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Existence of normalized solutions for the Schrödinger equation

  • In this paper, we devote to studying the existence of normalized solutions for the following Schrödinger equation with Sobolev critical nonlinearities.

    {Δu=λu+μ|u|q2u+|u|p2uin RN,RN|u|2dx=a2,

    where N3, 2<q<2+4N, p=2=2NN2, a,μ>0 and λR is a Lagrange multiplier. Since the existence result for 2+4N<p<2 has been proved, using an approximation method, that is let p2, we obtain that there exists a mountain-pass type solution for p=2.

    Citation: Shengbing Deng, Qiaoran Wu. Existence of normalized solutions for the Schrödinger equation[J]. Communications in Analysis and Mechanics, 2023, 15(3): 575-585. doi: 10.3934/cam.2023028

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  • In this paper, we devote to studying the existence of normalized solutions for the following Schrödinger equation with Sobolev critical nonlinearities.

    {Δu=λu+μ|u|q2u+|u|p2uin RN,RN|u|2dx=a2,

    where N3, 2<q<2+4N, p=2=2NN2, a,μ>0 and λR is a Lagrange multiplier. Since the existence result for 2+4N<p<2 has been proved, using an approximation method, that is let p2, we obtain that there exists a mountain-pass type solution for p=2.



    In this paper, we consider the existence of solutions for the following Schrödinger equation.

    iψt+Δψ+μ|ψ|q2ψ+|ψ|p2ψ=0in R+×RN, (1.1)

    where N3, 2<q<2+4N and p=2=2NN2. The Schrödinger equation is a famous equation in Physics and there are numerous papers to study it, we refer the readers to [1,2,3,4] and references therein.

    For (1.1), we are particularly interested in the stationary waves of the form ψ(x,t)=eiλtu(x), where λR and u:RNR. Then u satisfies the equation

    Δu=λu+μ|u|q2u+|u|p2uin RN. (1.2)

    If we fix the L2-norm of u, that is, let

    uSa:={vH1(RN):v22=a2},

    where a>0 is a constant. Then the corresponding functional of (1.2) is

    Ep(u)=12u22μquqq1pupp,

    and λ appears as a Lagrange multiplier. Solutions of (1.2) with prescribed mass are always called normalized solutions. It seems that there is profound physical significance to study normalized solutions. In fact, for the Schrödinger equation, |ψ(x,t)|2 represents the probability density of a single particle appearing in space x at time t. Naturally, there is

    RN|ψ(x,t)|2dx=1.

    Of course, in mathematics, we often consider

    RN|ψ(x,t)|2dx=a2.

    There are a lot of papers to study the normalized solutions of Schrödinger equations and it is impossible for us to provide complete references. We refer the readers to [5,6,7,8,9,10,11] and references therein. Moreover, we refer the readers to [12,13,14] for the normalized solutions of fractional Schrödinger equations and to [15,16,17] for the normalized solutions of Schrödinger systems.

    When we study the normalized solutions, there will be a L2-critical exponent 2+4N, which comes from the Gagliardo-Nirenberg inequality[18]: for every 2<p<2, there exists an optimal constant CN,p depending on N and p such that

    upCN,puγp2u1γp2uH1(RN),

    where

    γp:=N(p2)2p.

    By the Gagliardo-Nirenberg inequality, it is not difficult to prove that if the nonlinearities of equation are L2-subcritical, then the corresponding functional is bounded from below on Sa. For example,

    J(u)=12u221pupp

    is bounded from below on Sa for 2<p<2+4N and global minimizers of J|Sa can be found, see [8,19]. However, if the nonlinearities are L2-supercritical, the functional is unbounded from below on Sa and it seems impossible to search for a global minimizer. The first paper to deal with L2-supercritical is [5]. In [5], Jeanjean found the normalized solutions of mountain-pass type.

    Compared with pure L2-subcritical or L2-supercritical case, the mixed case is more complicated. In [9], Soave studied (1.2) for 2<q<2+4N<p<2 under L2 constraint. Since q is L2-subcritical exponent and p is L2-supercritical exponent, we call μ|u|q2+|u|p2u mixed nonlinearities. The first existence result of normalized solutions in Sobolev critical case was also obtained by Soave[10].

    Since the L2 constraint, there are some difficulties to observe the structure of Ep|Sa. A possible method is to consider the function

    Ψpu(s):=Ep(su)=12e2su22μqeqγqsuqq1pepγpsupp,

    where

    su:=eNs2u(es).

    It is not difficult to prove that suSa for all sR if uSa and hence we can study the structure of Ψpu to speculate the structure of Ep|Sa.

