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Smooth Transonic Flows Around Cones

  • Received: 01 March 2022 Published: 17 June 2022
  • Primary: 35L65, 35L67; Secondary: 76N10

  • We consider a conical body facing a supersonic stream of air at a uniform velocity. When the opening angle of the obstacle cone is small, the conical shock wave is attached to the vertex. Under the assumption of self-similarity for irrotational motions, the Euler system is transformed into the nonlinear ODE system. We reformulate the problem in a non-dimensional form and analyze the corresponding ODE system. The initial data is given on the obstacle cone and the solution is integrated until the Rankine-Hugoniot condition is satisfied on the shock cone. By applying the fundamental theory of ODE systems and technical estimates, we construct supersonic solutions and also show that no matter how small the opening angle is, a smooth transonic solution always exists as long as the speed of the incoming flow is suitably chosen for this given angle.

    Citation: Wen-Ching Lien, Yu-Yu Liu, Chen-Chang Peng. Smooth Transonic Flows Around Cones[J]. Networks and Heterogeneous Media, 2022, 17(6): 827-845. doi: 10.3934/nhm.2022028

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  • We consider a conical body facing a supersonic stream of air at a uniform velocity. When the opening angle of the obstacle cone is small, the conical shock wave is attached to the vertex. Under the assumption of self-similarity for irrotational motions, the Euler system is transformed into the nonlinear ODE system. We reformulate the problem in a non-dimensional form and analyze the corresponding ODE system. The initial data is given on the obstacle cone and the solution is integrated until the Rankine-Hugoniot condition is satisfied on the shock cone. By applying the fundamental theory of ODE systems and technical estimates, we construct supersonic solutions and also show that no matter how small the opening angle is, a smooth transonic solution always exists as long as the speed of the incoming flow is suitably chosen for this given angle.



    The supersonic flow over cones is a fundamental problem in fluid dynamics [1,8,14]. We consider a conical body facing a supersonic stream of air at a uniform velocity and the angle of attack is zero. Assume that the obstacle is an infinite cone with its vertex located at the origin. A shock wave is formed either as a bow shock, also called a detached shock away from the cone, or a conical shock attached to the vertex. We are interested in which case the opening angle of the conical obstacle is not too large and thus a conical shock wave with the same vertex is situated on the obstacle in three dimensional space.

    The essential property of the conical flow is that all flow properties are constant along rays from a given vertex. We take the x-axis as the axis of symmetry. y is the distance from the axis. u represents the component of the flow velocity in the direction of the axis. And v is the component in the perpendicular direction away from the axis. When the flow is isentropic and steady, the compressible Euler system is as follows:

    x(ρu)+y(ρv)=1y(ρv),x(ρu2+P)+y(ρuv)=1y(ρuv),x(ρuv)+y(ρv2+P)=1y(ρv2). (1.1)

    And the pressure P depends on the density ρ and is given by P(ρ)=ργ,γ>1. The above system can be regarded as one-dimensional hyperbolic conservation laws with a source term. Busemann [4] first gave a graphical method to construct self-similar solutions for the irrotational flow. The flow properties depend on the self-similar variable σ=x/y. Owing to self-similarity [3,5], he simplifies system (1.1) to obtain the nonlinear ODE.

    dvdσ+σdudσ=0,(1u2c2)dudσ2uvc2dvdσ(1v2c2)σdvdσ+v=0. (1.2)

    The sound speed c is a given function of u and v through Bernoulli's law. The conical flow in [4] is described as a solution of the initial value problem of the system (1.2). Through the Rankine-Hugoniot conditions, the flow velocity past the shock cone is given as the initial condition. The solution is continued so that σ increases up to an end point at which the flow and the obstacle boundary have the same direction. A given shock wave is assumed first and the particular cone that supports the given shock is then calculated. We note that a more realistic case is discussed in [11] when the obstacle is a perturbation of the infinite cone. It is shown that the perturbed 3-dimensional flow of system (1.1) exists globally in space and tends to the self-similar flow downstream. The analysis is based on an approximation scheme using local self-similar solutions as building blocks.

    Also, Maccoll and Taylor [13] discuss the problem in the spherical coordinate system. The numerical solution is constructed by a direct approach. Different from Busemann's method, the initial values are given at the surface of the obstacle cone. The complete solution is then worked out by numerical integration for three cones of semi-vertical angles θb=10,20 and 30. The calculated pressure at the surface is compared with observations of pressure made in a high speed wind channel and they have a good agreement.

