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Research article

Sum of some product-type operators from mixed-norm spaces to weighted-type spaces on the unit ball

  • Received: 17 May 2022 Revised: 12 July 2022 Accepted: 26 July 2022 Published: 11 August 2022
  • MSC : 30H05, 47B33, 47B37, 47B38

  • Let uj be the holomorphic functions on the open unit ball B in Cn, j=¯0,m, φ a holomorphic self-map of B, and j the jth iterated radial derivative operator. In this paper, the boundedness and compactness of the sum operator Smu,φ=mj=0MujCφj from the mixed-norm space H(p,q,ϕ), where 0<p,q<+, and ϕ is normal, to the weighted-type space Hμ are characterized. For the mixed-norm space H(p,q,ϕ), 1p<+, 1<q<+, the essential norm estimate of the operator is given, and the Hilbert-Schmidt norm of the operator on the weighted Bergman space A2α is also calculated.

    Citation: Cheng-shi Huang, Zhi-jie Jiang, Yan-fu Xue. Sum of some product-type operators from mixed-norm spaces to weighted-type spaces on the unit ball[J]. AIMS Mathematics, 2022, 7(10): 18194-18217. doi: 10.3934/math.20221001

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  • Let uj be the holomorphic functions on the open unit ball B in Cn, j=¯0,m, φ a holomorphic self-map of B, and j the jth iterated radial derivative operator. In this paper, the boundedness and compactness of the sum operator Smu,φ=mj=0MujCφj from the mixed-norm space H(p,q,ϕ), where 0<p,q<+, and ϕ is normal, to the weighted-type space Hμ are characterized. For the mixed-norm space H(p,q,ϕ), 1p<+, 1<q<+, the essential norm estimate of the operator is given, and the Hilbert-Schmidt norm of the operator on the weighted Bergman space A2α is also calculated.



    Let N={1,2,3,}, N0=N{0}, B(a,r)={zCn:|za|<r} the open ball in the complex vector space Cn centered at a with radius r, Bn=B=B(0,1), S the boundary of B and nN. Let z=(z1,z2,,zn) and w=(w1,w2,,wn) be two points in Cn, then z,w=z1¯w1+z2¯w2++zn¯wn and |z|2=z,z.

    Let H(B) be the set of all holomorphic functions on B and S(B) the set of all holomorphic self-maps of B. If φS(B), then by Cφf(z)=f(φ(z)), zB, is defined a operator, usually called the composition operator. If uH(B), then by Muf(z)=u(z)f(z), zB, is defined a operator, usually called the multiplication operator.

    When n=1, the open unit ball B is reduced to the open unit disk D. Let mN0, the mth differentiation operator Dm on some subspaces of H(D) is defined by

    Dmf(z)=f(m)(z),

    where f(0)=f. If m=1, it is the classical differentiation operator, denoted by D. There have been a lot of studies on the products related to one of the differentiation operators. For example, products DCφ and CφD were first studied (see, for example, [5,15,16,17,18,22,33,34,35]) containing the differentiation operator. What followed was the following six products of the operators were studied (see, for example, [25,40,41])

    DMuCφ,DCφMu,CφDMu,CφMuD,MuCφD,MuDCφ. (1.1)

    Afterwards, operators in (1.1) were studied in terms of replacing D by Dm (see, for example, [9,10,44]), that is, the following six products of the operators were studied

    DmMuCφ,DmCφMu,CφDmMu,CφMuDm,MuCφDm,MuDmCφ. (1.2)

    For some other products of the operators containing differentiation operators can be found in [11,12,29,46] and the related references therein.

    There are other ways to extend differentiation operators on domains in Cn. For example, the radial derivative operator

    f(z)=nj=1zjfzj(z)

    is one of natural extensions of the differentiation operators. The products of the composition, multiplication, and radial derivative operators

    MuCφ,CφMu,CφMu,MuCφ,MuCφ,CφMu (1.3)

    were studied in [19,20,21,47]. Operators MuCφ and MuCφ were also studied in [8]. Operators in (1.3) naturally generalize operators in (1.1) from the unit disk setting to the unit ball setting. Recently, they have been continuously studied in [45]. Some other products of the operators containing the radial derivative operators can be found, for example, in [31,49].

    An advantage of the radial derivative operator is that it can be employed iteratively, that is, if m1f is defined for some mN{1}, then mf is naturally defined by mf=(m1f). If m=0, then we regard that 0f=f. By using the mth iterated radial derivative operator, we obtain the related product-type operators

    MuCφm,CφmMu,CφMum,mMuCφ,MumCφ,mCφMu. (1.4)

    Operators in (1.4) are more complicated than those in (1.3). Clearly, the operator MuCφm can be regarded as the simplest one in (1.4), which was first studied and denoted by mu,φ in [32]. Recently, we have been reconsidered such operator in [38,39]. The reason why we consider the operator mu,φ again is that we need to get more information on the related function spaces in order to characterize its properties.

    Operators in (1.4) generalize operators in (1.2) from the unit disk case to the unit ball case. For the unit disk case, by using the famous Faà di Bruno's formula of (fφ)(m) (see [13]), operators DmMuCφ, DmCφMu and MuDmCφ have been studied (see, for example, [9,10]). But, we don't find any result on the operators mMuCφ, mCφMu and MumCφ. By a direct calculation, it is easy to see that

    CφMum=muφ,φandCφmMu=mi=0Cimi(miu)φ,φ. (1.5)

    Motivated by this interesting observation, we directly define the operator

    Smu,φ=mj=0juj,φ (1.6)

    on some subspaces of H(B), where ujH(B),j{0,1,,m} and φS(B).

    In this paper, the boundedness and compactness of the operator Smu,φ=mj=0juj,φ from the mixed-norm space to the weighted-type space on B are characterized. The essential norm estimate of the operator from the mixed-norm space to the weighted-type space on B is given, and the Hilbert-Schmidt norm of the operator on the weighted Hilbert-Bergman space is calculated. As corollaries, the corresponding results of the operator CφmMu from mixed-norm space to weighted-type space are also obtained. This study can be viewed as a continuation and extension of our previous work.

