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Research article

Decay for thermoelastic laminated beam with nonlinear delay and nonlinear structural damping

  • Received: 10 December 2023 Revised: 29 January 2024 Accepted: 08 February 2024 Published: 19 February 2024
  • MSC : 35B40, 35L56, 74F05, 93D15, 93D20

  • This paper discussed the decay of a thermoelastic laminated beam subjected to nonlinear delay and nonlinear structural damping. We provided explicit and general energy decay rates of the solution by imposing suitable conditions on both weight delay and wave speeds. To achieve this, we leveraged the properties of convex functions and employed the multiplier technique as a specific approach to demonstrate our stability results.

    Citation: Hicham Saber, Fares Yazid, Fatima Siham Djeradi, Mohamed Bouye, Khaled Zennir. Decay for thermoelastic laminated beam with nonlinear delay and nonlinear structural damping[J]. AIMS Mathematics, 2024, 9(3): 6916-6932. doi: 10.3934/math.2024337

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  • This paper discussed the decay of a thermoelastic laminated beam subjected to nonlinear delay and nonlinear structural damping. We provided explicit and general energy decay rates of the solution by imposing suitable conditions on both weight delay and wave speeds. To achieve this, we leveraged the properties of convex functions and employed the multiplier technique as a specific approach to demonstrate our stability results.



    In the current work, we study the following thermoelastic laminated beam along with nonlinear structural damping and nonlinear delay

    {ϱutt+G(φux)x=0,Iϱ(3vφ)ttD(3vφ)xxG(φux)=0,3Iϱvtt3Dvxx+3G(φux)+γθx+4δv+βg1(vt(x,t))+μg2(vt(x,tς))=0,ϱ3θtkθxx+γvtx=0, (1.1)

    where

    (x,t)(0,1)×(0,),

    with the following initial and boundary conditions

    {u(x,0)=u0(x),v(x,0)=v0(x),φ(x,0)=φ0(x),θ(x,0)=θ0(x),x(0,1),ut(x,0)=u1(x),vt(x,0)=v1(x),φt(x,0)=φ1(x),x(0,1),ux(0,t)=φ(0,t)=v(0,t)=θ(0,t)=0,t>0,φx(1,t)=vx(1,t)=u(1,t)=θ(1,t)=0,t>0,vt(x,tς)=f0(x,tς),(x,t)(0,1)×(0,ς). (1.2)

    Here, u,φ,v, and θ stand for the transverse displacement, the rotation angle, the amount of slip along the interface, and the difference temperature, respectively. ϱ,G,Iϱ,D,δ, and β are positive parameters representing the density, shear stiffness, mass moment of inertia, flexural rigidity, adhesive stiffness, and adhesive damping, respectively. We denote by ϱ3,k,γ the positive physical coefficients from thermoelasticity theory.

    Herein ς>0 is the time delay, and the positive parameter μ is the delay weight.

    The laminated beam is considered an interesting research subject owed to the broad business applicability of these materials across many industries, thus attracting the attention of researchers. Hansen and Spies in [1] proposed the following beam with two layers

    {ϱutt+G(φux)x=0,Iϱ(3vttφtt)D(3vxxφxx)G(φux)=0,3Iϱvtt3Dvxx+3G(φux)+4δv+4βvt=0. (1.3)

    The model has a comparable character to the well-known classical Timoshenko system because its equations of movement were contrived based on the concepts of the Timoshenko beam theory. The impacts of the kinetics of interfacial slip are depicted by a third equation which interlocks with the first two ones. Due to their importance, these kind of problems are now highly regarded within the scientific community, and a revived resurgence of interest in examining the asymptotic behavior of the solution of diverse thermoelastic laminated beams has flourished nowadays, see [2,3,4,5]. For the readers, the background and the newest works on the qualitative properties related to this topic can be found, especially for the laminated beam, in [6,7]. Recent studies have shown that delay may result in instability unless specific conditions are taken into account, and it can also lead to solutions that vary from those obtained in previous studies. Ensuring the stability of systems with delays is of utmost importance; hence, the studies of time delays has emerged as a critical and impactful field of research. Regarding the nonlinear delay, Mpungu and Apalara in [8] made a study worth mentioning, in which they took into account system (1.3) and incorporated nonlinear delay and nonlinear structural damping, specifically in the third equation. With the help of convenient conditions on both weight delay and wave speeds, the authors were able to establish a general energy decay rates of the solutions.

