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Review

Why there is water scarcity

  • During the Neolithic period very few humans (3 to 5 million) lived on Planet Earth. As described in this review, there was an excess of water to support the life of these people. After the advent of agricultural practices, the number of people, as well as the production of food, increased very much and, as a consequence, large amounts of water became necessary to support this development. The availability of water is still in large excess as compared to the needs. The lack of water is the consequence of the lack of the appropriate infrastructures required to transport water to the places where it is needed. People need water in the right places at the right moment. They ask their governments to provide it, but the answers are not satisfactory. The actions needed are at the level of improving the irrigation, the distribution of water, the growth of more efficient vegetables and many similar initiatives. What is needed is a plethora of concerted actions that require national and international initiatives. The answer is an "international" action, not an "intergovernmental" one.

    Citation: Maurizio Iaccarino. Why there is water scarcity[J]. AIMS Geosciences, 2021, 7(3): 529-541. doi: 10.3934/geosci.2021030

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  • During the Neolithic period very few humans (3 to 5 million) lived on Planet Earth. As described in this review, there was an excess of water to support the life of these people. After the advent of agricultural practices, the number of people, as well as the production of food, increased very much and, as a consequence, large amounts of water became necessary to support this development. The availability of water is still in large excess as compared to the needs. The lack of water is the consequence of the lack of the appropriate infrastructures required to transport water to the places where it is needed. People need water in the right places at the right moment. They ask their governments to provide it, but the answers are not satisfactory. The actions needed are at the level of improving the irrigation, the distribution of water, the growth of more efficient vegetables and many similar initiatives. What is needed is a plethora of concerted actions that require national and international initiatives. The answer is an "international" action, not an "intergovernmental" one.



    The topic of fractional differential equations received immense popularity and attraction due to their extensive use in the mathematical modeling of several real world phenomena. Examples include HIV-immune system with memory [1], stabilization of chaotic systems [2], chaotic synchronization [3,4], ecology [5], infectious diseases [6], economic model [7], fractional neural networks [8,9], COVID-19 infection [10], etc. A salient feature distinguishing fractional-order differential and integral operators from the classical ones is their nonlocal nature, which can provide the details about the past history of the phenomena and processes under investigation. In the recent years, many researchers contributed to the development of fractional calculus, for example, see [11,12,13,14,15,16,17,18,19,20,21,22,23,24] and the references cited therein. One can also find a substantial material about fractional order coupled systems in the articles [25,26,27,28,29,30,31,32,33,34].

    In this paper, motivated by [30], we consider a Caputo type coupled system of nonlinear fractional differential equations supplemented with a new set of boundary conditions in terms of the sum and difference of the governing functions given by

    {CDνφ(t)=f(t,φ(t),ψ(t)),tJ:=[0,T],CDρψ(t)=g(t,φ(t),ψ(t)),tJ:=[0,T],P1(φ+ψ)(0)+P2(φ+ψ)(T)=mi=1ai(φ+ψ)(σi),T0(φψ)(s)dsζη(φψ)(s)ds=A, (1.1)

    where CDχ is the Caputo fractional derivative operator of order χ{ν,ρ}, ν,ρ(0,1], 0<σi<η<ζ<T, i=1,,m (the case 0<η<ζ<σi<T can be treated in a similar way), P1,P2,ai,A are nonnegative constants, such that P1+P2mi=1ai0, Tζ+η0, and f,g:[0,T]×R2R are continuous functions.

    Here it is imperative to notice that the first condition introduced in the problem (1.1) can be interpreted as the sum of the governing functions φ and ψ at the end positions of the interval [0,T] is sum of similar contributions due to arbitrary positions at σi(0,T),i=1,...,m, while the second condition describes that the contribution of the difference of the governing functions φ and ψ on the domain [0,T] differs from the one an arbitrary sub-domain (η,ξ) by a constant A.

    We will also study the problem (1.1) by replacing A in the last condition with the one containing nonlinear Riemann-Liouville integral term of the form:

    1Γ(δ)T0(Ts)δ1h(s,φ(s),ψ(s))ds,δ>0, (1.2)

    where h:[0,T]×R2R is a given continuous function.

    We organize the rest of the paper as follows. In Section 2, we outline the related concepts of fractional calculus and establish an auxiliary lemma for the linear analogue of the problem (1.1). We apply the standard fixed point theorems to derive the existence and uniqueness results for the problem (1.1) in Section 3. The case of nonlinear Riemann-Liouville integral boundary conditions is discussed in Section 4. The paper concludes with some interesting observations and special cases.

