Research article

On the uniqueness of meromorphic functions that share small functions on annuli

  • Received: 31 December 2019 Accepted: 17 March 2020 Published: 27 March 2020
  • MSC : 30D30, 30D35

  • In this paper, we aim to investigate the uniqueness of meromorphic functions that share small functions on annuli. As a matter of fact, we give several uniqueness theorems about meromorphic functions sharing four or three distinct small functions on the annulus A={z:1R0<|z|<R0}, where 1 < R0+. To some extent, our theorems extend the previous work by T. B. Cao, H. X. Yi and H. Y. Xu, and also generalize the work by N. Wu and Q. Ge.

    Citation: Da Wei Meng, San Yang Liu, Nan Lu. On the uniqueness of meromorphic functions that share small functions on annuli[J]. AIMS Mathematics, 2020, 5(4): 3223-3230. doi: 10.3934/math.2020207

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  • In this paper, we aim to investigate the uniqueness of meromorphic functions that share small functions on annuli. As a matter of fact, we give several uniqueness theorems about meromorphic functions sharing four or three distinct small functions on the annulus A={z:1R0<|z|<R0}, where 1 < R0+. To some extent, our theorems extend the previous work by T. B. Cao, H. X. Yi and H. Y. Xu, and also generalize the work by N. Wu and Q. Ge.


    In this article, we assume that the readers are familiar with the basic results and the standard notations of Nevanlinna's value distribution theory [16,18]. Let f and g be two non-constant moromorphic functions, and let a be a complex number or a small function with respect to f and g. Then, we say that f and g share a IM (or CM) provided that fa and ga have the same zeros ignoring (or counting) multiplicities.

    It is well known that R. Nevanlinna [11] proved the five-value theorem in 1926: For two non-constant meromorphic functions f and g in the complex plane C, we have fg providing that f and g share aj IM for j=1,2,3,4,5, where aj(j=1,2,3,4,5) are five distinct values. In 2000 and 2001, Y. H. Li, J. Y. Qiao [9] and H. X. Yi [17] extended this very work to the case of sharing five small functions, proving the five small functions theorem: Let f and g be two non-constant meromorphic functions in the complex plane C, and aj(j=1,2,3,4,5) be five distinct small functions with respect to f and g. If f and g share aj(j=1,2,3,4,5) IM in C, then fg. In 2003 and 2004, J. H. Zheng [19,20] proved the five value theorem in one angular domain. In 2011, H. F. Liu and Z. Q. Mao [10] further gave the five small functions theorem in one angular domain.

    Next we will mainly discuss the uniqueness theory of meromorphic functions on annuli. For the basic results and necessary notations as T0(r,f),m0(r,f),N0(r,f), the readers can refer to [4,5,6,7,13,14,15]. Here, let f,g,α be meromorphic functions on the annulus A={z:1R0<|z|<R0}, where 1<R0+. Then, α is named as a small function with respect to f on A providing that T0(r,α)=o(T0(r,f)) as r except for the set r such that rrλ1dr<+ for R0=+, or T0(r,α)=o(T0(r,f)) as rR0 except for the set r such that rdr(R0r)λ+1<+ for R0<+. For a nonconstant meromorphic function f on the annulus A, it is called as a transcendental meromorphic function on the annulus A if

    lim suprT0(r,f)logr=,1<r<R0=+

    or

    lim suprR0T0(r,f)log(R0r)=,1<r<R0<+,

    respectively. Therefore, for a transcendental meromorphic function on the annulus A, S(r,f)=o(T0(r,f)) holds for all 1<r<R0 except for the set r such that rrλ1dr<+ or the set r such that rdr(R0r)λ+1<+, respectively. Additionally we denote by ¯NC(r,α) (¯ND(r,α)) the reduced counting function of common zeros (different zeros) of fα and gα on A. Then, it is obvious that f and g share α IM if ¯ND(r,α)=0. Furthermore, we say f and g share α "IM'' provided that ¯ND(r,α)=o(T0(r,f))+o(T0(r,g)).