    A positive continuous function ϕ on the interval [0,1) is called normal (see [28]), if there are λ[0,1), a and b (0<a<b) such that

    ϕ(r)(1r)ais decreasing on[λ,1),limr1ϕ(r)(1r)a=0;ϕ(r)(1r)bis increasing on[λ,1),limr1ϕ(r)(1r)b=+.

    The functions {ϕ,ψ} will be called a normal pair if ϕ is normal and for b in above definition of normal function, there exists β>b, such that

    ϕ(r)ψ(r)=(1r2)β.

    If ϕ is normal, then there exists ψ such that {ϕ,ψ} is normal pair (see [28]). Note that if {ϕ,ψ} is normal pair, then ψ is also normal.

    For 0<p,q<+ and a normal function ϕ, the mixed-norm space H(p,q,ϕ)(B):=H(p,q,ϕ) consists of all fH(B) such that

    fpH(p,q,ϕ)=10Mpq(f,r)ϕp(r)1rdr<+,

    where

    Mq(f,r)=(S|f(rζ)|qdσ(ζ))1q,

    and dσ is the normalized surface measure on S.

    If p=q, ϕ(r)=(1r2)(α+1)/p and α>1, then it is equivalent with the weighted Bergman space Apα (see [48]), which is defined by

    Apα={fH(B):fpApα=B|f(z)|p(1|z|2)αdv(z)<+},

    where dv denotes the normalized volume measure on B. Some facts can be found about the mixed-norm spaces, for example, in [1,2,26,27,36] (see also the references therein).

    A positive continuous function μ on B is called weight. The weighted-type space Hμ(B):=Hμ consists of all fH(B) such that

    fHμ=supzBμ(z)|f(z)|<+.

    With the norm Hμ, Hμ is a Banach space. In particular, if μ(z)=(1|z|2)σ(σ>0), then the space Hμ is called the classical weighted-type space Hσ. If μ1, then the space Hμ is reduced to the space H of bounded holomorphic functions on B. Many operators acting from or to the weighted-type spaces have been studied (see, for example, [14,16,24,46] and the related references therein).

    Let X and Y be two Banach spaces. It is said that a linear operator T:XY is bounded if there exists a positive constant K such that TfYKfX for all fX. The bounded operator T:XY is compact if it maps bounded sets into relatively compact sets. The norm of the operator T:XY, usually denoted by TXY, is defined by

    TXY=supfX1TfY.

    In this paper, we use the notation j=¯k,l instead of writing j=k,...,l, where k,lN0 and kl. Some positive constants are denoted by C, and they may differ from one occurrence to the other. The notation ab (resp. ab) means that there is a positive constant C such that aCb (resp. aCb). When ab and ba, we write ab.

    Here, we give several lemmas which are used in the proofs of the main results. First, we have the following point-evaluation estimate for the functions in H(p,q,ϕ) (see [36]).

    Lemma 2.1. Let 0<p,q<+ and ϕ normal. Then there is a positive constant C independent of fH(p,q,ϕ) and zB such that

    |f(z)|Cϕ(|z|)(1|z|2)nqfH(p,q,ϕ). (2.1)

    Now, we cite a point-evaluation estimate for the jth iterated radial derivatives of the functions in H(p,q,ϕ) (see [32]).

    Lemma 2.2. Let jN, 0<p,q<+ and ϕ normal. Then there is a positive constant C independent of fH(p,q,ϕ) and zB such that

    |jf(z)|C|z|ϕ(|z|)(1|z|2)nq+jfH(p,q,ϕ). (2.2)

    Remark 2.1. From (2.1) and (2.2), it follows that if {fk} is bounded in H(p,q,ϕ), then {fk} and {jfk} are uniformly bounded on any compact subset of B, and if {fk} converges to zero in H(p,q,ϕ), then {fk} and {jfk} converge to zero uniformly on any compact subset of B as k.

    To obtain a criterion for the compactness of a bounded linear operator T:H(p,q,ϕ)Hμ, we need to cite the following result, which can be found in [3] for the unit disk version. For the unit ball case, whose proof can be directly obtained by replacing the unit disk by the unit ball, and so the proof is omitted.

    Lemma 2.3. Let X be a reflexive Banach space of holomorphic functions on B, and Y a Banach space. Then a bounded linear operator T:XY is compact if and only if for any bounded sequence {fk} in X such that fk0 uniformly on any compact subset of B as k, it follows that {Tfk} converges to zero in the norm of Y as k.

    To give the conditions such that H(p,q,ϕ) is reflexive, we recall some studies of the dual spaces of H(p,q,ϕ). Jevtić in [7] showed that the dual space of H(p,q,ϕ), where 1p+ and 1q<+, is topologically isomorphic to H(p,q,ψ), where 1/p+1/p=1 and 1/q+1/q=1. Shi in [27] considered the dual spaces of H(p,q,ϕ) for two cases: (i) if 0<p1 and 1<q+, then the dual space of H(p,q,ϕ) is topologically isomorphic to H(+,q,ψ); (ii) if 0<p1 and 0<q1, then the dual space of H(p,q,ϕ) is topologically isomorphic to H(+,+,ψ).

    From above facts, we obtain the following remark.

    Remark 2.2. Considering the assumption 0<p,q<+, we see that if 1p<+ and 1<q<+, then H(p,q,ϕ) is reflexive.

    In Lemma 2.3, Banach space X is assumed to be reflexive. The author in [42] gave the following general result.

    Lemma 2.4. Let X, Y be Banach spaces of holomorphic functions on B. Suppose that

    (a) The point evaluation functionals on X are continuous.

    (b) The closed unit ball of X is a compact subset of X in the topology of uniform convergence on compact sets.

    (c) T:XY is continuous when X and Y are given the topology of uniform convergence on compact sets.

    Then the bounded operator T:XY is compact if and only if for every bounded sequence {fk} in X such that fk0 uniformly on compact sets as k, it follows that {Tfk} converges to zero in the norm of Y as k.

