Research article

Extremal unicyclic and bicyclic graphs of the Euler Sombor index

  • Received: 25 November 2024 Revised: 27 February 2025 Accepted: 06 March 2025 Published: 21 March 2025
  • MSC : 05C05, 05C09, 05C92

  • Topological indices are widely used to analyze and predict the physicochemical properties of compounds, and have good application prospects. Recently, the Euler Sombor index was introduced, which is defined as

    EP(G)=vivjE(G)d(vi)2+d(vj)2+d(vi)d(vj).

    As the latest index with geometry motivation, it has excellent discrimination and predictive ability for compounds, in addition to mathematical practicality. The unicyclic graphs and bicyclic graphs are composed of various chemical structures, and are of particular importance in the study of topological indices. In this paper, the maximal and minimal values of Euler Sombor index for all unicyclic and bicyclic graphs are determined, and the corresponding extremal graphs are characterized.

    Citation: Zhenhua Su, Zikai Tang. Extremal unicyclic and bicyclic graphs of the Euler Sombor index[J]. AIMS Mathematics, 2025, 10(3): 6338-6354. doi: 10.3934/math.2025289

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  • Topological indices are widely used to analyze and predict the physicochemical properties of compounds, and have good application prospects. Recently, the Euler Sombor index was introduced, which is defined as

    EP(G)=vivjE(G)d(vi)2+d(vj)2+d(vi)d(vj).

    As the latest index with geometry motivation, it has excellent discrimination and predictive ability for compounds, in addition to mathematical practicality. The unicyclic graphs and bicyclic graphs are composed of various chemical structures, and are of particular importance in the study of topological indices. In this paper, the maximal and minimal values of Euler Sombor index for all unicyclic and bicyclic graphs are determined, and the corresponding extremal graphs are characterized.



    As an important class of molecular descriptors, topological indices play a crucial role in mathematical chemistry as well as in graph theory. They have been applied to the physico-chemical properties, biological activity, and many other aspects of compounds [1,2]. Among these topological indices, the vertex-degree-based (VDB) indices are undoubtedly the most widely investigated, and have new chemical and pharmacological applications, see [3,4,5]. In recent years, some new VDB indices with geometric interpretations have been discovered.

    In 2021, the Sombor index was introduced by Gutman [5], defined as

    SO(G)=vivjE(G)d(vi)2+d(vj)2.

    This is the first topological index with geometric significance, which has attracted a lot of attention. Many results have been gained in recent papers, such as the extremal values of the Sombor index for trees and any connected graph G [5], the extremal value of this index among all molecular trees [6], the correlation between this index and Zagreb index [7], and the upper and lower bounds of this index for unicyclic graphs as well as the extremal value of chemical unicyclic graphs with given girth [8]. Furthermore, a few new indices with geometric significance, such as the elliptic Sombor index [9], KG-Sombor index [10], etc. have been introduced. For more results on these indices, readers are referred to the review papers [11,12,13].

    Recently, Gutman [14] and Tang et al. [15] proposed another index with geometric significance, defined as

    EP(G)=vivjE(G)d(vi)2+d(vj)2+d(vi)d(vj).

    Due to its origin from an approximate expression of the perimeter of the ellipse, which was given by Euler in 1773, it is named the Euler Sombor index.

    As the latest VDB index with geometric significance, the Euler Sombor index has irreplaceable importance. Formally an approximate expression of the perimeter for the ellipse, Gutman [14] determined some actual relations between the Euler Sombor index and Sombor index, and it can be used to estimate the Sombor index.

    In [15], Tang, Li, and Deng fitted the boiling point (bp) and concentricity factor (AcenFac) with the Euler Sombor index of octane isomers, and showed that it has strong discriminability for compounds and is very effective in predicting physical and chemical properties. They also determined the extremal values for the Euler Sombor index among all (molecular) trees and characterized the corresponding extremal graphs.

    Unicyclic graphs and bicyclic graphs are two important classic graphs in the study of topological indices, which are composed of various chemical structures. Cruz and Rada [16] attained the minimal values of (chemical) unicyclic and bicyclic graphs for the Sombor index and obtained an upper bound on the Sombor index of unicyclic and bicyclic graphs, but did not characterize the extremal graphs. In the same paper, they mentioned that the maximal graphs over the set of unicyclic and bicyclic graphs with respect to Sombor index is an interesting open problem. Very recently, Das completely solved these open problems in [17].