    Recently, T. B. Cao, H. X. Yi and H. X. Xu [1,2] obtained the following five-value theorem on the annulus A:

    Theorem A [1,2] Let f and g be two transcendental or admissible meromorphic functions on the annulus A={z:1R0<|z|<R0}, where 1<R0+. Let aj (j=1,2,3,4,5) be five distinct complex numbers in C{}. If f and g share aj IM for j=1,2,3,4,5, then fg. (In fact, this result for the case R0=+ was proved by A. A. Kondratyuk and I. Laine [6]).

    In 2015, N. Wu and Q. Ge [12] further proved the five small functions theorem on the annulus A as follows:

    Theorem B [12] Let f and g be two transcendental or admissible meromorphic functions on the annulus A={z:1R0<|z|<R0}, where 1<R0+. Let aj(j=1,2,3,4,5) be five distinct small functions with respect to f and g on the annulus A. If f and g share aj IM for j=1,2,3,4,5, then fg.

    Naturally, it is an interesting question to investigate whether Theorem B holds if f and g share less than five small functions. In this paper, we mainly deal with this question, and propose the following theorems, which partly generalize the five value theorem and the five small functions theorem on annuli.

    Theorem 1.1. Let f and g be two transcendental meromorphic functions on the annulus A={z:1R0<|z|<R0}, where 1<R0+. Let aiai(z)(i=1,2,3,4,5) be five distinct small functions with respect to f and g on A. If f and g share ai(i=1,2,3,4) "IM" and

    ¯NC(r,a5)S(r,f),

    then fg, where ¯NC(r,a5) is the reduced counting function of the common zeros of fa5 and ga5 (ignoring multiplicities) on A.

    Theorem 1.2. Let f and g be two transcendental meromorphic functions on the annulus A={z:1R0<|z|<R0}, where 1<R0+. Let aiai(z)(i=1,2,3,4,5) be five distinct small functions with respect to f and g on A. If f and g share ai(i=1,2,3) "IM" and

    ¯NC(r,a5)¯ND(r,a4)S(r,f),

    then fg, where ¯ND(r,aj) are the reduced counting functions of the different zeros of faj and gaj on A.

    In 2005, A. Y. Khrystiyanyn and A. A. Kondratyuk [4,5] proposed the following properties of meromorphic functions on annuli:

    Lemma 2.1. [4] Let f be a non-constant meromorphic function on the annulus A={z:1R0<|z|<R0}, where 1<r<R0+, then the following properties always hold:

    (ⅰ) T0(r,f)=T0(r,1f),

    (ⅱ) max{T0(r,f1f2),T0(r,f1/f2),T0(r,f1+f2)}T0(r,f1)+T0(r,f2)+O(1),

    (ⅲ) T0(r,1fa)=T0(r,f)+O(1),foreveryfixedaC.

    Lemma 2.2. [5] Let f be a non-constant meromorphic function on the annulus A={z:1R0<|z|<R0}, where R0+, and let λ0. Then

    (ⅰ) if R0=+, then m0(r,ff)=O(log(rT0(r,f))) for R(1;+) except for the set r such that rrλ1dr<+;

    (ⅱ) if R0<+, then m0(r,ff)=O(log(T0(r,f)R0r)) for r(1;R0) except for the set r such that rdr(R0r)λ+1<+.

    In addition, A. Y. Khrystiyanyn and A. A. Kondratyuk [5] proved the second fundamental theorem on annuli. Furthermore, T. B. Cao, H. X. Yi and H. Y. Xu [2] provided another form of the second fundamental theorem on the the annulus A:

    Lemma 2.3. [2] Let f be a non-constant meromorphic function on the annulus A={z:1R0<|z|<R0} in which 1<R0+. Let a1, a2, , aq be q distinct complex numbers in the extended complex plane ¯C. Then

    (q2)T0(r,f)<qj=1¯N0(r,1faj)+S(r,f).

    Motivated and inspired by the ideas of [3,8,17], we propose the following lemmas.

    Lemma 2.4. Let f be a transcendental meromorphic function on A={z:1R0<|z|<R0} in which 1<R0+, and let a1a1(z) and a2a2(z) be two distinct small functions with respect to f on A.

