We consider the class of functions u∈C2((0,∞)) satisfying second-order differential inequalities in the form u″(x)+kx2u(x)≥0 for all x>0. For this class of functions, we establish Hermite-Hadamard-type inequalities in both cases (k=14 and 0<k<14). We next extend our obtained results to the two-dimensional case. In the limit case k→0+ we deriver some existing results from the literature that are related to convex functions and convex functions on the coordinates. In our approach, we make use of some tools from ordinary differential equations.
Citation: Hassen Aydi, Bessem Samet, Manuel De la Sen. On Hermite-Hadamard-type inequalities for second order differential inequalities with inverse-square potential[J]. AIMS Mathematics, 2024, 9(7): 17955-17970. doi: 10.3934/math.2024874
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We consider the class of functions u∈C2((0,∞)) satisfying second-order differential inequalities in the form u″(x)+kx2u(x)≥0 for all x>0. For this class of functions, we establish Hermite-Hadamard-type inequalities in both cases (k=14 and 0<k<14). We next extend our obtained results to the two-dimensional case. In the limit case k→0+ we deriver some existing results from the literature that are related to convex functions and convex functions on the coordinates. In our approach, we make use of some tools from ordinary differential equations.
The double Hermite-Hadamard inequality [13, 14] can be stated as follows: If u:I→R is convex on I then for all a1,a2∈I with a1<a2 we have
u(122∑i=1ai)≤1a2−a1∫a2a1u(x)dx≤122∑i=1u(ai). | (1.1) |
Inequalities of type (1.1) have many applications in theoretical and applied mathematics, such as convex analysis, optimization, numerical integrations, etc. As it is mentioned above, (1.1) holds for convex functions u:I→R. A natural question is to ask whether it is possible to derive inequalities of type (1.1) for other classes of functions. Several results in this direction were obtained for different types of convex functions, such as m-convex functions [7, 10, 25], s-convex functions [11, 12, 17, 22, 27], h-convex functions [5, 23, 24], logarithmically convex functions [19, 20, 26], convex functions with respect to a pair of functions [3, 4, 21, 28] and convex functions on the coordinates [6, 15, 18].
The study of Hermite-Hadamard-type inequalities for second-order differential inequalities was first considered in [1, 2, 8, 9]. Namely, in [8], Dragomir established inequalities of type (1.1) for the class of functions u:I→R satisfying: For all a,b∈I with 0<b−a<πρ
u(x)≤sin[ρ(b−x)]sin[ρ(b−a)]u(a)+sin[ρ(x−a)]sin[ρ(b−a)]u(b),a≤x≤b, |
where ρ>0 is a constant. A function u satisfying the above condition is called trigonometrically ρ-convex. Moreover, in [1]- it was shown that, if u∈C2(I), then u is trigonometrically ρ-convex if and only if u satisfies the second order differential inequality
u″(x)+ρ2u(x)≥0,x∈I. |
Similar results were obtained in [9] for the class of functions u:I→R satisfying: For all a,b∈I with a<b
u(x)≤sinh[ρ(b−x)]sinh[ρ(b−a)]u(a)+sinh[ρ(x−a)]sinh[ρ(b−a)]u(b),a≤t≤b, |
where ρ>0 is a constant. A function u satisfying the above condition is called hyperbolic ρ-convex. On the other hand, it was proved in [2] that, if u∈C2(I), then u is hyperbolic ρ-convex if and only if u satisfies the second order differential inequality
u″(x)−ρ2u(x)≥0,x∈I. |
Motivated by the above cited works, we extend in this paper the (right) Hermite-Hadamard inequality (1.1) to the class of functions u∈C2((0,∞)) satisfying second-order differential inequalities of the form
u″(x)+kx2u(x)≥0,x>0, | (1.2) |
where 0<k≤14 is a constant. Remark that in the limit case, k=0 (1.2) reduces to
u″(x)≥0,x>0, |
which is equivalent to the convexity of u on (0,∞). Remark also that, if u≤0 on (0,∞) and u satisfies (1.2), then u is convex on (0,∞). However, if u satisfies (1.2) then u is not necessarily convex. For instance, the function u(x)=√x+x is concave on (0,∞) and
u″(x)+14x2u(x)=14x>0,x>0. |
The rest of the paper is arranged as follows: In Section 2 we fix some notations and establish some lemmas that will be used later. In Section 3, we establish Hermite-Hadamard-type inequalities for the class of functions u∈C2((0,∞)) satisfying (1.2). We discuss separately the cases of k=14 and 0<k<14. The obtained results in Section 3 are extended to the two-dimensional case in Section 4.
