
In this article, we focus on the blow-up problem of solution to Caputo-Hadamard fractional diffusion equation with fractional Laplacian and nonlinear memory. By virtue of the fundamental solutions of the corresponding linear and nonhomogeneous equation, we introduce a mild solution of the given equation and prove the existence and uniqueness of local solution. Next, the concept of a weak solution is presented by the test function and the mild solution is demonstrated to be a weak solution. Finally, based on the contraction mapping principle, the finite time blow-up and global solution for the considered equation are shown and the Fujita critical exponent is determined. The finite time blow-up of solution is also confirmed by the results of numerical experiment.
Citation: Zhiqiang Li. The finite time blow-up for Caputo-Hadamard fractional diffusion equation involving nonlinear memory[J]. AIMS Mathematics, 2022, 7(7): 12913-12934. doi: 10.3934/math.2022715
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In this article, we focus on the blow-up problem of solution to Caputo-Hadamard fractional diffusion equation with fractional Laplacian and nonlinear memory. By virtue of the fundamental solutions of the corresponding linear and nonhomogeneous equation, we introduce a mild solution of the given equation and prove the existence and uniqueness of local solution. Next, the concept of a weak solution is presented by the test function and the mild solution is demonstrated to be a weak solution. Finally, based on the contraction mapping principle, the finite time blow-up and global solution for the considered equation are shown and the Fujita critical exponent is determined. The finite time blow-up of solution is also confirmed by the results of numerical experiment.
The main purpose of this paper is to study the finite time blow-up to time-space fractional partial differential equation in the following form
{CHDαa,tu(x,t)+(−Δ)su(x,t)=HD−(1−γ)a,t(|u|p−1u)(x,t),x∈Rd,t>a>0,u(x,a)=ua(x),x∈Rd, | (1.1) |
where d∈N, 0<α<γ<1, 0<s<1, p>1, the operators CHDαa,t, (−Δ)s, and HD−(1−γ)a,t respectively denote the Caputo-Hadamard fractional derivative, fractional Laplacian, and Hadamard fractional integral, and the initial value ua(x)∈C0(Rd), where C0(Rd)={υ∈C(Rd)|lim|x|→∞υ(x)=0}.
Fractional calculus has attracted considerable attention during recent years because of its widespread applications in science and engineering fields such as physics, chemistry, biology, anomalous diffusion, control theory of dynamical systems, etc., see [1,2,3,4]. It has been found that Hadamard-type fractional calculus had many potential applications [5,6,7,8,9,10,11], for example, the ultraslowly diffusive process such as Sinai diffusion [5], fractal analysis [8], the Lomnitz logarithmic creep law in rheology [9], and some studies in this respect have been available [12,13,14,15,16,17,18,19]. The fractional Laplacian is a typically nonlocal pseudo-differential operator, which appears in different disciplines of mathematics and various applications, see [20,21,22,23] and the list of references therein.
We next recall some pioneering work on the blow-up problem for fractional diffusion equation, here we only mention the results related to our studies.
In the 1960s, Fujita [24] first considered the following semilinear heat equation
{ut=Δu+u1+α,x∈Rd,t>0,u|t=0=u0(x),x∈Rd, | (1.2) |
where α>0 and u0(x)≥0. In that paper, the author shown that: If u0(x)≢0 and 0<α<2d then the solution of (1.2) blows up in finite time; If α>2d and the initial value u0(x) can be bounded by sufficiently small Gaussian then the solution of (1.2) exists globally. As for the critical case α=2d, Weissler [25] proved that (1.2) has a global solution when ||u0||Lαd2(Rd) is sufficiently small.
Later, Cazenave et al. [26] studied the following Cauchy problem of heat equation with nonlinear memory
{ut−Δu=∫t0(t−τ)−γ|u(τ)|p−1u(τ)dτ,x∈Rd,t>0,u|t=0=u0(x),x∈Rd, | (1.3) |
where p>1,0≤γ<1, and u0∈C0(Rd). Let pγ=1+2(2−γ)(d−2+2γ)+ with (d−2+2γ)+=max{0,d−2+2γ}. They proved that: If γ≠0,p≤max{1γ,pγ},u0≥0, and u0≢0, then the solution of (1.3) blows up in finite time; if γ≠0,p>max{1γ,pγ} and ||u0||Lqsc(Rd) is sufficiently small with qsc=d(p−1)4−2γ, then (1.3) has global solution. In the case with γ=0, every nontrivial positive solution of (1.3) will blow up [27].
In [28], Fino and Kirane further investigated the equation involving fractional Laplacian with nonlinear memory
{ut+(−Δ)β2u=1Γ(1−γ)∫t0(t−τ)−γ|u(τ)|p−1u(τ)dτ,x∈Rd,t>0,u|t=0=u0(x),x∈Rd, | (1.4) |
where 0<β≤2,0<γ<1,p>1, and u0∈C0(Rd). They derived that: If u0≥0,u0≢0, and p≤max{1+β(2−γ)(d−β+βγ)+,1γ}, then the solution of (1.4) will blow up in finite time; if p>max{1+β(2−γ)(d−β+βγ)+,1γ} and ||u0||Lpsc(Rd) is very small with psc=d(p−1)β(2−γ), then (1.4) exists global solution.
Shortly after, Li and Zhang [29] discussed the following time fractional diffusion equation involving Caputo derivative with nonlinear memory
{CDα0,tu−Δu=1Γ(1−γ)∫t0(t−τ)−γ|u(τ)|p−1u(τ)dτ,x∈Rd,t>0,u|t=0=u0(x),x∈Rd, | (1.5) |
where 0<α<γ<1, p>1, and u0∈C0(Rd). They proved that: If 1<p<p∗=max{1+1−γα,1+2(1+α−γ)αd} and u0≥0 with u0≢0, then the solution of (1.5) will blow up in finite time; if d<2(1+α−γ)1−γ with p≥p∗ or d≥2(1+α−γ)1−γ with p>p∗, and ||u0||Lqc(Rd) is small enough, where qc=αd(p−1)2(1+α−γ), then (1.5) has global solution.
Recently, Li and Li [16] investigated the semilinear time-space fractional diffusion equation involving Caputo-Hadamard derivative and fractional Laplacian,
{CHDαa,tu(x,t)+(−Δ)su(x,t)=|u(x,t)|p−1u(x,t),x∈Rd,t>a>0,u(x,a)=ua(x),x∈Rd, | (1.6) |
where 0<α<1, 0<s<1, p>1, and ua∈C0(Rd). They obtained that: If 1<p<2sd and ua≥0 with ua≢0, then the solution of (1.6) will blow up in finite time; Conversely, if p≥1+2sd and ||ua||Lq∗(Rd) is sufficiently small, where q∗=d(p−1)2s, then (1.6) has a global solution.
