
In this study, the ruled developable surfaces with pointwise 1-type Gauss map of Frenet-type framed base (Ftfb) curve are introduced in Euclidean 3-space. The tangent developable surfaces, focal developable surfaces, and rectifying developable surfaces with singular points are considered. Then the conditions for the Gauss map of these surfaces to be pointwise 1-type are obtained separately. In order to form a basis for the study, first, the basic concepts related to the Ftfb curve and the Gauss map of a surface are recalled. Later, the necessary and sufficient conditions are found for these surfaces to be of the pointwise 1-type of the Gauss map. Finally, examples for each type of these surfaces are given, and their graphics are illustrated.
Citation: Yanlin Li, Kemal Eren, Kebire Hilal Ayvacı, Soley Ersoy. The developable surfaces with pointwise 1-type Gauss map of Frenet type framed base curves in Euclidean 3-space[J]. AIMS Mathematics, 2023, 8(1): 2226-2239. doi: 10.3934/math.2023115
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In this study, the ruled developable surfaces with pointwise 1-type Gauss map of Frenet-type framed base (Ftfb) curve are introduced in Euclidean 3-space. The tangent developable surfaces, focal developable surfaces, and rectifying developable surfaces with singular points are considered. Then the conditions for the Gauss map of these surfaces to be pointwise 1-type are obtained separately. In order to form a basis for the study, first, the basic concepts related to the Ftfb curve and the Gauss map of a surface are recalled. Later, the necessary and sufficient conditions are found for these surfaces to be of the pointwise 1-type of the Gauss map. Finally, examples for each type of these surfaces are given, and their graphics are illustrated.
In the late 1970s, the concept of finite-type submanifold was developed by Chen in Euclidean and semi-Euclidean spaces and this finite-type concept was later extended to differentiable maps defined on submanifolds. Thus, the finite-type Gauss map concept, which is very useful in classifying surfaces, was developed [1,2,3]. Chen and Piccinni presented a general study on the submanifolds of Euclidean spaces with finite-type Gauss map and formed the basis of the theory of submanifolds with finite-type Gauss map and classified compact surfaces with a 1-type Gauss map [4]. The ruled surfaces with a finite-type Gauss map have been studied by many researchers in Euclidean space [5,6,7,8]. In addition, pointwise 1-type Gauss maps of Darboux ruled surfaces, which are one of the special ruled surfaces, were examined and classified in the study [9].
Although the moving frame of a regular space curve has been generally taken into consideration in these studies on surfaces, it is known that an arbitrary curve can also have singular points. However, the moving frame of a space curve cannot be defined at points where the first derivative of the curve is zero. In other words, the Frenet frame cannot be defined at any singular point of a space curve. Due to this reason, our study considers curves that may have some singular points to make a difference from the previous research and present a wider perspective for new research.
Framed curves were introduced to generalize regular curves with the linear independent condition and Legendre curves in the unit tangent bundle in [10]. The basic concepts related to the framed curves and the existence and uniqueness conditions of the framed curve have been explored extensively in studies [11,12,13]. Moreover, the framed surfaces were investigated using curves with singular points. A framed surface in Euclidean space is a smooth surface with a moving frame. It is also a generalization of not only regular surfaces but also frontals at least locally. So, the framed surfaces may have singularities [14,15]. In recent years, some of the latest connected studies can be seen in [16,17,18,19,20,21,22,23,24,25,26,27,28,29,30,31,32]. The Gauss maps of the ruled developable surfaces have been investigated in previous studies, but the Gauss map of ruled developable surfaces with singular points has not been studied. For this reason, unlike the above studies, we want to contribute to the scientific world by investigating the Gauss map of ruled developable surfaces with singular points in our study and to form a basis for new research.
In this study, we investigate the tangent developable surface, the focal developable surface, and the rectifying developable surface with a pointwise 1- type Gauss map of the Frenet-type framed base (Ftfb) curve. Also, the graphs of some of these types of sample surfaces are drawn.
