Citation: Tayebe Lal Shateri, Ozgur Ege, Manuel de la Sen. Common fixed point on the bv(s)-metric space of function-valued mappings[J]. AIMS Mathematics, 2021, 6(2): 1065-1074. doi: 10.3934/math.2021063
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Let (X,d) be a metric space and T be a self mapping on X. A point x is said to be a fixed point of T, if Tx=x. Fixed point theory is one of the most important theory in mathematics. It has many applications to very different type of problems arise in different branches. Also uniqueness and existence problems of fixed points are important. One of the fixed point theorems is Geraghty-type fixed point theorem. In 1973, Geraghty [17] proved a fixed point result, generalizing the Banach contraction principle. Several authors have proved later various results using Geraghty-type conditions. Fixed point results of this kind in b-metric spaces were obtained by Dukiˊc et al. in [12].
It is well known that metric spaces are very important tool for all branches of mathematics. So mathematicians have been tried to generalize this space and transform their studies to more generalized metric spaces. As one of the most famous generalized metric spaces, in 1989, b-metric spaces was introduced by the following way.
Definition 1.1. [7] Let X be a nonempty set and s≥1 be a real number. A function d:X×X→[0,∞) is a b-metric if, for all x,y,z∈X, the following conditions are satisfied
(b1)d(x,y)=0 iff x=y,
(b2)d(x,y)=d(y,x),
(b3)d(x,z)≤s[d(x,y)+d(y,z)].
The pair (X,d) is called a b-metric space.
It is important to notice that b-metric spaces are also not metrizable. In particular, a b-metric might not be a continuous function of its variables (see [18,Ex. 2]).
In fact a b-metric space for s=1 is exactly a metric space. After this definition, many authors proved fixed point theorems for different type mappings in this space (see [3,4,5,8,9,14,15,16,19,20,22,23,29]) and the references cited therein.
Following b-metric spaces, some generalized version of this space such as extended b-metric space, dislocated b-metric space, rectangular b-metric space [13], partial b-metric space, partial ordered b-metric space, etc. were introduced. The latest generalized b-metric space was introduced by Mitrovic and Radenovic [24] in 2017 by the following way.
Definition 1.2. [24] Let X be a nonempty set, d:X×X→[0,∞) a function and v∈N. d is called a bv(s)-metric space if there exists a real number s≥1 such that for all x,z∈X and for all distinct points y1,y2,…,yv∈X, each of them different from x and z the following conditions are satisfied
(b1)d(x,y)=0 iff x=y,
(b2)d(x,y)=d(y,x),
(b3)d(x,z)≤s[d(x,y1)+d(y1,y2)+…+d(yv,z)].
The pair (X,d) is called a bv(s)-metric space.
Definition 1.3. [24] Let (X,d) be a bv(s)-metric space, {xn} be a sequence in X and x∈X. Then
(i) The sequence {xn} is called convergent in (X,d) and converges to x, if for every ϵ>0 there exists n0∈N such that d(xn,x)<ϵ for all n>n0 and this fact is represented by limn→∞xn=x or xn→x as n→∞.
(ii) The sequence {xn} is called a Cauchy sequence in (X,d) if for every ϵ>0 there exists n0∈N such that d(xn,xn+p)<ϵ for all n>n0, p>0 or equivalently, if limn→∞d(xn,xn+p)=0 for all p>0.
(iii) (X,d) is said to be a complete bv(s)-metric space if every Cauchy sequence in X converges to some x∈X.
Example 1.4. [28] Consider the set X={1n | n∈N, n≥2}. Define d:X×X→[0,∞) by
d(1k,1m)={|k−m|,if |k−m|≠112,if |k−m|=1. |
Then (X,d) is a b3(3)-metric space.
bv(s)-metric space generalizes not only b-metric space but also rectangular metric space, v-generalized metric space and rectangular b-metric space. Also, Mitrovic and Radenovic prove Banach contraction principle and Reich fixed point theorem in this space. Aleksic et al. [2] prove the common fixed point theorem of Jungck in bv(s)-metric spaces.
