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Research article

Ricci curvature of semi-slant warped product submanifolds in generalized complex space forms

  • Received: 19 July 2021 Revised: 24 January 2022 Accepted: 26 January 2022 Published: 08 February 2022
  • MSC : 53C25, 53C40, 53C42, 53D15

  • The objective of this paper is to achieve the inequality for Ricci curvature of a semi-slant warped product submanifold isometrically immersed in a generalized complex space form admitting a nearly Kaehler structure in the expressions of the squared norm of mean curvature vector and warping function. In addition, the equality case is likewise discussed. We provide numerous physical applications of the derived inequalities. Later, we proved that under a certain condition the base manifold Nn1T is isometric to a n1-dimensional sphere Sn1(λ1n1) with constant sectional curvature λ1n1.

    Citation: Ali H. Alkhaldi, Meraj Ali Khan, Shyamal Kumar Hui, Pradip Mandal. Ricci curvature of semi-slant warped product submanifolds in generalized complex space forms[J]. AIMS Mathematics, 2022, 7(4): 7069-7092. doi: 10.3934/math.2022394

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  • The objective of this paper is to achieve the inequality for Ricci curvature of a semi-slant warped product submanifold isometrically immersed in a generalized complex space form admitting a nearly Kaehler structure in the expressions of the squared norm of mean curvature vector and warping function. In addition, the equality case is likewise discussed. We provide numerous physical applications of the derived inequalities. Later, we proved that under a certain condition the base manifold Nn1T is isometric to a n1-dimensional sphere Sn1(λ1n1) with constant sectional curvature λ1n1.



    Non-Newtonian fluids are defined as fluids with an extra-tension tensor that cannot be expressed as a linear, isotropic function of the components of the strain rate tensor.One of the goals of asymptotic analysis is to obtain and describe a two-dimensional problem from a three-dimensional problem, passing to the limit on the thickness of the domain assumed to be already thin. In this context, several previous studies have been conducted to deal with this problem.

    The first study we mention is what the authors have done in [4], where they mainly examine the existence and behavior of weak solutions for a lubrication problem with Tresca law. In another study, the authors in [1] gave the nonlinear Reynolds equations for non-Newtonian thin-film fluid flows over a rough boundary. Suárez-Grau in [25] studied the asymptotic behavior of a non-Newtonian flow in a thin domain with Navier law on a rough boundary. The convergence stability of the solutions for the non-Newtonian fluid motion with large perturbation in R2 has been given in [9]. In [20], the authors presented an extension of the results related to the solutions of weakly compressible fluids with pressure-dependent viscosity. In contrast, the existence and uniqueness of stationary solutions of non-Newtonian viscous incompressible fluids were obtained in [11]. Other contexts and problems be found in the monographs such as in [21,27], and in the literature quoted within.

    The Herschel-Bulkley fluid is a generalized model of a non-Newtonian fluid. The name is related to Winslow Herschel and Ronald Bulkley [15], and it was first mentioned, in 1926, where the relationship between the stress tensor σε and the symmetric deformation velocity d(uε) is given by:

    σεij=πεδij+μ|d(uε)|r2d(uε)+δεd(uε)|d(uε)|

    where, d(uε)=12(uε+(uε)T), uε is the velocity field, μ>0 is the viscosity constant, πε is the pressure, δε0 is the yield stress, 1<r2 is the power law exponent of the material and δij is the Kronecker symbol.

    In this paper, we will adopt the constitutive law by considering that a Herschel-Bulkley incompressible fluid whose viscosity will follow the power law with a liquid-solid friction condition of Coulomb in three-dimensional domain Qε R3.

    The Herschel-Bulkley fluid has been studied intensively by mathematicians, physicists, and engineers as intensively as the Navier-Stokes. For example, we mention the studies carried out in the fields of metal fluxes, plastic solids and some polymers. The literature concerning this topic is extensive; see e.g. [24,26] and many others references. More recently, the authors in [17], have studied the two-dimensional slow flow of non-Newtonian fluids of the Herschel-Bulkley type an inclined plane. In the context of the Bingham fluid, r=2, the authors in [8,22] proved the asymptotic convergence of this fluid in the isothermal and non-isothermal case with non linear friction law. In the case δε=0, with the particular conditions of Tresca, this problem has been studied by [5,6] respectively in both non-isothermal and isothermal study cases. Benseridi et al. in [3] studied theasymptotic analysis of a contact between two general Bingham fluids, however Saadallah et al. in [23] studied the analog of the problem presented in this work but in thevery particular case where the velocity on the surface Γb is null with the friction of the Tresca type. We can also mention others studies where authors gave the numerical solutions of the Herschel-Bulkley fluid but in other particular cases (see [14,16,18,19]).

    In this study, the objective is to make an extension of our previous works [8,22,23] and to improve the result obtained in [5,6].

    The novelty of our study can be summarized in following two major points. First, we take into account a generalized model of a non-Newtonian fluid (1<r2 and δε0). Second, we choose the Coulomb friction with the velocity of the lower surface Γb different to zero, since all previously mentioned works were restricted only to the particular friction of Tresca.

    From our side, this choice will cause different difficulties in other parts of the study, especially with regard to Lemma 5.1, Theorems 4.2–4.4 and the uniqueness theorem.

    Accordingly, this work makes the following new contributions by finding solutions to these problems:

    The first contribution consists of finding the solution for the first difficulty coming from the fact that the integral on Γb has no clear meaning. In our study, we will replace the normal stress by some regularization as in [10]. The second contribution consists of dealing with the problem of choosing the test functions. In fact, we cannot choose the test functions as it was done in [5,6], their work does not contain the yield stress δε.

    This remaining of our paper is organized as follows: Section 2 will summarize the description of the problem and the basic equations. Moreover, we introduce some notations and preliminaries that will be used in other sections. Section 3 will be reserved to the proof of the related weak formulation. We will also discussing the problem in transpose form. The corresponding main convergence results will be stated in Theorems (4.j), j=1 to 5 of Section 4. The mathematical proofs will be presented in Section 5.

    We start by introducing some notations used in the paper. Motivated by lubrication problems, we consider:

    Qε={y=(y,y3)R3:y=(y1,y2)Γb and 0<y3/ε<h(y)}

    the domain of the flow, where Γb is a non-empty bounded domain of R2 with a Lipschitz continuous boundary, h(.) is a Lipschitz continuous function defined on Γb such that 0<hh(y)h, for all (y,0) in Γb and ε is a small parameter that will tend to zero.

    We decompose the boundary of Qε as Γε=¯Γεu¯Γεl¯Γb with

    ¯Γb={(y,y3)ˉQε:y3=0},¯Γεu={(y,y3)ˉQε:(y,0)Γb y3/ε=h(y)},¯Γεl={(y,y3)ˉQε:yΓb0<y3<εh(y)},

    where Γb is the bottom of the domain, Γεu is the upper surface and Γεl the lateral part of Γε. Let uε(y):QεR3 be the velocity and πε(y):QεR the pressure of the fluid. We denote by η=(η1,η2,η3) the unit outward normal to the boundary Γε, and we define the normal and tangential velocities of uε on Γε as:

    uεη=uε.η  uετ=uεuε.η.

    Similarly, for a regular tensor field σε, we denote by σεη and σετ the normal and tangential components of σε given by

    σεη=3i=1(σεij.ηj).ηi  σετ=(3i=1σεij.ηj(σεη).ηi)1i3.

    Let S be denotes the set of all symmetric 3×3 matrices and for η,ζS, we define the scalar product and the corresponding norm by

    (η:ζ)=3i,j=1ηijζij and |η|=(η:η)12.

    The boundary-value problem describing the stationary flow for generalized non-Newtonian and incompressible fluid is described by:

    ProblemPε. Find the pressure πε:QεR and a velocity field uε:QεR3  such that

    div(σε)=fεin Qε (2.1)
    σεij=˜σεijπεδij,˜σε=δεd(uε)|d(uε)|+μ|d(uε)|r2d(uε) if d(uε)0,|˜σε|δε if d(uε)=0,}in Qε (2.2)
    div(uε)=0in Qε (2.3)
    uε=0on Γεu, (2.4)
    uε=g with g3=0on Γεl (2.5)
    uε.η=0on Γb (2.6)
    |σετ|<kε|σεη|uετ=s                    |σετ|=kε|σεη|β0:uετ=sβσετ}on Γb (2.7)

    where, fε=(fεi)1i3 is the body forces, s is the velocity of the bottom boundary Γb. Furthermore, the Eq (2.1) represents the law of conservation of momentum. Relation (2.2) gives the law of behavior of the Herschel-Bulkley fluid. The formula (2.3) represents the incompressibility equation. Equations (2.4) and (2.5) represent the velocity on Γεu and Γεl respectively. On the other hand, Eq (2.6) justified the no-flux through on Γb. However, assuming that the friction is sufficiently large, the tangential velocity is unknown and satisfies the Coulomb boundary condition (2.7) on the part Γb, with kε is the friction coefficient. This law introduced by [2] is one of the most spread laws in mathematics and it is more realistic than the law of Tresca.