    Let us begin this section with some preliminary concepts of fractional calculus [11].

    Definition 2.1. The Riemann-Liouville fractional integral of order q>0 of a function h:[0,)R is defined by

    Iqh(t)=t0(ts)q1Γ(q)h(s)ds,t>0,

    provided the right-hand side is point-wise defined on (0,), where Γ is the Gamma function.

    Definition 2.2. The Caputo fractional derivative of order q for a function h:[0,]R with h(t)ACn[0,) is defined by

    CDqh(t)=1Γ(nq)t0h(n)(s)(ts)qn+1ds=Inqh(n)(t), t>0,n1<q<n.

    Lemma 2.1. Let q>0 and h(t)ACn[0,) or Cn[0,). Then

    (IqCDqh)(t)=h(t)n1k=0h(k)(0)k!tk,t>0,n1<q<n. (2.1)

    Now we present an auxiliary lemma related to the linear variant of problem (1.1).

    Lemma 2.2. Let F,GC[0,T], φ,ψAC[0,T].Then the solution of the following linear coupled system:

    {CDνφ(t)=F(t),tJ:=[0,T],CDρψ(t)=G(t),tJ:=[0,T],P1(φ+ψ)(0)+P2(φ+ψ)(T)=mi=1ai(φ+ψ)(σi),T0(φψ)(s)dsζη(φψ)(s)ds=A, (2.2)

    is given by

    φ(t)=t0(ts)ν1Γ(ν)F(s)ds+12{AΛ21Λ2T0(s0(sx)ν1Γ(ν)F(x)dxs0(sx)ρ1Γ(ρ)G(x)dx)dsP2Λ1(T0(Ts)ν1Γ(ν)F(s)ds+T0(Ts)ρ1Γ(ρ)G(s)ds)+1Λ2ξη(s0(sx)ν1Γ(ν)F(x)dxs0(sx)ρ1Γ(ρ)G(x)dx)ds+mi=1aiΛ1(σi0(σis)ν1Γ(ν)F(s)ds+σi0(σis)ρ1Γ(ρ)G(s)ds)}, (2.3)
    ψ(t)=t0(ts)ρ1Γ(ρ)G(s)ds+12{AΛ2+1Λ2T0(s0(sx)ν1Γ(ν)F(x)dxs0(sx)ρ1Γ(ρ)G(x)dx)dsP2Λ1(T0(Ts)ν1Γ(ν)F(s)ds+T0(Ts)ρ1Γ(ρ)G(s)ds)1Λ2ξη(s0(sx)ν1Γ(ν)F(x)dxs0(sx)ρ1Γ(ρ)G(x)dx)ds+mi=1aiΛ1(σi0(σis)ν1Γ(ν)F(s)ds+σi0(σis)ρ1Γ(ρ)G(s)ds)}, (2.4)

    where

    Λ1:=P1+P2mi=1ai0, (2.5)
    Λ2:=Tζ+η0. (2.6)

    Proof. Applying the operators Iν and Iρ on the first and second fractional differential equations in (2.2) respectively and using Lemma 2.1, we obtain

    φ(t)=t0(ts)ν1Γ(ν)F(s)ds+c1, (2.7)
    ψ(t)=t0(ts)ρ1Γ(ρ)G(s)ds+c2, (2.8)

    where c1,c2R. Inserting (2.7) and (2.8) in the condition P1(φ+ψ)(0)+P2(φ+ψ)(T)=mi=1ai(φ+ψ)(σi), we get

    c1+c2=1Λ1{mi=1ai(σi0(σis)ν1Γ(ν)F(s)ds+σi0(σis)ρ1Γ(ρ)G(s)ds)P2(T0(Ts)ν1Γ(ν)F(s)ds+T0(Ts)ρ1Γ(ρ)G(s)ds)}. (2.9)

    Using (2.7) and (2.8) in the condition T0(φψ)(s)dsζη(φψ)(s)ds=A, we obtain

    c1c2=1Λ2{AT0(s0(sx)ν1Γ(ν)F(x)dxs0(sx)ρ1Γ(ρ)G(x)dx)ds+ξη(s0(sx)ν1Γ(ν)F(x)dxs0(sx)ρ1Γ(ρ)G(x)dx)ds}. (2.10)

