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Solutions for systems of complex Fermat type partial differential-difference equations with two complex variables

  • By making use of the Nevanlinna theory and difference Nevanlinna theory of several complex variables, we investigate some properties of the transcendental entire solutions for several systems of partial differential difference equations of Fermat type, and obtain some results about the existence and the forms of transcendental entire solutions of the above systems, which improve and generalize the previous results given by Cao, Gao, Liu [5,24,39]. Some examples are given show that there exist some significant differences in the forms of transcendental entire solutions with finite order of the systems of equations with between several complex variables and a single complex variable.

    Citation: Hong Li, Keyu Zhang, Hongyan Xu. Solutions for systems of complex Fermat type partial differential-difference equations with two complex variables[J]. AIMS Mathematics, 2021, 6(11): 11796-11814. doi: 10.3934/math.2021685

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  • By making use of the Nevanlinna theory and difference Nevanlinna theory of several complex variables, we investigate some properties of the transcendental entire solutions for several systems of partial differential difference equations of Fermat type, and obtain some results about the existence and the forms of transcendental entire solutions of the above systems, which improve and generalize the previous results given by Cao, Gao, Liu [5,24,39]. Some examples are given show that there exist some significant differences in the forms of transcendental entire solutions with finite order of the systems of equations with between several complex variables and a single complex variable.



    As is known to all, Nevanlinna theory is an important tool in studying the value distribution of meromorphic solutions on complex differential equations [18]. In recent, with the development of difference analogues of Nevanlinna theory in C, many scholars paid consideration attention to considering the properties on complex difference equations, by using the difference analogue of the logarithmic derivative lemma given by Chiang and Feng [3], Halburd and Korhonen [8], respectively. In particular, Liu et al. [22,23,24] investigated the existence of entire solutions with finite order of the Fermat type differential-difference equations

    f(z)2+f(z+c)2=1, (1.1)
    f(z)2+[f(z+c)f(z)]2=1. (1.2)

    They proved that the transcendental entire solutions with finite order of Eq (1.1) must satisfy f(z)=sin(z±Bi), where B is a constant and c=2kπ or c=(2k+1)π, k is an integer, and the transcendental entire solutions with finite order of Eq (1.2) must satisfy f(z)=12sin(2z+Bi), where c=(2k+1)π, k is an integer, and B is a constant.

    The study of complex differential-difference equations in C can be traced back to Naftalevich's research [28,29]. He used operator theory and iteration method to consider the meromorphic solutions on complex differential-difference equations. But recently, by using Nevanlinna theory, a number of results on complex differential-difference equations in C are rapidly obtained until now, readers can refer to [25,31,32].

    Corresponding to Eq (1.1), Gao [5] in 2016 discussed the form of solutions for a class of system of differential-difference equation

    {[f1(z)]2+f2(z+c)2=1,[f2(z)]2+f1(z+c)2=1, (1.3)

    and obtained

    Theorem A (see [5,Theorem 1.1]). Suppose that (f1,f2) is a pair of finite order transcendental entire solutions for the system of differential-difference Eq (1.3). Then (f1,f2) satisfies

    (f1,f2)=(sin(zbi),sin(zb1i))or(f1(z),f2(z))=(sin(z+bi),sin(z+b1i)),

    where b,b1 are constants, and c=kπ, k is a integer.

    Here these conclusions are stated in several complex variables as follows. In many previous articles [13,16,19,25,26,35] about Fermat-type partial differential equations with several complex variables, G. Khavinson [16] pointed out that any entire solutions of the partial differential equations (fz1)2+(fz2)2=1 in C2 are necessarily linear. This partial differential equations in real variable case occur in the study of characteristic surfaces and wave propagation theory, and it is the two dimensional eiconal equation, one of the main equations of geometric optics (see [4,6]). Later, Li [20,21] further discussed a series of partial differential equations with more general forms including (fz1)2+(fz2)2=eg, (fz1)2+(fz2)2=p, etc., where g,p are polynomials in C2, and gave a number of important and interesting results about the existence and the forms of solutions for these partial differential equations.

    In 2012, Korhonen [17,Theorem 3.1] gave a logarithmic difference lemma for meromorphic functions in several variables of hyper order strictly less that 2/3. In 2016, Cao and Korhonen [2] improved it to the case for meromorphic functions with hyper order <1 in several variables. In 2018, Xu and Cao [39] investigated the existence of the entire and meromorphic solutions for some Fermat-type partial differential-difference equations by utilizing the Nevanlinna theory and difference Nevanlinna theory of several complex variables [2,17], and obtained:

    Theorem B (see [39,Theorem 1.1]). Let c=(c1,c2)C2. Then the Fermat-type partial differential-difference equation

    (f(z1,z2)z1)n+f(z1+c1,z2+c2)m=1

    doesn't have any transcendental entire solution with finite order, where m and n are two distinct positive integers.

