Research article

Multiple solutions for a fractional p-Kirchhoff equation with critical growth and low order perturbations

  • Received: 16 February 2022 Revised: 04 April 2022 Accepted: 22 April 2022 Published: 06 May 2022
  • MSC : 35J20, 35J60, 47G20

  • In this article, we deal with the following fractional p-Kirchhoff type equation

    {M(RNRN|u(x)u(y)|p|xy|N+psdxdy)(Δ)spu=|u|pα2u|x|α+λ|x|β,in  Ω,u>0,in  Ω,u=0,in  RNΩ,

    where ΩRN is a smooth bounded domain containing 0, (Δ)sp denotes the fractional p-Laplacian, M(t)=a+btk1 for t0 and k>1, a,b>0, λ>0 is a parameter, 0<s<1, 0α<ps<N, N(p2)+psp1<β<N(pα1)+αpα, 1<p<pk<pα=p(Nα)Nps is the fractional critical Hardy-Sobolev exponent. With aid of the variational method and the concentration compactness principle, we prove the existence of two distinct positive solutions.

    Citation: Zusheng Chen, Hongmin Suo, Jun Lei. Multiple solutions for a fractional p-Kirchhoff equation with critical growth and low order perturbations[J]. AIMS Mathematics, 2022, 7(7): 12897-12912. doi: 10.3934/math.2022714

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  • In this article, we deal with the following fractional p-Kirchhoff type equation

    {M(RNRN|u(x)u(y)|p|xy|N+psdxdy)(Δ)spu=|u|pα2u|x|α+λ|x|β,in  Ω,u>0,in  Ω,u=0,in  RNΩ,

    where ΩRN is a smooth bounded domain containing 0, (Δ)sp denotes the fractional p-Laplacian, M(t)=a+btk1 for t0 and k>1, a,b>0, λ>0 is a parameter, 0<s<1, 0α<ps<N, N(p2)+psp1<β<N(pα1)+αpα, 1<p<pk<pα=p(Nα)Nps is the fractional critical Hardy-Sobolev exponent. With aid of the variational method and the concentration compactness principle, we prove the existence of two distinct positive solutions.



    Consider the following fractional p-Kirchhoff type equation with critical growth

    {M(RNRN|u(x)u(y)|p|xy|N+psdxdy)(Δ)spu=|u|pα2u|x|α+λ|x|β,in  Ω,u>0,in  Ω,u=0,in  RNΩ, (1.1)

    where ΩRN is a smooth bounded domain containing 0, (Δ)sp denotes the fractional p-Laplacian, M(t)=a+btk1 for t0 and k>1, a,b>0, λ>0 is a parameter, 0<s<1, 0α<ps<N, N(p2)+psp1<β<N(pα1)+αpα, 1<p<pk<pα=p(Nα)Nps is the fractional critical Hardy-Sobolev exponent.

    Problem (1.1) reduces to the following stationary analogue of the Kirchhoff equation

    (a+bΩ|u|2dx)Δu=f(x,u), (1.2)

    which was proposed by Kirchhoff in [12] as an extension of the classical D'Alembert's wave equation for free vibrations of elastic strings

    ρ2ut2(P0h+E2LL0|ux|2dx)2ux2=f(x,u). (1.3)

    Kirchhoff's model takes into account the changes in length of the string produced by transverse vibrations. Here, L is the length of the string, f(x,u) is the area of the cross section, E is the Young modulus of the material, ρ is the mass density and P0 is the initial tension. The appearance of nonlocal term Ω|u|2dx in the equations make its importance in many physical applications. It was pointed out that such nonlocal problems appear in other fields like biological systems, such as population density, where u describes a process which depends on the average of itself (see [1]).

    Recently a great attention has been focused on studying the problems involving fractional Sobolev spaces and corresponding nonlocal equations. Indeed, nonlocal fractional problems arise in a quite natural way in many different contexts, such as, optimization, finance, phase transitions, stratified materials, anomalous diffusion, semipermeable membranes and flame propagation, conservation laws, ultra-relativistic limits of quantum mechanics, water waves and so on, we refer to [15] for more details.

    In particular, Chen et al. in [6] considered the following fractional p-Laplacian equation with subcritical and critical growths

    {(Δ)spu=λ|u|r2u+μ|u|q2u|x|α,in  Ω,u=0,in  RNΩ, (1.4)

    where 0<s<1,p>1,λ,μ>0,0αps<N,prpα. They obtained the existence of positive solutions, ground state solutions and sign-changing solutions of the fractional p-Laplacian Eq (1.4) by using the variational method.