Motivated mathematically by the results and methods in [16], this paper will further study the blow-up property and global solution to time-space fractional diffusion equation (1.1) with nonlinear memory. The main result is displayed in the following theorem.
Theorem 1.1. Let d∈N, 0<α<γ<1, 0<s<1, and p>1.Assume that ua∈C0(Rd) and ua≥0 with ua≢0.
(1) If 1<p<˜p=max{1+1−γα,1+2s(1+α−γ)αd}, then the mild solution of Eq (1.1) will blow up in finite time.
(2) If d<2s(1+α−γ)1−γ,p≥˜p or d≥2s(1+α−γ)1−γ,p>˜p, and ||ua||Lp∗(Rd) is small enough with p∗=αd(p−1)2s(1+α−γ), then Eq (1.1) exists global solution.
The organization of this paper is as follows. Section 2 recalls some basic definitions and presents several important lemmas. In Section 3, we define a mild solution to Eq (1.1) and then prove the local existence and uniqueness of the mild solution. Then, a weak solution of Eq (1.1) is introduced and the mild solution is actually proved to be a weak solution. Next, we show the finite time blow-up and global existence of the solution to Eq (1.1) in Section 4. Finally, an illustrative example is provided to verify the blow-up of solution in finite time in Section 5. The conclusions are given in the last section. Throughout the paper, we use the letter C to denote a generic positive constant which may take different values at different places.
Let us recall some basic definitions and several important lemmas, which will be applied in the next sections.
Definition 2.1. [4,30] Let a function f(t) be defined on the interval (a,b)(0≤a<b≤+∞) and α>0. The left- and right- sided Hadamard fractional integrals of the function f(t) with order α are given by
HD−αa,tf(t)=1Γ(α)∫ta(logtτ)α−1f(τ)dττ,t>a, | (2.1) |
and
HD−αt,bf(t)=1Γ(α)∫bt(logτt)α−1f(τ)dττ,t<b, | (2.2) |
where the Gamma function Γ(ξ)=∫∞0e−ttξ−1dt.
Definition 2.2. [4,31] Let a function f(t) be defined on the interval (a,b)(0≤a<b≤+∞) and n−1<α<n∈N. The left- and right- sided Caputo-Hadamard fractional derivative of the function f(t) with order α can be written as
CHDαa,tf(t)=HD−(n−α)a,t[δnf(t)]=1Γ(n−α)∫ta(logtτ)n−α−1δnf(τ)dττ,t>a, | (2.3) |
and
CHDαt,bf(t)=(−1)nHD−(n−α)t,b[δnf(t)]=(−1)nΓ(n−α)∫bt(logτt)n−α−1δnf(τ)dττ,t<b, | (2.4) |
where δnf(t)=(tddt)nf(t).
Definition 2.3. [2,20,30] The fractional Laplacian (−Δ)s with s∈(0,1) is defined by
(−Δ)sv(x)=C(d,s) P.V.∫Rdv(x)−v(y)|x−y|d+2sdy,∀x∈Rd, | (2.5) |
where P.V. denotes the Cauchy principle value and the constant
C(d,s)=(∫Rd1−cosy1|y|d+2sdy)−1 |
for any y=(y1,y2,⋯,yd)∈Rd.
To define a mild solution of Eq (1.1), let us consider the following linear equation,
{CHDαa,tu(x,t)+(−Δ)su(x,t)=f(x,t),x∈Rd,t>a>0,u(x,a)=ua(x),x∈Rd, | (2.6) |
whose solution is expressed by [14]
u(x,t)=Ga(x,t)∗ua(x)+∫taGf(x,atτ)∗f(x,τ)dττ:=∫RdGa(x−y,t)ua(y)dy+∫ta∫RdGf(x−y,atτ)f(y,τ)dydττ, | (2.7) |
where Ga(x,t) and Gf(x,t) are the fundamental solutions given by
Ga(x,t)=1|x|dπd2H2123(|x|2s22s(logta)α|(1,1);(1,α)(1,1),(d2,s);(1,s)), | (2.8) |
and
Gf(x,t)=(logta)α−1|x|dπd2H2123(|x|2s22s(logta)α|(1,1);(α,α)(1,1),(d2,s);(1,s)). | (2.9) |
The special function H2123(z) in the above equalities is the Fox H-function and some details regarding this function can be found in [4,32,33].
In the sequel, we list some properties of the functions Ga(x,t) and Gf(x,t).
Lemma 2.1. [16] Let d∈N, 0<α<1, and 0<s<1. Thenthe functions Ga(x,t) and Gf(x,t) in Eqs (2.8) and (2.9) have the following properties.
(1) Ga(x,t)>0, Gf(x,t)>0.
(2) ∫RdGa(x,t)dx=1, ∫RdGf(x,t)dx=1Γ(α)(logta)α−1. (3) HD−(1−α)a,tGf(x,t)=Ga(x,t).
Lemma 2.2. [16] Let d∈N, 0<α<1, and 0<s<1.If ua(x)≥0 and ua(x)≢0, then we have Ga(x,t)∗ua(x)>0 and ||Ga(x,t)∗ua(x)||L1(Rd)=||ua(x)||L1(Rd).Furthermore, when 1≤r≤q≤+∞ and 1r−1q<min{1,2sd}, it holds that
||Ga(x,t)∗ua(x)||Lq(Rd)≤C(logta)−αd2s(1r−1q)||ua(x)||Lr(Rd),t>a. | (2.10) |
Lemma 2.3. [16] Let d∈N, 0<α<1, and 0<s<1.If ua(x)≥0 and ua(x)≢0, then we have Gf(x,t)∗ua(x)>0 and ||Gf(x,t)∗ua(x)||L1(Rd)=1Γ(α)(logta)α−1||ua(x)||L1(Rd).Furthermore, when 1≤r≤q≤+∞ and 1r−1q<min{1,4sd}, it holds that
||Gf(x,t)∗ua(x)||Lq(Rd)≤C(logta)α−1−αd2s(1r−1q)||ua(x)||Lr(Rd),t>a. | (2.11) |
Lemma 2.4. [16] Let d∈N, 0<α<1, and 0<s<1. Assume ua(x)∈C0(Rd). Then for t>a>0, we have Ga(x,t)∗ua(x)∈C0(Rd) and
CHDαa,t[Ga(x,t)∗ua(x)]=−(−Δ)s[Ga(x,t)∗ua(x)],t>a>0. |
And there exists a constant C>0 such that
||(−Δ)s[Ga(x,t)∗ua(x)]||L∞(Rd)≤C(logta)−α||ua(x)||L∞(Rd),t>a>0. |
For simplicity of representation, from now on, we denote Ga(t)=Ga(x,t), Gf(t)=Gf(x,t), and so on.
