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Results on multiple nontrivial solutions to partial difference equations

  • In this paper, we consider the existence and multiplicity of nontrivial solutions to second order partial difference equation with Dirichlet boundary conditions by Morse theory. Given suitable conditions, we establish multiple results that the problem admits at least two nontrivial solutions. Moreover, we provide five examples to illustrate applications of our theorems.

    Citation: Huan Zhang, Yin Zhou, Yuhua Long. Results on multiple nontrivial solutions to partial difference equations[J]. AIMS Mathematics, 2023, 8(3): 5413-5431. doi: 10.3934/math.2023272

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  • In this paper, we consider the existence and multiplicity of nontrivial solutions to second order partial difference equation with Dirichlet boundary conditions by Morse theory. Given suitable conditions, we establish multiple results that the problem admits at least two nontrivial solutions. Moreover, we provide five examples to illustrate applications of our theorems.



    Let N and Z be natural number set and integer set, respectively. For integers a, b, define the discrete interval Z(a,b):={a,a+1,,b} for ab. Write Ω:=Z(1,T1)×Z(1,T2), where T1, T22 are given integers. We consider the existence and multiplicity of nontrivial solutions to the following nonlinear second order partial difference equation

    Δ21u(i1,j)+Δ22u(i,j1)=f((i,j),u(i,j)),(i,j)Ω, (1.1)

    with Dirichlet boundary conditions

    u(i,0)=u(i,T2+1)=0iZ(1,T1),u(0,j)=u(T1+1,j)=0jZ(1,T2), (1.2)

    where Δ1, Δ2 are the forward difference operators defined by Δ1u(i,j)=u(i+1,j)u(i,j) and Δ2u(i,j)=u(i,j+1)u(i,j). Δ2u(i,j)=Δ(Δu(i,j)). Here f((i,j),)C1(Ω×R,R) satisfies f((i,j),0)=0, which means that (1.1) and (1.2) possesses a trivial solution u=0. Meanwhile, We are interested in nontrivial solutions and intend to seek nontrivial solutions to (1.1) and (1.2).

    Due to wide applications in many fields such as computer science, economics and mechanical engineering, the theory of nonlinear discrete problems has been widely studied and many results are obtained [1,2,3,4,5,6]. With the rapid development of modern computer technology, more and more mathematical models involve functions with two or more variables. Partial difference equations, involving two or more discrete variables, are regarded as discrete analogs of partial differential equations. Therefore, the study of difference equations has gradually shifted to the study of partial difference equations and attracted much attentions, for example, [7,8,9,10,11,12,13,14].

    As known to all, with the rapid development of critical point theory, the Morse theory becomes a more and more powerful tool to study the multiplicity and existence of nontrivial solutions to both differential equations and difference equations having variational structure [15,16,17,18]. Very recently, [19,20,21] studied partial difference equations via the Morse theory and obtained rich results on the existence and multiplicity of nontrivial solutions. Thus those reasons are encouraging us to consider the existence and multiplicity of nontrivial solutions to (1.1) and (1.2) by the Morse theory.

    We organize this paper as follows. In Section 2, the variational structure and the corresponding functional are established. Moreover, we also recall some related definitions and propositions, which are necessary to our main results. Section 3 states our main results and their detailed proofs. Finally, five examples and numerical simulations are provided to demonstrate applications of our main results in Section 4.

    Let E be a T1T2-dimensional Euclidean space equipped with the usual inner product (,) and norm ||. Let

    S={u:Z(0,T1+1)×Z(0,T2+1)Rsuch thatu(i,0)=u(i,T2+1)=0,iZ(0,T1+1)andu(0,j)=u(T1+1,j)=0,jZ(0,T2+1)}.

    Define the inner product , on S as

    u,v=T1+1i=1T2j=1Δ1u(i1,j)Δ1v(i1,j)+T1i=1T2+1j=1Δ2u(i,j1)Δ2v(i,j1),u,vS.

    Then the induced norm is

    u=u,u=(T1+1i=1T2j=1|Δ1u(i1,j)|2+T1i=1T2+1j=1|Δ2u(i,j1)|2)12,uS.

    Thus S is a Hilbert space and isomorphic to E. Here and hereafter, we take uS an extension of uE if necessary.