In this section, we establish some lemmas that will be useful in the proofs of our main results. We first fix some notations that will be used throughout this paper.
We denote by M,N:(1,∞)→R the functions defined by
M(s)=1lns(s32−32lns−1),N(s)=1lns(s−32+32lns−1). |
For 0<k≤14 and 0<a<b, we introduce the terms
λk=√1−4k, |
A(a,b)=a32lnb−b32lnalnb−lna,B(a,b)=b32−a32lnb−lna |
Ck(a,b)=1−(ab)λk−321−(ab)λk,Dk(a,b)=1−(ab)λk+321−(ab)λk. |
Lemma 2.1. Let 0<a<b and
F(x)=A(a,b)+B(a,b)lnx−x32,a≤x≤b. | (2.1) |
Then the following holds:
(i) F(a)=F(b)=0;
(ii) F′(a)=√aM(ba), F′(b)=√bM(ba);
(iii) F(x)≥0 for all x∈[a,b].
Proof. (ⅰ) follows immediately from the definition of F. On the other hand, for all x∈[a,b], we have
F′(x)=B(a,b)−32x32x. | (2.2) |
Taking x=a (resp. x=b) in (2.2), we obtain (ⅱ). Furthermore, from (i) and Rolle's theorem, there exists at least c∈(a,b) such that F′(c)=0. However, from (2.2), we have F′(x)=0 if and only if
x=(23B(a,b))23. |
Consequently, c=(23B(a,b))23∈(a,b) and from (2.2) F reaches its maximum value at x=c. Then due to (ⅰ) we deduce that F(x)≥0 for all x∈[a,b], which proves (ⅲ).
Lemma 2.2. Let 0<a<b and
f(x)=49√xF(x),a≤x≤b, | (2.3) |
where F is the function defined by (2.1). Then the following holds:
(i) f(a)=f(b)=0;
(ii) f′(a)=4a9M(ba), f′(b)=−4b9N(ba);
(iii) f(x)≥0 for all x∈[a,b];
(iv) f″(x)+14x2f(x)=−1 for all x∈(a,b).
Proof. (ⅰ)–(ⅲ) are the immediate consequences of Lemma 2.1. (ⅳ) follows from the definition of f and some elementary calculations.
Lemma 2.3. Let 0<k<14, 0<a<b and
G(x)=aλk+32Ck(a,b)+b3−λk2Dk(a,b)xλk−xλk+32,a≤x≤b. | (2.4) |
Then the following holds:
(i) G(a)=G(b)=0;
(ii) G′(a)=λkaλk−1b3−λk2Dk(a,b)−(λk+32)aλk+12;
(iii) G′(b)=bλk+12(λkDk(a,b)−(λk+32));
(iv) G(x)≥0 for all x∈[a,b].
Proof. (ⅰ) follows immediately from the definition of G. On the other hand, for all x∈[a,b], we have
G′(x)=xλk−1(λkDk(a,b)b3−λk2−(λk+32)x3−λk2). | (2.5) |
Taking x=a (resp. x=b) in (2.5) we obtain (ⅱ) and (ⅲ). Furthermore, from (ⅰ) and Rolle's theorem, there exists at least c∈(a,b) such that G′(c)=0. However, from (2.5), G′(x)=0 if and only if
x=(2λkDk(a,b)λk+3)23−λkb. |
Consequently, c=(2λkDk(a,b)λk+3)23−λkb∈(a,b) and from (2.5), G reaches its maximum value at x=c. Then due to (ⅰ) we deduce that G(x)≥0 for all x∈[a,b], which proves (ⅳ).