    Inspired by these, we mainly study maximal and minimal values for the Euler Sombor index over all unicyclic and bicyclic graphs, and characterize corresponding extremum graphs. In Section 2, we present that Cn and Bi(n,1)(i=2,3), see Figure 1, are the only unicyclic and bicyclic graphs with the minimal value of EP(G), respectively. Moreover, we obtain that Sn is the unique unicyclic graph with the maximal value of EP(G) in Section 3, and also determine that Cn,4 is the only bicyclic graph with maximal value of EP(G) in Section 4, where n28.

    Figure 1.  Graphs B1, B2, and B3.

    All graphs considered are simple and connected. Let G=(V(G),E(G)) be a graph with its vertex set V(G) and edge set E(G). The degree of a vertex vi is denoted by dG(vi) or d(vi). In particular, the maximal degree and the second maximal degree will be denoted by Δ and Δ2, respectively. A vertex vi is said to be pendant if d(vi)=1. Similarly, an edge {vivj} is called pendant if d(vi)=1 or d(vj)=1. The neighbors of vertex vi, denoted by NG(vi) or N(vi), are the set of vertices adjacent to vi. For notations and terminology not mentioned, see [18].

    Recall that a k-cyclic graph G with |V(G)|=n vertices is a connected graph with |E(G)|=n+k1 edges. We denote by Gn,k the set of k-cyclic graphs G with n vertices. In particular, Gn,1 is the set of unicyclic graphs, while Gn,2 is the set of bicyclic graphs. Let Cn,4 be the graph obtained by attaching (n4) pendant edges to a vertex of degree three in K4e, and Sn the graph obtained from the star Sn by adding an edge. For convenience, an edge {vivj} in G with (d(vi),d(vj))=(x,y) (joining a vertex of degree x with a vertex of degree y) is called (x,y)-type, and mx,y=mx,y(G) is the number of edges with (x,y)-type in G.

    Let Pn={(x,y)N×N:1xyn1}{(1,1),(2,2),(2,3),(3,2),(3,3)} and Pn,k={(x,y)Pn:x+yn+k}.

    Lemma 2.1. Let

    g(x,y)=x2+y2+xy+(183619)x+yxy+(419153).

    Then g(2,2)<0, g(2,3)=g(3,2)=g(3,3)=0, and g(x,y)>0 for (x,y)Pn.

    Proof. We can easily to check g(2,2)<0, and g(2,3)=g(3,2)=g(3,3)=0. Note that

    g(x,y)=x2+y2+xy+(183619)x+yxy+(419153)>x2+y2+xy+(419153)=g1(x,y).

    For 5xy, immediately, g(x,y)>g1(5,5)=75+419153>0.11>0. For 1x4 and y8, we have g(x,y)>g(1,8)>g1(5,5)>0. Eventually, for 1x4 and 2y7, one can easily check that g(x,y)>0 by tedious algebraic calculations.

    Lemma 2.2. Let GGn,k and k{1,2}. Then

    EP(G)=(21933)n(419153)(k1)+g(2,2)m2,2+(x,y)Pn,kg(x,y)mx,y,

    where g(x,y) is defined as in Lemma 2.1.

    Proof. For GGn,k, it was proved in [16] that

    m2,3=2(n+22k)2m2,2+(x,y)Pn,k(46x+yxy)mx,y,m3,3=5kn5+m2,2+(x,y)Pn,k(56x+yxy)mx,y.

    Substituting the above equations into EP(G), it yields

    EP(G)=19m2,3+33m3,3+23m2,2+(x,y)Pn,kx2+y2+xymx,y=(21933)n(419153)(k1)+g(2,2)m2,2+(x,y)Pn,k[x2+y2+xy+(183619)x+yxy(153419)]mx,y=(21933)n(419153)(k1)+g(2,2)m2,2+(x,y)Pn,kg(x,y)mx,y.

    This completes the proof.

    Theorem 2.3. Let GGn,1. Then,

    EP(G)23n,

    with equality if and only if GCn.

