The aim of the paper is to obtain a interesting result about the atomic decomposition of Bloch-type space in the polydisk. The existing similar results have been applied many times to the atomic decompositions of Bloch-type and weighted Bergman spaces in the unit ball.
Citation: Zhi-jie Jiang. A result about the atomic decomposition of Bloch-type space in the polydisk[J]. AIMS Mathematics, 2023, 8(5): 10822-10834. doi: 10.3934/math.2023549
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The aim of the paper is to obtain a interesting result about the atomic decomposition of Bloch-type space in the polydisk. The existing similar results have been applied many times to the atomic decompositions of Bloch-type and weighted Bergman spaces in the unit ball.
Let C be the complex plane. Denote by D(a,r) the open disk in C centered at a with radius r, by CN the N-dimensional complex Euclidean space with the inner product ⟨z,w⟩=∑Nj=1zj¯wj, by D the open unit disk in C, by DN the open unit polydisk in CN, and by BN the open unit ball in CN. For given z∈CN, write |z|∞=max1≤j≤N|zj|. Let H(DN) be the space of all holomorphic functions on DN and H∞(DN) the space of all bounded holomorphic functions on DN with the supremum norm ‖f‖∞=supz∈DN|f(z)|.
A positive continuous radial function μ on the interval [0,1) is called normal (see, for example, [9]), if there are λ∈[0,1), a and b (0<a<b) such that
μ(r)(1−r)ais decreasing on[λ,1),limr→1μ(r)(1−r)a=0;μ(r)(1−r)bis increasing on[λ,1),limr→1μ(r)(1−r)b=+∞. |
For such function, the following examples were given in [9]:
μ(r)=(1−r2)α,α∈(0,+∞), |
μ(r)=(1−r2)α{log2(1−r2)−1}β,α∈(0,1),β∈[α−12log2,0], |
and
μ(r)=(1−r2)α{logloge2(1−r2)−1}γ,α∈(0,1),γ∈[α−12log2,0]. |
The following fact can be used to prove that there exist lots of non-normal functions. It follows from [14] that if μ is normal, then for each s∈(0,1) there exists a positive constant C=C(s) such that
C−1μ(t)≤μ(r)≤Cμ(t) | (1.1) |
for 0≤r≤t≤r+s(1−r). From (1.1), it is easy to check the following functions are non-normal
μ(r)=|sin(log11−r)|vα(r)+1 |
and
μ(r)=|sin(log11−r)|vα(r)+1ee11−r, |
where
vα(r)=[(1−r)(loge1−r)α]−1. |
The functions {μ,ν} will be called a normal pair if μ is normal and for b in above definition of normal function, there exists β>b such that
μ(r)ν(r)=(1−r2)β. |
If μ is normal, then there exists ν such that {μ,ν} is normal pair (see [17]). Note that if {μ,ν} is a normal pair, then ν is also normal. One of the purposes of introducing normal pair is to characterize the duality of spaces defined by the normal function (see [4,25]).
Given a normal function μ, the Bloch-type space Bμ(DN) consists of all f∈H(DN) such that
βμ(f)=supz∈DNN∑k=1μ(zk)|∂f∂zk(z,…,zN)|<+∞. |
Endowed with the norm ‖f‖Bμ(DN)=|f(0)|+βμ(f), it is a Banach space. There were a handful of studies on the space Bμ(DN) (see, for example, [5,6]). But the spaces with some special normal functions defined on the unit ball or unit disk and some operators have been extensively studied (see, for example, [3,12,19,20,28], where [28] contains the elementary knowledge of such space).
Given a normal function μ, the weighted-type space H∞μ(DN) consists of all f∈H(DN) such that
‖f‖H∞μ(DN)=supz∈DNN∏k=1μ(zk)|f(z,…,zN)|<+∞. |
H∞μ(DN) is a Banach space with the norm ‖⋅‖H∞μ(DN). There are lots of studies about such spaces on the unit ball or unit disk and some operators (see, for example, [7,8,10,11,21,22,24]).
