Research article Special Issues

Distance antimagic labeling of circulant graphs

  • A distance antimagic labeling of graph G=(V,E) of order n is a bijection f:V(G){1,2,,n} with the property that any two distinct vertices x and y satisfy ω(x)ω(y), where ω(x) denotes the open neighborhood sum aN(x)f(a) of a vertex x. In 2013, Kamatchi and Arumugam conjectured that a graph admits a distance antimagic labeling if and only if it contains no two vertices with the same open neighborhood. A circulant graph C(n;S) is a Cayley graph with order n and generating set S, whose adjacency matrix is circulant. This paper provides partial evidence for the conjecture above by presenting distance antimagic labeling for some circulant graphs. In particular, we completely characterized distance antimagic circulant graphs with one generator and distance antimagic circulant graphs C(n;{1,k}) with odd n.

    Citation: Syafrizal Sy, Rinovia Simanjuntak, Tamaro Nadeak, Kiki Ariyanti Sugeng, Tulus Tulus. Distance antimagic labeling of circulant graphs[J]. AIMS Mathematics, 2024, 9(8): 21177-21188. doi: 10.3934/math.20241028

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  • A distance antimagic labeling of graph G=(V,E) of order n is a bijection f:V(G){1,2,,n} with the property that any two distinct vertices x and y satisfy ω(x)ω(y), where ω(x) denotes the open neighborhood sum aN(x)f(a) of a vertex x. In 2013, Kamatchi and Arumugam conjectured that a graph admits a distance antimagic labeling if and only if it contains no two vertices with the same open neighborhood. A circulant graph C(n;S) is a Cayley graph with order n and generating set S, whose adjacency matrix is circulant. This paper provides partial evidence for the conjecture above by presenting distance antimagic labeling for some circulant graphs. In particular, we completely characterized distance antimagic circulant graphs with one generator and distance antimagic circulant graphs C(n;{1,k}) with odd n.


    Let G=G(V,E) be a finite, simple, undirected graph. The notion of {distance magic labeling} of a graph G was introduced in the Ph.D. thesis of Kamalappan [20] as a bijection f:V(G){1,2,,|V(G)|} with the property that there is a magic constant k such that at any vertex x, the weight of vertex x, ω(x)=yN(x)f(y)=k, where N(x) is the open neighborhood of x, i.e., the set of vertices adjacent to x. It has been proven that the magic constant of a distance magic graph is unique [2,14] and that many classes of graphs admit distance magic labeling (see [1] and [5]). However, the necessary and sufficient conditions for a graph to be distance magic are still unknown.

    In the case of distinct vertex weights, we have distance antimagic labeling, formally defined as follows [7]. A bijection f:V(G){1,2,...,|V(G)|} is called a {distance antimagic labeling} of graph G if ω(x)ω(y), for two distinct vertices x and y. A graph that admits distance antimagic labeling is called a {distance antimagic graph}. It is clear that if a graph contains two vertices with the same open neighborhood, then it does not admit a distance antimagic labeling. Kamatchi and Arumugam [7] then conjectured that the converse of the previous statement is also true and proposed the following:

    Conjecture A. [7] A graph G is distance antimagic if and only if G does not have two distinct vertices with the same open neighborhood.

    Some families of graphs are distance antimagic, among others the path Pn, the cycle Cn (n4), the wheel Wn (n4) [7], and the hypercube Qn (n3) [8]. In 2016, Llado and Miller [10] utilized combinatorial nullstellensatz to prove that a tree with l leaves and 2l vertices is distance antimagic. Recently, some product graphs have been shown to be distance antimagic [19,21].

    In this paper, we consider distance antimagic circulant graphs. Let n be a positive integer, and S={s1,s2,,sk} be a set of integers such that 1s1<s2<<sk<n. A circulant graph C(n;S) is a graph with a vertex-set V={v0,v1,,vn1} and an edge-set E={(viv(i+sj)(modn) | 0in1,1jk}. In other words, a circulant graph C(n;S) is a Cayley graph whose adjacency matrix is circulant, where S is the generating set. For each siS coprime to n, including s1=1, there exists a Hamiltonian cycle in C(n;S). In [3], it is shown that the circulant graph C(n;S) is connected if and only if gcd(s1,s2,,sk,n)=1.

