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Sharp Adams type inequalities in Lorentz-Sobole space

  • This article addresses several sharp weighted Adams type inequalities in Lorentz-Sobolev spaces by using symmetry, rearrangement and the Riesz representation formula. In particular, the sharpness of these inequalities were also obtained by constructing a proper test sequence.

    Citation: Guanglan Wang, Yan Wu, Guoliang Li. Sharp Adams type inequalities in Lorentz-Sobole space[J]. AIMS Mathematics, 2023, 8(9): 22192-22206. doi: 10.3934/math.20231131

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  • This article addresses several sharp weighted Adams type inequalities in Lorentz-Sobolev spaces by using symmetry, rearrangement and the Riesz representation formula. In particular, the sharpness of these inequalities were also obtained by constructing a proper test sequence.



    Sharp Moser-Trudinger inequality and its high-order form (which is called Adams inequality) have received a lot of attention due to their wide applications to problems in geometric analysis, partial differential equations, spectral theory and stability of matter [2,3,5,8,9,10,11,12,24,25,26,27]. This paper is concerned with the problem of finding optimal Adams type inequalities in Lorentz-Sobolev space.

    The Trudinger inequality, which can be seen as the critical case of the Sobolev imbedding, was first obtained by Trudinger [30]. More precisely, Trudinger employed the power series expansion to prove that there exists β>0, such that

    supunn1,uW1,n0(Ω)Ωexp(β|u|nn1)dx<, (1.1)

    where ΩRn is a bounded smooth domain and W1,p0(Ω) denotes the usual Sobolev space on Ω, i.e., the completion of C0(Ω)(the space of all functions being infinity-times continuously differential in Ω with compact support) with the norm

    uW1,p0(Ω)=Ω(|u(x)|p+|u(x)|p)dx.

    Let ΩRn be an open domain with finite measure. It is well known that for a positive integer k<n and 1p<nk, the Sobolev space Wk,p0(Ω) embeds continuously into Lnpnkp(Ω), but in the borderline case p=nk, Wk,nk0(Ω)L(Ω), unless k=n. For the case k=1, Yudovich [31] and Trudinger [30] have shown that

    W1,n0(Ω){uL1(Ω):Eβ:=Ωeβ|u|nn1dx<},for anyβ<

    and the function Eβ is continuous on W1,n0(Ω). In 1971, Moser sharped the Trudinger inequality and gave the sharp constant β=nw1n1n1 of (1.1) by using the technique of the symmetry and rearrangement in [20].

    Theorem A. [20] Let ΩRn be an open domain with finite measure. Then, there exists a sharp constant βn=n(nπn2Γ(n2)+1)1n1, such that

    1|Ω|Ωexp(β|f|nn1)dxC0<

    for any ββn and any fC0(Ω) with Ω|f|ndx1. The constant βn is sharp in the sense that the above inequality can no longer hold with some C0 independent of f if β>βn.

    Theorem A has been extended in many directions, one of which states that

    supuW1,n0(Ω), un11|Ω|Ωexp(β|u|nn1)dx<

    for any ββn=nω1n1n1, plays an important role in analysis, where ωn1 is the surface measure of the unit ball in Rn. In fact, the constant βn is sharp in the sense that if β>βn, the supremum is infinity.

    Since the Polyá-Szegö inequality, on which the technique of the symmetry and rearrangement depends, is not valid on the high-order Sobolev space, many challenges arise in the research of high-order Trudinger-Moser inequalities. In 1988, Adams [1] utilized the method of representative formulas and potential theory to establish the sharp Adams inequalities on bounded domains.

    Theorem B. [1] Let Ω be an open and bounded set in Rn. If m is a positive integer less than n, then there exists a constant C0=C(n,m)>0 such that for any uWm,nm0(Ω) with muLnm(Ω)1,

    1|Ω|Ωexp(β|u(x)|nnm)dxC0for all ββ(n,m), (1.2)

    where

    β(n,m)={nωn1[πn22mΓ(m+12)Γ(nm+12)]nnm,m is odd, nωn1[πn22mΓ(m2)Γ(nm2)]nnm,m is even.

