
Citation: Murat O. Mamchuev. Non-local boundary value problem for a system of fractional partial differential equations of the type I[J]. AIMS Mathematics, 2020, 5(1): 185-203. doi: 10.3934/math.2020011
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Consider the following system of equations
∂∂xu(x,y)+ADβ0yu(x,y)=Bu(x,y)+f(x,y),0<β<1, | (1.1) |
in the domain Ω={(x,y):l1<x<l2,0<y<T}, where u(x,y) and f(x,y) are unknown and given n-vectors, respectively; A and B are the given constant n×n matrices, Dβ0y is the Riemann – Liouville fracional integro-differentiation operator of order β [1,p. 9].
Let us review the papers associated with the investigation of the systems with fractional partial derivatives of order that is not higher than one including the scalar case n=1. In paper [2] for the equation
Dα0x(u−h1(y))+Dβ0y(u−h2(x))=f,0<α,β<1,x,y>0, | (1.2) |
the solvability of the boundary value problem with the initial conditions u(0,y)=h1(y), u(x,0)=h2(x) is studied in a class of Hölder's continuous functions. The authors obtained a fundamental solution of Eq. (1.2) in the form
ψα,β(x,y)=∞∫0τ−1α−1βφα(xτ−1α)φβ(yτ−1β)dτ, | (1.3) |
where
φμ(t)=1π∞∑k=1(−1)k+1k!sin(πμk)Γ(μk+1)t−μk−1. |
Note that the function ψα,β(x,y) can be represented (it is shown in [3]) as
ψα,β(x,y)=1xy∞∫0ϕ(−α,0;−τx−α)ϕ(−β,0;−τy−β)dτ. |
Paper [4] was devoted to study of Hölder's smoothness of solution for the following equation
Dα0x(u(x,y)−u0(y))+c(x,y)uy(x,y)=f(x,y),x,y>0, |
satisfying the boundary conditions u(0,y)=u0(y) and u(x,0)=u1(x).
The uniqueness and existence theorems for a boundary value problem regular solution for the equation
Dα0xu(x,y)+λDβ0yu(x,y)+μu(x,y)=f(x,y),0<α,β<1,λ>0,x,y>0 | (1.4) |
are proved in papers [5,6]. The fundamental solution has the form
w(x,y)=1xy∞∫0e−μτϕ(−α,0;−τx−α)ϕ(−β,0;−τy−β)dτ, |
in the case when λ=1, and, when μ=0 it has the form
w(x,y)=xα−1yeα,0α,β(−λxαyβ), |
where
eμ,να,β(z)=∞∑k=0zkΓ(μ+αk)Γ(ν−βk) |
is the Wright type function [6]. In addition a boundary value problem with negative coefficient λ<0 was studied for Eq. (1.4) in the case α=1, μ=0.
The Equation (1.4) with variable coefficients λ≡λ(x) and μ≡μ(x), where α=1 and the function λ(x) may have a zero of order m≥0 at the point x=0, was investigated in the papers [7,8,9]. In that case the fundamental solution
w(x,y;t,s)=exp(Λ(x,t))y−sϕ(−β,0;−M(x,t)(y−s)−β), |
was constructed. In the last expression Λ(x,t)=x∫tλ(ξ)dξ, M(x,t)=x∫tμ(ξ)dξ. The existence and uniqueness theorems for a boundary value problem and the Cauchy problem were proved.
We also note the papers [10] and [11], where the equation
∂αu(x,t)∂xα=λ∂βu(x,t)∂tβ |
was studied. The fractional derivatives are understood in the sense of Caputo and Riesz in paper [10], and in the sense of Caputo, Riemann–Liouville and Riesz in paper [11].
For the system
Dα0xu(x,y)+ADβ0yu(x,y)=Bu(x,y)+f(x,y), | (1.5) |
the boundary value problem was solved explicitly in [12] when A was an identity matrix, and in [13] when A was positive defined matrix. The fundamental solution of system (1.5) was constructed in terms of the introduced Wright function of the matrix argument in paper [13]. Article [3] used a similar approach to solve the problem with the boundary conditions in the multidimensional case.
Among the works devoted to the study of systems of equations with fractional partial derivatives, we also distinguish papers [14,15,16]. In [16] A. N. Kochubei described a class of first order systems of equations with constant coefficients containing a fractional derivative with respect to one of the independent variables, for which the Cauchy problem is solvable, and the fundamental solutions of which grow exponentially outside the set {|x|y−β≤1}. Such systems were called fractional hyperbolic systems. System (1.1) also belongs to this class of systems.
