
Topological indices are widely used to analyze and predict the physicochemical properties of compounds, and have good application prospects. Recently, the Euler Sombor index was introduced, which is defined as
EP(G)=∑vivj∈E(G)√d(vi)2+d(vj)2+d(vi)d(vj).
As the latest index with geometry motivation, it has excellent discrimination and predictive ability for compounds, in addition to mathematical practicality. The unicyclic graphs and bicyclic graphs are composed of various chemical structures, and are of particular importance in the study of topological indices. In this paper, the maximal and minimal values of Euler Sombor index for all unicyclic and bicyclic graphs are determined, and the corresponding extremal graphs are characterized.
Citation: Zhenhua Su, Zikai Tang. Extremal unicyclic and bicyclic graphs of the Euler Sombor index[J]. AIMS Mathematics, 2025, 10(3): 6338-6354. doi: 10.3934/math.2025289
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Topological indices are widely used to analyze and predict the physicochemical properties of compounds, and have good application prospects. Recently, the Euler Sombor index was introduced, which is defined as
EP(G)=∑vivj∈E(G)√d(vi)2+d(vj)2+d(vi)d(vj).
As the latest index with geometry motivation, it has excellent discrimination and predictive ability for compounds, in addition to mathematical practicality. The unicyclic graphs and bicyclic graphs are composed of various chemical structures, and are of particular importance in the study of topological indices. In this paper, the maximal and minimal values of Euler Sombor index for all unicyclic and bicyclic graphs are determined, and the corresponding extremal graphs are characterized.
As an important class of molecular descriptors, topological indices play a crucial role in mathematical chemistry as well as in graph theory. They have been applied to the physico-chemical properties, biological activity, and many other aspects of compounds [1,2]. Among these topological indices, the vertex-degree-based (VDB) indices are undoubtedly the most widely investigated, and have new chemical and pharmacological applications, see [3,4,5]. In recent years, some new VDB indices with geometric interpretations have been discovered.
In 2021, the Sombor index was introduced by Gutman [5], defined as
SO(G)=∑vivj∈E(G)√d(vi)2+d(vj)2. |
This is the first topological index with geometric significance, which has attracted a lot of attention. Many results have been gained in recent papers, such as the extremal values of the Sombor index for trees and any connected graph G [5], the extremal value of this index among all molecular trees [6], the correlation between this index and Zagreb index [7], and the upper and lower bounds of this index for unicyclic graphs as well as the extremal value of chemical unicyclic graphs with given girth [8]. Furthermore, a few new indices with geometric significance, such as the elliptic Sombor index [9], KG-Sombor index [10], etc. have been introduced. For more results on these indices, readers are referred to the review papers [11,12,13].
Recently, Gutman [14] and Tang et al. [15] proposed another index with geometric significance, defined as
EP(G)=∑vivj∈E(G)√d(vi)2+d(vj)2+d(vi)d(vj). |
Due to its origin from an approximate expression of the perimeter of the ellipse, which was given by Euler in 1773, it is named the Euler Sombor index.
As the latest VDB index with geometric significance, the Euler Sombor index has irreplaceable importance. Formally an approximate expression of the perimeter for the ellipse, Gutman [14] determined some actual relations between the Euler Sombor index and Sombor index, and it can be used to estimate the Sombor index.
In [15], Tang, Li, and Deng fitted the boiling point (bp) and concentricity factor (AcenFac) with the Euler Sombor index of octane isomers, and showed that it has strong discriminability for compounds and is very effective in predicting physical and chemical properties. They also determined the extremal values for the Euler Sombor index among all (molecular) trees and characterized the corresponding extremal graphs.
Unicyclic graphs and bicyclic graphs are two important classic graphs in the study of topological indices, which are composed of various chemical structures. Cruz and Rada [16] attained the minimal values of (chemical) unicyclic and bicyclic graphs for the Sombor index and obtained an upper bound on the Sombor index of unicyclic and bicyclic graphs, but did not characterize the extremal graphs. In the same paper, they mentioned that the maximal graphs over the set of unicyclic and bicyclic graphs with respect to Sombor index is an interesting open problem. Very recently, Das completely solved these open problems in [17].
