Research article

Some fixed point results for nonlinear contractive conditions in ordered proximity spaces with an application

  • Received: 13 February 2023 Revised: 02 April 2023 Accepted: 12 April 2023 Published: 19 April 2023
  • MSC : 47H10, 54H25

  • In this article, we use the concept of proximity spaces to prove common fixed point results for mappings satisfying generalized (ψ, β)-Geraghty contraction type mapping in partially ordered proximity spaces. Finally, we investigate an application to endorse our results.

    Citation: Demet Binbaşıoǧlu. Some fixed pointresults for nonlinear contractive conditions in ordered proximity spaceswith an application[J]. AIMS Mathematics, 2023, 8(6): 14541-14557. doi: 10.3934/math.2023743

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  • In this article, we use the concept of proximity spaces to prove common fixed point results for mappings satisfying generalized (ψ, β)-Geraghty contraction type mapping in partially ordered proximity spaces. Finally, we investigate an application to endorse our results.



    Frigyes Riesz [1] first discovered the fundamental ideas of proximity spaces in 1908. Later, in 1934, Efremovich [2] resurrected and axiomatized this theory, which was later printed in 1951. Numerous studies on proximity spaces have been conducted over the years [3,4,5,6]. Smirnov [5] explained the relationship between proximities and uniformities, as well as the relationship between the proximity relation and topological spaces.

    Inspired by [7], Kostic [8] introduced fixed point theory and defined the concepts of w-distance and w0-distance in proximity space. For more details on w-distance, see [9]. Naimpally et al. and Sharma [10,11] have also done studies on proximity spaces and their examples. Qasim et al. [12] give the theorems of Matkowski and Boyd-Wong in proximity spaces.

    Geraghty [13] established a class of functions in 1973, which he designated as the set of functions. Khan et al. [14] introduced the idea of an altering distance function. Alsamir et al. [15] gave some common fixed point teorems in partially ordered metric-like spaces.

    Moreover an important development is reported in fixed point theory via some applications. Hammad et al. [16,17,18] utilized some fixed point techniques to solve differential and integral equations.

    In this study, we give some common fixed point results via generalized (ψ, β)-Geraghty contraction mappings in proximity spaces and an application of the existence of a unique solution of an integral equation.

    In this section, we will include the basic definitions and theorems that will be necessary in the following parts of our work.

    Definition 2.1. [5] Suppose Ω is a set and δ is a relation on the set 2Ω. If the following hold, the pair (Ω,δ) is considered to be in a proximity space: for any A,B,C2Ω, where 2Ω is the power set of Ω.

    (p1) AδBBδA,

    (p2) AδBA,B,

    (p3) Aδ(BC)AδB or AδC,

    (p4) ABAδB,

    (p5) For all γΩ, Aδγ or Bδ(Ωγ) implies AδB.

    We shall write all ξΩ and AΩ as ξδA and Aδξ rather than {ξ}δA and Aδ{ξ}, respectively. If ξδμ means that ξ=μ for every ξ,μΩ, then the proximity space (Ω,δ) is said to be separated. Generalizations of uniform features are used to describe the characteristics of proximity spaces, metric and topological continuity qualities, respectively.

    Any proximity relation on a non-empty set Ω induces a topology τδ through the Kuratowski closure operator. When applied to all AΩ, the Kuratowski closure operator can be described as cl(A)={ξΩ:ξδA}. The topology τδ in this situation is always completely regular and if (Ω,δ) is separated, it is Tychonoff.

    If (Ω,τ) is a topological space and δ is a proximity on Ω such that τδ=τ, it is said that τ and δ are compatible. Every completely regular topology on a nonempty set Ω, has a compatible proximity. Also, we obtain ξδ{ξn} if a sequence {ξn} converges to a point ξΩ with regard to the induced topology τδ. Additionally, each uniform space (Ω,U) is associated with a proximity structure that is described by for all A,BΩ, AδB if (A×B)C for all CU. See [10,11] for more information.

    Example 2.1. [12] Give us a metric space (Ω,p). Take into account the relation δ on 2Ω,

    AδBp(A,B)=0 and p(A,B)=inf{p(u,v):uA,vB}.

    δ is thus a proximity on Ω. Additionally, the metric topologies τp and δ are compatible.

