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A Diophantine approximation problem with unlike powers of primes

  • Received: 04 November 2024 Revised: 17 December 2024 Accepted: 25 December 2024 Published: 13 January 2025
  • MSC : 11D75, 11P32, 11P55

  • Let λ1, λ2, λ3, and λ4 be non-zero real numbers, not all negative. Suppose that λ1/λ3is irrational and algebraic, δ>0, and the set V is a well-spaced sequence. In this paper, we prove that, for any ε>0, the number of vV with vX such that the inequality

    |λ1p1+λ2p22+λ3p33+λ4p44v|<vδ

    has no solution in primes p1, p2, p3, p4 that does not exceed O(X183144+2δ+2ε).

    Citation: Xinyan Li, Wenxu Ge. A Diophantine approximation problem with unlike powers of primes[J]. AIMS Mathematics, 2025, 10(1): 736-753. doi: 10.3934/math.2025034

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  • Let λ1, λ2, λ3, and λ4 be non-zero real numbers, not all negative. Suppose that λ1/λ3is irrational and algebraic, δ>0, and the set V is a well-spaced sequence. In this paper, we prove that, for any ε>0, the number of vV with vX such that the inequality

    |λ1p1+λ2p22+λ3p33+λ4p44v|<vδ

    has no solution in primes p1, p2, p3, p4 that does not exceed O(X183144+2δ+2ε).



    In 1953, Prachar [1] demonstrated that any sufficiently large odd integer N can be expressed as

    N=p1+p22+p33+p44+p55,

    where p1, p2, p3, p4, and p5 are prime numbers. Subsequently, as a result of [2, Theorem 1], Ren and Tsang reached the same conclusion as Prachar. It is significant to explore the analogous formulation for Diophantine inequalities. In 1973, Vaughan [3] first proved that for any real η, there are infinitely many solutions in primes pj to the inequality

    |λ1p1+λ2p2+λ3p3+η|<(maxpj)ξ+ε (1.1)

    with ξ=1/10. The exponent was subsequently improved several times, and the best result up to now is due to K. Matomäki [4] with ξ=2/9. Moreover, it is worth mentioning that Diophantine inequality (1.1) has also been resolved for special prime numbers. The solvability of (1.1) with primes p1, p2, and p3, where pi+2 are almost-primes, is discussed in [5]. Similarly, the cases where p3=x2+y2+1 or pi=[nc] (Piatetski-Shapiro primes) are addressed in [6,7], respectively.

    Then for related results for Diophantine inequalities with unlike powers of primes, we consider the following examples. Let λ1, λ2, λ3, λ4, and λ5 be non-zero real numbers, not all negative, and suppose that λ1/λ2 is irrational. In 2016, Ge and Li [8] demonstrated that for any given real numbers η and σ with 0<σ<1720, there exist infinitely many solutions in prime numbers pj to the inequality

    |λ1p1+λ2p22+λ3p33+λ4p44+λ5p55+η|<(max1j5pj)σ. (1.2)

    In 2017, Mu [9] made further improvements by extending the range of the exponent to σ1180 using the method outlined in Languasco and Zaccagnini [10]. Subsequently, Liu [11] optimized the result further, obtaining σ5288. Inspired by the work of Wang and Yao [12], Mu and Qu [13] combined the sieve methods from Harman [14] and Harman and Kumchev [15] to refine Liu's result and prove that (1.2) holds for σ5252. Very recently, this result was improved by Zhu [16], who obtained σ148. In 2022, Zhu [17] employed an innovative approach to estimate the correlation integral over the minor arcs, leading to a more robust estimation that σ19756.

    Building upon the advancements made in the study of Diophantine inequalities, subsequent research has explored different variations and forms of these inequalities. For clarity in discussion, we first introduce the definition of a well-spaced sequence. A set of positive real numbers V is called a well-space sequence if there exists a constant c>0 such that

    u,vV,uv|uv|>c.

    On this basis, in 2018, Ge and Zhao [18] dropped the linear prime variable in (1.2) and considered the exceptional set for the inequality

    |λ2p22+λ3p33+λ4p44+λ5p55v|<vδ, (1.3)

    where λ2, λ3, λ4, and λ5 are non-zero real numbers, not all negative. Let D be a well-spaced sequence, and suppose δ>0, and λ1/λ2 is algebraic and irrational. Denote by E(D,X,δ) the number of vD with vX such that the inequality (1.3) has no solution in primes p2, p3, p4, and p5. Recently, Ge and Zhao [18] demonstrated that

    E(D,X,δ)X1172+2δ+ε.

    Subsequently, Mu and Gao [19], as well as Liu and Liu [20], further improved upon the result of Ge and Zhao.

    In this paper, we drop the final prime variable in (1.2) and examine the exceptional set for the inequality

    |λ1p1+λ2p22+λ3p33+λ4p44v|<vδ. (1.4)

    Drawing on techniques from [18,20], we establish the following results.