    Consider the functional J:SR as

    J(u)=12T1+1i=1T2j=1|Δ1u(i1,j)|2+12T1i=1T2+1j=1|Δ2u(i,j1)|2T1i=1T2j=1F((i,j),u(i,j))=12u2T1i=1T2j=1F((i,j),u(i,j)),uS, (2.1)

    where F((i,j),u)=u0f((i,j),τ)dτ for each (i,j)Ω. Notice that f((i,j),u) is continuously differentiable with respect to u. Therefore, the expression of J means that JC2(S,R) and solutions of the problems (1.1) and (1.2) are precisely critical points of J(u). Moreover, for any u, vS, applying Dirichlet boundary conditions, direct computations gives that the Fréchet derivative of J(u) is

    J(u),v=T1+1i=1T2j=1Δ1u(i1,j)Δ1v(i1,j)+T1i=1T2+1j=1Δ2u(i,j1)Δ2v(i,j1)T1i=1T2j=1f((i,j),u(i,j))v(i,j)=T1i=1T2j=1[Δ21u(i1,j)+Δ22u(i,j1)+f((i,j),u(i,j))]v(i,j). (2.2)

    Let Ξ be the discrete Laplacian, which is defined by Ξu(i,j)=Δ21u(i1,j)+Δ22u(i,j1). Owe to [11], Ξ is invertible and the distinct eigenvalues of Ξ with zero Dirichlet boundary conditions on Ω can be denoted by 0<λ1<λ2λT1T2. Let ϕk=(ϕk(1),ϕk(2),,ϕk(T1T2))tr, k[1,T1T2] be an eigenvector corresponding to the eigenvalue λk. Write

    W=span{ϕ1,,ϕk1},W0=span{ϕk},W+=(WW0).

    Then S can be expressed in the form as

    S=WW0W+.

    For later use, define another norm as

    u2=(T1i=1T2j=1|u(i,j)|2)12,uS.

    Then for any uS, we have

    λ1u22u2λT1T2u22. (2.3)

    In particular, we have

    λk+1u22u2λT1T2u22,uW+,λ1u22u2λk1u22,uW. (2.4)

    Now we recall some basic results on the Morse theory.

    We say that the functional J satisfies the Palais-Smale condition ((PS) in short) if any sequence {un}S, there is a constant M>0 such that |J(un)|M, J(un)0 as n, has a convergent subsequence. From [22,23], if (PS) is satisfied, then both the weaker Cerami condition ((C) for short) and the deformation condition ((D) in short) are also fulfilled.

    Definition 2.1. [16,24] Let u0 be an isolated critical group of J with J(u0)=cR, and U be a neighborhood of u0, the group

    Cq(J,u0):=Hq(JcU,JcUu0),qZ,

    is called the q-th critical group of J at u0. Let κ={uS|J(u)=0}. For all aR each critical point of J is greater than a and JC2(S,R) satisfies (D), the group

    Cq(J,):=Hq(S,Ja),qZ,

    is called the q-th critical group of J at infinity.

    To compute critical groups of J at both an isolated critical point and infinity, the following auxiliary propositions are needed.

    Proposition 2.1. [16,24] Suppose that u0 is an isolated critical point of J with finite Morse index μ(u0) and zero nullity ν(u0). Then

    (Q1) Cq(J,u0)0 for q[μ(u0),μ(u0)+ν(u0)];

    (Q2) Cq(J,u0)δq,u0Z, qZ, if u0 is nondegenerate;

    (Q3) Cq(J,u0)δq,kZ for k=μ(u0) or k=μ(u0)+ν(u0), if Ck(J,u0)0.

    Proposition 2.2. [17] Let JC2(S,R) satisfy (D). We have

    (Q4) if Cq(J,)0 holds for some q, then J possesses a critical point u such that Cq(J,u)0;

    (Q5) if 0 is the isolated critical point of J and Cq(J,)Cq(J,0) holds for some q, then J has a non-zero critical point.

    Proposition 2.3. [25] Suppose that S is a Hilbert space. For all t[0,1], JtC2(S,R) is a functional satisfying Jt and tJt are locally continuous. If J0 and J1 satisfy (C), and there exist aR and δ>0 such that

    Jt(u)a(1+u)Jt(u)δ,t[0,1],

    then

    Cq(J0,)=Cq(J1,),qZ. (2.5)

    In particular, if there is R>0 such that

    inft[0,1],u>R(1+u)Jt(u)>0, (2.6)

    and

    inft[0,1],uR(1+u)Jt(u)>, (2.7)

    then (2.5) is satisfied.

    Proposition 2.4. [16] Let S be a real Hilbert space. JC1(S,R) satisfies

    J(u)=12Tu,u+Q(u), (2.8)

    where T:SS is a self-adjoint linear operator, and 0 is the isolated spectral point of T. Suppose QC1(S,R) satisfies

    limuQ(u)u=0. (2.9)

    Let W+(W) be an invariant subspace corresponding to the positive (negative) of spectrum of T, which has a bounded inverse. Assume that k=dimW is finite, then J satisfies (PS) and

    Cq(J,)δq,kZ,qZ.

