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Research article

Exponential stability and numerical simulation of a Bresse-Timoshenko system subject to a neutral delay

  • Received: 02 May 2023 Revised: 08 June 2023 Accepted: 11 June 2023 Published: 21 June 2023
  • MSC : 35B40, 35L70, 93D20

  • In the present work, we consider a one-dimensional Bresse-Timoshenko system with neutral delay term and a viscous damping acting on vertical displacement of the beam. Under appropriate assumptions on the kernel of this kind of delay and based on the multipliers method, we construct a suitable Lyapunov functional that allows us to establish an exponential decay of the energy in spite of the existence of the delay. Moreover, our result does not depend on any condition on the coefficients of the system. Finally, we present some numerical results to illustrate the theoretical result obtained.

    Citation: Houssem Eddine Khochemane, Ali Rezaiguia, Hasan Nihal Zaidi. Exponential stability and numerical simulation of a Bresse-Timoshenko system subject to a neutral delay[J]. AIMS Mathematics, 2023, 8(9): 20361-20379. doi: 10.3934/math.20231038

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  • In the present work, we consider a one-dimensional Bresse-Timoshenko system with neutral delay term and a viscous damping acting on vertical displacement of the beam. Under appropriate assumptions on the kernel of this kind of delay and based on the multipliers method, we construct a suitable Lyapunov functional that allows us to establish an exponential decay of the energy in spite of the existence of the delay. Moreover, our result does not depend on any condition on the coefficients of the system. Finally, we present some numerical results to illustrate the theoretical result obtained.



    Throughout the years, many works have dealt with beam theories due to their important applications in high technology of flexible structures. Historically, it is well known that one of the oldest beam theories is the Euler-Bernoulli beam theory, which is a simplification of linear isotropic beams. It was first enunciated circa 1750, but it was not applied on a large scale until the development of the Eiffel Tower and the Ferris Wheel in the late 19th century. Following these successful demonstrations, it quickly became a cornerstone of engineering and an enabler of the Second Industrial Revolution. Later on, other beam theories appeared and were considered as improvements of the Euler-Bernoulli theory, such as the Rayleigh beam theory [28] and the Timoshenko beam theory [31]. In [13,14,15], Elishakoff et al. gave a brief description of the beam model in the one-dimensional case for beam vibrations. The classical Euler-Bernoulli differential equation for free vibration of uniform beams is given by

    EIφxxxx+ρAφtt=0, (1.1)

    where φ(x,t) is the beam deflection from its equilibrium position, E is the modulus of elasticity, I is the moment of inertia of the cross section, ρ is the material density of the beam material, A is the cross-sectional area, x is the axial coordinate, and t is the time. Later, Rayleigh [28] proposed a correction to the Euler-Bernoulli equation (1.1), by taking into account the rotary movements of the beam elements in addition to the translatory ones. From a mathematical modeling point of view for vibrating beams, it is instructive to re-derive briefly this equation. The angle of rotation equals the slope of the deflection curve φx, and the corresponding angular acceleration is given by φxtt. As a consequence, the moment of inertia of the element about an axis through its center of mass equals ρIφxtt. By exploiting this moment and taking into account d'Alembert's principle for dynamic equilibrium [22], we obtain

    VMx+ρIφxtt=0, (1.2)

    where V(x,t) is the shearing force, and M(x,t) is the bending moment. Replacing V from Eq (1.2) in the case of dynamic equilibrium condition for forces in the φ-direction of the transverse vibration, we have

    Vx=ρAφtt=(MxρIφxtt)x.

    Physically and from elastic theory, the bending moment M coincides with EIφxx, which leads to the final governing equation obtained in the Rayleigh model for the uniform beam oscillations,

    EIφxxxx+ρAφttρIφxxtt=0, (1.3)

    which is known as the rotatory inertial equation.

    Afterwards, Timoshenko [31] extended Eq (1.3) by incorporating the impact of the shear deformation. In another term, he expressed the slope of the deflection curve in two parts,

    φx=ψ+β, (1.4)

    with ψ as the rotation of the cross-sections with the neglect of the shear deformation and β as the angle associated with the shear deformation at the neutral axis in the same cross-section. On the other hand, according to the mechanics of solids we can write

    M=EIψx, (1.5)
    V=k1βAG=k1AG(φx+ψ), (1.6)

    where k1 is the shear coefficient, and G is the shear modulus. The state of dynamic equilibrium of forces in the vertical direction is given by

    ρAφttVx=0. (1.7)

    Deriving with respect to t Eq (1.4) and substituting it in the dynamic equilibrium equation of motion (1.2), we get