    In order to get the proximity space version of the Banach fixed-point theorem, Kostic [8] defined the concepts of w-distance and w0 -distance, which were inspired by [7].

    Definition 2.2. [8] Let w:Ω×Ω[0,) be a function and (Ω,δ) be a proximity space. Then w is a w -distance on Ω, if the axiom below is true:

    (w1) if w(η,A)=0 and w(η,B)=0 imply AδB for all ηΩ and A,BΩ, when w(η,A)=inf{w(η,ξ):ξA}.

    Definition 2.3. [8] A w-distance on a proximity space (Ω,δ) is also referred to as a w0-distance if the axioms below are true:

    (w2) For any ξ,μ,ηΩ, w(ξ,μ)w(ξ,η)+w(η,μ),

    (w3) Since w is lower semicontinuous in both variables with regard to τδ, we get

    w(ξ,μ)liminfξξw(ξ,μ)=supBUξinfξBw(ξ,μ),andw(μ,ξ)liminfξξw(μ,ξ)=supBUξinfξBw(μ,ξ),

    where Uξ is a base of neighborhoods of the point ξΩ.

    Remark 2.1. [12] It is evident that for every sequence {ξn} convergent to ξ with respect to τδ, w(ξ,μ) liminfnw(ξn,μ) and w(μ,ξ) liminfnw(μ,ξn) exist. This is true if w is lower semicontinuous in both variables with respect to τδ.

    Example 2.2. [12] Let Ω=R possess the usual metric as well as the proximity δ specified in Example 1. Definition of w1, w2:Ω×Ω[0,) by

    w1(ξ,μ)=max{|ξ|,|μ|} and w2(ξ,μ)=|ξ|+|μ|2,

    both w1 and w2 are w0-distance on Ω.

    Lemma 2.1. [7,8] Let (Ω,δ) be a space of proximity with w-distance w. The following properties are then true:

    (i) If (Ω,δ) is separated, then w(η,ξ)=0 and w(η,μ)=0 imply ξ=μ,

    (ii) If w(η,ξ)=0 and w(η,ξn)0 as n, then {ξn} subsequently converges to ξ with respect to τδ.

    Definition 2.4. [15] Let (Ω,) be a partially ordered set and g,h:ΩΩ be two mappings. Then

    (i) The elements ξ,μΩ are called comparable if ξμ or μξ holds,

    (ii) g is called nondecreasing i.e., if ξμ implies gξgμ,

    (iii) The pair (g,h) is weakly increasing if gξhgξ and hξghξ for all ξΩ,

    (iv) The mapping g is weakly increasing if the pair (g,I) is weakly increasing, where I is denoted to the identity mapping on Ω.

    Definition 2.5. [15] Let (Ω,) be a partially ordered set. Ω is called regular, if whenever {ηn} is a nondecreasing sequence in Ω w.r.t. such that ηnη, then ηnη for nN.

    Definition 2.6. [13] If {xn} is a sequence in [0,) with α(xn)1, then xn0. The set of functions α:[0,)[0,1) which holds the condition is denoted with a class of functions Π.

    Definition 2.7. [14] If the circumstances below are true;

    (i) ψ is continuous and non-decreasing,

    (ii) ψ(x)=0x=0,

    afterward, the function ψ:[0,)[0,) is referred to as an altering distance function.

    The following lemma is introduced at the beginning of this section and will be used to prove our main results.

    Lemma 3.1. Let (Ω,δ) be a separated proximity space with w0distance w and {ηn} be a sequence in Ω such that limn+w(ηn,ηn+1)=0. If limn,m+w(ηn,ηm)0, then there exist ε>0 and two sequences {nk} and {mk} of positive integers with nk>mk>k such that following three sequences {w(ξ2nk,ξ2mk)}, {w(ξ2nk1,ξ2mk)}, {w(ξ2nk,ξ2mk+1)} converge to r+ when k.

    Proof. Let {ηn}Ω be a sequence such that

    limn+w(ηn,ηn+1)=0andlimn,m+w(ηn,ηm)0.