    Proof. First, by Lemma 2.2 and k=1, we have

    EP(G)=(21933)n+(53219)m2,2+(x,y)Pn,1g(x,y)mx,y.

    Using Lemma 2.1, one can easily obtain that g(x,y)>0 for all (x,y)Pn,1, and 53219=g(2,2)<0.05<0. Moreover, m2,2n by GGn,1, and

    EP(G)(21933)n+(53219)n=23n,

    with equality if and only if Pn,1= and m2,2=n, i.e., GCn.

    The three bicyclic graphs B1, B2, and B3 with n vertices are depicted in Figure 1, where two vertices of degree 3 in B2 and B3 are adjacent. One can easily obtain that

    EP(B1)=23n+8763,EP(B2)=EP(B3)=23n+41953.

    Theorem 2.4. Let GGn,2. Then,

    EP(G)23n+41953,

    with equality if and only if GB2 or GB3.

    Proof. Since GGn,2, we have m2,2n3, and the only graph with m2,2=n3 is the graph B1(n). Furthermore, one can check that EP(B1)>EP(B2)=EP(B3), and hence, we consider only the graphs with m2,2n4.

    By Lemma 2.2 and k=2, we have

    EP(G)=(21933)n(419153)+(53219)m2,2+(x,y)Pn,2g(x,y)mx,y.

    On the other hand, Lemma 2.1 implies that g(2,2)=53219<0.05<0, and g(x,y)>0 for (x,y)Pn,2. With m2,2n4, we obtain

    EP(G)(21933)n(419153)+(53219)(n4)=23n+41953,

    with equality if and only if Pn,2= and m2,2=n4, i.e., GB2 or GB3.

    In the remainder of this paper, we assume f(x,y)=x2+y2+xy with x,y1. Let vi,vjV(G). Then

    EP(G)=vivjE(G)d(vi)2+d(vj)2+d(vi)d(vj)=vivjE(G)f(d(vi),d(vj)).

    In this section, we use Un,k to represent the set of unicyclic graphs with order n and girth k.

    Lemma 3.1. Let f(x,y)=x2+y2+xy with x,y1, and xy. Then, f(x,y)(23)x+(31)(x+y).

    Proof. It can be concluded that

    (x+(31)y)2=x2+2(31)xy+(31)2y2=x2+(233)xy+xy+(423)y2x2+(233)y2+xy+(423)y2=x2+y2+xy.

    So, f(x,y)x+(31)y=(23)x+(31)(x+y).

    Lemma 3.2. Let GUn,k, k3, GCn, and vivjV(G).

    (1) If GUn,3, then Δ(G)n1 and d(vi)+d(vj)n+1.

    (2) If GUn,4, then Δ(G)n2 and d(vi)+d(vj)n.

    (3) If GUn,k(k5), then Δ(G)n3 and d(vi)+d(vj)n1.

    Proof. GUn,k implies that |V(G)|=|E(G)|=n. There are at least (k2) edges not incident with the vertex of degree Δ. Hence, Δ(G)nk+2. By the condition CnGUn,k, E(G)=E(Ck){e1,e2,,enk}, where e1,e2,,enk are edges not on the cycle Ck. If all e1,e2,,enk are incident with at most two vertices on Ck, then we obtain that d(vi)+d(vj)=nk+4. Otherwise, d(vi)+d(vj)nk+3. Therefore, (1)–(3) of this lemma hold.

    Lemma 3.3. Let GUn,3 and GCn. Then EP(G)EP(Sn) with equality if and only if GSn.

    Proof. From Lemma 3.2(1), we have Δ(G)n1 and d(vi)+d(vj)n+1 for any vivjV(G).

    If Δ=n1, then GSn and

    EP(Sn)=vivjE(G)f(d(vi),d(vj))=(n3)f(n1,1)+2f(n1,2)+f(2,2)=(n3)n2n+1+2n2+3+12.

    If Δ=n2, then GF1,1 or GF2 (see Figure 2) since G contains a cycle C3, and we can easily obtain

    EP(F1,1)=vivjE(G)f(d(vi),d(vj))=(n4)f(n2,1)+f(n2,3)+f(n2,2)+f(3,2)+f(3,1)<(n3)f(n1,1)+2f(n1,2)+f(2,2)=EP(Sn).EP(F2)=(n5)f(n2,1)+3f(n2,2)+f(2,2)+f(2,1)<(n3)f(n1,1)+2f(n1,2)+f(2,2)=EP(Sn).
    Figure 2.  Graphs F1,i and F2.