Inspired by these, we mainly study maximal and minimal values for the Euler Sombor index over all unicyclic and bicyclic graphs, and characterize corresponding extremum graphs. In Section 2, we present that Cn and Bi(n,1)(i=2,3), see Figure 1, are the only unicyclic and bicyclic graphs with the minimal value of EP(G), respectively. Moreover, we obtain that S′n is the unique unicyclic graph with the maximal value of EP(G) in Section 3, and also determine that C′n,4 is the only bicyclic graph with maximal value of EP(G) in Section 4, where n≥28.
All graphs considered are simple and connected. Let G=(V(G),E(G)) be a graph with its vertex set V(G) and edge set E(G). The degree of a vertex vi is denoted by dG(vi) or d(vi). In particular, the maximal degree and the second maximal degree will be denoted by Δ and Δ2, respectively. A vertex vi is said to be pendant if d(vi)=1. Similarly, an edge {vivj} is called pendant if d(vi)=1 or d(vj)=1. The neighbors of vertex vi, denoted by NG(vi) or N(vi), are the set of vertices adjacent to vi. For notations and terminology not mentioned, see [18].
Recall that a k-cyclic graph G with |V(G)|=n vertices is a connected graph with |E(G)|=n+k−1 edges. We denote by Gn,k the set of k-cyclic graphs G with n vertices. In particular, Gn,1 is the set of unicyclic graphs, while Gn,2 is the set of bicyclic graphs. Let C′n,4 be the graph obtained by attaching (n−4) pendant edges to a vertex of degree three in K4−e, and S′n the graph obtained from the star Sn by adding an edge. For convenience, an edge {vivj} in G with (d(vi),d(vj))=(x,y) (joining a vertex of degree x with a vertex of degree y) is called (x,y)-type, and mx,y=mx,y(G) is the number of edges with (x,y)-type in G.
Let Pn={(x,y)∈N×N:1≤x≤y≤n−1}−{(1,1),(2,2),(2,3),(3,2),(3,3)} and Pn,k={(x,y)∈Pn:x+y≤n+k}.
Lemma 2.1. Let
g(x,y)=√x2+y2+xy+(18√3−6√19)x+yxy+(4√19−15√3). |
Then g(2,2)<0, g(2,3)=g(3,2)=g(3,3)=0, and g(x,y)>0 for (x,y)∈Pn.
Proof. We can easily to check g(2,2)<0, and g(2,3)=g(3,2)=g(3,3)=0. Note that
g(x,y)=√x2+y2+xy+(18√3−6√19)x+yxy+(4√19−15√3)>√x2+y2+xy+(4√19−15√3)=g1(x,y). |
For 5≤x≤y, immediately, g(x,y)>g1(5,5)=√75+4√19−15√3>0.11>0. For 1≤x≤4 and y≥8, we have g(x,y)>g(1,8)>g1(5,5)>0. Eventually, for 1≤x≤4 and 2≤y≤7, one can easily check that g(x,y)>0 by tedious algebraic calculations.
Lemma 2.2. Let G∈Gn,k and k∈{1,2}. Then
EP(G)=(2√19−3√3)n−(4√19−15√3)(k−1)+g(2,2)m2,2+∑(x,y)∈Pn,kg(x,y)mx,y, |
where g(x,y) is defined as in Lemma 2.1.
Proof. For G∈Gn,k, it was proved in [16] that
m2,3=2(n+2−2k)−2m2,2+∑(x,y)∈Pn,k(4−6x+yxy)mx,y,m3,3=5k−n−5+m2,2+∑(x,y)∈Pn,k(5−6x+yxy)mx,y. |
Substituting the above equations into EP(G), it yields
EP(G)=√19m2,3+3√3m3,3+2√3m2,2+∑(x,y)∈Pn,k√x2+y2+xymx,y=(2√19−3√3)n−(4√19−15√3)(k−1)+g(2,2)m2,2+∑(x,y)∈Pn,k[√x2+y2+xy+(18√3−6√19)x+yxy−(15√3−4√19)]mx,y=(2√19−3√3)n−(4√19−15√3)(k−1)+g(2,2)m2,2+∑(x,y)∈Pn,kg(x,y)mx,y. |
This completes the proof.
