In this article, applying variational technique as well as critical point theory, we establish a series of criteria to ensure the existence and multiplicity of nontrivial periodic solutions to a second-order nonlinear partial difference equation. Our results generalize some known results. Moreover, numerical stimulations are presented to illustrate applications of our major findings.
Citation: Yuhua Long, Dan Li. Multiple nontrivial periodic solutions to a second-order partial difference equation[J]. Electronic Research Archive, 2023, 31(3): 1596-1612. doi: 10.3934/era.2023082
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In this article, applying variational technique as well as critical point theory, we establish a series of criteria to ensure the existence and multiplicity of nontrivial periodic solutions to a second-order nonlinear partial difference equation. Our results generalize some known results. Moreover, numerical stimulations are presented to illustrate applications of our major findings.
Denote the real number set and the integer set by R and Z, respectively. For any a,b∈Z with a≤b, define Z(a,b): = {a,a+1,⋯,b}. In this paper, we focus on multiple nontrivial periodic solutions of the following second-order partial difference equation:
△1[p(n−1,m)(△1u(n−1,m))η]+△2[r(n,m−1)(△2u(n,m−1))η]+q(n,m)(u(n,m))η+f((n,m),u(n,m))=0,n,m∈Z, | (1.1) |
where △1u(n,m)=u(n+1,m)−u(n,m) and △2u(n,m)=u(n,m+1)−u(n,m). f((n,m),u):Z2×R→R is continuous with respect to u. Given integers T1,T2>0, for any n,m∈Z, let nonzero sequences {p(n,m)}, {r(n,m)} and {q(n,m)} satisfy
p(n+T1,m)=p(n,m)=p(n,m+T2)>0,r(n+T1,m)=r(n,m)=r(n,m+T2)≥0, |
q(n+T1,m)=q(n,m)=q(n,m+T2)≤0, |
and
f((n+T1,m),u)=f((n,m),u)=f((n,m+T2),u),∀((n,m),u)∈Z2×R. |
Let η be the ratio of odd positive integers such that (−1)η=−1. If a solution u={u(n,m)} satisfies u(n+T1,m)=u(n,m)=u(n,m+T2) for any n,m∈Z, we call u a (T1,T2)-periodic solution. To help with understanding if a solution u is (T1,T2)-periodic, we give an example as a remark.
Remark 1.1. Consider (1.1) with T1=T2=2. Suppose (1.1) possesses four solutions, denoted by
u1=(u11,u12,u13,u14),u2=(u21,u22,u23,u24),u3=(u31,u32,u33,u34),u4=(u41,u42,u43,u44). |
If they are (2, 2)-periodic, that is, u(n+2,m)=u(n,m)=u(n,m+2), n,m=1,2, then
u31=u11=u13=u33,u32=u12=u14=u34;u41=u21=u23=u43,u42=u22=u24=u44. |
Actually, u1=u3 and u2=u4. Therefore, u11=u13 and u12=u14 ensure that the solution u1=(u11,u12,u13,u14) is (2, 2)-periodic.
In socio-economic activities and natural science research, we often encounter variables similar to time t. Meanwhile, one can often only observe or record values of these variables in discrete cases. Solving this problem is inseparable from difference equations. During past decades, difference equations have been used extensively [1,2], and scholars have studied difference equations in many ways, including period solutions, boundary value problems, homoclinic solutions, heteroclinic solutions [3,4,5,6,7,8] and so on. It is worth mentioning that Guo and Yu [3] made critical point theory an effective tool to discuss periodic solutions by constructing a new variational structure for the first time. In [9], by critical point theory, Cai and Yu studied the existence of solutions to the following equation:
△(pn(△xn−1)η)+qnxηn=f(n,xn),n∈Z. | (1.2) |
Obviously, Eq (1.2), involving only one independent variable, is a special case of (1.1). It has been studied by many authors, and certain conclusions [10,11,12] have been yielded.
On the other side, as modern technology advances rapidly, the use of mathematical modeling to solve problems is not only becoming more and more frequent, but also there are more and more factors needing to be considered. As a result, partial difference equations, containing multiple independent integer variables, have widespread applications in image processing, life sciences, quantum mechanics, and other fields [13] and capture great interest of many scholars. For example, [14,15,16] obtain multiple results on discrete Kirchhoff problems, and [17,18,19,20] concern second order partial difference equations via Morse theory. Very recently, [21] investigated periodic solutions of the equation
△1[p(n−1,m)△1u(n−1,m)]+△2[r(n,m−1)△2u(n,m−1)]+f((n,m),u(n,m))=0, | (1.3) |
via critical point theory. Clearly, letting η≡1, (1.1) is just (1.3), and (1.1) is more general than (1.3). Moreover, via critical point theory, [22,23] deal with the existence of multiple solutions for a partial discrete Dirichlet boundary value problem with mean curvature operator and homoclinic solutions for a differential inclusion system involving the p(t)-Laplacian, respectively. In view of the abovementioned results, we find that critical point theory serves as a robust method for studying both differential equations and difference equations. Therefore, motivated by the above obtained results, we intend to study periodic solutions to (1.1) by critical point theory. We also provide numerical stimulations to illustrate applications of our theoretical results. Our results generalize some results in [9] and [21]. The resulting problem engages two major difficulties: First, to estimate relations between norms, we need to transfer (1.1) into an equivalent form to compute its eigenvalues. Another difficulty we must overcome is verifying the link geometry and certifying boundedness of the Palais-Smale sequence.
