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Research article

An overdetermined problem for elliptic equations

  • Received: 27 March 2024 Revised: 07 June 2024 Accepted: 19 June 2024 Published: 25 June 2024
  • MSC : 35J25, 35N25

  • This paper is devoted to finding a necessary and sufficient condition for the solvability of the overdetermined problem for Poisson's equation with both the Dirichlet and Neumann conditions on the entire boundary. The proof is based on the boundary condition formula for the Newton potential. The obtained results are also extended to general second-order linear elliptic equations. As a byproduct, we present a characterization of the Schiffer property. It gives a definitive answer to the Schiffer problem.

    Citation: Tynysbek Kalmenov, Nurbek Kakharman. An overdetermined problem for elliptic equations[J]. AIMS Mathematics, 2024, 9(8): 20627-20640. doi: 10.3934/math.20241002

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  • This paper is devoted to finding a necessary and sufficient condition for the solvability of the overdetermined problem for Poisson's equation with both the Dirichlet and Neumann conditions on the entire boundary. The proof is based on the boundary condition formula for the Newton potential. The obtained results are also extended to general second-order linear elliptic equations. As a byproduct, we present a characterization of the Schiffer property. It gives a definitive answer to the Schiffer problem.


    The Cauchy problem for the Laplace equation can only have a solution if the given (initial) data has strong compatibility or smoothness conditions. Hadamard proved that if the compatibility relationship among the Cauchy data is not satisfied, then there cannot be a global solution. He also demonstrated that even if the data satisfies the conditions for a classical solution to exist, this solution will not depend continuously on the data. We refer to [1] and the references therein for detailed discussions in the field. In many studies, Cauchy data for Poisson's equation can be posed on a part of the boundary rather than on the whole boundary. Probably one of the best-known results on Cauchy-type overdetermined problems for Poisson's equation in ΩRn with both the Dirichlet and Neumann conditions on the entire boundary Ω goes back to [2]:

    Δu(x)=1,xΩRn (1.1)

    with

    u(x)|xΩ=0,u(x)nx|xΩ=const, (1.2)

    where nx is an outer normal derivative on the boundary. Serrin proved that if this overdetermined boundary value problem admits a solution, then Ω must be a ball and u is radially symmetric about its center. Shortly later, Weinberger in [3] introduced an alternative proof based on the analysis of the subharmonic function. These two methods have been instrumental in generalizing Serrin's theorem to various settings and nonlinearities. See [4,5] and the literature cited therein for other delicate issues related to symmetry problems in general. For further discussions, see also e.g., [6,7,8,9] and references therein.

    Let ΩRn(n2) be a bounded domain with a smooth connected boundary Ω. In this paper, we analyse the following overdetermined problem:

    Δu=f(x),xΩRn (1.3)

    with

    u(x)|xΩ=0,u(x)nx|xΩ=0. (1.4)

    The main aim of this paper is to establish a criterion for the solvability of the overdetermined Cauchy-type problems (1.3) and (1.4). We will also discuss some consequences and extensions. Note that overdetermined boundary value problems are crucial, for example, for solving inverse boundary value problems on finite networks since they provide the theoretical foundations for the recovery algorithm (see, e.g., [10]).

    As usual, a minimal Laplace operator

    Δ0:D(Δ0)R(Δ0)

    is the closure of the differential operator Δ on a subset of the functions uC2+α(¯Ω),α>0, with

    u|xΩ=unx|xΩ=0.

    It is known that if u0D(Δ0), then u0W22(Ω), and the inequality

    Δ0u0L2(Ω)cu0W22(Ω) (1.5)

    holds. Here and in the sequel, we denote the standard Sobolev spaces by W (with corresponding indexes).

    It is a natural question to find the function fR(Δ0), such that

    Δ0u0=f(x),u0|xΩ=u0nx|xΩ=0. (1.6)

    By Δ0, we denote the adjoint operator to the operator Δ0 in the space L2(Ω), and its kernel is denoted by kerΔ0.