    For the purpose to obtain the critical group at origin, the following proposition about local linking is important.

    Proposition 2.5. [26] Let 0 be an isolated critical point of J with Morse index μ0 and nullity ν0. Assume that J has a local linking at 0 subject to S=SS+, m=dimS<, namely, there exists ρ>0 such that

    J(u)0,uS,uρ,J(u)0,uS+,uρ.

    Then if m=μ0 or m=μ0+ν0, we get

    Cq(J,0)δq,mZ,qZ.

    In this section, we state our main results and provide detailed proofs. For convenience, we give some notations subject to our main results.

    α:=f((i,j),)=lim|u|f((i,j),u)uR,(i,j)Ω, (3.1)

    and

    α0:=f((i,j),0)=lim|u|0f((i,j),u)uR,(i,j)Ω. (3.2)

    Moreover, for all (i,j)Ω, we make the following assumptions:

    (I1) α0<λ1;

    (I2) α>λT1T2;

    (I3) λp<α0<λp+1, pZ(1,T1T21);

    (I4) α0>λT1T2;

    (I5) α<λ1;

    (I6) λp<α<λp+1, pZ(1,T1T21);

    (F±) For (i,j)Ω, there exists kZ(2,T1T21) such that

    limu+(f((i,j),u)λku)=±,limu(f((i,j),u)λku)=.

    We are now in a position to state our main results as the following:

    Theorem 3.1. If one of the following conditions is satisfied:

    (˙1) (I1), (I2) or (I6)   (˙1˙1) (I3), (I2) or (I5)    (˙1˙1˙1) (I4), (I5) or (I6),

    then (1.1) and (1.2) possesses at least two nontrivial solutions.

    Theorem 3.2. Suppose that α=λk. If T1T2 is odd, then (1.1) and (1.2) has at least two nontrivial solutions provided one of the following conditions is fulfilled:

    (˙1) (I1)    (˙1˙1) (I4)    (˙1˙1˙1) (I3) with pT1T22.

    Theorem 3.3. Let (F+)[(F)] hold and α=λk. Then (1.1) and (1.2) admits at least two nontrivial solutions provided one of the following conditions is met:

    (˙1) (I1)    (˙1˙1) (I4)    (˙1˙1˙1) (I3) with pk[pk1].

    Given the following sign conditions:

    (F+0) there exist mZ(1,T1T21) and δ>0 such that

    2F((i,j),u)λmu2>0,|u(i,j)|δ,(i,j)Ω,

    (F0) there exist mZ(2,T1T2) and δ>0 such that

    2F((i,j),u)λmu2<0,|u(i,j)|δ,(i,j)Ω.

    Then we have

    Theorem 3.4. Assume that (F+0)[(F0)] holds and α0=λm. Then (1.1) and (1.2) possesses at least two nontrivial solutions if one of the following conditions is fulfilled:

    (˙1) (I5)   (˙1˙1) (I2)    (˙1˙1˙1) (I6) with pm[pm1].

    Theorem 3.5. Let α=λk and α0=λm. If either

    (˙1) (F0), (F+) and m+1k, or

    (˙1˙1) (F+0), (F) and k+1m,

    then (1.1) and (1.2) admits at least two nontrivial solutions.

    To calculate the critical group at infinity under conditions of Theorems 3.1 and 3.4, we have the following lemma.

    Lemma 3.1. If (I5) or (I2) or (I6) is satisfied, then Cq(J,)δq,kZ, qZ.

    Proof. Let αs be a constant for sZ(1,T1T2) and denote

    lim|u|f((i,j),u)u=αs,(i,j)Ω. (3.3)

    Set

    J(u)=12u2T1i=1T2j=1F((i,j),u(i,j))=12Tu,u+Q(u),

    where Q(u)=12Λu,uT1i=1T2j=1F((i,j),u(i,j)). Then Q(u) is compact and T:SS is a self-adjoint bounded linear operator such that 0 is not in the spectrum of T. Thus T±=T|W± has bounded inverse on W±. Moreover, k=dimW=0 if (I5) is satisfied, k=T1T2 if (I2) is satisfied and k=p if (I6) is satisfied. Together with (3.3), it yields that (2.9) is fulfilled. As a matter of fact, using (3.3), we obtain

    lim|u|f((i,j),u)αsuu:=lim|u|˜f((i,j),u)u=0,(i,j)Ω.