Note that, the systems of type (1.1) are differ significantly at the formulations of initial and boundary-value problems, depending on the sign-determinacy or sign-indeterminacy of the eigenvalues of the matrix coefficient in the main part of the system.
In papers [12,13,17] boundary value problems in rectangular domains were studied for systems with sign-determined eigenvalues, including systems with partial derivatives, of order strictly lower than one. For such systems the formulation of boundary value problems is similar to the case with a single equation. We call this type of systems the type Ⅰ systems.
In papers [18,19,20,21,22,23] the Cauchy problem, mixed and non-local problems were investigated for a system of the type Ⅱ, i.e., for the systems, where the matrix coefficient in the main part has an eigenvalues of the different signs.
In this paper, we first solve in explicit form an auxiliary problem for system (1.1) with B=0. To do this, we use the properties of the Wright function of the matrix argument, which are studied in [13]. Next we investigate a non-local boundary value problem for system (1.1) by reducing to the auxiliary problem by using a system of integral equations. We prove the existence and uniqueness theorem. At the end, we give an example of the non-local boundary value problem and construct the graphs of its solution.
The Riemann-Liouville fractional integro-differentiation operator Dνay of order ν is defined as [1,p. 9]:
Dνayg(y)=sgn(y−a)Γ(−ν)y∫ag(s)ds|y−s|ν+1, |
for ν<0, and for ν≥0 the operator Dνay can be determined by recursive relation
Dνayg(y)=sgn(y−a)ddyDν−1ayg(y),ν≥0, |
where Γ(z) is the Euler gamma-function.
The symbol ∂ν0y denotes the Caputo fractional differentiation operator of order ν, [1,p. 11]:
∂νayg(y)=sgnn(y−a)Dν−nayg(n)(y),n−1<ν≤n,n∈N. |
The Wright function [24,25] is called an entire function, which is depended from two parameters ρ and μ, and represented by the series
ϕ(ρ,μ;z)=∞∑k=0zkk!Γ(ρk+μ),ρ>−1,μ∈C. |
Here we present the determination and some properties of the Wright function of the matrix argument, which are studied in [13].
Let A be a square matrix of order n. In view of the function ϕ(ρ,μ;z) is analytic everywhere in C, following series
ϕ(ρ,μ;A)=∞∑k=0Akk!Γ(ρk+μ),ρ>−1,μ∈C |
is converges for any matrix A given over the field of complex numbers C, and determine the Wright function of the matrix argument.
The following equality holds
ϕ(ρ,μ;Az)|z=0=1Γ(μ)I, | (2.1) |
here I is an identity matrix of order n.
Following differentiation formula holds
ddzϕ(ρ,μ;Az)=Aϕ(ρ,ρ+μ;Az). | (2.2) |
Now and further we assume that all of the eigenvalues of the matrix A are positive.
The next fractional integro-differentiation formula holds:
Dδ0yyμ−1ϕ(−β,μ;−Axy−β)=yμ−δ−1ϕ(−β,μ−δ;−Axy−β). | (2.3) |
It follows from (2.2) and (2.3) that
(∂∂x+ADβ0y)yμ−1ϕ(−β,μ;−Axy−β)=0. | (2.4) |
The following equality holds
∞∫0ϕ(−β,μ;−Az)dz=1Γ(μ+β)A−1. | (2.5) |
We denote by |A(x,y)|∗ the scalar function that takes at each point (x,y) the largest of the values of the moduli of the elements of the matrix A(x,y)=‖aij(x,y)‖, that is |A(x,y)|∗=maxi,j|aij(x,y)|. Similarly, for the vector b(x,y) with components bi(x,y) we denote |b(x,y)|∗=maxi|bi(x,y)|.
Following estimates are hold:
|yμ−1ϕ(−β,μ;−Axy−β)|∗≤Cx−θyμ+βθ−1,x>0,y>0, | (2.6) |
where β∈(0,1); and θ≥0 for μ≠0,−1,−2,..., and θ≥−1 for μ=0,−1,−2,...; and
|ϕ(−β,μ;−Az)|∗≤Cexp(−σz11−β),z≥0, | (2.7) |
where β∈(0,1), μ∈R, σ<(1−β)(λββ)11−β, λ=min1≤i≤p{λi}, λ1,...,λp are eigenvalues of the matrix A.