    Suppose that the function g=(gi)1i3 is in (W11/r,r(Γε))3, the space of traces of functions from (W1,r(Qε))3 on Γε which will define in the next section. Due to Γεg.ndσ=0 that there exists a function Gε ([10]):

    Gε(W1,r(Qε))3 with div(Gε)=0 in QεGε=g on Γε.

    Also, we suppose that g3=0 on Γε and g=s on Γb.

    Before starting this study, we need to introduce the functional framework and the functional spaces that we use in the rest of this work: Let Lr(Qε) represents the Lebesgue space for the norm .Lr(Qε) and W1,r(Qε) are the standard Sobolev spaces given by

    (W1,r(Qε))3={v(Lr(Qε))3:viyjLr(Qε) for i,j=1,2,3}

    for 1<r<, and W1,r0(Qε) is the closure of D(Qε) in W1,r(Qε). We denoted by W1,q(Qε) the dual space of W1,r0(Qε), where r1+q1=1.

    Moreover, we need the following functional spaces

    Eε={v(W1,r(Qε))3:v=Gε on Γεl, v=0 on Γεuv.η=0 on Γb}Eεdiv={vEε:div(v)=0}Eq0(Qε)={vLq(Qε):Qεv dydy3=0}.

    Assume that the problem (Pε) admits a solution denoted by (uε,πε), with sufficient regularity. Multiplying (2.1) by (vuε)Eε and then using Green's formula, along with the boundary conditions (2.4)–(2.7), we obtain:

    ProblemPεK. We are looking for the velocity uεEεdiv and πεEq0(Qε), which verify:

             F(uε,vuε)(πε,divv)+˜j(uε,v)˜j(uε,uε)(fε,vuε), vEε (3.1)

    where

    F(uε,v)=μQε|d(uε)|r2d(uε)d(v)dydy3, (3.2)
    (πε,divv)=Qεπεdivvdydy3, (3.3)
    ˜j(uε,v)=Γbkε|σεη||vs| dy+2δεQε|d(v)|dydy3, (3.4)
    (fε,v)=3i=1Qεfεivi dydy3. (3.5)

    The integral ˜j(uε,v) has no meaning for uεEε. Indeed, σεη is defined by duality as an element of W12,r(Γb) and |σεη| is not well defined on Γb. So following [10], we replace σεη by some regularization R(σεη), where R is a regularization operator from W12,r(Γb) into Lr(Γb) can be obtained by convolution with a positive regular function and defined by

    τW12,r(Γb), R(τ)L2(Γb), R(τ)(x)=τ,ϕ(xt)W12,r(Γb),W12,r00(Γb) xΓb, (3.6)

    ϕ is a given positive function of class C with compact support in Γb and W12,r(Γb) is the dual space to W12,r00(Γb)={v|Γb:vW1,r(Qε),v=0 on ΓεuΓεl}.

    After the regularization, we get the new problem:

    ProblemPε,rK. Find (uε,πε)Eεdiv ×Eq0(Qε), provided it verifies the problem:

             F(uε,vuε)(πε,divv)+j(uε,v)j(uε,uε)(fε,vuε), vEε (3.7)

    where

    j(uε,v)=Γbkε|R(σεη)||vs| dy+2δεQε|d(v)|dydy3.

    Remark 3.1. If vEεdiv the inequality (3.7) becomes

             F(uε,vuε)+j(uε,v)j(uε,uε)(fε,vuε)vEε. (3.8)

    Theorem 3.1. For fεLq(Qε)3 and kε>0 in L(Γb); then the problem Pε,rK admits a unique pair (uε,πε)Eεdiv×Eq0(Qε) verifying (3.7). Moreover, for a small value of the friction threshold kε, this solution becomes unique.

    Proof. To show the existence and uniqueness result of (3.7), we define the following intermediate problem:

    F(uε,vuε)+ΓbY(|vs||uεs|) dy+δEεdiv(v)δEεdiv(uε)(fε,vuε), vW1,rdiv(Qε)3 (3.9)

    where, Y defined from Lr(Γb) into Lr(Γb) as: YkεR(σεη) and

    W1,rdiv(Qε)3={vW1,r(Qε)3:div(v)=0},δEεdiv={0 for vEεdiv+ otherwise .

    By the analog of the techniques used in [16], it is easy to see that F(uε,vuε) is bounded coercive hemicontinuous and strictly monotone.

    Y+δEεdiv is a proper, convex and continuous function on Lr(Γb), then by Tichovo's fixed point theorem (as in [7]), we ensure the existence of a unique uε Eεdiv verifying the variational inequality (3.9). The existence of the pressure πεEq0(Qε) such that (uε,πε) satisfy (3.7) is found in [12].

    In this subsection, we use the dilatation in the variable y3 given by y3=zε, then our problem will be defined on a domain Q does not depend on ε given by:

    Q={(y,z)R3:(y,0)Γb,0<z<h(y)}

    and its boundary Γ=¯Γu¯Γl¯Γb.

    After this change of scale following the third component, it is normal to give the new functions and the new data defined on the new fixed domain Q:

    ˆuεi(y,z)=uεi(y,y3),i=1,2, ˆuε3(y,z)=ε1uε3(y,y3) and  ˆπε(y,z)=εrπε(y,y3). (3.10)
    ˆf(y,z)=εrfε(y,y3), ˆδ=εr1δε, ˆk=εr1kε, (3.11)
    ˆg(y,z)=g(y,y3),^Gi(y,z)=Gεi(y,y3)i=1,2^G3(y,y3)=ε1Gε3(y,y3) also div(ˆG)=0 and ˆG=ˆg on Γ (3.12)

    with all the new notations given in (3.11) and (3.12) do not depend on ε.

    Also, we denote by:

    E={ˆv(W1,r(Q))3:ˆv=ˆGon Γl,ˆv=0onΓu;ˆv.n=0 on Γb}Ediv={ˆvE(Q):divˆv=0}Ξ(E)={ˆv(W1,r(Q))2:ˆvi=ˆGi on Γl,ˆvi=0onΓui=1,2}˜Ξ(E)={ˆvΞ(E):ˆvsatisfy (3.13)}

    where the condition (3.13) is given by

     Q(ˆv1ωy1+ˆv2ωy2)dydz=0, for all ˆv(Lr(Q))2 and ωC0(Q). (3.13)

    Finally, the Banach space Θz and its linear subspace ˜Θz are denoted by:

    Θz={ˆv(Lr(Q))2;ˆvizLr(Q)i=1,2:ˆv=0 on Γu},
    ˜Θz={ˆvΘz:ˆvsatisfy the condition (3.13)},

    with the norm of Θz is given as follows:

    ˆvrΘz=2i=1(ˆvirLr(Q)+ˆvizrLr(Q)).

    By introducing all these new notations into the variational inequality (3.7), and then multiplying all the terms deduced by εr1 after this scaling, then the problem Pε,rK takes the following form:

    Problem PK. Find (ˆuε,ˆπε)Ediv ×Eq0(Q), such that

     ˆF(ˆuε,ˆvˆuε)(ˆπε,div(ˆvˆuε))+ˆj(ˆuε,ˆv)ˆj(ˆuε,ˆuε)(ˆf,ˆvˆuε), ˆvE (3.14)

    where

    ˆF(ˆuε,ˆvˆuε)=2i,j=1Q[ε2μ|˜d(ˆuε)|r2(12(ˆuεiyj+ˆuεjyi))](ˆviˆuεi)yjdydz+2i=1Qμ|˜d(ˆuε)|r2(12(ˆuεiz+ε2ˆuε3yi))(ˆviˆuεi)zdydz+Q(μ|˜d(ˆuε)|r2ε2ˆuε3z)(ˆv3ˆuε3)zdydz+2j=1Qε2μ|˜d(ˆuε)|r2(12(ε2ˆuε3yj+ˆuεjz))(ˆv3ˆuε3)yjdydz
    (ˆπε,div(ˆvˆuε))=Qˆπεdiv(ˆvˆuε)dydz,ˆj(ˆuε,ˆv)=Γbˆk|R(ˆσεη)||ˆvs|dy+2ˆδQ|˜d(ˆv)|dydz,(ˆf,ˆvˆuε)=2i=1Qˆfi(ˆviˆuεi)dydz+Qεˆf3(ˆv3ˆuε3)dydz,
    |˜d(ˆuε)|=(142i,j=1ε2(ˆuεiyj+ˆuεjyi)2+122i=1(ˆuεiz+ε2ˆuε3yi)2+ε2(ˆuε3z)2)1/2.

    We introduce some results found in [4] which we will need to use in the rest of this work.

    vεLr(Qε)Cd(vε)Lr(Qε), (3.15)
    vεLr(Qε)εhvεzLr(Qε), (3.16)
    αβαrr+βqq, (α,β)R2. (3.17)

    The convergence results of (ˆuε,ˆπε) towards (u,π) as well as the limit problem independently of the parameter ε will be given in the next of this subsection.

