Let uj be the holomorphic functions on the open unit ball B in Cn, j=¯0,m, φ a holomorphic self-map of B, and ℜj the jth iterated radial derivative operator. In this paper, the boundedness and compactness of the sum operator Sm→u,φ=∑mj=0MujCφℜj from the mixed-norm space H(p,q,ϕ), where 0<p,q<+∞, and ϕ is normal, to the weighted-type space H∞μ are characterized. For the mixed-norm space H(p,q,ϕ), 1≤p<+∞, 1<q<+∞, the essential norm estimate of the operator is given, and the Hilbert-Schmidt norm of the operator on the weighted Bergman space A2α is also calculated.
Citation: Cheng-shi Huang, Zhi-jie Jiang, Yan-fu Xue. Sum of some product-type operators from mixed-norm spaces to weighted-type spaces on the unit ball[J]. AIMS Mathematics, 2022, 7(10): 18194-18217. doi: 10.3934/math.20221001
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Let uj be the holomorphic functions on the open unit ball B in Cn, j=¯0,m, φ a holomorphic self-map of B, and ℜj the jth iterated radial derivative operator. In this paper, the boundedness and compactness of the sum operator Sm→u,φ=∑mj=0MujCφℜj from the mixed-norm space H(p,q,ϕ), where 0<p,q<+∞, and ϕ is normal, to the weighted-type space H∞μ are characterized. For the mixed-norm space H(p,q,ϕ), 1≤p<+∞, 1<q<+∞, the essential norm estimate of the operator is given, and the Hilbert-Schmidt norm of the operator on the weighted Bergman space A2α is also calculated.
Let N={1,2,3,…}, N0=N∪{0}, B(a,r)={z∈Cn:|z−a|<r} the open ball in the complex vector space Cn centered at a with radius r, Bn=B=B(0,1), S the boundary of B and n∈N. Let z=(z1,z2,…,zn) and w=(w1,w2,…,wn) be two points in Cn, then ⟨z,w⟩=z1¯w1+z2¯w2+⋯+zn¯wn and |z|2=⟨z,z⟩.
Let H(B) be the set of all holomorphic functions on B and S(B) the set of all holomorphic self-maps of B. If φ∈S(B), then by Cφf(z)=f(φ(z)), z∈B, is defined a operator, usually called the composition operator. If u∈H(B), then by Muf(z)=u(z)f(z), z∈B, is defined a operator, usually called the multiplication operator.
When n=1, the open unit ball B is reduced to the open unit disk D. Let m∈N0, the mth differentiation operator Dm on some subspaces of H(D) is defined by
Dmf(z)=f(m)(z), |
where f(0)=f. If m=1, it is the classical differentiation operator, denoted by D. There have been a lot of studies on the products related to one of the differentiation operators. For example, products DCφ and CφD were first studied (see, for example, [5,15,16,17,18,22,33,34,35]) containing the differentiation operator. What followed was the following six products of the operators were studied (see, for example, [25,40,41])
DMuCφ,DCφMu,CφDMu,CφMuD,MuCφD,MuDCφ. | (1.1) |
Afterwards, operators in (1.1) were studied in terms of replacing D by Dm (see, for example, [9,10,44]), that is, the following six products of the operators were studied
DmMuCφ,DmCφMu,CφDmMu,CφMuDm,MuCφDm,MuDmCφ. | (1.2) |
For some other products of the operators containing differentiation operators can be found in [11,12,29,46] and the related references therein.
There are other ways to extend differentiation operators on domains in Cn. For example, the radial derivative operator
ℜf(z)=n∑j=1zj∂f∂zj(z) |
is one of natural extensions of the differentiation operators. The products of the composition, multiplication, and radial derivative operators
MuCφℜ,CφℜMu,CφMuℜ,ℜMuCφ,MuℜCφ,ℜCφMu | (1.3) |
were studied in [19,20,21,47]. Operators MuCφℜ and ℜMuCφ were also studied in [8]. Operators in (1.3) naturally generalize operators in (1.1) from the unit disk setting to the unit ball setting. Recently, they have been continuously studied in [45]. Some other products of the operators containing the radial derivative operators can be found, for example, in [31,49].
An advantage of the radial derivative operator is that it can be employed iteratively, that is, if ℜm−1f is defined for some m∈N∖{1}, then ℜmf is naturally defined by ℜmf=ℜ(ℜm−1f). If m=0, then we regard that ℜ0f=f. By using the mth iterated radial derivative operator, we obtain the related product-type operators
MuCφℜm,CφℜmMu,CφMuℜm,ℜmMuCφ,MuℜmCφ,ℜmCφMu. | (1.4) |
Operators in (1.4) are more complicated than those in (1.3). Clearly, the operator MuCφℜm can be regarded as the simplest one in (1.4), which was first studied and denoted by ℜmu,φ in [32]. Recently, we have been reconsidered such operator in [38,39]. The reason why we consider the operator ℜmu,φ again is that we need to get more information on the related function spaces in order to characterize its properties.
Operators in (1.4) generalize operators in (1.2) from the unit disk case to the unit ball case. For the unit disk case, by using the famous Faà di Bruno's formula of (f∘φ)(m) (see [13]), operators DmMuCφ, DmCφMu and MuDmCφ have been studied (see, for example, [9,10]). But, we don't find any result on the operators ℜmMuCφ, ℜmCφMu and MuℜmCφ. By a direct calculation, it is easy to see that
CφMuℜm=ℜmu∘φ,φandCφℜmMu=m∑i=0Cimℜi(ℜm−iu)∘φ,φ. | (1.5) |
Motivated by this interesting observation, we directly define the operator
Sm→u,φ=m∑j=0ℜjuj,φ | (1.6) |
on some subspaces of H(B), where uj∈H(B),j∈{0,1,…,m} and φ∈S(B).
In this paper, the boundedness and compactness of the operator Sm→u,φ=∑mj=0ℜjuj,φ from the mixed-norm space to the weighted-type space on B are characterized. The essential norm estimate of the operator from the mixed-norm space to the weighted-type space on B is given, and the Hilbert-Schmidt norm of the operator on the weighted Hilbert-Bergman space is calculated. As corollaries, the corresponding results of the operator CφℜmMu from mixed-norm space to weighted-type space are also obtained. This study can be viewed as a continuation and extension of our previous work.
A positive continuous function ϕ on the interval [0,1) is called normal (see [28]), if there are λ∈[0,1), a and b (0<a<b) such that
ϕ(r)(1−r)ais decreasing on[λ,1),limr→1ϕ(r)(1−r)a=0;ϕ(r)(1−r)bis increasing on[λ,1),limr→1ϕ(r)(1−r)b=+∞. |
The functions {ϕ,ψ} will be called a normal pair if ϕ is normal and for b in above definition of normal function, there exists β>b, such that
ϕ(r)ψ(r)=(1−r2)β. |
If ϕ is normal, then there exists ψ such that {ϕ,ψ} is normal pair (see [28]). Note that if {ϕ,ψ} is normal pair, then ψ is also normal.
