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Research article

Multistep hybrid viscosity method for split monotone variational inclusion and fixed point problems in Hilbert spaces

  • Received: 27 April 2020 Accepted: 08 July 2020 Published: 22 July 2020
  • MSC : 47H05, 47H10, 47J22, 49J40

  • In this paper, we present a multi-step hybrid iterative method. It is proven that under appropriate assumptions, the proposed iterative method converges strongly to a common element of fixed point of a finite family of nonexpansive mappings, the solution set of split monotone variational inclusion problem and the solution set of triple hierarchical variational inequality problem (THVI) in real Hilbert spaces. In addition, we give a numerical example of a triple hierarchical system derived from our generalization.

    Citation: Jamilu Abubakar, Poom Kumam, Jitsupa Deepho. Multistep hybrid viscosity method for split monotone variational inclusion and fixed point problems in Hilbert spaces[J]. AIMS Mathematics, 2020, 5(6): 5969-5992. doi: 10.3934/math.2020382

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  • In this paper, we present a multi-step hybrid iterative method. It is proven that under appropriate assumptions, the proposed iterative method converges strongly to a common element of fixed point of a finite family of nonexpansive mappings, the solution set of split monotone variational inclusion problem and the solution set of triple hierarchical variational inequality problem (THVI) in real Hilbert spaces. In addition, we give a numerical example of a triple hierarchical system derived from our generalization.


    L. Carlitz ([1]) introduced analogues of Bernoulli numbers for the rational function (finite) field K=Fr(T), which are called Bernoulli-Carlitz numbers now. Bernoulli-Carlitz numbers have been studied since then (e.g., see [2,3,4,5,6]). According to the notations by Goss [7], Bernoulli-Carlitz numbers BCn are defined by

    xeC(x)=n=0BCnΠ(n)xn. (1.1)

    Here, eC(x) is the Carlitz exponential defined by

    eC(x)=i=0xriDi, (1.2)

    where Di=[i][i1]r[1]ri1 (i1) with D0=1, and [i]=TriT. The Carlitz factorial Π(i) is defined by

    Π(i)=mj=0Dcjj (1.3)

    for a non-negative integer i with r-ary expansion:

    i=mj=0cjrj(0cj<r). (1.4)

    As analogues of the classical Cauchy numbers cn, Cauchy-Carlitz numbers CCn ([8]) are introduced as

    xlogC(x)=n=0CCnΠ(n)xn. (1.5)

    Here, logC(x) is the Carlitz logarithm defined by

    logC(x)=i=0(1)ixriLi, (1.6)

    where Li=[i][i1][1] (i1) with L0=1.

    In [8], Bernoulli-Carlitz numbers and Cauchy-Carlitz numbers are expressed explicitly by using the Stirling-Carlitz numbers of the second kind and of the first kind, respectively. These properties are the extensions that Bernoulli numbers and Cauchy numbers are expressed explicitly by using the Stirling numbers of the second kind and of the first kind, respectively.

    On the other hand, for N1, hypergeometric Bernoulli numbers BN,n ([9,10,11,12]) are defined by the generating function

    11F1(1;N+1;x)=xN/N!exN1n=0xn/n!=n=0BN,nxnn!, (1.7)

    where

    1F1(a;b;z)=n=0(a)(n)(b)(n)znn!

    is the confluent hypergeometric function with (x)(n)=x(x+1)(x+n1) (n1) and (x)(0)=1. When N=1, Bn=B1,n are classical Bernoulli numbers defined by

    xex1=n=0Bnxnn!.

    In addition, hypergeometric Cauchy numbers cN,n (see [13]) are defined by

    12F1(1,N;N+1;x)=(1)N1xN/Nlog(1+t)N1n=1(1)n1xn/n=n=0cN,nxnn!, (1.8)

    where

    2F1(a,b;c;z)=n=0(a)(n)(b)(n)(c)(n)znn!

    is the Gauss hypergeometric function. When N=1, cn=c1,n are classical Cauchy numbers defined by

    xlog(1+x)=n=0cnxnn!.