    It is clear that the circulant graph C(n;S) is isomorphic to C(n;S), where S={ns1,ns2,,nsk}, and so throughout the paper we consider a generating set S={s1,s2,,sk}, where 1s1<s2<<skn2. In this case, the circulant graph C(n;S) is regular of degree 2k if skn/2, and 2k1 if sk=n/2.

    In recent years, researchers have taken interest in the study of both distance magic and antimagic labeling of circulant graphs. This is due to the fact that the circulant graphs are Cayley and so vertex transitive. Cichacz and Froncek [4] completely characterized distance magic C(n;{1,p}) for odd p and gave some sufficient conditions for even p. Miklavic and Šparl later settled the characterization problem for even p [12] in 2021. Miklavic and Šparl then provided a partial classification of distance magic C(n;{a,b,c}) [13]. For more generators, Godinho and Singh [6] gave necessary and sufficient conditions for distance magic C(n;{1,2,r}), for gcd(n,r) is even.

    In 2019, Patel and Vasava [15] proved that the circulant graph C(2n;{1,n}) is distance antimagic for even n, and later in 2021, Shrimali and Rathod [17] proved the case for odd n. Another result for distance antimagic circulant graphs is in [16], where it is proved that the circulant graph C(2m;{2,,m2,m}) is distance antimagic.

    We start our study by characterizing distance antimagic circulant graphs with one generator in Section 2. We then circulant graphs with two generators in Section 3, where we characterize distance antimagic C(n;1,k) with odd n. We also provide an alternative unified construction of distance antimagic labeling for the circulant graph C(2n;{1,n}), n3, as opposed to the two different labeling constructions in [15] and [17]. Section 4 provides sufficient conditions for distance antimagic circulant graphs with arbitrary generating sets. We conclude by summarizing and proposing an open problem in Section 5.

    Let n and k be positive integers, where kn2. The circulant graph C(n;{k}) can be categorized based on n and k as follows:

    ● If gcd(n,k)=1, then the circulant graph C(n;{k}) is a cycle on n vertices, Cn.

    ● If gcd(n,k)=s1 and n2k, then C(n;{k}) is isomorphic to sCns.

    ● If n=2k, then C(n;{k}) is isomorphic to kP2.

    Examples of the three types of C(n;{k}) can be found in Figure 1.

    Figure 1.  The circulant graphs (a) C(8;3), (b) C(8;2), and (c) C(8;4).

    We are ready to show that Conjecture A is true for circulant graphs with one generator, C(n;{k}).

    Theorem 2.1. Let n and k be positive integers, where kn2. The circulant graph C(n;{k}) is distance antimagic if and only if n4k.

    Proof. It is clear that the vertices with the same open neighborhoods belong to C4 and C(n;{k}) admits C4 as a component when n=4k. Thus, the proof is completed by considering the following results:

    (1) For n4, the disjoint copies of Cn are distance antimagic [7,18].

    (2) The disjoint copies of P2 are distance antimagic.

    We begin by considering the circulant graph C(n;{1,k}), where 1<k<n2. In the following lemma, we provide sufficient conditions for such circulant graphs with even n to admit distance antimagic labeling.

    Lemma 3.1. Let n be an even integer. For 1<k<n2, the circulant graph C(n;{1,k}) contains two vertices with the same open neighborhood if and only if k=n21.

    Proof. Since kn2, the circulant graph C(n;{1,k}) is a 4regular graph. Let k=n21 and consider two vertices, v0 and vn2. Obviously, v0 is adjacent to v1, and vn21. Also, vn1 is adjacent to v((n1)+1)(modn)=v0 and vn2+1 is adjacent to v((n2+1)+n21)(modn)=v0. Thus, N(v0)={v1,vn21,vn2+1,vn1}. On the other hand, vn2 is adjacent to vn2+1 and vn1. Also, v1 and vn21 are adjacent to vn2. This leads to N(vn2)={vn2+1,vn1,v1,vn21}.

