Let λ1, λ2, λ3, and λ4 be non-zero real numbers, not all negative. Suppose that λ1/λ3is irrational and algebraic, δ>0, and the set V is a well-spaced sequence. In this paper, we prove that, for any ε>0, the number of v∈V with v≤X such that the inequality
|λ1p1+λ2p22+λ3p33+λ4p44−v|<v−δ
has no solution in primes p1, p2, p3, p4 that does not exceed O(X1−83144+2δ+2ε).
Citation: Xinyan Li, Wenxu Ge. A Diophantine approximation problem with unlike powers of primes[J]. AIMS Mathematics, 2025, 10(1): 736-753. doi: 10.3934/math.2025034
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Let λ1, λ2, λ3, and λ4 be non-zero real numbers, not all negative. Suppose that λ1/λ3is irrational and algebraic, δ>0, and the set V is a well-spaced sequence. In this paper, we prove that, for any ε>0, the number of v∈V with v≤X such that the inequality
|λ1p1+λ2p22+λ3p33+λ4p44−v|<v−δ
has no solution in primes p1, p2, p3, p4 that does not exceed O(X1−83144+2δ+2ε).
In 1953, Prachar [1] demonstrated that any sufficiently large odd integer N can be expressed as
N=p1+p22+p33+p44+p55, |
where p1, p2, p3, p4, and p5 are prime numbers. Subsequently, as a result of [2, Theorem 1], Ren and Tsang reached the same conclusion as Prachar. It is significant to explore the analogous formulation for Diophantine inequalities. In 1973, Vaughan [3] first proved that for any real η, there are infinitely many solutions in primes pj to the inequality
|λ1p1+λ2p2+λ3p3+η|<(maxpj)−ξ+ε | (1.1) |
with ξ=1/10. The exponent was subsequently improved several times, and the best result up to now is due to K. Matomäki [4] with ξ=2/9. Moreover, it is worth mentioning that Diophantine inequality (1.1) has also been resolved for special prime numbers. The solvability of (1.1) with primes p1, p2, and p3, where pi+2 are almost-primes, is discussed in [5]. Similarly, the cases where p3=x2+y2+1 or pi=[nc] (Piatetski-Shapiro primes) are addressed in [6,7], respectively.
Then for related results for Diophantine inequalities with unlike powers of primes, we consider the following examples. Let λ1, λ2, λ3, λ4, and λ5 be non-zero real numbers, not all negative, and suppose that λ1/λ2 is irrational. In 2016, Ge and Li [8] demonstrated that for any given real numbers η and σ with 0<σ<1720, there exist infinitely many solutions in prime numbers pj to the inequality
|λ1p1+λ2p22+λ3p33+λ4p44+λ5p55+η|<(max1≤j≤5pj)−σ. | (1.2) |
In 2017, Mu [9] made further improvements by extending the range of the exponent to σ≤1180 using the method outlined in Languasco and Zaccagnini [10]. Subsequently, Liu [11] optimized the result further, obtaining σ≤5288. Inspired by the work of Wang and Yao [12], Mu and Qu [13] combined the sieve methods from Harman [14] and Harman and Kumchev [15] to refine Liu's result and prove that (1.2) holds for σ≤5252. Very recently, this result was improved by Zhu [16], who obtained σ≤148. In 2022, Zhu [17] employed an innovative approach to estimate the correlation integral over the minor arcs, leading to a more robust estimation that σ≤19756.
Building upon the advancements made in the study of Diophantine inequalities, subsequent research has explored different variations and forms of these inequalities. For clarity in discussion, we first introduce the definition of a well-spaced sequence. A set of positive real numbers V is called a well-space sequence if there exists a constant c>0 such that
u,v∈V,u≠v⇒|u−v|>c. |
On this basis, in 2018, Ge and Zhao [18] dropped the linear prime variable in (1.2) and considered the exceptional set for the inequality
|λ2p22+λ3p33+λ4p44+λ5p55−v|<v−δ, | (1.3) |
where λ2, λ3, λ4, and λ5 are non-zero real numbers, not all negative. Let D be a well-spaced sequence, and suppose δ>0, and λ1/λ2 is algebraic and irrational. Denote by E(D,X,δ) the number of v∈D with v≤X such that the inequality (1.3) has no solution in primes p2, p3, p4, and p5. Recently, Ge and Zhao [18] demonstrated that
E(D,X,δ)≪X1−172+2δ+ε. |
Subsequently, Mu and Gao [19], as well as Liu and Liu [20], further improved upon the result of Ge and Zhao.