    We obtain the following result, which can be proved similar to Proposition 3.11 in [4]. However, here we prove this result by using Lemma 2.4.

    Lemma 2.5. Let 0<p,q<+, ϕ normal, and T be one of the operators in (1.4) and (1.6). Then the bounded operator T:H(p,q,ϕ)Hμ is compact if and only if for any bounded sequence {fk} in H(p,q,ϕ) such that fk0 uniformly on any compact subset of B as k, it follows that {Tfk} converges to zero in the norm of Hμ as k.

    Proof. Without lose of generality, we choose T=MuCφm to prove this result. Let X=H(p,q,ϕ) and Y=Hμ. By Remark 2.1, it is easy to see that conditions (a) and (c) in Lemma 2.4 hold (here, we would like to mention that, for an abstract bounded linear operator T:H(p,q,ϕ)Hμ, condition (c) may not be valid.)

    Let {fk} be a sequence in the closed unit ball of X. From (2.1), we see that {fk} is uniformly bounded on every compact subset of B. Therefore, by Montel's theorem, there is a subsequence {fki} such that fkig uniformly on every compact subset of B for some gH(B) as i. By the definition of Mpq(f,r) and Fatou's theorem, we have

    Mpq(g,r)=(S|g(rζ)|qdσ(ζ))pq=(Slimk|fki(rζ)|qdσ(ζ))pqlim infi(S|fki(rζ)|qdσ(ζ))pq=lim infiMpq(fki,r). (2.3)

    Hence, from (2.3) it follows that

    10Mpq(g,r)ϕp(r)1rdrlim infi10Mpq(fki,r)ϕp(r)1rdr=lim infifkiH(p,q,ϕ)=1,

    which shows that gH(p,q,ϕ), that is, condition (b) in Lemma 2.4 holds. From Lemma 2.4, the desired result follows.

    The following result was proved in [6] (also see [36]). Hence, its proof is omitted.

    Lemma 2.6. Let τ>b. Then for each t0 and fixed wB, the following function is in H(p,q,ϕ)

    fw,t(z)=(1|w|2)t+1+τϕ(|w|)(1z,w)nq+t+1+τ. (2.4)

    Moreover,

    supwBfw,tH(p,q,ϕ)1.

    We need the following result, which can be found in [30].

    Lemma 2.7. Let s>0, wB, and

    gw,s(z)=1(1z,w)s,zB.

    Then

    kgw,s(z)=kt=1a(k)t(t1j=0(s+j))z,wt(1z,w)s+t,

    where the sequences {a(k)t}t=¯1,k, kN, are defined by the relations

    a(k)k=a(k)1=1 (2.5)

    for kN and

    a(k)t=ta(k1)t+a(k1)t1 (2.6)

    for 2tk1,k3.

    We use the idea essentially obtained in [30] to construct some suitable linear combinations of the functions in Lemma 2.6, which will be used in the proofs of the main results.

    Lemma 2.8. Let mN and wB, fw,t be the set of functions in (2.4), and the sequences {a(k)t}t=¯1,k, k=¯1,m, are defined by the relations in (2.5) and (2.6). Then, for each l{1,2,...,m}, there are constants cj=c(l)j, j=¯0,m such that the function

    h(l)w(z)=mk=0c(l)kfw,k(z)

    satisfies

    jh(l)w(w)=0,0j<l, (2.7)

    and

    ih(l)w(w)=a(i)l|w|2lϕ(|w|)(1|w|2)nq+l,lim. (2.8)

    Moreover,

    supwBh(l)wH(p,q,ϕ)<+. (2.9)

    Proof. For the sake of simplicity, we write dk=nq+k+1+τ. By some calculations and using Lemma 2.7, we have

    h(l)w(w)=c0+c1++cmϕ(|w|)(1|w|2)nqh(l)w(w)=(d0c0+d1c1+dmcm)|w|2ϕ(|w|)(1|w|2)nq+12h(l)w(w)=(d0c0+d1c1++dmcm)|w|2ϕ(|w|)(1|w|2)nq+1+(d0d1c0+d1d2c1++dmdm+1cm)|w|4ϕ(|w|)(1|w|2)nq+2mh(l)w(w)=a(m)1(d0c0+d1c1++dmcm)|w|2ϕ(|w|)(1|w|2)nq+1+a(m)2(d0d1c0+d1d2c1++dmdm+1cm)|w|4ϕ(|w|)(1|w|2)nq+2++a(m)l(d0dl1c0+d1dlc1++dmdm+l1cm)|w|2lϕ(|w|)(1|w|2)nq+l++a(m)m(d0dm1c0+d1dmc1++dmd2m1cm)|w|2mϕ(|w|)(1|w|2)nq+m. (2.10)

    From (2.10), we obtain that the system consists of (2.7) and (2.8) is equivalent to the following m+1 linear equations

    (111d0d1dml1k=0dkl1k=0dk+1l1k=0dm+km1k=0dkm1k=0dk+1m1k=0dm+k)(c0c1clcm)=(0010). (2.11)

    Since dk>0, k=¯0,m, by Lemma 5 in [35], the determinant of system (2.11) is Dm+1(d0)=mj=1j!, which is different from zero. Hence, there are unique constants cj=c(l)j, j=¯0,m such that the system (2.11) holds. Moreover, we have that the relations in (2.7) and (2.8) hold when such obtained constants cj, j=¯0,m, are used in (2.11). Finally, by Lemma 2.6, it is clear that (2.9) holds. The proof is finished.

    Lemma 2.9. Let mN and wB, fw,t be the set of functions in (2.4), and the sequences {a(k)t}t=¯1,k, k=¯1,m, are defined by the relations in (2.5) and (2.6). Then, there are constants cj=c(0)j, j=¯0,m, such that the function

    h(0)w(z)=mk=0c(0)kfw,k(z)

    satisfies

    ih(0)w(w)=0,i=¯1,m, (2.12)

    and

    h(0)w(w)=1ϕ(|w|)(1|w|2)nq. (2.13)

    Moreover,

    supwBh(0)wH(p,q,ϕ)<+. (2.14)

    Proof. From the proof of Lemma 2.8, we know that the determinant of system consists of (2.12) and (2.13) is not zero. Therefore, there are unique constants c(0)j, j=¯0,m, in the system of (2.12) and (2.13). For the same reason, we also have that the relations in (2.12) and (2.13) hold, and moreover, (2.14) holds.