    Further, the operators Δ0 and Δ0 are called the minimal and maximal operators, respectively, generated by the Laplacian. Using the properties of Δ0 and kerΔ0 by the method of regular extension of the operator Δ0, Vishik [11] described all (regular) boundary value problems for Poison's equation (1.3) in the Hilbert space L2(Ω). An operator ΔK is called a regular extension of the operator Δ0, if

    Δ0ΔKΔ0andΔ1k<,
    uD(Δk)u=u0+Kv+L1Qv,ΔKu=Δ0u=Δ0u0+v,
    vkerΔ0,K:kerΔ0kerΔ0,

    where K is a linear bounded operator and LQ is a fixed differential operator generated by Eq (1.3) and the regular boundary conditions, see [12,13].

    Otelbaev et al. [12] extended Vishik's result to Banach spaces. They also described the correct restriction of the maximal operator Δ0, which can handle not only boundary value problems but also problems with internal "boundary" conditions. Such problems include the Bitsadze–Samarskii problem [14], which arises in the study of liquid plasma motion.

    The boundary conditions of problems (1.3) and (1.4) are overdetermined along the entire boundary Ω, making it an ill-posed problem. Therefore, the main objective of this paper is to identify conditions that ensure the solvability of problems (1.3) and (1.4).

    We begin by noting that since

    D(Δ0)=W22(Ω)

    is dense in L2(Ω), we have the following equality:

    L2(Ω)=R(Δ0)kerΔ0. (1.7)

    Thus, the condition for the operator Δ0 to be invertible coincides with the condition for f to be orthogonal to the whole kerΔ0, that is, to all harmonic functions. This viewpoint from the perspective of operator theory provides us with an understanding of the solvability of the overdetermined problems (1.3) and (1.4). Nevertheless, ensuring the fulfillment of this condition can pose significant challenges.

    Alternatively, suppose L1Df is the solution of the Dirichlet problem. Then, we have

    u=L1Df=ΩG(x,ξ)f(ξ)dξ,

    where G(x,ξ) is the Green's function of the Dirichlet problem, satisfying:

    L1Df|xΩ=0.

    Hence, one of the necessary conditions for the overdetermined problem is satisfied, so that uD(Δ0) is necessary and sufficient for

    nxΩG(x,ξ)f(ξ)dξ|xΩ=0. (1.8)

    However, it is typically challenging to verify the above condition (1.8) due to the lack of an explicit formula for Green's function G(x,ξ) in Ω, which is only known for some specific domains.

    Let ε(x) denote the fundamental solution of Eq (1.3), which satisfies:

    Δxε(x)=δ(x), (1.9)

    where δ(x) is the Dirac delta function. We use the representations of ε(x) given by:

    ε(x)=12πln|x|,xR2,ε(x)=1(n2)ωn1|x|n2,xRn,n3, (1.10)

    where ωn is the surface area of the unit sphere in Rn.

    We define the Newton potential in the following form

    u(x)=Ωε(xy)f(y)dy. (1.11)

    In the present paper, we establish a solvability criterion for the overdetermined problems (1.3) and (1.4) in terms of the Newton potential. Our approach not only addresses this specific problem but also offers potential extensions to more general elliptic operators. Additionally, we demonstrate the applicability of our method in solving the Schiffer problem from [15].

    This short paper has a simple structure: In Section 2, we present a solvability criterion for the problems (1.3) and (1.4) in L2(Ω). That is, we provide a necessary and sufficient condition for the problems (1.3) and (1.4) to be uniquely solvable in L2(Ω). The proof of this criterion relies on the boundary condition of the Newton potential, which was constructed in [16]. We also refer to [17,18] for more general cases. In Section 3, we demonstrate the consequences of our result with one-dimensional examples that involve explicit computations. In Section 4, we apply our result to provide a novel characterization of the Schiffer property of sets. By employing our findings, we offer new insights into the Schiffer problem. Finally, in Section 5, we discuss some extensions of our results to general elliptic equations.

    We state the main result of this paper below.

    Theorem 2.1. The Cauchy problem for Poisson's equation (1.3) with the condition (1.4) on the entire boundary Ω, that is, the minimal operator Δ0 is invertible in L2(Ω) if and only if the following condition holds

    Ωε(xy)f(y)dy|xΩ=0, (2.1)

    where the kernel ε is the fundamental solution of the Laplacian.

    It is important to note that the Newton potential of a ball of constant density is constant on the surface of the ball. Interestingly, this property in fact uniquely characterizes the balls for any dimension n2, as was shown by Fraenkel [19] (see also [20]). In essence, the Newton potential of constant mass density is constant on the boundary Ω if and only if Ω is a ball.

