This article reports the survey findings of a pilot study on primary students' views, attitudes, self-concept, identity, and experiences toward STEM education. This survey was held in China Shandong Province. Applying a mixed-method approach, we administered the survey to 332 students and interviewed 8 students to learn about their views about STEM education after the activity. The survey data was analyzed using Rasch on five constructs, namely views, attitudes, self-concept, identity, and experiences in STEM learning. The transcribed interviews were analyzed using emergent coding. The findings showed that students generally responded positively to the five constructs. Students thought that problem-solving was essential, but it was still difficult for them to solve a real-world problem. They agreed that joining STEM activities could enhance their interest in STEM jobs, but they still had less confidence in pursuing a STEM job. The findings provide some insights into a pilot STEM curriculum work in a province and open up possibilities for broadening and deepening knowledge about STEM teaching and learning in China, which is at its nascent stages.
Citation: Feiyue Wang, Tang Wee Teo, Shoubao Gao. China primary school students' STEM views, attitudes, self-concept, identity and experiences: A pilot study in Shandong province[J]. STEM Education, 2024, 4(4): 381-420. doi: 10.3934/steme.2024022
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This article reports the survey findings of a pilot study on primary students' views, attitudes, self-concept, identity, and experiences toward STEM education. This survey was held in China Shandong Province. Applying a mixed-method approach, we administered the survey to 332 students and interviewed 8 students to learn about their views about STEM education after the activity. The survey data was analyzed using Rasch on five constructs, namely views, attitudes, self-concept, identity, and experiences in STEM learning. The transcribed interviews were analyzed using emergent coding. The findings showed that students generally responded positively to the five constructs. Students thought that problem-solving was essential, but it was still difficult for them to solve a real-world problem. They agreed that joining STEM activities could enhance their interest in STEM jobs, but they still had less confidence in pursuing a STEM job. The findings provide some insights into a pilot STEM curriculum work in a province and open up possibilities for broadening and deepening knowledge about STEM teaching and learning in China, which is at its nascent stages.
The radial addition K˜+L of star sets K and L can be defined by
ρ(K˜+L,⋅)=ρ(K,⋅)+ρ(L,⋅), |
where a star set is a compact set that is star-shaped at o and contains o and ρ(K,⋅) denotes the radial function of star set K. The radial function is defined by
ρ(K,u)=max{c≥0:cu∈K}, | (1.1) |
for u∈Sn−1, where Sn−1 denotes the surface of the unit ball centered at the origin. The initial study of the radial addition can be found in [1, p. 235]. K is called a star body if ρ(K,⋅) is positive and continuous, and let Sn denote the set of star bodies. The radial addition and volume are the basis and core of the dual Brunn-Minkowski theory (see, e.g., [2,3,4,5,6,7,8,9,10]). It is important that the dual Brunn-Minkowski theory can count among its successes the solution of the Busemann-Petty problem in [3,11,12,13,14]. Recently, it has turned to a study extending from Lp-dual Brunn-Minkowski theory to Orlicz dual Brunn-Minkowski theory. The Orlicz dual Brunn-Minkowski theory and its dual have attracted people's attention [15,16,17,18,19,20,21,22,23,24,25,26,27,28].
For K∈Sn and u∈Sn−1, the half chord of K in the direction u is defined by
d(K,u)=12(ρ(K,u)+ρ(K,−u)). |
If there exists a constant λ>0 such that d(K,u)=λd(L,u), for all u∈Sn−1, then star bodies K,L are said to have similar chord (see Gardner [1] or Schneider [29]). Lu [30] introduced the i-th chord integral of star bodies: For K∈Sn and 0≤i<n, the i-th chord integral of K, is denoted by Bi(K), is defined by
Bi(K)=1n∫Sn−1d(K,u)n−idS(u). | (1.2) |
Obviously, for i=0, Bi(K) becomes the chord integral B(K).
The main aim of the present article is to generalize the chord integrals to Orlicz space. We introduce a new affine geometric quantity which we shall call Orlicz mixed chord integrals. The fundamental notions and conclusions of the chord integral and related isoperimetric inequalities for the chord integral are extended to an Orlicz setting. The new inequalities in special cases yield the Lp-dual Minkowski and Lp-dual Brunn-Minkowski inequalities for the Lp-mixed chord integrals. The related concepts and inequalities of Lp-mixed chord integrals are derived. As extensions, Orlicz multiple mixed chord integrals and Orlicz-Aleksandrov-Fenchel inequality for the Orlicz multiple mixed chord integrals are also derived.
In Section 3, we introduce the following new notion of Orlicz chord addition of star bodies.
Orlicz chord addition Let K and L be star bodies, the Orlicz chord addition of K and L, is denoted by Kˇ+ϕL, is defined by
ϕ(d(K,u)d(Kˇ+ϕL,u),d(L,u)d(Kˇ+ϕL,u))=1, | (1.3) |
where u∈Sn−1, and ϕ∈Φ2, which is the set of convex functions ϕ:[0,∞)2→(0,∞) that are decreasing in each variable and satisfy ϕ(0,0)=∞ and ϕ(∞,1)=ϕ(1,∞)=1.