    If u is a critical point of Ep|Sa, then 0 may be a critical point of Ψpu. If 0 is a critical point of Ψpu, then (Ψpu)(0)=0, that is

    u22=μγquqq+γpupp. (1.3)

    In fact, by Pohozaev identity, u satisfies (1.3) as long as u is a critical point of Ep. Now, we can define a manifold

    Pa,p:={uSa:Pp(u)=0},

    where

    Pp(u):=u22μγquqqγpupp.

    It is clear that all critical points of Ep|Sa belong to Pa,p and suPa,p if and only if (Ψpu(s))=0. We divide Pa,p into three parts.

    P+a,p={uPa,p:(Ψpu)(0)>0}={uPa,p:2u22>μqγ2quqq+pγ2pupp},
    P0a,p={uPa,p:(Ψpu)(0)=0}={uPa,p:2u22=μqγ2quqq+pγ2pupp},

    and

    Pa,p={uPa,p:(Ψpu)(0)<0}={uPa,p:2u22<μqγ2quqq+pγ2pupp}.

    Define

    m(a,p):=infuPa,pEp(u)andm±(a,p):=infuP±a,pEp(u).

    For 2<q<2+4N<p2, since qγq<2 and pγp>2, the function Ψpu may have two critical points on R, one is local minimum point and the other is global maximum point. Moreover, if we assume su is the local minimum and tu is the global maximum. Then, it is not difficulty to check that suuP+a,p and tuuPa,p (see [9, Lemma 5.3] and [10, Lemma 4.2] for more details). Therefore, it is natural to speculate that Ep has two critical points on Sa under appropriate assumptions, one is a local minimizer on Sa and is also a minimizer on P+a,p, the other is a mountain-pass type critical point and is also a minimizer on Pa,p.

    In fact, the local minimizer and mountain-pass type solution of Ep|Sa for 2<q<2+4N<p<2 have been found by Soave, see [9, Theorem 1.3]. For 2<q<2+4N<p=2, Soave obtained the local minimum, but due to H1rad(RN)L2(RN) is not compact, there are some difficulties to obtain the mountain-pass type solution (see Theorem 1.1 and Remark 1.1 in [10]). Therefore, it is natural to ask the following question:

    (Q) Does E2|Sa has a second critical point of mountain pass type when 2<q<2+4N? In [6], Jeanjean and Le proved E2|Sa has a mountain-pass type solution and the solution is also a minimizer on Pa,2 when N4. They constructed a minimax structure and proved a strict inequality m(a,2)<m+(a,2)+1NSN2 to obtain the compactness of a Palais-smale(PS) sequence. The proof of [6] is complicated especially the proof of the strict inequality, see Propositions 1.10, 1.11 and 1.12 for more details. After that, Wei and Wu [11] gave a simpler proof of m(a,2)<m+(a,2)+1NSN2 and proved that the answer is also positive for (Q) when N=3. Different from [6], We and Wu didn't construct the minimax structure, but directly proved the convergence of the minimizing sequence for m(a,2), see Lemma 3.1 and Proposition 3.1 of [11] for more details.

    Our main goal is giving a new proof of (Q) and the method we call the Sobolev subcritical approximation method. The idea of the Sobolev subcritical approximation method is: by [9, Theorem1.3 (ii)], we know Ep|Sa has a mountain-pass type solution up when 2+4N<p<2. Let p2, it is not difficult to prove that upu in H1(RN). Then, we prove that u is the solution of (1.2), upu in H1(RN), u is a critical point of E2|Sa and is the minimum of E2 on Pa,2. Proving strong convergence is a crucial step in our proof, we also need use the strict inequality m(a,2)<m+(a,2)+1NSN2.

    Let

    C=(2S22(2γqq)2(2γqq))2γqq22q(22)2CqN,q(2γqq) (1.4)

    and

    C=22NγqCqN,q(2γqq)(γqqSN22γqq)2γqq2.

    Define α(N,q):=min{C,C}. Our main result can be stated as follows.

    Theorem 1.1. Let N3, 2<q<2+4N, p=2 and a,μ>0. Moreover, let us suppose that μaq(1γq)<α(N,q). Then E2|Sa has a critical point of mountain-pass type which is positive, radially symmetric and solves (1.2) for some λ<0.

    Remark 1.1. The definition of α(N,q) comes from [10, (1.6)] to ensure that Ψpu has two critical points.

    Remark 1.2. The Sobolev subcritical approximation method has been used by [20, Remark 1.3] and [7]. In [7], Li considered the normalized solutions of (1.2) with 2+4N<q<p=2 and proved (1.2) has a normalized ground state for every μ>0, see [7, Theorem 1.4]. Li solve an open problem

    (Q') Does E2|Sa have a ground state if μ>0 and μa(1γq)q large? which is raised by Soave [10, Page 7]. For 2<q<2+4N<p=2, if we follow the step of Li, the last inequality is invalid since qγq<2 (see [7, Page 13]) and we can not prove uSa. In fact, we refer some ideas of [10,11] to obtain strong convergence in H1(RN).

