In this paper, we devote to studying the existence of normalized solutions for the following Schrödinger equation with Sobolev critical nonlinearities.
{−Δu=λu+μ|u|q−2u+|u|p−2uin RN,∫RN|u|2dx=a2,
where N⩾3, 2<q<2+4N, p=2∗=2NN−2, a,μ>0 and λ∈R is a Lagrange multiplier. Since the existence result for 2+4N<p<2∗ has been proved, using an approximation method, that is let p→2∗, we obtain that there exists a mountain-pass type solution for p=2∗.
Citation: Shengbing Deng, Qiaoran Wu. Existence of normalized solutions for the Schrödinger equation[J]. Communications in Analysis and Mechanics, 2023, 15(3): 575-585. doi: 10.3934/cam.2023028
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In this paper, we devote to studying the existence of normalized solutions for the following Schrödinger equation with Sobolev critical nonlinearities.
{−Δu=λu+μ|u|q−2u+|u|p−2uin RN,∫RN|u|2dx=a2,
where N⩾3, 2<q<2+4N, p=2∗=2NN−2, a,μ>0 and λ∈R is a Lagrange multiplier. Since the existence result for 2+4N<p<2∗ has been proved, using an approximation method, that is let p→2∗, we obtain that there exists a mountain-pass type solution for p=2∗.
In this paper, we consider the existence of solutions for the following Schrödinger equation.
iψt+Δψ+μ|ψ|q−2ψ+|ψ|p−2ψ=0in R+×RN, | (1.1) |
where N⩾3, 2<q<2+4N and p=2∗=2NN−2. The Schrödinger equation is a famous equation in Physics and there are numerous papers to study it, we refer the readers to [1,2,3,4] and references therein.
For (1.1), we are particularly interested in the stationary waves of the form ψ(x,t)=e−iλtu(x), where λ∈R and u:RN→R. Then u satisfies the equation
−Δu=λu+μ|u|q−2u+|u|p−2uin RN. | (1.2) |
If we fix the L2-norm of u, that is, let
u∈Sa:={v∈H1(RN):‖v‖22=a2}, |
where a>0 is a constant. Then the corresponding functional of (1.2) is
Ep(u)=12‖∇u‖22−μq‖u‖qq−1p‖u‖pp, |
and λ appears as a Lagrange multiplier. Solutions of (1.2) with prescribed mass are always called normalized solutions. It seems that there is profound physical significance to study normalized solutions. In fact, for the Schrödinger equation, |ψ(x,t)|2 represents the probability density of a single particle appearing in space x at time t. Naturally, there is
∫RN|ψ(x,t)|2dx=1. |
Of course, in mathematics, we often consider
∫RN|ψ(x,t)|2dx=a2. |
There are a lot of papers to study the normalized solutions of Schrödinger equations and it is impossible for us to provide complete references. We refer the readers to [5,6,7,8,9,10,11] and references therein. Moreover, we refer the readers to [12,13,14] for the normalized solutions of fractional Schrödinger equations and to [15,16,17] for the normalized solutions of Schrödinger systems.
When we study the normalized solutions, there will be a L2-critical exponent 2+4N, which comes from the Gagliardo-Nirenberg inequality[18]: for every 2<p<2∗, there exists an optimal constant CN,p depending on N and p such that
‖u‖p⩽CN,p‖∇u‖γp2‖u‖1−γp2∀u∈H1(RN), |
where
γp:=N(p−2)2p. |
By the Gagliardo-Nirenberg inequality, it is not difficult to prove that if the nonlinearities of equation are L2-subcritical, then the corresponding functional is bounded from below on Sa. For example,
J(u)=12‖∇u‖22−1p‖u‖pp |
is bounded from below on Sa for 2<p<2+4N and global minimizers of J|Sa can be found, see [8,19]. However, if the nonlinearities are L2-supercritical, the functional is unbounded from below on Sa and it seems impossible to search for a global minimizer. The first paper to deal with L2-supercritical is [5]. In [5], Jeanjean found the normalized solutions of mountain-pass type.
Compared with pure L2-subcritical or L2-supercritical case, the mixed case is more complicated. In [9], Soave studied (1.2) for 2<q<2+4N<p<2∗ under L2 constraint. Since q is L2-subcritical exponent and p is L2-supercritical exponent, we call μ|u|q−2+|u|p−2u mixed nonlinearities. The first existence result of normalized solutions in Sobolev critical case was also obtained by Soave[10].
