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Research article Special Issues

Energy equality in the isentropic compressible Navier-Stokes-Maxwell equations

  • This paper concerns energy conservation for weak solutions of compressible Navier-Stokes-Maxwell equations. For the energy equality to hold, we provide sufficient conditions on the regularity of weak solutions, even for solutions that may include exist near-vacuum or on a boundary. Our energy conservation result generalizes/extends previous works on compressible Navier-Stokes equations and an incompressible Navier-Stokes-Maxwell system.

    Citation: Jie Zhang, Gaoli Huang, Fan Wu. Energy equality in the isentropic compressible Navier-Stokes-Maxwell equations[J]. Electronic Research Archive, 2023, 31(10): 6412-6424. doi: 10.3934/era.2023324

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  • This paper concerns energy conservation for weak solutions of compressible Navier-Stokes-Maxwell equations. For the energy equality to hold, we provide sufficient conditions on the regularity of weak solutions, even for solutions that may include exist near-vacuum or on a boundary. Our energy conservation result generalizes/extends previous works on compressible Navier-Stokes equations and an incompressible Navier-Stokes-Maxwell system.



    In this paper, the following isentropic compressible Navier-Stokes-Maxwell (CNSM) system is considered, which consists of Navier-Stokes equations of fluid dynamics and Maxwell's equations of electromagnetism. The coupling comes from the Lorentz force in the fluid equation and the electric current in the Maxwell following equations:

    {tρ+div(ρu)=0,t(ρu)+div(ρuu)μΔu(λ+μ)divu+P(ρ)=j×b,tE×b+j=0,j:=E+u×b,tb+×E=0,divb=0, (1.1)

    with the initial data

    (ρ,u,E,b)(,0)=(ρ0,u0,E0,b0), (1.2)

    where ρ is the density, u is the velocity field, and E and b represent electronic and magnetic fields, respectively. The fluid pressure is represented by P(ρ) meets:

    P(ρ)=aργwitha>0,γ>1, (1.3)

    where a is a physical constant and γ is the adiabatic exponent. The viscosity coefficients μ and λ are constant and satisfy the physical restrictions μ>0 and 2μ+3λ0. j is the electric current expressed by the Ohms law. The force term j×B in Navier-Stokes equations comes from Lorentz force under a quasi-neutrality assumption of the net charge carried by the fluid. If the electric current is ignored (i.e., j=0), (1.1) reduces to the well-known isentropic compressible Navier-Stokes (CNS) system. Equation (1.1) is one of the most important mathematical models in continuum mechanics. Lions [1] and Feireisl [2,3,4] proved that the CNS system admits a weak solution, as long as the adiabatic exponent γ>32. Due to a lack of regularity of weak solutions, it is not known whether weak solutions satisfy the energy equality for both incompressible and compressible fluids equations. It is a nature problem: how "good" is regularity for weak solutions needed to ensure the energy equality?

    For a CNS system, the appearance of ρ makes t(ρu) nonlinear, and; therefore, some density regularity is required in when using commutator estimates. Yu [5] used the Lions's commutator estimate to show energy conservation for compressible Navier-Stokes equations with a degenerate viscosity but without vacuum. Nguyen et al. [6] extended Yu's result with a weaker regularity condition in a bounded domain. Liang [7] established a LpLs type condition for the energy equality, in particular, there was no need regularly assume the density derivative. Recently, Ye et al. [8] showed that Lions' condition for energy balance is also valid for the weak solutions of isentropic compressible Navier-Stokes equations allowing for vacuum under suitable integral conditions on the density and its derivative. This is a very interesting result.

    Comparing with fruitful results for either an incompressible Navier-Stokes system or a compressible case, there are a few results regarding an incompressible/compressible NSM model due to its hyperbolic structure. For the incompressible NSM system, Ma and Wu [9] obtained the Shinbrot type energy conservation criteria for the weak solution. In addition, for the distributional solution, he showed the Lions' energy conservation criteria [10]. To the best of our knowledge, there is no result concerning the energy equality for a CNSM system (1.1).

    Motivated by [7,8,9,10], the purpose of this paper is to establish the conditional energy conservation of weak solutions to the CNSM system (1.1) allowing for vacuum. By proving an energy conservation/equality, the commutator estimates are required for treating the nonlinear terms. Furthermore, due to the special structure of parabolic hyperbolic coupling, the derivative to the velocity field u needs to be transfered. We state the result in detail in the theorem below.