    Theorem 4.1. Assume that the assumptions of Theorem 3.1 hold, there exist πEq0(Q) and u=(u1,u2)˜Θz satisfy the following convergences:

    ˆuεiui in  ˜Θz,  1i2, (4.1)
    εˆuεiyj0, in Lr(Q),  1i,j2, (4.2)
    εˆuε3z0,  in Lr(Q), (4.3)
    ε2ˆuε3yi0, in Lr(Q),  1i2, (4.4)
    εˆuε30,  in Lr(Q), (4.5)
    ˆπεπ,in Eq0(Q), with  π depend only of y. (4.6)

    Theorem 4.2. With the same assumptions as Theorem 4.1, the pair (u,π) satisfies:

    ˆuεiui,  strongly  in ˜Θz , i=1,2, 1<r2, (4.7)
    μ2i=1Q12(122i=1(uiz)2)r22(ui)z(ˆviui)zdydzQπ(y) (ˆv1y1+ˆv2y2)dydz+ˆδ22Q(|ˆvz||uz|)dydz+Γbˆk|R(π)|(|ˆvs||us|)dy 2i=1Qˆfi(ˆviui)dydz,ˆvΞ(E). (4.8)

    Theorem 4.3. Suppose that the assumptions of the previous theorem hold, and if |uz|0, the solution (u,π) satisfies

    πW1,q(Γb) (4.9)
    z[12μ(122i=1(uiz)2)r22uz+ˆδ22u/z|u/z|]=ˆfπ, in Lq(Q)2. (4.10)

    Theorem 4.4. Suppose that the assumptions of Theorem 4.2 hold, then τ, s satisfy the inequality:

    2i=1Γbˆk|R(ˆση(π))|ϕi(sisi)dyΓbˆμτϕ|ss|dy0, ϕLr(Γb)2 (4.11)

    and the limit form of Coulomb law:

    μ|τ|<ˆk|R(ˆση(π))|s=sμ|τ|=ˆk|R(ˆση(π))|β0:s=s+βτ} a.e. in Γb. (4.12)

    Also, the solution (u,π) satisfies the weak generalized form:

    Γb[h312π+˜H+μh0y0B(y,ξξ)u(y,ξ)ξdξdy+ˆδh0y0u/z|u/z|(y,ξ)dξdy].v(y)dy+Γb[hμ2h0B(y,ξξ)u(y,ξ)ξdξˆδh2h0u/z|u/z|(y,ξ)dξ]v(y)dy,vW1,r(Γb), (4.13)

    where

    τ=B(y,0)uz(y,0), s=uz(y,0), B(y,ξ)=12(122i=1(uz(y,ξ))2)r22˜H(y,h)=h0H(y,y)dyh2H(y,h), H(y,y)=y0ξ0ˆf(y,t)dtdξ.

    Theorem 4.5. For ˆfLq(Q)3 and ˆk>0 in L(Γb); there exists ¯k>0 sufficiently small such that for ˆkL(Γb)¯k, the solution (u,π) of the limiting problem (4.8) is unique in ˜Θz×(Eq0(Γb)W1,q(Γb))2.

    Proof of Theorem 4.1. Before starting the proof of this theorem, we need the following estimates which can be considered as the key that allows us to make a passage to the limit when ε tends to zero.

    Lemma 5.1. Assume that fεLq(Qε)3 and let (uε,πε)Eεdiv×Eq0(Qε) be a solution of Pε,rK, where the friction coefficient kε>0 in L(Γb). Then there exists a constant C independent of ε such that

    2i,j=1εˆuεiyjrLr(Q)+εˆuε3zrLr(Q)+2i=1(ˆuεizrLr(Q)+ε2ˆuε3yirLr(Q))C (5.1)
    ˆπεyiW1,q(Q)C,  for i=1,2, (5.2)
    ˆπεzW1,q  (Q)εC. (5.3)

    Proof of Lemma 5.1. Choosing v= Gε in (3.8) and using the fact that Gε=s on Γb, we find

    F(uε,uε)F(uε,Gε)+(fε,uε)(fε,Gε). (5.4)

    By applying Korn's inequality, we ensure the existence of a constant CK>0 that does not depend on ε with:

    F(uε,uε)2μCKuεrLr(Q). (5.5)

    Now we apply Hölder's inequality and then Young's, the increase of the first term of (5.4) is given by

    F(uε,Gε)μCK2Qεμ|d(uε)|q(r1)dydy3+2(r1)  μr(qCK)r/qQε|d(Gε)|rdydy3. (5.6)

    By (3.15), the inequality (5.6) becomes

    F(uε,v)uεrLr(Qε)+2(r1)  μr(qCK)r/qGεrLr(Qε). (5.7)

    We apply (3.16) and (3.17), we obtain the analogue of (5.7)

    |(fε,uε)|μCK2uεrLr(Qε)+(εh)qq(12μrCK)q/rfεqLq(Qε) (5.8)
    |(fε,Gε)|μCK2GεrLr(Qε)+(εh)qq(μ2rCK)q/rfεqLq(Qε). (5.9)

    Now, from (5.4)(5.9), we obtain

    μCKuεrLr(Q)(2(r1)μr(qCK)r/q+μCK2)GεrLr(Qε)+2(εh)qq(μ2rCK)q/rfεqLq(Qε). (5.10)

    We multiply (5.10) by εr1 then using the fact that

    εqfεqLq(Qε)=ε1rˆfqLq(Q)

    and

    uεix3rLr(Qε)=ε1rˆuεizrLr(Q),

    for i=1,2, we deduce (5.1) with

    C=1μCK[(2(r1)μr(qCK)r/q+μCK2)ˆGrLr(Q)+2(εh)qq(μ2rCK)q/rˆfqLq(Q)].

    For get the estimate (5.2), we choose in (3.14), ˆv=ˆuε+ϕ, with ϕW1,r0(Q)3, we find

    F(ˆuε,ϕ)(ˆπε,divϕ)+ˆδQ|˜d(ˆuε+ϕ)|dydzˆδQ|˜d(ˆuε)|dydz(ˆfε,ϕ),

    then

    (ˆπε,divϕ)a(ˆuε,ϕ)+2ˆδQ|˜d(ˆuε+ϕ)|dydz2ˆδQ|˜d(ˆuε)|dydz(ˆfε,ϕ),

    as

    |˜d(ˆuε+ϕ)|2|˜d(ˆuε)|+2|˜d(ϕ)|,

    we obtain

    (ˆπε,divϕ)a(ˆuε,ϕ)+2ˆδQ|˜d(ϕ)|dydz+(22)ˆδQ|˜d(ˆuε)|dydzQˆfϕdydz.

    As

    ˜d(ϕ)Lr(Q)ϕW1,r(Q)3 ,ε]0,1[.

    By Hölder's inequality, we get

    (ˆπε,divϕ)μd(ˆuε)rqLr(Q)ϕW1,r(Q)3+2ˆδ|Q|1qϕW1,r(Q)3+(22)ˆδ|Q|1qˆuεW1,r(Q)3+ˆfLq(Q)3ϕW1,r(Q)3. (5.11)

    We apply the results of (5.1) , we have:

    \begin{equation} \int_{\mathbb{Q}}\dfrac{\partial \widehat{\pi}^{\varepsilon}}{\partial y_{i}}\, \, \phi dy'dz\leq \mu C\left \Vert \phi \right \Vert _{_{W^{1, r}\left( \mathbb{Q} \right) \ \ ^{3}}} +2\hat{\delta}\left \vert \mathbb{Q} \right \vert ^{\frac{1}{q}}\left \Vert \phi \right \Vert _{_{W^{1, r}\left( \mathbb{Q} \right) \ \ ^{3}}}+\left( 2-\sqrt {2}\right) \hat{\delta}\left \vert \mathbb{Q} \right \vert ^{\frac{1}{q} }C+\left \Vert \hat{f}\right \Vert _{_{L^{q}\left( \mathbb{Q} \right) \ \ ^{3}} }\left \Vert \phi \right \Vert _{W^{1, r}\left( \mathbb{Q} \right) \ \ ^{3}}. \end{equation} (5.12)

    The same, we choose in (3.14) : \hat{v} = \hat {u}^{\varepsilon}-\phi, \phi \in W_{0}^{1, r}\left(\mathbb{Q} \right) ^{3} , we obtain

    \begin{equation} \begin{array} [c]{c} -\int_{\mathbb{Q}}\dfrac{\partial \widehat{\pi}^{\varepsilon}}{\partial y_{i} }\, \, \phi dy'dz\leq \mu \left \Vert d(\hat{u}^{\varepsilon})\right \Vert _{L^{r}\left( \mathbb{Q} \right) \ \ }^{\frac{r}{q}}\left \Vert \phi \right \Vert _{_{W^{1, r}\left( \mathbb{Q} \right) \ \ ^{3}}}+2\hat{\delta}\left \vert \mathbb{Q} \right \vert ^{\frac{1}{q}}\left \Vert \phi \right \Vert _{_{W^{1, r}\left( \mathbb{Q} \right) \ \ ^{3}}}\\ \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; +\left( 2-\sqrt{2}\right) \hat{\delta}\left \vert \mathbb{Q} \right \vert ^{\frac{1}{q}}C+\left \Vert \hat{f}\right \Vert _{_{L^{q}\left( \mathbb{Q} \right) \ \ ^{3}}}\left \Vert \phi \right \Vert _{W^{1, r}\left( \mathbb{Q} \right) \ \ ^{3}}\text{.} \end{array} \end{equation} (5.13)