    Theorem C (see [39,Theorem 1.2]). Let c=(c1,c2)C2. Then any transcendental entire solutions with finite order of the partial differential-difference equation

    (f(z1,z2)z1)2+f(z1+c1,z2+c2)2=1

    has the form of f(z1,z2)=sin(Az1+B), where A is a constant on C satisfying AeiAc1=1, and B is a constant on C; in the special case whenever c1=0, we have f(z1,z2)=sin(z1+B).

    Inspired by the above theorems, the authors [37] in 2020 extended the results of Theorems A, B from the complex Fermat types partial differential difference equations to the Fermat types system of partial differential-difference equations and obtained:

    Theorem D (see [37,Theorem 1.1]). Let c=(c1,c2)C2, and mj,nj (j=1,2) be positive integers. If the following system of Fermat-type partial differential-difference equations

    {(f1(z1,z2)z1)n1+f2(z1+c1,z2+c2)m1=1,(f2(z1,z2)z1)n2+f1(z1+c1,z2+c2)m2=1, (1.4)

    satisfies one of the conditions

    (i) m1m2>n1n2;

    (ii) mj>njnj1 for nj2, j=1,2.

    Then system (1.4) does not have any pair of transcendental entire solution with finite order.

    Theorem E (see [37,Theorem 1.3]). Let c=(c1,c2)C2. Then any pair of transcendental entire solutions with finite order for the system of Fermat-type partial differential-difference equations

    {(f1(z1,z2)z1)2+f2(z1+c1,z2+c2)2=1,(f2(z1,z2)z1)2+f1(z1+c1,z2+c2)2=1

    have the following forms

    (f1(z),f2(z))=(eL(z)+B1+e(L(z)+B1)2,A21eL(z)+B1+A22e(L(z)+B1)2),

    where L(z)=a1z1+a2z2, B1 is a constant in C, and a1,c,A21,A22 satisfy one of the following cases

    (i) A21=i, A22=i, and a1=i, L(c)=(2k+12)πi, or a1=i, L(c)=(2k12)πi;

    (ii) A21=i, A22=i, and a1=i, L(c)=(2k12)πi, or a1=i, L(c)=(2k+12)πi;

    (iii) A21=1, A22=1, and a1=i, L(c)=2kπi, or a1=i, L(c)=(2k+1)πi;

    (iv) A21=1, A22=1, and a1=i, L(c)=(2k+1)πi, or a1=i, L(c)=2kπi.

    From Theorems D and E, we can see that there only contains the partial differentiation of the first variable z1 of the unknown functions f1,f2 in those systems of partial differential difference equations. Naturally, a question arises: What will happen when the system of the partial differential-difference equations include both the difference fj(z+c) and fj(z1,z2)z1,fj(z1,z2)z2,(j=1,2)? In the past two decades, in spite of a number of important and meaningful results about the complex difference equation of single variable and the complex Fermat difference equation were obtained (can be found in [9,10,11,24,31,33]), but as far as we know, there are few results concerning the complex differential and complex difference equation in several complex variables. Further more, it appears that the study of systems of this Fermat type equations in several complex variables has been less addressed in the literature before.

    The main purpose of this paper is concerned with the description of the transcendental entire solutions for some Fermat-type equations systems which include both difference operator and two kinds of partial differentials by utilizing the Nevanlinna theory and difference Nevanlinna theory of several complex variables [2,17]. We obtained some results about the existence and the forms of the transcendental entire solutions of some Fermat type systems of partial differential difference equations in C2, which improve the previous results given by Xu and Cao, Xu, Liu and Li, Gao [5,37,38,39,40].

    Here and below, let z+w=(z1+w1,z2+w2) for any z=(z1,z2) and w=(w1,w2). Now, our main results of this paper are stated below.

    Theorem 2.1. Let c=(c1,c2)C2, and mj,nj(j=1,2) be positive integers. If the following system of Fermat-type partial differential-difference equations

    {(f1(z1,z2)z1+f1(z1,z2)z2)m1+f2(z1+c1,z2+c2)n1=1,(f2(z1,z2)z1+f2(z1,z2)z2)m2+f1(z1+c1,z2+c2)n2=1, (2.1)

    satisfies one of the conditions

    (i) n1n2>m1m2;

    (ii) mj>njnj1 for nj2, j=1,2.

    Then system (2.1) does not admit any pair of transcendental entire solution with finite order.

    Remark 2.1. Here, (f,g) is called as a pair of finite order transcendental entire solutions for system

    {fm1+gn1=1,fm2+gn2=1,

    if f,g are transcendental entire functions and ρ(f,g)=max{ρ(f),ρ(g)}<.

    The following examples show system (2.1) admits a transcendental entire solution of finite order when m1=m2=2 and n1=n2=1.

    Example 2.1. Let

    {f1(z1,z2)=5z214+12(z2z1)(z11)14[(z2z1)1]2+eπi(z2z1)(2z1z2)e2πi(z2z1),f2(z1,z2)=5z214+12(z2z1)(z11)14[(z2z1)1]2eπi(z2z1)(2z1z2)e2πi(z2z1).