    First, we need to characterize the boundedness of the operator 0u,φ:H(p,q,ϕ)Hμ. Although it is a folklore, we still give a proof for the completeness and benefit of the reader.

    Theorem 3.1. Let 0<p,q<+, ϕ normal, uH(B), φS(B) and μ a weight function on B. Then the operator 0u,φ:H(p,q,ϕ)Hμ is bounded if and only if

    I0:=supzBμ(z)|u(z)|ϕ(|φ(z)|)(1|φ(z)|2)nq<+. (3.1)

    Moreover, if the operator 0u,φ:H(p,q,ϕ)Hμ is bounded, then the following asymptotic relationship holds

    0u,φH(p,q,ϕ)HμI0. (3.2)

    Proof. Assume (3.1) holds. By Lemma 2.1, for every fH(p,q,ϕ) and zB, we have

    μ(z)|0u,φf(z)|=μ(z)|u(z)f(φ(z))|Cμ(z)|u(z)|ϕ(|φ(z)|)(1|φ(z)|2)nqfH(p,q,ϕ). (3.3)

    By taking the supremum in inequality (3.3) over the unit ball in the space H(p,q,ϕ), and using (3.1), we obtain that the operator 0u,φ:H(p,q,ϕ)Hμ is bounded. Moreover, we have

    0u,φH(p,q,ϕ)HμCI0. (3.4)

    Assume that the operator 0u,φ:H(p,q,ϕ)Hμ is bounded. Let gw(z)=fφ(w),1(z) and wB. Then we have

    L:=supwBgwH(p,q,ϕ)<+,

    and

    0u,φgwHμ=supzBμ(z)|0u,φgw(z)|μ(w)|u(w)gw(φ(w))|=μ(w)|u(w)|ϕ(|φ(w)|)(1|φ(w)|2)nq. (3.5)

    From (3.5) and the boundedness of the operator 0u,φ:H(p,q,ϕ)Hμ, we have

    L0u,φH(p,q,ϕ)HμsupzBμ(z)|u(z)|ϕ(|φ(z)|)(1|φ(z)|2)nq. (3.6)

    From (3.6), condition (3.1) follows, and moreover,

    I0L0u,φH(p,q,ϕ)Hμ. (3.7)

    Also (3.4) and (3.7) imply asymptotic relationship (3.2), finishing the proof.

    Remark 3.1. When kN, from [32] it follows that the operator ku,φ:H(p,q,ϕ)Hμ is bounded if and only if

    Ik:=supzBμ(z)|u(z)||φ(z)|ϕ(|φ(z)|)(1|φ(z)|2)nq+k<+.

    Now, we consider the boundedness of the operator Smu,φ:H(p,q,ϕ)Hμ.

    Theorem 3.2. Let mN, 0<p,q<+, ϕ normal, ujH(B), j=¯0,m, φS(B) and μ a weight function on B. Then the operators juj,φ:H(p,q,ϕ)Hμ, j=¯0,m, are bounded if and only if the operator Smu,φ:H(p,q,ϕ)Hμ is bounded and

    supzBμ(z)|uj(z)||φ(z)|<+,j=¯1,m. (3.8)

    Proof. Assume that the operators juj,φ:H(p,q,ϕ)Hμ, j=¯0,m, are bounded, then the operator Smu,φ:H(p,q,ϕ)Hμ is obviously bounded. By using the functions fi(z)=ziH(p,q,ϕ), i=¯1,n, we have that juj,φfiH(p,q,ϕ), i=¯1,n. From this and since fi=fi, i=¯1,n, we have

    juj,φfiHμ=supzBμ(z)|uj(z)||φi(z)|juj,φH(p,q,ϕ)HμziH(p,q,ϕ),

    which shows that

    supzBμ(z)|uj(z)||φ(z)|juj,φH(p,q,ϕ)Hμni=1ziH(p,q,ϕ)<+. (3.9)

    From (3.9), we have that (3.8) holds.

    Assume that the operator Smu,φ:H(p,q,ϕ)Hμ is bounded and (3.8) holds. Then there exists a positive constant C such that

    Smu,φfHμCfH(p,q,ϕ) (3.10)

    for each fH(p,q,ϕ). By Theorem 3.1 and Remark 3.1, we need to prove

    Mj=supzBμ(z)|uj(z)||φ(z)|ϕ(|φ(z)|)(1|φ(z)|2)nq+j<+,j=¯1,m, (3.11)

    and

    M0=supzBμ(z)|u0(z)|ϕ(|φ(z)|)(1|φ(z)|2)nq<+. (3.12)

    By Lemma 2.8, if φ(w)0, then there is a function h(m)φ(w)H(p,q,ϕ) such that

    ih(m)φ(w)(φ(w))=0,0i<m, (3.13)

    and

    mh(m)φ(w)(φ(w))=a(m)m|φ(w)|2mϕ(|φ(w)|)(1|φ(w)|2)nq+m. (3.14)

    Let Lm=supwBh(m)φ(w)H(p,q,ϕ). Then Lm<+. From this, (3.10), (3.13) and (3.14), we have that

    LmSmu,φH(p,q,ϕ)HμSmu,φh(m)φ(w)Hμ=supzBμ(z)|mj=0juj,φh(m)φ(w)(z)|μ(w)|mj=0uj(w)jh(m)φ(w)(φ(w))|μ(w)|um(w)mh(m)φ(w)(φ(w))|=μ(w)|um(w)||φ(w)|2mϕ(|φ(w)|)(1|φ(w)|2)nq+m. (3.15)