    VMx+ρIψtt=0. (1.8)

    The Timoshenko system was obtained by substituting, respectively, (1.6) and (1.5) into (1.7) and (1.8), thus:

    {k1AG(φx+ψ)x+ρAφtt=0,k1AG(φx+ψ)EIψxx+ρIψtt=0,

    where ρ1=ρA represents the mass density, ρ2=ρI is the moment mass inertia, b=EI is the rigidity coefficient (of the cross-section), and k=k1AG is the shear modulus of elasticity. Then, the Timoshenko system takes the following form:

    {ρ1φttk(φx+ψ)x=0,ρ2ψttbψxx+k(φx+ψ)=0.

    It should be noted that the mentioned problem plays a crucial role in engineering applications, and for more details on the valuable resources that have been realized regarding the Timoshenko system, we refer the readers to [5,6,7,8,9,31].

    For the physical and technical reasons mentioned in [13], Elishakoff proposed a combination of Eq (1.2) which comes from d'Alembert's principle with Eq (1.7) from the Timoshenko hypothesis, resulting in the following coupled system:

    {ρ1φttk(φx+ψ)x=0,ρ2φttxbψxx+k(φx+ψ)=0.

    Many investigations have been realized concerning the asymptotic behavior of the solution of the Bresse-Timoshenko system. Among them, we cite the works [18,19,34], in which the authors established different types of stability results such as exponential and general decay based on many dissipation terms.

    There are also other investigations concerning the delay which appear in many models of mathematics that come from engineering biological science, economics, physiology and epidemiology. Delay effects arise in many applications depending not only on the present state but also on some past occurrences, and they have attracted a lot of attention from researchers in diverse fields of human endeavors, such as mathematics, engineering, science and economics. The presence of delay may be a source of instability of systems which are uniformly asymptotically stable in the absence of delay unless additional control terms have been used (see [10,11,17,25,26,33]). Also, the introducing of this complementary may lead to ill-posedness, as shown in many works such as [11,27] and the references therein. On the other hand, the delay has an important role in the control of PDEs, and this has appeared in a lot of studies (see [1,2,3,4,17,20,21,24,25,26,33]). In addition to the well-known discrete delays, there are several others. We are interested here in the neutral delay, where the delay is occurring in the second (highest) derivative. For more details, see previous studies ([12,13,14,15,16,23,32]) and the references therein.

    Among the investigations that have been realized concerning the asymptotic behavior with neutral delay, we cite the work of Tatar [30] where he considered the wave equation with neutral delay, and he showed that the solution decays in an exponential manner under some conditions on the kernel of distributed neutral delay.

    In [29], Seghour et al. studied the following thermoelastic laminated system with neutral delay:

    {ρwtt+G(ψwx)x+Awt=0,x(0,1),t>0,Iρ(3sttψtt)G(ψwx)(3sψ)+μθx=0,x(0,1),t>0,3Iρ(st+t0h(tr)st(r)dr)t+3G(ψwx)+4γs3sxx=0,x(0,1),t>0,θtκθxx+μ(3sψ)tx=0,x(0,1),t>0,

    with boundary conditions

    {ψ(0,t)=s(0,t)=θx(0,t)=wx(0,t)=0,t0,θ(1,t)=w(1,t)=sx(1,t)=ψx(1,t)=0,t0,

    and initial data

    {(w,ψ,s,θ)(x,0)=(w0,ψ0,s0,θ0),x(0,1),(wt,ψt,st)(x,0)=(w1,ψ1,s1),x(0,1).

    They showed that the dissipation given by the combination of heat effect and the frictional damping stabilize exponentially the system in the case of equal speeds of wave propagation even if the delays, in general, are of a destructive nature. In the case of non-equal wave speeds and with an additional assumption on the kernel, they proved a polynomial stability.

    Motivated by the previous works, in this paper we consider the following Bresse-Timoshenko system subject to a neutral delay:

    {ρ1(φt+t0h(ts)φt(s)ds)t=k(φx+ψ)xμ1φtρ2φttx=bψxxk(φx+ψ),in (0,1)×(0,+),in (0,1)×(0,+), (1.9)

    with the initial and boundary conditions

    {φ(x,0)=φ0(x), φt(x,0)=φ1(x), ψ(x,0)=ψ0(x), ψt(x,0)=ψ1(x),φ(0,t)=φ(1,t)=ψ(0,t)=ψ(1,t)=0, x(0,1),x(0,1),t(0,+). (1.10)