    Theorem 1.1. Let λ1, λ2, λ3, and λ4 be non-zero real numbers, not all negative. Suppose that λ1/λ3is irrational and algebraic, δ>0, and the set V is a well-spaced sequence. Denote by E(V,X,δ) the number of vV with vX such that the inequality

    |λ1p1+λ2p22+λ3p33+λ4p44v|<vδ

    has no solution in primes p1, p2, p3, p4. Then, for any ε>0, we have

    E(V,X,δ)X183144+2δ+2ε. (1.5)

    Theorem 1.2. Let λ1, λ2, λ3, and λ4 be non-zero real numbers, not all negative. Suppose that λ1/λ3is irrational and algebraic, δ>0, and the set V is a well-spaced sequence. Then there is a sequence Xj such that

    E(V,Xj,δ)Xj183144+2δ+2ε (1.6)

    for any ε>0. Moreover, if the convergent denominators qj for λ1/λ3satisfy q1wj+1qj for w[0,1), then, for all X1 and any ε>0,

    E(V,X,δ)X121112χ+2δ+2ε, (1.7)

    with

    χ=min(4190ω492(1ω),112). (1.8)

    Remark. Theorem 1.1 follows directly from Theorem 1.2. Since λ1/λ3 is algebraic, we can set w=ε, and thus χ=112. Therefore, we focus on proving Theorem 1.2 in the following.

    Notation. Throughout this paper, the letter p denotes a prime number, with or without subscripts. The non-zero real numbers λ1, λ2, λ3, λ4, and δ are given constants. Implicit constants in the O, and notations usually depend at most on λ1, λ2, λ3, and λ4. The letter ε represents an arbitrarily small positive constant, but not necessarily the same each time. We write e(x)=exp(2πix).

    Let X be a sufficiently large positive number. Suppose that Ik=[(ηX)1/k,(X)1/k] for k=1,2,3,4 and 0<τ<1. Define

    Kτ(α)={(sinπταπα)2α0;  τ2α=0, (2.1)

    and

    Sk(α)=pIk(logp)e(αpk),Uk(α)=nIke(αnk), (2.2)

    for k=1,2,3,4. Then, it is simple to obtain

    Kτ(α)min(τ2,|α|2),+Kτ(α)e(αx)dα=max(0,τ|x|). (2.3)

    For convenience, Φ is defined as an arbitrary measurable subset of R, and then

    I(v,X;Φ)=ΦS1(λ1α)S2(λ2α)S3(λ3α)S4(λ4α)Kτ(α)e(vα)dα.

    By (2.3), we have

    I(v,X;R)=+S1(λ1α)S2(λ2α)S3(λ3α)S4(λ4α)Kτ(α)e(vα)dα=pkIk(logp1)(logp4)+e((λ1p1+λ2p22+λ3p33+λ4p44v)α)Kτ(α)dα=pkIk(logp1)(logp4)max(0,τ|λ1p1+λ2p22+λ3p33+λ4p44v|)(logX)4pkIkmax(0,τ|λ1p1+λ2p22+λ3p33+λ4p44v|). (2.4)

    Thus

    0I(v,X;R)τ(logX)4N(v,X),

    where N(v,X) counts the number of solutions to the inequality

    |λ1p1+λ2p22+λ3p33+λ4p44v|<τ,pkIk(k=1,2,3,4).

    To estimate (2.4), we divide the region of integration into three parts: The major arc M, the minor arc m, and the trivial arc t, defined as

    M={α:|α|ϕ}{α:ϕ<|α|ξ},m={α:ξ<|α|<γ},t={α:|α|γ},

    and then we can write

    I(v,X;R)=I(v,X;M)+I(v,X;m)+I(v,X;t), (2.5)

    where ϕ=X5241ε,ξ=X79ε,γ=τ2X712+2ε.

    It is sufficient to establish a positive lower bound for I(v,X;R). We employ a standard dyadic argument, focusing on those values of v that satisfy 12XvX. We will estimate the three terms on the right-hand side of (2.5) in Sections 4–6. Additionally, Sections 3 and 6 will present preliminary lemmas and conclude the proof of Theorem 1.2.

    Lemma 3.1. Suppose that XZ1X45+2ε and |S1(λ1α)|>Z1. Then, there exist two coprime integers a and q such that

    1q(X1+εZ1)2,|qλ1αa|(X1+εZ1)2X1.

    Proof. This is extracted from [13, Lemma 4.1].

    Lemma 3.2. Suppose that α is a real number, and there exist aZ and qN with

    (q,a)=1,1qP32,|qαa|<P32.

    Then one has

    P<p2P(logp)e(αp3)P1112+ε+P1+εq12(1+P3|αaq|)12.

    Proof. See [18, Lemma 2.3].

    Lemma 3.3. Let k1 be a real number. For any fixed real number A6, we have

    |α|X1+56kε|Sk(α)Uk(α)|2dαX2k1(logX)A.

    Proof. This follows from [21, Corollary 2.3].