    Then ρ(f1,f2)=1 and (f1,f2) satisfies system (2.1) with (c1,c2)=(1,2), m1=m2=2 and n1=n2=1.

    Theorem 2.2. Let c=(c1,c2)C2. If (f1,f2) is a pair of transcendental entire solutions with finite order for the system of Fermat-type difference equations

    {(f1(z1,z2)z1+f1(z1,z2)z2)2+f2(z1+c1,z2+c2)2=1,(f2(z1,z2)z1+f2(z1,z2)z2)2+f1(z1+c1,z2+c2)2=1. (2.2)

    Then (f1,f2) is of the following forms

    (f1,f2)=(eϕ(z)+B0eϕ(z)B02(a1+a2),A21eϕ(z)+B0+A22eϕ(z)B02),

    where ϕ(z)=L(z)+H(c2z1c1z2), L(z)=a1z1+a2z2, a1,a2,B0 is a constant in C, H is a polynomial in C, and

    (c1c2)H0,(a1+a2)2=1,e2L(c)=±1,

    and c,A21,A22 satisfy one of the following cases

    (i) L(c)=2kπi, here and below, kZ, A21=i and A22=i;

    (ii) L(c)=(2k+1)πi, A21=i and A22=i;

    (iii) L(c)=(2k+12)πi, A21=1 and A22=1;

    (iv) L(c)=(2k12)πi, A21=1 and A22=1.

    Here, we only list the following examples to explain the existence of transcendental entire solutions with finite order for system (2.2).

    Example 2.2. Let a=(a1,a2)=(2i,i), H=4π2(z1z2)2, A21=i,A22=i and B0=0. That is

    (f1,f2)=(f(z1,z2),f(z1,z2)),

    where

    f(z1,z2)=ei(2z1z2)+4π2(z1z2)2ei(2z1z2)4π2(z1z2)22i.

    Thus, ρ(f1,f2)=2 and (f1,f2) satisfies system (2.2) with (c1,c2)=(2π,2π).

    Example 2.3. Let a=(a1,a2)=(2i,i), H=πn(z1z2)n,nZ+, A21=i,A22=i and B0=0. That is

    (f1,f2)=(f(z1,z2),f(z1,z2)),

    where

    f(z1,z2)=ei(2z1z2)+πn(z1z2)nei(2z1z2)πn(z1z2)n2i.

    Thus, ρ(f1,f2)=n and (f1,f2) satisfies system (2.2) with (c1,c2)=(π,π).

    Remark 2.2. From the conclusions of Theorems C and E, there only exists finite order transcendental entire solutions with growth order ρ(f1,f2)=1(ρ(f)=1). However, in view of Theorem 2.2, we can see that there exists transcendental entire solution of system (2.2) with growth order ρ(f1,f2)>1, for example, ρ(f1,f2)=2 in Example 2.2 and ρ(f1,f2)=n,nZ+ in Example 2.3, these properties are quite different from the previous results. Hence, our results are some improvements of the previous theorems given by Xu, Liu and Li [37], Xu and Cao[39], Liu Cao and Cao [23].

    To state our last result, throughout this paper, let s1=z2z1, G1(s1), G2(s1) be the finite order entire period functions in s1 with period 2s0=2(c2c1), where c1c2, G1(s1), G2(s1) can not be the same at every time occurrence.

    Theorem 2.3. Let c=(c1,c2)C2 and c1c2. Then any pair of transcendental entire solutions with finite order for the system of Fermat-type partial differential-difference equations

    {(f1(z1,z2)z1+f1(z1,z2)z2)2+[f2(z1+c1,z2+c2)f1(z1,z2)]2=1,(f2(z1,z2)z1+f2(z1,z2)z2)2+[f1(z1+c1,z2+c2)f2(z1,z2)]2=1, (2.3)

    are one of the following forms

    (i)

    (f1,f2)=(G1(s1)+A0s1,G2(s1)+A0s1),

    where A0=ξ2+ξ12(c2c1), G2(s1+s0)=G1(s1)+ξ2ξ12, and ξ21=ξ22=1;

    (ii)

    (f1,f2)=(ξ3z1+A0s1+G1(s1),ξ3z1+A0s1+G2(s1)),

    where A0=ξ1+ξ22c1ξ32(c2c1), G2(s1+s0)=G1(s1)+ξ1ξ22, ξ21+ξ23=1, and ξ1=±ξ2;

    (iii)

    (f1,f2)=(eL(z)+B1e(L(z)+B1)4i+G1(s1),eL(z)+B2e(L(z)+B2)4i+G2(s1))

    where

    a1+a2=2i,e2L(c)=1,eB1B2=eL(c),G2(s1+s0)=G1(s1);

    (iv)

    (f1,f2)=(z1eL(z)+B1+eL(z)B12+G3(s1),D0z1eL(z)+B1+eL(z)B12+G4(s1)),

    where

    a1+a2=0,e2L(c)=1,

    and G3(s1),G4(s1),D0 satisfying one of the following cases:

    (iv1) L(c)=2kπi, D0=1,

    G3(s1)=G1(s1)c1+i2s0s1ea2s1+B1c1i2s0s1ea2s1B1,

    and

    G4(s1)=G2(s1)c1+i2s0s1ea2s1+B1c1i2s0s1ea2s1B1;

    (iv2) L(c)=(2k+1)πi, D0=1,

    G3(s1)=G1(s1)c1+i2s0s1ea2s1+B1c1i2s0s1ea2s1B1,

    and

    G4(s1)=G2(s1)+c1+i2s0s1ea2s1+B1+c1i2s0s1ea2s1B1;

    where G2(s+s0)=G1(s).

