Research article Special Issues

Hilfer iterated-integro-differential equations and boundary conditions

  • Received: 26 January 2022 Revised: 11 April 2022 Accepted: 21 April 2022 Published: 26 May 2022
  • MSC : 34A08, 34B15

  • In this research, a new class of fractional boundary value problems is introduced and studied, which combine Hilfer fractional derivatives with iterated Riemann-Liouville and Hadamard fractional integrals boundary conditions. Existence and uniqueness results are obtained by using standard tools from fixed point theory. The obtained results are well illustrated by numerical examples.

    Citation: Sunisa Theswan, Ayub Samadi, Sotiris K. Ntouyas, Jessada Tariboon. Hilfer iterated-integro-differential equations and boundary conditions[J]. AIMS Mathematics, 2022, 7(8): 13945-13962. doi: 10.3934/math.2022770

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  • In this research, a new class of fractional boundary value problems is introduced and studied, which combine Hilfer fractional derivatives with iterated Riemann-Liouville and Hadamard fractional integrals boundary conditions. Existence and uniqueness results are obtained by using standard tools from fixed point theory. The obtained results are well illustrated by numerical examples.



    Fractional calculus and fractional differential equations have been of great interest, because they describe many real world processes from applied sciences (biology, physics, chemistry, economics, ecology, control theory and so on) more accurately, as compared to classical order differential equations. For the basic theory on the topic see the monographs as [1,2,3,4,5,6,7,8], Many researchers have studied boundary value problems for fractional differential equations, see [9,10,11,12,13,14,15,16,17,18] and references cited therein. In the literature there are several kinds of fractional derivatives, such as Riemann-Liouville, Caputo, Erfely-Kober, Hadamard, Hilfer, Katugampola, to name a few. Hilfer fractional derivative [19] extends both Riemann-Liouville and Caputo fractional derivatives. Many applications of Hilfer fractional differential equations can be found in many fields of mathematics, physics, etc. (see [20,21,22,23,24,25]). The study of boundary value problems for Hilfer-fractional differential equations of order in (1,2], and nonlocal boundary conditions were initiated in [26] by studying the boundary value problem of the form:

    {HDα,βu(z)=h(z,u(z)),z[c,d],1<α2,0β1,u(c)=0,u(d)=mi=1εiIϕiu(ξi),ϕi>0,εiR,ξi[c,d], (1.1)

    where HDα,β is the Hilfer fractional derivative of order α, and parameter β, h:[c,d]×RR is a continuous function, mZ+, c0, and Iϕi is the Riemann-Liouville fractional integral of order ϕi,i=1,2,,m. By using well known fixed point theorems, existence and uniqueness results were proved.

    Recently, in [27], the authors initiated the study of boundary value problems containing sequential fractional derivatives of mixed Riemann-Liouville and Hadamard-Caputo type, subjected to iterated fractional integral boundary conditions of the form:

    {RLDp(HCDqx)(t)=f(t,x(t)),t[0,T],HCDqx(0)=0,x(T)=λ1˜R(αn,βn1,,β1,α1)x(ξ1)+λ2ˆR(δm,γm,,δ1,γ1)x(ξ2), (1.2)

    where RLDp and HCDq are respectively the fractional derivatives of Riemann-Liouville and Hadamard-Caputo type of orders p and q, 0<p, q<1, f:[0,T]×RR is a continuous function, m,nZ+, the given constants λ1,λ2R,

    ˜R(αn,,β1,α1)x(t)=RLIαnHIβn1RLIαn1HIβn2HIβ2RLIα2HIβ1RLIα1x(t)

    and

    ˆR(δm,,δ1,γ1)x(t)=HIδmRLIγmHIδm1RLIγm1HIδ2RLIγ2HIδ1RLIγ1x(t)

    are the iterated fractional integrals, where t=ξ1 and t=ξ2, respectively, ξ1,ξ2(0,T), RLIϕ and HIψ are the fractional integrals of Riemann-Liouville and Hadamard type of orders ϕ,ψ>0, respectively, ϕ{α(),γ()}, ψ{β(),δ()}. Existence and uniqueness results are established by applying a variety of fixed point theorems.