The particular instance of interest corresponds to using (1.3) with ϕ(x1,x2)=ϕ1(x1)+εϕ2(x2) for ε>0 and some ϕ1,ϕ2∈Φ, which are the sets of convex functions ϕ1,ϕ2:[0,∞)→(0,∞) that are decreasing and satisfy ϕ1(0)=ϕ2(0)=∞, ϕ1(∞)=ϕ2(∞)=0 and ϕ1(1)=ϕ2(1)=1.
In accordance with the spirit of Aleksandrov [31], Fenchel and Jessen's [32] introduction of mixed quermassintegrals, and introduction of Lutwak's [33] Lp-mixed quermassintegrals, we are based on the study of first-order variations of the chord integrals. In Section 4, we prove that the first order Orlicz variation of the mixed chord integral can be expressed as: For K,L∈Sn, ϕ1,ϕ2∈Φ, 0≤i<n and ε>0,
ddε|ε=0+Bi(Kˇ+ϕε⋅L)=(n−i)⋅1(ϕ1)′r(1)⋅Bϕ2,i(K,L), | (1.4) |
where (ϕ1)′r(1) denotes the value of the right derivative of convex function ϕ1 at point 1. In this first order variational equation (1.4), we find a new geometric quantity. Based on this, we extract the required geometric quantity, denoted by Bϕ,i(K,L) which we shall call Orlicz mixed chord integrals of K and L, as follows
Bϕ2,i(K,L)=1n−i⋅(ϕ1)′r(1)⋅ddε|ε=0+Bi(Kˇ+ϕε⋅L). | (1.5) |
We show also that the new affine geometric quantity has an integral representation as follows:
Bϕ,i(K,L)=1n∫Sn−1ϕ(d(L,u)d(K,u))d(K,u)n−idS(u). | (1.6) |
When ϕ(t)=t−p and p≥1, the new affine geometric quantity becomes a new Lp-mixed chord integrals of K and L, denoted by Bp,i(K,L), which as is in (2.7).
In Section 5, we establish an Orlicz Minkowski inequality for the mixed chord and Orlicz mixed chord integrals.
Orlicz Minkowski inequality for the Orlicz mixed chord integrals If K,L∈Sn, 0≤i<n and ϕ∈Φ, then
Bϕ,i(K,L)≥Bi(K)⋅ϕ((Bi(L)Bi(K))1/(n−i)). | (1.7) |
If ϕ is strictly convex, the equality holds if and only if K and L are similar chord.
When ϕ(t)=t−p and p≥1, (1.7) becomes a new Lp-Minkowski inequality (2.8) for the Lp-mixed chord integrals.
In Section 6, as an application, we establish an Orlicz Brunn-Minkowski inequality for the Orlicz chord additions and the mixed chord integrals:
Orlicz Brunn-Minkowski inequality for the Orlicz chord additions If K,L∈Sn, 0≤i<n and ϕ∈Φ2, then
1≥ϕ((Bi(K)Bi(Kˇ+ϕL))1/(n−i),(Bi(L)Bi(Kˇ+ϕL))1/(n−i)). | (1.8) |
If ϕ is strictly convex, the equality holds if and only if K and L are similar chord.
When ϕ(t)=t−p and p≥1, (1.8) becomes a new Lp-Brunn-Minkowski inequality (2.9) for the mixed chord integrals.
A new isoperimetric inequality for the chord integrals is given in Section 7. In Section 8, Orlicz multiple mixed chord integrals is introduced and Orlicz-Aleksandrov-Fenchel inequality for the Orlicz multiple mixed chord integrals is established.
The setting for this paper is n-dimensional Euclidean space Rn. A body in Rn is a compact set equal to the closure of its interior. For a compact set K⊂Rn, we write V(K) for the (n-dimensional) Lebesgue measure of K and call this the volume of K. Associated with a compact subset K of Rn which is star-shaped with respect to the origin and contains the origin, its radial function is ρ(K,⋅):Sn−1→[0,∞) is defined by
ρ(K,u)=max{λ≥0:λu∈K}. |
Note that the class (star sets) is closed under union, intersection, and intersection with subspace. The radial function is homogeneous of degree −1, that is (see e.g. [1]),
ρ(K,ru)=r−1ρ(K,u), |
for all u∈Sn−1 and r>0. Let ˜δ denote the radial Hausdorff metric, as follows: if K,L∈Sn, then
˜δ(K,L)=|ρ(K,u)−ρ(L,u)|∞. |
From the definition of the radial function, it follows immediately that for A∈GL(n) the radial function of the image AK={Ay:y∈K} of K is given by (see e.g. [29])
ρ(AK,x)=ρ(K,A−1x), | (2.1) |
for all x∈Rn.
For Ki∈Sn,i=1,…,m, define the real numbers RKi and rKi by
RKi=maxu∈Sn−1d(Ki,u),andrKi=minu∈Sn−1d(Ki,u). | (2.2) |
Obviously, 0<rKi<RKi, for all Ki∈Sn. Writing R=max{RKi} and r=min{rKi}, where i=1,…,m.
