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Research article

Derivative of self-intersection local time for the sub-bifractional Brownian motion

  • Received: 26 December 2021 Revised: 22 February 2022 Accepted: 02 March 2022 Published: 24 March 2022
  • MSC : 60G22, 60J55

  • Let SH,K={SH,Kt,t0} be the sub-bifractional Brownian motion (sbfBm) of dimension 1, with indices H(0,1) and K(0,1]. We mainly consider the existence of the self-intersection local time and its derivative for the sbfBm. Moreover, we prove its derivative is H¨older continuous in space variable and time variable, respectively.

    Citation: Nenghui Kuang, Huantian Xie. Derivative of self-intersection local time for the sub-bifractional Brownian motion[J]. AIMS Mathematics, 2022, 7(6): 10286-10302. doi: 10.3934/math.2022573

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  • Let SH,K={SH,Kt,t0} be the sub-bifractional Brownian motion (sbfBm) of dimension 1, with indices H(0,1) and K(0,1]. We mainly consider the existence of the self-intersection local time and its derivative for the sbfBm. Moreover, we prove its derivative is H¨older continuous in space variable and time variable, respectively.



    Recently, El-Nouty and Journˊe [3] introduced the process SH,K={SH,Kt,t0} on the probability space (Ω,F,P) with indices H(0,1) and K(0,1], named the sub-bifractional Brownian motion (sbBm) and defined as follows:

    SH,Kt=12(2K)/2(BH,Kt+BH,Kt), (1.1)

    where {BH,Kt,tR} is a bifractional Brownian motion (bBm) with indices H(0,1) and K(0,1], namely,

    BH,Kt={BH,Kt(1),if  t0;BH,Kt(2),if  t<0. (1.2)

    and BH,Kt(1) and BH,Kt(2) are independent bifractional Brownian motions in [0,+) with indices H(0,1) and K(0,1], where bifractional Brownian motion {BH,Kt(1),t0} is a centered Gaussian process, starting from zero, with covariance

    E[BH,Kt(1)BH,Ks(1)]=12K[(t2H+s2H)K|ts|2HK],

    with H(0,1) and K(0,1].

    Clearly, the sbBm is a centered Gaussian process such that SH,K0=0, with probability 1, and Var(SH,Kt)=(2K22HK1)t2HK. Since (2H1)K1<K10, it follows that 2HK1<K. We can easily verify that SH,K is self-similar with index HK. When K=1, SH,1 is the sub-fractional Brownian motion (sfBm). For more on sub-fractional Brownian motion, we can see Kuang and Xie [15,16], Kuang and Liu [13,14], Xie and Kuang [21] and so on. Straightforward computations show that for all s,t0,

    E(SH,KtSH,Ks)=(t2H+s2H)K12(t+s)2HK12|ts|2HK (1.3)

    and

    C1|ts|2HKE[(SH,KtSH,Ks)2]C2|ts|2HK, (1.4)

    where

    C1=min{2K1,2K22HK1},    C2=max{1,222HK1}. (1.5)

    (See El-Nouty and Journˊe [3]). Kuang [11] investigated the collision local time of two independent sub-bifractional Brownian motions. Kuang and Li [12] obtained Berry-Esséen bounds and proved the almost sure central limit theorem for the quadratic variation of the sub-bifractional Brownian motion.

    The self-intersection local time of fractional Brownian motion (fBm) BH={BHt,t0} was first studied in Rosen [17], and formally defined by

    αt(y):=Dδ(BHsBHry)drds,

    where D={(r,s):0<r<s<t} and δ is the Dirac delta function. It was further investigated in Hu [4] and Hu and Nualart [5]. Jiang and Wang [8] considered self-intersection local time and collision local time of bifractional Brownian motion. Chen et al. [2] studied renormalized self-intersection local time of bifractional Brownian motion.

    The context of derivative for the self-intersection local time is organized as follows. Rosen [18] first studied the Brownian motion case, and Yan et al. [22] extended this to fractional Brownian motion. On this basis, Jung and Markowsky [9,10] considered some in-depth results for derivative of the self-intersection local time of fractional Brownian motion. Jaramillo and Nualart [6,7] studied asymptotic properties of the derivative of self-intersection local time of fractional Brownian motion and functional limit theorem for the self-intersection local time of the fractional Brownian motion, respectively. Yan and Yu [23] considered the multidimensional fractional Brownian motion case. Yu [24] investigated higher order derivative of self-intersection local time for fBm. Shi [19] investigated fractional smoothness of derivative of self-intersection local time for bi-fractional Brownian motion.