    From (5.12) and (5.13) , we deduce

    \begin{equation} \begin{array} [c]{c} \left \vert \int_{\mathbb{Q}}\dfrac{\partial \widehat{\pi}^{\varepsilon}}{\partial x_{i}}\, \, \phi dy'dz\right \vert \leq \mu \left \Vert d(\hat{u}^{\varepsilon})\right \Vert _{L^{r}\left( \mathbb{Q} \right) \ \ }^{\frac{r}{q}}\left \Vert \phi \right \Vert _{_{W^{1, r}\left( \mathbb{Q} \right) \ \ ^{3}}}+2\hat{\delta}\left \vert \mathbb{Q} \right \vert ^{\frac{1}{q}}\left \Vert \phi \right \Vert _{_{W^{1, r}\left( \mathbb{Q} \right) \ \ ^{3}}}\\ \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; +\left( 2-\sqrt{2}\right) \hat{\delta}\left \vert \mathbb{Q} \right \vert ^{\frac{1}{q}}C+\left \Vert \hat{f}\right \Vert _{_{L^{q}\left( \mathbb{Q} \right) \ \ ^{3}}}\left \Vert \phi \right \Vert _{W^{1, r}\left( \mathbb{Q} \right) \ \ ^{3}}\text{.} \end{array} \end{equation} (5.14)

    Choosing \phi = \left(\phi_{1}, 0, 0\right) then \phi = \left(0, \phi_{2}, 0\right) , in (5.14) , we find

    \begin{equation} \left \vert \int_{\mathbb{Q}}\dfrac{\partial \widehat{\pi}^{\varepsilon}}{\partial x_{i}}\, \, \phi dy'dz\right \vert \leq \left( \mu C+2\hat{\delta}\left \vert \mathbb{Q} \right \vert ^{\frac{1}{q}}+\left \Vert \hat {f}_{i}\right \Vert _{_{L^{q}\left( \mathbb{Q} \right) }}\right) \left \Vert \phi \right \Vert _{_{W^{1, r}\left( \mathbb{Q} \right) \ \ ^{3}}}+\left( 2-\sqrt {2}\right) \hat{\delta}\left \vert \mathbb{Q} \right \vert ^{\frac{1}{q}} C\text{.}\nonumber \end{equation}

    Then (5.2) follows for i = 1, 2 .

    For get (5.3) , we take in the inequality (5.14) , \phi = \left(0, 0, \phi_{3}\right), we find

    \begin{align*} &\dfrac{1}{\varepsilon}\left \vert \int_{\mathbb{Q}}\dfrac{\partial \widehat {p}^{\varepsilon}}{\partial z}\, \, \phi dy'dz\right \vert \\ \leq & \left( C+2\hat{\delta}\left \vert \mathbb{Q} \right \vert ^{\frac{1}{q}}+\left \Vert \hat {f}_{3}\right \Vert _{_{L^{q}\left( \mathbb{Q} \right) }}\right) \left \Vert \phi \right \Vert _{_{W^{1, r}\left( \mathbb{Q} \right) \ \ ^{3}}}+\left( \sqrt {2}-1\right) \hat{\delta}\left \vert \mathbb{Q} \right \vert ^{\frac{1}{q}}C\text{.} \end{align*}

    Which completes the proof of Lemma 5.1.

    Now, the convergence (4.1) (4.6) of Theorem 4.1 are a direct result of inequalities (5.1) (5.3) . Indeed, by (5.1) , \exists C > 0 not related to \varepsilon , and verifying

    \begin{equation} \left \Vert \dfrac{\partial \hat{u}_{i}^{\varepsilon}}{\partial z}\right \Vert _{_{L^{r}\left( \mathbb{Q} \right) }}\leq C\text{, for }i = 1, 2. \end{equation} (5.15)

    It is clear that (4.1) deduces directly from (5.15) and the using of the Poincaré's inequality in the fixed domain \mathbb{Q} . Also (4.2) (4.4) follows from (5.1) . The obtaining of (4.5) is done as in [6]. Finally, it is easy (4.6) follows from (5.2) and (5.3) .

    In order to proceed to the proof of strong convergence (4.7) of Theorem 4.2, it suffices to demonstrate the strong convergence of the integral term defined on \Gamma_b .

    Lemma 5.2. Let R is a regularization operator from W^{-\frac{1}{2}, r}(\Gamma_b) into L^{r}(\Gamma_b) , then the choice of R ensures the existence of a subsequence of R(\widehat{\sigma}_{\eta}^{\varepsilon}\left(\hat{u}^{\varepsilon }, \widehat{\pi}^{\varepsilon}\right)) strongly converges to R\left(-\pi^{\star}\right) in L^{r}\left(\Gamma_b \right) .

    Proof of Lemma 5.2. From the equilibrium Eq (2.1) , we have

    \begin{array} [b]{cc} -\operatorname{div}\left( \sigma^{\varepsilon}\right) = f^{\varepsilon} & \text{in }\mathbb{Q}^{\varepsilon}\text{, } \end{array}

    with f^{\varepsilon}\in \left(L^{q}\left(\mathbb{Q} \right) \right) ^{3} . By the results of Theorem 4.1, we deduce that \left(\hat {u}^{\varepsilon}, \widehat{\pi}^{\varepsilon}\right) are bounded in \widetilde\Theta _{z} \times E_{0}^{q}(\mathbb{Q}) , then \widehat {\sigma}^{\varepsilon} is bounded in

    H_{\operatorname{div}} = \left \{ v\in \left( L^{r}\left( \mathbb{Q} \right) \right) ^{3}:\operatorname{div}(v)\in L^{q}\left( \mathbb{Q} \right) \right \} \text{, }

    which shows that there exists a subsequence converging weakly towards \sigma^{\star} . Now, we show that \widehat{\sigma}_{\eta} (\widehat{u}^{\varepsilon}, \widehat{\pi}^{\varepsilon}) converges weakly to \left(-\pi^{\star}\right) in W^{\frac{-1}{2}, r}(\Gamma_b) .

    Indeed, as \sigma_{\eta}^{\varepsilon} = \sigma_{ij}^{\varepsilon}\eta_{i}\eta_{j}, 1\leq i, j\leq3 , we have

    \begin{array} [c]{c} \widehat{\sigma}_{\eta}(\widehat{u}^{\varepsilon}, \widehat{\pi}^{\varepsilon} ) = \underset{i = 1}{\overset{2}{\sum\limits}}\left( \varepsilon^{2} \mu \left \vert \tilde{d}\left( \hat{u}^{\varepsilon}\right) \right \vert ^{r-2}\dfrac{\partial \hat{u}_{i}^{\varepsilon}}{\partial y_{i}}+\varepsilon \hat{\delta}\left( \left \vert \tilde{d}\left( \hat{u}^{\varepsilon}\right) \right \vert \right) ^{-1}\dfrac{\partial \hat{u}_{i}^{\varepsilon}}{\partial x_{i}}-\pi ^{\varepsilon }\right) \\ \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; \; +\left( \varepsilon^{2} \mu \left \vert \tilde{d}\left( \hat{u}^{\varepsilon}\right) \right \vert ^{r-2}\dfrac{\partial \hat{u}_{3}^{\varepsilon}}{\partial z}+\varepsilon \hat{\delta}\left( \left \vert \tilde{d}\left( \hat{u}^{\varepsilon}\right) \right \vert \right) ^{-1}\dfrac{\partial \hat{u}_{3}^{\varepsilon}}{\partial z}-\pi ^{\varepsilon }\right). \end{array}

    Since \widehat{\sigma}^{\varepsilon} is bounded in H_{div} (\mathbb{Q}) , then there exists a subsequence converging weakly towards \sigma^{\star} in H_{div}(\mathbb{Q}) . Using the fact that the trace operator is continuous from H_{div}(\mathbb{Q}) into W^{\frac{-1}{2}, r}(\Gamma_b) , we therefore obtain the weakly convergence of \widehat {\sigma}_{\eta}(\widehat{u}^{\varepsilon}, \widehat{\pi}^{\varepsilon}) to \widehat{\sigma}_{\eta}(u^{\star}, \pi^{\star}) in W^{\frac{-1}{2}, r}(\Gamma_b) . We apply now the results of Theorem 4.1 in the formula of \widehat{\sigma}_{\eta}(\widehat{u}^{\varepsilon}, \widehat{\pi}^{\varepsilon}) , we obtain the desired result.