    Then there exist r>0 and two sequences {nk}, {mk} of positive integers such that the lowest positive integer, nk, for which nk>mk>k, w(η2nk,η2mk)r. This means that w(η2nk2,η2mk)<r. The triangular inequality implies that

    rw(η2nk,η2mk)w(η2nk,η2nk1)+w(η2nk1,η2nk2)+w(η2nk2,η2mk)<w(η2nk,η2nk1)+w(η2nk1,η2nk2)+r.

    Letting k in the above inequalities, implies that

    limn+w(ξ2nk,ξ2mk)=r+.

    Once more, we may determine that

    |w(ξ2nk,ξ2mk+1)w(ξ2nk,ξ2mk)|w(ξ2mk,ξ2mk+1)

    from the triangular inequality. In the inequality above, if we let k go, we get

    limk+w(ξ2nk,ξ2mk+1)=r+.

    Similarly, one can easily show that

    limk+w(ξ2nk1,ξ2mk)=r+.

    Definition 3.1. Let (Ω,) be a partially ordered set, (Ω,δ) be a separated proximity space with w0distance w and g,h:ΩΩ be two mappings. If αΠ, ψΨ and a continuous function β:[0,)[0,) exists with β(t) ψ(t) for all t>0 such that

    ψ(w(gξ,hμ))α(Kξ,μ)β(Kξ,μ), (3.1)

    holds for all comparable elements ξ,μΩ, where

    Kξ,μ=max{w(ξ,μ),w(gξ,ξ),w(μ,hμ)},

    we may then state that the pair (g,h) is of the generalized (ψ, β)-Geraghty contraction type.

    Theorem 3.2. Let (Ω,) be a partially ordered set, (Ω,δ) be a separated proximity space with w0distance w and g,h:ΩΩ be two mappings that meet the requirements listed below:

    (i) The pair (g,h) is weakly increasing,

    (ii) The pair (g,h) is generalized (ψ, β)-Geraghty contraction type,

    (iii) Either g or h is continuous,

    (iv) For all ηΩ, any iterative sequences {gnη} and {hnη} have convergent subsequences with respect to τδ.

    Then g and h have a common fixed point ν Ω with w(ν,ν)=0. Furthermore, assume that if η, uΩ such w(η,η)=w(u,u)=0 implies that η and u are comparable then the common fixed point of g and h is unique.

    Proof. Let ξ0Ω, ξ1=gξ0 and ξ2=hξ1. By continuing in this manner, we create a sequence {ξn}Ω defined by ξ2n+1=gξ2n and ξ2n+2=hξ2n+1. Since the pair (g,h) is weakly increasing

    ξ1=gξ0hgξ0=ξ2=gξ1...hgξ2n=ξ2n+2....

    Thus ξnξn+1 for all nN. If there exists some lN such that w(ξ2nl,ξ2nl+1)=0. Hence ξ2l=ξ2l+1 and gξ2l=ξ2l. To show that hξ2l=ξ2l it is enough to show that ξ2l=ξ2l+1=ξ2l+2. Assume

    w(ξ2l+1,ξ2l+2)0 and w(ξ2l+2,ξ2l+1)0.

    Since ξ2lξ2l+1, then by (3.1) we have

    ψ(w(ξ2l+1,ξ2l+2))=ψ(w(gξ2l,hξ2l+1))α(Kξ2l,ξ2l+1)β(Kξ2l,ξ2l+1)=α(max{w(ξ2l,ξ2l+1),w(ξ2l,gξ2l),w(ξ2l+1,hξ2l+1)})β(max{w(ξ2l,ξ2l+1),w(ξ2l,gξ2l),w(ξ2l+1,hξ2l+1)}}=α(max{w(ξ2l,ξ2l+1),w(ξ2l,ξ2l+1),w(ξ2l+1,ξ2l+2)}) β(max{w(ξ2l,ξ2l+1),w(ξ2l,ξ2l+1),w(ξ2l+1,ξ2l+2)})=α(w(ξ2l+1,ξ2l+2))β(w(ξ2l+1,ξ2l+2))<β(w(ξ2l+1,ξ2l+2))ψ(w(ξ2l+1,ξ2l+2)),

    which is a contradiction. So w(ξ2l+1,ξ2l+2)=0 and similarly w(ξ2l+2,ξ2l+1)=0. That is ξ2l=ξ2l+1=ξ2l+2. Thus ξ2l is a common fixed point for g and h. We now presume that