Since the L2 constraint, there are some difficulties to observe the structure of Ep|Sa. A possible method is to consider the function
Ψpu(s):=Ep(s⋆u)=12e2s‖∇u‖22−μqeqγqs‖u‖qq−1pepγps‖u‖pp, |
where
s⋆u:=eNs2u(es⋅). |
It is not difficult to prove that s⋆u∈Sa for all s∈R if u∈Sa and hence we can study the structure of Ψpu to speculate the structure of Ep|Sa.
If u is a critical point of Ep|Sa, then 0 may be a critical point of Ψpu. If 0 is a critical point of Ψpu, then (Ψpu)′(0)=0, that is
‖∇u‖22=μγq‖u‖qq+γp‖u‖pp. | (1.3) |
In fact, by Pohozaev identity, u satisfies (1.3) as long as u is a critical point of Ep. Now, we can define a manifold
Pa,p:={u∈Sa:Pp(u)=0}, |
where
Pp(u):=‖∇u‖22−μγq‖u‖qq−γp‖u‖pp. |
It is clear that all critical points of Ep|Sa belong to Pa,p and s⋆u∈Pa,p if and only if (Ψpu(s))′=0. We divide Pa,p into three parts.
P+a,p={u∈Pa,p:(Ψpu)″(0)>0}={u∈Pa,p:2‖∇u‖22>μqγ2q‖u‖qq+pγ2p‖u‖pp}, |
P0a,p={u∈Pa,p:(Ψpu)″(0)=0}={u∈Pa,p:2‖∇u‖22=μqγ2q‖u‖qq+pγ2p‖u‖pp}, |
and
P−a,p={u∈Pa,p:(Ψpu)″(0)<0}={u∈Pa,p:2‖∇u‖22<μqγ2q‖u‖qq+pγ2p‖u‖pp}. |
Define
m(a,p):=infu∈Pa,pEp(u)andm±(a,p):=infu∈P±a,pEp(u). |
For 2<q<2+4N<p⩽2∗, since qγq<2 and pγp>2, the function Ψpu may have two critical points on R, one is local minimum point and the other is global maximum point. Moreover, if we assume su is the local minimum and tu is the global maximum. Then, it is not difficulty to check that su⋆u∈P+a,p and tu⋆u∈P−a,p (see [9, Lemma 5.3] and [10, Lemma 4.2] for more details). Therefore, it is natural to speculate that Ep has two critical points on Sa under appropriate assumptions, one is a local minimizer on Sa and is also a minimizer on P+a,p, the other is a mountain-pass type critical point and is also a minimizer on P−a,p.
In fact, the local minimizer and mountain-pass type solution of Ep|Sa for 2<q<2+4N<p<2∗ have been found by Soave, see [9, Theorem 1.3]. For 2<q<2+4N<p=2∗, Soave obtained the local minimum, but due to H1rad(RN)↪L2∗(RN) is not compact, there are some difficulties to obtain the mountain-pass type solution (see Theorem 1.1 and Remark 1.1 in [10]). Therefore, it is natural to ask the following question:
(Q) Does E2∗|Sa has a second critical point of mountain pass type when 2<q<2+4N? In [6], Jeanjean and Le proved E2∗|Sa has a mountain-pass type solution and the solution is also a minimizer on P−a,2∗ when N⩾4. They constructed a minimax structure and proved a strict inequality m−(a,2∗)<m+(a,2∗)+1NSN2 to obtain the compactness of a Palais-smale(PS) sequence. The proof of [6] is complicated especially the proof of the strict inequality, see Propositions 1.10, 1.11 and 1.12 for more details. After that, Wei and Wu [11] gave a simpler proof of m−(a,2∗)<m+(a,2∗)+1NSN2 and proved that the answer is also positive for (Q) when N=3. Different from [6], We and Wu didn't construct the minimax structure, but directly proved the convergence of the minimizing sequence for m−(a,2∗), see Lemma 3.1 and Proposition 3.1 of [11] for more details.
Our main goal is giving a new proof of (Q) and the method we call the Sobolev subcritical approximation method. The idea of the Sobolev subcritical approximation method is: by [9, Theorem1.3 (ii)], we know Ep|Sa has a mountain-pass type solution up when 2+4N<p<2∗. Let p→2∗, it is not difficult to prove that up⇀u in H1(RN). Then, we prove that u is the solution of (1.2), up→u in H1(RN), u is a critical point of E2∗|Sa and is the minimum of E2∗ on P−a,2∗. Proving strong convergence is a crucial step in our proof, we also need use the strict inequality m−(a,2∗)<m+(a,2∗)+1NSN2.