For 0<p,q<+∞ and a normal function ϕ, the mixed-norm space H(p,q,ϕ)(B):=H(p,q,ϕ) consists of all f∈H(B) such that
‖f‖pH(p,q,ϕ)=∫10Mpq(f,r)ϕp(r)1−rdr<+∞, |
where
Mq(f,r)=(∫S|f(rζ)|qdσ(ζ))1q, |
and dσ is the normalized surface measure on S.
If p=q, ϕ(r)=(1−r2)(α+1)/p and α>−1, then it is equivalent with the weighted Bergman space Apα (see [48]), which is defined by
Apα={f∈H(B):‖f‖pApα=∫B|f(z)|p(1−|z|2)αdv(z)<+∞}, |
where dv denotes the normalized volume measure on B. Some facts can be found about the mixed-norm spaces, for example, in [1,2,26,27,36] (see also the references therein).
A positive continuous function μ on B is called weight. The weighted-type space H∞μ(B):=H∞μ consists of all f∈H(B) such that
‖f‖H∞μ=supz∈Bμ(z)|f(z)|<+∞. |
With the norm ‖⋅‖H∞μ, H∞μ is a Banach space. In particular, if μ(z)=(1−|z|2)σ(σ>0), then the space H∞μ is called the classical weighted-type space H∞σ. If μ≡1, then the space H∞μ is reduced to the space H∞ of bounded holomorphic functions on B. Many operators acting from or to the weighted-type spaces have been studied (see, for example, [14,16,24,46] and the related references therein).
Let X and Y be two Banach spaces. It is said that a linear operator T:X→Y is bounded if there exists a positive constant K such that ‖Tf‖Y≤K‖f‖X for all f∈X. The bounded operator T:X→Y is compact if it maps bounded sets into relatively compact sets. The norm of the operator T:X→Y, usually denoted by ‖T‖X→Y, is defined by
‖T‖X→Y=sup‖f‖X≤1‖Tf‖Y. |
In this paper, we use the notation j=¯k,l instead of writing j=k,...,l, where k,l∈N0 and k≤l. Some positive constants are denoted by C, and they may differ from one occurrence to the other. The notation a≲b (resp. a≳b) means that there is a positive constant C such that a≤Cb (resp. a≥Cb). When a≲b and b≳a, we write a≍b.
Here, we give several lemmas which are used in the proofs of the main results. First, we have the following point-evaluation estimate for the functions in H(p,q,ϕ) (see [36]).
Lemma 2.1. Let 0<p,q<+∞ and ϕ normal. Then there is a positive constant C independent of f∈H(p,q,ϕ) and z∈B such that
|f(z)|≤Cϕ(|z|)(1−|z|2)nq‖f‖H(p,q,ϕ). | (2.1) |
Now, we cite a point-evaluation estimate for the jth iterated radial derivatives of the functions in H(p,q,ϕ) (see [32]).
Lemma 2.2. Let j∈N, 0<p,q<+∞ and ϕ normal. Then there is a positive constant C independent of f∈H(p,q,ϕ) and z∈B such that
|ℜjf(z)|≤C|z|ϕ(|z|)(1−|z|2)nq+j‖f‖H(p,q,ϕ). | (2.2) |
Remark 2.1. From (2.1) and (2.2), it follows that if {fk} is bounded in H(p,q,ϕ), then {fk} and {ℜjfk} are uniformly bounded on any compact subset of B, and if {fk} converges to zero in H(p,q,ϕ), then {fk} and {ℜjfk} converge to zero uniformly on any compact subset of B as k→∞.
To obtain a criterion for the compactness of a bounded linear operator T:H(p,q,ϕ)→H∞μ, we need to cite the following result, which can be found in [3] for the unit disk version. For the unit ball case, whose proof can be directly obtained by replacing the unit disk by the unit ball, and so the proof is omitted.
Lemma 2.3. Let X be a reflexive Banach space of holomorphic functions on B, and Y a Banach space. Then a bounded linear operator T:X→Y is compact if and only if for any bounded sequence {fk} in X such that fk→0 uniformly on any compact subset of B as k→∞, it follows that {Tfk} converges to zero in the norm of Y as k→∞.
To give the conditions such that H(p,q,ϕ) is reflexive, we recall some studies of the dual spaces of H(p,q,ϕ). Jevtić in [7] showed that the dual space of H(p,q,ϕ), where 1≤p≤+∞ and 1≤q<+∞, is topologically isomorphic to H(p′,q′,ψ), where 1/p+1/p′=1 and 1/q+1/q′=1. Shi in [27] considered the dual spaces of H(p,q,ϕ) for two cases: (i) if 0<p≤1 and 1<q≤+∞, then the dual space of H(p,q,ϕ) is topologically isomorphic to H(+∞,q′,ψ); (ii) if 0<p≤1 and 0<q≤1, then the dual space of H(p,q,ϕ) is topologically isomorphic to H(+∞,+∞,ψ).
From above facts, we obtain the following remark.
Remark 2.2. Considering the assumption 0<p,q<+∞, we see that if 1≤p<+∞ and 1<q<+∞, then H(p,q,ϕ) is reflexive.
In Lemma 2.3, Banach space X is assumed to be reflexive. The author in [42] gave the following general result.
Lemma 2.4. Let X, Y be Banach spaces of holomorphic functions on B. Suppose that
(a) The point evaluation functionals on X are continuous.
(b) The closed unit ball of X is a compact subset of X in the topology of uniform convergence on compact sets.
(c) T:X→Y is continuous when X and Y are given the topology of uniform convergence on compact sets.
Then the bounded operator T:X→Y is compact if and only if for every bounded sequence {fk} in X such that fk→0 uniformly on compact sets as k→∞, it follows that {Tfk} converges to zero in the norm of Y as k→∞.
We obtain the following result, which can be proved similar to Proposition 3.11 in [4]. However, here we prove this result by using Lemma 2.4.
Lemma 2.5. Let 0<p,q<+∞, ϕ normal, and T be one of the operators in (1.4) and (1.6). Then the bounded operator T:H(p,q,ϕ)→H∞μ is compact if and only if for any bounded sequence {fk} in H(p,q,ϕ) such that fk→0 uniformly on any compact subset of B as k→∞, it follows that {Tfk} converges to zero in the norm of H∞μ as k→∞.