If K1,…,Kn∈Sn, the mixed chord integral of K1,…,Kn, is denoted by B(K1,…,Kn), is defined by (see [30])
B(K1,…,Kn)=1n∫Sn−1d(K1,u)⋯d(Kn,u)dS(u). |
If K1=⋯=Kn−i=K, Kn−i+1=⋯=Kn=L, the mixed chord integral B(K1,…,Kn) is written as Bi(K,L). If L=B (B is the unit ball centered at the origin), the mixed chord integral Bi(K,L)=Bi(K,B) is written as Bi(K) and called the i-th chord integral of K. Obviously, For K∈Sn and 0≤i<n, we have
Bi(K)=1n∫Sn−1d(K,u)n−idS(u). | (2.3) |
If K1=⋯=Kn−i−1=K, Kn−i=⋯=Kn−1=B and Kn=L, the mixed chord integral B(K,…,K⏟n−i−1,B,…,B⏟i,L) is written as Bi(K,L) and called the i-th mixed chord integral of K and L. For K,L∈Sn and 0≤i<n, it is easy to see that
Bi(K,L)=1n∫Sn−1d(K,u)n−i−1d(L,u)dS(u). | (2.4) |
This integral representation (2.4), together with the Hölder inequality, immediately give the Minkowski inequality for the i-th mixed chord integral: If K,L∈Sn and 0≤i<n, then
Bi(K,L)n−i≤Bi(K)n−i−1Bi(L), | (2.5) |
with equality if and only if K and L are similar chord.
Definition 2.1 (The Lp-chord addition) Let K,L∈Sn and p≥1, the Lp chord addition ˇ+p of star bodies K and L, is defined by
d(Kˇ+pL,u)−p=d(K,u)−p+d(L,u)−p, | (2.6) |
for u∈Sn−1.
Obviously, putting ϕ(x1,x2)=x−p1+x−p2 and p≥1 in (1.3), (1.3) becomes (2.6). The following result follows immediately from (2.6) with p≥1.
−npn−ilimε→0+Bi(Kˇ+pε⋅L)−Bi(L)ε=1n∫Sn−1d(K,u)n−i+pd(L,u)−pdS(u). |
Definition 2.2 (The Lp-mixed chord integrals) Let K,L∈Sn, 0≤i<n and p≥1, the Lp-mixed chord integral of star K and L, denoted by Bp,i(K,L), is defined by
Bp,i(K,L)=1n∫Sn−1d(K,u)n−i+pd(L,u)−pdS(u). | (2.7) |
Obviously, when K=L, the Lp-mixed chord integral Bp,i(K,K) becomes the i-th chord integral Bi(K). This integral representation (2.7), together with the Hölder inequality, immediately gives:
Proposition 2.3 If K,L∈Sn, 0≤i<n and p≥1, then
Bp,i(K,L)n−i≥Bi(K)n−i+pBi(L)−p, | (2.8) |
with equality if and only if K and L are similar chord.
Proposition 2.4 If K,L∈Sn, 0≤i<n and p≥1, then
Bi(Kˇ+pL)−p/(n−i)≥Bi(K)−p/(n−i)+Bi(L)−p/(n−i), | (2.9) |
with equality if and only if K and L are similar chord.
Proof From (2.6) and (2.7), it is easily seen that the Lp-chord integrals is linear with respect to the Lp-chord addition, and together with inequality (2.8), we have for p≥1
Bp,i(Q,Kˇ+pL)=Bp,i(Q,K)+Bp,i(Q,L)≥Bi(Q)(n−i+p)/(n−i)(Bi(K)−p/(n−i)+Bi(L)−p/(n−i)), |
with equality if and only if K and L are similar chord.
Take Kˇ+pL for Q, recall that Bp,i(Q,Q)=Bi(Q), inequality (2.9) follows easily.
Throughout this paper, the standard orthonormal basis for Rn will be {e1,…,en}. Let Φn, n∈N, denote the set of convex functions ϕ:[0,∞)n→(0,∞) that are strictly decreasing in each variable and satisfy ϕ(0)=∞ and ϕ(ej)=1, j=1,…,n. When n=1, we shall write Φ instead of Φ1. The left derivative and right derivative of a real-valued function f are denoted by (f)′l and (f)′r, respectively. We first define the Orlicz chord addition.
Definition 3.1 (The Orlicz chord addition) Let m≥2,ϕ∈Φm, Kj∈Sn and j=1,…,m, the Orlicz chord addition of K1,…,Km, is denoted by ˇ+ϕ(K1,…,Km), is defined by
d(ˇ+ϕ(K1,…,Km),u)=sup{λ>0:ϕ(d(K1,u)λ,…,d(Km,u)λ)≤1}, | (3.1) |
for u∈Sn−1. Equivalently, the Orlicz chord addition ˇ+ϕ(K1,…,Km) can be defined implicitly by
ϕ(d(K1,u)d(ˇ+ϕ(K1,…,Km),u),…,d(Km,u)d(ˇ+ϕ(K1,…,Km),u))=1, | (3.2) |
for all u∈Sn−1.
An important special case is obtained when
ϕ(x1,…,xm)=m∑j=1ϕj(xj), |
for some fixed ϕj∈Φ such that ϕ1(1)=⋯=ϕm(1)=1. We then write ˇ+ϕ(K1,…,Km)=K1ˇ+ϕ⋯ˇ+ϕKm. This means that K1ˇ+ϕ⋯ˇ+ϕKm is defined either by
d(K1ˇ+ϕ⋯ˇ+ϕKm,u)=sup{λ>0:m∑j=1ϕj(d(Kj,u)λ)≤1}, | (3.3) |
for all u∈Sn−1, or by the corresponding special case of (3.2).
