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Research article Special Issues

Normalized solutions for the mixed dispersion nonlinear Schrödinger equations with four types of potentials and mass subcritical growth

  • This paper is devoted to considering the attainability of minimizers of the L2-constraint variational problem

    mγ,a=inf{Jγ(u):uH2(RN),RN|u|2dx=a2},

    where

    Jγ(u)=γ2RN|Δu|2dx+12RN|u|2dx+12RNV(x)|u|2dx12σ+2RN|u|2σ+2dx,

    γ>0, a>0, σ(0,2N) with N2. Moreover, the function V:RN[0,+) is continuous and bounded. By using the variational methods, we can prove that, when V satisfies four different assumptions, mγ,a are all achieved.

    Citation: Cheng Ma. Normalized solutions for the mixed dispersion nonlinear Schrödinger equations with four types of potentials and mass subcritical growth[J]. Electronic Research Archive, 2023, 31(7): 3759-3775. doi: 10.3934/era.2023191

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  • This paper is devoted to considering the attainability of minimizers of the L2-constraint variational problem

    mγ,a=inf{Jγ(u):uH2(RN),RN|u|2dx=a2},

    where

    Jγ(u)=γ2RN|Δu|2dx+12RN|u|2dx+12RNV(x)|u|2dx12σ+2RN|u|2σ+2dx,

    γ>0, a>0, σ(0,2N) with N2. Moreover, the function V:RN[0,+) is continuous and bounded. By using the variational methods, we can prove that, when V satisfies four different assumptions, mγ,a are all achieved.



    Over the past several decades, the mixed dispersion nonlinear Schrödinger equation

    iψtγΔ2ψ+βΔψV(x)ψ+f(ψ)=0inRN (1.1)

    has been studied by many researchers. Biharmonic Schrödinger equations have played an important role in considering the small biharmonic dispersion terms in the transmission of intense laser beams in a bulk medium with Kerr nonlinearity; see [1,2]. Biharmonic Schrödinger equations are also important in depicting the motion of a vortex filament in an incompressible fluid; see [3]. Since then, biharmonic Schrödinger equations have received attention due to whose applications in physics.

    An interesting topic is to study the standing waves of Eq (1.1). By applying the ansatz ψ(t,x)=eiλtu(x), Eq (1.1) yields the following equation:

    γΔ2uβΔu+V(x)u=λu+f(u)inRN, (1.2)

    where γ>0, λR, βR, and u:RNR is a function which does not rely on time. Moreover, if u(x) is a solution to (1.2), we can obtain that ψ(t,x)=eiλtu(x) is a solution to (1.1).

    Above all, when γ=0, β=1 and V(x)0, we consider the existence of the L2-constraint variational problem

    Dα=inf{12RN|u|2dxRNF(|u|)dx:uH1(RN),RN|u|2dx=α2}.

    When f(u)=|u|2σu(0<σ<2N), by assuming H1-precompactness of any minimizing sequences, Cazenave and Lions [4] obtained the existence of the L2-constraint minimization problem. To this end, the subadditivity assumption

    Dα+β<Dα+Dβ (1.3)

    is very crucial. Due to the assumption (1.3), we can eliminate the dichotomy of minimizing sequences.

    If only V(x)0, many papers are dedicated to this equation:

    γΔ2uβΔu=λu+f(u)inRN. (1.4)