Abdullahi and Kumam [1] present the notion of partial bv(s)-metric space. They obtain some topological properties and prove some fixed point theorems in this space with supporting examples. Mitrovic et al. [25] prove Khan type and Dass-Gupta type fixed point theorems in bv(s)-metric spaces. Aydi et al. [6] obtain some common fixed point theorems in partial bv(s)-metric spaces. For other related studies, see [11,21,26,27].
In this paper, using ideas from [10,30] we prove some common fixed point theorems in bv(s)-metric space. Moreover, we give some examples to support our new results. Thus, we obtain generalizations of several known fixed point results from the literature.
In this section, we give some common fixed point results. Following [12], for a real number s>1, let Fs be the collection of all functions β:[0,∞)→[0,1s) satisfying the following condition:
lim supn→∞β(tn)=1simplieslimn→∞tn=0. |
As an example of a function in Fs may be given by β(t)=e−2t, for t>0 and β(0)∈[0,12). Let (X,ˆd) be a complete bv(s)-metric space and let B be the collection of all bounded functions f defined on X with metric d(f,g)=sup{ˆd(f(x),g(y)):x,y∈X}. Recall that a function f on X is said to be bounded if f(X) is a bounded subset in X.
Remark 2.1. The metric d defined as above is a bv(s)-metric on B because d(f,g)=0 if and only if ˆd(f(x),g(y))=0, for all x,y∈X, and so f=g. Also for all f,g,h1,⋯,hn∈B and x,y∈X, we have
ˆd(f(x),g(y))≤s[ˆd(f(x),h1(y))+ˆd(h1(y),h2(y))+⋯+ˆd(hn(y),g(y))]≤s[sup{ˆd(f(x),h1(y)):x,y∈X}+sup{ˆd(h1(y),h2(y)):x,y∈X}+⋯+sup{ˆd(hn(y),g(y):x,y∈X)}], |
and so
sup{ˆd(f(x),g(y)):x,y∈X}≤s[sup{ˆd(f(x),h1(y)):x,y∈X}+sup{ˆd(h1(y),h2(y)):x,y∈X}+⋯+sup{ˆd(hn(y),g(y):x,y∈X)}]. |
Therefore
d(f,g)≤s[d(f,h1)+d(h1,h2)+⋯+d(hn,g)]. |
Theorem 2.2. Let (X,ˆd) be a complete bv(s)-metric space. Let B be the collection of all bounded functions f defined on X with metric
d(f,g)=sup{ˆd(f(x),g(y)):x,y∈X}. |
Also, let T and I be the commuting mappings (i.e., T(I(f))=I(T(f)) for all f in B) defined on B in which T(B)⊆I(B), I be a continuous mapping satisfying the following contraction
d(Tf,Tg)≤β(d(f,g))M(f,g), | (2.1) |
where β∈Fs and
M(f,g)=max{d(If,Ig),d(If,Tf)d(Ig,Tg)1+d(Tf,Tg),d(If,Tf)d(Ig,Tg)1+d(If,Ig),d(If,Tf)d(Ig,Tg)1+d(If,Tg)+d(Ig,Tf)}, |
for all f,g∈B. Then T and I have a unique common fixed point.