    Djilali et al. [9] integrated a nonlinear delay into a viscoelastic Timoshenko beam problem and managed to demonstrate a global existence result, as well as asymptotic behavior of the solutions while presuming that a certain relation among the weight of the term with no delay and the weight of delay is maintained.

    Concerning the researches on boundary stabilization. The work by Wang et al. in [10] was the first to present results and to prove an exponential decay result, the authors considered system (1.3) with mixed homogeneous, boundary conditions and unequal wave speeds. Many authors improved upon the work of [10], under the assumption that ϱG<Iϱ, to establish a similar exponential decay result [11,12].

    Recently, Fayssal in [13], examined a thermoelastic laminated beam with structural damping and proved it to be exponentially stable when the condition below is valid:

    ϱG=IϱD. (1.4)

    The remaining sections of the paper are organized as follows: In Section 2, we exhibit the study's major results after providing its necessary materials. In Section 3, we prove necessary lemmas that will support the proof of our results. In Section 4, once we go by the multiplier technique, our intended stability results are established.

    In this section, we give required assumptions and resources for our study, then we highlight our major results.

    We start by setting the necessary assumptions as in [14]:

    ● (A1) The function g1:RR is increasing and of class C0. Moreover, there exist constants λ1,λ2,ε>0 and a function XC1([0,+)), being strictly increasing, fulfilling X(0)=0, and the latter is linear on [0,ε] or strictly convex of class C2 on (0,ε], in a way that we have

    {r2+g21(r)X1(rg1(r)), for all |r|ε,λ1|r||g1(r)|λ2|r|, for all |r|ε. (2.1)

    ● (A2) The function g2:RR is odd, increasing, and belongs to C1(R). In addition, there exist positive constants ϑ,ϑ1,ϑ2, such that

    |g2(r)|ϑ,

    and

    ϑ1rg2(r)ξ(r)ϑ2rg1(r), (2.2)

    where

    ξ(r)=r0g2(y)dy,

    and

    ϑ2μ<ϑ1β. (2.3)

    Remark 2.1. Exploiting assumption (A1), one can see that

    rg1(r)>0,r0.

    It follows by (A2) and the monotonicity of g2, with the mean value theorem (for integrals) that

    ξ(r)rg2(r), (2.4)

    therefore

    ϑ11.

    To deal with the nonlinearity of the delay, we shall present a constant κ that is positive and fulfilling

    μ(1ϑ1)ϑ1<κ<βϑ2μϑ2. (2.5)

    As in [15], to begin, we introduce

    S(x,p,t)=vt(x,tςp) in (0,1)×(0,1)×(0,). (2.6)

    Thus, S satisfies

    ςSt(x,p,t)+Sp(x,p,t)=0. (2.7)

    Therefore, we obtain the following new system equivalent to the previous one (1.1)

    {ϱutt+G(φux)x=0,Iϱ(3vφ)ttD(3vφ)xxG(φux)=0,3Iϱvtt3Dvxx+3G(φux)+γθx+4δv+βg1(vt(x,t))+μg2(S(x,1,t))=0,ϱ3θtkθxx+γvtx=0,ςSt(x,p,t)+Sp(x,p,t)=0, (2.8)

    with

    {u(x,0)=u0(x),v(x,0)=v0(x),φ(x,0)=φ0(x),θ(x,0)=θ0(x),x(0,1),ut(x,0)=u1(x),vt(x,0)=v1(x),φt(x,0)=φ1(x),x(0,1),ux(0,t)=φ(0,t)=v(0,t)=θ(0,t)=0,t>0,φx(1,t)=vx(1,t)=u(1,t)=θ(1,t)=0,t>0,S(x,0,t)=vt(x,t),S(x,p,0)=f0(x,ςp),(x,p)((0,1))2,t>0. (2.9)

    Establishing the existence and uniqueness result is achievable by pursuing the reasoning behind the Faedo Galerkin approach, as expounded in [16]. To maintain simplicity, we will use S(p) to represent S(x,p,t).