Let dA(z)=1πdxdy be the normalized Lebesgue measure on D and dAα(z)=(α+1)(1−|z|2)αdA(z) the weighted Lebesgue measure on D, where −1<α<+∞. For given →α=(α1,…,αN), −1<αj<+∞, j=1,…,N, and 0<p<+∞, the weighted Bergman space Ap→α(DN) consists of all f∈H(DN) such that
‖f‖pAp→α(DN)=∫DN|f(z)|pdA→α(z)<+∞, |
where dA→α(z)=dAα1(z1)…dAαN(zN). For some information about this space, see, for example, [23]. When p≥1, the weighted Bergman space with the norm ‖⋅‖Ap→α(DN) becomes a Banach space. While p∈(0,1), it is a Fréchet space with the translation invariant metric
d(f,g)=‖f−g‖pAp→α(DN). |
The reason why people study the atomic decompositions for holomorphic function spaces is that it is very useful in operator theory. In particular, it can be used to describe dual spaces or to study basic questions such as the boundedness, the compactness or the Schatten class membership of concrete operators (see, for example, [1,13,14,15,18]). The atomic decompositions for holomorphic function spaces have been studied. For example, Coifman and Rochberg in [2] studied this problem on the weighted Bergman space. Zhu in [28] modified the proof of [2] and gave the atomic decomposition for the weighted Bloch space on the unit ball. Motivated by the previous studies, Zhang et al. in [26] characterized the atomic decomposition for the μ-Bergman space on the unit ball. Later, Zhang et al. in [27] also considered the atomic decomposition for μ-Bloch space on the unit ball. The works of [26,27] extended the corresponding results in [28].
We find that in above-mentioned works, the following result have been used many times in the atomic decompositions (see [28] for some details):
For any p>0 and α>−1, there exists a positive constant C independent of the separation constants r and η such that
|f(z)−Sf(z)|≤Cσ∞∑k=1(1−|ak|2)(pb−N−1−α)/p|1−⟨z,ak⟩|b(∫D(ak,2r)|f(w)|pdvα(w))1p |
for all r∈(0,1), z∈BN and f∈H(BN), where σ is some constant related to r and η, and the operator S on H(BN) is defined by
Sf(z)=N∑k=1J∑j=1vβ(Dkj)f(akj)(1−⟨z,akj⟩)b. | (1.2) |
A very natural problem is to extend this useful result to some other domains in CN. For example, here we will consider the result on DN. Another reason of our extension is that DN and BN are completely different domains in CN (see, for example, [16]), which may produce some differences in methods and techniques.
In this paper, positive numbers are denoted by C, and they may vary in different situations. The notation a≲b (resp. a≳b) means that there is a positive number C such that a≤Cb (resp. a≥Cb). When a≲b and b≳a, we write a≍b.
In this section, we will obtain several elementary results which are used to prove the main results. We first have the following basic one (see, for example, [28]).
Lemma 2.1. There exists a positive integer ˆN such that for any 0<r<1, we can find a sequence {ak} in D and a set {Dk} consisting of Lebesgue measurable sets satisfying the following conditions:
(1) D=∪∞k=1D(ak,r);
(2) Dk∩Dj=∅ for k≠j;
(3) D(ak,r4)⊂Dk⊂D(ak,r) for every k∈N;
(4) Each point z∈D belongs to at most ˆN of the sets D(ak,4r).
Let →r=(r1,…,rN), 0<rj<1, j=1,…,N. Then for each fixed rj there exist a sequence {ajk} and a set {Djk} satisfy Lemma 2.1. For convenience, we denote by ak=(a1k,…,aNk), by ˆD(ak,→r)=D(a1k,r1)×⋯×D(aNk,rN), and by ˆDk=D1k×⋯×DNk.