    From (3.15), we have

    LmSmu,φH(p,q,ϕ)Hμsup|φ(z)|>1/2μ(z)|um(z)||φ(z)|2mϕ(|φ(z)|)(1|φ(z)|2)nq+m122m1sup|φ(z)|>1/2μ(z)|um(z)||φ(z)|ϕ(|φ(z)|)(1|φ(z)|2)nq+m. (3.16)

    From (3.16) and (3.8) with j=m, since ϕ is normal, we have

    sup|φ(z)|1/2μ(z)|um(z)||φ(z)|ϕ(|φ(z)|)(1|φ(z)|2)nq+m(4/3)nq+mmax|z|1/2ϕ(|z|)sup|φ(z)|1/2μ(z)|um(z)||φ(z)|(4/3)nq+mmax|z|1/2ϕ(|z|)supzBμ(z)|um(z)||φ(z)|<+. (3.17)

    From (3.16) and (3.17), it follows that Mm<+.

    Assume that (3.11) holds for j=¯s+1,m, for some s{1,2,,m1}. By using the function h(s)φ(w)(z) in Lemma 2.8, we have Ls:=supwBh(s)φ(w)H(p,q,ϕ)<+ and

    LsSmu,φH(p,q,ϕ)HμsupzBμ(z)|mj=suj(z)jh(s)φ(w)(φ(z))|μ(w)|mj=sa(j)suj(w)|φ(w)|2sϕ(|φ(w)|)(1|φ(w)|2)nq+s|a(s)sμ(w)|us(w)||φ(w)|2sϕ(|φ(w)|)(1|φ(w)|2)nq+smj=s+1a(j)sμ(w)|uj(w)||φ(w)|2sϕ(|φ(w)|)(1|φ(w)|2)nq+s,

    from which along with (2.5) we obtain

    μ(w)|us(w)||φ(w)|2sϕ(|φ(w)|)(1|φ(w)|2)nq+sLsSmu,φH(p,q,ϕ)Hμ+mj=s+1a(j)sμ(w)|uj(w)||φ(w)|2sϕ(|φ(w)|)(1|φ(w)|2)nq+s. (3.18)

    From (3.18) and since s1, it follows that

    sup|φ(z)|>1/2μ(z)|us(z)||φ(z)|ϕ(|φ(z)|)(1|φ(z)|2)nq+s22s1sup|φ(z)|>1/2μ(z)|us(z)||φ(z)|2sϕ(|φ(z)|)(1|φ(z)|2)nq+s22s1LsSmu,φH(p,q,ϕ)Hμ+22s1mj=s+1a(j)ssup|φ(z)|>1/2μ(z)|uj(z)||φ(z)|2sϕ(|φ(z)|)(1|φ(z)|2)nq+s22s1LsSmu,φH(p,q,ϕ)Hμ+22s1mj=s+1a(j)sMj. (3.19)

    From (3.8) with j=s and (3.19), we have

    sup|φ(z)|1/2μ(z)|us(z)||φ(z)|ϕ(|φ(z)|)(1|φ(z)|2)nq+s(4/3)nq+smax|z|1/2ϕ(|z|)sup|φ(z)|1/2μ(z)|us(z)||φ(z)|(4/3)nq+smax|z|1/2ϕ(|z|)supzBμ(z)|us(z)||φ(z)|<+. (3.20)

    So, (3.19) and (3.20) imply that Ms<+. Hence, from induction it follows that for each j{1,,m}, (3.11) holds.

    By Lemma 2.9, we have that for each wB there exists a function h(0)φ(w)H(p,q,ϕ) such that

    h(0)φ(w)(φ(w))=1ϕ(|φ(w)|)(1|φ(w)|2)nq,jh(0)φ(w)(φ(w))=0,j=¯1,m, (3.21)

    and

    L0:=supwBh(0)φ(w)H(p,q,ϕ)<+.

    From this, (3.10) and (3.21), we have

    L0Smu,φH(p,q,ϕ)HμSmu,φh(0)φ(w)Hμ=supzBμ(z)|mj=0juj,φh(0)φ(w)(z)|μ(w)|mj=0uj(w)jh(0)φ(w)(φ(w))|μ(w)|u0(w)h(0)φ(w)(φ(w))|=μ(w)|u0(w)|ϕ(|φ(w)|)(1|φ(w)|2)nq. (3.22)

    Hence,

    L0Smu,φH(p,q,ϕ)HμsupzBμ(z)|u0(z)|ϕ(|φ(z)|)(1|φ(z)|2)nq. (3.23)

    From (3.23), we see that (3.12) holds. This completes the proof.

    From Theorem 3.2 and (1.5), we obtain the following result.

    Corollary 3.1. Let mN, 0<p,q<+, ϕ normal, uH(B), φS(B) and μ a weight function on B. Then the operators M(mju)φCφj:H(p,q,ϕ)Hμ, j=¯0,m, are bounded if and only if the operator CφmMu:H(p,q,ϕ)Hμ is bounded and

    supzBμ(z)|mju(φ(z))||φ(z)|<+,j=¯1,m. (3.24)

    Remark 3.2. When kN, the author in [32] proved that the operator ku,φ:H(p,q,ϕ)Hμ is compact if and only if ku,φ:H(p,q,ϕ)Hμ is bounded and

    lim|φ(z)|1μ(z)|u(z)||φ(z)|ϕ(|φ(z)|)(1|φ(z)|2)nq+k=0.

    Here, we need to characterize the compactness of the operator 0u,φ:H(p,q,ϕ)Hμ.

