Let λf(n) be the nth normalized Fourier coefficient of a holomorphic cusp form f for the full modular group. In this paper, we established asymptotic formulae for high power sums of Fourier coefficients of cusp forms and further improved previous results. Moreover, as an application, we studied the signs of the sequences {λf(n)} and {λf(n)λg(n)} in short intervals, and presented some quantitative results for the number of sign changes for n≤x.
Citation: Guangwei Hu, Huixue Lao, Huimin Pan. High power sums of Fourier coefficients of holomorphic cusp forms and their applications[J]. AIMS Mathematics, 2024, 9(9): 25166-25183. doi: 10.3934/math.20241227
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Let λf(n) be the nth normalized Fourier coefficient of a holomorphic cusp form f for the full modular group. In this paper, we established asymptotic formulae for high power sums of Fourier coefficients of cusp forms and further improved previous results. Moreover, as an application, we studied the signs of the sequences {λf(n)} and {λf(n)λg(n)} in short intervals, and presented some quantitative results for the number of sign changes for n≤x.
Let H∗k denote the set of all primitive holomorphic cusp forms of even integral weight k≥2 for the full modular group SL(2,Z). Every f∈H∗k has a Fourier expansion at the cusp ∞ of the type
f(z)=∞∑n=1λf(n)nk−12e2πinz. |
The Fourier coefficient λf(n) satisfies the multiplicative relation
λf(m)λf(n)=∑d∣(m,n)λf(mnd2). |
In 1974, Deligne [1] proved the Ramanujan-Petersson conjecture
|λf(n)|≤d(n)≪nϵ, | (1.1) |
where d(n) is the divisor function.
For f∈H∗k, we define the i-th symmetric power L-function attached to f as
L(symif,s)=∏pi∏m=0(1−αf(p)i−mβf(p)mps)−1 | (1.2) |
provided that ℜs>1, where αf(p) and βf(p) are two complex numbers satisfying
αf(p)βf(p)=|αf(p)|=|βf(p)|=1,λf(p)=αf(p)+βf(p). |
We can express it as a Dirichlet series:
L(symif,s)=∞∑n=1λsymif(n)ns=∏p(1+∞∑v=1λsymif(pv)pvs), | (1.3) |
where λsymif(n) is a real multiplicative function, and
λsymif(p)=i∑m=0αf(p)i−mβf(p)m=λf(pi). |
It's easy to see that
{L(sym0f,s)=ζ(s),L(sym1f,s)=L(f,s). |
Let f,g∈H∗k be two different cusp forms. The Rankin-Selberg L-function attached to symif and symjg is defined by
L(symif×symjg,s)=∏pi∏m=0j∏n=0(1−αf(p)i−mβf(p)mαg(p)j−nβg(p)nps)−1 |
for ℜs>1. Further, this can also be written as
L(symif×symjg,s)=∞∑n=1λsymif×symjg(n)ns=∏p(1+∞∑v=1λsymif×symjg(pv)pvs). | (1.4) |
Then, we get
λsymif×symjg(p)=i∑m=0j∑n=0αf(p)i−mβf(p)mαf(p)j−nβf(p)n=λsymif(p)λsymjg(p), |
where i,j≥1 are integers. In particular, we have
{L(sym1f×sym1g,s)=L(f×g,s),L(sym1f×symjg,s)=L(f×symjg,s). |
For a more comprehensive investigation on basic properties of symmetric power L-functions and Rankin-Selberg L-functions, the interested readers can refer to [2, Chapter 13].
There are many hidden structures underlying the Fourier coefficients λf(n). In analytic number theory, it is a classical problem to estimate the sums of the type
∑n≤xλf(n)lλg(n)m, | (1.5) |
where l,m∈N. The study of O-results on the sum (1.5) is of great significance and has attracted much attention of many number theorists. For l=1 and m=0, the best result to date was given by Wu [3]. Rankin [4] and Selberg [5] studied the average behavior of the power sum for the case l=2 and m=0. More recently, Huang [6] established the better result
∑n≤xλf(n)2=Cx+O(x35−1560+ϵ). |
Fomenko [7] solved the problem when l=3,4 and m=0. Lü [8] improved Fomenko's result and successfully established the results with l=6,8 and m=0 for the first time. Shortly afterward, Lau et al. [9] considered more general cases and obtained better results. Recently, Newton and Thorne [10] proved in a general setting that symif is automorphic for i≥1. On the basis of the deep results of Newton and Thorne, by applying some techniques of analytic number theory, Xu [11] and Liu [12] investigated the average behavior of the power sums (1.5) with l∈N and m=0. Hua [13] focused on the sum (1.4) with l≥9,m=0 over indices that are sums of two squares.