In this paper, we drop the final prime variable in (1.2) and examine the exceptional set for the inequality
|λ1p1+λ2p22+λ3p33+λ4p44−v|<v−δ. | (1.4) |
Drawing on techniques from [18,20], we establish the following results.
Theorem 1.1. Let λ1, λ2, λ3, and λ4 be non-zero real numbers, not all negative. Suppose that λ1/λ3is irrational and algebraic, δ>0, and the set V is a well-spaced sequence. Denote by E(V,X,δ) the number of v∈V with v≤X such that the inequality
|λ1p1+λ2p22+λ3p33+λ4p44−v|<v−δ |
has no solution in primes p1, p2, p3, p4. Then, for any ε>0, we have
E(V,X,δ)≪X1−83144+2δ+2ε. | (1.5) |
Theorem 1.2. Let λ1, λ2, λ3, and λ4 be non-zero real numbers, not all negative. Suppose that λ1/λ3is irrational and algebraic, δ>0, and the set V is a well-spaced sequence. Then there is a sequence Xj→∞ such that
E(V,Xj,δ)≪Xj1−83144+2δ+2ε | (1.6) |
for any ε>0. Moreover, if the convergent denominators qj for λ1/λ3satisfy q1−wj+1≪qj for w∈[0,1), then, for all X≥1 and any ε>0,
E(V,X,δ)≪X12−1112χ+2δ+2ε, | (1.7) |
with
χ=min(41−90ω492(1−ω),112). | (1.8) |
Remark. Theorem 1.1 follows directly from Theorem 1.2. Since λ1/λ3 is algebraic, we can set w=ε, and thus χ=112. Therefore, we focus on proving Theorem 1.2 in the following.
Notation. Throughout this paper, the letter p denotes a prime number, with or without subscripts. The non-zero real numbers λ1, λ2, λ3, λ4, and δ are given constants. Implicit constants in the O, ≪ and ≫ notations usually depend at most on λ1, λ2, λ3, and λ4. The letter ε represents an arbitrarily small positive constant, but not necessarily the same each time. We write e(x)=exp(2πix).
Let X be a sufficiently large positive number. Suppose that Ik=[(ηX)1/k,(X)1/k] for k=1,2,3,4 and 0<τ<1. Define
Kτ(α)={(sinπταπα)2α≠0; τ2α=0, | (2.1) |
and
Sk(α)=∑p∈Ik(logp)e(αpk),Uk(α)=∑n∈Ike(αnk), | (2.2) |
for k=1,2,3,4. Then, it is simple to obtain
Kτ(α)≪min(τ2,|α|−2),∫+∞−∞Kτ(α)e(αx)dα=max(0,τ−|x|). | (2.3) |
For convenience, Φ is defined as an arbitrary measurable subset of R, and then
I(v,X;Φ)=∫ΦS1(λ1α)S2(λ2α)S3(λ3α)S4(λ4α)Kτ(α)e(−vα)dα. |
By (2.3), we have
I(v,X;R)=∫+∞−∞S1(λ1α)S2(λ2α)S3(λ3α)S4(λ4α)Kτ(α)e(−vα)dα=∑pk∈Ik(logp1)⋅⋅⋅(logp4)∫+∞−∞e((λ1p1+λ2p22+λ3p33+λ4p44−v)α)Kτ(α)dα=∑pk∈Ik(logp1)⋅⋅⋅(logp4)max(0,τ−|λ1p1+λ2p22+λ3p33+λ4p44−v|)≪(logX)4∑pk∈Ikmax(0,τ−|λ1p1+λ2p22+λ3p33+λ4p44−v|). | (2.4) |
Thus
0≤I(v,X;R)≤τ(logX)4N(v,X), |
where N(v,X) counts the number of solutions to the inequality
|λ1p1+λ2p22+λ3p33+λ4p44−v|<τ,pk∈Ik(k=1,2,3,4). |
To estimate (2.4), we divide the region of integration into three parts: The major arc M, the minor arc m, and the trivial arc t, defined as
M={α:|α|≤ϕ}∪{α:ϕ<|α|≤ξ},m={α:ξ<|α|<γ},t={α:|α|≥γ}, |
and then we can write
I(v,X;R)=I(v,X;M)+I(v,X;m)+I(v,X;t), | (2.5) |
where ϕ=X524−1−ε,ξ=X−79−ε,γ=τ−2X712+2ε.