    Theorem 3.3. Let 0<p,q<+, ϕ normal, uH(B), φS(B) and μ a weight function on B. Then the operator 0u,φ:H(p,q,ϕ)Hμ is compact if and only if 0u,φ:H(p,q,ϕ)Hμ is bounded and

    lim|φ(z)|1μ(z)|u(z)|ϕ(|φ(z)|)(1|φ(z)|2)nq=0. (3.25)

    Proof. Suppose that the operator 0u,φ:H(p,q,ϕ)Hμ is compact. Then, it is bounded. If φ<1, then (3.25) holds. Let φ=1 and {zi}iN be a sequence in B such that |φ(zi)|1 as i, and hi(z)=fφ(zi),1(z), where fw,t is defined in Lemma 2.6. Then supiNhiH(p,q,ϕ)<+. Since limi(1|φ(zi)|2)t+1+τ=0, we see that hi0 uniformly on compact subsets of B as i. Hence, by Lemma 2.5 we have

    limi0u,φhiHμ=0. (3.26)

    On the other hand, by (3.5), we see that sufficiently large i

    μ(zi)|u(zi)|ϕ(|φ(zi)|)(1|φ(zi)|2)nqC0u,φhiHμ. (3.27)

    Letting i in (3.27) and using (3.26), equality (3.25) follows.

    Assume that the operator 0u,φ:H(p,q,ϕ)Hμ is bounded and (3.25) holds. By using the function f(z)1, we obtain that

    ˆM:=supzBμ(z)|u(z)|0u,φH(p,q,ϕ)Hμ1H(p,q,ϕ)<+. (3.28)

    From (3.25), we have that for each ε>0 there is a δ(0,1) such that

    μ(z)|u(z)|ϕ(|φ(z)|)(1|φ(z)|2)nq<ε (3.29)

    on the set {zB:δ<|φ(z)|<1}. Suppose that {fi} is a sequence such that supiNfiH(p,q,ϕ)M, and fi0 uniformly on compacts of B as i. Then, by Lemma 2.1 and using (3.28) and (3.29), we have

    0u,φfiHμ=supzBμ(z)|u(z)0fi(φ(z))|supzKμ(z)|u(z)fi(φ(z))|+supzBKμ(z)|u(z)fi(φ(z))|supzKμ(z)|u(z)||fi(φ(z))|+CfiH(p,q,ϕ)supzBKμ(z)|u(z)|ϕ(|φ(z)|)(1|φ(z)|2)nqˆMsup|z|δ|fi(z)|+CMε, (3.30)

    where K={zB:|φ(z)|δ}. Since {z:|z|δ} is a compact subset of B and fi0 uniformly on compacts of B as i, we have

    limi0u,φfiHμ=0. (3.31)

    From (3.31) and Lemma 2.5, it follows that the operator 0u,φ:H(p,q,ϕ)Hμ is compact.

    Next, we characterize the compactness of the operator Smu,φ:H(p,q,ϕ)Hμ.

    Theorem 3.4. Let mN, 0<p,q<+, ϕ normal, ujH(B), j=¯0,m, φS(B) and μ a weight function on B. Then the operator Smu,φ:H(p,q,ϕ)Hμ is compact and (3.8) holds if and only if the operators juj,φ:H(p,q,ϕ)Hμ are compact for j=¯0,m.

    Proof. Assume that every operator juj,φ:H(p,q,ϕ)Hμ is compact, then we have that the operator Smu,φ:H(p,q,ϕ)Hμ is clearly compact. Furthermore, from Theorem 3.2 it follows that (3.8) holds.

    Now, assume that the operator Smu,φ:H(p,q,ϕ)Hμ is compact and (3.8) holds. Then the operator Smu,φ:H(p,q,ϕ)Hμ is bounded. In order to prove the operator juj,φ:H(p,q,ϕ)Hμ is compact, from Remark 3.2 and Theorem 3.3, we only need to prove

    lim|φ(z)|1μ(z)|uj(z)||φ(z)|ϕ(|φ(z)|)(1|φ(z)|2)nq+j=0,j=¯1,m, (3.32)

    and

    lim|φ(z)|1μ(z)|u0(z)|ϕ(|φ(z)|)(1|φ(z)|2)nq=0. (3.33)

    If φ<1, then (3.32) and (3.33) are obviously true. Hence, assume that φ=1. Let {zk}kN be a sequence in B such that |φ(zk)|1 as k, and h(s)k(z)=h(s)φ(zk)(z), where h(s)w is defined in Lemma 2.8 for a fixed s{1,2,,m}. Then, we have supkNh(s)kH(p,q,ϕ)<+. Since limk(1|φ(zk)|2)t+1+τ=0, we see that h(s)k0 uniformly on any compact subset of B as k. Hence, by Lemma 2.5 we have

    limkSmu,φh(s)kHμ=0. (3.34)

    On the other hand, from (3.15) we have that for sufficiently large k

    μ(zk)|um(zk)||φ(zk)|ϕ(|φ(zk)|)(1|φ(zk)|2)nq+mCSmu,φh(m)kHμ. (3.35)

    Letting k in (3.35) and using (3.34) with s=m, then we obtain that (3.32) holds for j=m.

    Now, suppose that (3.32) holds for j=¯s+1,m, for some sN. Then, from (3.18), we easily have that

    μ(zk)|us(zk)||φ(zk)|ϕ(|φ(zk)|)(1|φ(zk)|2)nq+sSmu,φh(s)kH(p,q,ϕ)Hμ+mj=s+1μ(zk)|uj(zk)||φ(zk)|ϕ(|φ(zk)|)(1|φ(zk)|2)nq+j (3.36)

    for sufficiently large k. Letting k in (3.36), using (3.34) and the induction hypothesis, we have that (3.32) holds for j=s, from which by induction it follows that (3.32) holds for each s{1,2,,m}.

    Let h(0)k(z)=h(0)φ(zk)(z), where h(0)w is defined in Lemma 2.9. Then we have that supkNh(0)kH(p,q,ϕ)<+ and h(0)k0 uniformly on any compact subset of B as k. Hence, by Lemma 2.5 we have

    limkSmu,φh(0)kHμ=0. (3.37)

    From (3.22), for sufficiently large k it follows that

    μ(zk)|u0(zk)|ϕ(|φ(zk)|)(1|φ(zk)|2)nqCSmu,φh(0)kHμ. (3.38)

    Letting k in (3.38) and using (3.37), (3.33) follows. The proof is finished.

    We also have the following result.