Lemma 3.2 The Orlicz chord addition ˇ+ϕ:(Sn)m→Sn is monotonic.
Proof This follows immediately from (3.1).
Lemma 3.3 The Orlicz chord addition ˇ+ϕ:(Sn)m→Sn is GL(n) covariant.
Proof From (2.1), (3.1) and let A∈GL(n), we obtain
d(ˇ+ϕ(AK1,AK2…,AKm),u) |
=sup{λ>0:ϕ(d(AK1,u)λ,d(AK2,u)λ,…,d(AKm,u)λ)≤1}=sup{λ>0:ϕ(d(K1,A−1u)λ,d(K2,A−1u)λ,…,d(Km,A−1u)λ)≤1}=d(ˇ+ϕ(K1,…,Km),A−1u)=d(ˇ+ϕ(K1,…,Km),u). |
This shows Orlicz chord addition ˇ+ϕ is GL(n) covariant.
Lemma 3.4 Suppose K1,…,Km∈Sn. If ϕ∈Φ, then
ϕ(d(K1,u)t)+⋯+ϕ(d(Km,u)t)=1 |
if and only if
d(ˇ+ϕ(K1,…,Km),u)=t |
Proof This follows immediately from Definition 3.1.
Lemma 3.5 Suppose Km,…,Km∈Sn. If ϕ∈Φ, then
rϕ−1(1m)≤d(ˇ+ϕ(K1,…,Km),u)≤Rϕ−1(1m). |
Proof Suppose d(ˇ+ϕ(K1,…,Km),u)=t, from Lemma 3.4 and noting that ϕ is strictly deceasing on (0,∞), we have
1=ϕ(d(K1,u)t)+⋯+ϕ(d(Km,u)t)≤ϕ(rK1t)+⋯+ϕ(rKmt)=mϕ(rt). |
Noting that the inverse ϕ−1 is strictly deceasing on (0,∞), we obtain the lower bound for d(ˇ+ϕ(K1,…,Km),u):
t≥rϕ−1(1m). |
To obtain the upper estimate, observe the fact from the Lemma 3.4, together with the convexity and the fact ϕ is strictly deceasing on (0,∞), we have
1=ϕ(d(K1,u)t)+⋯+ϕ(d(Km,u)t)≥mϕ(d(K1,u)+⋯+d(Km,u)mt)≥mϕ(Rt). |
Then we obtain the upper estimate:
t≤Rϕ−1(1m). |
Lemma 3.6 The Orlicz chord addition ˇ+ϕ:(Sn)m→Sn is continuous.
Proof To see this, indeed, let Kij∈Sn, i∈N∪{0}, j=1,…,m, be such that Kij→K0j as i→∞. Let
d(ˇ+ϕ(Ki1,…,Kim),u)=ti. |
Then Lemma 3.5 shows
rijϕ−1(1m)≤ti≤Rijϕ−1(1m), |
where rij=min{rKij} and Rij=max{RKij}. Since Kij→K0j, we have RKij→RK0j<∞ and rKij→rK0j>0, and thus there exist a,b such that 0<a≤ti≤b<∞ for all i. To show that the bounded sequence {ti} converges to d(ˇ+ϕ(K01,…,K0m),u), we show that every convergent subsequence of {ti} converges to d(ˇ+ϕ(K01,…,K0m),u). Denote any subsequence of {ti} by {ti} as well, and suppose that for this subsequence, we have
ti→t∗. |
Obviously a≤t∗≤b. Noting that ϕ is a continuous function, we obtain
t∗→sup{t∗>0:ϕ(d(K01,u)t∗,…,d(K0m,u)t∗)≤1} |
=d(ˇ+ϕ(K01,…,K0m),u). |
Hence
d(ˇ+ϕ(Ki1,…,Kim),u)→d(ˇ+ϕ(K01,…,K0m),u) |
as i→∞.
This shows that the Orlicz chord addition ˇ+ϕ:(Sn)m→Sn is continuous.
Next, we define the Orlicz chord linear combination for the case m=2.
Definition 3.7 (The Orlicz chord linear combination) The Orlicz chord linear combination, denoted by ˇ+ϕ(K,L,α,β) for K,L∈Sn, and α,β≥0 (not both zero), is defined by
α⋅ϕ1(d(K,u)d(ˇ+ϕ(K,L,α,β),u))+β⋅ϕ2(d(L,u)d(ˇ+ϕ(K,L,α,β),u))=1, | (3.4) |
for ϕ1,ϕ2∈Φ and all u∈Sn−1.
We shall write Kˇ+ϕε⋅L instead of ˇ+ϕ(K,L,1,ε), for ε≥0 and assume throughout that this is defined by (3.1), if α=1,β=ε and ϕ∈Φ. We shall write Kˇ+ϕL instead of ˇ+ϕ(K,L,1,1) and call it the Orlicz chord addition of K and L.
In order to define Orlicz mixed chord integrals, we need the following Lemmas 4.1-4.4.
Lemma 4.1 Let ϕ∈Φ and ε>0. If K,L∈Sn, then Kˇ+ϕε⋅L∈Sn.