    w(ξn,ξn+1)0 and w(ξn+1,ξn)0

    for all nN. When n is even, n=2t follows some tN

    ψ(w(ξn,ξn+1))=ψ(w(ξ2t,ξ2t+1)) =ψ(w(gξ2t,hξ2t1))α(max{w(ξ2t1,ξ2t),w(ξ2t1,hξ2t1),w(ξ2t,gξ2t)})β(max{w(ξ2t1,ξ2t),w(ξ2t1,hξ2t1),w(ξ2t,gξ2t)})=α(max{w(ξ2t1,ξ2t),w(ξ2t,ξ2t+1)})β(max{w(ξ2t1,ξ2t),w(ξ2t,ξ2t+1)})<β(max{w(ξ2t1,ξ2t),w(ξ2t,ξ2t+1)}). (3.2)

    Assume

    max{w(ξ2t1,ξ2t),w(ξ2t,ξ2t+1)}=w(ξ2t,ξ2t+1).

    By (3.2), we get

    ψ(w(ξ2t,ξ2t+1))<ψ(w(ξ2t,ξ2t+1)),

    which is a contradiction. Thus,

    max{w(ξ2t1,ξ2t),w(ξ2t,ξ2t+1)}=w(ξ2t1,ξ2t).

    Therefore

    ψ(w(ξ2n,ξ2n+1))<ψ(w(ξ2n1,ξ2n)). (3.3)

    Because ψ is an altering distance function, we draw the conclusion that

    w(ξ2n,ξ2n+1)<w(ξ2n1,ξ2n)

    is true for every nN. n=2t+1 for some tN if n is odd. By (3.1) we have

    ψ(w(ξn,ξn+1))=ψ(w(ξ2t+1,ξ2t+2))=ψ(w(gξ2t,hξ2t+1))α(max{w(ξ2t,ξ2t+1),w(ξ2t,gξ2t),w(ξ2t+1,hξ2t+1)})β(max{w(ξ2t,ξ2t+1),w(ξ2t,gξ2t),w(ξ2t+1,hξ2t+1)})=α(max{w(ξ2t,ξ2t+1),w(ξ2t+1,ξ2t+2)}) β(max{w(ξ2t,ξ2t+1),w(ξ2t+1,ξ2t+2)})<β(max{w(ξ2t,ξ2t+1),w(ξ2t+1,ξ2t+2)}). (3.4)

    Assume that

    max{w(ξ2t,ξ2t+1),w(ξ2t+1,ξ2t+2)}=w(ξ2t+1,ξ2t+2).

    By (3.4) we get

    ψ(w(ξ2t+1,ξ2t+2))<ψ(w(ξ2t+1,ξ2t+2)),

    which is a contradiction. Then,

    max{w(ξ2t,ξ2t+1),w(ξ2t+1,ξ2t+2)}=w(ξ2t,ξ2t+1).

    Thus,

    ψ(w(ξn,ξn+1))<ψ(w(ξn1,ξn)).

    We conclude that

    w(ξ2n+1,ξ2n+2)w(ξ2n,ξ2n+1) (3.5)

    holds for all nN since ψ is an altering distance function. The result of combining (3.3) and (3.5) is that

    w(ξn,ξn+1)w(ξn1,ξn)

    holds for all nN. The sequence {w(ξn,ξn+1)} is hence a decreasing sequence. Therefore, ν0 exists such that limnw(ξn,ξn+1)=ν and the sequence {w(ξn,ξn+1)} is a decreasing sequence.

    We now have proof that ν=0. Consider the contrary, which is ν>0. We get

    ψ(w(ξn,ξn+1))α(w(ξn1,ξn))β(w(ξn1,ξn))

    from (3.2) and (3.4). The inequality above indicates that ψ(ν)<β(ν)ψ(ν) if the limsup is taken. This is a contradiction. Therefore, ν=0. This implies that

    w(ξn,ξn+1)0 as n.

    In a similar way, we can get

    w(ξn+1,ξn)0 as n.

    We can now prove that

    limn,mw(ξn,ξm)=0 and limn,mw(ξm,ξn)=0.

    Assume that

    limn,mw(ξn,ξm)0.