For the power sum (1.5) with m>0, Ogg [14] first established an asymptotic formula for l,m=1. Subsequently, Fomenko [7] considered the sum of coefficient of the Rankin-Selberg L-function, and then successfully attained the O-results of the case of l=1,m=2 and l=2,m=2. In 2014, Lü[15] showed that
∑n≤xλf(n)λg(n)≪x35logx−23(1−83π) |
and
∑n≤xλf(n)2λg(n)2=Cx+O(x78+ϵ), | (1.6) |
which improved the results of Fomenko [7]. The current best known estimate for (1.6) is due to He [16], who showed that
∑n≤xλf(n)2λg(n)2=Cx+O(x1315+ϵ). |
Lü[17] also investigated the cases of l=m=3,l=4,m=2, and l=4,m=4.
The first purpose of this paper is to further improve the upper bounds on the error term of the sum (1.5) with m=0 and m≥2, respectively. The result is formulated in the following theorem:
Theorem 1.1. Let f∈H∗k and g∈H∗k be two different nonzero cusp forms:
(ⅰ) For l=2r≥6, we have
∑n≤xλf(n)l=xPl(logx)+O(xθl+ϵ), |
where Pl(y) denotes a polynomial in y of degree (lr)−(lr−1)−1, and
θl={32713391, l=6,1−θ−12,r, l≥8. |
Here,
θ2,r=1342r(lr−1)+185(r−1)(lr−2)+12(r−2∑n=1(l−2n+1)2n(ln−1)+l+1)−314. |
(ⅱ) For l≥2, m≥2, we have
∑n≤xλf(n)lλg(n)m=xPl,m(logx)+O(xθl,m+ϵ), |
where Pl,m(y) denotes a polynomial in y of degree ((l[l2])−(l[l2]−1))((m[m2])−(l[m2]−1))−1 for 2∣l and 2∣m; otherwise, 0. In the O-term, we have
θ2,2=773893=0.865621⋯ | θ2,3=θ3,2=206221=0.932126⋯ | θ2,4=θ4,2=349361=0.966759⋯ |
θ2,6=θ6,2=1461114731=0.991853⋯ | θ4,4=36773707=0.991907⋯ | θ4,6=θ6,4=2994130001=0.998000⋯ |
θl,m={1−θ−12,2,r,ˉr, l=2r,m=2ˉr,l=m=6,l≥8 or m≥8,1−θ−11,1,t,ˉt, l=2t+1,m=2ˉt+1,l,m≥3,1−θ−11,2,t,ˉr, l=2t+1,m=2ˉr,l≠3 or m≠2,1−θ−12,1,r,ˉt, l=2r,m=2ˉt+1,l≠2 or m≠3. |
Here,
θ2,2,r,ˉr=13(lr−1)(mˉr−1)42rˉr+18(lr−2)(mˉr−1)5ˉr(r−1)+18(lr−1)(mˉr−2)5r(ˉr−1)+r−2∑n1=1(l−2n1+1)2ˉrn1(ln1−1)(mˉr−1)+(l+1)1ˉr(mˉr−1)2+ˉr−2∑n2=1(m−2n2+1)2rn2(lr−1)(mn2−1)(m+1)1r(lr−1)2+(l+1)(m+1)2+r−1∑n1=1(l−2n1+1)2(m+1)n1(ln1−1)2+ˉr−1∑n2=1(m−2n2+1)2(l+1)n2(mn2−1)2+r−1∑n1=1ˉr−1∑n2=1(l−2n1+1)2(m−2n2+1)2n1n2(ln1−1)(mn2−1)2−314,θ1,1,t,ˉt=(l+1)(m+1)2+t∑n1=1ˉt∑n2=1(l−2n1+1)2(m−2n2+1)2n1n2(ln1−1)(mn2−1)2+t∑n1=1(l−2n1+1)2(m+1)n1(ln1−1)2+ˉt∑n2=1(m−2n2+1)2(l+1)n2(mn2−1)2,θ1,2,t,ˉr=4(lt−1)(mˉr−1)3tˉr+81(lt−1)(mˉr−2)5t(ˉr−1)+4(m+1)t(lt−1)+ˉr−2∑n2=14(m−2n2+1)2tn2(lt−1)(mn2−1)2+(l+1)(m+1)2+t−1∑n1=1(l−2n1+1)2(m+1)n1(ln1−1)2+ˉr∑n2=1(m−2n2+1)2(l+1)n2(mn2−1)2+t−1∑n1=1ˉr∑n2=1(l−2n1+1)2(m−2n2+1)2n1n2(ln1−1)(mn2−1)2,θ2,1,r,ˉt=4(lr−1)(mˉt−1)3rˉt+81(lr−2)(mˉt−1)5ˉt(r−1)+4(l+1)ˉt(mˉt−1)+t−2∑n1=14(l−2n1+1)2ˉtn1(ln1−1)(mˉt−1)2+(l+1)(m+1)2+r∑n1=1(l−2n1+1)2(m+1)n1(ln1−1)2+ˉt−1∑n2=1(m−2n2+1)2(l+1)n2(mn2−1)2+r∑n1=1ˉt−1∑n2=1(l−2n1+1)2(m−2n2+1)2n1n2(ln1−1)(mn2−1)2. |
Remark 1.2 Compared with Liu [12, Theorem 1.1], He [16, Proposition 4.2], and [17, Theorems 1.4 and 1.5], we improve the previous results. In fact, we have
Old | θ′6=0.9647⋯ | θ′8=0.9914⋯ | θ′2,2=0.8666⋯ | θ′4,2=0.9687⋯ | θ′4,4=0.9921⋯ |