A regular solution of system (1.1) in the domain Ω is defined as the vector function u=u(x,y) satisfying system (1.1) at all points x∈Ω, such that ∂u∂x, Dβ0yu∈C(Ω), y1−βu(x,y)∈ C(ˉΩ).
Before turning to the presentation of the main results, we solve the following auxiliary problem for the case of system (1.1) with B=0.
Problem 1. In the domain Ω find a solution of the system
∂∂xu(x,y)+ADβ0yu(x,y)=f(x,y),0<β<1, | (3.1) |
with the conditions
limy→0Dβ−10yu(x,y)=φ(x),l1≤x≤l2, | (3.2) |
u(l1,y)=ψ(y),0<y<T, | (3.3) |
where φ(x) and ψ(y) are given n-vectors.
Theorem 1. Let all the eigenvalues of the matrix A be positive, φ(x)∈C[l1,l2], y1−βψ(y)∈C[0,T], y1−βf(x,y)∈C(¯Ω), f(x,y) satisfies the Hölder condition with respect to y, and the matching condition
limy→0Dβ−10yψ(y)=φ(l1) | (3.4) |
holds. Then there exists a unique regular in the domain Ω, solution of Problem 1. Solution can be represented as
u(x,y)=x∫l1G(x−t,y)Aφ(t)dt+y∫0G(x−l1,y−s)ψ(s)ds+ |
+y∫0x∫l1G(x−t,y−s)f(t,s)dtds, | (3.5) |
where
G(x,y)=y−1ϕ(−β,0;−Axy−β). |
Remark 1. Without loss of generality, we prove Theorem 1 for the domain Ω with l1=0 and l2=l. A more general case reduces to this case by replacing the independent variables x=ξ+l1, y=η.
To prove Theorem 1, we need the following assertions.
Lemma 1. Any regular in the domain Ω solution u(x,y) of Problem 1 can be represented in form (3.5).
Proof. Let u(x,y) be a solution of Problem 1. The function V(x,y) is the solution of the equation
∂∂xV(x,y)+∂β0yV(x,y)A=I, | (3.6) |
with the conditions
V(0,y)=0,V(x,0)=0, | (3.7) |
where I is the identity matrix.
Using (2.2), (2.3), (2.1), (2.7) and the relation
Dα0yyβΓ(1+β)=yβ−αΓ(1+β−α), |
it is easy to see that
V(x,y)=−A−1yβϕ(−β,1+β;−Axy−β)+A−1Γ(1+β)yβ |
is the solution of problems (3.6), (3.7).
From (2.2) and (2.3) it follows that
Vxy(x,y)=G(x,y). | (3.8) |
Let ε>0. Integration by parts taking into account Eqs. (2.1), (2.7) and (3.7) leads to
x∫εy∫εV(x−t,y−s)∂∂tu(t,s)dsdt= |
=x∫εy∫ε∂∂tV(x−t,y−s)u(t,s)dtds−y∫εV(x−t,y−s)u(t,s)|t=εds, |
x∫εy∫εV(x−t,y−s)ADβ0su(t,s)dsdt= |
=x∫εy∫ε∂∂sV(x−t,y−s)ADβ−10su(t,s)dtds−x∫εV(x−t,y−s)ADβ−10su(t,s)|s=εdt. |
From the last two relations we get
x∫εy∫εV(x−t,y−s)(∂∂t+ADβ0s)u(t,s)dsdt= |
=x∫εy∫ε(∂∂tV(x−t,y−s)u(t,s)+∂∂sV(x−t,y−s)ADβ−10su(t,s))dsdt− |
−y∫εV(x−t,y−s)u(t,s)|t=εds−x∫εV(x−t,y−s)ADβ−10su(t,s)|s=εdt. |
Passing to the limit as ε→0, by using (3.1), (3.2), (3.3), (3.6) and analogue of the integration by parts formula in fractional calculus [1,p. 34]
y∫0g(y−s)Dν0yh(s)ds=y∫0h(s)Dνysg(y−s)ds,v<0, |
we obtain
x∫0y∫0u(t,s)dsdt=x∫0y∫0V(x−t,y−s)f(t,s)dsdt+ |
+y∫0V(x,y−s)φ(s)ds+x∫0V(x−t,y)Aψ(t)dt. | (3.9) |
Differentiating (3.9) by x and by y, with (3.7) and (3.8), we get (3.5). Lemma 1 is proved.