Theorem 2.3. Let G∈Gn,1. Then,
EP(G)≥2√3n, |
with equality if and only if G≅Cn.
Proof. First, by Lemma 2.2 and k=1, we have
EP(G)=(2√19−3√3)n+(5√3−2√19)m2,2+∑(x,y)∈Pn,1g(x,y)mx,y. |
Using Lemma 2.1, one can easily obtain that g(x,y)>0 for all (x,y)∈Pn,1, and 5√3−2√19=g(2,2)<−0.05<0. Moreover, m2,2≤n by G∈Gn,1, and
EP(G)≥(2√19−3√3)n+(5√3−2√19)n=2√3n, |
with equality if and only if Pn,1=∅ and m2,2=n, i.e., G≅Cn.
The three bicyclic graphs B1, B2, and B3 with n vertices are depicted in Figure 1, where two vertices of degree 3 in B2 and B3 are adjacent. One can easily obtain that
EP(B1)=2√3n+8√7−6√3,EP(B2)=EP(B3)=2√3n+4√19−5√3. |
Theorem 2.4. Let G∈Gn,2. Then,
EP(G)≥2√3n+4√19−5√3, |
with equality if and only if G≅B2 or G≅B3.
Proof. Since G∈Gn,2, we have m2,2≤n−3, and the only graph with m2,2=n−3 is the graph B1(n). Furthermore, one can check that EP(B1)>EP(B2)=EP(B3), and hence, we consider only the graphs with m2,2≤n−4.
By Lemma 2.2 and k=2, we have
EP(G)=(2√19−3√3)n−(4√19−15√3)+(5√3−2√19)m2,2+∑(x,y)∈Pn,2g(x,y)mx,y. |
On the other hand, Lemma 2.1 implies that g(2,2)=5√3−2√19<−0.05<0, and g(x,y)>0 for (x,y)∈Pn,2. With m2,2≤n−4, we obtain
EP(G)≥(2√19−3√3)n−(4√19−15√3)+(5√3−2√19)(n−4)=2√3n+4√19−5√3, |
with equality if and only if Pn,2=∅ and m2,2=n−4, i.e., G≅B2 or G≅B3.
In the remainder of this paper, we assume f(x,y)=√x2+y2+xy with x,y≥1. Let vi,vj∈V(G). Then
EP(G)=∑vivj∈E(G)√d(vi)2+d(vj)2+d(vi)d(vj)=∑vivj∈E(G)f(d(vi),d(vj)). |
In this section, we use Un,k to represent the set of unicyclic graphs with order n and girth k.
Lemma 3.1. Let f(x,y)=√x2+y2+xy with x,y≥1, and x≥y. Then, f(x,y)≤(2−√3)x+(√3−1)(x+y).
Proof. It can be concluded that
(x+(√3−1)y)2=x2+2(√3−1)xy+(√3−1)2y2=x2+(2√3−3)xy+xy+(4−2√3)y2≥x2+(2√3−3)y2+xy+(4−2√3)y2=x2+y2+xy. |
So, f(x,y)≤x+(√3−1)y=(2−√3)x+(√3−1)(x+y).
Lemma 3.2. Let G∈Un,k, k≥3, G≇Cn, and vi≠vj∈V(G).
(1) If G∈Un,3, then Δ(G)≤n−1 and d(vi)+d(vj)≤n+1.
(2) If G∈Un,4, then Δ(G)≤n−2 and d(vi)+d(vj)≤n.
(3) If G∈Un,k(k≥5), then Δ(G)≤n−3 and d(vi)+d(vj)≤n−1.
Proof. G∈Un,k implies that |V(G)|=|E(G)|=n. There are at least (k−2) edges not incident with the vertex of degree Δ. Hence, Δ(G)≤n−k+2. By the condition Cn≇G∈Un,k, E(G)=E(Ck)∪{e1,e2,⋯,en−k}, where e1,e2,⋯,en−k are edges not on the cycle Ck. If all e1,e2,⋯,en−k are incident with at most two vertices on Ck, then we obtain that d(vi)+d(vj)=n−k+4. Otherwise, d(vi)+d(vj)≤n−k+3. Therefore, (1)–(3) of this lemma hold.