    Bonheure et al. considered a mixed dispersion nonlinear Schrödinger equation in [5]. More precisely, they studied the existence of the ground states and positive solutions. They also studied the multiplicity of radial solutions and the standing waves of the related dispersive equation. Recently, Goubet and Manoubi [6] studied semilinear Schrödinger equations with a non-standard dispersion that is discontinuous at x=0. They obtained both the existence and the uniqueness of standing waves for these equations. Then, they discussed the orbital stability of these standing waves in a subspace of the energy space, by using some classical methods such as the concentration-compactness method of Lions. In [7], Khiddi and Essafi obtained the existence of infinitely many solutions for a class of quasilinear Schrödinger equations without assuming the 4-superlinear at infinity on the nonlinearity. The approach is based on the fountain theorem, and the involved potential term is continuous and satisfies suitable regularities. In [8], Alotaibi et al. studied both the existence and nonexistence of global weak solutions to a class of inhomogeneous nonlinear Schrödinger equations. The main problem is related to gradient, which requires certain specific estimates to develop the precise proofs of results. The approach is based on rescaled test function arguments derived from the Mitidieri and Pokhozhaev method, and it also involves the Fujita critical exponent. In [9], Bonheure et al. studied two related constraint minimization problems: One is related to a constraint on the L2-norm, and another one is related to a constraint on the L2σ+2-norm. They also studied the attainability and the qualitative properties of minimizers, namely, their sign, symmetry, decay and so on. In [10], Fernández et al. established non-homogeneous Gagliardo-Nirenberg-type inequalities depending on the Tomas-Stein inequality. They proved the attainability of minimizers in the mass-subcritical and mass-critical cases. For more research about the biharmonic Schrödinger equations, see [11,12,13,14,15] and the references therein.

    Usually, if V(x)0, the scaling u(sx) is useful, and we can show (1.3). However, when V(x)0 the scaling u(sx) does not work generally, and it is harder to show the subadditivity condition. Therefore, the L2-constraint minimization problem is hard. Just because of this, the solutions to the problem would not be enough. For the biharmonic Schrödinger equations with a potential, see [16] and the references therein.

    Although the biharmonic nonlinear Schrödinger equations are related to physics, they are far from being properly understood. The nonlinear Schrödinger equations have been studied in [17,18,19,20,21], but the fourth order Schrödinger equations have been studied very little. Apart from some papers already mentioned, there are actually few papers dealing with biharmonic nonlinear Schrödinger equations.

    Inspired by the past work of [22,23,24], in this paper, we consider the attainability of minimizers of the L2-constraint variational problem:

    mγ,a=inf{Jγ(u):uH2(RN),RN|u|2dx=a2},

    where

    Jγ(u)=γ2RN|Δu|2dx+12RN|u|2dx+12RNV(x)|u|2dx12σ+2RN|u|2σ+2dx,

    γ>0, a>0, σ(0,2N) with N2 and the continuous bounded function V:RN[0,+). Here, we consider four functions:

    (V1) V is a function that is 1-periodic in x1,x2,,xN.

    (V2) V is an asymptotically periodic function. Namely there exists a function Vq:RNR which is 1-periodic in x1,x2,,xN, and V satisfies the following conditions:

    Vq(x)V(x),for anyxRN. (1.5)
    |Vq(x)V(x)|0,as|x|+. (1.6)

    (V3) VL(RN), and

    0<infxRNV(x)=V0<lim inf|x|+V(x)=V. (1.7)

    (V4) Suppose that μW(x)=V(x) and a constant M1>0 such that

    |{xRN:M1<W(x)}|<+. (1.8)

    Moreover, Ω=int(W1(0)).

    Next, we describe the first result of this paper.

    Theorem 1.1. Let γ>0, σ(0,2N) and assume that (V1) holds or (V2) holds. There exists a constant δ(a)>0 for any a>0, and if |V|<δ when V satisfies (V1), or |Vq|<δ when V satisfies (V2), mγ,a<0 is achieved.

    Our second result is combined with the L2-constraint variational problem:

    mγ,a,ε=inf{Jγ,ε(u):uH2(RN),RN|u|2dx=a2} (1.9)

    where

    Jγ,ε(u)=γ2RN|Δu|2dx+12RN|u|2dx+12RNV(εx)|u|2dx12σ+2RN|u|2σ+2dx,

    γ>0, a>0, ε>0 are real numbers, and σ(0,2N) with N2.

    The second result is as follows.

    Theorem 1.2. Let γ>0, σ(0,2N) and assume that (V3) holds. Then, there exist two constants δ(a), ε0>0 for any a>0, and if |V|<δ, mγ,a,ε<0 is achieved for any ε(0,ε0).

    In (V4), we choose r>0 such that Br(x1)Ω. We study a constrained variational problem:

    mγ,a,μ=inf{Jλ,μ(u):uH2(RN),RN|u|2dx=a2},

    where

    Jγ,μ(u)=γ2RN|Δu|2dx+12RN|u|2dx+12RNμW(x)|u|2dx12σ+2RN|u|2σ+2dx,

    and γ>0, a>0, σ(0,2N) with N2. Finally, we describe the third main result.