    In [14], for N0, the truncated Bernoulli-Carlitz numbers BCN,n and the truncated Cauchy-Carlitz numbers CCN,n are defined by

    xrN/DNeC(x)N1i=0xri/Di=n=0BCN,nΠ(n)xn (1.9)

    and

    (1)NxrN/LNlogC(x)N1i=0(1)ixri/Li=n=0CCN,nΠ(n)xn, (1.10)

    respectively. When N=0, BCn=BC0,n and CCn=CC0,n are the original Bernoulli-Carlitz numbers and Cauchy-Carlitz numbers, respectively. These numbers BCN,n and CCN,n in (1.9) and (1.10) in function fields are analogues of hypergeometric Bernoulli numbers in (1.7) and hypergeometric Cauchy numbers in (1.8) in complex numbers, respectively. In [15], the truncated Euler polynomials are introduced and studied in complex numbers.

    It is known that any real number α can be expressed uniquely as the simple continued fraction expansion:

    α=a0+1a1+1a2+1a3+, (1.11)

    where a0 is an integer and a1,a2, are positive integers. Though the expression is not unique, there exist general continued fraction expansions for real or complex numbers, and in general, analytic functions f(x):

    f(x)=a0(x)+b1(x)a1(x)+b2(x)a2(x)+b3(x)a3(x)+, (1.12)

    where a0(x),a1(x), and b1(x),b2(x), are polynomials in x. In [16,17] several continued fraction expansions for non-exponential Bernoulli numbers are given. For example,

    n=1B2n(4x)n=x1+12+x12+13+x13+14+x. (1.13)

    More general continued fractions expansions for analytic functions are recorded, for example, in [18]. In this paper, we shall give expressions for truncated Bernoulli-Carlitz numbers and truncated Cauchy-Carlitz numbers.

    In [19], the hypergeometric Bernoulli numbers BN,n (N1, n1) can be expressed as

    BN,n=(1)nn!|N!(N+1)!10N!(N+2)!N!(N+1)!10N!(N+n1)!N!(N+n2)!N!(N+1)!1N!(N+n)!N!(N+n1)!N!(N+2)!N!(N+1)!|.

    When N=1, we have a determinant expression of Bernoulli numbers ([20,p.53]). In addition, relations between BN,n and BN1,n are shown in [19].

    In [21,22], the hypergeometric Cauchy numbers cN,n (N1, n1) can be expressed as

    cN,n=n!|NN+110NN+2NN+110NN+n1NN+n2NN+11NN+nNN+n1NN+2NN+1|.

    When N=1, we have a determinant expression of Cauchy numbers ([20,p.50]).

    Recently, in ([23]) the truncated Euler-Carlitz numbers ECN,n (N0), introduced as

    xq2N/D2NCoshC(x)N1i=0xq2i/D2i=n=0ECN,nΠ(n)xn,

    are shown to have some determinant expressions. When N=0, ECn=EC0,n are the Euler-Carlitz numbers, denoted by

    xCoshC(x)=n=0ECnΠ(n)xn,

    where

    CoshC(x)=i=0xq2iD2i

    is the Carlitz hyperbolic cosine. This reminds us that the hypergeometric Euler numbers EN,n ([24]), defined by

    t2N/(2N)!coshtN1n=0t2n/(2n)!=n=0EN,nxnn!,

    have a determinant expression [25,Theorem 2.3] for N0 and n1,

    EN,2n=(1)n(2n)!|(2N)!(2N+2)!10(2N)!(2N+4)!01(2N)!(2N+2n)!(2N)!(2N+4)!(2N)!(2N+2)!|.

    When N=0, we have a determinant expression of Euler numbers (cf. [20,p.52]). More general cases are studied in [26].