    Solving (2.9) and (2.10) for c1 and c2, yields

    c1=12{AΛ21Λ2T0(s0(sx)ν1Γ(ν)F(x)dxs0(sx)ρ1Γ(ρ)G(x)dx)dsP2Λ1(T0(Ts)ν1Γ(ν)F(s)ds+T0(Ts)ρ1Γ(ρ)G(s)ds)+1Λ2ξη(s0(sx)ν1Γ(ν)F(x)dxs0(sx)ρ1Γ(ρ)G(x)dx)ds+1Λ1mi=1ai(σi0(σis)ν1Γ(ν)F(s)ds+σi0(σis)ρ1Γ(ρ)G(s)ds)},

    and

    c2=12{AΛ2+1Λ2T0(s0(sx)ν1Γ(ν)F(x)dxs0(sx)ρ1Γ(ρ)G(x)dx)dsP2Λ1(T0(Ts)ν1Γ(ν)F(s)ds+T0(Ts)ρ1Γ(ρ)G(s)ds)1Λ2ξη(s0(sx)ν1Γ(ν)F(x)dxs0(sx)ρ1Γ(ρ)G(x)dx)ds+1Λ1mi=1ai(σi0(σis)ν1Γ(ν)F(s)ds+σi0(σis)ρ1Γ(ρ)G(s)ds)}.

    Substituting the values of c1 and c2 in (2.7) and (2.8) respectively, we get the solution (2.3) and (2.4). By direct computation, one can obtain the converse of this lemma. The proof is complete.

    Let X=C([0,T],R)×C([0,T],R) denote the Banach space endowed with the norm (φ,ψ)=φ+ψ=supt[0,T]|φ(t)|+supt[0,T]|ψ(t)|, (φ,ψ)X. In view of Lemma 2.2, we define an operator Φ:XX in relation to the problem (1.1) as

    Φ(φ,ψ)(t):=(Φ1(φ,ψ)(t),Φ2(φ,ψ)(t)), (3.1)

    where

    Φ1(φ,ψ)(t)=1Γ(ν)t0(ts)ν1f(s,φ(s),ψ(s))ds+12{AΛ21Λ2T0(s0(sx)ν1Γ(ν)f(x,φ(x),ψ(x))dxs0(sx)ρ1Γ(ρ)g(x,φ(x),ψ(x))dx)dsP2Λ1(T0(Ts)ν1Γ(ν)f(s,φ(s),ψ(s))ds+T0(Ts)ρ1Γ(ρ)g(s,φ(s),ψ(s))ds)+1Λ2ξη(s0(sx)ν1Γ(ν)f(x,φ(x),ψ(x))dxs0(sx)ρ1Γ(ρ)g(x,φ(x),ψ(x))dx)ds+1Λ1mi=1ai(σi0(σis)ν1Γ(ν)f(s,φ(s),ψ(s))ds+σi0(σis)ρ1Γ(ρ)g(s,φ(s),ψ(s))ds)}, (3.2)

    and

    Φ2(φ,ψ)(t)=1Γ(ρ)t0(ts)ρ1g(s,φ(s),ψ(s))ds+12{AΛ2+1Λ2T0(s0(sx)ν1Γ(ν)f(x,φ(x),ψ(x))dxs0(sx)ρ1Γ(ρ)g(x,φ(x),ψ(x))dx)dsP2Λ1(T0(Ts)ν1Γ(ν)f(s,φ(s),ψ(s))ds+T0(Ts)ρ1Γ(ρ)g(s,φ(s),ψ(s))ds)1Λ2ξη(s0(sx)ν1Γ(ν)f(x,φ(x),ψ(x))dxs0(sx)ρ1Γ(ρ)g(x,φ(x),ψ(x))dx)ds+1Λ1mi=1ai(σi0(σis)ν1Γ(ν)f(s,φ(s),ψ(s))ds+σi0(σis)ρ1Γ(ρ)g(s,φ(s),ψ(s))ds)}. (3.3)

    In the forthcoming analysis, we need the following assumptions.

    (H1) There exist continuous nonnegative functions μi,κiC([0,1],R+),i=1,2,3, such that

    |f(t,φ,ψ)|μ1(t)+μ2(t)|φ|+μ3(t)|ψ|(t,φ,ψ)J×R2;
    |g(t,φ,ψ)|κ1(t)+κ2(t)|φ|+κ3(t)|ψ|(t,φ,ψ)J×R2.

    (H2) There exist positive constants αi,βi,i=1,2, such that

    |f(t,φ1,ψ1)f(t,φ2,ψ2)|α1|φ1φ2|+α2|ψ1ψ2|,tJ,φi,ψiR,i=1,2;
    |g(t,φ1,ψ1)g(t,φ2,ψ2)|β1|φ1φ2|+β2|ψ1ψ2|,tJ,φi,ψiR,i=1,2.