New | θ6=0.9646⋯ | θ8=0.9913⋯ | θ2,2=0.8656⋯ | θ4,2=0.9667⋯ | θ4,4=0.9919⋯ |
As an application of Theorem 1.1, we then investigate quantitative results of the sign changes of λf(n) and λf(n)λg(n). The sign changes of the sequence of Fourier coefficients in short intervals was first investigated by Murty [18]. Later, Meher and Murty [19] established a lower bound for the number of sign changes of the sequence {λf(n)}. In addition, the analogous questions of simultaneous sign changes of λf(n)λg(n) was considered by Kumari and Murty [20], where f and g are two different cusp forms. In 2019, He[16] improved the result of Kumari and Murty [20]. Here, we obtain the better quantitative results for sign changes of the sequences {λf(n)} and {λf(n)λg(n)}.
Theorem 1.3. Let λf(n) and λg(n) be the coefficients of L(f,s) and L(g,s), respectively.
(ⅰ) Suppose f∈H∗k. Then, for any r1 with 67112<r1<1, the sequence {λf(n)} has at least one sign change for n∈(x,x+xr1]. Moreover, the number of sign changes for n≤x is ≫x1−r1 for sufficiently large x.
(ⅱ) Suppose f,g∈H∗k. Then, for any r2 with 773893<r2<1, the sequence {λf(n)λg(n)} has at least one sign change for n∈(x,x+xr2]. Moreover, the number of sign changes for n≤x is ≫x1−r2 for sufficiently large x.
Remark 1.4 In view of
35=0.6>0.5982⋯=67112, 1315=0.8666⋯>0.8656⋯=773893, |
we improve the results of Meher and Murty [19, Theorem 1.2] and He [16, Theorem 1.5].
In this section, we will recall and establish some preliminary results which are used to prove the main theorems in this paper.
We define
Fl(s)=∞∑n=1λf(n)lns and Fl,m(s)=∞∑n=1λf(n)lλg(n)mns. | (2.1) |
Lemma 2.1. Let f∈H∗k, then we have
Fl(s)=Gl(s)Hl(s), |
where
Gl(s)=[l2]∏n=0L(syml−2nf,s)((ln)−(ln−1)). |
(ln) is the binomial coefficient with the convention that (ln)=0 if n<0, and the function Hl(s) admits a Dirichlet series convergent absolutely in ℜs>1/2. Noting Hl(s)≠0 for ℜs=1.
Proof. This can be found in Xu [11, Lemma 5].
Based on Ivić [21, Theorem 8.4], Bourgain [22, Theorem 5], and Ramachandra and Sankaranarayanan [23, Lemma 2], we give the following lemma:
Lemma 2.2. For any ϵ>0, we have
∫T0|ζ(57+iτ)|12dτ≪ϵT1+ϵ | (2.2) |
uniformly for T≥1 and
ζ(σ+iτ)≪(|τ+1|)max{1342(1−σ),0}+ϵ | (2.3) |
uniformly for 1/2≤σ≤2 and |τ|≥1. Moreover, for U>U0, where U0 is sufficiently large, there exists a T∗∈(U,2U) such that
maxσ≥12|ζ(σ+iT∗)|≪ϵexp(C(loglogU)2). | (2.4) |
Lemma 2.3. Let f∈H∗k, then we have
∫T0|L(f,58+iτ)|4dτ≪f,ϵT1+ϵ | (2.5) |
uniformly for T≥1 and
L(f,σ+iτ)≪f,ϵ(|τ+1|)max{23(1−σ),0}+ϵ, | (2.6) |
L(sym2f,σ+iτ)≪f,ϵ(|τ+1|)max{65(1−σ),0}+ϵ, | (2.7) |
L(f×sym2g, σ+iτ)≪f,g,ϵ(|τ+1|)2710(1−σ)+ϵ | (2.8) |
uniformly for 12≤σ≤2 and |τ|≥1.
Proof. These are Ivić [24, Theorem 2], Good [25, Corollary 3], Lin et al. [26, Corollary 1.2], and Lin and Sun [27, Corollary 1.3], respectively.