    In [22], Xiang et al. studied the following fractional p-Laplacian Kirchhoff type equation with critical growth

    M(RNRN|u(x)u(y)|p|xy|N+psdxdy)(Δ)spu=|u|ps2u+λf(x),in  RN, (1.5)

    where M(t)=a+btk1 for t0 and k>1, a0, b>0, 0<s<1 and 1<p<N/s, ps=Np/(Nps) is the critical Sobolev exponent, λ0 is a parameter, fLps/(ps1)(RN{0}) is a nonnegative function. By the variational method, the authors proved that Eq (1.5) admits at least two nonnegative solutions.

    Recently, the following fractional p-Laplacian Kirchhoff type equation with critical growth has been well studied by various authors

    {M(RNRN|u(x)u(y)|p|xy|N+psdxdy)(Δ)spu=|u|pα2u|x|α+λf(x,u),in  Ω,u=0,in  RNΩ, (1.6)

    where M(t)=a+btk1 with t0 and k>1, 0<s<1, a0,b>0, 0α<ps<N, λ>0 is a parameter. When f(x,u)=w(x)|u|q2u, Fiscella and Pucci in [10] deal with the existence and the asymptotic behavior of nontrivial solutions for Eq (1.6) with pk<q<pα. In [5], Chen and Gui obtained the existence of multiple solutions to Eq (1.6) with w(x)=1 and 1<q<p<pk. When f(x,u)=(IμF(x,u))f(u), Iμ=|x|μ is the Riesz potential of order μ(0,min{N,2ps}), Chen [4] established the existence of positive solutions to Eq (1.6). Chen, Rǎdulescu and Zhang in [7] obtained the existence of a positive weak solution of Eq (1.6) with f(x,u)=|u|q2u and 1<q<NpNps. Many papers studied the existence of infinitely many weak solutions and nontrivial solutions of Eq (1.6), we refer the readers to [3,9,11,16,17,18,19,20,21,23,24] and the reference therein.

    In this paper, we are interested in the existence and multiplicity of positive solutions of Problem (1.1) with critical growth. Our technique based on the Ekland variational principle and the Mountain pass lemma. Since the Problem (1.1) is critical growth, which leads to the cause of the lack of compactness of the embedding Ws,p(Ω)Lpα(Ω), we overcome this difficulty by using the concentration compactness principle.

    Now we state our main result.

    Theorem 1.1. Let 0α<ps<N and N(p2)+psp1<β<N(pα1)+αpα, there exists Λ>0 such that for all λ(0,Λ), problem (1.1) has at least two positive solutions.

    Define Ws,p(Ω), the usual fractional Sobolev space endowed with the norm

    uWs,p(Ω)=uLp(Ω)+(ΩΩ|u(x)u(y)|p|xy|N+psdxdy)1p.

    Let Q=RN×RN(CΩ×CΩ) with CΩ=RNΩ, define

    X={u:RNRmeasurable,u|ΩLp(Ω)andQ|u(x)u(y)|p|xy|N+psdxdy<}.

    The space X is endowed with the norm

    uX=uLp(Ω)+(Q|u(x)u(y)|p|xy|N+psdxdy)1p,

    where the norm in Lp(Ω) is denoted by p. The space X0 is defined as X0={uX:u=0onCΩ} or equivalently the closure of C0 in X, for all p>1, it is a uniformly convex Banach space endowed with the norm

    u:=uX0=(RNRN|u(x)u(y)|p|xy|N+psdxdy)1p. (2.1)

    The dual space of X0 will be denoted by X0. Since u=0 in RNΩ, the integral in (2.1) can be extended to RN×RN.

    The energy functional Iλ:X0R associated with Eq (1.1) is

    Iλ(u)=apup+bpkupk1pαΩ|u|pα|x|αdxλΩu|x|βdx.

    We say that u is a weak solution of Eq (1.1), if u satisfies

    (a+bup(k1))u,φs,p=Ω|u|pα2uφ|x|αdx+λΩφ|x|βdx,

    for all φX0, where

    u,φs,p=RNRN|u(x)u(y)|p2(u(x)u(y))[φ(x)φ(y)]|xy|N+psdxdy.