    Observing Theorem 2.1, it is straightforward to discern that if the density f is a constant other than zero, there exists no solution for the overdetermined boundary value problems (1.3) and (1.4) for any ΩRn,n3. This is because the fundamental solution is negative when n3. As an example, the overdetermined torsion problem, where f=2, also lacks a solution in any ΩRn,n3.

    The proof of Theorem 2.1 is based on the boundary property of the Newton potential u(x) given by Eq (1.11), which was obtained in [16, Theorem 1]:

    Theorem 2.2. For any fL2(Ω), the Newton potential defined by the formula (1.11) belongs to W22(Ω) and satisfies the following boundary condition:

    u(x)2+Ω(ε(xy)u(y)nyε(xy)nyu(y))dy=0,xΩ. (2.2)

    Conversely, if uW22(Ω) satisfies Eq (1.3) and the boundary condition (2.2), then it coincides with the Newton potential in Ω.

    Note that the special boundary condition (2.2) can be called the boundary condition of the Newton potential.

    Proof of Theorem 2.1. Necessity. Let uD(Δ0) and Δ0u=f, then

    u|xΩ=0

    and

    unx|xΩ=0.

    Hence, u(x) satisfies the boundary condition (2.2). According to Theorem 2.2, the function u(x) is the Newton potential and satisfies

    u(x)|xΩ=Ωε(xy)f(y)dy|xΩ=0. (2.3)

    Thus, the necessity condition (2.1) is proven.

    Sufficiency. If the condition (2.1) is satisfied, then we seek the solution of Δ0u=f in the form

    u(x)=Ωε(xy)f(y)dy,xΩ.

    By Theorem 2.2, this Newton potential satisfies the boundary condition (2.2), and it also satisfies the Dirichlet boundary condition

    u|xΩ=0

    according to (2.1).

    Therefore, combining (2.2) with (2.1), we have

    Ωε(xy)nyu(y)dy=0,xΩ. (2.4)

    Hence, the function

    v(x)=Ωε(xy)nyu(y)dy,xΩ (2.5)

    is a solution to the Laplace equation

    Δxv(x)=0,xΩ (2.6)

    with the Dirichlet boundary condition

    v(x)|xΩ=0. (2.7)

    From the uniqueness of the solution of the Dirichlet problem, it follows that v(x)0 in ¯Ω. If we continue v(x) throughout Rn by 0, and use the property of the simple-layer potential, then we arrive at

    0=vnx|xΩ+vnx|xΩ=unx|xΩ.

    Here, \(\partial \Omega^{+}\) denotes an exterior domain, while \(\partial \Omega^{-}\) denotes an interior domain. Indeed, the simple-layer potential \(v(x)\) is harmonic in \(\Omega\) and \(\mathbb{R}^n \setminus \overline{\Omega}\), and it has a jump discontinuity across the boundary \(\partial \Omega\) (see [21,22])

    vnx|xΩ+vnx|xΩ=unx|xΩ.

    Since \(v(x) = 0 \) inside \(\overline{\Omega}\), then we have

    vnx|xΩ=0,

    and its normal derivative from outside \(\partial \Omega^{+}\) is zero.

    The proof is now complete.

    In the one-dimensional case, the Newton potential u(x) is given by the formula

    u(x)=1210|xξ|f(ξ)dξ. (3.1)

    Let us find the boundary condition for the integral (3.1).

    Substituting f(ξ) by d2dξ2u(ξ) in (3.1) and integrating by part, we obtain

    u(x)=1210|xξ|f(ξ)dξ=1210|xξ|d2dξ2u(ξ)dξ=12x0(xξ)d2dξ2u(ξ)dξ+121x(ξx)d2dξ2u(ξ)dξ=12[(xξ)ddξu(ξ)|x0+u(ξ)|x0+(ξx)ddξu(ξ)|1xu(ξ)|1x]=u(x)+12[xu(0)u(0)+(1x)u(1)u(1)]. (3.2)

    Thus,

    x(u(0)u(1))u(0)+u(1)u(1)=0,x(0,1).

