1.
Introduction
In modern era, delay differential equations (DEs) have become almost the center of interest. Many things in the world are directed by differential systems. We assume that the systems are independent of past state and future state depends on present state neutral delays. DEs are natural extensions of the delay DE which involve derivatives of the unknown at the delayed argument. Mathematical modeling with delay DEs is widely used for analysis and predictions in various areas of life science, for example, population dynamics, epidemiology, immunology, neutral networks, chemistry, physics, engineering, etc. The literature connected to impulsive delay differential system is vast.
Below, we are going to provide some background of oscillation theory of impulsive DEs. The authors in [1] are concerned with the asymptotic behavior of a class of higher-order sublinear Emden-Fowler delay differential equations
where 0<ν<1 is a ratio of odd natural numbers, q2∈C1[ι0,∞), q2>0, q′2≥0, q1,τ∈C[ι0,∞), τ(ι)<ι, limι→∞τ(ι)=∞, q1(ι)≥0 and q2(ι) is not identically zero for large ι (for instanse, consider [2,3,4,5]). Shen et al. have taken the impulsive system (IS)
where q,Ik∈C(R,R), and they established the sufficient conditions for the oscillatory and asymptotic behavior of (1.2) [6]. Graef et al. in [7] considered the IS
and considering q2(ι)∈PC([ι0,∞),R+) (q2(ι) piece wisely continuous in [ι0,∞)) set up results on sufficient conditions for oscillation (1.3). Shen et al. have established new sufficient conditions for oscillation of the IS
and established some new conditions for the oscillation of (1.4) when q3(ι)∈PC([ι0,∞),R+) and ηi≤Ji(ϱ)ϱ≤1 [8]. Karpuz et al. [9] studied on advanced case, that is, taking a non homogeneous system and established the results for sufficient conditions for oscillation of (1.4). Tripathy et al. [10] have taken the following equations to establish the oscillatory and non-oscillatory character of a second order neutral impulsive differential system (IDS)
here k∈N, all coefficients and delays are constants. In [11] new result established for second-order neutral delay DS
where k∈N. Santra et al. [12] observed the characteristic of solutions for first-order neutral delay IS of the form
here k∈N, taking varying values of the neutral coefficient q2. Also, Santra et al. in [13] established the necessary and sufficient results for oscillation of the solutions of the below systems with impulses applying Lebesgue's Dominated convergent theorem,
where w(ι)=ϱ(ι)+ˊq(ι)ϱ(ˊσ(ι)), with
and −1≤ˊq(ι)≤0. In 2020, Li et al. studied the dynamic behavior of a computer worm system under a discontinuous control strategy and some conditions for globally asymptotically stable solutions of the discontinuous system were obtained by using the Bendixson–Dulac theorem, Green's formula and the Lyapunov function [14]. Also, they investigated the global dynamics of a controlled discontinuous diffusive SIR epidemic system under Neumann boundary conditions [15].
The authors observed oscillatory and non-oscillatory both conditions for the solutions of the non linear neutral DE of the form
At last we observed some modern results in [16] where Tripathy and Santra improved oscillatory results of non-linear neutral IS of the form
where w(ι)=ϱ(ι)+ˉq(ι)ϱ(ˊσ(ι)) with −1≤ˉq(ι)≤0 [17].
Motivated by the above works, in this paper, we consider the IS
where ℘i,qi,ˊq,σi are continuous and α be the quotient of two positive odd integers which satisfy the given following postulate as
(B1) σi∈C([0,∞),R), σi(ι)<ι, limι→∞σi(ι)=∞;
(B2) ˊq∈C1([0,∞),R), qi∈C([0,∞),R); ˊq(ι)>0, qi(ι)≥0, for each ι≥0 & i=1,2,…,m, ∑qi(ι)≠0 in any [τ,∞);
(B3) ϱi∈C(R,R) is non-decreasing and ℘i(ϱ)ϱ>0 for ϱ≠0(i=1,2,…,m);
(B4) limι→∞˚R(ι)=∞ where
(B5) α be the quotient of two positive odd integers and the sequence ιk satisfies ι1<ι2<⋯<ιk→∞, as k→∞.
The main objective of this paper is to find out both necessary and sufficient conditions for the oscillation of all solutions to IS (1.10). In this direction, we refer [18,19,20,21,22,23,24,25,26,27,28,29,30,31,32] to the readers for more details on this study. All functional inequalities assumed here should be held eventually i.e., for all large ι that also satisfy whereas the domain is not clearly given.
In Section 2, we recall some essential definition and necessary lemmas. Section 3 contains our main results in this work, while an example is presented to support the validity of our obtained results in Section 4. In Section 5, conclusion are presented.
2.
Primary consequences
First we start and prove the following key lemma.