For the rest of this paper, we organize in the following way. In Section 2, we give a variational structure and look for the corresponding functional to (1.1). Moreover, some definitions and lemmas are recalled. Our main results and detailed proofs are provided in Section 3. Finally, Section 4 presents three examples to demonstrate the application of our main results.
In this section, we establish the corresponding variational framework to (1.1) and state some preliminaries and notations to make preparation for our main results.
Write
u=(⋯;⋯,u(1,1),u(2,1),u(3,1),⋯;⋯,u(1,2),u(2,2),u(3,2),⋯;⋯), |
and let
S={u={u(n,m)}|u(n,m)∈R,n,m∈Z} |
be a vector space which is composed of all u={u(n,m)}n,m∈Z. Define
E={u={u(n,m)}∈S|u(n+T1,m)=u(n,m)=u(n,m+T2),n,m∈Z} |
as a subset of S. Define an inner product ⟨⋅,⋅⟩ on E as
⟨u,v⟩=T1∑n=1T2∑m=1u(n,m)v(n,m),∀u,v∈E. |
Then, the induced norm ‖⋅‖ is
‖u‖=(T1∑n=1T2∑m=1|u(n,m)|2)12,∀u∈E. |
Clearly, the dimension of the Hilbert space E is T1T2-dimensional. Thus, E is homeomorphic to RT1T2.
For s>1, define another norm ‖⋅‖s on E as
‖u‖s=(T1∑n=1T2∑m=1|u(n,m)|s)1s,∀u∈E. |
Then, ‖u‖2=‖u‖, and for β>η+1 there exist constants C2≥C1>0, C4≥C3>0 such that
C1‖u‖≤‖u‖η+1≤C2‖u‖,C3‖u‖≤‖u‖β≤C4‖u‖,∀u∈E. | (2.1) |
Moreover, there holds
T1∑n=1T2∑m=1|u(n,m)|2≤(T1T2)η−1η+1(T1∑n=1T2∑m=1|u(n,m)|η+1)2η+1. |
Then,
(T1T2)−η−12(η+1)(T1∑n=1T2∑m=1|u(n,m)|2)12≤(T1∑n=1T2∑m=1|u(n,m)|η+1)1η+1, |
which means that we can choose C1=(T1T2)−η−12(η+1).
Consider a functional I:E→R in the following form:
I(u)=1η+1T1∑n=1T2∑m=1[p(n−1,m)(△1u(n−1,m))η+1+r(n,m−1)(△2u(n,m−1))η+1−q(n,m)(u(n,m))η+1]−T1∑n=1T2∑m=1F((n,m),u(n,m)), | (2.2) |
where F((n,m),u)=∫u0f((n,m),s)ds. Since f((⋅,⋅),u) is continuous with respect to u, it follows that I∈C1(E,R). Moreover, for any u∈E, using the periodic condition, direct computation yields
∂I∂u(n,m)=p(n−1,m)(△1u(n−1,m))η−p(n,m)(△1u(n,m))η+r(n−1,m)(△2u(n,m−1))η−r(n,m)(△2u(n,m))η−q(n,m)(u(n,m))η−f((n,m),u(n,m))=−△1[p(n−1,m)(△1u(n−1,m))η]−△2[r(n,m−1)(△2u(n,m−1))η]−q(n,m)(u(n,m))η−f((n,m),u(n,m)). |
Hence, u∈E being a critical point for I is equivalent to
△1[p(n−1,m)(△1u(n−1,m))η]+△2[r(n,m−1)(△2u(n,m−1))η]+q(n,m)(u(n,m))η+f((n,m),u(n,m))=0,∀u∈E, |
which is just (1.1). Therefore, we transform the problem to find (T1,T2)-periodic solutions to (1.1) to the problem to seek critical points of I on E.
