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Research article

Normalized solutions for Kirchhoff equations with Choquard nonlinearity: mass Super-Critical Case

  • In the present paper, we investigated the existence of normalized solutions for the following Kirchhoff equation with Choquard nonlinearity

    (a+bR3|u|2dx)Δuλu=μ|u|q2u+(Iα|u|p)|u|p2u,xR3

    with prescribed mass R3|u|2dx=c2, where a,b,c>0, μR, α(0,3), 103q<6, 3+α3p<3+α and λR is a Lagrange multiplier. We first considered the case of μ>0 and obtained mountain pass type solutions. For the defocusing situation μ<0, we proved the existence result by constructing a minimax characterization for the energy functional. Finally, we discussed the asymptotic behavior of normalized solutions obtained above as b0+ when μ>0.

    Citation: Zhi-Jie Wang, Hong-Rui Sun. Normalized solutions for Kirchhoff equations with Choquard nonlinearity: mass Super-Critical Case[J]. Communications in Analysis and Mechanics, 2025, 17(2): 317-340. doi: 10.3934/cam.2025013

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  • In the present paper, we investigated the existence of normalized solutions for the following Kirchhoff equation with Choquard nonlinearity

    (a+bR3|u|2dx)Δuλu=μ|u|q2u+(Iα|u|p)|u|p2u,xR3

    with prescribed mass R3|u|2dx=c2, where a,b,c>0, μR, α(0,3), 103q<6, 3+α3p<3+α and λR is a Lagrange multiplier. We first considered the case of μ>0 and obtained mountain pass type solutions. For the defocusing situation μ<0, we proved the existence result by constructing a minimax characterization for the energy functional. Finally, we discussed the asymptotic behavior of normalized solutions obtained above as b0+ when μ>0.



    In this paper we are interested in the following Kirchhoff equation with Choquard nonlinearity:

    (a+bR3|u|2dx)Δuλu=μ|u|q2u+(Iα|u|p)|u|p2u,xR3 (1.1)

    under the constraint

    R3|u|2dx=c2, (1.2)

    where a,b,c>0, μR, λR, α(0,3), 103q<6, 3+α3p<3+α. Iα:RN{0}R is the Riesz potential defined by

    Iα(x):=Aα|x|NαwithAα=Γ(Nα2)2απN2Γ(α2).

    The problem (1.1) is closely related to the equation

    (a+bR3|u|2dx)Δu=f(x,u), (1.3)

    which is the stationary analog of the equation

    utt(a+bR3|u|2dx)Δu=f(x,u), (1.4)

    where f(x,u) is a general nonlinearity. The problem (1.4) was proposed by Kirchhoff [1] as an extension of the classical D'Alembert's wave equations for free vibration of elastic strings. In problem (1.4), u denotes the displacement, the nonlinear term f is the external force, and a is the initial tension while b is related to the intrinsic properties of the string. Mathematically, the problem (1.4) is often referred to be nonlocal as the appearance of the term (R3|u|2dx)Δu, which depends not only on the pointwise value of Δu, but also on the integral of |u|2 over the whole space. This phenomenon causes some mathematical difficulties, which make the study of Kirchhoff type equations particularly interesting.

    After the pioneering work of Lions [2], (1.3) began to receive much attention and many researchers studied its steady-state model, see [3,4,5,6] for more important research progress. Some scholars have also considered generalizations of fixed-frequency solutions for Kirchhoff equations. Gao et al. [7] studied the nonlinear coupled Kirchhoff system with purely Sobolev critical exponent

    {(a1+b1RN|u|2dx)Δu=μ1|u|22u+αγ2|u|α2u|v|βxRN,(a2+b2RN|v|2dx)Δv=μ2|v|22v+βγ2|u|α|v|β2vxRN, (1.5)

    where N3, ai,bi0, i=1,2, μ1,μ2,γ>0, and α+β=2. They gave a complete classification of positive ground states for (1.5) in any dimension 3 or 4. Sun et al. [8] extended the results to the p-sub-Laplacians and obtained the multiple solutions. As to the case of bounded domains in RN, Cabanillas [9] studied the global existence theorem and its exponential decay. In addition, Yang and Tang [10] dealt with the nonlinear Kirchhoff problem with a sign potential

    (a+bR3|u|2dx)Δu+V(x)u=f(u),xR3, (1.6)

    where b>0 and the nonlinearity fC(R,R) exhibits subcritical growth. By using a more general global compactness lemma and a sign-changing Nehari manifold, they showed the existence of a least energy sign-changing solution for b>0 that is sufficiently small and established the asymptotic behavior when b0+.

    Now there are two substantially different viewpoints in terms of the frequency λ in (1.1). One is to regard the frequency λ as a given constant. In this situation, solutions of (1.1) are critical points of the following functional

    Iμ(u):=a2R3|u|2dx+b4(R3|u|2dx)2λ2R3|u|2dxμqR3|u|qdx12pR3(Iα|u|p)|u|pdx.

    Although this is not the concern of our present article, we still refer the readers to [11,12,13,14]. Naturally, the other one is to regard λ as an unknown parameter, which is exactly what our article is concerned. For this case, standing wave solutions are required to possess a priori prescribed L2-norm, which also have attracted widespread attention during recent years. These solutions are commonly called as normalized solutions, which provide valuable insights into dynamical properties of stationary solutions, such as the stability or instability of orbits. In addition, it is natural to prescribe the value of the mass so that λ can be interpreted as a Lagrange multiplier. For example, from a physical point of view, the normalized condition may represent the number of particles of each component in Bose-Einstein condensates or the power supply in the nonlinear optics framework. To obtain the solutions of (1.1)-(1.2), it suffices to consider critical points of the functional

    Eμ(u):=a2R3|u|2dx+b4(R3|u|2dx)2μqR3|u|qdx12pR3(Iα|u|p)|u|pdx (1.7)

    on

    Sc:={uH1(R3):R3|u|2dx=c2}

    with the parameter λR appearing as a Lagrange multiplier.

    In order to narrate the relevant results and state our motivation conveniently, we consider the following Kirchhoff-type equations with convolutional terms:

    {(a+bRN|u|2dx)Δu=λu+μ|u|q2u+γ(Iα|u|p)|u|p2u,xRN,RN|u|2dx=c2, (1.8)

    where a>0,b0,c>0, N3, μ,γR, 2<q<2NN2, and N+αN<p<N+αN2.