    Our goal in this paper, inspired by the above-mentioned papers, is to enrich the new research topic concerning boundary value problems for Hilfer fractional iterated-integro-differential equations, subjected to iterated boundary conditions. Thus, in this paper, we investigate the qualitative theory of existence to a nonlinear Hilfer iterated-integro-differential equation with iterated Riemann-Liouville and Hadamard fractional integrals of the form:

    {(HDα,βx)(t)+λ1(HDα1,βx)(t)=f(t,x(t),R(δm,,δ1)x(t)),t[0,T],x(0)=0,x(T)=λ2R(μn,,μ1)x(ξ),ξ(0,T), (1.3)

    where HDα,β is the fractional derivative of Hilfer of order α, 1<α<2, 0<β<1, γ=α+(2α)β, λ1,λ2R, f:[0,T]×R×RR is a nonlinear continuous function, m,nN and

    R(ϕρ,,ϕ1)x(t)={HIϕρIϕρ1HIϕρ2Iϕρ3HIϕ4Iϕ3HIϕ2Iϕ1x(t),ρ is even,IϕρHIϕρ1Iϕρ2HIϕρ3HIϕ4Iϕ3HIϕ2Iϕ1x(t),ρ is odd,

    is the iterated fractional integrals of mixed Riemann-Liouville and Hadamard type, ϕ{δ,μ}, ρ{m,n}. Iϕ(), HIϕ() are defined as fractional integrals of Riemann-Liouville and Hadamard type of order ϕ()>0, respectively.

    Notice that: The iterated fractional integrals, R(ϕρ,,ϕ1)(), can be reduced to a single Riemann-Liouville fractional integral when ρ=1 as R(ϕ1)()=Iϕ1() and to Hadamard integral integral when ρ=2, ϕ1=0 as R(ϕ2,0)()=HIϕ2().

    In addition, we are now considering some special cases of the Hilfer iterated-integro-differential equation that appeared in the first equation of problem (1.3). If we put α=2, β=0, f(u,v,w)=u+v+w and the iterated integral term R(δm,,δ1)x=R(δ1)x, then we have

    x(t)+λ1x(t)=t+x(t)+1Γ(δ1)t0(ts)δ11x(s)ds,

    which is a well known integro-differential equation. If the iterated integral term presents R(δm,,δ1)x=R(δ2,0)x, then we obtain a new integro-differential equation with Hadamard integral as

    x(t)+λ1x(t)=t+x(t)+1Γ(δ2)t0(logetloges)δ21x(s)dss.

    By replacing the iterated integral term R(δm,,δ1)x=R(δ2,δ1)x, we get

    x(t)+λ1x(t)=t+x(t)+1Γ(δ1)Γ(δ2)t0s0(logetloges)δ21(sr)δ11x(r)drdss,

    which is an integro-differential equation with a mixed kernel of logarithm and power functions. Another one kernel can be interchanged by replacing R(δm,,δ1)x=R(δ3,δ2,0)x as

    x(t)+λ1x(t)=t+x(t)+1Γ(δ2)Γ(δ3)t0s0(ts)δ31(logesloger)δ21x(r)drrds.

    Both of the double integrals in the above two equations can not be reduced to a single integral because of differences of the kernels. These show some significance of studying the new iterated-integro-differential equation in (1.3), which is a new novel in literature.

    By using standard tools from fixed point theory we establish existence and uniqueness results for the boundary value problem (1.3). More precisely, the existence is proved via Leray-Schauder nonlinear alternative, while the existence of a unique solution is established by using Banach's contraction mapping principle.

    The remaining part of this manuscript is organized as follows: Section 2 contain some basic notations and definitions from fractional calculus. Section 3 presents the main results, while Section 4 contains illustrative examples. A brief conclusion closes the paper.

    In this section, we introduce some notations and definitions of fractional calculus in the sense of Riemann-Liouville, Hadamard and also Hilfer differential operators. Moreover, we present some lemmas that needed in main results later.

    Definition 2.1. [2] The Riemann-Liouville fractional integral of oreder α>0 to a function f:[0,)R is defined by

    (Iαf)(t)=1Γ(α)t0(ts)α1f(s)ds,0<t<, (2.1)

    where Γ() is the Euler Gamma function, provided that the right-hand side is point-wise defined on (0,).

    Definition 2.2. [2] The Hadamard fractional integral of oreder α>0 is defined as

    (HIαf)(t)=1Γ(α)t0(logts)α1f(s)dss,0<t<, (2.2)

    where log()=loge(), provided the integral exists.

    Definition 2.3. [2] The Riemann-Liouville fractional derivative of order α for a function f on [0,) is defined as follows:

    (RDαf)(t)={1Γ(nα)dndtnt0(ts)nα1f(s)ds,0n1<α<nN,dndtnf(t),α=nN,

    provided that the right-hand side is point-wise defined on (0,).