    Now, we shall present our energy of the system (2.8)-(2.9) by

    E(t)=1210{ϱu2t+Iϱ(3vtφt)2+D(3vxφx)2+3Iϱv2t+3Dv2x}dx+1210{G(φux)2+4δv2+ϱ3θ2}dx+1010ςκξ(S(p))dpdx, (2.10)

    and right after, we exhibit the stability result.

    Theorem 2.1. Let (u,φ,v,θ,S) be the solution of (2.8)-(2.9). Suppose that (A1), (A2), and (1.4) hold, then, there exist positive constants α0,α1,α2, and ε0 such that

    E(t)α0X11(α1t+α2),t0, (2.11)

    where

    X1(t)=1t1X0(r)dr,

    and

    X0(t)={t,ifXis linear on[0,ε],tX(ε0t),ifX(0)=0andX>0on(0,ε].

    Prior researches have given examples related to our stability result and assumptions; see [8].

    The lemmas necessary to back up our proof of stability results will be established in this part. To achieve our stability result's proof, a specific method named the multiplier technique will be employed and a generic constant K>0 will be used for the sake of simplicity. Note that K may change from line to line or in the same line.

    Lemma 3.1. Let (u,φ,v,θ,S) be the solution of (2.8)-(2.9), then, the energy functional satisfies

    E(t)k10θ2xdxM010vtg1(vt)dxM110S(1)g2(S(1))dx,t0, (3.1)

    where M0 and M1 are positive constants.

    Proof. To begin, let us multiply (2.8)1–(2.8)4 by ut, (3vtφt),vt, and θ, respectively, then integrate over (0,1) and use integration by parts to get

    12ddt10{ϱu2t+Iϱ(3vtφt)2+D(3vxφx)2+3Iϱv2t+3Dv2x+4δv2}dx+12ddt10{G(φux)2+ϱ3θ2}dx=k10θ2xdxβ10vtg1(vt)dxμ10vtg2(S(1))dx. (3.2)

    After that, we multiply Eq (2.8)5 by κg2(S(p)), integrate over (0,1)×(0,1), and notice that S(0)=vt, to find

    κς1010g2(S(p))St(p)dpdx=κ1010pξ(S(p))dpdx=κ10ξ(S(0))dxκ10ξ(S(1))dx=κ10ξ(vt)dxκ10ξ(S(1))dx, (3.3)

    hence,

    κςddt1010ξ(S(p))dpdx=κ10ξ(vt)dxκ10ξ(S(1))dx,

    which, together with both (3.2) and (2.2), gives us

    E(t)k10θ2xdx(βϑ2κ)10vtg1(vt)dxκ10ξ(S(1))dxμ10vtg2(S(1))dx. (3.4)

    Let us now define the conjugate function of ξ by

    ξ(r)=supsR+(rsξ(r)),

    thus, ξ is the Legendre transformation of ξ, and it is given as

    ξ(r)=r(ξ)1(r)ξ[(ξ)1(r)],r0. (3.5)

    In this way, the following relation is valid (see [14,17])

    rsξ(r)+ξ(s),r,s0. (3.6)

    Exploiting (3.5), along with the definition of ξ, leads to

    ξ(r)=rg12(r)ξ(g12(r)). (3.7)

    The use of (3.7) together with (2.2) yields

    ξ(g2(S(1)))=S(1)g2(S(1))ξ(S(1))(1ϑ1)S(1)g2(S(1)). (3.8)

    Therefore, taking advantage of (3.6), (3.8), and (2.2), we can write

    μ10vtg2(S(1))dxμ10ξ(vt)dx+μ10ξ(g2(S(1)))dxμ10ξ(vt)dx+μ(1ϑ1)10S(1)g2(S(1))dxϑ2μ10vtg1(vt)dx+μ(1ϑ1)10S(1)g2(S(1))dx. (3.9)

    Finally, combining (3.9) and (3.4) with the help of (2.5) and (2.3), the estimate (3.1) is established.