For convenience, write u∈E as
u=(u(1,1),⋯,u(T1,1);u(1,2),⋯,u(T1,2);⋯;u(1,T2),⋯,u(T1,T2))T, |
where ⋅T denotes the transpose of vector ⋅. Let matrices A and B be defined by
A=(B0B⋱0B)T1T2×T1T2. B=(2−10⋯0−1−12−1⋯000−12⋯00⋯⋯⋯⋯⋯⋯000⋯2−1−100⋯−12)T1×T1, |
By matrix theory, we find that the matrix B is semi-definite positive, and its eigenvalues are
λk=2(1−cos2kπT1),k=0,1,2,⋯,T1−1. |
Then, λ1=0<λ2≤λ3≤⋯≤λT1, and
λ2=2(1−cos2πT1). |
Moreover, matrices A and B have the same eigenvalues λ1=0<λ2≤λ3≤⋯≤λT1, and the multiplicity of each eigenvalue λk of matrix A is T2. Direct computation gives
‖△1u(n−1,m)‖2=T1∑n=1T2∑m=1[△1u(n−1,m)]2=T1∑n=1T2∑m=1(u(n,m)−u(n−1,m))2=T1∑n=1T2∑m=1u2(n,m)−2T1∑n=1T2∑m=1u(n,m)u(n−1,m)+T1∑n=1T2∑m=1u2(n−1,m)=2T1∑n=1T2∑m=1u2(n,m)−2T1∑n=1T2∑m=1u(n,m)u(n−1,m)=⟨Au,u⟩, |
and
‖△1u(n,m)‖2=T1∑n=1T2∑m=1[△1u(n,m)]2=T1∑n=1T2∑m=1(u(n+1,m)−u(n,m))2=T1∑n=1T2∑m=1u2(n+1,m)−2T1∑n=1T2∑m=1u(n+1,m)u(n,m)+T1∑n=1T2∑m=1u2(n,m)=2T1∑n=1T2∑m=1u2(n,m)−2T1∑n=1T2∑m=1u(n,m)u(n−1,m)=⟨Au,u⟩=‖△1u(n−1,m)‖2. |
Define an orthogonal matrix
![]() |
such that
v=Pu=(u(1,1),⋯,u(1,T2);u(2,1),⋯,u(2,T2);⋯;u(T1,1),⋯,u(T1,T2))T. |
Then, the matrix P is a rearrangement transformation of u, and ‖u‖s=‖v‖s for any s>0.
Similarly, given matrices C and D as
C=(2−10⋯0−1−12−1⋯000−12⋯00⋯⋯⋯⋯⋯⋯000⋯2−1−100⋯−12)T2×T2, D=(C0C⋱0C)T1T2×T1T2, |
it follows that eigenvalues of matrix C are μ1=0<μ2≤μ3≤⋯≤μT2, and
μ2=2(1−cos2πT2). |
In the same manner, we have that eigenvalues of matrix D are also μ1=0<μ2≤μ3≤⋯≤μT2, and each eigenvalue μκ, 1≤κ≤T2 is T1-multiple. Further,
‖△2u(n,m−1)‖2=T1∑n=1T2∑m=1[△2u(n,m−1)]2=⟨Dv,v⟩, |
and
‖△2u(n,m)‖2=T1∑n=1T2∑m=1[△2u(n,m)]2=⟨Dv,v⟩=‖△2u(n,m−1)‖2. |
Set W={w∈E|w={c},c∈R} and Y=W⊥. Then, E=Y⊕W. Thus, for any u∈Y, we have
λ2‖u‖2≤‖△1u(n−1,m)‖2=‖△1u(n,m)‖2=⟨Au,u⟩≤λT1‖u‖2,μ2‖u‖2=μ2‖v‖2≤‖△2u(n,m−1)‖2=‖△2u(n,m)‖2=⟨Dv,v⟩≤μT2‖v‖2=μT2‖u‖2. | (2.3) |
Thus, for any w∈W, we get
‖△1w(n−1,m)‖2=‖△1w(n,m)‖2=⟨Aw,w⟩=0,‖△2w(n,m−1)‖2=‖△2w(n,m)‖2=⟨DPw,Pw⟩=0. | (2.4) |
In the following, we recall some definitions and lemmas which are useful to our main results.
Definition 2.1. Let I∈C1(E,R). If any sequence {uk}⊂E such that {I(uk)} is bounded and I′(uk)→0 as k→∞ possesses a convergent subsequence, then I satisfies the Palais-Smale (P.S. for short) condition.
Let Bρ denote an open ball whose center is 0 and radius is ρ in E. Let ∂Bρ stand for the boundary of Bρ. The following Lemmas 2.1–2.3 are main tools to prove our results, and we can refer to [24] for detail.
Lemma 2.1. (Mountain Pass Lemma[24]) Let X be a real Banach space and I∈C1(X,R) satisfy the P.S. condition. Moreover, I(0)=0. Suppose
(f1) there exist constants ρ, a>0 such that I|∂Bρ≥a;
(f2) there exists e∈X∖Bρ such that I(e)≤0.