    Definition 2.4. [2] The Caputo fractional derivative of order α of the nth-derivatives function f is given on [0,) by

    (CDαf)(t)={1Γ(nα)t0(ts)nα1dndsnf(s)ds,0n1<α<nN,dndtnf(t),α=nN,

    provided that the right-hand side is point-wise defined on (0,).

    Definition 2.5. [19] The Hilfer fractional derivative of order α with parameter β for a function f on [0,) is defined by

    (HDα,βf)(t)=Iβ(nα)(ddt)nI(1β)(nα)f(t), (2.3)

    where 0n1<α<n, and 0β1 for t>0.

    The Hilfer fractional derivative can be reduced to Riemann-Liouville and Caputo operators depending on the parameter β(0β1). If β=0, (2.3) is reduced to the Riemann-Liouville fractional derivative as

    (HDα,0f)(t)=(RDαf)(t),t[0,), (2.4)

    while if β=1, (2.3) is reduced to the Caputo fractional derivative by

    (HDα,1f)(t)=(CDαf)(t),t[0,). (2.5)

    Lemma 2.1. [28] Let fL1(0,T), n1<αn, nN, j=0,1,,n1, 0β1, γ=α+nβαβ, I(nγ)Cn([0,T],R). Then

    (IαHDα,βf)(t)=f(t)n1j=0tj(nγ)Γ(j(nγ)+1)limt0+dkdtk(Inγf)(t). (2.6)

    Lemma 2.2. [2] Let α>0 and m>0 be given constants. Then the following fomula

    HIαtm=mαtm (2.7)

    holds.

    Lemma 2.3. [27] Let m>1, μi>0,i=1,2,,n, be constants. Then the following equation holds:

    R(μn,,μ1)tm=Γ(m+1)n2i=1(m+ik=1μ2k1)μ2iΓ(m+1+n2k=1μ2k1)tm+n2k=1μ2k1. (2.8)

    For m=0 in Eq (2.8), we get

    R(μn,,μ1)1=n2i=1(ik=1μ2k1)μ2iΓ(1+n2k=1μ2k1)tn2k=1μ2k1, (2.9)

    where n, n are the ceiling and floor functions of n, respectively.

    Now, we present some examples of our notations. The ceiling and floor functions of a number 2.4 are shown as 2.4=3 and 2.4=2, respectively. The odd and even iterations of Riemann-Liouville and Hadamard fractional integrals of functions f(t)=t3 and f(t)=1, respectively, can be seen as

    R(45,16,15,14,34,13,12)t3=Γ(3+1)(3+12)13(3+12+34)14(3+12+34+15)16Γ(3+1+12+34+15+45)×t3+12+34+15+450.0116×t5.25

    and

    R(74,12,13,34)1=(34)13(34+12)74Γ(1+34+12)×t34+120.6574×t1.25.

    Let f(t)=t be a given function. The iterations of Riemann-Liouville and Hadamard fractional integrals and its consecutive iterations can be considered as follows: f(t)=(I14I13I12s)(t) (RRR), g(t)=(HI14HI13HI12s)(t) (HHH), h(t)=(I14HI13I12s)(t) (RHR) and q(t)=(HI14I13HI12s)(t) (HRH). The graphs of functions f(t), g(t), h(t) and q(t) for t[0,4] are shown in Figure 1.

    Figure 1.  The graphs of functions f(t), g(t), h(t) and q(t).

    The next lemma concerns a linear variant of the boundary value problem (1.3) and is useful to transform the boundary value problem (1.3) into an integral equation.

    Lemma 2.4. Let 1<α<2, 0<β<1, γ=α+(2α)β, λ1,λ2R, be constants and h:[0,T]R be a continuous function and

    Ω:=Tγ1Γ(γ)λ2Γ(γ+n2k=1μ2k1)n2i=1(γ1+ik=1μ2k1)μ2i×ξγ1+n2k=1μ2k10.

    Then the Hilfer iterated boundary value problem

    {(HDα,βx)(t)+λ1(HDα1,βx)(t)=h(t),t[0,T],x(0)=0,x(T)=λ2R(μn,,μ1)x(ξ),ξ(0,T), (2.10)

    is equivalent the following integral equation:

    x(t)=tγ1ΩΓ(γ)[λ1λ2R(μn,,μ1+1)x(ξ)+λ2R(μn,,μ1+α)h(ξ)+λ1I1x(T)Iαh(T)]λ1I1x(t)+Iαh(t). (2.11)

    Proof. Operating Riemann-Liouville fractional integral of order α to both sides of Eq (2.10), we have