    Furthermore, the constant β(n,m) is best possible in the sense that for any β>β(n,m), the integral can be made as large as possible. In the case of Sobolev space with homogeneous Navier boundary conditions Wm,nmN(Ω), the Adams inequality was extended by Cassani and Tarsi in [6]. It is easy to check that Wm,nmN(Ω) contains Wm,nm0(Ω) as a closed subspace.

    Adimurthi and Sandeep proved a singular Moser-Trudinger inequality with the sharp constant in [2]. Since then, Moser's results for the first order derivatives and Adams' result for the high order derivatives were extended to the unbounded domain case. Earlier research of the Moser-Trudinger inequalities on the whole space goes back to Cao's work in [7]. Later, Li and Ruf [19,23] improved Cao's result and established the following result

    supuW1,n(Rn)1RnΦ(βn|u|nn1)dxCn, (1.3)

    where proof relies on the rearrangement argument and the Polyá-Szegö inequality. For more on the rearrangement argument, see [21,29]. In 2013, Lam and Lu [17] used a symmetrization-free approach to give a simple proof for the sharp Moser-Trudinger inequalities in W1,n(Rn). It should be pointed out that this approach is surprisingly simple and can be easily applied to other settings where symmetrization argument does not work. Furthermore, they also developed a new tool to establish the Moser-Trudinger inequalities on the Heisenberg group and the Fractional Adams inequalities in Ws,ns(Rn) (0<s<n) ([16]). For more applications of the symmetrization-free method, see also [18,32]. The Adams type inequality on Wm,nm0(Ω) when Ω has infinite volume and m is an even integer was studied recently by Ruf and Sani in [22].

    In [22], Ruf and Sani used the norm um,n=(+I)m2unm, which is equivalent to the standard Sobolev norm

    uWm,nm=(unmnm+mj=1junmnm)mn.

    In particular, if uWm,nm0(Ω) or uWm,nm(Rn), then uWm,nmum,n. Since Ruf and Sani only considered the case when m is even, it leaves an open question if Ruf and Sani,s result is still right when m is odd. Recently, the authors of [17] solved the problem and proved the results of Adams type inequalities on unbounded domains when m is odd.

    We notice that when Ω has infinite volume, the usual Moser-Truding inequality become meaningless. In the case |Ω|=+, a modified Moser-Truding type inequality was established in [13].

    Theorem C. [13] Assume n2, β>0,<sα<n and uLn(Rn;|x|sdx)W1,n(Rn), there esists a positive constant C=C(n,s,α,β) such that the inequality

    Rnϕ(β|u|nn1)|x|αdxCun(nα)nsLn(Rn;|x|sdx).

    Furthermore, for all β(1αn)βn, there holds

    Rnϕ(β|u|nn1)|x|αdxCun(nα)nsLn(Rn;|x|sdx),

    where ϕ(t)=etn2j=0tjj! and Ln(Rn;|x|sdx) denotes the weighted Lebesgue space endowed with the norm

    uLn(Rn;|x|sdx):=(Rn|u(x)|n|x|sdx)1n.

    Moreover the constant (1αn)βn is sharp in the sense that if β>(1αn)βn, the supremum is infinity.

    When α=0, Ruf in [23] and Li-Ruf in [19] proved the above modified Moser-Truding type inequality in R2. Such type of inequality on unbounded domains in the subcritical case (β<βn, α=0) was first established by Cao in [7] for n=2 and Adachi Tanaka in [4] for n3 in high dimension.

    In this paper, we will consider some sharp Adams type inequalities in Lorentz-Sobolev space Wαnm,q(ΩRn) with qn (If q=n, the Lorentz norm becomes the Ln(Rn) domain norm). Let 1<p<+ and 1q<+. Then we recall the Lorentz space Lp,q(Rn) as: ψLp,q(Rn) if

    ψp,q={(+0[ψ(t)t1p]qdtt)1q<, 1q<,supt>0ψ(t)t1p<,           q=. (1.4)

    It is well known that p,q is not a norm, and

    ψp,q=(+0[ψ(t)t1p]qdtt)1q

    is a norm for any p and q. However, they are equivalent in the sense that

    ψp,qψp,qC(p,q)ψp,q.