    Theorem 1.3. Let γ>0,σ(0,2N) and assume that V satisfies (V4). Then, there exist two constants r0(a), μ0(a)>0 for any a>0 such that mγ,a,μ<0 is achieved for any μμ0, rr0.

    Notation

    C,C1,C2, represent positive constants, and they are independent of each other.

    Br(y) represents an open ball centered at yRN with radius r>0, Bcr(y) represents its complement in RN.

    represents the common norm of the Sobolev space H2(RN), and ||p represents the common norm of the Lebesgue space Lp(RN), for p[1,].

    on(1) represents a real number sequence with on(1)0 as n+.

    In the following, we study the functional Jγ:ER, namely,

    Jγ(u)=γ2RN|Δu|2dx+12RN|u|2dx+12RNV(x)|u|2dx12σ+2RN|u|2σ+2dx,

    constrained on the sphere in L2(RN) given by

    S(a)={uH2(RN):|u|2=a},

    where γ>0, and the continuous function V:RN[0,+). E is described as the space

    E={uH2(RN):RNV(x)|u|2dx<+},

    and the norm of E is given by

    u=(RN(|Δu|2+|u|2+(V(x)+1)|u|2)dx)12.

    We can infer E=H2(RN) if VL(RN).

    According to the definition of E, it is obvious that the embedding EH2(RN) is continuous. The following embeddings

    EL2σ+2(RN),for2σ+2[2,+]whenN=2,

    and

    EL2σ+2(RN),for2σ+2[2,2]whenN3,

    are continuous, too.

    In addition, we introduce two Gagliardo-Nirenberg interpolation inequalities; see [25,26,27]. When the function uH2(RN), we have

    u2σ+2L2σ+2CN(σ)ΔuσN2L2u2σ+2σN2L2, (2.1)

    where

    {0σforN4,0σ4N4forN>4,

    and

    u2σ+2L2σ+2BN(σ)uσNL2u2σ+2σNL2, (2.2)

    where

    {0σforN2,0σ2N2forN>2,

    the constants B=BN(σ)>0 and C=CN(σ)>0. Therefore, we have

    Jγ(u)12RN|u|2dxBa2σ+2σN2σ+2(RN|u|2dx)σN2 (2.3)

    and

    Jγ(u)γ2RN|Δu|2dxCa2σ+2σN22σ+2(RN|Δu|2dx)σN4. (2.4)

    Since σ(0,2N), we know that σN<2. Hence, Jγ is bounded from below on S(a) for any a>0, γ>0. Relying on the above arguments, we infer that

    mγ,a=infuS(a)Jγ(u)

    is well-defined.

    Lemma 2.1. Let VL(RN) and γ>0. There exists a constant δ(a)>0 for each a>0 such that mγ,a<0 when |V|<δ.

    Proof. We choose u1S(a) for every a>0, and set

    uk(x)=eNk2u1(ekx),for allxRNand allkR.

    By calculation, we have

    RN|uk(x)|2dx=a2

    and

    RN|uk(x)|2σ+2dx=eσNkRN|u1(x)|2σ+2dx. (2.5)

    Therefore, we infer that

    Jγ(uk)γe4k2RN|Δu1|2dx+e2k2RN|u1|2dx+|V|a22eσNk2σ+2RN|u1|2σ+2dx.

    As σ(0,2N), there exists a constant k<0 such that

    γe4k2RN|Δu1|2dx+e2k2RN|u1|2dxeσNk2σ+2RN|u1|2σ+2dx=Dk<0.

    Now, we choose fixed δ=Dka2 and consider |V|<δ, and we have

    Jγ(uk)<DkDk2=Dk2<0,

    which shows mγ,a<0.

    Lemma 2.2. Let γ>0, and there are x1RN, r>0 and

    V(x)=0,for anyxBr(x1). (2.6)

    Then, there exists a constant r0>0 that does not rely on μ in (V4) and such that mγ,a<0 for any rr0.