    Taking a=1 and b=0, (1.8) reduces to the nonlinear Choquard equation with combined nonlinearities. The endpoints of N+αN and N+αN2 established in [15] are called lower- and upper-critical exponent. The upper-critical exponent plays a similar role as the Sobolev critical exponent in the local semilinear equations, for instance, Li [16] proved the existence and orbital stability of ground states of (1.8) when p=N+αN2, γ=1. As to the lower critical exponent, it seems to be a new feature for the Choquard equation, which is related to a new phenomenon of bubbling at infinity, see [17,18].

    If b>0, N=3, then (1.8) is a nonlinear Kirchhoff equation. Zeng and Zhang [19] proved the existence and uniqueness of solutions to (1.8) with q(2,6), γ=0, and μ=1 by using some simple energy estimates rather than the concentration-compactness principles. In addition, Ye [20] considered the existence and mass concentration of solutions of (1.8) under the case of L2-critical exponent, namely, q=143. If γ0, then (1.8) can be viewed as a Kirchhoff-Choquard type equation. Liu [21] considered the case of γ=1, μ=0, and N+αN<p<N+αN2, and he provided threshold values c and c related to c separating the existence and nonexistence of normalized solutions of it when p belongs to different ranges. In addition, he also deduced that (1.8) has no nontrivial solutions in the cases of p=N+αN or p=N+αN2. For the cases of non-autonomous Kirchhoff equations, Qiu et al. [22] considered the following non-autonomous Kirchhoff equation with a perturbation:

    {(a+bRN|u|2dx)Δu+λu=h(x)|u|q2u+|u|p2u,xRN,RN|u|2dx=c2, (1.9)

    where 1N3, a,b,c>0, 1q<2, 2<p<2, h(x)R. They proved the existence of mountain pass solutions and bound-state solutions. Furthermore, Ni et al. [23] dealt with the following non-autonomous Kirchhoff equations with general nonlinearities:

    {(aε+bεR3|u|2dx)Δu+V(x)u=λu+f(u),xR3,R3|u|2dx=c2ε, (1.10)

    where a,b,c>0, V is a nonnegative continuous function, and f is a continuous function with L2-subcritical growth. When ε>0 is small enough, by using minimization techniques and the Lusternik-Schnirelmann theory, they pointed out that the number of normalized solutions was related to the topological richness of the set where the potential V attained its minimum value.

    Motivated by the above analysis, we consider (1.8) with γ=1, μ0, and N=3. Compared to the case of μ=0, at this time, (1.8) is regarded as a Kirchhoff type mixed equation with convolutional terms, which leads to a more complex geometric structure of the energy functional and makes the compactness analysis and energy estimates more difficult. In addition, we need to accurately determine the range of the parameter p to ensure that the convolution term (Iα|u|p)|u|p2u is the leading term.

    In the present paper, we study the existence and asymptotic behavior of solutions to (1.1)-(1.2). We say that u0 is a ground state to (1.1)-(1.2) if it is a solution to (1.1)-(1.2) having minimal energy among all the solutions belong to Sc

    dEμ|Sc(u0)=0andEμ(u0)=inf{Eμ(u):dEμ|Sc(u)=0,uSc}. (1.11)

    The following Gagliardo-Nirenberg inequality [24] is also crucial in our argument, that is, there exists a best constant Cq depending on q such that

    uqCquδq2u1δq2,q(2,6),uH1(R3), (1.12)

    where δq:=3(q2)2q.

    The following inequality introduced in [25] is called Gagliardo-Nirenberg inequality of Hartree type:

    R3(Iα|u|p)|u|pdxpQp2p22u2pγp2u3+αp2,uH1(R3), (1.13)

    where γp:=3p3α2p and equality holds for u=Qp, Qp is a nontrivial solution of

    3p3α2ΔQp+3+αp2Qp=(Iα|Qp|p)|Qp|p2Qp,xR3.

    Now, we state our main results:

    Theorem 1.1. Let a,b,c>0, 3+α3p<3+α, α(0,3), and μ>0.

    (1) If q=103 with μcq(1δq)<aq2Cqq or 143q<6, the problem (1.1)-(1.2) has a positive radial ground state solution of mountain pass type at a positive level m for some λ<0.

    (2) If 103<q<143, the problem (1.1)-(1.2) has a positive radial solution of mountain pass type at a positive level m for some λ<0.

    Theorem 1.2. Let a,b,c>0, 103q143p<3+α, and α(53,3). If the following inequality

    (11γp)(γpγpδq)cq(δq1)Cqq(a+b~C0)~C02qδq2<μ<0 (1.14)

    holds, where ~C0=(acp3αpγpQp2p22)22pγp2, then the problem (1.1)-(1.2) has a mountain pass type ground state ˜u, with the following properties: ˜u is a radial function, and solves (1.1)-(1.2) for some λ<0 and Eμ(˜u)>0.

    Theorem 1.3. Let ubSc,r be the solution of (1.1) obtained by Theorem 1.1. Then, up to a subsequence, we have ubu in H1r(R3) as b0+, where uSc,r is a solution of

    aΔu=λu+μ|u|q2u+(Iα|u|p)|u|p2u,inR3 (1.15)

    for some λ<0.

    Remark 1.4. Compared with b=0, the case of b>0 is more delicate because of the presence of the nonlocal term (R3|u|2dx)Δu, which causes that the weak limit u of a Palais-Smale sequence {un} may not solve (1.1)-(1.2) and makes compactness analysis more complex. In addition, dealing with the convergence of the convolutional term (Iα|u|p)|u|p2u is a challenge. Finally, motivated by the defocusing case of Schrödinger equations, which were studied by Soave [26] and Luo et al. [27], we discuss the existence of solutions to (1.1)-(1.2) under the case μ<0. Compared to [26] and [27], b>0 has a significant impact on the analysis of compactness in the defocusing case.

    Remark 1.5. When p=3+α, the term (Iα|u|p)|u|p2u can be seen a Sobolev critical term and the lack of compactness is a challenge. Soave [26] and Li et al. [28] both used the method introduced by Brezis and Nirenberg [29] in Sobolev critical case; this method ensured that energy level is less than a threshold, which is an essential ingredient in compactness argument. However, in our article, the existence of (R3|u|2dx)Δu and (Iα|u|p)|u|p2u makes it difficult for us to accurately estimate the energy level. So, the convergence of a Palais-Smale sequence is a very delicate problem, which at the moment we could not solve.