By using Lemma 2.1, we obtain the following similar disjoint decomposition of DN.
Lemma 2.2. There exists a positive integer ˆN such that for any →r=(r1,…,rN), 0<rj<1, j=1,…,N, we can find a sequence {ak} in DN and a set {ˆDk} consisting of Lebesgue measurable sets satisfying the following conditions:
(1) DN=∪∞k=1ˆD(ak,→r);
(2) ˆDk∩ˆDj=∅ for k≠j;
(3) ˆD(ak,14→r)⊂ˆDk⊂ˆD(ak,→r) for every k∈N;
(4) Each point z∈DN belongs to at most ˆNN sets ˆD(ak,4→r).
The following integral expression for the functions in A1α(BN) is well known (see [28]).
Lemma 2.3. If α>−1 and f∈A1α(BN), then
f(z)=∫BNf(w)dvα(w)(1−⟨z,w⟩)α+N+1. |
Let x∗=(x1,…,xj−1) and x∗=(xj+1,…,xN), j=1,…,N. As an application of Lemma 2.3 for N=1, if we regard the function f(z1,…,zN)∈A1→α(DN) as a one-variable function f(z∗,zj,z∗)∈A1αj(D), j=1,…,N, then we have the following integral expression on A1→α(DN).
Lemma 2.4. If αj>−1, j=1,…,N, and f∈A1→α(DN), then
f(z)=∫DNf(w)dA→α(w)∏Nj=1(1−¯wjzj)αj+2. |
Remark 2.1. In order to obtain Theorem 3.1, we need give a key decomposition for DN. We first further partition the sets {ˆDk} in Lemma 2.2. Actually, we partition the set ˆD1 and use automorphisms to carry the partition to other ˆDk's. To this end, we let →η=(η1,…,ηN), where each ηj denotes a positive number that is much smaller than the separation constant rj in →r=(r1,…,rN), in the sense that the quotient ηj/rj is small. We fix a finite sequence {z1,…,zJ} in ˆD(0,→r), depending on →η, such that {ˆD(zj,→η)} covers ˆD(0,→r) and that {ˆD(zj,14→η)} are disjoint. We then can enlarge each set ˆD(zj,14→η)∩ˆD(0,→r) to a Borel set Ej in the way that Ej⊂ˆD(zj,→η) and that
ˆD(0,→r)=J⋃j=1Ej |
is a disjoint union. Here we just give a instruction. If you would like, you can see the proof of Lemma 2.28 in [28] for how to achieve this.
Let w=(w1,…,wN)∈DN and φw(z) be the involutive automorphism of DN. Then
φw(z)=(φw1(z1),…,φwN(zN)), |
where
φwj(zj)=wj−zj1−¯wjzj |
is the involutive automorphism of D.
For fixed j∈{1,…,J} and ak=(a1k,…,aNk), we define bjk=φak(zj). For l∈{1,…,N}, we define Elj={zl∈D:(z∗,zl,z∗)∈Ej}. Let Bljk=Dlk∩φalk(Elj), where sets {Dlk} are in Lemma 2.1 for {alk} and l∈{1,…,N}. Since
Dlk=J⋃j=1Bljk |
is a disjoint union for every l and k, we obtain a disjoint decomposition
DN=∞⋃k=1J⋃j=1ˆBjk |
of DN, where ˆBjk is the Cartesian product of Bljk, l=1,…,N.
By using the decomposition of DN, we give the following definition, which is similar to those of (1.2).
Definition 2.1. Let bl>1 and βl=bl−2, l=1,…,N. Then the operator S on H(DN) is defined by
Sf(z)=∞∑k=1J∑j=1A→β(ˆBjk)f(bjk)∏Nl=1(1−¯bljkzl)bl. |
Remark 2.2. From the definition of dA→β, it follows that
A→β(ˆBjk)=N∏l=1Aβl(Bljk). |
After discussions in Part 2, we now return to the following result.