Lemma 2.5. [16] Let d∈N, 0<α<1, 0<s<1, and T>a>0.Let also f∈Lq((a,T),C0(Rd)) with q>1 and
θ(t)=∫taGf(atτ)∗f(τ)dττ. |
Then we have
HD−(1−α)a,tθ(t)=∫taGa(atτ)∗f(τ)dττ. |
Furthermore, one has θ(t)∈C([a,T],C0(Rd)) provided that qα>1.
In this part, we first define a mild solution of Eq (1.1) and then prove the local existence and uniqueness of the mild solution in terms of the contraction mapping principle. Next, the definition of a weak solution is introduced to Eq (1.1). We can also prove that the mild solution is just a weak solution. Let us begin by introducing the definition of a mild solution to Eq (1.1).
Definition 3.1. Let d∈N, 0<α<γ<1, 0<s<1, p>1 and T>a>0. Let ua∈C0(Rd). Then a mild solution u∈C([a,T],C0(Rd)) of Eq (1.1) is given by
u(t)=Ga(t)∗ua+∫taGf(atτ)∗[HD−(1−γ)a,τ(|u|p−1u)(τ)]dττ,t∈[a,T]. | (3.1) |
Theorem 3.1. Let d∈N, 0<α<γ<1, 0<s<1, p>1, and T>a>0.Let ua∈C0(Rd). Then there isa maximal time Tmax>a such that Eq (1.1) hasa unique mild solution u∈C([a,Tmax),C0(Rd)), where, either Tmax=∞ or Tmax<∞ and ||u||L∞((a,T),L∞(Rd)→∞ as t→T−max. Moreover, if ua≥0 and ua≢0, then u(t)>0 for any a<t<Tmax. Besides, if ua∈Lr(Rd) for 1≤r<∞, then one has u∈C([a,Tmax),Lr(Rd)).
Proof. For given T>a>0 and ua∈C0(Rd), let
Ea,T={u∈C([a,T],C0(Rd))|||u||L∞((a,T),L∞(Rd))≤2||ua||L∞(Rd)} |
and
d(u,v)=maxt∈[a,T]||u(t)−v(t)||L∞(Rd),∀u,v∈Ea,T. |
Obviously, (Ea,T,d) is a complete metric space. By means of the fundamental solutions Ga(t) and Gf(t), we define the following operator F on the metric space (Ea,T,d),
F(u)(t)=Ga(t)∗ua+∫taGf(atτ)∗[HD−(1−γ)a,τ(|u|p−1u)(τ)]dττ,u∈Ea,T. |
It follows from Lemma 2.5 that F(u)∈C([a,T],C0(Rd)).
We next show that F:Ea,T→Ea,T. For u∈Ea,T and t∈[a,T], by Definition 2.1 and Lemma 2.1, we get
||F(u)(t)||L∞(Rd)≤||Ga(t)∗ua||L∞(Rd)+∫ta||Gf(atτ)∗[HD−(1−γ)a,τ(|u|p−1u)(τ)]||L∞(Rd)dττ≤||ua||L∞(Rd)+2pΓ(α)Γ(1−γ)∫ta∫τa(logtτ)α−1(logτw)−γdwwdττ||ua||pL∞(Rd)=||ua||L∞(Rd)+2pΓ(α)Γ(2−γ)∫ta(logtτ)α−1(logτa)1−γdττ||ua||pL∞(Rd)=||ua||L∞(Rd)+2pΓ(α)Γ(2−γ)(logta)α−γ+1∫10τα−1(1−τ)1−γdτ||ua||pL∞(Rd)=||ua||L∞(Rd)+2pΓ(α)Γ(2−γ)Γ(α)Γ(2−γ)Γ(2+α−γ)(logta)α−γ+1||ua||pL∞(Rd)≤||ua||L∞(Rd)+2p||ua||p−1L∞(Rd)Γ(2+α−γ)(logTa)α−γ+1||ua||L∞(Rd). |
Choosing T>a sufficiently close to a such that
2pΓ(2+α−γ)(logTa)α−γ+1||ua||p−1L∞(Rd)≤1, |
then we obtain ||F(u)||L∞((a,T),L∞(Rd))≤2||ua||L∞(Rd) and F(u)∈Ea,T, viz., the operator F maps Ea,T into itself.
We need to show that the operator F is contractive on Ea,T. For u,v∈Ea,T and t∈[a,T], one can deduce that
||F(u)(t)−F(v)(t)||L∞(Rd)≤1Γ(α)Γ(1−γ)∫ta∫τa(logtτ)α−1(logτw)−γ×|||u(w)|p−1u(w)−|v(w)|p−1v(w)||L∞(Rd)dwwdττ≤2pC(p)Γ(2+α−γ)(logTa)α−γ+1||ua||p−1L∞(Rd)||u−v||L∞((a,T),L∞(Rd)). |
Taking T>a sufficiently close to a gives rise to
2pC(p)Γ(2+α−γ)(logTa)α−γ+1||ua||p−1L∞(Rd)≤12, |
which means ||F(u)(t)−F(v)(t)||L∞(Rd)≤12||u−v||L∞((a,T),C0(Rd)). This illustrates the operator F is contractive on Ea,T and thus it has a fixed point u∈Ea,T by the contraction mapping principle. Moreover, using Gronwall inequality immediately knows the uniqueness of the mild solutions to Eq (1.1) holds.