Lemma 2.1. Consider postulates (B1)–(B4), and that ϱ is converges to zero for the Eq (1.10). So there exist ι1≥ι0 and δ>0, so we have
Proof. Suppose ϱ is converge to zero. From (B1) There exists ι∗ so that ϱ(ι)>0 and ϱ(σi(ι))>0, for all ι≥ι∗ and i=1,2,…,m. Then by (1.10) we get
So, ˊq(ι)(ϱ′(ι))α is non-increasing for ι≥ι∗. Then ˊq(ι)(ϱ′(ι))α>0. For contradiction let us consider
at a certain time ι≥ι∗. Applying ∑qi≠0 in [τ,∞), and that ℘(ϱ)>0 for ϱ>0, by (2.3), there exist ι2≥ι∗ we get
From (B5), we get
Taking integration from ι2 to ι, we get
Applying (B4), in the right part goes to −∞; so limι→∞ϱ(ι)=−∞. That contradict to ϱ(ι)>0. Consequently
By ˊq(ι)(ϱ′(ι))α is non-increasing, so we get
Now we integrate the above inequality ι1 to ι and applying ϱ is continuous we have
As limι→∞˚R(ι)=∞, then ∃δ>0 so that (2.1) satisfies. As
and non-increasing, so the limit of
non negatively exists. Taking integration (1.10) from ι to τ, we have
Calculating the limit when τ→∞,
Therefore
As ϱ(ι1)>0, integrating this inequality derives
As the integrand is positive, increasing the lower limit from η to ι, and after that using the definition of ˚R(ι), we have
this yields (2.2). □
3.
Main results
Now for next result we consider the a constant γ, which satisfy (B5) with γ<α, so that
is non-increasing for z>0(i=1,2,…,m).
Example 3.1. An instant ℘i(z)=|z|βsgn(z), with 0<β<γ holds this condition.
Theorem 3.2. Letting (B1)–(B5) and (3.1), each solution of (1.10) is oscillatory iff
Proof. We prove the sufficient part by contradiction. For the purpose of sufficient part prove, at the beginning let ϱ is eventually positive solution. As, Lemma 2.1 satisfies, and so that there exists ι1≥ι0, we have
where
As limι→∞˚R(ι)=∞, then there exists ι2≥ι1, so that ˚R(ι)−˚R(ι1)≥12˚R(ι), for ι≥ι2. Then
Therefore
Therefore from the above we see that w≥0 and decreasing. As ϱ is positive, from (B3), ℘i(ϱ(σi(ι))) is also positive, and by (B2), it gives us
in any [τ,∞); thus w′≠0 and w never be a constant in any interval [τ,∞). Thus w(ι) be also positive for ι≥ι1. Calculating derivative,
Integrating (3.4) from ι2 to ι, and applying w>0, we get
Next we search a lower bound for the right part of (3.5), which is not dependent of the solution ϱ. From (B3), (2.1), (3.1) and (3.3), we get
As w is non-increasing, γα>0, and σi(η)<η, it ensure us that
Returning to (3.5), we get
As 1−γα is positive, from (3.2) the right part goes to infinity as ι→∞. It is a contradiction (3.7) and completes the sufficient part of the eventually positive solutions. Now we find solution for negative ϱ, for that we set the variables ˊϱ=−ϱ and
Thus (1.10) converted to positive solution of ˊϱ and ˊ℘i in exchange with ℘i. Write after ˊ℘i satisfies (B3) and (3.1) then using the method for the solution ˊϱ from the above. In the subsequent part we prove the necessary condition by contrapositive thought. Whenever (3.2) does not satisfy we search an eventually positive solution which diverge to zero. Then for positive δ and for each positive ϵ there exists ι1≥ι0 if (3.2) does not satisfy so that
for all η≥ι1. Here ι1 rely on δ. Now here we are assume there exist set of continuous function
Next, we define an operator O on Υ by
Here we see that when ϱ is continuous, Oϱ is also continuous on [0,∞). If Oϱ=ϱ, i.e., ϱ is a fixed point of O(ϱ) is a solution of (1.10). Initially we calculate (Oϱ)(ι) from below. Since ϱ∈Υ, we get
By (B3), we get 0≤℘i(ϱ(σi(η))) and by (B2) we get
Then we calculate (Oϱ)(ι) from above. For ϱ in Υ, from (B2) and (B3), we get
From (3.8),
Thus, O maps Υ to Υ. Later on we will look for O in Υ. We are going to explain a sequence of function Υ by the iterative formula
Now when we fixed ι, we can get z1(ι)≥z0(ι). Applying that ℘ is non-decreasing and also using induction formula of mathematics, we can formulate that zn+1(ι)≥zn(ι). Thus, {zn} convergent sequence which converges to z∗ pointwise. Here we find the fixed point z∗ for the operator O in Υ applying dominated convergence theorem of Lebesgue. From consideration (3.8) shows that the solution is eventually positive i.e., does not converge to zero. Hence the proof of the theorem is complete.
□
For subsequent theorem, let us consider there exists a continuously differentiable function σ0 satisfying
Also, we suppose a constant γ, satisfy first part of (B5), and α<γ, such that
is non-decreasing for z>0(i=1,2,…,m). The Example 3.1, ℘i(z)=|z|βsgn(z) with γ<β holds this condition.