    In this paper, we study steady Euler system in the spherical coordinates. Due to the self-similarity for conical flows, we obtain the following Taylor-Maccoll equation for Vr and Vθ

    {γ12(V2mV2rV2θ)(2Vr+Vθcotθ+dVθdθ)Vθ(VrdVrdθ+VθdVθdθ)=0.dVrdθ=Vθ. (1.3)

    Here, the radial and normal components of the flow velocity V are denoted by Vr and Vθ respectively. Vm is the theoretical maximum speed for Bernoulli's law. We reformulate the problem in a non-dimensional form and analyze the corresponding nonlinear ODE system. The initial data is given on the obstacle cone and the solution is integrated until the Rankine-Hugoniot condition is satisfied on the shock cone. According to previous numerical results [13], the flow is either supersonic or transonic. We are thus interested in the transition between different flow patterns. The flowfield is constructed as follows. First, the obstacle cone is given with semi-vertical angle θb of opening and θb is not too large. Also, the non-dimensional speed U0 of the incoming supersonic flow is given in the range (μ,1), μ=(γ1)/(γ+1). We solve the initial value problem of the ODE system with the initial data given on the cone boundary. The flow velocity is chosen parallel to the boundary and the corresponding Mach number is set to be 1. Second, the solution curve of the ODE system is continued until it intersects with the shock polar for U0. And we obtain the angle θS where the intersection happens. Finally, we need to verify that the surface of the shock cone is exactly θ=θS when U0 is correctly selected.

    By applying the fundamental theory of ODE system, we show that no matter how small the opening angle θb is, smooth transonic solutions always exist when the Mach number on the cone boundary varies around 1. We note that the system is non-autonomous. To construct the solutions, we focus on a fixed region to check the Lipschitz condition. We require γ(1,5) so that the function A of the system has a positive lower bound. Hence, the Lipschitz constant can be calculated, which is shown in Section 3. Although cotθb is an important factor of the Lipschitz constant for the ODE system, it is a fixed constant since the solution is restricted to the region for which the Mach number M is around 1. We also note that θS changes as U0 varies. The relation between θS and the angle β of the shock cone is investigated for the existence of the fixed point θS=β. For technical estimates, θb is required to be small and satisfy the following condition:

    Condition A:arctan(1μ2μ)arctan(μ)+θb.

    At present, our main concern is the existence of smooth transonic flows. The transition line between the subsonic and supersonic regions can be clearly indicated. Analogous to the problem [11], we might ask: Does there exist a transonic flow past the obstacle which coincides at infinity with the given undisturbed flow? This is a mixed type problem and should be investigated in the context of the partial differential equations. Steady transonic flow in multidimensional space has always been an important and challenging topic. We refer to the work of Chen and Fang [6] in which they also study the conical flow. They consider the transonic shock front behind which the flow is completely subsonic. They show that the self-similar transonic shock solution is conditionally stable with respect to the conical perturbation of the cone boundary. In two dimensional space, the problem of a flow past a straight wedge for a high subsonic free stream Mach number has been investigated by several authors. Cole [7] determined the singularity required to represent the flow near the point at infinity and showed how the condition at the stagnation point must be interpreted if one uses the transonic approximation which, in principle, does not permit stagnation point. His solution can be described as resulting from the assumption of a vertical sonic line. We also refer to [2] and [10] for more knowledge of transonic flows.

    The paper is organized as follows. In Section 2, we describe the self-similar flow in the spherical coordinate system. The basic properties and equations are summarized in Section 2.1. Due to the self-similarity and the conservation laws, the Taylor-Maccoll equation is derived as a 2nd order ordinary differential equation. In Section 2.2, we introduce the non-dimensional physical quantities and rewrite the equation as a 1st order system for the self-similar solutions. In Section 3, we analyze the nonlinear ODE system. By the fundamental theory and some technical estimates, we construct the supersonic solutions. Further analysis using Gronwall's inequality reveals the phenomenon of the transition from the supersonic to subsonic region. Finally, the numerical simulations are presented in Section 4. In the Appendix, we derive the Rankine-Hugoniot condition and the equation of the shock polar in the spherical coordinates.