    Let Sα be the best fractional critical Hardy-Sobolev constant

    Sα:=infuWs,p(Ω){0}RNRN|u(x)u(y)|p|xy|N+psdxdy(Ω|u|pα|x|αdx)p/pα.

    Denote by Sρ (respectively, Bρ) the sphere (respectively, the closed ball) of center zero and radius ρ, i.e., Sρ={uX0:u=ρ}, Bρ={uX0:uρ}. C,C1,C2, denote various positive constants, which may vary from line to line.

    Then, we can obtain the following useful Lemma.

    Lemma 2.1. There exist constants r,ρ,Λ0>0, such that the functional Iλ satisfies the following conditions for all λ(0,Λ0):

    (i) Iλ(u)r with u=ρ and infIλ(u)<0 for uρ;

    (ii) There exists eX0 such that e>ρ and Iλ(e)<0.

    Proof. (i) Let R be a constant such that ΩB(0,R)={xRN:|x|<R}, by the H¨older inequality and the Sobolev inequality, for all β<N(pα1)+αpα, we have

    |Ωu|x|βdx|Ω(|u||x|α|x|β)1|x|αdx(Ω|u|pα|x|αdx)1pα(Ω1|x|α(|x|α|x|β)pαpα1dx)pα1pαS1pαu(ωR0t(N1)+αpαpα1αβpαpα1dt)pα1pα=S1pαu(ωα(pαpα11)+Nβpαpα1Rα(pαpα11)+Nβpαpα1)pα1pα=S1pαuψpα1pα, (2.2)

    where ψ=ωα(pαpα11)+Nβpαpα1Rα(pαpα11)+Nβpαpα1 and ω denotes the N-dimensional measure of the unit sphere. Combining with (2.2) and the Sobolev inequality, one has

    Iλ(u)=apup+bpkupk1pαΩ|u|pα|x|αdxλΩu|x|βdxbpkupk1pαSpαpαupαλS1pαuψpα1pα=u(bpkupk11pαSpαpαupα1λS1pαψpα1pα). (2.3)

    Let h(t)=bpktpk11pαSpαpαtpα1 for t>0, then there exists

    ρ=[bpα(pα1)pk(pk1)Spαpα]1pαpk>0

    such that maxt>0h(t)=h(ρ)>0. Setting Λ0=S1pαh(ρ)ψpα1pα, there exists a constant r>0, for all λ(0,Λ0), we obtain that Iλ(u)r>0 with u=ρ.

    For all uX0{0}, we get

    limt0Iλ(tu)t=λΩu|x|βdx<0. (2.4)

    Hence, we obtain that Iλ(tu)<0 with t>0 small enough, when uρ, one has

    m:=infuX0Iλ(u)<0.

    (ii) For every uX0{0}, we have

    Iλ(tu)=atppup+btpkpkupktpαpαΩ|u|pα|x|αdxλΩtu|x|βdx

    as t+. Consequently, we can find eX0 such that Iλ(e)<0 provided with e>ρ. The proof is complete.

    Next, we assume that a, b and k satisfy one of the following cases:

    Case 2.1. k=NαNps,a>0,0<b<Skα,

    Case 2.2. k=2Npsα2(Nps),a>0,b>0.

    Denote

    Λ={(1p1pk)(akSkα1bSkα)1k1,(Case2.1.1),a(1p1pk)(bS2k1α+Sk1αb2S2kα+4aSα2)1k1+(1pk1pα)(bSkα+b2S2kα+4aSα2)2k1k1,(Case2.2.1),

    and

    D=(aSαpaSαpk)1p1(11pk)pp1ψp(pα1)pα(p1).

    Then, we have the following compactness result.

    Lemma 2.2. Suppose that a,b>0 and 1<p<pk<pα, then the functional Iλ satisfies the (PS)cλ condition for cλ<c=ΛDλpp1.

    Proof. Let {un}X0 be a (PS)cλ sequence for

    Iλ(un)cλ, and Iλ(un)0 as n. (2.5)

    It follows form (2.2) and (2.5) that

    cλ+1+o(un)Iλ(un)1pαIλ(un),un(1p1pα)aunp+(1pk1pα)bunpk(11pα)λS1punψpα1pα.