    In this paper, we also give similar determinant expressions of truncated Bernoulli-Carlitz numbers and truncated Cauchy-Carlitz numbers as natural extensions of those of hypergeometric numbers.

    Let the n-th convergent of the continued fraction expansion of (1.12) be

    Pn(x)Qn(x)=a0(x)+b1(x)a1(x)+b2(x)a2(x)++bn(x)an(x). (2.1)

    There exist the fundamental recurrence formulas:

    Pn(x)=an(x)Pn1(x)+bn(x)Pn2(x)(n1),Qn(x)=an(x)Qn1(x)+bn(x)Qn2(x)(n1), (2.2)

    with P1(x)=1, Q1(x)=0, P0(x)=a0(x) and Q0(x)=1.

    From the definition in (1.9), truncated Bernoulli-Carlitz numbers satisfy the relation

    (DNi=0xrN+irNDN+i)(n=0BCN,nΠ(n)xn)=1.

    Thus,

    Pm(x)=DN+mDN,Qm(x)=DN+mmi=0xrN+irNDN+i

    yield that

    Qm(x)n=0BCN,nΠ(n)xnPm(x)(m).

    Notice that the n-th convergent pn/qn of the simple continued fraction (1.11) of a real number α yields the approximation property

    |qnαpn|<1qn+1.

    Now,

    P0(x)Q0(x)=1=11,P1(x)Q1(x)=1xrN+1rNDN+1/DN+xrN+1rN

    and Pn(x) and Qn(x) (n2) satisfy the recurrence relations

    Pn(x)=(DN+nDN+n1+xrN+nrN+n1)Pn1(x)DN+n1DN+n2xrN+nrN+n1Pn2(x)Qn(x)=(DN+nDN+n1+xrN+nrN+n1)Qn1(x)DN+n1DN+n2xrN+nrN+n1Qn2(x)

    (They are proved by induction). Since by (2.2) for n2

    an(x)=DN+nDN+n1+xrN+nrN+n1andbn(x)=DN+n1DN+n2xrN+nrN+n1,

    we have the following continued fraction expansion.

    Theorem 1.

    n=0BCN,nΠ(n)xn=1xrN+1rNDN+1DN+xrN+1rNDN+1DNxrN+2rN+1DN+2DN+1+xrN+2rN+1DN+2DN+1xrN+3rN+2DN+3DN+2+xrN+3rN+2.

    Put N=0 in Theorem 1 to illustrate a simpler case. Then, we have a continued fraction expansion concerning the original Bernoulli-Carlitz numbers.

    Corollary 1.

    n=0BCnΠ(n)xn=1xr1D1+xr1D1xr2rD2D1+xr2rD2D1xr3r2D3D2+xr3r2.

    From the definition in (1.10), truncated Cauchy-Carlitz numbers satisfy the relation

    (LNi=0(1)ixrN+irNLN+i)(n=0CCN,nΠ(n)xn)=1.

    Thus,

    Pm(x)=LN+mLN,Qm(x)=LN+mmi=0(1)ixrN+irNLN+i

    yield that

    Qm(x)n=0CCN,nΠ(n)xnPm(x)(m).

    Now,

    P0(x)Q0(x)=1=11,P1(x)Q1(x)=1+xrN+1rNLN+1/LNxrN+1rN

    and Pn(x) and Qn(x) (n2) satisfy the recurrence relations

    Pn(x)=(LN+nLN+n1xrN+nrN+n1)Pn1(x)+LN+n1LN+n2xrN+nrN+n1Pn2(x)Qn(x)=(LN+nLN+n1xrN+nrN+n1)Qn1(x)+LN+n1LN+n2xrN+nrN+n1Qn2(x).

    Since by (2.2) for n2

    an(x)=LN+nLN+n1xrN+n+rN+n1andbn(x)=LN+n1LN+n2xrN+nrN+n1,

    we have the following continued fraction expansion.