    Iα(HDα,βx)(t)+λ1Iα(HDα1,βx)(t)=Iαh(t), (2.12)

    from which, by using Lemma 2.1, we get

    x(t)c1Γ(γ)tγ1c2Γ(γ1)tγ2+λ1I1x(t)=Iαh(t),

    where c1=(I1γx)(0) and c2=(I2γx)(0). From the first boundary condition x(0)=0, we have c2=0. Then we get

    x(t)=c1Γ(γ)tγ1λ1I1x(t)+Iαh(t). (2.13)

    Next, by using Lemma 2.3, we obtain

    λ2R(μn,,μ1)x(ξ)=c1λ2Γ(γ)R(μn,,μ1)ξγ1λ1λ2R(μn,,μ1+1)x(ξ)+λ2R(μn,,μ1+α)h(ξ)=c1λ2Γ(γ)(Γ(γ)n2i=1(γ1+ik=1μ2k1)μ2iΓ(γ+n2k=1μ2k1)×ξγ1+n2k=1μ2k1)λ1λ2R(μn,,μ1+1)x(ξ)+λ2R(μn,,μ1+α)h(ξ).

    Applying the second boundary condition x(T)=λ2R(μn,,μ1)x(ξ) with x(T)=c1Γ(γ)Tγ1λ1I1x(T)+Iαh(T), we have

    c1Γ(γ)Tγ1c1λ2(n2i=1(γ1+ik=1μ2k1)μ2iΓ(γ+n2k=1μ2k1)×ξγ1+n2k=1μ2k1)=λ1λ2R(μn,,μ1+1)x(ξ)+λ2R(μn,,μ1+α)h(ξ)+λ1I1x(T)Iαh(T),

    form which we get

    c1=1Ω[λ1λ2R(μn,,μ1+1)x(ξ)+λ2R(μn,,μ1+α)h(ξ)+λ1I1x(T)Iαh(T)].

    Incerting the value of c1 in (2.13), we obtain the solution (2.11). The converse of this lemma can be proved by direct computation. The proof is finished.

    Let C=C([0,T],R) be a Banach space of all continuous function from [0,T] to R endowed with the supremum norm defined as

    x=supt[0,T]|x(t)|.

    In view of Lemma 2.4, we transform the problem (1.3) into a fixed point problem x=Ax, where A:CC is defined by

    (Ax)(t)=tγ1ΩΓ(γ)[λ1λ2R(μn,,μ1+1)x(ξ)+λ2R(μn,,μ1+α)f(ξ,x(ξ),R(δm,,δ1)x(ξ))+λ1I1x(T)Iαf(T,x(T),R(δm,,δ1)x(T))]λ1I1x(t)+Iαf(t,x(t),R(δm,,δ1)x(t)). (3.1)

    For computational convenience, we set

    Λ0:=1+1Λ3m2i=1(ik=1δ2k1)δ2i×Tm2k=1δ2k1, (3.2)
    Λ1:=Γ(γ+n2k=1μ2k1),Λ2:=Γ(1+α+n2k=1μ2k1),Λ3:=Γ(1+m2k=1δ2k1),Λ4:=Γ(2+n2k=1μ2k1),Φ1:=|λ2|Tγ1|Ω|Γ(γ)Λ2n2i=1(α+ik=1μ2k1)μ2i×ξα+n2k=1μ2k1+Tγ+α1|Ω|Γ(γ)Γ(α+1)+TαΓ(α+1), (3.3)
    Φ2:=|λ1||λ2|Tγ1|Ω|Γ(γ)Λ4n2i=1(1+ik=1μ2k1)μ2i×ξ1+n2k=1μ2k1+|λ1|Tγ|Ω|Γ(γ)+λ1T. (3.4)

    Now we present our main results for the boundary value problem (1.3). Our existence result is based on Leray-Schauder's nonlinear alternative [29].

    Theorem 3.1. Let f:[0,T]×R×RR be a continuous function. Assume that Φ2<1 where Φ2 is defined by (3.4). In addition, we suppose that:

    (H1) There exist a function pC([0,T],R+) and a continuous nondecreasing function ψ:[0,)[0,) which is subhomogeneous (that is, ψ(μx)μψ(x), for all μ1 and xC), such that

    |f(t,u,v)|p(t)ψ(|u|+|v|)foreach(t,u,v)[0,T]×R2;

    (H2) There exists a constant M>0, such that

    (1Φ2)MpΛ0ψ(M)Φ1>1, (3.5)

    where Λ0 and Φ1 are defined in (3.2) and (3.3) respectively.

    Then there exists at least one solution of the boundary value problem (1.3) on [0,T].