In view of the uniqueness, there is a maximal time Tmax>a such that the solution of Eq (1.1) exists on the interval [a,Tmax), where
Tmax=sup{T>a|there is a mild solution u∈C([a,T],C0(Rd)) to (1.1)}≤+∞. |
Next, we show ||u||L∞((a,T),L∞(Rd))→∞ as t→T−max provided that Tmax<∞. If Tmax<∞ and there is M>0 satisfying ||u(t)||L∞(Rd)≤M for t∈[a,Tmax), then we have for a<ξ<η<Tmax,
||u(ξ)−u(η)||L∞(Rd)≤||[Ga(ξ)−Ga(η)]∗ua||L∞(Rd)+||∫ηξGf(aητ)∗[HD−(1−γ)a,τ(|u|p−1u)(τ)]dττ||L∞(Rd)+||∫ξa(Gf(aξτ)−Gf(aητ))∗[HD−(1−γ)a,τ(|u|p−1u)(τ)]dττ||L∞(Rd)≤||[Ga(ξ)−Ga(η)]∗ua||L∞(Rd)+MpΓ(α)Γ(2−γ)∫ηξ(logητ)α−1(logτa)1−γdττ+CMpΓ(2−γ)∫ξa(logτa)1−γmin{(logξτ)α−1,(logξτ)α−2(logηξ)}dττ≤||[Ga(ξ)−Ga(η)]∗ua||L∞(Rd)+MpΓ(α)Γ(2−γ)(logTmaxa)1−γ∫ηξ(logητ)α−1dττ+CMpΓ(2−γ)(logTmaxa)1−γ∫ξamin{(logξτ)α−1,(logξτ)α−2(logηξ)}dττ≤||[Ga(ξ)−Ga(η)]∗ua||L∞(Rd)+Mp(logTmaxa)1−γΓ(α+1)Γ(2−γ)(logηξ)α+CMp(logTmaxa)1−γ(logηξ)α, |
which implies limt→T−maxu(t) exists in C0(Rd).
Now we define limt→T−maxu(t)=uTmax. Therefore one gets u∈C([a,Tmax],C0(Rd)). Furthermore, using Lemma 2.5 yields that
∫taGf(atτ)∗[HD−(1−γ)a,τ(|u|p−1u)(τ)]dττ∈C([a,Tmax],C0(Rd)). |
For h>0 and σ>0, consider a set
˜Eh,σ={u∈C([Tmax,Tmax+h],C0(Rd))|u(Tmax)=uTmax,d(u,uTmax)≤σ} |
equipped with
d(u,v)=maxt∈[Tmax,Tmax+h]||u(t)−v(t)||L∞(Rd),∀u,v∈˜Eh,σ. |
Then the metric space (˜Eh,σ,d) is complete.
On the space (˜Eh,σ,d), define an operator Q as follows,
Q(v)(t)=Ga(t)∗ua+∫TmaxaGf(atτ)∗[HD−(1−γ)a,τ(|u|p−1u)(τ)]dττ+∫tTmaxGf(atτ)∗[HD−(1−γ)a,τ(|v|p−1v)(τ)]dττ,v∈Eh,σ. |
It is easy to see that Q(v)∈C([Tmax,Tmax+h],C0(Rd)) and Q(v)(Tmax)=uTmax.
We first prove Q(v)∈˜Eh,σ for v∈˜Eh,σ. As a matter of fact, if t∈[Tmax,Tmax+h], then
||Q(v)(t)−uTmax||L∞(Rd)≤||Ga(t)∗ua−Ga(Tmax)∗ua||L∞(Rd)+||∫tTmaxGf(atτ)∗[HD−(1−γ)a,τ(|v|p−1v)(τ)]dττ||L∞(Rd)+||∫Tmaxa[Gf(atτ)−Gf(aTmaxτ)]∗[HD−(1−γ)a,τ(|u|p−1u)(τ)]dττ||L∞(Rd)=||J1||L∞(Rd)+||J2||L∞(Rd)+||J3||L∞(Rd). |
By taking sufficiently small h, we arrive at
||J1||L∞(Rd)≤σ3, ||J3||L∞(Rd)≤σ3. |
In regard to ||J2||L∞(Rd), one has
||J2||L∞(Rd)≤||∫tTmaxGf(atτ)∗[HD−(1−γ)a,τ(|v(τ)|p−1v(τ)−|uTmax|p−1uTmax)]dττ||L∞(Rd)+||∫tTmaxGf(atτ)∗[HD−(1−γ)a,τ(|uTmax|p−1uTmax)]dττ||L∞(Rd)≤(Cσα+(logta)1−γΓ(α+1)Γ(2−γ)||uTmax||pL∞(Rd))(logtTmax)α≤σ3, |
for t∈[Tmax,Tmax+h] and h small enough. Therefore, there holds ||Q(v)(t)−uTmax||L∞(Rd)≤σ, i.e., d(Q(v),uTmax)≤σ for t∈[Tmax,Tmax+h].
We next show that the operator Q is contractive on ˜Eh,σ. Assume that v,w∈˜Eh,σ and t∈[Tmax,Tmax+h], it follows that
||Q(v)(t)−Q(w)(t)||L∞(Rd)≤C(p)Γ(α)Γ(2−γ)(||v||p−1L∞((Tmax,Tmax+h),L∞(Rd))+||w||p−1L∞((Tmax,Tmax+h),L∞(Rd)))×∫tTmax(logtτ)α−1(logτa)1−γdττ||v−w||L∞((Tmax,Tmax+h),L∞(Rd))≤2C(p)(logta)1−γΓ(α+1)Γ(2−γ)(σ+||uTmax||L∞(Rd))p−1(logtTmax)αd(v,w). |
In this case, for t∈[Tmax,Tmax+h], one may take very small h such that
2C(p)(logta)1−γΓ(α+1)Γ(2−γ)(σ+||uTmax||L∞(Rd))p−1(logtTmax)α≤12, |
which suggests the operator Q is contractive on ˜Eh,σ and thus it has a fixed point v∈˜Eh,σ. In view of v(Tmax)=Q(v)(Tmax)=u(Tmax), we set
¯u(t)={u(t), t∈[a,Tmax),v(t), t∈[Tmax,Tmax+h], |
such that ¯u(t)∈C([a,Tmax+h],C0(Rd)) and
¯u(t)=Ga(t)∗ua+∫taGf(atτ)∗[HD−(1−γ)a,τ(|¯u(τ)|p−1¯u)(τ)]dττ, |
which means ¯u(t) is indeed a mild solution of Eq (1.1). Recalling the definition of Tmax, this yields a contradiction.
The proof of the remainder of this theorem follows that of Theorem 3.2 in [16] and so is omitted. The proof is thus complete.
In the following, we present the definition of a weak solution to Eq (1.1) and show that the mild solution given by Definition 3.1 is a weak solution.