Lemma 3.3. Let G∈Un,3 and G≇Cn. Then EP(G)≤EP(S′n) with equality if and only if G≅S′n.
Proof. From Lemma 3.2(1), we have Δ(G)≤n−1 and d(vi)+d(vj)≤n+1 for any vi≠vj∈V(G).
If Δ=n−1, then G≅S′n and
EP(S′n)=∑vivj∈E(G)f(d(vi),d(vj))=(n−3)f(n−1,1)+2f(n−1,2)+f(2,2)=(n−3)√n2−n+1+2√n2+3+√12. |
If Δ=n−2, then G≅F1,1 or G≅F2 (see Figure 2) since G contains a cycle C3, and we can easily obtain
EP(F1,1)=∑vivj∈E(G)f(d(vi),d(vj))=(n−4)f(n−2,1)+f(n−2,3)+f(n−2,2)+f(3,2)+f(3,1)<(n−3)f(n−1,1)+2f(n−1,2)+f(2,2)=EP(S′n).EP(F2)=(n−5)f(n−2,1)+3f(n−2,2)+f(2,2)+f(2,1)<(n−3)f(n−1,1)+2f(n−1,2)+f(2,2)=EP(S′n). |
If Δ≤n−3, we assume that there is a graph G∈Un,3 with EP(G)≥EP(S′n). Then the following claims will hold.
Claim 1. Δ≥n−8 and there exists vi≠vj∈V(G) with d(vi)+d(vj)=n+1 for n−8≤Δ≤n−6.
Proof. Otherwise, Δ≤n−9. From Lemma 3.1, we have
f(d(vi),d(vj))≤(2−√3)Δ+(√3−1)(d(vi)+d(vj))≤(2−√3)(n−9)+(√3−1)(n+1)<(n−32). |
Using this result, we can deduce that
EP(G)=∑vivj∈E(G)f(d(vi),d(vj))<n(n−32)<(n−3)(n−12)+2n<(n−3)√n2−n+1+2√n2+3+√12=EP(S′n), |
a contradiction to EP(G)≥EP(S′n). So, Δ≥n−8.
Next, we will prove the rest of the claim. Otherwise, let n−8≤Δ≤n−6 and d(vi)+d(vj)≤n for all vi≠vj∈V(G). Then,
f(d(vi),d(vj))≤(2−√3)Δ+(√3−1)(d(vi)+d(vj))≤(2−√3)(n−6)+(√3−1)n<(n−32), |
and
EP(G)=∑vivj∈E(G)f(d(vi),d(vj))<n(n−32)<(n−3)(n−12)+2n<EP(S′n), |
a contradiction to EP(G)≥EP(S′n). Claim 1 is proved.
Claim 2. If n−5≤Δ≤n−3, then there exist two vertices vi≠vj∈V(G) such that d(vi)+d(vj)=n+1 or n. In particular, if there are two vertices vi≠vj∈V(G) such that d(vi)+d(vj)=n, then G has no (1,2)-type or (2,2)-type edge.
Proof. Otherwise, d(vi)+d(vj)≤n−1 for any vi≠vj∈V(G). We have
f(d(vi),d(vj))≤(2−√3)Δ+(√3−1)(d(vi)+d(vj))≤(2−√3)(n−3)+(√3−1)(n−1)<(n−32), |
and
EP(G)<n(n−32)<(n−3)(n−12)+2n<EP(S′n), |
a contradiction to EP(G)≥EP(S′n).
In the following, we will show that G has no (1,2)-type or (2,2)-type edge if there are two vertices vi≠vj∈V(G) such that d(vi)+d(vj)=n. Otherwise, there is an edge vkvl∈E(G) such that f(d(vk),d(vl))≤√12. By Lemma 3.1,
f(d(vi),d(vj))≤(2−√3)Δ+(√3−1)(d(vi)+d(vj))≤(2−√3)(n−3)+(√3−1)n<(n−12). |
Consequently, we obtain
EP(G)<(n−1)(n−12)+√12<EP(S′n), |
a contradiction to EP(G)≥EP(S′n).