    For the rest of proof, using the same techniques as in [2,13], we get the result.

    Proof of Theorem 4.2. For u^{\varepsilon} the solution on (3.8) , we obtain for v \in E_{div}^{\varepsilon }

    \begin{align*} &F(u^{\varepsilon}, u^{\varepsilon}-v)-F(v, u^{\varepsilon} -v)-j(u^{\varepsilon}, v)+j\left( u^{\varepsilon}, u^{\varepsilon }\right) \\ \leq& (f^{\varepsilon}, v-u^{\varepsilon})+F(v , u^{\varepsilon}-v)\text{.} \end{align*}

    Using the inequality as ([24])

    \begin{equation} \left( \left \vert a\right \vert ^{r-2}a-\left \vert b\right \vert ^{r-2} b, a-b\right) \geq \left( r-1\right) \left( \left \vert a\right \vert +\left \vert b\right \vert \right) ^{r-2}\left \vert a-b\right \vert ^{2} , \text{ for } \ a, b\in \mathbb{R}^{n} \text{ and } \ r\in \left] 1, 2\right[ \end{equation} (5.16)

    and by using the Korn's inequality, we find

    \begin{array} [c]{c} \left( r-1\right) \mu C_{K} { \sum \limits_{i, j = 1}^{3}} \int_{\mathbb{Q}^{\varepsilon}}\left( \left \vert \frac{\partial u_{i} ^{\varepsilon}}{\partial y_{j}}\right \vert ^{r-2}+\left \vert \frac {\partial v_{i}}{\partial y_{j}}\right \vert ^{r-2}\right) \left( \left \vert \frac{\partial}{\partial y_{j}}(u_{i}^{\varepsilon}-v _{i})\right \vert ^{2}\right) dy'dy_{3}\\ -j(u^{\varepsilon}, v)+j\left( u^{\varepsilon}, u^{\varepsilon}\right) \leq(f^{\varepsilon}, u^{\varepsilon}-v)+F(v, u^{\varepsilon }-v)\text{.} \end{array}

    We multiply the last formula by \varepsilon^{r-1} , as well as the convergence of Theorem 4.1, we get in the fixed domain \mathbb{Q}

    \begin{array} [c]{c} \left( r-1\right) \mu C_{K} { \sum \limits_{i = 1}^{2}} \left \Vert \dfrac{\partial}{\partial z}\left( \hat{u}_{i}^{\varepsilon }-\widehat{v}_{i}\right) \right \Vert _{L^{r}(\mathbb{Q})}^{r} dy'dz-\widehat{j}(\hat{u}^{\varepsilon}, \widehat{v})+\widehat{j}\left( \hat{u}^{\varepsilon}, \hat{u}^{\varepsilon}\right) \\ \leq \underset{i = 1}{\overset{2}{\sum\limits}}\int_{\mathbb{Q}}\hat{f}_{i}(\hat{u} _{i}^{\varepsilon}-\hat{v}_{i})dy'dz+a(\widehat{v}, \hat {u}^{\varepsilon}-\widehat{v})\text{.} \end{array}

    We pose, \overline{u}^{\varepsilon} = (\hat{u}_{1}^{\varepsilon}, \hat{u}_{2}^{\varepsilon}), u^{\star} = (u_{1}^{\star}, u_{2}^{\star}), \overline{v} = (\widehat{v}_{1}, \widehat{v}_{2}) , so \overline{v}\in \widetilde{\Xi}(E) and

    \begin{align*} & \lim\limits_{\varepsilon \rightarrow0}\sup \left[ \left( r-1\right) \mu C_{K}\left \Vert \frac{\partial}{\partial z}\left( \overline{u}^{\varepsilon }-\widehat{v}_{i}\right) \right \Vert _{L^{r}(\mathbb{Q})}^{r} dy'dz-\widehat{j}(\overline{u}^{\varepsilon}, \overline{v})+\widehat {j}\left( \overline{u}^{\varepsilon}, \overline{u}^{\varepsilon}\right) \right] \\ & \leq \mu \int_{\mathbb{Q}}\left( \frac{1}{2}\underset{i = 1}{\overset{2}{\sum\limits} }\left( \dfrac{\partial \widehat{v}_{i}}{\partial z}\right) ^{2}\right) ^{\frac{r-2}{2}}\frac{\partial \overline{v}}{\partial z}\frac{\partial}{\partial z}\left( \overline{v}-u^{\star}\right) dy'dz+\underset{i = 1}{\overset{2}{\sum\limits}}\int_{\mathbb{Q}}\hat{f}_{i}(u_{i}^{\star }-\hat{v}_{i})dy'dz. \end{align*}

    Consequently,

    \begin{align*} & \left( r-1\right) \mu C_{K}\left \Vert \frac{\partial}{\partial z}\left( \overline{u}^{\varepsilon}-\overline{v}\right) \right \Vert _{L^{r}(\mathbb{Q})}^{r}dy'dz-\widehat{j}(\overline{u}^{\varepsilon}, \overline {v})+\widehat{j}\left( \overline{u}^{\varepsilon}, \overline {u}^{\varepsilon}\right) \\ & \leq \mu \int_{\mathbb{Q}}\left( \frac{1}{2}\underset{i = 1}{\overset{2}{\sum\limits} }\left( \dfrac{\partial \widehat{v}_{i}}{\partial z}\right) ^{2}\right) ^{\frac{r-2}{2}}\frac{\partial \overline{v}}{\partial z}\frac{\partial}{\partial z}\left( \overline{v}-u^{\star}\right) dy'dz+\underset{i = 1}{\overset{2}{\sum\limits}}\int_{\mathbb{Q}}\hat{f}_{i}(u_{i}^{\star }-\hat{v}_{i})dy'dz+\eth, \end{align*}

    for \varepsilon < \varepsilon(\eth) , where \eth > 0 is arbitrary.

    Therefore, \exists \overline{v}\in \widetilde{\Xi}(E):\overline{v}\rightarrow u^{\star} in \widetilde\Theta _{z} , which gives

    \left( r-1\right) \mu C_{K}\left \Vert \frac{\partial}{\partial z}\left( \overline{u}^{\varepsilon}-u^{\star}\right) \right \Vert _{L^{r}(\mathbb{Q})}^{r}dy'dz+\widehat{j}\left( \overline{u}^{\varepsilon }, \overline{u}^{\varepsilon}\right) -\widehat{j}(\overline{u}^{\varepsilon }, u^{\star})\leq \eth \text{, }\forall \varepsilon < \varepsilon(\eth)\text{.}

    Now, since \lim \inf \widehat{j}\left(\overline{u}^{\varepsilon }\right) \geq \widehat{j}\left(u^{\star}\right) , we deduce: \overline{u}^{\varepsilon}\rightharpoonup u^{\star} in \widetilde\Theta _{z} . Furthermore, \widehat{j}\left(\overline{u}^{\varepsilon }, \overline{u}^{\varepsilon}\right) \rightarrow \widehat{j}(\overline {u}^{\varepsilon}, u^{\star}) for \varepsilon \rightarrow0 , which gives the convergence (4.7) .

    If r = 2 , we follow the same techniques but (5.16) we will be replaced by

    \begin{equation} \left( \left \vert a\right \vert ^{r-2}a-\left \vert b\right \vert ^{r-2} b, a-b\right) \geq \left( 1/2\right) ^{r-1}\left \vert a-b\right \vert ^{r}, \text{ for } \ a, b\in \mathbb{R}^{n}. \end{equation} (5.17)

    For the proof of the inequality (4.8) , we introduce in (3.14) the condition of incompressibility of the fluid ( \operatorname{div}\left(\hat{u}^{\varepsilon}\right) = 0 in \mathbb{Q} ), then by the application of Minty's Lemma, we deduce:

    \begin{align*} & F(\hat{v}, \hat{v}-\hat{u}^{\varepsilon})-\underset {i = 1}{\overset{2}{\sum\limits}}\left( \widehat{\pi}^{\varepsilon}\, , \frac{\partial \hat{v}_{i}}{\partial y_{i}}\right) -\left( \widehat{\pi}^{\varepsilon }\, , \frac{\partial \hat{v}_{3}}{\partial z}\right) +\widehat{j}(\hat {u}^{\varepsilon}, \hat{v})-\widehat{j}\left( \hat{u}^{\varepsilon} , \hat{u}^{\varepsilon}\right) \\ & \geq \underset{i = 1}{\overset{2}{\sum\limits}}\int_{\mathbb{Q}}\hat{f}_{i}(\hat{v }_{i}-\hat{u}_{i}^{\varepsilon})dy'dz+\int_{\mathbb{Q}}\varepsilon \hat{f}_{3} (\hat{v}_{3}-\hat{u}_{3}^{\varepsilon})dy'dz\text{, }\forall \hat{v }\in E. \end{align*}