    Theorem 2.

    n=0CCN,nΠ(n)xn=1+xrN+1rNLN+1LNxrN+1rN+LN+1LNxrN+2rN+1LN+2LN+1xrN+2rN+1+LN+2LN+1xrN+3rN+2LN+3LN+2xrN+3rN+2+.

    In [14], some expressions of truncated Cauchy-Carlitz numbers have been shown. One of them is for integers N0 and n1,

    CCN,n=Π(n)nk=1(LN)ki1,,ik1rN+i1++rN+ik=n+krN(1)i1++ikLN+i1LN+ik (3.1)

    [14,Theorem 2].

    Now, we give a determinant expression of truncated Cauchy-Carlitz numbers.

    Theorem 3. For integers N0 and n1,

    CCN,n=Π(n)|a110a2a10a11(1)nana2a1|,

    where

    al=(1)iLNδlLN+i(l1)

    with

    δl={1if l=rN+irN(i=0,1,);0otherwise. (3.2)

    We need the following Lemma in [27] in order to prove Theorem 3.

    Lemma 1. Let {αn}n0 be a sequence with α0=1, and R(j) be a function independent of n. Then

    αn=|R(1)10R(2)R(1)10R(n1)R(n2)R(1)1R(n)R(n1)R(2)R(1)|. (3.3)

    if and only if

    αn=nj=1(1)j1R(j)αnj(n1) (3.4)

    with α0=1.

    Proof of Theorem 3. By the definition (1.10) with (1.6), we have

    1=(i=0(1)iLNLN+i)xrN+irN(m=0CCmΠ(m)xm)=(l=0alxl)(m=0CCmΠ(m)xm)=n=0l=0alCCnlΠ(nl)xn.

    Thus, for n1, we get

    l=0alCCnlΠ(nl)=0.

    By Lemma 1, we have

    CCnΠ(n)=nl=1alCCnlΠ(nl)=nl=1(1)l1(1)lalCCnlΠ(nl)=|a110a2a10a11(1)nana2a1|.

    Examples. When n=rN+1rN,

    CCrN+1rNΠ(rN+1rN)=|0101(1)rN+1rNarN+1rN00|=(1)rN+1rN+1(1)rN+1rN(1)2N+1LNLN+1=LNLN+1.

    Let n=rN+2rN. For simplicity, put

    ˉa=(1)rN+1rN(1)2N+1LNLN+1,ˆa=(1)rN+2rN(1)2N+2LNLN+2.

    Then by expanding at the first column, we have

    CCrN+1rNΠ(rN+1rN)=|0100ˉa00ˆa00rN+2rN+1ˉa0100rN+1rN1|=(1)rN+1rN+1ˉa|11ˉarN+1rN101ˉa210rN+1rN1|+(1)rN+2rN+1ˆa|10ˉa0ˉa1|.

    The second term is equal to

    (1)rN+2rN+1(1)rN+2rNLNLN+2=LNLN+2.

    The first term is

    (1)rN+1rN+1ˉa|01ˉarN+22rN+1+rNˉa10rN+1rN1|=(1)2(rN+1rN+1)ˉa2|11ˉarN+1rN101ˉa210rN+1rN1|=(1)r(rN+1rN+1)ˉar|0101ˉa00|rN+1rN=(1)(r+1)(rN+1rN+1)ˉar+1=(1)(r+1)(rN+1rN+1)(1)(rN+1rN)(r+1)(1)r+1Lr+1NLr+1N+1=Lr+1NLr+1N+1.

    Therefore,

    CCrN+1rNΠ(rN+1rN)=Lr+1NLr+1N+1LNLN+2.

    From this procedure, it is also clear that CCN,n=0 if rN+1rNn, since all the elements of one column (or row) become zero.

    In [14], some expressions of truncated Bernoulli-Carlitz numbers have been shown. One of them is for integers N0 and n1,

    BCN,n=Π(n)nk=1(DN)ki1,,ik1rN+i1++rN+ik=n+krN1DN+i1DN+ik (4.1)

    [14,Theorem 1].