    First, we give an existence and uniqueness result of the solution using the Faedo-Galerkin method. Then, based on the energy method and by constructing a suitable Lyapunov functional using the multipliers method as well as under an appropriate assumptions on the kernel of the neutral delay term, we prove that the system is exponentially stable in spite of the existence of the neutral delay irrespective of any stability number. In the absence of neutral delay, there is a similarity with the previous works like [18,19,34] concerning the estimation of the energy terms. In our case and compared to the work of Seghour et al. in [29], we were able to dispense the thermal effect depending on the viscous damping acting on vertical displacement of the beam to control the neutral delay term and to guarantee an exponential stability of the solution irrespective of wave speeds or any other relationship between the system parameters. In other words, the unique dissipation given only by the viscous damping is strong enough to provoke an exponential stability and control the neutral delay. Finally, we present some numerical results using MATLAB software to validate the theoretical result obtained by carrying out a discretization using the classical finite difference method for the spatial and temporal discretization.

    This paper is organized as follows: In Section 2, we introduce some assumptions needed in the next sections to prove the main result, and we give a result concerning the well-posedness of problem (1.9)–(1.10). In Section 3, we prove the energy decay of the system. In Section 4, we use the energy method to prove the exponential decay result. In Section 5, some numerical simulations are presented.

    In this section we present our assumptions on both kernels and introduce the energy functional and another functional.

    We use the standard Lebesgue space L2(0,1) and the Sobolev space H10(0,1) with their usual scalar products and norms. Also, in what follows we will use the following notations:

    (hΨ)(t)=t0h(ts)(10(Ψ(t)Ψ(s))2dx)ds, t0,

    and

    (hΨ)(t)=10t0h(ts)Ψ(s)2dsdx, t0.

    To achieve our goal, we need to introduce the following hypothesis and assumptions:

    (H1) The kernel h is a nonnegative continuously differentiable and summable function satisfying

    μh(t)h(t)0,t0, where μ>0,ˉh=0h(s)ds<1.

    (H2) exp(ςt)h(t)L1(R+) for some ς>0.

    Note that if +0eςsh(s)ds<, and limtexp(ςt)h(t)<, then

    +0eςs|h(s)|ds=+0eςsh(s)ds=eςsh(s)0+ς+0eςsh(s)ds<.

    To simplify the calculations, we are obligated to announce this lemma which is usable in the following sections.

    Lemma 1 ([29]). For any function ΨC1([0,);L2(0,1)) and any hC1([0,)), we have the following identity:

    10Ψ(t)(t0h(ts)Ψt(s)ds)dx=12(hΨ)(t)+12ddt10(t0h(ts)Ψ2(s)ds)dx+h(t)210Ψ2dxh(t)10Ψ(0)Ψ(t)dx.

    For completeness, we state without proof the following global existence and regularity result which can be proved by using the standard Faedo-Galerkin method, for which we refer the reader to [24].

    Theorem 1. Let (φ0,φ1)H10(0,1)×L2(0,1) and (ψ0,ψ1)H10(0,1)×L2(0,1) be given. Assume that (H1)–(H2) are satisfied, and then the problem (1.9)–(1.10) has a unique global (weak) solution satisfying

    φ,ψC(R+,H10(0,1))C1(R+,L2(0,1)).

    In this section, we use the energy method to study the asymptotic behavior of solutions of the system (1.9)–(1.10). First, we state and prove the following lemma.

    Lemma 2. Let (φ,ψ) be a solution of system (1.9)–(1.10). Then, the energy associated to the system (1.9)–(1.10) is defined by

    E(t)=1210(ρ1φ2t +k(φx+ψ)2+ρ2φ2tx+bψ2x+ρ1ρ2kφ2tt)dx+ρ1(hφt)(t)+ρ1ρ2k(hφtt)(t), (3.1)

    satisfying

    ddtE(t)ρ12(hφt)(t)μ1ρ2k10φ2ttdx+ρ1ρ2k(hφtt)(t)μ110φ2t dx+ζh(t),ζ>0. (3.2)

    Proof. Multiplying (1.9)1 and (1.9)2, respectively, by φt and ψt and integrating by parts, we get

    {ρ12ddt10φ2t dx+ρ110φt(t0h(ts)φt(s)ds)t dx=k10(φx+ψ)φtx dxμ110 φ2tdx,ρ210φttψxtdx+b2ddt10ψ2xdx=k10(φx+ψ)ψtdx. (3.3)

    Taking the derivative of (1.9)1 with respect to t, we obtain

    ψtx=ρ1kφtttφtxx+ρ1k(t0h(ts)φt(s)ds)tt+μ1kφtt,

    noting that

    (t0h(ts)φt(s)ds)tt=(t0h(ts)φtt(s)ds+h(t)φt(0))t=t0h(ts)φttt(s)ds+h(t)φtt(0)+h(t)φt(0).