Lemma 2.4. Let 0<k<14, 0<a<b and
g(x)=1k+2x1−λk2G(x),a≤x≤b, | (2.6) |
where G is the function defined by (2.4). Then the following holds:
(i) g(a)=g(b)=0;
(ii) g′(a)=3+λk2(k+2)a(2λk3+λk(ba)3−λk2Dk(a,b)−1);
(iii) g′(b)=3+λk2(k+2)b(2λk3+λkDk(a,b)−1);
(iv) g(x)≥0 for all x∈[a,b];
(v) g″(x)+kx2g(x)=−1 for all x∈(a,b).
Proof. (ⅰ)–(ⅳ) are the immediate consequences of Lemma 2.3. (ⅴ) follows from the definition of g and some elementary calculations.
Lemma 2.5. We have
M(s)≥0,N(s)≥0 |
for all s>1.
Proof. We have
M(s)=1lnsφ(s),s>1, |
where
φ(s)=s32−32lns−1. |
Remark that lims→1+φ(s)=0. On the other hand, for all s>1 we have
φ′(s)=32√s−32s−1=32s−1(s32−1)≥0, |
which shows that φ is a nondecreasing function. Consequently, we have φ(s)≥0, which implies that M(s)≥0. Similarly, we have
N(s)=1lnsψ(s),s>1, |
where
ψ(s)=s−32+32lns−1. |
Remark that lims→1+ψ(s)=0. We also have
ψ′(s)=−32s−52+32s−1=32s−1(1−s−32)≥0, |
which shows that ψ is a nondecreasing function. Consequently, we have ψ(s)≥0, which implies that N(s)≥0.
Lemma 2.6. Let 0<k<14 and 0<a<b. Then the following holds:
(ba)3−λk22λkλk+3Dk(a,b)−1≥0 | (2.7) |
and
1−2λkλk+3Dk(a,b)≥0. | (2.8) |
Proof. We have
(ba)3−λk22λkλk+3Dk(a,b)−1=[1−(ab)λk]−1γ(ba), | (2.9) |
where
γ(s)=2λkλk+3s3−λk2+3−λk3+λks−λk−1,s≥1. |
Observe that γ(1)=0. On the other hand, for all s≥1, we have
γ′(s)=λk(3−λk)λk+3s−λk−1(sλk+32−1)≥0, |
which shows that γ is a nondecreasing function. Consequently, we have γ(s)≥0 for all s≥1, which implies that γ(ba)≥0. Then by (2.9), we obtain (2.7). On the other hand, we have
1−2λkλk+3Dk(a,b)=[1−(ab)λk]−1η(ab), | (2.10) |
where
η(s)=3−λkλk+3+2λkλk+3s3+λk2−sλk,0<s≤1. |
Remark that η(1)=0, and for all 0<s≤1, we have
η′(s)=λks1+λk2(1−sλk−32)≤0, |
which shows that γ is a decreasing function. Consequently, we have η(ab)≥η(1)=0. Then by (2.10) we obtain (2.8).
For 0<k≤14, we consider the class of real-valued functions
C2,+k((0,∞))={u∈C2((0,∞)):u″(x)+kx2u(x)≥0 for all x>0}. |
Remark that, in the limit case k=0, we have
C2,+0((0,∞))={u∈C2((0,∞)):u is convex on (0,∞)}. |
In this section we establish Hermite-Hadamard-type inequalities for functions u∈C2,+k((0,∞)).
We first consider the case k=14.