    Proof. We choose u1S(a)C0(RN), x1RN with V(x)=0 for any xBr(x1) and set

    uk(x)=eNk2u1(ek(xx1)),for anyxRNand anykR.

    By calculation we have

    RN|uk(x)|2dx=a2

    and

    RN|uk(x)|2σ+2dx=eσNkRN|u1(x)|2σ+2dx, (2.7)

    which lead to

    Jγ(uk)=γe4k2RN|Δu1|2dx+e2k2RN|u1|2dx+12supp(u1)V(ekx+x1)|u1|2dxeσNk2σ+2RN|u1|2σ+2dx.

    As σ(0,2N), there exists a constant k<0 such that

    γe4k2RN|Δu1|2dx+e2k2RN|u1|2dxeσNk2σ+2RN|u1|2σ+2dx=Dk<0.

    Now, we can choose M1=sup{|x|:xsupp(u1)}, r0=ekM1 for each rr0>0. Then, it is easy to deduce that

    V(ekx+x1)=0,for allxsupp(u1).

    Hence,

    Jγ(uk)<0,

    which shows mγ,a<0.

    Lemma 2.3. Let the conditions of Lemma 2.1 hold or Lemma 2.2 hold. When 0<a2<a1, then a22a21mγ,a1<mγ,a2<0.

    Proof. We set ω>1 such that a1=ωa2 and choose a minimizing sequence (un)S(a2) with respect to mγ,a2, namely,

    Jγ(un)mγ,a2,asn+.

    Let ˜un=ωun, and it is easy to see ˜unS(a1). Then

    mγ,a1J(˜un)=ω2J(un)+(ω2ω2σ+2)2σ+2RN|un|2σ+2dx.

    Claim 2.4. There exist two constants C1>0 and n1N such that RN|un|2σ+2dxC1 for any nn1.

    If not, we can infer that

    RN|un|2σ+2dx0,asn+,

    and if necessary we can choose a subsequence. Let us recall that

    12σ+2RN|un|2σ+2dxJγ(un)=mγ,a2+on(1)<0,fornN,

    which is a contradiction. Hence, the proof of Claim 2.4 is completed.

    Applying Claim 2.4, ω2ω2σ+2<0, we can get that for nN big enough

    mγ,a1ω2J(un)+(ω2ω2σ+2)C12σ+2.

    Taking the limit n+, we have

    mγ,a1ω2mγ,a2+(ω2ω2σ+2)C12σ+2<ω2mγ,a2,

    namely,

    a22a21mγ,a1<mγ,a2,

    and the proof of the Lemma 2.3 is completed.

    Lemma 2.5. Suppose that there exists a minimizing sequence (un)S(a) with respect to mγ,a such that u0, un(x)u(x) a.e. in RN, and unu in H2(RN). Then, unu in H2(RN), Jγ(u)=mγ,a and uS(a).

    Proof. Actually, if not, we can obtain that |u|2=ca. Relying on u0 and Fatou's lemma, it is easy to infer that c(0,a). Applying Brezis-Lieb lemma (see[28,Lemma 1.32]), we can obtain

    |unu|22=|un|22|u|22+on(1)

    and

    |unu|2σ+22σ+2=|un|2σ+22σ+2|u|2σ+22σ+2+on(1).

    Let ˜un=unu, bn=|˜un|2, and assume |˜un|2b. We infer a2=c2+b2 and bn(0,a) for n big enough. Moreover, by using Lemma 2.3, we have

    mγ,a+on(1)=Jγ(un)=Jγ(u)+Jγ(˜un)+on(1)mγ,bn+mγ,c+on(1)b2na2mγ,a+mγ,c+on(1).

    Taking the limit n+, we obtain that

    mγ,ab2a2mγ,a+mγ,c. (2.8)

    As c(0,a), we can apply the Lemma 2.3 in (2.8), and it is easy to obtain this inequality:

    mγ,a>b2a2mγ,a+c2a2mγ,a=(b2a2+c2a2)mγ,a=mγ,a.

    We get a contradiction, which implies |u|2=a, namely, uS(a).

    Since |un|2=|u|2=a, unu in L2(RN),

    unuinL2(RN).