    Theorem 1.1. Let 0ρ<c<, ρL4(0,T;L4(T3)), uL(0,T;L2(T3))L2(0,T;H1(T3)), (E,b)L(0,T;L2(T3)) and jL2(0,T;L2(T3)) be a weak solution to system (1.1). In addition, if (u,b)L4(0,T;L4(T3)) and EL2(0,T;L2(T3)), then the weak solution satisfies the following energy equality:

    T3(12|ρu|2+12|E|2+12|b|2+aργγ1)dx+T0T3μ|u|2+(μ+λ)|divu|2+|j|2dxds=T3(12|ρ0u0|2+12|E0|2+12|b0|2+aργ0γ1)dx. (1.4)

    Remark 1.1. This theorem extends the energy equality of the incompressible NSM to the isentropic compressible equations (1.1) with vacuum.

    Remark 1.2. Since u,bL(0,T;L2(T3))Lp(0,T;Lq(T3)), for any 1p+1q12, q4, one can deduce that

    uL4(0,T;L4(T3))CuaL(0,T;L2(T3))u1aLp(0,T;Lq(T3)),

    and

    bL4(0,T;L4(T3))CbaL(0,T;L2(T3))b1aLp(0,T;Lq(T3)),

    for some a(0,1). Thus, it is also true that L4(0,T;L4(T3)) in Theorem 1.1 is replaced with Lp(0,T;Lq(T3)), for any 1p+1q12, q4.

    We will recall some definitions and lemmas that will be used later. First, we denote D(T3) as the space of indefinitely differentiable with compact support and D(T3) as the space of distributions.

    Definition 2.1. The (ρ,u,E,b) is called a weak solution to the CNSM systems (1.1) and (1.2) if (ρ,u,E,b) satisfies the following assumptions for any time t[0,T]:

    The problems (1.1) and (1.2) holds in D(0,T;T3);

    The equation (1.1)1 is satisfied in the sense of renormalized solutions: for any function bC1(R) such that b(x)=0 for xM), we get in D(0,T;T3):

    tb(ρ)+div(b(ρ)u)+(b(ρ)ρb(ρ))divu=0

    where M is a constant that varies for different functions b.

    The weak solutions require the following properties:

    ρuL(0,T;L2(T3)),uL2(0,T;W1,20(T3)),EL(0,T;L2(T3)),ρL(0,T;L1Lγ(T3)),bL(0,T;L2(T3)),jL2(0,T;L2(T3)), (2.1)

    The energy inequality for weak solutions holds:

    T3(12|ρu|2+12|E|2+12|b|2+aργγ1)dx+T0T3μ|u|2+(μ+λ)|divu|2+|j|2dxdsT3(12|ρ0u0|2+12|E0|2+12|b0|2+aργ0γ1)dx. (2.2)

    Let ηCc(Rd) (d is the number of the space dimension) be a standard mollification kernel and set

    ηε(x)=1εd+1η(xε),wϵ=ηεw,fε(w)=f(w)ηε.

    We should notice that wε is well-defined on Ωε={xΩ:d(x,Ω)>ε}. Next, we recall some useful lemmas which will be frequently used throughout the paper.

    Lemma 2.1. [8] Let r,s,r1,r2,s1,s2[1,+) with 1r=1r1+1r2 and 1s=1s1+1s2. Assume fLr1(0,T;Ls1(T3)) and gLr2(0,T;Ls2(T3)). Then, for any ε>0, there holds

    (fg)εfεgεLr(0,T;Ls(T3))0,asε0,

    and

    (f×g)ε(fε×gε)Lr(0,T;Ls(T3))0,asε0.

    Lemma 2.2. [8,11,12] Let 1r,s,r1,s1,r2,s2, with 1r=1r1+1r2 and 1s=1s1+1s2. Let be a partial derivative in space or time; in addition, let tf, fLr1(0,T;Ls1(T3)), gLr2(0,T;Ls2(T3)). Then, there holds

    (fg)ε(fgε)Lr(0,T;Ls(T3))C(tfLr1(0,T;Ls1(T3))+fLr1(0,T;Ls1(T3)))gLr2(0,T;Ls2(T3)),

    or some constant C>0 independent of ε, f and g. Moreover, as ε0 if r2,s2<,

    (fg)ε(fgε)0inLr(0,T;Ls(T3)).