    Lemma 3.4. Let k be a positive integer, we have

    |α|X1+23kε|Sk(λα)|2dαX2k1.

    Proof. This lemma corresponds to [13, Lemma 3.3] or [19, Lemma 3.1].

    Lemma 3.5. Suppose X181|α|X18, we have

    |S4(λ4α)|X141512+ε.

    Proof. This result is derived from [22, Theorem 1] by taking q=[|λ4α|1] and a=1. It can also be found in [20].

    Lemma 3.6. For k=1,2,3,4, and a positive integer m such that 1mk, we have

    +|Sk(α)|2mKτ(α)dατX(2mm)/k+ε,11|Sk(α)|2mdαX(2mm)/k+ε.

    Proof. These results are derived from Hua's Lemma, with further details outlined in [3, Lemma 2.5].

    Lemma 3.7. Suppose that α is a real number, and there exist aZ and qN with

    (q,a)=1,1qP4721,|qαa|P4721.

    Then one has

    pP(logp)e(αp4)P2324+ε+P1+εq12(1+P4|αaq|)12.

    Proof. This result is derived from [23, Theorem 1] by taking k=4.

    Lemma 3.8. Let m(3)=136, m(4)=196, λ and μ be nonzero constants. For i=3,4, suppose that X1im(i)+εZiX1i. We define

    ρ(Zi)={αR:Zi|Si(λiα)|X1i}.

    i) For αρ(Zi), there exist coprime integers ai, qi satisfying

    1qi(X1i+εZi)2,|αqiλiai|(X1i+εZi)2X1.

    ii) For l4, we have

    ρ(Zi)|Si(λα)|2|Sl(μα)|2Kτ(α)dατ(X2i+2l1+ε+X4i+1l1+εZi2).

    Proof. For i=3, let P=X13, Q=P32. By Dirichlet's approximation theorem, there exist two coprime integers a3, q3 with 1q3Q and |αλ3q3a3|Q1. Then it follows from Lemma 3.2 and the hypothesis Z3X13m(3)+ε, we have

    X13m(3)+εZ3|S3(λ3α)|X13m(3)+ε+X13+ε(q3+X|αλ3q3a3|)12. (3.1)

    Thus, we have

    1q3(X13+εZ3)2,|αq3λ3a3|(X13+εZ3)2X1.

    For i=4, let P=X14, Q=P4721. By Dirichlet's approximation theorem, there exist two coprime integers a4, q4 with 1q4Q and |αλ4q4a4|Q1. Then it follows from Lemma 3.7 and the hypothesis Z4X14m(4)+ε, we have

    X14m(4)+εZ4|S4(λ4α)|X14m(4)+ε+X14+ε(q4+X|αλ4q4a4|)12. (3.2)

    Thus, we have

    1q4(X14+εZ4)2,|αq4λ4a4|(X14+εZ4)2X1,

    which completes the proof of Lemma 3.8 i).

    Next, we give the proof of Lemma 3.8 ii). Using Brüdern's method from [24], the result can be established for the case when λ=1. To simplify the analysis, we assume that λ=1. Define Qi=X2i+εZ2i and

    ρi(qi,ai)={α:|αaiqi|QiqiX},i=3,4.

    Let Vi(α) be a function of period 1. Further, define the function Vi(α) for α(QiX1,1+QiX1] as

    Vi(α)={(qi+X|αqiai|)1,αρi;0,α(QiX1,1+QiX1]ρi,

    where ρi is the union of all intervals ρi(qi,ai) such that 1aiqiQi and (ai,qi)=1. Let ρi=ρi+Z be the union of all such intervals, then

    ρ(Zi)ρi. (3.3)

    For αρ(Zi), by combining (3.1)–(3.3), we obtain

    |Si(λα)|X1i+εVi(α)12.

    Next, we express

    |Sl(μα)|2=ve(αv)ψ(v),

    where l4,

    ψ(v)=p3,p4Ilμ(pl3pl4)=v.(logp3)(logp4),

    We can deduce from [24, Lemma3] that

    ρ(Zi)|Si(λα)|2|Sl(μα)|2Kτ(α)dαX2i+ερiVi(α)v(ψ(v)e(αv))Kτ(α)dατX2i1+ε(1+τ)1+ε(vψ(v)+Qi|v|τψ(v)). (3.4)

    We easily derive

    vψ(v)=|Sl(0)|2X2l. (3.5)

    Since τ0 as X, by the Prime Number Theorem, we have

    |v|τψ(v)=pIl(logp)2X1l+ε. (3.6)

    Lemma 3.8 ii) can be readily proven by substituting (3.5) and (3.6) into (3.4).

    In this section, we refine our analysis by dividing the major arc into two distinct regions, M1 and M2, which are defined as follows:

    M1={α:|α|X5241ε},M2={α:X5241ε<|α|X79ε}.

    In this subsection, we establish a lower bound for the integral over the M1. For k = 1, 2, 3, 4, define

    Fk(α)=Ike(αuk)du.