    The Sobolev-Lorentz space ([15])

    Wαnm,q(Rn):=(IΔ)α2Lnm,q(Rn)

    equipped with the norm

    uWαnm,q=(IΔ)α2unm,q

    for 0<α<n,m<n,1<q<. For simplicity of notation, we write

    ¯Wmnm,q(Ω)={uWmnm,q(Ω), (I)m2unm,q1}

    for any ΩRn. Then we can formulate our main results as follows.

    Theorem 1. Let mn be an integer, 0α<n, 1<q<+ and A be a positive real number. Then for any bounded domain ΩRn with |Ω|A>0, we have

    (1) supu¯Wmnm,q(Ω)1|Ω|Ωexp(βn,m,q|u|qq1)dxCm,n,q.

    Additionally, the constant βn,m,q=(nωn1)qnmnKqm,n is sharp in the sense that the supremum is infinity if β>βn,m,q, where Km,n=Γ(nm2)πn22mΓ(m2).

    (2) supu¯Wmnm,q(Ω)Ωexp[βn,m,q(1αn)|u|qq1]|x|αCm,n,q,α.

    Additionally, the constant βn,m,q is sharp in the sense that the supremum is infinity if β>βn,m,q.

    For the unbounded domain, we take Rn for example to have the following inequalities.

    Theorem 2. Let m,q,α be the same as in Theorem 1. Then we have

    supu¯Wmnm,q(Rn)RnΦ(βn,m,q|u|qq1)dxCm,n,q,

    and

    supu¯Wmnm,q(Rn)RnΦ[βn,m,q(1αn)|u|qq1]|x|αdx˜Cm,n,q,α,

    where Φ(x)=exk0j=0xjj!,k0=[q1qnm] and βn,m,q is sharp in the sense that the supremum is infinity if β>βn,m,q.

    We begin this section with some preparations which are necessary for the proofs of our main results. Let f:RnR such that

    |{xRn:|f(x)|>t}|={xRn:|f(x)|>t}dx<+

    for every t>0. Its distribution function df(t) and its decreasing rearrangement f are defined by

    df(t)=|{x:|f(x)|>t}|,

    and

    f(s)=sup{t>0,μf(t)>s},

    respectively. Now, define f:RnR by

    f(x)=f(vn|x|n),

    where vn is the volume of the unit ball in Rn. Then for every continuous increasing function Ψ:[0,+)[0,+), it follows from [14] that

    RnΨ(f)dx=RnΨ(f)dx.

    Since f is nonincreasing, the maximal function of f, which is defined by

    f:=1ss0fdtfors0

    is also nonincreasing and ff. For more properties of the rearrangement, we refer the reader to [14,28].

    Lemma 2.1. Let 0<α1,1<p< and a(s,t) be a non-negative measurable function on (,)×[0,] such that

    a(s,t)1,when0<s<t,
    supt>0(0a(s,t)pds+ta(s,t)pds)1/p=b<.

    Then there is a constant c0=c0(p,b,α) such that if

    ϕ(s)pds1,forϕ0,

    then

    0eFα(t)dtc0,whereFα(t)=αtα(a(s,t)ϕ(s)ds)p. (2.1)

    Proof. The integral in (2.1) can be written as

    |Eαλ|eλdλ=0eFα(t)dt,

    where Fα(t)λ and Eαλ=Ωeαλ|u|nn1dx.

    We first show that there is a constant C=C(p,b,α)>0 such that Fα(t)C for all t0. To do so, we claim that if Eαλ, then λC, and furthermore that if tEαλ, then there are A1>0 and B1>0 such that

    (bp+t)1p(tϕ(s)pds)1pA1+B1|λ|1p.

    In fact, if Eαλ, and tEαλ, then

    tλαtFα(t)α(a(s,t)ϕ(s)ds)p.

    Hence the desired result can be obtained by repeating the argument as in the proof of [1, Lemma 1].

    The second is to prove that |Eαλ|A|λ|+B for constants A and B depending only on p,b and α, which is straightforward via modifying the argument of [1, Lemma 1]. Thus, we complete the proof of Lemma 2.1.