It is sufficient to establish a positive lower bound for I(v,X;R). We employ a standard dyadic argument, focusing on those values of v that satisfy 12X≤v≤X. We will estimate the three terms on the right-hand side of (2.5) in Sections 4–6. Additionally, Sections 3 and 6 will present preliminary lemmas and conclude the proof of Theorem 1.2.
Lemma 3.1. Suppose that X≥Z1≥X45+2ε and |S1(λ1α)|>Z1. Then, there exist two coprime integers a and q such that
1≤q≪(X1+εZ1)2,|qλ1α−a|≪(X1+εZ1)2X−1. |
Proof. This is extracted from [13, Lemma 4.1].
Lemma 3.2. Suppose that α is a real number, and there exist a∈Z and q∈N with
(q,a)=1,1≤q≤P32,|qα−a|<P−32. |
Then one has
∑P<p≤2P(logp)e(αp3)≪P1112+ε+P1+εq12(1+P3|α−aq|)12. |
Proof. See [18, Lemma 2.3].
Lemma 3.3. Let k≥1 be a real number. For any fixed real number A≥6, we have
∫|α|≤X−1+56k−ε|Sk(α)−Uk(α)|2dα≪X2k−1(logX)−A. |
Proof. This follows from [21, Corollary 2.3].
Lemma 3.4. Let k be a positive integer, we have
∫|α|≤X−1+23k−ε|Sk(λα)|2dα≪X2k−1. |
Proof. This lemma corresponds to [13, Lemma 3.3] or [19, Lemma 3.1].
Lemma 3.5. Suppose X18−1≤|α|≤X−18, we have
|S4(λ4α)|≪X14−1512+ε. |
Proof. This result is derived from [22, Theorem 1] by taking q=[|λ4α|−1] and a=1. It can also be found in [20].
Lemma 3.6. For k=1,2,3,4, and a positive integer m such that 1≤m≤k, we have
∫+∞−∞|Sk(α)|2mKτ(α)dα≪τX(2m−m)/k+ε,∫1−1|Sk(α)|2mdα≪X(2m−m)/k+ε. |
Proof. These results are derived from Hua's Lemma, with further details outlined in [3, Lemma 2.5].
Lemma 3.7. Suppose that α is a real number, and there exist a∈Z and q∈N with
(q,a)=1,1≤q≤P4721,|qα−a|≤P−4721. |
Then one has
∑p≤P(logp)e(αp4)≪P2324+ε+P1+εq12(1+P4|α−aq|)12. |
Proof. This result is derived from [23, Theorem 1] by taking k=4.
Lemma 3.8. Let m(3)=136, m(4)=196, λ and μ be nonzero constants. For i=3,4, suppose that X1i−m(i)+ε≤Zi≤X1i. We define
ρ(Zi)={α∈R:Zi≤|Si(λiα)|≤X1i}. |
i) For α∈ρ(Zi), there exist coprime integers ai, qi satisfying
1≤qi≪(X1i+εZi)2,|αqiλi−ai|≪(X1i+εZi)2X−1. |
ii) For l≥4, we have
∫ρ(Zi)|Si(λα)|2|Sl(μα)|2Kτ(α)dα≪τ(X2i+2l−1+ε+X4i+1l−1+εZi−2). |
Proof. For i=3, let P=X13, Q=P32. By Dirichlet's approximation theorem, there exist two coprime integers a3, q3 with 1≤q3≤Q and |αλ3q3−a3|≤Q−1. Then it follows from Lemma 3.2 and the hypothesis Z3≥X13−m(3)+ε, we have
X13−m(3)+ε≤Z3≤|S3(λ3α)|≤X13−m(3)+ε+X13+ε(q3+X|αλ3q3−a3|)12. | (3.1) |
Thus, we have
1≤q3≪(X13+εZ3)2,|αq3λ3−a3|≪(X13+εZ3)2X−1. |
For i=4, let P=X14, Q=P4721. By Dirichlet's approximation theorem, there exist two coprime integers a4, q4 with 1≤q4≤Q and |αλ4q4−a4|≤Q−1. Then it follows from Lemma 3.7 and the hypothesis Z4≥X14−m(4)+ε, we have
X14−m(4)+ε≤Z4≤|S4(λ4α)|≤X14−m(4)+ε+X14+ε(q4+X|αλ4q4−a4|)12. | (3.2) |
Thus, we have
1≤q4≪(X14+εZ4)2,|αq4λ4−a4|≪(X14+εZ4)2X−1, |
which completes the proof of Lemma 3.8 i).