    For necessity, suppose that kn21, then all vertices have distinct open neighborhoods.

    Now, we are ready to construct distance antimagic labeling for the circulant graph C(n;{1,k}), 1<k<n2, with odd n.

    Theorem 3.1. Let n be an odd integer. For 1<k<n2, the circulant graph C(n;{1,k}) is distance antimagic.

    Proof. Define a labeling f for C(n;{1,k}) such that f(vi)=i+1, for i=0,1,,n1. Thus, the distinct weights of the vertices are

    ω(vi)={2n+4,i=0,n+4i+4,i=1,2,,k2,k1,4i+4,i=k,k+1,,nk2,nk1,4i+4n,i=nk,nk+1,,n3,n2,2n,i=n1.

    Figure 2 illustrates an example of the labeling.

    Figure 2.  A distance antimagic labeling for C(11,{1,4}).

    For even n, we characterize the distance antimagic C(n;{1,2}) and C(n;{1,3}) in the following theorems.

    Theorem 3.2. Let n>3 be an even integer. The circulant graph C(n;{1,2}) is distance antimagic if and only if n6.

    Proof. For n=4, the circulant graph C(4;{1,2}) is the complete graph K4, which clearly is distance antimagic. By Lemma 3.1, the circulant graph C(6;{1,2}) is not distance antimagic. For n>6, we consider two cases based on the remainder modulo 4.

    Case 1. Let n2(mod4). Define a labeling g1:V{1,2,,n} by

    g1(vi)={n,i=0,i+1,i=1,2,3,,n2,1,i=n1,

    and so we obtain the following distinct vertex weights:

    ω(vi)={n+3i+5,i=0,1,2,4i+4,i=3,4,5,,n4,3i+2,i=n3,n2,n1.

    Case 2. Let n0(mod4). Consider the following two sub-cases:

    Subcase 2.1. Let n=12 or n>16. Define a labeling g2:V{1,2,,n} by

    g2(vi)={i+1,i=0,1,n,i=2,i,i=3,4,,n1,

    and so we obtain the distinct vertex weights as follows:

    ω(vi)={3n1,i=0,2n+3,i=1,10,i=2,n+3i+2,i=3,4,4i,i=5,6,,n4,n3,3n7,i=n2,2n2,i=n1.

    Subcase 2.2. Let n=8,16. Define a labeling g3:V{1,2,,n} by

    g3(vi)={i+1,i=0,1,,n23,n22,n2+1,n2+2,,n2,n1,ni,i=n21,n2.

    For n=8, the distinct vertex weights are

    ω(v0)=20,ω(v1)=17,ω(v2)=12,ω(v3)=15,ω(v4)=21,ω(v5)=24,ω(v6)=19,ω(v7)=16.

    And for n=16, the distinct vertex weights are

    ω(vi)={36,i=0,24,i=1,4i+4,i=2,3,4,6,9,11,12,13,4i+5,i=5,8,4i+3,i=7,10,3n4,i=14,2n,i=15.

    Figure 3 illustrates an example of the labeling for the case of n2(mod4).

    Figure 3.  A distance antimagic labeling for circulant graph C(10;{1,2}).

    Theorem 3.3. Let n be an even integer. The circulant graph C(n;{1,3}) is distance antimagic if and only if n>8.

    Proof. The circulant graph C(6;{1,3}) has two vertices with the same open neighborhood, so it is not distance antimagic. According to Lemma 3.1, the circulant graph C(8;{1,3}) is not distance antimagic. For n>8, consider the following two cases:

    Case 1. Let n18. Define a labeling h1:V{1,2,,n} by

    h1(vi)={n,i=0,i+1,i=1,2,,n2,1,i=n1,

    and so that we obtain the following distinct vertex weights:

    ω(vi)={n+5,i=0,2n+7,i=1,13,i=2,n+15,i=3,4i+4,i=4,5,,n5,3n11,i=n4,4n9,i=n3,2n3,i=n2,3n1,i=n1.