Let
C′=(2∗S2∗2(2−γqq)2(2∗−γqq))2−γqq2∗−2q(2∗−2)2CqN,q(2∗−γqq) | (1.4) |
and
C″=22∗NγqCqN,q(2∗−γqq)(γqqSN22−γqq)2−γqq2. |
Define α(N,q):=min{C′,C″}. Our main result can be stated as follows.
Theorem 1.1. Let N⩾3, 2<q<2+4N, p=2∗ and a,μ>0. Moreover, let us suppose that μaq(1−γq)<α(N,q). Then E2∗|Sa has a critical point of mountain-pass type which is positive, radially symmetric and solves (1.2) for some λ<0.
Remark 1.1. The definition of α(N,q) comes from [10, (1.6)] to ensure that Ψpu has two critical points.
Remark 1.2. The Sobolev subcritical approximation method has been used by [20, Remark 1.3] and [7]. In [7], Li considered the normalized solutions of (1.2) with 2+4N<q<p=2∗ and proved (1.2) has a normalized ground state for every μ>0, see [7, Theorem 1.4]. Li solve an open problem
(Q') Does E2∗|Sa have a ground state if μ>0 and μa(1−γq)q large? which is raised by Soave [10, Page 7]. For 2<q<2+4N<p=2∗, if we follow the step of Li, the last inequality is invalid since qγq<2 (see [7, Page 13]) and we can not prove u∈Sa. In fact, we refer some ideas of [10,11] to obtain strong convergence in H1(RN).
In this section, we collect some results which will be used in the rest of the paper. First, let us recall the Sobolev inequality.
Lemma 2.1. For every N⩾3, there is an optimal constant S>0 depending only on N such that
S‖u‖22∗⩽‖∇u‖22∀u∈D1,2(RN), |
where D1,2(RN) denotes the completion of C∞c(RN) with respect to the norm ‖u‖D1,2:=‖∇u‖2.
It is well known [21] that S is achieved by
Uε,y(x)=[N(N−2)]N−24(εε2+|x−y|2)N−22for ∀ε>0 and y∈RN, |
and Uε,y satisfies the equation
−Δu=u2∗−1,u>0in RN. |
Moreover,
‖∇Uε,y‖22=‖Uε,y‖2∗2∗=SN2. |
Let CN,p be the optimal constant of Gagliardo-Nirenberg inequality. Then, we have
Lemma 2.2. Let 2<p<2∗, then limp→2∗CN,p=S−12.
Proof. Denoting by uε:=φUε,0∈H1(RN), where φ∈C∞c(RN) be a radial cut-off function with
0⩽φ⩽1,φ=1 in B1andφ=0 in Bc2. |
By the classical results[20], we have
‖∇uε‖22=‖uε‖2∗2∗=SN2+oε(1). |
Since
|uε(x)|p⩽|uε(x)|2+|uε(x)|2∗∀x∈RN, |
the Lebesgue dominated convergence theorem implies limp→2∗‖uε‖pp=‖uε‖2∗2∗. Using the Gagliardo-Nirenberg inequality, we have
‖uε‖p⩽CN,p‖∇uε‖γp2‖uε‖1−γp2. |
Taking p→2∗, we obtain
‖uε‖2∗⩽lim infp→2∗CN,p‖∇uε‖2, |
which implies S−12⩽lim infp→2∗CN,p.
For every u∈H1(RN)∖{0}, using the Hölder inequality and the Sobolev inequality, we have
‖u‖p⩽‖u‖γp2∗‖u‖1−γp2⩽S−γp2‖∇u‖γp2‖u‖1−γp2 |
By the definition of CN,p, we obtain S−γp2⩾CN,p. Therefore, S−12⩾lim supp→2∗CN,p.
For every 0<μ<aq(γq−1)α(N,q). In order to use the existence result of Sobolev subcritical case[9, Theorem 1.3], μ should satisfy
0<μ<aq(γq−1)+(1−γp)p(2−γqq)γpp−2(p(2−γqq)2CpN,p(γpp−γqq))2−γqqγpp−2q(γpp−2)2CqN,q(γpp−γqq):=μp. | (3.1) |
By Lemma 2.2, is it not difficult to prove that
μp→aq(γq−1)C′⩾aq(γq−1)α(N,q) |
as p→2∗, where C′ is defined by (1.4). Therefore, μ satisfies (3.1) as long as p is close enough to 2∗.