    So,

    ψtx=ρ1kφtttφtxx+ρ1kt0h(ts)φttt(s)ds+ρ1kh(t)φtt(0)+ρ1kh(t)φt(0)+μ1kφtt. (3.4)

    Substituting (3.4) in (3.3)2, the system (3.3) becomes

    {ρ12ddt10φ2t dx+ρ110φt(t0h(ts)φt(s)ds)t dx=k10(φx+ψ)φtxdxμ110 φ2tdx,ρ1ρ22kddt10φ2ttdx+ρ22ddt10φ2txdx+ρ1ρ2k10φtt(t0h(ts)φttt(s)ds)dx+ρ1ρ2kh(t)10φttφtt(0)dx+ρ1ρ2kh(t)10φttφt(0)dx+b2ddt10ψ2xdx=μ1ρ2k10φ2ttdxk10(φx+ψ)ψtdx. (3.5)

    On the other hand, by applying Lemma 1, we have

    ρ110(t0h(ts)φt(s)ds)tφt dx=ρ1h(t)10φtφt(0)dx+ρ110φt(t0h(ts)φtt(s)ds) dx=ρ1h(t)10φtφt(0)dxρ12(hφt)(t)+ρ12ddt10(t0h(ts)φ2t(s)ds)dx+ρ12h(t)10φ2t dxρ1h(t)10φtφt(0)dx,

    and

    ρ1ρ2k10φtt(t0h(ts)φttt(s)ds)dx=ρ1ρ22kddt10(t0h(ts)φ2tt(s)ds)dxρ1ρ2kh(t)10φttφtt(0)dx+ρ1ρ2kh(t)10φ2ttdxρ1ρ2k(hφtt)(t).

    Therefore, the system (3.5) is equivalent to

    d2dt10(ρ1φ2t +k(φx+ψ)2+ρ2φ2tx+bψ2x+ρ1ρ2kφ2tt+ρ1t0h(ts)φ2t(s)ds+ρ1ρ2kt0h(ts)φ2tt(s)ds)dx=ρ12(hφt)(t)ρ1ρ2k(1+h(t)2)10φ2ttdx+ρ1ρ2k(hφtt)(t)(ρ12h(t)+μ1)10φ2t dxρ1ρ2kh(t)10φttφt(0)dx.

    By using Young's inequality and the hypothesis (H1), we obtain

    ρ1ρ22h(t)10φttφt(0)dx=ρ1ρ22μh(t)101kφttkφt(0)dxρ1ρ22kμh(t)δ110φ2ttdx+ρ1ρ22δ1μh(t)k10φ2t(0)dx,

    and taking δ1=12μ

    ρ1ρ22h(t)10φttφt(0)dxρ1ρ24kh(t)10φ2ttdx+ρ1ρ24μ2h(t)k10φ2t(0)dx.

    Then,

    ddtE(t)ρ12(hφt)(t)ρ1ρ2k10φ2ttdx+ρ1ρ2k(hφtt)(t)μ110φ2t dx+ζh(t),

    where ζ=ρ1ρ24μ2k10φ2t(0)dx.

    In this section, we establish an exponential decay result of solutions for the considered problem. For that, we need the following lemmas to achieve our goal.

    Lemma 3. Let (φ,ψ) be the solution of (1.9)–(1.10). Then, the functional

    F1(t)=ρ110φt(φt+t0h(ts)φt(s)ds)dxk10φtxφxdxμ1210φ2tdx,

    satisfies the estimate

    F1(t)k10φ2txdx+((3+h(t)2)ρ1+k24ε1)10φ2ttdx+ε110ψ2xdx+ρ12(3+h(t))10φ2tdx+ρ1h(t)10φ2t(0)dx+ρ1¯h2(hφt)(t)+ρ1¯h(hφtt)(t).