    The essential property of the conical flow is that all flow properties are constant along rays from a given vertex. When the opening angle is not too large, an oblique shock wave S is attached at the vertex. The shape of the shock wave is also conical. This aspect of conical flow has been proven experimentally. We take the x3-axis as the axis of symmetry and use the spherical coordinates:

    x1=rsinθcosϕ,x2=rsinθsinϕ,x3=rcosθ,

    where r0, 0θπ and 0ϕ2π. The corresponding components of the flow velocity V in the spherical coordinates are denoted by Vr, Vϕ, and Vθ respectively.([1,Ch10.3]) The Euler equations for the steady flow are as follows.

    Conservation of Mass:ρr=1Vr[ρVrr+2ρVrr+1rsinθ(ρVθsinθ)θ+1rsinθ(ρVϕ)ϕ] (2.1)
    Momentum in r direction:Vrr=1Vr[VθrVrθ+VϕrsinθVrϕV2θ+V2ϕr+1ρPr] (2.2)
    Momentum in θ direction:Vθr=1Vr[VθrVθθ+VϕrsinθVθϕ+VrVθrV2ϕcotθr+1rρPθ] (2.3)
    Momentum in ϕ direction:Vϕr=1Vr[VθrVϕθ+VϕrsinθVϕϕ+VrVϕr+VθVϕcotθr+1rρsinθPϕ] (2.4)

    Here we consider the polytropic gases: P(ρ)=ργ, γ>1.

    The PDE system (2.1)-(2.4) is complicated and thus we focus on the typical model with the self-similarity property [3,5]. We know that for the conical flow, ϕ0 due to the axisymmetry. That is, ϕρ=0, ϕVr=0, ϕVϕ=0, and ϕVθ=0. And the flow properties are constant along a ray from the vertex, which implies that rρ=0 and rVr=0. Hence, the conservation law of mass is as follows:

    2ρVr+ρVθcotθ+ρVθθ+Vθρθ=0. (2.5)

    Since the conical flow is irrotational:  curl V=×V=0, we obtain that in spherical coordinates,

    Vθ=Vrθ. (2.6)

    From the conservation laws, Bernoulli's law for steady flow holds across a shock front:

    c2γ1+V22=V2m2, (2.7)

    where c=P(ρ) is the sound speed and Vm is the theoretical maximum velocity. Note that Vm can be served as the characteristic velocity. Here we use the notation V2=V2r+V2θ since Vϕ=0. We note that the flow is everywhere isentropic behind the shock front. Thus, Vm is a constant for the flow. ([8,Ch 6.B], or [1,13]). Since Vr, Vθ and ρ depend only on one variable θ (see Figure 1); thus, the PDE system can be transformed into the ODE system.

    Figure 1. 

    Spherical coordinate system

    .

    The Bernoulli principle [1,Ch8.2] for irrotational flows can be expressed as follows.

    dP=12ρd(V2).

    Hence,

    dP=ρ(VrdVr+VθdVθ). (2.8)

    Since

    dPdρ=c2,

    by (2.7) and (2.8), we obtain

    dρρ=2γ1(VrdVr+VθdVθV2mV2rV2θ). (2.9)

    By (2.5), (2.6) and (2.9), we obtain the Taylor-Maccoll equation:

    γ12[V2mV2r(dVrdθ)2][2Vr+dVrdθcotθ+d2Vrdθ2]dVrdθ[VrdVrdθ+dVrdθd2Vrdθ2]=0. (2.10)

    We note that ρ can be represented by Vr and Vθ through (2.7).

    Because of (2.9), (2.5) can be written as a system of first order ODEs. Together with (2.6), we obtain the following system:

    {γ12(V2mV2rV2θ)(2Vr+Vθcotθ+dVθdθ)Vθ(VrdVrdθ+VθdVθdθ)=0.dVrdθ=Vθ. (2.11)

    We introduce the non-dimensional physical quantities as follows.

    UVVm,UrVrVm,UθVθVm.

    After direct calculations, we obtain

    {UθUrdUrdθ+AdUθdθ=B,dUrdθ=Uθ, (2.12)

    where

    {A=U2θ+(γ12)(1U2rU2θ)B=(1γ2)(1U2rU2θ)(2Ur+Uθcotθ).

    Hence, we have the ODE system:

    {dUθdθ=U2θUr+BA,dUrdθ=Uθ. (2.13)

    By direct calculations, we obtain the following lemma.

    Lemma 2.1. Let γ>1. A=U2θ+(γ12)(1U2rU2θ).