    Applying the first derivative estimate for trigonometric integrals (see [25, Lemma 4.2]), we derive the bound

    Fk(α)X1k1min(X,|α|1). (4.1)

    Lemma 4.1. We have

    I(v,X;M1)τ2X1312.

    Proof. It can be easily demonstrated that

    M1S1(λ1α)S2(λ2α)S3(λ3α)S4(λ4α)Kτ(α)e(vα)dα=M1F1(λ1α)F2(λ2α)F3(λ3α)F4(λ4α)Kτ(α)e(vα)dα+M1(S1(λ1α)F1(λ1α))F2(λ2α)F3(λ3α)F4(λ4α)Kτ(α)e(vα)dα+M1S1(λ1α)(S2(λ2α)F2(λ2α))F3(λ3α)F4(λ4α)Kτ(α)e(vα)dα+M1S1(λ1α)S2(λ2α)(S3(λ3α)F3(λ3α))F4(λ4α)Kτ(α)e(vα)dα+M1S1(λ1α)S2(λ2α)S3(λ3α)(S4(λ4α)F4(λ4α))Kτ(α)e(vα)dα=J0+J1+J2+J3+J4,

    where it is shown that J0τ2X1312 and Jk=o(τ2X1312) for k = 1, 2, 3, 4.

    The analysis begins by establishing a lower bound for J0,

    J0=RF1(λ1α)F2(λ2α)F3(λ3α)F4(λ4α)Kτ(α)e(vα)dα+O(|α|>X5241ε|F1(λ1α)F2(λ2α)F3(λ3α)F4(λ4α)|Kτ(α)dα). (4.2)

    Utilizing Eqs (2.3) and (4.1), we deduce that the error term in (4.2) satisfies

    τ2X2312|α|>X5241ε1|α|4dατ2X2312+198+3ε=o(τ2X1312). (4.3)

    For brevity, let yj=λjxjj for j = 1, 2, 3, 4. By changing the order of integration and substituting variables, we note that the domains of integration for y1, y2, y3, and y4 are [λjηX,λjX]. Moreover, the integral satisfies |4j=1yjv|<τ. Considering |4j=1yjv|<τ2 and the bounds on y4, we derive the lower bound for the final integral. Therefore

    RF1(λ1α)F2(λ2α)F3(λ3α)F4(λ4α)Kτ(α)e(vα)dα=124λ1λ21/2λ31/3λ41/4y10y212y323y434Re((4j=1yjv)α)Kτ(α)dαdy1dy2dy3dy4τX34λ1Xλ1ηXλ2Xλ2ηXλ3Xλ3ηX3j=1yj+v+τ23j=1yj+vτ2y10y212y323dy1dy2dy3dy4τ2X1312,

    which means that

    RF1(λ1α)F2(λ2α)F3(λ3α)F4(λ4α)Kτ(α)e(vα)dατ2X1312. (4.4)

    Thus, combining (4.2)–(4.4), we have

    J0τ2X1312. (4.5)

    Then we turn to dealing with J1, J2, J3, and J4. According to Euler's summation formula, we have

    |Uk(α)Fk(α)|1+|α|X,k=1,2,3,4. (4.6)

    Using (2.3), we estimate J1 as follows:

    J1τ2M1|S1(λ1α)F1(λ1α)||F2(λ2α)F3(λ3α)F4(λ4α)|dατ2M1|S1(λ1α)U1(λ1α)||F2(λ2α)F3(λ3α)F4(λ4α)|dα+τ2M1|U1(λ1α)F1(λ1α)||F2(λ2α)F3(λ3α)F4(λ4α)|dα=:τ2(A1+B1). (4.7)

    Utilizing Cauchy's inequality along with Lemma 3.3 and (4.1), we derive

    A1X712(M1|S1(λ1α)U1(λ1α)|2dα)12(M1|F2(λ2α)|2dα)12X1312(logX)A2(1X0Xdα+X1+524ε1XX1|α|2dα)12X1312(logX)A2. (4.8)

    Similarly, from (4.1) and (4.6), we have

    B11X0|F2(λ2α)F3(λ3α)F4(λ4α)|dα+XX1+524ε1X|α||F2(λ2α)F3(λ3α)F4(λ4α)|dαX112+XX1+524ε1X|α|2X2312dαX112. (4.9)

    Hence, by combining (4.7)–(4.9), it follows that

    J1=o(τ2X1312). (4.10)

    Following analogous reasoning for J2 by (2.3), we have

    J2τ2M1|S1(λ1α)||S2(λ2α)F2(λ2α)||F3(λ3α)F4(λ4α)|dατ2M1|S1(λ1α)||S2(λ2α)U2(λ2α)||F3(λ3α)F4(λ4α)|dα+τ2M1|S1(λ1α)||U2(λ2α)F2(λ2α)||F3(λ3α)F4(λ4α)|dα=:τ2(A2+B2). (4.11)

    Applying Cauchy's inequality along with Lemmas 3.3 and 3.4, it can be further derived that