    In this section, we give some preliminary results that will be used throughout the rest of the paper. To start, we introduce the following notations:

    H1(R3) is the usual Sobolev space endowed with the norm u=(u22+u22)12.

    H1r(R3) denotes the subspace of functions in H1(R3) which are radially symmetric with respect to 0, Sc,r=H1r(R3)Sc.

    Lp(R3)(1p<), denotes the Lebesgue space with the norm up=(R3|u|pdx)1p.

    D1,2(R3)={uL2(R3):uL2(R3)}.

    on(1) denotes the vanishing quantities as n.

    Next, we give some lemmas that will be used throughout the rest of the paper.

    Lemma 2.1. If uH1(R3) is a weak solution of (1.1), then the Nehari-Pohozaev identity

    Pμ(u):=au22+bu42μδquqqγpR3(Iα|u|p)|u|pdx=0

    holds.

    Proof. If u is a weak solution of

    Δu+λu=μ|u|q2u+γ(Iα|u|p)|u|p2u,xR3,

    then we get

    12u22+32u22=μ3quqq+γ3+α2pR3(Iα|u|p)|u|pdx. (2.1)

    by [30, Corollary 2.5]. Furthermore, we can regard the term (a+bR3|u|2dx) in (1.1) as a constant coefficient motivated by [28, Lemma 2.3]. Therefore, combining (2.1) with the conclusion of Pohozaev identity of Schrödinger equation [31], we see immediately that

    a2u22+b2u42=32λu22+μ3quqq+3+α2pR3(Iα|u|p)|u|pdx. (2.2)

    In addition, since uH1(R3) is a weak solution of (1.1)-(1.2), we have

    au22+bu42=λu22+μuqq+R3(Iα|u|p)|u|pdx. (2.3)

    Combining (2.2) with (2.3), we infer that

    au22+bu42μδquqqγpR3(Iα|u|p)|u|pdx=0.

    When the energy functional Eμ is unbounded from below on Sc, we introduce the Pohozaev set:

    Pc,μ:={uSc:Pμ(u)=0}. (2.4)

    Lemma 2.1 implies that any critical point of Eμ|Sc is contained in Pc,μ. For tR and uSc, we define

    (tu)(x):=e3t2u(etx).

    Then, tuSc. The map

    (t,u)R×H1(R3)(tu)H1(R3)iscontinuous, (2.5)

    see [32, Lemma 3.5]. Similar to [33], we define the fiber map

    Ψuμ(t):=Eμ(tu)=a2e2tu22+b4e4tu42μqeqδqtuqq12pe2pγptR3(Iα|u|p)|u|pdx. (2.6)

    An easy computation shows that

    (Ψuμ)(t)=Pμ(tu). (2.7)

    So we see immediately that for uSc, t is a critical point of Ψuμ(t) if and only if tuPc,μ.

    We need to recall the Hardy-Littlewood-Sobolev inequality.

    Lemma 2.2. (Hardy-Littlewood-Sobolev inequality) [34] Let N1, p,r>1, and 0<α<N with 1p+NαN+1r=2, uLp(RN), vLr(RN). Then, there exists a sharp constant C(N,α,p) independent of u and v such that

    |RNRNu(x)v(y)|xy|Nαdxdy|C(N,α,p)upvr.

    Lemma 2.3. [35, Lemma 2.3] Let N3, α(0,N), and p[N+αN,N+αN2]. Assume that the sequence {un}H1(RN) satisfies unu in H1(RN) as n. Then,

    (Iα|un|p)|un|p2un(Iα|u|p)|u|p2uinH1(RN)asn.

    Lemma 2.4. [32, Lemma 3.6] For uSc and tR, the map φtφ from TuSc to TtuSc is a linear isomorphism with inverse ψ(t)ψ, where TuSc={φSc:R3uφ=0}.

    Lemma 2.5. Assume 3+α3p3+α. Then the energy functional ϕ is invariant under any orthogonal transformation in R3, where

    ϕ(u)=R3(Iα|u|p)|u|pdx,uH1(R3).

    Proof. We define the following group with orthogonal invariance:

    O(3):={AR3×3|ATA=I}

    and

    ˜x:=Ax,˜y:=Ay,uA(x):=u(˜x),uA(y):=u(˜y),

    with AO(3). We obtain

    ϕ(uA)=R3(Iα|uA|p)|uA|pdx=R3×R3|uA(x)|p|uA(y)|p|xy|3αdxdy=R3×R3|u(˜x)|p|u(˜y)|p|A1˜xA1˜y|3αd˜xd˜y=R3×R3|u(˜x)|p|u(˜y)|p|˜x˜y|3αd˜xd˜y=R3(Iα|u|p)|u|pdx=ϕ(u)

    by |det(˜xx)|=|det(˜yy)|=|det(A)|=1. Thus, ϕ is invariant under any orthogonal transformation in R3.

    In this section, we prove the existence of mountain pass type critical points for Eμ|Sc,r when μ>0 and we assume that 3+α3p<3+α.

    We first investigate the mountain pass geometry of Eμ on Sc,r.

    Lemma 3.1. Suppose that 103<q<6 or q=103 with μcq(1δq)<aq2Cqq.

    (i) There exist two positive numbers k1<k2 sufficiently small such that

    0<sup¯Ak1Eμ(u)<infAk2Eμ(u)andEμ(u)>0,Pμ(u)>0foruAk2,

    where

    Ak:={uSc,r:u2<k}. (3.1)

    (ii) There exists u0Sc,rAk2 such that Eμ(u0)<0.

    Proof. (i) In view of (1.12), (1.13) and 2qδq<2pγp, we obtain

    Eμ(u)=a2u22+b4u42μquqq12pR3(Iα|u|p)|u|pdxa2u22+b4u42μqCqqcq(1δq)uqδq2c3+αp2Qp2p22u2pγp2

    and

    Pμ(u)=au22+bu42μδquqqγpR3(Iα|u|p)|u|pdxau22+b4u42μδqCqqcq(1δq)uqδq2pγpc3+αpQp2p22u2pγp2.

    It is also clear that

    Eμ(u)a2u22+b4u42.

    Notice that 2qδq<6 and μcq(1δq)<aq2Cqq when qδq=2. Taking two small positive numbers k1<k2, we arrive at the desired result.

    (ii) For uSc,r, we have

    limt+(tu)2=+,limt+Eμ(tu)=.

    Choosing u0=tu with t>0 large enough, we deduce that u0Sc,rAk2 and Eμ(u0)<0.