Proof. Without lose of generality, we choose T=MuCφℜm to prove this result. Let X=H(p,q,ϕ) and Y=H∞μ. By Remark 2.1, it is easy to see that conditions (a) and (c) in Lemma 2.4 hold (here, we would like to mention that, for an abstract bounded linear operator T:H(p,q,ϕ)→H∞μ, condition (c) may not be valid.)
Let {fk} be a sequence in the closed unit ball of X. From (2.1), we see that {fk} is uniformly bounded on every compact subset of B. Therefore, by Montel's theorem, there is a subsequence {fki} such that fki→g uniformly on every compact subset of B for some g∈H(B) as i→∞. By the definition of Mpq(f,r) and Fatou's theorem, we have
Mpq(g,r)=(∫S|g(rζ)|qdσ(ζ))pq=(∫Slimk→∞|fki(rζ)|qdσ(ζ))pq≤lim infi→∞(∫S|fki(rζ)|qdσ(ζ))pq=lim infi→∞Mpq(fki,r). | (2.3) |
Hence, from (2.3) it follows that
∫10Mpq(g,r)ϕp(r)1−rdr≤lim infi→∞∫10Mpq(fki,r)ϕp(r)1−rdr=lim infi→∞‖fki‖H(p,q,ϕ)=1, |
which shows that g∈H(p,q,ϕ), that is, condition (b) in Lemma 2.4 holds. From Lemma 2.4, the desired result follows.
The following result was proved in [6] (also see [36]). Hence, its proof is omitted.
Lemma 2.6. Let τ>b. Then for each t≥0 and fixed w∈B, the following function is in H(p,q,ϕ)
fw,t(z)=(1−|w|2)t+1+τϕ(|w|)(1−⟨z,w⟩)nq+t+1+τ. | (2.4) |
Moreover,
supw∈B‖fw,t‖H(p,q,ϕ)≲1. |
We need the following result, which can be found in [30].
Lemma 2.7. Let s>0, w∈B, and
gw,s(z)=1(1−⟨z,w⟩)s,z∈B. |
Then
ℜkgw,s(z)=k∑t=1a(k)t(t−1∏j=0(s+j))⟨z,w⟩t(1−⟨z,w⟩)s+t, |
where the sequences {a(k)t}t=¯1,k, k∈N, are defined by the relations
a(k)k=a(k)1=1 | (2.5) |
for k∈N and
a(k)t=ta(k−1)t+a(k−1)t−1 | (2.6) |
for 2≤t≤k−1,k≥3.
We use the idea essentially obtained in [30] to construct some suitable linear combinations of the functions in Lemma 2.6, which will be used in the proofs of the main results.
Lemma 2.8. Let m∈N and w∈B, fw,t be the set of functions in (2.4), and the sequences {a(k)t}t=¯1,k, k=¯1,m, are defined by the relations in (2.5) and (2.6). Then, for each l∈{1,2,...,m}, there are constants cj=c(l)j, j=¯0,m such that the function
h(l)w(z)=m∑k=0c(l)kfw,k(z) |
satisfies
ℜjh(l)w(w)=0,0≤j<l, | (2.7) |
and
ℜih(l)w(w)=a(i)l|w|2lϕ(|w|)(1−|w|2)nq+l,l≤i≤m. | (2.8) |
Moreover,
supw∈B‖h(l)w‖H(p,q,ϕ)<+∞. | (2.9) |
Proof. For the sake of simplicity, we write dk=nq+k+1+τ. By some calculations and using Lemma 2.7, we have
h(l)w(w)=c0+c1+⋯+cmϕ(|w|)(1−|w|2)nqℜh(l)w(w)=(d0c0+d1c1+⋯dmcm)|w|2ϕ(|w|)(1−|w|2)nq+1ℜ2h(l)w(w)=(d0c0+d1c1+⋯+dmcm)|w|2ϕ(|w|)(1−|w|2)nq+1+(d0d1c0+d1d2c1+⋯+dmdm+1cm)|w|4ϕ(|w|)(1−|w|2)nq+2⋮ℜmh(l)w(w)=a(m)1(d0c0+d1c1+⋯+dmcm)|w|2ϕ(|w|)(1−|w|2)nq+1+a(m)2(d0d1c0+d1d2c1+⋯+dmdm+1cm)|w|4ϕ(|w|)(1−|w|2)nq+2+⋯+a(m)l(d0⋯dl−1c0+d1⋯dlc1+⋯+dm⋯dm+l−1cm)|w|2lϕ(|w|)(1−|w|2)nq+l+⋯+a(m)m(d0⋯dm−1c0+d1⋯dmc1+⋯+dm⋯d2m−1cm)|w|2mϕ(|w|)(1−|w|2)nq+m. | (2.10) |
From (2.10), we obtain that the system consists of (2.7) and (2.8) is equivalent to the following m+1 linear equations
(11⋯1d0d1⋯dm⋮⋮⋱⋮l−1∏k=0dkl−1∏k=0dk+1⋯l−1∏k=0dm+k⋮⋮⋱⋮m−1∏k=0dkm−1∏k=0dk+1⋯m−1∏k=0dm+k)(c0c1⋮cl⋮cm)=(00⋮1⋮0). | (2.11) |
Since dk>0, k=¯0,m, by Lemma 5 in [35], the determinant of system (2.11) is Dm+1(d0)=∏mj=1j!, which is different from zero. Hence, there are unique constants cj=c(l)j, j=¯0,m such that the system (2.11) holds. Moreover, we have that the relations in (2.7) and (2.8) hold when such obtained constants cj, j=¯0,m, are used in (2.11). Finally, by Lemma 2.6, it is clear that (2.9) holds. The proof is finished.
Lemma 2.9. Let m∈N and w∈B, fw,t be the set of functions in (2.4), and the sequences {a(k)t}t=¯1,k, k=¯1,m, are defined by the relations in (2.5) and (2.6). Then, there are constants cj=c(0)j, j=¯0,m, such that the function
h(0)w(z)=m∑k=0c(0)kfw,k(z) |
satisfies
ℜih(0)w(w)=0,i=¯1,m, | (2.12) |
and
h(0)w(w)=1ϕ(|w|)(1−|w|2)nq. | (2.13) |
Moreover,
supw∈B‖h(0)w‖H(p,q,ϕ)<+∞. | (2.14) |
Proof. From the proof of Lemma 2.8, we know that the determinant of system consists of (2.12) and (2.13) is not zero. Therefore, there are unique constants c(0)j, j=¯0,m, in the system of (2.12) and (2.13). For the same reason, we also have that the relations in (2.12) and (2.13) hold, and moreover, (2.14) holds.
First, we need to characterize the boundedness of the operator ℜ0u,φ:H(p,q,ϕ)→H∞μ. Although it is a folklore, we still give a proof for the completeness and benefit of the reader.