    For computational convenience, we introduce the notation:

    ϱ1=12|Λ1|[mi=1aiσνiΓ(ν+1)+P2TνΓ(ν+1)]+12|Λ2|[ζν+1ην+1Γ(ν+2)+Tν+1Γ(ν+2)], (3.4)
    ϱ2=12|Λ1|[mi=1aiσρiΓ(ρ+1)+P2TρΓ(ρ+1)]+12|Λ2|[ζρ+1ηρ+1Γ(ρ+2)+Tρ+1Γ(ρ+2)], (3.5)

    and

    M0=min{1[μ2(2ϱ1+TνΓ(ν+1))+κ2(2ϱ2+TρΓ(ρ+1))],1[μ3(2ϱ1+TνΓ(ν+1))+κ3(2ϱ2+TρΓ(ρ+1))]}.

    We make use of the following fixed point theorem [35] to prove the existence of solutions for the problem (1.1).

    Lemma 3.1. Let E be the Banach space and Q:EE be a completely continuous operator. If the set Ω={xE|x=μQx,0<μ<1} is bounded, then Q has a fixed point in E.

    Theorem 3.1. Suppose that f,g:J×R2R are continuousfunctions and the condition (H1) holds. Then there exists at least one solution for the problem (1.1) on J if

    μ2(2ϱ1+TνΓ(ν+1))+κ2(2ϱ2+TρΓ(ρ+1))<1,μ3(2ϱ1+TνΓ(ν+1))+κ3(2ϱ2+TρΓ(ρ+1))<1, (3.6)

    where ϱi(i=1,2) are defined in (3.4)–(3.5).

    Proof. Observe that continuity of Φ:XX follows from that of the functions f and g. Now we show that the operator Φ maps any bounded subset of X into a relatively compact subset of X. For that, let ΩˉrX be bounded. Then, for the positive real constants Lf and Lg, we have

    |f(t,φ(t),ψ(t))|Lf,|g(t,φ(t),ψ(t))|Lg,(φ,ψ)Ωˉr.

    So, for any (φ,ψ)Ωˉr, tJ, we get

    |Φ1(φ,ψ)(t)|LfΓ(ν)t0(ts)ν1ds+12{A|Λ2|+1Λ2T0(Lfs0(sx)ν1Γ(ν)dx+Lgs0(sx)ρ1Γ(ρ)dx)ds+P2|Λ1|(LfT0(Ts)ν1Γ(ν)ds+LgT0(Ts)ρ1Γ(ρ)ds)+1|Λ2|ξη(Lfs0(sx)ν1Γ(ν)dx+Lgs0(sx)ρ1Γ(ρ)dx)ds+1|Λ1|mi=1ai(Lfσi0(σis)ν1Γ(ν)ds+Lgσi0(σis)ρ1Γ(ρ)ds)}LfTνΓ(ν+1)+Lf2|Λ1|[mi=1aiσνiΓ(ν+1)+P2TνΓ(ν+1)]+Lf2|Λ2|[ζν+1ην+1Γ(ν+2)+Tν+1Γ(ν+2)]+Lg2|Λ1|[mi=1aiσρiΓ(ρ+1)+P2TρΓ(ρ+1)]+Lg2|Λ2|[ζρ+1ηρ+1Γ(ρ+2)+Tρ+1Γ(ρ+2)]+A2|Λ2|,

    which, in view of (3.4) and (3.5), takes the form:

    |Φ1(φ,ψ)(t)|Lf(TνΓ(ν+1)+ϱ1)+Lgϱ2+A2|Λ2|. (3.7)

    In a similar fashion, one can obtain

    |Φ2(φ,ψ)(t)|Lfϱ1+Lg(TρΓ(ρ+1)+ϱ2)+A2|Λ2|. (3.8)

    From (3.7) and (3.8), we get

    Φ(φ,ψ)=Φ1(φ,ψ)+Φ2(φ,ψ)Lf(TνΓ(ν+1)+2ϱ1)+Lg(TρΓ(ρ+1)+2ϱ2)+A|Λ2|.

    From the foregoing inequality, we deduce that the operator Φ is uniformly bounded.

    In order to show that Φ maps bounded sets into equicontinuous sets of X, let t1,t2[0,T],t1<t2, and (φ,ψ)Ωˉr. Then

    |Φ1(φ,ψ)(t2)Φ1(φ,ψ)(t1)||1Γ(ν)(t10[(t2s)ν1(t1s)ν1]f(s,φ(s),ψ(s))ds+t2t1(t2s)ν1f(s,φ(s),ψ(s))ds)|Lf(2(t2t1)ν+tν2tν1Γ(ν+1)).