Proof. Let f0∈B be arbitrary. Then Tf0 and If0 are well defined. Since Tf0∈I(B), there exists a function f1∈B such that If1=Tf0. In general, if fn is chosen, then we can choose a point fn+1 in B such that Ifn+1=Tfn. If for some n, Ifn=Ifn+1=Tfn, then Ifn=u is a function such that Tu=Iu, because we have
Tu=T(Ifn)=(TIfn)=(ITfn)=I(Tfn)=I(Ifn)=Iu. |
Now let d(u,Tu)>0, then we get
d(u,Tu)=d(Tfn,Tu)≤β(d(fn,u))M(fn,u)=β(d(fn,u))max{d(Ifn,Iu),d(Ifn,Tfn)d(Iu,Tu)1+d(Tfn,Tu),d(Ifn,Tfn)d(Iu,Tu)1+d(Ifn,Iu),d(Ifn,Tfn)d(Iu,Tu)1+d(Ifn,Tu)+d(Iu,Tfn)}=β(d(fn,u))max{d(u,Iu),d(u,u)d(Iu,Tu)1+d(u,Tu),d(u,u)d(Iu,Tu)1+d(u,Iu),d(u,u)d(Iu,Tu)1+d(u,Tu)+d(Iu,u)}=β(d(fn,u))d(u,Iu)=β(d(fn,u))d(u,Tu)<d(u,Tu), |
but it is a contradiction. Hence Tu=Iu=u, and so the proof of this case is completed.
Now, let Ifn≠Ifn+1, for all n≥0. We show that {Ifn} is a Cauchy sequence.
Step I. First we prove that limn→∞d(Ifn+1,Ifn)=l=0. From (2.1) for all m,n∈N we get
d(Ifn+1,Ifn)=d(Tfn,Tfn−1)≤β(d(fn,fn−1))M(fn,fn−1)<M(fn,fn−1)=max{d(Ifn,Ifn−1),d(Ifn,Tfn)d(Ifn−1,Tfn−1)1+d(Tfn,Tfn−1),d(Ifn,Tfn)d(Ifn−1,Tfn−1)1+d(Ifn,Ifn−1),d(Ifn,Tfn)d(Ifn,Tfn−1)1+d(Ifn,Tfn−1)+d(Ifn−1,Tfn)}=max{d(Ifn,Ifn−1),d(Ifn,Ifn−1)d(Tfn,Tfn−1)1+d(Tfn,Tfn−1),d(Ifn,Ifn+1)d(Ifn−1,Ifn)1+d(Ifn,Ifn−1),d(Ifn,Ifn−1)d(Ifn,Ifn−2)1+d(Ifn,Ifn−2)+d(Ifn−1,Ifn−1)}≤max{d(Ifn,Ifn−1),d(Ifn,Ifn−1),d(Ifn,Ifn+1),d(Ifn,Ifn−1)}=max{d(Ifn,Ifn−1),d(Ifn,Ifn+1)}. |
If max{d(Ifn,Ifn−1)),d(Ifn,Ifn+1)}=d(Ifn,Ifn+1), then
d(Ifn+1,Ifn)=d(Tfn,Tfn−1)≤β(d(fn,fn−1))M(fn,fn−1)<d(Ifn,Ifn+1), |
which is a contradiction. Hence max{d(Ifn,Ifn−1)),d(Ifn,Ifn+1)}=d(Ifn,Ifn−1), so
d(Ifn+1,Ifn)≤β(d(fn,fn−1))M(fn,fn−1)<d(Ifn,Ifn−1). | (2.2) |
Therefore the sequence {d(Ifn+1,Ifn)} is decreasing. So there exists l≥0 such that
limn→∞d(Ifn+1,Ifn)=l. |
If l>0, then letting n→∞ in (2.1) we obtain l≤β(d(fn,fn−1))l, which is impossible. Therefore
limn→∞d(Ifn+1,Ifn)=0. | (2.3) |
Step II. Suppose that Ifn=Ifm, for some n>m. Hence Ifn+1=Tfn=Tfm=Ifm+1, and by continuing this process we get Ifn+i=Ifm+i, for each i∈N. Then
d(Ifm,Ifm+1)=d(Ifn,Ifn+1)=d(Tfn−1,Tfn)≤β(d(fn−1,fn))M(fn−1,fn)≤max{d(Ifn−1,Ifn),d(Ifn,Ifn+1)}. |
If max{d(Ifn−1,Ifn),d(Ifn,Ifn+1)}=d(Ifn,Ifn+1), then d(Ifn,Ifn+1)<d(Ifn,Ifn+1) which is a contradiction. If max{d(Ifn−1,Ifn),d(Ifn,Ifn+1)}=d(Ifn−1,Ifn), then we have