    Corollary 3.2. Let mN, 0<p,q<+, ϕ normal, uH(B), φS(B) and μ a weight function on B. Then the operator CφmMu:H(p,q,ϕ)Hμ is compact and (3.24) holds if and only if the operators M(mju)φCφj:H(p,q,ϕ)Hμ, j=¯0,m, are compact.

    In this section, we estimate the essential norm of Smu,φ:H(p,q,ϕ)Hμ. Let us recall the definition of the essential norm of the bounded linear operators. Assume that X and Y are Banach spaces and T:XY is a bounded linear operator, then the essential norm of the operator T:XY is defined by

    Te,XY=inf{TKXY:KK},

    where K denotes the set of all compact linear operators from X to Y. It is easy to see that Te,XY=0 if and only if the bounded operator T:XY is compact.

    Theorem 4.1. Let mN, 1p<+, 1<q<+, ujH(B), j=¯0,m, φS(B), ϕ normal, μ a weight function on B and (3.8) hold. If the operator Smu,φ:H(p,q,ϕ)Hμ is bounded, then

    Smu,φe,H(p,q,ϕ)Hμlim sup|φ(z)|1(μ(z)|u0(z)|ϕ(|φ(z)|)(1|φ(z)|2)nq+mj=1μ(z)|uj(z)||φ(z)|ϕ(|φ(z)|)(1|φ(z)|2)nq+j).

    Proof. Assume that {zi}iN is a sequence in B such that |φ(zi)|1 as i. Take the function h(s)i=h(s)φ(zi), where h(s)w is defined in Lemma 2.8 for a fixed s{1,2,,m}. Then we have supiNh(s)iH(p,q,ϕ)<+ and h(s)i0 uniformly on compacts of B as i. Hence, by Lemma 2.3 and Remark 2.2 we have Kh(s)iH(p,q,ϕ)0 as i. Thus, from (3.15) it follows that

    Smu,φKH(p,q,ϕ)Hμ=suphH(p,q,ϕ)=1(Smu,φK)hHμlim supi(Smu,φK)h(m)iHμh(m)iH(p,q,ϕ)lim supiSmu,φh(m)iHμKh(m)iHμh(m)iH(p,q,ϕ)lim supiμ(zi)|um(zi)||φ(zi)|ϕ(|φ(zi)|)(1|φ(zi)|2)nq+m.

    From induction and combining these inequalities, it follows that

    Smu,φKH(p,q,ϕ)Hμlim supimj=1μ(zi)|uj(zi)||φ(zi)|ϕ(|φ(zi)|)(1|φ(zi)|2)nq+j. (4.1)

    Take the function h(0)i=h(0)φ(zi), where h(0)w is defined in Lemma 2.9. Then we have that supiNh(0)iH(p,q,ϕ)<+, and h(0)i0 uniformly on compacts of B as i. Then from (3.22), we have

    Smu,φKH(p,q,ϕ)Hμlim supiμ(zi)|u0(zi)|ϕ(|φ(zi)|)(1|φ(zi)|2)nq. (4.2)

    By taking the infimum in (4.1) and (4.2) over the set of all compact operators K:H(p,q,ϕ)Hμ, we have

    Smu,φe,H(p,q,ϕ)Hμlim sup|φ(zi)|1(μ(zi)|u0(zi)|ϕ(|φ(zi)|)(1|φ(zi)|2)nq+mj=1μ(zi)|uj(zi)||φ(zi)|ϕ(|φ(zi)|)(1|φ(zi)|2)nq+j).

    Now, assume that {ri}iN is a positive sequence which increasingly converges to 1. For each ri, we define the operator by

    Smu,riφ=mj=0juj,riφ.

    Since the operator Smu,φ:H(p,q,ϕ)Hμ is bounded, by Theorem 3.2 one can obtain that the operator Smu,riφ:H(p,q,ϕ)Hμ is bounded. Since |riφ(z)|ri<1, by Lemma 2.5 the operator Smu,riφ:H(p,q,ϕ)Hμ is also compact. Hence, from Lemmas 2.1 and 2.2, we have

    Smu,φSmu,riφH(p,q,ϕ)Hμ=supfH(p,q,ϕ)=1(Smu,φSmu,riφ)fHμ=supfH(p,q,ϕ)=1supzBμ(z)|mj=0juj,φfmj=0juj,riφf|supfH(p,q,ϕ)=1supzBmj=0μ(z)|uj(z)||jf(φ(z))jf(riφ(z))|supfH(p,q,ϕ)=1sup|φ(z)|δmj=0μ(z)|uj(z)||jf(φ(z))jf(riφ(z))|+supfH(p,q,ϕ)=1sup|φ(z)|>δmj=0μ(z)|uj(z)||jf(φ(z))jf(riφ(z))|supfH(p,q,ϕ)=1sup|φ(z)|δmj=0μ(z)|uj(z)||jf(φ(z))jf(riφ(z))|+sup|φ(z)|>δ(μ(z)|u0(z)|ϕ(|φ(z)|)(1|φ(z)|2)nq+mj=1μ(z)|uj(z)||φ(z)|ϕ(|φ(z)|)(1|φ(z)|2)nq+j)+sup|φ(z)|>δ(μ(z)|u0(z)|ϕ(|riφ(z)|)(1|riφ(z)|2)nq+mj=1μ(z)|uj(z)||riφ(z)|ϕ(|riφ(z)|)(1|riφ(z)|2)nq+j). (4.3)

    For each fH(B) and |φ(z)|δ, we have

    |f(φ(z))f(riφ(z))|=|f(φ1(z),φ2(z),,φn(z))f(riφ1(z),riφ2(z),,riφn(z))|nk=1|f(riφ1(z),,riφk1(z),φk(z),φk+1(z),φn(z))f(riφ1(z),,riφk1(z),riφk(z),φk+1(z),φn(z))|=nk=1|(1ri)φk(z)10fzk(riφ1(z),,riφk1(z),θk(t),φk+1(z),φn(z))dt|(1ri)nk=110|fzk(riφ1(z),,riφk1(z),θk(t),φk+1(z),φn(z))|dt(1ri)nk=1sup|w|δ|fzk(w)|C(1ri), (4.4)

    where θk(t)=(1t)riφk(z)+tφk(z). Let g=j1f, j=¯1,m, from (4.4) and |φ(z)|δ, we have that

    |jf(φ(z))jf(riφ(z))||g(φ(z))g(riφ(z))||φ(z)|(1ri)|φ(z)|nk=1sup|w|δ|gzk(w)|C(1ri)|φ(z)|. (4.5)