Theorem 3.1. Let 0<p,q<+∞, ϕ normal, u∈H(B), φ∈S(B) and μ a weight function on B. Then the operator ℜ0u,φ:H(p,q,ϕ)→H∞μ is bounded if and only if
I0:=supz∈Bμ(z)|u(z)|ϕ(|φ(z)|)(1−|φ(z)|2)nq<+∞. | (3.1) |
Moreover, if the operator ℜ0u,φ:H(p,q,ϕ)→H∞μ is bounded, then the following asymptotic relationship holds
‖ℜ0u,φ‖H(p,q,ϕ)→H∞μ≍I0. | (3.2) |
Proof. Assume (3.1) holds. By Lemma 2.1, for every f∈H(p,q,ϕ) and z∈B, we have
μ(z)|ℜ0u,φf(z)|=μ(z)|u(z)f(φ(z))|≤Cμ(z)|u(z)|ϕ(|φ(z)|)(1−|φ(z)|2)nq‖f‖H(p,q,ϕ). | (3.3) |
By taking the supremum in inequality (3.3) over the unit ball in the space H(p,q,ϕ), and using (3.1), we obtain that the operator ℜ0u,φ:H(p,q,ϕ)→H∞μ is bounded. Moreover, we have
‖ℜ0u,φ‖H(p,q,ϕ)→H∞μ≤CI0. | (3.4) |
Assume that the operator ℜ0u,φ:H(p,q,ϕ)→H∞μ is bounded. Let gw(z)=fφ(w),1(z) and w∈B. Then we have
L:=supw∈B‖gw‖H(p,q,ϕ)<+∞, |
and
‖ℜ0u,φgw‖H∞μ=supz∈Bμ(z)|ℜ0u,φgw(z)|≥μ(w)|u(w)gw(φ(w))|=μ(w)|u(w)|ϕ(|φ(w)|)(1−|φ(w)|2)nq. | (3.5) |
From (3.5) and the boundedness of the operator ℜ0u,φ:H(p,q,ϕ)→H∞μ, we have
L‖ℜ0u,φ‖H(p,q,ϕ)→H∞μ≥supz∈Bμ(z)|u(z)|ϕ(|φ(z)|)(1−|φ(z)|2)nq. | (3.6) |
From (3.6), condition (3.1) follows, and moreover,
I0≤L‖ℜ0u,φ‖H(p,q,ϕ)→H∞μ. | (3.7) |
Also (3.4) and (3.7) imply asymptotic relationship (3.2), finishing the proof.
Remark 3.1. When k∈N, from [32] it follows that the operator ℜku,φ:H(p,q,ϕ)→H∞μ is bounded if and only if
Ik:=supz∈Bμ(z)|u(z)||φ(z)|ϕ(|φ(z)|)(1−|φ(z)|2)nq+k<+∞. |
Now, we consider the boundedness of the operator Sm→u,φ:H(p,q,ϕ)→H∞μ.
Theorem 3.2. Let m∈N, 0<p,q<+∞, ϕ normal, uj∈H(B), j=¯0,m, φ∈S(B) and μ a weight function on B. Then the operators ℜjuj,φ:H(p,q,ϕ)→H∞μ, j=¯0,m, are bounded if and only if the operator Sm→u,φ:H(p,q,ϕ)→H∞μ is bounded and
supz∈Bμ(z)|uj(z)||φ(z)|<+∞,j=¯1,m. | (3.8) |
Proof. Assume that the operators ℜjuj,φ:H(p,q,ϕ)→H∞μ, j=¯0,m, are bounded, then the operator Sm→u,φ:H(p,q,ϕ)→H∞μ is obviously bounded. By using the functions fi(z)=zi∈H(p,q,ϕ), i=¯1,n, we have that ℜjuj,φfi∈H(p,q,ϕ), i=¯1,n. From this and since ℜfi=fi, i=¯1,n, we have
‖ℜjuj,φfi‖H∞μ=supz∈Bμ(z)|uj(z)||φi(z)|≤‖ℜjuj,φ‖H(p,q,ϕ)→H∞μ‖zi‖H(p,q,ϕ), |
which shows that
supz∈Bμ(z)|uj(z)||φ(z)|≤‖ℜjuj,φ‖H(p,q,ϕ)→H∞μn∑i=1‖zi‖H(p,q,ϕ)<+∞. | (3.9) |
From (3.9), we have that (3.8) holds.
Assume that the operator Sm→u,φ:H(p,q,ϕ)→H∞μ is bounded and (3.8) holds. Then there exists a positive constant C such that
‖Sm→u,φf‖H∞μ≤C‖f‖H(p,q,ϕ) | (3.10) |
for each f∈H(p,q,ϕ). By Theorem 3.1 and Remark 3.1, we need to prove
Mj=supz∈Bμ(z)|uj(z)||φ(z)|ϕ(|φ(z)|)(1−|φ(z)|2)nq+j<+∞,j=¯1,m, | (3.11) |
and
M0=supz∈Bμ(z)|u0(z)|ϕ(|φ(z)|)(1−|φ(z)|2)nq<+∞. | (3.12) |
By Lemma 2.8, if φ(w)≠0, then there is a function h(m)φ(w)∈H(p,q,ϕ) such that
ℜih(m)φ(w)(φ(w))=0,0≤i<m, | (3.13) |
and
ℜmh(m)φ(w)(φ(w))=a(m)m|φ(w)|2mϕ(|φ(w)|)(1−|φ(w)|2)nq+m. | (3.14) |
Let Lm=supw∈B‖h(m)φ(w)‖H(p,q,ϕ). Then Lm<+∞. From this, (3.10), (3.13) and (3.14), we have that
Lm‖Sm→u,φ‖H(p,q,ϕ)→H∞μ≥‖Sm→u,φh(m)φ(w)‖H∞μ=supz∈Bμ(z)|m∑j=0ℜjuj,φh(m)φ(w)(z)|≥μ(w)|m∑j=0uj(w)ℜjh(m)φ(w)(φ(w))|≥μ(w)|um(w)ℜmh(m)φ(w)(φ(w))|=μ(w)|um(w)||φ(w)|2mϕ(|φ(w)|)(1−|φ(w)|2)nq+m. | (3.15) |
From (3.15), we have
Lm‖Sm→u,φ‖H(p,q,ϕ)→H∞μ≥sup|φ(z)|>1/2μ(z)|um(z)||φ(z)|2mϕ(|φ(z)|)(1−|φ(z)|2)nq+m≥122m−1sup|φ(z)|>1/2μ(z)|um(z)||φ(z)|ϕ(|φ(z)|)(1−|φ(z)|2)nq+m. | (3.16) |
From (3.16) and (3.8) with j=m, since ϕ is normal, we have
sup|φ(z)|≤1/2μ(z)|um(z)||φ(z)|ϕ(|φ(z)|)(1−|φ(z)|2)nq+m≤(4/3)nq+mmax|z|≤1/2ϕ(|z|)sup|φ(z)|≤1/2μ(z)|um(z)||φ(z)|≤(4/3)nq+mmax|z|≤1/2ϕ(|z|)supz∈Bμ(z)|um(z)||φ(z)|<+∞. | (3.17) |
From (3.16) and (3.17), it follows that Mm<+∞.