    Some examples are listed to exhibit the existence of solutions for system (2.3).

    Example 2.4. Let G1(s1)=G2(s1)=eπis1, and ξ1=1, ξ2=1. Then it follows that A0=0 and

    (f1(z1,z2),f2(z1,z2))=(eπi(z2z1),eπi(z2z1)1).

    Thus, ρ(f1,f2)=1 and (f1,f2) satisfies the system (2.3) with (c1,c2)=(1,2).

    Example 2.5. Let ξ1=0, ξ2=0, ξ3=1 and G1(s1)=G2(s1)=e2πis1. Then it follows that A0=1 and

    (f1,f2)=(2z1z2+e2πi(z2z1),2z1z2+e2πi(z2z1)).

    Thus, ρ(f1,f2)=1 and (f1,f2) satisfies system (2.3) with (c1,c2)=(1,2).

    Example 2.6. Let L(z)=i(z1+z2) and G1(s1)=G2(s1)=ei4s1. That is

    (f1,f2)=(eL(z)eL(z)4i+ei4(z2z1),eL(z)eL(z)4iei4(z2z1)).

    Thus, ρ(f)=1 and (f1,f2) satisfies system (2.3) with (c1,c2)=(π,3π).

    Example 2.7. Let a1=i, a2=i, L(z)=i(z1z2), G1(s1)=G2(s1)=ei4s1 and B1=0. Then, it follows that

    f1(z1,z2)=z12(eL(z)+eL(z))2π+i8π(z2z1)eL(z)2πi8π(z2z1)eL(z)+ei4(z2z1),
    f2(z1,z2)=z12(eL(z)+eL(z))2π+i8π(z2z1)eL(z)2πi8π(z2z1)eL(z)ei4(z2z1),

    Thus, ρ(f1,f2)=1 and (f1,f2) satisfies system (2.3) with (c1,c2)=(2π,2π).

    Example 2.8. Let a1=1, a2=1, L(z)=z1z2, G1(s1)=G2(s1)=es1 and B1=0. Then, it follows that

    f1(z1,z2)=z12(eL(z)+eL(z))+π24π(z2z1)eL(z)+π+24π(z2z1)eL(z)+ez2z1,
    f2(z1,z2)=z12(eL(z)+eL(z))π24π(z2z1)eL(z)π+24π(z2z1)eL(z)ez2z1.

    Thus, (f1,f2) satisfies system (2.3) with (c1,c2)=(12πi,12πi).

    From Theorems 2.1–2.3, we can see that our results are some extension of the previous results given by Xu and Cao [39] from the equations to the systems, and some supplements of the results given by Xu, Liu and Li [37]. More importantly, Examples 2.2 and 2.3 show that system (2.2) can admit the transcendental entire solutions of any positive integer order. However, the conclusions of Theorem C and Theorem E showed that the order of the transcendental entire solutions of the equations must be equal to 1. In fact, this is a very significant difference. Finally, one can find that we only focus on the finite-order transcendental entire solutions of systems (1.4)–(2.2) in this article; thus, the following question can be raised naturally:

    Question 3.1. How should the meromorphic solutions of systems (2.2) and (2.3) be characterized?

    Similar to the argument as in the proof of Theorems 1.1 and 1.3 in Ref. [37], one can obtain the conclusions of Theorems 2.1 and 2.2 easily. Thus, we only give the proof of Theorem 2.3 as follow. However, the following lemmas play the key roles in proving Theorem 2.3.

    Lemma 4.1. ([34,36]) For an entire function F on Cn, F(0)0 and put ρ(nF)=ρ<. Then there exist a canonical function fF and a function gFCn such that F(z)=fF(z)egF(z). For the special case n=1, fF is the canonical product of Weierstrass.

    Remark 4.1. Here, denote ρ(nF) to be the order of the counting function of zeros of F.

    Lemma 4.2. ([30]) If g and h are entire functions on the complex plane C and g(h) is an entire function of finite order, then there are only two possible cases: either

    (a) the internal function h is a polynomial and the external function g is of finite order; or else

    (b) the internal function h is not a polynomial but a function of finite order, and the external function g is of zero order.

    Lemma 4.3. ([15] or [14,Lemma 3.1]) Let fj(0),j=1,2,3, be meromorphic functions on Cm such that f1 is not constant. If f1+f2+f3=1, and if

    3j=1{N2(r,1fj)+2¯N(r,fj)}<λT(r,f1)+O(log+T(r,f1)),

    for all r outside possibly a set with finite logarithmic measure, where λ<1 is a positive number, then either f2=1 or f3=1.