    Lemma 2.2. [15] There exists a constant Kn,m depending only on m and n such that

    u(t)Kn,mmin{(log(e+1t))1q,tmn}uWαnm,q(Rn)

    for all uWαnm,q(Rn) and 1<q+.

    Having disposed of the above lemmas, we can now turn to the proofs of Theorems 1 and 2.

    Since uWmnm,q(Rn), there exists a function fLnm,q(Rn) with u=(IΔ)m2f and fnm,q1. Then u=Gmf, where

    Gm(x)=1(4π)m/2Γ(m/2)+0eπ|x|2tt4πtmn2dtt.

    It follows from O'Neil's lemma [21] that for all t0,

    u(t)u(t)tGm(t)f(t)++tf(r)Gr(r)dr=1tt0f(r)drt0Gm(r)dr++tf(r)Gm(r)dr.

    Since Gm is radial and decreasing, Gm(r)=Gm(v1nnr1n). Therefore, by taking

    {ϕ(t)=|Ω|mnemntf(|Ω|et),ψ(t)=(βn,m,q)q1q|Ω|1mne(1mn)tGm(|Ω|et),

    and using the Hardy-Littlewood inequality, we find

    1|Ω|Ωexp[βn,m,q|u|qq1]dx1|Ω|Ωexp[βn,m,q(u(t))qq1]dx1|Ω|+0exp[βn,m,q|u(es|Ω|)|qq1]es|Ω|ds+0exp[βn,m,q|u(es|Ω|)|qq1]esds+0exp{βn,m,q[es|Ω||Ω|es0f(r)dr|Ω|es0Gm(r)dr++|Ω|esf(r)Gm(r)dr]qq1}esds+0exp{βn,m,q[|Ω|es+sf(|Ω|et)etdt+sGm(|Ω|et)etdt+|Ω|sf(|Ω|et)Gm(|Ω|et)etdt]qq1}esds=+0exp{[es+sϕ(t)e(mn1)tdt+sψ(t)emntdt+sϕ(t)ψ(t)dt]qq1}esds+0exp(F(s))ds,

    where

    F(s)=s[es+sϕ(t)e(mn1)tdt+sψ(t)emntdt+sϕ(t)ψ(t)dt]qq1.

    Hence,

    +Φq(t)dt=+(|Ω|mnemntf(|Ω|et))qdr=+0(f(s)1snm)qdss=(I)m2uqnm,q1.

    Set

    a(t,s)={ψ(t), if ts,e(mn1)t(+sψ(r)emnrdr)es, if s<t.

    Since

    Gm(x){|x|n+m, if |x|2,e|x|, if |x|>2,

    and |Ω|>A>0, we get

    0a(t,s)qdt=0ψ(t)qdt=Cn0(|Ω|1mne(1mn)tGm(|Ω|et))qdt=Cn|Ω|(s1mnGm(v1/nns1/n))qdss=Cnv1nn|Ω|1n((tnvn)1mnGm(t))qtnv1nv1nnn(tnvn)11ndt=Cnv1nn|Ω|1nnt(tnmvnmnnGm(t))qdt=Cn(2v1nn|Ω|1nnt(tnmvnmnntmn)qdt++2nt(tnmvnmnnet)qdt)Cn,m,q,A<+,

    and

    +sa(t,s)qdt=esq+se(mn1)tqdt(+sψ(t)emntdt)q=Cn,m,qesq(mn)(s|Ω|1mnetGm(|Ω|et)dt)qCn,m,qesq(mn)esq(mn)=Cn,m,q<.

    It's easy to check that when 0<s<t, a(s,t)1. This, along with Lemma 2.1 gives +0exp[F(s)]dsC0. Therefore, we have obtained

    1|Ω|Ωexp[βn,m,q|u|qq1]dxC.

    Next, we show the sharpness of βn,m,q according to Adams method in [1]. The equivalent form of Theorem 1(1) is

    1|Ω|Ωexp(β|Gmf(x)fnm,q|q)dxCm,n,q.