    Using Lemma 3.1, there exist r>0, two sequences {ξnk} and {ξmk} of {ξn} with 2nk>2mkk such that the three sequences {w(ξ2nk,ξ2mk)}, {w(ξ2nk1,ξ2mk)}, {w(ξ2nk,ξ2mk+1)} converge to r+ when k. From (3.1) we have

    ψ(w(ξ2nk,ξ2mk+1))=ψ(w(gξ2mk,hξ2nk1))α(Kξ2mk,ξ2nk1)β(Kξ2mk,ξ2nk1), (3.6)

    where

    Kξ2mk,ξ2nk1=max{w(ξ2nk1,ξ2mk),w(ξ2nk1,hξ2nk1),w(ξ2mk,gξ2mk)}=max{w(ξ2nk1,ξ2mk),w(ξ2nk1,ξ2nk),w(ξ2mk,ξ2mk+1)}.

    Letting k in (3.6) and using the properties of ψ, α and β, we deduce that

    ψ(r)α(r)β(r)<β(r)ψ(r),

    a contradiction. Therefore

    limn,mw(ξn,ξm)=0.

    We can get limn,mw(ξm,ξn)=0 in a similar way. According to (iv), if the sequence {ξn} has a subsequence {ξnl} that is convergent with regard to τδ to some ηΩ, then we get

    w(η,ξnl)limkinfw(ξnk,ξnl)=0 (3.7)

    and symmetrically, we obtain

    w(ξnl,η)limkinfw(ξnl,ξnk)=0.

    Since g or h is continuous, we get

    limnw(ξn+1,hη)=limnw(gξn,hη)=w(gη,hη), (3.8)
    limnw(gη,ξn+1)=limnw(gη,hξn)=w(gη,hη). (3.9)

    Thus,

    limnw(ξn+1,hη)=w(η,hη), (3.10)
    limnw(gη,ξn+1)=w(gη,η). (3.11)

    Combining (3.8) and (3.10), we conclude that w(η,hη)=w(gη,hη). Also, by (3.9) and (3.10) we deduce that w(gη,η)=w(gη,hη). So,

    w(η,hη)=w(gη,η)=w(gη,hη). (3.12)

    We now demonstrate how w(gη,η)=0 and w(η,hη)=0. Suppose that, on the contrary, is w(η,hη)>0 and w(gη,η)>0. Thus, we get

    ψ(w(η,hη))=ψ(w(gη,hη))α(Kη,η)β(Kη,η)<β(Kη,η)ψ(Kη,η), (3.13)

    and

    ψ(w(gη,η))=ψ(w(gη,hη))α(Kη,η)β(Kη,η)<β(Kη,η)ψ(Kη,η), (3.14)

    where

    Kη,η=max{w(η,η),w(gη,η),w(η,hη)}=max{w(gη,η),w(η,hη)},

    which is a contradiction. Thus we obtain w(gη,η)=0 and w(η,hη)=0. Hence gη=η, η=hη. So, η is a common fixed point of g, h.

    We assume that u is yet another fixed point of g and h in order to demonstrate the uniqueness of the common fixed point.

    We now show that w(u,u)=0. On the contrary, suppose that is w(u,u)>0.

    ψ(w(u,u))=ψ(w(gu,hu))α(w(u,u))β(w(u,u))<β(w(u,u))ψ(w(u,u))

    is a contradiction because of uu. Hence w(u,u)=0.

    So get the conclusion that η and u are comparable on the additional requirements on Ω.

    We suppose that w(η,u)0.

    ψ(w(η,u))=ψ(w(gη,hu))α(w(η,u))β(w(η,u))<β(w(η,u))ψ(w(η,u)),

    and

    ψ(w(u,η))=ψ(w(gu,hη))α(w(u,η))β(w(u,η))<β(w(u,η)) ψ(w(u,η)),

    this is a contradiction. Thus w(η,u)=0 and w(u,η)=0. Hence u=η. Thus g and h have a unique common fixed point.

    Theorem 3.3. Let (Ω,) be a partially ordered set, (Ω,δ) be a separated proximity space with w0distance w and g,h:ΩΩ be two mappings that meet the requirements listed below:

    (i) The pair (g,h) is weakly increasing,

    (ii) The pair (g,h) is generalized (ψ, β)-Geraghty contraction type,

    (iii) Ω is regular,

    (iv) For all ηΩ, any iterative sequences {gnη} and {hnη} have convergent subsequences with respect to τδ.