Theorem 3.1. For p>0, αl>−1, l=1,…,N, there exists a positive constant C independent of the separation constants →r, →η, f∈H(DN) and z∈DN, such that
|f(z)−Sf(z)|≤Cσ∞∑k=1∏Nl=1(1−|alk|2)bl−αl+2p∏Nl=1|1−¯alkzl|bl(∫ˆD(ak,2→r)|f(w)|pdA→α(w))1p |
for all →r=(r1,…,rN), 0<rl<1, l=1,…,N, where
σ=|→η′|(r′1r′2⋯r′N)2p−1+η1η2⋯ηN,r′l=tanh(rl),→η′=(tanh(η1),…,tanh(ηN)), |
and tanh(⋅) is the hyperbolic tangent function.
Proof. Without loss of generality, we may assume that f∈A1→β(DN). By the integral expression of the functions in A1→β(DN), we have
f(z)=∫DNf(w)dA→β(z)∏Nl=1(1−¯wlzl)bl. |
Since {ˆBjk} is a partition of DN, we can write
f(z)−Sf(z)=∞∑k=1J∑j=1∫ˆBjk[f(w)∏Nl=1(1−¯wlzl)bl−f(bjk)∏Nl=1(1−¯bljkzl)bl]dA→β(w). | (3.1) |
Since ˆBjk is the Cartesian product of Bljk, l=1,…,N, it follows that
∫ˆBjkdA→β(w)=∫B1jk∫B2jk⋯∫BNjkdA→β(w). | (3.2) |
By using the triangle inequality in (3.1), we have
|f(z)−Sf(z)|≤I(z)+H(z), |
where by (3.2) we get
I(z)=∞∑k=1J∑j=11∏Nl=1|1−¯bljkzl|bl∫B1jk∫B2jk⋯∫BNjk|f(w)−f(bjk)|dA→β(w) |
and
H(z)=∞∑k=1J∑j=11∏Nl=1|1−¯bljkzl|bl∫B1jk∫B2jk⋯∫BNjk|∏Nl=1(1−¯bljkzl)bl∏Nl=1(1−¯wlzl)bl−1||f(w)|dA→β(w). |
We first estimate I(z). Let
Ijk=∫B1jk∫B2jk⋯∫BNjk|f(w)−f(bjk)|dA→β(w). | (3.3) |
By a change of variables in (3.3), we have
Ijk=N∏l=1(1−|bljk|2)bl∫E1jk∫E2jk⋯∫ENjk|f∘φbjk(w)−f∘φbjk(0)|∏Nl=1|1−¯bljkwl|2bldA→β(w), | (3.4) |
where
Eljk=φbljk(Bljk)⊂φbljk∘φalk(Elj)⊂φbljk∘φalk(D(zlj,ηl)=φbljk(D(bljk,ηl))=D(0,ηl). |
For wl∈Eljk, the quantities (1−|wl|2)βj+2 and |1−¯bljkwl| are both bounded from below and from above. Also, since each bljk∈D(alk,rl), the quantities 1−|bljk|2 and 1−|alk|2 are comparable. Therefore, there exists a positive constant C independent of →r and →η, such that
Ijk≤CN∏l=1(1−|alk|2)bl∫E1jk∫E2jk⋯∫ENjk|f∘φbjk(w)−f∘φbjk(0)|dA(w). | (3.5) |