    In this section, we collect some results which will be used in the rest of the paper. First, let us recall the Sobolev inequality.

    Lemma 2.1. For every N3, there is an optimal constant S>0 depending only on N such that

    Su22u22uD1,2(RN),

    where D1,2(RN) denotes the completion of Cc(RN) with respect to the norm uD1,2:=u2.

    It is well known [21] that S is achieved by

    Uε,y(x)=[N(N2)]N24(εε2+|xy|2)N22for ε>0 and yRN,

    and Uε,y satisfies the equation

    Δu=u21,u>0in RN.

    Moreover,

    Uε,y22=Uε,y22=SN2.

    Let CN,p be the optimal constant of Gagliardo-Nirenberg inequality. Then, we have

    Lemma 2.2. Let 2<p<2, then limp2CN,p=S12.

    Proof. Denoting by uε:=φUε,0H1(RN), where φCc(RN) be a radial cut-off function with

    0φ1,φ=1 in B1andφ=0 in Bc2.

    By the classical results[20], we have

    uε22=uε22=SN2+oε(1).

    Since

    |uε(x)|p|uε(x)|2+|uε(x)|2xRN,

    the Lebesgue dominated convergence theorem implies limp2uεpp=uε22. Using the Gagliardo-Nirenberg inequality, we have

    uεpCN,puεγp2uε1γp2.

    Taking p2, we obtain

    uε2lim infp2CN,puε2,

    which implies S12lim infp2CN,p.

    For every uH1(RN){0}, using the Hölder inequality and the Sobolev inequality, we have

    upuγp2u1γp2Sγp2uγp2u1γp2

    By the definition of CN,p, we obtain Sγp2CN,p. Therefore, S12lim supp2CN,p.

    For every 0<μ<aq(γq1)α(N,q). In order to use the existence result of Sobolev subcritical case[9, Theorem 1.3], μ should satisfy

    0<μ<aq(γq1)+(1γp)p(2γqq)γpp2(p(2γqq)2CpN,p(γppγqq))2γqqγpp2q(γpp2)2CqN,q(γppγqq):=μp. (3.1)

    By Lemma 2.2, is it not difficult to prove that

    μpaq(γq1)Caq(γq1)α(N,q)

    as p2, where C is defined by (1.4). Therefore, μ satisfies (3.1) as long as p is close enough to 2.

    Lemma 3.1. We have

    lim supp2m(a,p)m(a,2).

    Proof. For every uSa, by [9, Lemma 5.3], there exists a unique tp,uR such that tp,uuPa,p, that is

    e2tp,uu22=μγqeqγqtp,uuqq+γpepγptp,uupp, (3.2)

    and

    2e2tp,uu22<μqγ2qeqγqtp,uuqq+pγ2pepγptp,uupp. (3.3)

    Since qγq<2 and pγp>2, by (3.2), we have

    (μγquqqu22)12qγq<etp,u<(u22γpupp)1pγp2.

    We know

    |u(x)|p|u(x)|2+|u(x)|2xRN,

    the Lebesgue dominated convergence theorem implies limp2upp=u22. Therefore, there exists two constants t2>t1 independent of p such that tp,u[t1,t2] when p close enough to 2. Up to a subsequence, we assume that tp,utu as p2.

    Let p2, by (3.2) and (3.3), we obtain

    e2tuu22=μγqeqγqtuuqq+e2tuu22,

    and

    2e2tuu22μqγ2qeqγqtuuqq+2e2tuu22,

    which implies tuuPa,2P0a,2. From [10, Page 20], we know P0a,2= and hence tuuPa,2.

    By the definition of m(a,p), we have

    m(a,p)Ep(tp,uu)=12e2tp,uu22μqeqγqtp,uuqq1pepγptp,uupp,

    which implies

    lim supp2m(a,p)lim supp2Ep(tp,uu)=E2(tuu).

    By the definition of m(a,2) and the arbitrary of u, we know the conclusion holds.

    The proof of the following two lemmas can be found in [11, Lemmas 3.1, 3.2].

    Lemma 3.2. 0<m(a,2)<m+(a,2)+1NSN2.

    Lemma 3.3. m±(a,2) is non-increasing for 0<a<(μ1α(N,q))1q(1γq).

    Let 2+4N<pn<2 and pn2 as n. By [9, Theorem 1.3 (ii)], there exists mountain-pass type solutions {un}Pa,pn for Epn|Sa which are positive, radially symmetric such that Epn(un)=m(a,pn).