    Moreover, many authors have proposed to use more general self-similar Gaussian processes and random fields as stochastic models, and such applications have raised many interesting theoretical questions about self-similar Gaussian processes and fields in general. Therefore, some generalizations of the fBm has been introduced. However, contrast to the extensive studies on fractional Brownian motion, there has been little systematic investigation on other self-similar Gaussian processes. The main reason for this is the complexity of dependence structures for self-similar Gaussian processes which do not have stationary increments. Thus, it seems interesting to study some extensions of fractional Brownian motion such as sbfBm.

    In this paper, we will study the existence of the self-intersection local time and its derivative for the sub-bifractional Brownian motion SH,K={SH,Kt,t0}. They are defined by, respectively,

    αt(y):=Dδ(SH,KsSH,Kry)drds (1.6)

    and

    αt(y):=Dδ(SH,KsSH,Kry)drds, (1.7)

    where D={(r,s):0<r<s<t}.

    Set

    pϵ(x):=12πϵex22ϵ=12πReipxeϵp22dp (1.8)

    and

    pϵ(x):=dpϵ(x)dx=x2πϵ3ex22ϵ=i2πRpeipxeϵp22dp. (1.9)

    Now we state our main results as follows.

    Theorem 1.1. Existence of self-intersection local time.

    Define:

    αt,ϵ(y):=t0s0pϵ(SH,KsSH,Kry)drds,  yR, (1.10)

    for H(0,1) and K(0,1]. Then αt,ϵ(y) converges in L2(Ω,P) as ϵ0, we denote the limit by αt(y).

    Theorem 1.2. Existence of the derivative of self-intersection local time.

    Define:

    αt,ϵ(y):=t0s0pϵ(SH,KsSH,Kry)drds,  yR. (1.11)

    If H(0,1),K(0,1], and 0<2HK<1, then αt,ϵ(y) converges in L2(Ω,P) as ϵ0, we denote the limit by αt(y).

    Theorem 1.3. Let n1 be an arbitrary but fixed integer, t,˜t[0,T] and as 0<2HK<1.

    (1) For any τ(0,min{1,1HK2}), there exists a positive constant C, such that

    E[|αt(y1)αt(y2)|n]C|y1y2|nτ, (1.12)

    where y1,y2R.

    (2) For any γ<12HK, there exists a positive constant C, such that

    E[|αt(y)α˜t(y)|n]C|t˜t|nγ, (1.13)

    where yR.

    In what follows, we will use m to denote unspecified positive and finite constants whose value may be different in each occurrence.

    In this section, we give some useful lemmas in order to prove the Theorems 1.1–1.3.

    Lemma 2.1. For all constants 0<a<b, SH,K is strongly locally φ-nondeterministic onI=[a,b] with φ(r)=r2HK. That is, there exist positive constants c1 and r0 such that for all tI and all 0<rmin{t,r0},

    Var{SH,Kt|SH,Ks:sI,r|st|r0}c1φ(r). (2.1)

    Proof. See Kuang [11].

    From the local nondeterminism (see Berman [1], Xiao [20]), we have the following property: if 0t1<t2<<tn<T, then there is a constant m>0 such that

    Var(ni=2ui(SH,KtiSH,Kti1))mni=2u2i|titi1|2HK, (2.2)

    for any uiR,i=2,3,,n.

    Lemma 2.2. Let

    λ:=Var(SH,KsSH,Kr),ρ:=Var(SH,KsSH,Kr),

    and

    μ:=Cov(SH,KsSH,Kr,SH,KsSH,Kr).

    Case 2.1. If (r,s,r,s)D1:={(r,s,r,s)|0<r<r<s<s<t}, denoting a=rr,b=sr,c=ss, then we have

    (1)

    C1(a+b)2HKλ=λ1C2(a+b)2HK,C1(b+c)2HKρ=ρ1C2(b+c)2HK, (2.3)

    where C1 and C2 are given by (1.5).

    (2) There exists a positive constant m, such that

    λ1ρ1μ21m[(a+b)2HKc2HK+(b+c)2HKa2HK], (2.4)

    where μ=μ1.