    Lemma 2.3. [13] Let B0BB1 be three Banach spaces with compact embedding B0↪↪B1, and let there exist 0<δ<1 and C>0 such that

    uBCu1δB0uδB1foralluB0B1.

    Denote for T>0,

    W(0,T)=Ws0,r0(0,T;B0)Ws1,r1(0,T;B1)

    with

    s0,s1R;0r0,r1.
    sδ=(1δ)s0+δs1,1rδ=1δr0+δr1,s=sδ1rδ.

    Assume that sδ>0 and G is a bounded set in W(0,T), Then, we have the following:

    If s0, then G is relatively compact in Lp(0,T;B) for all 1p<p:=1s.

    If s>0, then G is relatively compact in C(0,T;B).

    First, we mollify the system (1.1) and obtain

    tρε+(ρu)ε=0, (3.1)
    t(ρu)ε+(ρuu)εμΔuε(λ+μ)divuε+(P(ρ))ε=(j×b)ε, (3.2)
    tEε(×b)ε+jε=0, (3.3)

    and

    tbε+(×E)ε=0 (3.4)

    for any 0<ε<1.

    Next, let ϕ(t) be a smooth solution function compactly supported in (0,+). Multiplying (3.2)–(3.4) by ϕ(t)uε, ϕ(t)Eε, and ϕ(t)bε, respectively, then integrating over (0,T)×T3, one has the following:

    T0T3ϕ(t)uεt(ρu)εdxdt+T0T3ϕ(t)uε(ρuu)εdxdtμT0T3ϕ(t)uεΔuεdxdt(λ+μ)T0T3ϕ(t)uεdivuεdxdt+T0T3ϕ(t)uε(P(ρ))εdxdtT0T3ϕ(t)uε(j×b)εdxdt+T0T3ϕ(t)EεtEεdxdtT0T3ϕ(t)Eε(×b)εdxdt+T0T3ϕ(t)Eεjεdxdt+T0T3ϕ(t)bεtbεdxdt+T0T3ϕ(t)bε(×E)εdxdt=0. (3.5)

    We use (A)–(H) and (J)–(L) to represent the terms on the left-hand side of (3.5), respectively. We will estimate them as follows.

    By a straightforward computation, we can obtain the following:

    (A)=T0T3ϕ(t)uε(t(ρu)εt(ρuε))dxdt+T0T3ϕ(t)uεt(ρuε)dxdt=:(A1)+T0T3ϕ(t)ρt|uε|2dxdt+T0T3ϕ(t)ρt|uε|22dxdt=:(A1)+(A2)+(A3).

    We know that (A3) is the desire term while (A2) will be canceled with the term (B2) later. By Hölder's inequality and Lemma 2.2, it gives that the following:

    (A1)=T0T3ϕ(t)uε(t(ρu)εt(ρuε))dxdtCuεL4(0,T;L4(T3))t(ρu)εt(ρuε)L43(0,T;L43(T3))Cu2L4(0,T;L4(T3))(tρL2(0,T;L2(T3))+ρL2(0,T;L2(T3))).

    Based on system (1.1), ρt and ρ can be denoted as follows:

    ρt=2ρvρρdivu,ρ=2ρρ.

    We will obtain the estimate of ρt and ρ by using 0ρ<c<, (u,ρ)L4(0,T;L4(T3)) and uL2(0,T;L2(T3)) in Theorem 1.1, which implies that

    ρtL2(0,T;L2(T3))C(2ρuρL2(0,T;L2(T3))+ρdivuL2(0,T;L2(T3)))C(uL4(0,T;L4(T3))ρL4(0,T;L4(T3))+uL2(0,T;L2(T3))), (3.6)

    and

    ρL2(0,T;L2(T3))CρρL2(0,T;L2(T3))CρL4(0,T;L4(T3)). (3.7)

    Inserting (3.6) and (3.7) into (A1) yields the following:

    T0T3ϕ(t)uε[t(ρu)εt(ρuε)]dxdtCu2L4(0,T;L4(T3))((uL4(0,T;L4(T3))+1)ρL4(0,T;L4(T3))+uL2(0,T;L2(T3)))C.

    From Lemma 2.2, we get the estimate of (A1) that

    lim supε0|(A1)|=0.