Definition 3.2. Let d∈N, 0<α<γ<1, 0<s<1, p>1, and T>a>0. For given ua∈L∞Loc(Rd), a function u is said to be a weak solution of Eq (1.1) if u∈Lp((a,T),L∞Loc(Rd)) and
∫Rd∫Ta(HD−(1−γ)a,τ(|u|p−1u)φ+uaCHDαt,Tφ)dttdx=∫Rd∫Ta(u(−Δ)sφ+uCHDαt,Tφ)dttdx, | (3.2) |
for any test function φ∈C2,1x,t(Rd×[a,T]) satisfying suppxφ⊂⊂Rd and φ(⋅,T)=0.
Theorem 3.2. Let d∈N, 0<α<γ<1, 0<s<1, p>1, and T>a>0.If the initial value ua∈C0(Rd), thenthe mild solution u∈C([a,T],C0(Rd)) of Eq (1.1) is also its weak solution.
Proof. Assume that u∈C([a,T],C0(Rd)) is a mild solution to Eq (1.1). Then Definition 3.1 gives
u−ua=Ga(t)∗ua−ua+∫taGf(atτ)∗[HD−(1−γ)a,τ(|u|p−1u)]dττ. |
Use Lemma 2.5 to get
HD−(1−α)a,t(u−ua)=HD−(1−α)a,t(Ga(t)∗ua−ua)+∫taGa(atτ)∗[HD−(1−γ)a,τ(|u|p−1u)]dττ. |
Therefore, for every φ∈C2,1x,t(Rd×[a,T]) satisfying suppxφ⊂⊂Rd and φ(⋅,T)=0, there holds
∫RdHD−(1−α)a,t(u−ua)φdx=∫RdHD−(1−α)a,t(Ga(t)∗ua−ua)φdx+∫Rd∫taGa(atτ)∗[HD−(1−γ)a,τ(|u|p−1u)]dττφdx=I1+I2. |
For I1, an application of Lemma 2.4 leads to
δI1=−∫Rd(−Δ)s(Ga(t)∗ua)φdx+∫RdHD−(1−α)a,t(Ga(t)∗ua−ua)δφdx. | (3.3) |
To estimate I2, we set h>0, t∈[a,T) and t+h≤T, then
I2(t+h)−I2(t)log(t+h)−log(t)=1log(t+h)−log(t)∫Rd∫t+htGa(at+hτ)∗[HD−(1−γ)a,τ(|u|p−1u)]dττφ(t+h,x)dx+1log(t+h)−log(t)∫Rd∫taGa(at+hτ)∗[HD−(1−γ)a,τ(|u|p−1u)]dττ[φ(t+h,x)−φ(t,x)]dx+1log(t+h)−log(t)∫Rd∫ta[Ga(at+hτ)−Ga(atτ)]∗[HD−(1−γ)a,τ(|u|p−1u)]dττφ(t,x)dx=I21+I22+I23. |
Applying the mean value theorem yields that
limh→0I21=∫RdHD−(1−γ)a,τ(|u|p−1u)φdx, |
limh→0I22=∫Rd∫taGa(atτ)∗[HD−(1−γ)a,τ(|u|p−1u)]dττδφdx, |
and
limh→0I23=−∫Rd∫taGf(atτ)∗[HD−(1−γ)a,τ(|u|p−1u)]dττ(−Δ)sφdx. |
Consequently,
δI2=∫RdHD−(1−γ)a,t(|u|p−1u)φdx+∫RdHD−(1−α)a,t∫taGf(atτ)∗[HD−(1−γ)a,τ(|u|p−1u)]dττδφdx−∫Rd∫taGf(atτ)∗[HD−(1−γ)a,τ(|u|p−1u)]dττ(−Δ)sφdx. | (3.4) |
Combining (3.3) and (3.4), we obtain
0=∫Taδ∫RdHD−(1−α)a,t(u−ua)φdxdtt=∫Ta(δI1+δI2)dtt=−∫Ta∫Rdu(−Δ)sφdxdtt+∫Ta∫RdHD−(1−γ)a,t(|u|p−1u)φdxdtt−∫Ta∫Rd(u−ua)CHDαt,Tφdxdtt, |
which is the desired result and the proof is now ended.
Proof of Theorem 1.1.
(1) We consider two cases: (i) 1<p<˜p=1+1−γα. (ii) 1<p<˜p=1+2s(1+α−γ)αd.
(i) Assume that 1<p<˜p=1+1−γα. Let
ω(x)=(∫Rde−√d2+|x|2dx)−1e−√d2+|x|2,x∈Rd, |
and the function Φ satisfy
Φ∈C∞0(R), Φ(ξ)={1, |ξ|≤1,0, |ξ|≥2, 0≤Φ≤1. |
Thanks to Theorem 3.2, we may take φ1(x)=ω(x)Φn(x) with Φn(x)=Φ(|x|/n),n=1,2,…, and φ2(t)=(1−log(t/a)log(T/a))m for t∈[a,T], where m≥max{2,p(1+α−γ)p−1}. Now we set φ(x,t)=CHD1−γt,T(φ1(x)φ2(t)). From Definition 3.2 of the weak solution, one has
∫Rd∫Ta(HD−(1−γ)a,tupCHD1−γt,T(φ1φ2)+uaCHDαt,TCHD1−γt,T(φ1φ2))dttdx=∫Rd∫Ta(u(−Δ)sφ1CHD1−γt,Tφ2+uCHDαt,TCHD1−γt,T(φ1φ2))dttdx. | (4.1) |
Furthermore, it follows that
∫Rd∫Ta(upφ1φ2+uaφ1CHD1+α−γt,Tφ2)dttdx=∫Rd∫Ta(u(−Δ)sφ1CHD1−γt,Tφ2+uφ1CHD1+α−γt,Tφ2)dttdx. | (4.2) |
According to the inequality (−Δ)sω(x)≤ω(x) in [16] and the Lebesgue dominated convergence theorem, we have with n→∞ in (4.2),
∫Rd∫Taupωφ2dttdx+∫Rd∫TauaωCHD1+α−γt,Tφ2dttdx≤∫Rd∫Ta(uωCHD1−γt,Tφ2+uωCHD1+α−γt,Tφ2)dttdx. | (4.3) |
Using Jensen's inequality in (4.3) gives
∫Ta(∫Rduωdx)pφ2dtt+∫Rd∫TauaωCHD1+α−γt,Tφ2dttdx≤∫Rd∫Ta(uωCHD1−γt,Tφ2+uωCHD1+α−γt,Tφ2)dttdx. | (4.4) |
Denoting f(t)=∫Rduωdx, it is easy to see that f(t)≥0 and f(a)>0. In view of inequality (4.4), Hölder inequality and Young's inequality, we obtain
∫Tafp(t)φ2(t)dtt+∫Taf(a)CHD1+α−γt,Tφ2(t)dtt≤∫Taf(t)CHD1−γt,Tφ2(t)dtt+∫Taf(t)CHD1+α−γt,Tφ2(t)dtt=∫Taf(t)φ1p2(t)φ−1p2(t)CHD1−γt,Tφ2(t)dtt+∫Taf(t)φ1p2(t)φ−1p2(t)CHD1+α−γt,Tφ2(t)dtt≤12∫Tafp(t)φ2(t)dtt+C∫Taφ−1p−12(t)(CHD1−γt,Tφ2(t))pp−1dtt+C∫Taφ−1p−12(t)(CHD1+α−γt,Tφ2(t))pp−1dtt. |
Hence there holds
12∫Tafp(t)φ2(t)dtt+Cf(a)(logTa)γ−α≤C(logTa)pγ−1p−1+C(logTa)pγ−pα−1p−1. |
Then we get
f(a)<C(logTa)pγ−1p−1+α−γ+C(logTa)pγ−pα−1p−1+α−γ. | (4.5) |
If Eq (1.1) has a global solution, we know that f(a)=0 as T→∞ in (4.5) by 0<α<γ<1 and p<1+1−γα, which is inconsistent with f(a)>0. Hence, the mild solution of Eq (1.1) blows up in finite time.