    A2X712(|α|X1+23ε|S1(λ1α)|2dα)12(M1|S2(λ2α)U2(λ2α)|2dα)12X1312(logX)A2. (4.12)

    Similarly, using the estimates derived from (4.1) and (4.6), along with the results from Lemma 3.4, we have

    B21X0|S1(λ1α)F3(λ3α)F4(λ4α)|dα+XX1+524ε1X|α||S1(λ1α)F3(λ3α)F4(λ4α)|dαX712+X512X1+524ε1X|α|1|S1(λ1α)|dαX712+X512(X1+524ε1X|α|2dα)12(|α|X1+23ε|S1(λ1α)|2dα)12X712. (4.13)

    Therefore, combining (4.11)–(4.13) results in the conclusion that

    J2=o(τ2X1312). (4.14)

    Similar arguments for J3 and J4, utilizing Lemmas 3.3 and 3.4, we obtain

    Jj=o(τ2X1312),j=3,4. (4.15)

    Hence, by combining (4.5), (4.10), (4.14), and (4.15), the proof of Lemma 4.1 is complete.

    In this subsection, we derive an upper bound for the integral over the region M2 to quantify its contribution to the overall integral.

    Lemma 4.2. We conclude that

    I(v,X;M2)=o(τ2X1312). (4.16)

    Proof. By applying Cauchy's inequality, along with the results from (2.3) and Lemmas 3.4 and 3.5, we derive the following:

    I(v,X;M2)=M2S1(λ1α)S2(λ2α)S3(λ3α)S4(λ4α)Kτ(α)e(vα)dατ2XmaxαM2|S4(λ4α)|(M2|S2(λ2α)|2dα)12(M2|S3(λ3α)|2dα)12τ2X541512+ε(M2|S2(λ2α)|2dα)12(M2|S3(λ3α)|2dα)12τ2X13121512+ε=o(τ2X1312).

    Subsequently, combining the results from Lemmas 4.1 and 4.2, we conclude the integral estimation over the major arc M, to obtain the following lemma.

    Lemma 4.3. We have

    I(v,X;M)τ2X1312.

    In this section, we demonstrate

    I(v,X;t)=o(τ2X1312). (5.1)

    Utilizing Cauchy's inequality and the trivial bounds of S1(λ1α), S4(λ4α), we obtain

    I(v,X;t)=tS1(λ1α)S2(λ2α)S3(λ3α)S4(λ4α)Kτ(α)e(vα)dαX1+14(t|S2(λ2α)|2Kτ(α)dα)12(t|S3(λ3α)|2Kτ(α)dα)12. (5.2)

    By the periodicity of S2(λ2α), along with (2.3) and Lemma 3.6, we obtain

    t|S2(λ2α)|2Kτ(α)dαγ|S2(λ2α)|21|α|2dα|λ2|γ|S2(α)|21|α|2dαm=[|λ2|γ]m+1m|S2(α)|21|α|2dαm=[|λ2|γ]m+1m|S2(α)|21m2dα10|S2(α)|2dαm=[|λ2|γ]1m2X12+εγ1. (5.3)

    Similarly, we can conclude that

    t|S3(λ3α)|2Kτ(α)dαX13+εγ1. (5.4)

    By combining (5.2)–(5.4), we have

    tS1(λ1α)S2(λ2α)S3(λ3α)S4(λ4α)Kτ(α)e(vα)dαX2012+εγ1X2012+ετ2X7122ετ2X1312ε.

    Thus, (5.1) follows directly.

    This section provides a precise estimation of the integral over the minor arc and proves Theorem 1.2. We define m=mm, with ρ=112 and τ=Xδ.

    Let E=E(V,X,δ) denote the set of elements v in V for which the inequality (1.4) has no solution in the prime variables pj for j=1,2,3,4. Thus, we have E(V,X,δ)=|E(V,X,δ)|. By selecting an appropriate complex number ϑv such that |ϑv|=1, we can reformulate the integral as follows:

    E(V,X,δ)τ2X1312vE|mS1(λ1α)S2(λ2α)S3(λ3α)S4(λ4α)Kτ(α)e(vα)dα|=vEϑvmS1(λ1α)S2(λ2α)S3(λ3α)S4(λ4α)Kτ(α)e(vα)dα=mS1(λ1α)S2(λ2α)S3(λ3α)S4(λ4α)T(α)Kτ(α)dα. (6.1)

    In this case, we have

    T(α)=vEϑve(vα).