    Analogously, we can obtain

    |Φ2(φ,ψ)(t2)Φ2(u,v)(t1)|Lg(2(t2t1)ρ+tρ2tρ1Γ(ρ+1)).

    Clearly the right-hand sides of the above inequalities tend to zero when t1t2, independently of (φ,ψ)Ωˉr. Thus it follows by the Arzelá-Ascoli theorem that the operator Φ:XX is completely continuous.

    Next we consider the set E={(φ,ψ)X|(φ,ψ)=λΦ(φ,ψ),0<λ<1} and show that it is bounded. Let (φ,ψ)E, then (φ,ψ)=λΦ(φ,ψ),0<λ<1. For any tJ, we have

    φ(t)=λΦ1(φ,ψ)(t),ψ(t)=λΦ2(φ,ψ)(t).

    As in the previous step, using ϱi(i=1,2) given by (3.4)-(3.5), we find that

    |φ(t)|=λ|Φ1(φ,ψ)(t)|(μ1+μ2φ+μ3ψ)(TνΓ(ν+1)+ϱ1)+(κ1+κ2φ+κ3ψ)ϱ2+A2|Λ2|,
    |ψ(t)|=λ|Φ2(φ,ψ)(t)|(μ1+μ2φ+μ3ψ)ϱ1+(κ1+κ2φ+κ3ψ)(TρΓ(ρ+1)+ϱ2)+A2|Λ2|.

    In consequence, we get

    φ+ψμ1(2ϱ1+TνΓ(ν+1))+κ1(2ϱ2+TρΓ(ρ+1))+A|Λ2|+[μ2(2ϱ1+TνΓ(ν+1))+κ2(2ϱ2+TρΓ(ρ+1))]φ+[μ3(2ϱ1+TνΓ(ν+1))+κ3(2ϱ2+TνΓ(ν+1))]ψ.

    Thus, by the condition (3.6), we have

    (φ,ψ)1M0{μ1(2ϱ1+TνΓ(ν+1))+κ1(2ϱ2+TρΓ(ρ+1))+A|Λ2|},

    which shows that (φ,ψ) is bounded for tJ. In consequence, the set E is bounded. Thus it follows by the conclusion of Lemma 3.1 that the operator Φ has at least one fixed point, which is indeed a solution of the problem (1.1).

    Letting μ2(t)=μ3(t)0 and κ2(t)=κ3(t)0, the statement of Theorem 3.1 takes the following form.

    Corollary 3.1. Let f,g:J×R2R be continuousfunctions such that

    |f(t,φ,ψ)|μ1(t),|g(t,φ,ψ)|κ1(t),(t,φ,ψ)J×R2,

    where μ1,κ1C([0,T],R+). Then there exists at least one solution for the problem (1.1) on J.

    Corollary 3.2. If μi(t)=λi,κi(t)=εi,i=1,2,3, then the condition (H1) becomes:

    (H1) there exist real constants λi,εi>0,i=1,2, such that

    |f(t,φ,ψ)|λ1+λ2|φ|+λ3|ψ|(t,φ,ψ)J×R2;
    |f(t,φ,ψ)|ε1+ε2|φ|+ε3|ψ|(t,φ,ψ)J×R2;

    and (3.6) takes the form:

    λ2(2ϱ1+TνΓ(ν+1))+ε2(2ϱ2+TρΓ(ρ+1))<1,λ3(2ϱ1+TνΓ(ν+1))+ε3(2ϱ2+TρΓ(ρ+1))<1.

    Then there exists at least one solution for the problem (1.1) on J.

    The next result is concerned with the existence of a unique solution for the problem (1.1) and is reliant on the contraction mapping principle due to Banach.

    Theorem 3.2. Let f,g:[0,1]×R2R be continuous functions and the assumption (H2) holds.Then the problem (1.1) has a unique solution on J if

    α(TνΓ(ν+1)+2ϱ1)+β(TρΓ(ρ+1)+2ϱ2)<1, (3.9)

    where α=max{α1,α2},β=max{β1,β2} and ϱi,i=1,2, are defined in (3.4)-(3.5).