    Thus for any ε>0, there exists R>0 such that

    |˜f((i,j),u)|<λ1ε2|u(i,j)|,(i,j)Ω,|u(i,j)|>R. (3.4)

    Thanks to the continuity of ˜f((i,j),u), there exists some Mε>0 such that

    |˜f((i,j),u)|Mε:=max(i,j)Ω,|u(i,j)|R{|˜f((i,j),u)|}. (3.5)

    If u>max{T1T2λT1T2R,2T1T2Mεε}, (2.3) implies that |u(i,j)|>R for any (i,j)Ω. Consequently,

    T1i=1T2j=1˜f2((i,j),u(i,j))=|u(i,j)|R˜f2((i,j),u(i,j))+|u(i,j)|>R˜f2((i,j),u(i,j))<T1T2M2ε+ε2λ12u22T1T2M2ε+ε22u2ε2u2,

    which ensures that (2.9) is valid. By Proposition 2.4, we conclude that Cq(J,)δq,kZ, qZ.

    In the following Lemmas 3.2 and 3.3, we calculate critical groups at both infinity and origin to make preparations for the proof of Theorem 3.3.

    Lemma 3.2. Assume α=λk. Then

    (1) Cq(J,)δq,k1Z, qZ if (F) holds;

    (2) Cq(J,)δq,T1T2kZ, qZ if (F+) is valid.

    Proof. We prove the case (1) at length. The proof of (2) is similar and is omitted for brevity.

    For t[0,1], consider

    ˆJ(u)=u+2+u02u2,u+W+,uW,u0W0.

    Define Jt:SR as

    Jt(u)=(1t)J(u)+tˆJ(u),uS. (3.6)

    In order to apply Proposition 2.3, we need to prove that there exist aR and δ>0 such that

    Jt(u)aJt(u)δ,t[0,1]. (3.7)

    Otherwise, there exist {un}S, tn[0,1] such that

    Jtn(un)n,Jtn(un)<1n,

    that is,

    Jtn(un)+,Jtn(un)0. (3.8)

    Note

    |Jtn(un)|=|(tn1)J(un)tnˆJ(un)||(tn1)J(un)|+|tnˆJ(un)||tnJ(un)|+|J(un)|+|tnˆJ(un)|2|J(un)|+|ˆJ(un)|2|J(un)|+un2.

    If {un} is bounded, for J is continuous, then there exists M>0 such that J(un)Mun, which leads to

    Jtn(un)(2M+1)un. (3.9)

    Obviously, (3.9) is inconsistent with (3.8). Thus, un.

    Define a bilinear function

    σ(u,v)=λkT1i=1T2j=1(u(i,j),v(i,j)),u,vS.

    Since |σ(u,v)|λkλ1uv, there exists an unique continuous linear operator K:SS such that

    Ku,v=λkT1i=1T2j=1(u(i,j),v(i,j)).

    Let g((i,j),u)=f((i,j),u)λku, where G((i,j),u)=u0g((i,j),τ)dτ=F((i,j),u)12λku2. Then for any u, v in S,

    J(u),v=u,vλku,vT1i=1T2j=1g((i,j),u(i,j))v(i,j)=(IK)u,vT1i=1T2j=1g((i,j),u(i,j))v(i,j), (3.10)

    and tJt=J(u)+ˆJ(u) is locally continuous. Denoted by ˆu=u++u0u, then (3.10) can be rewritten as

    J(u),ˆu=(IK)u,ˆuT1i=1T2j=1g((i,j),u(i,j))ˆu(i,j). (3.11)

    By the definition of ˆu, we have

    (IK)u,ˆu=(IK)u++u0+u,u++u0u=u+2λku+22+u02λku022u2+λku22(1λkλk+1)u+2+(λkλk11)u2.

    In view of α=λk and (F), there exist 0<ε<λkλk11, R1>0 such that

    λ1ε<g((i,j),u)u0,|u(i,j)|>R1,(i,j)Ω.

    Moreover,

    g((i,j),u)ˆu=g((i,j),u)uuˆu=g((i,j),u)u[(u++u0)2(u)2]<λ1ε(u)2.

    Consequently,

    T1i=1T2j=1g((i,j),u(i,j)ˆu(i,j)=|u(i,j)|>R1g((i,j),u(i,j)ˆu(i,j)+|u(i,j)|R1g((i,j),u(i,j)ˆu(i,j)<λ1ε|u(i,j)|>R1(u(i,j))2+C1|u(i,j)|R1|ˆu(i,j)|λ1εT1i=1T2j=1(u(i,j))2+C1T1i=1T2j=1|ˆu(i,j)|λ1εu22+C1ˆu2=λ1εu22+C1u2εu2+C1λ1u,

    where C1:=max(i,j)Ω,|u(i,j)|R1{|g((i,j),u(i,j))|}. Denoted by C2:=C1λ1 and C3:=min{1λkλk+1,λkλk11ε}, from (3.11), we obtain

    J(u),ˆu(1λkλk+1)u+2+(λkλk11ε)u2C2uC3(u+2+u2)C2u.

