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Infinitely many solutions for a class of fractional Robin problems with variable exponents

  • In this paper, we are concerned with a class of fractional Robin problems with variable exponents. Their main feature is that the associated Euler equation is driven by the fractional p()Laplacian operator with variable coefficient while the boundary condition is of Robin type. This paper is a continuation of the recent work established by A. Bahrouni, V. Radulescu and P. Winkert [5].

    Citation: Ramzi Alsaedi. Infinitely many solutions for a class of fractional Robin problems with variable exponents[J]. AIMS Mathematics, 2021, 6(9): 9277-9289. doi: 10.3934/math.2021539

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  • In this paper, we are concerned with a class of fractional Robin problems with variable exponents. Their main feature is that the associated Euler equation is driven by the fractional p()Laplacian operator with variable coefficient while the boundary condition is of Robin type. This paper is a continuation of the recent work established by A. Bahrouni, V. Radulescu and P. Winkert [5].



    Fractional Sobolev spaces have major applications to various nonlinear problems, including phase transitions, thin obstacle problem, anomalous diffusion, crystal dislocation, semipermeable membranes and flame propagation, ultra-relativistic limits of quantum mechanics, minimal surfaces, water waves, etc. For more details, we refer the readers to Di Nezza, Palatucci and Valdinoci [21]. More recently, the works of Caffarelli et al. [9,10,11], led to a large amount of papers involving the fractional diffusion operator (Δ)s (0<s<1). The cited results turn out to be very fruitful in order to recover an elliptic PDE approach in a nonlocal framework, and they have recently been used very often, see [1,6,7,16,18,24,26,27]. We mention that there are also a great number of results which do not survive in the fractional framework, such as the ones mentioned in [13,14].

    On the other hand, the study of PDE's involving variable exponents has become very attractive in recent decades, see [15,17,19,23,25,30] and the references therein.

    It is therefore a natural question to see which results "survive" when the p(x)Laplacian is replaced by the fractional p(x)Laplacian.

    As far as we know, the first result about the fractional Sobolev spaces with variable exponent of the form Ws,q(),p(,)(Ω) and the fractional p(x)Laplacian is obtained by Kaufmann-Rossi-Vidal in [22]. In particular it is shown that theses spaces are compactly embedded into variable exponent Lebesgue spaces. They also study the existence existence of solution for nonlocal problems involving the fractional p(,)Laplacian. Bahrouni-Radulescu [2] obtained some further qualitative properties of the fractional Sobolev spaces and the fractional p(,)Laplacian. Further developments have been done by Bahrouni, Ho, Biswas, Chung, Zhang, see [3,4,5,8,12,20,29].

    The main goal of this paper is to study the existence of infinitely many solutions for fractional p(,)Laplacian equation with nonlocal Robin boundary condition. Precisely, we deal with the following problem

    (Δ)sp(,)u+|u|¯p(x)2u=a(x)|u|q(x)2uin Ω,Ns,p(,)u+β(x)|u|¯p(x)2u=0in RN¯Ω, (1.1)

    where ΩRN, N>1, is a bounded domain with Lipschitz boundary, a,qL(Ω), s(0,1), p:R2N(1,+) is a symmetric, continuous function bounded away from 1, ¯p()=p(,), βL(RNΩ) with β0 in RNΩ and (Δ)sp(,) stands for the fractional p(,)Laplacian which is given by

    (Δ)sp(,)u(x)=p. v.RN|u(x)u(y)|p(x,y)2(u(x)u(y))|xy|N+sp(x,y)dyfor xΩ. (1.2)

    Furthermore, Ns,p(,) is defined by

    Ns,p(,)u(x)=Ω|u(x)u(y)|p(x,y)2(u(x)u(y))|xy|N+sp(x,y)dyfor xRN¯Ω, (1.3)

    and denotes the nonlocal normal p(,)-derivative (or p(,)Neumann boundary condition) and describes the natural Neumann boundary condition in presence of the fractional p(,)Laplacian. We would like to mention that the nonlocal normal derivative was introduced for the first time by A. Bahrouni, V. Radulescu and P. Winkert in [5]. This paper can be considered as a continuation of this study. Precisely, using variational methods, we will prove the existence of infinitely many solutions of Eq (1.1).