For general L-functions, we have the following averaged or individual convexity bounds (see [28]):
Lemma 2.4. Suppose that L(s) is a general L-function of degree m. Then, for any ϵ>0, we have
∫2TT|L(σ+iτ)|2dτ≪Tm(1−σ)+ϵ | (2.9) |
uniformly for 1/2≤σ≤2 and T≥1, and
L(σ+iτ)≪(|τ|+1)max{m2(1−σ),0}+ϵ | (2.10) |
uniformly for 1/2≤σ≤1+ϵ and |τ|≥1.
Remark 2.5 According to the Euler product (1.2), the degree of L(symjf,s) is j+1. In the proof of Theorem 1.1, we take m=j+1 in Lemma 2.4 for L(symjf,s),j≥3. Similarly, take m=(i+1)(j+1) for the Rankin-Selberg L-function L(symif×symjg,s).
By the Perron formula ([29, Proposition 5.54]) with (1.1), we obtain
∑n≤xλf(n)l=12πi∫1+ϵ+iT1+ϵ−iTFl(s)xssds+Of,ϵ(x1+ϵT) |
uniformly for 2≤T≤x, where the implied constant depends only on f and ϵ. From Lemma 2.1, we can easily get that the point s=1 is the only pole of the integrand in the region σ0≤σ≤1+ϵ and |τ|≤T for any σ0∈[1/2+ϵ,1). Using the Cauchy residue theorem, we get
∑n≤xλf(n)l=Ress=1Fl(s)xss+12πi(∫1+ϵ+iTσ0+iT+∫1+ϵ−iTσ0−iT+∫σ0+iTσ0−iT)Fl(s)xssds+Of,ϵ(x1+ϵT). |
The factorization expression of Fl(s) in Lemma 2.1 contains ζ(s)(ln)−(ln−1), which means s=1 is a pole of order (ln)−(ln−1) of Fl(s) in the half-plane ℜs>1/2. Thus, by standard argument in complex analysis, we know the residue at s=1 is equal to xPl(logx), where Pl(logx) is a polynomial of degree (lr)−(lr−1)−1 for l=2r; otherwise, 0. Thus, we get
∑n≤xλf(n)l=xPl(logx)+12πi(∫1+ϵ+iTσ0+iT+∫1+ϵ−iTσ0−iT+∫σ0+iTσ0−iT)Fl(s)xssds+Of,ϵ(x1+ϵT). | (3.1) |
The absolute convergence of Hl(s) for ℜs>1/2+ϵ yields Hl(s)≪1. Hence, (3.1) can be written as
∑n≤xλf(n)l=xPl(logx)+Of,ϵ(x1+ϵT+Rhl+Rvl), | (3.2) |
where
Rhl=1T∫1+ϵσ0|Gl(σ+iT)|xσdσ |
and
Rvl=xσ0∫T1|Gl(σ0+iτ)|dττ≪xσ0+ϵsup1≤T1≤T1T1∫2T1T1|Gl(σ0+iτ)|dτ. |
Our goal is to test for constraints on Rhl and Rvl, which can certify Rhl≪x1+ϵ/T and Rvl≪x1+ϵ/T.
Let us consider 2∣l,l≥6. When the power of ζ(s) is less than 12, (2.2) cannot be used directly. In order to get better results, we consider it separately.
Case 1. For l=6, according to Lemma 2.1, we have
G6(s)=ζ(s)5L(sym2f,s)9L(sym4f,s)5L(sym6f,s). |
Taking U=x1203391 in (2.4), there must exist a T∗∈(U,2U) such that
ζ(σ+iT∗)≪ϵexp(C(loglogU)2)≪Uϵ. |
Suppose that T=δU with 1<δ<2. Now, we choose
σ0=57, T=T∗=δU=δx1203391 |
in (3.2). Then, we obtain
Rh6≪1T∫1+ϵ57(Tδ)5ϵT∗(9×65+5×52+72)(1−σ)+ϵxσdσ≪T1295+ϵ∫1+ϵ57(xT1345)σdσ≪x1+ϵT+x57+ϵT23335+ϵ. | (3.3) |
Applying the Hölder's inequality, we obtain
Rv6≪x57+ϵsup1≤T1≤T1T1∫2T1T1|G6(57+iτ)|dτ≪x57+ϵsup1≤T1≤T1T1(∫2T1T1|ζ(57+iτ)|12dτ)512(∫2T1T1|L(sym4f,57+iτ)|607dτ)712×L(sym2f,57+iT1)9L(sym6f,57+iT1). |
By (2.2), (2.7), and Lemma 2.4, we have
Rv6≪x57+ϵT−1+512(1+ϵ)+(5×712+52×467×712+9×65+72)(1−57)+ϵ≪x57+ϵT2971420+ϵ. | (3.4) |
Combining (3.2)–(3.4), we obtain
∑n≤xλf(n)6=xP6(logx)+O(x1+ϵT+x57+ϵT2971420+ϵ). |
Recall that
T=δx1203391 |
with 1<δ<2. Thus, we get the required result.