    We apply the convergence of Theorem 4.1, Lemma 5.2 and the fact \widehat{j} is convex and lower semi-continuous, we obtain

    \begin{align*} & \mu \underset{i = 1}{\overset{2}{\sum\limits}}\int_{\mathbb{Q}}\dfrac{1}{2}\left( \dfrac{1} {2}\underset{i = 1}{\overset{2}{\sum\limits}}\left( \dfrac{\partial \hat{v}_{i} }{\partial z}\right) ^{2}\right) ^{\frac{r-2}{2}}\dfrac{\partial \hat {v}_{i}}{\partial z}{\dfrac{\partial(\hat{v}_{i}-u_{i}^{\star} )}{\partial z}}dy'dz \\ &- \int_{\mathbb{Q}}\pi^{\star}\left( \dfrac{\partial \hat{v}_{1}}{\partial y_{1}}+\dfrac{\partial \hat{v}_{2}}{\partial y_{2}}\right) dy'dz+\hat{\delta}\frac{\sqrt{2}}{2}\int_{\mathbb{Q}}\left( \left \vert \dfrac{\partial \hat{v}}{\partial z}\right \vert -\left \vert \dfrac{\partial u^{\star}}{\partial z}\right \vert \right) dy'dz\\ & +\int_{\Gamma_b}\hat{k}\left \vert R(-\pi^{\star})\right \vert \left( |\hat{v}-s|-|u^{\star}-s|\right) dy'\\ & \geq \ \underset{i = 1}{\overset{2}{\sum\limits}}\int_{\mathbb{Q}}\hat{f}_{i} (\hat{v}_{i}-u_{i}^{\star})dy'dz\; \text{.} \end{align*}

    From [5,Lemma 5.1] , \pi^{\star} independent of z , then applying Minty's lemma for the second time, we deduce (4.8) .

    Proof of Theorem 4.3. Choosing \hat{v} in (4.8) (as in [3]) by: \hat{v}_{i} = u_{i}^{\star }+\phi_{i}, i = 1, 2 , with \phi_{i}\in W_{0}^{1, r}(\mathbb{Q}) , we find

    \begin{align*} & \mu \underset{i = 1}{\overset{2}{\sum\limits}}\int_{\mathbb{Q}}\dfrac{1}{2}\left( \dfrac{1} {2}\left( \dfrac{\partial u_{1}^{\star} }{\partial z}+\dfrac{\partial u_{2}^{\star} }{\partial z}\right) ^{2}\right) ^{\frac{r-2}{2}}\dfrac{\partial u_{i}^{\star}}{\partial z}{\dfrac{\partial \phi_{i}}{\partial z}} dy'dz-\int_{\mathbb{Q}}\pi^{\star}\left(\dfrac {\partial \phi_{1}}{\partial y_1}+\dfrac {\partial \phi_{2}}{\partial y_2}\right)dy'dz\\ & = \ \underset{i = 1}{\overset{2}{\sum\limits}}\int_{\mathbb{Q}}\hat{f}_{i}\phi _{i}dy'dz. \end{align*}

    By using Green's formula, and choosing in the first step \phi_{1} = 0 and \phi_{2} \in W_{0}^{1, r}(\mathbb{Q}) then reversing this choice in the second step, we find (4.9) .

    Now, for the prove of (4.10) , we cannot choose the test function as in [5,6], since their works do not contain the term \hat{\delta}\frac{\sqrt{2}}{2}\int_{\mathbb{Q}}\partial \hat{v}/\partial z dy'dz . For this, we use the following techniques. Firstly, we choose \hat{v} in (4.8) by v = u^{\star}+\lambda \phi then v = u^{\star}-\lambda \phi , \phi \in W_{0}^{1, r}\left(\mathbb{Q} \right) ^{2} , we obtain

    \begin{align} & \mu \underset{i = 1}{\overset{2}{\sum\limits}}\int_{\mathbb{Q}}\dfrac{1}{2}\left( \dfrac{1} {2}\left( \dfrac{\partial u_{1}^{\star} }{\partial z}+\dfrac{\partial u_{2}^{\star} }{\partial z}\right) ^{2}\right) ^{\frac{r-2}{2}}\dfrac{\partial u_{i}^{\star}}{\partial z}{\dfrac{\partial(\lambda \phi_{i})}{\partial z} }dy'dz-\underset{i = 1}{\overset{2}{\sum\limits}}\int_{\mathbb{Q}}\pi^{\star}\left( y'\right) \dfrac{\partial(\lambda \phi_{i})}{\partial y_{i}}dy'dz \end{align} (5.18)
    \begin{align} & +\hat{\delta}\frac{\sqrt{2}}{2}\int_{\mathbb{Q}}\left( \left \vert \dfrac{\partial \left( u^{\star}+\lambda \phi \right) }{\partial z}\right \vert -\left \vert \dfrac{\partial u^{\star}}{\partial z}\right \vert \right) dy'dz\geq \ \underset{i = 1}{\overset{2}{\sum\limits}}\int_{\mathbb{Q}}\hat{f} _{i}(\lambda \phi_{i})dy'dz, \; \ \ \ \ \forall \phi \in W_{0}^{1, r}\left( \mathbb{Q} \right) ^{2}.\ \\ & \mu \underset{i = 1}{\overset{2}{\sum\limits}}\int_{\mathbb{Q}}\dfrac{1}{2}\left( \dfrac{1} {2}\underset{i = 1}{\overset{2}{\sum\limits}}\left( \dfrac{\partial u_{i}^{\star} }{\partial z}\right) ^{2}\right) ^{\frac{r-2}{2}}\dfrac{\partial u_{i}^{\star}}{\partial z}{\dfrac{\partial \phi_{i}}{\partial z}} dy'dz-\underset{i = 1}{\overset{2}{\sum\limits}}\int_{\mathbb{Q}}\pi^{\star}\left( y'\right) \dfrac{\partial(\lambda \phi_{i})}{\partial y_{i}}dy'dz \end{align} (5.19)
    \begin{align} & -\hat{\delta}\frac{\sqrt{2}}{2}\int_{\mathbb{Q}}\left( \left \vert \dfrac{\partial (u^{\star}-\lambda \phi)}{\partial z}\right \vert -\left \vert \dfrac{\partial u^{\star}}{\partial z}\right \vert \right) dy'dz\leq \ \underset{i = 1}{\overset{2}{\sum\limits}}\int_{\mathbb{Q}}\hat{f}_{i}(\lambda \phi _{i})dy'dz, \ \ \ \ \forall \phi \in W_{0}^{1, r}\left( \mathbb{Q} \right) ^{2}\text{.}\nonumber \end{align}

    Secondly, dividing \left(5.18\right) \; and \left(5.19\right) by \lambda and the passage to the limit when \lambda tends to zero, we find

    \begin{equation} \begin{array} [c]{c} \mu \underset{i = 1}{\overset{2}{\sum\limits}}\int_{\mathbb{Q}}\dfrac{1}{2}\left( \dfrac{1} {2}\underset{i = 1}{\overset{2}{\sum\limits}}\left( \dfrac{\partial u_{i}^{\star} }{\partial z}\right) ^{2}\right) ^{\frac{r-2}{2}}\dfrac{\partial u_{i}^{\star}}{\partial z}{\dfrac{\partial \phi_{i}}{\partial z}} dy'dz-\underset{i = 1}{\overset{2}{\sum\limits}}\int_{\mathbb{Q}}\pi^{\star}\left( y'\right) \dfrac{\partial \phi_{i}}{\partial y_{i}}dy'dz\\ +\hat{\delta}\frac{\sqrt{2}}{2}\underset{i = 1}{\overset{2}{\sum\limits}}\int_{\mathbb{Q} }\left( \left \vert \dfrac{\partial u^{\star}}{\partial z}\right \vert \right) ^{-1}\dfrac{\partial u^{\star}}{\partial z}\dfrac{\partial \phi_{i}}{\partial z}dy'dz\geq \ \underset{i = 1}{\overset{2}{\sum\limits}}\int_{\mathbb{Q}}\hat{f} _{i}\phi_{i}dy'dz, \; \ \forall \phi \in W_{0}^{1, r}\left( \mathbb{Q} \right) ^{2}\text{, } \end{array} \end{equation} (5.20)
    \begin{equation} \begin{array} [c]{c} \mu \underset{i = 1}{\overset{2}{\sum\limits}}\int_{\mathbb{Q}}\dfrac{1}{2}\left( \dfrac{1} {2}\underset{i = 1}{\overset{2}{\sum\limits}}\left( \dfrac{\partial u_{i}^{\star} }{\partial z}\right) ^{2}\right) ^{\frac{r-2}{2}}\dfrac{\partial u_{i}^{\star}}{\partial z}{\dfrac{\partial \phi_{i}}{\partial z}} dy'dz-\underset{i = 1}{\overset{2}{\sum\limits}}\int_{\mathbb{Q}}\pi^{\star}\left( y'\right) \dfrac{\partial \phi_{i}}{\partial y_{i}}dy'dz\\ +\hat{\delta}\frac{\sqrt{2}}{2}\underset{i = 1}{\overset{2}{\sum\limits}}\int_{\mathbb{Q} }\left( \left \vert \dfrac{\partial u^{\star}}{\partial z}\right \vert \right) ^{-1}\dfrac{\partial u^{\star}}{\partial z}\dfrac{\partial \phi_{i}}{\partial z}dy'dz\leq \ \underset{i = 1}{\overset{2}{\sum\limits}}\int_{\mathbb{Q}}\hat{f} _{i}\phi_{i}dy'dz, \; \forall \phi \in W_{0}^{1, r}\left( \mathbb{Q} \right) ^{2}\text{.} \end{array} \end{equation} (5.21)