Then, I admits a critical value c≥a given by
c=infh∈Γsups∈[0,1]I(h(s)) |
where
Γ={h∈C([0,1],X)|h(0)=0,h(1)=e}. |
Lemma 2.2. (Linking theorem[24]) Let X=X1⊕X2 be a real Banach space, where X1 is a finite-dimensional subspace of X. Suppose that I∈C1(E,R) satisfies the P.S. condition. If
(f3) there exist constants ρ, a>0 such that I|∂Bρ∩X2≥a, and
(f4) there exist constants e∈∂B1∩X2, R0>ρ such that I|∂Q≤0, where Q=(ˉBR0∩X1)⊕{re|0<r<R0},
then I has a critical value c≥a, and
c=infh∈Γmaxu∈ˉQI(h(u)), |
where
Γ={h∈C(ˉQ,X):h|∂Q=id}. |
Lemma 2.3. (Saddle point theorem[24]) Let X=X1⊕X2 be a real Banach space and X1≠{0} be a finite-dimensional subspace of X. Suppose I∈C1(E,R) satisfies the P.S. condition. If
(f5) there exist constants σ and ρ>0 such that I|∂Bρ∩X1≤σ, and
(f6) there exist constants e∈Bρ∩X1, ω>σ such that I|e+X2≥ω,
then I has a critical value c≥ω, and
c=infh∈Γmaxu∈Bρ∩X1I(h(u)), |
where
Γ={h∈C(ˉBρ∩X1,X)|h|∂Bρ∩X1=id}. |
For convenience, we give some notations first. Write Ω:=Z(1,T1)×Z(1,T2), and
pmax=max(n,m)∈Ωp(n,m)>0,pmin=min(n,m)∈Ωp(n,m)>0,rmax=max(n,m)∈Ωr(n,m)≥0,rmin=min(n,m)∈Ωr(n,m)≥0,qmax=max(n,m)∈Ωq(n,m)≤0,qmin=min(n,m)∈Ωq(n,m)≤0. |
To study (1.1), the following assumptions are needed:
(F1)limu→0f((n,m),u)uη=0, ∀((n,m),u)∈Ω×R.
(F2) There exist constants a1>0, a2>0 and β>η+1 such that
F((n,m),u)≥a1|u|β−a2,∀((n,m),u)∈Ω×R. |
Remark 3.1. By (F2), we have
(F′2)lim|u|→+∞F((n,m),u)uη+1=+∞,∀((n,m),u)∈Ω×R.
Thus, (F1) and (F′2) mean that f((n,m),u) is superlinearly increasing at both 0 and ∞.
Now, we are in the position to present our main results.
Theorem 3.1. Let (F1) and (F2) hold. Moreover,
(q) for any (n,m)∈Ω, q(n,m)<0.
Then, (1.1) possesses at least two nontrivial (T1,T2)-periodic solutions.
Theorem 3.2. Suppose (F1) and (F2) are satisfied. If T1∑n=1T2∑m=1F((n,m),u)≥0 and
(q′) q(n,m)≡0, ∀(n,m)∈Ω,
then (1.1) admits at least two nontrivial (T1,T2)-periodic solutions.
Recall C1=(T1T2)−η−12(η+1), λ2=2(1−cos2πT1) and μ2=2(1−cos2πT2). We have the following.
Theorem 3.3. If (q) and
(F3)
T1∑n=1T2∑m=1(−q(n,m))(T1∑n=1T2∑m=1f2(n,m))η+12(1C1)η+1<(pminλη+122+rminμη+122−qmax)(T1∑n=1T2∑m=1f(n,m))η+1,∀(n,m)∈Ω, |
hold, then equation
△1[p(n−1,m)(△1u(n−1,m))η]+△2[r(n,m−1)(△2u(n,m−1))η]+q(n,m)(u(n,m))η+f(n,m)=0,n,m∈Z, | (3.1) |
has at least a (T1,T2)-periodic solution.
Remark 3.2. In fact, (1.2) and (1.3) are special cases of (1.1). Consider (1.1) with r(n,m)≡0, and (1.1) can be written in the form of (1.2). Meanwhile, if q(n,m)=0 and η=1, then (1.1) changes to (1.3). Moreover, our Theorems 3.1–3.3 are able to override Theorem 3.2 of [9], Theorem 3.1 of [21] and Theorem 3.3 of [9]. Consequently, (1.1) is a generalization of both (1.2) and (1.3), and our results are more universal.
Before stating proofs of Theorems 3.1–3.3, we need to prove the compactness of I first.
Lemma 3.1. Assume (F2) holds. Then, I satisfies the P.S. condition on E.