    We need to prove that (nωn1)q(nm)n is the best one for Ω=B (the unit ball centered at the origin). Choose f0 such that Gmf1 for xBr:={xR:|x|r} with 0<r<1. The equivalent form gives

    |Br||B|×eαfqLnm,q(B)C,

    and hence

    αfqnm,q(log|B||Br|+logC),

    thereby finding

    αnlimr0log1r[CapWmLnm,q(Br,B)]q,

    with CapWmLnm,q(Br,B)=inffqLnm,q(B). Here the infimum is taken over all f>0 vanishing on the complement of B, and Gmf(x)1 on E. It follows from the proof of [1, Theorem 2] that for any ε>0, one can find 0<r<1 small enough such that

    Gmfr(y)1,    on  Br,

    with

    fr(y)={1ωn1(1ε)(log1r)1|y|m,r<|y|<1,0, otherwise,

    and

    h(y)={|y|m,r<|y|<1,0, otherwise.

    Then the domain of h(t) is (rnωn1n, ), where

    h(t)={(tnωn1)mn,rnωn1n<t<ωn1n,0, otherwise.

    Consequently,

    frLnm,q(B)=tmn1qfr(t)Lq(0,|B|)1ωn1(1ε)(log1r)1(ωn1nrnωn1n[(tnωn1)mntmn1q]qdt)1q=n1qωn1(1ε)(ωn1n)mn(log1r)1qq.

    This gives

    CapWmLnm,q(Br;B)frLnm,q(B)=n1qωn1(1ε)(ωn1n)sn(log1r)1qq.

    Finally, a simple computation yields

    αnlimr0log1r(n1qωn1(1ε)(ωn1n)mn(log1r)1qq)q=(nωn1)qnmn,

    which complete the proof of (1).

    The statement (2) can be proved similarly as that of (1), we only pay attention to the difference arguments as follows. The Hardy-Littlewood inequality shows that

    1|Ω|1αnΩexp[(1αn)βn,m,q|u|qq1]|x|αdx1|Ω|1αn|Ω|0exp[(1αn)βn,m,q(u(t))qq1)](tvn)αndt=1|Ω|1αn+0exp[(1αn)βn,m,q|u(es|Ω|)|qq1](es|Ω|vn)αnes|Ω|ds=vαnn+0exp[(1αn)βn,m,q|u(es|Ω|)|qq1]es(1αn)dsvαnn+0exp{(1αn)βn,m,q[es|Ω||Ω|es0f(r)dr|Ω|es0Gm(r)dr++|Ω|esf(r)Gm(r)dr]qq1}e(1αn)sds=vαnn+0exp{(1αn)βn,m,q[|Ω|es+sf(|Ω|et)etdt+sGm(|Ω|et)etdt+|Ω|sf(|Ω|et)Gm(|Ω|et)etdt]qq1}e(1αn)sds=vαnn+0exp{(1αn)[es+sϕ(t)e(mn1)tdt+sψ(t)emntdt+rϕ(t)ψ(t)dt]qq1}×e(1αn)sdsvαnn+0exp[F1αn(s)]ds,

    where

    F1αn(s)=(1αn)s(1αn)[es+sϕ(t)e(mn1)tdt+sψ(t)emntdt+sϕ(t)ψ(t)dt]qq1.

    Let

    a(t,s)={ψ(t), if ts,e(mn1)t(+sψ(r)emnrdr)es, if s<t.

    Then

    0a(t,s)qdt=0ψ(t)qdt=Cn0(|Ω|1mne(1mn)tGm(|Ω|et))qdt=Cn|Ω|(s1mnGm(v1/nns1/n))qdssCn,m,q<+,

    and

    +sa(t,s)qdt=esq+se(mn1)tqdt(+sψ(t)emntdt)qCn,m,q<.

    Since a(s,t)1 for 0<s<t, we have +0exp[F1βn(s)]ds by Lemma 2.1. Hence

    1|Ω|1αnΩexp[(1αn)βn,m,q|u|qq1]|x|αdxC.