    Define P:SW as Pu=u. Then

    ˆJ(u)=u,u2Pu,u=(I2P)u,u,ˆJ(u)=2(I2P)u,ˆJ(u)=2(I2P).

    In the following, our aim is to show tn0 as n. Or else, there exists t0>0 such that tnt0 and C2(1tn)C2(1t0). Define C4:=C2(1t0), since Jtn(un)0 as un, there exists some R2>0 such that

    unJtn(un),ˆun=(1tn)J(un),ˆun+2tnun2(1tn)C3(u+2+u2)C4un+2tnun2as|u(i,j)|>R2,

    which implies

    (1+C4)un(1tn)C3(u+2+u2)+2tnun22tnun2.

    Making use of (3.11), we obtain tn0 and

    (1+C4)unC3(u+n2+un2).

    Therefore,

    u+n2un+un2un1+C4C3,

    which means both {u+n2un} and {un2un} are bounded, and

    u+n2un2+un2un21+C4C31un. (3.12)

    Recall un, (3.12) implies that

    u+nun0andunun0.

    Joint with un2=u+n2+u0n2+un2, we obtain u0nun1. Therefore, u+n2+u0n2un2>0, namely, ˆJ(un)>0.

    Since

    J(un)=12un2T1i=1T2j=1F((i,j),u(i,j))=12(IK)un,unT1i=1T2j=1G((i,j),u(i,j))12[(1λkλk+1)u+n2+(λkλk11)un2]T1i=1T2j=1G((i,j),u(i,j))12(λkλk11)un2T1i=1T2j=1G((i,j),u(i,j)),

    then

    1unJ(un)12(λkλk11)un2unT1i=1T2j=11unG((i,j),u(i,j))C5T1i=1T2j=11unG((i,j),u(i,j)), (3.13)

    where C5:=12(λkλk11)1+C4C3. Denote vn=unun, then vn=1. Hence up to a convergent subsequence, without loss of generality, we set the subsequence to be the subsequence, which means that there exists some vS satisfying v=1 such that vnv as n.

    Setting

    Θ:={(i,j)|(i,j)Ω,v(i,j)0},

    then Θ. If (i,j)Θ, then un(i,j)=vn(i,j)un and lim|u|G((i,j),u)|u(i,j)|=+. Therefore, for any M1>0, there exists N2>0 such that G((i,j),u)|u(i,j)|>M1 as n>N2. If (i,j)Θ, then vn(i,j)0. Since un, there exist C6, N3>0 such that G((i,j),u)unC6. Consequently,

    limnT1i=1T2j=1G((i,j),un(i,j))un=+.

    Combining with (3.13), we can deduce that 1unJ(un)+. Further,

    Jtn(un)=(1tn)J(un)+tnˆJ(un)(1tn)J(un)un2(1unJ(un))+,

    which is a contradiction. Thus {Jt:t[0,1]} satisfies (PS), that is, J=J0 and J1 satisfy (PS). By Proposition 2.3, we have

    Cq(J,)Cq(J0,)Cq(J1,). (3.14)

    If ˆJ(u)=J1(u)=0, then u++u0=u, namely u=2u. Therefore, u=0 is the only critical point of J1 such that

    Cq(J1,)=Cq(J1,0). (3.15)

    Let J1(0)u=0, it is easy to compute that u=0, which means that u=0 is a nondegenerate critical point of J1 and its corresponding Morse index μ0=dimW=k1. Finally, combining (3.14) with (3.15), we achieve Cq(J,)δq,k1Z, qZ. And this completes the proof of Lemma 3.2.

    Lemma 3.3. Assume α=λk and (F) holds. Then

    (1) Cq(J,0)δq,0 if (I1) is satisfied;

    (2) Cq(J,0)δq,T1T2 if (I4) is satisfied;

    (3) Cq(J,0)δq,p if (I3) is satisfied, where pk1.

    Proof. In case (1), u=0 is a local minimizer of J and Cq(J,0)δq,0Z. In case (2), combing u=0 is a local maximum of J with the Morse index on u=0 is μ0=T1T2, it follows that Cq(J,0)δq,T1T2Z. In case (3), μ0=pk1, which means that Cq(J,0)δq,pZ.

    To prove Theorem 3.4, the following lemma on local linking is needed.

    Lemma 3.4. Let α0=λm and (F+0) (or (F0)) hold. Then J has a local linking at 0 with respect to

    S=SS+,

    where S=span{ϕ1,,ϕm} (or S=span{ϕ1,,ϕm1}).

    Proof. In view of (F+0), there exists ˉδ>0 such that

    F((i,j),u)12λmu2,|u(i,j)|ˉδ,(i,j)Ω.