Lemma 3.1. We have
lim supp→2∗m−(a,p)⩽m−(a,2∗). |
Proof. For every u∈Sa, by [9, Lemma 5.3], there exists a unique tp,u∈R such that tp,u⋆u∈P−a,p, that is
e2tp,u‖∇u‖22=μγqeqγqtp,u‖u‖qq+γpepγptp,u‖u‖pp, | (3.2) |
and
2e2tp,u‖∇u‖22<μqγ2qeqγqtp,u‖u‖qq+pγ2pepγptp,u‖u‖pp. | (3.3) |
Since qγq<2 and pγp>2, by (3.2), we have
(μγq‖u‖qq‖∇u‖22)12−qγq<etp,u<(‖∇u‖22γp‖u‖pp)1pγp−2. |
We know
|u(x)|p⩽|u(x)|2+|u(x)|2∗∀x∈RN, |
the Lebesgue dominated convergence theorem implies limp→2∗‖u‖pp=‖u‖2∗2∗. Therefore, there exists two constants t2>t1 independent of p such that tp,u∈[t1,t2] when p close enough to 2∗. Up to a subsequence, we assume that tp,u→tu as p→2∗.
Let p→2∗, by (3.2) and (3.3), we obtain
e2tu‖∇u‖22=μγqeqγqtu‖u‖qq+e2∗tu‖u‖2∗2∗, |
and
2e2tu‖∇u‖22⩽μqγ2qeqγqtu‖u‖qq+2∗e2∗tu‖u‖2∗2∗, |
which implies tu⋆u∈P−a,2∗∪P0a,2∗. From [10, Page 20], we know P0a,2∗=∅ and hence tu⋆u∈P−a,2∗.
By the definition of m−(a,p), we have
m−(a,p)⩽Ep(tp,u⋆u)=12e2tp,u‖∇u‖22−μqeqγqtp,u‖u‖qq−1pepγptp,u‖u‖pp, |
which implies
lim supp→2∗m−(a,p)⩽lim supp→2∗Ep(tp,u⋆u)=E2∗(tu⋆u). |
By the definition of m−(a,2∗) and the arbitrary of u, we know the conclusion holds.
The proof of the following two lemmas can be found in [11, Lemmas 3.1, 3.2].
Lemma 3.2. 0<m−(a,2∗)<m+(a,2∗)+1NSN2.
Lemma 3.3. m±(a,2∗) is non-increasing for 0<a<(μ−1α(N,q))1q(1−γq).
Let 2+4N<pn<2∗ and pn→2∗ as n→∞. By [9, Theorem 1.3 (ii)], there exists mountain-pass type solutions {un}∈P−a,pn for Epn|Sa which are positive, radially symmetric such that Epn(un)=m−(a,pn).
Lemma 3.4. {un} is bounded in H1(RN).
Proof. By Lemma 3.1, we have
m−(a,2∗)+1⩾Epn(un)=(12−1pnγpn)‖∇un‖22−μγq(1qγq−1pnγpn)‖un‖qq⩾(12−1pnγpn)‖∇un‖22−μγq(1qγq−1pnγpn)CqN,qaq(1−γq)‖∇un‖qγq2 |
for n sufficiently large. Since qγq<2, we know {un} is bounded in H1(RN).
Up to a subsequence, there exists u∈H1(RN) such that un⇀u in H1(RN), un→u in Lr(RN) with r∈(2,2∗) and un→u a.e. in RN. Our main goal is to prove that u is the mountain-pass type solution of E2∗|Sa. Next, we prove u satisfies (1.2).
Lemma 3.5. There exists λ⩽0 such that
−Δu=λu+μuq−1+u2∗−1, | (3.4) |
and λ=0 if and only if u≡0.
Proof. By [9, Theorem 1.3], there exists λn<0 such that
−Δun=λnun+μuq−1n+upn−1n, | (3.5) |
which together with un∈P−a,pn, implies
λna2=μ(γq−1)‖un‖qq+(γpn−1)‖un‖pnpn. | (3.6) |
Let n→∞, by (3.6), we have that there exists a λ⩽0 such that λn→λ and
λa2=μ(γq−1)‖u‖qq. |
Therefore, λ=0 if and only if u≡0.