    (3) When 0<2HK<1, there exists a positive constant m, such that

    μ=μ1m(a2HK+b2HK+c2HK). (2.5)

    Case 2.2. If (r,s,r,s)D2:={(r,s,r,s)|0<r<r<s<s<t}, denoting a=rr,b=sr,c=ss, then we have

    (1)

    C1(a+b+c)2HKλ=λ2C2(a+b+c)2HK,  C1b2HKρ=ρ2C2b2HK, (2.6)

    where C1 and C2 are given by (1.5).

    (2) There exists a positive constant m, such that

    λ2ρ2μ22mb2HK(a2HK+c2HK), (2.7)

    where μ=μ2.

    (3) When 0<2HK<1, there exists a positive constant m, such that

    μ=μ2mb2HK. (2.8)

    Case 2.3. If (r,s,r,s)D3:={(r,s,r,s)|0<r<s<r<s<t}, denoting a=sr,b=rs,c=sr, then we have

    (1)

    C1a2HKλ=λ3C2a2HK,  C1c2HKρ=ρ3C2c2HK, (2.9)

    where C1 and C2 are given by (1.5).

    (2) There exists a positive constant m, such that

    λ3ρ3μ23ma2HKc2HK, (2.10)

    where μ=μ3.

    (3) When 0<2HK<1, for α,β>0 with α+β=1, there exists a positive constant m, such that

    μ=μ3mb2α(HK1)(ac)β(HK1)+1. (2.11)

    Proof. The proof of this lemma is given in the Appendix since its proof is long.

    Lemma 2.3. Let H(0,1),K(0,1], as 0<2HK<1, we have

    D2μ(λρμ2)3/2drdsdrds<+, (2.12)

    where D2:={(r,s,r,s)|0<r<s<t,0<r<s<t}, and λ,ρ and μ are given in Lemma 2.2.

    Proof. Since D2{r<r}=D1D2D3, where D1,D2 and D3 are given in Lemma 2.2, it is suffice to show that

    Diμi(λiρiμ2i)3/2drdsdrds<+,  i=1,2,3.

    For i=1, by (2.4) and (2.5), we obtain

    D1μ1(λ1ρ1μ21)3/2drdsdrds
    m[0,t]3a2HK+b2HK+c2HK[(a+b)2HKc2HK+(b+c)2HKa2HK]3/2dadbdcm[0,t]3a2HK+b2HK+c2HK(a+b)3HK2(b+c)3HK2(ac)3HK2dadbdcm[0,t]3a2HKa3HK2b3HK2(ac)3HK2dadbdc+m[0,t]3b2HKb3HK2b3HK2(ac)3HK2dadbdc+m[0,t]3c2HKb3HK2c3HK2(ac)3HK2dadbdc=m[0,t]31aHKb3HK2c3HK2dadbdc+m[0,t]31bHKa3HK2c3HK2dadbdc+m[0,t]31cHKa3HK2b3HK2dadbdc<+,

    since 0<2HK<1.

    For i=2, by (2.7) and (2.8), we obtain

    D2μ2(λ2ρ2μ22)3/2drdsdrdsm[0,t]3b2HK[b2HK(a2HK+c2HK)]3/2dadbdcm[0,t]31bHKa3HK2c3HK2dadbdc<+,

    since 0<2HK<1.

    For i=3, by (2.10) and (2.11), we obtain

    D3μ3(λ3ρ3μ23)3/2drdsdrdsm[0,t]3b2α(HK1)(ac)β(HK1)+1[(a2HKc2HK)]3/2dadbdc=m[0,t]31b2α(1HK)(ac)β(1HK)+3HK1dadbdc.

    Since 0<2HK<1, then 2(1HK)=22HK>1. We first choose α>0, such that 2α(1HK)<1, and we have

    β(1HK)+3HK1=(1α)(1HK)+3HK1                      =2HKα(1HK)                      <1,

    which imply

    D3μ3(λ3ρ3μ23)3/2drdsdrds<+.

    The proof of Lemma 2.3 is now complete.

    In this section, we will prove Theorems 1.1–1.3.

    Proof. We prove the theorem in two steps.