Proof Let u0∈Sn−1, and {ui}⊂Sn−1 be any subsequence such that ui→u0 as i→∞.
Let
d(Kˇ+ϕL,ui)=λi. |
Then Lemma 3.5 shows
rϕ−1(12)≤λi≤Rϕ−1(12), |
where R=max{RK,RL} and r=min{rK,rL}.
Since K,L∈Sn, we have 0<rK≤RK<∞ and 0<rL≤RL<∞, and thus there exist a,b such that 0<a≤λi≤b<∞ for all i. To show that the bounded sequence {λi} converges to d(Kˇ+ϕε⋅L,u0), we show that every convergent subsequence of {λi} converges to d(Kˇ+ϕε⋅L,u0). Denote any subsequence of {λi} by {λi} as well, and suppose that for this subsequence, we have
λi→λ0. |
Obviously a≤λ0≤b. From (3.4) and note that ϕ1,ϕ2 are continuous functions, so ϕ−11 is continuous, we obtain
λi→d(K,u0)ϕ−11(1−εϕ2(d(L,u0)λ0)) |
as i→∞. Hence
ϕ1(d(K,u0)λ0)+εϕ2(d(L,u0)λ0)=1. |
Therefore
λ0=d(Kˇ+ϕε⋅L,u0). |
That is
d(Kˇ+ϕε⋅L,ui)→d(Kˇ+ϕε⋅L,u0). |
as i→∞.
This shows that Kˇ+ϕε⋅L∈Sn.
Lemma 4.2 If K,L∈Sn, ε>0 and ϕ∈Φ, then
Kˇ+ϕε⋅L→K | (4.1) |
as ε→0+.
Proof This follows immediately from (3.4).
Lemma 4.3 If K,L∈Sn, 0≤i<n and ϕ1,ϕ2∈Φ, then
ddε|ε=0+d(Kˇ+ϕε⋅L,u)n−i=n−i(ϕ1)′r(1)⋅ϕ2(d(L,u)d(K,u))⋅d(K,u)n−i. | (4.2) |
Proof From (3.4), Lemma 4.2 and notice that ϕ−11, ϕ2 are continuous functions, we obtain for 0≤i<n
ddε|ε=0+d(Kˇ+ϕε⋅L,u)n−i |
=limε→0+(n−i)d(K,u)n−i−1(d(K,u)ϕ2(d(L,u)d(Kˇ+ϕε⋅L,u)))×limy→1−ϕ−11(y)−ϕ−11(1)y−1=n−i(ϕ1)′r(1)⋅ϕ2(d(L,u)d(K,u))⋅d(K,u)n−i, |
where
y=1−εϕ2(d(L,u)d(Kˇ+ϕε⋅L,u)), |
and note that y→1− as ε→0+.
Lemma 4.4 If ϕ∈Φ2, 0≤i<n and K,L∈Sn, then
(ϕ1)′r(1)n−i⋅ddε|ε=0+Bi(Kˇ+ϕε⋅L)=1n∫Sn−1ϕ2(d(L,u)d(K,u))⋅d(K,u)n−idS(u). | (4.3) |
Proof This follows immediately from (2.1) and Lemma 4.3.
Denoting by Bϕ,i(K,L), for any ϕ∈Φ and 0≤i<n, the integral on the right-hand side of (4.3) with ϕ2 replaced by ϕ, we see that either side of the equation (4.3) is equal to Bϕ2,i(K,L) and hence this new Orlicz mixed chord integrals Bϕ,i(K,L) has been born.
Definition 4.5 (The Orlicz mixed chord integral) For ϕ∈Φ and 0≤i<n, Orlicz mixed chord integral of star bodies K and L, Bϕ,i(K,L), is defined by
Bϕ,i(K,L)=:1n∫Sn−1ϕ(d(L,u)d(K,u))⋅d(K,u)n−idS(u). | (4.4) |
Lemma 4.6 If ϕ1,ϕ2∈Φ, 0≤i<n and K,L∈Sn, then
Bϕ2,i(K,L)=(ϕ1)′r(1)n−ilimε→0+Bi(Kˇ+ϕε⋅L)−Bi(K)ε. | (4.5) |
Proof This follows immediately from Lemma 4.4 and (4.4).
Lemma 4.7 If K,L∈Sn, ϕ∈Φ and any A∈SL(n), then for ε>0
A(Kˇ+ϕε⋅L)=(AK)ˇ+ϕε⋅(AL). | (4.6) |
Proof This follows immediately from (2.1) and (3.3).
We find easily that Bϕ,i(K,L) is invariant under simultaneous unimodular centro-affine transformation.
Lemma 4.8 If ϕ∈Φ, 0≤i<n and K,L∈Sn, then for A∈SL(n),
Bϕ,i(AK,AL)=Bϕ,i(K,L). | (4.7) |
Proof This follows immediately from Lemmas 4.6 and 4.7.
In this section, we will define a Borel measure in Sn−1, denoted by Bn,i(K,υ), which we shall call the chord measure of star body K.