    This implies that {un} is bounded in X0. Up to a subsequence, still denote by {un}, there exists uX0 such that

    {unu,weaklyinX0,unu,stronglyinLq(Ω)(1q<pα),un(x)u(x),a.e.inΩ. (2.6)

    By using the concentration compactness principle ([6], Lemma 4.5), there exist uX0, two Borel regular measures σ and ν, J denumerable, at most countable set {xj}jJˉΩ, and non-negative numbers {σj}jJ,{νj}jJ[0,), for all jJ, such that

    unpσ,|un|pα|x|αν,dσup+jJσjδxj,σj:=σ({xj}),dν=|u|pα|x|α+jJνjδxj,νj:=ν({xj}),σjSανppαj, (2.7)

    as n. Fix ε>0, let ϕε,j(x)C0(B(xj,2ε)) be a smooth cut-off function centered at xj such that 0ϕε,j1, ϕε,jCε, and

    ϕε,j(x)={1,inB(xj,ε),0,inΩB(xj,2ε).

    Clear {ϕε,jun} is bounded in X0, it follows from Iλ(un),ϕε,jun0 as n that

    (a+bunp(k1))RNRN|un(x)un(y)|p2(un(x)un(y))[ϕε,j(x)un(x)ϕε,j(y)un(y)]|xy|N+psdxdy=Ω|un|pαϕε,j(x)|x|αdx+λΩunϕε,j(x)|x|βdx+o(1). (2.8)

    From the first term in (2.8), we have

    RNRN|un(x)un(y)|p2(un(x)un(y))[ϕε,j(x)un(x)ϕε,j(y)un(y)]|xy|N+psdxdy=RNRN|un(x)un(y)|p2(un(x)un(y))[un(x)un(y)]ϕε,j(x)|xy|N+psdxdy+RNRN|un(x)un(y)|p2(un(x)un(y))un(y)[ϕε,j(x)ϕε,j(y)]|xy|N+psdxdy. (2.9)

    Note that {un} is bounded in X0, the third term in (2.9), by using the H¨older inequality and Lemma 2.3 in [22], we get

    limε0limn|RNRN|un(x)un(y)|p2(un(x)un(y))un(y)[ϕε,j(x)ϕε,j(y)]|xy|N+psdxdy|limε0limn(RNRN|un(x)un(y)|p|xy|N+psdxdy)p1p(RNRN|(ϕε,j(x)ϕε,j(y))un(y)|p|xy|N+psdxdy)1pClimε0limn(RNRN|(ϕε,j(x)ϕε,j(y))un(y)|p|xy|N+psdxdy)1p=0,

    where C>0 is a positive constant. Letting ε0, by (2.2) and (2.7), we get

    limε0limnΩunϕε,j(x)|x|βdx=0,limε0limnRNRN|un(x)un(y)|pϕε,j(x)|xy|N+psdxdy(limε0RNRN|u(x)u(y)|pϕε,j(x)|xy|N+psdxdy+σj)=σj,limε0limnΩ|un|pαϕε,j(x)|x|αdx=(limε0Ω|u|pαϕε,j(x)|x|αdx+νj)=νj. (2.10)

    Combining the above facts with (2.8), we have

    limε0limn(a+bunp(k1))RNRN|un(x)un(y)|pϕε,j(x)|xy|N+psdxdylimε0limn{aRNRN|u(x)u(y)|pϕε,j(x)|xy|N+psdxdy+aσj+b(RNRN|u(x)u(y)|pϕε,j(x)|xy|N+psdxdy+σj)k}=aσj+bσkj. (2.11)

    Hence, taking the limit for n and ε0 in (2.8), it follows from (2.10) and (2.11) that

    νjaσj+bσkj.

    This together with (2.7) implies that either νj=0 or

    νj{(aSα1bSkα)kk1,(Case2.1.2),(bSkα+b2S2kα+4aSα2)2k1k1,(Case2.2.2). (2.12)

    From (2.7) and (2.12), we obtain that σj=0 or

    σj{(aSkα1bSkα)1k1,(Case2.1.3),(bS2k1α+Sk1αb2S2kα+4aSα2)1k1,(Case2.2.3). (2.13)

    To proceed further we show that (2.12) and (2.13) are impossible. Indeed, by contradiction, we assume that there exists j0J such that (2.12) and (2.13) hold. Applying (2.2), (2.7) and the Sobolev inequality, we get

    cλ=limn{Iλ(un)1pkIλ(un),un}=limn{a(1p1pk)RNRN|un(x)un(y)|p|xy|N+psdxdy+(1pk1pα)Ω|un|pα|x|αdx(11pk)λΩun|x|βdx}a(1p1pk)(up+σj0)+(1pk1pα)(Ω|u|pα|x|αdx+νj0)(11pk)λΩu|x|βdxa(1p1pk)(Sαuppα+σj0)+(1pk1pα)(upαpα+νj0)(11pk)λψpα1pαupα.