    By Lemma 3.1, we define the mountain pass level of the functional Eμ on Sc,r by

    σ(c,μ):=infγΓmaxt[0,1]Eμ(γ(t)). (3.2)

    where

    Γ:={γC([0,1],Sc,r):γ(0)¯Ak1,Eμ(γ(1))0}. (3.3)

    Clearly, we have

    σ(c,μ)infAk2Eμ(u)>0. (3.4)

    Lemma 3.2. Suppose that 103<q<6 or q=103 with μcq(1δq)<aq2Cqq. Then, there exists a Palais-Smale sequence {un}Sc,r for Eμ|Sc,r at the level σ(c,μ) with Pμ(un)0 as n.

    Proof. Motivated by [33], we define the augmented functional ˜Eμ:R×H1(R3)R

    ˜Eμ(t,u):=Eμ(tu)=Ψuμ(t), (3.5)

    where Ψuμ(t) is defined in (2.6). Notice that ˜Eμ is of class C1. By Lemma 2.5, we know that ˜Eμ is invariant under rotations applied to u. Therefore, [31, Theorem 1.28] indicates that a critical point for ˜Eμ|R×Sc,r is a critical point for ˜Eμ|R×Sc.

    Now, we denote

    ˜Γ:={˜γC([0,1],R×Sc,r):˜γ(0){0}ׯAk1,˜γ(1){0}×E0μ},

    where E0μ:={uSc,r:Eμ(u)0}. We easily see that if γΓ, then ˜γ:=(0,γ)˜Γ and ˜Eμ(˜γ(t))=Eμ(γ(t)) for t[0,1]; while if ˜γ=(˜γ1,˜γ2)˜Γ, then γ():=˜γ1˜γ2Γ and ˜Eμ(˜γ(t))=Eμ(γ(t)) for t[0,1]. Therefore, we have

    σ(c,μ)=inf˜γ˜Γmaxt[0,1]˜Eμ(˜γ(t)).

    By the definition of σ(c,μ), for εn=1n2, there exists γnΓ such that

    maxt[0,1]Eμ(γ(t))σ(c,μ)+1n2,

    setting ˜γn=(0,γn), we obtain

    maxt[0,1]˜Eμ(˜γ(t))σ(c,μ)+1n2.

    According to Ekeland's variational principle [33, Lemma 2.3], there exists a sequence {(tn,vn)}R×Sc,r such that

    ˜Eμ(tn,vn)σ(c,μ)and(˜Eμ|R×Sc,r)(tn,vn)0asn, (3.6)

    with the additional property that

    |tn|+distH1(R3)(vn,βn([0,1]))0asn. (3.7)

    Note that ˜Eμ(tn,vn)=˜Eμ(0,tnvn) and

    (˜Eμ|R×Sc,r)(tn,vn),(t,ψ)=(˜Eμ|R×Sc,r)(0,tnvn),(t,tnψ) (3.8)

    for (t,ψ)R×H1r(R3) with R3vnψ=0. Setting un=tnvnSc,r, by (3.6), we obtain

    Eμ(un)=˜Eμ(0,tnvn)=˜Eμ(tn,vn)σ(c,μ),asn.

    We take (1,0) as a test function in (3.8), and it follows from (3.6) that

    Pμ(un)=t˜Eμ(0,un)0,asn.

    For wH1r(R3) with R3(tnvn)w=0, we take (0,(tn)w) as a test function in (3.8). In view of (3.6) and (3.7), we have that Eμ|Sc,r(un)0 as n.

    Lemma 3.3. If ri>0,i=1,2,3, then the function

    g(t)=r1e2t+r2e4tr3e2pγpt,tR

    has a unique critical point at which g achieves its maximum.

    Proof. By direct computation, we have

    g(t)=2r1e2t+4r2e4t2pγpr3e2pγpt=e4t(2r1e2t+4r22pγpr3e(2pγp4)t):=e4t˜g(t).

    Obviously, ˜g is decreasing, limt˜g(t)=+ and limt+˜g(t)=, so there exists a unique t0R such that ˜g(t0)=0, ˜g(t)<0 if t>t0, and ˜g(t)>0 if t<t0. Then, t0 is the unique critical point of the function g(t) and g(t0)=maxtRg(t)>0 since g()=0+ and g(+)=.

    Similar to Lemma 3.3, we have

    Lemma 3.4. If ri>0,i=1,2,3,4 and τ4, then the function

    g(t)=r1e2t+r2e4tr3eτtr4e2pγpt,tR

    has a unique critical point at which g achieves its maximum.

    Lemma 3.5. Suppose that 143q<6 or q=103 with μcq(1δq)<aq2Cqq. For any uSc, there exists a unique tuR such that tuuPc,μ, tu is the unique critical point of Ψuμ, and it is a strict maximum at a positive level. Moreover, Ψuμ is strictly decreasing on (tu,+) and tu<0 implies Pμ(u)<0. The map uSctuR is of class C1.

    Proof. If q=103, recalling qδq=2, letting uSc, by (2.6) and (2.7), we have

    Ψuμ(t)=(a2u22μquqq)e2t+b4e4tu4212pe2pγptR3(Iα|u|p)|u|pdx

    and (Ψuμ)(t)=0Pμ(tu)=0tuPc,μ. In view of (1.12), we obtain

    Ψuμ(t)(a2μqCqqcq(1δq))e2tu22+b4e4tu4212pe2pγptR3(Iα|u|p)|u|pdx. (3.9)

    Since μcq(1δq)<aq2Cqq and 2pγp>4, in view of Lemma 3.3 and (3.9), there exists a unique tuR such that (Ψuμ)(tu)=0 and Ψuμ(tu)=maxtRΨuμ(t)>0.

    Similarly, we deduce that 4qδq<2pγp when 143q<6, in view of Lemma 3.4 and (2.6), there exists a unique tuR such that (Ψuμ)(tu)=0 and Ψuμ(tu)=maxtRΨuμ(t)>0. Thus, we infer that

    Ψuμ()=0+,Ψuμ(+)=

    and Ψuμ is strictly decreasing on (tu,+). Since (Ψuμ)(t)<0 if and only if t>tu, we deduce that tu<0 implies Pμ(u)=(Ψuμ)(0)<0.

    Define Φ:R×H1r(R3)R by Φ(t,u)=(Ψuμ)(tu). It is clear that Φ is of class C1, Φ(tu,u)=0 and tΦ(tu,u)=(Ψuμ)(tu)<0. Applying the implicit function theorem, we see that the map uSctuR is of class C1.