Write r′l=tanh(rl), η′l=tanh(ηl). Since each ηl is much smaller than rl for l∈{1,…,N}, we may as well assume that R=max1≤l≤Nη′l/r′l≤12. By Lemma 2.4, there exists a positive constant C such that
|∇g(z)|≤C(∫DN|g(w)|pdA(w))1p,|z|≤R, |
for g∈H(DN). Let →r′=(r′1,…,r′N) and →η′=(η′1,…,η′N). Consider g(z)=h(→r′z), where h(z)=f∘φbjk(z), →r′z=(r′1z1,…,r′NzN), z∈DN. After a change of variables, we obtain
r′1r′2⋯r′N|∇h(→r′z)|≤C(1(r′lr′2⋯r′N)2∫ˆD(0,→r)|h(w)|pdA(w))1p |
for all |z|≤R. That is,
|∇h(→r′z)|≤C(r′1r′2⋯r′N)1+2/p(∫ˆD(0,→r)|h(w)|pdA(w))1p | (3.6) |
for all z∈ˆD(0,→η). For any w∈ˆEjk⊂ˆD(0,→η), the identity
h(w)−h(0)=∫10(N∑l=1wl∂h∂wl(tw))dt |
directly leads to
|h(w)−h(0)|≤|→η′|sup{|∇h(u)|:u∈ˆD(0,→η)}. | (3.7) |
From (3.5) and (3.7), we therefore have
Ijk≤C|→η′|N∏l=1(1−|alk|2)blA(ˆEjk)sup{|∇h(u)|:u∈ˆD(0,→η)}, | (3.8) |
where ˆEjk is the Cartesian product of Eljk, l=1,…,N. Combining (3.6) with (3.8), we obtain
Ijk≤C|→η′|(r′1r′2⋯r′N)1+2/pN∏l=1(1−|alk|2)blA(ˆEjk)(∫ˆD(0,→r)|h(w)|pdA(w))1p. | (3.9) |
By a change of variables again,
∫ˆD(0,→r)|h(w)|pdA(w)=∫D(b1jk,r1)∫D(b2jk,r2)⋯∫D(bNjk,rN)|f(w)|pN∏l=1(1−|bljk|2)2|1−¯bljkwl|4dA(w). | (3.10) |
It is easy to see that the quantities 1−|bljk|2 and |1−¯bljkwl| are both comparable to 1−|alk|2 for wl∈D(bljk,rl). This along with the fact that for each l∈{1,…,N} it follows that D(bljk,rl)⊂D(alk,2rl) shows that
∫D(b1jk,r1)∫D(b2jk,r2)⋯∫D(bNjk,rN)|f(w)|pN∏l=1(1−|bljk|2)2|1−¯bljkwl|4dA(w)≤CN∏l=11(1−|alk|2)2∫D(a1k,2r1)∫D(a2k,2r2)⋯∫D(aNk,2rN)|f(w)|pdA(w). |
Since 1−|alk|2 is comparable to 1−|wl|2 for wl∈D(alk,2rl), we have
∫D(b1jk,r1)∫D(b2jk,r2)⋯∫D(bNjk,rN)|h(w)|pN∏l=1(1−|bljk|2)2|1−¯bljkwl|4dA(w)≤CN∏l=11(1−|alk|2)αl+2∫D(a1k,2r1)∫D(a2k,2r2)⋯∫D(aNk,2rN)|f(w)|pdA→α(w). | (3.11) |
From (3.9)–(3.11), we have
Ijk≤C|→η′|(r′1r′2⋯r′N)1+2/pN∏l=1(1−|alk|2)bl−αl+2pA(ˆEjk)(∫ˆD(ak,2→r)|f(w)|pdA→α(w))1p. | (3.12) |
Since
J∑j=1A(ˆEjk)=J∑j=1N∏l=1Al(Eljk)≤J∑j=1N∏l=1Al(D(0,ηl)=Jη21η22⋯η2N |
and