Based on Claims 1 and 2, we have the following in two cases.
Case 1. n−8≤Δ≤n−3. Then, there exists two vertices vi≠vj∈V(G) such that d(vi)+d(vj)=n+1.
If Δ=n−3, then G≅F1,2, where n≥7. Similarly, it can be concluded that G≅F1,1+k if Δ=n−(3+k), where 1≤k≤5 and n≥7+2k. Consequently, G≅F1,i (shown in Figure 2), where 2≤i≤7. We deduce that
EP(F1,2)=∑vivj∈E(G)f(d(vi),d(vj))=(n−5)f(n−3,1)+f(n−3,4)+f(n−3,2)+2f(4,1)+f(4,2)<(n−3)f(n−1,1)+2f(n−1,2)+f(2,2)=EP(S′n).EP(F1,3)=(n−6)f(n−4,1)+f(n−4,5)+f(n−4,2)+3f(5,1)+f(5,2)<(n−3)f(n−1,1)+2f(n−1,2)+f(2,2)=EP(S′n).EP(F1,4)=(n−7)f(n−5,1)+f(n−5,6)+f(n−5,2)+4f(6,1)+f(6,2)<(n−3)f(n−1,1)+2f(n−1,2)+f(2,2)=EP(S′n).EP(F1,5)=(n−8)f(n−6,1)+f(n−6,7)+f(n−6,2)+5f(7,1)+f(7,2)<(n−3)f(n−1,1)+2f(n−1,2)+f(2,2)=EP(S′n).EP(F1,6)=(n−9)f(n−7,1)+f(n−7,8)+f(n−7,2)+6f(8,1)+f(8,2)<(n−3)f(n−1,1)+2f(n−1,2)+f(2,2)=EP(S′n).EP(F1,7)=(n−10)f(n−8,1)+f(n−8,9)+f(n−8,2)+7f(9,1)+f(9,2)<(n−3)f(n−1,1)+2f(n−1,2)+f(2,2)=EP(S′n). |
Case 2. n−5≤Δ≤n−3. Then, there exist two vertices vi≠vj∈V(G) such that d(vi)+d(vj)=n, and there is no edge with (1,2)-type or (2,2)-type.
If Δ=n−3, then G≅F3, where n≥6. Similarly, if Δ=n−4 or Δ=n−5, then G≅F4 or G≅F5, where n≥8 and n≥10, see Figure 3. We obtain
EP(F3)=∑vivj∈E(G)f(d(vi),d(vj))=(n−5)f(n−3,1)+2f(n−3,3)+f(3,3)+2f(3,1)<(n−3)f(n−1,1)+2f(n−1,2)+f(2,2)=EP(S′n).EP(F4)=(n−6)f(n−4,1)+f(n−4,3)+f(n−4,3)+f(4,3)+2f(4,1)+f(3,1)<(n−3)f(n−1,1)+2f(n−1,2)+f(2,2)=EP(S′n). |
EP(F5)=(n−7)f(n−5,1)+f(n−5,5)+f(n−5,3)+f(5,3)+3f(5,1)+f(3,1)<(n−3)f(n−1,1)+2f(n−1,2)+f(2,2)=EP(S′n). |
Therefore, together with Cases 1 and 2, Lemma 3.3 is done.
Lemma 3.4. Let G∈Un,4 and G≇Cn. Then EP(G)<EP(S′n).
Proof. By Lemma 3.2(2), Δ≤n−2, and d(vi)+d(vj)≤n for vi≠vj∈V(G). We will prove the lemma by contradiction, and assume there exists a graph G∈Un,4 such that EP(G)≥EP(S′n). We give the following claims at first.
Claim 1. There is no edge with (1,2)-type and (2,2)-type.