    If Δn3, we assume that there is a graph GUn,3 with EP(G)EP(Sn). Then the following claims will hold.

    Claim 1. Δn8 and there exists vivjV(G) with d(vi)+d(vj)=n+1 for n8Δn6.

    Proof. Otherwise, Δn9. From Lemma 3.1, we have

    f(d(vi),d(vj))(23)Δ+(31)(d(vi)+d(vj))(23)(n9)+(31)(n+1)<(n32).

    Using this result, we can deduce that

    EP(G)=vivjE(G)f(d(vi),d(vj))<n(n32)<(n3)(n12)+2n<(n3)n2n+1+2n2+3+12=EP(Sn),

    a contradiction to EP(G)EP(Sn). So, Δn8.

    Next, we will prove the rest of the claim. Otherwise, let n8Δn6 and d(vi)+d(vj)n for all vivjV(G). Then,

    f(d(vi),d(vj))(23)Δ+(31)(d(vi)+d(vj))(23)(n6)+(31)n<(n32),

    and

    EP(G)=vivjE(G)f(d(vi),d(vj))<n(n32)<(n3)(n12)+2n<EP(Sn),

    a contradiction to EP(G)EP(Sn). Claim 1 is proved.

    Claim 2. If n5Δn3, then there exist two vertices vivjV(G) such that d(vi)+d(vj)=n+1 or n. In particular, if there are two vertices vivjV(G) such that d(vi)+d(vj)=n, then G has no (1,2)-type or (2,2)-type edge.

    Proof. Otherwise, d(vi)+d(vj)n1 for any vivjV(G). We have

    f(d(vi),d(vj))(23)Δ+(31)(d(vi)+d(vj))(23)(n3)+(31)(n1)<(n32),

    and

    EP(G)<n(n32)<(n3)(n12)+2n<EP(Sn),

    a contradiction to EP(G)EP(Sn).

    In the following, we will show that G has no (1,2)-type or (2,2)-type edge if there are two vertices vivjV(G) such that d(vi)+d(vj)=n. Otherwise, there is an edge vkvlE(G) such that f(d(vk),d(vl))12. By Lemma 3.1,

    f(d(vi),d(vj))(23)Δ+(31)(d(vi)+d(vj))(23)(n3)+(31)n<(n12).

    Consequently, we obtain

    EP(G)<(n1)(n12)+12<EP(Sn),

    a contradiction to EP(G)EP(Sn).

    Based on Claims 1 and 2, we have the following in two cases.

    Case 1. n8Δn3. Then, there exists two vertices vivjV(G) such that d(vi)+d(vj)=n+1.

    If Δ=n3, then GF1,2, where n7. Similarly, it can be concluded that GF1,1+k if Δ=n(3+k), where 1k5 and n7+2k. Consequently, GF1,i (shown in Figure 2), where 2i7. We deduce that

    EP(F1,2)=vivjE(G)f(d(vi),d(vj))=(n5)f(n3,1)+f(n3,4)+f(n3,2)+2f(4,1)+f(4,2)<(n3)f(n1,1)+2f(n1,2)+f(2,2)=EP(Sn).EP(F1,3)=(n6)f(n4,1)+f(n4,5)+f(n4,2)+3f(5,1)+f(5,2)<(n3)f(n1,1)+2f(n1,2)+f(2,2)=EP(Sn).EP(F1,4)=(n7)f(n5,1)+f(n5,6)+f(n5,2)+4f(6,1)+f(6,2)<(n3)f(n1,1)+2f(n1,2)+f(2,2)=EP(Sn).EP(F1,5)=(n8)f(n6,1)+f(n6,7)+f(n6,2)+5f(7,1)+f(7,2)<(n3)f(n1,1)+2f(n1,2)+f(2,2)=EP(Sn).EP(F1,6)=(n9)f(n7,1)+f(n7,8)+f(n7,2)+6f(8,1)+f(8,2)<(n3)f(n1,1)+2f(n1,2)+f(2,2)=EP(Sn).EP(F1,7)=(n10)f(n8,1)+f(n8,9)+f(n8,2)+7f(9,1)+f(9,2)<(n3)f(n1,1)+2f(n1,2)+f(2,2)=EP(Sn).