Let σ:I→R3 be a smooth space curve with singular points in Euclidean 3-space and Δ2 be a 3-dimensional smooth manifold, then Δ2 is denoted by
Δ2={μ=(μ1,μ2)∈R3×R3:⟨μi,μj⟩=δij,i,j=1,2}. |
Let μ=(μ1,μ2)∈Δ2, then the unit vector υ is defined as υ=μ1∧μ2 [10].
Definition 2.1. (σ,μ):I→R3×Δ2 is called framed curve if ⟨σ′(y),μ1(y)⟩=⟨σ′(y),μ2(y)⟩=0 for each y∈I. Also, σ:I→R3 is a framed base curve if there exists μ:I→Δ2 such that (σ,μ) is a framed curve [10].
Let (σ,μ1,μ2):I→R3×Δ2 be a framed curve and υ=μ1∧μ2. Then we can write the Frenet-Serret type formula of the framed curve as follows:
[μ1′(y)μ2′(y)υ′(y)]=[0l(y)m(y)−l(y)0n(y)−m(y)−n(y)0][μ1(y)μ2(y)υ(y)], |
where l(y)=⟨μ′1(y),μ2(y)⟩, m(y)=⟨μ′1(y),υ(y)⟩ and n(y)=⟨μ′2(y),υ(y)⟩ [10]. Also, there exists a smooth mapping α:I→R such that
σ′(y)=α(y)υ(y) |
and α(y0)=0 if and only if y0 is a singular point of the curve σ. In addition, the functions {l(y),m(y),n(y),α(y)} are called the curvatures of the framed curve σ. If m(y)=n(y)=0, then υ′(y)=0. The case υ′(y)≠0 is assumed in this article. If the curve σ has a singular point, then the Frenet frame cannot be constructed along the curve σ. But under a certain condition, one can define Frenet type frame along σ.
Definition 2.2. σ:I→R3 is called Frenet type framed base (Ftfb) curve, if there exists a regular curve T:I→S2 and a smooth function α:I→R such that σ′(y)=α(y)T(y) for each y∈I. Then, we call T(y) as the unit tangent vector and α(y) as a speed function of σ(y) [18].
T(y), N(y)=T′(y)‖T′(y)‖ and B(y)=T(y)∧N(y) are unit tangent vector, unit principal normal vector and unit binormal vector of the curve σ(y) with singular point, respectively. Then there exists an orthonormal frame {T(y),N(y),B(y)}. This frame is called the Frenet type frame along σ and we can give the Frenet type framed formula as follows:
[T′(y)N′(y)B′(y)]=[0κ(y)0−κ(y)0τ(y)0−τ(y)0][T(y)N(y)B(y)], |
where κ(y)=‖T′(y)‖ and τ(y)=det(T(y),T′(y),T″(y))‖T′(y)‖2 are the curvature and the torsion of the Ftfb curve σ, respectively. From here, we can say that σ is a framed base curve. Moreover, {σ,N,B} is a framed curve with the curvature {τ(y),−κ(y),0,α(y)}.
Let M:X=X(y,u) be a surface in Euclidean 3-space. It is well-known that, the Gauss map of a surface M carries the unit normal vector at any point p on the surface M to the center of S2 which denotes the unit sphere centered at the origin. Denoting the Gauss map of a surface M with Ω, then it is defined as
Ω:M→S2⊂E3p→Ω(p)=Xy∧Xu‖Xy∧Xu‖, |
where "∧" denotes the cross product of two vectors, Xy=∂X∂y and Xu=∂X∂u are the first order partial derivatives according to the parameters of X.
Let gij=⟨∂X∂xi,∂X∂xj⟩,(1≤i,j≤2) be an induced metric on the surface M. Then the Laplacian operator Δ with respect to the induced metric on M is defined as
Δ=−1√g2∑i,j=1∂∂xi(√ggij∂∂xj), |
where xi (1≤i≤2) are the local coordinates on M. Moreover, the matrices (gij) and the inverse matrix (gij) of (gij) are defined as gij=(g11g12g21g22) and gij=1det(gij)(g22−g12−g21g11), respectively. Also, g=det(gij) denotes the determinant of the matrix (gij).