d(Ifm,Ifm+1)=d(Ifn,Ifn+1)=d(Tfn−1,Tfn)≤β(d(fn−1,fn))M(fn−1,fn)<d(Ifn−1,Ifn)≤β(d(fn−1,fn))M(fn−2,fn−1)≤max{d(Ifn−2,Ifn−1),d(Ifn−1,Ifn)}<d(Ifn−2,Ifn−1) ⋮<d(Ifm,Ifm+1), |
which is impossible. Therefore, we can assume that Ifn≠Ifm for n≠m. Since d is a bv(s)-metric space we have
d(Ifn,Ifm)≤s(d(Ifn,Ifn+1)+d(Ifn+1,Ifm+1)+d(Ifm+1,Ifm))≤s(d(Ifn,Ifn+1)+β(d(fn,fm))M(fn,fm)+d(Ifm+1,Ifm)). | (2.4) |
Moreover
d(Ifn,Ifm)≤M(fn,fm)=max{d(Ifn,Ifm),d(Ifn,Tfn)d(Ifm,Tfm)1+d(Tfn,Tfm),d(Ifn,Tfn)d(Ifm,Tfm)1+d(Ifn,Ifm),d(Ifn,Tfn)d(Ifm,Tfm)1+d(Ifn,Tfm)+d(Ifm,Tfn)}. |
Taking the upper limit as n,m→∞ and using (2.3), we get
lim supn,m→∞M(fn,fm)=lim supn,m→∞d(Ifn,Ifm). |
Using (2.4), we conclude that
lim supn,m→∞d(Ifn,Ifm)≤sβ(d(fn,fm))lim supn,m→∞M(fn,fm)=sβ(d(fn,fm))lim supn,m→∞d(Ifn,Ifm), |
since β(d(fn,fm))<1s, this is impossible elsewhere lim supn,m→∞d(Ifn,Ifm)=0. Hence the sequence {Ifn} is a Cauchy sequence in B. As B is the family of bounded functions defined on the complete metric space (X,d∗), so (B,d) is a complete metric space and thus the sequence {Ifn} is convergent to f∈B, that is limn→∞Ifn=limn→∞Tfn−1=f.
Step III. In this step, we show that f is a common fixed point of T and I. Since T and I commute, we obtain
I(f)=I(limn→∞Tfn)=limn→∞ITfn=limn→∞TIfn=Tf. |
Let Tf=If=g, then we get Tg=TIf=ITf=Ig. If Tf≠Tg, then by (2.1), we obtain
d(Tf,Tg)≤β(d(f,g))M(f,g)=β(d(f,g))max{d(If,Ig),d(If,Tg)d(Ig,Tg)1+d(Tf,Tg),d(If,Tf)d(Ig,Tg)1+d(If,Ig),d(If,Tf)d(Ig,Tg)1+d(If,Tg)+d(Ig,Tf)}<d(If,Ig)=d(Tf,Tg), |
a contradiction. So we have g=Tf=Tg, and so Tg=Ig=g, i.e., g is a common fixed point for T and I. Condition (2.1) implies that g is the unique common fixed point.
If in Theorem 2.2 we set β(t)=λ<1s for t≥0, then we get the following result.
Corollary 2.3. Let (X,ˆd) be a complete bv(s)-metric space. Let B be the collection of all bounded functions f defined on X with metric d(f,g)=sup{ˆd(f(x),g(y)):x,y∈X}. Also, let T and I be the commuting mappings defined on B in which T(B)⊆I(B), I be a continuous mapping satisfying the following contraction
d(Tf,Tg)≤λM(f,g), |
where 0≤λ<1s and M(f,g) is as in Theorem 2.2, for all f,g∈B. Then T and I have a unique common fixed point.