    Lemma 3.6. Suppose that 143q<6 or q=103 with μcq(1δq)<aq2Cqq. We define

    m(c,μ):=infuPc,μEμ(u), (3.10)

    then m(c,μ)>0.

    Proof. If uPc,μ, combining Pμ(u)=0 with (1.12), (1.13), we obtain

    au22+bu42μδqCqqcq(1δq)uqδq2+pγpc3+αpQp2p22u2pγp2.

    So, in view of 4qδq<2pγp or qδq=2 when μcq(1δq)<aq2Cqq, there exists a positive constant C0 such that

    infuPc,μu2C0>0. (3.11)

    In addition, for uPc,μ, we have

    Eμ(u)=Eμ(u)14Pμ(u)=a4u22+μqδq44uqq+(γp412p)R3(Iα|u|p)|u|pdx{14(a2μqCqqcq(1δq))u22>0,q=103a4u22>0,143q<6. (3.12)

    Then, we get m(c,μ)>0.

    Lemma 3.7. Suppose that 143q<6 or q=103 with μcq(1δq)<aq2Cqq. Then, σ(c,μ)=m(c,μ), where σ(c,μ) is defined in (3.2).

    Proof. Denote

    mr(c,μ):=infuPc,μSc,rEμ(u). (3.13)

    For any uPc,μSc,r, recalling that

    limt(tu)2=0,limt+(tu)2=+,limt+Eμ(tu)=.

    Then, there exist t1<0 and t2>0 such that t1uAk1, t2uSc,rAk2 and Eμ(t2u)<0 by Lemma 3.1. Setting γ(t)=((1t)t1+tt2)u for t[0,1], we easily see that γΓ. In addition, by Lemma 3.5, we have maxt[0,1]Eμ(γ(t))=Eμ(u) if (1t)t1+tt2=0, from which it follows that mr(c,μ)σ(c,μ).

    On the other hand, we prove σ(c,μ)mr(c,μ), it suffices to verify that γ([0,1])Pc,μ for any γΓ. If uSc,r, by (3.12), we get

    Eμ(u)14Pμ(u)>0.

    So, we have Pμ(γ(1))<4Eμ(γ(1))0 for any γΓ. Note that Pμ(γ(0))>0. Let us consider the function

    Pγ:τ[0,1]Pμ(γ(τ)),foruSc,r.

    Obviously, Pγ is continuous by (2.5). Hence, we infer that there exists τγ(0,1) such that Pγ(τγ)=0, namely, γ(τγ)Pc,μ, which implies that γ(τγ)γ([0,1])Pc,μ, namely, γ([0,1])Pc,μ. Thus, we obtain

    mr(c,μ)=σ(c,μ). (3.14)

    Finally, we prove mr(c,μ)=m(c,μ). Since mr(c,μ)m(c,μ), we only prove m(c,μ)mr(c,μ). Suppose by contradiction that there exists ˉuPc,μSc,r such that

    Eμ(ˉu)<mr(c,μ). (3.15)

    Let ˉv=|ˉu| be the symmetric decreasing rearrangement of |ˉu|, then by the properties of symmetric decreasing rearrangement, we have

    ˉv2ˉu2,ˉvq=ˉuq,ˉv2=ˉu2,R3(Iα|ˉv|p)|ˉv|pdxR3(Iα|ˉu|p)|ˉu|pdx. (3.16)

    Since ˉvSc,r, by Lemma 3.5, there exists a unique tˉvR such that tˉvˉvPc,μ and

    Eμ(tˉvˉv)=maxtREμ(tˉv). (3.17)

    Hence, in view of (3.15)-(3.17), we have

    Eμ(ˉu)<mr(c,μ)Eμ(tˉvˉv)=a2e2tˉvˉv22+b4e4tˉvˉv42μqeqδqtˉvˉvqq12pe2pγptˉvR3(Iα|ˉv|p)|ˉv|pdxa2e2tˉvˉu22+b4e4tˉvˉu42μqeqδqtˉvˉuqq12pe2pγptˉvR3(Iα|ˉu|p)|ˉu|pdx=Eμ(tˉvˉu)Eμ(tˉuˉu)=Eμ(ˉu),

    which is impossible. Therefore, mr(c,μ)=m(c,μ). Combining with (3.14), we have

    σ(c,μ)=m(c,μ).

    In what follows, we will discuss the convergence of Palais-Smale sequences satisfying suitable additional conditions, following the ideas introduced by [28, Proposition 3.1].

    Proposition 3.8. Suppose that 103<q<6 or q=103 with μcq(1δq)<aq2Cqq, {un}Sc,r is a Palais-Smale sequence for Eμ|Sc,r at the positive level σ(c,μ) with Pμ(un)0 as n. Then, up to a subsequence, unu in H1r(R3), and uSc,r is a solution to (1.1) for some λ<0.

    Proof. Step 1. Boundedness of {un} in H1r(R3).

    If 103q<143, then 2qδq<4. Using (1.12) and Pμ(un)=on(1) yields

    σ(c,μ)+1Eμ(un)12pγpPμ(un)+on(1)=a(1212pγp)un22+b(1412pγp)un42μ(2pγpqδq2pqδq)unqq+on(1)b(1412pγp)un42μ(2pγpqδq2pqδq)Cqqcq(1δq)unqδq2+on(1),

    from which we see that {un} is bounded in H1r(R3).

    If 143q<6, then 4qδq<6. Using (1.12) and Pμ(un)=on(1) again, we obtain

    σ(c,μ)+1Eμ(un)14Pμ(un)+on(1)=a4un22+μ(qδq44q)unqq+pγp24pR3(Iα|un|p)|un|pdx+on(1)a4un22+on(1).

    Hence, {un} is bounded in H1r(R3).

    Step 2. We prove that there exist Lagrange multipliers λnλR.

    Since {un} is bounded in H1r(R3), by the compactness of H1r(R3)Lq(R3)(q(2,6)), up to a subsequence, there exists a function uH1r(R3), such that unu in H1r(R3), unu in Lq(R3) and unu a.e. on R3. Notice {un} is a bounded Palais-Smale sequence of Eμ|Sc,r, by the Lagrange multipliers rule, there exists {λn}R such that

    (a+bun22)R3unφdxμR3|un|q2unφdxR3(Iα|un|p)|un|p2unφdxλnR3unφdx=on(1)φ, (3.18)

    for every φH1(R3). Choosing φ=un, then

    λnc2=(a+bun22)un22μunqqR3(Iα|un|p)|un|pdx+on(1). (3.19)

    By (1.12) and (1.13), the boundedness of {un} implies that {unq} and {R3(Iα|un|p)|un|pdx} are bounded. Thus, {λn} is bounded as well, up to a subsequence, λnλR.