    Case 2. n5Δn3. Then, there exist two vertices vivjV(G) such that d(vi)+d(vj)=n, and there is no edge with (1,2)-type or (2,2)-type.

    If Δ=n3, then GF3, where n6. Similarly, if Δ=n4 or Δ=n5, then GF4 or GF5, where n8 and n10, see Figure 3. We obtain

    EP(F3)=vivjE(G)f(d(vi),d(vj))=(n5)f(n3,1)+2f(n3,3)+f(3,3)+2f(3,1)<(n3)f(n1,1)+2f(n1,2)+f(2,2)=EP(Sn).EP(F4)=(n6)f(n4,1)+f(n4,3)+f(n4,3)+f(4,3)+2f(4,1)+f(3,1)<(n3)f(n1,1)+2f(n1,2)+f(2,2)=EP(Sn).
    EP(F5)=(n7)f(n5,1)+f(n5,5)+f(n5,3)+f(5,3)+3f(5,1)+f(3,1)<(n3)f(n1,1)+2f(n1,2)+f(2,2)=EP(Sn).
    Figure 3.  Graphs F3, F4 and F5.

    Therefore, together with Cases 1 and 2, Lemma 3.3 is done.

    Lemma 3.4. Let GUn,4 and GCn. Then EP(G)<EP(Sn).

    Proof. By Lemma 3.2(2), Δn2, and d(vi)+d(vj)n for vivjV(G). We will prove the lemma by contradiction, and assume there exists a graph GUn,4 such that EP(G)EP(Sn). We give the following claims at first.

    Claim 1. There is no edge with (1,2)-type and (2,2)-type.

    Proof. Otherwise, there exists an edge e=vkvl such that f(d(vk),d(vl))f(2,2)=12. By Lemma 3.1, we have

    f(d(vi),d(vj))(23)Δ+(31)(x+y)(23)(n2)+(31)n<(n12).

    And

    EP(G)=vivjE(G)f(d(vi),d(vj))<(n1)(n12)+12<(n3)n2n+1+2n2+3+12=EP(Sn).

    So, Claim 1 is done.

    Claim 2. n5Δn2 and there exists two vertices vi and vj in G with d(vi)+d(vj)=n.

    Proof. Otherwise, Δn6. From Lemma 3.1, we have

    f(d(vi),d(vj))(23)Δ+(31)(d(vi)+d(vj))(23)(n6)+(31)n<(n32),

    and

    EP(G)<n(n32)<(n3)(n12)+2n<EP(Sn),

    a contradiction. Consequently, n5Δn2.

    Next, we will prove there exists two vertices vivjV(G) such that d(vi)+d(vj)=n.

    If Δ=n2, then GH1,0, as shown in Figure 4, and there exists two vertices vi and vj such that d(vi)+d(vj)=n.

    Figure 4.  Graph H1,i(0i3).

    If n5Δn3, and d(vi)+d(vj)n1 for any vertices vivjV(G), then we have

    f(d(vi),d(vj))(23)Δ+(31)(d(vi)+d(vj))(23)(n3)+(31)(n1)<(n32),

    and

    EP(G)<n(n32)<(n3)(n12)+2n<EP(Sn),

    a contradiction. Claim 2 is proved.

    Now, we consider the following cases according to Claims 1 and 2.

    If Δ=n2, then GH1,0, and this graph contains edges of (2,2)-type, which contradicts with Claim 1.

    If Δ=n3, there exists vivjV(G) with d(vi)+d(vj)=n, and there is no edge with (2,2)-type. Then GH1,1, see Figure 4.

    If Δ=n4 or Δ=n5, then we have only GH1,2 or GH1,3, as shown in Figure 4.

    Therefore, we deduce that

    EP(H1,1)=(n5)f(n2,1)+2f(n2,2)+2f(3,2)+f(3,1)<(n3)n2n+1+2n2+3+12=EP(Sn).EP(H1,2)=(n6)f(n3,1)+2f(n3,2)+2f(4,2)+f(4,1)<(n3)n2n+1+2n2+3+12=EP(Sn).EP(H1,3)=(n7)f(n5,1)+2f(n5,2)+2f(5,2)+f(5,1)<(n3)n2n+1+2n2+3+12=EP(Sn).