    By applying Cauchy's inequality, we can bound the expression as follows:

    E(V,X,δ)τ2X1312(m|S2(λ2α)T(α)|2Kτ(α)dα)12×(m|S1(λ1α)S3(λ3α)S4(λ4α)|2Kτ(α)dα)12. (6.2)

    Next, we define m=m1m2m3 and m=mm, with X=q9049, where

    m1={α:|S3(λ3α)|<X1313ρ+ε,|S4(λ4α)|<X1418ρ+ε},m2={α:|S1(λ1α)|<X1125ρ+ε,|S3(λ3α)|X1313ρ+ε},m3={α:|S1(λ1α)|<X1125ρ+ε,|S4(λ4α)|X1418ρ+ε}. (6.3)

    Lemma 6.1. We have

    m|S2(λ2α)T(α)|2Kτ(α)dατ(E(V,X,δ)X12+ε+(E(V,X,δ))2Xε). (6.4)

    Proof. According to (2.3), we have

    R|S2(λ2α)T(α)|2Kτ(α)dα=v1,v2Eϑv1ϑv2ηXp12,p22X(logp1)(logp2)Re[(λ2(p12p22)(v1v2))α]Kτ(α)dα=v1,v2Eϑv1ϑv2ηXp12,p22X(logp1)(logp2)max(0,τ|λ2(p12p22)(v1v2)|)(logX)2L(X),

    where L(X) represents the number of solutions to the inequality

    |λ2(p12p22)(v1v2)|<τ

    with v1,v2E and ηXp12,p22X.

    Since X is sufficiently large and τ=Xδ. When v1=v2, there must exist the case that p1=p2. Under this condition, we can deduce that

    L(X)τE(V,X,δ)X12.

    When v1v2, there exists at most one integer n such that nX and the inequality |λ2n(v1v2)|<τ holds. For any integer n, the number of solutions to n=p12p22 is bounded by Xε. Consequently, we obtain

    L(X)τ(E(V,X,δ))2Xε.

    Combining both cases, we obtain

    L(X)τ(E(V,X,δ)X12+(E(V,X,δ))2Xε).

    Thus, Lemma 6.1 is established.

    Lemma 6.2. We have

    m|S1(λ1α)S3(λ3α)S4(λ4α)|2Kτ(α)dατX1361112ρ+ε. (6.5)

    Proof. Utilizing Lemmas 3.6 and 3.8 ii) along with the trivial bounds for S3(λ3α) and S4(λ4α), we analyze the integrals over m1, m2, and m3 separately.

    For the integral over the interval m1, we obtain

    m1|S1(λ1α)S3(λ3α)S4(λ4α)|2Kτ(α)dα(X13136+ε)2(X14196+ε)2(m1|S1(λ1α)|2Kτ(α)dα)τX1361112ρ+ε.

    For the integral over the interval m2, we obtain

    m2|S1(λ1α)S3(λ3α)S4(λ4α)|2Kτ(α)dα(X115+ε)2(m2|S3(λ3α)|2|S4(λ4α)|2Kτ(α)dα)τX136245ρ+ε.

    For the integral over the interval m3, we obtain

    m3|S1(λ1α)S3(λ3α)S4(λ4α)|2Kτ(α)dα(X115+ε)2(R|S3(λ3α)|4Kτ(α)dα)12(m3|S4(λ4α)|2|S4(λ4α)|2Kτ(α)dα)12τX136145ρ+ε.

    By combining these estimates, Lemma 6.2 follows immediately.

    Lemma 6.3. We have

    m|S1(λ1α)S3(λ3α)S4(λ4α)|2Kτ(α)dατX1369815ρ+5ε. (6.6)

    Proof. Employing Harman's method as outlined in [14], we partition the region m into disjoint sets S(Z1,Z3,y) defined as

    S(Z1,Z3,y)={αm:Z1|S1(λ1α)|<2Z1,Z3|S3(λ3α)|<2Z3,y|α|2y},

    where Z1=X1125ρ+2ε2t1, Z3=X1313ρ+2ε2t2, y=ξ2t3 for some positive integers t1, t2, and t3.

    By invoking Lemmas 3.1 and 3.8 i), we obtain integers a1, q1 and a3, q3 such that (a1,q1)=1 and (a3,q3)=1 satisfying

    1q1(X1+εZ1)2,|q1λ1αa1|X1(X1+εZ1)2, (6.7)
    1q3(X13+εZ3)2,|q3λ3αa3|X1(X13+εZ3)2. (6.8)

    Note that a1a30.

    We further dissect S(Z1,Z3,y) into subsets S(Z1,Z3,y,Q1,Q3) with α satisfying |α|y=ξ2t3ξ=X79ε and |aiλiα|qi for i=1,3, where

    Q1q1<2Q1,Q3q3<2Q3,Q1(X1+εZ1)2,Q3(X13+εZ3)2.

    Then, we have

    |a3q1λ1λ3a1q3|=|a1(a3q3λ3α)+a3(q1λ1αa1)λ3α|Q1X1(X13+εZ3)2+Q3X1(X1+εZ1)2X1+8215ρ4εX49904ε. (6.9)

    Assuming that |a3q1| takes only R distinct values. By the pigeonhole principle, we have RyQ1Q3q. Due to bounds on the divisor function, each value of |a3q1| corresponds to significantly fewer than Xε pairs a3,q1. For fixed a3 and q1, the value of |a1q3| is the integral part of a3q1λ1λ3; thus there are significantly fewer than Xε pairs a1,q3. Consequently, by (6.7) and (6.8), the length of S(Z1,Z3,y,Q1,Q3) is

    RXεmin(1Q1X(X1+εZ1)2,1Q3X(X13+εZ3)2)X101180+εyqZ1Z3.