    By letting i in (4.3), from (3.8), (3.28), (4.4) and (4.5), we obtain

    Smu,φSmu,riφH(p,q,ϕ)Hμsup|φ(z)|>δ(μ(z)|u0(z)|ϕ(|φ(z)|)(1|φ(z)|2)nq+mj=1μ(z)|uj(z)||φ(z)|ϕ(|φ(z)|)(1|φ(z)|2)nq+j)

    as i. Since

    Smu,φe,H(p,q,ϕ)HμSmu,φSmu,riφH(p,q,ϕ)Hμ,

    we finish the proof.

    From Theorem 4.1 and (1.5), we obtain the following result.

    Corollary 4.1. Let mN, 1p<+, 1<q<+, ϕ normal, uH(B), φS(B), μ a weight function on B and (3.24) hold. If the operator CφmMu:H(p,q,ϕ)Hμ is bounded, then

    CφmMue,H(p,q,ϕ)Hμlim sup|φ(z)|1(μ(z)|mu(φ(z))|ϕ(|φ(z)|)(1|φ(z)|2)nq+mj=1μ(z)|mju(φ(z))||φ(z)|ϕ(|φ(z)|)(1|φ(z)|2)nq+j).

    In this section, we calculate Hilbert-Schmidt norm of the operator Smu,φ:A2αA2α. For some related results, one can see [37,43]. If H is a separable Hilbert space, then the Hilbert-Schmidt norm THS,HH of an operator T:HH is defined by

    THS,HH=(n=1Ten2)12, (5.1)

    where {en}nN is an orthonormal basis on H. The right-hand side in (5.1) does not depend on the choice of basis. Hence, we have that THS,HHTHH the operator norm.

    Theorem 5.1. Let mN and α>1. Then Hilbert-Schmidt norm of the operator Smu,φ on A2α is

    Smu,φHS,A2αA2α=(mj=0B|uj(z)|2(j1(1ni=1wi)n+α+1)|wi=|φi(z)|2dvα(z))12.

    Proof. From Proposition 1.4.9 in [23] (or Lemma 1.11 in [48]), for each multi-index β=(β1,,βn), we have

    B|zβ|2dvα(z)=β!Γ(n+α+1)Γ(n+|β|+α+1),

    where β!=β1!βn!, and

    Bzβzγdvα(z)=0,βγ.

    From this, we have that the vectors

    eβ(z)=Γ(n+|β|+α+1)β!Γ(n+α+1)zβ

    form an orthonormal basis in A2α. By using the definition of the Hilbert-Schmidt norm and the monotone convergence theorem, we have

    Smu,φ2HS,A2αA2α=βSmu,φeβ2A2α=βΓ(n+|β|+α+1)β!Γ(n+α+1)Smu,φzβ2A2α=βΓ(n+|β|+α+1)β!Γ(n+α+1)mj=0|β|jB|uj(z)|2ni=1|φi(z)|2βidvα(z)=mj=0B|uj(z)|2β|β|jΓ(n+|β|+α+1)β!Γ(n+α+1)ni=1|φi(z)|2βidvα(z). (5.2)

    For each fH(B), by using the Taylor expansion

    f(z)=|β|0aβzβ,

    and taking the jth radial derivatives, we have

    jf(z)=|β|0|β|jaβzβ, (5.3)

    where β=(β1,β2,,βn) is a multi-index, |β|=β1++βn and zβ=zβ11zβnn.

    On the other hand, from Proposition 1.14 in [48] (also see [32]), we have

    (1ni=1wi)(n+α+1)=lΓ(n+α+|l|+1)l!Γ(n+α+1)ni=1wlii. (5.4)

    Hence, from (5.3) and (5.4), we have

    j1(1ni=1wi)n+α+1=l|l|jΓ(n+α+|l|+1)l!Γ(n+α+1)ni=1wlii. (5.5)

    From (5.2) and (5.5), the desired result follows.

    From Theorem 5.1 and (1.5), we obtain the following result.

    Corollary 5.1. Let mN and α>1. Then Hilbert-Schmidt norm of the operator CφmMu on A2α is

    CφmMuHS,A2αA2α=(mj=0B|mju(φ(z))|2(j1(1ni=1wi)n+α+1)|wi=|φi(z)|2dvα(z))12.

    In this paper, we define the operator Smu,φ=mj=0MujCφj on some subspaces of H(B), where ujH(B),j{0,1,,m} and φS(B). We completely characterized the boundedness and compactness of the operator Smu,φ:H(p,q,ϕ)Hμ in terms of the behaviours of the symbols uj and φ. In order to study the essential norm estimate of the operator Smu,φ:H(p,q,ϕ)Hμ, we considered the conditions for the reflexivity of H(p,q,ϕ). By using a criterion of the compactness for a bounded linear operator T:XY, where X is a reflexive Banach space of holomorphic functions on B and Y is any Banach space, we obtained the essential norm estimate of the operator Smu,φ:H(p,q,ϕ)Hμ. Moreover, we also calculated the Hilbert-Schmidt norm of the operator on the weighted Bergman space A2α. As an application, the corresponding results of the operator CφmMu:H(p,q,ϕ)Hμ are obtained. This paper can be viewed as a continuation and extension of our previous work. We hope that this study can attract people's more attention for such operators and mixed-norm spaces.

    This work was supported by the Innovation Fund of Postgraduate, Sichuan University of Science and Engineering (Y2021098) and the Key Project of Zigong City (2020YGJC24).

    The authors declare that they have no competing interests.



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