    Then g and h have a common fixed point ν Ω with w(ν,ν)=0. Furthermore, assume that if η, uΩ such w(η,η)=w(u,u)=0 implies that if η and u are comparable, then the common fixed point of g and h is unique.

    Proof. After proving Theorem 3.2 we create a a sequence {ξn}Ω such that

    ξnνΩ with w(ν,ν)=0.

    Since Ω is regular, ξnν for all nN.

    Therefore, the elements ξn and ν are comparable for any nN.

    We now show that w(v,hv)=0.

    Suppose to the contrary, that is

    w(v,hv)>0.

    By (3.1), we have

    ψ(w(ξ2n+1,hν))=ψ(w(gξ2n,hν))α(max{w(ξ2n,ν),w(ξ2n,gξ2n),w(ν,hν)})β(max{w(ξ2n,ν),w(ξ2n,gξ2n),w(ν,hν)})=α(max{w(ξ2n,ν),w(ξ2n,ξ2n+1),w(ν,hν)})β(max{w(ξ2n,ν),w(ξ2n,ξ2n+1),w(ν,hν)}).

    Letting n in above inequalities, as a result, we say

    ψ(w(ν,hν))α(w(ν,hν))β(w(ν,hν)).

    Utilizing the properties of ψ, α and β,

    ψ(w(ν,hν))<ψ(w(ν,hν)),

    a contradiction.

    Thus, w(ν,hν)=0 that is ν is a fixed point of h.

    We can prove that is ν is a fixed point of g by using arguments similar to those used above. Similar arguments to those used in the proof of Theorem 3.2 are used to establish the uniqueness of the common fixed point of g and h.

    Corollary 3.1. Let (Ω,) be a partially ordered set, (Ω,δ) be a separated proximity space with w0distance w and g:ΩΩ be a mapping that meet the requirements listed below:

    (i) There exist αΠ, ψΨ and a continuous function β:[0,)[0,) with β(t)ψ(t) for all t>0 such that

    ψ(w(gμ,gξ))α(max{w(μ,ξ),w(ξ,gξ),w(gμ,μ)})β(max{w(μ,ξ),w(ξ,gξ),w(gμ,μ)}),

    holds for all comparable elements μ,ξΩ,

    (ii) gξg(gξ) for all ξΩ,

    (iii) g is continuous,

    (iv) For all ηΩ, any iterative sequence {gnη} has convergent subsequences with respect to τδ.

    Then g has a fixed point ν Ω with w(ν,ν)=0. Furthermore, assume that if η,uΩ such w(η,η)=w(u,u)=0 implies that η and u are comparable then the fixed point of g is unique.

    Proof. Theorem 3.2 implies that by inserting h=g.

    Corollary 3.2. Let we take that

    (iii) Ω is regular,

    Instead of (iii) in Corollary 3.1, again we can have the same result.

    Proof. Theorem 3.3 implies that by inserting h=g.

    Corollary 3.3. Let (Ω,) be a partially ordered set, (Ω,δ) be a separated proximity space with w0distance w and g,h:ΩΩ be two mappings that meet the requirements listed below:

    (i) There exist αΠ, ψΨ and a continuous function β:[0,)[0,) with β(t)ψ(t) for all t>0 such that

    ψ(w(gμ,hξ))α(w(μ,ξ))β(w(μ,ξ))

    holds for all comparable elements μ,ξΩ,

    (ii) The pair (g,h) is weakly increasing,

    (iii) Either g or h is continuous,

    (iv) For all ηΩ, any iterative sequences {gnη} and {hnη} have convergent subsequences with respect to τδ.

    Then g and h have a common fixed point ν Ω with w(ν,ν)=0. Furthermore, assume that if η, uΩ such w(η,η)=w(u,u)=0 implies that η and u are comparable then the common fixed point of g and h is unique.

    Corollary 3.4. Let (Ω,) be a partially ordered set, (Ω,δ) be a separated proximity space with w0distance w and g,h:ΩΩ be two mappings that meet the requirements listed below:

    (i) There exist αΠ, ψΨ and a continuous function β:[0,)[0,) with β(t)ψ(t) for all t>0 such that

    ψ(w(gμ,hξ))α(w(μ,ξ))β(w(μ,ξ))

    holds for all comparable elements μ,ξΩ,

    (ii) The pair (g,h) is weakly increasing,

    (iii) Ω is regular,

    (iv) For all ηΩ, any iterative sequences {gnη} and {hnη} have convergent subsequences with respect to τδ.

