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On a Diophantine equation with prime variables

  • Received: 04 February 2021 Accepted: 23 June 2021 Published: 25 June 2021
  • MSC : 11J25, 11L03, 11P32

  • Let $ [\alpha] $ denote the integer part of the real number $ \alpha $, $ N $ be a sufficiently large integer and $ (\kappa, \lambda) $ be the exponent pair. In this paper, we prove that for $ 1 < c < \frac{3+3\kappa-\lambda}{3\kappa+2} $, the Diophantine equation $ [p_1^c]+[p_2^c]+[p_3^c] = N $ is solvable in prime variables $ p_1, p_2, p_3 $. If we take $ (\kappa, \lambda) = \left(\frac{81}{242}, \frac{132}{242}\right) $, we can get the range $ 1 < c < \frac{837}{727} $, which improves the previous result of Cai.

    Citation: Jing Huang, Ao Han, Huafeng Liu. On a Diophantine equation with prime variables[J]. AIMS Mathematics, 2021, 6(9): 9602-9618. doi: 10.3934/math.2021559

    Related Papers:

  • Let $ [\alpha] $ denote the integer part of the real number $ \alpha $, $ N $ be a sufficiently large integer and $ (\kappa, \lambda) $ be the exponent pair. In this paper, we prove that for $ 1 < c < \frac{3+3\kappa-\lambda}{3\kappa+2} $, the Diophantine equation $ [p_1^c]+[p_2^c]+[p_3^c] = N $ is solvable in prime variables $ p_1, p_2, p_3 $. If we take $ (\kappa, \lambda) = \left(\frac{81}{242}, \frac{132}{242}\right) $, we can get the range $ 1 < c < \frac{837}{727} $, which improves the previous result of Cai.



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