    By using the Young inequality, when a>0, we have

    (11pk)λψpα1pαupα(apapk)Sαuppα+(aSαpaSαpk)1p1(11pk)pp1ψp(pα1)pα(p1)λpp1.

    Consequently, we deduce that cλc=ΛDλpp1. This is a contradiction. Hence σj=νj=0 for all jJ, which implies that

    Ω|un|pα|x|αdxΩ|u|pα|x|αdx, (2.14)

    as n. Now, we prove that unu in X0, let φX0 be fixed and Bφ be the linear functional on X0 defined by

    Bφ(v)=RNRN|φ(x)φ(y)|p2\(φ(x)φ(y))|xy|N+ps(v(x)v(y))dxdy,

    for every vX0. By using the H¨older inequality, one has

    |Bφ(v)|φp1v.

    According to Iλ(un)0 in X0 and unu in X0, we have

    o(1)=Iλ(un)Iλ(u),unu=(a+bunp(k1))Bun(unu)(a+bup(k1))Bu(unu)Ω|un|pα2un|u|pα2u|x|α(unu)dxλΩunu|x|βdx=(a+bunp(k1))[Bun(unu)Bu(unu)]+[(a+bunp(k1))(a+bup(k1))]Bu(unu)Ω|un|pα2un|u|pα2u|x|α(unu)dxλΩunu|x|βdx. (2.15)

    Since {un} is bounded in X0, by (2.6), one has

    limn(a+bunp(k1))Bun(unu)=0,limn(a+bunp(k1))Bu(unu)=0,limnΩunu|x|βdx=0, (2.16)

    then

    limn(a+bunp(k1))[Bun(unu)Bu(unu)]=0.

    By a,b>0, we get

    limn[Bun(unu)Bu(unu)]=0. (2.17)

    Moreover, it follows from the Brezis-Lieb Lemma that

    Ω|unu|pα|x|αdx=Ω|un|pα|x|αdxΩ|u|pα|x|αdx+o(1)0,asn.

    This together with (2.14) and the H¨older inequality, one has

    Ω|un|pα2un|u|pα2u|x|α(unu)dx0,asn.

    Let us now recall the well-known Simon inequalities. That is, for every ξ,ηRN

    |ξη|p{cp(|ξ|p2ξ|η|p2η)(ξη),forp2,Cp[(|ξ|p2ξ|η|p2η)(ξη)]p2(|ξ|p+|η|p)2p2,for1<p<2, (2.18)

    where cp,Cp>0 depending only on p. According to (2.18), we distinguish two cases:

    Case 2.3. if p2, it follows from (2.17) and (2.18) as n that

    unup=RNRN|un(x)u(x)un(y)+u(y)|p|xy|N+psdxdycpRNRN|un(x)un(y)|p2(un(x)un(y))|u(x)u(y)|p2(u(x)u(y))|xy|N+ps×(un(x)u(x)un(y)+u(y))dxdy=cp[Bun(unu)Bu(unu)]=o(1).

    Case 2.4. if 1<p<2, letting ξ=un(x)un(y) and η=u(x)u(y) in (2.18) as n, we get

    unupCp[Bun(unu)Bu(unu)]p2(unp+up)2p2Cp[Bun(unu)Bu(unu)]p2(unp(2p)2+up(2p)2)Cp[Bun(unu)Bu(unu)]p2=o(1).

    Indeed, since unp and up are bounded in X0, by the subadditivity inequality, for all ξ,η0 and 1<p<2, one has

    (ξ+η)2p2ξ2p2+η2p2.

    Thus, we obtain that unu in X0. The proof is complete.

    From [13], let 0α<ps<N, for all minimizer Uα for Sα, there exist x0RN and a non-increasing u:R+R such that Uα=u(|xx0|). Next, we fix a positive radially symmetric decreasing minimizer Uα=Uα(r) for Sα, multiplying Uα by a positive constant, we assume that

    (Δ)spUα=Upα1α|x|α,inRN.