Proof. Assume that for any {uk}⊂E there exists a constant M>0 such that
|I(uk)|≤MandI′(uk)→0,ask→+∞. |
As E is a finite-dimensional space, we only need to prove that {uk} is bounded. By (F2), we have
−M≤I(uk)=1η+1T1∑n=1T2∑m=1[p(n−1,m)(△1uk(n−1,m))η+1+r(n,m−1)(△2uk(n,m−1))η+1]−1η+1T1∑n=1T2∑m=1q(n,m)(uk(n,m))η+1−T1∑n=1T2∑m=1F((n,m),uk(n,m))≤pmaxη+1T1∑n=1T2∑m=1(△1uk(n−1,m))η+1+rmaxη+1T1∑n=1T2∑m=1(△2uk(n,m−1))η+1−qminη+1T1∑n=1T2∑m=1(uk(n,m))η+1−a1T1∑n=1T2∑m=1|uk(n,m)|β+a2T1T2=pmaxη+1‖△1uk(n−1,m)‖η+1η+1+rmaxη+1‖△2uk(n,m−1)‖η+1η+1−qminη+1‖uk‖η+1η+1−a1‖uk‖ββ+a2T1T2. | (3.2) |
Moreover, due to (2.1) and (2.3), it follows that
‖△1uk(n−1,m)‖η+1η+1≤Cη+12‖△1uk(n−1,m)‖η+1≤Cη+12λη+12T1‖uk‖η+1,‖△2uk(n,m−1)‖η+1η+1≤Cη+12‖△2uk(n,m−1)‖η+1≤Cη+12μη+12T2‖uk‖η+1,‖uk‖η+1η+1≤Cη+12‖uk‖η+1,‖uk‖ββ≥Cβ3‖uk‖β. | (3.3) |
Therefore, combining (3.2) with (3.3), it yields that
−M≤pmaxCη+12λη+12T1η+1‖uk‖η+1+rmaxCη+12μη+12T2η+1‖uk‖η+1−qminCη+12η+1‖uk‖η+1−a1Cβ3‖uk‖β+a2T1T2. |
That is,
a1Cβ3‖uk‖β−Cη+12(pmaxλη+12T1+rmax μη+12T2−qmin)η+1‖uk‖η+1≤a2T1T2+M. | (3.4) |
Since β>η+1, (3.4) ensures that {uk}⊂E is a bounded sequence. Consequently, I satisfies the P.S. condition, and the proof is finished.
Proof of Theorem 3.1 By Lemma 3.1, I satisfies the P.S. condition on E. In the following, we verify conditions (f1) and (f2) of Lemma 2.1 to complete the proof.
In fact, from (F1), it follows that
limu→0F((n,m),u)uη+1=0,∀(n,m)∈Ω. |
Then, there is a ρ>0 such that
|F((n,m),u)|≤−qmax2(η+1)uη+1,∀(n,m)∈Ω,|u|≤ρ. |
Hence, for any u∈E with ‖u‖≤ρ, we obtain
I(u)≥−qmaxη+1‖u‖η+1η+1+qmax2(η+1)‖u‖η+1η+1=−qmax2(η+1)‖u‖η+1η+1≥−qmax Cη+112(η+1)‖u‖η+1. | (3.5) |
Take a=−qmaxCη+112(η+1)ρη+1>0, and then (3.5) ensures I(u)|∂Bρ≥a>0. Thus, (f1) of Lemma 2.1 is fulfilled.
Given ω∈E with ‖ω‖=1 and α>0, we have
I(αω)=1η+1T1∑n=1T2∑m=1[p(n−1,m)(△1αω(n−1,m))η+1+r(n,m−1)(△2αω(n,m−1))η+1]−1η+1T1∑n=1T2∑m=1q(n,m)(αω(n,m))η+1−T1∑n=1T2∑m=1F((n,m),αω(n,m))≤αη+1pmaxη+1‖△1ω(n−1,m)‖η+1η+1+αη+1rmaxη+1‖△2ω(n,m−1)‖η+1η+1−αη+1qminη+1‖ω‖η+1η+1−a1αβ‖ω‖ββ+a2T1T2≤αη+1pmaxCη+12η+1‖△1ω(n−1,m)‖η+1+αη+1rmaxCη+12η+1‖△2ω(n,m+1)‖η+1−αη+1qminCη+12η+1−a1αβCβ3+a2T1T2≤αη+1pmaxCη+12λη+12T1η+1+αη+1rmaxCη+12μη+12T2η+1−αη+1qminCη+12η+1−a1αβCβ3+a2T1T2→−∞,asα→+∞, |
which means that there exists α>ρ large enough such that I(u0)<0, where u0=αω∈E∖Bρ. Moreover, I(0)=0. Thus, Lemma 2.1 guarantees that there is a critical value c≥a>0. Assume ˉu is a critical point, namely, I(ˉu)=c and I′(ˉu)=0.