Case 2. When l=2r≥8, according to Lemma 2.1, we obtain
Gl(s)=r∏n=0L(syml−2nf,s)((ln)−(ln−1)). |
Take U=xθ−12,r in (2.4), where
θ2,r=1342r(lr−1)+185(r−1)(lr−2)+r−2∑n=1(l−2n+1)2n(ln−1)+l+12−314. |
Then, there must exist a T∗∈(U,2U) such that
ζ(σ+iT∗)≪ϵexp(C(loglogU)2)≪Uϵ. |
Suppose that T=δU with 1<δ<2. Now, we choose
σ0=57, T=T∗=δU=δxθ−12,r |
in (3.2). Then, we obtain
Rhl≪1T∫1+ϵ57(Tδ)1r(lr−1)ϵT(185(r−1)(lr−2)+r−2∑n=1(l−2n+1)2n(ln−1)+l+12)(1−σ)+ϵxσdσ≪Tθ2,r−1342r(lr−1)+314−1+ϵ∫1+ϵ57(xTθ2,r−1342r(lr−1)+314)σdσ≪x1+ϵT+x57+ϵT27(θ2,r−1342r(lr−1)+314)−1+ϵ. | (3.5) |
Applying the Hölder inequality and (2.2), we obtain
Rvl≪x57+ϵsup1≤T1≤T1T1∫2T1T1|Gl(57+iτ)|dτ≪x57+ϵsup1≤T1≤T1T1(∫2T1T1|ζ(57+iτ)|12dτ)ζ(57+iT1)1341r(lr−1)−12×r−2∏n=0L(syml−2nf,57+iT1)((ln)−(ln−1))≪x57+ϵT27θ2,r−1+ϵ. | (3.6) |
Combining (3.2), (3.5), and (3.6), we obtain
∑n≤xλf(n)l=xPl(logx)+O(x1+ϵT+x57+ϵT27θ2,r−1+ϵ). |
Recall that T=δxθ−12,r with 1<δ<2. Thus, we get the required result.
To prove these results, we will use the following proposition:
Proposition 3.1. Let f,g∈H∗k, then we have
Fl,m(s)=Gl,m(s)Hl,m(s), |
where
Gl,m(s)=[l2]∏n1=0[m2]∏n2=0L(syml−2n1f×symm−2n2g,s)((ln1)−(ln1−1))((mn2)−(mn2−1)), | (3.7) |
(ln1) and (mn2) are the binomial coefficients with the convention that (ln1)=0 and (mn2)=0 if n1,n2<0, and the function Hl,m(s) admits a Dirichlet series convergent absolutely in ℜs>1/2. Note Hl,m(s)≠0 for ℜs=1.
Proof. For f∈H∗k, we know
Fl,m(s)=∞∑n=1λf(n)lλg(n)mns=∏p(1+∑v≥1λf(pv)lλg(pv)mpvs). |
By [11, Lemma 5], we get that
λf(p)l=[l2]∑n1=0((ln1)−(ln1−1))λsyml−2n1f(p),λg(p)m=[m2]∑n2=0((mn2)−(mn2−1))λsymm−2n2g(p). |
Hence, the coefficient of p−s is
λf(p)lλg(p)m=([l2]∑n1=0((ln1)−(ln1−1))λsyml−2n1f(p))×([m2]∑n2=0((mn2)−(mn2−1))λsymm−2n2g(p))=[l2]∑n1=0[m2]∑n2=0((ln1)−(ln1−1))((mn2)−(mn2−1))λsyml−2n1f×symm−2n2g(p). |
We define
Hl,m(s)=Fl,m(s)/Gl,m(s), |
and its p-local factor is of the form 1+O(p−2s). So, the Euler product (hence, the Dirichlet series) of Hl,m(s) converges absolutely in ℜs>1/2.
Utilizing the similar method in Section 3.1 and the decomposition in Proposition 3.1, we can get the claim easily.