    Step 3. We show that λ<0 and u0.

    We first prove that

    limnR3(Iα|un|p)|un|pdx=R3(Iα|u|p)|u|pdx. (3.20)

    By Hardy-Littlewood-Sobolev inequality and Minkowski inequality, we obtain

    |R3(Iα|un|p)|un|pdxR3(Iα|u|p)|u|pdx|=|R3(Iα(|un|p+|u|p))(|un|p|u|p)dx|C1|un|p+|u|p63+α|un|p|u|p63+αC1(unp6p3+α+up6p3+α)|un|p|u|p63+α.

    By virtue of (1.12), 2<6p3+α<6, and the boundedness of {un} in H1r(R3), we deduce that {un6p3+α} is bounded. In addition, we have

    |un|p|u|p63+α0 (3.21)

    by unu6p3+α0. Thus, (3.20) is established. Combining (3.19) with Pμ(un)=on(1), we get

    λnc2=μ(δq1)unqq+p3α2pR3(Iα|un|p)|un|pdx+on(1).

    Then, we obtain

    λc2=μ(δq1)uqq+p3α2pR3(Iα|u|p)|u|pdx (3.22)

    by virtue of λnλ, unu in Lq(R3) and (3.20). Since μ>0, 0<δq<1 and p<3+α, we deduce that λ0, with λ=0 if and only if u0. If λn0, we have

    unq0,R3(Iα|un|p)|un|pdx0

    by the compactness of H1r(R3)Lq(R3) and (3.20). Using again Pμ(un)=on(1), we have Eμ(un)0, which is a contradiction with Eμ(un)m>0, and thus λnλ<0 and u0.

    Step 4. unu in H1r(R3).

    Since unu0 in H1r(R3) and H1r(R3)D1,2(R3), we get

    ˜B=limnun22u22>0. (3.23)

    Then, (3.18) and Lemma 2.3 imply that

    (a+b˜B)R3uφdxλR3uφdxμR3|u|q2uφdxR3(Iα|u|p)|u|p2uφdx=0,φH1(R3). (3.24)

    Test (3.18)-(3.24) with φ=unu, we obtain

    (a+˜Bb)(unu)22λunu22=μR3(|un|q2un|u|q2u)(unu)dx+R3[(Iα|un|p)|un|p2un(Iα|u|p)|u|p2u](unu)dx+on(1). (3.25)

    By using the Hölder inequality and the strong convergence of un to u in Lq(R3), we obtain

    |R3(|un|q2un|u|q2u)(unu)dx|0. (3.26)

    In addition, by the Hardy-Littlewood-Sobolev inequality and generalized Hölder inequality, we have

    |R3(Iα|un|p)|un|p2un(unu)dx|C|un|p63+α|un|p2un(unu)63+αCunp6p3+α|un|p2unpp163+αunu6p3+α=Cun2p16p3+αunu6p3+α.

    So, by the boundedness of {un6p3+α} and unu6p3+α0, we obtain

    |R3(Iα|un|p)|un|p2un(unu)dx|0. (3.27)

    Similarly, we get

    |R3(Iα|u|p)|u|p2u(unu)dx|0. (3.28)

    In view of (3.26), (3.27), (3.28), and (3.25), we have

    (a+˜Bb)(unu)22λunu220,

    which implies that unu in H1r(R3) by λ<0, and uSc,r solves (1.1) for some λ<0.

    According to Lemma 3.2, there exists a sequence {un}Sc,r with the following properties

    Eμ(un)σ(c,μ),Eμ|Sc,r(un)0,Pμ(un)0,asn.

    Then, by Propostion 3.8, unu in H1r(R3), uSc,r is a solution to (1.1) for some λ<0 with Eμ(u)=σ(c,μ). In addition, by Lemma 3.7, we get Eμ(u)=σ(c,μ)=m(c,μ), namely, u is a ground state solution under the cases of q=103 and 143q<6. Recalling that βn(τ)0 a.e. in R3 for every τ, (3.7) and the convergence imply that u is non-negative. The strong maximum principle implies that u>0.

    In this section, we prove the existence of a mountain pass type solution when μ<0.

    Lemma 4.1. Suppose that 103q143p<3+α, α(53,3) and μ<0. For any uSc, there exists a unique tuR such that tuuPc,μ, tu is the unique critical point of Ψuμ and it is a strict maximum at a positive level. Moreover, Ψuμ is strictly decreasing on (tu,+) and tu<0 implies Pμ(u)<0. The map uSctuR is of class C1.

    Proof. In view of μ<0, 2qδq4<2pγp and (2.6), we have

    Ψuμ()=0+andΨuμ(+)=. (4.1)

    Therefore, Ψuμ(t) has a global maximum point at positive level. The rest of the proof is similar to that of Lemma 3.5.

    Lemma 4.2. Suppose that 103q143p<3+α, α(53,3) and μ<0. Then, m(c,μ)>0, where m(c,μ) is defined in (3.10).

    Proof. Combining (1.13) with Pμ(u)=0, we obtain

    au22+bu42μδquqq=γpR3(Iα|u|p)|u|pdxpγpc3+αpQp2p22u2pγp2. (4.2)

    By virtue of μ<0 and (4.2), we have

    u22pγpc3+αpaQp2p22u2pγp2. (4.3)

    Thus,

    u22(acp3αpγpQp2p22)22pγp2=~C0>0. (4.4)

    For any uPc,μ, the energy functional can be seen

    Eμ(u)=a(1212pγp)u22+b(1412pγp)u42μ2pγp42pqγpuqq.

    In view of 2pγp>4, μ<0 and (4.4), we obtain

    Eμ(u)a(1212pγp)u22a(1212pγp)~C0,

    and the desired result follows from the inequality above.

    Lemma 4.3. Suppose that 103q143p<3+α, α(53,3) and μ<0. Then, there exists k>0 sufficiently small such that

    Eμ(u)>0,Pμ(u)>0foru¯Akandsup¯AkEμ(u)<m(c,μ),

    where ¯Ak:={uSc:u2k}.