    Step 1. Show that for each ϵ>0,αt,ϵ(y)L2(Ω,P). In fact, by (1.8) and (1.10), we have

    αt,ϵ(y)=t0s0pϵ(SH,KsSH,Kry)drds          =12πt0s0Reiξ(SH,KsSH,Kry)eϵξ22dξdrds.

    Let D2:={(r,s,r,s)|0<r<s<t,0<r<s<t}. Then,

    E(|αt,ϵ(y)|2)=E[14π2D2R2exp(iξ(SH,KsSH,Kry)+iη(SH,KsSH,Kry))                    exp(ϵ(ξ2+η2)2)dξdηdrdsdrds]14π2D2R2E[exp(iξ(SH,KsSH,Kry)+iη(SH,KsSH,Kry))]dξdηdrdsdrds=14π2D2R2exp[12Var(ξ(SH,KsSH,Kry)+η(SH,KsSH,Kry))]dξdηdrdsdrds=14π2D2R2exp[12Var(ξ(SH,KsSH,Kr)+η(SH,KsSH,Kr))]dξdηdrdsdrds=12π2(D1+D2+D3)R2exp[12Var(ξ(SH,KsSH,Kr)+η(SH,KsSH,Kr))]dξdηdrdsdrds      :=12π2(A1+A2+A3),

    where

    D1={(r,s,r,s)|0<r<r<s<s<t},
    D2={(r,s,r,s)|0<r<r<s<s<t},
    D3={(r,s,r,s)|0<r<s<r<s<t}.

    Denote M=Var(ξ(SH,KsSH,Kr)+η(SH,KsSH,Kr)), by (2.2), we obtain

    (1) if (r,s,r,s)D1, then

    M=Var(ξ(SH,KrSH,Kr)+(ξ+η)(SH,KsSH,Kr)+η(SH,KsSH,Ks))m[ξ2(rr)2HK+(ξ+η)2(sr)2HK+η2(ss)2HK]m[ξ2(rr)2HK+(ξ+η)2(sr)2HK].

    Thus,

    A1=D1R2exp(M2)dξdηdrdsdrdsD1R2exp(m[ξ2(rr)2HK+(ξ+η)2(sr)2HK]2)dξdηdrdsdrds=2πmD1(rr)HK(sr)HKdrdsdrds<+,

    since 0<HK<1.

    (2) if (r,s,r,s)D2, then

    M=Var(ξ(SH,KrSH,Kr)+(ξ+η)(SH,KsSH,Kr)+ξ(SH,KsSH,Ks))    m[ξ2(rr)2HK+(ξ+η)2(sr)2HK+ξ2(ss)2HK]    m[ξ2(rr)2HK+(ξ+η)2(sr)2HK].

    Thus,

    A2=D2R2exp(M2)dξdηdrdsdrds  D2R2exp(m[ξ2(rr)2HK+(ξ+η)2(sr)2HK]2)dξdηdrdsdrds  =2πmD2(rr)HK(sr)HKdrdsdrds  <+,

    since 0<HK<1.

    (3) if (r,s,r,s)D3, then

    M=Var(ξ(SH,KsSH,Kr)+η(SH,KsSH,Kr))m[ξ2(sr)2HK+η2(sr)2HK].

    Thus,

    A3=D3R2exp(M2)dξdηdrdsdrds  D3R2exp(m[ξ2(sr)2HK+η2(sr)2HK]2)dξdηdrdsdrds  =2πmD3(sr)HK(sr)HKdrdsdrds  <+,

    since 0<HK<1. Hence, for any H(0,1) and K(0,1], we have

    E(|αt,ϵ(y)|2)<+.

    Step 2. Show that {αt,ϵ(y),ϵ>0} is a Cauchy sequence in L2(Ω,P). Since the proof of Step 2 is similar to that of Theorem 3.1 in Jiang and Wang [8], we omitted the details.

    Therefore we obtain limϵ0αt,ϵ(y) exists in L2 and the theorem follows.