Assume that (3.11) holds for j=¯s+1,m, for some s∈{1,2,…,m−1}. By using the function h(s)φ(w)(z) in Lemma 2.8, we have Ls:=supw∈B‖h(s)φ(w)‖H(p,q,ϕ)<+∞ and
Ls‖Sm→u,φ‖H(p,q,ϕ)→H∞μ≥supz∈Bμ(z)|m∑j=suj(z)ℜjh(s)φ(w)(φ(z))|≥μ(w)|m∑j=sa(j)suj(w)|φ(w)|2sϕ(|φ(w)|)(1−|φ(w)|2)nq+s|≥a(s)sμ(w)|us(w)||φ(w)|2sϕ(|φ(w)|)(1−|φ(w)|2)nq+s−m∑j=s+1a(j)sμ(w)|uj(w)||φ(w)|2sϕ(|φ(w)|)(1−|φ(w)|2)nq+s, |
from which along with (2.5) we obtain
μ(w)|us(w)||φ(w)|2sϕ(|φ(w)|)(1−|φ(w)|2)nq+s≤Ls‖Sm→u,φ‖H(p,q,ϕ)→H∞μ+m∑j=s+1a(j)sμ(w)|uj(w)||φ(w)|2sϕ(|φ(w)|)(1−|φ(w)|2)nq+s. | (3.18) |
From (3.18) and since s≥1, it follows that
sup|φ(z)|>1/2μ(z)|us(z)||φ(z)|ϕ(|φ(z)|)(1−|φ(z)|2)nq+s≤22s−1sup|φ(z)|>1/2μ(z)|us(z)||φ(z)|2sϕ(|φ(z)|)(1−|φ(z)|2)nq+s≤22s−1Ls‖Sm→u,φ‖H(p,q,ϕ)→H∞μ+22s−1m∑j=s+1a(j)ssup|φ(z)|>1/2μ(z)|uj(z)||φ(z)|2sϕ(|φ(z)|)(1−|φ(z)|2)nq+s≤22s−1Ls‖Sm→u,φ‖H(p,q,ϕ)→H∞μ+22s−1m∑j=s+1a(j)sMj. | (3.19) |
From (3.8) with j=s and (3.19), we have
sup|φ(z)|≤1/2μ(z)|us(z)||φ(z)|ϕ(|φ(z)|)(1−|φ(z)|2)nq+s≤(4/3)nq+smax|z|≤1/2ϕ(|z|)sup|φ(z)|≤1/2μ(z)|us(z)||φ(z)|≤(4/3)nq+smax|z|≤1/2ϕ(|z|)supz∈Bμ(z)|us(z)||φ(z)|<+∞. | (3.20) |
So, (3.19) and (3.20) imply that Ms<+∞. Hence, from induction it follows that for each j∈{1,…,m}, (3.11) holds.
By Lemma 2.9, we have that for each w∈B there exists a function h(0)φ(w)∈H(p,q,ϕ) such that
h(0)φ(w)(φ(w))=1ϕ(|φ(w)|)(1−|φ(w)|2)nq,ℜjh(0)φ(w)(φ(w))=0,j=¯1,m, | (3.21) |
and
L0:=supw∈B‖h(0)φ(w)‖H(p,q,ϕ)<+∞. |
From this, (3.10) and (3.21), we have
L0‖Sm→u,φ‖H(p,q,ϕ)→H∞μ≥‖Sm→u,φh(0)φ(w)‖H∞μ=supz∈Bμ(z)|m∑j=0ℜjuj,φh(0)φ(w)(z)|≥μ(w)|m∑j=0uj(w)ℜjh(0)φ(w)(φ(w))|≥μ(w)|u0(w)h(0)φ(w)(φ(w))|=μ(w)|u0(w)|ϕ(|φ(w)|)(1−|φ(w)|2)nq. | (3.22) |
Hence,
L0‖Sm→u,φ‖H(p,q,ϕ)→H∞μ≥supz∈Bμ(z)|u0(z)|ϕ(|φ(z)|)(1−|φ(z)|2)nq. | (3.23) |
From (3.23), we see that (3.12) holds. This completes the proof.
From Theorem 3.2 and (1.5), we obtain the following result.
Corollary 3.1. Let m∈N, 0<p,q<+∞, ϕ normal, u∈H(B), φ∈S(B) and μ a weight function on B. Then the operators M(ℜm−ju)∘φCφℜj:H(p,q,ϕ)→H∞μ, j=¯0,m, are bounded if and only if the operator CφℜmMu:H(p,q,ϕ)→H∞μ is bounded and
supz∈Bμ(z)|ℜm−ju(φ(z))||φ(z)|<+∞,j=¯1,m. | (3.24) |
Remark 3.2. When k∈N, the author in [32] proved that the operator ℜku,φ:H(p,q,ϕ)→H∞μ is compact if and only if ℜku,φ:H(p,q,ϕ)→H∞μ is bounded and
lim|φ(z)|→1μ(z)|u(z)||φ(z)|ϕ(|φ(z)|)(1−|φ(z)|2)nq+k=0. |
Here, we need to characterize the compactness of the operator ℜ0u,φ:H(p,q,ϕ)→H∞μ.
Theorem 3.3. Let 0<p,q<+∞, ϕ normal, u∈H(B), φ∈S(B) and μ a weight function on B. Then the operator ℜ0u,φ:H(p,q,ϕ)→H∞μ is compact if and only if ℜ0u,φ:H(p,q,ϕ)→H∞μ is bounded and
lim|φ(z)|→1μ(z)|u(z)|ϕ(|φ(z)|)(1−|φ(z)|2)nq=0. | (3.25) |
Proof. Suppose that the operator ℜ0u,φ:H(p,q,ϕ)→H∞μ is compact. Then, it is bounded. If ‖φ‖∞<1, then (3.25) holds. Let ‖φ‖∞=1 and {zi}i∈N be a sequence in B such that |φ(zi)|→1 as i→∞, and hi(z)=fφ(zi),1(z), where fw,t is defined in Lemma 2.6. Then supi∈N‖hi‖H(p,q,ϕ)<+∞. Since limi→∞(1−|φ(zi)|2)t+1+τ=0, we see that hi→0 uniformly on compact subsets of B as i→∞. Hence, by Lemma 2.5 we have
limi→∞‖ℜ0u,φhi‖H∞μ=0. | (3.26) |
On the other hand, by (3.5), we see that sufficiently large i
μ(zi)|u(zi)|ϕ(|φ(zi)|)(1−|φ(zi)|2)nq≤C‖ℜ0u,φhi‖H∞μ. | (3.27) |
Letting i→∞ in (3.27) and using (3.26), equality (3.25) follows.