    1. A0 if and only if

    (γ+1γ1)U2θ+U2r1.

    2. Let U2=U2θ+U2r. Suppose that (Uθ,Ur) is a solution of the system (2.13). Then

    ddθ(U2)=1A[(1γ)(1U2)Uθ(Ur+cotθUθ)].

    Proof. (1) can be proved by direct calculations.

    (2): Substituting (2.13) gives

    ddθ(U2)=dUθdθ2Uθ+dUrdθ2Ur=1A[2Uθ(1γ2)(1U2)(2Ur+cotθUθ)+2UrUθ(γ12)(1U2)]=1A[(1γ)(1U2)Uθ(Ur+cotθUθ)].

    Remark 1. By (2.12), we have that

    AdUθdθ=U2θUr+B,=Ur(A)+(1γ2)(1U2rU2θ)(Ur+Uθcotθ).

    If A=0 at some point (Uθ(˜θ),Ur(˜θ)), then Ur+Uθcotθ=0 at (Uθ(˜θ),Ur(˜θ)).

    Remark 2. Since Vm is determined by (2.7)

    12V2+c2γ1=12V2m,

    it follows that

    U22+U2(γ1)(V/c)2=12.

    Here, U2=U2r+U2θ. The relationship between the Mach number M=V/c and the non-dimensional speed |U| is as follows

    |U|=[1+2(γ1)M2]1/2. (2.14)

    In this section, we present the existence and stability of solutions of the system (2.13). Let the solution be denoted by

    U=(Uθ,Ur).

    We rewrite the system as follows:

    {dUθdθ=F(Uθ,Ur,θ)=U2θUr+BA,dUrdθ=G(Uθ,Ur,θ)=Uθ, (3.1)

    where A=U2θ+(γ12)(1U2rU2θ) and B=(1γ2)(1U2rU2θ)(2Ur+Uθcotθ). Since the flow is parallel to the obstacle cone on the cone boundary θ=θb (Fig 2), we have Uθ(θb)=0. Hence, the initial condition of system (3.1) is always given on the boundary of the obstacle cone as follows:

    U(θb)=(0,ub). (3.2)
    Figure 2. 

    The shock cone

    .

    Here 0<ub<1 and A(θb)>0 according to Lemma 2.1. The ODE system is non-autonomous. We need to prove that the functions F and G are Lipschitz in U=(Uθ,Ur). Thus, by the fundamental existence and uniqueness theorem of differential equations [9], the solution exists and is continuous with respect to the initial conditions. Furthermore, the boundary condition of the solution is given by the shock conditions on the shock cone, which is derived in the Appendix. That is, the solution of the ODE system is continued until it intersects with the shock polar.

    The procedure of the construction is as follows.

    Step 1. (Initial Condition)

    The initial condition is chosen as

    U(θb)=(0,γ1γ+1).

    That is, M=1 at θ=θb. We first solve the initial value problem of the ODE system (3.1) and such solution is denoted by U1(θ).

    Step 2. (Boundary Condition)

    The non-dimensional speed U0 of the incoming supersonic flow is given in the range (μ,1). The solution curve U1(θ) of the ODE system is continued until it intersects with the corresponding shock polar for U0. And we obtain the angle θS and the 1-state (Uθ(θS),Ur(θS)) where the intersection happens.

    Step 3. (The Shock Condition)

    The angle the shock makes with the upstream flow is denoted by β and it is calculated by the formula (in the Appendix)

    tanβ=U20U2rUr

    Here the 1-state (Uθ,Ur) is obtained in Step 2. Finally, we need to verify whether or not

    θS=β

    for the given U0. The shock cone is shown in Figure 2.

    We first focus on the region Ω in UθUr plane, where

    Ω={(Uθ,Ur):Ur(0,γ1γ+1],Uθ[γ1γ+3,0]}

    According to (A.8) in the Appendix, the non-dimensional speed U0 of the incoming supersonic flow is chosen to satisfy that

    1>U0>γ1γ+1. (3.3)

    The intersection point of the shock polar with the Uθ axis is denoted by (p0,0). By the Remark A.1 and direct calculations, 0<p0<γ1γ+3 for U0>γγ+1. Hence, the corresponding shock polar which we discuss is inside the region Ω. We also note that the curve of M=1 (or U2r+U2θ=γ1γ+1) intersects with the shock polar in Ω by straightforward calculations. The local solutions are in the region Ω when the incoming speed satisfies U0>γγ+1.