    Remark 4.2. Here, N2(r,1f) is the counting function of the zeros of f in |z|r, where the simple zero is counted once, and the multiple zero is counted twice.

    Lemma 4.4. Let c=(c1,c2) be a constant in C2, c10,c20 and c2c1. Let p(z),q(z) be two polynomial solutions of the equation

    hz1+hz2=γ0, (4.1)

    and q(z+c)p(z)=ζ1,p(z+c)q(z)=ζ2, where ζ1,ζ2,γ0C, then p(z)=L(z)+B1, q(z)=L(z)+B2, where L(z)=a1z2+a2z2, a1,a2,B1,B2C.

    Proof. The characteristic equations of the Eq (4.1) are

    dz1dt=1,dz2dt=1,dhdt=γ0,

    Using the initial conditions: z1=0,z2=s1, and h=h(0,s1):=h0(s1) with a parameter. Then z1=t, z2=t+s1, and h=t0γ0dt+h0(s1)=γ0t+h0(s), where s1=z2z1, h0(s1) is a function in s1. Since p(z),q(z) are the solutions of (4.1), then it yields that

    p(z1,z2)=p(t,s1)=γ0t+h1(s1),q(z1,z2)=p(t,s1)=γ0t+h2(s1), (4.2)

    where h1(s1),h2(s1) are two polynomials in s1. Substituting (4.2) into q(z+c)p(z)=ζ1,q(z)p(z+c)=ζ2, it leads to

    h2(s1+s0)h1(s1)=ζ1γ0c1,h1(s1+s0)h2(s1)=ζ2γ0c1. (4.3)

    Hence, we have

    h1(s1+2s0)=h1(s1)+ε0,h2(s1+2s0)=h2(s1)+ε0, (4.4)

    where ε0=ζ1+ζ22γ0c1. The fact that h1(s1),h2(s1) are polynomials leads to

    h1(s1)=γ1s1+B1,h2(s1)=γ1s1+B2, (4.5)

    where γ1=ε02s0, B1,B2C. By combining with (4.2) and (4.5), it follows that

    p(z1,z2)=γ0t+γ1s1+B1=γ0z1+γ1(z1z2)+B1=a1z1+a2z2+B1,q(z1,z2)=γ0t+γ1s1+B2=γ0z1+γ1(z1z2)+B2=a1z1+a2z2+B2,

    where a1=γ0+γ1,a2=γ1.

    Therefore, Lemma 4.4 is proved.

    The Proof of Theorem 2.3: Let (f1,f2) be a pair of transcendental entire functions with finite order satisfying system (2.3). In view of [7,27], we know that the entire solutions of the Fermat type functional equation f2+g2=1 are f=cosa(z),g=sina(z), where a(z) is an entire function. Hence, we only consider the following cases.

    (i) Suppose that f1(z1,z2)z1+f1(z1,z2)z2=0. Then it follows from (2.3) that

    f2(z1+c1,z2+c2)f1(z1,z2)ξ1,ξ21=1, (4.6)

    and

    f2(z+c)z1+f2(z+c)z2=f1(z1,z2)z1+f1(z1,z2)z2=0. (4.7)

    In view of (4.6), (4.7) and (2.3), it yields that

    f2z1+f2z2=0,f1(z1+c1,z2+c2)f2(z1,z2)ξ2,ξ22=1. (4.8)

    By solving the equations fjz1+fjz2=0 (j=1,2), we have

    f1(z1,z2)=g1(s1):=g1(z2z1),f2(z1,z2)=g2(s1):=g2(z2z1), (4.9)

    where g1,g2 are transcendental entire functions of finite order. Substituting (4.9) into (4.6), (4.8), it yields that

    f2(z1+c1,z2+c2)f1(z1,z2)=g2(s1+s0)g1(s1)=ξ1,f1(z1+c1,z2+c2)f2(z1,z2)=g1(s1+s0)g2(s1)=ξ2.

    which implies

    g1(s1+2s0)=g1(s1)+ξ1+ξ2,g2(s1+2s0)=g2(s1)+ξ1+ξ2, (4.10)
    g2(s1+s0)=g1(s1)+ξ1,g1(s1+s0)=g2(s1)+ξ2. (4.11)

    Thus, in view of (4.10) and (4.11), we conclude that

    g1(s1)=G1(s1)+A0s1,g2(s1)=G2(s1)+B0s1,

    where A0=B0=ξ1+ξ22(c2c1), G1(s1),G2(s1) are the finite order entire period functions with period 2s0, and

    G2(s1+s0)=G1(s1)+ξ1ξ22,G1(s1+s0)=G2(s1)+ξ2ξ12.

    Thus, this proves the conclusions of Theorem 2.3 (i).