    Proof. By (1.9) and (1.11), we get

    E[αt,ϵ(y)]2=E[i2πt0s0Rξeiξ(SH,KsSH,Kry)eϵξ22dξdrds]2              =14π2D2R2ξηe12Var(ξ(SH,KsSH,Kry)+η(SH,KsSH,Kry))eϵ(ξ2+η2)2dξdηdrdsdrds              =14π2D2R2ξηe12Var(ξ(SH,KsSH,Kr)+η(SH,KsSH,Kr))eϵ(ξ2+η2)2dξdηdrdsdrds              =14π2D2R2ξηeλ+ϵ2ξ2ρ+ϵ2η2ξημdξdηdrdsdrds              =12πD2μ[(λ+ϵ)(ρ+ϵ)μ2]3/2drdsdrds,

    where λ,ρ and μ are given in Lemma 2.2,

    By Lemma 2.3, as 0<2HK<1, we have

    limϵ0E[αt,ϵ(y)]2<+,

    which implies αt,ϵ(y)L2(Ω,P) for each ϵ>0.

    Similar to Step 2 of the proof of Theorem 1.1, we can prove that {αt,ϵ(y),ϵ>0} is a Cauchy sequence in L2(Ω,P). Here we omitted the details. Therefore the proof of Theorem 1.2 is completed.

    Proof. (1) It is enough to prove that

    E[|αt,ϵ(y1)αt,ϵ(y2)|n]m|y1y2|nτ,

    holds for every t[0,T] and n1.

    Since

    |αt,ϵ(y1)αt,ϵ(y2)|=|i2πt0s0Rξeiξ(SH,KsSH,Kr)eϵξ22(eiξy1eiξy2)dξdrds|, (3.1)

    and

    |eiξbeiξa|m|ξ|τ|ba|τ,  forany τ(0,1). (3.2)

    Hence

    E[|αt,ϵ(y1)αt,ϵ(y2)|n]=1(2π)n|DnRnEnj=1ξjeiξj(SH,KsjSH,Krj)(eiξjy1eiξjy2)eϵξ2j2nj=1dξjdrjdsj|m|y1y2|nτDnRn|Enj=1eiξj(SH,KsjSH,Krj)|nj=1|ξj|1+τdξjdrjdsj, (3.3)

    for any τ(0,1).

    Let us first deal with the product insider the expectation. Using the method of sample configuration as in Jung and Markowsky [10]. Fix such an ordering and let l1l2l2n be a relabeling of the set {r1,s1,r2,s2,,rn,sn}. We obtain

    nj=1eiξj(SH,KsjSH,Krj)=2n1j=1eiuj(SH,Klj+1SH,Klj), (3.4)

    where the uj,s are properly chosen linearly combinations of the ξj,s to make (3.4) an equality. By local non-deterministic property for SH,Kt, we have

    |Enj=1eiξj(SH,KsjSH,Krj)|em2n1j=1u2j(lj+1lj)2HK. (3.5)

    Fixing ξj, we choose j1 to be the smallest value such that uj1 contains ξj as a term and then choose j2 to be the smallest value strictly larger than j1 such that uj2 does not contain ξj as a term. Thus,

    |ξj|1+τ=|uj1uj11|1+τ2|uj21uj2|1+τ2      m(|uj1|1+τ2+|uj11|1+τ2)(|uj2|1+τ2+|uj21|1+τ2). (3.6)

    Let aj=lj+1lj (with l0=0),by (3.3), (3.5) and (3.6), we deduce

    E[|αt,ϵ(y1)αt,ϵ(y2)|n]m[0,t]2nRnem2n1j=1u2ja2HKj2nj=1(|uj|1+τ2+|uj1|1+τ2)dξdl      mRn2nj=1(|uj|1+τ2+|uj1|1+τ2)2n1j=1(1+|uj|1HK)dξ, (3.7)

    where dξ=dξ1dξ2dξn,  dl=dl1dl2dl2n,  u0=u2n=0, and we use the inequality

    t0em|u|2a2HKdam1+|u|1HK. (3.8)

    Expanding the product in the numerator of (3.7) gives us the sum of a number of terms of the form

    2n1j=1|uj|(1+τ)mj2,

    where mj=0,1 or 2 (terms containing |u0| or |u2n| are equal to 0). Thus, it is suffice to show that

    Rn12n1j=1(1+|uj|1HK(1+τ)mj2)dξ1dξ2dξn (3.9)

    is finite. We make a linear transformation changing this into an integral with respect to variables uk1,uk2,,ukn{u1,,u2n1} which span {ξ1,ξ2,,ξn} in order to bound (3.9) by

    mRn12n1j=1(1+|ukj|1HK(1+τ)mj2)duk1duk2duknmRn12n1j=1(1+|ukj|1HK(1+τ))duk1duk2dukn.