    Case 2. Let n=18. Define a labeling h2:V{1,2,,n} by

    h2(vi)={i+1,0in22orn2+1in1,ni,i=n21,n2.

    Thus, we obtain the following distinct vertex weights:

    ω(vi)={2n+4,i=0,n+4+4i,i=1,2,4i+4,i=3,4,13,14,4i+5,i=5,7,9,11,4i+3,i=6,8,10,12,4in+4,i=15,16,2n,i=17.

    Figure 4 illustrates examples of the labelings for both cases of n18 and n=18.

    Figure 4.  Distance antimagic labelings for C(14;{1,3}) and C(18;{1,3}).

    For even n, we could only prove the distance antimagicness of the circulant graph C(n;{1,k}) with k=2,3 (Theorems 3.2 and 3.3). For the sake of completeness, we propose the following:

    Conjecture 3.1. For even n and 3<k<n21, the circulant graph C(n;{1,k}) is distance antimagic.

    The remaining case for the circulant graph C(n;{1,k}) is for k=n2, which implicitly requires n to be even. Patel and Vasava [15] proved that the circulant graph C(2n;{1,n}) is distance antimagic for even n. Subsequently, Shrimali and Rathod [17] proved that the circulant graph C(2n;{1,n}) is distance antimagic for odd n. Both results utilized different labeling constructions, and here we prove Theorem 3.4 by an alternative unified construction of distance antimagic labeling for circulant graph C(2n;{1,n}), n3. The following observation is useful, and the proof is left to the readers.

    Observation 1. The circulant graph C(2n;{1,n}) contains two vertices with the same open neighborhood if and only if n=3.

    Theorem 3.4. The circulant graph C(2n;{1,n}) is distance antimagic if and only if n3.

    Proof. For n=1 or 2, the circulant graphs C(2n;{1,n}) are complete graphs, which are obviously distance antimagic.

    For n4, define a labeling o:V{1,2,,2n} by

    o(vi)={2n,i=0,i+1,1in2,n+1,i=n1,in+1,i=n,2n1,3ni,n+1i2n2.

    Thus, the following distinct vertex weights are obtained:

    ω(vi)={n+3,i=0,4n+2,i=1,2n+2+i,2in3,3n+1,i=n2,2n,i=n1,5n,i=n,2n+1,i=n+1,5n+1i,n+2i2n3,3n+2,i=2n2,4n+3,i=2n1.

    Figure 5 illustrates an example of the labeling.

    Figure 5.  A distance antimagic labeling for C(8;{1,4}).

    We conclude this section by providing a sufficient condition such that the circulant graph C(2n;{a1,a2}) is not distance antimagic and, subsequently, labeling for the circulant graph C(n;{a1,a2}), for odd n and 1<a1<a2<n2.

    Theorem 3.5. Let n,a1,a2 be positive integers with a1<a2<n. If a1+a2=n, then the circulant graph C(2n;{a1,a2}) is not distance antimagic.

    Proof. It is clear that v0 and vn are not adjacent. However, v0 is adjacent to va1 and v2na1, and vn is adjacent to vna1 and vn+a1. Since a2=na1, v0 is adjacent to vna1 and vn+a1, and vn is adjacent to va1 and v2na1. Therefore, N(v0)=N(vn).

    Theorem 3.6. Let n be odd. If a1,a2 are positive integers, where 1<a1<a2<n2, then the circulant graph C(n;{a1,a2}) is distance antimagic.

    Proof. Define a labeling q:V{1,2,,n} by q(vi)=i+1, for i=0,1,,n1. Thus, the following distinct vertex weights are obtained:

    ω(vi)={2n+4i+4,i=0,1,,a11,n+4i+4,i=a1,a1+1,,a21,4i+4,i=a2,a2+1,...,na21,4i+4n,i=na2,na2+1,...,na11,4i+42n,i=na1,na1+1,...,n1.