    (ii) Suppose that

    f1(z1,z2)z1+f1(z1,z2)z2=ξ3,ξ30. (4.12)

    In view of (2.3), we conclude that

    f2(z1,z2)z1+f2(z1,z2)z2=ξ3, (4.13)
    f2(z1+c1,z2+c2)f1(z1,z2)ξ1,ξ21+ξ23=1, (4.14)
    f1(z1+c1,z2+c2)f2(z1,z2)ξ2,ξ22+ξ23=1. (4.15)

    The characteristic equations of Eq (4.12) are

    dz1dt=1,dz2dt=1,df1dt=ξ3,

    Using the initial conditions: z1=0,z2=s1, and f1=f1(0,s1):=g1(s1) with a parameter. Thus, we have z1=t, z2=t+s1 and f1(t,s1)=t0ξ3dt+g1(s1)=ξ3t+g1(s1), where s1=z2z1, g1(s1) is a transcendental entire function of finite order. Hence, it yields that

    f1(z1,z2)=ξ3z1+g1(z2z1). (4.16)

    Similar to the same argument for Eq (4.13), we have

    f2(z1,z2)=ξ3z1+g2(z2z1), (4.17)

    where g2(s1) is a transcendental entire function of finite order.

    Substituting (4.16), (4.17) into (4.14), (4.15), we conclude that

    g2(s1+s0)g1(s1)=c1ξ3+ξ1, (4.18)
    g1(s1+s0)g2(s)=c1ξ3+ξ2. (4.19)

    which lead to

    g2(s1+s0)=g1(s1)+ξ1c1ξ3,g1(s1+s0)=g2(s1)+ξ2c1ξ3,g1(s1+2s0)=g1(s1)+ξ1+ξ22c1ξ3,g2(s1+2s0)=g2(s1)+ξ1+ξ22c1ξ3.

    Since g1(s1),g2(s1) are the transcendental entire functions of finite order. then we have

    g1(s1)=G1(s1)+A0s1,g2(s1)=G2(s1)+B0s1,

    where A0=B0=ξ1+ξ22c1ξ32(c2c1), G1(s1),G2(s1) are the finite order entire period functions with period 2s0, and

    G2(s1+s0)=G1(s1)+ξ1ξ22.

    Thus, this proves the conclusions of Theorem 2.3 (ii).

    (iii) If f1z1+f1z2 is transcendental, then f2(z1+c1,z2+c2)f1(z1,z2) is transcendental. Here, we can deduce that f1(z1+c1,z2+c2)f2(z1,z2) and f2z1+f2z2 are transcendental.

    Suppose that f1(z1+c1,z2+c2)f2(z1,z2) is not transcendental. Since f1z1+f1z2 is transcendental, then f2z1+f2z2 is transcendental. In view of (2.3), it yields that f1(z1+c1,z2+c2)f2(z1,z2) is transcendental, a contradiction.

    Suppose that f2z1+f2z2 is not transcendental. In view of (2.3), it follows that f1(z1+c1,z2+c2)f2(z1,z2) is not transcendental. Thus, it yields that f1(z+c)z1+f1(z+c)z2 is not transcendental. This is a contradiction with f1z1+f1z2 is transcendental.

    Hence, if f1z1+f1z2 is transcendental, then f2(z1+c1,z2+c2)f1(z1,z2), f1(z1+c1,z2+c2)f2(z1,z2) and f2z1+f2z2 are transcendental. Thus, system (2.3) can be rewritten as

    {(f1z1+f1z2+i[f2(z+c)f1(z1,z2)])(f1z1+f1z2i[f2(z+c)f1(z1,z2)])=1,(f2z1+f2z2+i[f1(z+c)f2(z1,z2)])(f2z1+f2z2i[f1(z+c)f2(z1,z2)])=1. (4.20)

    Since f1,f2 are transcendental entire functions with finite order, then by Lemmas 4.1 and 4.2, there exist two nonconstant polynomials p(z),q(z) such that

    {f1z1+f1z2+i[f2(z1+c1,z2+c2)f1(z1,z2)]=ep,f1z1+f1z2i[f2(z1+c1,z2+c2)f1(z1,z2)]=ep,f2z1+f2z2+i[f1(z1+c1,z2+c2)f2(z1,z2)]=eq,f2z1+f2z2i[f1(z1+c1,z2+c2)f2(z1,z2)]=eq. (4.21)

    Thus, it follows from (4.21) that

    {f1(z1,z2)z1+f1(z1,z2)z2=ep(z1,z2)+ep(z1,z2)2,f2(z1+c1,z2+c2)f1(z1,z2)=ep(z1,z2)ep(z1,z2)2i,f2(z1,z2)z1+f2(z1,z2)z2=eq(z1,z2)+eq(z1,z2)2,f1(z1+c1,z2+c2)f2(z1,z2)=eq(z1,z2)eq(z1,z2)2i, (4.22)

    which implies

    i(pz1+pz2+i)ep(z)+q(z+c)i(pz1+pz2+i)eq(z+c)p(z)e2q(z+c)1, (4.23)
    i(qz1+qz2+i)eq(z)+p(z+c)i(qz1+qz2+i)ep(z+c)q(z)e2p(z+c)1. (4.24)

    Obviously, pz1+pz2i. Otherwise, it follows that e2q(z+c)1, this is impossible because q(z) is a nonconstant polynomial. Similarly, qz1+qz2i. Thus, by Lemma 4.3, and in view of (4.23), (4.24), we conclude that

    i(pz1+pz2+i)eq(z+c)p(z)1,ori(pz1+pz2+i)ep(z)+q(z+c)1,

    and

    i(qz1+qz2+i)ep(z+c)q(z)1,ori(qz1+qz2+i)eq(z)+p(z+c)1.