    What is left is to show the sharpness of (1αn)βn,m,q, which also inspired by [1]. Since the equivalent form of (2) is

    Ωexp[(1αn)β|Imf(x)fLnm, q(Ω)|q]|x|αdxCn,p|Ω|1αn,  β(nωn1)qnmn, (2.2)

    we only need to prove that (nωn1)qnmn is the best one for Ω=B. Similarly analysis as that of (1), we choose f0 such that Gmf1 for xBr with 0<r<1, it follows from (1) that

    |BrB|1αn|Br|αn1rαe(1αn)βfqLns,q|BrB|1αn1|Br|1αnBre(1αn)βfqLnm,q|x|αdx|BrB|1αn1|Br|1αnBre(1αn)βGmf(x)fqLnm,q|x|αdx1|Br|1αnBe(1αn)βGmf(x)fqLnm,q|x|αdxC,

    and

    (1αn)βfqLns,q(B)((1αn)log|BBr|+log(rα|Br|αn)+logC)fqLns,q(B)((1αn)log|BBr|+log|B|αn+logC).

    Hence, βnlimr0(log1r)[Cap˙wLnm,q(Br;B)]q, with Cap˙wLnm,q(E;B)=inffLns,q(B), and E is a compact subset of B, where the infimum is taken over all f0 vanishing on the complement of B, and Gmf(x)1 on  E. Analysis similar as that of (1), for any ε>0, we can choose 0<r<1 small enough such that

    Gmfr(y)1,      on   Br,

    with

    fr(y)={1ωn1(1ε)(log1r)1|y|m,r<|y|<1,0,otherwise.&h(y)={|y|m,r<|y|<1,0,otherwise.

    Consequently, we get

    frLnm,q(B)=tmn1qfr(t)Lq(0,|B|)n1qωn1(1ε)(ωn1n)sn(log1r)1qq.

    This shows

    Cap˙wLnm,q(Br;B)frLnm,q(B)=n1qωn1(1ε)(ωn1n)sn(log1r)1qq,

    which gives

    βnlimr0log1r(n1qωn1(1ε)(ωn1n)mn(log1r)1qq)q=(nωn1)qnmn

    as desired.

    For any uWmnm,q(Rn) with (IΔ)m2unm,q1, set A(u)=uwnm,q and Ω={xRn:|u|>A(u)}. Then it is clear that A(u)1. By the property of the rearrangement, we know that for any t[0,|Ω|),

    u(t)>uwnm,q. (2.3)

    At the same time, Lemma 2.2 shows

    u(t)Kn,mtmnuwnm,q. (2.4)

    Combining (2.3) with (2.4), we have tKnmn,m for any t[0,|Ω|). Therefore |Ω|Knmn,m. Write

    RnΦ[βn,m,q|u|qq1]dx=I1+I2,

    where

    I1=ΩΦ[βn,m,q|u|qq1]dx,  I2=RnΩΦ[βn,m,q|u|qq1]dx.

    Choose Ω such that ΩΩ and |Ω|=Knmn,m. Then by Theorem B, we have

    Ωexp(βn,m,q|u|qq1)Cn,m,q|Ω|Cn,m,q,

    thereby finding

    I1=ΩΦ(βn,m,q|u|qq1)dxCn,m,q.

    For the term I2, since RnΩ{|u(x)|<1} and (k0+1)qq1=([qq1nm]+1)qq1>nm, the Hardy-Littlewood inequality and Lemma 2.2 shows that

    I2{|u|1}j=k0+1βjn,m,qj!|u|jqq1dxj=k0+1βjn,m,qj!{|u|1}|u|(k0+1)qq1dxCn,m,q+0[u(t)](k0+1)qq1dt=Cn,m,q(10[u(t)](k0+1)qq1dt++1[u(t)](k0+1)qq1dt)Cn,m,q(10[ln(e+1t)](k0+1)umWnm,qdt++1tnm(k0+1)qq1umWnm,qdt)Cn,m,q.

    This is the first desired result.

    The second inequality of Theorem 2 can be proved similarly via Theorem 1 and the above arguments, we omit its proof here.

    We deal mainly with several sharp weighted Adams type inequalities in Lorentz-Sobolev spaces. In particular, the sharpness of these inequalities were also obtained by constructing a proper test sequence. Moreover, we discuss the boundedness of partial fractional integral operators.

    The authors declare they have not used Artificial Intelligence (AI) tools in the creation of this article.

    The authors are supported by National Natural Science Foundation of China (Grant No.12271232) and Natural Science Foundation of Shandong Province (Grant No. ZR2022MA18).

    The authors declare no conflicts of interest in this paper.



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