    Lemma 3.2. Consider the functional

    I1(t)=3IϱG10(3vφ)vtdxϱD10(3vxφx)utdxIϱG10(3vtφt)uxdx, (3.10)

    then, it satisfies

    I1(t)GD210(3vxφx)2dx+ϵ110(3vtφt)2dx+K10v2xdx (3.11)
    +Kϵ110v2tdx+K10g21(vt)dx+K10S(1)g2(S(1))dx
    +K10(φux)2dx+K10θ2xdx,ϵ1>0.

    Proof. We first take I1, then exploit Eq (2.8)1(2.8)3, integration by parts and ux=(φux)+φ, to reach

    I1(t)=GD10(3vxφx)2dx+3IϱG10vt(3vtφt)dx3G210(φux)(3vφ)dx4δG10(3vφ)vdxγG10(3vφ)θxdxβG10(3vφ)g1(vt)dxμG10(3vφ)g2(S(1))dxG210ux(φux)dx+(IϱGϱD)10ut(3vφ)xtdx. (3.12)

    Since ux=3v(φux)(3vφ) and hypothesis (1.4) holds, we find

    I1(t)=GD10(3vxφx)2dx+3IϱG10vt(3vtφt)dx2G210(φux)(3vφ)dx4δG10(3vφ)vdxγG10(3vφ)θxdxβG10(3vφ)g1(vt)dxμG10(3vφ)g2(S(1))dx+G210(φux)2dx3G210v(φux)dx. (3.13)

    To continue, it is convenient to consider (2.4), along with (3.6) and (3.8), to obtain

    g22(S(1))2S(1)g2(S(1)). (3.14)

    We next apply (3.14) and Young and Poincaré's inequalities to finally get (3.11).

    Lemma 3.3. Consider functional

    I2(t):=3IϱG10vt(φux)dx3ϱD10utvxdx, (3.15)

    which satisfies, for any ϵ2>0,

    I2(t)G210(φux)2dx+ϵ210(3vtφt)2dx+K(1+1ϵ2)10v2tdx (3.16)
    +K10v2xdx+K10θ2xdx+K10g21(vt)dx+K10S(1)g2(S(1))dx.

    Proof. We begin by differentiating I2, then we take advantage of both (2.8)1,3, and integration by parts. We get

    I2(t)=3G210(φux)2dx+3(ϱDIϱG)10vtuxtdx+3IϱG10vtφtdx4δG10(φux)vdxγG10(φux)θxdβG10(φux)g1(vt)dxμG10(φux)g2(S(1))dx. (3.17)

    Since φt=3vt(3vtφt), and by (1.4), we have

    I2(t)=3G210(φux)2dx3IϱG10vt(3vtφt)dx4δG10(φux)vdx+9IϱG10v2tdxγG10(φux)θxdxβG10(φux)g1(vt)dxμG10(φux)g2(S(1))dx. (3.18)

    Now, with the help of (3.14) and Young and Poincaré's inequalities, one can write

    4δG10(φux)vdxδ2210v2xdx+G2210(φux)2dx, (3.19)
    γG10(φux)θxdxγ2210θ2xdx+G2210(φux)2dx, (3.20)
    βG10(φux)g1(vt)dxβ2210g21(vt)dx+G2210(φux)2dx, (3.21)
    μG10(φux)g2(S(1))dxμ2210g22(S(1))dx+G2210(φux)2dx,μ210S(1)g2(S(1))dx+G2210(φux)2dx, (3.22)

    and for any ϵ2>0,

    3IϱG10vt(3vtφt)dxϵ210(3vtφt)2dx+Kϵ210v2tdx. (3.23)

    The combination of (3.19)–(3.23) and (3.18) gives us (3.16).