    Proof. Leray-Schauder's nonlinear alternative will be used to prove that the operator A, defined by (3.1), has a fixed point. Firstly, we shall show that A is continuous. Let {xq} be a sequence such that xqx as q in C. Then, for each t[0,T],

    |(Axq)(t)(Ax)(t)|Tγ1|Ω|Γ(γ)[|λ1||λ2|R(μn,,μ1+1)|xqx|(ξ)+|λ2|R(μn,,μ1+α)|f(,xq,R(δm,,δ1)xq)(ξ)f(,x,R(δm,,δ1)x)(ξ)|+|λ1|I1|xqx|(T)+Iα|f(,xq,R(δm,,δ1)xq)f(,x,R(δm,,δ1)x)|(T)]+|λ1|I1|xqx|(t)+Iα|f(,xq,R(δm,,δ1)xq)f(,x,R(δm,,δ1)x)|(t)Tγ1|Ω|Γ(γ)[|λ2|R(μn,,μ1+α)|f(,xq,R(δm,,δ1)xq)f(,x,R(δm,,δ1)x)|(ξ)+Iα|f(,xq,R(δm,,δ1)xq)f(,x,R(δm,,δ1)x)|(T)]+Iα|f(,xq,R(δm,,δ1)xq)f(,x,R(δm,,δ1)x)|(T)+Tγ1|Ω|Γ(γ)[|λ1||λ2|R(μn,,μ1+1)|xqx|(ξ)+|λ1|I1|xqx|(T)]+|λ1|I1|xqx|(T)|f(,xq,R(δm,,δ1)xq)f(,x,R(δm,,δ1)x)|(Tγ+α1|Ω|Γ(γ)Γ(α+1)+TαΓ(α+1)+|λ2|Tγ1|Ω|Γ(γ)Λ2n2i=1(α+ik=1μ2k1)μ2i×ξα+n2k=1μ2k1)+xqx[|λ1|Tγ|Ω|Γ(γ)+λ1T+|λ1||λ2|Tγ1|Ω|Γ(γ)Λ4n2i=1(1+ik=1μ2k1)μ2i×ξ1+n2k=1μ2k1].

    Since f is a continuous function, it implies that

    AxqAx0,q. (3.6)

    Next, we show that A maps bounded sets into bounded set in C. For any r>0, let Br:={xC:xr}. For convenience, putting ˜fx(t):=f(t,x(t),R(δm,,δ1)x(t)) and using (H1), we have that

    |˜fx(t)|p[ψ(|x(t)|+|R(δm,,δ1)x(t)|)]p[ψ(x+xR(δm,,δ1)(1))]=p[ψ(xΛ0)]pΛ0ψ(x),

    where Λ0 is defined by (3.2).

    Therefore, we obtain

    |(Ax)(t)|tγ1|Ω|Γ(γ)[|λ1||λ2|R(μn,,μ1+1)|x|(ξ)+|λ2|R(μn,,μ1+α)|˜fx|(ξ)+|λ1|I1|x|(T)+Iα|˜fx|(T)]+|λ1|I1|x|(t)+Iα|˜fx|(t)pΛ0ψ(x)(|λ2|Tγ1|Ω|Γ(γ)(R(μn,,μ1+α)1)(ξ)+Tγ1|Ω|Γ(γ)(Iα1)(T)+(Iα1)(T))+x(|λ1||λ2|Tγ1|Ω|Γ(γ)(R(μn,,μ1+1)1)(ξ)+|λ1|Tγ1|Ω|Γ(γ)I1(1)(T)+|λ1|I1(1)(T))pΛ0ψ(x)[|λ2|Tγ1|Ω|Γ(γ)Λ2n2i=1(α+ik=1μ2k1)μ2i×ξα+n2k=1μ2k1+Tγ+α1|Ω|Γ(γ)Γ(α+1)+TαΓ(α+1)]+x[|λ1|Tγ|Ω|Γ(γ)+λ1T+|λ1||λ2|Tγ1|Ω|Γ(γ)Λ4n2i=1(1+ik=1μ2k1)μ2i×ξ1+n2k=1μ2k1]=pΛ0ψ(x)Φ1+xΦ2,

    and consequently

    AxpΛ0ψ(r)Φ1+rΦ2,

    which means that the set (ABr) is uniformly bounded.