Proof. Otherwise, there exists an edge e=vkvl such that f(d(vk),d(vl))≤f(2,2)=√12. By Lemma 3.1, we have
f(d(vi),d(vj))≤(2−√3)Δ+(√3−1)(x+y)≤(2−√3)(n−2)+(√3−1)n<(n−12). |
And
EP(G)=∑vivj∈E(G)f(d(vi),d(vj))<(n−1)(n−12)+√12<(n−3)√n2−n+1+2√n2+3+√12=EP(S′n). |
So, Claim 1 is done.
Claim 2. n−5≤Δ≤n−2 and there exists two vertices vi and vj in G with d(vi)+d(vj)=n.
Proof. Otherwise, Δ≤n−6. From Lemma 3.1, we have
f(d(vi),d(vj))≤(2−√3)Δ+(√3−1)(d(vi)+d(vj))≤(2−√3)(n−6)+(√3−1)n<(n−32), |
and
EP(G)<n(n−32)<(n−3)(n−12)+2n<EP(S′n), |
a contradiction. Consequently, n−5≤Δ≤n−2.
Next, we will prove there exists two vertices vi≠vj∈V(G) such that d(vi)+d(vj)=n.
If Δ=n−2, then G≅H1,0, as shown in Figure 4, and there exists two vertices vi and vj such that d(vi)+d(vj)=n.
If n−5≤Δ≤n−3, and d(vi)+d(vj)≤n−1 for any vertices vi≠vj∈V(G), then we have
f(d(vi),d(vj))≤(2−√3)Δ+(√3−1)(d(vi)+d(vj))≤(2−√3)(n−3)+(√3−1)(n−1)<(n−32), |
and
EP(G)<n(n−32)<(n−3)(n−12)+2n<EP(S′n), |
a contradiction. Claim 2 is proved.
Now, we consider the following cases according to Claims 1 and 2.
If Δ=n−2, then G≅H1,0, and this graph contains edges of (2,2)-type, which contradicts with Claim 1.
If Δ=n−3, there exists vi≠vj∈V(G) with d(vi)+d(vj)=n, and there is no edge with (2,2)-type. Then G≅H1,1, see Figure 4.
If Δ=n−4 or Δ=n−5, then we have only G≅H1,2 or G≅H1,3, as shown in Figure 4.
Therefore, we deduce that
EP(H1,1)=(n−5)f(n−2,1)+2f(n−2,2)+2f(3,2)+f(3,1)<(n−3)√n2−n+1+2√n2+3+√12=EP(S′n).EP(H1,2)=(n−6)f(n−3,1)+2f(n−3,2)+2f(4,2)+f(4,1)<(n−3)√n2−n+1+2√n2+3+√12=EP(S′n).EP(H1,3)=(n−7)f(n−5,1)+2f(n−5,2)+2f(5,2)+f(5,1)<(n−3)√n2−n+1+2√n2+3+√12=EP(S′n). |
So, the assumption is not true, and this completes the proof.
Theorem 3.5. Let G∈Gn,1, n≥4. Then,
EP(G)≤(n−3)√n2−n+1+2√n2+3+√12, |
with equality if and only if G≅S′n.
Proof. If G≅Cn, then
EP(G)=√12n<(n−3)√n2−n+1+2√n2+3+√12=EP(S′n), |
and the theorem holds.
Next, let G∈Un,k and G≇Cn.
Using Lemmas 3.3 and 3.4, the theorem holds for G∈Un,3 and G∈Un,4, especially, with equality if G≅S′n. Otherwise, G∈Un,k and k≥5. Lemma 3.2 implies that Δ≤n−3, and d(vi)+d(vj)≤n−1 for vi,vj∈G. With Lemma 3.1, we deduce that
f(d(vi),d(vj))≤(2−√3)Δ+(√3−1)(d(vi)+d(vj))≤(2−√3)(n−3)+(√3−1)(n−1)<(n−32), |
and
EP(G)<n(n−32)<(n−3)(n−12)+2n<EP(S′n). |
In this section, we establish the upper bound of EP(G) for bicyclic graphs, as well as characterize the extremal graph, where n≥28.