    Lemma 3.4. Consider the functional

    I3(t):=3Iϱ10vvtdx3ϱ10vx0ut(y)dydx, (3.24)

    then for any ϵ3>0, it satisfies

    I3(t)δ10v2dx3D10v2xdx+ϵ310u2tdx+K10θ2xdx+K(1+1ϵ3)10v2tdx+K10g21(vt)dx+K10S(1)g2(S(1))dx. (3.25)

    Proof. We first find the derivative of I3, then exploit Eq (2.8)1,3 along with integration by parts, to get

    I3(t)=4δ10v2dx+3Iϱ10v2tdx3D10v2xdxγ10vθxdxβ10g1(vt)vdxμ10g2(S(1))vdx3ϱ10vtx0ut(y)dydx.

    By (3.14) and Young and Poincaré's inequalities, the proof is accomplished.

    Lemma 3.5. Consider the functional

    I4(t):=ϱ10uutdx, (3.26)

    then, it satisfies

    I4(t)ϱ10u2tdx+K10v2xdx+D10(3vxφx)2dx+K10(φux)2dx. (3.27)

    Proof. Taking I4, Eq (2.8)1, integration by parts and by ux=(3vφ)(φux)+3v, we get

    I4(t)=ϱ10u2tdx+G210(φux)2dx3G10v(φux)dx+G10(φux)(3vφ)dx. (3.28)

    By Young and Poincaré's inequalities, we establish (3.27).

    Lemma 3.6. Consider the functional

    I5(t):=Iϱ10(3vφ)(3vφ)tdx, (3.29)

    then it satisfies

    I5(t)2D10(3vxφx)2dxIϱ10(3vtφt)2dx+K10(φux)2dx. (3.30)

    Proof. By direct calculations, once we consider (2.8)2 and integration by parts, we obtain

    I5(t)=D10(3vxφx)2dxIϱ10(3vtφt)2dG10(3vφ)(φux)dx. (3.31)

    By Young and Poincaré's inequalities, we reach

    G10(3vφ)(φux)dxG24D10(φux)2dx+D10(3vxφx)2dx. (3.32)

    Hence, the combination of (3.32) and (3.31) gives us (3.30).

    Lemma 3.7. Consider the functional

    I6(t):=ς1010epςξ(S(p))dpdx, (3.33)

    then it satisfies

    I6(t)ϑ1eς10S(1)g2(S(1))dx+ϑ210vtg1(vt)dxςeς1010ξ(S(p))dpdx. (3.34)

    Proof. Taking both I6 and Eq (2.8)5, then exploiting S(0)=vt, we get

    I6(t)=ς1010eςpSt(p)g2(S(p))dpdx=1010eςpSp(p)g2(S(p))dpdx=1010eςppξ(S(p))dpdx=1010p[eςpξ(S(p))]dpdxς1010eςpξ(S(p))dpdx=eς10ξ(S(1))dx+10ξ(vt)dxς1010eςpξ(S(p))dpdx.

    By using both (2.2) and eςepς1,p(0,1), we then prove (3.34).

    Our intended stability results are established here based on the previously stated lemmas.

    Proof of Theorem 2.1. To begin, we consider a Lyapunov functional

    K(t)=NE(t)+6i=1NiIi(t),t0, (4.1)

    where the constants N,Ni>0,i=16, will be chosen later.

    According to (4.1), we write

    |K(t)NE(t)|N1ϱD10|ut(3vxφx)|dx+3N1IϱG10|vt(3vφ)|dx+N1IϱG10|ux(3vtφt)|dx+3N2ϱD10|utvx|dx+3N2IϱG10|(φux)vt|dx+3N3Iϱ10|vvt|dx+3N3ϱ10|vx0ut(y)dy|dx+N4ϱ10|utu|dx+N5Iϱ10|(3vφ)t(3vφ)|dx+ςN61010epς|ξ(S(p))|dpdx.