In the following, we look for another critical point ˜u for I. By (3.4), we get
I(u)≤Cη+12(pmaxλη+12T1+rmaxμη+12T2−qmin)η+1‖uk‖η+1−a1Cβ3‖u‖β+a2T1T2, |
which indicates I is bounded from above. Denote the supremum of {I(u)}u∈E by cmax, and then ˜u∈E and I(˜u)=cmax. Obviously, ˜u≠0. If ˉu≠˜u, the proof is finished. Else, c=cmax. Lemma 2.1 means that
c=infh∈Γsupt∈[0,1]I(h(t)), |
where
Γ={h∈C([0,1],E)|h(0)=0,h(1)=u0}. |
Hence, for any h∈Γ, cmax=maxt∈[0,1]I(h(t)). In view of I(h(t)) being continuous with respect to t, I(0)≤0 and I(u0)<0, it follows that there exists a t0∈(0,1) such that I(h(t0))=cmax. Choose h1,h2 such that {h1(t)|t∈(0,1)}∩{h2(t)|t∈(0,1)}=∅, and then there exist t1,t2∈(0,1) such that I(h1(t1))=I(h2(t2))=cmax. Thus, we obtain two different critical points u1=h1(t1) and u2=h2(t2). Consequently, there exist at least two nontrivial critical points which correspond to the critical value cmax. This completes the proof.
Proof of Theorem 3.2 Let W={w∈E|w={c},c∈R}, Y=W⊥, and then E=W⊕Y. By (F1), there exist some ρ>0 and u∈Bρ such that
F((n,m),u)≤pmin λη+122+rmin μη+12Cη+112(η+1)Cη+12|u|η+1. |
Then, for every u∈(∂Bρ)∩Y, one obtains
I(u)≥pminη+1‖△1u(n−1,m)‖η+1η+1+rminη+1‖△2u(n,m−1)‖η+1η+1−(pminλη+122+rminμη+122)Cη+112(η+1)Cη+12‖u‖η+1η+1≥pminCη+11η+1‖△1u(n−1,m)‖η+1+rminCη+11η+1‖△2u(n,m−1)‖η+1−(pminλη+122+rminμη+122)Cη+112(η+1)‖u‖η+1≥(pminλη+122+rminμη+122)Cη+11η+1‖u‖η+1−(pminλη+122+rminμη+122)Cη+112(η+1)‖u‖η+1=(pminλη+122+rminμη+122)Cη+112(η+1)‖u‖η+1=(pminλη+122+rminμη+122)Cη+11ρη+12(η+1). | (3.6) |
Set a=(pminλη+122+rminμη+122)Cη+11ρη+12(η+1), and then (3.6) implies I(u)≥a, u∈(∂Bρ)∩Y. Thus, (f3) of Lemma 2.2 is valid.
Let e∈∂B1∩Y, and for every w∈W and s∈R, set u=se+w. From (2.4) together with (F2), it follows that △1w=△2w=0, ‖e‖=1, and
I(u)=I(se+w)=1η+1T1∑n=1T2∑m=1[p(n−1,m)(△1se(n−1,m))η+1+r(n,m−1)(△2se(n,m−1))η+1]−T1∑n=1T2∑m=1F((n,m),(se+w)(n,m)).≤sη+1pmaxη+1‖△1e(n−1,m)‖η+1η+1+sη+1rmaxη+1‖△2e(n,m−1)‖η+1η+1−a1T1∑n=1T2∑m=1|se(n,m)+w(n,m)|β+a2T1T2≤sη+1pmaxCη+12η+1‖△1e(n−1,m)‖η+1+sη+1rmaxCη+12η+1‖△2e(n,m−1)‖η+1−a1Cβ3‖se+w‖β+a2T1T2≤sη+1Cη+12η+1(pmaxλη+12T1+rmaxμη+12T2)−a1Cβ3‖se‖β−a1Cβ3‖w‖β+a2T1T2=sη+1Cη+12η+1(pmaxλη+12T1+rmaxμη+12T2)−a1Cβ3sβ−a1Cβ3‖w‖β+a2T1T2. |
Write
g1(s)=sη+1Cη+12η+1(pmaxλη+12T1+rmaxμη+12T2)−a1Cβ3sβ,g2(τ)=−a1Cβ3τβ+a2T1T2. |
Then, both g1(s) and g2(τ) are bounded from above. Moreover, β>η+1 leads to lims→+∞g1(s)=−∞ and limτ→+∞g2(τ)=−∞. Thus, there exists a positive constant R0>ρ such that I(u)≤0 holds for any u∈∂Q and Q=(ˉBR0∩W)⊕{se|0<s<R0}.