Case 1. When l=m=2, according to Proposition 3.1, we have
G2,2(s)=ζ(s)L(sym2f,s)L(sym2g,s)L(sym2f×sym2g,s). |
Taking U=x120/893 in (2.4), there must exist a T∗∈(U,2U) such that
ζ(σ+iT∗)≪ϵexp(C(loglogU)2)≪Uϵ. |
Suppose that T=δU with 1<δ<2. Now, we choose
σ0=57, T=T∗=δU=δx120893 |
in (3.2). Then,
Rh2,2≪1T∫1+ϵ57(Tδ)ϵT(65+65+92)(1−σ)+ϵxσdσ≪T5910+ϵ∫1+ϵ57(xT6910)σdσ≪x1+ϵT+x57+ϵT3435+ϵ. | (3.8) |
Applying Hölder's inequality, we obtain
Rv2,2≪x57+ϵsup1≤T1≤T1T1∫2T1T1|G2,2(57+iτ)|dτ≪x57+ϵsup1≤T1≤T1T1(∫2T1T1|ζ(57+iτ)|12dτ)112(∫2T1T1|L(sym2f×sym2g,57+iτ)|2dτ)12×(∫2T1T1|L(sym2f,57+iτ)|125dτ)512L(sym2g,57+iT1). |
By (2.2), (2.7), and Lemma 2.4, we have
Rv2,2≪x57+ϵT−1+112(1+ϵ)+(92+25×512×65+512×3+65)(1−57)+ϵ≪x57+ϵT473420+ϵ. | (3.9) |
Combining (3.2), (3.8), and (3.9), we obtain
∑n≤xλf(n)2λg(n)2=xP2,2(logx)+O(x1+ϵT+x57+ϵT473420+ϵ). |
Recall that T=δx120893 with 1<δ<2, Thus, we get the required result.
Utilizing the similar method of λf(n)2λg(n)2, we can get the results of λf(n)2λg(n)4, λf(n)4λg(n)2, λf(n)4λg(n)4, λf(n)4λg(n)6, and λf(n)6λg(n)4 easily.
Case 2. When l=m=6, l≥8, or m≥8, we have
Gl,m(s)=r∏n1=0ˉr∏n2=0L(syml−2n1f×symm−2n2g,s)((ln1)−(ln1−1))((mn2)−(mn2−1))=ζ(s)((lr)−(lr−1))((mˉr)−(mˉr−1))L(sym2f,s)((lr−1)−(lr−2))((mˉr)−(mˉr−1))L(sym2g,s)((lr)−(lr−1))((mˉr−1)−(mˉr−2))×r−2∏n1=0L(syml−2n1f,s)((ln1)−(ln1−1))((mˉr)−(mˉr−1))ˉr−2∏n2=0L(symm−2n2g,s)((lr)−(lr−1))((mn2)−(mn2−1))×r−1∏n1=0ˉr−1∏n2=0L(syml−2n1f×symm−2n2g,s)((ln1)−(ln1−1))((mn2)−(mn2−1)), |
where l=2r, m=2ˉr.
Taking U=xθ−12,2,r,ˉr in (2.4), there must exist a T∗∈(U,2U) such that
ζ(σ+iT∗)≪ϵexp(C(loglogU)2)≪Uϵ. |
Suppose that T=δU with 1<δ<2. Now, we choose
σ0=57, T=T∗=δU=δxθ−12,2,r,ˉr, |
where
θ2,2,r,ˉr=13(lr−1)(mˉr−1)42rˉr+18(lr−2)(mˉr−1)5ˉr(r−1)+18(lr−1)(mˉr−2)5r(ˉr−1)+r−2∑n1=1(l−2n1+1)2ˉrn1(ln1−1)(mˉr−1)+(l+1)1ˉr(mˉr−1)2+ˉr−2∑n2=1(m−2n2+1)2rn2(lr−1)(mn2−1)(m+1)1r(lr−1)2+(l+1)(m+1)2+r−1∑n1=1(l−2n1+1)2(m+1)n1(ln1−1)2+ˉr−1∑n2=1(m−2n2+1)2(l+1)n2(mn2−1)2+r−1∑n1=1ˉr−1∑n2=1(l−2n1+1)2(m−2n2+1)2n1n2(ln1−1)(mn2−1)2−314 |
in (3.2). Then,
Rhl,m≪1T∫1+ϵ57(Tδ)1rˉr(lr−1)(mˉr−1)ϵT(θ2,2,r,ˉr−1342rˉr(lr−1)(mˉr−1)+314)(1−σ)xσdσ≪T(θ2,2,r,ˉr−1342rˉr(lr−1)(mˉr−1)+314)−1+ϵ∫1+ϵ57(xT(θ2,2,r,ˉr−1342rˉr(lr−1)(mˉr−1)+314))σdσ≪x1+ϵT+x57+ϵT27(θ2,2,r,ˉr−1342rˉr(lr−1)(mˉr−1)+314)−1+ϵ. | (3.10) |
Applying the Hölder's inequality, we obtain
Rvl,m≪x57+ϵsup1≤T1≤T1T1∫2T1T1|Gl,m(57+iτ)|dτ≪x57+ϵsup1≤T1≤T1T1(∫2T1T1|ζ(57+iτ)|12dτ)T(θ2,2,r,ˉr−72)(1−57)+ϵ1≪x57+ϵT27θ2,2,r,ˉr−1+ϵ. | (3.11) |
Combining (3.2), (3.10), and (3.11), we obtain
∑n≤xλf(n)lλg(n)m=xP1(logx)+O(x1+ϵT+x57+ϵT27θ2,2,r,ˉr−1+ϵ). |
Recall that T=δxθ−12,2,r,ˉr with 1<δ<2. Thus, we get the required result.