    Proof. By differentiating F1(t) with respect to t, using the first equation of (1.9) and integrating by parts, we obtain

    F1(t)=2ρ110φttφtdx+ρ110φ2ttdxk10φttψxdxk10φ2txdxρ110φttt0h(ts)φt(s)dsdxρ110φtt0h(ts)φtt(s)dsdx+ρ110φttt0h(ts)φtt(s)dsdxρ1h(t)10φtφt(0)dx+ρ1h(t)10φt(0)φttdx. (4.1)

    By using Young's inequality, we obtain

    2ρ110φttφtdxρ110φ2ttdx+ρ110φ2tdx, (4.2)
    ρ1h(t)10φtφt(0)dxρ12h(t)10φ2tdx+ρ12h(t)10φ2t(0)dx, (4.3)
    ρ1h(t)10φt(0)φttdxρ12h(t)10φ2ttdx+ρ12h(t)10φ2t(0)dx, (4.4)
    k10φttψxdxε110ψ2xdx+k24ε110φ2ttdx. (4.5)

    By using Young's and Cauchy Schwarz inequalities, we obtain

    ρ110φttt0h(ts)φt(s)dsdxρ1210φ2ttdx+ρ1¯h2(hφt)(t), (4.6a)
    ρ110φtt0h(ts)φtt(s)dsdxρ1210φ2tdx+ρ1¯h2(hφtt)(t), (4.7)
    ρ110φttt0h(ts)φtt(s)dsdxρ1210φ2ttdx+ρ1¯h2(hφtt)(t). (4.8)

    Inserting (4.2)–(4.8) in (4.1), we obtain (4.1).

    Lemma 4. Let (φ,ψ) be the solution of (1.9)–(1.10). Then, the functional

    F2(t):=ρ210φtxψdx+ρ110φ(φt+t0h(ts)φt(s)ds)dx, (4.9)

    satisfies the estimate

    F2(t)b10ψ2xdxk10(φx+ψ)2dx+ρ210φ2txdx+3ρ1210φ2tdx+ρ1¯h2(hφtt)(t). (4.10)

    Proof. By differentiating F2(t) with respect to t, exploiting (1.9), integrating by parts and using the Timoshenko hypothesis (1.4), we obtain

    F2(t)=b10ψ2xdx+ρ210φ2txdxk10(φx+ψ)2dx+ρ110φ2tdx+ρ110φtt0h(ts)φt(s)dsdx.

    By using Young's and Cauchy Schwarz inequalities, we have (4.10).

    Lemma 5. Let (φ,ψ) be the solution of (1.9)–(1.10). Then, the functional

    F3(t):=eζt10t0eζs˜H1(ts)φ2t(s)dsdx, (4.11)

    satisfies the following estimate:

    F3(t)=ζF3(t)+˜H1(0)10φ2tdx(hφt)(t), (4.12)

    where ˜H1(t)=th(s)eζsds.

    Proof. By differentiating F3(t) with respect to t,

    F3(t)=ζeζt10t0eζs˜H1(ts)φ2t(s)dsdx+eζt10(t0eζs˜H1(ts)φ2t(s)ds)tdx=ζF3(t)+eζt10(eζt˜H1(0)φ2tt0eζth(ts)φ2t(s)ds)dx=ζF3(t)+˜H1(0)10φ2tdx(hφt)(t),

    which gives (4.12).

    Lemma 6. Let (φ,ψ) be the solution of (1.9)–(1.10). Then, the functional

    F4(t):=eζt10t0eζs˜H1(ts)φ2tt(s)dsdx (4.13)

    satisfies the estimate

    F4(t)ζF4(t)+˜H1(0)10φ2ttdx(hφtt)(t). (4.14)

    Proof. By differentiating F4(t) with respect to t, as in the case of F3(t), we obtain the desired result.

    Next, we define a Lyapunov function L(t) by

    L(t):=NE(t)+N1F1(t)+N2F2(t)+N3(F3(t)+F4(t)), (4.15)

    where N, N1, N2 and N3 are positive constants that will be chosen appropriately later.

    Lemma 7. Let (φ,ψ) be the solution of (1.9)–(1.10). Then, there exist two positive constants κ1 and κ2 such that the Lyapunov functional (4.15) satisfies

    κ1(E(t)+F3(t)+F4(t))L(t)κ2(E(t)+F3(t)+F4(t)),t0, (4.16)

    and

    L(t)β1(E(t)+F3(t)+F4(t))+C2h(t),β1>0. (4.17)

    Proof. From (4.15), we have

    |L(t)NE(t)N3(F3(t)+F4(t))|=N1|F1(t)|+N2|F2(t)|+N3|F3(t)+F4(t)|ρ1N110|φt(φt+t0h(ts)φt(s)ds)|dx+kN110|φtxφx|dx+μ12N110φ2tdx+ρ2N210|φtxψ|dx+ρ1N210|φ(φt+t0h(ts)φt(s)ds)|dx.

    By Young's, Cauchy Schwarz and Poincaré's inequalities and with some transformations, we obtain

    |L(t)NE(t)N3(F3(t)+F4(t))|λ1E(t).