Lemma 2. Following estimates
|G(x,y)|∗≤Cx−θyβθ−1,θ≥−1, | (3.10) |
|Dβ−10yG(x,y)|∗≤Cx−θyβθ−β,θ≥0, | (3.11) |
|∂∂xG(x,y)|∗≤Cx−θyβθ−β−1,θ≥0, | (3.12) |
|Dβ0yG(x,y)|∗≤Cx−θyβθ−β−1,θ≥0, | (3.13) |
are hold, here C is a positive constant.
The validity of Lemma 2 follows from the relations (2.2), (2.3) and (2.6).
Lemma 3. Let all the eigenvalues of the matrix A be positive, φ(x)∈C[0,l], y1−βψ(y)∈C[0,T], then the relations
limx→0x∫0G(x−t,y)Aψ(t)dt=0,y>ε>0, | (3.14) |
limy→0Dβ−10yy∫0G(x,y−s)φ(s)ds=0,x>ε>0, | (3.15) |
limy→0Dβ−10yx∫0G(x−t,y)Aψ(t)dt=ψ(x),x>ε>0, | (3.16) |
limx→0y∫0G(x,y−s)φ(s)ds=φ(y),y>ε>0 | (3.17) |
are valid, and limits (3.15) and (3.16) are uniform on any closed subset of (0;l), and limits (3.14) and (3.17) on any closed subset of (0;T).
Proof. The validity of relations (3.14) and (3.15) follows from estimates (3.10), (3.11), |ψ(x)|∗≤C and |φ(y)|∗≤Cyβ−1.
Let us transform the following integral
Dβ−10yx∫0G(x−t,y)Aψ(t)dt=(ε∫0+x∫ε)Dβ−10yG(t,y)Aψ(x−t)dt. | (3.18) |
The limit of the second integral in the right-hand side of (3.18) with y→0, due to estimate (3.11) and the boundedness of the function ψ(x), is zero for x>ε>0. Denote by I1(x,y) the first integral in the right-hand side of (3.18), then
I1(x,y)=ε∫0Dβ−10yG(t,y)A[ψ(x−t)−ψ(x)]dt+[ε∫0Dβ−10yG(t,y)dt]Aψ(x). | (3.19) |
Taking advantage of the fact that, by virtue of (2.2),
Ay−βϕ(−β,1−β;−Axy−β)=−∂∂xϕ(−β,1;−Axy−β), |
we obtain that
Aε∫0Dβ−10yG(t,y)dt=I−ϕ(−β,1;−Aεy−β). | (3.20) |
Passing to the limit at y→0, taking into account formula (2.7), we get
limy→0Aε∫0Dβ−10yG(t,y)dt=I. | (3.21) |
The function ψ(t) is continuous on [x−ε,x], therefore ω(ε)=sup|ψ(x−t)−ψ(x)|→0 with ε→0. Since ε can be chosen arbitrary, then the first term in (3.19) is arbitrarily small for any fixed y, that is, tends to zero, with y→0.
The second term, by virtue of (3.21), tends to ψ(x). Thus limy→0I1(x,y)=ψ(x). From the latter, together with (3.18) follows (3.16). The relation (3.17) can be proved similarly. Lemma 3 is proved.
Lemma 4. Under the conditions of Theorem 1, function (3.5) is a solution of system (3.1), such that ∂∂xu,Dβ0yu∈C(Ω).
Proof. It follows from (3.12), (3.13) that the estimates
|∂∂xG(x,y)|∗<Cx−θ−1,|Dβ0yG(x,y)|∗<Cx−θ−1,θ≥−1, |
are valid for any fixed y>ε>0 and the estimates
|∂∂xG(x,y)|∗<Cyβθ−1,|Dβ0yG(x,y)|∗<Cyβθ−1,θ≥0, |
for x>ε>0. From these estimates, taking into account relations (2.4), we can see that the first two terms (we denote their sum u0(x,y)) on the right-hand side of (3.5) there are solutions of the homogeneous system
∂∂xu0(x,y)+ADβ0yu0(x,y)=0, |
at that ∂∂xu0,Dβ0yu0∈C(Ω).