    Then, we have the following Lemma.

    Lemma 2.3. ([13]) There exist c1,c2>0 and θ>1 such tha

    c1rnpsp1Uα(r)c2rnpsp1,Uα(θr)Uα(r)12,foreveryr1.

    For any ε>0, the function

    Uα,ε(x)=εNpspUα(xε)

    is also a minimizer for Sα. For all δε>0, let

    mε,δ=Uα,ε(δ)Uα,ε(δ)Uα,ε(θδ),

    and

    gε,δ(t)={0,if0tUα,ε(θδ),mpε,δ(tUα,ε(θδ)),ifUα,ε(θδ)tUα,ε(δ),t+Uα,ε(δ)(mp1ε,δ1),iftUα,ε(δ),

    as well as

    Gε,δ(t)=t0gε,δ(τ)1pdτ={0,if0tUα,ε(θδ),mε,δ(tUα,ε(θδ)),ifUα,ε(θδ)tUα,ε(δ),t,iftUα,ε(δ).

    The functions gε,δ and Gε,δ are nondecreasing and absolutely continuous. Consider now the radiallysymmetric non-increasing function uε,δ(r)=Gε,δ(Uα,ε(r)), which satisfies

    uε,δ(r)={Uα,ε(r),ifrδ,0,ifrθδ.

    Moreover, from [6,13], there exists C>0 such that for all 0<2εδ<θ1δΩ, we have

    {RNRN|uε,δ(x)uε,δ(y)|p|xy|N+psdxdySNαpsαα+C(εδ)Npsp1,RN|uε,δ|pα|x|αdxSNαpsααC(εδ)Nαp1. (2.19)

    Then we have the following Lemma.

    Lemma 2.4. Suppose that 0α<ps<N and N(p2)+psp1<β<N(pα1)+αpα.Then there exists Λ>0, for all λ(0,Λ) such that supt0Iλ(tuε)<c=ΛDλpp1( where c isthe constant given in Lemma 2.2).

    Proof. By Lemma 2.1, we obtain that Iλ(tu) as t and Iλ(tu)<0 as t0, then there exists tε>0 such that Iλ(tεu)=supt>0Iλ(tu)r>0. Assume that there exist positive constants t1,t2>0 such that 0<t1<tε<t2<+. Without loss of generality, we take δ=1 in the definition of uε,δWs,p(Ω) given in Lemma 2.3, for any sufficiently small 0<ε<1, set uε=uε,1 and Iλ(tuε)=J(t)λΩuε|x|βdx, where

    J(t)=atppuεp+btpkpkuεpktpαpαΩ|uε|pα|x|αdx.

    It is easy to see that limt0J(t)=0 and limtJ(t)=. Hence, there exists tε>0 such that J(tε)=maxt0J(t), that is

    J(t)|tε=atp1εuεp+btpk1εuεpktpα1εΩ|uε|pα|x|αdx=0. (2.20)

    By (2.20), we have

    tε={(auεpΩ|uε|pα|x|αdxbuεpk)1p(k1),(Case2.1.4),[buεpk+b2uε2pk+4auεpΩ|uε|pα|x|αdx2Ω|uε|pα|x|αdx]1p(k1),(Case2.2.4). (2.21)

    In addition, by the definition of uε, we have

    Ωuε|x|βdxBδuε|x|βdx=BδεNpspU(xε)|x|βdx=εNβNpspBδεU(x)|x|βdxCεNβNpspBδεB11|x|Npsp1|x|βdxC1εNβNpsp, (2.22)

    where β<N(pα1)+αpα=NNpsp and C1>0 is a positive constant. Now, we consider the following two cases:

    For Case 2.1, if k=NαNps,a>0,0<b<Skα and pα=pk. It follows from (2.19), (2.20) and (2.22) that

    supt0J(t)=J(tε)=tpε(apuεp+bpktp(k1)εuεpk1pαtpαpεΩ|uε|pα|x|αdx)=tpε(apapk)uεp+(1pk1pα)tpαεΩ|uε|pα|x|αdx=(apapk)uεp(auεpΩ|uε|pα|x|αdxbuεpk)1k1(apapk)(SNαpsαα+CεNpsp1)(a(SNαpsαα+CεNpsp1)(SNαpsααCεNαp1)b(SNαpsαα+CεNpsp1)k)1k1(1p1pk)(akSkα1bSkα)1k1+C2εNpsp1.