Theorem 4.1. Let G∈Gn,2, n≥28. Then,
EP(G)≤(n−4)√n2−n+1+2√n2+3+√n2+n+7+2√19, |
with equality if and only if G≅C′n,4.
Proof. Let vi≠vj∈V(G). We divide into the following three cases.
Case 1. 3≤Δ≤n−13.
For 3≤Δ≤14, we have
f(d(vi),d(vj))≤Δ√3≤14√3<24.3. |
With n≥28, we deduce that
EP(G)<24.3(n+1)<(n−4)(n−12)+2n+(n+12)+2√19<(n−4)√n2−n+1+2√n2+3+√n2+n+7+2√19=EP(C′n,4). |
For 15≤Δ≤n−13, we assume that d(vi)≥d(vj). Because G is a bicyclic graph, d(vi)+d(vj)≤n+2. Let g(x)=x2−(n+2)x+(n+2)2. Then, g(x) is monotonically decreasing for x∈[15,n+22], and monotonically increasing for x∈[n+22,n−13]. Therefore,
f(d(vi),d(vj))≤√d(vi)2+(n+2−d(vi))2+d(vi)(n+2−d(vi))=√max{g(15),g(n−13)}≤√g(n−13)=√n2−11n+199. | (4.1) |
If n≥32, then √n2−11n+199<√n2−5n+254=(n−52), and
EP(G)<24.3(n+1)<(n+1)(n−52)<(n−4)√n2−n+1+2√n2+3+√n2+n+7+2√19=EP(C′n,4). |
If 28≤n≤31, then we can also conclude that EP(G)<EP(C′n,4) by (4.1), and the detailed results see Table 1.
orders n | Upper bounds of (n+1)√n2−11n+199 | EP(C′n,4) |
28 | 753.443 | 753.772 |
29 | 805.543 | 809.264 |
30 | 859.656 | 866.758 |
31 | 921.911 | 926.253 |
Case 2. n−12≤Δ≤n−3.
Recall that Δ2 is the second maximal degree in G. Since G∈Gn,2, Δ+Δ2≤n+2. Next, we will consider two subcases.
Subcase 2.1. Δ2=n+2−Δ.
In this case, G≅G1,n−1−Δ, as shown in Figure 5. Consequently,
EP(G)=(Δ−3)f(Δ,1)+2f(Δ,2)+f(Δ,Δ2)+(Δ2−3)f(Δ2,1)+2f(Δ2,2)=(Δ−3)f(Δ,1)+2f(Δ,2)+f(Δ,n+2−Δ)+(n−1−Δ)f(n+2−Δ,1)+2f(n+2−Δ,2). | (4.2) |
For n−12≤Δ≤n−3, we have the following relations:
f(Δ,1)<f(Δ,2)≤f(n−3,2)<f(n−1,1),f(n+2−Δ,1)<f(n+2−Δ,2)≤f(14,2)<f(n−1,1),f(Δ,n+2−Δ)≤f(n−3,5)<f(n−1,1). |
Together with (4.2), we have
EP(G)<(n−3)f(n−1,1)+2f(14,2)+2f(14,1)<(n−4)√n2−n+1+2√n2+3+√n2+n+7+2√19(n≥28)=EP(C′n,4). |
Subcase 2.2. Δ2≤n+1−Δ.
For any vi≠vj∈V(G), d(vi)+d(vj)≤n+1. If n−12≤Δ≤n−9, then
f(d(vi),d(vj))≤√d(vi)2−(n+1)d(vi)+(n+1)2≤√(n−9)2−(n+1)(n−9)+(n+1)2<(n−52)(n≥28). |
In this case, we obtain
EP(G)≤(n+1)(n−52)<(n−4)(n−12)+2n+(n+12)+2√19<EP(C′n,4). |
If n−8≤Δ≤n−3, then we deduce that
EP(G)=∑{vivj}∈E(G)f(d(vi),d(vj))≤Δ√Δ2+Δ22+ΔΔ2+Δ2√3Δ22. | (4.3) |
Furthermore, we have the relations
√Δ2+Δ22+ΔΔ2≤√(n−3)2−(n+1)(n−3)+(n+1)2=√n2−2n+13<(n−12), |
and
√3Δ22≤√3(n+1−Δ)≤√3(n+1−n+8)=9√3, |
Thus, the Eq (4.3) yields that
EP(G)≤(n−12)Δ+9√3Δ2=(n−12)Δ+9√3(n+1−Δ)=(n−9√3−12)Δ+9√3(n+1)<n2−3.4n+64<n2−32n+11.2(n≥28)<(n−4)√n2−n+1+2√n2+3+√n2+n+7+2√19=EP(C′n,4). |
Case 3. n−2≤Δ≤n−1.