Let M be a surface in Euclidean 3-space. The Gauss map Ω of M is 1–type Gauss map if and only if the Gauss map Ω is to satisfy the equation ΔΩ=λ(Ω+C) for a non-zero real constant λ and constant vector C [11]. With the studies carried out over time, it has been observed that the Gauss maps of some surfaces such as helicoids and catenoids in E3 provide this equality for a regular function f, not for a constant λ. This situation led to the emergence of the concept called the Gauss map, which is a pointwise 1-type. If the Gauss map Ω of a surface M in E3 satisfies the equation ΔΩ=f(Ω+C) for a regular function f and a constant vector C. Then, this map is called the pointwise 1-type Gauss map [7,11]. If the constant vector C=0, the pointwise 1-type Gauss map is called the first kind, otherwise, the second kind. On the other hand, if ΔΩ=0 it is called that the surface M has a harmonic Gauss map, see details in [8].
In this section, we study the tangent developable surface, focal developable surface, and rectifying developable surface with the Ftfb curve. These surfaces are classified via their pointwise 1-type Gauss maps and the examples of these surfaces are also illustrated.
Note that, the curvature of the Ftfb curve has to be non-zero, otherwise, at the construction of the Frenet type frame along the Ftfb curve, the normal, accordingly, binormal vectors are undefined.
Let M1 be a tangent developable surface associated with the Ftfb curve σ:I→R3 and {T,N,B} be the Frenet type frame of σ such that σ′(y)=α(y)T(y) and α(y) be the speed function of σ(y) for all y∈I, then the parametric equation of the tangent developable surface associated with the Ftfb curve can be written as follows:
M1:X(y,u)=σ(y)+uT(y). | (3.1) |
Here, the curve σ(y) and the vector field T(y) are called the base curve and the director curve or director vector of the surface, respectively [14]. The first order partial derivatives with respect to parameters y and u of the surface defined by (3.1) are found as
Xy=αT+uκNandXu=T. |
The Gauss map of the tangent developable surface M1 parameterized by (3.1) is given by
Ω=−B. |
For the matrix (gij) consisting of the components of the metric on the tangent developable surface M1, we denote by g and (gij) the determinant and the inverse matrix of the matrix (gij), respectively. In this case, we can easily find that
gij=(α2+u2κ2αα1),g=u2κ2andgij=(1u2κ2−αu2κ2−αu2κ21+α2u2κ2). |
Therefore, the formula of the Laplacian Δ on the surface M1 is given in terms of y and u by
Δ=−1u2κ2∂2∂y2−u2κ2+α2u2κ2∂2∂u2+ακ−uκ′u3κ3∂∂y−α2κ+u2κ3−uακ′u3κ3∂∂u+2αu2κ2∂2∂y∂u. | (3.2) |
Now, let's apply the Laplace operator Δ to the Gauss map Ω. If the derivatives of the Gauss map Ωy, Ωyy, Ωu, Ωuu and Ωyu are calculated and the derivatives of the Gauss map are substituted in Eq (3.2), then we get
ΔΩ=τ2u2κ2Ω+τu2κT+τ2(ακ−uκ′)−uκτ′u3κ3N. |
From this last equation, we have τ=0 if and only if ΔΩ=0. In this case, we can give the following Theorem.
Theorem 3.1. Let M1 be a tangent developable surface associated with the Ftfb curve, then the surface M1 has a harmonic Gauss map if and only if the Ftfb curve σ is a plane curve.