    By utilizing integration by parts and the mass equation (1.1), we deduce that

    (B)=T0T3ϕ(t)uε(ρuu)εdxdt=T0T3ϕ(t)uε[(ρuu)ε(ρu)uε]dxdtT0T3ϕ(t)uε((ρu)uε)dxdt=:(B1)+T0T3ϕ(t)uεdiv((ρu)uε)dxdt=:(B1)+T0T3ϕ(t)[div(ρu)|uε|2+12(ρu)|uε|2]dxdt=:(B1)+T0T3ϕ(t)div(ρu)|uε|2dxdt12T0T3ϕ(t)div(ρu)|uε|2dxdt=:(B1)+(B2)+12T0T3ϕ(t)tρ|uε|2dxdt=:(B1)+(B2)+(B3).

    Taking the mass equation (1.1)1 into consideration, we know that (A2)+(B2)=0. The (B3) is the desired term.

    (A3)+(B3)=12T0T3ϕ(t)t(ρ|uε|2)dxdt. (3.8)

    By Hölder's inequality and triangle inequality, we deduce the following:

    (B1)=T0T3ϕ(t)uε[(ρuu)ε(ρu)uε]dxdtCuεL2(0,T;L2(T3))(ρuu)ε(ρu)uεL2(0,T;L2(T3))CuεL2(0,T;L2(T3))((ρuu)ε(ρu)uL2(0,T;L2(T3))+(ρu)u(ρu)uεL2(0,T;L2(T3)))CuεL2(0,T;L2(T3))((ρuu)ε(ρu)uL2(0,T;L2(T3))+ρuL4(0,T;L4(T3))uuεL4(0,T;L4(T3)))

    Thanks to the standard properties of mollifiers, we have the following:

    lim supε0|(B1)|=0.

    Utilizing integration by parts, we know that the following (C) and (D) are the desired terms, where

    (C)=μT0T3ϕ(t)uεΔuεdxdt=μT0T3ϕ(t)|uε|2dxdt,

    and

    (D)=(λ+μ)T0T3ϕ(t)uεdivuεdxdt=(λ+μ)T0T3ϕ(t)|divuε|2dxdt.

    Utilizing integration by parts and applying (1.1) leads to the following:

    (E)=T0T3ϕ(t)uε[(P(ρ))εP(ρ)]dxdt+T0T3ϕ(t)uεP(ρ)dxdt=:(E1)+T0T3ϕ(t)(uεu)P(ρ)dxdt+T0T3ϕ(t)uP(ρ)dxdt=:(E1)+(E2)+T0T3ϕ(t)uaγγ1ρ(ργ1)dxdt=:(E1)+(E2)T0T3ϕ(t)div(ρu)aγγ1ργ1dxdt=:(E1)+(E2)+T0T3ϕ(t)tρaγγ1ργ1dxdt=:(E1)+(E2)+1γ1T0T3ϕ(t)t(aρ)γdxdt=:(E1)+(E2)+1γ1T0T3ϕ(t)tP(ρ)dxdt=:(E1)+(E2)+(E3).

    The term (E3) is the desired term, and the estimate of (E1) and (E2) will be finished as follows:

    (E1)=T0T3ϕ(t)uε[(P(ρ))εP(ρ)]dxdtuεL4(0,T;L4(T3))(P(ρ))εP(ρ)L43(0,T;L43(T3)),

    and

    (E2)=T0T3ϕ(t)(uεu)P(ρ)dxdtCuεuL4(0,T;L4(T3))P(ρ)L43(0,T;L43(T3)).

    By the upper bounded of ρ and Hölder's inequality, we have the following:

    P(ρ)L43(0,T;L43(T3))CP(ρ)ρL43(0,T;L43(T3))CρL4(0,T;L4(T3)). (3.9)

    Combining the standard properties of mollifiers and (3.9), we know that

    lim supε0|(E1)|=lim supε0|(E2)|=0.

    Next, we turn to estimate (F) and (J), of which the proof is inspired by [10], and we include that

    (F)+(J)=T0T3ϕ(t)[uε(j×b)ε+Eεjε]dxdt=T0T3ϕ(t)uε[(j×b)ε+(jε×bε)(jε×bε)]+ϕ(t)Eεjεdxdt=T0T3ϕ(t)uε[(jε×bε)(j×b)ε)]dxdt+T0T3ϕ(t)[(uε×bε)jε+Eεjε]dxdt=:(FJ)1+T0T3ϕ(t)|jε|2dxdt+T0T3ϕ(t)[(uε×bε)(u×b)ε]jεdxdt=:(FJ)1+(FJ)2+(FJ)3.