Theorem 3.1. If u∈C2,+1/4((0,∞)), then for all a,b∈R with 0<a<b, we have
∫bau(x)dx≤49(aM(ba)u(a)+bN(ba)u(b)). | (3.1) |
Proof. Let u∈C2,+1/4((0,∞)) and 0<a<b. By Lemma 2.2-(ⅳ), we have
∫bau(x)dx=−∫bau(x)(f″(x)+14x2f(x))dx, | (3.2) |
where f is the function defined by (2.1). Integrations by parts give us that
−∫bau(x)(f″(x)+14x2f(x))dx=−[f′(x)u(x)]bx=a+∫bau′(x)f′(x)dx−∫baf(x)14x2u(x)dx=−f′(b)u(b)+f′(a)u(a)+[f(x)u′(x)]bx=a−∫baf(x)u″(x)dx−∫baf(x)14x2u(x)dx=f′(a)u(a)−f′(b)u(b)+(f(b)u′(b)−f(a)u′(a))−∫baf(x)(u″(x)+14x2u(x))dx. |
On the other hand, from Lemma 2.2-(ⅰ) we know that f(a)=f(b)=0. Consequently, we have
−∫bau(x)(f″(x)+14x2f(x))dx=f′(a)u(a)−f′(b)u(b)−∫baf(x)(u″(x)+14x2u(x))dx. | (3.3) |
From (3.2) and (3.3), we deduce that
∫bau(x)dx=f′(a)u(a)−f′(b)u(b)−∫baf(x)(u″(x)+14x2u(x))dx. |
Since f≥0 by Lemma 2.2-(ⅲ) and u∈C2,+1/4((0,∞)), then
∫baf(x)(u″(x)+14x2u(x))dx≥0. |
Hence, it holds that
∫bau(x)dx≤f′(a)u(a)−f′(b)u(b). |
Finally, using Lemma 2.2-(ⅱ), we obtain (3.1).
We now consider case 0<k<14.
Theorem 3.2. Let 0<k<14. If u∈C2,+k((0,∞)), then for all a,b∈R with 0<a<b, we have
∫bau(x)dx≤λk+32(k+2)[a((ba)3−λk22λkλk+3Dk(a,b)−1)u(a)+b(1−2λkλk+3Dk(a,b))u(b)]. | (3.4) |
Proof. Let u∈C2,+k((0,∞)) and 0<a<b. We shall follow the same approach used in the proof of Theorem 3.1. Namely, by Lemma 2.4-(v), we have
∫bau(x)dx=−∫bau(x)(g″(x)+kx2g(x))dx, | (3.5) |
where g is the function defined by (2.6). Integrating by parts, we get
−∫bau(x)(g″(x)+kx2g(x))dx=g′(a)u(a)−g′(b)u(b)+g(b)u′(b)−g(a)u′(a)−∫bag(x)(u″(x)+kx2u(x))dx, |
which implies by Lemma 2.4-(ⅰ) that
−∫bau(x)(g″(x)+kx2g(x))dx=g′(a)u(a)−g′(b)u(b)−∫bag(x)(u″(x)+kx2u(x))dx. | (3.6) |
In view of (3.5) and (3.6), we have
∫bau(x)dx=g′(a)u(a)−g′(b)u(b)−∫bag(x)(u″(x)+kx2u(x))dx. |
Since g≥0 by Lemma 2.4-(ⅳ) and u∈C2,+k((0,∞)), then
∫bag(x)(u″(x)+kx2u(x))dx≥0. |
Consequently, we get
∫bau(x)dx≤g′(a)u(a)−g′(b)u(b). |
Finally, using Lemma 2.4-(ⅱ)-(ⅲ), we obtain (3.4).
Remark 3.1. Remark that in the limit case k=0, (3.4) reduces to the right Hermite-Hadamard inequality for convex functions
1b−a∫bau(x)dx≤u(a)+u(b)2. |
We now consider the class of real-valued functions
C2,+k((0,∞)2)={u∈C2((0,∞)2):∂2u∂x2(x,y)+kx2u(x,y)≥0,∂2u∂y2(x,y)+ky2u(x,y)≥0,x,y>0}, |
where 0<k≤14 and (0,∞)2=(0,∞)×(0,∞). Notice that in the limit case k=0, C2,+0((0,∞)2) is the class of functions u∈C2((0,∞)2) such that u is convex on the coordinates in (0,∞)2 (see Dragomir [6]). In this section, we extend some of the obtained results in [6] to the class of functions C2,+k((0,∞)2).