From (3.7), we have
Gl,m(s)=t∏n1=0ˉt∏n2=0L(syml−2n1f×symm−2n2g,s)((ln1)−(ln1−1))((mn2)−(mn2−1))=t∏n1=1L(syml−2n1f×symmg,s)((ln1)−(ln1−1))ˉt∏n2=1L(symlf×symm−2n2g,s)((mn2)−(mn2−1))×L(symlf×symmg)t∏n1=1ˉt∏n2=1L(syml−2n1f×symm−2n2g,s)((ln1)−(ln1−1))((mn2)−(mn2−1)), |
where l=2t+1, m=2ˉt+1. Then,
Rhl,m≪1T∫1+ϵ12Tθ1,1,t,ˉt(1−σ)xσdσ≪Tθ1,1,t,ˉt−1∫1+ϵ12(xTθ1,1,t,ˉt)σdσ≪x1+ϵT+x12+ϵT12θ1,1,t,ˉt−1, | (3.12) |
where
θ1,1,t,ˉt=(l+1)(m+1)2+t∑n1=1(l−2n1+1)2(m+1)n1(ln1−1)2+ˉt∑n2=1(m−2n2+1)2(l+1)n2(mn2−1)2+t∑n1=1ˉt∑n2=1(l−2n1+1)2(m−2n2+1)2n1n2(ln1−1)(mn2−1)2. |
Applying the Cauchy inequality and (2.9), we obtain
Rvl,m≪x12+ϵsup1≤T1≤T1T1∫2T1T1|Gl,m(12+iτ)|dτ≪x12+ϵsup1≤T1≤T1T1∫2T1T1|L(syml−2f×symmg,s)|2dτ×T(θ1,1,t,ˉt−2(l−1)(m+1)2)(1−12)+ϵ1≪x12+ϵT12θ1,1,t,ˉt−1+ϵ. | (3.13) |
Combining (3.2), (3.12), and (3.13), we obtain
∑n≤xλf(n)lλg(n)m=xPl,m(logx)+O(x1+ϵT+x12+ϵT12θ1,1,t,ˉt−1+ϵ). |
By taking a fixed T=xθ−11,1,t,ˉt, we obtain the result.
When 2∤l,2∣m, because (2.5) cannot be used directly when the power of L(f,s) is less than 4, we need to think about this case separately.
Case 1. When l=3,m=2, according to Proposition 3.1 and taking σ0=58, we have
G3,2(s)=L(f,s)2L(f×sym2g,s)2L(sym3f,s)L(sym3f×sym2g,s). |
Then, we get
Rh3,2=1T∫1+ϵ58|L(f,s)2L(f×sym2g,s)2L(sym3f,s)L(sym3f×sym2g,s)|xσdσ≪1T∫1+ϵ58T(2×23+2×2710+42+122)(1−σ)+ϵxσdσ≪T20615+ϵ∫1+ϵ58(xT22115)σdσ≪x1+ϵT+x58+ϵT18140+ϵ. | (3.14) |
In order to estimate Rv3,2, we apply the Cauchy-Schwarz inequality to obtain
Rv3,2≪x58+ϵsup1≤T1≤T1T1∫2T1T1|G3,2(58+iτ)|dτ≪x58+ϵsup1≤T1≤T1T1T1(2×2710+122)(1−58)+ϵ(∫2T1T1|L(symf,58+iτ)|4dτ)12×(∫2T1T1|L(sym3f,58+iτ)|2dτ)12≪x58+ϵsup1≤T1≤T1T1T1(2×2710+122)(1−58)+ϵT112+ϵT112×4×(1−58)+ϵ≪x58+ϵT18140+ϵ. | (3.15) |
Combining (3.14) and (3.15) with (3.2) and T=x15221, we get the required result.
Case 2. When l is odd, m is even, and l≠3 or m≠2. From (3.7), we have
Gl,m(s)=t∏n1=0ˉr∏n2=0L(syml−2n1f×symm−2n2g,s)((ln1)−(ln1−1))((mn2)−(mn2−1))=L(f,s)((lt)−(lt−1))((mˉr)−(mˉr−1))t−1∏n1=0ˉr∏n2=0L(syml−2n1f×symm−2n2g,s)((ln1)−(ln1−1))((mn2)−(mn2−1))×L(f×sym2g,s)((lt)−(lt−1))((mˉr−1)−(mˉr−2))ˉr−2∏n2=0L(f×symm−2n2g,s)((lt)−(lt−1))((mn2)−(mn2−1)), |
where l=2t+1, m=2ˉr. By taking σ0=58, then
Rhl,m≪1T∫1+ϵ58Tθ1,2,t,ˉr(1−σ)xσdσ≪Tθ1,2,t,ˉr−1∫1+ϵ58(xTθ1,2,t,ˉr)σdσ≪x1+ϵT+x58+ϵT38θ1,2,t,ˉr−1, | (3.16) |
where
θ1,2,t,ˉr=4(lt−1)(mˉr−1)3tˉr+81(lt−1)(mˉr−2)5t(ˉr−1)+4(m+1)t(lt−1)+ˉr−2∑n2=14(m−2n2+1)2tn2(lt−1)(mn2−1)2+(l+1)(m+1)2+t−1∑n1=1(l−2n1+1)2(m+1)n1(ln1−1)2+ˉr∑n2=1(m−2n2+1)2(l+1)n2(mn2−1)2+t−1∑n1=1ˉr∑n2=1(l−2n1+1)2(m−2n2+1)2n1n2(ln1−1)(mn2−1)2. |
Applying the Hölder inequality, we obtain
Rvl,m≪x58+ϵsup1⩽ | (3.17) |
Combining (3.16) and (3.17) with (3.2) and T = x^{\theta_{1, 2, t, \bar{r}}^{-1}} , we get the required result.