(ii) Suppose that 1<p<˜p=1+2s(1+α−γ)αd. For t∈[a,T] with T>a>0, we take
φ1(x)=(Φ((logTa)−α2s|x|))2pp−1, φ2(t)=(1−log(t/a)log(T/a))m |
with m≥max{2,p(1+α−γ)p−1}, and φ(x,t)=CHD1−γt,T(φ1(x)φ2(t)).
Let u be a mild solution of Eq (1.1), then Theorem 3.2 implies
∫Rd∫Ta(upφ1φ2+uaφ1CHD1+α−γt,Tφ2)dttdx=∫Rd∫Ta(u((−Δ)sφ1)CHD1−γt,Tφ2+uφ1CHD1+α−γt,Tφ2)dttdx. | (4.6) |
Note that the fact
(−Δ)sφ1CHD1−γt,Tφ2≤C1(logTa)−(1+α−γ)φ1p1φ1p2, | (4.7) |
and
φ1CHD1+α−γt,Tφ2≤C2(logTa)−(1+α−γ)φ1p1φ1p2, | (4.8) |
where the positive constants C1 and C2 are independent of T.
According to (4.6)–(4.8), together with Young's inequality and Hölder inequality, it holds that
∫Rd∫Ta(upφ1φ2+uaφ1CHD1+α−γt,Tφ2)dttdx≤C(logTa)−(1+α−γ)+(1+αd2s)p−1p(∫Rd∫Taupφ1φ2dttdx)1p≤C(p)(logTa)1+αd2s−p(1+α−γ)p−1+∫Rd∫Taupφ1φ2dttdx. | (4.9) |
As a result,
C(α,γ)(logTa)γ−α∫Rduaφ1dx≤C(p)(logTa)1+αd2s−p(1+α−γ)p−1, | (4.10) |
i.e.,
∫Rduaφdx≤C(α,γ,p)(logTa)1+α−γ+αd2s−p(1+α−γ)p−1. | (4.11) |
The condition 1<p<1+2s(1+α−γ)αd indicates 1+α−γ+αd2s−p(1+α−γ)p−1<0. If Eq (1.1) has a global solution, then ∫Rduaφdx=0 as T→∞, that is ua≡0, which makes a contradiction with the assumption ua≢0. Therefore, blowup of the mild solution u of Eq (1.1) occurs in finite time.
(2) Based on the fixed point principle, we demonstrate the required result by constructing the global solution of Eq (1.1). Firstly, the condition p≥1+2s(1+α−γ)αd implies that
αd(p−1)2s(pα−pγ+1)+>1, | (4.12) |
where (pα−pγ+1)+=max{0,pα−pγ+1}. If d<2s(1+α−γ)1−γ, one has p≥˜p=1+2s(1+α−γ)αd, and if d≥2s(1+α−γ)1−γ, one gets p>˜p=1+1−γα. In either case, we obtain
αd(p−1)2sp(1+α−γ−(p−1)α)+>1. | (4.13) |
In addition, by p>1+1−γα>1γ, it follows that
d(p−1)2sp<αd(p−1)2s(p(α−γ)+1)+, | (4.14) |
and
d(p−1)2sp<αd(p−1)2sp(2α+1−γ−αp)+. | (4.15) |
Hence, taking (4.12)–(4.15) into account, we can choose q>p such that
1+α−γp−1−1p<αd2sq<αp−1, | (4.16) |
and
1+α−γp−1−α<αd2sq<αp−1. | (4.17) |
Let
β=αd2s(1p∗−1q)=1+α−γp−1−αd2sq. | (4.18) |
Then (4.16) gives
0<pβ<1. | (4.19) |
If the initial value ua satisfies
supt>a(logta)β||Ga(t)∗ua||Lq(Rd)=ϑ, | (4.20) |
then ϑ<+∞ by (4.18) and (2.10) provided that ua∈Lp∗(Rd) with p∗=αd(p−1)2s(1+α−γ).