    So the last two formulas, we give:

    \begin{equation} \begin{array} [c]{c} \mu \underset{i = 1}{\overset{2}{\sum\limits}}\int_{\mathbb{Q}}\dfrac{1}{2}\left( \dfrac{1} {2}\underset{i = 1}{\overset{2}{\sum\limits}}\left( \dfrac{\partial u_{i}^{\star} }{\partial z}\right) ^{2}\right) ^{\frac{r-2}{2}}\dfrac{\partial u_{i}^{\star}}{\partial z}{\dfrac{\partial \phi_{i}}{\partial z}} dy'dz-\underset{i = 1}{\overset{2}{\sum\limits}}\int_{\mathbb{Q}}\pi^{\star}\left( y'\right) \dfrac{\partial \phi_{i}}{\partial y_{i}}dy'dz\\ +\hat{\delta}\frac{\sqrt{2}}{2}\underset{i = 1}{\overset{2}{\sum\limits}}\int_{\mathbb{Q} }\left( \left \vert \dfrac{\partial u^{\star}}{\partial z}\right \vert \right) ^{-1}\dfrac{\partial u^{\star}}{\partial z}\dfrac{\partial \phi_{i}}{\partial z}dy'dz = \ \underset{i = 1}{\overset{2}{\sum\limits}}\int_{\mathbb{Q}}\hat{f}_{i} \phi_{i}dy'dz, \; \ \forall \phi \in W_{0}^{1, r}\left( \mathbb{Q} \right) ^{2}\text{.} \end{array} \end{equation} (5.22)

    By the Green's formula, we get (4.10) .

    Proof of Theorem 4.4. We take in (4.8) , \hat{v} _{i} = u_{i}^{\star}+\lambda \phi_{i} for i = 1, 2 , where \phi_{i}\in W_{\Gamma_{u}\cup \Gamma_{l}}^{1, r}\left(\mathbb{Q} \right) and

    W_{\Gamma_{u}\cup \Gamma_{l}}^{1, r}\left( \mathbb{Q} \right) = \{ \phi \in W^{1, r}\left( \mathbb{Q} \right) :\phi_{i} = 0\text{ on }\Gamma_{u}\cup \Gamma _{l}\},

    then

    \begin{align*} & \mu \underset{i = 1}{\overset{2}{\sum\limits}}\int_{\mathbb{Q}}\dfrac{1}{2}\left( \dfrac{1} {2}\underset{i = 1}{\overset{2}{\sum\limits}}\left( \dfrac{\partial u_{i}^{\star} }{\partial z}\right) ^{2}\right) ^{\frac{r-2}{2}}\dfrac{\partial u_{i}^{\star}}{\partial z}\dfrac{\partial(\lambda \phi_{i})}{\partial z} dy'dz-\underset{i = 1}{\overset{2}{\sum\limits}}\int_{\mathbb{Q}}\pi^{\star}\left( y'\right) \frac{\partial(\lambda \phi_{i})}{\partial y_i}dy'dz\\ & +\hat{\delta}\frac{\sqrt{2}}{2}\underset{i = 1}{\overset{2}{\sum\limits}} \int_{\mathbb{Q}}\left( \left \vert \dfrac{\partial \left( \lambda \phi+u^{\star }\right) }{\partial z}\right \vert -\left \vert \dfrac{\partial u^{\star} }{\partial z}\right \vert \right) dy'dz+\int_{\Gamma_b}\hat{k}\left \vert R(-\pi^{\star})\right \vert \left( |\lambda \phi+s^{\star}-s|-|s^{\star }-s|\right) dy'\\ & \geq \ \underset{i = 1}{\overset{2}{\sum\limits}}\int_{\mathbb{Q}}\hat{f}_{i} (\hat{v}_{i}-u_{i}^{\star})dy'dz\text{.} \end{align*}

    Dividing the last inequality by \lambda and the passage to the limit when \lambda tends to zero, we find

    \begin{equation} \begin{array} [c]{c} \mu \underset{i = 1}{\overset{2}{\sum\limits}}\int_{\mathbb{Q}}\dfrac{1}{2}\left( \dfrac{1} {2}\underset{i = 1}{\overset{2}{\sum\limits}}\left( \dfrac{\partial u_{i}^{\star} }{\partial z}\right) ^{2}\right) ^{\frac{r-2}{2}}\dfrac{\partial u_{i}^{\star}}{\partial z}\dfrac{\partial \phi_{i}}{\partial z}dy'dz\\ -\underset{i = 1}{\overset{2}{\sum\limits}}\int_{\mathbb{Q}}\pi^{\star}\left( y'\right) \dfrac{\partial \phi_{i}}{\partial y_i}dy'dz+\hat{\delta}\frac{\sqrt{2}} {2}\underset{i = 1}{\overset{2}{\sum\limits}}\int_{\mathbb{Q}}\left( \left \vert \dfrac{\partial u^{\star}}{\partial z}\right \vert \right) ^{-1} \dfrac{\partial u^{\star}}{\partial z}\dfrac{\partial \phi_{i}}{\partial z}dy'dz\\ +\underset{i = 1}{\overset{2}{\sum\limits}}\int_{\Gamma_b}\hat{k}\left \vert R(-p^{\star })\right \vert \dfrac{\phi_{i}\left( s_{i}^{\star}-s_{i}\right) }{|s^{\star }-s|}dy'\geq \ \underset{i = 1}{\overset{2}{\sum\limits}}\int_{\mathbb{Q}}\hat{f} _{i}(\hat{v}_{i}-u_{i}^{\star})dy'dz\text{.} \end{array} \end{equation} (5.23)

    Finally, using the Green formula in (5.23) and from (4.10) , we find

    \underset{i = 1}{\overset{2}{\sum\limits}}\int_{\Gamma_b}\widehat{k}\left \vert R(\widehat{\sigma}_{\eta}({-}\pi^{\star}))\right \vert \phi_{i}(s_{i}^{\star }-s_{i})dy'-\int_{\Gamma_b}\widehat{\mu}\tau^{\star}\phi \left \vert s^{\star }-s\right \vert dy'\geq0, \ \forall \phi \in \left( W_{\Gamma_{u}\cup \Gamma_{l}}^{1, r}\left( \mathbb{Q} \right) \right) ^{2}\text{.}

    This last formula holds for any \phi \in D(\Gamma_b)^{2} , but given the density of D(\Gamma_b) in L^{r}(\Gamma_b) , we find the desired result (4.11) . For the proof of (4.12) , we follow the same techniques as in [4].

    To establish \left(4.13\right) , we integrate twice (4.10) from 0 to z , we get

    \begin{equation} \begin{array} [c]{c} -\int_{0}^{z} \mu B^{\star}\left( y', \xi \right) \dfrac{\partial u^{\star}}{\partial \xi}\left( y';\xi \right) d\xi-\hat{\delta}\frac{\sqrt{2}}{2}\int_{0}^{z}\dfrac{\partial u^{\star}/\partial z}{\left \vert \partial u^{\star}/\partial z\right \vert }d\xi+ \mu \tau^{\star}\left( y'\right) z\\ +\hat{\delta}\frac{\sqrt{2}}{2}\dfrac{s^{\star}\left( y'\right) }{\left \vert s^{\star}\left( y'\right) \right \vert } \ z = \int_{0}^{z}\int_{0}^{\xi }\hat{f}\left( y', t\right) dtd\xi-\dfrac{z^{2}}{2}\nabla \pi^{\star}(y'). \end{array} \end{equation} (5.24)

    Substituting z by h in (4.24) , we get

    \begin{equation} \begin{array} [c]{c} -\int_{0}^{h} \mu B^{\star}\left( y', \xi \right) \dfrac{\partial u^{\star}}{\partial \xi}\left( y';\xi \right) d\xi-\hat{\delta}\frac{\sqrt{2}}{2}\int_{0}^{h}\dfrac{\partial u^{\star}/\partial z}{\left \vert \partial u^{\star}/\partial z\right \vert }d\xi+ \mu \tau^{\star}\left( y'\right) h\\ +\hat{\delta}\frac{\sqrt{2}}{2}\dfrac{s^{\star}\left( y'\right) }{\left \vert s^{\star}\left( y'\right) \right \vert } \ h = \int_{0}^{h}\int_{0}^{\xi }\hat{f}\left( y', t\right) dtd\xi-\dfrac{h^{2}}{2}\nabla \pi^{\star}(y'). \end{array} \end{equation} (5.25)