    Lemma 3.1. Let γ(1,5). The function A defined in Lemma 2.1 has a positive lower bound a0(γ) for Ur(0,(γ1)/(γ+1)] and |Uθ|[0,(γ1)/(γ+3)].

    Proof. By direct calculations, we obtain

    A=12(γ1)[1U2rγ+1γ1U2θ](γ1)(5γ2)2(γ+1)(γ+3)=a0(γ)

    for Ur(0,(γ1)/(γ+1)] and |Uθ|[0,(γ1)/(γ+3)]. And a0(γ)>0 for γ(1,5).

    Lemma 3.2. For any given opening angle of the obstacle cone θb(0,π/2) and dcotθb>0, there exist someconstants C1=C1(γ) and C2=C2(γ) such that

    |FUθ|+|FUr|+|GUθ|+|GUr|C1d+C2

    for Ur(0,(γ1)/(γ+1)] and |Uθ|[0,(γ1)/(γ+3)].

    Proof. We know that cotθ is decreasing with respect to θ and 0<cotθd for θ[θb,π/2). By calculating the partial derivatives of B, where

    B=12(1γ)(1U2rU2θ)(2Ur+Uθcotθ),

    we have

    |B|+|BUr|+|BUθ|c1d+c2.

    Here ci are some constants depending on γ.

    Furthermore, G=Uθ and F=1A(U2θUr+B).

    FUθ=1A2[A(2UrUθ+BUθ)AUθ(U2θUr+B)]FUr=1A2[A(U2θ+BUr)AUr(U2θUr+B)]

    It is easy to check by calculations and Lemma 3.1 that

    a0(γ)<A+|AUr|+|AUθ|ˆc,

    where ˆc is a constant depending on γ. By combining the above estimates, we obtain the lemma.

    By Lemma 3.2, the functions F and G are Lipschitz in U. By the fundamental existence and uniqueness theorem of differential equations [9], the solution U1(θ) exists and is continuous with respect to the initial condition. We write

    U1(θ)=(Uθ(θ),Ur(θ))

    and the corresponding A of U1 is

    A(θ)=U2θ(θ)+(γ12)(1U2r(θ)U2θ(θ)).

    We note that there exists ˉθ>θb such that A(θ)>0 for all θ[θb,ˉθ) and A(ˉθ)=0.

    Lemma 3.3. Let g(θ)=Ur(θ)+cotθUθ(θ). Theng(θ)>0 for all θ[θb,ˉθ).

    Proof. Due to the system (3.1) and direct calculations, we have

    g(θ)=Ur+(csc2θ)Uθ+cotθUθ=cot2θUθcotθUr(cotθC(θ)g(θ))=cotθ(1+C(θ))g(θ),

    where

    C(θ)=(γ12)(1U2rU2θ)A

    We note that C(θ)>0. And thus

    g(θ)=(eθθbcotτ(1+C(τ))dτ)g(θb).

    Since g(θb)=μ>0, we obtain that g(θ)>0 for all θ[θb,ˉθ).

    Theorem 3.4. Let the non-dimensional speed U0 of the incoming flow be given in(γγ+1,1). Then, the solution U1(θ)intersects with the corresponding shock polar at some point U1(θS) and U1(θ) is supersonic for θ(θb,θS].

    Proof. We first solve system (3.1) with (3.2) given by ub=γ1γ+1; that is, M=1 at θ=θb. According to system (3.1), dUrdθ(θb)=0 and dUθdθ(θb)=2ub. Such solution is denoted by U1(θ). By Lemma 2.1 and Lemma 3.3,

    ddθ(U2)=1A[(1γ)(1U2)Uθ(Ur+cotθUθ)]>0.

    |U1(θ)| is increasing in θ. Thus M is increasing with respect to θ by (A.8)

    |U|=[1+2(γ1)M2]1/2.

    According to the ODE system, Uθ<0 for θ>θb and Ur is decreasing in θ. Since M is increasing in θ, U1(θ) is a supersonic solution for θ>θb. Hence, the curve of U1(θ) lies above the curve M=1 (or U2r+U2θ=γ1γ+1) and below the horizontal line Ur=γ1γ+1. Let Γ denote the region enclosed by the shock polar for the given U0, the curve M=1 and the horizontal line Ur=γ1γ+1 as shown in Figure 3. U1(θ) is inside the region Γ. By Remark A.1, the shock polar is given by

    Uθ=μ2(1U2r)U20U2r
    Figure 3. 