We first consider the case k=14.
Theorem 4.1. If u∈C2,+1/4((0,∞)2), then for all a,b,c,d∈R with 0<a<b and 0<c<d we have
∫ba∫dcu(x,y)dxdy≤29∫ba(cM(dc)u(x,c)+dN(dc)u(x,d))dx+29∫dc(aM(ba)u(a,y)+bN(ba)u(b,y))dy≤16ac81M(dc)M(ba)u(a,c)+16bc81M(dc)N(ba)u(b,c)+16ad81M(ba)N(dc)u(a,d)+16bd81N(ba)N(dc)u(b,d). | (4.1) |
Proof. Let u∈C2,+1/4((0,∞)2) and a,b,c,d∈R with 0<a<b and 0<c<d. By the definition of C2,+1/4((0,∞)2), the function u(x,⋅):y↦u(x,⋅)(y)=u(x,y) belongs to C2,+1/4((0,∞)) for all x>0. Then by Theorem 3.1 we have
∫dcu(x,y)dy≤49(cM(dc)u(x,c)+dN(dc)u(x,d)). |
for all x>0. Integrating the above-mentioned inequality over (a,b) we get
∫ba∫dcu(x,y)dxdy≤49(cM(dc)∫bau(x,c)dx+dN(dc)∫bau(x,d)dx). | (4.2) |
Similarly, by the definition of C2,+1/4((0,∞)2), the function u(⋅,y):x↦u(⋅,y)(x)=u(x,y) belongs to C2,+1/4((0,∞)) for all y>0. Then by Theorem 3.1 we have
∫bau(x,y)dx≤49(aM(ba)u(a,y)+bN(ba)u(b,y)). |
for all y>0. Integrating the above inequality over (c,d), we obtain
∫ba∫dcu(x,y)dxdy≤49(aM(ba)∫dcu(a,y)dy+bN(ba)∫dcu(b,y)dy). | (4.3) |
Summing (4.2) and (4.3), we obtain
∫ba∫dcu(x,y)dxdy≤29∫ba(cM(dc)u(x,c)+dN(dc)u(x,d))dx+29∫dc(aM(ba)u(a,y)+bN(ba)u(b,y))dy, |
which proves the first inequality in (4.1). On the other hand, since the function u(⋅,c):x↦u(⋅,c)(x)=u(x,c) belongs to C2,+1/4((0,∞)), then by Theorem 3.1 we have
∫bau(x,c)dx≤49(aM(ba)u(a,c)+bN(ba)u(b,c)). |
Multiplying the above inequality by cM(dc) and using Lemma 2.5, we obtain
cM(dc)∫bau(x,c)dx≤49cM(dc)(aM(ba)u(a,c)+bN(ba)u(b,c)). | (4.4) |
Similarly, we have
∫bau(x,d)dx≤49(aM(ba)u(a,d)+bN(ba)u(b,d)), |
which implies after multiplication by dN(dc) (notice that by Lemma 2.5 we have N(s)≥0 for all s>1) that
dN(dc)∫bau(x,d)dx≤49dN(dc)(aM(ba)u(a,d)+bN(ba)u(b,d)). | (4.5) |
In the same manner, we obtain
aM(ba)∫dcu(a,y)dy≤49aM(ba)(cM(dc)u(a,c)+dN(dc)u(a,d)) | (4.6) |
and
bN(ba)∫dcu(b,y)dy≤49bN(ba)(cM(dc)u(b,c)+dN(dc)u(b,d)). | (4.7) |
Finally, the second inequality in (4.1) follows from (4.4)–(4.7).
We next consider case 0<k<14.