    Then g and h have a common fixed point ν Ω with w(ν,ν)=0. Furthermore, assume that if η, uΩ such w(η,η)=w(u,u)=0 implies that η and u are comparable then the common fixed point of g and h is unique.

    Corollary 3.5. Let (Ω,) be a partially ordered set, (Ω,δ) be a separated proximity space with w0distance w and g:ΩΩ be a mapping that meet the requirements listed below:

    (i) There exist αΠ, ψΨ and a continuous function β:[0,)[0,) with β(t)ψ(t) for all t>0 such that

    ψ(w(gμ,gξ))α(w(μ,ξ))β(w(μ,ξ))

    holds for all comparable elements μ,ξΩ,

    (ii) gξg(gξ) for all ξΩ,

    (iii) g is continuous,

    (iv) For all ηΩ, any iterative sequences {gnη} has convergent subsequences with respect to τδ.

    Then g has a fixed point ν Ω with w(ν,ν)=0. Furthermore, assume that if η, uΩ such w(η,η)=w(u,u)=0 implies that η and u are comparable then the fixed point of g is unique.

    Corollary 3.6. Let (Ω,) be a partially ordered set, (Ω,δ) be a separated proximity space with w0distance w and g:ΩΩ be a mapping that meet the requirements listed below:

    (i) There exist αΠ, ψΨ and a continuous function β:[0,)[0,) with β(t)ψ(t) for all t>0 such that

    ψ(w(gμ,gξ))α(w(μ,ξ))β(w(μ,ξ))

    holds for all comparable elements μ,ξΩ,

    (ii) gξg(gξ) for all ξΩ,

    (iii) Ω is regular,

    (iv) For all ηΩ, any iterative sequence {gnη} has convergent subsequences with respect to τδ.

    Then g has a fixed point ν Ω with w(ν,ν)=0. Furthermore, assume that if η, uΩ such w(η,η)=w(u,u)=0 implies that η and u are comparable then the fixed point of g is unique.

    Example 3.1. Let Ω={0,1,2} be equipped with the following partial order ,

    ⪯:={(0,0),(1,1),(2,2),(1,0)}.

    Also, let Ω be endowed with the usual metric and the proximity δ on 2Ω as

    AδBp(A,B)=0,where p(A,B)=min{p(u,v):uA,vB}.

    Define w:Ω×Ω[0,) by

    w(ξ,μ)=max{|ξ|,|μ|},

    w(0,0)=0, w(1,1)=1, w(2,2)=2, w(0,1)=w(1,0)=1, w(0,2)=w(2,0)=2,w(1,2)=w(2,1)=2.

    It is easy to see that (Ω,δ) be a separated proximity space with w0 distance w.

    Also define g,h:ΩΩ with g(0)=0, g(1)=0, g(2)=1 and h(0)=0, h(1)=1, h(2)=0. It is simple to observe that g and h are continuous and that the pair (g,h) is weakly increasing with respect to .

    Define α(t)=et16, β(t)=1011et, ψ(t)=1et if t>0 and α(0)=0.

    We next verify that the functions (g,h) satisfies the inequality

    ψ(w(gξ,hμ))α(Kξ,μ)β(Kξ,μ).

    For that, given ξ,μΩ with ξμ.

    Then we have the following cases:

    Case i ξ=0 and μ=0. Then

    ψ(w(g0,h0))=ψ(w(0,0))=0α(K0,0)β(K0,0).

    Case ii ξ=1 and μ=1. Then

    ψ(w(g1,h1))=ψ(w(0,1))=ψ(1)=1e

    and

    K1,1=max{w(1,1),w(g1,1),w(1,h1)}=max{1,1,1}=1.

    So,

    α(K1,1)=α(1)=e116
    β(K1,1)=β(1)=1011e.

    Hence

    ψ(w(g1,h1))α(K1,1)β(K1,1).