    So, the assumption is not true, and this completes the proof.

    Theorem 3.5. Let GGn,1, n4. Then,

    EP(G)(n3)n2n+1+2n2+3+12,

    with equality if and only if GSn.

    Proof. If GCn, then

    EP(G)=12n<(n3)n2n+1+2n2+3+12=EP(Sn),

    and the theorem holds.

    Next, let GUn,k and GCn.

    Using Lemmas 3.3 and 3.4, the theorem holds for GUn,3 and GUn,4, especially, with equality if GSn. Otherwise, GUn,k and k5. Lemma 3.2 implies that Δn3, and d(vi)+d(vj)n1 for vi,vjG. With Lemma 3.1, we deduce that

    f(d(vi),d(vj))(23)Δ+(31)(d(vi)+d(vj))(23)(n3)+(31)(n1)<(n32),

    and

    EP(G)<n(n32)<(n3)(n12)+2n<EP(Sn).

    In this section, we establish the upper bound of EP(G) for bicyclic graphs, as well as characterize the extremal graph, where n28.

    Theorem 4.1. Let GGn,2, n28. Then,

    EP(G)(n4)n2n+1+2n2+3+n2+n+7+219,

    with equality if and only if GCn,4.

    Proof. Let vivjV(G). We divide into the following three cases.

    Case 1. 3Δn13.

    For 3Δ14, we have

    f(d(vi),d(vj))Δ3143<24.3.

    With n28, we deduce that

    EP(G)<24.3(n+1)<(n4)(n12)+2n+(n+12)+219<(n4)n2n+1+2n2+3+n2+n+7+219=EP(Cn,4).

    For 15Δn13, we assume that d(vi)d(vj). Because G is a bicyclic graph, d(vi)+d(vj)n+2. Let g(x)=x2(n+2)x+(n+2)2. Then, g(x) is monotonically decreasing for x[15,n+22], and monotonically increasing for x[n+22,n13]. Therefore,

    f(d(vi),d(vj))d(vi)2+(n+2d(vi))2+d(vi)(n+2d(vi))=max{g(15),g(n13)}g(n13)=n211n+199. (4.1)

    If n32, then n211n+199<n25n+254=(n52), and

    EP(G)<24.3(n+1)<(n+1)(n52)<(n4)n2n+1+2n2+3+n2+n+7+219=EP(Cn,4).

    If 28n31, then we can also conclude that EP(G)<EP(Cn,4) by (4.1), and the detailed results see Table 1.

    Table 1.  Upper bounds of (n+1)n211n+199 and EP(Cn,4).
    orders n Upper bounds of (n+1)n211n+199 EP(Cn,4)
    28 753.443 753.772
    29 805.543 809.264
    30 859.656 866.758
    31 921.911 926.253

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    Case 2. n12Δn3.

    Recall that Δ2 is the second maximal degree in G. Since GGn,2, Δ+Δ2n+2. Next, we will consider two subcases.

    Subcase 2.1. Δ2=n+2Δ.

    In this case, GG1,n1Δ, as shown in Figure 5. Consequently,

    EP(G)=(Δ3)f(Δ,1)+2f(Δ,2)+f(Δ,Δ2)+(Δ23)f(Δ2,1)+2f(Δ2,2)=(Δ3)f(Δ,1)+2f(Δ,2)+f(Δ,n+2Δ)+(n1Δ)f(n+2Δ,1)+2f(n+2Δ,2). (4.2)
    Figure 5.  Graphs G1,i and G2.

    For n12Δn3, we have the following relations:

    f(Δ,1)<f(Δ,2)f(n3,2)<f(n1,1),f(n+2Δ,1)<f(n+2Δ,2)f(14,2)<f(n1,1),f(Δ,n+2Δ)f(n3,5)<f(n1,1).

    Together with (4.2), we have

    EP(G)<(n3)f(n1,1)+2f(14,2)+2f(14,1)<(n4)n2n+1+2n2+3+n2+n+7+219(n28)=EP(Cn,4).