    Set

    L(f,a1,a2)=|ff1a1a11a2a21|,

    then, we have

    m0(r,L(f,a1,a2)fk(fa1)(fa2))=S(r,f),

    where k = 0, 1.

    Proof. It follows from the determinant nature that

    L(f,a1,a2)(fa1)(fa2)=fa2fa2fa1fa1.

    This implies

    m0(r,L(f,a1,a2)(fa1)(fa2))=S(r,f)

    by applying Lemma 2.2.

    Next we can deduce

    L(f,a1,a2)f(fa1)(fa2)=(a1a2)+a2fa2fa2a1fa1fa1

    by some simple computing. It follows that

    m0(r,L(f,a1,a2)f(fa1)(fa2))=S(r,f).

    Lemma 2.4 is proved.

    Lemma 2.5. Let f and g be two transcendental meromorphic functions on A, and let a1=0, a2=1, a3=, a4=a(z) be four distinct small functions respect to f and g on A, in which a(z)0,1,. Set

    HL(f,0,1)(fg)L(g,1,a)f(f1)(g1)(ga)L(g,0,1)(fg)L(f,1,a)g(g1)(f1)(fa).

    Then we get

    T0(r,H)4i=1¯ND(r,ai)+S(r,f)+S(r,g),

    where ¯ND(r,ai) is the reduced counting function of the different zeros of fai and gai on A.

    Proof. Here, we consider the counting function N0(r,H). It is obvious that the poles of H only come from the zeros, 1-points, poles of f or g, and the zeros of fa or ga on A. Firstly, let z4 be a common zero of fa and ga on A with multiplicity p and q respectively, satisfying that a(z4)0,1,. Applying the determinate nature, we have

    H(fg)[(ff1ff)(gagagg1)(gg1gg)(fafaff1)](fg)[ff1gaga+ggfafa+ffgg1gg1fafaffgagaggff1].

    It follows that H(z4) since z4 is a zero of (fg), and a simple pole or an analytic point of

    [ff1gaga+ggfafa+ffgg1gg1fafaffgagaggff1]. (2.1)

    Secondly, let z3 (resp. z1, z2) be a common pole (resp. zero, 1-points) of f and g on A with multiplicity p and q respectively, satisfying that a(z4)0,1, (resp. a(z1)0,1,, a(z2)0,1,). Without loss of generality, assume that pq. By simple computation, we can write H as

    a(a1)fg(fg)2f(f1)(fa)g(g1)(ga)+a(fg)[f(f1)(ga)gg(g1)(fa)f]f(f1)(fa)g(g1)(ga). (2.2)

    Noting that z3 is a pole of a(a1)fg(fg)2 with multiplicity 3p+q+2 at most, a pole of a(fg)[f(f1)(ga)gg(g1)(fa)f] with multiplicity 3p+2q+1 at most, and a pole of f(f1)(fa)g(g1)(ga) with multiplicity 3p+3q, we obtain H(z3). In the same manner, we can get H(z1),H(z2). Therefore, the poles of H only come from the different zeros of f,g,f1,g1,fa,ga and the different poles of f,g on A. In order to analyze these different zeros and different poles, we distinguish the following distinct cases.

    Case 1. Let ζ1 be a zero of f, which is neither a zero of g, a, and a1 nor a pole of a. Then, from (2.1) and (2.2) we find that ζ1 is a pole of H with multiplicity at most 1 if g(ζ1)1,,a(ζ1); and otherwise ζ1 is a pole of H with multiplicity at most 2.

    Case 2. Let ζ2 be a zero of f1, which is neither a zero of g1, a, and a1 nor a pole of a. By (2.1) and (2.2) we know that ζ2 is a pole of H with multiplicity at most 1 if g(ζ2)0,,a(ζ2); and otherwise ζ2 is a pole of H with multiplicity at most 2.

    Case 3. Let ζ3 be a pole of f, which is neither a pole of g and a nor a zero of a and a1. Then, it is clear that ζ3 is a pole of H with multiplicity at most 1 if g(ζ3)0,1,a(ζ3); and otherwise ζ3 is a pole of H with multiplicity at most 2.