    Using the interpolation theorem in the Lebesgue space, it is easy to obtain that

    unuinL2σ+2(RN).

    Moreover, as RNγ|Δu|2+|u|2+V(x)|u|2dx is convex and continuous in H2(RN), this functional is weakly lower semicontinuous, namely,

    lim infn+RNγ|Δun|2+|un|2+V(x)|un|2dxRNγ|Δu|2+|u|2+V(x)|u|2dx.

    The above limit together with mγ,a=limn+Jγ(un) shows that

    mγ,aJγ(u).

    Since uS(a), Jγ(u)=mγ,a, and Jγ(un)Jγ(u). Since unu in L2σ+2(RN), we infer unu in H2(RN).

    We suppose that V satisfies V1 and set a minimizing sequence unS(a) with respect to mγ,a, namely,

    Jγ(un)mγ,a,asn+.

    As σ(0,2N), the above limit combined with (2.3) and (2.4) ensures (|Δun|2) and (|un|2) are bounded sequences. Hence, (un) is a bounded sequence in H2(RN). Furthermore, there exist a subsequence of (un), still represented by (un), and uH2(RN) such that

    un(x)u(x)a.e. inRN,

    and

    unuinH2(RN).

    As the discussion of Claim 2.4, there is a constant C1>0, and the following inequality is established

    RN|un|2σ+2dxC1,fornNbig enough. (3.1)

    Lemma 3.1. If (un)S(a) is a minimizing sequence, then (un) can be chosen to be a new minimizing sequence ˜unS(a) such that ˜un˜u and ˜u0.

    Proof. Above all, there exist β>0, R>0 and ynRN such that

    BR(yn)|un|2dxβ,for allnN. (3.2)

    If not, we can infer that un0 in L2σ+2(RN), which is a contradiction. A brief discussion implies that we can suppose ynRN and R>0 big enough in (3.2). Then, setting ˜un(x)=u(x+yn), we infer (˜un)S(a) and (˜un) is also a minimizing sequence with respect to mγ,a. Furthermore, there exists ˜uH2(RN){0} such that

    ˜un(x)˜u(x)a.e. inRN,

    and

    ˜un˜uinH2(RN).

    The proof is completed.

    Proof. Using Lemma 3.1, we can get a bounded minimizing sequence (un)S(a) with respect to mγ,a and its weak limit u0. Now, by Lemma 2.5, it is easy to infer uS(a), Jγ(u)=mγ,a and unu in H2(RN). Hence, by the Lagrange multiplier, there exists a constant λ(a)R such that

    Jγ(u)=λ(a)Ψ(u)in(H2(RN)), (3.3)

    where Ψ:H2(RN)R, and

    Ψ(u)=RN|u|2dx,uH2(RN).

    According to (3.3),

    γΔ2uΔu+V(x)u=λ(a)u+|u|2σuinRN.

    Therefore, the proof is completed when V satisfies (V1).

    In this section, let VVq. Therefore, there exists a measurable set ΩRN with |Ω|>0 and

    Vq(x)>V(x),for anyxΩ. (4.1)

    Then, let us represent by Jγ,q:H2(RN)R the functional

    Jγ,q(u)=γ2RN|Δu|2dx+12RN|u|2dx+12RNVq(x)|u|2dx12σ+2RN|u|2σ+2dx,

    and the constant

    mγ,a,q=infuS(a)Jγ,q(u).

    Depending on the conditions of Theorem 1.1, as the discussion in Section 3, there exists upS(a) such that Jγ,p(up)=mγ,a,p. Furthermore, by (4.1), we can infer

    mγ,a<mγ,a,q. (4.2)

    Now, we choose a minimizing sequence (un)S(a) with respect to mγ,a, namely,

    Jγ(un)mγ,a,asn+.

    Since σ(0,2N), as the discussion in Section 2, sequence (un) is bounded in H2(RN). Therefore, there exist uH2(RN) and a subsequence of (un), still represented by (un), such that

    un(x)u(x)a.e. inRN,

    and

    unuinH2(RN).

    Lemma 4.1. If u is the weak limit of (un)S(a), then u0.