    Evaluating the integral over S(Z1,Z3,y,Q1,Q3), we obtain

    S(Z1,Z3,y,Q1,Q3)|S1(λ1α)S3(λ3α)S4(λ4α)|2Kτ(α)dαmin(τ2,y2)Z12Z23X24S(Z1,Z3,y,Q1,Q3)dατy1Z21Z23X12X101180+εyqZ1Z3τy1Z1Z3X12X101180+εyqτX4311804115ρ+5εqτX136+5εqτX7345+5ε.

    Finally, summing over all possible values of Z1,Z3,y,Q1,Q3, we have

    m|S1(λ1α)S3(λ3α)S4(λ4α)|2Kτ(α)dατX7345+6ε.

    Combining Lemmas 6.2 and 6.3, we arrive at Lemma 6.4.

    Lemma 6.4. We have

    m|S1(λ1α)S3(λ3α)S4(λ4α)|2Kτ(α)dατX1361112ρ+ε.

    Proof of Theorem 1.2. We now proceed to prove the first part of Theorem 1.2. Substituting (6.4) and Lemma 6.4 into (6.2), we have

    E(V,X,δ)τ2X1312(τ(E(V,X,δ)X12+ε+(E(V,X,δ))2Xε))12(τX13611144+ε)12τE(V,X,δ)12X161211288+ε+τE(V,X,δ)X131211288+ε.

    Due to 0<δ<11288, there is τX131211288+ε=o(τ2X1312), we obtain

    E(V,X,δ)τ2X1312τE(V,X,δ)12X161211288+ε.

    Thus, we find

    E(V,X,δ)τ2X1211144+2εX61144+2δ+2ε.

    Since λ1/λ3 is irrational, there exist infinitely many values of q that can be selected with a sequence Xj such that

    E(V,Xj,δ)X61144+2δ+2εj.

    This completes the proof of the first part of Theorem 1.2.

    Next, we prove the second part of Theorem 1.2. By the proof methods from Lemmas 6.2 and 6.3, we observe that replacing ρ with χ (as defined in Theorem 1.2) is sufficient, resulting in the following conditions:

    X(1ω)(18215χ)qX(18215χ).

    Substituting and simplifying, we obtain

    E(V,X,δ)τ2X1312τ(E(V,X,δ))12X16121124χ+ε+τE(V,X,δ)X13121124χ+ε.

    Given the conditions of the theorem, specifically 0<δ<1124χ, we have the asymptotic relation τX13121124χ+ε=o(τ2X1312). From this, we can deduce that

    E(V,X,δ)τ2X121112χ+2εX121112χ+2δ+2ε.

    Thus, the second part of Theorem 1.2 is proved.

    In this paper, we prove that, for any ε>0, the number of vV with vX such that the inequality

    |λ1p1+λ2p22+λ3p33+λ4p44v|<vδ

    has no solution in primes p1, p2, p3, p4 that does not exceed O(X183144+2δ+2ε).

    Xinyan Li: Writing-review and editing, writing-original draft, validation, resources, methodology, formal analysis, conceptualization; Wenxu Ge: Writing-review and editing, resources, methodology, supervision, validation, formal analysis. All authors have read and approved the final version of the manuscript for publication.

    The authors declare they have not used Artificial Intelligence (AI) tools in the creation of this article.

    We express our sincere gratitude to the High-level Talent Research Start-up Project Funding of Henan Academy of Sciences (Grant No. 252019083) for providing us with crucial initial funding for our research. Additionally, we would like to thank the National Natural Science Foundation of China (Grant No. 12071132) and the Joint Fund of Henan Province Science and Technology R&D Program (Grant No. 225200810032) for their financial support and generous funding. These funds have played an essential role in the successful completion of our research.

    The authors declare that they have no conflict of interest.