    Next, we show that the operator A maps bounded sets into equicontinuous sets of C. Let t1,t2[0,T] with t1<t2 and xBr. Then we get

    |(Ax)(t2)(Ax)(t1)|1Γ(α)|t10[(t2s)α1(t1s)α1]˜fx(s)ds+t2t1(t2s)α1˜fx(s)ds|+|λ1||I1x(t2)I1x(t1)|+(tγ12tγ11)||Ω|Γ(γ)(|λ1||λ2|R(μn,,μ1+1)|x|(ξ)+Iα|˜fx|(T)+|λ2|R(μn,,μ1+α)|˜fx|(ξ))+|λ1||Ω|Γ(γ)|tγ12I1x(t2)tγ11I1x(t1)|1Γ(α+1)pΛ0ψ(r)[2(t2t1)α+|tα2tα1|]+|λ1|r(t2t1)+r|Ω|Γ(γ)(|λ1|(tγ2tγ1)+(tγ12tγ11)Λ2|λ1||λ2|n2i=1(1+ik=1μ2k1)μ2i×ξ1+n2k=1μ2k1)+(tγ12tγ11)|Ω|Γ(γ)pΛ0ψ(r)(|λ2|Λ2n2i=1(α+ik=1μ2k1)μ2i×ξα+n2k=1μ2k1+TαΓ(α+1)).

    As t2t10, the right hand side of the above inequality tends to zero, independently of x, which implies that the set (ABr) is an equicontinuous set. Hence, we can conclude that (ABr) is relatively compact. By application of Arzelá-Ascoli theorem, the operator A is completely continuous.

    The result will follow from the Leray-Schauder's nonlinear alternative once we have proved the boundedness of the set of all solutions to the equations x=θAx for θ(0,1).

    Let x be a solution of (1.3). Then, for t[0,T], and following calculations similar to the second step above, we obtain

    |x(t)|=|θAx(t)||Ax(t)|pΛ0ψ(x)Φ1+xΦ2,

    which lends to

    xpΛ0ψ(x)Φ1+xΦ2,

    or

    (1Φ2)xpΛ0ψ(x)Φ11.

    In view of (H2), there exists a constant M>0 such that xM. Let us set

    K:={xC:x<M}.

    We see that the operator A:¯KC is continuous and completely continuous. From the choice of ¯K, there is no xK such that x=θAx for some θ(0,1). Consequently, by the nonlinear alternative of Leray-Schauder type, we deduce that the operator A has a fixed point x¯K, which is a solution of the problem (1.3). The proof is completed.

    Corollary 3.1. If the function ψ in (H1) is replaced by the following three special cases, then we obtain some interesting results.

    (i) If ψ(x)=Q, where Q>0, then the problem (1.3) has at least one solution with

    M>pΛ0QΦ11Φ2. (3.7)

    (ii) If ψ(x)=Gx+Q, where G,Q are positive constants and if Φ2+pΛ0Φ1G<1, then the boundary value problem (1.3) has at least one solution provided that

    M>pΛ0QΦ1(1Φ2pΛ0Φ1G). (3.8)

    (iii) If ψ(x)=Gx2+Q, where G,Q>0 and if 4GQp2Λ20Φ21(1Φ2)2<1, then the problem (1.3) has at least one solution with

    M(114GQp2Λ20Φ21(1Φ2)22(pΛ0GΦ11Φ2),1+14GQp2Λ20Φ21(1Φ2)22(pΛ0GΦ11Φ2)). (3.9)

    Now we prove an existence and uniqueness result via Banach's contraction mapping principle.

    Theorem 3.2. Assume that the nonlinear function f:[0,T]×R×RR satisfies the following condition:

    (H3) There exists a constant L>0 such that

    |f(t,x1,x2)f(t,y1,y2)|L(|x1y1|+|x2y2|),

    for each t[0,T] and xi,yiR, i=1,2.

    Then the boundary value problem (1.3) has a unique solution on [0,T], provided that

    LΛ0Φ1+Φ2<1, (3.10)

    where Λ0, Φ1 and Φ2 are defined by (3.2), (3.3) and (3.4), respectively.

    Proof. By using the benefit of Banach contraction mapping principle, we will show that the operator A, defined by (3.1), has a unique fixed point, which is the unique solution of the problem (1.3).

    Let N be a constant as N=supt[0,T]|f(t,0,0)|. Next, we give Br:={xC:xr} with r satisfies

    rNΦ11(LΛ0Φ1+Φ2). (3.11)

    Observe that Br is a bounded, closed, and convex subset of C. The proof is divided into two steps:

    Step Ⅰ. We show that (ABr)Br.