    The Γ region

    .

    and Uθ is increasing with respect to Ur. By direct calculations, the shock polar intersects with the curve M=1 at p1 and also with the horizontal line Ur=γ1γ+1. Thus, U1(θ), which is in between the curves M=1 and Ur=γ1γ+1, intersects with the shock polar in the region Γ.

    In Section 3.1, we just show that the supersonic solution exists in the Γ region when U0(γγ1,1). Actually, U1(θ) can be extended until the fixed point is reached for the shock condition to be satisfied. In this subsection, we prove the existence of the fixed point θS=β under the following condition:

    Condition A:arctan(1μ2μ)arctan(μ)+θb. (3.4)

    Let ϕ denote the angle between ¯OU1(θ) and the positive Ur-axis as shown in Figure 4. That is,

    ϕ(θ)=arctan(Uθ(θ)Ur(θ)),θ[θb,ˉθ).
    Figure 4. 

    ϕ and β

    .

    Lemma 3.5. ϕ(θb)=0, and ϕ(θ)1 for θ[θb,ˉθ).

    Proof. Substituting U1(θb)=(Uθ(θb),Ur(θb))=(0,ub) on ϕ(θ) yields

    ϕ(θb)=arctan(Uθ(θb)Ur(θb))=arctan(0μ)=0.

    By direct calculations, we have

    ϕ(θ)=(11+(UθUr)2)(UθUr(Uθ)UrU2r)=U2r+U2θ+UrC(θ)g(θ)U2r+U2θ,

    where

    C(θ)=(γ12)(1U2rU2θ)A>0

    and by Lemma 3.3

    g(θ)=Ur(θ)+cotθUθ(θ)>0.

    Since Ur>0, C(θ)>0 and g(θ)>0, we obtain ϕ(θ)1.

    To investigate the relation between θS and the shock angle β, we need to calculate the following function along the solution U1(θ):

    tanβ(θ)=U20U2r(θ)Ur(θ),

    where U0 is given by the formula

    U2θ(θ)=μ4(1U2r(θ))2U20U2r(θ). (3.5)

    We then compare these functions y=β(θ), y=θ and y=ϕ(θ) in the following lemmas to show the existence of the fixed point (see Figure 5).

    Figure 5. 

    The fixed point

    .

    Lemma 3.6. β(θ)>ϕ(θ) for all θ[θb,ˉθ).

    Proof. By (3.5), we have

    tanβ(θ)=U20U2rUr=1Ur|Uθ|γ1γ+1(1U2r).

    Since A>0,

    U2θ<(γ1γ+1)(1U2r).

    Hence,

    tanβ(θ)=1Ur|Uθ|γ1γ+1(1U2r)>U2θUr|Uθ|=|Uθ|Ur=tanϕ(θ).

    We thus obtain that β(θ)>ϕ(θ) for all θ[θb,ˉθ).

    Remark 3. We also obtain that β(ˉθ)=ϕ(ˉθ) by following the proof of the above lemma when A=0.

    Lemma 3.7. θ>ϕ(θ) for all θ[θb,ˉθ).

    Proof. It is clear that θb>ϕ(θb). If there exists ˆθ(θb,ˉθ) such that ϕ(ˆθ)=ˆθ, i.e. tan(ˆθ)=Uθ(ˆθ)Ur(ˆθ), then

    g(ˆθ)=Ur(ˆθ)+cot(ˆθ)Uθ(ˆθ)=0,

    which is a contradiction to Lemma 3.3.

    When U0=1, the formula of the corresponding shock polar is given by (A.5):

    U2θ=μ4(1U2r). (3.6)

    Since ϕ(θ)1, we know that U1(θ) intersects with the shock polar (3.6) and there exists uniquely θ1(θb,ˉθ) such that

    U2θ(θ1)μ4+U2r(θ1)=1.

    Lemma 3.8. For the solution U1(θ),

    1μ>tanβ(θ1)>1μ2μ

    Proof. We focus on the Γ region and set U0=1. We know that U1(θ) intersects with the shock polar at θ=θ1. The shock polar intersects with the horizontal line Ur=μ at the point (μ21μ2,μ) and it intersects with the curve M=1 at the point p1=(μ2/1+μ2,μ/1+μ2) by direct calculations. Thus,

    μ>Ur(θ1)>μ1+μ2.