Definition 5.1 (The chord measure) Let K∈Sn and 0≤i<n, the chord measure of star body K, denoted by Bn,i(K,υ), is defined by
dBn,i(K,υ)=1n⋅d(K,υ)n−iBi(K)dS(υ). | (5.1) |
Lemma 5.2 (Jensen's inequality) Let μ be a probability measure on a space X and g:X→I⊂R be a μ-integrable function, where I is a possibly infinite interval. If ψ:I→R is a convex function, then
∫Xψ(g(x))dμ(x)≥ψ(∫Xg(x)dμ(x)). | (5.2) |
If ψ is strictly convex, the equality holds if and only if g(x) is constant for μ-almost all x∈X (see [34, p. 165]).
Lemma 5.3 Suppose that ϕ:[0,∞)→(0,∞) is decreasing and convex with ϕ(0)=∞. If K,L∈Sn and 0≤i<n, then
1nBi(K)∫Sn−1ϕ(d(L,u)d(K,u))d(K,u)n−idS(u)≥ϕ((Bi(L)Bi(K))1/(n−i)). | (5.3) |
If ϕ is strictly convex, the equality holds if and only if K and L are similar chord.
Proof For K∈Sn−1, 0≤i<n and any u∈Sn−1, the chord measure d(K,u)n−inBi(K)dS(u) is a probability measure on Sn−1. Hence, from (2.4), (2.5), (5.1) and by using Jensen's inequality, and in view of ϕ is decreasing, we obtain
1nBi(K)∫Sn−1ϕ(d(L,u)d(K,u))d(K,u)n−idS(u) |
=∫Sn−1ϕ(d(L,u)d(K,u))dBn,i(K,u)≥ϕ(Bi(K,L)Bi(K))≥ϕ((Bi(L)Bi(K))1/(n−i)). |
Next, we discuss the equality in (5.3). If ϕ is strictly convex, suppose the equality holds in (5.3), form the equality necessary conditions of Jensen's inequality and (2.5), it follows that d(L,u)/d(K,u) is constant, and K and L are similar chord, respectively. This yields that there exists r>0 such that d(L,u)=rd(K,u), for all u∈Sn−1. On the other hand, suppose that K and L are similar chord, i.e. there exists λ>0 such that d(L,u)=λd(K,u) for all u∈Sn−1. Hence
1nBi(K)∫Sn−1ϕ(d(L,u)d(K,u))d(K,u)n−idS(u) |
=1nBi(K)∫Sn−1ϕ((Bi(L)Bi(K))1/(n−i))d(K,u)n−idS(u)=ϕ((Bi(L)Bi(K))1/(n−i)). |
This implies the equality in (5.3) holds.
Theorem 5.4 (Orlicz chord Minkowski inequality) If K,L∈Sn, 0≤i<n and ϕ∈Φ, then
Bϕ,i(K,L)≥Bi(K)⋅ϕ((Bi(L)Bi(K))1/(n−i)). | (5.4) |
If ϕ is strictly convex, the equality holds if and only if K and L are similar chord.
Proof This follows immediately from (4.4) and Lemma 5.3.
Corollary 5.5 If K,L∈Sn, 0≤i<n and p≥1, then
Bp,i(K,L)n−i≥Bi(K)n−i+pBi(L)−p, | (5.5) |
with equality if and only if K and L are similar chord.
Proof This follows immediately from Theorem 5.4 with ϕ1(t)=ϕ2(t)=t−p and p≥1.
Taking i=0 in (5.5), this yields Lp-Minkowski inequality: If K,L∈Sn and p≥1, then
Bp(K,L)n≥B(K)n+pB(L)−p, |
with equality if and only if K and L are similar chord.
Corollary 5.6 Let K,L∈M⊂Sn, 0≤i<n and ϕ∈Φ, and if either
Bϕ,i(Q,K)=Bϕ,i(Q,L),forallQ∈M | (5.6) |
or
Bϕ,i(K,Q)Bi(K)=Bϕ,i(L,Q)Bi(L),forallQ∈M, | (5.7) |
then K=L.
Proof Suppose (5.6) holds. Taking K for Q, then from (2.3), (4.4) and (5.3), we obtain
Bi(K)=Bϕ,i(K,L)≥Bi(K)ϕ((Bi(L)Bi(K))1/(n−i)) |
with equality if and only if K and L are similar chord. Hence
Bi(K)≤Bi(L), |
with equality if and only if K and L are similar chord. On the other hand, if taking L for Q, by similar arguments, we get Bi(K)≥Bi(L), with equality if and only if K and L are similar chord. Hence Bi(K)=Bi(L), and K and L are similar chord, it follows that K and L must be equal.
Suppose (5.7) holds. Taking L for Q, then from from (2.3), (4.4) and (5.3), we obtain
1=Bϕ,i(K,L)Bi(K)≥ϕ((Bi(L)Bi(K))1/(n−i)), |
with equality if and only if K and L are similar chord. Hence
Bi(K)≤Bi(L), |
with equality if and only if K and L are similar chord. On the other hand, if taking K for Q, by similar arguments, we get Bi(K)≥Bi(L), with equality if and only if K and L are similar chord. Hence Bi(K)=Bi(L), and K and L have similar chord, it follows that K and L must be equal.
When ϕ1(t)=ϕ2(t)=t−p and p≥1, Corollary 5.6 becomes the following result.