Next, we give the proof of Lemma 3.8 ii). Using Brüdern's method from [24], the result can be established for the case when λ=1. To simplify the analysis, we assume that λ=1. Define Qi=X2i+εZ−2i and
ρi′(qi,ai)={α:|α−aiqi|≤QiqiX},i=3,4. |
Let Vi(α) be a function of period 1. Further, define the function Vi(α) for α∈(QiX−1,1+QiX−1] as
Vi(α)={(qi+X|αqi−ai|)−1,α∈ρi′;0,α∈(QiX−1,1+QiX−1]∖ρi′, |
where ρi′ is the union of all intervals ρi′(qi,ai) such that 1≤ai≤qi≤Qi and (ai,qi)=1. Let ρ∗i=ρi′+Z be the union of all such intervals, then
ρ(Zi)⊆ρ∗i. | (3.3) |
For α∈ρ(Zi), by combining (3.1)–(3.3), we obtain
|Si(λα)|≪X1i+εVi(α)12. |
Next, we express
|Sl(μα)|2=∑ve(αv)ψ(v), |
where l≥4,
ψ(v)=∑p3,p4∈Ilμ(pl3−pl4)=v.(logp3)(logp4), |
We can deduce from [24, Lemma3] that
∫ρ(Zi)|Si(λα)|2|Sl(μα)|2Kτ(α)dα≪X2i+ε∫ρ∗iVi(α)∑v(ψ(v)e(αv))Kτ(α)dα≪τX2i−1+ε(1+τ)1+ε(∑vψ(v)+Qi∑|v|≤τψ(v)). | (3.4) |
We easily derive
∑vψ(v)=|Sl(0)|2≪X2l. | (3.5) |
Since τ→0 as X→∞, by the Prime Number Theorem, we have
∑|v|≤τψ(v)=∑p∈Il(logp)2≪X1l+ε. | (3.6) |
Lemma 3.8 ii) can be readily proven by substituting (3.5) and (3.6) into (3.4).
In this section, we refine our analysis by dividing the major arc into two distinct regions, M1 and M2, which are defined as follows:
M1={α:|α|≤X524−1−ε},M2={α:X524−1−ε<|α|≤X−79−ε}. |
In this subsection, we establish a lower bound for the integral over the M1. For k = 1, 2, 3, 4, define
Fk(α)=∫Ike(αuk)du. |
Applying the first derivative estimate for trigonometric integrals (see [25, Lemma 4.2]), we derive the bound
Fk(α)≪X1k−1min(X,|α|−1). | (4.1) |
Lemma 4.1. We have
I(v,X;M1)≫τ2X1312. |
Proof. It can be easily demonstrated that
∫M1S1(λ1α)S2(λ2α)S3(λ3α)S4(λ4α)Kτ(α)e(−vα)dα=∫M1F1(λ1α)F2(λ2α)F3(λ3α)F4(λ4α)Kτ(α)e(−vα)dα+∫M1(S1(λ1α)−F1(λ1α))F2(λ2α)F3(λ3α)F4(λ4α)Kτ(α)e(−vα)dα+∫M1S1(λ1α)(S2(λ2α)−F2(λ2α))F3(λ3α)F4(λ4α)Kτ(α)e(−vα)dα+∫M1S1(λ1α)S2(λ2α)(S3(λ3α)−F3(λ3α))F4(λ4α)Kτ(α)e(−vα)dα+∫M1S1(λ1α)S2(λ2α)S3(λ3α)(S4(λ4α)−F4(λ4α))Kτ(α)e(−vα)dα=J0+J1+J2+J3+J4, |
where it is shown that J0≫τ2X1312 and Jk=o(τ2X1312) for k = 1, 2, 3, 4.