    For uS with |u(i,j)|ˉδ, there has

    J(u)=12u2T1i=1T2j=1F((i,j),u(i,j))12u212λmu22=0. (3.16)

    Since α0=λm, we have

    limu02F((i,j),u)u2=limu0f((i,j),u)u=λm.

    Then for any ε>0, there exists ˜δ>0 such that |2F((i,j),u)u2λm|<ε as 0<|u(i,j)|<˜δ, that is, λmε<2F((i,j),u)u2<λm+ε. Thus,

    12(λmε)u2<F((i,j),u)<12(λm+ε)u2,0<|u(i,j)|<˜δ,(i,j)Ω.

    For uS with 0<|u(i,j)|<˜δ, we have

    J(u)12u212(λm+ε)u2212(1λm+ελm+1)u2. (3.17)

    Choose δ=min{ˉδ,˜δ} and 0<ε<λm+1λm. Denote ρ=δT1T2λT1T2. Then (3.16) and (3.17) indicate that

    J(u)0,uS,uρ,J(u)0,uS+,uρ.

    Moreover, J(0)=0 is obvious. Consequently, J has a local linking at 0. And the proof is achieved.

    As for Theorem 3.5, we consider the critical groups at infinity with respect to J. In the same manner as Lemma 3.3, we have

    Lemma 3.5. Let (F+) hold and α=λk. Then

    (1) Cq(J,0)δq,T1T2, if (I1) is satisfied;

    (2) Cq(J,0)δq,0, if (I4) is satisfied;

    (3) Cq(J,0)δq,T1T2p, if (I3) is satisfied and pk.

    With above preparations, it is time for us to provide detailed proofs of Theorems 3.1–3.5.

    Proof of Theorem 3.1 Since all three cases of Theorem 3.1 can be proved similarly, here we only prove the case (i) at length for brevity.

    On account of (I1), u=0 is a local minimizer of J and its Morse index μ0=0 and zero nullity ν0=0 and

    Cq(J,0)δq,0Z,qZ.

    By Lemma 3.1, we get

    Cq(J,)δq,kZ,qZ.

    Moreover, the process of proof of Lemma 3.1 indicates that J satisfies (PS). By Proposition 2.2, there exists u1κ such that u10 and Ck(J,u1)0. Then u1 is a non-zero critical point of J and

    J(u1)=Idiag{f((1,1),u1(1,1)),,f((T1,T2),u1(T1,T2))}.

    Note that the rank of J(u1) is greater than T1T21, which implies ν(u1)=dimker(J(u1))1 and Cq(J,u1)δq,kZ, qZ. Assume that κ={0,u1}, then the Morse equality is

    (1)0+(1)k=(1)k,

    which is impossible. Hence, J has at least another nontrivial critical point, namely, (1.1) and (1.2) possesses at least two nontrivial solutions. And the proof of Theorem 3.1 is completed.

    Proof of Theorem 3.2 Recall G((i,j),u)=F((i,j),u)12λku2, there has

    J(u)=12(IK)u,uG(u):=12Bu,uG(u).

    Then B:SS is a self-adjoint bounded linear operator such that 0 is not in the spectrum of B and B(u) is compact. Write B±=B|W±, then B± has a bounded inverse on W±. Let k=dimW=T1T22, then α=λk guarantees that (2.9) is valid. By Proposition 2.4, we obtain

    Cq(J,)δq,T1T22Z,qZ,

    and J satisfies (PS). Use (I1) once more, we have u=0 is a local minimizer of J and

    Cq(J,0)δq,0Z,qZ.

    According to Proposition 2.2 and ν(u2)1, we draw a conclusion that there exists u2κ with u20 such that

    CT1T22(J,u2)0.

    Assume κ={0,u2}, then the Morse equality expresses as

    (1)0+(1)T1T22=(1)T1T22,

    which is a contradiction. Therefore, J has at least another nontrivial critical point, (1.1) and (1.2) possesses at least two nontrivial solutions. And this completes the proof of Theorem 3.2.

    Proof of Theorem 3.3 By Lemma 3.2, Cq(J,)=δq,k1Z, qZ and J satisfies (PS). Then Proposition 2.2 indicates there exists u3κ such that Ck1(J,u3)0, which means that u3 is a non-zero critical point of J. Since

    J(u3)=Idiag{f((1,1),u3(1,1)),,f((T1,T2),u3(T1,T2))},

    and the rank of J(u3) is greater than T1T21. Then ν(u3)=dimker(J(u3))1. If q[μ(u3),μ(u3)+ν(u3)] and Cq(J,u3)=0, then either k1=μ(u3)+ν(u3) or k1=μ(u3). Thus, Cq(J,u3)δq,k1Z. If κ={0,u3}, by the Morse equality, we have

    (1)+(1)k1=(1)k1, (3.18)

    where =0, T1T2 or p corresponds to (I1), (I4) or (I3), respectively. Meanwhile, it is impossible for (3.18) to be true. Therefore, J at least has another non-zero critical point, and (1.1)–(1.2) possesses at least two nontrivial solutions and the proof is achieved.