    Next, we consider the following four cases.

    Case 1.

    {i(pz1+pz2+i)eq(z+c)p(z)1,i(qz1+qz2+i)ep(z+c)q(z)1. (4.25)

    Since p(z),q(z) are polynomials, then from (4.25), we know that pz1+pz2 and qz1+qz2 are constants in C. Otherwise, we obtain a contradiction from the fact that the right of the above equations is not transcendental, but the left is transcendental. In addition, we get that q(z+c)p(z)C1 and p(z+c)q(z)C2, that is, p(z+2c)p(z)C1+C2 and q(z+2c)q(z)C1+C2. In view of c1c2, then by Lemma 4.4, it means that p(z)=L(z)+B1,q(z)=L(z)+B2, where L is a linear function as the form L(z)=a1z1+a2z2, a1,a2,B1,B2 are constants.

    By combining with (4.23)–(4.25), we have

    {i(a1+a2+i)eL(c)+B2B11,i(a1+a2+i)eL(c)+B1B21,i(a1+a2+i)eL(c)+B1B21,i(a1+a2+i)eL(c)B1+B21. (4.26)

    This means

    (a1+a2+i)2=1,e2L(c)=1,eB1B2=i(a1+a2+i)eL(c). (4.27)

    Thus, it follows that a1+a2=2i or a1+a2=0.

    If a1+a2=2i. Thus, e2L(c)=1,eB1B2=eL(c). The characteristic equations of the first equation in (4.22) are

    dz1dt=1,dz2dt=1,df1dt=eL(z)+B1+eL(z)B12,

    Using the initial conditions: z1=0,z2=s1, and f1=f1(0,s1):=g0(s1) with a parameter. Thus, it follows that z1=t, z2=t+s1 and

    f1(t,s1)=t0e(a1+a2)t+a2s1+B1+e[(a1+a2)t+a2s1+B1]2dt+g0(s1)=ea2s1+B12t0e(a1+a2)tdt+e(a2s1+B1)2t0e(a1+a2)tdt+g0(s1)=ea2s1+B12(a1+a2)e(a1+a2)te(a2s1+B1)2(a1+a2)e(a1+a2)t+g1(s1),

    where g1(s1) is a finite order entire function, and

    g1(s1)=g0(s1)+ea2s1+B12(a1+a2)e(a2s1+B1)2(a1+a2).

    In view of z1=t, z2=t+s1, we have

    f1(z1,z2)=eL(z)+B1eL(z)B14i+g1(s1). (4.28)

    Similar to the same argument for the third equation in (4.22), we have

    f2(z1,z2)=eL(z)+B2eL(z)B24i+g2(s1), (4.29)

    where g2(s1) is a finite order entire function.

    Substituting (4.28), (4.29) into (4.22), and applying (4.27), it yields that

    g2(s1+s0)g1(s1)=0,g1(s1+s0)g2(s1)=0. (4.30)

    Thus, from (4.30), we can deduce that

    g1(s1)=G1(s1),g2(s1)=G2(s1),

    where G1(s1),G2(s1) are the finite order entire period functions with period 2s0, and

    G2(s1+s0)=G1(s1).

    If a1+a2=0, then it follows that e2L(c)=1,eB1B2=eL(c). In view of z1=t, z2=t+s1, it leads to L(z)=a1z1+a2z2=a2s1. The characteristic equations of the first equation in (4.22) are

    dz1dt=1,dz2dt=1,df1dt=eL(z)+B1+eL(z)B12,

    Using the initial conditions: z1=0,z2=s1, and f1=f1(0,s):=G3(s) with a parameter. This leads to

    f1(t,s1)=t0ea2s1+B1+e(a2s1+B1)2dt+G3(s1)=t(ea2s1+B12+e(a2s1+B1)2)+G3(s1)=tea2s1+B1+e(a2s1+B1)2+G3(s1),

    that is

    f1(z1,z2)=z1eL(z)+B1+e(L(z)+B1)2+G3(s1), (4.31)

    where G3(s1) is an entire function of finite order. Similarly, we have

    f2(z1,z2)=z1eL(z)+B2+eL(z)B22+G4(s1),

    where G4(s1) is an entire function of finite order.