Example 3.1. Let M1 be a tangent developable surface associated with the Ftfb curve σ:R→R3 defined by the parametric equation
σ(y)=(y2,y3,0). |
The curve σ has a singular point at y=0, so this curve is not a Frenet curve. The curve σ is a Ftfb curve with the mapping (T,α):R→S2×R. Then
T(y)=1√4+9y2(2,3y,0) |
and
α(y)=y√4+9y2 |
are the unit tangent vector and the speed function of σ, respectively. By making the necessary calculations, the normal, the binormal vectors, the curvature, and the torsion of the curve σ are found as follows, respectively
N(y)=1√4+9y2(−3y,2,0),B(y)=(0,0,1),κ=64+9y2andτ=0. |
Consequently, the tangent developable surface associated with the Ftfb curve is parametric by
X(y,u)=(y2+2u√4+9y2,y3+3yu√4+9y2,0). |
Hence,
Ω=(0,0,−1)andΔΩ=0. |
As the fact that, the tangent developable surface X(y,u) has harmonic Gauss map, see Figure 1.
Let M2 be a focal developable surface associated with the Ftfb curve and σ:I→R3 be a Ftfb curve with Frenet type frame {T,N,B} such that σ′(y)=α(y)T(y) and α(y) is the speed function of σ(y) for all y∈I, then the parametric equation of the focal developable surface can be written as following:
M2:X(y,u)=σ(y)+α(y)κ(y)N(y)+uB(y), | (3.3) |
where N and B are the principal normal vector and binormal vector of the curve σ, respectively [14]. The first order partial derivatives with respect to parameters y and u of the surface M2 are found as
Xy=(η′−uτ)N+ητBandXu=B, |
where η(y)=α(y)κ(y). The Gauss map of the focal developable surface M2 parameterized by (3.3) is given by
G=T |
at the points satisfying η′−uτ≠0. Considering the matrix (gij) consisting of the components of the metric on the surface M2, we can express the matrix (gij), the determinant g and the inverse matrix (gij) of the matrix (gij) as
gij=(η2τ2+(η′−uτ)2ητητ1),g=(η′−uτ)2 |
and
gij=(1(η′−uτ)2−ητ(η′−uτ)2−ητ(η′−uτ)21+η2τ2(η′−uτ)2),η′−uτ≠0, |
respectively. Therefore, the formula of the Laplacian Δ on the surface M2 is found as
Δ=−1(η′−uτ)2∂2∂y2−(η′−uτ)2+η2τ2(η′−uτ)2∂2∂u2+uτ′−ητ2−η″(η′−uτ)3∂∂y+τ((u2+η2)τ2−2uτη′+η′2+η(−uτ′+η″))(η′−uτ)3∂∂u+2ητ(η′−uτ)2∂2∂y∂u. | (3.4) |
Now, let's apply the Laplace operator Δ to the Gauss map Ω. If the partial derivatives of the Gauss map Ωy, Ωyy, Ωu, Ωuu and Ωyu are found and these are substituted in Eq (3.4), then we get
ΔΩ=κ2(η′−uτ)2Ω−κ′(−uτ+η′)+κ(ητ2−uτ′+η″)(η′−uτ)3N−κτ(η′−uτ)2B. | (3.5) |
Theorem 3.2. Let M2 be a focal developable surface associated with the Ftfb curve, then the surface M2 has pointwise 1-type Gauss map of the first kind if and only if κη′ is constant and Ftfb curve is planar.
Proof. Let M2 have pointwise 1-type Gauss map of the first kind, the following conditions are satisfied:
κ2(η′−uτ)2≠0 |
and
κ′(−uτ+η′)+κ(ητ2−uτ′+η″)(η′−uτ)3N+κτ(η′−uτ)2B=0. |
The first condition is always true. For the second one, by considering N and B are linearly independent, we obtain
κ′(−uτ+η′)+κ(ητ2−uτ′+η″)(η′−uτ)3=0 |
and
κτ(η′−uτ)2=0. |
Solving these equations, we get that κη′ is constant and τ=0.
The sufficiency is obviously proven by substituting κη′ is constant and τ=0 in Eq (3.5).
As a result, we can give the following corollary.