    Now, we recall some results obtained by U. Kaufmann et al. [22]. Let Ω be a bounded Lipschitz domain in RN, s(0,1), qC(¯Ω,R), and pC(¯ΩׯΩ,R). Throughout this paper, we assume that

    1<p(x,y)=p(y,x)<Ns, (x,y)¯Ω×¯Ω (P')

    and

    1<q(x)<Np(x,x)Nsp(x,x)=:ps(x), x¯Ω. (Q')

    We define the fractional Sobolev space with variable exponents Ws,q(),p(,)(Ω) as

    Ws,q(),p(,)(Ω)={uLq()(Ω):  λ>0,  Ω×Ω|u(x)u(y)|p(x,y)λp(x,y)|xy|N+sp(x,y)dxdy<}.

    Let

    [u]s,p(,),Ω=inf{λ>0: Ω×Ω|u(x)u(y)|p(x,y)λp(x,y)|xy|N+sp(x,y)dxdy1}

    be the corresponding variable exponent Gagliardo seminorm. For brevity, we denote Ws,q(),p(,)(Ω) by E for a general qC(¯Ω,R) satisfying  (Q')  and by Ws,p(,)(Ω) when q(x)=p(x,x) on ¯Ω. We equip E with the norm

    uE=[u]s,p(,),Ω+uLq()(Ω).

    Then, E becomes a reflexive and separable Banach space.

    Now, we are ready to recall a crucial theorem which prove some embedding results was obtained in [22] for the case q(x)>p(x,x) on ¯Ω and then was refined in [20,29].

    Theorem 1.1. Let ΩRN be a bounded Lipschitz domain and let s(0,1). Let pC(¯ΩׯΩ,R) and qC(¯Ω,R) satisfy  (P')  and  (Q')  with q(x)p(x,x) for all x¯Ω. Let rC(¯Ω,R) satisfy

    1<r(x)<ps(x), x¯Ω. (R)

    Then, there exists a constant C=C(N,s,p,q,r,Ω) such that

    fLr()(Ω)CfE, fE.

    Thus, E is continuously embedded in Lr()(Ω). Moreover, this embedding is compact.

    From Theorem 1.1 and using assumptions  (P')  and  (Q')  with q(x)p(x,x) for all x¯Ω, we can deduce that spaces E and Ws,p(,)(Ω) actually coincide. Evidently, E is not suitable for studying the fractional p(.,.)Laplacian problem with Robin boundary condition and hence, we need to introduce another space as our solution space.

    We suppose the following assumptions:

    (A) aL(Ω) and a>0 in Ω.

    (S) sR with s(0,1);

    (P) p:R2N(1,+) is a symmetric, continuous function bounded away from 1, that is,

    p(x,y)=p(y,x)for all x,yR2N

    with

    1<p:=min(x,y)R2Np(x,y)p(x,y)p+:=max(x,y)R2Np(x,y).

    and sp+<N;

    (β) βL(RNΩ) and β0 in RNΩ;

    Let u:RNR be a measurable function and let ¯p(x)=p(x,x) for all xR2N. We set

    uX:=[u]s,p(,),R2N(CΩ)2+uL¯p()(Ω)+β1¯p()uL¯p()(CΩ),

    where CΩ=RNΩ and

    X:={u:RNR measurable : uX<}.

    (X,X) is a reflexive and separable Banach space, see [5]. Let us recall the compact embedding result introduced in [22].

    Proposition 1.2. Assume that (S), (P) and (β) hold. Then, for any rC(¯Ω) with 1<r(x)<ps(x) for all x¯Ω, there exists a constant α>0 such that

    uLr()(Ω)αuXfor alluX.

    Moreover, this embedding is compact.

    Now we give our main result.

    Theorem 1.3. Assume that q(x)(1,p), for all xΩ and conditions (A), (S), (P) and (β) are fulfilled. Then problem (1.1) has infinitely many solutions.

    This paper is organized as follows. In Section 2 we recall some definitions and fundamental properties of the spaces Lp()(Ω) and W1,p()(Ω). In Section 3 we give the proof of Theorem 1.3.

    In this section, we recall some definition and basic properties concerning the basic function spaces with variable exponent. We refer to [5,15,17,23,25,30] and the references therein.

    We start by giving a bounded Lipschitz domain ΩRN. Next, we consider the following set

    C+(¯Ω)={pC(¯Ω,R):p(x)>1forallx¯Ω}.

    For any pC+(¯Ω), denote

    p+=supxΩp(x)andp=infxΩp(x)

    and recall the variable exponent Lebesgue space Lp()(Ω) as

    Lp()(Ω)={u: u is measurable real-valued function, Ω|u(x)|p(x)dx<},

    which is endowed with the following Luxemburg norm

    uLp()(Ω)=inf{μ>0:Ω|u(x)μ|p(x)dx1}.