    Subcase 2.2. Δ2n+1Δ.

    For any vivjV(G), d(vi)+d(vj)n+1. If n12Δn9, then

    f(d(vi),d(vj))d(vi)2(n+1)d(vi)+(n+1)2(n9)2(n+1)(n9)+(n+1)2<(n52)(n28).

    In this case, we obtain

    EP(G)(n+1)(n52)<(n4)(n12)+2n+(n+12)+219<EP(Cn,4).

    If n8Δn3, then we deduce that

    EP(G)={vivj}E(G)f(d(vi),d(vj))ΔΔ2+Δ22+ΔΔ2+Δ23Δ22. (4.3)

    Furthermore, we have the relations

    Δ2+Δ22+ΔΔ2(n3)2(n+1)(n3)+(n+1)2=n22n+13<(n12),

    and

    3Δ223(n+1Δ)3(n+1n+8)=93,

    Thus, the Eq (4.3) yields that

    EP(G)(n12)Δ+93Δ2=(n12)Δ+93(n+1Δ)=(n9312)Δ+93(n+1)<n23.4n+64<n232n+11.2(n28)<(n4)n2n+1+2n2+3+n2+n+7+219=EP(Cn,4).

    Case 3. n2Δn1.

    Subcase 3.1. Δ=n2.

    One can easily check that Δ24. If Δ2=4, then we deduce that GG1,1, shown in Figure 5. Recall that n28. We obtain

    EP(G)<(n5)(n2)2+1+(n2)+2(n2)2+4+2(n2)+(n2)2+16+4(n2)+228+21<(n4)n2n+1+2n2+3+n2+n+7+219=EP(Cn,4).

    Next, we assume Δ2=3. In this case, GG3 or GG4 (see Figure 6). Since n28, we have an immediate consequence by calculation:

    EP(G3)=(n5)(n2)2+1+(n2)+2(n2)2+9+3(n2)+(n2)2+4+2(n2)+27+19+13<(n4)n2n+1+2n2+3+n2+n+7+219=EP(Cn,4).EP(G4)=(n6)(n2)2+1+(n2)+3(n2)2+4+2(n2)+219+27+7<(n4)n2n+1+2n2+3+n2+n+7+219=EP(Cn,4).
    Figure 6.  Graphs G3 and G4.

    Otherwise, Δ22, we deduce that

    EP(G)(n2)(n2)2+4+2(n2)+312<(n4)n2n+1+2n2+3+n2+n+7+219=EP(Cn,4).

    Subcase 3.2. Δ=n1.

    If GCn,4, then

    EP(G)=EP(Cn,4)=(n4)n2n+1+2n2+3+n2+n+7+219.

    Otherwise, GG2, where G2 is shown in Figure 5. Noting that n2n+1+n2+n+72n2+3, we have

    EP(G2)=(n5)n2n+1+4n2+3+212<(n4)n2n+1+2n2+3+n2+n+7+219=EP(Cn,4),

    and the theorem is proved.

    Topological indices are commonly molecular structure descriptors that can be used to simulate and predict the physical, chemical, and biological properties of compounds, and they promoted the development of applied disciplines such as chemistry and pharmacology. Recently, the Euler Sombor index derived from geometry, has been shown to have excellent discriminability for compounds and has therefore received much attention.

    In this paper, we present Cn, and Bi(n,1)(i=2,3) are the only graphs with the minimum Euler Sombor index among all unicyclic and bicyclic graphs, respectively. Moreover, we completely obtain that Sn is the unique unicyclic graph with the maximum value of EP(G), and also determine that Cn,4 is the only bicyclic graph with maximal value of EP(G), where n28. The extremal values of the Euler Sombor index among multi-cyclic graphs, as well as its chemical applications in compounds, may be the research interests of mathematics and chemistry in the future.

    Zhenhua Su: Writing-original draft preparation, Writing-review and editing; Zikai Tang: Formal analysis, Methodology. All authors have read and agreed to the published version of the manuscript.

    The authors declare they have not used Artificial Intelligence (AI) tools in the creation of this article.

    The authors would like to thank the anonymous reviewers for their helpful comments.

    This work was supported by Hunan Province Natural Science Foundation (2025JJ70485).

    The authors declare no conflict of interest.



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