    By Young, Cauchy-Schwarz, and Poincaré's inequalities, we have

    |K(t)NE(t)|aE(t), where a>0,

    i.e.,

    (Na)E(t)K(t)(N+a)E(t). (4.2)

    To continue, we take K(t) and employ (3.1), (3.11), (3.16), (3.25), (3.27), (3.30), and (3.34), then we set

    N1=8G,N4=N5=N6=1,ϵ1=Iϱ4N1,ϵ2=Iϱ4N2,ϵ3=ϱ2N3,

    to get

    K(t)Iϱ210(3vtφt)2dxD10(3vxφx)2dx[G2N2K]10(φux)2dxϱ210u2tdxδN310v2dx[3DN3KN2K]10v2xdx[kNKN2KN3K]10θ2xdx[M0Nϑ2]10vtg1(vt)dx[M1NKN2KN3K+eςϑ1]10S(1)g2(S(1))dxςeς1010ξ(S(p))dpdx+[N2K(1+N2)+N3K(1+N3)+K]10v2tdx+[KN2+KN3+K]10g21(vt)dx. (4.3)

    We then select coefficients in (4.3), to make them all (with the exception of the last two) negative. By taking N2 big enough such that

    G2N2K>0,

    we can choose N3 fairly large, so

    3DN3KN2K>0.

    We set N big enough, to get (4.2) and

    {M1NKN2KN3K+eςϑ1>0,kNKN2KN3K>0,M0Nϑ2>0.

    These choices, with Poincaré's inequality, lead to

    K(t)ϑ3E(t)+ϑ410(v2t+g21(vt))dx,ϑ3,ϑ4>0,t0. (4.4)

    In the context of our demonstration, we have two cases to treat:

    Case 1. Suppose that X is linear on [0,ε]. By hypothesis (A1), we have

    {λ1r2rg1(r)λ2r2,rλ1g1(r)g21(r)rλ2g1(r),rR,

    which, when combined with (4.4), results in

    K(t)ϑ3E(t)+ˉϑ410vtg1(vt)dx,ˉϑ4>0. (4.5)

    By merging (3.1) and (4.5), we find

    K(t)ϑ3E(t)ϑ5E(t),ϑ5>0. (4.6)

    We will now proceed by presenting

    K(t):=K(t)+ϑ5E(t),t0. (4.7)

    Once considering (4.2), we see that

    ˉa1E(t)K(t)ˉa2E(t),ˉa1,ˉa2>0. (4.8)

    Consequently, when we consider (4.7) and (4.8), we get

    K(t)α1K(t),α1=ϑ3ˉa2. (4.9)

    Finally, we conclude by simply integrating (4.9) and employing (4.8), to prove that

    E(t)α0eα1t,where α0=ˉa2E(0)ˉa1,t0. (4.10)

    Case 2. Suppose that X is nonlinear on (0,ε]. We take as in [18], 0<ε1ε, to have

    rg1(r)min{ε,X(ε)},|r|ε1.

    It is helpful to consider the continuous function g1, with (A1) and to note that |g1(r)|>0,r0, to have

    {r2+g21(r)X1(rg1(r)),|r|ε1,λ1|r||g1(r)|λ2|r|,|r|ε1. (4.11)

    Now, we need to work on estimating

    10(v2t+g21(vt))dx.

    To this end, we consider, as in [19], the partitions below

    B1={x(0,1):|vt|ε1},B2={x(0,1):|vt|>ε1}.

    The combination of the Jensen's inequality with the concavity of X1, results in

    X1(B(t))λ5B1X1(vtg1(vt))dx, (4.12)

    where

    B(t)=B1vtg1(vt)dx, and λ5>0.

    If we take (3.1), (4.11), and (4.12), we get

    10(v2t+g21(vt))dx=B1(v2t+g21(vt))dx+B2(v2t+g21(vt))dxB1X1(vtg1(vt))dx+λ6B2(vtg1(vt))dxλ6X1(B(t))λ6E(t),λ6>0. (4.13)

    We then present the functional

    K0(t):=K(t)+λ7E(t),where λ7>0. (4.14)

    Relation (4.2) implies that

    a1E(t)K0(t)a2E(t),a1,a2>0. (4.15)

    Thus, once we merge (4.13) and (4.4) and exploit (4.14), we conclude that

    K0(t)ϑ3E(t)+λ7X1(B(t)),t0. (4.16)