Assume that the operator ℜ0u,φ:H(p,q,ϕ)→H∞μ is bounded and (3.25) holds. By using the function f(z)≡1, we obtain that
ˆM:=supz∈Bμ(z)|u(z)|≤‖ℜ0u,φ‖H(p,q,ϕ)→H∞μ‖1‖H(p,q,ϕ)<+∞. | (3.28) |
From (3.25), we have that for each ε>0 there is a δ∈(0,1) such that
μ(z)|u(z)|ϕ(|φ(z)|)(1−|φ(z)|2)nq<ε | (3.29) |
on the set {z∈B:δ<|φ(z)|<1}. Suppose that {fi} is a sequence such that supi∈N‖fi‖H(p,q,ϕ)≤M, and fi→0 uniformly on compacts of B as i→∞. Then, by Lemma 2.1 and using (3.28) and (3.29), we have
‖ℜ0u,φfi‖H∞μ=supz∈Bμ(z)|u(z)ℜ0fi(φ(z))|≤supz∈Kμ(z)|u(z)fi(φ(z))|+supz∈B∖Kμ(z)|u(z)fi(φ(z))|≤supz∈Kμ(z)|u(z)||fi(φ(z))|+C‖fi‖H(p,q,ϕ)supz∈B∖Kμ(z)|u(z)|ϕ(|φ(z)|)(1−|φ(z)|2)nq≤ˆMsup|z|≤δ|fi(z)|+CMε, | (3.30) |
where K={z∈B:|φ(z)|≤δ}. Since {z:|z|≤δ} is a compact subset of B and fi→0 uniformly on compacts of B as i→∞, we have
limi→∞‖ℜ0u,φfi‖H∞μ=0. | (3.31) |
From (3.31) and Lemma 2.5, it follows that the operator ℜ0u,φ:H(p,q,ϕ)→H∞μ is compact.
Next, we characterize the compactness of the operator Sm→u,φ:H(p,q,ϕ)→H∞μ.
Theorem 3.4. Let m∈N, 0<p,q<+∞, ϕ normal, uj∈H(B), j=¯0,m, φ∈S(B) and μ a weight function on B. Then the operator Sm→u,φ:H(p,q,ϕ)→H∞μ is compact and (3.8) holds if and only if the operators ℜjuj,φ:H(p,q,ϕ)→H∞μ are compact for j=¯0,m.
Proof. Assume that every operator ℜjuj,φ:H(p,q,ϕ)→H∞μ is compact, then we have that the operator Sm→u,φ:H(p,q,ϕ)→H∞μ is clearly compact. Furthermore, from Theorem 3.2 it follows that (3.8) holds.
Now, assume that the operator Sm→u,φ:H(p,q,ϕ)→H∞μ is compact and (3.8) holds. Then the operator Sm→u,φ:H(p,q,ϕ)→H∞μ is bounded. In order to prove the operator ℜjuj,φ:H(p,q,ϕ)→H∞μ is compact, from Remark 3.2 and Theorem 3.3, we only need to prove
lim|φ(z)|→1μ(z)|uj(z)||φ(z)|ϕ(|φ(z)|)(1−|φ(z)|2)nq+j=0,j=¯1,m, | (3.32) |
and
lim|φ(z)|→1μ(z)|u0(z)|ϕ(|φ(z)|)(1−|φ(z)|2)nq=0. | (3.33) |
If ‖φ‖∞<1, then (3.32) and (3.33) are obviously true. Hence, assume that ‖φ‖∞=1. Let {zk}k∈N be a sequence in B such that |φ(zk)|→1 as k→∞, and h(s)k(z)=h(s)φ(zk)(z), where h(s)w is defined in Lemma 2.8 for a fixed s∈{1,2,…,m}. Then, we have supk∈N‖h(s)k‖H(p,q,ϕ)<+∞. Since limk→∞(1−|φ(zk)|2)t+1+τ=0, we see that h(s)k→0 uniformly on any compact subset of B as k→∞. Hence, by Lemma 2.5 we have
limk→∞‖Sm→u,φh(s)k‖H∞μ=0. | (3.34) |
On the other hand, from (3.15) we have that for sufficiently large k
μ(zk)|um(zk)||φ(zk)|ϕ(|φ(zk)|)(1−|φ(zk)|2)nq+m≤C‖Sm→u,φh(m)k‖H∞μ. | (3.35) |
Letting k→∞ in (3.35) and using (3.34) with s=m, then we obtain that (3.32) holds for j=m.
Now, suppose that (3.32) holds for j=¯s+1,m, for some s∈N. Then, from (3.18), we easily have that
μ(zk)|us(zk)||φ(zk)|ϕ(|φ(zk)|)(1−|φ(zk)|2)nq+s≲‖Sm→u,φh(s)k‖H(p,q,ϕ)→H∞μ+m∑j=s+1μ(zk)|uj(zk)||φ(zk)|ϕ(|φ(zk)|)(1−|φ(zk)|2)nq+j | (3.36) |
for sufficiently large k. Letting k→∞ in (3.36), using (3.34) and the induction hypothesis, we have that (3.32) holds for j=s, from which by induction it follows that (3.32) holds for each s∈{1,2,…,m}.
Let h(0)k(z)=h(0)φ(zk)(z), where h(0)w is defined in Lemma 2.9. Then we have that supk∈N‖h(0)k‖H(p,q,ϕ)<+∞ and h(0)k→0 uniformly on any compact subset of B as k→∞. Hence, by Lemma 2.5 we have
limk→∞‖Sm→u,φh(0)k‖H∞μ=0. | (3.37) |
From (3.22), for sufficiently large k it follows that
μ(zk)|u0(zk)|ϕ(|φ(zk)|)(1−|φ(zk)|2)nq≤C‖Sm→u,φh(0)k‖H∞μ. | (3.38) |
Letting k→∞ in (3.38) and using (3.37), (3.33) follows. The proof is finished.
We also have the following result.
Corollary 3.2. Let m∈N, 0<p,q<+∞, ϕ normal, u∈H(B), φ∈S(B) and μ a weight function on B. Then the operator CφℜmMu:H(p,q,ϕ)→H∞μ is compact and (3.24) holds if and only if the operators M(ℜm−ju)∘φCφℜj:H(p,q,ϕ)→H∞μ, j=¯0,m, are compact.