    We integrate (5.24) from 0 to z , it comes:

    \begin{equation} \begin{array} [c]{c} -\int_{0}^{h}\int_{0}^{y} \mu B^{\star}\left( y', \xi \right) \dfrac{\partial u^{\star}}{\partial z}\left( y';\xi \right) d\xi dy-\hat{\delta}\frac{\sqrt{2}}{2}\int_{0}^{h}\int_{0} ^{y}\dfrac{\partial u^{\star}/\partial z}{\left \vert \partial u^{\star }/\partial z\right \vert }d\xi dy+ \mu \tau^{\star}\left( y'\right) \dfrac{h^{2}}{2}\\ +\hat{\delta}\frac{\sqrt{2}}{4}\dfrac{s^{\star}\left( y'\right) }{\left \vert s^{\star}\left( y'\right) \right \vert }h^{2} = \int_{0}^{h}\int_{0}^{y}\int _{0}^{\xi}\hat{f}\left( y', t\right) dtd\xi dy-\dfrac{h^{3}}{6}\nabla \pi^{\star}(y')\text{.} \end{array} \end{equation} (5.26)

    From (5.25), we deduce

    \begin{equation} \begin{array} [c]{c} \left[ \mu \tau^{\star}\left( y'\right) +\hat{\delta}\frac{\sqrt{2}}{4}\dfrac{s^{\star }\left( y'\right) }{\left \vert s^{\star}\left( y'\right) \right \vert }\right] \dfrac{h^{2}}{2} = \dfrac{ \mu h}{2}\int_{0}^{h}B^{\star}\left( y', \xi \right) \dfrac{\partial u^{\star} }{\partial \xi}\left( y';\xi \right) d\xi\\ +\hat{\delta}h\dfrac{\sqrt{2}}{4}\int_{0}^{h}\frac{\partial u^{\star}/\partial z}{\left \vert \partial u^{\star}/\partial z\right \vert }d\xi+\dfrac{h}{2} \int_{0}^{h}\int_{0}^{y}\hat{f}\left( y', \xi \right) d\xi dy-\dfrac{h^{3}} {4}\nabla \pi^{\star}(y')\text{.} \end{array} \end{equation} (5.27)

    By (5.26) and (5.27) , we deduce \left(4.13\right) .

    Proof of Theorem 4.5. Suppose that the boundary value problem (4.8) admits two solutions which we denote by \left(u^{\star, 1}, \pi^{\star, 1}\right) and \left(u^{\star, 2}, \pi^{\star, 2}\right) . Taking \hat{v} = u^{\star, 2} and \hat{v} = u^{\star, 1} respectively, as test function in \left(4.8\right) then by summing two inequalities, we get

    \begin{equation} \begin{array} [c]{c} \mu \underset{i = 1}{\overset{2}{\sum\limits}}\int_{\mathbb{Q}}\left( \dfrac{1}{2}\right) ^{\frac{r}{2}}\left( \underset{i = 1}{\overset{2}{\sum\limits}}\left( \dfrac{\partial u_{i}^{\star, 1}}{\partial z}\right) ^{2}\right) ^{\frac{r-2}{2}} \dfrac{\partial u_{i}^{\star, 1}}{\partial z}{\dfrac{\partial}{\partial z} }(u_{i}^{\star, 1}-u_{i}^{\star, 2})dy'dz\\ \; \; \; \; \; \; \; \; \; \; \; \; \; - \mu \underset{i = 1}{\overset{2}{\sum\limits}}\int_{\mathbb{Q}}\left( \dfrac{1}{2}\right) ^{\frac{r}{2}}\left( \underset{i = 1}{\overset{2}{\sum\limits}}\left( \dfrac{\partial u_{i}^{\star, 2}}{\partial z}\right) ^{2}\right) ^{\frac{r-2}{2}} \dfrac{\partial u_{i}^{\star, 2}}{\partial z}{\dfrac{\partial}{\partial z} }(u_{i}^{\star, 1}-u_{i}^{\star, 2})dy'dz\\ -\int_{\Gamma_b}\hat{k}\left \vert R(-\pi^{\star, 1})-R(-\pi^{\star, 2})\right \vert |u_{i}^{\star, 1}-u_{i}^{\star, 2}|dy'\leq0. \end{array} \end{equation} (5.28)

    We apply (5.16) and (5.17) , we obtain

    \begin{equation} {\mu} \left \Vert \dfrac{\partial }{\partial z}\left( u^{\star , 1}-u^{\star , 2}\right) \right \Vert _{(L^{r}\left( \mathbb{Q})\right)^2}^{r} \leq \Vert \widehat{k}\Vert _{L^{\infty }(\Gamma _{b})}\int_{\Gamma _{b}}\left \vert R(-\pi ^{\star , 1})-R(-\pi ^{\star , 2})\right \vert |u^{\star , 1}-u^{\star , 2}|dy^{\prime }. \end{equation} (5.29)

    By the inequality (3.16) , then we apply the Hölder inequality on the second term of (5.29) , we have

    \begin{align*} &\left \Vert \dfrac{\partial }{\partial z}\left( u^{\star , 1}-u^{\star , 2}\right) \right \Vert _{(L^{r}\left( \mathbb{Q})\right)^2 }^{r} \\ \leq& h^{\star}\Vert \widehat{k}\Vert_{L^{\infty}(\Gamma_b)}C_{0}\left( \int_{\Gamma_b}\left \vert R(-\pi^{\star, 1})-R(-\pi^{\star, 2})\right \vert ^{q}dy'\right) ^{1/q}\left \Vert \dfrac{\partial }{\partial z}\left( u^{\star , 1}-u^{\star , 2}\right) \right \Vert _{(L^{r}\left( \mathbb{Q})\right)^2 } \end{align*}

    whence

    \begin{equation} \left \Vert \dfrac{\partial }{\partial z}\left( u^{\star , 1}-u^{\star , 2}\right) \right \Vert _{(L^{r}\left( \mathbb{Q})\right)^2 }^{r-1}\leq \frac{h^{\star}\Vert \widehat{k} \Vert_{L^{\infty}(\Gamma_b)}C_{0}}{ \mu }\left \Vert R(-\pi^{\star, 1})-R(-\pi^{\star, 2})\right \Vert _{L^{q}\left( \Gamma_b \right) }. \end{equation} (5.30)

    Using the fact that R is a linear continuous operator W^{-\frac{1}{2}, r}(\Gamma_b) into L^{r}(\Gamma_b) , there exists a constant C_{1} depending on R , such that

    \begin{equation} \left \Vert R(-\pi^{\star, 1})-R(-\pi^{\star, 2})\right \Vert _{L^{q}\left( \Gamma_b \right) }\leq C_{1}\left \Vert \pi^{\star, 1}-\pi^{\star, 2}\right \Vert _{L^{q}\left( \Gamma_b \right) }. \end{equation} (5.31)

    Combining (5.30) and (5.31) we deduce that if \Vert \widehat{k} \Vert_{L^{\infty}(\Gamma_b)}\leq \overline{k} for sufficiently small \overline{k} , then we have

    \left \Vert \dfrac{\partial }{\partial z}\left( u^{\star , 1}-u^{\star , 2}\right) \right \Vert _{(L^{r}\left( \mathbb{Q})\right)^2 } = 0.

    Using Poincaré's inequality, we get

    \left \Vert u^{\star , 1}-u^{\star , 2} \right \Vert _{\widetilde\Theta _{z}} = 0.

    The uniqueness of the \pi ^{\ast } in the E_{0}^{q}\left(\Gamma_b \right) follows from (4.13) , in fact we take first in the Reynolds equation (4.13) the pressure value \pi ^{\ast } = \pi^{\star, 1} then \pi ^{\ast } = \pi^{\star, 2} respectively, at the end by subtracting the equations obtained, it becomes:

    \begin{equation*} \int_{\Gamma_b }\frac{h^{3}}{12}\nabla \left( \pi^{\star, 1}-\pi^{\star, 2}\right) \nabla v dy' = 0\text{.} \end{equation*}

    Choosing v = \pi^{\star, 1}-\pi^{\star, 2} , and by Poincaré's inequality, we find

    \begin{equation*} \pi^{\star, 1} = \pi^{\star, 2}\text{, almost everywhere in }\Gamma_b \text{.} \end{equation*}

    This ends the proof of the Theorem 4.5.

    The aim of this study is to examine the strong convergence of the velocity of a non-Newtonian incompressible fluid whose viscosity follows the power law with Coulomb friction, where we give in a first step the description of the problem and basic equations. Then, we present the functional framework. The following paragraph is reserved for the main convergence results. Finally, we give the detail of the proofs of these results. In the future work we will extend and develop our work to new space.

    Researchers would like to thank the Deanship of Scientific Research, Qassim University for funding publication of this project.

    The authors declares that they have no conflicts of interest.



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