The analysis begins by establishing a lower bound for J0,
J0=∫RF1(λ1α)F2(λ2α)F3(λ3α)F4(λ4α)Kτ(α)e(−vα)dα+O(∫|α|>X524−1−ε|F1(λ1α)F2(λ2α)F3(λ3α)F4(λ4α)|Kτ(α)dα). | (4.2) |
Utilizing Eqs (2.3) and (4.1), we deduce that the error term in (4.2) satisfies
≪τ2X−2312∫|α|>X524−1−ε1|α|4dα≪τ2X−2312+198+3ε=o(τ2X1312). | (4.3) |
For brevity, let yj=λjxjj for j = 1, 2, 3, 4. By changing the order of integration and substituting variables, we note that the domains of integration for y1, y2, y3, and y4 are [λjηX,λjX]. Moreover, the integral satisfies |4∑j=1yj−v|<τ. Considering |4∑j=1yj−v|<τ2 and the bounds on y4, we derive the lower bound for the final integral. Therefore
∫RF1(λ1α)F2(λ2α)F3(λ3α)F4(λ4α)Kτ(α)e(−vα)dα=124λ1λ21/2λ31/3λ41/4∫∫∫∫y10y2−12y3−23y4−34∫Re((4∑j=1yj−v)α)Kτ(α)dαdy1dy2dy3dy4≫τX−34∫λ1Xλ1ηX∫λ2Xλ2ηX∫λ3Xλ3ηX∫−3∑j=1yj+v+τ2−3∑j=1yj+v−τ2y10y2−12y3−23dy1dy2dy3dy4≫τ2X1312, |
which means that
∫RF1(λ1α)F2(λ2α)F3(λ3α)F4(λ4α)Kτ(α)e(−vα)dα≫τ2X1312. | (4.4) |
Thus, combining (4.2)–(4.4), we have
J0≫τ2X1312. | (4.5) |
Then we turn to dealing with J1, J2, J3, and J4. According to Euler's summation formula, we have
|Uk(α)−Fk(α)|≪1+|α|X,k=1,2,3,4. | (4.6) |
Using (2.3), we estimate J1 as follows:
J1≪τ2∫M1|S1(λ1α)−F1(λ1α)||F2(λ2α)F3(λ3α)F4(λ4α)|dα≪τ2∫M1|S1(λ1α)−U1(λ1α)||F2(λ2α)F3(λ3α)F4(λ4α)|dα+τ2∫M1|U1(λ1α)−F1(λ1α)||F2(λ2α)F3(λ3α)F4(λ4α)|dα=:τ2(A1+B1). | (4.7) |
Utilizing Cauchy's inequality along with Lemma 3.3 and (4.1), we derive
A1≪X712(∫M1|S1(λ1α)−U1(λ1α)|2dα)12(∫M1|F2(λ2α)|2dα)12≪X1312(logX)−A2(∫1X0Xdα+∫X−1+524−ε1XX−1|α|−2dα)12≪X1312(logX)−A2. | (4.8) |
Similarly, from (4.1) and (4.6), we have
B1≪∫1X0|F2(λ2α)F3(λ3α)F4(λ4α)|dα+X∫X−1+524−ε1X|α||F2(λ2α)F3(λ3α)F4(λ4α)|dα≪X112+X∫X−1+524−ε1X|α|−2X−2312dα≪X112. | (4.9) |
Hence, by combining (4.7)–(4.9), it follows that
J1=o(τ2X1312). | (4.10) |
Following analogous reasoning for J2 by (2.3), we have
J2≪τ2∫M1|S1(λ1α)||S2(λ2α)−F2(λ2α)||F3(λ3α)F4(λ4α)|dα≪τ2∫M1|S1(λ1α)||S2(λ2α)−U2(λ2α)||F3(λ3α)F4(λ4α)|dα+τ2∫M1|S1(λ1α)||U2(λ2α)−F2(λ2α)||F3(λ3α)F4(λ4α)|dα=:τ2(A2+B2). | (4.11) |
Applying Cauchy's inequality along with Lemmas 3.3 and 3.4, it can be further derived that
A2≪X712(∫|α|≤X−1+23−ε|S1(λ1α)|2dα)12(∫M1|S2(λ2α)−U2(λ2α)|2dα)12≪X1312(logX)−A2. | (4.12) |
Similarly, using the estimates derived from (4.1) and (4.6), along with the results from Lemma 3.4, we have
B2≪∫1X0|S1(λ1α)F3(λ3α)F4(λ4α)|dα+X∫X−1+524−ε1X|α||S1(λ1α)F3(λ3α)F4(λ4α)|dα≪X712+X−512∫X−1+524−ε1X|α|−1|S1(λ1α)|dα≪X712+X−512(∫X−1+524−ε1X|α|−2dα)12(∫|α|≤X−1+23−ε|S1(λ1α)|2dα)12≪X712. | (4.13) |
Therefore, combining (4.11)–(4.13) results in the conclusion that
J2=o(τ2X1312). | (4.14) |
Similar arguments for J3 and J4, utilizing Lemmas 3.3 and 3.4, we obtain
Jj=o(τ2X1312),j=3,4. | (4.15) |
Hence, by combining (4.5), (4.10), (4.14), and (4.15), the proof of Lemma 4.1 is complete.
In this subsection, we derive an upper bound for the integral over the region M2 to quantify its contribution to the overall integral.