    Case iii ξ=2 and μ=2. Then

    ψ(w(g2,h2))=ψ(w(1,0))=ψ(1)=1e

    and

    K2,2=max{w(2,2),w(g2,2),w(2,h2)}=max{2,2,2}=2.

    So,

    α(K2,2)=α(2)=e216=e18
    β(K2,2)=β(2)=2011e.

    Hence

    ψ(w(g2,h2))α(K2,2)β(K2,2).

    Case iv 10. Then we have two subcases:

    Subcase i ξ=1 and μ=0. Then

    ψ(w(g1,h0))=ψ(w(0,0))=0

    and

    K1,0=max{w(1,0),w(g1,0),w(1,h0)}=max{1,0,1}=1.

    So,

    α(K1,0)=α(1)=e116
    β(K1,0)=β(1)=1011e.

    Hence

    ψ(w(g1,h0))α(K1,0)β(K1,0).

    Subcase ii ξ=0 and μ=1. Then

    ψ(w(g0,h1))=ψ(w(0,1))=ψ(1)=1e

    and

    K0,1=max{w(0,1),w(g0,1),w(0,h1)}=max{1,1,1}=1.

    So,

    α(K0,1)=α(1)=e116
    β(K0,1)=β(1)=1011e.

    Hence

    ψ(w(g0,h1))α(K0,1)β(K0,1).

    Therefore, requirements of Theorem3.3 are all satisfied and so g and h have a common fixed point (0 is a common fixed point of g and h).

    Let (Ω,δ) be the proximity space, where Ω=C[0,1] and δ is induced by the uniform metric p(ξ,μ)=sup{|ξ(t)μ(t)|:t[0,1]}. In this case (Ω,δ) is separated proximity space. Consider the following w0distance w on Ω defined by

    w(ξ,μ)=sup{et|ξ(t)μ(t)|:t[0,1]}.

    Now, consider the integral equation

    ξ(t)=G(t)+10S(t,s)F(s,ξ(s))ds,t[0,1] (4.1)

    where F:[0,1]×RR, G:[0,1]R, S:[0,1]×[0,1][0,). By utilizing the outcome from Corollary 1, the objective of this section is to provide an existence answer to (4.1). We give Ω the partial order "" provided by:

    ξμξ(t)μ(t)

    for all t[0,1].

    Theorem 4.1. Suppose that the following conditions are satisfied:

    (i) There exists α:[0,)[0,1] such that for all s[0,1] and for all ξ,μΩ

    0|F(s,ξ(s))F(s,μ(s))|α(es|ξ(s)μ(s)|)

    and

    α(tn)1tn0,

    (ii) 10S(t,s)ds|ξ(t)μ(t)|.

    Then the integral equation (4.1) has a solution in Ω.

    Proof. Consider the mapping g:ΩΩ defined by

    gξ(t)=10S(t,s)F(s,ξ(s))ds,

    for all ξΩ and t[0,1]. Then the (4.1) is equivalent to finding a fixed point of g.

    Now, let ξ,μΩ. We have:

    |gξ(t)gμ(t)|=|10S(t,s)[F(s,ξ(s))F(s,μ(s))]ds|10S(t,s)|F(s,ξ(s))F(s,μ(s))|ds10S(t,s)α(es|ξ(s)μ(s)|)ds  |ξ(t)μ(t)|α(et|ξμ|)p(ξ,μ)α(et|ξμ|)p(ξ,μ)α(w(ξ,μ))

    and then we obtain

    et|gξ(t)gμ(t)|w(ξ,μ)α(w(ξ,μ))

    i.e.,

    w(gξ,gμ)w(ξ,μ)α(w(ξ,μ))

    for all ξ,μΩ.

    Now, let γC[0,1] be an arbitrary function. Define a sequence of functions {ξn} as gnξ=ξn. Since etp(ξ,μ)w(ξ,μ)p(ξ,μ) for all ξ,μΩ, we have p(ξn,ξm)0 as m,n. That is the sequence {ξn} is Cauchy and so has a convergent subsequence with respect to p since (Ω,p) is complete. Consequently, there exists a unique ξΩ which is a fixed point of the operator g, moreover w(ξ,ξ)=0. Hence the integral equation (4.1) has a unique solution in Ω.

    The author is thankful to the referees and editor for making valuable suggestions leading to the better presentations of the paper.

    The author declares no conflict of interest.



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