Theorem 4.2. Let 0<k<14. If u∈C2,+k((0,∞)2), then for all a,b,c,d∈R with 0<a<b and 0<c<d we have
4(k+2)λk+3∫ba∫dcu(x,y)dxdy≤c((dc)3−λk22λkλk+3Dk(c,d)−1)∫bau(x,c)dx+d(1−2λkλk+3Dk(c,d))∫bau(x,d)dx+a((ba)3−λk22λkλk+3Dk(a,b)−1)∫dcu(a,y)dy+b(1−2λkλk+3Dk(a,b))∫dcu(b,y)dy≤[(λk+3)ack+2((dc)3−λk22λkλk+3Dk(c,d)−1)((ba)3−λk22λkλk+3Dk(a,b)−1)]u(a,c)+[(λk+3)bck+2((dc)3−λk22λkλk+3Dk(c,d)−1)(1−2λkλk+3Dk(a,b))]u(b,c)+[(λk+3)adk+2(1−2λkλk+3Dk(c,d))((ba)3−λk22λkλk+3Dk(a,b)−1)]u(a,d)+[(λk+3)bdk+2(1−2λkλk+3Dk(c,d))(1−2λkλk+3Dk(a,b))]u(b,d). | (4.8) |
Proof. Let u∈C2,+k((0,∞)2) and a,b,c,d∈R with 0<a<b and 0<c<d. By Theorem 3.2, we have
∫dcu(x,y)dy≤λk+32(k+2)[c((dc)3−λk22λkλk+3Dk(c,d)−1)u(x,c)+d(1−2λkλk+3Dk(c,d))u(x,d)] |
for all x>0. Integrating the above inequality over (a,b), we obtain
2(k+2)λk+3∫ba∫dcu(x,y)dxdy≤c((dc)3−λk22λkλk+3Dk(c,d)−1)∫bau(x,c)dx+d(1−2λkλk+3Dk(c,d))∫bau(x,d)dx. | (4.9) |
Similarly, by Theorem 3.1, we have
∫bau(x,y)dx≤λk+32(k+2)[a((ba)3−λk22λkλk+3Dk(a,b)−1)u(a,y)+b(1−2λkλk+3Dk(a,b))u(b,y)] |
for all y>0. Integrating the above inequality over (c,d), we obtain
2(k+2)λk+3∫ba∫dcu(x,y)dxdy≤a((ba)3−λk22λkλk+3Dk(a,b)−1)∫dcu(a,y)dy+b(1−2λkλk+3Dk(a,b))∫dcu(b,y)dy. | (4.10) |
Summing (4.9) and (4.10), we obtain
4(k+2)λk+3∫ba∫dcu(x,y)dxdy≤c((dc)3−λk22λkλk+3Dk(c,d)−1)∫bau(x,c)dx+d(1−2λkλk+3Dk(c,d))∫bau(x,d)dx+a((ba)3−λk22λkλk+3Dk(a,b)−1)∫dcu(a,y)dy+b(1−2λkλk+3Dk(a,b))∫dcu(b,y)dy, |
which proves the first inequality in (4.8). We now use Theorem 3.2 to get
∫bau(x,c)dx≤λk+32(k+2)[a((ba)3−λk22λkλk+3Dk(a,b)−1)u(a,c)+b(1−2λkλk+3Dk(a,b))u(b,c)]. |
Multiplying the above inequality by c((dc)3−λk22λkλk+3Dk(c,d)−1), it follows from Lemma 2.6 (see (2.7)) that
c((dc)3−λk22λkλk+3Dk(c,d)−1)∫bau(x,c)dx≤λk+32(k+2)c((dc)3−λk22λkλk+3Dk(c,d)−1)⋅[a((ba)3−λk22λkλk+3Dk(a,b)−1)u(a,c)+b(1−2λkλk+3Dk(a,b))u(b,c)]. | (4.11) |
Using Theorem 3.2, we obtain
∫bau(x,d)dx≤λk+32(k+2)[a((ba)3−λk22λkλk+3Dk(a,b)−1)u(a,d)+b(1−2λkλk+3Dk(a,b))u(b,d)]. |
Multiplying the above inequality by d(1−2λkλk+3Dk(c,d)), it follows from Lemma 2.6 (see (2.8)) that
d(1−2λkλk+3Dk(c,d))∫bau(x,d)dx≤λk+32(k+2)d(1−2λkλk+3Dk(c,d))⋅[a((ba)3−λk22λkλk+3Dk(a,b)−1)u(a,d)+b(1−2λkλk+3Dk(a,b))u(b,d)]. | (4.12) |
Similarly, we have
a((ba)3−λk22λkλk+3Dk(a,b)−1)∫dcu(a,y)dy≤λk+32(k+2)a((ba)3−λk22λkλk+3Dk(a,b)−1)⋅[c((dc)3−λk22λkλk+3Dk(c,d)−1)u(a,c)+d(1−2λkλk+3Dk(c,d))u(a,d)] | (4.13) |
and
b(1−2λkλk+3Dk(a,b))∫dcu(b,y)dy≤λk+32(k+2)b(1−2λkλk+3Dk(a,b))⋅[c((dc)3−λk22λkλk+3Dk(c,d)−1)u(b,c)+d(1−2λkλk+3Dk(c,d))u(b,d)]. | (4.14) |