    Since x(0,1) is arbitrary, it follows that

    u(0)+u(1)=0,u(1)=u(0)+u(1). (3.3)

    Thus, the condition (3.3) is the boundary condition for the one-dimensional Newton potential (3.1), that is, it is the one-dimensional analogue of (2.2).

    Now, we rewrite the condition

    Ωε(xy)f(y)dy|xΩ=0

    in the one-dimensional case. A direct calculation gives

    u(0)=1210|xξ|f(ξ)dξ|x=0=1210ξf(ξ)dξ=0,

    hence,

    u(1)=1210|xξ|f(ξ)dξ|x=1=1210f(ξ)dξ=0.

    That is, in the one-dimensional case, the condition (2.1) is equivalent to f(x) being orthogonal to both 1 and x. To show the sufficiency of this condition, let us assume that f(x) is orthogonal to both 1 and x. Taking into account (3.3) and

    u(0)=u(1)=0,

    it follows that

    u(0)=u(1)=u(0)=u(1)=0.

    It means that the solution

    uW22(0,1)

    defined by the formula (3.1) satisfies the (one-dimensional) condition (2.1).

    Now let us show necessity. We need to show that if the problem

    v(x)=f(x),x(0,1) (3.4)

    with the overdetermined conditions

    v(0)=v(1)=v(0)=v(1)=0 (3.5)

    has a solution, then f(x) is orthogonal to both 1 and x. If a solution exists, it can be written in the form

    v(x)=1210|xξ|f(ξ)dξ+C1x+C2. (3.6)

    According to the boundary conditions, we have

    v(0)=1210ξf(ξ)dξ+C2=0,v(1)=1210f(ξ)dξ1210ξf(ξ)dξ+C1+C2=0,v(0)=u(0)+C1=0,v(1)=u(1)+C1=0.

    This confirms Theorem 2.1, where

    1012|xy|f(y)dy|x=0,1=0

    or equivalently, f is orthogonal to 1 and x. That is, the overdetermined problem

    u(x)=f(x),x(0,1) (3.7)

    with the boundary condition

    u(0)=u(1)=u(0)=u(1)=0 (3.8)

    has a solution if and only if f(x) is orthogonal to both 1 and x. For example, set

    f(x)=x2x+16.

    Since

    10f(x)dx=0

    and

    10f(x)xdx=0,

    in this case, the overdetermined problems (3.4)–(3.8) must have a solution. Indeed, the solution is

    u(x)=112x2(1x)2.

    A domain ΩRn(n2) with a smooth connected boundary is said to have the Schiffer property if there is no λ>0 such that the overdetermined boundary value problem

    Δu+λu=1

    in Ω, with

    u=unx=0

    on Ω where nx is the exterior normal to Ω, has a solution. For further details on the original statement of this problem, we refer to [15] and [23, Problem 80].

    Let us consider the following: non-homogeneous Helmholtz equation

    Δu(x)+λu(x)=f(x),xΩ, (4.1)

    with

    u(x)|xΩ=0,u(x)nx|xΩ=0. (4.2)

    The analog of Theorem 2.2 for the non-homogeneous Helmholtz equation was proved in [24]. Imitating the proof of Theorem 2.1, we obtain that the overdetermined boundary value problems (4.1) and (4.2) have a solution if and only if

    Ωελ(xy)f(y)dy|xΩ=0, (4.3)

    where ελ is the fundamental solution of the Helmholtz equation satisfying the Sommerfield radiation condition

    lim|x||x|(n1)/2(ελ|x|+iλελ)=0.

    That is, Ω has the Schiffer property if and only if

    Ωελ(xy)dy|xΩ0 (4.4)

    for all λ>0.

    Thus, it gives a definitive answer to the Schiffer problem, which consists of deciding which sets Ω have the Schiffer property. Note that it is also related to the so-called Pompeiu property (see, e.g., [25]).

    Let ΩRn(n2) with a smooth connected boundary. Consider the following elliptic (Newton) potential

    u(x)=Ωε(x,ξ)ρ(ξ)dξ, (5.1)

    where ε(x,ξ) is the fundamental solution of the second order linear elliptic equation, i.e.,

    Lu(x):=ni,j=1xiaij(x)xju(x)+a(x)u=ρ(x), (5.2)

    where

    ni,j=1aij(x)ξiξjδ|ξ|2,δ>0,|ξ|2=ni,j=1ξ2i,

    aij(x)C3(ˉΩ), a(x)C2(ˉΩ), and a(x)0.