Corollary 5.7 Let K,L∈M⊂Sn, 0≤i<n and p≥1, and if either
Bp,i(K,Q)=Bp,i(L,Q),forallQ∈M |
or
Bp,i(K,Q)Bi(K)=Bp,i(L,Q)Bi(L),forallQ∈M, |
then K=L.
Lemma 6.1 If K,L∈Sn, 0≤i<n, and ϕ1,ϕ2∈Φ, then
Bi(Kˇ+ϕL)=Bϕ1,i(Kˇ+ϕL,K)+Bϕ2,i(Kˇ+ϕL,L). | (6.1) |
Proof From (3.1), (3.4) and (4.4), we have for Kˇ+ϕL=Q∈Sn
Bϕ1,i(Q,K)+Bϕ2,i(Q,L) |
=1n∫Sn−1ϕ(d(K,u)d(Q,u),d(L,u)d(Q,u))d(Q,u)n−idS(u) |
=Bi(Q). | (6.2) |
The completes the proof.
Lemma 6.2 Let K,L∈Sn, ε>0 and ϕ∈Φ.
(1) If K and L are similar chord, then K and Kˇ+ϕε⋅L are similar chord.
(2) If K and Kˇ+ϕε⋅L are similar chord, then K and L are similar chord.
Proof Suppose exist a constant λ>0 such that d(L,u)=λd(K,u), we have
ϕ(d(K,u)d(Kˇ+ϕε⋅L,u))+εϕ(λd(K,u)d(Kˇ+ϕε⋅L,u))=1. |
On the other hand, the exist unique constant δ>0 such that
ϕ(d(K,u)d(δK,u))+εϕ(λd(K,u)d(δK,u))=1, |
where δ satisfies that
ϕ(1δ)+εϕ(λδ)=1. |
This shows that d(Kˇ+ϕε⋅L,u)=δd(K,u).
Suppose exist a constant λ>0 such that d(Kˇ+ϕε⋅L,u)=λd(K,u). Then
ϕ(1λ)+εϕ(d(L,u)d(Kˇ+ϕε⋅L,u))=1. |
This shows that
d(L,u)d(Kˇ+ϕε⋅L,u) |
is a constant. This yields that Kˇ+ϕε⋅L and L are similar chord. Namely K and L are similar chord.
Theorem 6.3 (Orlicz chord Brunn-Minkowski inequality) If K,L∈Sn, 0≤i<n and ϕ∈Φ2, then
1≥ϕ((Bi(K)Bi(Kˇ+ϕL))1/(n−i),(Bi(L)Bi(Kˇ+ϕL))1/(n−i)). | (6.3) |
If ϕ is strictly convex, the equality holds if and only if K and L are similar chord.
Proof From (5.4) and Lemma 6.1, we have
Bi(Kˇ+ϕL)=Bϕ1,i(Kˇ+ϕL,K)+Bϕ2,i(Kˇ+ϕL,L)≥Bi(Kˇ+ϕL)(ϕ1((Bi(K)Bi(Kˇ+ϕL))1/(n−i))+ϕ2((Bi(L)kBi(Kˇ+ϕL))1/(n−i)))=Bi(Kˇ+ϕL)ϕ((Bi(K)Bi(Kˇ+ϕL))1/(n−i),(Bi(L)Bi(Kˇ+ϕL))1/(n−i)). |
This is just inequality (6.3). From the equality condition of (5.4) and Lemma 6.3, it yields that if ϕ is strictly convex, equality in (6.3) holds if and only if K and L are similar chord.
Corollary 6.4 If K,L∈Sn, 0≤i<n and p≥1, then
Bi(Kˇ+pL)−p/(n−i)≥Bi(K)−p/(n−i)+Bi(L)−p/(n−i), | (6.4) |
with equality if and only if K and L are similar chord.
Proof This follows immediately from Theorem 6.2 with ϕ(x1,x2)=x−p1+x−p2 and p≥1.
Taking i=0 in (6.4), this yields the Lp-Brunn-Minkowski inequality for the chord integrals. If K,L∈Sn and p≥1, then
B(Kˇ+pL)−p/n≥B(K)−p/n+B(L)−p/n, |
with equality if and only if K and L are similar chord.
As a application, in the section, we give a new isoperimetric inequality for chord integrals. As we all know, the isoperimetric inequality for convex bodies can be stated below (see e.g. [26], p. 318).
The isoperimetric inequality If K is convex body in Rn, then
(V(K)V(B))n−1≤(S(K)S(B))n, | (7.1) |
with equality if and only if K is an n-ball.
Here B is the unit ball centered at the origin, V(K) denotes the volume of K and S(K) is the surface area of K, defined by (see [26], p. 318)
S(K)=limε→0V(K+εB)−V(K)ε=nV1(K,B), |
where + the usual Minkowski sum. Here, the mixed volume of convex bodies K and L, V1(K,L), defined by (see e.g. [1])
V1(K,L)=1n∫Sn−1h(L,u)dS(K,u). | (7.2) |
Next, we give some new isoperimetric inequalities for mixed chord integrals by using the Orlicz chord Minkowski inequality established in Section 5.
Theorem 7.1 (The Lp-isoperimetric inequality for mixed chord integrals) If K∈Sn, 0≤i<n and p≥1, then
(˜Bp,i(K)S(B))n−i≥(Bi(K)V(B))n−i+p, | (7.3) |
with equality if and only if K is an n-ball, where ˜Bp,i(K)=nBp,i(K,B).