    Proof. Consider the operator Φ:XX defined by (3.1) and take

    r>M1(TνΓ(ν+1)+2ϱ1)+M2(TρΓ(ρ+1)+2ϱ2)+A|Λ2|1(α(TνΓ(ν+1)+2ϱ1)+β(TρΓ(ρ+1)+2ϱ2)),

    where M1=supt[0,T]|f(t,0,0)|, and M2=supt[0,T]|g(t,0,0)|. Then we show that ΦBrBr, where Br={(φ,ψ)X:(φ,ψ)r}. By the assumption (H1), for (φ,ψ)Br,t[0,T], we have

    |f(t,φ(t),ψ(t))||f(t,φ(t),ψ(t))f(t,0,0)|+|f(t,0,0)|α(|φ(t)|+|ψ(t)|)+M1α(φ+ψ)+M1.

    In a similar manner, one can find that

    |g(t,φ(t),ψ(t))|β(φ+ψ)+M2.

    In consequence, for (φ,ψ)Br, we obtain

    |Φ1(φ,ψ)(t)|TνΓ(ν+1)(α(φ+ψ)+M1)+12[A|Λ2|+1|Λ2|(Tν+1Γ(ν+2)(α(φ+ψ)+M1)+Tρ+1Γ(ρ+2)(β(φ+ψ)+M2))+P2|Λ1|(TνΓ(ν+1)(α(φ+ψ)+M1)+TρΓ(ρ+1)(β(φ+ψ)+M2))+1|Λ2|(ζν+1ην+1Γ(ν+2)(α(φ+ψ)+M1)+ζρ+1ηρ+1Γ(ρ+2)(β(φ+ψ)+M2))+1|Λ1|mi=1ai(σνiΓ(ν+1)(α(φ+ψ)+M1)+σρiΓ(ρ+1)(β(φ+ψ)+M2))],

    which, on taking the norm for tJ, yields

    Φ1(φ,ψ)(α(TνΓ(ν+1)+ϱ1)+βϱ2)(φ+ψ)+M1(TνΓ(ν+1)+ϱ1)+M2ϱ2+A2|Λ2|.

    In the same way, for (φ,ψ)Br, one can obtain

    Φ2(φ,ψ)(αϱ1+β(TρΓ(ρ+1)+ϱ2))(φ+ψ)+M1ϱ1+M2(TρΓ(ρ+1)+ϱ2)+A2|Λ2|.

    Therefore, for any (φ,ψ)Br, we have

    Φ(φ,ψ))=Φ1(φ,ψ)+Φ2(φ,ψ)(α(TνΓ(ν+1)+2ϱ1)+β(TρΓ(ρ+1)+2ϱ2))(φ+ψ)+M1(TνΓ(ν+1)+2ϱ1)+M2(TρΓ(ρ+1)+2ϱ2)+A|Λ2|<r,

    which shows that Φ maps Br into itself.

    Next it will be shown that the operator Φ is a contraction. For (φ1,ψ1),(φ2,ψ2)E,t[0,T], it follows by (H2) that

    |Φ1(φ1,ψ1)(t)Φ1(φ2,ψ2)(t)|t0(ts)ν1Γ(ν)|f(s,φ1(s),ψ1(s))f(s,φ2(s),ψ2(s))|ds+12{1|Λ2|T0(s0(sx)ν1Γ(ν)|f(x,φ1(x),ψ1(x))f(x,φ2(x),ψ2(x))|dx+s0(sx)ρ1Γ(ρ)|g(x,φ1(x),ψ1(x))g(x,φ2(x),ψ2(x))|dx)ds+P2|Λ1|(T0(Ts)ν1Γ(ν)|f(s,φ1(s),ψ1(s))f(s,φ2(s),ψ2(s))|ds+T0(Ts)ρ1Γ(ρ)|g(s,φ1(s),ψ1(s))g(s,φ2(s),ψ2(s))|ds)+1|Λ2|ξη(s0(sx)ν1Γ(ν)|f(x,φ1(x),ψ1(x))f(x,φ2(x),ψ2(x))|dx+s0(sx)ρ1Γ(ρ)|g(x,φ1(x),ψ1(x))g(x,φ2(x),ψ2(x))|dx)ds+1|Λ1|mi=1ai(σi0(σis)ν1Γ(ν)|f(s,φ1(s),ψ1(s))f(s,φ2(s),ψ2(s))|ds+σi0(σis)ρ1Γ(ρ)|g(s,φ1(s),ψ1(s))g(s,φ2(s),ψ2(s))|ds)}{α(TνΓ(ν+1)+ϱ1)+βϱ2}(φ1φ2+ψ1ψ2),