    From |˜fx(t)|:=|f(t,x(t),R(δm,,δ1)x(t))| and (H3), we obtain

    |˜fx(t)||˜fx(t)˜f0(t)|+|˜f0(t)|L(x(1+R(δm,,δ1)(1)))+N=LΛ0x+N.

    For xBr, we have

    |(Ax)(t)|Tγ1|Ω|Γ(γ)[|λ1||λ2|R(μn,,μ1+1)|x|(ξ)+|λ2|R(μn,,μ1+α)|˜fx|(ξ)+|λ1|I1|x|(T)+Iα|˜fx|(T)]+|λ1|I1|x|(t)+Iα|˜fx|(t)(LΛ0x+N)(|λ2|Tγ1|Ω|Γ(γ)(R(μn,,μ1+α)1)(ξ)+Tγ1|Ω|Γ(γ)(Iα1)(T)+(Iα1)(T))+x(|λ1||λ2|Tγ1|Ω|Γ(γ)(R(μn,,μ1+1)1)(ξ)+|λ1|Tγ1|Ω|Γ(γ)I1(1)(T)+|λ1|I1(1)(T))(LΛ0x+N)[|λ2|Tγ1|Ω|Γ(γ)Λ2n2i=1(α+ik=1μ2k1)μ2i×ξα+n2k=1μ2k1+Tγ+α1|Ω|Γ(γ)Γ(α+1)+TαΓ(α+1)]+x[|λ1|Tγ|Ω|Γ(γ)+λ1T+|λ1||λ2|Tγ1|Ω|Γ(γ)Λ4n2i=1(1+ik=1μ2k1)μ2i×ξ1+n2k=1μ2k1](LΛ0r+N)Φ1+rΦ2r,

    which implies that Axr. This confirms (ABr)Br.

    Step Ⅱ. We show that A:CC is a contraction operator.

    For any x, yC and for each t[0,T], we have

    |(Ax)(t)(Ay)(t)|Tγ1|Ω|Γ(γ)[|λ1||λ2|R(μn,,μ1+1)|xy|(ξ)+|λ2|R(μn,,μ1+α)|f(,x,R(δm,,δ1)x)f(,y,R(δm,,δ1)y)|(ξ)+|λ1|I1|xy|(T)+Iα|f(,x,R(δm,,δ1)x)f(,y,R(δm,,δ1)y)|(T)]+|λ1|I1|xy|(t)+Iα|f(,x,R(δm,,δ1)x)f(,y,R(δm,,δ1)y)|(t)Tγ1|Ω|Γ(γ)[|λ2|R(μn,,μ1+α)|f(,x,R(δm,,δ1)x)f(,y,R(δm,,δ1)y)|(ξ)+Iα|f(,x,R(δm,,δ1)x)f(,y,R(δm,,δ1)y)|(T)]+Iα|f(,x,R(δm,,δ1)x)f(,y,R(δm,,δ1)y)|(T)+Tγ1|Ω|Γ(γ)[|λ1||λ2|R(μn,,μ1+1)|xy|(ξ)+|λ1|I1|xy|(T)]+|λ1|I1|xy|(T)LΛ0xy[Tγ+α1|Ω|Γ(γ)Γ(α+1)+TαΓ(α+1)+|λ2|Tγ1|Ω|Γ(γ)Λ2n2i=1(α+ik=1μ2k1)μ2i×ξα+n2k=1μ2k1]+xy[|λ1|Tγ|Ω|Γ(γ)+λ1T+|λ1||λ2|Tγ1|Ω|Γ(γ)Λ4n2i=1(1+ik=1μ2k1)μ2i×ξ1+n2k=1μ2k1]=(LΛ0Φ1+Φ2)xy.

    Thus, we obtain the relation that

    AxAy(LΛ0Φ1+Φ2)xy.

    Since LΛ0Φ1+Φ2<1, the operator A is a contraction. Therefore, by applying Banach contraction mapping principle, the operator A has a fixed point, which implies that the boundary problem (1.3) has a unique solution on [0,T]. The proof is completed.

    Example 4.1. Consider the following boundary value problem containing Hilfer fractional derivative and iterated integrals as

    {(HD32,12x)(t)+19(HD12,12x)(t)=f(t,x(t),(R(98,27,35,73)x)(t)),t[0,134],x(0)=0,x(134)=115R(74,54,16,12,13)x(65). (4.1)

    Here, α=3/2, T=13/4, β=1/2, λ1=1/9, m=4, δ1=7/3,δ2=3/5,δ3=2/7,δ4=9/8, λ2=1/15, ξ=6/5, n=5, μ1=1/3, μ2=1/2, μ3=1/6, μ4=5/4, μ5=7/4, and

    R(98,27,35,73)x(t)=HI98I27HI35I73x(t),R(74,54,16,12,13)x(65)=I74HI54I16HI12I13x(65).

