem 3.4 is finished.
Proof of Theorem 3.5 Let α∞=λk and (F+∞) be satisfied, Lemma 3.2 gives
Cq(−J,∞)≅δq,T1T2−kZ,q∈Z. |
Furthermore, (F−0) and α0=λm lead to
Cq(−J,0)≅δq,T1T2−(m+1)Z,q∈Z. |
Notice that m+1≠k and nondegenerate critical points are isolated, then there exists some critical point u5∈κ with u5≠0 such that
CT1T2−k(−J,u5)≆0, |
then
Cq(−J,u5)≅δq,T1T2−kZ. |
If κ={0,u5}, then there holds the Morse equality
(−1)T1T2−(m+1)+(−1)T1T2−k=(−1)T1T2−k, |
which is impossible. Then −J at least has another non-zero critical point, (1.1) and (1.2) possesses at least two nontrivial solutions. The proof of Theorem 3.5 is completed.
Finally, we present five examples to verify the feasibility of our results.
Example 4.1. Take T1=3, T2=2, consider
Δ21u(i−1,j)+Δ22u(i,j−1)+(λ12−2λT1T2)u1+u2+2λT1T2u=0, | (4.1) |
with boundary value conditions (1.2).
Because f((i,j),u)=(λ12−2λT1T2)u1+u2+2λT1T2u, it follows that f((i,j),0)=0 and
f′((i,j),u)=(6λT1T2−λ12)u2+2λT1T2u4+λ12(1+u2)2. |
Then f′((i,j),0)=λ12<λ1 and f′((i,j),∞)=2λT1T2>λT1T2, which means that (I1) and (I2) are satisfied. Consequently, Theorem 3.1 guarantees that (4.1) and (1.2) admits at least two nontrivial solutions.
Example 4.2. Take T1=3, T2=5, consider
Δ21u(i−1,j)+Δ22u(i,j−1)+(λ12−λk)u1+u2+λku=0, | (4.2) |
with boundary value conditions (1.2).
Clear, T1T2=15 is odd and
f((i,j),u)=(λ12−λk)u1+u2+λku. |
It is easy to calculate that f((i,j),0)=0 and
α∞=lim|u|→∞f((i,j),u)u=lim|u|→∞[λ12−λk1+u2+λk]=λk. |
Moreover, direct computation gives
f′((i,j),u)=(3λk−λ12)u2+λku4+λ12(1+u2)2, |
which indicates f′((i,j),0)=λ12<λ1. As a result, (I1) is valid and Theorem 3.2 ensures that (4.2) and (1.2) admits at least two nontrivial solutions.
Example 4.3. Take T1=3, T2=2, r=eλ12−λk>0. Consider
Δ21u(i−1,j)+Δ22u(i,j−1)+(λ12−λk)sinuu+1+λku+u13ln(r+|u|3)=0, | (4.3) |
with boundary value conditions (1.2).
Since f((i,j),u)=(λ12−λk)sinuu+1+λku+u13ln(r+|u|3), it is easy to get that f((i,j),0)=0 and
α∞=lim|u|→∞f((i,j),u)u=lim|u|→∞[(λ12−λk)sinuu(u+1)+λk+ln(r+|u|3)u23]=λk. |
Further,
f′((i,j),u)=λk+cosu(λ12−λk)(u+1)−sinu(λ12−λk)(u+1)2+u−23ln(r+|u|3)+3u73r+|u|3. |
Thus f′((i,j),0)=λ12<λ1 and (I1) is satisfied.
At last, by direct computation, we obtain
limu→+∞(f((i,j),u)−λku)=limu→+∞((λ12−λk)sinuu+1+u13ln(r+|u|3))=+∞,limu→−∞(f((i,j),u)−λku)=limu→−∞((λ12−λk)sinuu+1+u13ln(r+|u|3))=−∞, |
which means that (F+∞) is met.
Therefore, all conditions of Theorem 3.3 are fulfilled and (4.3) and (1.2) admits at least two nontrivial solutions.
Example 4.4. Take T1=3, T2=2. Consider
Δ21u(i−1,j)+Δ22u(i,j−1)+2(λm−λp+λp+12)u2−u2+λp+λp+12u=0, | (4.4) |
with boundary value conditions (1.2).