A(ˆD(0,→r))=J∑j=1A(Ej)≥J∑j=1A(ˆD(zj,→η))=J∑j=1N∏l=1Al(D(zlj,ηl))≥CJη21η22⋯η2N, |
where the last inequality follows from Lemma 1.23 in [28], we have
J∑j=1A(ˆEjk)≤CA(ˆD(0,→r′))=C(r′1)2(r′2)2⋯(r′N)2. | (3.13) |
From (3.12) and (3.13), it follows that
J∑j=1Ijk≤C|→η′|(r′1r′2⋯r′N)2p−1N∏l=1(1−|alk|2)bl−αl+2p(∫ˆD(ak,2→r)|f(w)|pdA→α(w))1p. |
For each k∈N and 1≤j≤J, it follows from Lemma 2.27 in [28] for N=1 that |1−¯bljkzl|bl is comparable to |1−¯alkzl|bl. Therefore,
I(z)≤C|→η′|(r′1r′2⋯r′N)2p−1∞∑k=1∏Nl=1(1−|alk|2)bl−αl+2p∏Nl=1|1−¯alkzl|bl(∫ˆD(ak,2→r)|f(w)|pdA→α(w))1p. |
Now we estimate H(z). Let
Hjk=∫B1jk∫B2jk⋯∫BNjk|∏Nl=1(1−¯bljkzl)bl∏Nl=1(1−¯wlzl)bl−1||f(w)|dA→β(w). |
By Lemma 2.27 for N=1 in [28], we have
Hjk≤Cη1η2…ηNN∏l=1(1−|bljk|2)βl∫B1jk∫B2jk⋯∫BNjk|f(w)|dA(w). |
From [23], there is a positive constant C independent of f∈H(DN) and z∈DN such that
|f(z)|p≤C∏Nl=1(1−|zl|2)αl+2∫ˆD(z,→r)|f(w)|pdA→α(w). | (3.14) |
By the definition of Bljk and since ˆBjk is the Cartesian product of Bljk, l=1,…,N, we deduce that ˆBjk⊆ˆDk, and then by Lemma 2.2 we further obtain that ˆBjk⊆ˆDk⊆ˆD(ak,2→r). From this and replacing z by ak in (3.14), for every w∈ˆBjk we have
|f(w)|≤C∏Nl=1(1−|alk|2)αl+2p(∫ˆD(ak,2→r)|f(w)|pdA→α(w))1p. |
Then
Hjk≤Cη1η2…ηN∏Nl=1(1−|bljk|2)βl∏Nl=1(1−|alk|2)αl+2pA(ˆBjk)(∫ˆD(ak,2→r)|f(w)|pdA→α(w))1p. |
Since
J∑j=1A(ˆBjk)=A(ˆDk)≤A(ˆD(ak,→r))≤N∏l=1(1−|alk|2)2, |
we deduce that
J∑j=1Hjk≤Cη1η2…ηN∏Nl=1(1−|bljk|2)βl∏Nl=1(1−|alk|2)αl+2p−2(∫ˆD(ak,2→r)|f(w)|pdA→α(w))1p. |
From above same reasons, we have seen that 1−|bljk|2 and 1−|alk|2 are comparable, and |1−¯bljkzl| and |1−¯alkzl| are also comparable. It follows that
H(z)≤Cη1η2…ηN∞∑k=1∏Nl=1(1−|alk|2)bl−αl+2p∏Nl=1|1−¯alkzl|bl(∫ˆD(ak,2→r)|f(w)|pdA→α(w))1p. |
This completes the proof.
As an important application of Theorem 3.1, we obtain the next result, which shows that the operator I−S is bounded on H∞μ(DN).