    Proof of Theorem 3.4 Lemma 3.1 yields Cq(J,)δq,kZ, qZ, which means that there exists u4κ such that Ck(J,)0. Since

    J(u4)=Idiag{f((1,1),u4(1,1)),,f((T1,T2),u4(T1,T2))},

    and the rank of J(u4) is greater than T1T21, then ν(u4)=dimker(J(u4))1. If q[μ(u4),μ(u4)+ν(u4)] and Cq(J,u4)=0, then either k=μ(u4) or k=μ(u4)+ν(u4), which implies that Cq(J,u4)δq,kZ. Note that Lemma 3.4 shows that J has a local linking at 0 and dimS=m. Further, 0 is the isolated critical point of J and J(0) is a Fredholm operator and Cm(J,0)0, then Cq(J,0)δq,mZ. If κ={0,u4}, the Morse equality is in the form as

    (1)m+(1)k=(1)k. (3.19)

    However, (3.19) is impossible. Consequently, J at least has another non-zero critical point, (1.1) and (1.2) possesses at least two nontrivial solutions. The proof of Theorem 3.4 is finished.

    Proof of Theorem 3.5 Let α=λk and (F+) be satisfied, Lemma 3.2 gives

    Cq(J,)δq,T1T2kZ,qZ.

    Furthermore, (F0) and α0=λm lead to

    Cq(J,0)δq,T1T2(m+1)Z,qZ.

    Notice that m+1k and nondegenerate critical points are isolated, then there exists some critical point u5κ with u50 such that

    CT1T2k(J,u5)0,

    then

    Cq(J,u5)δq,T1T2kZ.

    If κ={0,u5}, then there holds the Morse equality

    (1)T1T2(m+1)+(1)T1T2k=(1)T1T2k,

    which is impossible. Then J at least has another non-zero critical point, (1.1) and (1.2) possesses at least two nontrivial solutions. The proof of Theorem 3.5 is completed.

    Finally, we present five examples to verify the feasibility of our results.

    Example 4.1. Take T1=3, T2=2, consider

    Δ21u(i1,j)+Δ22u(i,j1)+(λ122λT1T2)u1+u2+2λT1T2u=0, (4.1)

    with boundary value conditions (1.2).

    Because f((i,j),u)=(λ122λT1T2)u1+u2+2λT1T2u, it follows that f((i,j),0)=0 and

    f((i,j),u)=(6λT1T2λ12)u2+2λT1T2u4+λ12(1+u2)2.

    Then f((i,j),0)=λ12<λ1 and f((i,j),)=2λT1T2>λT1T2, which means that (I1) and (I2) are satisfied. Consequently, Theorem 3.1 guarantees that (4.1) and (1.2) admits at least two nontrivial solutions.

    Example 4.2. Take T1=3, T2=5, consider

    Δ21u(i1,j)+Δ22u(i,j1)+(λ12λk)u1+u2+λku=0, (4.2)

    with boundary value conditions (1.2).

    Clear, T1T2=15 is odd and

    f((i,j),u)=(λ12λk)u1+u2+λku.

    It is easy to calculate that f((i,j),0)=0 and

    α=lim|u|f((i,j),u)u=lim|u|[λ12λk1+u2+λk]=λk.

    Moreover, direct computation gives

    f((i,j),u)=(3λkλ12)u2+λku4+λ12(1+u2)2,

    which indicates f((i,j),0)=λ12<λ1. As a result, (I1) is valid and Theorem 3.2 ensures that (4.2) and (1.2) admits at least two nontrivial solutions.

    Example 4.3. Take T1=3, T2=2, r=eλ12λk>0. Consider

    Δ21u(i1,j)+Δ22u(i,j1)+(λ12λk)sinuu+1+λku+u13ln(r+|u|3)=0, (4.3)

    with boundary value conditions (1.2).

    Since f((i,j),u)=(λ12λk)sinuu+1+λku+u13ln(r+|u|3), it is easy to get that f((i,j),0)=0 and

    α=lim|u|f((i,j),u)u=lim|u|[(λ12λk)sinuu(u+1)+λk+ln(r+|u|3)u23]=λk.