    Now we recall briefly a method for constructing the fundamental solution of Eq (5.2) according to the classical approach proposed by Bitsadze [14].

    Let us denote by Aij the division ratios of the algebraic complement of the elements aij of the matrix aij of the leading coefficients of Eq (5.2) in the determinant

    a=detaij.

    We introduce the function:

    σ(x,ξ)=ni,j,ξAij(x)(xiξi)(xjξj),

    where x and ξ are arbitrary points in Ω.

    Suppose

    aij(x)C3(ˉΩ)anda(x)C1(ˉΩ).

    It is known that (5.1) is uniformly elliptic, and there are positive constants k0 and k1 such that

    k0|xξ|2σ(x,ξ)k1|xξ|2.

    For xξ we define the function

    ε(x,ξ)={σ0(ξ)σ(x,ξ)2n2,n>2,12πσ0¯a(ξ)lnσ(x,ξ), n=2, (5.3)

    where for n>2,

    σ0(ξ)=[ωn(n2)|¯a(ξ)|]1,

    ωn is the area of an n-dimensional unit sphere, and ¯a(ξ) is the determinant of the matrix {ai,j}.

    The following theorem is analogous to Theorem 2.2, and the proof is similar (see [16, Theorem 1]).

    Theorem 5.1. Let ρL2(Ω), then the elliptic potential defined by formula (5.1) satisfies the following boundary condition:

    u(x)2+Ωu(ξ)ni,j=1niaij(ξ)ξjε(x,ξ)dξΩε(x,ξ)ni,j=1niaij(ξ)ξju(ξ)dξ=0,xΩ. (5.4)

    Conversely, if a function uW22(Ω) satisfies Eq (5.2) and the boundary condition (5.4), then u(x) coincides with elliptic potential (5.1).

    Now, we have the following (elliptic) extensions of the results stated in Section 2.

    Theorem 5.2. For all fL2(Ω), the following Cauchy problem

    Lu=f,xΩ,u|xΩ=unx|xΩ=0,

    has a unique solution if and only if

    Ωε(x,y)f(y)dy|xΩ=0,

    where ε(x,y) is the fundamental solution of the elliptic operator L.

    Proof. Necessity. Let uD(Δ0) and Δ0u=f, then

    u|xΩ=0

    and

    unx|xΩ=0.

    Hence, u(x) satisfies the boundary condition (5.4). According to Theorem 5.1, the function u(x) is the volume potential and satisfies

    u(x)|xΩ=Ωε(x,y)f(y)dy|xΩ=0. (5.5)

    Thus, the necessity condition is proved.

    Sufficiency. Assuming that the condition (5.5) is fulfilled, we propose the solution to Δ0u=f as follows:

    u(x)=Ωε(xy)f(y)dy,xΩ.

    By Theorem 5.1, this Newton potential satisfies the boundary condition (5.4). Now sufficiency can be established using the same method as demonstrated in the proof of Theorem 2.1.

    In this paper, we establish a criterion for the solvability of the overdetermined problem for Poisson's equation

    Δu=f(x),xΩRn

    with both the Dirichlet and Neumann conditions on the entire boundary

    u(x)|xΩ=0,u(x)nx|xΩ=0.

    The proof is based on the boundary condition formula for the Newton potential

    u(x)2+Ω(ε(xy)u(y)nyε(xy)nyu(y))dy=0,xΩ.

    The obtained results are also extended to general second-order linear elliptic equations. As a byproduct, we present a characterization of the Schiffer property. It gives a definitive answer to the Schiffer problem.

    Tynysbek Kalmenov: completing the main study, carring out the results of this article, drafting the paper; Nurbek Kakharman: writing-original draft, editing. All authors have read and approved the final version of the manuscript for publication. Both authors read and approved the final version of the manuscript.

    The authors declare they have not used Artificial Intelligence (AI) tools in the creation of this article.

    The authors would like to thank Professor Durvudkhan Suragan for valuable discussions to complete this paper. This research was funded by the Science Committee of the Ministry of Science and Higher Education of Kazakhstan (Grant No. AP14871460). This work was also supported by the Nazarbayev University program 20122022CRP1601.

    The authors declare that they have no conflicts of interest.



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