Lemma 4.2. We conclude that
I(v,X;M2)=o(τ2X1312). | (4.16) |
Proof. By applying Cauchy's inequality, along with the results from (2.3) and Lemmas 3.4 and 3.5, we derive the following:
I(v,X;M2)=∫M2S1(λ1α)S2(λ2α)S3(λ3α)S4(λ4α)Kτ(α)e(−vα)dα≪τ2Xmaxα∈M2|S4(λ4α)|(∫M2|S2(λ2α)|2dα)12(∫M2|S3(λ3α)|2dα)12≪τ2X54−1512+ε(∫M2|S2(λ2α)|2dα)12(∫M2|S3(λ3α)|2dα)12≪τ2X1312−1512+ε=o(τ2X1312). |
Subsequently, combining the results from Lemmas 4.1 and 4.2, we conclude the integral estimation over the major arc M, to obtain the following lemma.
Lemma 4.3. We have
I(v,X;M)≫τ2X1312. |
In this section, we demonstrate
I(v,X;t)=o(τ2X1312). | (5.1) |
Utilizing Cauchy's inequality and the trivial bounds of S1(λ1α), S4(λ4α), we obtain
I(v,X;t)=∫tS1(λ1α)S2(λ2α)S3(λ3α)S4(λ4α)Kτ(α)e(−vα)dα≪X1+14(∫t|S2(λ2α)|2Kτ(α)dα)12(∫t|S3(λ3α)|2Kτ(α)dα)12. | (5.2) |
By the periodicity of S2(λ2α), along with (2.3) and Lemma 3.6, we obtain
∫t|S2(λ2α)|2Kτ(α)dα≪∫∞γ|S2(λ2α)|21|α|2dα≪∫∞|λ2|γ|S2(α)|21|α|2dα≪∞∑m=[|λ2|γ]∫m+1m|S2(α)|21|α|2dα≪∞∑m=[|λ2|γ]∫m+1m|S2(α)|21m2dα≪∫10|S2(α)|2dα∞∑m=[|λ2|γ]1m2≪X12+εγ−1. | (5.3) |
Similarly, we can conclude that
∫t|S3(λ3α)|2Kτ(α)dα≪X13+εγ−1. | (5.4) |
By combining (5.2)–(5.4), we have
∫tS1(λ1α)S2(λ2α)S3(λ3α)S4(λ4α)Kτ(α)e(−vα)dα≪X2012+εγ−1≪X2012+ετ2X−712−2ε≪τ2X1312−ε. |
Thus, (5.1) follows directly.
This section provides a precise estimation of the integral over the minor arc and proves Theorem 1.2. We define m=∧m∪m∗, with ρ=112 and τ=X−δ.
Let E=E(V,X,δ) denote the set of elements v in V for which the inequality (1.4) has no solution in the prime variables pj for j=1,2,3,4. Thus, we have E(V,X,δ)=|E(V,X,δ)|. By selecting an appropriate complex number ϑv such that |ϑv|=1, we can reformulate the integral as follows:
E(V,X,δ)τ2X1312≪∑v∈E|∫mS1(λ1α)S2(λ2α)S3(λ3α)S4(λ4α)Kτ(α)e(−vα)dα|=∑v∈Eϑv∫mS1(λ1α)S2(λ2α)S3(λ3α)S4(λ4α)Kτ(α)e(−vα)dα=∫mS1(λ1α)S2(λ2α)S3(λ3α)S4(λ4α)T(α)Kτ(α)dα. | (6.1) |
In this case, we have
T(α)=∑v∈Eϑve(−vα). |
By applying Cauchy's inequality, we can bound the expression as follows:
E(V,X,δ)τ2X1312≪(∫m|S2(λ2α)T(α)|2Kτ(α)dα)12×(∫m|S1(λ1α)S3(λ3α)S4(λ4α)|2Kτ(α)dα)12. | (6.2) |
Next, we define ∧m=m1∪m2∪m3 and m∗=m∖∧m, with X=q9049, where
m1={α:|S3(λ3α)|<X13−13ρ+ε,|S4(λ4α)|<X14−18ρ+ε},m2={α:|S1(λ1α)|<X1−125ρ+ε,|S3(λ3α)|≥X13−13ρ+ε},m3={α:|S1(λ1α)|<X1−125ρ+ε,|S4(λ4α)|≥X14−18ρ+ε}. | (6.3) |
Lemma 6.1. We have
∫m|S2(λ2α)T(α)|2Kτ(α)dα≪τ(E(V,X,δ)X12+ε+(E(V,X,δ))2Xε). | (6.4) |
Proof. According to (2.3), we have
∫R|S2(λ2α)T(α)|2Kτ(α)dα=∑v1,v2∈Eϑv1ϑv2∑ηX≤p12,p22≤X(logp1)(logp2)∫Re[(λ2(p12−p22)−(v1−v2))α]Kτ(α)dα=∑v1,v2∈Eϑv1ϑv2∑ηX≤p12,p22≤X(logp1)(logp2)max(0,τ−|λ2(p12−p22)−(v1−v2)|)≪(logX)2L(X), |
where L(X) represents the number of solutions to the inequality
|λ2(p12−p22)−(v1−v2)|<τ |
with v1,v2∈E and ηX≤p12,p22≤X.