Proof Putting L=B, ϕ(t)=t−p and p≥1 in Orlicz chord Minkowski inequality (5.4)
Bp,i(K,B)Bi(K)≥(Bi(B)Bi(K))−p/(n−i). |
That is
(Bp,i(K,B)Bi(K))n−i≥(Bi(K)V(B))p. |
Hence
(nBp,i(K,B)S(B))n−i≥(Bi(K)V(B))n−i+p. |
From the equality of (5.4), we find that the equality in (7.3) holds if and only if K and B are similar chord. This yields that the equality in (7.3) holds if and only if K is an n-ball.
Theorem 7.2 (The isoperimetric inequality for the chord integrals) If K∈Sn, then
(˜B(K)S(B))n≥(B(K)V(B))n+1, | (7.4) |
with equality if and only if K is an n-ball, where ˜B(K)=nB1(K,B).
Proof This follows immediately from (7.3) with p=1 and i=0.
This is just a similar form of the classical isoperimetric inequality (7.1).
As extensions, in the Section, the Orlicz mixed chord integral of K and L, Bϕ(K,L), is generalized into Orlicz multiple mixed chord integral of (n+1) star bodies L1,K1,…,Kn. Further, we generalize the Orlicz-Minklowski inequality into Orlicz-Aleksandrov-Fenchel inequality for the Orlicz multiple mixed chord integrals.
Theorem 8.1 If L1,K1,…,Kn∈Sn and ϕ1,ϕ2∈Φ, then
ddε|ε=0+B(L1ˇ+ϕε⋅K1,K2,⋯,Kn)=1n(ϕ1)′r(1) |
×∫Sn−1ϕ2(d(K1,u)d(L1,u))d(L1,u)d(K2,u)⋯d(Kn,u)dS(u). | (8.1) |
Proof This may yield by using a generalized idea and method of proving Lemma 4.4. Here, we omit the details.
Obviously, (4.3) is a special case of (8.1). Moreover, from Theorem 8.1, we can find the following definition:
Definition 8.2 (Orlicz multiple mixed chord integrals) Let L1,K1,…,Kn∈Sn and ϕ∈Φ, the Orlicz multiple mixed chord integral of (n+1) star bodies L1,K1,…,Kn, is denoted by Bϕ(L1,K1,…,Kn), is defined by
Bϕ(L1,K1,…,Kn)=1n∫Sn−1ϕ(d(K1,u)d(L1,u))d(L1,u)d(K2,u)⋯d(Kn,u)dS(u). | (8.2) |
When L1=K1, Bϕ(L1,K1,…,Kn) becomes the well-known mixed chord integral B(K1,…,Kn). Obviously, for 0≤i<n, Bϕ,i(K,L) is also a special case of Bϕ(L1,K1,…,Kn).
Corollary 8.3 If L1,K1,…,Kn∈Sn and ϕ1,ϕ2∈Φ, then
Bϕ2(L1,K1,…,Kn)=(ϕ1)′r(1)⋅ddε|ε=0B(L1+ϕε⋅K1,K2,…,Kn). | (8.3) |
Proof This yields immediately from (8.1) and (8.2).
Similar to the proof of Theorem 5.4, we may establish an Orlicz-Aleksandrov-Fenchel inequality as follows:
Theorem 8.4 (Orlicz-Aleksandrov-Fenchel inequality for the Orlicz multiple mixed chord integrals) If L1,K1,…,Kn∈Sn, ϕ∈Φ and 1≤r≤n, then
Bϕ(L1,K1,K2,⋯,Kn)≥B(L1,K2,⋯,Kn)⋅ϕ(r∏i=1B(Ki…,Ki,Kr+1,…,Kn)1rB(L1,K2…,Kn)). | (8.4) |
If ϕ is strictly convex, equality holds if and only if L1,K1,…,Kr are all of similar chord.
Proof This yields immediately by using a generalized idea and method of proving Theorem 5.4. Here, we omit the details.
Obviously, the Orlicz-Minklowski inequality (5.4) is a special case of the Orlicz-Aleksandrov-Fenchel inequality (8.4). Moreover, when L1=K1, (8.4) becomes the following Aleksandrov-Fenchel inequality for the mixed chords.
Corollary 8.5 (Aleksandrov-Fenchel inequality for the mixed chord integrals) If K1,…,Kn∈Sn and 1≤r≤n, then
B(K1,⋯,Kn)≤r∏i=1B(Ki…,Ki,Kr+1,…,Kn)1r. | (8.5) |
with equality if and only if K1,…,Kr are all of similar chord.
Finally, it is worth mentioning: when ϕ(t)=t−p and p≥1, Bϕ(L1,K1,…,Kn) written as Bp(L1,K1,…,Kn) and call it Lp-multiple mixed chord integrals of (n+1) star bodies L1,K1,…,Kn. So, the new concept of Lp-multiple mixed chord integrals and Lp-Aleksandrov-Fenchel inequality for the Lp-multiple mixed chord integrals may be also derived. Here, we omit the details of all derivations.
Research is supported by National Natural Science Foundation of China (11371334, 10971205).
The author declares that no conflicts of interest in this paper.
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