    It is well known that (Lp()(Ω),Lp()(Ω)) is a separable reflexive Banach space.

    The variable exponent Sobolev space W1,p()(Ω) is defined by

    W1,p()(Ω)={uLp()(Ω):|u|Lp()(Ω)}

    with the norm

    u1,p()=up()+up().

    Let Lq()(Ω) be the conjugate space of Lp()(Ω), that is, 1/p(x)+1/q(x)=1 for all x¯Ω. If uLp()(Ω) and vLq()(Ω), then the Hölder-type inequality

    |Ωuvdx|(1p+1q)up()vq()

    is satisfied.

    Defining the modular function ρ:Lp()(Ω)R by

    ρ(u)=Ω|u|p(x)dx.

    Then, we have the following crucial result which will be useful in the sequel.

    Proposition 2.1. Assume that uLp()(Ω). Then:

    (i) up()<1(=1,>1)ρ(u)<1(=1,1);

    (ii) up()>1  upp()ρ(u)up+p();

    (iii) up()<1  up+p()ρ(u)upp()\.

    Proposition 2.2. Assume that u,unLp()(Ω) with nN. Then the following statements are equivalent:

    (i) limn+unup()=0;

    (ii) limn+ρ(unu)=0;

    (iii) un(x)u(x) a. e. in Ω and limn+ρ(un)=ρ(u).

    Now, we introduce the variational setting for problem (1.1). We define the functional I:XR by

    I(u)=R2N(CΩ)2|u(x)u(y)|p(x,y)2p(x,y)|xy|N+sp(x,y)dxdy+Ω|u|¯p(x)¯p(x)dx+CΩβ(x)|u|¯p(x)¯p(x)dxΩa(x)q(x)|u|q(x)dx,

    which is well defined and of class C1 on X. Clearly, the weak solutions of our main problem (1.1) are exactly the critical points of the Euler-Lagrange functional I.

    In this section, we investigate the existence of infinitely many solutions for problem (1.1). It is known that, by [19], there exist (en)X and enX such that

    en(em)=1   if  n=m   and  en(em)=0  if  nm.

    It follows that

    X=¯span{en, n1}  and  X=¯span{en, n1}.

    For any integer k1, denote

    Ek=span{ek},  Yk=kj=1Ej  and  Zk=¯j=kEj.

    Consider now the functional

    Iλ(u)=J(u)λK(u),

    where

    J(u)=R2N(CΩ)2|u(x)u(y)|p(x,y)2p(x,y)|xy|N+sp(x,y)dxdy+Ω|u|¯p(x)¯p(x)dx+CΩβ(x)|u|¯p(x)v¯p(x)dx

    and

    K(u)=Ωa(x)|u(x)|q(x)q(x)dx.

    An important ingredient in the proof of Theorem 1.3 is the following version of the fountain theorem, see Zou [31].

    Theorem 3.1. Suppose that the functional Iλ defined above satisfies the following conditions:

    (T1)  Iλ maps bounded sets to bounded sets uniformly for λ[1,2]. Furthermore, Iλ(u)=Iλ(u) for all (λ,u)[1,2]×X;

    (T2)  K(u)0,  K(u) as u on any finite dimensional subspace of X;

    (T3) there exist ρk>rk>0 such that

    ak(λ):=infuZk,u=ρkIλ(u)0>bk(λ)=maxuYk,u=rkIλ(u)for λ[1,2],
    dk(λ)=infuZk,uρkIλ(u)0as k uniformly for λ[1,2].

    Then there exist a sequence of real numbers (λn) converging to 1 and u(λn)Yn such that Iλn|Yn(uλn)=0 and (Iλn)(u(λn))ck[dk(2),bk(1)] as n. In particular, fixed kN, if (u(λn)) has a convergent subsequence to uk, then I1 has infinitely many nontrivial critical points (uk)X{0} satisfying I1(uk)0 as k.

    We start with the following auxiliary property.

    Lemma 3.2. Suppose that condition (A) is satisfied. Then

    βk=supuZk,u=1Ωa(x)|u(x)|q(x)q(x)dx0  as  k+.

    Proof. It is easy to see that 0<βk+1βk, so that βkβ0 as k+. For every k0, by definition of βk, there exists ukZk such that uk=1 and Ωa(x)|uk|q(x)q(x)dx>βk2. Since ukZk, it follows that uk0 in X. From Proposition 1.2, we deduce that Ωa(x)|uk|q(x)q(x)dx0 as k+. Thus, β=0 and the proof is complete.

    Next, we prove the coercivity of K on finite dimensional subspaces of X.