    Figure 6 illustrates an example of the labeling.

    Figure 6.  A distance antimagic labeling for C(15;{4,7}).

    In [16], Semeniuta proved that the circulant graph C(2m;{2,,m2,m}) is distance antimagic. Here, we provide some sufficient conditions for the distance antimagicness of circulant graphs with arbitrary generating sets. We start by using similar reasoning as in the proof of Theorem 3.5, which results in the following theorem.

    Theorem 4.1. Let k be an even integer and a1,a2,,ak1,ak,n be positive integers with a1<a2<<ak1<ak<n. If ai+aki+1=n, 1ik2, then:

    (1) The circulant graph C(2n;{a1,a2,,ak1,ak}) is not distance antimagic,

    (2) The circulant graph C(2n;{1,2,,n2,n1) is not distance antimagic, and

    (3) For even n, the circulant graph C(2n;{a1,a2,,ak2,n2,ak2+1,,ak1,ak}) is not distance antimagic.

    Theorem 4.2. Let m be an odd integer, m3, and n be a positive integer. If k is a positive integer, with k<n2, then the circulant graph C(mn;{k,nk,n+k,2nk,2n+k,,m2nk,m2n+k}) is not distance antimagic.

    Proof. Since k<n2, then k<nk<n+k<2nk<2n+k<<m2nk<m2n+k. And since m is odd, then m2=m12. Consider v0 and vn.

    v0 is adjacent to vi and vmni, i{k,nk,n+k,2nk,2n+k,...m2nk,m2n+k}, and

    vn is adjacent to vn+j and vmn+nj(modmn), j{k,nk,n+k,2nk,2n+k,...,m2nk,m2n+k}.

    Thus, N(v0)=N(vn).

    Two examples of circulant graphs that are not distance antimagic can be found in Figure 7.

    Figure 7.  The circulant graphs C(16;{3,4,5}) and C(15;{1,4,6}) that are not distance antimagic.

    Similarly, we can prove the following:

    Theorem 4.3. Let m be an odd integer, m3, and n be a positive integer. If b1,b2,,bk are positive integers, where b1<b2<<bk<n2, then the circulant graph C(mn;{b1,,bk,,m2nbk,,m2nb1,m2n+b1,,m2n+bk}) is not distance antimagic.

    This article completely characterizes distance antimagic circulant graphs with one generator. For circulant graphs with two generators, we completely characterized distance antimagic C(n;{1,k}) for odd n. For even n, we managed to only show the distance antimagicness of C(n;{1,k}) for k=2,3. Due to the many isomorphism properties within circulant graphs, for instance, C(n;{s1,,si,,sk})C(n;{s1,,nsi,,sk}) and C(n;{s1,,sk})C(n;{ts1,,tsk}), when gcd(n,t)=1, we automatically obtain some distance antimagic C(n;{a1,a2}), with a11. For more details on the isomorphism within circulant graphs, refer to [9,11].

    In general, the distance antimagicness of circulant graphs with more than two generators is still largely unknown. Therefore, we propose the following:

    Open problem 1. Determine all n and S such that a circulant graph C(n;S) is distance antimagic.

    Rinovia Simanjuntak: Conceptualization; Rinovia Simanjuntak and Tamaro Nadeak: Methodology, Formal analysis, Writing-original draft; Syafrizal Sy, Rinovia Simanjuntak, Tamaro Nadeak, Kiki Ariyanti Sugeng and Tulus Tulus: Writing-review & editing; Syafrizal Sy: Supervision; Syafrizal Sy, Kiki Ariyanti Sugeng and Tulus Tulus: Funding acquisition. All authors have read and approved the final version of the manuscript for publication.

    The authors declare they have not used Artificial Intelligence (AI) tools in the creation of this article.

    This research was supported by Riset Kolaborasi Indonesia (RKI) Skema A (Host) No. 7/UN16.19/PT.01.03/IS-RKI Skema A (Host)/2023.

    The authors declare no conflicts of interest.



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