    Therefore,

    (Nλ1)E(t)+N3(F3(t)+F4(t))L(t)(N+λ1)E(t)+N3(F3(t)+F4(t)).

    By choosing N (depending on N1, N2, N3) sufficiently large, we obtain (4.16) with

    κ1=min{Nλ1,N3},κ2=max{N+λ1,N3}.

    Now, by differentiating L(t), recalling (3.2), (4.1), (4.10), (4.12) and (4.14), and setting ε1=1N1, we arrive at

    L(t)[Nμ1N1ρ12(3+h(t))3ρ14N2N3˜H1(0)]10φ2tdxN3˜H1(0)10ψ2tdxkN210(φx+ψ)2dx(kN1N2ρ2)10φ2txdx[ρ1ρ2kNN21k24N3˜H1(0)]10φ2ttdx(N2b1)10ψ2xdx(N3ρ1¯h2N1)(hφtt)(t)[N3ρ1¯h2N1ρ1¯h2N2](hφt)(t)+(ρ12N)(hφt)(t)+(ρ1ρ2kN)(hφtt)(t)N3ζ(F3(t)+F4(t)). (4.18)

    At this point, we need to choose our constants very carefully. First, we choose N2 large enough such that

    N2b1>0.

    Once N2 is fixed, we take N1 large enough so that

    kN1N2ρ2>0.

    After that, we pick N3 large enough such that

    {N3ρ1¯h2N1ρ1¯h2N2>0, andN3ρ1¯h2N1>0.

    Finally, we select N large enough so that

    {Nμ1N1ρ12(3+h(t))3ρ14N2N3˜H1(0)>0,andρ1ρ2kNN21k24N3˜H1(0)>0.

    With all these choices, we obtain (4.17).

    We are now ready to state and prove the following exponential stability result.

    Lemma 8. Let (φ,ψ) be a solution of (1.9)–(1.10), and assume that (H1)–(H2) hold. Then, there exist two positive constants τ1 and τ2 such that

    E(t)τ2eτ1t, t0. (4.19)

    Proof. By using (4.17) and the right side of (4.16), we get

    L(t)C1L(t)+C2h(t), (4.20)

    where C1=β1κ2>0.

    Multiplying (4.20) by exp(C1t), we obtain

    ddt(L(t)exp(C1t))C2exp(C1t)h(t). (4.21)

    Integrating over (0,T) the inequation (4.21) and choosing C1 smaller than ς, we have

    L(T)exp(C1T)L(0)+C2T0exp(ςt)h(t)dtL(0)+C20exp(ςt)h(t)dt.

    Thanks to the hypothesis (H2), we can write

    L(T)C3exp(C1T),C3>0,

    which yields the serial result (4.19), using the fact that F3(t),F4(t) are positive and the other side of the equivalence relation (4.16) again. The proof is complete.

    In this section, we will solve numerically the system (1.9)–(1.10) in the one-dimension domain. For that, we use the classic finite difference method for the spatial and temporal discretization. Furthermore, in order to verify the asymptotic behavior of the solution of the discretized problem, we give an example in which the numerical experiment shows that the discrete energy En decays exponentially for different choices of the system parameters. Let us introduce the functions ˆφ=φt, and for any M,NN, we introduce the nets

    ΩN={xi=iΔx,i=0,...,N+1 where Δx=1N+1},
    ΓM={tn=nΔt,n=0,...,M+1 where Δt=TM+1}.

    Our problem is to find (ˆφ,ψ) satisfying the following numerical scheme:

    {ρ1Δt(ˆφniˆφn1i)=k(Δx)2(φni+12φni+φni1)+k2Δx(ψni+1ψni1)μ1ˆφniρ1(Δt)2tn0h(tns)(ˆφniˆφn1i)ds+h(tn)φ1(xi)ρ22ΔxΔt(ˆφni+1ˆφni1)=ρ22ΔxΔt(ˆφn1i+1ˆφn1i1)+b(Δx)2(ψni+12ψni+ψni1)k2Δx(φni+1φni1)kψni, (5.1)

    where sn=nΔsn, n=0,...,M+1 with Δsn=tnM+1, φni=φ(xi,tn), ˆφni=φt(xi,tn), ψni=ψ(xi,tn), ˆψni=ψt(xi,tn), for all i=1,...,N and n = 1, ..., M . To simplify our numerical calculations in our scheme, we consider the discrete boundary conditions given by

    \begin{equation} \left\{ \begin{array}{l} \psi _{0}^{n} = \psi _{N+1}^{n} = \varphi _{N+1}^{n} = \varphi _{0}^{n} = 0, \end{array} \right. \end{equation} (5.2)