    This is finite if we choose τ such that 1HK(1+τ)>1, namely τ<1HK2.

    (2) It is enough to prove that

    E[|αt,ϵ(y)α˜t,ϵ(y)|n]m|t˜t|nγ,

    holds for t,˜t[0,T], every yR and n1.

    Since

    |αt,ϵ(y)α˜t,ϵ(y)|=12π|˜tts0Rξeiξ(SH,KsSH,Kry)eϵξ22dξdrds|.

    Hence,

    E[|αt,ϵ(y)α˜t,ϵ(y)|n]m[t,˜t]n[0,s1]××[0,sn]Rnnj=1|ξj|E[nj=1eiξj(SH,KsjSH,Krj)]nj=1dξjdrjdsjm˜Dnnj=1I[t,˜t](sj)Rnnj=1|ξj|E[nj=1eiξj(SH,KsjSH,Krj)]nj=1dξjdrjdsjm|t˜t|nγ{˜Dn[Rnnj=1|ξj|E[nj=1eiξj(SH,KsjSH,Krj)]nj=1dξj]11γnj=1drjdsj}1γ=:m|t˜t|nγΛ,

    where ˜D={(r,s):0<r<s<˜t} and we use the H¨older's inequality in the last inequality with γ<12HK.

    Using the similar method as in the proof of (1) in Theorem 1.3, Λ is bounded by

    [Ennj=1(lj+1lj)HK1γ2n1j=1(lj+1lj)HKmj2(1γ)dl1dl2dl2n]1γ,

    where En={0<l1<<l2n<t}.

    Since 1γ>2HK, there exists a constant m>0, such that

    E[|αt,ϵ(y)α˜t,ϵ(y)|n]m|t˜t|nγ.

    Thus, we finished the proof of Theorem 1.3.

    We mainly study the existence of the self-intersection local time and its derivative for the sub-bifractional Brownian motion. Moreover, we prove its derivative is H¨older continuous in space variable and time variable, respectively. In the future, we will consider its higher order derivative.

    Research supported by the Natural Science Foundation of Hunan Province under Grant 2021JJ30233.

    The authors declare that they have no known competing financial interests or personal relationships that could have appeared to influence the work reported in this paper.

    In this section we prove Lemma 2.2.

    Proof. By (1.4), we obtain (2.3), (2.6) and (2.9) easily. Since the proofs of (2.4), (2.7) and (2.10) are similar to those of Hu [4]and Hu and Nualart [5], we omitted the details. Thus we only need to prove (2.5), (2.8) and (2.11).

    In order to prove (2.5), let e=r, by (1.3), we have

    μ=[(s2H+(s)2H)K(s2H+(r)2H)K(r2H+(s)2H)K+(r2H+(r)2H)K]+12[(s+r)2HK(s+s)2HK+(r+s)2HK(r+r)2HK]+12[|sr|2HK|ss|2HK+|rs|2HK|rr|2HK]. (A.1)

    Hence,

    μ1={[(e+a+b)2H+(e+a+b+c)2H]K[(e+a+b)2H+(e+a)2H]K                            [e2H+(e+a+b+c)2H]K+[e2H+(e+a)2H]K}+12[(2e+2a+b)2HK(2e+2a+2b+c)2HK+(2e+a+b+c)2HK(2e+a)2HK]+12[b2HKc2HK+(a+b+c)2HKa2HK]:=Δ1,1+Δ1,2+Δ1,3.

    For Δ1,1, we obtain

    Δ1,1=e+a+bed{[x2H+(e+a+b+c)2H]K[x2H+(e+a)2H]K}    =2HKe+a+bex2H1{[x2H+(e+a+b+c)2H]K1[x2H+(e+a)2H]K1}dx    0, (A.2)

    since 0<K1.

    For Δ1,2, we get

     Δ1,2=12[(2e+2a+b)2HK(2e+2a+2b+c)2HK+(2e+a+b+c)2HK(2e+a)2HK]12[(2e+a+b+c)2HK(2e+a)2HK]12(b+c)2HK=12(b2+2bc+c2)HK12[2(b2+c2)]HK2HK1(b2HK+c2HK), (A.3)

    since 0<2HK<1, where we use the inequality xαyα|xy|α for any x>0,y>0,0<α<1.