    Lemma 3.3. Suppose that conditions of Theorem 1.3 are fulfilled. Then K(u)+ as u+ on any finite dimensional subspace of X.

    Proof. Let F be a finite dimensional subspace of X. Put

    ˜a(x)=a(x)q(x),  xΩ.

    First we show that there exists ϵ1>0 such that

    m{xΩ;  ˜a(x)|u|q(x)ϵ1uq(x)}ϵ1,  uF{0}. (3.1)

    Arguing by contradiction, for any positive integer n, there exists unF{0} such that

    m{xΩ;  ˜a(x)|un|q(x)1nunq(x)}<1n. (3.2)

    Set vn(x)=un(x)unF{0}. Then vn=1 for all nN and

    m{xΩ;  ˜a(x)|vn|q(x)1n}<1n.

    We may assume, up to a subsequence, that vnv0 in X for some v0F. Then v0=1 and, by Proposition 1.2,

    Ω˜a(x)|vnv0|q(x)dx0  as  n+. (3.3)

    Claim: There exists γ0>0 such that

    m{xΩ;  ˜a(x)|v0|q(x)γ0}γ0. (3.4)

    Otherwise, we have

    m{xΩ;  ˜a(x)|v0|q(x)1n}=0,  nN.

    It follows that

    0Ω˜a(x)|v0|q(x)+1dx<v01n0,  as  n+.

    Hence v0=0, which contradicts v0=1.

    Set

    Ω0={xΩ;  ˜a(x)|v0|q(x)γ0},  Ωn={xΩ;  ˜a(x)|vn|q(x)<1n}

    and

    Ωcn={xΩ;  ˜a(x)|vn|q(x)1n}.

    By (3.2) and (3.4), we obtain

    m(ΩnΩ0)=m(Ω0(ΩcnΩ0))m(Ω0)m(ΩcnΩ0)γ01n>γ02

    for large enough n. Consequently, for all large n, we have

    Ω˜a(x)|vnv0|q(x)dxΩnΩ0˜a(x)|vnv0|q(x)dx12q+1ΩnΩ0˜a(x)|v0|q(x)dxΩnΩ0˜a(x)|vn|q(x)dx(γ02q+11n)m(ΩnΩ0)γ202q++1>0,

    which is a contradiction to (3.3). Therefore (3.1) holds. For the ϵ1 given in (3.1), let

    Ωu={xΩ;  ˜a(x)|u|q(x)ϵ1uq(x)},  uF{0}.

    Then

    m(Ωu)ϵ1    uF{0}. (3.5)

    Using (B) and (3.5), for any uF{0} with u1, we infer that

    K(u)=Ω˜a(x)|u|q(x)dxΩu˜a(x)|u|q(x)dxϵ1uqm(Ωu)ϵ21uq.

    This shows that K(u) as u on any finite dimensional subspace of X and this gives the proof of our desired result.

    Lemma 3.4. Suppose that the conditions of Theorem 1.3 are satisfied. Then there exists a sequence ρk0+ as k+ such that

    ak(λ)=infuZk,u=ρkIλ(u)0,  kk1

    and

    dk(λ)=infuZk,uρkIλ(u)0  as  k+  uniformly for  λ[1,2].

    Proof. By Propositions 1.2 and 2.1, we deduce that for any uZk with u<1, we have

    Iλ(u)R2N(CΩ)2|u(x)u(y)|p(x,y)2p(x,y)|xy|N+sp(x,y)dxdy+Ω|u|¯p(x)¯p(x)dx+CΩβ(x)|u|¯p(x)v¯p(x)dxλΩa(x)q(x)|u(x)|q(x)dx13p+1p+up+λuq+Ωa(x)q(x)(|u(x)|u)q(x)dx13p+1p+up+2βkquq+. (3.6)

    We denote ρk=(3p+1(4p+)βkq)1p+q+. By Lemma 3.2 we deduce that ρk0 as k+. Then there exists k1N such that ρk13p+1p+ for all kk1. Relation (3.6) implies that

    ak(λ)=infuZk,u=ρkIλ(u)12.3p+1p+ρp++1k,  for all  kk1.

    Furthermore, by (3.6), we have

    0infuZk,uρkIλ(u)2βkquq,  kk1.

    Since βk0 as k+, we deduce that

    dk(λ)=infuZk,u=ρkIλ(u)0  as  k+  uniformly for  λ[1.2].

    This completes the proof.

    Lemma 3.5. Assume that hypotheses of Theorem 1.3 are fulfilled. Then, for the sequence obtained in Lemma 3.4, there exists 0<rk<ρk for all kN such that

    bk(λ)=maxuYk,u=rkIλ(u)<0  for all  λ[1,2].