In this section, we estimate the essential norm of Sm→u,φ:H(p,q,ϕ)→H∞μ. Let us recall the definition of the essential norm of the bounded linear operators. Assume that X and Y are Banach spaces and T:X→Y is a bounded linear operator, then the essential norm of the operator T:X→Y is defined by
‖T‖e,X→Y=inf{‖T−K‖X→Y:K∈K}, |
where K denotes the set of all compact linear operators from X to Y. It is easy to see that ‖T‖e,X→Y=0 if and only if the bounded operator T:X→Y is compact.
Theorem 4.1. Let m∈N, 1≤p<+∞, 1<q<+∞, uj∈H(B), j=¯0,m, φ∈S(B), ϕ normal, μ a weight function on B and (3.8) hold. If the operator Sm→u,φ:H(p,q,ϕ)→H∞μ is bounded, then
‖Sm→u,φ‖e,H(p,q,ϕ)→H∞μ≍lim sup|φ(z)|→1(μ(z)|u0(z)|ϕ(|φ(z)|)(1−|φ(z)|2)nq+m∑j=1μ(z)|uj(z)||φ(z)|ϕ(|φ(z)|)(1−|φ(z)|2)nq+j). |
Proof. Assume that {zi}i∈N is a sequence in B such that |φ(zi)|→1 as i→∞. Take the function h(s)i=h(s)φ(zi), where h(s)w is defined in Lemma 2.8 for a fixed s∈{1,2,…,m}. Then we have supi∈N‖h(s)i‖H(p,q,ϕ)<+∞ and h(s)i→0 uniformly on compacts of B as i→∞. Hence, by Lemma 2.3 and Remark 2.2 we have ‖Kh(s)i‖H(p,q,ϕ)→0 as i→∞. Thus, from (3.15) it follows that
‖Sm→u,φ−K‖H(p,q,ϕ)→H∞μ=sup‖h‖H(p,q,ϕ)=1‖(Sm→u,φ−K)h‖H∞μ≥lim supi→∞‖(Sm→u,φ−K)h(m)i‖H∞μ‖h(m)i‖H(p,q,ϕ)≥lim supi→∞‖Sm→u,φh(m)i‖H∞μ−‖Kh(m)i‖H∞μ‖h(m)i‖H(p,q,ϕ)≥lim supi→∞μ(zi)|um(zi)||φ(zi)|ϕ(|φ(zi)|)(1−|φ(zi)|2)nq+m. |
From induction and combining these inequalities, it follows that
‖Sm→u,φ−K‖H(p,q,ϕ)→H∞μ≳lim supi→∞m∑j=1μ(zi)|uj(zi)||φ(zi)|ϕ(|φ(zi)|)(1−|φ(zi)|2)nq+j. | (4.1) |
Take the function h(0)i=h(0)φ(zi), where h(0)w is defined in Lemma 2.9. Then we have that supi∈N‖h(0)i‖H(p,q,ϕ)<+∞, and h(0)i→0 uniformly on compacts of B as i→∞. Then from (3.22), we have
‖Sm→u,φ−K‖H(p,q,ϕ)→H∞μ≳lim supi→∞μ(zi)|u0(zi)|ϕ(|φ(zi)|)(1−|φ(zi)|2)nq. | (4.2) |
By taking the infimum in (4.1) and (4.2) over the set of all compact operators K:H(p,q,ϕ)→H∞μ, we have
‖Sm→u,φ‖e,H(p,q,ϕ)→H∞μ≳lim sup|φ(zi)|→1(μ(zi)|u0(zi)|ϕ(|φ(zi)|)(1−|φ(zi)|2)nq+m∑j=1μ(zi)|uj(zi)||φ(zi)|ϕ(|φ(zi)|)(1−|φ(zi)|2)nq+j). |
Now, assume that {ri}i∈N is a positive sequence which increasingly converges to 1. For each ri, we define the operator by
Sm→u,riφ=m∑j=0ℜjuj,riφ. |
Since the operator Sm→u,φ:H(p,q,ϕ)→H∞μ is bounded, by Theorem 3.2 one can obtain that the operator Sm→u,riφ:H(p,q,ϕ)→H∞μ is bounded. Since |riφ(z)|≤ri<1, by Lemma 2.5 the operator Sm→u,riφ:H(p,q,ϕ)→H∞μ is also compact. Hence, from Lemmas 2.1 and 2.2, we have
‖Sm→u,φ−Sm→u,riφ‖H(p,q,ϕ)→H∞μ=sup‖f‖H(p,q,ϕ)=1‖(Sm→u,φ−Sm→u,riφ)f‖H∞μ=sup‖f‖H(p,q,ϕ)=1supz∈Bμ(z)|m∑j=0ℜjuj,φf−m∑j=0ℜjuj,riφf|≤sup‖f‖H(p,q,ϕ)=1supz∈Bm∑j=0μ(z)|uj(z)||ℜjf(φ(z))−ℜjf(riφ(z))|≤sup‖f‖H(p,q,ϕ)=1sup|φ(z)|≤δm∑j=0μ(z)|uj(z)||ℜjf(φ(z))−ℜjf(riφ(z))|+sup‖f‖H(p,q,ϕ)=1sup|φ(z)|>δm∑j=0μ(z)|uj(z)||ℜjf(φ(z))−ℜjf(riφ(z))|≤sup‖f‖H(p,q,ϕ)=1sup|φ(z)|≤δm∑j=0μ(z)|uj(z)||ℜjf(φ(z))−ℜjf(riφ(z))|+sup|φ(z)|>δ(μ(z)|u0(z)|ϕ(|φ(z)|)(1−|φ(z)|2)nq+m∑j=1μ(z)|uj(z)||φ(z)|ϕ(|φ(z)|)(1−|φ(z)|2)nq+j)+sup|φ(z)|>δ(μ(z)|u0(z)|ϕ(|riφ(z)|)(1−|riφ(z)|2)nq+m∑j=1μ(z)|uj(z)||riφ(z)|ϕ(|riφ(z)|)(1−|riφ(z)|2)nq+j). | (4.3) |
For each f∈H(B) and |φ(z)|≤δ, we have
|f(φ(z))−f(riφ(z))|=|f(φ1(z),φ2(z),…,φn(z))−f(riφ1(z),riφ2(z),…,riφn(z))|≤n∑k=1|f(riφ1(z),…,riφk−1(z),φk(z),φk+1(z)…,φn(z))−f(riφ1(z),…,riφk−1(z),riφk(z),φk+1(z)…,φn(z))|=n∑k=1|(1−ri)φk(z)∫10∂f∂zk(riφ1(z),…,riφk−1(z),θk(t),φk+1(z)…,φn(z))dt|≤(1−ri)n∑k=1∫10|∂f∂zk(riφ1(z),…,riφk−1(z),θk(t),φk+1(z)…,φn(z))|dt≤(1−ri)n∑k=1sup|w|≤δ|∂f∂zk(w)|≤C(1−ri), | (4.4) |
where θk(t)=(1−t)riφk(z)+tφk(z). Let g=∇ℜj−1f, j=¯1,m, from (4.4) and |φ(z)|≤δ, we have that
|ℜjf(φ(z))−ℜjf(riφ(z))|≤|g(φ(z))−g(riφ(z))||φ(z)|≤(1−ri)|φ(z)|n∑k=1sup|w|≤δ|∂g∂zk(w)|≤C(1−ri)|φ(z)|. | (4.5) |
By letting i→∞ in (4.3), from (3.8), (3.28), (4.4) and (4.5), we obtain
‖Sm→u,φ−Sm→u,riφ‖H(p,q,ϕ)→H∞μ≲sup|φ(z)|>δ(μ(z)|u0(z)|ϕ(|φ(z)|)(1−|φ(z)|2)nq+m∑j=1μ(z)|uj(z)||φ(z)|ϕ(|φ(z)|)(1−|φ(z)|2)nq+j) |
as i→∞. Since
‖Sm→u,φ‖e,H(p,q,ϕ)→H∞μ≤‖Sm→u,φ−Sm→u,riφ‖H(p,q,ϕ)→H∞μ, |
we finish the proof.