Denote by uf(x,y) the third term on the right-hand side of (3.5). Under the condition of Theorem 1, the function f(x,y) satisfies the Hölder condition in the variable y, that is,
|f(x,y)−f(x,s)|∗≤K|y−s|q,0<q<1, | (3.22) |
here K is positive number. Then
∂∂xuf(x,y)=∂∂xx∫0dty∫0G(x−t,y−s)f(t,s)ds=limt→xy∫0G(x−t,y−s)f(t,s)ds+ |
+x∫0dty∫0∂∂xG(x−t,y−s)[f(t,s)−f(t,y)]ds+x∫0dty∫0∂∂xG(x−t,y−s)f(t,y)ds. | (3.23) |
Taking into account estimate (3.12) and condition (3.22), we obtain the estimate for the integrand in the second term of (3.23)
|∂∂xG(x−t,y−s)[f(t,s)−f(t,y)]|∗≤nMC(x−t)−θ−1(y−s)βθ−1+q, | (3.24) |
choosing θ∈[−1;0) with q>β and θ∈(−q/β;0) with q≤β, it is easy to see that the integral converges uniformly over all x and y for any q∈(0,1). Transforming the last term of (3.23) with (2.4), we get
∂∂xuf(x,y)=f(x,y)+x∫0dty∫0∂∂xG(x−t,y−s)[f(t,s)−f(t,y)]ds− |
−Ax∫0Dβ−10yG(x−t,y)f(t,y)dt. | (3.25) |
From (3.10), (3.11), (3.24) and (3.25) it follows that ∂∂xuf∈C(Ω).
Consider the function Fε(x,y)=x∫0dty−ε∫0Dβ−1ysG(x−t,y−s)f(t,s)ds. From estimate (3.11) we see that limε→0Fε(x,y)=Dβ−10yuf(x,y)∈C(Ω). In view of (3.11) and
|DβysG(x−t,y−s)[f(t,s)−f(t,y)]|∗≤nCK(x−t)−θ−1(y−s)βθ−1+q, | (3.26) |
we get that the derivative
∂∂yFε(x,y)=x∫0Dβ−10εG(x−t,ε)f(t,y−ε)dt−x∫0Dβ−10εG(x−t,ε)f(t,y)dt+ |
+x∫0dty−ε∫0DβysG(x−t,y−s)[f(t,s)−f(t,y)]ds+x∫0Dβ−10sG(x−t,y)f(t,y)dt |
is continuous in Ω for ε→0. Therefore
limε→0∂∂yFε(x,y)=∂∂ylimε→0Fε(x,y)=Dβ0yuf(x,y), |
that is
Dβ0yuf(x,y)=x∫0dty∫0DβysG(x−t,y−s)[f(t,s)−f(t,y)]ds+ |
+x∫0Dβ−10yG(x−t,y)f(t,y)dt. | (3.27) |
From (2.4), (3.25) and (3.27) we get
(∂∂x+ADβ0y)uf(x,y)=f(x,y). |
Lemma 4 is proved.
Using estimates (3.10) and |f(x,y)|≤Cyβ−1, we get
|uf(x,y)|∗≤Cx1−θyβθ+β−1,θ∈(0;1), | (3.28) |
where uf(x,y) is the third term on the right-hand side of equality (3.5). From (3.28) follow relations
limx→0uf(x,y)=0,limy→0Dβ−10yuf(x,y)=0, | (3.29) |
and the inclusion y1−βuf∈C(¯Ω). Relations (3.14) – (3.17) and (3.29) imply the fulfillment of boundary conditions (3.2) and (3.3).
Denote by uψ(x,y) and uφ(x,y), respectively, the first and second term on the right-hand side of Eq. (3.5). Using estimate (3.10) and the conditions of Theorem 1 on the functions ψ(x) and φ(y), we get estimates
|uψ(x,y)|∗≤Cx1−θyβθ−1,θ∈[−1,1), |
|uφ(x,y)|∗≤Cx−θyβθ+β−1,θ∈(0,2). |
From the last two inequalities we get that y1−β(uψ+uφ)∈C(Ω).