    We see that (FJ)2 is desired term, while the estimates of (FJ)1 and (FJ)2 will be finished. By Hölder's inequality, we can conclude that

    (FJ)1=T0T3ϕ(t)uε[(jε×bε)(j×b)ε)]dxdtCuεL4(0,T;L4(T3))(jε×bε)(j×b)εL43(0,T;L43(T3))CuL4(0,T;L4(T3))(jεbε)(jb)εL43(0,T;L43(T3)),

    and

    (FJ)3=T0T3ϕ(t)[(uε×bε)(u×b)ε]jεdxdtC(uε×bε)(u×b)εL2(0,T;L2(T3))jεL2(0,T;L2(T3))C(uε×bε)(u×b)εL2(0,T;L2(T3))jL2(0,T;L2(T3)).

    However, the following results are valid by using Hölder's inequality:

    jεbεL43(0,T;L43(T3))CjL2(0,T;L2(T3))bL4(0,T;L4(T3)). (3.10)

    and

    uε×bεL2(0,T;L2(T3))CuL4(0,T;L4(T3))bL4(0,T;L4(T3)). (3.11)

    Therefore, from (FJ)1, (FJ)3, (3.10) and (3.11), with the help of Lemma 2.1, we obtain the following:

    lim supε0|(FJ)1|=0,lim supε0|(FJ)3|=0.

    The remaining is to estimate (G), (H), (L) and (K). Using a straightforward computation leads to

    (G)=T0T3ϕ(t)tEεEεdxdt=12T0T3ϕ(t)t|Eε|2dxdt,

    and

    (H)+(L)=T0T3ϕ(t)[Eε(×b)ε+bε(×E)ε]dxdt=T0T3ϕ(t)Eεiϵijkjbεkdxdt+T0T3ϕ(t)bε(×E)εdxdt=T0T3ϕ(t)ϵijkjEεibεkdxdt+T0T3ϕ(t)bε(×E)εdxdt=T0T3ϕ(t)ϵkjijEεibεkdxdt+T0T3ϕ(t)bε(×E)εdxdt=T0T3ϕ(t)bε(×E)εdxdt+T0T3ϕ(t)bε(×E)εdxdt=0,

    and

    (K)=T0T3ϕ(t)bεtbεdxdt=12T0T3ϕ(t)t|bε|2dxdt.

    Then, summarizing all above the aforementioned estimates, putting them into (3.5) and taking the limit as ε0, we obtain the following:

    T0T3ϕ(t)t(12ρ|u|2+12|E|2+12|b|2+aργγ1)dxdt+T0T3ϕ(t)(μ|u|2+(μ+λ)|divu|2+|j|2)dxdt=0.

    We can express it in the following form:

    T0T3ϕt(12ρ|u|2+12|E|2+12|b|2+aργγ1)dxdt+T0T3ϕ(t)(μ|u|2+(μ+λ)|divu|2+|j|2)dxdt=0. (3.12)

    Next, we study a similar method in [5] and shall prove the energy equality up to the initial time t=0. First, we claim that the following results are valid for any t00:

    limtt+0E(t)L2(T3)=E(t0)L2(T3),limtt+0b(t)L2(T3)=b(t0)L2(T3),limtt+0ρu(t)L2(T3)=ρu(t0)L2(T3),limtt+0ργ(t)L1(T3)=ργ(t0)L1(T3). (3.13)

    Based on the mass equation (1.1), we can write

    tργ=γργdivu2γργ12uρ,

    and

    t(ρ)=ρ2divuuρ,

    which, together with the assumptions in Theorem 1.1, gives

    (tργ,tρ)L2(0,T;L2(T3)),

    and

    (ργ,ρ)L4(0,T;L4(T3)).

    Hence, due to Lemma 2.3, it yields that the following:

    (ργ,ρ)C([0,T];L2(T3)). (3.14)

    Consequently, for any t00, by the right temporal continuity of ργ in L2(T3) and L2(T3)L1(T3), we deduce that the following:

    ργ(t)ργ(t0)stronglyinL1(T3)astt+0, (3.15)

    Furthermore, using the momentum equation (1.1)2, we obtain the following:

    ρuL(0,T;L2(T3)),(ρu)tL2(0,T;H1(T3)).