    Proof. If not, we have that un0 in H2(RN). Then,

    Jγ,q(un)+RN(V(x)Vq(x))|un|2dx+on(1)=Jγ(un)=mγ,a+on(1),

    which leads to

    mγ,a,p+RN(V(x)Vq(x))|un|2dx+on(1)Jγ(un)=mγ,a+on(1). (4.3)

    Since un0 in L2loc(RN), the condition (1.6) shows

    RN(V(x)Vq(x))|un|2dx0.

    Let n+ in (4.3), and applying the above limit, we get that

    mγ,amγ,a,q.

    We get a conclusion that contradicts (4.2). Hence, u is nontrivial.

    Relying on Lemma 4.1, first of all, we have a minimizing sequence (un)S(a) with respect to mγ,a and its weak limit u0. By using Lemma 2.5, we can obtain unu in H2(RN), uS(a), Jγ(u)=mγ,a. The rest is similar to Theorem 1.1 when V satisfies (V1), and we do not repeat it.

    In this section, let us represent by Jγ,,Jγ,0,:H2(RN)R these functionals:

    Jγ,(u)=γ2RN|Δu|2dx+12RN|u|2dx+12RNV|u|2dx12σ+2RN|u|2σ+2dx

    and

    Jγ,0(u)=γ2RN|Δu|2dx+12RN|u|2dx+12RNV0|u|2dx12σ+2RN|u|2σ+2dx.

    Furthermore, let us represent by mγ,a,, mγ,a,0 these constants:

    mγ,a,=infuS(a)Jγ,(u)

    and

    mγ,a,0=infuS(a)Jγ,0(u).

    According to the conditions of Theorem 1.2, we can get a constant δ(a)>0 for any a>0, and |V|<δ. Hence, by (V3), we have V0<δ and V<δ. Depending on Section 3, we can get two functions u0,uS(a) and Jγ,(u)=mγ,a,, Jγ,0(u0)=mγ,a,0. Moreover, from Lemma 2.1 and (1.7),

    mγ,a,0<mγ,a,<0. (5.1)

    Lemma 5.1. mγ,a,0lim supε0+mγ,a,ε.

    Proof. In the following, let x1RN such that

    V(x1)=infxRNV(x),

    and vε(x)=u1(xx1ε). So, vεS(a), and

    mγ,a,εJγ,ε(vε)=γ2RN|Δu1|2dx+12RN|u1|2dx+12RNV(εx+x1)|u1|2dx12σ+2RN|u1|2σ+2dx.

    Taking the limit ε0+, we have

    lim supε0+mγ,a,εlimε0+Jγ,ε(vε)=Jγ,0(u0)=mγ,a,0.

    From Lemma 5.1 and (5.1), there exists ε0>0 such that

    mγ,a,ε<mγ,a,,for allε(0,ε0). (5.2)

    We choose a minimizing sequence (un)S(a) with respect to mγ,a,ε, namely,

    Jγ,ε(un)mγ,a,ε,asn+.

    As σ(0,2N), the above limit combined with (2.3) and (2.4) ensures (|Δun|2) and (|un|2) are bounded sequences, from where we infer that (un) is bounded in H2(RN). Therefore, there exist a function uH2(RN) and a subsequence of (un), still represented by (un), such that

    un(x)u(x)a.e. inRN,

    and

    unuinH2(RN).

    Lemma 5.2. When ε(0,ε0), u0, where u is the weak limit of (un).

    Proof. If not, we have u=0. Then,

    mγ,a,ε+on(1)=Jγ,ε(un)=Jγ,(un)+RN(V(εx)V)|un|2dx.

    Relying on (V3), for each given η>0, there exist a constant R>0 and

    V(x)Vη,for any|x|R.

    Therefore,

    mγ,a,ε+on(1)=Jγ,ε(un)Jγ,(un)+BR/ε(0)(V(εx)V)|un|2dxηBcR/ε(0)|un|2dx.

    We recall that (un) is bounded in H2(RN), un0 in L2(BR/ε(0)). Hence, can infer that

    mγ,a,ε+on(1)Jγ,(un)ηC1mγ,a,ηC1

    where C1>0. As η>0 is arbitrary, we have

    mγ,a,mγ,a,ε,

    and we get a conclusion that contradicts (5.2). Hence, u0 when ε(0,ε0).