    Proof. Let uYk with u<1 and λ[1,2]. By (A), (P) and (3.1), there exists ϵk>0 such that

    Iλ(u)=R2N(CΩ)2|u(x)u(y)|p(x,y)2p(x,y)|xy|N+sp(x,y)dxdy+Ω|u|¯p(x)¯p(x)dx+CΩβ(x)|u|¯p(x)v¯p(x)dxλΩa(x)|u(x)|q(x)q(x)dx3pupϵkuqm(Ωu)3pupϵ2kuq.

    Since 0<q<q+<p<p+, we deduce that for small u=rk we have

    bk(λ)<0,  kN.

    This completes the proof of our lemma.

    Proof of Theorem 1.3 completed. It is cleat that condition (T1) in Theorem 3.1 holds. Combining Lemmas 3.3, 3.4 and 3.5, we concludethat conditions (T2) and (T3) in Theorem 3.1 are satisfied. Then, by Theorem 3.1 there exist λn1 and u(λn)Yn such that

    Iλn|Yn(u(λn))=0,  Iλn(u(λn))ck[dk(2),bk(1)]

    as n+.

    For the sake of notational simplicity, we always set in what follows un=u(λn) for all nN.

    Claim: the sequence (un) is bounded in X.

    Otherwise, we can assume that (un) is unbounded in X. Without loss of generality, we can assume that un>1 for all n1.

    First, we can observe that there exists c>0 such that for large enough n,

    Iλn(un),unun  and  |Iλn(un)|c. (3.7)

    Using relation (3.7), we have

    cIλn(un)12p+R2N(CΩ)2|un(x)un(y)|p(x,y)|xy|N+sp(x,y)dxdy+1p+Ω|un|¯p(x)dx+1p+CΩβ(x)|un|¯p(x)dx1qΩa(x)|un(x)|q(x)dx. (3.8)

    From Proposition 2.1, relation (3.8) and since q+<p, we get that (un) is bounded in X. This proves that our claim is true. So, by Proposition 1.2 and up to a subsequence, we suppose that

    unu0  in  X

    and

    unu0  in  Lq(x)(Ω).

    In what follows we show that

    unu0  in  X.

    Recalling that (un) is a bounded sequence, we get

    limn+Iλn(un)Iλn(u0),unu0=0. (3.9)

    Hence, (3.9) and Proposition 1.2 give as n+

    o(1)=Iλn(un)Iλn(u0),unu0=R2N(CΩ)2|un(x)un(y)|p(x,y)2(un(x)un(y))|u(x)u(y)|p(x,y)2(u(x)u(y))|xy|N+sp(x,y)A(x,y)dxdy+Ω[|un|¯p(x)2un|u|¯p(x)2u](unu)dx+CΩβ(x)[|un|¯p(x)2un|u|¯p(x)2u](unu)dx

    where A(x,y)=(un(x)u(x)un(y)+u(y)).

    We have for all nN

    R2N(CΩ)2|un(x)un(y)|p(x,y)2(un(x)un(y))|u(x)u(y)|p(x,y)2(u(x)u(y))|xy|N+sp(x,y)A(x,y)dxdy0,
    Ω[|un|¯p(x)2un|u|¯p(x)2u](unu)dx0,

    and

    CΩβ(x)[|un|¯p(x)2un|u|¯p(x)2u](unu)dx0

    Therefore

    limn+R2N(CΩ)2|un(x)un(y)|p(x,y)2(un(x)un(y))|u(x)u(y)|p(x,y)2(u(x)u(y))|xy|N+sp(x,y)A(x,y)dxdy=0, (3.10)
    limn+Ω[|un|¯p(x)2un|u|¯p(x)2u](unu)dx=0, (3.11)

    and

    limn+CΩβ(x)[|un|¯p(x)2un|u|¯p(x)2u](unu)dx=0. (3.12)

    Let us now recall the Simon inequalities [28 formula 2.2]

    {|xy|pcp(|x|p2x|y|p2y).(xy)for  p2|xy|pCp[(|x|p2x|y|p2y).(xy)]p2(|x|p+|y|p)2p2for  1<p<2, (3.13)

    for all x,yRN, where cp and Cp are positive constants depending only on p. Combining (3.10), (3.11), (3.12) and (3.13), we conclude that

    limn+unu0=0.

    Now, by Theorem 3.1, we conclude the proof of Theorem 1.3.

    The author declares no conflict of interest.



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