For every ψ∈H1(RN), since {u2∗−1n} is bounded in L2∗2∗−1(RN) and {uq−1n} is bounded in Lqq−1(RN), by weak convergence, we have
∫RNu2∗−1nψdx→∫RNu2∗−1ψdxand∫RNuq−1nψdx→∫RNuq−1ψdx |
as n→∞. We know that
|un(x)|pn−1|ψ(x)|⩽|un(x)|q−1|ψ(x)|+|un(x)|2∗−1|ψ(x)|∀x∈RN. |
Therefore, the Lebesgue dominated convergence theorem implies
∫RNupn−1nψdx→∫RNu2∗−1ψdxas n→∞. |
By (3.5), we have
0=∫RN(∇un⋅∇ψ−λnunψ−μuq−1nψ−upn−1nψ)dx→∫RN(∇u⋅∇ψ−λuψ−μuq−1ψ−u2∗−1ψ)dx, |
as n→∞, which implies u satisfies (3.4).
Set ‖u‖2=c⩽a. By Pohozaev identity, we know u∈Pc,2∗. Thus, by [10, (4.2)],
E2∗(u)⩾m(c,2∗)=m+(c,2∗) |
Lemma 3.6. We have un→u in D1,2(RN) as n→∞.
Proof. Let vn=un−u⇀0 in H1(RN) as n→∞. The Brézis-Lieb Lemma[22] implies
‖∇un‖22=‖∇u‖22+‖∇vn‖22+on(1),‖un‖2∗2∗=‖u‖2∗2∗+‖vn‖2∗2∗+on(1), |
and
‖un‖qq=‖u‖qq+‖vn‖qq+on(1)=‖u‖qq+on(1). |
Since un∈P−a,pn, by the Young inequality, we know
‖∇un‖22=μγq‖un‖qq+γpn‖un‖pnpn⩽μγq‖un‖qq+γpn(2∗−pn2∗−q‖un‖qq+pn−q2∗−q‖un‖2∗2∗)=μγq‖un‖qq+‖un‖2∗2∗+on(1). |
Therefore,
‖∇vn‖22⩽‖vn‖2∗2∗+o(1)⩽S−2∗2‖∇vn‖2∗2+on(1). | (3.7) |
We assume that ‖∇vn‖22→l as n→∞. By (3.7), we know l=0 or l⩾SN2. If l⩾SN2, by Lemmas 3.1 and 3.3, we have
m−(a,2∗)⩾lim supn→∞m−(a,pn)=lim supn→∞Epn(un)=lim supn→∞[(12−1pnγpn)‖∇un‖22−μγq(1qγq−1pnγpn)‖un‖qq]=lim supn→∞[(12−12∗)‖∇un‖22−μγq(1qγq−12∗)‖un‖qq]=lim supn→∞(12−12∗)‖∇vn‖22+[(12−12∗)‖∇u‖22−μγq(1qγq−12∗)‖u‖qq]=lim supn→∞(12−12∗)‖∇vn‖22+E2∗(u)⩾lim supn→∞(12−12∗)‖∇vn‖22+m+(c,2∗)⩾1NSN2+m+(a,2∗), |
which contradicts with Lemma 3.2. Thus, we obtain l=0 which implies un→u in D1,2(RN).
Lemma 3.7. We have u≢.
Proof. Since , we have
(3.8) |
and
(3.9) |
Combining (3.8) and (3.9), there is
That is
Let , by Lemma 2.2, we obtain
which implies .
Remark 3.1. By Lemma 3.5, we have . $
Lemma 3.8. in as and hence .
Proof. The idea of this proof comes from the proof of [10, Proposition 3.1]. Multiplying on both sides of (3.4) and (3.5), integrating and then subtract, we obtain
(3.10) |
By Lemma 3.6, since in , the first, third and fourth integrals of (3.10) tend to as . Therefore,
which implies in .
Remark 3.2 From Lemma 8, we get that in as .
Proof of Theorem 1.1. By Lemma 3.5 and Remark 3.2, we just need to prove that and . Since in , by the Sobolev inequality, in . Therefore, combining Lemma 3.1, we have
(3.11) |
which implies . Let , by (3.8) and (3.9), we know that . Since (see [10, Page 20]), there is .
Remark 3.3. From (3.11), we can get that .
The second author was supported by Postgraduate Research an Innovation Project of Chongqing (No. CYS23184).
The authors declare they have not used Artificial Intelligence (AI) tools in the creation of this article.
The authors declare there is no conflict of interest.
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