    Depending on Lemma 5.2, we can choose (un)S(a) which is a minimizing sequence with respect to mγ,a,ε such that unu and u0. Moreover, using Lemma 2.5, it follows that unu in H2(RN), uS(a), and Jγ,ε(u)=mγ,a,ε.

    The following part is dedicated to studying the attainability of minimizers when V satisfies (V4). We can choose a minimizing sequence (un)S(a) with respect to mγ,a,μ, namely,

    Jγ,μmγ,a,μ,asn+.

    Since σ(0,2N), arguing as the discussion in Section 2, we infer that (un) is bounded in E. Therefore, we can get uE and a subsequence of (un), still represented by (un), such that

    un(x)u(x)a.e. inRN,

    and

    unuinE.

    Lemma 6.1. There exist two constants C1, r0>0, which do not rely on μ>0, and

    lim infn+RN|un|2σ+2dxC1,for allrr0. (6.1)

    Proof. Set u1S(a)C0(RN) with supp(u1)Ω, where Ω=int(W1(0)), x1Ω, and

    uk(x)=eNk2u1(ek(xx1)),for anyxRNand anykR.

    By calculation, we have

    RN|uk(x)|2dx=a2,

    and

    RN|uk(x)|2σ+2dx=eσNkRN|u1(x)|2σ+2dx. (6.2)

    Therefore,

    Jγ,μ(uk)=γe4k2RN|Δu1|2dx+e2k2RN|u1|2dx+μ2supp(u1)W(ekx+x1)|u1|2dxeσNk2σ+2RN|u1|2σ+2dx.

    As σ(0,2N), there exists a constant k<0 such that

    γe4k2RN|Δu1|2dx+e2k2RN|u1|2dxeσNk2σ+2RN|u1|2σ+2dx=Dk<0.

    Now, we choose M1=sup{|x|:xsupp(u1)} and r0=ekM1. If rr0>0, and then

    W(ekx+x1)=0,for allxsupp(u1).

    Hence,

    Jγ,μ(uk)<0.

    It shows there is a constant C1>0 that does not rely on μ and mγ,a,μ<C1 when μ>0. Let us recall

    mγ,a,μ+on(1)=Jγ,μ(un)=γ2RN|Δun|2dx+12RN|un|2dx+μ2RNW(x)|un|2dx12σ+2RN|un|2σ+2dx.

    Then, we have

    C1+on(1)12σ+2RN|un|2σ+2dx

    and

    lim infn+RN|un|2σ+2dxC1>0,

    where C1 is independent of μ.

    Lemma 6.2. There exist two constants μ0>0, R>0, and when μμ0>0, this inequality is established:

    lim supn+BcR(0)|un|2σ+2dxC12,

    where C1>0 is given in Lemma 6.1.

    Proof. Actually, as the discussion in [29,Lemma 2.5], for each ε>0, there exist R>0 and μ0>0 such that

    lim supn+BcR(0)|un|2dxε,for allμμ0.

    Now, apply that the result (un) is bounded in L2(RN) by a constant, and the constant is independent of μ. In the following, we can use interpolation theorem of Lebesgue spaces and the proper ε>0 to get the expected result.

    Lemma 6.3. When μμ0>0, u0, where u is the weak limit of (un).

    Proof. If not, we have that u=0 for some μμ0. As un0 in L2σ+2(BR(0)) for each R>0, according to Lemmas 6.1 and 6.2 we have

    C1lim infn+RN|un|2σ+2dx=lim infn+BcR(0)|un|2σ+2dxlim supn+BcR(0)|un|2σ+2dxC12.

    We get a contradiction, which implies that there exists a constant μ0>0 such that u0 when μμ0.

    According to Lemma 6.3, we can get (un)S(a) which is a minimizing sequence with respect to mγ,a,μ such that unu and u0. Moreover, we can use Lemma 2.5, and then, unu in E, uS(a) and Jγ,μ(u)=mγ,a,μ.

    The author would like to thank the anonymous referee for many valuable comments to improve the manuscript.

    The author declares there is no conflict of interest.



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