    If eL(c)=1, that is, L(c)=2kπi, which leads to eB1B2=1. Thus, it follows that

    f2(z1,z2)=z1eL(z)+B1+eL(z)B12+G4(s1). (4.32)

    Substituting (4.31), (4.32) into the second and fourth equations in (4.22), we have

    G4(s1+s0)G3(s1)=ea2s1+B1ea2s1B12ic1ea2s1+B1+ea2s1B12,G3(s1+s0)G4(s1)=ea2s1+B1ea2s1B12ic1ea2s1+B1+ea2s1B12.

    that is,

    G4(s1+2s0)G4(s1)=(c1+i)ea2s1+B1(c1i)ea2s1B1,G3(s1+2s0)G3(s1)=(c1+i)ea2s1+B1(c1i)ea2s1B1.

    Thus, we can deduce that

    G3(s1)=G1(s1)c1+i2s0s1ea2s1+B1c1i2s0s1ea2s1B1,G4(s1)=G2(s1)c1+i2s0s1ea2s1+B1c1i2s0s1ea2s1B1,

    where G1(s1),G2(s1) are the finite order entire period functions with period 2s0, and G2(s1+s0)=G1(s1).

    If eL(c)=1, that is L(c)=(2k+1)πi, then it follows that eB1B2=1, which means

    f2(z1,z2)=z1eL(z)+B1+eL(z)B12+G4(s1). (4.33)

    Substituting (4.31), (4.33) into the second and fourth equations in (4.22), we have

    G4(s1+s0)G3(s1)=ea2s1+B1ea2s1B12ic1ea2s1+B1+ea2s1B12,G3(s1+s0)G4(s1)=ea2s1+B1ea2s1B12i+c1ea2s1+B1+ea2s1B12.

    Thus, it yields

    G4(s1+2s0)G4(s1)=(c1+i)ea2s1+B1+(c1i)ea2s1B1,G3(s1+2s0)G3(s1)=(c1+i)ea2s1+B1(c1i)ea2s1B1.

    This leads to

    G3(s1)=G1(s1)c1+i2s0s1ea2s1+B1c1i2s0s1ea2s1B1,G4(s1)=G2(s1)+c1+i2s0s1ea2s1+B1+c1i2s0s1ea2s1B1,

    where G1(s1),G2(s1) are the finite order entire period functions with period 2s0, and G2(s+s0)=G1(s).

    Case 2.

    {i(pz1+pz2+i)eq(z+c)p(z)1,i(qz1+qz2+i)eq(z)+p(z+c)1. (4.34)

    In view of (4.34), the fact that p(z),q(z) are polynomials leads to q(z+c)p(z)C1 and q(z)+p(z+c)C2. This means q(z+2c)+q(z)C1+C2, this is a contradiction with the assumption of q(z) being a nonconstant polynomial.

    Case 3.

    {i(pz1+pz2+i)ep(z)+q(z+c)1,i(qz1+qz2+i)ep(z+c)q(z)1. (4.35)

    In view of (4.35), the fact that p(z),q(z) are polynomials leads to p(z)+q(z+c)C1 and p(z+c)q(z)C2. This means p(z+2c)+p(z)C1+C2, this is a contradiction with the assumption of p2(z) being a nonconstant polynomial.

    Case 4.

    {i(pz1+pz2+i)ep(z)+q(z+c)1,i(qz1+qz2+i)eq(z)+p(z+c)1. (4.36)

    In view of (4.36), the fact that p1(z),p2(z) are polynomials leads to p(z)+q(z+c)C1 and q(z)+p(z+c)C2, that is, p(z+2c)p(z)C1+C2 and q(z+2c)q(z)C2+C1. Similar to the same argument in Case 1 of Theorem 2.3, we obtain that p(z)=L(z)+B1,q(z)=L(z)+B2, where L is a linear function as the form L(z)=a1z1+a2z2, a1,a2,B1,B2 are constants. In view of (4.23), (4.24) and (4.36), we have

    {i(a1+a2+i)eL(c)+B1+B21,i(a1+a2+i)eL(c)B1B21,i(a1+a2i)eL(c)+B1+B21,i(a1+a2i)eL(c)B1B21, (4.37)

    which implies (a1+a2+i)2=(a1+a2i)2, that is, a1+a2=0. Thus, we conclude from (4.37) that

    a1+a2=0,e2L(c)=1,eB1+B2=eL(c). (4.38)

    Similar to the argument as in Case 1 of Theorem 2.3, we get the conclusions of Theorem 2.3 (iv).

    Therefore, from Cases 1–4, we complete the proof of Theorem 2.3.

    The first author is supported by the Key Project of Jiangxi Province Education Science Planning Project in China (20ZD062), the Key Project of Jiangxi Province Culture Planning Project in China (YG2018149I), the Science and Technology Research Project of Jiangxi Provincial Department of Education (GJJ181548, GJJ180767), the 2020 Annual Ganzhou Science and Technology Planning Project in China. The third author was supported by the National Natural Science Foundation of China (11561033), the Natural Science Foundation of Jiangxi Province in China (20181BAB201001) and the Foundation of Education Department of Jiangxi (GJJ190876, GJJ202303, GJJ201813, GJJ191042) of China.

    The authors declare that none of the authors have any competing interests in the manuscript.



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