    Let us now consider the functional below

    K1(t):=X(E(t)E(0)ε0)K0(t)+γ0E(t),ε0<ε,γ0>0. (4.17)

    Combining (4.15) and the fact that

    E0,X>0,X>0,on (0,ε],

    we get

    ˉa1E(t)K1(t)ˉa2E(t),ˉa1,ˉa2>0. (4.18)

    Additionally, relation (4.16) yields

    K1(t)=ε0E(t)E(0)X(E(t)E(0)ε0)K0(t)+X(E(t)E(0)ε0)K0(t)+γ0E(t)ϑ3X(E(t)E(0)ε0)E(t)+λ7X(E(t)E(0)ε0)X1(B(t))+γ0E(t). (4.19)

    Let us set

    Q=λ7X(E(t)E(0)ε0)X1(B(t)).

    Similar to what we did earlier with (3.5), we shall now estimate Q by letting X be the convex conjugate of X given by

    X(r)=r(X)1(r)X[(X)1(r)]r(X)1(r), where r(0,X(ε)). (4.20)

    Additionally, the use of the general Young's inequality, indicates

    rsX(r)+X(s), where r(0,X(ε)),s(0,ε]. (4.21)

    We set

    r=X(E(t)E(0)ε0), and s=X1(B(t)),

    By (4.20), (4.21), and

    B(t)=B1vtg1(vt)dx10vtg1(vt)dx1M0E(t),

    we have

    Q=λ7X(E(t)E(0)ε0)X1(B(t))λ7ε0E(t)E(0)X(E(t)E(0)ε0)λ8E(t),λ8>0. (4.22)

    The replacement of (4.22) into (4.19) leads to

    K1(t)[ϑ3E(0)λ7ε0]E(t)E(0)X(E(t)E(0)ε0)+(γ0λ8)E(t). (4.23)

    Now, selecting ε0=ϑ3E(0)2λ7 and γ0=2λ8 gives us

    K1(t)˜ϑ3E(t)E(0)X(E(t)E(0)ε0)+λ8E(t);˜ϑ3=ϑ3E(0)2,

    and provided that E(t)0, we get

    K1(t)˜ϑ3E(t)E(0)X(E(t)E(0)ε0)=˜ϑ3X0(E(t)E(0)), (4.24)

    where X0(r)=rX(ε0r).

    Now, X being strictly convex on (0,ε], implies that X0(r),X0(r)>0 on (0,1]. Hence, letting

    K1(t):=˜a1K1(t)E(0), (4.25)

    we find that

    ˜a1E(t)K1(t)˜a2E(t),˜a1,˜a2>0. (4.26)

    Furthermore, the employment of (4.24), results in

    K1(t)˜a1˜ϑ3E(0)X0(E(t)E(0)).

    In addition, if we take into account (4.26) and that X0 is increasing, we achieve

    K1(t)α1X0(K1(t)),α1>0,t0. (4.27)

    According to (4.27), we have

    [X1(K1(t))]α1, (4.28)

    where

    X1(t)=1t1X0(r)dr.

    If we integrate (4.28) over (0,t), we get

    X1(K1(t))α1t+α2,α2=X1(K1(0)),t0. (4.29)

    Since X11 is a decreasing function, we deduce

    K1(t)X11(α1t+α2). (4.30)

    We exploit relation (4.26) to ultimately achieve

    E(t)α0X11(α1t+α2),t0, (4.31)

    where α0=1˜a1. The proof is then concluded.

    A class of thermoelastic laminated beams is considered. In addition to the impact of thermoelasticity, we are interested here in the interaction between the weights of two terms with delay and without delay given in nonlinear forms. We have shown explicit and general energy decay rates of the solution by using the properties of convex functions and employing the multiplier technique.

    The authors declare they have not used Artificial Intelligence (AI) tools in the creation of this article.

    This research was funded by King Khalid University through large research project under grant number R.G.P.2/252/44.

    The authors declare that there are no conflicts of interest.



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