    and initial conditions

    \begin{equation} \psi _{i}^{0} = \psi _{0}\left( x_{i}\right) , \;\hat{\psi}_{i}^{0} = \psi _{1}\left( x_{i}\right) , \;\varphi _{i}^{0} = \varphi _{0}\left( x_{i}\right), \;\hat{\varphi}_{i}^{0} = \varphi _{1}\left( x_{i}\right), \end{equation} (5.3)

    where

    \begin{equation*} \varphi _{i}^{n} = \varphi _{i}^{n-1}+\Delta t\hat{\varphi}_{i}^{n}, \; \psi _{i}^{n} = \psi _{i}^{n-1}+\Delta t\hat{\psi}_{i}^{n}, \end{equation*}

    for all i = 1, ..., N and n = 1, ..., M .

    Note that to find \left(\hat{\varphi}, \psi \right) , we need to solve two coupled systems of algebraic equations. So, to solve the problem (5.1)–(5.3) at each time step, we propose to consider the following fixed-point algorithm that is stopped when the difference between two successive iterations becomes smaller than a given tolerance \varepsilon .

    \begin{equation} \left\{ \begin{array}{l} \hat{\varphi}_{i}^{n, l} = \dfrac{k}{c_{1}\left( \Delta x\right) ^{2}}\left( \varphi _{i+1}^{n, l-1}-2\varphi _{i}^{n, l-1}+\varphi _{i-1}^{n, l-1}\right) + \dfrac{k}{c_{1}2\Delta x}\left( \psi _{i+1}^{n, l-1}-\psi _{i-1}^{n, l-1}\right) \\ +\dfrac{\rho _{1}}{c_{1}\Delta t}\hat{\varphi}_{i}^{n-1}-\dfrac{\rho _{1}}{ \left( \Delta t\right) ^{2}}\int_{0}^{t_{n}}h\left( t_{n}-s\right) \left( \hat{\varphi}_{i}^{n^{\prime }, l-1}-\hat{\varphi}_{i}^{n^{\prime }-1, l-1}\right) ds+h\left( t_{n}\right) \varphi _{1}\left( x_{i}\right) \text{, } \\ \dfrac{b}{\left( \Delta x\right) ^{2}}\psi _{i+1}^{n, l}-\left( 2\dfrac{b}{ \left( \Delta x\right) ^{2}}+k\right) \psi _{i}^{n, l}+\dfrac{b}{\left( \Delta x\right) ^{2}}\psi _{i-1}^{n, l} = \dfrac{-\rho _{2}}{2\Delta x\Delta t} \left( \hat{\varphi}_{i+1}^{n, l}-\hat{\varphi}_{i-1}^{n, l}\right) \\ +\dfrac{\rho _{2}}{2\Delta x\Delta t}\left( \hat{\varphi}_{i+1}^{n-1, l}-\hat{ \varphi}_{i-1}^{n-1, l}\right) +\dfrac{k}{2\Delta x}\left( \varphi _{i+1}^{n, l}-\varphi _{i-1}^{n, l}\right) \text{, } \end{array} \right. \end{equation} (5.4)

    with

    \begin{equation*} \left\{ \begin{array}{l} \varphi _{i}^{n, 0} = \varphi _{i}^{n-1}, \;\psi _{i}^{n, 0} = \psi _{i}^{n-1}, \;\varphi _{i}^{n, l} = \varphi _{i}^{n-1}+\Delta t\hat{\varphi }_{i}^{n, l}, \\ \psi _{i}^{n, l} = \psi _{i}^{n-1}+\Delta t\hat{\psi}_{i}^{n, l}, \end{array} \right. \end{equation*}

    for all i = 1, ..., N and n = 1, ..., M and l = 1, 2...

    To approximate the continuous energy (3.1), we use the trapezoidal quadrature formula to compute the integral I = \int_{0}^{1}f(x)dx :

    \begin{equation*} I_{N} = \sum\limits_{i = 1}^{N}a_{i}f(x_{i})\approx I, \end{equation*}

    where the weights \left\{ a_{i}\right\} _{i = 1}^{N} are given by a_{1} = a_{N} = \dfrac{K}{2} , for i = 2, 3, ..., N-1, a_{i} = K with K = \dfrac{1 }{N}.