Notice that Lemma 3.1 shows I satisfies the P.S. condition on E. Therefore, Lemma 2.2 ensures that I admits a critical value c≥a, and
c=infh∈Γmaxu∈ˉQI(h(u)),Γ={h∈C(ˉQ,E):h|∂Q=id}. |
Take ˉu∈E to be a critical point which corresponds to c, that is, I(ˉu)=c. By (3.4), I is bounded from above. Hence, there will be a ˜u∈E such that
I(˜u)=cmax=supu∈EI(u). |
Then, ˉu and ˜u are nontrivial (T1,T2)-periodic solutions of (1.1). If ˉu≠˜u, then Theorem 3.2 holds. Otherwise, ˉu=˜u, and then c=cmax, that is,
supu∈EI(u)=infh∈Γsupu∈ˉQI(h(u)). |
Choose h=id, and we get supu∈ˉQI(u)=cmax. Consider −e∈∂Bρ∩Y. With the arbitrariness of e, it follows that there is an R1>ρ such that I|∂Q1≤0, where Q1=(ˉBR1∩W)⊕{−se|0<s<R1}. In the same way, by Lemma 2.2, I possesses a new critical value c′≥a>0, and
c′=infh∈Γmaxu∈ˉQ1I(h(u)),Γ={h∈C(ˉQ1,E):h|∂Q1=id}. |
If c′≠cmax, then this proof is done. If c′=cmax, then for any h∈Γ, we have maxu∈ˉQ1I(h(u))=cmax. Specifically, take h=id, and then maxu∈ˉQ1I(u)=cmax. Since I|∂Q≤0, I|∂Q1≤0 and cmax>0, the maximum value of I is given at a point inside Q and Q1, respectively. In addition, Q∩Q1⊂W, and for every w∈W, we have
I(w)=−T1∑n=1T2∑m=1F((n,m),w(n,m))≤0. |
Therefore, a point ˆu which is different from ˜u must exist in E such that I(ˆu)=c′=cmax. In summary, if c<cmax, then (1.1) admits at least two nontrivial (T1,T2)-periodic solutions; if c=cmax, then (1.1) admits an infinite number of nontrivial (T1,T2)-periodic solutions. This completes the proof.
Proof of Theorem 3.3 Similar to (2.2), the variational functional associated to (3.1) is expressed by
ˆI(u)=1η+1T1∑n=1T2∑m=1[p(n−1,m)(△1u(n−1,m))η+1+r(n,m−1)(△2u(n,m−1))η+1−q(n,m)(u(n,m))η+1]−T1∑n=1T2∑m=1f(n,m)u(n,m). | (3.7) |
In the following, we utilize Lemma 2.3 to finish the proof. To begin with, it is to show that ˆI meets the P.S. condition on E. Suppose {uk}⊂E, and there is a constant ˆM>0 such that
|ˆI(uk)|≤ˆM,ˆI′(uk)→0,k→+∞. |
Since the dimension of E is T1T2, it is necessary for us to show {uk} is bounded in E. In view of (3.7) and the oddness of η, there holds
ˆM≥ˆI(uk)≥−1η+1T1∑n=1T2∑m=1q(n,m)(uk(n,m))η+1−T1∑n=1T2∑m=1f(i,i)uk(n,m)≥−qmaxη+1‖uk‖η+1η+1−(T1∑n=1T2∑m=1f2(n,m))12(T1∑n=1T2∑m=1u2k(n,m))12≥−qmaxCη+11η+1‖uk‖η+1−(T1∑n=1T2∑m=1f2(n,m))12‖uk‖. | (3.8) |
Recall η+1>1, and then (3.8) implies that {uk} is bounded in E. Therefore, ˆI satisfies the P.S. condition on E.
Next, we show (f5) and (f6) of Lemma 2.3 are met. For any w=(z,⋯,z)T∈W, one has
ˆI(w)=−1η+1T1∑n=1T2∑m=1q(n,m)zη+1−T1∑n=1T2∑m=1f(n,m)z. |
Take
z=(−∑T1n=1∑T2m=1f(n,m)∑T1n=1∑T2m=1q(n,m))1η,ρ=‖w‖=√T1T2|∑T1n=1∑T2m=1f(n,m)∑T1n=1∑T2m=1q(n,m)|1η. |
Then
ˆI(w)=ηη+1[∑T1n=1∑T2m=1f(n,m)]η+1η[∑T1n=1∑T2m=1q(n,m)]1η. |
Thus,
ˆI(u)=σ≜ηη+1[∑T1n=1∑T2m=1 f(n,m)]η+1η[∑T1n=1∑T2m=1 q(n,m)]1η,∀u∈∂Bρ∩W, |
which means that (f5) of Lemma 2.3 holds.