    Consider the function

    f(x)=1x2x,x(0,1).

    It is easy to check that f(x)<0. Hence,

    f(μ)<f(Ur(θ1))<f(μ1+μ2).

    That is,

    1μ2μ<tanβ(θ1)<1μ.

    Lemma 3.9. β(θ1)>θ1 when (3.4) is true.

    Proof. We focus on the Γ region and follow the proof of Lemma 3.7. By considering the point p1 and U1(θ1), we have that

    ϕ(θ1)<arctan(μ21+μ2μ1+μ2)=arctan(μ). (3.7)

    By mean value theorem, there exists θc(θb,θ1) so that

    ϕ(θ1)ϕ(θb)=ϕ(θc)(θ1θb).

    By Lemma 3.4 and (3.7),

    arctan(μ)>ϕ(θ1)θ1θb.

    Since we have that arctan(1μ2μ)arctan(μ)+θb, by Lemma 3.7,

    β(θ1)>arctan(1μ2μ)>θ1.

    Theorem 3.10. For the solution U1(θ), there exists θS[θb,ˉθ] such that θS=β(θS) when (3.4) is true.

    Proof. β(θ) is a continuous function defined along the solution U1(θ). By Lemma 3.8, β(θ1)>θ1. By Lemma 3.6 and Remark 3.1, β(ˉθ)ˉθ. Thus, there exists θS[θb,ˉθ] such that θS=β(θS).

    Remark 4. We note that β(θ) may not be a decreasing function when θb is very small according to our numerical results.

    We now construct the transonic solution U(θ) as follows. Let ϵ>0 be sufficiently small and the initial data of U(θ) given by

    U(θb)=(0,γ1γ+1ϵ).

    Thus, M<1 at θ=θb. By Lemma 3.1 and Lemma 3.2, K=C1d+C2 is a Lipschitz constant in U for F and G. K depends only on γ and d. By the fundamental theory [9], the solution U(θ) exists and is continuous with respect to the initial conditions. According to the system and following the proofs in Section 3.1 and 3.2, Ur(θ) is decreasing with respect to θ.

    The solution U1(θ) can be continued until it intersects with the shock polar. According to Theorem 3.2, U1(θ) intersect with the shock polar at θ=θ1S, where θ1S is the angle of the shock cone. We can choose some θ(θb,θ1S) such that |U1(θ)|>μ and A(U(θ))>a0(γ)>0. Gronwall's inequality gives that

    |U1(θ)U(θ)|e(K|θθb|)|U1(θb)U(θb)|.

    Since U1 is supersonic and |θ1Sθb|<π/2, we then choose ϵ small enough so that |U(θ)|>μ and U is supersonic in the neighborhood of θ. Hence, U(θ) is a smooth transonic solution of the initial value problem for the system (3.1) and (3.2). We state the main results in this section as follows.

    Theorem 3.11. Let γ(1,5). For any small opening semi-vertical angle θb of the obstacle cone satisfying (3.4), the solution of system (3.1) exists with the initial data given inthe neighborhood of ub=γ1γ+1. Thesolution can be continued until it intersects with the shock polar.

    Most importantly,

    1. The solution U1(θ) exists with the initial data U1(θb)=(0,γ1γ+1). And U1(θ) is supersonic for θ(θb,θ1S]. Here, θ1S is the angle of the shock cone.

    2. We can choose ϵ>0 sufficiently small such that the solution U(θ) is transonic with the initial data given by U(θb)=(0,γ1γ+1ϵ).

    In summary, we construct smooth transonic solutions when the opening angle of the conical obstacle is small and a conical shock wave is situated on the obstacle with the same vertex. Under the assumption of self-similarity for irrotational fluid, the Euler system (1.1) of steady flows is transformed into the nonlinear ODE system (3.1). We analyze the ODE system in Section 3 and present the numerical solutions in this section.

    We choose U0=0.95 and γ=1.4 in Figure 6. Since the numerical results are similar for different angles θb=5,10 and 30, we only show the result of θb=30. When γ=1.4, Condition A is true if θb<43. And the numerical result for βθSU0 relation is shown in Figure 7. We note that the fixed point for θS=β is found when U0 is around 0.6.

    Figure 6. 