Subcase 3.1. Δ=n−2.
One can easily check that Δ2≤4. If Δ2=4, then we deduce that G≅G1,1, shown in Figure 5. Recall that n≥28. We obtain
EP(G)<(n−5)√(n−2)2+1+(n−2)+2√(n−2)2+4+2(n−2)+√(n−2)2+16+4(n−2)+2√28+√21<(n−4)√n2−n+1+2√n2+3+√n2+n+7+2√19=EP(C′n,4). |
Next, we assume Δ2=3. In this case, G≅G3 or G≅G4 (see Figure 6). Since n≥28, we have an immediate consequence by calculation:
EP(G3)=(n−5)√(n−2)2+1+(n−2)+2√(n−2)2+9+3(n−2)+√(n−2)2+4+2(n−2)+√27+√19+√13<(n−4)√n2−n+1+2√n2+3+√n2+n+7+2√19=EP(C′n,4).EP(G4)=(n−6)√(n−2)2+1+(n−2)+3√(n−2)2+4+2(n−2)+2√19+√27+√7<(n−4)√n2−n+1+2√n2+3+√n2+n+7+2√19=EP(C′n,4). |
Otherwise, Δ2≤2, we deduce that
EP(G)≤(n−2)√(n−2)2+4+2(n−2)+3√12<(n−4)√n2−n+1+2√n2+3+√n2+n+7+2√19=EP(C′n,4). |
Subcase 3.2. Δ=n−1.
If G≅C′n,4, then
EP(G)=EP(C′n,4)=(n−4)√n2−n+1+2√n2+3+√n2+n+7+2√19. |
Otherwise, G≅G2, where G2 is shown in Figure 5. Noting that √n2−n+1+√n2+n+7≥2√n2+3, we have
EP(G2)=(n−5)√n2−n+1+4√n2+3+2√12<(n−4)√n2−n+1+2√n2+3+√n2+n+7+2√19=EP(C′n,4), |
and the theorem is proved.
Topological indices are commonly molecular structure descriptors that can be used to simulate and predict the physical, chemical, and biological properties of compounds, and they promoted the development of applied disciplines such as chemistry and pharmacology. Recently, the Euler Sombor index derived from geometry, has been shown to have excellent discriminability for compounds and has therefore received much attention.
In this paper, we present Cn, and Bi(n,1)(i=2,3) are the only graphs with the minimum Euler Sombor index among all unicyclic and bicyclic graphs, respectively. Moreover, we completely obtain that S′n is the unique unicyclic graph with the maximum value of EP(G), and also determine that C′n,4 is the only bicyclic graph with maximal value of EP(G), where n≥28. The extremal values of the Euler Sombor index among multi-cyclic graphs, as well as its chemical applications in compounds, may be the research interests of mathematics and chemistry in the future.
Zhenhua Su: Writing-original draft preparation, Writing-review and editing; Zikai Tang: Formal analysis, Methodology. All authors have read and agreed to the published version of the manuscript.
The authors declare they have not used Artificial Intelligence (AI) tools in the creation of this article.
The authors would like to thank the anonymous reviewers for their helpful comments.
This work was supported by Hunan Province Natural Science Foundation (2025JJ70485).
The authors declare no conflict of interest.
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orders n | Upper bounds of (n+1)√n2−11n+199 | EP(C′n,4) |
28 | 753.443 | 753.772 |
29 | 805.543 | 809.264 |
30 | 859.656 | 866.758 |
31 | 921.911 | 926.253 |