    and

    |Φ2(φ1,ψ1)(t)Φ2(φ2,ψ2)(t)|t0(ts)ρ1Γ(ρ)|g(s,φ1(s),ψ1(s))g(s,φ2(s),ψ2(s))|ds+12{1|Λ2|T0(s0(sx)ν1Γ(ν)|f(x,φ1(x),ψ1(x))f(x,φ2(x),ψ2(x))|dx+s0(sx)ρ1Γ(ρ)|g(x,φ1(x),ψ1(x))g(x,φ2(x),ψ2(x))|dx)ds+P2|Λ1|(T0(Ts)ν1Γ(ν)|f(s,φ1(s),ψ1(s))f(s,φ2(s),ψ2(s))|ds+T0(Ts)ρ1Γ(ρ)|g(s,φ1(s),ψ1(s))g(s,φ2(s),ψ2(s))|ds)+1|Λ2|ξη(s0(sx)ν1Γ(ν)|f(x,φ1(x),ψ1(x))f(x,φ2(x),ψ2(x))|dx+s0(sx)ρ1Γ(ρ)|g(x,φ1(x),ψ1(x))g(x,φ2(x),ψ2(x))|dx)ds+1|Λ1|mi=1ai(σi0(σis)ν1Γ(ν)|f(s,φ1(s),ψ1(s))f(s,φ2(s),ψ2(s))|ds+σi0(σis)ρ1Γ(ρ)|g(s,φ1(s),ψ1(s))g(s,φ2(s),ψ2(s))|ds)}{αϱ1+β(TρΓ(ρ+1)+ϱ2)}(φ1φ2+ψ1ψ2).

    In view of the foregoing inequalities, it follows that

    Φ(φ1,ψ1)Φ(φ2,ψ2)=Φ1(φ1,ψ1)Φ1(φ2,ψ2)+Φ2(φ1,ψ1)Φ2(φ2,ψ2){α(TνΓ(ν+1)+2ϱ1)+β(TρΓ(ρ+1)+2ϱ2)}(φ1φ2,ψ1ψ2).

    Using the condition (3.9), we deduce from the above inequality that Φ is a contraction mapping. Consequently Φ has a unique fixed point by the application of contraction mapping principle. Hence there exists a unique solution for the problem (1.1) on J. The proof is finished.

    Example 3.1. Consider the following problem

    {CD1/2φ(t)=f(t,φ(t),ψ(t)),tJ:=[0,2],CD4/5ψ(t)=g(t,φ(t),ψ(t)),tJ:=[0,2],(φ+ψ)(0)+5/2(φ+ψ)(2)=1/2(φ+ψ)(1/4)+3/2(φ+ψ)(1/2),20(φψ)(s)ds3/42/3(φψ)(s)ds=1, (3.10)

    where ν=1/2,ρ=4/5,η=2/3,ζ=3/4,a1=1/2,a2=3/2,P1=1,P2=5/2,σ1=1/4,σ2=1/2,A=1,T=2, and f(t,φ,ψ) and g(t,φ,ψ) will be fixed later.

    Using the given data, we find that Λ1=1.5,Λ2=1.91666667, ϱ1=2.110627579,ϱ2=2.494392906, where Λ1,Λ2,ϱ1 and ϱ2 are respectively given by (2.5), (2.6), (3.4) and (3.5). For illustrating theorem 3.1, we take

    f(t,φ,ψ)=et516+t2(tan1φ+ψ+cost)andg(t,φ,ψ)=1(t+2)6(|φ|1+|ψ|+tψ+et). (3.11)

    Clearly f and g are continuous and satisfy the condition (H1) with μ1(t)=etcost516+t2,μ2(t)=et516+t2,μ3(t)=et1016+t2,κ1(t)=et(t+2)6,κ2(t)=1(t+2)6, and κ3(t)=12(t+2)6. Also

    μ2(2ϱ1+TνΓ(ν+1))+κ2(2ϱ2+TρΓ(ρ+1))0.398009902,

    and

    μ3(2ϱ1+TνΓ(ν+1))+κ3(2ϱ2+TρΓ(ρ+1))0.199004951<1.

    Thus all the conditions of theorem 3.1 hold true and hence the problem (3.10) with f(t,φ,ψ) and g(t,φ,ψ) given by (3.11) has at least one solution on [0,2].

    Next we demonstrate the application of Theorem 3.2. Let us choose

    f(t,φ,ψ)=ettan1φ+cosψ516+t2andg(t,φ,ψ)=1(2+t)6(|φ|2+|φ|+sinψ). (3.12)

    It is easy to show that the condition (H2) is satisfied with α1=α2=1/20=α and β1=1/64,β2=1/128 and so, β=1/64. Also α(TνΓ(ν+1)+2ϱ1)+β(TρΓ(ρ+1)+2ϱ2)0.39800990<1. Thus the hypothesis of Theorem 3.2 holds and hence its conclusion implies that the problem (3.10) with f(t,φ,ψ) and g(t,φ,ψ) given by (3.12) has a unique solution on [0,2].