Since X is sufficiently large and τ=X−δ. When v1=v2, there must exist the case that p1=p2. Under this condition, we can deduce that
L(X)≪τE(V,X,δ)X12. |
When v1≠v2, there exists at most one integer n such that n≪X and the inequality |λ2n−(v1−v2)|<τ holds. For any integer n, the number of solutions to n=p12−p22 is bounded by Xε. Consequently, we obtain
L(X)≪τ(E(V,X,δ))2Xε. |
Combining both cases, we obtain
L(X)≪τ(E(V,X,δ)X12+(E(V,X,δ))2Xε). |
Thus, Lemma 6.1 is established.
Lemma 6.2. We have
∫∧m|S1(λ1α)S3(λ3α)S4(λ4α)|2Kτ(α)dα≪τX136−1112ρ+ε. | (6.5) |
Proof. Utilizing Lemmas 3.6 and 3.8 ii) along with the trivial bounds for S3(λ3α) and S4(λ4α), we analyze the integrals over m1, m2, and m3 separately.
For the integral over the interval m1, we obtain
∫m1|S1(λ1α)S3(λ3α)S4(λ4α)|2Kτ(α)dα≪(X13−136+ε)2(X14−196+ε)2(∫m1|S1(λ1α)|2Kτ(α)dα)≪τX136−1112ρ+ε. |
For the integral over the interval m2, we obtain
∫m2|S1(λ1α)S3(λ3α)S4(λ4α)|2Kτ(α)dα≪(X1−15+ε)2(∫m2|S3(λ3α)|2|S4(λ4α)|2Kτ(α)dα)≪τX136−245ρ+ε. |
For the integral over the interval m3, we obtain
∫m3|S1(λ1α)S3(λ3α)S4(λ4α)|2Kτ(α)dα≪(X1−15+ε)2(∫R|S3(λ3α)|4Kτ(α)dα)12(∫m3|S4(λ4α)|2|S4(λ4α)|2Kτ(α)dα)12≪τX136−145ρ+ε. |
By combining these estimates, Lemma 6.2 follows immediately.
Lemma 6.3. We have
∫m∗|S1(λ1α)S3(λ3α)S4(λ4α)|2Kτ(α)dα≪τX136−9815ρ+5ε. | (6.6) |
Proof. Employing Harman's method as outlined in [14], we partition the region m∗ into disjoint sets S(Z1,Z3,y) defined as
S(Z1,Z3,y)={α∈m∗:Z1≤|S1(λ1α)|<2Z1,Z3≤|S3(λ3α)|<2Z3,y≤|α|≤2y}, |
where Z1=X1−125ρ+2ε2t1, Z3=X13−13ρ+2ε2t2, y=ξ2t3 for some positive integers t1, t2, and t3.
By invoking Lemmas 3.1 and 3.8 i), we obtain integers a1, q1 and a3, q3 such that (a1,q1)=1 and (a3,q3)=1 satisfying
1≤q1≪(X1+εZ1)2,|q1λ1α−a1|≪X−1(X1+εZ1)2, | (6.7) |
1≤q3≪(X13+εZ3)2,|q3λ3α−a3|≪X−1(X13+εZ3)2. | (6.8) |
Note that a1a3≠0.