    For Δ1,3, we deduce,

    Δ1,3=12[(a+b+c)2HK+b2HKa2HKc2HK]=12[(a2+b2+c2+2ab+2ac+2bc)HK+b2HKa2HKc2HK]12[(3a2+3b2+3c2)HK+b2HKa2HKc2HK]3HK12(a2HK+c2HK)+3HK+12b2HK3HK+12(a2HK+b2HK+c2HK).                                     (A.4)

    Therefore (2.5) holds from (A.2)–(A.4).

    In order to prove (2.8), let e=r, by (1.3) and (A.1), we have

    μ2={[(e+a+b+c)2H+(e+a+b)2H]K[(e+a+b+c)2H+(e+a)2H]K                            [e2H+(e+a+b)2H]K+[e2H+(e+a)2H]K}+12[(2e+2a+b+c)2HK(2e+2a+2b+c)2HK+(2e+a+b)2HK(2e+a)2HK]  +12[(b+c)2HKc2HK+(a+b)2HKa2HK]:=Δ2,1+Δ2,2+Δ2,3.

    For Δ2,1, we obtain

    Δ2,1=e+a+b+ced{[x2H+(e+a+b)2H]K[x2H+(e+a)2H]K}   =2HKe+a+b+cex2H1{[x2H+(e+a+b)2H]K1[x2H+(e+a)2H]K1}dx0, (A.5)

    since 0<K1.

    For Δ2,2, we get

     Δ2,2=12[(2e+2a+b+c)2HK(2e+2a+2b+c)2HK+(2e+a+b)2HK(2e+a)2HK]12[(2e+a+b)2HK(2e+a)2HK]12b2HK, (A.6)

    since 0<2HK<1.

    For Δ2,3, we deduce,

    Δ2,3=12[(a+b)2HKa2HK+(b+c)2HKc2HK]12(b2HK+b2HK)=b2HK, (A.7)

    since 0<2HK<1. Therefore (2.8) holds from (A.5)–(A.7).

    In order to prove (2.11), let e=r, by (1.3) and (A.1), we have

    μ3={[(e+a)2H+(e+a+b+c)2H]K[(e+a)2H+(e+a+b)2H]K                                    [e2H+(e+a+b+c)2H]K+[e2H+(e+a+b)2H]K}+12[(2e+2a+b)2HK(2e+2a+b+c)2HK+(2e+a+b+c)2HK(2e+a+b)2HK]  +12[b2HK(b+c)2HK+(a+b+c)2HK(a+b)2HK]:=Δ3,1+Δ3,2+Δ3,3.

    For Δ3,1, we obtain

    Δ3,1=e+aed{[x2H+(e+a+b+c)2H]K[x2H+(e+a+b)2H]K}   =2HKe+aex2H1{[x2H+(e+a+b+c)2H]K1[x2H+(e+a+b)2H]K1}dx      0, (A.8)

    since 0<K1.

    For Δ3,2, and for α,β>0 with α+β=1, we get

    Δ3,2=1221d[(2e+b+c+ua)2HK(2e+b+ua)2HK]       =HKa21[(2e+b+c+ua)2HK1(2e+b+ua)2HK1]du       =HKa21[10d(2e+b+ua+vc)2HK1]du       =HK(2HK1)ac2110(2e+b+ua+vc)2HK2dvdu       =HK(12HK)ac2110(2e+b+ua+vc)2HK2dvdu       HK(12HK)ac2110(b+ua+vc)2HK2dvdu       HK(12HK)ac2110[bα(ua+vc)β]2HK2dvdu       mac2110[bα(ua)β2(vc)β2]2HK2dvdu (A.9)

    since 0<2HK<1.

    For Δ3,3, we deduce,

    Δ3,3=12[(a+b+c)2HK(b+c)2HK(a+b)2HK+b2HK]       =1210d[(b+a+vc)2HK(b+vc)2HK]       =HKc10[(b+a+vc)2HK1(b+vc)2HK1]dv       =HKc10[10d(b+ua+vc)2HK1]dv       =HK(2HK1)ac1010(b+ua+vc)2HK2dudv       0, (A.10)

    since 0<2HK<1. Therefore (2.11) holds from (A.8)–(A.10). Thus we have finished the proof of Lemma 2.2.



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