Let us show the validity of the inclusion y1−β(uψ+uφ)∈C(¯Ω). For this purpose we represent uψ(x,y) in the form
uψ(x,y)=Ax∫0G(x−t,y)ψ(t)dt=Ax∫0G(t,y)ψ(x−t)dt= |
=Ax∫0G(t,y)[ψ(x−t)−ψ(x)]dt+A[x∫0G(t,y)dt]ψ(x). | (3.30) |
In view of (2.2) and (2.1) we obtain
Ax∫0G(t,y)dt=Ax∫0y−1ϕ(−β,0;−Aty−β)dt=−x∫0yβ−1∂∂tϕ(−β,β;−Aty−β)dt= |
=yβ−1Γ(β)I−yβ−1ϕ(−β,β;−Axy−β). | (3.31) |
Similarly we get
uφ(x,y)=y∫0G(x,s)φ(y−s)ds= |
=y∫0G(x,s)(y−s)β−1[φ∗(y−s)−φ∗(y)]ds+[y∫0G(x,s)(y−s)β−1ds]φ∗(y), | (3.32) |
where φ∗(y)=y1−βφ(y), and
y∫0G(x,s)(y−s)β−1ds=Γ(β)D−β0yy−1ϕ(−β,0;−Axy−β)dt= |
=Γ(β)yβ−1ϕ(−β,β;−Axy−β). | (3.33) |
Using (3.30)–(3.33), (2.1), (2.5), (2.7), we get
limx→0y1−βuψ(x,y)=0,limy→0y1−βuψ(x,y)=1Γ(β)ψ(x), | (3.34) |
limx→0y1−βuφ(x,y)=1Γ(β)φ∗(y),limy→0y1−βuφ(x,y)=0. | (3.35) |
Relations (3.34) and (3.35) imply that y1−β(uψ+uφ)∈C(¯Ω∖{(0,0)}).
Let limx→0y→0xy−β=c, 0≤c≤∞. Then from relation (3.31) we obtain
limx→0y→0y1−βuψ(x,y)=[I−ϕ(−β,β;−Ac)]ψ(0), | (3.36) |
limx→0y→0y1−βuφ(x,y)=Γ(β)ϕ(−β,β;−Ac)φ∗(0). | (3.37) |
In view of (3.36) and (3.37) we obtain
limx→0y→0y1−β[uψ(x,y)+uφ(x,y)]=ψ(0)+[Γ(β)φ∗(0)−ψ(0)]ϕ(−β,β;−Ac). |
This limit does not depend on c, if
limx→0ψ(x)=Γ(β)limy→0y1−βφ(y), |
that is, under condition (3.4).
The above together with Lemma 4 proves the existence of the solution to problems (3.1), (3.2), (3.3) from the class specified in Theorem 1. The uniqueness of the solution to Problem 1 follows from Lemma 1. Theorem 1 is proved.
In this section, we investigate the following non-local boundary value problem in a rectangular domain for system (1.1) of the type Ⅰ.
Problem 2. Find a solution of system (1.1) in the domain Ω with conditions (3.2) and
Mu(l1,y)+Nu(l2,y)=ρ(y),0<y<T, | (4.1) |
where φ(x) and ρ(y) are given n-vectors, M and N are the given constant n×n matrix,
Theorem 2. Let all the eigenvalues of the matrix A be positive, φ(x)∈C[l1,l2], y1−βρ(y)∈C[0,T], y1−βf(x,y)∈C(¯Ω), f(x,y) satisfies the Hölder condition with respect to y, and the matching condition
limy→0Dβ−10yρ(y)=Mφ(l1)+Nφ(l2), | (4.2) |
holds, matrix M is nonsingular. Then there exists a unique regular in the domain Ω, solution of Problem 2.
Proof. By virtue of Theorem 1, the solution to Problem 1 for system (1.1) is a solution to the system of the integral equations
u(x,y)−y∫0x∫l1G(x−t,y−s)Bu(t,s)dtds=F(x,y), | (4.3) |
where
F(x,y)=y∫0G(x−l1,y−s)ψ(s)ds+Φ(x,y), |
Φ(x,y)=x∫l1G(x−t,y)Aφ(t)dt+y∫0x∫l1G(x−t,y−s)f(t,s)dtds. |
Due to estimate (3.10) we get the inclusion y1−βF(x,y)∈C(¯Ω).