Corollary 3.1. Let M2 be a focal developable surface with pointwise 1-type Gauss map of the first kind, then the following equality is satisfied:
ΔΩ=(κη′)2Ω. |
Example 3.2. Let M2 be a focal developable surface associated with the Ftfb curve σ:R→R3 defined by the parametric equation
σ(y)=((y+1)siny+cosy,−(y+1)cosy+siny,0). |
The curve σ has a singular point at y=−1, so this curve is not a Frenet curve. The curve σ is a Ftfb curve with the mapping (T,α):R→S2×R;
T(y)=(cosy,siny,0),α(y)=(y+1). |
The normal and binormal vector of the curve σ are obtained as
N(y)=(−siny,cosy,0),B(y)=(0,0,1). |
Also, the curvature and torsion of the curve σ are
κ=1andτ=0. |
Consequently, the focal developable surface associated with the Ftfb curve is parameterized as
X(y,u)=(cosy,siny,u). |
Hence,
Ω=(cosy,siny,0)andΔΩ=Ω. |
Therefore, the Gauss map Ω has pointwise 1-type of the first kind, see Figure 2.
Let M3 be a rectifying developable surface associated with the Ftfb curve and σ:I→R3 be a Ftfb curve with Frenet type frame {T,N,B} such that σ′(y)=α(y)T(y) and α(y) is a speed function of σ(y) for all y∈I, then the parametric equation of the rectifying developable surface M3 can be written as following:
M3:X(y,u)=σ(y)+uτ(y)T(y)+κ(y)B(y)√τ(y)2+κ(y)2, | (3.6) |
where T and B are unit tangent vector and binormal vector of the Ftfb curve σ, respectively [14,18]. The first order partial derivatives with respect to parameters y and u of the surface M3 are found as
Xy=(α−uκρδ3)T+uτρδ3BandXu=τδT+κδB, |
where δ2=κ2+τ2 and ρ=τκ′−κτ′.
At the points satisfying ακδ+uρδ2≠0, the Gauss map of the rectifying developable surface M3 parameterized by (3.6) is given by
Ω=−N. |
Considering the matrix (gij) consisting of the components of the metric on the surface M3, we can easily find the matrix (gij), the determinant g and the inverse matrix (gij) of the matrix (gij) as
gij=(hατδατδ1),g=h−α2τ2δ2,δ≠0 |
and
gij=(δ2hδ2−α2τ2−αδτhδ2−α2τ2−αδτhδ2−α2τ2hδ2hδ2−α2τ2),hδ2−α2τ2≠0, |
where h=(α−uκρδ3)2+u2ρ2τ2δ6. Therefore, the formula of the Laplacian Δ on the surface M3 is calculated as
Δ=−δ2hδ2−α2τ2∂2∂y2−hδ2hδ2−α2τ2∂2∂u2+αδτ(−2ατδ′+2δ(τα′+ατ′)+δ2hu)−δ4hy2(hδ2−α2τ2)2∂∂y+−2α2δτ3α′+2α3τ2(τδ′−δτ′)−hδ4hu+αδ3τhy2(hδ2−α2τ2)2∂∂u+2αδτhδ2−α2τ2∂2∂y∂u, | (3.7) |
where hy=∂h∂y and hu=∂h∂u are given by
hy=2δ7(u2τρ(−3ρτδ′+δ(τρ)′)+(αδ3−uκρ)(δ4α′+3uκρδ′−uδ(ρκ)′)) |
and
hu=2ρ(−αδκ+uρ)δ4, |
respectively. Now, let's apply the Laplace operator Δ to the Gauss map of the surface M3. If the partial derivatives of the Gauss map Ωy, Ωyy, Ωu, Ωuu and Ωyu are calculated and these are substituted in Eq (3.7), then we get
ΔΩ=δ4hδ2−α2τ2Ω−2δ2κ′(hδ2−α2τ2)−αδκτ(−2αδ′τ+2δ(τα′+ατ′)+δ2hu)+κδ4hy2(hδ2−α2τ2)2T+2δ2τ′(hδ2−α2τ2)−αδτ2(−2αδ′τ+2δ(τα′+ατ′)+δ2hu)+τδ4hy2(hδ2−α2τ2)2B. | (3.8) |
Theorem 3.3. Let M3 be a rectifying developable surface of the Ftfb curve with the Frenet type frame {T,N,B}, then the surface M3 has pointwise 1-type Gauss map of the first kind if and only if the Ftfb curve is a helix.