    Proof. In view of (1.13), 2pγp>4, and μ<0, if u¯Ak with k small enough, then we obtain

    Eμ(u)=a2u22+b4u42μquqq12pR3(Iα|u|p)|u|pdxa2u22+b4u42c3+αp2Qp2p22u2pγp2>0

    and

    Pμ(u)=au22+bu42μδquqqγpR3(Iα|u|p)|u|pdxau22+b4u42pγpc3+αpQp2p22u2pγp2>0.

    If we could replace k with a smaller positive number, combining (1.12) with Lemma 4.2, then it is obvious that

    Eμ(u)a2u22+b4u42μqCqqcq(1δq)u22<m(c,μ).

    Proposition 4.4. Suppose that 103q143p<3+α, α(53,3), and μ<0. If {un}Sc,r is a Palais-Smale sequence for Eμ|Sc,r at non-zero level ˜c with Pμ(un)0 as n and (1.14) holds, then up to a subsequence, un˜u in H1r(R3), and ˜uSc,r is a solution to (1.1) for some λ<0.

    Proof. We divide the proof into four steps.

    Step 1. Boundedness of {un} in H1r(R3).

    Combining μ<0 with Pμ(un)=on(1), we obtain

    ˜c+1Eμ(un)a(1212pγp)un22+b(1412pγp)un42+on(1),

    then we deduce that {un2} is bounded by 2pγp>4. Thus, {un} is bounded in H1r(R3).

    Step 2. We prove that there exist Lagrange multipliers λnλ.

    By the compactness of H1r(R3)Lq(R3)(q(2,6)), up to a subsequence, there exists a function ˜uH1r(R3), such that un˜u in H1r(R3), un˜u in Lq(R3) and un˜u a.e. on R3. Notice {un} is a bounded Palais-Smale sequence of Eμ|Sc,r, by the Lagrange multipliers rule, there exists {λn}R such that

    (a+bun22)R3unφdxμR3|un|q2unφdxR3(Iα|un|p)|un|p2unφdxλnR3unφdx=on(1)φ,

    for every φH1r(R3). Choosing φ=un, then we obtain

    λn=1c2((a+bun22)un22μunqqR3(Iα|un|p)|un|pdx)+on(1). (4.5)

    By (1.12) and (1.13), the boundedness of {un} implies that {unq} and {R3(Iα|un|p)|un|pdx} are bounded. Thus, {λn} is bounded as well, up to a subsequence, λnλR.

    Step 3. λ<0.

    Combining μ<0 with Pμ(un)=on(1), we get

    aun22+bun42=μδqunqq+γpR3(Iα|un|p)|un|pdx+on(1)γpR3(Iα|un|p)|un|pdx+on(1),

    using (1.13) again, we have

    aun22γpR3(Iα|un|p)|un|pdx+on(1)pγpc3+αpQp2p22un2pγp2+on(1). (4.6)

    Now, we may assume that

    ˆB=limnun22˜u220, (4.7)

    by (4.6) and (4.7), we obtain

    ˆB(acp3αpγpQp2p22)22pγp2=~C0>0. (4.8)

    Combining (4.5) with Pμ(un)=on(1), we obtain

    λn=1c2[(11γp)(a+bun22)un22+μ(δqγp1)unqq]+on(1). (4.9)

    Since 103q143p<3+α, we get 11γp<0 and δqγp<1, in view of (4.7), (4.8), (4.9), and (1.12), we infer that

    λn1c2~C0qδq2[(11γp)(a+b~C0)~C02qδq2+μ(δqγp1)Cqqcq(1δq)]+on(1). (4.10)

    Thus, observing assumption (1.14), taking to the limit of (4.10) as n, we obtain

    λnλ<0.

    Step 4. We show that un˜u in H1(R3).

    Similar to (3.24)-(3.28), we easily obtain

    (a+ˆBb)(un˜u)22λun˜u220,asn,

    which, being λ<0, implies that un˜u in H1(R3).

    Denoting by Edμ the closed sublevel set {uSc,r:Eμ(u)d}, we introduce the minimax class

    Γ0:={γ=(α,β)C([0,1],R×Sc,r):γ(0)(0,¯Ak),γ(1)(0,E0μ)},

    with associated minimax level

    ˆσ(c,μ):=infγΓ0max(t,u)γ([0,1])˜Eμ(t,u),

    where Ak and ˜Eμ(t,u) are defined in (3.1) and (3.5), respectively.

    We split the proof into the following steps.

    Step 1. We show ˆσ(c,μ)=mr(c,μ), where mr(c,μ) is defined (3.13).

    Let uSc,r, by (4.1), there exist t01 and t11 such that

    γu:τ[0,1](0,((1τ)t0+τt1))uR×Sc,r (4.11)

    is a path in Γ0(the continuity from (2.5)), then ˆσ(c,μ) is a real number.

    We claim that for every γΓ0, there exists τγ(0,1) such that α(τγ)β(τγ)Pc,μ. Indeed, let us consider the function

    ˜Pγ:τ[0,1]Pμ(α(τ)β(τ))R.

    By Lemma 4.3, we get ˜Pγ(0)=Pμ(β(0))>0. On the other hand, by Lemma 4.1, since (Ψβ(1)μ)(t)>0 for every t(,tβ(1)] and Ψβ(1)μ(0)=Eμ(β(1))0, then tβ(1)<0. Again by Lemma 4.1, we can see that Pμ(β(1))<0. Therefore, by the continuity of ˜Pγ(see (2.5)), we can deduce that there exists τγ(0,1) such that ˜Pγ(τγ)=0, so α(τγ)β(τγ)Pc,μ. This implies that

    maxγ([0,1])˜Eμ˜Eμ(γ(τγ))=Eμ(α(τγ)β(τγ))infPc,μSc,rEμ.

    Thus,

    ˆσ(c,μ)infPc,μSc,rEμ. (4.12)

    On the other hand, γu is the corresponding path defined by (4.11), and if uPc,μSc,r, then by Lemma 4.1, we get

    Eμ(u)=˜Eμ(0,u)=maxγu([0,1])˜Eμˆσ(c,μ).

    So, we infer that

    infPc,μSc,rEˆσ(c,μ). (4.13)

    Combining (4.12) with (4.13), we have

    infPc,μSc,rE=ˆσ(c,μ).

    Then, we have

    mr(c,μ)=ˆσ(c,μ) (4.14)

    and ˆσ(c,μ)>0 by Lemma 4.2.

    Step 2. We prove the existence of a Palais-Smale sequence {un} of Eμ|Sc,r at the level ˆσ(c,μ).