Finally the second inequality in (4.8) follows from (4.11)–(4.14).
Remark 4.1 In the limit case k=0, we have
λ0=1,D0(a,b)=1+ab,D0(c,d)=1+cd. |
In this case, (4.8) reduces to
1(d−c)(b−a)∫ba∫dcu(x,y)dxdy≤14(b−a)(∫bau(x,c)dx+∫bau(x,d)dx)+14(d−c)(∫dcu(a,y)dy+∫dcu(b,y)dy)≤u(a,c)+u(b,c)+u(a,d)+u(b,d)4. |
The above inequalities were derived previously by Dragomir [6] when u is convex on the coordinates.
Hermite-Hadamard-type inequalities are very useful in many branches of pure and applied mathematics. Such inequalities were established by many authors for different kinds of convex functions. The class of functions u∈C2((0,∞)) satisfying second-order differential inequalities of the form
u″(x)+kx2u(x)≥0,x>0 |
is investigated in this paper. Namely, Hermite-Hadamard-type inequalities are established for this class of functions in both cases k=14 (see Theorem 3.1) and 0<k<14 (see Theorem 3.2). Next, the obtained results are extended to the two-dimensional case by considering the class of functions u=u(x,y)∈C2((0,∞)2) satisfying the system of second order differential inequalities
{∂2u∂x2(x,y)+kx2u(x,y)≥0,x,y>0,∂2u∂y2(x,y)+ky2u(x,y)≥0,x,y>0. |
Hermite-Hadamard-type inequalities are derived for this class of functions in the case k=14 (see Theorem 4.1) and the case 0<k<14 (see Theorem 4.2).
An interesting question consists of studying the class of functions u∈C2(Ω) satisfying second-order differential inequalities of the form
Δu+k|x|2u(x)≥0,x∈Ω, |
where Ω⊂Rn∖{0} and Δ is the Laplacian operator (Δ=∂2∂x21+⋯+∂2∂x2n). Notice that in the limit case k=0, the above class of functions reduces to the class of subharmonic functions (see, e.g., [16]).
Hassen Aydi: Conceptualization, methodology, investigation, formal analysis, writing review and editing; Bessem Samet: Conceptualization, methodology, validation, investigation, writing original draft preparation; Manuel De La Sen: methodology, validation, formal analysis, investigation, writing review and editing. All authors have read and approved the final version of the manuscript for publication.
The authors declare they have not used Artificial Intelligence (AI) tools in the creation of this article.
B. Samet is supported by Researchers Supporting Project number (RSP2024R4), King Saud University, Riyadh, Saudi Arabia. M. De La Sen is supported by the project: Basque Government IT1555-22.
The authors declare no conflict of interest.
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