    From the given data, we find Ω2.6192, Λ01.4925, Φ10.0034 and Φ20.0021.

    (ⅰ) Let the function f(t,,) in (4.1) be given by

    f(t,x,R(δm,,δ1)x)=1(t+20)2[et2(x30|x|29+2)+et2(|R(98,27,35,73)x|271+(R(98,27,35,73)x)26)+1]. (4.2)

    By direct computation, we have

    |f(t,u,v)|et(t+20)2[12(|u|+|v|)+1]:=p(t)ψ(|u|+|v|),

    which yields that (H1) is satisfied when p(t)=et(t+20)2 and ψ(y)=y2+1. Therefore, there exists a constant M>0.9 that satisfies (H2). By Theorem 3.1, the boundary value problem (4.1), with f defined by (4.2), has at least one solution on [0,134].

    (ⅱ) If f:[0,13/4]×R×RR is defined by

    f(t,x,R(δm,,δ1)x)=cos2πt2(t+70)[2(x+R(98,27,35,73)x)2+1], (4.3)

    then we have

    |f(t,u,v)|12(t+70)[2(u+v)2+1].

    We choose p(t)=12(t+70) and ψ(y)=2y2+1. Then p=1/140, G=2 and Q=1. Hence, the inequality 4GQp2Λ20Φ21(1Φ2)20.9494<1 holds. Therefore, by Corollary 1 (iii), the boundary value problem (4.1), with f defined by (4.3), has at least one solution on [0,134].

    (ⅲ) Assume the function f:[0,13/4]×R×RR is defined by

    f(t,x,R(δm,,δ1)x)=et2(t+25)2[2x2+|x|1+2|x|+R(98,27,35,73)x]+14.

    It is obvious that

    |f(t,x1,x2)f(t,y1,y2)|et2(t+25)2(|x1y1|+|x2y2|) (4.4)
    1625(|x1y1|+|x2y2|). (4.5)

    Thus, (H3) is satisfied with L=1625. By the given data we can compute that LΛ0Φ1+Φ20.7475<1. Therefore, by Theorem 3.2, the boundary value problem (4.1), with f defined by (4.4), has a unique solution on [0,134].

    Example 4.2. The functions y(t)=(t6)4, t[0,4] and x(t)=t3, t[0,3], are analytic solutions of the following boundary value problems with iterated fractional integral (RHR) of the form:

    { (HD32,12y)(t)=136R(14,12,54)y14(t),t[0,4],y(0)=0,y(4)=1050I34HI12I94y(2), (4.6)

    and (HRH):

    { (HD32,12x)(t)=18320R(320,13,720)x13(t),t[0,3],x(0)=0,x(3)=43Γ(358)HI18I38HI12x(32), (4.7)

    respectively.

    Indeed, by direct computations, we have

    (HD32,12y)(t)=Γ(5)Γ(7/2)64t52=136R(14,12,54)y14(t)

    and

    (HD32,12x)(t)=Γ(4)Γ(5/2)t32=18320R(320,13,720)x13(t),

    which satisfy the first equation of (4.6) and (4.7), respectively. Clearly, the conditions y(0)=0 and x(0)=0 are satisfied. Finally,

    1050I34HI12I94y(2)=Γ(5)Γ(8)1050(25/4)1/227=44=y(4),

    and

    43Γ(358)HI18I38HI12x(32)=27=x(3).

    Therefore, the analytic solutions of problems (4.6) and (4.7) are claimed.

    In this paper we studied a fractional boundary value problem, in which a differential equation with Hilfer fractional derivative is combined with iterated fractional integral boundary conditions of Riemann-Liouville and Hadamard type. As far as we know, this combination appears in the literature for the first time. Firstly, we transformed the given nonlinear fractional boundary value problem into a fixed point problem. Then, by applying Banach's contraction mapping principle and Leray-Schauder nonlinear alternative, we established our main existence and uniqueness results. Furthermore, some numerical examples are illustrated to support the theoretical results. Our results are new in the given configuration and enrich the literature on the new topic of boundary value problems for fractional differential equations of Hilfer type with iterated boundary conditions of Riemann-Liouville and Hadamard type.

    This research project was supported by the Thailand Research Fund and National Research Council of Thailand for providing the Royal Golden Jubilee Ph. D. program (PHD/0080/2560).

    The authors declare that they have no conflicts of interest.



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