    The numerical solution for γ=1.4

    .
    Figure 7. 

    The numerical result for βθSU0 relation

    .

    We briefly review the quantitative analysis of shock polars for polytropic gases. We refer the readers to Courant and Friedrichs [8,Ch4.C: Section 121] and the references therein for more details.

    Consider a shock S in the (x,y)-plane with the upstream state of velocity V0=(V0,0) and the downstream state of velocity V1, which makes angle θ with the upstream flow. The angle the shock makes with the upstream flow is denoted by β as shown in Figure 8. For the given velocity V0 and density ρ0, there is a one-parametric family of possible states, with velocity V1 and density ρ1, which can be reached through a shock. These possible states are given by the Rankine-Hugoniot conditions of the conservation of mass, momentum and energy. On the phase space of the velocity V, the states V1 lie on a curve, called the shock polar. Let N and L be the normal and tangential components of the velocity V to the shock line S respectively. We have

    N0=V0sinβ (A.1)
    L1=L0=V0cosβ(continuity of tangential component) (A.2)
    Figure 8. 

    List of the symbols

    .
    Figure 9. 

    The simulations of shock polars

    .

    Furthermore, Bernoulli's law for steady flows holds across a shock front:

    12V20+c20γ1=12V21+c21γ1=12V2m. (A.3)

    Also, we have the Prandtl relation for the polytropic gases.

    N0N1=c2pμ2L20, (A.4)

    where μ2=γ1γ+1. cp=μVm is the critical speed. In the present case, we consider steady and irrotational flows. The flow is everywhere isentropic behind the shock front. Thus, the maximum speed Vm is the same throughout the flow field. [8,CH6.B]

    By (A.1) and (A.2), the angle β satisfies

    sinβ=1V0V20L21.

    It thus follows from (A.3) and (A.4) that

    N1=c2pμ2L21V0sinβ=c2pμ2L21V20L21.

    In the spherical coordinates, the radial and normal components of the flow velocity V are denoted by Vr and Vθ respectively. That is, N1=|Vθ| and L1=|Vr|. We then obtain the equation of the shock polar:

    |Vθ|=c2pμ2V2rV20V2r.

    By using the non-dimensional velocity, U0=V0/Vm, Ur=Vr/Vm and Uθ=Vθ/Vm, we have the following equation

    U2θ=μ4(1U2r)2U20U2r. (A.5)

    Hence, for a given speed U0, the possible 1-states (Uθ,Ur) satisfy the following equation:

    Uθ=μ2(1U2r)U20U2r. (A.6)

    And for the 1-state (Uθ,Ur), β can be calculated by

    tanβ=U20U2rUr. (A.7)

    For the present problem, the incoming flow is supersonic with the given density ρ0 and the velocity V0, i.e., V0>c0. Then, the flow continues as a conical flow with constant entropy after crossing the shock. Density and pressure rise across the shock front. Thus, |V0|>|V1|. We note that at the 0 state,

    N20=μ2(V2mL20),V20=N20+L20.

    Hence at the 0 state,

    U2θ=[1U20]μ2/(1μ2),U2r=[U20μ2]/(1μ2).

    And U0[μ,1]. In the following figure, we choose γ=1.4. The circle denotes the 0 state. The thick line branch is all the possible 1 states for which |V0|>|V1|.

    Since Vm is determined by (A.3)

    12V20+c20γ1=12V2m,

    it follows that

    U202+U20(γ1)(V0/c0)2=12.

    The relationship between the Mach number M=V/c and the non-dimensional speed |U| is as follows

    |U|=[1+2(γ1)M2]1/2. (A.8)

    When U0=0.8, M0 is around 3.

    Remark 5. For the present problem, Uθ(1,0] and Ur(0,γ1γ+1]. γ>1 is given. Considering equation (A.5), we can regard Uθ as a function depending on Ur. By careful calculations, if U0>γγ+1, then Uθ increases as Ur increases.

    Remark 6. At the shock angle β, we need to request A(β)>0 for the ODE system (2.13). By Lemma 2.1 and (A.5), it is equivalent to the following condition:

    U20>(γ1γ+1)+U2r(2γ+1). (A.9)

    The authors would like to thank Prof. M-H. Chen for his helpful discussions. Lien is supported in part by MOST Grant 107-2115-M-006-012. Liu is supported in part by MOST Grant 107-2115-M-006-017.



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