    [1] K. Prachar, Über ein Problem vom Waring-Goldbach'schen Typ II, Monatsh. Math., 57 (1953), 113–116. https://doi.org/10.1007/BF01299628 doi: 10.1007/BF01299628
    [2] X. M. Ren, K. M. Tsang, Waring-Goldbach problem for unlike powers, Acta Math. Sin., 23 (2007), 265–280. https://doi.org/10.1007/s10114-005-0733-z doi: 10.1007/s10114-005-0733-z
    [3] R. C. Vaughan, Diophantine approximation by prime numbers I, P. Lond. Math. Soc., 28 (1974), 373–384. https://doi.org/10.1112/plms/s3-28.2.373 doi: 10.1112/plms/s3-28.2.373
    [4] K. Matomäki, Diophantine approximation by primes, Glasgow Math. J., 52 (2010), 87–106. https://doi.org/10.1017/S0017089509990176 doi: 10.1017/S0017089509990176
    [5] S. I. Dimitrov, Diophantine approximation by special primes, arXiv Preprint, 2017.
    [6] S. I. Dimitrov, Diophantine approximation with one prime of the form p=x2+y2+1, Lith. Math. J., 61 (2021), 445–459. https://doi.org/10.1063/1.5082104 doi: 10.1063/1.5082104
    [7] S. I. Dimitrov, Diophantine approximation by Piatetski-Shapiro primes, Indian J. Pure Ap. Mat., 53 (2022), 875–883. https://doi.org/10.1007/s13226-021-00193-7 doi: 10.1007/s13226-021-00193-7
    [8] W. X. Ge, W. P. Li, One diophantine inequality with unlike powers of prime variables, J. Inequal. Appl., 33 (2016), 8. https://doi.org/10.1186/s13660-016-0983-6 doi: 10.1186/s13660-016-0983-6
    [9] Q. W. Mu, One diophantine inequality with unlike powers of prime variables, Int. J. Number Theory, 13 (2017), 1531–1545. https://doi.org/10.1142/S1793042117500853 doi: 10.1142/S1793042117500853
    [10] A. Languasco, A. Zaccagnini, A Diophantine problem with a prime and three squares of primes, J. Number Theory, 132 (2012), 3016–3028. https://doi.org/10.1016/j.jnt.2012.06.01 doi: 10.1016/j.jnt.2012.06.01
    [11] Z. X. Liu, Diophantine approximation by unlike powers of primes, Int. J. Number Theory, 13 (2017), 2445–2452. https://doi.org/10.1142/S1793042117501330 doi: 10.1142/S1793042117501330
    [12] Y. C. Wang, W. L. Yao, Diophantine approximation with one prime and three squares of primes, J. Number Theory, 180 (2017), 234–250. https://doi.org/10.1016/j.jnt.2017.04.013 doi: 10.1016/j.jnt.2017.04.013
    [13] Q. W. Mu, Y. Y. Qu, A note on Diophantine approximation by unlike powers of primes, Int. J. Number Theory, 14 (2018), 1651–1668. https://doi.org/10.1142/S1793042118501002 doi: 10.1142/S1793042118501002
    [14] G. Harman, The values of ternary quadratic forms at prime arguments, Mathematika, 51 (2004), 83–96. https://doi.org/10.1112/S0025579300015527 doi: 10.1112/S0025579300015527
    [15] G. Harman, A. V. Kumchev, On sums of squares of primes, Math. Proc. Cambridge, 140 (2006), 1–13. https://doi.org/10.1017/S0305004105008819
    [16] L. Zhu, Diophantine inequality by unlike powers of primes, Ramanujan J., 51 (2020), 307–318. https://doi.org/10.1007/s11139-019-00152-1 doi: 10.1007/s11139-019-00152-1
    [17] L. Zhu, Diophantine Inequality by unlike powers of primes, Chinese Ann. Math. B, 43 (2022), 125–136. https://doi.org/10.1007/s11401-022-0326-5 doi: 10.1007/s11401-022-0326-5
    [18] W. X. Ge, F. Zhao, The exceptional set for Diophantine inequality with unlike powers of prime variables, Czech. Math. J., 68 (2018), 149–168. https://doi.org/10.21136/CMJ.2018.0388-16 doi: 10.21136/CMJ.2018.0388-16
    [19] Q. W. Mu, Z. P. Gao, A note on the exceptional set for Diophantine approximation with mixed powers of primes, Ramanujan J., 60 (2023), 551–570. https://doi.org/10.1007/s11139-022-00633-w doi: 10.1007/s11139-022-00633-w
    [20] H. F. Liu, R. Liu, On the exceptional set for Diophantine inequality with unlike powers of primes, Lith. Math. J., 64 (2024), 34–52. https://doi.org/10.1007/s10986-024-09624-4 doi: 10.1007/s10986-024-09624-4
    [21] W. P. Li, W. X. Ge, Diophantine approximation of prime variables, Acta Math. Sin., 62 (2019), 49–58. https://doi.org/10.12386/A2019sxxb0005 doi: 10.12386/A2019sxxb0005
    [22] G. Harman, Trigonometric sums over primes I, Mathematika, 28 (1981), 249–254. https://doi.org/10.1112/S0025579300010305 doi: 10.1112/S0025579300010305
    [23] A. V. Kumchev, On Weyl sums over primes and almost primes, Mich. Math. J., 54 (2006), 243–268. https://doi.org/10.1307/MMJ/1156345592 doi: 10.1307/MMJ/1156345592
    [24] J. Brüdern, The Davenport-Heilbronn Fourier transform method and some Diophantine inequalities, In: Number Theory and its Applications (Kyoto, 1997), Dordrecht: Kluwer Acad. Publ., 2 (1999), 59–87.
    [25] C. Bauer, An improvement on a theorem of the Goldbach-Waring type, Rocky Mt. J. Math., 31 (2001), 1151–1170. https://doi.org/10.1216/RMJM/1021249436 doi: 10.1216/RMJM/1021249436
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