We further dissect S(Z1,Z3,y) into subsets S(Z1,Z3,y,Q1,Q3) with α satisfying |α|≥y=ξ2t3≥ξ=X−79−ε and |aiλiα|≪qi for i=1,3, where
Q1≤q1<2Q1,Q3≤q3<2Q3,Q1≪(X1+εZ1)2,Q3≪(X13+εZ3)2. |
Then, we have
|a3q1λ1λ3−a1q3|=|a1(a3−q3λ3α)+a3(q1λ1α−a1)λ3α|≪Q1X−1(X13+εZ3)2+Q3X−1(X1+εZ1)2≪X−1+8215ρ−4ε≪X−4990−4ε. | (6.9) |
Assuming that |a3q1| takes only R distinct values. By the pigeonhole principle, we have R≪yQ1Q3q. Due to bounds on the divisor function, each value of |a3q1| corresponds to significantly fewer than Xε pairs a3,q1. For fixed a3 and q1, the value of |a1q3| is the integral part of a3q1λ1λ3; thus there are significantly fewer than Xε pairs a1,q3. Consequently, by (6.7) and (6.8), the length of S(Z1,Z3,y,Q1,Q3) is
≪RXεmin(1Q1X(X1+εZ1)2,1Q3X(X13+εZ3)2)≪X101180+εyqZ1Z3. |
Evaluating the integral over S(Z1,Z3,y,Q1,Q3), we obtain
∫S(Z1,Z3,y,Q1,Q3)|S1(λ1α)S3(λ3α)S4(λ4α)|2Kτ(α)dα≪min(τ2,y−2)Z12Z23X24∫S(Z1,Z3,y,Q1,Q3)dα≪τy−1Z21Z23X12X101180+εyqZ1Z3≪τy−1Z1Z3X12X101180+εyq≪τX431180−4115ρ+5εq≪τX136+5εq≪τX7345+5ε. |
Finally, summing over all possible values of Z1,Z3,y,Q1,Q3, we have
∫m∗|S1(λ1α)S3(λ3α)S4(λ4α)|2Kτ(α)dα≪τX7345+6ε. |
Combining Lemmas 6.2 and 6.3, we arrive at Lemma 6.4.
Lemma 6.4. We have
∫m|S1(λ1α)S3(λ3α)S4(λ4α)|2Kτ(α)dα≪τX136−1112ρ+ε. |
Proof of Theorem 1.2. We now proceed to prove the first part of Theorem 1.2. Substituting (6.4) and Lemma 6.4 into (6.2), we have
E(V,X,δ)τ2X1312≪(τ(E(V,X,δ)X12+ε+(E(V,X,δ))2Xε))12(τX136−11144+ε)12≪τE(V,X,δ)12X1612−11288+ε+τE(V,X,δ)X1312−11288+ε. |
Due to 0<δ<11288, there is τX1312−11288+ε=o(τ2X1312), we obtain
E(V,X,δ)τ2X1312≪τE(V,X,δ)12X1612−11288+ε. |
Thus, we find
E(V,X,δ)≪τ−2X12−11144+2ε≪X61144+2δ+2ε. |
Since λ1/λ3 is irrational, there exist infinitely many values of q that can be selected with a sequence Xj→∞ such that
E(V,Xj,δ)≪X61144+2δ+2εj. |
This completes the proof of the first part of Theorem 1.2.
Next, we prove the second part of Theorem 1.2. By the proof methods from Lemmas 6.2 and 6.3, we observe that replacing ρ with χ (as defined in Theorem 1.2) is sufficient, resulting in the following conditions:
X(1−ω)(1−8215χ)≪q≪X(1−8215χ). |
Substituting and simplifying, we obtain
E(V,X,δ)τ2X1312≪τ(E(V,X,δ))12X1612−1124χ+ε+τE(V,X,δ)X1312−1124χ+ε. |
Given the conditions of the theorem, specifically 0<δ<1124χ, we have the asymptotic relation τX1312−1124χ+ε=o(τ2X1312). From this, we can deduce that
E(V,X,δ)≪τ−2X12−1112χ+2ε≪X12−1112χ+2δ+2ε. |
Thus, the second part of Theorem 1.2 is proved.
In this paper, we prove that, for any ε>0, the number of v∈V with v≤X such that the inequality
|λ1p1+λ2p22+λ3p33+λ4p44−v|<v−δ |
has no solution in primes p1, p2, p3, p4 that does not exceed O(X1−83144+2δ+2ε).
Xinyan Li: Writing-review and editing, writing-original draft, validation, resources, methodology, formal analysis, conceptualization; Wenxu Ge: Writing-review and editing, resources, methodology, supervision, validation, formal analysis. All authors have read and approved the final version of the manuscript for publication.
The authors declare they have not used Artificial Intelligence (AI) tools in the creation of this article.
We express our sincere gratitude to the High-level Talent Research Start-up Project Funding of Henan Academy of Sciences (Grant No. 252019083) for providing us with crucial initial funding for our research. Additionally, we would like to thank the National Natural Science Foundation of China (Grant No. 12071132) and the Joint Fund of Henan Province Science and Technology R&D Program (Grant No. 225200810032) for their financial support and generous funding. These funds have played an essential role in the successful completion of our research.
The authors declare that they have no conflict of interest.
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