Theorem 3.3. Under assumptions (B1)–(B4), (3.9), (3.10), and ˊq(ι) is non-decreasing, every solution of (1.10) is converges to zero iff
Proof. Our aim to prove sufficient part by contradiction method. First we consider that the solution ϱ does not converges to zero. Applying similar logic same as in Lemma 2.1, we get ι1≥ι0 and ϱ(σi(ι)) is positive and
and non-increasing. Since ˊq(ι)>0 so ϱ(ι) is increasing for ι≥ι1. From (B3), ϱ(ι)≥ϱ(ι1) and (3.10), we have
From (B1) we can find ι2≥ι1 and also σi(ι)≥ι1 when ι≥ι2. Therefore
Using this inequality, (2.5), we have σi(ι)≥σ0(ι) which shows that σ is increasing, and ϱ is also so, thus
for ι≥ι2. From ˊq(ι)(ϱ′(ι))α being non-increasing and σ0(ι)≤ι, we get
We apply this in the left part of the above inequality. Additionally, dividing by ˊq(σ0(ι))>0, uplift right and left part to 1α index, and divided by ϱβ/γ(σ0(ι))>0, we get
for ι≥ι2. Multiply by σ′0(ι)/β≥1 left part, and taking integration from ι1 to ι,
As α<γ, taking integration left part of above inequality, we finally reach
Our main task is to show that (3.11) right part going to infinity as ι tends to infinity for that here apply
and ˊq(σ0(s))≤ˊq(s), (3.14) right part. For eventually negative solutions, we use the same change of variables as in Theorem 3.2, and proceed as above. To prove the necessary part we assume that (3.11) does not hold, and obtain an eventually positive solution that does not converge to zero. If (3.11) does not hold, then for each ϵ>0 there exists ι1≥ι0 such that
Construct the continuous functions
Now we define the operator O,
Note that if ϱ is continuous, for ι=ι1, O(ϱ) is a continuous function. Also as ϱ is a fixed point i.e., Oϱ=ϱ it give us that ϱ is a solution of (1.10). Our main criteria to calculate (Oϱ)(ι) from both equations for first part let ϱ∈Υ. By 0<ϵ2≤ϱ, we have
on [ι1,∞). For the next part let ϱ∈Υ. Then ϱ≤ϵ and from (3.15), we have
Hence O is a rules from Υ to Υ. For finding a fixed point of O we can construct a sequence of function by recursive rules
Now when we fixed ι, thus z1(ι)≥z0(ι). Applying ℘ is non-decreasing and also induction formula of mathematics, we can establish zn+1(ι)≥zn(ι) so that {zn} convergent sequence which converges to z in Υ pointwise. Hence, z be a positive solution of (1.10). This completes the proof.
□
4.
Conclusions and future scope
In this section, we are going to conclude the paper by providing two examples to show the effectiveness and feasibility of the main results.
Example 4.1. Consider the IS
Comparing with said systems we get α=113, ˊq(ι)=e−ι, σ1(ι)=ι−2, σ2(ι)=ι−1, from (1.11)
℘1(ϱ)=ϱ1╱3 and ℘2(ϱ)=ϱ5╱3. For β=73, we have
and
which both are non increasing. To verify (3.2), by employing (4.2), we have
as integrand goes to +∞ since η to positive infinity.
One can see these results in Tables 1 and 2. We can see graphical representation of the inequality (4.3) for η∈[0,0.6] and η∈[0,1.75] in Figure 1 (a) and (b), respectively, for η=1.5 and δ∈{0.5,2.5} in Figure 2. Algorithmes 1 and 2 can be used for this purpose.
Therefore, all the postulates of Theorem 3.2 hold true. Hence, by Theorem 3.2 all solution of (4.1) is oscillatory.
Example 4.2. Let us assume nonlinear IS
Now comparing with given system we have α=13, ˊq(ι)=1, σ1(ι)=ι−2, σ2(ι)=ι−1, from (1.11)
℘1(ϱ)=ϱ7╱3 and ℘2(ϱ)=ϱ11╱3. For {\rm{ \mathsf{ γ}}} = \frac{5}{3} , thus
also
two functions are increasing functions. To verify (3.11) we get
Therefore, all postulate of Theorem 3.3 hold true. Hence, by Theorem 3.3, all solution of (4.4) is oscillatory or converges to zero.
5.
Conclusions
After concluding the paper and introducing [16,17,22,23,25,29,30,33,34,35], we have an open question that "Can we find the necessary and sufficient conditions for the oscillatory solution of the second order neutral impulsive delay differential system with several delays and arguments"?
Use of AI tools declaration
The authors declare they have not used Artificial Intelligence (AI) tools in the creation of this article.
Acknowledgments
The authors are very grateful to the reviewers for their careful reading of the manuscript. M. Altanji's work has been supported by the Deanship of Scientific Research at King Khalid University through the Research Group program with Grant Number R.G.P2/91/44.
Conflict of interest
The authors declare that they have no competing interests.
Appendix