The solution of the system of integral Eqs. (4.3) can be obtained by an iterative method. This solution has the form
u(x,y)=F(x,y)+y∫0x∫l1R(x−t,y−s)F(t,s)dtds, | (4.4) |
where
R(x,y)=∞∑n=1Kn(x,y), | (4.5) |
K1(x,y)=K(x,y)=G(x,y)B, |
Kn(x,y)=y∫0x∫l1Kn−1(x−t,y−s)K1(t,s)dtds. |
For iterated kernels, in view of (3.10), the estimate
|Km(x,y)|∗≤Cm|B|m∗Γm(ε)Γm(δ)Γ(mε)Γ(mδ)xmε−1ymδ−1,ε=1−θ,δ=βθ,0<θ<1. |
is valid. Using this estimate, we obtain the convergence of series (4.5) and the estimate for the resolvent
|R(x,y)|∗≤∞∑m=1[C|B|∗Γ(ε)Γ(δ)]mΓ(mε)Γ(mδ)xmε−1ymδ−1=xε−1yδ−1∞∑m=0[C1xεyδ]mΓ(mε+ε)Γ(mδ+δ)≤ |
≤Cxε−1yδ−1∞∑m=0[C1xεyδ]mm!Γ(mδ+δ)=Cxε−1yδ−1ϕ(δ,δ;C1xεyδ), |
where C1=C|B|∗Γ(ε)Γ(δ), and C is a large enough number. Due to the continuity of the function ϕ(δ,δ;z), the following estimate is valid
|R(x,y)|∗≤Cx−θyβθ−1,0<θ<1. | (4.6) |
Thus, solution (4.4) can be represented as
u(x,y)=Ψ(x,y)+y∫0R1(x,y−s)u(l1,s)ds, | (4.7) |
where
Ψ(x,y)=Φ(x,y)+y∫0x∫l1R(x−t,y−s)Φ(t,s)dtds, |
R1(x,y−s)=G(x−l1,y−s)+y∫sx∫l1R(x−ξ,y−η)G(ξ−l1,η)dξdη. |
It is easy to show that function (4.4) is the solution to Problem 2. Now let u(x,y) be a regular solution of Problem 1 in the domain Ω, then equality (4.7) also holds. Using representation (4.7), we express the boundary value:
u(l2,y)=¯Ψ(y)+y∫0¯K(y−s)u(l1,s)ds, | (4.8) |
where ¯Ψ(y)=Ψ(l2,y), ¯K(y−s)=R1(l2,y−s).
Since the matrix M is invertible, condition (4.2) can be rewritten as
u(l1,y)+M−1Nu(l2,y)=M−1ρ(y),0<y<T. |
Using (4.8), from the last equality we get
u(l1,y)+y∫0˜K(y−s)u(l1,s)ds=P(y), | (4.9) |
where
˜K(y)=M−1N¯K(y),P(y)=M−1ρ(y)+M−1N¯Ψ(y). |
From (3.10) and (4.5) follow the estimate
|R1(x,y−s)|∗≤C(x−l1)−θ(y−s)βθ−1,0<θ<1, |
and the following inclusions
y1−β¯Ψ(y),y1−β˜K(y)∈C[0,T]. | (4.10) |
It follows from (4.10) and the conditions of Theorem 2 on the function ρ(y), that y1−βP(y)∈C[0,T].
From relations (4.9) and (4.10), it follows that system (4.8) is a system of the Volterra integral equations of the second kind with a weak singularity in the kernel, and has the unique solution u(l1,y) such that y1−βu(l1,y)∈C[0,T]. After the value of u(l1,y) is found, the solution to Problem 2 can be obtained from representation (4.7).
From Theorem 1 it follows that for the inclusion y1−βu(x,y)∈C(¯Ω) the condition
limy→0Dβ−10yu(l1,y)=φ(l1) | (4.11) |
should be met. Taking into account equality (4.9), we rewrite condition (4.11) as
limy→0Dβ−10yu(l1,y)=limy→0y∫0˜K(y−s)Dβ−10su(l1,s)ds+ |
+M−1limy→0Dβ−10yρ(y)+M−1Nlimy→0Dβ−10y¯Ψ(y)=φ(l1). | (4.12) |
From inclusions (4.10), estimates (3.10), (4.5) and |u(l1,y)|∗≤Cyβ−1 we obtain the relations
limy→0y∫0˜K(y−s)Dβ−10su(l1,s)ds=0, | (4.13) |
|Φ(x,y)|∗≤Cyβ−1, |
|Dβ−10sy∫0x∫l1R(x−t,y−s)Φ(t,s)dtds|∗≤Cyβθ,0<θ<1. | (4.14) |
By virtue of (4.14) and the relation
limy→0Dβ−10yx∫l1G(x−t,y)Aφ(t)dt=φ(x), |
which follows from (3.16) and Remark 1, we obtain
limy→0Dβ−10y¯Ψ(y)=limy→0Dβ−10yΦ(l2,y)=limy→0Dβ−10yl2∫l1G(l2−t,y)Aφ(t)dt=φ(l2). | (4.15) |
In view of (4.13) and (4.15), equality (4.12) takes the form
M−1limy→0Dβ−10yρ(y)−M−1Nφ(l2)=φ(l1). |
Therefore, condition (4.2) is sufficient for y1−βu(x,y)∈C(¯Ω). Theorem 2 is proved.