    Consequently, from the above information, we obtain

    supt0Iλ(tuε)J(tε)λΩuε|x|βdxΛ+C2εNpsp1C1λεNβNpsp<ΛDλpp1,

    where C1,C2>0 (independent of ε,λ). Here we have used the fact that N(p2)+psp1<β<N(pα1)+αpα, and let ε=λpNps, 0<λ<Λ1=min{1,(C2+DC1)(Nps)(p1)p[(Nβ)(p1)(Nps)]},then

    C2λpp1C1λ(λpNps)NβNpsp=λpp1(C2C1λp[(Nβ)(p1)(Nps)](Nps)(p1))<Dλpp1. (2.23)

    For Case 2.2, if k=2Npsα2(Nps),a>0,b>0. According to (2.19), (2.20) and (2.22), we have

    supt0J(t)=J(tε)=tpε(apuεp+bpktp(k1)εuεpk1pαtpαpεΩ|uε|pα|x|αdx)=(apapk)tpεuεp+(1pk1pα)tpαεΩ|uε|pα|x|αdx=a(1p1pk)[buεpk+b2uε2pk+4auεpΩ|uε|pα|x|αdx2Ω|uε|pα|x|αdx]1k1uεp+(1pk1pα)[buεpk+b2uε2pk+4auεpΩ|uε|pα|x|αdx2Ω|uε|pα|x|αdx]pαp(k1)Ω|uε|pα|x|αdxa(1p1pk)(bS2k1α+Sk1αb2S2kα+4aSα2)1k1+(1pk1pα)(bSkα+b2S2kα+4aSα2)2k1k1+C3εNpsp1,

    where C3>0 (independent of ε,λ). Consequently, it is similar to Case 2.1, by (2.23), there exists Λ2>0 such that 0<λ<Λ2, we get

    supt0Iλ(tuε)J(tε)λΩuε|x|βdxΛ+C3εNpsp1C1εNβNpsp<ΛDλpp1.

    The proof is complete.

    Theorem 3.1. Suppose that 0<λ<Λ (Λ=min{Λ0,Λ1,Λ2,1}). Then the Eq (1.1) has two positive solutions.

    Proof. It follows from Lemma 2.1 that

    m:=infuBρ(0)Iλ(u)<0.

    By the Ekland variational principle [8], there exists a minimizing sequence {un}¯Bρ(0) such that

    Iλ(un)infu¯Bρ(0)Iλ(u)+1n,Iλ(v)Iλ(un)1nvun,v¯Bρ(0).

    Hence, we obtain that Iλ(un)m and Iλ(un)0 as n. By Lemma 2.2, we have unuλ in X0 with Iλ(un)m<0, which implies that uλ0. Note that Iλ(un)=Iλ(|un|), we have uλ0. Thus, by using the strong maximum principle ([14], Lemma 2.3), we obtain that uλ is a positive solution of Eq (1.1) such that Iλ(uλ)<0.

    Applying the Mountain pass Lemma [2], Lemmas 2.1 and 2.2, there exists a sequence {un}X0 such that

    Iλ(un)cλ,andIλ(un)0asn,

    where

    cλ=infγΓmaxt[0,1]Iλ(γ(t)),

    and

    Γ={γC([0,1],X0):γ(0)=0,γ(1)=e}.

    According to Lemma 2.2, we know that {un}X0 has a convergent subsequence, still denoted by {un}, we may assume that unu in X0 as n.

    Iλ(u)=limnIλ(un)>r>0,

    which implies that u0. Similarly, we can obtain that u is a positive solution of Eq (1.1) with Iλ(u)>0. That is, the proof of Theorem 1.1 is complete.

    In this paper, we consider a class of fractional p-Kirchhoff type equations with critical growth. Under some suitable assumptions, by using the variational method and the concentration compactness principle, we obtain the existence and multiplicity of positive solutions.

    This research was supported by the National Natural Science Foundation of China (No. 11661021). Supported by the projects of Education Department of Guizhou province (No. [2018]140). The school level fund project of Guizhou Minzu University (No. GZMUZK[2021]QN05).

    The authors declare no conflict of interest in this paper.



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