    Now, we give a determinant expression of truncated Bernoulli-Carlitz numbers.

    Theorem 4. For integers N0 and n1,

    BCN,n=Π(n)|d110d2d10d11(1)ndnd2d1|,

    where

    dl=DNδlDN+i(l1)

    with δl as in (3.2).

    Proof. The proof is similar to that of Theorem 3, using (1.9) and (1.2).

    Example. Let n=2(rN+1rN). For convenience, put

    ˉd=DNDN+1.

    Then, we have

    BCN,2(rN+1rN)Π(2(rN+1rN))=|010ˉdˉdrN+1rN+1100rN+1rN1|=(1)rN+1rN+1|11ˉdrN+1rN10ˉd110rN+1rN1|=(1)rN+1rN+1ˉd|011ˉd0|rN+1rN=(1)2(rN+1rN+1)ˉd2|11|=D2ND2N+1.

    It is also clear that BCN,n=0 if rN+1rNn.

    We shall use Trudi's formula to obtain different explicit expressions and inversion relations for the numbers CCN,n and BCN,n.

    Lemma 2. For a positive integer n, we have

    |a1a00a2a10an1a1a0anan1a2a1|=t1+2t2++ntn=n(t1++tnt1,,tn)(a0)nt1tnat11at22atnn,

    where (t1++tnt1,,tn)=(t1++tn)!t1!tn! are the multinomial coefficients.

    This relation is known as Trudi's formula [28,Vol.3,p.214], [29] and the case a0=1 of this formula is known as Brioschi's formula [30], [28,Vol.3,pp.208–209].

    In addition, there exists the following inversion formula (see, e.g. [27]), which is based upon the relation

    nk=0(1)nkαkD(nk)=0(n1).

    Lemma 3. If {αn}n0 is a sequence defined by α0=1 and

    αn=|D(1)10D(2)01D(n)D(2)D(1)|, then D(n)=|α110α201αnα2α1|.

    From Trudi's formula, it is possible to give the combinatorial expression

    αn=t1+2t2++ntn=n(t1++tnt1,,tn)(1)nt1tnD(1)t1D(2)t2D(n)tn.

    By applying these lemmata to Theorem 3 and Theorem 4, we obtain an explicit expression for the truncated Cauchy-Carlitz numbers and the truncated Bernoulli-Carlitz numbers.

    Theorem 5. For integers N0 and n1, we have

    CCN,n=Π(n)t1+2t2++ntn=n(t1++tnt1,,tn)(1)nt2t4t2n/2at11atnn,

    where an are given in Theorem 3.

    Theorem 6. For integers N0 and n1, we have

    BCN,n=Π(n)t1+2t2++ntn=n(t1++tnt1,,tn)(1)nt2t4t2n/2dt11dtnn,

    where dn are given in Theorem 4.

    By applying the inversion relation in Lemma 3 to Theorem 3 and Theorem 4, we have the following.

    Theorem 7. For integers N0 and n1, we have

    an=(1)n|CCN,1Π(1)10CCN,2Π(2)CCN,1Π(1)10CCN,n1Π(n1)CCN,n2Π(n2)CCN,1Π(1)1CCN,nΠ(n)CCN,n1Π(n1)CCN,2Π(2)CCN,1Π(1)|,

    where an is given in Theorem 3.

    Theorem 8. For integers N0 and n1, we have

    dn=(1)n|BCN,1Π(1)10BCN,2Π(2)BCN,1Π(1)10BCN,n1Π(n1)BCN,n2Π(n2)BCN,1Π(1)1BCN,nΠ(n)BCN,n1Π(n1)BCN,2Π(2)BCN,1Π(1)|,

    where dn is given in Theorem 4.

    We would like to thank the referees for their valuable comments.

    The authors declare no conflict of interest.



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