Next we use the contractive mapping principle to obtain result. To this end, we denote
E={u∈L∞((a,∞),Lq(Rd))|||u||E=supt>a(logta)β||u||Lq(Rd)<+∞} |
and
Ψ(u)(t)=Ga(t)∗ua+∫taGf(atτ)∗[HD−(1−γ)a,τ(|u|p−1u)(τ)]dττ,∀u∈E. |
Define
EK={u∈E|||u||E≤K,K>0}. |
By q>p and q>d(p−1)4s, one gets pq−1q<min{1,4sd}. Thus, for any u,v∈EK and t>a, it follows that
(logta)β||Ψ(u)(t)−Ψ(v)(t)||Lq(Rd)≤(logta)β∫ta||Gf(atτ)∗[HD−(1−γ)a,τ(up(τ)−vp(τ))]||Lq(Rd)dττ≤CΓ(1−γ)(logta)β∫ta(logtτ)α−1−αd(p−1)2sq∫τa(logτw)−γ||up−vp||Lqp(Rd)dwwdττ≤CΓ(1−γ)(logta)β∫ta(logtτ)α−1−αd(p−1)2sq×∫τa(logτw)−γ(||u||p−1Lq(Rd)+||v||p−1Lq(Rd))||u−v||Lq(Rd)dwwdττ≤CKp−1Γ(1−γ)(logta)β∫ta(logtτ)α−1−αd(p−1)2sq∫τa(logτw)−γ(logwa)−pβdwwdττ||u−v||E=CKp−1Γ(1−γ)∫10(1−τ)α−1−αd(p−1)2sqτ1−γ−pβdτ∫10(1−w)−γw−pβdw||u−v||E=CKp−1Γ(1−γ)Γ(α−αd(p−1)2sq)Γ(2−γ−pβ)Γ(2+α−pβ−γ−αd(p−1)2sq)Γ(1−pβ)Γ(1−γ)Γ(2−γ−pβ)||u−v||E=CKp−1Γ(α−αd(p−1)2sq)Γ(1−pβ)Γ(2+α−pβ−γ−αd(p−1)2sq)||u−v||E. | (4.21) |
By taking K small enough such that
CK^{p-1}\frac{\Gamma(\alpha-\frac{\alpha d(p-1)}{2s q}\;\;)\Gamma(1-p\beta)} {\Gamma(2+\alpha-p\beta-\gamma-\frac{\alpha d(p-1)}{2s q}\;\;)} < \frac{1}{2}, |
which yields ||\Psi(u)-\Psi(v)||_{E}\leq \frac{1}{2}||u-v||_{E} by Eq (4.21).
A similar calculation as (4.21) results in
\begin{align} \left(\log\frac{t}{a}\right)^{\beta}||\Psi(u)(t)||_{L^{q}(\mathbb{R}^{d})} \leq \vartheta+ CK^{p}\frac{\Gamma(\alpha-\frac{\alpha d(p-1)}{2s q})\Gamma(1-p\beta)} {\Gamma(2+\alpha-p\beta-\gamma-\frac{\alpha d(p-1)}{2s q})}. \end{align} | (4.22) |
Choose sufficiently small \vartheta and K such that
\vartheta+ CK^{p}\frac{\Gamma(\alpha-\frac{\alpha d(p-1)}{2s q}\;\;)\Gamma(1-p\beta)} {\Gamma(2+\alpha-p\beta-\gamma-\frac{\alpha d(p-1)}{2s q}\;\;)}\leq K. |
This implies \Psi(u)\in E_{K} and thus \Psi has a fixed point u\in E_{K} by the contractive mapping principle.
Finally, We need to prove u\in C([a, \infty), C_{0}(\mathbb{R}^{d})) . For a T sufficiently close to a , let
E_{K, T} = \left\{u\in L^{\infty}((a,T), L^{q}(\mathbb{R}^{d}))\,\Big|\, \sup\limits_{a < t < T}\left(\log\frac{t}{a}\right)^{\beta} ||u(t)||_{L^{q}(\mathbb{R}^{d})}\leq K\right\}. |
As demonstrated before, it is known that there is a unique solution u on E_{K, T} . It follows from Theorem 3.1 and the initial value u_{a}\in C_{0}(\mathbb{R}^{d})\cap L^{q}(\mathbb{R}^{d}) that there exists a unique solution \widetilde{u}\in C([a, T], C_{0}(\mathbb{R}^{d}))\cap C([a, T], L^{q}(\mathbb{R}^{d})) for T sufficiently close to a . Hence, for T sufficiently close to a , one has \sup\limits_{a < t < T}\left(\log\frac{t}{a}\right)^{\beta} ||\widetilde{u}(t)||_{L^{q}(\mathbb{R}^{d})}\leq K . This means that u = \widetilde{u} for t\in [a, T] from the uniqueness of solution and thus u\in C([a, T], C_{0}(\mathbb{R}^{d}))\cap C([a, T], L^{q}(\mathbb{R}^{d})) .
Our purpose is to prove u\in C([a, \infty), C_{0}(\mathbb{R}^{d})) . In fact, for t > T , it holds that
\begin{align*} \label{mainresult-23} &u-G_{a}(t)*u_{a} = \int_{a}^{t}G_{f}\left(a\frac{t}{\tau}\right)* [\,_{H}{\rm{D}}^{-(1-\gamma)}_{a,\tau}u^{p}(\tau)]\frac{{\rm d}\tau}{\tau} \\ = &\int_{a}^{T}G_{f}\left(a\frac{t}{\tau}\right)*[\,_{H}{\rm{D}}^{-(1-\gamma)}_{a,\tau}u^{p}(\tau)]\frac{{\rm d}\tau}{\tau} +\int_{T}^{t}G_{f}\left(a\frac{t}{\tau}\right)*[\,_{H}{\rm{D}}^{-(1-\gamma)}_{a,\tau}u^{p}(\tau)]\frac{{\rm d}\tau}{\tau} \\ = &I_{1}+I_{2}. \end{align*} |
Using the fact u\in C([a, T], C_{0}(\mathbb{R}^{d})) , one obtains
I_{1} \in C([T, \infty), C_{0}(\mathbb{R}^{d}))\cap C([T, \infty), L^{q}(\mathbb{R}^{d})). |
For any \widetilde{T} > T , it can be easily find that u^{p}\in L^{\infty} ((T, \widetilde{T}), L^{q/p}(\mathbb{R}^{d})) and _{H}{\rm{D}}^{-(1-\gamma)}_{a, \tau}u^{p}\in L^{\infty}((T, \widetilde{T}), L^{q/p}(\mathbb{R}^{d})) . On the other hand, the condition q > \frac{d(p-1)}{2s} indicates that we may choose r > q such that \frac{d}{2s}(\frac{p}{q}-\frac{1}{r}) < 1 . As what we have proved in Lemma 2.5, it is obvious that I_{2}\in C([T, \widetilde{T}], L^{r}(\mathbb{R}^{d})) . By the arbitrariness of \widetilde{T} , we see that I_{2}\in C([T, \infty), L^{r}(\mathbb{R}^{d})) and thus u\in C([T, \infty), L^{r}(\mathbb{R}^{d})) .