    Lemma 3.4. {un} is bounded in H1(RN).

    Proof. By Lemma 3.1, we have

    m(a,2)+1Epn(un)=(121pnγpn)un22μγq(1qγq1pnγpn)unqq(121pnγpn)un22μγq(1qγq1pnγpn)CqN,qaq(1γq)unqγq2

    for n sufficiently large. Since qγq<2, we know {un} is bounded in H1(RN).

    Up to a subsequence, there exists uH1(RN) such that unu in H1(RN), unu in Lr(RN) with r(2,2) and unu a.e. in RN. Our main goal is to prove that u is the mountain-pass type solution of E2|Sa. Next, we prove u satisfies (1.2).

    Lemma 3.5. There exists λ0 such that

    Δu=λu+μuq1+u21, (3.4)

    and λ=0 if and only if u0.

    Proof. By [9, Theorem 1.3], there exists λn<0 such that

    Δun=λnun+μuq1n+upn1n, (3.5)

    which together with unPa,pn, implies

    λna2=μ(γq1)unqq+(γpn1)unpnpn. (3.6)

    Let n, by (3.6), we have that there exists a λ0 such that λnλ and

    λa2=μ(γq1)uqq.

    Therefore, λ=0 if and only if u0.

    For every ψH1(RN), since {u21n} is bounded in L221(RN) and {uq1n} is bounded in Lqq1(RN), by weak convergence, we have

    RNu21nψdxRNu21ψdxandRNuq1nψdxRNuq1ψdx

    as n. We know that

    |un(x)|pn1|ψ(x)||un(x)|q1|ψ(x)|+|un(x)|21|ψ(x)|xRN.

    Therefore, the Lebesgue dominated convergence theorem implies

    RNupn1nψdxRNu21ψdxas n.

    By (3.5), we have

    0=RN(unψλnunψμuq1nψupn1nψ)dxRN(uψλuψμuq1ψu21ψ)dx,

    as n, which implies u satisfies (3.4).

    Set u2=ca. By Pohozaev identity, we know uPc,2. Thus, by [10, (4.2)],

    E2(u)m(c,2)=m+(c,2)

    Lemma 3.6. We have unu in D1,2(RN) as n.

    Proof. Let vn=unu0 in H1(RN) as n. The Brézis-Lieb Lemma[22] implies

    un22=u22+vn22+on(1),un22=u22+vn22+on(1),

    and

    unqq=uqq+vnqq+on(1)=uqq+on(1).

    Since unPa,pn, by the Young inequality, we know

    un22=μγqunqq+γpnunpnpnμγqunqq+γpn(2pn2qunqq+pnq2qun22)=μγqunqq+un22+on(1).

    Therefore,

    vn22vn22+o(1)S22vn22+on(1). (3.7)

    We assume that vn22l as n. By (3.7), we know l=0 or lSN2. If lSN2, by Lemmas 3.1 and 3.3, we have

    m(a,2)lim supnm(a,pn)=lim supnEpn(un)=lim supn[(121pnγpn)un22μγq(1qγq1pnγpn)unqq]=lim supn[(1212)un22μγq(1qγq12)unqq]=lim supn(1212)vn22+[(1212)u22μγq(1qγq12)uqq]=lim supn(1212)vn22+E2(u)lim supn(1212)vn22+m+(c,2)1NSN2+m+(a,2),

    which contradicts with Lemma 3.2. Thus, we obtain l=0 which implies unu in D1,2(RN).

    Lemma 3.7. We have u.

    Proof. Since , we have

    (3.8)

    and

    (3.9)

    Combining (3.8) and (3.9), there is

    That is

    Let , by Lemma 2.2, we obtain

    which implies .

    Remark 3.1. By Lemma 3.5, we have . $

    Lemma 3.8. in as and hence .

    Proof. The idea of this proof comes from the proof of [10, Proposition 3.1]. Multiplying on both sides of (3.4) and (3.5), integrating and then subtract, we obtain

    (3.10)

    By Lemma 3.6, since in , the first, third and fourth integrals of (3.10) tend to as . Therefore,

    which implies in .

    Remark 3.2 From Lemma 8, we get that in as .

    Proof of Theorem 1.1. By Lemma 3.5 and Remark 3.2, we just need to prove that and . Since in , by the Sobolev inequality, in . Therefore, combining Lemma 3.1, we have

    (3.11)

    which implies . Let , by (3.8) and (3.9), we know that . Since (see [10, Page 20]), there is .

    Remark 3.3. From (3.11), we can get that .

    The second author was supported by Postgraduate Research an Innovation Project of Chongqing (No. CYS23184).

    The authors declare they have not used Artificial Intelligence (AI) tools in the creation of this article.

    The authors declare there is no conflict of interest.



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