From Theorem 4.1 and (1.5), we obtain the following result.
Corollary 4.1. Let m∈N, 1≤p<+∞, 1<q<+∞, ϕ normal, u∈H(B), φ∈S(B), μ a weight function on B and (3.24) hold. If the operator CφℜmMu:H(p,q,ϕ)→H∞μ is bounded, then
‖CφℜmMu‖e,H(p,q,ϕ)→H∞μ≍lim sup|φ(z)|→1(μ(z)|ℜmu(φ(z))|ϕ(|φ(z)|)(1−|φ(z)|2)nq+m∑j=1μ(z)|ℜm−ju(φ(z))||φ(z)|ϕ(|φ(z)|)(1−|φ(z)|2)nq+j). |
In this section, we calculate Hilbert-Schmidt norm of the operator Sm→u,φ:A2α→A2α. For some related results, one can see [37,43]. If H is a separable Hilbert space, then the Hilbert-Schmidt norm ‖T‖HS,H→H of an operator T:H→H is defined by
‖T‖HS,H→H=(∞∑n=1‖Ten‖2)12, | (5.1) |
where {en}n∈N is an orthonormal basis on H. The right-hand side in (5.1) does not depend on the choice of basis. Hence, we have that ‖T‖HS,H→H≥‖T‖H→H the operator norm.
Theorem 5.1. Let m∈N and α>−1. Then Hilbert-Schmidt norm of the operator Sm→u,φ on A2α is
‖Sm→u,φ‖HS,A2α→A2α=(m∑j=0∫B|uj(z)|2(ℜj1(1−n∑i=1wi)n+α+1)|wi=|φi(z)|2dvα(z))12. |
Proof. From Proposition 1.4.9 in [23] (or Lemma 1.11 in [48]), for each multi-index β=(β1,…,βn), we have
∫B|zβ|2dvα(z)=β!Γ(n+α+1)Γ(n+|β|+α+1), |
where β!=β1!⋯βn!, and
∫Bzβzγdvα(z)=0,β≠γ. |
From this, we have that the vectors
eβ(z)=√Γ(n+|β|+α+1)β!Γ(n+α+1)zβ |
form an orthonormal basis in A2α. By using the definition of the Hilbert-Schmidt norm and the monotone convergence theorem, we have
‖Sm→u,φ‖2HS,A2α→A2α=∑β‖Sm→u,φeβ‖2A2α=∑βΓ(n+|β|+α+1)β!Γ(n+α+1)‖Sm→u,φzβ‖2A2α=∑βΓ(n+|β|+α+1)β!Γ(n+α+1)m∑j=0|β|j∫B|uj(z)|2n∏i=1|φi(z)|2βidvα(z)=m∑j=0∫B|uj(z)|2∑β|β|jΓ(n+|β|+α+1)β!Γ(n+α+1)n∏i=1|φi(z)|2βidvα(z). | (5.2) |
For each f∈H(B), by using the Taylor expansion
f(z)=∑|β|≥0aβzβ, |
and taking the jth radial derivatives, we have
ℜjf(z)=∑|β|≥0|β|jaβzβ, | (5.3) |
where β=(β1,β2,…,βn) is a multi-index, |β|=β1+⋯+βn and zβ=zβ11⋯zβnn.
On the other hand, from Proposition 1.14 in [48] (also see [32]), we have
(1−n∑i=1wi)−(n+α+1)=∑lΓ(n+α+|l|+1)l!Γ(n+α+1)n∏i=1wlii. | (5.4) |
Hence, from (5.3) and (5.4), we have
ℜj1(1−n∑i=1wi)n+α+1=∑l|l|jΓ(n+α+|l|+1)l!Γ(n+α+1)n∏i=1wlii. | (5.5) |
From (5.2) and (5.5), the desired result follows.
From Theorem 5.1 and (1.5), we obtain the following result.
Corollary 5.1. Let m∈N and α>−1. Then Hilbert-Schmidt norm of the operator CφℜmMu on A2α is
‖CφℜmMu‖HS,A2α→A2α=(m∑j=0∫B|ℜm−ju(φ(z))|2(ℜj1(1−n∑i=1wi)n+α+1)|wi=|φi(z)|2dvα(z))12. |
In this paper, we define the operator Sm→u,φ=∑mj=0MujCφℜj on some subspaces of H(B), where uj∈H(B),j∈{0,1,…,m} and φ∈S(B). We completely characterized the boundedness and compactness of the operator Sm→u,φ:H(p,q,ϕ)→H∞μ in terms of the behaviours of the symbols uj and φ. In order to study the essential norm estimate of the operator Sm→u,φ:H(p,q,ϕ)→H∞μ, we considered the conditions for the reflexivity of H(p,q,ϕ). By using a criterion of the compactness for a bounded linear operator T:X→Y, where X is a reflexive Banach space of holomorphic functions on B and Y is any Banach space, we obtained the essential norm estimate of the operator Sm→u,φ:H(p,q,ϕ)→H∞μ. Moreover, we also calculated the Hilbert-Schmidt norm of the operator on the weighted Bergman space A2α. As an application, the corresponding results of the operator CφℜmMu:H(p,q,ϕ)→H∞μ are obtained. This paper can be viewed as a continuation and extension of our previous work. We hope that this study can attract people's more attention for such operators and mixed-norm spaces.
This work was supported by the Innovation Fund of Postgraduate, Sichuan University of Science and Engineering (Y2021098) and the Key Project of Zigong City (2020YGJC24).
The authors declare that they have no competing interests.
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