Observe that
αd(If,Ig)+γd(If,Tg)d(Ig,Tg)1+d(Tf,Tg)+δd(If,Tf)d(Ig,Tg)1+d(If,Ig)+ζd(If,Tf)d(Ig,Tg)1+d(If,Tg)+d(Ig,Tf)≤(α+γ+δ+ζ)max{d(If,Ig),d(If,Tg)d(Ig,Tg)1+d(Tf,Tg),d(If,Tf)d(Ig,Tg)1+d(If,Ig),d(If,Tf)d(Ig,Tg)1+d(If,Tg)+d(Ig,Tf)}=(α+γ+δ+ζ)M(f,g). |
Hence, putting β(t)=α+γ+δ+ζ in (2.1) we get the following corollary.
Corollary 2.4. Let (X,ˆd) be a complete bv(s)-metric space. Let B be the collection of all bounded functions defined on X with metric d(f,g)=sup{ˆd(f(x),g(y))):x,y∈X}. Also, let T and I be commuting mappings defined on B in which T(B)⊆I(B), I be a continuous mapping satisfying the following contraction
d(Tf,Tg)≤αd(If,Ig)+γd(If,Tg)d(Ig,Tg)1+d(Tf,Tg)+δd(If,Tf)d(Ig,Tg)1+d(If,Ig)+ζd(If,Tf)d(Ig,Tg)1+d(If,Tg)+d(Ig,Tf), |
for all f,g∈B, where α,γ,δ,ζ≥0 and α+γ+δ+ζ<1s. Then T and I have a unique common fixed point.
In following, we give two examples to support these results.
Example 2.5. Let X=[0,1] and ˆd be a bv(s)-metric on X and B=C[0,1], the set of all real-valued continuous functions on [0,1]. Define the mappings T and I on B as T(f)(x)=23f(x) and I(f)(x)=f(x), for all f∈C[0,1] and x∈[0,1]. Then for 23<λ<1 we have
d(Tf,Tg)=d(23f,23g)=sup{ˆd(23f(x),23g(y)):x,y∈X}=23sup{ˆd(f(x),g(y)):x,y∈X}<λd(f,g)≤λM(f,g), |
where
M(f,g)=max{d(f,g),d(f,23f)d(g,23g)1+d(23f,23g),d(f,23f)d(g,23g)1+d(f,g),d(f,23f)d(g,23g)1+d(f,23g)+d(g,23f)}. |
Since all the conditions required for Corollary 2.3 are satisfied, there exists a unique common fixed function of T and I. In fact, null function is a unique common fixed function.
Example 2.6. Let X=[0,2] and ˆd(x,y)=|x−y|, and B={f,g}, where f,g are bounded functions on [0,2] defined as follows.
f(x)={1,x∈[0,1]0,otherwise,g(x)={−1,x∈[0,1]0,otherwise |
and
β(t)={12,t∈[0,2]0,otherwise. |
Define the mappings T,I on B as T(f)=f2 and I(f)=f, for all f∈B and let d be the metric defined on B as
d(f,g)=∫20|f(x)−g(x)|dx. |
It is clear that (X,ˆd) is a complete b1(s)-metric space and T,I are continuous mappings. Also, f and g are bounded functions. T and I satisfy (2.1) because
d(Tf,Tg)=d(f2,g2)=∫20|f2(x)−g2(x)|dx=0. |
Moreover M(f,g)=2 and so we have
d(Tf,Tg)=0<β(d(f,g))M(f,g)=1. |
Hence, all of conditions of Theorem 2.2 are fulfilled, and so there exists a common fixed function in B. In fact, f is a common fixed function of T and I.
The authors would like to thank the anonymous referees for their careful reading of our manuscript and their many insightful comments and suggestions. The authors thank the Basque Government for its support of this work through Grant IT1207-19.
The authors declare that they have no competing interests concerning the publication of this article.
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