    Case 4. Let ζ4 be a zero of fa, which is neither a zero of ga, a, and a1 nor a pole of a. It is obvious that that ζ4 is a pole of H with multiplicity at most 1 if g(ζ4)0,1,; and otherwise ζ4 is a pole of H with multiplicity at most 2.

    In view of the discussion above, we deduce that

    N0(r,H)4i=1¯ND(r,ai)+N0(r,1a)+N0(r,1a1)+N0(r,a)=4i=1¯ND(r,ai)+S(r,f).

    Moreover, it is a direct consequence of Lemma 2.4 that m0(r,H)=S(r,f)+S(r,g), which implies that

    T0(r,H)=m0(r,H)+N0(r,H)4i=1¯ND(r,ai)+S(r,f)+S(r,g).

    Lemma 2.5 is proved.

    By Lemma 2.1 and Lemma 2.3, we derive that T0(r,f)3T0(r,g)+S(r,f) and T0(r,g)3T0(r,f)+S(r,g) noting that f and g share ai(i=1,2,3,4) "IM". Then, it is obvious that S(r,f)=S(r,g).

    By applying the quasi-M¨obius transformation

    fa1fa3a2a3a2a1,

    we can assume that a1(z)=0, a2(z)=1, a3(z)=, a4(z)=a(z), a5(z)=b(z), where a,b are two distinct small functions of f and g on A satisfying a,b0,1,. As in Lemma 2.5, we set

    HL(f,0,1)(fg)L(g,1,a)f(f1)(g1)(ga)L(g,0,1)(fg)L(f,1,a)g(g1)(f1)(fa).

    Since f and g share 0,1,,a "IM", we can deduce T0(r,H)=S(r,f) by the virtue of Lemma 2.5.

    It is obvious that a common zero of fb and gb must be a zero of H when it is not a zero of b,b1,ba. We assume that H0, then, we get

    ¯NC(r,b)N0(r,1H)+S(r,f)T0(r,H)+S(r,f)=S(r,f).

    This contradict ¯NC(r,b)S(r,f). It follows that H0.

    In the following we assume that fg. From H0 we have

    L(f,0,1)L(g,1,a)f(ga)L(g,0,1)L(f,1,a)g(fa).

    It follows that

    ff[a(a1)gaga]gg[a(a1)fafa]. (3.1)

    If a is a constant, then from (3.1) we get

    ff[(a1)gga]gg[(a1)ffa],

    which further yields fg. This is a contradiction, we consequently have a0. Note that the equation (3.1) can be written as

    f[a(ga)(a1)(ga)]g[a(fa)(a1)(fa)]1=f(ga)g(fa)1.

    This implies

    fgfg=gg1a[a(fa)(a1)(fa)]ag(g1)(fa). (3.2)

    Since ¯NC(r,b)S(r,f), there exist a point z0 satisfying that z0 is a common zero of fb and gb, but not a zero or pole of a,a,b,b1,ba. It follows that z0 is a simple pole of the left side of (3.2), but not a pole of the right side of (3.2), which is impossible. Hence Theorem 1.1 is proved.

    To the contrary, we suppose that fg. Similarly to the proof of Theorem 1.1, we can get

    T0(r,H)¯ND(r,a)+S(r,f)

    by utilizing Lemma 2.5. If H0, then we have

    ¯NC(r,b)N0(r,1H)+S(r,f)T0(r,H)+S(r,f)¯ND(r,a)+S(r,f),

    which contradict ¯NC(r,b)¯ND(r,a)S(r,f). We consequently obtain H0, and then the equations (3.1) and (3.2) still hold.

    Note that ¯NC(r,b)¯ND(r,a)S(r,f) implies ¯NC(r,b)S(r,f). So there exists a point z0 satisfying that z0 is a common zero of fb and gb, but not a zero or pole of a,a,b,b1,ba. Clearly, z0 is a simple pole of the left side of (3.2), but not a pole of the right side of (3.2). This is impossible. Therefore we have proved Theorem 1.2.

    This work was supported by the NSF of China (11271227, 11561033, 61373174) and the Fundamental Research Funds for the Central Universities (JB180708). The authors would like to thank the editors and referees for making valuable suggestions to improve this paper.

    The authors declare no conflicts of interest.



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