    The same quadrature formula is used to evaluate the integral with respect to s at each time step t_{n}. Therefore, the discrete energy formula is given by

    \begin{align} E(t_{n})& \approx J^{n} = \frac{1}{2}\sum\limits_{i = 1}^{N}a_{i}[\rho _{1}\left( \hat{ \varphi}_{i}^{n}\right) ^{2}\ +k\left( \left( \varphi _{x}\right) _{i}^{n}+\psi _{i}^{n}\right) ^{2}+\frac{\rho _{2}\rho _{1}}{k}\left( \left( \hat{\varphi}_{t}\right) _{i}^{n}\right) ^{2} \\ & +\rho _{2}\left( \left( \varphi _{tx}\right) _{i}^{n}\right) ^{2}+b\left( \left( \psi _{x}\right) _{i}^{n}\right) ^{2}]+\rho _{1}(h_{n}\ast \hat{ \varphi}_{i}^{n}) \\ & +\frac{\rho _{2}\rho _{1}}{k}(h_{n}\ast \left( \hat{\varphi}_{t}\right) _{i}^{n}), \end{align} (5.5)

    with

    \begin{gather*} \hat{\varphi}_{i}^{n} = \varphi _{t}\left( x_{i}, t_{n}\right) , \;\left( \hat{\varphi}_{t}\right) _{i}^{n} = \dfrac{1}{\Delta t}\left( \hat{\varphi} _{i}^{n+1}-\hat{\varphi}_{i}^{n}\right) , \\ \left( \hat{\varphi}_{t}\right) _{i}^{n} = \dfrac{1}{\Delta t}\left( \hat{ \varphi}_{i}^{n+1}-\hat{\varphi}_{i}^{n}\right) , \end{gather*}
    \begin{equation*} \left( \varphi _{x}\right) _{i}^{n} = \frac{\varphi _{i+1}^{n}-\varphi _{i-1}^{n}}{2\Delta x}, \;\left( \psi _{x}\right) _{i}^{n} = \frac{\psi _{i+1}^{n}-\psi _{i-1}^{n}}{2\Delta x}\text{ and }\left( \varphi _{tx}\right) _{i}^{n} = \frac{\hat{\varphi}_{i+1}^{n}-\hat{\varphi}_{i-1}^{n}}{ 2\Delta x}. \end{equation*}

    Next, we describe the following numerical example:

    Example 1. For this numerical test, we choose the following different values for the coefficients of the system:

    \begin{equation*} \rho _{1} = 1.1, \;\rho _{2} = 10, \;k = 0.01, \;\mu _{1} = 10, \text{ }b = 1.5. \end{equation*}

    We run our code for the following discretization parameters: N = 100, M = 200 , T = 1 . We take \varepsilon = 10^{-5} . Also, we choose the following initial conditions:

    \begin{eqnarray*} \varphi _{0}\left( x\right) & = &\frac{17}{20}x^{2}e^{-2x}, \;\varphi _{1}\left( x\right) = \frac{1}{4}\left( x^{3}-\frac{2}{3}x^{2}\right) , \text{ }h(t) = \exp (-4t), \\ \psi _{0}\left( x\right) & = &x^{3}\left( 1-x\right) ^{2}, \;\varphi _{2}\left( x\right) = x^{3}-\frac{2}{3}x^{2}. \end{eqnarray*}

    Here are the evolution in time of the solutions \varphi and \psi , the discrete energy and the evolution with respect to x of \varphi throughout time.

    In the above numerical example, the graphics presented in Figures 1 and 2 show the evolution in time of the approximation solutions \varphi and \psi on the interval \left[0, T\right] , for different choices of the system parameters and of the initial data. Furthermore, Figures 3 and 4 show that the approximate energy (5.5) decays in an exponential manner, which confirms the main theoretical result obtained and the evolution of \varphi with respect to x throughout time.

    Figure 1.  Evolution in time of the function \varphi .
    Figure 2.  Evolution in time of the function \psi .
    Figure 3.  Evolution in time of the discrete energy.
    Figure 4.  Evolution in x of the function \varphi throughout time.

    In this work we investigated the sufficient conditions on the kernel of the neutral delay term to assure the exponential stability of solutions of the Bresse-Timoshenko system subject to this complementary control based on the multipliers technique to construct a suitable Lyapunov functional that allows us to estimate the energy of the considered system. As a future work, we propose to consider the same problem without dissipation due to the frictional damping, and we will search for additional conditions on the kernel of neutral delay term from which the energy can be decreased in an exponential manner.

    The authors declare they have not used Artificial Intelligence (AI) tools in the creation of this article.

    This research has been funded by the Deputy for Research Innovation, Ministry of Education through Initiative of Institutional Funding at University of Ha'il-Saudi Arabia through project number IFP-22142.

    The authors declare that they have no competing interests.



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