For y∈Y, one has
ˆI(y)≥pminη+1‖△1y(n−1,m)‖η+1η+1+rminη+1‖△2y(n,m−1)‖η+1η+1−qmaxη+1‖y‖η+1η+1−(T1∑n=1T2∑m=1f2(n,m))12‖y‖≥Cη+11η+1(pminλη+122+rminμη+122−qmax)‖y‖η+1−(T1∑n=1T2∑m=1f2(n,m))12‖y‖≥−ηη+1(∑T1n=1∑T2m=1f2(n,m))η+12η(1C1)η+1η(pminλη+122+γminμη+122−qmax)1η, |
and the last inequality is obtained by minimization with respect to ‖y‖. Set
ω0=−ηη+1(∑T1n=1∑T2m=1f2(n,m))η+12η(1C1)η+1η(pminλη+122+γmin μη+122−qmax)1η. |
Together with (F3), this yields that
ˆI(u)≥ω0>σ,∀u∈ Y. |
So, (f6) of Lemma 2.3 holds by taking e=0. Thus, all conditions of Lemma 2.3 are satisfied, and (3.1) admits at least a (T1,T2)-periodic solution.
Finally, we give three examples to demonstrate the validity of our results. Let
˜E={u={u(n,m)}∈S|u(n+2,m)=u(n,m)=u(n,m+2),n,m∈Z(1,2)}. |
Example 4.1. Take η=3. Consider Eq (1.1) with p(n,m)>0, r(n,m)≥0 and q(n,m)<0 for any n,m∈Z, and
f((n,m),u)=6u5,n,m∈Z,u∈R. |
Then,
F((n,m),u)=u6,n,m∈Z,u∈R. |
Obviously, f((n,m),u) satisfies all conditions of Theorem 3.1. Then, (1.1) with f((n,m),u)=6u5 admits at least two nontrivial (T1,T2)-periodic solutions.
Specially, let p(n,m)=r(n,m)=1, q(n,m)=−2 and T1=T2=2, and then (1.1) can be rewritten in the form of
△1(△1u(n−1,m))3+△2(△2u(n,m−1))3−2(u(n,m))3+6(u(n,m))5=0. | (4.1) |
Using MATLAB, we find that (4.1) has at least two nontrivial solutions u1={u1(n,m)}∈˜E and u2={u2(n,m)}∈˜E, where
u1=(√3,−√3,√3,−√3),u2=(−√3,√3,−√3,√3). |
By Remark 1.1, u1 and u2 are two different nontrivial (2, 2)-periodic solutions to (4.1).
Example 4.2. For every n,m∈Z, consider (1.1) with p(n,m)>0, r(n,m)≥0 and q(n,m)=0. Set η=3, and
f((n,m),u)=6u5,n,m∈Z,u∈R. |
Then, all conditions of Theorem 3.2 are satisfied, and (1.1) has at least two nontrivial (T1,T2)-periodic solutions.
Take p(n,m)=r(n,m)=1 and T1=T2=2, and then (1.1) becomes
△1(△1u(n−1,m))3+△2(△2u(n,m−1))3+6(u(n,m))5=0. | (4.2) |
Utilizing MATLAB, (4.2) has at least two nontrivial solutions
u1=(2√63,−2√63,2√63,−2√63),u2=(−2√63,2√63,−2√63,2√63). |
From Remark 1.1, (4.2) has at least two different nontrivial (2, 2)-periodic solutions u1 and u2.
Example 4.3. Set T1=T2=2, η=3 and f(n,m)=2. Consider (3.1) with p(n,m)=1, r(n,m)=1 and q(n,m)=−2. Clearly, p(n,m), r(n,m), q(n,m) and f(n,m) are all (2, 2)-periodic, and (3.1) is in the following form:
△1(△1u(n−1,m))3+△2(△2u(n,m−1))3−2(u(n,m))3+2=0. | (4.3) |
Obviously, we only need to verify (F3). Simple calculation gives
T1∑n=1T2∑m=1(−q(n,m))(T1∑n=1T2∑m=1f2(n,m))η+12(1C1)η+1=8×162×4=8192,(pminλη+122+γminμη+122−qmax)(T∑n=1T2∑m=1f(n,m))η+1=(42+42+2)×84=139264>2048. |
Thus, Theorem 3.3 ensures that (4.3) possesses at least one nontrivial (2, 2)-periodic solution. By MATLAB and Remark 1.1, (4.3) admits at least a (2, 2)-periodic solution
u(1,1)=1,u(2,1)=1,u(1,2)=1,u(2,2)=1. |
This work is supported by the Program for Changjiang Scholars and Innovative Research Team in University (Grant No. IRT_16R16).
All authors declare no conflicts of interest in this paper.
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