    Further,

    f((i,j),u)=λk+cosu(λ12λk)(u+1)sinu(λ12λk)(u+1)2+u23ln(r+|u|3)+3u73r+|u|3.

    Thus f((i,j),0)=λ12<λ1 and (I1) is satisfied.

    At last, by direct computation, we obtain

    limu+(f((i,j),u)λku)=limu+((λ12λk)sinuu+1+u13ln(r+|u|3))=+,limu(f((i,j),u)λku)=limu((λ12λk)sinuu+1+u13ln(r+|u|3))=,

    which means that (F+) is met.

    Therefore, all conditions of Theorem 3.3 are fulfilled and (4.3) and (1.2) admits at least two nontrivial solutions.

    Example 4.4. Take T1=3, T2=2. Consider

    Δ21u(i1,j)+Δ22u(i,j1)+2(λmλp+λp+12)u2u2+λp+λp+12u=0, (4.4)

    with boundary value conditions (1.2).

    Owe to f((i,j),u)=2(λmλp+λp+12)u2u2+λp+λp+12u, it follows that f((i,j),0)=0 and

    F((i,j),u)=(λp+λp+12λm)ln(2u2)+λp+λp+14u2.

    Then

    f((i,j),u)=2(λmλp+λp+12)(2+u2)(2u2)2+λp+λp+12,

    and

    α=lim|u|0f((i,j),u)u=λm.

    Additionally, λp<f((i,j),)=λp+λp+12<λp+1, which implies that (I6) is met. In the following, we check (F+0). Write

    A=(410100141010014001100410010141001014),

    then A is positive-define and the corresponding eigenvalues are

    λ1=32,λ2=3,λ3=52,λ4=3+2,λ5=5,λ6=5+2.

    Take m=1, p=3, then there exists δ>0 such that 2F((i,j),u)λmu2>0 when |u(i,j)|δ. In fact, for any (i,j)Z(1,3)×Z(1,2), we can choose δ=1>0, then 0<|u(i,j)|21 for 0<|u(i,j)|1, which means that

    (2+1)ln(2u2)+(21)u2>0.

    Thus (F+0) is fulfilled. Consequently, Theorem 3.4 ensures that (4.4) and (1.2) possesses at least two nontrivial solutions.

    More clearly, using Matlab, we find that problem (4.4) and (1.2) has 63 solutions including 1 trivial solution and 62 nontrivial solutions. Here we list a few: (-2.1408, 1.8608, -2.1408, 2.1408, -1.8608, 2.1408), (2.1408, -1.8608, 2.1408, -2.1408, 1.8608, -2.1408), (8.3211×109, 1.1767×108, 8.3211×109, 8.3211×109, 1.1767×108, 8.3211×109), (8.3211×109, 1.1767×108, 8.3211×109, 8.3211×109, 1.1767×108, 8.3211×109).

    Example 4.5. Take T1=3, T2=2. Consider

    Δ21u(i1,j)+Δ22u(i,j1)+(λkλm)u31+u2+λmu+u13ln(1+|u|3)=0, (4.5)

    with boundary value conditions (1.2).

    From (4.5), we find f((i,j),u)=(λkλm)u31+u2+λmu+u13ln(1+|u|3), then

    F((i,j),u)=12λmu2+λkλm2(u2ln(1+u2))+uln(1+u)u+ln(1+u)+C,

    take C=1 and δ=e1>0, then when m>k and 0<|u(i,j)|<δ,

    F((i,j),u)12λmu2=λkλm2(u2ln(1+u2))+uln(1+u)u+ln(1+u)+C=(u+1)(ln(u+1)1)+λkλm2(u2ln(1+u2))=(u+1)(ln(u+1)lne)+λkλm2(u2ln(1+u2))<0,

    which means that (F0) is fulfilled.

    On the other side, it is easy to get f((i,j),0)=0 and

    α=lim|u|f((i,j),u)u=lim|u|[(λkλm)u21+u2+λm+ln(1+|u|3)u23]=λk,α0=lim|u|0f((i,j),u)u=lim|u|0[(λkλm)u21+u2+λm+ln(1+|u|3)u23]=λm.

    Furthermore, there hold

    limu+(f((i,j),u)λku)=limu+(u13ln(1+|u|3)+(λmλk)u+(λkλm)u31+u2)=+,limu(f((i,j),u)λku)=limu(u13ln(1+|u|3)+(λmλk)u+(λkλm)u31+u2)=,

    which guarantees that (F+) is satisfied.

    Therefore, all conditions of Theorem 3.5 are valid and (4.5) and (1.2) has at least two nontrivial solutions.

    This paper is supported by the National Natural Science Foundation of China (NSFC) (No. 11971126).

    All authors declare no conflicts of interest in this paper.



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