    In this section, we consider a variant of the problem (1.1) involving a nonlinear Riemann-Liouville integral term in the last boundary condition given by

    {CDνφ(t)=f(t,φ(t),ψ(t)),tJ:=[0,T],CDρψ(t)=g(t,φ(t),ψ(t)),tJ:=[0,T],P1(φ+ψ)(0)+P2(φ+ψ)(T)=mi=1ai(φ+ψ)(σi),T0(φψ)(s)dsζη(φψ)(s)ds=1Γ(δ)T0(Ts)δ1h(s,φ(s),ψ(s))ds,δ>0. (4.1)

    Now we state a uniqueness result for the problem (4.1). We do not provide the proof of this result as it is similar to that of Theorem 3.2.

    Theorem 4.1. Let f,g,h:[0,1]×R2R be continuous functions and the following assumption holds:

    (¯H2) There exist positive constants αi,βi,γi,i=1,2, such that

    |f(t,φ1,ψ1)f(t,φ2,ψ2)|α1|φ1φ2|+α2|ψ1ψ2|,tJ,φi,ψiR,i=1,2;
    |g(t,φ1,ψ1)g(t,φ2,ψ2)|β1|φ1φ2|+β2|ψ1ψ2|,tJ,φi,ψiR,i=1,2;
    |h(t,φ1,ψ1)h(t,φ2,ψ2)|γ1|φ1φ2|+γ2|ψ1ψ2|,tJ,φi,ψiR,i=1,2.

    Then the problem (4.1) has a unique solution on J if

    γTδ|Λ2|Γ(δ+1)+α(TνΓ(ν+1)+2ϱ1)+β(TρΓ(ρ+1)+2ϱ2)<1, (4.2)

    where α=max{α1,α2},β=max{β1,β2},γ=max{γ1,γ2}, and ϱi,i=1,2 are defined in (3.4)-(3.5).

    Example 4.1. Let us consider the data given in Example 3.1 for the problem (4.1) with (3.12), h(t,φ,ψ)=(sinφ+cosψ+1/2)/t2+49 and δ=3/2. Then γ=1/7 and

    γTδ|Λ2|Γ(δ+1)+α(TνΓ(ν+1)+2ϱ1)+β(TρΓ(ρ+1)+2ϱ2)0.5565956<1.

    Clearly the assumptions of Theorem 4.1 are satisfied. Hence, by the conclusion of Theorem 4.1, the problem (4.1) with the given data has a unique solution on [0,2].

    We have studied a coupled system of nonlinear Caputo fractional differential equations supplemented with a new class of nonlocal multipoint-integral boundary conditions with respect to the sum and difference of the governing functions by applying the standard fixed point theorems. The existence and uniqueness results presented in this paper are not only new in the given configuration but also provide certain new results by fixing the parameters involved in the given problem. For example, our results correspond to the ones with initial-multipoint-integral and terminal-multipoint-integral boundary conditions by fixing P2=0 and P1=0 respectively in the present results. By taking A=0 in the present study, we obtain the results for the given coupled system of fractional differential equations with the boundary conditions of the form:

    P1(φ+ψ)(0)+P2(φ+ψ)(T)=mi=1ai(φ+ψ)(σi),T0(φψ)(s)ds=ζη(φψ)(s)ds,

    where the second (integral) condition means that the contribution of the difference of the unknown functions (φψ) on the domain (0,T) is equal to that on the sub-domain (η,ζ). Such a situation arises in heat conduction problems with sink and source. In the last section, we discussed the uniqueness of solutions for a variant of the problem (1.1) involving nonlinear Riemann-Liouville integral term in the last boundary condition of (1.1). This consideration further enhances the scope of the problem at hand. As a special case, the uniqueness result (Theorem 4.1) for the problem (4.1) corresponds to nonlinear integral boundary conditions for δ=1.

    This project was funded by the Deanship of Scientific Research (DSR), King Abdulaziz University, Jeddah, Saudi Arabia under grant no. (KEP-PhD-80-130-42). The authors, therefore, acknowledge with thanks DSR technical and financial support. The authors also thank the reviewers for their useful remarks that led to the improvement of the original manuscript.

    The authors declare that they have no competing interests.



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