    By Lemma 4.3, we infer that

    ˆσ(c,μ)=mr(c,μ)>sup¯AkE0μEμ=sup(0,¯Ak)(0,E0μ)˜E.

    Taking

    X=R×Sc,r,F={γ([0,1]):γΓ0},B=(0,¯Ak)(0,E0μ),
    F={(t,u)R×Sc,r|˜Eμ(t,u)ˆσ(c,μ)},A=γ([0,1]),An=γn([0,1]).

    Then, we consider that F={γ([0,1]):γΓ0} is a homotopy stable family of compact subsets of R×Sc,r with extended boundary B=(0,¯Ak)(0,E0μ) and the assumptions of [36, Theorem 5.2] hold with the superlevel {˜Eˆσ(c,μ)}. Thus, taking any minimizing sequence {γn=(αn,βn)}Γ0 for ˆσ(c,μ) with the property that αn0 and βn(τ)0 a.e. in R3 for every τ[0,1], there exists a Palais-Smale sequence {(tn,vn)}R×Sc,r for ˜Eμ|R×Sc,r at the level ˆσ(c,μ)>0 such that

    s˜Eμ(tn,vn)0andu˜Eμ(tn,vn)(TvnSc,r)0, (4.15)

    as n. Moreover,

    |tn|+distH1(R3)(vn,βn([0,1]))0,asn. (4.16)

    From (4.15), we have Pμ(tnvn)0 as n. In addition, we have

    ae2tnR3vnφ+be4tnvn22R3vnφμeqδqtnR3|vn|q2vnφe(3p3α)tnR3(Iα|vn|p)|vn|p2vnφ=on(1)φ, (4.17)

    for every φTvnSc,r. Thus, (4.17) leads to

    Eμ(tnvn),tnφ=on(1)φH1(R3)=on(1)tnφH1(R3), (4.18)

    for every φTvnSc,r, with on(1)0 as n, in the last equality, we used that {tn} is bounded, due to (4.16). From Lemma 2.4 and (4.18), we see that {un:=tnvn}Sc,r is a Pohozaev-Palais-Smale sequence for Eμ|Sc,r at the level mr(c,μ)=ˆσ(c,μ).

    Step 3. We notice that the assumptions of Proposition 4.4 are satisfied for the Palais-Smale sequence {un} obtained in the previous step. Then, up to a subsequence, we have un˜u strongly in H1r(R3) and ˜u is a radial normalized solution to (1.1)-(1.2) for some ˆλ<0. We complete the proof.

    In this section, we study the asymptotic behavior of normalized solutions obtained in Theorem 1.1 as b0+ and give the proof of Theorem 1.3.

    Let {ub:0<b<ˉb} be the solutions to (1.1)-(1.2) obtained by Theorem 1.1, where ˉb is small enough. We split the proof into three steps.

    Step 1. We show that the family of radial solutions {ub} is bounded in H1r(R3).

    Note that Pμ(ub)=0. If 103q<143, namely, 2qδq<4<2pγp, then we obtain

    σ(c,μ)+1Eμ(ub)=Eμ(ub)12pγpPμ(ub)=a(1212pγp)ub22+b(1412pγp)ub42μ(2pγpqδq2pqδq)ubqqb(1412pγp)ub42μ(2pγpqδq2pqδq)Cqqcq(1δq)ubqδq2.

    While if 143q<6, namely, 4qδq<2pγp, then

    σ(c,μ)+1Eμ(ub)=Eμ(ub)14Pμ(ub)=a4ub22+μ(qδq44q)ubqq+pγp24pR3(Iα|ub|p)|ub|pdxa4ub22.

    Hence, we deduce from the above two cases that {ub} is bounded in H1r(R3).

    Step 2. We prove that there exist Lagrange multipliers λnλR.

    Since {ub} is bounded in H1r(R3), there exists uH1r(R3) such that, up to a subsequence, ubu in H1r(R3), and ubu in Lq(R3), ubu a.e. on R3. We also know that

    (Eμ|Sc,r)(ub)0inH1(R3)Eμ(ubn)1c2Eμ(ub),ubub0inH1(R3).

    Thus, for every φH1r(R3), we have

    (a+bub22)R3ubφdxμR3|ub|q2ubφdxR3(Iα|ub|p)|ub|p2ubφdxλnR3ubφdx=on(1)φ. (5.1)

    Choosing φ=ub, then

    λnc2=aub22+bub42μubqqR3(Iα|ub|p)|ub|pdx+on(1)=μ(δq1)ubqq+p3α2pR3(Iα|ub|p)|ub|pdx+on(1). (5.2)

    By (1.12) and (1.13), the boundedness of {ub} implies that {ubq} and {R3(Iα|ub|p)|ub|pdx} are bounded. Thus, {λn} is bounded as well, up to a subsequence, λnλR.

    Step 3. We prove that u is a weak solution of (1.15) and ubuH1r(R3).

    By (3.20) and ubu in Lq(R3), we obtain

    λc2=μ(δq1)uqq+p3α2pR3(Iα|u|p)|u|pdx

    from (5.2). Obviously, we deduce that λ0, with "=" if and only if u0. Similar to Step 3 of the proof of Proposition 3.8, we get λ<0 and u0. In view of ubu0 in H1r(R3), H1r(R3)D1,2(R3), Lemma 2.3 and (5.1), we get

    aR3uφdxμR3|u|q2uφdxR3(Iα|u|p)|u|p2uφdxλR3uφdx=0 (5.3)

    for any φH1r(R3) as b0+. That is, u satisfies

    aΔu=λu+μ|u|q2u+(Iα|u|p)|u|p2uinR3,

    test (5.1)-(5.3) with φ=ubu, as b0+, we have

    a(ubu)22λubu220,

    which implies that ubu in H1r(R3) by λ<0, and uSc,r solves (1.1) for some λ<0.

    By (5.3) and H1r(R3)L2(R3), u is a weak solution of (1.15) and u2=c, namely, u is a normalized solution of (1.15).

    Zhi-Jie Wang: Writing-original draft, Writing-review and editing; Hong-Rui Sun: Supervision, Writing-review and editing, Methodology, Validation.

    The authors declare they have not used Artificial Intelligence (AI) tools in the creation of this article.

    Research of H.R. Sun was partially supported by the NSF of Gansu Province of China (24JRRA414, 21JR7RA535).

    The authors declare there is no conflict of interest.



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