    Then, because of Lemma 2.3, we have the following:

    ρuC([0,T];L2weak(T3)). (3.16)

    Similarly, from (1.1)3, (1.1)4 and (2.2), we can deduce that the following:

    tEL2(0,T;L2(T3)),,tbL(0,T;L2(T3)).

    On the other hand, the assumptions in Theorem 1.1 implies

    (E,b)L(0,T;L2(T3)),

    which can be obtained that leads to the following conclusion:

    (E,b)C([0,T];L2(T3)). (3.17)

    Hence, for any t00, from (3.17), we get that the following:

    E(t)E(t0)stronglyinL2(T3)astt+0,b(t)b(t0)stronglyinL2(T3)astt+0. (3.18)

    Meanwhile, utilizing (2.2), (3.14), (3.16), (3.17) and the assumptions in Theorem 1.1 yields to the following:

    0¯limt0|ρuρ0u0|2dx=2¯limt0((12ρ|u|2+12|E|2+12|b|2+aργγ1)dx(12ρ0|u0|2+12|E0|2+12|b0|2+aργ0γ1)dx)+2¯limt0(ρ0u0(ρ0u0ρu)dx+aγ1(ργ0ργ)dx)+¯limt0((E20E2)+(b20b2)dx)2¯limt0ρ0u0(ρ0u0ρu)dx2¯limt0u0(ρ0u0ρu)dx+2¯limt0u0ρu(ρρ0)dx=0,

    which implies

    ρu(t)ρu(0)stronglyinL2(T3)ast0+. (3.19)

    Similarly, we can establish the right temporal continuity of ρu in L2(T3); hence, for any t00, we have the following:

    ρu(t)ρu(t0)stronglyinL2(T3)astt+0. (3.20)

    Combining (3.15), (3.18) and (3.20), we have now completed the proof of (3.13).

    We notice that (3.12) is valid for ϕ belonging to W1, rather than C1. Therefore, for any t0>0, we can use a new test function ϕτ to represent ϕ for some positive τ and α such that τ+α<t0, that is

    ϕτ(t)={0,0tτ,tτα,τtτ+α,1,τ+αtt0,t0tα,t0tt0+α,0,t0+αt.

    Then, substituting this function into (3.12), we have the following:

    τ+ατT31α(12ρ|u|2+12|E|2+12|b|2+aργγ1)dxdt+1αt0+αt0T3(12ρ|u|2+12|E|2+12|b|2+aργγ1)dxdt+1αt0+ατT3ϕτ(μ|u|2+(μ+λ)|divu|2+|j|2)dxdt=0. (3.21)

    Letting α0 and using the fact that t0T3ϕτ(μ|u|2+(μ+λ)|divu|2+|j|2)dxdt is continuous with respect to t and the Lebesgue point Theorem, for all τ and t0[0,T], we arrive at the following:

    T3(12ρ|u|2+12|E|2+12|b|2+aργγ1)(τ)dt+T3(12ρ|u|2+12|E|2+12|b|2+aργγ1)(t0)dt+t0τT3(μ|u|2+(μ+λ)|divu|2+|j|2)dxdt=0. (3.22)

    Finally, taking τ0, combining the continuity of t00T3(μ|u|2+(μ+λ)|divu|2+|j|2)dxdt and (3.13), for all t0[0,T], we can deduce that

    T3(12ρ|u|2+12|E|2+12|b|2+aργγ1)(t0)dt+t00T3(μ|u|2+(μ+λ)|divu|2+|j|2)dxdt=T3(12ρ0|u0|2+12|E0|2+12|b0|2+aργ0γ1)dt.

    This now completes the proof of Theorem 1.1.

    The authors declare they have not used Artificial Intelligence (AI) tools in the creation of this article.

    Jie Zhang was supported by Innovation Research for the Postgraduates of Guangzhou University (No. 2022GDJC-D08), Guangdong Basic and Applied Basic Research Foundation (No. 2022A1515010566) and National Natural Science Foundation of China (No. 12171111). Fan Wu was supported by the Science and Technology Project of Jiangxi Provincial Department of Education (No. GJJ2201524) and the Jiangxi Provincial Natural Science Foundation(No. 20224BAB211003).

    The authors declare there is no conflicts of interest.



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