Proof. Let the Gauss map be pointwise 1-type map of the first kind, it requires the following conditions:
δ4hδ2−α2τ2≠0, |
which is obviously satisfied, and
−2δ2κ′(hδ2−α2τ2)−αδκτ(−2αδ′τ+2δ(τα′+ατ′)+δ2hu)+κδ4hy2(hδ2−α2τ2)2T+2δ2τ′(hδ2−α2τ2)−αδτ2(−2αδ′τ+2δ(τα′+ατ′)+δ2hu)+τδ4hy2(hδ2−α2τ2)2B=0. |
Since T and B are linearly independent, we obtain
−2δ2κ′(hδ2−α2τ2)−αδκτ(−2αδ′τ+2δ(τα′+ατ′)+δ2hu)+κδ4hy2(hδ2−α2τ2)2=0 |
and
2δ2τ′(hδ2−α2τ2)−αδτ2(−2αδ′τ+2δ(τα′+ατ′)+δ2hu)+τδ4hy2(hδ2−α2τ2)2=0. |
If the first and second equations are multiplied by τ and κ, respectively, and then they are added, it is found
−δ2(κ′τ−κτ′)(hδ2−α2τ2)=0. |
Since δ≠0 and (hδ2−α2τ2)≠0, we get κτ is constant which means that the curve is framed helix.
For the sufficient condition, if the Ftfb curve is a framed helix, then κτ is constant. Thus, κ′τ−κτ′=0 requires ρ to vanish, that is, h=α. From (3.8), we see that the Gauss map is pointwise 1-type map of the first kind.
Equation (3.8) gives us the following corollary.
Corollary 3.2. Let M3 be a rectifying developable surface with pointwise 1-type Gauss map of the first kind, then the following equality
ΔΩ=δ4α2κ2Ω |
is satisfied at non-singular points where α≠0.
Example 3.3. Let's investigate the Gauss map the rectifying developable surface associated with the Ftfb curve σ:[0,2π)→R3 defined by the parametric equation
σ(y)=(cos3y,sin3y,cos2y). |
The curve σ has singular points at y=0,π2,π,3π2, so this curve is not a Frenet curve. The curve σ is a Ftfb curve with the mapping (T,α):R→S2×R;
T(y)=15(−3cosy,3siny,−4),α(y)=5cosysiny. |
By calculations, we get the normal, binormal vectors, the curvature and the torsion of the curve σ are, respectively, obtained as
N(y)=(siny,cosy,0),B(y)=15(4cosy,−4siny,−3),κ=35andτ=45. |
Consequently, the rectifying developable surface associated with the Ftfb curve is parametric by
X(y,u)=(cos3y,sin3y,−u+cos2y). |
Hence, the Gauss map is found as
Ω=(−siny,−cosy,0)andΔΩ=49sin22yΩ, |
where y≠0,π2,π,3π2. Obviously, it is seen that the pointwise 1-type Gauss map is first kind, see Figure 3.
In this study, unlike other studies, we have examined developable surfaces with pointwise 1-type Gauss map constructed by curves with singular points in Euclidean 3-space. The tangent, focal, and rectifying developable surfaces of the Ftfb curve were studied in [14,16,18]. As a contribution to them, we have studied these surfaces with a pointwise 1-type Gauss map. In addition, we have obtained their characterizations to be the first kind or harmonic. The examples of obtained results have been illustrated in detail for each type of surface.
We gratefully acknowledge the constructive comments from the editor and the anonymous referees. This work was funded by National Natural Science Foundation of China (Grant No. 12101168), Zhejiang Provincial Natural Science Foundation of China (Grant No. LQ22A010014).
The authors declare no conflict of interest.
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