The proof of 2\mid l, 2\nmid m is similar to 2\nmid l, 2\mid m , so it can be estimated in a similar way. In order to avoid repetition, we shall not prove it verbatim here.
In order to prove Theorem 1.3, we state the following result of Meher and Murty [19, Theorem 1.1] to detect sign changes:
Lemma 4.1. Suppose a sequence of real numbers \{a(n)\} satisfies
(1) a(n) = O(x^{\alpha+\epsilon}),
(2) \sum\limits_{n\leq x}a(n) = O(x^{\beta+\epsilon}),
(3) \sum\limits_{n\leq x}a(n)^2 = cx+O(x^{\gamma+\epsilon}),
where \alpha, \beta, \gamma , and c are positive real constants. If \alpha+\beta < 1 , then for any r with \max\{\alpha+\beta, \gamma\} < r < 1 , the sequence \{a(n)\} has at least one sign change for n\in (x, x+x^r] for sufficiently large x . Moreover, the number of sign changes of \{a(n)\} for n\leq x is \gg x^{1-r} .
(ⅰ) Let f\in H_k^* . From Wu [3, Theorem 2] and Huang [6, Theorem 1], we have
\begin{align} \sum\limits_{n\leq x} \lambda_f(n)\ll x^\frac{1}{3}(\log x)^{-0.118}\ \ \ \ \text{and}\ \ \ \ \sum\limits_{n\leq x} \lambda_f(n)^{2} = Cx + O\big(x^{\frac{3}{5}-\frac{1}{560}+\epsilon} \big). \end{align} | (4.1) |
Combining (1.1) and (4.1) in Lemma 4.1, we know that \alpha = 0, \ \beta = {1}/{3}, \ \gamma = {67}/{112} , which means
\max\{\alpha+\beta,\gamma\} = {67}/{112} < 1. |
(ⅱ) Let f, g\in H_k^* . In 2014, Lü[15] proved that
\sum\limits_{n\leq x}\lambda_f(n)\lambda_g(n)\ll x^{\frac{3}{5}}\log x ^{-\frac{2}{3}(1-\frac{8}{3\pi})}. |
From Theorem 1.1, we improve the error term for the sharp-cut sum (1.5) with l = m = 2 from O(x^{{13}/{15}+\epsilon}) to O(x^{{773}/{893}+\epsilon}) . With Lemma 4.1, we obtain \alpha = 0, \ \beta = {3}/{5}, \ \gamma = {773}/{893} , which means
\max\{\alpha+\beta,\gamma\} = {773}/{893} < 1. |
Thus, we finish the proof of Theorem 1.3.
In this paper, we study the distribution of Fourier coefficients of holomorphic cusp forms. Let \lambda_f(n) be the n th normalized Fourier coefficient of a holomorphic cusp form f for the full modular group. Combining the classical analytic method with property of some primitive automorphic L-functions, we establish asymptotic formulae for high power sums of Fourier coefficients of cusp forms. As an application, we also use a general criteria to detect the signs of \lambda_f(n) and \lambda_f(n)\lambda_g(n) , and obtain some quantitative results for the number of sign changes for n\leq x . We are able to improve or extend previous results.
Guangwei Hu: writing-review and editing, supervision, validation, methodology, formal analysis, conceptualization, funding acquisition; Huixue Lao: writing-review and editing, resources, methodology, supervision, validation, formal analysis; Huimin Pan: writing-original draft, methodology, validation, formal analysis. All authors read and approved the final manuscript.
The authors declare they have not used Artificial Intelligence (AI) tools in the creation of this article.
The authors are very grateful to the referees for some extremely helpful remarks. This work is supported by National Natural Science Foundation of China (Grant No. 12201363) and Natural Science Foundation of Shandong Province (Grant No. ZR2022QA047).
The authors declare that they have no conflicts of interest.
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