Let r = q\lambda^{n} and \lambda > 1 satisfy
\frac{d}{2s}\left(\frac{p}{q\lambda^{n-1}}-\frac{1}{q\lambda^{n}}\right) < 1,\, n = 1,2,\ldots, |
then u\in C([T, \infty), L^{q\lambda^{n}}(\mathbb{R}^{d})) . After finite steps, one has \frac{p}{q\lambda^{n}} < \frac{2s}{d} . In other words, we show u\in C([a, \infty), C_{0}(\mathbb{R}^{d})) . This concludes the proof of the theorem.
Remark 4.1. It is worth noticing that, according to Theorem 1.1, the Fujita critical exponent to Eq (1.1) is the number \widetilde{p} = \max\{1+\frac{1-\gamma}{\alpha}, 1+\frac{2s(1+\alpha-\gamma)}{\alpha d}\} .
Remark 4.2. In the Eq (1.1) , we consider the case 0 < \alpha < \gamma < 1 and prove the main result, i.e., Theorem 1.1. If \gamma\geq \alpha with 0 < \alpha < 1 and 0\leq \gamma < 1 , then it is easy to verify that Theorems 3.1 and 3.2 are still valid provided that a mild solution and a weak solution are defined as Definitions 3.1 and 3.2. However, compared with Theorem 1.1, we see that the main conclusions are very different. In fact, we can derive the following result whose proof is similar to that of Theorem 1.1 or can also refer to the proof of Theorem 1 in [34].
Theorem 4.1. Let d\in \mathbb{N} , 0 < \alpha < 1 , 0\leq\gamma < 1 , \gamma\leq \alpha , 0 < s < 1 , and p > 1 .Assume that u_{a}\in C_{0}(\mathbb{R}^{d}) and u_{a}\geq 0 with u_{a}\not\equiv 0 .
(1) If 1 < p\leq\overline{p} = \max\{\frac{1}{\gamma}, 1+\frac{2s(1+\alpha-\gamma)}{(2+\alpha d-2s(1+\alpha-\gamma))_{+}}\} , then the mild solution of Eq (1.1) will blow up in finite time.
(2) If p > \overline{p} and ||u_{a}||_{L^{p^{*}}(\mathbb{R}^{d})} is small enough with p^{*} = \frac{\alpha d(p-1)}{2s(1+\alpha-\gamma)} , then Eq (1.1) exists global solution.
Remark 4.3. From Theorem 4.1, we remark that the Fujita critical exponent is \overline{p} = \max\{\frac{1}{\gamma}, 1+\frac{2s(1+\alpha-\gamma)}{(2+\alpha d-2s(1+\alpha-\gamma))_{+}}\} when \gamma\leq \alpha for 0 < \alpha < 1 and 0\leq\gamma < 1 .
In this section, we show the finite time blow-up of the solution to Eq (1.1) by numerical simulation. For this purpose, we have to approximate the Caputo-Hadamard derivative, fractional Laplacian and Hadamard fractional integral in Eq (1.1), respectively. We shall use formulaes (3.2) and (3.3) in [35] to discretize the Caputo-Hadamard derivative of order \alpha\in (0, 1) and apply formula (2.9) in [36] to approximate the fractional Laplacian of order s\in (0, 1) . For the right sided Hadamard fractional integral of order 1-\gamma\, (\gamma\in (0, 1)) in Eq (1.1), we present the following discrete scheme.
Let a = t_{0} < t_{1} < \ldots < t_{k} < \ldots < t_{N} = T be a partition of the interval [a, T] with N\in \mathbb{N} and some positive number T > a . Then the Hadamard fractional integral with order 1-\gamma\, (\gamma\in (0, 1)) can be approximated by, for t = t_{k}, 1\leq k\leq N ,
\begin{align*} _{H}{\rm{D}}_{a,t}^{-(1-\gamma)} g(t)|_{t = t_{k}} = &\frac{1}{\Gamma(1-\gamma)}\int_{a}^{t_{k}} \left(\log\frac{t_{k}}{\tau}\right)^{-\gamma}g(\tau)\frac{{\rm{d}}\tau}{\tau} \\ = &\frac{1}{\Gamma(1-\gamma)}\sum\limits_{j = 1}^{k}\int_{t_{j-1}}^{t_{j}} \left(\log\frac{t_{k}}{\tau}\right)^{-\gamma}g(\tau)\frac{{\rm{d}}\tau}{\tau} \\ \approx & \frac{1}{\Gamma(1-\gamma)}\sum\limits_{j = 1}^{k}\int_{t_{j-1}}^{t_{j}} \left(\log\frac{t_{k}}{\tau}\right)^{-\gamma}g(t_{j-1})\frac{{\rm{d}}\tau}{\tau} \\ = & \frac{1}{\Gamma(2-\gamma)}\sum\limits_{j = 1}^{k}\left[\left(\log\frac{t_{k}}{t_{j-1}}\right)^{1-\gamma} -\left(\log\frac{t_{k}}{t_{j}}\right)^{1-\gamma}\right]g(t_{j-1}) \\ = & \sum\limits_{j = 1}^{k}b_{j,k}g(t_{j-1}), \end{align*} |
where
b_{j,k} = \frac{1}{\Gamma(2-\gamma)}\left[\left(\log\frac{t_{k}}{t_{j-1}}\right)^{1-\gamma} -\left(\log\frac{t_{k}}{t_{j}}\right)^{1-\gamma}\right]. |
Based on these results, we obtain a numerical scheme to Eq (1.1). For simplicity, we now take d = 1, a = 1, p = 2 and u_{a} = 10 in Eq (1.1). Figure 1 depicts the curves of the solution to Eq (1.1) when the parameters \alpha and s choose different values and \gamma = 0.8 , which displays the finite time blow-up of solution of Eq (1.1) and thus shows the effectiveness of the results in Theorem 1.1. Similarly, Figure 2 presents the curves of the solution to Eq (1.1) in the case \gamma\leq \alpha and illustrates the validity of the results given by Theorem 4.1.
In this paper, we study the blow-up and global existence of solution of the Cauchy problem to time-space fractional partial differential Eq (1.1) with nonlinear memory. A mild solution and a weak solution are introduced to Eq (1.1) and the mild solution is actually shown to be the weak solution. We next prove the local existence and uniqueness of the mild solution of Eq (1.1) by using the fixed point argument. Finally, the finite time blow-up and global solution of Eq (1.1) are established and the Fujita critical exponent is also determined, where the blowing-up character of the solution in a finite time is verified by numerical simulations.
The work was partially supported by the Scientific and Technological Innovation Programs of Higher Education Institutions in Shanxi, China (No. 2021L573).
The author declare no conflict of interest.
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