Owe to f((i,j),u)=2(λm−λp+λp+12)u2−u2+λp+λp+12u, it follows that f((i,j),0)=0 and
F((i,j),u)=(λp+λp+12−λm)ln(2−u2)+λp+λp+14u2. |
Then
f′((i,j),u)=2(λm−λp+λp+12)(2+u2)(2−u2)2+λp+λp+12, |
and
α∞=lim|u|→0f((i,j),u)u=λm. |
Additionally, λp<f′((i,j),∞)=λp+λp+12<λp+1, which implies that (I6) is met. In the following, we check (F+0). Write
A=(4−10−100−14−10−100−1400−1−1004−100−10−14−100−10−14), |
then A is positive-define and the corresponding eigenvalues are
λ1=3−√2,λ2=3,λ3=5−√2,λ4=3+√2,λ5=5,λ6=5+√2. |
Take m=1, p=3, then there exists δ>0 such that 2F((i,j),u)−λmu2>0 when |u(i,j)|≤δ. In fact, for any (i,j)∈Z(1,3)×Z(1,2), we can choose δ=1>0, then 0<|u(i,j)|2≤1 for 0<|u(i,j)|≤1, which means that
(√2+1)ln(2−u2)+(√2−1)u2>0. |
Thus (F+0) is fulfilled. Consequently, Theorem 3.4 ensures that (4.4) and (1.2) possesses at least two nontrivial solutions.
More clearly, using Matlab, we find that problem (4.4) and (1.2) has 63 solutions including 1 trivial solution and 62 nontrivial solutions. Here we list a few: (-2.1408, 1.8608, -2.1408, 2.1408, -1.8608, 2.1408), (2.1408, -1.8608, 2.1408, -2.1408, 1.8608, -2.1408), (−8.3211×10−9, −1.1767×10−8, −8.3211×10−9, −8.3211×10−9, −1.1767×10−8, −8.3211×10−9), (8.3211×10−9, 1.1767×10−8, 8.3211×10−9, 8.3211×10−9, 1.1767×10−8, 8.3211×10−9).
Example 4.5. Take T1=3, T2=2. Consider
Δ21u(i−1,j)+Δ22u(i,j−1)+(λk−λm)u31+u2+λmu+u13ln(1+|u|3)=0, | (4.5) |
with boundary value conditions (1.2).
From (4.5), we find f((i,j),u)=(λk−λm)u31+u2+λmu+u13ln(1+|u|3), then
F((i,j),u)=12λmu2+λk−λm2(u2−ln(1+u2))+uln(1+u)−u+ln(1+u)+C, |
take C=−1 and δ=e−1>0, then when m>k and 0<|u(i,j)|<δ,
F((i,j),u)−12λmu2=λk−λm2(u2−ln(1+u2))+uln(1+u)−u+ln(1+u)+C=(u+1)(ln(u+1)−1)+λk−λm2(u2−ln(1+u2))=(u+1)(ln(u+1)−lne)+λk−λm2(u2−ln(1+u2))<0, |
which means that (F−0) is fulfilled.
On the other side, it is easy to get f((i,j),0)=0 and
α∞=lim|u|→∞f((i,j),u)u=lim|u|→∞[(λk−λm)u21+u2+λm+ln(1+|u|3)u23]=λk,α0=lim|u|→0f((i,j),u)u=lim|u|→0[(λk−λm)u21+u2+λm+ln(1+|u|3)u23]=λm. |
Furthermore, there hold
limu→+∞(f((i,j),u)−λku)=limu→+∞(u13ln(1+|u|3)+(λm−λk)u+(λk−λm)u31+u2)=+∞,limu→−∞(f((i,j),u)−λku)=limu→−∞(u13ln(1+|u|3)+(λm−λk)u+(λk−λm)u31+u2)=−∞, |
which guarantees that (F+∞) is satisfied.
Therefore, all conditions of Theorem 3.5 are valid and (4.5) and (1.2) has at least two nontrivial solutions.
This paper is supported by the National Natural Science Foundation of China (NSFC) (No. 11971126).
All authors declare no conflicts of interest in this paper.
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