Theorem 3.2. Let μ be normal on [0,1). Then there exist a positive constant C independent of f∈H∞μ(DN), →r and →η, such that
‖(I−S)f‖H∞μ(DN)≤C‖f‖H∞μ(DN). |
Proof. We first choose →α=0 and p=1 in Theorem 3.1. Then we obtain
|f(z)−Sf(z)|≤Cσ∞∑k=1∏Nl=1(1−|alk|2)bl−2∏Nl=1|1−¯alkzl|bl∫ˆD(ak,2→r)|f(w)|dA(w) | (3.15) |
for →r=(r1,…,rN), 0<rl<1, l=1,…,N, z∈DN. From Lemma 2.3 for N=1 in [26], there exists a positive constant Al for each 0≤l≤N such that
A−1l≤|1−ˉalkzl||1−¯wlzl|≤Al. | (3.16) |
Then, from (3.15) and (3.16), it follows that there exists a positive constant C independent of →η and →r such that
|f(z)−Sf(z)|≤Cσ∞∑k=1∫ˆD(ak,2→r)∏Nl=1(1−|wl|2)bl−2∏Nl=1|1−¯wlzl|bl|f(w)|dA(w)≤CˆNNσ∫DN∏Nl=1(1−|wl|2)bl−2∏Nl=1|1−¯wlzl|bl|f(w)|dA(w). |
Which shows that
N∏l=1μ(zl)|f(z)−Sf(z)|≤CˆNNσ∫DN∏Nl=1(1−|wl|2)bl−2∏Nl=1μ(zl)∏Nl=1|1−¯wlzl|bl|f(w)|dA(w)=CˆNNσ∫DN∏Nl=1(1−|wl|2)bl−2∏Nl=1μ(zl)∏Nl=1μ(wl)∏Nl=1|1−¯wlzl|bl∏Nl=1μ(wl)|f(w)|dA(w)≤CˆNNσ‖f‖H∞μ(DN)∫DN∏Nl=1(1−|wl|2)bl−2∏Nl=1μ(zl)∏Nl=1|1−¯wlzl|bl∏Nl=1μ(wl)dA(w). | (3.17) |
By Lemma 2.2 in [26], for each l∈{1,…,N} we have
μ(zl)μ(wl)≤(1−|zl|21−|wl|2)a+(1−|zl|21−|wl|2)b. |
We therefore obtain
N∏l=1μ(zl)μ(wl)≤N∏l=1[(1−|zl|21−|wl|2)a+(1−|zl|21−|wl|2)b]. | (3.18) |
For convenience, write
xl=1−|zl|21−|wl|2, |
then from (3.17) and (3.18), we have that
N∏l=1μ(zl)|f(z)−Sf(z)|≤CˆNNσ‖f‖H∞μ(DN)∫DN∏Nl=1(1−|wl|2)bl−2∏Nl=1|1−¯wlzl|blN∏l=1(xal+xbl)dA(w). | (3.19) |
It is easy to see that there are 2N terms in ∏Nl=1(xal+xbl). For arbitrary term h(x1,…,xN), without lose of generality, we may assume that
h(x1,…,xN)=xa1⋯xalxbl+1⋯xbjxaj+1⋯xakxbk+1⋯xbmxam+1⋯xaN. | (3.20) |
Substituting xl in (3.20), we obtain
h(x1,…,xN)=∏llj=1(1−|zlj|2)a∏jlj=l+1(1−|zlj|2)b∏klj=j+1(1−|zlj|2)a∏llj=1(1−|wlj|2)a∏jlj=l+1(1−|wlj|2)b∏klj=j+1(1−|wlj|2)a×∏mlj=k+1(1−|zlj|2)b∏Nlj=m+1(1−|zlj|2)a∏mlj=k+1(1−|wlj|2)b∏Nlj=m+1(1−|wlj|2)a. |
Then by Theorem 2.12 in [28] we obtain
∫DN∏Nl=1(1−|wl|2)bl−2∏Nl=1|1−¯wlzl|blh(x1,…,xN)dA(w)≍1. |
From this and (3.19), the desired result follows. This completes the proof.
In this paper, a interesting result in the polydisk about the atomic decomposition of Bloch-type space has been obtained. It is well known that the existing similar results in the unit ball have been applied many times to the atomic decompositions of Bloch-type and weighted Bergman spaces. Hope that this study can attract people's more attention for the atomic decomposition of Bloch-type space.
The author would like to thank the anonymous referee for providing valuable comments that improved the presentation of the paper. This work was supported by the Sichuan Science and Technology Program (2022ZYD0010).
The authors declare that they have no competing interests.
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