Remark 2. The case when all the eigenvalues of the matrix are negative, is reduced to the case with positive eigenvalues by changing the variables ξ=x−l1, η=y, and the function u(x,y)=u(ξ+l1,η)=w(ξ,η). Moreover, for the solvability of Problem 2, the matrix N must be nonsingular.
As example consider Problem 2 with n=2, AB=BA, l1=0, l2=1, T=1, M=N=I, f(x,y)≡0, φ(x)≡0, ρ(y)=yβ−1Γ(β)(12), i.e., the system
∂∂xu(x,y)+(2134)Dβ0yu(x,y)=(1265)u(x,y), | (5.1) |
with the conditions
limy→0Dβ−10yu(x,y)=(00),0≤x≤1, | (5.2) |
u(0,y)+u(1,y)=ρ(y),0<y<1. | (5.3) |
Solution of problem (5.1)–(5.3) satisfies the following relation
u(x,y)=y∫0G(x,y−s)u(0,s)ds, | (5.4) |
where
G(x,y)=1yH(e−xϕ(−β,0;−xy−β)00e7xϕ(−β,0;−5xy−β))H−1, |
H=(11−13),H−1=14(3−111). |
From (5.4) we get
u(1,y)=y∫0G(1,y−s)u(0,s)ds. | (5.5) |
Substituting (5.5) into (5.4) we obtain following system of integral equations with respect to u(0,y)
u(0,y)+y∫0K1(y−s)u(0,s)ds=ρ(y), | (5.6) |
where
K1(y)=G(1,y). |
Using the Wright functions convolution formula, we calculate the iterative kernels
Kn(y)=∫y0Kn−1(y−s)K1(s)ds, |
Kn(y)=1yH(e−nϕ(−β,0;−ny−β)00e7nϕ(−β,0;−5ny−β))H−1, |
and find the following solution of integral Eq. (5.5)
u(0,y)=ρ(y)+y∫0R(y−s)ρ(s)ds, | (5.7) |
where
R(y)=∞∑n=1(−1)nKn(y)= |
=1yH∞∑n=1(−1)n(e−nϕ(−β,0;−ny−β)00e7nϕ(−β,0;−5ny−β))H−1. |
Put (5.7) into (5.5) we obtain the solution to problems (5.1)–(5.3) in the form
u(x,y)=y∫0G(x,y−s)ρ(s)ds+y∫0[y∫sG(x,y−ξ)R(ξ−s)dξ]ρ(s)ds= |
=y∫0G0(x,y−s)ρ(s)ds, | (5.8) |
where
G0(x,y)=1yH∞∑n=0(−1)n(e−(x+n)ϕ(−β,0;−(x+n)y−β)00e7(x+n)ϕ(−β,0;−5(x+n)y−β))H−1. |
After calculating the integrals, we write equality (5.8) in the form
u1(x,y)=yβ−1∞∑n=1(−1)n[e−(x+n)ϕ(−β,β;−(x+n)y−β)+2e7(x+n)ϕ(−β,β;−5(x+n)y−β)], |
u2(x,y)=yβ−1∞∑n=1(−1)n[−e−(x+n)ϕ(−β,β;−(x+n)y−β)+9e7(x+n)ϕ(−β,β;−5(x+n)y−β)]. |
Figures 1 and 2 illustrate the solutions of problems (5.1)–(5.3) in cases β=0.4 and β=0.6.
We investigated the non-local boundary value Problem 2 for system (1.1). For this, we have written out an explicit solution of auxiliary Problem 1 for system (1.1) with the matrix B = 0 in terms of the matrix Wright function. Then, using the integral equations method, we reduced Problem 2 to Problem 1. Our approach is schematically illustrated by a particular example described in section 5. The system under study is of the type Ⅰ. We previously studied some problems for a system of the type Ⅱ, including Problem 2, which generalizes them. Comparing the results of [23] and the present work, we see that the conditions on the matrices M and N, for which Problem 2 is correct, depend on the distribution of the eigenvalues of the matrix A, that is, they are differ for systems of the type Ⅰ and Ⅱ.
Further research will be aimed at expanding the classes of systems and generalizing the described results.
The author declares no conflict of interest in this paper.
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